use vstd::prelude::*; fn main() {} verus! { pub struct Solution; impl Solution { pub closed spec fn is_sequential_digits(n: int) -> bool decreases n { if n < 10 { 1 <= n && n <= 9 } else { let last = n % 10; let rest = n / 10; let prev = rest % 10; 2 <= last && last <= 9 && prev == last - 1 && Self::is_sequential_digits(rest) } } pub fn sequential_digits(low: i32, high: i32) -> (result: Vec) requires 10 <= low <= high <= 1000000000, ensures forall|i: int| 0 <= i < result.len() ==> low <= #[trigger] result[i] <= high, forall|i: int| 0 <= i < result.len() ==> Self::is_sequential_digits(#[trigger] result[i] as int), forall|i: int, j: int| 0 <= i < j < result.len() ==> #[trigger] result[i] < #[trigger] result[j], forall|x: int| (low <= x <= high && Self::is_sequential_digits(x)) ==> exists|k: int| 0 <= k < result.len() && #[trigger] result[k] == x as i32, { let candidates = [ 12i32, 23, 34, 45, 56, 67, 78, 89, 123, 234, 345, 456, 567, 678, 789, 1234, 2345, 3456, 4567, 5678, 6789, 12345, 23456, 34567, 45678, 56789, 123456, 234567, 345678, 456789, 1234567, 2345678, 3456789, 12345678, 23456789, 123456789, ]; let mut result: Vec = Vec::new(); let mut i = 0; while i < candidates.len() { let x = candidates[i]; if low <= x && x <= high { result.push(x); } i += 1; } result } } }