use vstd::prelude::*; fn main() {} verus!{ fn f1_reverse_to_k(list: &Vec, n: usize) -> (reversed_list: Vec) requires list@.len() > 0, 0 < n < list@.len(), { let mut reversed_list = Vec::new(); let mut index = 0; while index < n { reversed_list.push(list[n - 1 - index]); index += 1; } index = n; while index < list.len() { reversed_list.push(list[index]); index += 1; } reversed_list } fn f2_contains(arr: &Vec, key: i32) -> (result: bool) { let mut i = 0; while i < arr.len() { if (arr[i] == key) { return true; } i += 1; } false } fn f2_any_value_exists(arr1: &Vec, arr2: &Vec) -> (result: bool) { let mut index = 0; while index < arr1.len() { if (f2_contains(arr2, arr1[index])) { return true; } index += 1; } false } spec fn step1(__hp0: Seq, __hp1: usize, outp: Seq) -> bool { (outp == __hp0.subrange(0, __hp1 as int).reverse().add( __hp0.subrange(__hp1 as int, __hp0.len() as int), )) } spec fn step2(inp: Seq, p2_key: i32, outp: bool) -> bool { (outp == (exists|i: int| 0 <= i < inp.len() && (inp[i] == p2_key))) } fn chain_driver(list: &Vec, n: usize, p2_key: i32) -> (r_final: bool) requires list@.len() > 0, 0 < n < list@.len(), ensures exists|v1: Seq| #[trigger] step1(list@, n, v1) && step2(v1, p2_key, r_final), { let x1 = f1_reverse_to_k(list, n); let x2 = f2_contains(&x1, p2_key); proof { assert(step1(list@, n, x1@)); assert(step2(x1@, p2_key, x2)); } x2 } } // verus!