"""How each program's fire set is chosen. No LLM, no gradients, no search. Every program in this dataset has the same shape: fire = {' George', 'George', ' Osama', 'ORGE'} return 1 if input_tokens[-1] in fire else 0 so building one comes down to a single question: WHICH tokens go in the set? `choose_fire_set` below is the step that answers it. Start from an empty set. Repeatedly try adding every token that is not in the set yet, and keep whichever one raises the F1 of the WHOLE SET the most. Stop as soon as no single token improves it, or once the set is full. For the George feature this runs: add ' George' -> F1 0.877 add 'George' -> F1 0.927 add ' Osama' -> F1 0.954 add 'ORGE' -> F1 0.958 nothing else helps, so stop with four tokens. This is NOT the same as taking the most frequent tokens in order. At each step every remaining candidate is re-scored, and the winner is usually not the next most frequent one -- across layer-6 features it differs 98.7% of the time. A token that fires 531 times out of 2,227 appearances loses to one that fires 142 times out of 145, because the first drags in 1,696 false positives. Everything here is measured on the TRAINING corpus. The test split is touched once, at the very end, to score the finished program. TWO SMALL STEPS COME AFTER THIS ONE, so the set you get from `choose_fire_set` alone is not always byte-identical to the shipped program: * other spellings of a chosen word are added where they help (' George' is chosen, so 'George' and 'GEORGE' are considered too) * word families contributing under 0.25% of the feature's firings are dropped, since one or two firings is not evidence of anything For the George feature that second step is why `choose_fire_set` returns a fifth token, 'Americ', that the shipped program does not have: it scraped a hair above zero gain here and was pruned as a tail family afterwards. Both steps live in `fit_programs.py`. """ from typing import List import numpy as np def choose_fire_set(token_stats: List[dict], total_firings: int, max_tokens: int = 50) -> List[str]: """Pick the tokens that go in one feature's fire set. token_stats One dict per token the feature was ever seen firing on: 'token' the token itself, e.g. ' George' 'fires' times the feature fired on it (3,249) 'occurrences' times the token appeared at all (3,249) `occurrences - fires` is how often the token showed up WITHOUT the feature firing, i.e. the false positives it would cost us. This is why we need the corpus occurrence count and not just the firing count. total_firings How many times the feature fires anywhere in the corpus. Firings not covered by the chosen tokens are the false negatives. max_tokens Size limit on the set, so the printed program stays readable. 50 is what this dataset used. Returns the chosen tokens, in the order they were added. """ if not token_stats or total_firings <= 0 or max_tokens <= 0: return [] tokens = [t["token"] for t in token_stats] fires = np.array([t["fires"] for t in token_stats], dtype=np.float64) occurrences = np.array([t["occurrences"] for t in token_stats], dtype=np.float64) chosen: List[int] = [] still_available = np.ones(len(token_stats), dtype=bool) true_pos = false_pos = 0.0 best_f1_so_far = 0.0 for _ in range(min(max_tokens, len(token_stats))): # if we added each candidate to the set, what would the set score? new_true_pos = true_pos + fires new_false_pos = false_pos + (occurrences - fires) false_neg = total_firings - new_true_pos f1 = np.where( new_true_pos > 0, 2 * new_true_pos / (2 * new_true_pos + new_false_pos + false_neg), 0.0, ) f1[~still_available] = -1.0 # already in the set best = int(np.argmax(f1)) if f1[best] <= best_f1_so_far: break # nothing left that helps best_f1_so_far = float(f1[best]) true_pos = float(new_true_pos[best]) false_pos = float(new_false_pos[best]) still_available[best] = False chosen.append(best) return [tokens[i] for i in chosen]