use vstd::prelude::*; fn main() {} verus!{ fn f1_reverse_to_k(list: &Vec, n: usize) -> (reversed_list: Vec) requires list@.len() > 0, 0 < n < list@.len(), { let mut reversed_list = Vec::new(); let mut index = 0; while index < n { reversed_list.push(list[n - 1 - index]); index += 1; } index = n; while index < list.len() { reversed_list.push(list[index]); index += 1; } reversed_list } fn f2_find_negative_numbers(arr: &Vec) -> (negative_list: Vec) { let mut negative_list: Vec = Vec::new(); let input_len = arr.len(); let mut index = 0; while index < arr.len() { if (arr[index] < 0) { negative_list.push(arr[index]); } index += 1; } negative_list } pub open spec fn count_frequency_rcr(seq: Seq, key: i32) -> int decreases seq.len(), { if seq.len() == 0 { 0 } else { count_frequency_rcr(seq.drop_last(), key) + if (seq.last() == key) { 1 as int } else { 0 as int } } } fn f3_count_frequency(arr: &Vec, key: i32) -> (frequency: usize) { let mut index = 0; let mut counter = 0; while index < arr.len() { if (arr[index] == key) { counter += 1; } index += 1; } counter } fn f3_remove_duplicates(arr: &Vec) -> (unique_arr: Vec) { let mut unique_arr: Vec = Vec::new(); let input_len = arr.len(); let mut index = 0; while index < arr.len() { if f3_count_frequency(&arr, arr[index]) == 1 { unique_arr.push(arr[index]); } index += 1; } unique_arr } spec fn step1(__hp0: Seq, __hp1: usize, outp: Seq) -> bool { (outp == __hp0.subrange(0, __hp1 as int).reverse().add( __hp0.subrange(__hp1 as int, __hp0.len() as int), )) } spec fn step2(inp: Seq, outp: Seq) -> bool { (outp == inp.filter(|x: i32| x < 0)) } spec fn step3(inp: Seq, p3_key: i32, outp: usize) -> bool { (count_frequency_rcr(inp, p3_key) == outp) } fn chain_driver(list: &Vec, n: usize, p3_key: i32) -> (r_final: usize) requires list@.len() > 0, 0 < n < list@.len(), ensures exists|v1: Seq, v2: Seq| #[trigger] step1(list@, n, v1) && #[trigger] step2(v1, v2) && step3(v2, p3_key, r_final), { let x1 = f1_reverse_to_k(list, n); let x2 = f2_find_negative_numbers(&x1); let x3 = f3_count_frequency(&x2, p3_key); proof { assert(step1(list@, n, x1@)); assert(step2(x1@, x2@)); assert(step3(x2@, p3_key, x3)); } x3 } } // verus!