package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

const (
	initialBufSize = 10000
	maxBufSize     = 1000000
	mod            = 1e9 + 7
)

var (
	sc *bufio.Scanner = func() *bufio.Scanner {
		sc := bufio.NewScanner(os.Stdin)
		buf := make([]byte, initialBufSize)
		sc.Buffer(buf, maxBufSize)
		sc.Split(bufio.ScanWords)
		return sc
	}()
)

func main() {
	A := getInt()
	B := getInt()

	gcd := calcGcd(A, B)
	cd := getDivisor(gcd)

	result := 0

	for _, cd := range cd {
		if cd == 1 || isPrime(cd) {
			result++
		}
	}

	fmt.Println(result)
}

func getDivisor(n int) []int {
	var divisor []int
	divisor = append(divisor, 1)
	divisor = append(divisor, n)

	sqrt := int(math.Sqrt(float64(n)))
	for i := 2; i <= sqrt; i++ {
		if n % i == 0 {
			divisor = append(divisor, i)
			divisor = append(divisor, n/i)
		}
	}
	return divisor
}

func calcGcd(x, y int) int {
	if y == 0 {
		return x
	} else if x >= y {
		return calcGcd(y, x % y)
	} else {
		return calcGcd(x, y % x)
	}
}

type Graph struct {
	n     int
	edges [][]int
}

func NewGraph(n int) *Graph {
	g := &Graph{
		n:     n,
		edges: make([][]int, n),
	}
	return g
}

func (g *Graph) AddEdge(u, v int) {
	g.edges[v] = append(g.edges[v], u)
	g.edges[u] = append(g.edges[u], v)
}

func dfs(c int, edges [][]int, visited map[int]struct{}) {
	visited[c] = struct{}{}

	for _, v := range edges[c] {
		_, flag := visited[v]
		if flag {
			continue
		}
		dfs(v, edges, visited)
	}
}

func getInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func getIntArray(n int) []int {
	array := make([]int, n)
	for i := 0; i < n; i++ {
		array[i] = getInt()
	}
	return array
}

func getString() string {
	sc.Scan()
	return sc.Text()
}

func abs(a int) int {
	return int(math.Abs(float64(a)))
}

func pow(p, q int) int {
	return int(math.Pow(float64(p), float64(q)))
}

func powMod(n, p int) int {
	if p == 0 {
		return 1
	} else if p%2 == 0 {
		t := powMod(n, p/2)
		return calcMod(t * t)
	} else {
		return calcMod(n * powMod(n, p-1))
	}
}

func min(nums ...int) int {
	if len(nums) == 0 {
		panic("funciton min() requires at least one argument.")
	}
	res := nums[0]
	for i := 0; i < len(nums); i++ {
		res = int(math.Min(float64(res), float64(nums[i])))
	}
	return res
}

func max(nums ...int) int {
	if len(nums) == 0 {
		panic("funciton max() requires at least one argument.")
	}
	res := nums[0]
	for i := 0; i < len(nums); i++ {
		res = int(math.Max(float64(res), float64(nums[i])))
	}
	return res
}

func strSearch(a []string, b string) bool {
	for i := 0; i < len(a); i++ {
		if a[i] == b {
			return true
		}
	}
	return false
}

func printIntArray(array []int) {
	strArray := fmt.Sprint(array)
	fmt.Println(strArray[1 : len(strArray)-1])
}

func calcMod(x int) int {
	return x % mod
}

func reverse(s string) string {
	runes := []rune(s)
	for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 {
		runes[i], runes[j] = runes[j], runes[i]
	}
	return string(runes)
}

func isPrime(n int) bool {
	if n < 2 {
		return false
	} else if n == 2 {
		return true
	} else if n % 2 == 0 {
		return false
	}

	sqrtN := int(math.Sqrt(float64(n)))
	for i := 3; i <= sqrtN; i += 2 {
		if n % i == 0 {
			return false
		}
	}

	return true
}

func contains(s []int, e int) bool {
	for _, v := range s {
		if e == v {
			return true
		}
	}
	return false
}

func makeRange(min, max int) []int {
	a := make([]int, max-min+1)
	for i := range a {
		a[i] = min + i
	}
	return a
}

func powerset2(nums []int) [][]int {
	length := int(math.Pow(2, float64(len(nums))))
	result := make([][]int, length)

	index := 0
	result[index] = []int{}
	index++

	for _, n := range nums {
		max := index
		for i := 0; i < max; i++ {
			result[index] = copyAndAppend(result[i], n)
			index++
		}
	}

	return result
}

func copyAndAppend(nums []int, n int) []int {
	dst := make([]int, len(nums)+1)
	copy(dst, nums)
	dst[len(nums)] = n
	return dst
}

Score : 400 points

Problem Statement

Given are positive integers A and B.

Let us choose some number of positive common divisors of A and B.

Here, any two of the chosen divisors must be coprime.

At most, how many divisors can we choose?

Definition of common divisor

An integer d is said to be a common divisor of integers x and y when d divides both x and y.

Definition of being coprime

Integers x and y are said to be coprime when x and y have no positive common divisors other than 1.

Definition of dividing

An integer x is said to divide another integer y when there exists an integer \alpha such that y = \alpha x.

Constraints

All values in input are integers.

1 \leq A, B \leq 10^{12}

Input

Input is given from Standard Input in the following format:

A B

Output

Print the maximum number of divisors that can be chosen to satisfy the condition.

Sample Input 1

12 18

Sample Output 1

3

12 and 18 have the following positive common divisors: 1, 2, 3, and 6.

1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.

Sample Input 2

420 660

Sample Output 2

4

Sample Input 3

1 2019

Sample Output 3

1

1 and 2019 have no positive common divisors other than 1.


package main

import (
	"bufio"
	"bytes"
	"fmt"
	"io"
	"os"
	"strconv"
)

// -----------------------------------------------------------------------------

// IO helper functions

// Returns next token from input.  It must be initialized by SetInput()
// before the first call.
var nextToken func() ([]byte, error)
var nextLine func() ([]byte, error)

// Holds a buffer for output.  It must be initialized by SetOutput().
// All IO fucntions (read*() and [e]print*()) should write to OutputWriter
// instead of this.
var OutputBuffer *bufio.Writer

// Holds an io.Writer.  It must be initialized by SetOutput()
var OutputWriter io.Writer

// Set IO functions for interactive input/output.
func SetInteractive(w io.Writer, r io.Reader) {
	SetUnbefferedInput(r)
	OutputBuffer = nil
	OutputWriter = w
}

// Setup OutputBuffer and OutputWriter.
func SetOutput(w io.Writer) {
	OutputBuffer = bufio.NewWriter(w)
	OutputWriter = OutputBuffer
}

// Flushes OutputBuffer
func Flush() {
	if OutputBuffer != nil {
		OutputBuffer.Flush()
	}
}

// Returns true if c is a white space
func IsSpace(c byte) bool {
	switch c {
	case '\t', '\n', '\v', '\f', '\r', ' ':
		return true
	}
	return false
}

func IsNewLine(c byte) bool {
	switch c {
	case '\n', '\r':
		return true
	}
	return false
}

// Setup nextToken with input buffer.
func SetInput(r io.Reader) {
	buf := new(bytes.Buffer)
	var b []byte

	var i int
	rest := func() ([]byte, error) {
		for i < len(b) && IsSpace(b[i]) {
			i++
		}
		if i == len(b) {
			return nil, io.ErrUnexpectedEOF
		}
		j := i
		for i < len(b) && !IsSpace(b[i]) {
			i++
		}
		return b[j:i], nil
	}
	initial := func() ([]byte, error) {
		io.Copy(buf, r)
		b = buf.Bytes()
		nextToken = rest
		return rest()
	}
	nextToken = initial

	restLn := func() ([]byte, error) {
		for i < len(b) && IsNewLine(b[i]) {
			i++
		}
		if i == len(b) {
			return nil, io.ErrUnexpectedEOF
		}
		j := i
		for i < len(b) && !IsNewLine(b[i]) {
			i++
		}
		return b[j:i], nil
	}

	initialLn := func() ([]byte, error) {
		io.Copy(buf, r)
		b = buf.Bytes()
		nextLine = restLn
		return restLn()
	}
	nextLine = initialLn
}

// Setup nextToken without input buffer.
func SetUnbefferedInput(r io.Reader) {
	buf := bufio.NewReader(r)
	var b []byte

	var i int
	nextToken = func() ([]byte, error) {
		var err error
		if i == len(b) {
			b, err = buf.ReadBytes('\n')
			if err != nil {
				return nil, err
			}
			i = 0
			j := len(b) - 1
			for 0 <= j && IsSpace(b[j]) {
				j--
			}
			b = b[0 : j+1]
		}
		for i < len(b) && IsSpace(b[i]) {
			i++
		}
		j := i
		for i < len(b) && !IsSpace(b[i]) {
			i++
		}
		if i == j {
			return nil, io.ErrUnexpectedEOF
		}
		return b[j:i], nil
	}
}

// -----------------------------------------------------------------------------

// IO functions

// Reads next token and return it as []byte
func readb() []byte {
	b, err := nextToken()
	if err != nil {
		panic(err)
	}
	return b
}

// Reads next token and return it as string
func reads() string {
	return string(readb())
}

// Read next line as []byte
func readbln() []byte {
	b, err := nextLine()
	if err != nil {
		panic(err)
	}
	return b
}

// Read next line as string
func readsln() string {
	return string(readbln())
}

// Reads next token and return it as int64
func readll() int64 {
	i, err := strconv.ParseInt(reads(), 10, 64)
	if err != nil {
		panic(err.Error())
	}
	return i
}

// Reads next token and return it as int
func readi() int {
	return int(readll())
}

// Reads next token and return it as float64
func readf() float64 {
	f, err := strconv.ParseFloat(reads(), 64)
	if err != nil {
		panic(err.Error())
	}
	return f
}

// Write args to OutputWriter with the format f
func printf(f string, args ...interface{}) (int, error) {
	return fmt.Fprintf(OutputWriter, f, args...)
}

// Write args to OutputWriter without format
func println(args ...interface{}) (int, error) {
	return fmt.Fprintln(OutputWriter, args...)
}

// Write args to stderr with the format f
func eprintf(f string, args ...interface{}) (int, error) {
	return fmt.Fprintf(os.Stderr, f, args...)
}

// Write args to stderr without format
func eprintln(args ...interface{}) (int, error) {
	return fmt.Fprintln(os.Stderr, args...)
}

// -----------------------------------------------------------------------------

// Simple math functions

const (
	// big prime
	INF  = 1000000007
	INF2 = 1000000009
	INF3 = 998244353
)

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

func minll(a, b int64) int64 {
	if a < b {
		return a
	}
	return b
}

func max(a, b int) int {
	if a < b {
		return b
	}
	return a
}

func maxll(a, b int64) int64 {
	if a < b {
		return b
	}
	return a
}

func abs(a int) int {
	if a < 0 {
		return -a
	}
	return a
}

func absll(a int64) int64 {
	if a < 0 {
		return -a
	}
	return a
}

// egcd(a, b) returns d, x, y:
//   d is gcd(a,b)
//   x, y are  integers that satisfy ax + by = d
func egcd(a, b int) (int, int, int) {
	if b == 0 {
		return a, 1, 0
	}
	d, x, y := egcd(b, a%b)
	return d, y, x - a/b*y
}

func egcdll(a, b int64) (int64, int64, int64) {
	if b == 0 {
		return a, 1, 0
	}
	d, x, y := egcdll(b, a%b)
	return d, y, x - a/b*y
}

func gcd(a, b int) int {
	d, _, _ := egcd(a, b)
	return d
}

func gcdll(a, b int64) int64 {
	d, _, _ := egcdll(a, b)
	return d
}

// set up IO functions
func init() {
	// for non-interactive
	SetInput(os.Stdin)
	SetOutput(os.Stdout)

	// Enable below when interactive.  Its ok to leave above intact.
	// SetInteractive(os.Stdout, os.Stdin)
}

func main() {
	defer Flush()

	A := readi()
	B := readi()
	d := gcd(A, B)
	if d == 1 {
		println(1)
		return
	}

	p := NewPrimes(d + 1)
	println(len(p.Factorize(d)) + 1)

}

type Primes struct {
	p []bool
	d []int
}

func NewPrimes(n int) Primes {
	m := n + 1
	p := Primes{
		p: make([]bool, m),
		d: make([]int, m),
	}
	p.d[1] = 1
	for i := 3; i < m; i += 2 {
		p.p[i] = true
		p.d[i-1] = 2
	}
	if n%2 == 0 {
		p.d[n] = 2
	}
	p.p[2] = true
	i := 3
	for ; i*i < m; i += 2 {
		if !p.p[i] {
			continue
		}
		p.d[i] = i
		for j := i * i; j < m; j += i {
			p.p[j] = false
			if p.d[j] == 0 {
				p.d[j] = i
			}
		}
	}

	for i = i - 2; i < m; i += 2 {
		if p.d[i] == 0 {
			p.d[i] = i
		}
	}

	return p
}

func (ps Primes) IsPrime(x int) bool {
	return ps.p[x]
}

func (ps Primes) Divisor(x int) int {
	return ps.d[x]
}

func (ps Primes) Factorize(x int) [][2]int {
	res := make([][2]int, 0)
	if x == 1 {
		res = append(res, [2]int{1, 1})
		return res
	}
	v := x
	for v != 1 {
		d := ps.d[v]
		if d == x {
			break
		}
		if 0 < len(res) && res[len(res)-1][0] == d {
			res[len(res)-1][1]++
		} else {
			res = append(res, [2]int{d, 1})
		}
		v /= d
	}
	return res
}

func (ps Primes) FactorizeMap(x int) map[int]int {
	m := make(map[int]int)
	for _, f := range ps.Factorize(x) {
		m[f[0]] = f[1]
	}
	return m
}

// newFactorial(n, p int) returns 2 functions.
// 1. factorial(x int) int: returns factorial x modulo p (0 <= x <= n)
// 2. combination(x, r int int: returns xCr modulo p (1 <= r <= x <= n)
func newFactorial(n, p int) (factorial func(int) int, combination func(int, int) int) {
	if n < 1 {
		panic("newFactorial: n must be more than 0")
	}

	fact := make([]int, n+1)
	fact[1] = 1
	for i := 2; i <= n; i++ {
		fact[i] = mul(fact[i-1], i, p)
	}

	ifact := make([]int, n+1)
	ifact[n] = inv(fact[n], p)
	for i := n - 1; 0 <= i; i-- {
		ifact[i] = mul(ifact[i+1], i+1, p)
	}

	factorial = func(i int) int {
		return fact[i]
	}
	combination = func(n, r int) int {
		return mul3(fact[n], ifact[n-r], ifact[r], p)
	}
	return
}

func mul(a, b, p int) int {
	return int(int64(a) * int64(b) % int64(p))
}

func mul3(a, b, c, p int) int {
	return int(int64(a) * int64(b) % int64(p) * int64(c) % int64(p))
}

func mulm(a, b int, rest ...int) int {
	n := len(rest) - 1
	p := int64(rest[n])
	rest = rest[:n]
	res := int64(a) * int64(b) % p
	for _, v := range rest {
		res = res * int64(v) % p
	}

	return int(res)
}

func div(n, d, p int) int {
	return mul(n, inv(d, p), p)
}

func inv(a, p int) int {
	return exp(a, p-2, p)
}

func exp(n, e, p int) int {
	if e == 0 {
		return 1
	}
	if e&1 == 1 {
		return mul(n, exp(n, e-1, p), p)
	} else {
		return square(exp(n, e/2, p), p)
	}
}

func square(a, p int) int {
	return mul(a, a, p)
}

Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.

Submitted source-code file size, in bytes.

Execution CPU time reported by official Project CodeNet metadata, in milliseconds.

Peak memory usage reported by official Project CodeNet metadata, in kilobytes.


package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var sc *bufio.Scanner = func() *bufio.Scanner {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)
	return sc
}()

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func calcGcd(l, r int) int {
	if r > l {
		r, l = l, r
	}

	d := l % r
	for d != 0 {
		l = r
		r = d
		d = l % r
	}
	return r
}

func calcDsOCd(l, r int) int {
	gcd := calcGcd(l, r)
	primes := []int{1}

	for i := 2; i <= gcd; i++ {
		isDivid := false
		for gcd%i == 0 {
			gcd = gcd / i
			isDivid = true
		}
		if isDivid {
			primes = append(primes, i)
		}
	}
	return len(primes)
}

func main() {
	l, r := nextInt(), nextInt()
	result := calcDsOCd(l, r)
	fmt.Println(result)
}


package main

import (
	"errors"
	"fmt"
	"math"
)

type int int64

func main() {

	var A,B int
	fmt.Scan(&A,&B)

	var gcd int
	gcd, _ = GCD(A,B)

	var ans []int
	ans = PrimeFactors(gcd)

	fmt.Println(len(ans) + 1)

}

func GCD(a, b int) (int, error) {
	ret := int(-1)

	var n int
	for n = 1; n*n <= a; n++ {
		if a%n == 0 {
			if b%n == 0 {
				ret = int(math.Max(float64(n), float64(ret)))
			}

			t := a / n
			if b%t == 0 {
				ret = int(math.Max(float64(t), float64(ret)))
			}
		}
	}

	if ret == -1 {
		return ret, errors.New("empty!")
	} else {
		return ret, nil
	}
}

func PrimeFactors(n int) (pfs []int) {
	// Get the number of 2s that divide n
	for n%2 == 0 {
		pfs = append(pfs, 2)
		n = n / 2
	}

	// n must be odd at this point. so we can skip one element
	// (note i = i + 2)
	var i int
	for i = 3; i*i <= n; i = i + 2 {
		// while i divides n, append i and divide n
		for n%i == 0 {
			pfs = append(pfs, i)
			n = n / i
		}
	}

	// This condition is to handle the case when n is a prime number
	// greater than 2
	if n > 2 {
		pfs = append(pfs, n)
	}

	return
}


package main

import (
  "bufio"
  "os"
  "strconv"
  "strings"
  "fmt"
)

var reader = bufio.NewReaderSize(os.Stdin, 1000000)
var writer = bufio.NewWriter(os.Stdout)
func NextLine() string {
  var line, buffer []byte
  var isPrefix bool = true
  var err error
  for isPrefix {
    line, isPrefix, err = reader.ReadLine()
    if err != nil { panic(err) }
    buffer = append(buffer, line...)
  }
  return string(buffer)
}
func NextIntVec() []int {
  L := strings.Split(NextLine(), " ")
  N := make([]int, len(L))
  for i := range N {
    N[i], _ = strconv.Atoi(L[i])
  }
  return N
}
func Write(s interface{}) {
  fmt.Fprintln(writer, s)
}
func Output() {
  _ = writer.Flush()
}

func gcd(a, b int) int {
    if b == 0 {
        return a
    }
    return gcd(b, a%b)
}

func primeSet(n int) []int {
  if n == 1 { return []int{} }
  for i := 2; i * i < n; i++ {
    if n % i > 0 { continue }
    P := append([]int{i}, primeSet(n / i)...)
    if len(P) > 1 && P[0] == P[1] {
      return P[1:]
    }
    return P
  }
  return []int{n}
}

func main() {
  AB := NextIntVec()
  GCD := gcd(AB[0], AB[1])
  Write(len(primeSet(GCD)) + 1)
  Output()
}


package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

var scanner = bufio.NewScanner(os.Stdin)

func scanInt() int {
	scanner.Scan()
	a, err := strconv.Atoi(scanner.Text())
	if err != nil {
		fmt.Println(err)
	}
	return a
}

func powUInt2(n int) uint {
	ret := uint(1)
	for i := 0; i < n; i++ {
		ret *= 2
	}
	return ret
}

func main() {
	scanner.Split(bufio.ScanWords)

	n := scanInt()
	m := scanInt()

	a := make([]int, m)
	b := make([]uint, m)
	for i := 0; i < m; i++ {
		a[i] = scanInt()
		nb := scanInt()
		for j := 0; j < nb; j++ {
			b[i] |= powUInt2(scanInt() - 1)
		}
	}

	bMaskMap := map[uint]uint{}
	bMaskMap[0] = uint(0)
	for i := 1; i <= n; i++ {
		for j := powUInt2(i - 1); j < powUInt2(i); j++ {
			bMaskMap[j] = powUInt2(i) - 1
		}
	}

	dp := make([][]int, m+1)
	for i := range dp {
		dp[i] = make([]int, powUInt2(n))
	}

	dp[0][0] = 0
	for i := 1; i < int(powUInt2(n)); i++ {
		dp[0][i] = math.MaxInt32
	}

	for i := 0; i < m; i++ {
		for j := uint(0); j < powUInt2(n); j++ {

			l := dp[i][j^(bMaskMap[j]&b[i])] + a[i]
			r := dp[i][j]
			if l > r {
				dp[i+1][j] = r
			} else {
				dp[i+1][j] = l
			}
		}
	}
	if dp[m][powUInt2(n)-1] == math.MaxInt32 {
		fmt.Println(-1)
	} else {
		fmt.Println(dp[m][int(powUInt2(n))-1])
	}
}

Score : 500 points

Problem Statement

We have N locked treasure boxes, numbered 1 to N.

A shop sells M keys. The i-th key is sold for a_i yen (the currency of Japan), and it can unlock b_i of the boxes: Box c_{i1}, c_{i2}, ..., c_{i{b_i}}. Each key purchased can be used any number of times.

Find the minimum cost required to unlock all the treasure boxes. If it is impossible to unlock all of them, print -1.

Constraints

All values in input are integers.

1 \leq N \leq 12

1 \leq M \leq 10^3

1 \leq a_i \leq 10^5

1 \leq b_i \leq N

1 \leq c_{i1} < c_{i2} < ... < c_{i{b_i}} \leq N

Input

Input is given from Standard Input in the following format:

N M
a_1 b_1
c_{11} c_{12} ... c_{1{b_1}}
:
a_M b_M
c_{M1} c_{M2} ... c_{M{b_M}}

Output

Print the minimum cost required to unlock all the treasure boxes.
If it is impossible to unlock all of them, print -1.

Sample Input 1

2 3
10 1
1
15 1
2
30 2
1 2

Sample Output 1

25

We can unlock all the boxes by purchasing the first and second keys, at the cost of 25 yen, which is the minimum cost required.

Sample Input 2

12 1
100000 1
2

Sample Output 2

-1

We cannot unlock all the boxes.

Sample Input 3

4 6
67786 3
1 3 4
3497 1
2
44908 3
2 3 4
2156 3
2 3 4
26230 1
2
86918 1
3

Sample Output 3

69942


package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

type key struct {
	a int
	c int
}

const inf = 1 << 60

func main() {
	n, m := getInt(), getInt()
	ks := make([]key, m)
	for i := range ks {
		ks[i].a = getInt()

		b := getInt()
		for j := 0; j < b; j++ {
			tmp := uint(getInt()) - 1
			ks[i].c += 1 << tmp
		}
	}

	if !checker(ks, n) {
		fmt.Println(-1)
		return
	}

	dp := make([]int, (1 << uint(n)))
	for i := range dp {
		dp[i] = inf
	}
	dp[0] = 0

	for _, k := range ks {
		dp[k.c] = min(dp[k.c], k.a)
		for j := range dp {
			dp[k.c|j] = min(dp[k.c|j], dp[k.c]+dp[j])
		}
	}

	fmt.Println(dp[(1<<uint(n))-1])
}

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

func checker(ks []key, n int) bool {
	m := 0
	for _, k := range ks {
		m |= k.c
	}

	if n > m {
		return false
	}
	return true
}

// -----------------------------------------

var sc = bufio.NewScanner(os.Stdin)

func init() {
	// buf := 200001
	// sc.Buffer(make([]byte, buf), buf)
	sc.Split(bufio.ScanWords)
}

func getInt() int {
	i, err := strconv.Atoi(getString())
	if err != nil {
		panic(err)
	}
	return i
}

func getString() string {
	sc.Scan()
	s := sc.Text()
	return s
}


package main

import (
	"bufio"
	"bytes"
	"fmt"
	"io"
	"os"
	"strconv"
)

// -----------------------------------------------------------------------------

// IO helper functions

// Returns next token from input.  It must be initialized by SetInput()
// before the first call.
var nextToken func() ([]byte, error)

// Holds a buffer for output.  It must be initialized by SetOutput().
// All IO fucntions (read*() and [e]print*()) should write to OutputWriter
// instead of this.
var OutputBuffer *bufio.Writer

// Holds an io.Writer.  It must be initialized by SetOutput()
var OutputWriter io.Writer

// Set IO functions for interactive input/output.
func SetInteractive(w io.Writer, r io.Reader) {
	SetUnbefferedInput(r)
	OutputBuffer = nil
	OutputWriter = w
}

// Setup OutputBuffer and OutputWriter.
func SetOutput(w io.Writer) {
	OutputBuffer = bufio.NewWriter(w)
	OutputWriter = OutputBuffer
}

// Flushes OutputBuffer
func Flush() {
	if OutputBuffer != nil {
		OutputBuffer.Flush()
	}
}

// Returns true if c is a white space
func IsSpace(c byte) bool {
	switch c {
	case '\t', '\n', '\v', '\f', '\r', ' ':
		return true
	}
	return false
}

// Setup nextToken with input buffer.
func SetInput(r io.Reader) {
	buf := new(bytes.Buffer)
	var b []byte

	var i int
	rest := func() ([]byte, error) {
		for i < len(b) && IsSpace(b[i]) {
			i++
		}
		j := i
		for i < len(b) && !IsSpace(b[i]) {
			i++
		}
		if i == j {
			return nil, io.ErrUnexpectedEOF
		}
		return b[j:i], nil
	}
	initial := func() ([]byte, error) {
		io.Copy(buf, r)
		b = buf.Bytes()
		nextToken = rest
		return rest()
	}
	nextToken = initial
}

// Setup nextToken without input buffer.
func SetUnbefferedInput(r io.Reader) {
	buf := bufio.NewReader(r)
	var b []byte

	var i int
	nextToken = func() ([]byte, error) {
		var err error
		if i == len(b) {
			b, err = buf.ReadBytes('\n')
			if err != nil {
				return nil, err
			}
			i = 0
			j := len(b) - 1
			for 0 <= j && IsSpace(b[j]) {
				j--
			}
			b = b[0 : j+1]
		}
		for i < len(b) && IsSpace(b[i]) {
			i++
		}
		j := i
		for i < len(b) && !IsSpace(b[i]) {
			i++
		}
		if i == j {
			return nil, io.ErrUnexpectedEOF
		}
		return b[j:i], nil
	}
}

// -----------------------------------------------------------------------------

// IO functions

// Reads next token and return it as []byte
func readb() []byte {
	b, err := nextToken()
	if err != nil {
		panic(err)
	}
	return b
}

// Reads next token and return it as string
func reads() string {
	return string(readb())
}

// Reads next token and return it as int64
func readll() int64 {
	i, err := strconv.ParseInt(reads(), 10, 64)
	if err != nil {
		panic(err.Error())
	}
	return i
}

// Reads next token and return it as int
func readi() int {
	return int(readll())
}

// Reads next token and return it as float64
func readf() float64 {
	f, err := strconv.ParseFloat(reads(), 64)
	if err != nil {
		panic(err.Error())
	}
	return f
}

// Write args to OutputWriter with the format f
func printf(f string, args ...interface{}) (int, error) {
	return fmt.Fprintf(OutputWriter, f, args...)
}

// Write args to OutputWriter without format
func println(args ...interface{}) (int, error) {
	return fmt.Fprintln(OutputWriter, args...)
}

// Write args to stderr with the format f
func eprintf(f string, args ...interface{}) (int, error) {
	return fmt.Fprintf(os.Stderr, f, args...)
}

// Write args to stderr without format
func eprintln(args ...interface{}) (int, error) {
	return fmt.Fprintln(os.Stderr, args...)
}

// -----------------------------------------------------------------------------

// Simple math functions

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

func min64(a, b int64) int64 {
	if a < b {
		return a
	}
	return b
}

func max(a, b int) int {
	if a < b {
		return b
	}
	return a
}

func max64(a, b int64) int64 {
	if a < b {
		return b
	}
	return a
}

func abs(a int) int {
	if a < 0 {
		return -a
	}
	return a
}

func abs64(a int64) int64 {
	if a < 0 {
		return -a
	}
	return a
}

func gcd(a, b int) int {
	if b == 0 {
		return a
	}
	return gcd(b, a%b)
}

func gcd64(a, b int64) int64 {
	if b == 0 {
		return a
	}
	return gcd64(b, a%b)
}

// set up IO functions
func init() {
	// for non-interactive
	SetInput(os.Stdin)
	SetOutput(os.Stdout)

	// Enable below when interactive.  Its ok to leave above intact.
	// SetInteractive(os.Stdout, os.Stdin)
}

func main() {
	defer Flush()
	H := readi()
	W := readi()
	A := readi()
	B := readi()

	f := make([][]int, H)
	for i := range f {
		f[i] = make([]int, W)
	}

	solve(f, A, B)
	//for i := range f {
	//	eprintln(f[i])
	//}

	if !check(f, A, B) {
		println("No")
		return
	}
	for i := range f {
		for j := range f[i] {
			printf("%d", f[i][j])
		}
		println()
	}

}

func solve(f [][]int, A, B int) {
	H := len(f)
	W := len(f[0])
	if A == 0 {
		A = len(f[0])
	}
	if B == 0 {
		B = len(f)
	}
	//eprintln(H, W, A, B)
	for i, j := 0, 0; i < H && j < W; i, j = i+B, j+A {
		for k := i; k < H && k < i+B; k++ {
			for l := j; l < W && l < j+A; l++ {
				f[k][l] = 1
			}
		}
	}
}

func check(f [][]int, A, B int) bool {
	H := len(f)
	W := len(f[0])
	for i := range f {
		var count int
		for j := range f[i] {
			if f[i][j] == 1 {
				count++
			}
		}
		if min(count, W-count) != A {
			return false
		}
	}
	for j := range f[0] {
		var count int
		for i := range f {
			if f[i][j] == 1 {
				count++
			}
		}
		if min(count, H-count) != B {
			return false
		}
	}
	return true
}

Score : 300 points

Problem Statement

We have a square grid with H rows and W columns.
Snuke wants to write 0 or 1 in each of the squares.
Here, all of the following conditions have to be satisfied:

For every row, the smaller of the following is A: the number of 0s contained in the row, and the number of 1s contained in the row. (If these two numbers are equal, “the smaller” should be read as “either”.)

For every column, the smaller of the following is B: the number of 0s contained in the column, and the number of 1s contained in the column.

Determine if these conditions can be satisfied by writing 0 or 1 in each of the squares. If the answer is yes, show one way to fill the squares so that the conditions are satisfied.

Constraints

1 \leq H,W \leq 1000

0 \leq A

2 \times A \leq W

0 \leq B

2 \times B \leq H

All values in input are integers.

Input

Input is given from Standard Input in the following format:

H W A B

Output

If the conditions cannot be satisfied by writing 0 or 1 in each of the squares, print -1.

If the conditions can be satisfied, print one way to fill the squares so that the conditions are satisfied, in the following format:

s_{11}s_{12}\cdots s_{1W}
s_{21}s_{22}\cdots s_{2W}
\vdots
s_{H1}s_{H2}\cdots s_{HW}

Here s_{ij} is the digit written in the square at the i-th row from the top and the j-th column from the left in the grid.

If multiple solutions exist, printing any of them will be accepted.

Sample Input 1

3 3 1 1

Sample Output 1

100
010
001

Every row contains two 0s and one 1, so the first condition is satisfied.
Also, every column contains two 0s and one 1, so the second condition is satisfied.

Sample Input 2

1 5 2 0

Sample Output 2

01010


package main

import (
	"fmt"
)

var weathers []string = []string{"Sunny", "Cloudy", "Rainy"}

func main() {
	var in string
	fmt.Scanf("%s", &in)

	for i := 0; i < len(weathers); i++ {
		if weathers[i] == in {
			fmt.Printf("%s\n", weathers[(i+1)%len(weathers)])
		}
	}
}

Score: 100 points

Problem Statement

The weather in Takahashi's town changes day by day, in the following cycle: Sunny, Cloudy, Rainy, Sunny, Cloudy, Rainy, ...

Given is a string S representing the weather in the town today. Predict the weather tomorrow.

Constraints

S is Sunny, Cloudy, or Rainy.

Input

Input is given from Standard Input in the following format:

S

Output

Print a string representing the expected weather tomorrow, in the same format in which input is given.

Sample Input 1

Sunny

Sample Output 1

Cloudy

In Takahashi's town, a sunny day is followed by a cloudy day.

Sample Input 2

Rainy

Sample Output 2

Sunny


package main

import (
        "errors"
        "fmt"
        "strings"
)

func isTapDanceEasy(s string) bool {
        if len(s) >= 1 && len(s) <= 100 {
                odds := make([]string, 0)
                evens := make([]string, 0)
                sl := strings.Split(s, "")

                for i, char := range sl {
                        if (i+1)%2 == 0 {
                                evens = append(evens, char)
                                continue
                        }
                        odds = append(odds, char)
                }
                odd := strings.Join(odds, "")
                even := strings.Join(evens, "")
                if strings.Contains(odd, "L") || strings.Contains(even, "R") {
                        return false
                }
                return true
        }
        panic(errors.New("No solution"))
}

func main() {
        var s string
        fmt.Scan(&s)
        if isTapDanceEasy(s) {
                fmt.Println("Yes")
        }
        fmt.Println("No")
}

Score: 200 points

Problem Statement

Takahashi will do a tap dance. The dance is described by a string S where each character is L, R, U, or D. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.

S is said to be easily playable if and only if it satisfies both of the following conditions:

Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is R, U, or D.

Every character in an even position (2-nd, 4-th, 6-th, \ldots) is L, U, or D.

Your task is to print Yes if S is easily playable, and No otherwise.

Constraints

S is a string of length between 1 and 100 (inclusive).

Each character of S is L, R, U, or D.

Input

Input is given from Standard Input in the following format:

S

Output

Print Yes if S is easily playable, and No otherwise.

Sample Input 1

RUDLUDR

Sample Output 1

Yes

Every character in an odd position (1-st, 3-rd, 5-th, 7-th) is R, U, or D.

Every character in an even position (2-nd, 4-th, 6-th) is L, U, or D.

Thus, S is easily playable.

Sample Input 2

DULL

Sample Output 2

No

The 3-rd character is not R, U, nor D, so S is not easily playable.

Sample Input 3

UUUUUUUUUUUUUUU

Sample Output 3

Yes

Sample Input 4

ULURU

Sample Output 4

No

Sample Input 5

RDULULDURURLRDULRLR

Sample Output 5

Yes


package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func main() {
	scanner := bufio.NewScanner(os.Stdin)
	scanner.Split(bufio.ScanLines)
	var n, k, q int
	_, _ = fmt.Scan(&n, &k, &q)

	scores := make([]int, n)

	for i, _ := range scores {
		scores[i] = k
	}

	for i := 0; i < q; i++ {
		scanner.Scan()
		a, _ := strconv.Atoi(scanner.Text())
		for j, s := range scores {
			if a-1 != j {
				scores[j] = s - 1
			}
		}
	}

	for _, s := range scores {
		if s > 0 {
			fmt.Println("Yes")
		} else {
			fmt.Println("No")
		}
	}
}

Score: 300 points

Problem Statement

Takahashi has decided to hold fastest-finger-fast quiz games. Kizahashi, who is in charge of making the scoreboard, is struggling to write the program that manages the players' scores in a game, which proceeds as follows.

A game is played by N players, numbered 1 to N. At the beginning of a game, each player has K points.

When a player correctly answers a question, each of the other N-1 players receives minus one (-1) point. There is no other factor that affects the players' scores.

At the end of a game, the players with 0 points or lower are eliminated, and the remaining players survive.

In the last game, the players gave a total of Q correct answers, the i-th of which was given by Player A_i.
For Kizahashi, write a program that determines whether each of the N players survived this game.

Constraints

All values in input are integers.

2 \leq N \leq 10^5

1 \leq K \leq 10^9

1 \leq Q \leq 10^5

1 \leq A_i \leq N\ (1 \leq i \leq Q)

Input

Input is given from Standard Input in the following format:

N K Q
A_1
A_2
.
.
.
A_Q

Output

Print N lines. The i-th line should contain Yes if Player i survived the game, and No otherwise.

Sample Input 1

6 3 4
3
1
3
2

Sample Output 1

No
No
Yes
No
No
No

In the beginning, the players' scores are (3, 3, 3, 3, 3, 3).

Player 3 correctly answers a question. The players' scores are now (2, 2, 3, 2, 2, 2).

Player 1 correctly answers a question. The players' scores are now (2, 1, 2, 1, 1, 1).

Player 3 correctly answers a question. The players' scores are now (1, 0, 2, 0, 0, 0).

Player 2 correctly answers a question. The players' scores are now (0, 0, 1, -1, -1, -1).

Players 1, 2, 4, 5 and 6, who have 0 points or lower, are eliminated, and Player 3 survives this game.

Sample Input 2

6 5 4
3
1
3
2

Sample Output 2

Yes
Yes
Yes
Yes
Yes
Yes

Sample Input 3

10 13 15
3
1
4
1
5
9
2
6
5
3
5
8
9
7
9

Sample Output 3

No
No
No
No
Yes
No
No
No
Yes
No


package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

var sc = bufio.NewScanner(os.Stdin)

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func main() {
	sc.Split(bufio.ScanWords)
	n := nextInt()
	k := nextInt()
	q := nextInt()
	scores := make([]int, n)
	for i := 0; i < q; i++ {
		scores[nextInt()-1]++
	}
	for i := 0; i < n; i++ {
		if score := k - q + scores[i]; score > 0 {
			fmt.Println("Yes")
		} else {
			fmt.Println("No")
		}
	}
}


package main

import (
	"bufio"
	"fmt"
	basicIO "io"
	"os"
	"strconv"
)

func main() {
	protagonist(os.Stdin, os.Stdout)
}

func protagonist(r basicIO.Reader, w basicIO.Writer) {
	io := NewIO(r, w)
	N, _ := io.nextInt()
	K, _ := io.nextInt()
	Q, _ := io.nextInt()

	A := make([]int, N)

	for i := 0; i < Q; i++ {
		n, _ := io.nextInt()
		A[n-1]++
	}

	for _, val := range A {
		if (Q - val) < K {
			io.PutString("Yes")
		} else {
			io.PutString("No")
		}
	}
}

type IO struct {
	Scanner *bufio.Scanner
	Writer  basicIO.Writer
}

func NewIO(r basicIO.Reader, w basicIO.Writer) *IO {
	s := bufio.NewScanner(r)
	s.Split(bufio.ScanWords)
	return &IO{
		Scanner: s,
		Writer:  w,
	}
}

func (io *IO) nextString() string {
	io.Scanner.Scan()
	return io.Scanner.Text()
}

func (io *IO) nextInt() (int, error) {
	io.Scanner.Scan()
	i, err := strconv.Atoi(io.Scanner.Text())
	return i, err
}

func (io *IO) PutInt(v int) {
	fmt.Fprintf(io.Writer, "%d\n", v)
}

func (io *IO) PutString(s string) {
	fmt.Fprintf(io.Writer, "%s\n", s)
}


package main

import (
	"fmt"
)

func main() {

	var N int
	fmt.Scanf("%d", &N)

	fmt.Println(N * N * N)
}

Score : 100 points

Problem Statement

Takahashi is going to set a 3-character password.

How many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?

Constraints

1 \leq N \leq 9

N is an integer.

Input

Input is given from Standard Input in the following format:

N

Output

Print the number of possible passwords.

Sample Input 1

2

Sample Output 1

8

There are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.

Sample Input 2

1

Sample Output 2

1

There is only one possible password if you can only use one kind of character.


package main

import (
	"fmt"
)

func main() {
	var n int
	fmt.Scan(&n)
	fmt.Println(n * n * n)
}

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

func max(a, b int) int {
	if a > b {
		return a
	}
	return b
}

func abs(a int) int {
	if a < 0 {
		return -a
	}
	return a
}


package main

import "fmt"

func main() {
	var n int
	fmt.Scan(&n)
	fmt.Println(n * n * n)
}


package main

import (
	"fmt"
	"math"
)

func main() {
	var N int
	fmt.Scan(&N)
	fmt.Println(math.Pow(float64(N), float64(3)))

}


package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

const pi = math.Pi

var mod int = pow(10, 9) + 7
var Umod uint64 = 1000000007
var ans, cnt, sum int

func main() {
	reader.Split(bufio.ScanWords)
	N, _ := strconv.Atoi(read())
	fmt.Println(pow(N, 3))
}

/*  ----------------------------------------  */

var reader = bufio.NewScanner(os.Stdin)

func read() string {
	reader.Scan()
	return reader.Text()
}

func lcm(x, y int) int {
	return (x / gcd(x, y)) * y
}

func gcd(x, y int) int {
	if x%y == 0 {
		return y
	} else {
		r := x % y
		return gcd(y, r)
	}
}

var fac [1000000]int
var finv [1000000]int
var inv [1000000]int

func combination_init() {
	fac[0], fac[1] = 1, 1
	finv[0], finv[1] = 1, 1
	inv[1] = 1

	// invは a^(-1) mod p
	// pをaで割ることを考える

	// p/a*(a) + p%a = p
	// p/a*(a) + p%a = 0          (mod p)
	// -p%a = p/a*(a)             (mod p)
	// -p%a *a^(-1)= p/a          (mod p)
	// a^(-1)= p/a * (-p%a)^(-1)  (mod p)
	// a^(-1) =

	for i := 2; i < 1000000; i++ {
		fac[i] = fac[i-1] * i % mod
		inv[i] = mod - inv[mod%i]*(mod/i)%mod
		finv[i] = finv[i-1] * inv[i] % mod
	}
}

func combination(x, y int) int {
	if x < y {
		return 0
	}
	if fac[0] != 1 {
		combination_init()
	}
	return fac[x] * (finv[y] * finv[x-y] % mod) % mod
	//return fac[x] / (fac[y] * fac[x-y])
}

func permutation(x, y int) int {
	if x < y {
		return 0
	}
	if fac[0] != 1 {
		combination_init()
	}
	return fac[x] * (finv[x-y] % mod) % mod
	//return fac[x] / fac[x-y]
}

func max(x ...int) int {
	var res int = x[0]
	for i := 1; i < len(x); i++ {
		res = int(math.Max(float64(x[i]), float64(res)))
	}
	return res
}

func min(x ...int) int {
	var res int = x[0]
	for i := 1; i < len(x); i++ {
		res = int(math.Min(float64(x[i]), float64(res)))
	}
	return res
}
func pow(x, y int) int { return int(math.Pow(float64(x), float64(y))) }
func abs(x int) int    { return int(math.Abs(float64(x))) }
func floor(x int) int  { return int(math.Floor(float64(x))) }
func ceil(x int) int   { return int(math.Ceil(float64(x))) }

type SortBy []int

func (a SortBy) Len() int           { return len(a) }
func (a SortBy) Swap(i, j int)      { a[i], a[j] = a[j], a[i] }
func (a SortBy) Less(i, j int) bool { return a[i] < a[j] }

type PriorityQueue []int

func (h PriorityQueue) Len() int            { return len(h) }
func (h PriorityQueue) Less(i, j int) bool  { return h[i] < h[j] }
func (h PriorityQueue) Swap(i, j int)       { h[i], h[j] = h[j], h[i] }
func (h *PriorityQueue) Push(x interface{}) { *h = append(*h, x.(int)) }
func (h *PriorityQueue) Pop() interface{} {
	old := *h
	n := len(old)
	x := old[n-1]
	*h = old[0 : n-1]
	return x
}


package main

import (
	"fmt"
)

func main() {
	var n int
	fmt.Scan(&n)

	a := make([]int,n)
	b := make([]int,n)
	c := make([]int,n-1)

	for i := 0; i < n; i++ {
		var val int
		fmt.Scan(&val)
		a[i] = val
	}

	for i := 0; i < n; i++ {
		var val int
		fmt.Scan(&val)
		b[i] = val
	}

	for i := 0; i < n - 1; i++ {
		var val int
		fmt.Scan(&val)
		c[i] = val
	}

	tmp := a[0]
	var ans int
	for i := 0; i < n; i++ {
		ans += b[a[i] - 1]
		if a[i] == tmp + 1 {
			ans += c[a[i] - 2]
		}
		tmp = a[i]
	}
	fmt.Println(ans)
}

Score : 200 points

Problem Statement

Takahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \ldots, Dish N) once.

The i-th dish (1 \leq i \leq N) he ate was Dish A_i.

When he eats Dish i (1 \leq i \leq N), he gains B_i satisfaction points.

Additionally, when he eats Dish i+1 just after eating Dish i (1 \leq i \leq N - 1), he gains C_i more satisfaction points.

Find the sum of the satisfaction points he gained.

Constraints

All values in input are integers.

2 \leq N \leq 20

1 \leq A_i \leq N

A_1, A_2, ..., A_N are all different.

1 \leq B_i \leq 50

1 \leq C_i \leq 50

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 ... A_N
B_1 B_2 ... B_N
C_1 C_2 ... C_{N-1}

Output

Print the sum of the satisfaction points Takahashi gained, as an integer.

Sample Input 1

3
3 1 2
2 5 4
3 6

Sample Output 1

14

Takahashi gained 14 satisfaction points in total, as follows:

First, he ate Dish 3 and gained 4 satisfaction points.

Next, he ate Dish 1 and gained 2 satisfaction points.

Lastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.

Sample Input 2

4
2 3 4 1
13 5 8 24
45 9 15

Sample Output 2

74

Sample Input 3

2
1 2
50 50
50

Sample Output 3

150


package main

import (
	"bufio"
	"fmt"
	"io"
	"math"
	"os"
	"strconv"
)

func main() {
	n := readInt()

	ans, pre := 0, math.MaxInt64
	for i := 0; i < n-1; i++ {
		cur := readInt()
		ans += min(cur, pre)
		pre = cur
	}
	ans += pre

	fmt.Println(ans)
}

// sort ------------------------------------------------------------

type xxx struct {
	x int
}

type sortArray []xxx

func (s sortArray) Len() int           { return len(s) }
func (s sortArray) Swap(i, j int)      { s[i], s[j] = s[j], s[i] }
func (s sortArray) Less(i, j int) bool { return s[i].x < s[j].x }

// -----------------------------------------------------------------

var (
	readString func() string
	readBytes  func() []byte
)

func init() {
	readString, readBytes = newReadString(os.Stdin)
}

func newReadString(ior io.Reader) (func() string, func() []byte) {
	r := bufio.NewScanner(ior)
	r.Buffer(make([]byte, 1024), int(1e+11))
	r.Split(bufio.ScanWords)

	f1 := func() string {
		if !r.Scan() {
			panic("Scan failed")
		}
		return r.Text()
	}
	f2 := func() []byte {
		if !r.Scan() {
			panic("Scan failed")
		}
		return r.Bytes()
	}
	return f1, f2
}

func readInt() int {
	return int(readInt64())
}

func readInt64() int64 {
	i, err := strconv.ParseInt(readString(), 10, 64)
	if err != nil {
		panic(err.Error())
	}
	return i
}

func readFloat64() float64 {
	f, err := strconv.ParseFloat(readString(), 64)
	if err != nil {
		panic(err.Error())
	}
	return f
}

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

func max(a, b int) int {
	if a > b {
		return a
	}
	return b
}

func abs(a int) int {
	if a < 0 {
		return -a
	}
	return a
}

func sum(a []int) int {
	var ret int
	for i := range a {
		ret += a[i]
	}
	return ret
}

func sumFloat64(a []float64) float64 {
	var ret float64
	for i := range a {
		ret += a[i]
	}
	return ret
}

func gcd(m, n int) int {
	for m%n != 0 {
		m, n = n, m%n
	}
	return n
}

func lcm(m, n int) int {
	return m / gcd(m, n) * n
}

Score : 300 points

Problem Statement

There is an integer sequence A of length N whose values are unknown.

Given is an integer sequence B of length N-1 which is known to satisfy the following:

B_i \geq \max(A_i, A_{i+1})

Find the maximum possible sum of the elements of A.

Constraints

All values in input are integers.

2 \leq N \leq 100

0 \leq B_i \leq 10^5

Input

Input is given from Standard Input in the following format:

N
B_1 B_2 ... B_{N-1}

Output

Print the maximum possible sum of the elements of A.

Sample Input 1

3
2 5

Sample Output 1

9

A can be, for example, ( 2 , 1 , 5 ), ( -1 , -2 , -3 ), or ( 2 , 2 , 5 ). Among those candidates, A = ( 2 , 2 , 5 ) has the maximum possible sum.

Sample Input 2

2
3

Sample Output 2

6

Sample Input 3

6
0 153 10 10 23

Sample Output 3

53


package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

var (
	sc = bufio.NewScanner(os.Stdin)
	mod int = 1e9 + 7
)

func init() {
	sc.Split(bufio.ScanWords)
}

func main() {
	n := getInt()

	var bs []int

	for i := 0; i < n-1; i++ {
		bs = append(bs, getInt())
	}

	var as []int
	as = append(as, bs[0])
	for i := 0; i < n-2; i++ {
		b1 := bs[i]
		b2 := bs[i+1]

		if b1 <= b2 {
			as = append(as, b1)
		} else {
			as = append(as, b2)
		}
	}
	as = append(as, bs[n-2])

	sum := 0
	for _, a := range as {
		sum += a
	}
	fmt.Println(sum)
}

func getInt() int {
	sc.Scan()
	str := sc.Text()
	value, _ := strconv.Atoi(str)
	return value
}

func getString() string {
	sc.Scan()
	return sc.Text()
}

func abs(a int) int {
	return int(math.Abs(float64(a)))
}

func pow(p, q int) int {
	return int(math.Pow(float64(p), float64(q)))
}

func min(nums ...int) int {
	if len(nums) == 0 {
		panic("funciton min() requires at least one argument.")
	}
	res := nums[0]
	for i := 0; i < len(nums); i++ {
		res = int(math.Min(float64(res), float64(nums[i])))
	}
	return res
}

func max(nums ...int) int {
	if len(nums) == 0 {
		panic("funciton max() requires at least one argument.")
	}
	res := nums[0]
	for i := 0; i < len(nums); i++ {
		res = int(math.Max(float64(res), float64(nums[i])))
	}
	return res
}

func strSearch(a []string, b string) bool {
	for i := 0; i < len(a); i++ {
		if a[i] == b {
			return true
		}
	}
	return false
}

func printIntArray(array []int) {
	strArray := fmt.Sprint(array)
	fmt.Println(strArray[1 : len(strArray) - 1])
}

func calcMod(x int) int {
	return x % mod
}


// https://atcoder.jp/contests/abc140/tasks/abc140_d

package main

import (
	"bufio"
	"bytes"
	"fmt"
	"os"
	"reflect"
	"runtime"
	"sort"
	"strconv"
	"strings"
)

// d: debug IO. it can print debug in test.
func solve(io *Io, d *Io) {
	_ = io.NextInt()
	K := io.NextInt()
	S := io.NextRunes()

	res := 0
	can := K

	switchedCt := 0

	curr := S[0]

	for i := 1; i < len(S); i++ {
		prev := curr
		curr = S[i]

		if prev == curr {
			res++
			continue
		}

		if prev != curr {
			switchedCt++
		}

		if switchedCt == 2 && can > 0 {
			switchedCt = 0
			res += 2
			can--
		}
	}

	if switchedCt == 1 && can > 0 {
		res++
	}

	io.Println(res)
}

func main() {
	io := NewIo()
	defer io.Flush()
	solve(io, nil)
}

/* IO Helpers */

// Io combines reader, writer, & tokens as the state when processing the input
type Io struct {
	reader    *bufio.Reader
	writer    *bufio.Writer
	tokens    []string
	nextToken int
}

// NewIo creates Io with Stdin & Stdout
func NewIo() *Io {
	return &Io{
		reader: bufio.NewReader(os.Stdin),
		writer: bufio.NewWriter(os.Stdout),
	}
}

// Flush calls the writer's Flush
func (io *Io) Flush() {
	io.writer.Flush()
}

// NextLine returns the string from reader.ReadLine()
func (io *Io) NextLine() string {
	if io.nextToken < len(io.tokens) {
		panic("io.nextToken < len(io.tokens)")
	}

	var buffer bytes.Buffer

	for {
		line, isPrefix, err := io.reader.ReadLine()
		if err != nil {
			panic(err)
		}
		buffer.Write(line)
		if !isPrefix {
			break
		}
	}

	return buffer.String()
}

// NextLines returns []string from next n lines
func (io *Io) NextLines(n int) []string {
	res := make([]string, n)
	for i := 0; i < n; i++ {
		res[i] = io.NextLine()
	}
	return res
}

// Next returns the string token (partial string of the line divided by spaces)
func (io *Io) Next() string {
	if io.nextToken >= len(io.tokens) {
		line := io.NextLine()
		io.tokens = strings.Fields(line)
		io.nextToken = 0
	}

	res := io.tokens[io.nextToken]
	io.nextToken++
	return res
}

// NextStrings returns the []string from the next n tokens
func (io *Io) NextStrings(n int) []string {
	res := make([]string, n)
	for i := 0; i < n; i++ {
		res[i] = io.Next()
	}
	return res
}

// NextRunes returns next string as []rune
func (io *Io) NextRunes() []rune {
	return []rune(io.Next())
}

// NextInt returns the int from the next token
func (io *Io) NextInt() int {
	res, err := strconv.Atoi(io.Next())
	if err != nil {
		panic(err)
	}
	return res
}

// NextInts returns the []int from the next n tokens
func (io *Io) NextInts(n int) []int {
	res := make([]int, n)
	for i := 0; i < n; i++ {
		res[i] = io.NextInt()
	}
	return res
}

// NextFloat returns the float64 from the next token
func (io *Io) NextFloat() float64 {
	res, err := strconv.ParseFloat(io.Next(), 64)
	if err != nil {
		panic(err)
	}
	return res
}

// NextFloats returns the []float64 from the next n tokens
func (io *Io) NextFloats(n int) []float64 {
	res := make([]float64, n)
	for i := 0; i < n; i++ {
		res[i] = io.NextFloat()
	}
	return res
}

// Println prints the input to the writer in an easy-to-see form
func (io *Io) Println(a ...interface{}) {
	var values []string
	for i := 0; i < len(a); i++ {
		values = append(values, "%v")
	}
	io.Printfln(strings.Join(values, " "), a...)
}

// Print calls Fprint to the writer
func (io *Io) Print(a interface{}) {
	fmt.Fprint(io.writer, a)
}

// Printf calls Fprintf to the writer
func (io *Io) Printf(format string, a ...interface{}) {
	fmt.Fprintf(io.writer, format, a...)
}

// Printfln calls Fprint to the writer
func (io *Io) Printfln(format string, a ...interface{}) {
	fmt.Fprintf(io.writer, format+"\n", a...)
}

// PrintInts prints ints with space and new line at the end
func (io *Io) PrintInts(ints []int) {
	for i, e := range ints {
		io.Print(e)

		if i == len(ints)-1 {
			io.Println()
		} else {
			io.Print(" ")
		}
	}
}

// Debug calls Println and Flush immediately
func (io *Io) Debug(a ...interface{}) {
	if io == nil {
		return
	}

	io.Println(a...)
	io.Flush()
}

// Assert checks the value equality for debug
func (io *Io) Assert(a, b interface{}) {
	if io == nil {
		return
	}

	if !reflect.DeepEqual(a, b) {
		_, _, line, _ := runtime.Caller(1)
		io.Debug("Diff:", line, "\na:", a, "\nb:", b)
	}
}

/* Math Helpers */

// MOD is 10^9 + 7
const MOD = 1000000007

// Max of the ints
func Max(numbers ...int) int {
	max := numbers[0]
	for i, number := range numbers {
		if i == 0 {
			continue
		}
		if number > max {
			max = number
		}
	}
	return max
}

// Min of the ints
func Min(numbers ...int) int {
	min := numbers[0]
	for i, number := range numbers {
		if i == 0 {
			continue
		}
		if min > number {
			min = number
		}
	}
	return min
}

// Sum of the ints
func Sum(numbers ...int) int {
	sum := 0

	for _, number := range numbers {
		sum += number
	}

	return sum
}

// Pow calculates the pow for int with O(log e)
func Pow(a, e int) int {
	if a < 0 || e < 0 {
		panic(fmt.Sprintf("Pow was called for a < 0 or e < 0, a: %d, e: %d", a, e))
	}

	if e == 0 {
		return 1
	}

	if e%2 == 0 {
		half := Pow(a, e/2)
		return half * half
	}

	return a * Pow(a, e-1)
}

// Abs returns the absolute value of the input
func Abs(a int) int {
	if a < 0 {
		return -a
	}

	return a
}

/* Structure Helpers */

// Set is orderless List
type Set map[interface{}]struct{}

// NewSet returns empty Set
func NewSet() *Set {
	return &Set{}
}

// Add the value to the set
func (set *Set) Add(value interface{}) {
	(*set)[value] = struct{}{}
}

// Includes check the set has the value
func (set *Set) Includes(value interface{}) bool {
	_, included := (*set)[value]
	return included
}

// Remove deletes the value from the set if exists
func (set *Set) Remove(value interface{}) {
	if !set.Includes(value) {
		return
	}

	delete(*set, value)
}

// ImmutableSort returns sorted slice without mutating original one
func ImmutableSort(slice []int) []int {
	res := make([]int, len(slice))
	copy(res, slice)
	sort.Ints(res)
	return res
}

/* Util helpers */

// Ternary is like `cond ? a : b`. should assert the returned value like `Ternary(cond, a, b).(int)`
func Ternary(cond bool, a, b interface{}) interface{} {
	if cond {
		return a
	}

	return b
}

// TernaryInt uses Ternary and assert the value as int
func TernaryInt(cond bool, a, b int) int {
	return Ternary(cond, a, b).(int)
}

// TernaryString uses Ternary and assert the value as string
func TernaryString(cond bool, a, b string) string {
	return Ternary(cond, a, b).(string)
}

Score : 400 points

Problem Statement

There are N people standing in a queue from west to east.

Given is a string S of length N representing the directions of the people.
The i-th person from the west is facing west if the i-th character of S is L, and east if that character of S is R.

A person is happy if the person in front of him/her is facing the same direction.
If no person is standing in front of a person, however, he/she is not happy.

You can perform the following operation any number of times between 0 and K (inclusive):

Operation: Choose integers l and r such that 1 \leq l \leq r \leq N, and rotate by 180 degrees the part of the queue: the l-th, (l+1)-th, ..., r-th persons. That is, for each i = 0, 1, ..., r-l, the (l + i)-th person from the west will stand the (r - i)-th from the west after the operation, facing east if he/she is facing west now, and vice versa.

What is the maximum possible number of happy people you can have?

Constraints

N is an integer satisfying 1 \leq N \leq 10^5.

K is an integer satisfying 1 \leq K \leq 10^5.

|S| = N

Each character of S is L or R.

Input

Input is given from Standard Input in the following format:

N K
S

Output

Print the maximum possible number of happy people after at most K operations.

Sample Input 1

6 1
LRLRRL

Sample Output 1

3

If we choose (l, r) = (2, 5), we have LLLRLL, where the 2-nd, 3-rd, and 6-th persons from the west are happy.

Sample Input 2

13 3
LRRLRLRRLRLLR

Sample Output 2

9

Sample Input 3

10 1
LLLLLRRRRR

Sample Output 3

9

Sample Input 4

9 2
RRRLRLRLL

Sample Output 4

7


package main

import (
  "bufio"
  "os"
  "strconv"
  "strings"
  "fmt"
  "sort"
)

var reader = bufio.NewReaderSize(os.Stdin, 1000000)
var writer = bufio.NewWriter(os.Stdout)
func NextLine() string {
  var line, buffer []byte
  var isPrefix bool = true
  var err error
  for isPrefix {
    line, isPrefix, err = reader.ReadLine()
    if err != nil { panic(err) }
    buffer = append(buffer, line...)
  }
  return string(buffer)
}
func NextInt() int {
  var n int
  n, _ = strconv.Atoi(NextLine())
  return n
}
func NextIntVec() []int {
  L := strings.Split(NextLine(), " ")
  N := make([]int, len(L))
  for i := range N {
    N[i], _ = strconv.Atoi(L[i])
  }
  return N
}
func Write(s interface{}) {
  fmt.Fprintln(writer, s)
}
func Output() {
  _ = writer.Flush()
}

func main() {
  N := NextInt()
  S := NextIntVec()
  M := len(S)
  sort.Sort(sort.Reverse(sort.IntSlice(S)))
  C := make([]int, M)
  C[0] = N
  pos := 1
  ans := "Yes"
  for i, c := range C {
    for j := 0; j < c - 1; j++ {
      if S[i] == S[pos + j] { ans = "No" }
      C[pos + j] = c - j - 1
    }
    pos += c - 1
  }
  M /= 2
  for i := 0; i < M; i++ {
    if S[i] == S[M + i] { ans = "No" }
  }
  Write(ans)
  Output()
}

Score : 600 points

Problem Statement

We have one slime.

You can set the health of this slime to any integer value of your choice.

A slime reproduces every second by spawning another slime that has strictly less health. You can freely choose the health of each new slime. The first reproduction of our slime will happen in one second.

Determine if it is possible to set the healths of our first slime and the subsequent slimes spawn so that the multiset of the healths of the 2^N slimes that will exist in N seconds equals a multiset S.

Here S is a multiset containing 2^N (possibly duplicated) integers: S_1,~S_2,~...,~S_{2^N}.

Constraints

All values in input are integers.

1 \leq N \leq 18

1 \leq S_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
S_1 S_2 ... S_{2^N}

Output

If it is possible to set the healths of the first slime and the subsequent slimes spawn so that the multiset of the healths of the 2^N slimes that will exist in N seconds equals S, print Yes; otherwise, print No.

Sample Input 1

2
4 2 3 1

Sample Output 1

Yes

We will show one way to make the multiset of the healths of the slimes that will exist in 2 seconds equal to S.

First, set the health of the first slime to 4.

By letting the first slime spawn a slime whose health is 3, the healths of the slimes that exist in 1 second can be 4,~3.

Then, by letting the first slime spawn a slime whose health is 2, and letting the second slime spawn a slime whose health is 1, the healths of the slimes that exist in 2 seconds can be 4,~3,~2,~1, which is equal to S as multisets.

Sample Input 2

2
1 2 3 1

Sample Output 2

Yes

S may contain multiple instances of the same integer.

Sample Input 3

1
1 1

Sample Output 3

No

Sample Input 4

5
4 3 5 3 1 2 7 8 7 4 6 3 7 2 3 6 2 7 3 2 6 7 3 4 6 7 3 4 2 5 2 3

Sample Output 4

No


package main

import "fmt"

func main() {
	var s, t []byte
	fmt.Scan(&s, &t)
	var count int
	for i := 0; i < 3; i++ {
		if s[i] == t[i] {
			count++
		}
	}
	fmt.Println(count)
}

Score : 100 points

Problem Statement

You will be given a string S of length 3 representing the weather forecast for three days in the past.

The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. S, C, and R stand for sunny, cloudy, and rainy, respectively.

You will also be given a string T of length 3 representing the actual weather on those three days.

The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. S, C, and R stand for sunny, cloudy, and rainy, respectively.

Print the number of days for which the forecast was correct.

Constraints

S and T are strings of length 3 each.

S and T consist of S, C, and R.

Input

Input is given from Standard Input in the following format:

S
T

Output

Print the number of days for which the forecast was correct.

Sample Input 1

CSS
CSR

Sample Output 1

2

For the first day, it was forecast to be cloudy, and it was indeed cloudy.

For the second day, it was forecast to be sunny, and it was indeed sunny.

For the third day, it was forecast to be sunny, but it was rainy.

Thus, the forecast was correct for two days in this case.

Sample Input 2

SSR
SSR

Sample Output 2

3

Sample Input 3

RRR
SSS

Sample Output 3

0


package main

import (
	"fmt"
	//"math"
)

func main() {
	var s1 string
	fmt.Scanf("%s", &s1)
	var s2 string
	fmt.Scanf("%s", &s2)
	c := 0
	for i:=0;i<3;i++{
		if s1[i] == s2[i]{
			c++
		}
	}
	print(c)
}


package main

import (
	"bufio"
	"fmt"
	"os"
)

func main() {
	reader := bufio.NewReader(os.Stdin)
	S, _ := reader.ReadString('\n')
	T, _ := reader.ReadString('\n')
	var n int
	for i:=0;i<3;i++ {
		if S[i] == T[i] {
			n++
		}
	}
	fmt.Println(n)
}


package main

import "fmt"

func main() {
	var s, t string
	fmt.Scan(&s, &t)

	var cnt int
	for i := 0; i < 3; i++ {
		str1 := s[i : i+1]
		str2 := t[i : i+1]

		if str1 == str2 {
			cnt++
		}
	}

	fmt.Println(cnt)
}


package main

import "fmt"

func main() {
	var a, b int

	fmt.Scan(&a)
	fmt.Scan(&b)

	fmt.Println(solve(a, b))
}

func solve(a, b int) int {
	if (b-1)%(a-1) == 0 {
		return (b - 1) / (a - 1)
	} else {
		return (b-1)/(a-1) + 1
	}
}

Score : 200 points

Problem Statement

Takahashi's house has only one socket.

Takahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.

One power strip with A sockets can extend one empty socket into A empty sockets.

Find the minimum number of power strips required.

Constraints

All values in input are integers.

2 \leq A \leq 20

1 \leq B \leq 20

Input

Input is given from Standard Input in the following format:

A B

Output

Print the minimum number of power strips required.

Sample Input 1

4 10

Sample Output 1

3

3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.

Sample Input 2

8 9

Sample Output 2

2

2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.

Sample Input 3

8 8

Sample Output 3

1


package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

const (
	initialBufSize = 10000
	maxBufSize     = 1000000
	mod            = 1e9 + 7
)

var (
	sc *bufio.Scanner = func() *bufio.Scanner {
		sc := bufio.NewScanner(os.Stdin)
		buf := make([]byte, initialBufSize)
	sc.Buffer(buf, maxBufSize)
		sc.Split(bufio.ScanWords)
		return sc
	}()
)

func main() {
	A := getInt()
	B := getInt()

	num := 1
	cnt := 0
	for ; num < B; {
		num += A
		num--
		cnt++
	}

	fmt.Println(cnt)
}

type Graph struct {
	n     int
	edges [][]int
}

func NewGraph(n int) *Graph {
	g := &Graph{
		n:     n,
		edges: make([][]int, n),
	}
	return g
}

func (g *Graph) AddEdge(u, v int) {
	g.edges[v] = append(g.edges[v], u)
	g.edges[u] = append(g.edges[u], v)
}

func dfs(c int, edges [][]int, visited map[int]struct{}) {
	visited[c] = struct{}{}

	for _, v := range edges[c] {
		_, flag := visited[v]
		if flag {
			continue
		}
		dfs(v, edges, visited)
	}
}

func getInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func getString() string {
	sc.Scan()
	return sc.Text()
}

func abs(a int) int {
	return int(math.Abs(float64(a)))
}

func pow(p, q int) int {
	return int(math.Pow(float64(p), float64(q)))
}

func powMod(n, p int) int {
	if p == 0 {
		return 1
	} else if p%2 == 0 {
		t := powMod(n, p/2)
		return calcMod(t * t)
	} else {
		return calcMod(n * powMod(n, p-1))
	}
}

func min(nums ...int) int {
	if len(nums) == 0 {
		panic("funciton min() requires at least one argument.")
	}
	res := nums[0]
	for i := 0; i < len(nums); i++ {
		res = int(math.Min(float64(res), float64(nums[i])))
	}
	return res
}

func max(nums ...int) int {
	if len(nums) == 0 {
		panic("funciton max() requires at least one argument.")
	}
	res := nums[0]
	for i := 0; i < len(nums); i++ {
		res = int(math.Max(float64(res), float64(nums[i])))
	}
	return res
}

func strSearch(a []string, b string) bool {
	for i := 0; i < len(a); i++ {
		if a[i] == b {
			return true
		}
	}
	return false
}

func printIntArray(array []int) {
	strArray := fmt.Sprint(array)
	fmt.Println(strArray[1 : len(strArray)-1])
}

func calcMod(x int) int {
	return x % mod
}

func reverse(s string) string {
	runes := []rune(s)
	for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 {
		runes[i], runes[j] = runes[j], runes[i]
	}
	return string(runes)
}

func isPrime(n int) bool {
	if n < 2 {
		return false
	} else if n == 2 {
		return true
	} else if n % 2 == 0 {
		return false
	}

	sqrtN := int(math.Sqrt(float64(n)))
	for i := 3; i <= sqrtN; i += 2 {
		if n % i == 0 {
			return false
		}
	}

	return true
}


package main

import (
	"fmt"
	"math"
)

func main() {
	var a, b float64
	fmt.Scan(&a, &b)

	if b > a {
		fmt.Println(0)
	}
	fmt.Println(math.Ceil(b / a))
}


package main

import (
	"fmt"
)

func main() {
	var a, b int
	fmt.Scan(&a)
	fmt.Scan(&b)

	currentTap := 1
	tapCount := 0
	for {
		if b == 1 {
			break
		}
		currentTap = currentTap - 1 + a
		tapCount++
		if currentTap >= b {
			break
		}
	}

	fmt.Println(tapCount)

}


package main

import (
	"bufio"
	"fmt"
	"io"
	"os"
	"strconv"
)

type MyScanner struct {
	sc *bufio.Scanner
}

type MyWriter struct {
	stdout io.Writer
}

type MyPut interface{}

func getScanner(fp io.Reader) *bufio.Scanner {
	sc := bufio.NewScanner(fp)
	sc.Split(bufio.ScanWords)
	sc.Buffer(make([]byte, 500001), 500000)
	return sc
}

func getHugeScanner(fp io.Reader, size int) *bufio.Scanner {
	sc := bufio.NewScanner(fp)
	sc.Split(bufio.ScanWords)
	sc.Buffer(make([]byte, size), size)
	return sc
}

func (mysc *MyScanner)String() string {
	mysc.sc.Scan()
	return mysc.sc.Text()
}

func (mysc *MyScanner)Int() int {
	i, _ := strconv.Atoi(mysc.String())
	return i
}

func (mysc *MyScanner)Int64() int64 {
	i, _ := strconv.ParseInt(mysc.String(), 10, 64)
	return i
}

func (mysc *MyScanner)Float64() float64 {
	i, _ := strconv.ParseFloat(mysc.String(), 64)
	return i
}

func (mw MyWriter)Puts(v MyPut) {
	_, _ = fmt.Fprintf(mw.stdout, "%v\n", v)
}

func Solve(stdin io.Reader, stdout io.Writer) {
	sc := MyScanner{getScanner(stdin)}
	mw := MyWriter{stdout}

	a := sc.Int()
	b := sc.Int()

	num := 1
	ans := 0

	for b > num {
		ans++
		num += a - 1
	}

	mw.Puts(ans)
}

func main() {
	Solve(os.Stdin, os.Stdout)
	return
}


package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func main() {
	sc := bufio.NewScanner(os.Stdin)
	sc.Split(bufio.ScanWords)
	sc.Scan()
	n, _ := strconv.Atoi(sc.Text())
	// sc.Scan()
	// fmt.Println(n, sc.Text())
	h := make([]int, n)
	for i := 0; i < n; i++ {
		// fmt.Scan(&h[i])
		sc.Scan()
		h[i], _ = strconv.Atoi(sc.Text())
	}
	var cnt int
	var ans int
	for i := 0; i < n-1; i++ {
		if h[i] >= h[i+1] {
			cnt++
			ans = max(cnt, ans)
		} else {
			cnt = 0
		}
	}
	fmt.Println(ans)
}

func max(a ...int) int {
	r := a[0]
	for i := 0; i < len(a); i++ {
		if r < a[i] {
			r = a[i]
		}
	}
	return r
}

Score : 300 points

Problem Statement

There are N squares arranged in a row from left to right.

The height of the i-th square from the left is H_i.

You will land on a square of your choice, then repeat moving to the adjacent square on the right as long as the height of the next square is not greater than that of the current square.

Find the maximum number of times you can move.

Constraints

All values in input are integers.

1 \leq N \leq 10^5

1 \leq H_i \leq 10^9

Input

Input is given from Standard Input in the following format:

N
H_1 H_2 ... H_N

Output

Print the maximum number of times you can move.

Sample Input 1

5
10 4 8 7 3

Sample Output 1

2

By landing on the third square from the left, you can move to the right twice.

Sample Input 2

7
4 4 5 6 6 5 5

Sample Output 2

3

By landing on the fourth square from the left, you can move to the right three times.

Sample Input 3

4
1 2 3 4

Sample Output 3

0


package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
	"strings"
)

// main is...
func main() {
	var n int
	fmt.Scanln(&n)

	var sc = bufio.NewScanner(os.Stdin)
	var list = make([]string, n)
	// var listInt = make([]int64, n)
	var listInt = make([]int, n)

	if sc.Scan() {
		list = strings.Fields(sc.Text())
	}

	for idx, value := range list {
		valueInt, _ := strconv.Atoi(value)
		// valueInt, _ := strconv.ParseInt(value, 10, 64)
		listInt[idx] = valueInt
	}

	max, tmp := 0, 0
	// for i := n - 1; i > 0; i-- {
	// 	if listInt[i-1] >= listInt[i] {
	// 		tmp++
	// 	} else {
	// 		tmp = 0
	// 	}

	// 	if tmp > max {
	// 		max = tmp
	// 	}
	// }
	for i := 1; i < n; i++ {
		if listInt[i-1] >= listInt[i] {
			tmp++
		} else {
			tmp = 0
		}

		if tmp > max {
			max = tmp
		}
	}
	fmt.Println(max)

}


package main

import (
    "fmt"
)

func main() {
    var n int
    fmt.Scan(&n)
    hs := make([]int, n)
    for i := range hs {
        fmt.Scan(&hs[i])
    }
    var ph, cnt, max int
    for i := range hs {
        if hs[i] <= ph {
            cnt++
            if cnt > max {
                max = cnt
            }
        } else {
            cnt = 0
        }
        ph = hs[i]
    }
    fmt.Println(max)
}


package main

import "fmt"

func main() {
	var n int
	fmt.Scan(&n)

	sum := 0
	for i := 0; i < n - 1; i++ {
		sum = sum + i + 1
	}

	fmt.Println(sum)
}

Score : 400 points

Problem Statement

For an integer N, we will choose a permutation \{P_1, P_2, ..., P_N\} of \{1, 2, ..., N\}.

Then, for each i=1,2,...,N, let M_i be the remainder when i is divided by P_i.

Find the maximum possible value of M_1 + M_2 + \cdots + M_N.

Constraints

N is an integer satisfying 1 \leq N \leq 10^9.

Input

Input is given from Standard Input in the following format:

N

Output

Print the maximum possible value of M_1 + M_2 + \cdots + M_N.

Sample Input 1

2

Sample Output 1

1

When the permutation \{P_1, P_2\} = \{2, 1\} is chosen, M_1 + M_2 = 1 + 0 = 1.

Sample Input 2

13

Sample Output 2

78

Sample Input 3

1

Sample Output 3

0


// ProblemURL : https://atcoder.jp/contests/abc139/tasks/abc139_d
// ---------------------------------------------
package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
)

func abs(x int) int {
	if x < 0 {
		return -x
	}
	return x
}
func larger(a, b int) int {
	if a > b {
		return a
	}
	return b
}
func smaller(a, b int) int {
	if a < b {
		return a
	}
	return b
}
func largest(a, b, c int) (lgst int) {
	if a > b {
		lgst = a
	} else {
		lgst = b
	}
	if c > lgst {
		lgst = c
	}
	return
}
func smallerst(a, b, c int) (slst int) {
	if a < b {
		slst = a
	} else {
		slst = b
	}
	if c < slst {
		slst = c
	}
	return
}
func max(a []int) (idx, val int) {
	if len(a) == 0 {
		panic("func max requires at least one argument")
	}
	val = a[0]
	for i, aa := range a {
		if aa > val {
			idx, val = i, aa
		}
	}
	return
}
func min(a []int) (idx, val int) {
	if len(a) == 0 {
		panic("func min requires at least one argument")
	}
	val = a[0]
	for i, aa := range a {
		if aa < val {
			idx, val = i, aa
		}
	}
	return
}
func sum(a []int) int {
	res := 0
	for _, v := range a {
		res += v
	}
	return res
}
func isEven(n int) bool            { return n&1 == 0 }
func isOdd(n int) bool             { return n&1 == 1 }
func swap(a int, b int) (int, int) { return b, a }
func fill(a []int, val int) {
	for i := 0; i < len(a); i++ {
		a[i] = val
	}
	return
}
func calcMod(n int) int   { return n % mod }
func sigma(x int) int     { return x * (x + 1) / 2 }
func powInt(a, b int) int { return int(math.Pow(float64(a), float64(b))) }

var (
	sc = bufio.NewScanner(os.Stdin)
	bw = bufio.NewWriter(os.Stdout)
)

func init() {}
func ru() (n int) {
	sc.Scan()
	if err := sc.Err(); err != nil {
		panic(err)
	}
	for _, v := range sc.Bytes() {
		n = n*10 + int(v-48)
	}
	return
}
func ri() (n int) {
	sc.Scan()
	if err := sc.Err(); err != nil {
		panic(err)
	}
	b := sc.Bytes()
	neg := false
	if b[0] == 45 {
		neg = true
	}
	for _, v := range b {
		n = n*10 + int(v-48)
	}
	if neg {
		n = -n
	}
	return
}
func rs() string {
	sc.Scan()
	if err := sc.Err(); err != nil {
		panic(err)
	}
	return sc.Text()
}
func rb() []byte {
	sc.Scan()
	if err := sc.Err(); err != nil {
		panic(err)
	}
	return sc.Bytes()
}
func pf(format string, a ...interface{}) {
	if _, err := fmt.Fprintf(bw, format, a...); err != nil {
		panic(err)
	}
}
func pln(a ...interface{}) {
	if _, err := fmt.Fprintln(bw, a...); err != nil {
		panic(err)
	}
}
func pall(a []int) {
	for _, v := range a {
		fmt.Fprintln(bw, v)
	}
}
func pallol(a []int) {
	s := fmt.Sprint(a)
	if _, err := fmt.Fprintln(bw, s[1:len(s)-1]); err != nil {
		panic(err)
	}
}
func debug(a ...interface{}) {
	s := fmt.Sprint(a)
	if _, err := fmt.Fprintln(os.Stderr, s[1:len(s)-1]); err != nil {
		panic(err)
	}
}
func main() {
	sc.Split(bufio.ScanWords)
	sc.Buffer(make([]byte, 1e7), 1e7)
	solve()
	bw.Flush()
}

const (
	// maxInt64  = 9223372036854775807  // 9e18
	// maxInt32  = 2147483647           // 2e9
	// maxUint64 = 18446744073709551615 // 1e19
	inf = 1 << 60
	mod = 1e9 + 7
)

type pair struct{ a, b int }
type point struct{ x, y int }

func solve() {
	n := ri()
	pln(sigma(n - 1))
}


package main

import "fmt"

func main() {
	var n int
	fmt.Scan(&n)

	ret := 0.0
	for i := 0; i < n; i++ {
		var a int
		fmt.Scan(&a)
		ret += 1 / float64(a)
	}

	fmt.Println(1 / ret)
}

Score : 200 points

Problem Statement

Given is a sequence of N integers A_1, \ldots, A_N.

Find the (multiplicative) inverse of the sum of the inverses of these numbers, \frac{1}{\frac{1}{A_1} + \ldots + \frac{1}{A_N}}.

Constraints

1 \leq N \leq 100

1 \leq A_i \leq 1000

Input

Input is given from Standard Input in the following format:

N
A_1 A_2 \ldots A_N

Output

Print a decimal number (or an integer) representing the value of \frac{1}{\frac{1}{A_1} + \ldots + \frac{1}{A_N}}.

Your output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.

Sample Input 1

2
10 30

Sample Output 1

7.5

\frac{1}{\frac{1}{10} + \frac{1}{30}} = \frac{1}{\frac{4}{30}} = \frac{30}{4} = 7.5.

Printing 7.50001, 7.49999, and so on will also be accepted.

Sample Input 2

3
200 200 200

Sample Output 2

66.66666666666667

\frac{1}{\frac{1}{200} + \frac{1}{200} + \frac{1}{200}} = \frac{1}{\frac{3}{200}} = \frac{200}{3} = 66.6666....

Printing 6.66666e+1 and so on will also be accepted.

Sample Input 3

1
1000

Sample Output 3

1000

\frac{1}{\frac{1}{1000}} = 1000.

Printing +1000.0 and so on will also be accepted.


package main

import (
	"bufio"
	"fmt"
	"os"
	"sort"
	"strconv"
)

const mod = 1000000007

// 1MB
const ioBufferSize = 1 * 1024 * 1024

var sc = func() *bufio.Scanner {
	sc := bufio.NewScanner(os.Stdin)
	sc.Buffer(make([]byte, ioBufferSize), ioBufferSize)
	sc.Split(bufio.ScanWords)
	return sc
}()

func next() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

func main() {
	n := nextInt()
	v := make([]float64, n)

	for i := 0; i < n; i++ {
		v[i] = float64(nextInt())
	}

	for len(v) > 1 {
		sort.Float64s(v)
		s := (v[0] + v[1]) / 2
		v = v[2:]
		v = append(v, s)
	}

	fmt.Println(v[0])
}

Score : 300 points

Problem Statement

You have a pot and N ingredients. Each ingredient has a real number parameter called value, and the value of the i-th ingredient (1 \leq i \leq N) is v_i.

When you put two ingredients in the pot, they will vanish and result in the formation of a new ingredient. The value of the new ingredient will be (x + y) / 2 where x and y are the values of the ingredients consumed, and you can put this ingredient again in the pot.

After you compose ingredients in this way N-1 times, you will end up with one ingredient. Find the maximum possible value of this ingredient.

Constraints

2 \leq N \leq 50

1 \leq v_i \leq 1000

All values in input are integers.

Input

Input is given from Standard Input in the following format:

N
v_1 v_2 \ldots v_N

Output

Print a decimal number (or an integer) representing the maximum possible value of the last ingredient remaining.

Your output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.

Sample Input 1

2
3 4

Sample Output 1

3.5

If you start with two ingredients, the only choice is to put both of them in the pot. The value of the ingredient resulting from the ingredients of values 3 and 4 is (3 + 4) / 2 = 3.5.

Printing 3.50001, 3.49999, and so on will also be accepted.

Sample Input 2

3
500 300 200

Sample Output 2

375

You start with three ingredients this time, and you can choose what to use in the first composition. There are three possible choices:

Use the ingredients of values 500 and 300 to produce an ingredient of value (500 + 300) / 2 = 400. The next composition will use this ingredient and the ingredient of value 200, resulting in an ingredient of value (400 + 200) / 2 = 300.

Use the ingredients of values 500 and 200 to produce an ingredient of value (500 + 200) / 2 = 350. The next composition will use this ingredient and the ingredient of value 300, resulting in an ingredient of value (350 + 300) / 2 = 325.

Use the ingredients of values 300 and 200 to produce an ingredient of value (300 + 200) / 2 = 250. The next composition will use this ingredient and the ingredient of value 500, resulting in an ingredient of value (250 + 500) / 2 = 375.

Thus, the maximum possible value of the last ingredient remaining is 375.

Printing 375.0 and so on will also be accepted.

Sample Input 3

5
138 138 138 138 138

Sample Output 3

138


package main

import (
	"math/rand"
	"time"
	"os"
	"bufio"
	"fmt"
	"strconv"
	"strings"
)

var(
	sc = bufio.NewScanner(os.Stdin)
	stdin = bufio.NewReader(os.Stdin)
	mod = 1000000007
	mod9 = 1000000009
)

func init()  {
	rand.Seed(time.Now().UnixNano())
	buf := make([]byte, 0) //ここのサイズは何でもよさそう
	sc.Buffer(buf, 1000000009)
}

//||||||||||||||||||||||||||入力|||||||||||||||||||||||||||||||||||||||\
//数字一文字入力
func nextInt() int {
	sc.Scan()
	i, e := strconv.Atoi(sc.Text())
	if e != nil {
		panic(e)
	}
	return i
}

//文字列を一行入力
func nextLine() string {
	sc.Scan()
	return sc.Text()
}

//空白区切りの文字列の入力
func spaceLine() []string {
	sc.Scan()
	return strings.Split(sc.Text()," ")
}

//数字を一行入力
func intLine() []int {
	str := spaceLine()
	buf := make([]int,len(str))
	for i,s:=range str{
		buf[i],_ = strconv.Atoi(s)
	}
	return buf
}

//次のスペースか改行まで読み込む
func gostring() string {
	byte_ls := make([]byte,0)
	check := false
	for  {
		b, _ := stdin.ReadByte()
		if b == 32 || (check == true && b == 10){
			return string(byte_ls)
		} else if b == 13 {
			check = true
		} else {
			byte_ls = append(byte_ls,b)
		}
	}
}

//上の関数のintバージョン
func goint() int {
	n,_ := strconv.Atoi(gostring())
	return n
}

//|||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||

//ソートする
//sは最初のインデックス fは最後のインデックス
func Sort(ls []int,l int,r int)  {
	if r - l <= 0{return}
	pipot := l + rand.Intn(r-l+1)
	ls[r],ls[pipot] = ls[pipot],ls[r]
	i := l
	for j:=l;j<r;j++{
		if ls[j] < ls[r]{
			ls[i],ls[j] = ls[j],ls[i]
			i ++
		}
	}
	ls[i],ls[r] = ls[r],ls[i]
	Sort(ls,l,i-1)
	Sort(ls,i+1,r)
}

//配列の大小を指定した要素で比較
//a < bならtrue
func sizeCheck(a []int,b []int,ls []int) bool {
	for _,i:= range ls{
		if a[i] < b[i]{
			return true
		} else if a[i] > b[i] {
			return false
		}
	}
	return false
}

//二次元配列のソート
func Sort2D(ls [][]int,l int,r int,index ...int)  {
	if r - l <= 0{return}
	pipot := l + rand.Intn(r-l+1)
	ls[r],ls[pipot] = ls[pipot],ls[r]
	i := l
	for j:=l;j<r;j++{
		if sizeCheck(ls[j],ls[r],index){
			ls[i],ls[j] = ls[j],ls[i]
			i ++
		}
	}
	ls[i],ls[r] = ls[r],ls[i]
	Sort2D(ls,l,i-1,index ...)
	Sort2D(ls,i+1,r,index ...)
}

func main() {
	n := goint()
	ls := make([]int,n)
	for i:=0;i<n;i++{
		ls[i] = goint()
	}
	Sort(ls,0,len(ls)-1)
	c := (float64(ls[0]) + float64(ls[1])) / 2.0
	for i:=2;i<n;i++{
		c = (c + float64(ls[i])) / 2.0
	}
	fmt.Println(c)
}

func min(a ...int) int {
	ans := a[0]
	for i:=1;i<len(a);i++{
		if ans > a[i]{
			ans = a[i]
		}
	}
	return ans
}


package main

import (
	"bufio"
	"fmt"
	"math"
	"os"
	"strconv"
)

var sc = bufio.NewScanner(os.Stdin)

func main() {
	sc.Split(bufio.ScanWords)
	n := readInt()
	values := make([]float64, n)
	for i := 0; i < n; i++ {
		values[i] = float64(readInt())
	}
	fmt.Println(solve(values))
}

func solve(values []float64) float64 {
	x := values[0]
	y := values[1]
	if len(values) == 2 {
		return pot(x, y)
	}
	for len(values) > 1 {
		// 最小値を２つ選ぶ
		minIndex1, min1 := min(values)
		values = remove(values, minIndex1)
		minIndex2, min2 := min(values)
		values = remove(values, minIndex2)
		// 鍋に入れた結果を戻す
		newValue := pot(min1, min2)
		values = append(values, newValue)
	}
	return values[0]
}

func pot(x, y float64) float64 {
	return (x + y) / 2
}

// スライス内の最小値を取得する
func min(nums []float64) (index int, min float64) {
	min = math.MaxFloat64
	for i, n := range nums {
		if n < min {
			index = i
			min = n
		}
	}
	return
}

// ある要素を削除したスライスを返す
func remove(nums []float64, i int) []float64 {
	return append(nums[:i], nums[i+1:]...)
}

func read() string {
	sc.Scan()
	return sc.Text()
}

func readInt() int {
	i, e := strconv.Atoi(read())
	if e != nil {
		panic(e)
	}
	return i
}


package main

import (
        "bufio"
        "fmt"
        "os"
)

var rdr = bufio.NewReaderSize(os.Stdin, 1000000)

func readLine() string {
        buf := make([]byte, 0, 1000000)
        for {
                l, p, e := rdr.ReadLine()
                if e != nil {
                        panic(e)
                }
                buf = append(buf, l...)
                if !p {
                        break
                }
        }
        return string(buf)
}

func lowerBound(a []int, x int) int {
        n := len(a)
        ok := n
        ng := -1
        for ok-ng > 1 {
                mid := (ok + ng) / 2
                if a[mid] >= x {
                        ok = mid
                } else {
                        ng = mid
                }
        }
        return ok
}

func main() {
        var s string
        var t string

        s = readLine()
        t = readLine()

        idxs := make([][]int, 256)

        for i := 0; i < len(s); i++ {
                idxs[s[i]] = append(idxs[s[i]], i)
        }

        n := int64(len(s))
        cur := int64(0)
        ng := false

        for i := 0; i < len(t); i++ {
                is := idxs[t[i]]
                if is == nil || len(is) == 0 {
                        ng = true
                        break
                }
                base := (cur / n) * n

                nidx := lowerBound(is, int(cur%n))
                if nidx == len(is) {
                        cur = base + int64(is[0]) + n + 1
                } else {
                        cur = base + int64(is[nidx]) + 1
                }
        }
        if ng {
                fmt.Println(-1)
        } else {
                fmt.Println(cur)
        }
}

Score : 500 points

Problem Statement

Given are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.

Let s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\ldots{s'}_i (the first i characters in s').

Notes

A subsequence of a string a is a string obtained by deleting zero or more characters from a and concatenating the remaining characters without changing the relative order. For example, the subsequences of contest include net, c, and contest.

Constraints

1 \leq |s| \leq 10^5

1 \leq |t| \leq 10^5

s and t consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

s
t

Output

If there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print -1.

Sample Input 1

contest
son

Sample Output 1

10

t = son is a subsequence of the string contestcon (the first 10 characters in s' = contestcontestcontest...), so i = 10 satisfies the condition.

On the other hand, t is not a subsequence of the string contestco (the first 9 characters in s'), so i = 9 does not satisfy the condition.

Similarly, any integer less than 9 does not satisfy the condition, either. Thus, the minimum integer i satisfying the condition is 10.

Sample Input 2

contest
programming

Sample Output 2

-1

t = programming is not a substring of s' = contestcontestcontest.... Thus, there is no integer i satisfying the condition.

Sample Input 3

contest
sentence

Sample Output 3

33

Note that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.


package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func getScanner(fp *os.File) *bufio.Scanner {
	scanner := bufio.NewScanner(fp)
	scanner.Split(bufio.ScanWords)
	scanner.Buffer(make([]byte, 500001), 500000)
	return scanner
}

func getNextString(scanner *bufio.Scanner) string {
	scanner.Scan()
	return scanner.Text()
}

func getNextInt(scanner *bufio.Scanner) int {
	i, _ := strconv.Atoi(getNextString(scanner))
	return i
}

func getNextInt64(scanner *bufio.Scanner) int64 {
	i, _ := strconv.ParseInt(getNextString(scanner), 10, 64)
	return i
}
func getNextFloat64(scanner *bufio.Scanner) float64 {
	i, _ := strconv.ParseFloat(getNextString(scanner), 64)
	return i
}

func main() {
	fp := os.Stdin
	if len(os.Args) > 1 {
		fp, _ = os.Open(os.Args[1])
	}

	scanner := getScanner(fp)
	writer := bufio.NewWriter(os.Stdout)

	s := getNextString(scanner)
	t := getNextString(scanner)

	var indexes [26][]int
	var ll [26]int

	for i := 0; i < 26; i++ {
		indexes[i] = make([]int, 0)
	}

	n := len(s)
	for i := 0; i < n; i++ {
		indexes[s[i]-'a'] = append(indexes[s[i]-'a'], i)
	}
	for i := 0; i < 26; i++ {
		ll[i] = len(indexes[i])
	}

	tn := len(t)
	now := 0
	var ans int64
	for i := 0; i < tn; i++ {
		ch := int(t[i] - 'a')
		l := 0
		r := ll[ch]
		if r == 0 {
			ans = -1
			break
		}
		for l < r {
			m := (l + r) >> 1
			if indexes[ch][m] < now {
				l = m + 1
				continue
			}
			r = m
		}
		if l == ll[ch] {
			ans += int64(n - now)
			now = 0
			i--
			continue
		}
		ans += int64(indexes[ch][l] - now + 1)
		now = indexes[ch][l] + 1
	}

	fmt.Fprintln(writer, ans)

	writer.Flush()
}


package main

import (
	"bufio"
	"fmt"
	"os"
	"strconv"
)

func main() {
	sc.Split(bufio.ScanWords)
	s := nextMega()
	n := len(s)

	ans := 1
	prev := string(s[0])
	for i := 1; i < n; i++ {
		for j := i + 1; j <= n; j++ {
			if prev != s[i:j] {
				prev = s[i:j]
				if j-i == 1 {
					i = j - 1
				} else {
					i = j - 1
				}
				ans++
				break
			}
		}
	}
	puts(ans)
	wt.Flush()
}

var (
	sc  = bufio.NewScanner(os.Stdin)
	rdr = bufio.NewReaderSize(os.Stdin, 1000000)
	wt  = bufio.NewWriter(os.Stdout)
)

func next() string {
	sc.Scan()
	return sc.Text()
}

func nextInt() int {
	i, _ := strconv.Atoi(next())
	return i
}

func nextFloat64() float64 {
	f, _ := strconv.ParseFloat(next(), 64)
	return f
}

func nextInts(n int) []int {
	slice := make([]int, n)
	for i := 0; i < n; i++ {
		slice[i] = nextInt()
	}
	return slice
}

func nextFloat64s(n int) []float64 {
	slice := make([]float64, n)
	for i := 0; i < n; i++ {
		slice[i] = nextFloat64()
	}
	return slice
}

func nextMega() string {
	buf := make([]byte, 0, 1000000)
	for {
		l, p, _ := rdr.ReadLine()
		buf = append(buf, l...)
		if !p {
			break
		}
	}
	return string(buf)
}

func putf(format string, a ...interface{}) {
	fmt.Fprintf(wt, format, a...)
}

func puts(a ...interface{}) {
	fmt.Fprintln(wt, a...)
}

Score : 300 points

Problem Statement

Given is a string S consisting of lowercase English letters. Find the maximum positive integer K that satisfies the following condition:

There exists a partition of S into K non-empty strings S=S_1S_2...S_K such that S_i \neq S_{i+1} (1 \leq i \leq K-1).

Here S_1S_2...S_K represents the concatenation of S_1,S_2,...,S_K in this order.

Constraints

1 \leq |S| \leq 2 \times 10^5

S consists of lowercase English letters.

Input

Input is given from Standard Input in the following format:

S

Output

Print the maximum positive integer K that satisfies the condition.

Sample Input 1

aabbaa

Sample Output 1

4

We can, for example, divide S into four strings aa, b, ba, and a.

Sample Input 2

aaaccacabaababc

Sample Output 2

12


package main

import "fmt"

var s string

func main() {
	fmt.Scanf("%s", &s)
	a := make([]string, len(s))
	for i := range s {
		a[i] = s[i : i+1]
	}
	fmt.Println(fix(a))
}

func fix(a []string) int {
	// fmt.Printf("fix %q\n", a)
	best := 0
	for i := 0; i < len(a)-1; i++ {
		if a[i] == a[i+1] {
			if i-1 > 0 {
				n := fix(merge(a, i-1))
				if best < n {
					best = n
				}
			}
			n := fix(merge(a, i))
			if best < n {
				best = n
			}
			if i+1 < len(a)-1 {
				n := fix(merge(a, i+1))
				if best < n {
					best = n
				}
			}
			return best
		}
	}

	return len(a)
}

func merge(a []string, i int) []string {
	return append(append(append([]string{}, a[:i]...), a[i]+a[i+1]), a[i+2:]...)
}


package main

import (
	"bufio"
	"os"
	"strconv"
	"fmt"
)

var sc = bufio.NewScanner(os.Stdin)
var ReadString func() string
var ReadLine func() string
var ReadInt64 func() int64
var ReadInt func() int
var ReadIntSlice func(int) []int
var ReadInt64Slice func(int) []int64
var GetIntAbs func(int) int
var Atoi func(string) int
var FindMin func([] int) int
var FindMax func([] int) int
var StrReverse func(string) string

func init() {
	ReadString = newReadString()
	ReadLine = readLine
	ReadInt64 = readInt64
	ReadInt = readInt
	ReadIntSlice = readIntSlice
	FindMin = findMin
	FindMax = findMax
	StrReverse = strReverse
	GetIntAbs = getIntAbs
}

func main() {
  s := ReadString()
  sl := len(s)
  var rs int
  var prev string
  for i := 0; i < sl; i++ {
    v := string(s[i])
    if prev != v {
      rs += 1
      prev = v
    } else if i + 1 < sl {
      t := v
      for k := i + 1; k < sl; k++ {
        if k >= sl {
          break
        }
        t = fmt.Sprintf("%s%s", t, string(s[k]))
        if t != prev {
          rs += 1
          prev = t
          i = k
          break
        }
      }

    }

  }
  fmt.Println(rs)
}

func strReverse(s string) string {
	runes := []rune(s)
	l := len(runes)
	for i, j := 0, l-1; i < j; i, j = i+1, j-1 {
		runes[i], runes[j] = runes[j], runes[i]
	}
	return string(runes)
}

func newReadString() func() string {
	sc.Buffer(make([]byte, 202400), 404800)
	sc.Split(bufio.ScanWords)
	return func() string {
		if !sc.Scan() {
			panic("scanできなかった")
		}
		return sc.Text()
	}
}

func readLine() string {
	if !sc.Scan() {
		panic("line をscanできなかった")
	}
	return sc.Text()
}

func readInt64() int64 {
	i, err := strconv.ParseInt(ReadString(), 0, 64)
	if err != nil {
		fmt.Println("parseInt失敗")
		panic(err.Error())
	}
	return int64(i)
}

func readInt() int {
	i := ReadInt64()
	return int(i)
}

func readIntSlice(n int) []int {
	arr := make([]int, n)
	for i := 0; i < n; i++ {
		arr[i] = ReadInt()
	}
	return arr
}

func readInt64Slice(n int) []int64 {
	arr := make([]int64, n)
	for i := 0; i < n; i++ {
		arr[i] = ReadInt64()
	}
	return arr
}

/*------ number util ------*/

func getIntAbs(n int) int {
	if n < 0 {
		return -n
	}
	return n
}

func atoi(a string) int {
	i, err := strconv.Atoi(a)
	if err != nil {
		panic(err.Error())
	}
	return i
}

func findMin(arr []int) int {
	if len(arr) == 0 {
		return 0
	}
	min := arr[0]
	for _, v := range arr {
		if v < min {
			min = v
		}
	}
	return min
}

func findMax(arr []int) int {
	if len(arr) == 0 {
		return 0
	}
	max := arr[0]
	for _, v := range arr {
		if v > max {
			max = v
		}
	}
	return max
}


// https://atcoder.jp/contests/agc037/tasks/agc037_d

package main

import (
	"bufio"
	"bytes"
	"fmt"
	"os"
	"sort"
	"strconv"
	"strings"
)

type BipartiteMatching struct {
	edges [][]int
	match []int
	used  []bool
}

func (b *BipartiteMatching) init(n int) {
	b.edges = make([][]int, n)
	b.match = make([]int, n)

	for i := range b.match {
		b.match[i] = -1
	}
}

func (b *BipartiteMatching) add(from, to int) {
	b.edges[from] = append(b.edges[from], to)
	b.edges[to] = append(b.edges[to], from)
}

func (b *BipartiteMatching) dfs(v int) bool {
	b.used[v] = true

	for _, u := range b.edges[v] {
		w := b.match[u]
		if w == -1 || !b.used[w] && b.dfs(w) {
			b.match[u] = v
			b.match[v] = u
			return true
		}
	}

	return false
}

func (b *BipartiteMatching) exec() int {
	res := 0

	for v := 0; v < len(b.edges); v++ {
		if b.match[v] == -1 {
			b.used = make([]bool, len(b.edges))

			if b.dfs(v) {
				res++
			}
		}
	}

	return res
}

// d: debug IO. it can print debug in test.
func solve(io *Io, d *Io) {
	N := io.NextInt()
	M := io.NextInt()

	mat := make([][]int, N)
	for i := range mat {
		mat[i] = make([]int, M)

		for j := 0; j < M; j++ {
			mat[i][j] = io.NextInt()
		}
	}

	filledA := make([][]bool, N)
	for i := range filledA {
		filledA[i] = make([]bool, M)
	}

	matA := make([][]int, N)
	for i := range matA {
		matA[i] = make([]int, M)
	}

	for i := range mat {
		bp := BipartiteMatching{}
		bp.init(M * 2)

		for j, val := range mat[i] {
			row := (val - 1) / M

			for k := 0; k < M; k++ {
				if !filledA[row][k] {
					bp.add(j, k+M)
				}
			}
		}

		bp.exec()

		for j, val := range mat[i] {
			row := (val - 1) / M
			if bp.match[j] == -1 {
				return
			}
			k := bp.match[j] - M

			matA[i][k] = val
			filledA[row][k] = true
		}
	}

	for i := range matA {
		io.PrintInts(matA[i])
	}

	matB := make([][]int, N)
	for i := range matB {
		matB[i] = make([]int, M)
	}

	// 縦でソートして埋める
	for i := 0; i < M; i++ {
		tmp := make([]int, N)

		for j := 0; j < N; j++ {
			tmp[j] = matA[j][i]
		}

		sort.Ints(tmp)

		for j := 0; j < N; j++ {
			matB[j][i] = tmp[j]
		}
	}

	for i := range matB {
		io.PrintInts(matB[i])
	}
}

func main() {
	io := NewIo()
	defer io.Flush()
	solve(io, nil)
}

/* IO Helpers */

// Io combines reader, writer, & tokens as the state when processing the input
type Io struct {
	reader    *bufio.Reader
	writer    *bufio.Writer
	tokens    []string
	nextToken int
}

// NewIo creates Io with Stdin & Stdout
func NewIo() *Io {
	return &Io{
		reader: bufio.NewReader(os.Stdin),
		writer: bufio.NewWriter(os.Stdout),
	}
}

// Flush calls the writer's Flush
func (io *Io) Flush() {
	io.writer.Flush()
}

// NextLine returns the string from reader.ReadLine()
func (io *Io) NextLine() string {
	if io.nextToken < len(io.tokens) {
		panic("io.nextToken < len(io.tokens)")
	}

	var buffer bytes.Buffer

	for {
		line, isPrefix, err := io.reader.ReadLine()
		if err != nil {
			panic(err)
		}
		buffer.Write(line)
		if !isPrefix {
			break
		}
	}

	return buffer.String()
}

// NextLines returns []string from next n lines
func (io *Io) NextLines(n int) []string {
	res := make([]string, n)
	for i := 0; i < n; i++ {
		res[i] = io.NextLine()
	}
	return res
}

// Next returns the string token (partial string of the line divided by spaces)
func (io *Io) Next() string {
	if io.nextToken >= len(io.tokens) {
		line := io.NextLine()
		io.tokens = strings.Fields(line)
		io.nextToken = 0
	}

	res := io.tokens[io.nextToken]
	io.nextToken++
	return res
}

// NextStrings returns the []string from the next n tokens
func (io *Io) NextStrings(n int) []string {
	res := make([]string, n)
	for i := 0; i < n; i++ {
		res[i] = io.Next()
	}
	return res
}

// NextInt returns the int from the next token
func (io *Io) NextInt() int {
	res, err := strconv.Atoi(io.Next())
	if err != nil {
		panic(err)
	}
	return res
}

// NextInts returns the []int from the next n tokens
func (io *Io) NextInts(n int) []int {
	res := make([]int, n)
	for i := 0; i < n; i++ {
		res[i] = io.NextInt()
	}
	return res
}

// NextFloat returns the float64 from the next token
func (io *Io) NextFloat() float64 {
	res, err := strconv.ParseFloat(io.Next(), 64)
	if err != nil {
		panic(err)
	}
	return res
}

// NextFloats returns the []float64 from the next n tokens
func (io *Io) NextFloats(n int) []float64 {
	res := make([]float64, n)
	for i := 0; i < n; i++ {
		res[i] = io.NextFloat()
	}
	return res
}

// Println prints the input to the writer in an easy-to-see form
func (io *Io) Println(a ...interface{}) {
	var values []string
	for i := 0; i < len(a); i++ {
		values = append(values, "%v")
	}
	io.Printfln(strings.Join(values, " "), a...)
}

// Print calls Fprint to the writer
func (io *Io) Print(a interface{}) {
	fmt.Fprint(io.writer, a)
}

// Printf calls Fprintf to the writer
func (io *Io) Printf(format string, a ...interface{}) {
	fmt.Fprintf(io.writer, format, a...)
}

// Printfln calls Fprint to the writer
func (io *Io) Printfln(format string, a ...interface{}) {
	fmt.Fprintf(io.writer, format+"\n", a...)
}

// PrintInts prints ints with space and new line at the end
func (io *Io) PrintInts(ints []int) {
	for i, e := range ints {
		io.Print(e)

		if i == len(ints)-1 {
			io.Println()
		} else {
			io.Print(" ")
		}
	}
}

// Debug calls Println and Flush immediately
func (io *Io) Debug(a ...interface{}) {
	if io == nil {
		return
	}

	io.Println(a...)
	io.Flush()
}

/* Math Helpers */

// MOD is 10^9 + 7
const MOD = 1000000007

// Max of the ints
func Max(numbers ...int) int {
	max := numbers[0]
	for i, number := range numbers {
		if i == 0 {
			continue
		}
		if number > max {
			max = number
		}
	}
	return max
}

// Min of the ints
func Min(numbers ...int) int {
	max := numbers[0]
	for i, number := range numbers {
		if i == 0 {
			continue
		}
		if max > number {
			max = number
		}
	}
	return max
}

// DigitSum returns sum of the int's digits
func DigitSum(n int) int {
	if n < 0 {
		return -1
	}

	res := 0

	for n > 0 {
		res += n % 10
		n /= 10
	}

	return res
}

// Sum of the ints
func Sum(numbers ...int) int {
	sum := 0

	for _, number := range numbers {
		sum += number
	}

	return sum
}

// Pow calculates the pow for int with O(log e)
func Pow(a, e int) int {
	if a < 0 || e < 0 {
		panic(fmt.Sprintf("Pow was called for a < 0 or e < 0, a: %d, e: %d", a, e))
	}

	if e == 0 {
		return 1
	}

	if e%2 == 0 {
		half := Pow(a, e/2)
		return half * half
	}

	return a * Pow(a, e-1)
}

// Abs returns the absolute value of the input
func Abs(a int) int {
	if a < 0 {
		return -a
	}

	return a
}

/* Structure Helpers */

// Set is orderless List
type Set map[interface{}]struct{}

// NewSet returns empty Set
func NewSet() *Set {
	return &Set{}
}

// Add the value to the set
func (set *Set) Add(value interface{}) {
	(*set)[value] = struct{}{}
}

// Includes check the set has the value
func (set *Set) Includes(value interface{}) bool {
	_, included := (*set)[value]
	return included
}

// Remove deletes the value from the set if exists
func (set *Set) Remove(value interface{}) {
	if !set.Includes(value) {
		return
	}

	delete(*set, value)
}

// ImmutableSort returns sorted slice without mutating original one
func ImmutableSort(slice []int) []int {
	res := make([]int, len(slice))
	copy(res, slice)
	sort.Ints(res)
	return res
}

/* Util helpers */

// Ternary is like `cond ? a : b`. should assert the returned value like `Ternary(cond, a, b).(int)`
func Ternary(cond bool, a, b interface{}) interface{} {
	if cond {
		return a
	}

	return b
}

// TernaryInt uses Ternary and assert the value as int
func TernaryInt(cond bool, a, b int) int {
	return Ternary(cond, a, b).(int)
}

// TernaryString uses Ternary and assert the value as string
func TernaryString(cond bool, a, b string) string {
	return Ternary(cond, a, b).(string)
}

Score : 1100 points

Problem Statement

We have a grid with N rows and M columns of squares.
Each integer from 1 to NM is written in this grid once.
The number written in the square at the i-th row from the top and the j-th column from the left is A_{ij}.

You need to rearrange these numbers as follows:

First, for each of the N rows, rearrange the numbers written in it as you like.

Second, for each of the M columns, rearrange the numbers written in it as you like.

Finally, for each of the N rows, rearrange the numbers written in it as you like.

After rearranging the numbers, you want the number written in the square at the i-th row from the top and the j-th column from the left to be M\times (i-1)+j.
Construct one such way to rearrange the numbers. The constraints guarantee that it is always possible to achieve the objective.

Constraints

1 \leq N,M \leq 100

1 \leq A_{ij} \leq NM

A_{ij} are distinct.

Input

Input is given from Standard Input in the following format:

N M
A_{11} A_{12} ... A_{1M}
:
A_{N1} A_{N2} ... A_{NM}

Output

Print one way to rearrange the numbers in the following format:

B_{11} B_{12} ... B_{1M}
:
B_{N1} B_{N2} ... B_{NM}
C_{11} C_{12} ... C_{1M}
:
C_{N1} C_{N2} ... C_{NM}

Here B_{ij} is the number written in the square at the i-th row from the top and the j-th column from the left after Step 1, and C_{ij} is the number written in that square after Step 2.

Sample Input 1

3 2
2 6
4 3
1 5

Sample Output 1

2 6
4 3
5 1
2 1
4 3
5 6

Sample Input 2

3 4
1 4 7 10
2 5 8 11
3 6 9 12

Sample Output 2

1 4 7 10
5 8 11 2
9 12 3 6
1 4 3 2
5 8 7 6
9 12 11 10


package main

import "fmt"

func main() {

	var a, b int
	fmt.Scan(&a, &b)

	if a+b > a-b {
		if a+b > a*b {
			fmt.Println(a + b)
		} else if a+b < a*b {
			fmt.Println(a * b)
		}
	} else if a+b < a-b {
		if a-b > a*b {
			fmt.Println(a - b)
		} else if a-b < a*b {
			fmt.Println(a * b)
		}

	}
}

Score : 100 points

Problem Statement

We have two integers: A and B.

Print the largest number among A + B, A - B, and A \times B.

Constraints

All values in input are integers.

-100 \leq A,\ B \leq 100

Input

Input is given from Standard Input in the following format:

A B

Output

Print the largest number among A + B, A - B, and A \times B.

Sample Input 1

-13 3

Sample Output 1

-10

The largest number among A + B = -10, A - B = -16, and A \times B = -39 is -10.

Sample Input 2

1 -33

Sample Output 2

34

The largest number among A + B = -32, A - B = 34, and A \times B = -33 is 34.

Sample Input 3

13 3

Sample Output 3

39

The largest number among A + B = 16, A - B = 10, and A \times B = 39 is 39.


package main

import (
	"fmt"
)

func main() {
	var a, b int
	fmt.Scanf("%d %d", &a, &b)

	tmp := a + b

	if tmp2 := a - b; tmp < tmp2 {
		tmp = tmp2
	}

	if tmp2 := a * b; tmp < tmp2 {
		tmp = tmp2
	}

	fmt.Println(tmp)
}


package main

import (
	"bufio"
	"fmt"
	"os"
	"sort"
	"strconv"
)

var s = bufio.NewScanner(os.Stdin)

func getInt() int {
	s.Scan()
	a, _ := strconv.Atoi(s.Text())
	return a
}

func main() {
	s.Split(bufio.ScanWords)
	a, b := getInt(), getInt()

	num := []int{a + b, a - b, a * b}

	sort.Ints(num)

	n := len(num)

	fmt.Println(num[n-1])

}