#|
------------------------------------
|               Utils               |
------------------------------------
|#

(eval-when (:compile-toplevel :load-toplevel :execute)
  (defparameter OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 0) (safety 3) (debug 3)))
  #+swank (progn (ql:quickload '(:cl-debug-print :fiveam))
                 (shadow :run)
                 (use-package :fiveam)))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)

#-swank
(unless (member :child-sbcl *features*)
  (quit
   :unix-status
   (process-exit-code
    (run-program *runtime-pathname*
                 `("--control-stack-size" "128MB"
                   "--noinform" "--disable-ldb" "--lose-on-corruption" "--end-runtime-options"
                   "--eval" "(push :child-sbcl *features*)"
                   "--script" ,(namestring *load-pathname*))
                 :output t :error t :input t))))

(defconstant +mod+ 1000000007)

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~a" b)) () '(signed-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~a" b)) () '(unsigned-byte ,b))) bits)))

(define-int-types 2 4 8 16 32 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1
        (write obj :stream stream)
      (fresh-line stream))))

(defmacro safe-sort (list test &key (key #'identity))
  `(progn
    (declaim (inline sort sb-impl::stable-sort-list))
    (sort (copy-seq ,list) ,test :key ,key)))

(defmacro read-numbers-to-list (size)
  `(loop repeat ,size collect (read)))

(defmacro read-numbers-to-array (size)
  (let ((i (gensym))
        (arr (gensym)))
    `(let ((,arr (make-array ,size
                             :element-type 'fixnum)))
       (declare ((array fixnum 1) ,arr))
       (loop for ,i of-type fixnum below ,size do
            (setf (aref ,arr ,i) (read))
          finally
            (return ,arr)))))

(defmacro read-characters-to-board (row-size column-size)
  (let ((board (gensym))
        (r (gensym))
        (c (gensym))
        (tmp (gensym)))
    `(let ((,board (make-array '(,row-size ,column-size) :element-type 'character :adjustable nil)))
       (dotimes (,r ,row-size ,board)
         (let ((,tmp (read-line)))
           (dotimes (,c ,column-size)
             (setf (aref ,board ,r ,c) (char ,tmp ,c))))))))

(defmethod princ-for-each-line ((sequence list))
  (format t "~{~a~&~}" sequence))

(defmethod princ-for-each-line ((sequence vector))
  (loop for i below (length sequence) do
       (princ (aref sequence i))
       (fresh-line)))

(defun unwrap (list)
  (format nil "~{~a~^ ~}" list))

(defmacro with-buffered-stdout (&body body)
  (let ((out (gensym)))
    `(let ((,out (make-string-output-stream :element-type 'base-char)))
       (let ((*standard-output* ,out))
         ,@body)
       (write-string (get-output-stream-string ,out)))))

#|
------------------------------------
|               Body               |
------------------------------------
|#

(defun solve (n m edges-arr)
  (declare (fixnum n m)
           ((array list 1) edges-arr))
  (labels ((dfs (pos &optional (cnt 0) (visited (list pos)))
             (declare (fixnum pos cnt)
                      (list visited))
             (if (= cnt (1- n))
                 1
                 (let ((edges (aref edges-arr pos)))
                   (declare (list edges))
                   (reduce #'+
                           (mapcar (lambda (node)
                                     (if (find node visited)
                                         0
                                         (dfs node (1+ cnt) (cons node visited))))
                                   edges))))))
    (dfs 0)))

(defun main ()
  (declare #.OPT)
  (let* ((n (read))
         (m (read))
         (edges (make-array n :initial-element nil)))
    (loop repeat m do
         (let ((a (1- (read)))
               (b (1- (read))))
           (push b (aref edges a))
           (push a (aref edges b))))
    (format t "~a~&" (solve n m edges))))

#-swank (main)

Score : 300 points

Problem Statement

You are given an undirected unweighted graph with N vertices and M edges that contains neither self-loops nor double edges.

Here, a self-loop is an edge where a_i = b_i (1≤i≤M), and double edges are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).

How many different paths start from vertex 1 and visit all the vertices exactly once?

Here, the endpoints of a path are considered visited.

For example, let us assume that the following undirected graph shown in Figure 1 is given.

Figure 1: an example of an undirected graph

The following path shown in Figure 2 satisfies the condition.

Figure 2: an example of a path that satisfies the condition

However, the following path shown in Figure 3 does not satisfy the condition, because it does not visit all the vertices.

Figure 3: an example of a path that does not satisfy the condition

Neither the following path shown in Figure 4, because it does not start from vertex 1.

Figure 4: another example of a path that does not satisfy the condition

Constraints

2≦N≦8

0≦M≦N(N-1)/2

1≦a_i<b_i≦N

The given graph contains neither self-loops nor double edges.

Input

The input is given from Standard Input in the following format:

N M
a_1 b_1
a_2 b_2
:
a_M b_M

Output

Print the number of the different paths that start from vertex 1 and visit all the vertices exactly once.

Sample Input 1

3 3
1 2
1 3
2 3

Sample Output 1

2

The given graph is shown in the following figure:

The following two paths satisfy the condition:

Sample Input 2

7 7
1 3
2 7
3 4
4 5
4 6
5 6
6 7

Sample Output 2

1

This test case is the same as the one described in the problem statement.


#-swank
(unless (member :child-sbcl *features*)
  (quit
   :unix-status
   (process-exit-code
    (run-program *runtime-pathname*
                 `("--control-stack-size" "128MB"
                   "--noinform" "--disable-ldb" "--lose-on-corruption" "--end-runtime-options"
                   "--eval" "(push :child-sbcl *features*)"
                   "--script" ,(namestring *load-pathname*))
                 :output t :error t :input t))))
(eval-when (:compile-toplevel :load-toplevel :execute)
  (sb-int:defconstant-eqx OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0))
    #'equal)
  #+swank (ql:quickload '(:cl-debug-print :fiveam) :silent t)
  #-swank (set-dispatch-macro-character
           ;; enclose the form with VALUES to avoid being captured by LOOP macro
           #\# #\> (lambda (s c p) (declare (ignore c p)) `(values ,(read s nil nil t)))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)
#-swank (disable-debugger) ; for CS Academy

;; BEGIN_INSERTED_CONTENTS
(macrolet ((def (name fname)
             `(define-modify-macro ,name (new-value) ,fname)))
  (def minf min)
  (def maxf max)
  (def mulf *)
  (def divf /)
  (def iorf logior)
  (def xorf logxor)
  (def andf logand))

(declaim (ftype (function * (values fixnum &optional)) read-fixnum))
(defun read-fixnum (&optional (in *standard-input*))
  "NOTE: cannot read -2^62"
  (macrolet ((%read-byte ()
               `(the (unsigned-byte 8)
                     #+swank (char-code (read-char in nil #\Nul))
                     #-swank (sb-impl::ansi-stream-read-byte in nil #.(char-code #\Nul) nil))))
    (let* ((minus nil)
           (result (loop (let ((byte (%read-byte)))
                           (cond ((<= 48 byte 57)
                                  (return (- byte 48)))
                                 ((zerop byte) ; #\Nul
                                  (error "Read EOF or #\Nul."))
                                 ((= byte #.(char-code #\-))
                                  (setq minus t)))))))
      (declare ((integer 0 #.most-positive-fixnum) result))
      (loop
        (let* ((byte (%read-byte)))
          (if (<= 48 byte 57)
              (setq result (+ (- byte 48)
                              (* 10 (the (integer 0 #.(floor most-positive-fixnum 10))
                                         result))))
              (return (if minus (- result) result))))))))

(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;;;
;;; Body
;;;

(defun main ()
  (let* ((n (read))
         (as (make-array n :element-type 'uint32))
         (graph (make-array n :element-type 'list :initial-element nil))
         (dp (make-array n :element-type 'fixnum)))
    (dotimes (i n)
      (setf (aref as i) (read-fixnum)))
    (dotimes (i (- n 1))
      (let ((a (- (read-fixnum) 1))
            (b (- (read-fixnum) 1)))
        (push a (aref graph b))
        (push b (aref graph a))))
    (sb-int:named-let dfs ((v 0) (parent -1))
      (if (and (null (cdr (aref graph v)))
               (= parent (car (aref graph v))))
          (setf (aref dp v) (aref as v))
          (let ((sum 0)
                (max 0))
            (dolist (child (aref graph v))
              (unless (= child parent)
                (let ((value (dfs child v)))
                  (incf sum value)
                  (maxf max value))))
            (let ((res (- (* (aref as v) 2) sum)))
              (dbg res sum max v dp)
              (unless (and (>= res 0)
                           (<= (- (aref as v) res)
                               (if (>= max (- sum max))
                                   (- sum max)
                                   (ash sum -1))))
                (write-line "NO")
                (return-from main))
              (setf (aref dp v) res)))))
    (write-line "YES")))

#-swank (main)

;;;
;;; Test and benchmark
;;;

#+swank
(defun io-equal (in-string out-string &key (function #'main) (test #'equal))
  "Passes IN-STRING to *STANDARD-INPUT*, executes FUNCTION, and returns true if
the string output to *STANDARD-OUTPUT* is equal to OUT-STRING."
  (labels ((ensure-last-lf (s)
             (if (eql (uiop:last-char s) #\Linefeed)
                 s
                 (uiop:strcat s uiop:+lf+))))
    (funcall test
             (ensure-last-lf out-string)
             (with-output-to-string (out)
               (let ((*standard-output* out))
                 (with-input-from-string (*standard-input* (ensure-last-lf in-string))
                   (funcall function)))))))

#+swank
(defun get-clipbrd ()
  (with-output-to-string (out)
    (run-program "powershell.exe" '("-Command" "Get-Clipboard") :output out :search t)))

#+swank (defparameter *this-pathname* (uiop:current-lisp-file-pathname))
#+swank (defparameter *dat-pathname* (uiop:merge-pathnames* "test.dat" *this-pathname*))

#+swank
(defun run (&optional thing (out *standard-output*))
  "THING := null | string | symbol | pathname

null: run #'MAIN using the text on clipboard as input.
string: run #'MAIN using the string as input.
symbol: alias of FIVEAM:RUN!.
pathname: run #'MAIN using the text file as input."
  (let ((*standard-output* out))
    (etypecase thing
      (null
       (with-input-from-string (*standard-input* (delete #\Return (get-clipbrd)))
         (main)))
      (string
       (with-input-from-string (*standard-input* (delete #\Return thing))
         (main)))
      (symbol (5am:run! thing))
      (pathname
       (with-open-file (*standard-input* thing)
         (main))))))

#+swank
(defun gen-dat ()
  (uiop:with-output-file (out *dat-pathname* :if-exists :supersede)
    (format out "")))

#+swank
(defun bench (&optional (out (make-broadcast-stream)))
  (time (run *dat-pathname* out)))

;; To run: (5am:run! :sample)
#+swank
(it.bese.fiveam:test :sample
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "5
1 2 1 1 2
2 4
5 2
3 2
1 3
"
    "YES
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "3
1 2 1
1 2
2 3
"
    "NO
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "6
3 2 2 2 2 2
1 2
2 3
1 4
1 5
4 6
"
    "YES
")))

Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.

Score : 700 points

Problem Statement

There is a tree with N vertices, numbered 1 through N.
The i-th of the N-1 edges connects vertices a_i and b_i.

Currently, there are A_i stones placed on vertex i.
Determine whether it is possible to remove all the stones from the vertices by repeatedly performing the following operation:

Select a pair of different leaves. Then, remove exactly one stone from every vertex on the path between those two vertices.
Here, a leaf is a vertex of the tree whose degree is 1, and the selected leaves themselves are also considered as vertices on the path connecting them.

Note that the operation cannot be performed if there is a vertex with no stone on the path.

Constraints

2 ≦ N ≦ 10^5

1 ≦ a_i,b_i ≦ N

0 ≦ A_i ≦ 10^9

The given graph is a tree.

Input

The input is given from Standard Input in the following format:

N
A_1 A_2 … A_N
a_1 b_1
:
a_{N-1} b_{N-1}

Output

If it is possible to remove all the stones from the vertices, print YES. Otherwise, print NO.

Sample Input 1

5
1 2 1 1 2
2 4
5 2
3 2
1 3

Sample Output 1

YES

All the stones can be removed, as follows:

Select vertices 4 and 5. Then, there is one stone remaining on each vertex except 4.

Select vertices 1 and 5. Then, there is no stone on any vertex.

Sample Input 2

3
1 2 1
1 2
2 3

Sample Output 2

NO

Sample Input 3

6
3 2 2 2 2 2
1 2
2 3
1 4
1 5
4 6

Sample Output 3

YES

Submitted source-code file size, in bytes.

Execution CPU time reported by official Project CodeNet metadata, in milliseconds.

Peak memory usage reported by official Project CodeNet metadata, in kilobytes.


Score : 100 points

Problem Statement

Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) otherwise.

You are given Smeke's current rating, x. Print ABC if Smeke will participate in ABC, and print ARC otherwise.

Constraints

1 ≦ x ≦ 3{,}000

x is an integer.

Input

The input is given from Standard Input in the following format:

x

Output

Print the answer.

Sample Input 1

1000

Sample Output 1

ABC

Smeke's current rating is less than 1200, thus the output should be ABC.

Sample Input 2

2000

Sample Output 2

ARC

Smeke's current rating is not less than 1200, thus the output should be ARC.


(princ (multiple-value-bind (x y) (ceiling (read) 11)
         (if (< y -5) (1- (* 2 x)) (* 2 x))))

Score : 300 points

Problem Statement

Snuke has decided to play with a six-sided die. Each of its six sides shows an integer 1 through 6, and two numbers on opposite sides always add up to 7.

Snuke will first put the die on the table with an arbitrary side facing upward, then repeatedly perform the following operation:

Operation: Rotate the die 90° toward one of the following directions: left, right, front (the die will come closer) and back (the die will go farther). Then, obtain y points where y is the number written in the side facing upward.

For example, let us consider the situation where the side showing 1 faces upward, the near side shows 5 and the right side shows 4, as illustrated in the figure.
If the die is rotated toward the right as shown in the figure, the side showing 3 will face upward.
Besides, the side showing 4 will face upward if the die is rotated toward the left, the side showing 2 will face upward if the die is rotated toward the front, and the side showing 5 will face upward if the die is rotated toward the back.

Find the minimum number of operation Snuke needs to perform in order to score at least x points in total.

Constraints

1 ≦ x ≦ 10^{15}

x is an integer.

Input

The input is given from Standard Input in the following format:

x

Output

Print the answer.

Sample Input 1

7

Sample Output 1

2

Sample Input 2

149696127901

Sample Output 2

27217477801


(let ((in (parse-integer (read-line))))
  (format t "~A~%"
          (multiple-value-bind (q r)
              (truncate in 11)
            (cond
              ((> r 6) (+ (* q 2) 2))
              ((= r 0) (* q 2))
              (t (1+ (* q 2)))))))


(let ((x (read))
    (ans 0))
    (setq ans (* (floor (/ x 11)) 2))
    (setq x (rem x 11))
    (if (>= x 6)
        (incf ans 2)
        (if (not (= x 0))
            (incf ans)
        )
    )
    (princ ans)
)


#-swank
(unless (member :child-sbcl *features*)
  (quit
   :unix-status
   (process-exit-code
    (run-program *runtime-pathname*
                 `("--control-stack-size" "128MB"
                   "--noinform" "--disable-ldb" "--lose-on-corruption" "--end-runtime-options"
                   "--eval" "(push :child-sbcl *features*)"
                   "--script" ,(namestring *load-pathname*))
                 :output t :error t :input t))))
(defmacro dp (name args memo-size &body body)
  (let ((memo (gensym)))
    `(let ((,memo (make-array ,memo-size :initial-element nil)))
       (defun ,name ,args
         (or (aref ,memo ,@args)
             (setf (aref ,memo ,@args)
                   ,@body))))))

(defun split (x str)
  (let ((pos (search x str))
        (size (length x)))
    (if pos
      (cons (subseq str 0 pos)
            (split x (subseq str (+ pos size))))
      (list str))))

(defmacro collect-times (time body)
  `(loop repeat ,time collect ,body))

(defun read-times (time)
  (collect-times time (read)))

(defun main (line)
  (let ((size (length (remove-duplicates line))))
    (if (oddp size)
        size
        (1- size))))

(princ (main (read-times (read))))

Score : 400 points

Problem Statement

Snuke has decided to play a game using cards.
He has a deck consisting of N cards. On the i-th card from the top, an integer A_i is written.

He will perform the operation described below zero or more times, so that the values written on the remaining cards will be pairwise distinct. Find the maximum possible number of remaining cards. Here, N is odd, which guarantees that at least one card can be kept.

Operation: Take out three arbitrary cards from the deck. Among those three cards, eat two: one with the largest value, and another with the smallest value. Then, return the remaining one card to the deck.

Constraints

3 ≦ N ≦ 10^{5}

N is odd.

1 ≦ A_i ≦ 10^{5}

A_i is an integer.

Input

The input is given from Standard Input in the following format:

N
A_1 A_2 A_3 ... A_{N}

Output

Print the answer.

Sample Input 1

5
1 2 1 3 7

Sample Output 1

3

One optimal solution is to perform the operation once, taking out two cards with 1 and one card with 2. One card with 1 and another with 2 will be eaten, and the remaining card with 1 will be returned to deck. Then, the values written on the remaining cards in the deck will be pairwise distinct: 1, 3 and 7.

Sample Input 2

15
1 3 5 2 1 3 2 8 8 6 2 6 11 1 1

Sample Output 2

7


;; -*- coding: utf-8 -*-
(eval-when (:compile-toplevel :load-toplevel :execute)
  (sb-int:defconstant-eqx OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0))
    #'equal)
  #+swank (ql:quickload '(:cl-debug-print :fiveam) :silent t)
  #-swank (set-dispatch-macro-character
           ;; enclose the form with VALUES to avoid being captured by LOOP macro
           #\# #\> (lambda (s c p) (declare (ignore c p)) `(values ,(read s nil nil t)))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)
#-swank (disable-debugger) ; for CS Academy

;; BEGIN_INSERTED_CONTENTS
(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;;;
;;; Body
;;;

(defun main ()
  (let* ((n (read))
         (as (make-array n :element-type 'uint31))
         (bs (make-array n :element-type 'uint31))
         (res 0))
    (dotimes (i n)
      (setf (aref as i) (read-fixnum)
            (aref bs i) (read-fixnum)))
    (loop for i from (- n 1) downto 0
          for a = (+ (aref as i) res)
          for b = (aref bs i)
          for dest = (* b (ceiling a b))
          do (incf res (- dest a)))
    (println res)))

#-swank (main)

;;;
;;; Test and benchmark
;;;

#+swank
(defun io-equal (in-string out-string &key (function #'main) (test #'equal))
  "Passes IN-STRING to *STANDARD-INPUT*, executes FUNCTION, and returns true if
the string output to *STANDARD-OUTPUT* is equal to OUT-STRING."
  (labels ((ensure-last-lf (s)
             (if (eql (uiop:last-char s) #\Linefeed)
                 s
                 (uiop:strcat s uiop:+lf+))))
    (funcall test
             (ensure-last-lf out-string)
             (with-output-to-string (out)
               (let ((*standard-output* out))
                 (with-input-from-string (*standard-input* (ensure-last-lf in-string))
                   (funcall function)))))))

#+swank
(defun get-clipbrd ()
  (with-output-to-string (out)
    ;; (run-program "C:/Windows/System32/WindowsPowerShell/v1.0/powershell.exe" '("get-clipboard") :output out)
    (run-program "powershell.exe" '("-Command" "Get-Clipboard") :output out :search t)))

#+swank (defparameter *this-pathname* (uiop:current-lisp-file-pathname))
#+swank (defparameter *dat-pathname* (uiop:merge-pathnames* "test.dat" *this-pathname*))

#+swank
(defun run (&optional thing (out *standard-output*))
  "THING := null | string | symbol | pathname

null: run #'MAIN using the text on clipboard as input.
string: run #'MAIN using the string as input.
symbol: alias of FIVEAM:RUN!.
pathname: run #'MAIN using the text file as input."
  (let ((*standard-output* out))
    (etypecase thing
      (null
       (with-input-from-string (*standard-input* (delete #\Return (get-clipbrd)))
         (main)))
      (string
       (with-input-from-string (*standard-input* (delete #\Return thing))
         (main)))
      (symbol (5am:run! thing))
      (pathname
       (with-open-file (*standard-input* thing)
         (main))))))

#+swank
(defun gen-dat ()
  (uiop:with-output-file (out *dat-pathname* :if-exists :supersede)
    (format out "")))

#+swank
(defun bench (&optional (out (make-broadcast-stream)))
  (time (run *dat-pathname* out)))

;; To run: (5am:run! :sample)
#+swank
(it.bese.fiveam:test :sample
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "3
3 5
2 7
9 4
"
    "7
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
"
    "22
")))

Score : 300 points

Problem Statement

There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons.
When the i-th (1 ≦ i ≦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.

There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.

Find the minimum number of times Takahashi will press the buttons.

Constraints

All input values are integers.

1 ≦ N ≦ 10^5

0 ≦ A_i ≦ 10^9(1 ≦ i ≦ N)

1 ≦ B_i ≦ 10^9(1 ≦ i ≦ N)

Input

The input is given from Standard Input in the following format:

N
A_1 B_1
:
A_N B_N

Output

Print an integer representing the minimum number of times Takahashi will press the buttons.

Sample Input 1

3
3 5
2 7
9 4

Sample Output 1

7

Press the first button twice, the second button twice and the third button three times.

Sample Input 2

7
3 1
4 1
5 9
2 6
5 3
5 8
9 7

Sample Output 2

22


#-swank
(unless (member :child-sbcl *features*)
  (quit
   :unix-status
   (process-exit-code
    (run-program *runtime-pathname*
                 `("--control-stack-size" "128MB"
                   "--noinform" "--disable-ldb" "--lose-on-corruption" "--end-runtime-options"
                   "--eval" "(push :child-sbcl *features*)"
                   "--script" ,(namestring *load-pathname*))
                 :output t :error t :input t))))
(eval-when (:compile-toplevel :load-toplevel :execute)
  (sb-int:defconstant-eqx OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0))
    #'equal)
  #+swank (ql:quickload '(:cl-debug-print :fiveam) :silent t)
  #-swank (set-dispatch-macro-character
           ;; enclose the form with VALUES to avoid being captured by LOOP macro
           #\# #\> (lambda (s c p) (declare (ignore c p)) `(values ,(read s nil nil t)))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)
#-swank (disable-debugger) ; for CS Academy

;; BEGIN_INSERTED_CONTENTS
(declaim (ftype (function * (values fixnum &optional)) read-fixnum))
(defun read-fixnum (&optional (in *standard-input*))
  "NOTE: cannot read -2^62"
  (macrolet ((%read-byte ()
               `(the (unsigned-byte 8)
                     #+swank (char-code (read-char in nil #\Nul))
                     #-swank (sb-impl::ansi-stream-read-byte in nil #.(char-code #\Nul) nil))))
    (let* ((minus nil)
           (result (loop (let ((byte (%read-byte)))
                           (cond ((<= 48 byte 57)
                                  (return (- byte 48)))
                                 ((zerop byte) ; #\Nul
                                  (error "Read EOF or #\Nul."))
                                 ((= byte #.(char-code #\-))
                                  (setq minus t)))))))
      (declare ((integer 0 #.most-positive-fixnum) result))
      (loop
        (let* ((byte (%read-byte)))
          (if (<= 48 byte 57)
              (setq result (+ (- byte 48)
                              (* 10 (the (integer 0 #.(floor most-positive-fixnum 10))
                                         result))))
              (return (if minus (- result) result))))))))

;;;
;;; Memoization macro
;;;

;;
;; Basic usage:
;;
;; (with-cache (:hash-table :test #'equal :key #'cons)
;;   (defun add (a b)
;;     (+ a b)))
;; This function caches the returned values for already passed combinations of
;; arguments. In this case ADD stores the key (CONS A B) and the returned value
;; to a hash-table when (ADD A B) is evaluated for the first time. ADD returns
;; the stored value when it is called with the same arguments (w.r.t. EQUAL)
;; again.
;;
;; The storage for cache can be hash-table or array. Let's see an example for
;; array:
;; (with-cache (:array (10 20 30) :initial-element -1 :element-type 'fixnum)
;;   (defun foo (a b c) ... ))
;; This form stores the value of FOO in an array created by (make-array (list 10
;; 20 30) :initial-element -1 :element-type 'fixnum). Note that INITIAL-ELEMENT
;; must always be given here as it is used as the flag expressing `not yet
;; stored'. (Therefore INITIAL-ELEMENT should be a value FOO never takes.)
;;
;; If you want to ignore some arguments, you can put `*' in dimensions:
;; (with-cache (:array (10 10 * 10) :initial-element -1)
;;   (defun foo (a b c d) ...)) ; then C is ignored when querying or storing cache
;;
;; Available definition forms in WITH-CACHE are DEFUN, LABELS, FLET, and
;; SB-INT:NAMED-LET.
;;
;; You can trace the memoized function by :TRACE option:
;; (with-cache (:array (10 10) :initial-element -1 :trace t)
;;   (defun foo (x y) ...))
;; Then FOO is traced as with CL:TRACE.
;;

;; TODO & NOTE: Currently a memoized function is not enclosed with a block of
;; the function name.

;; FIXME: *RECURSION-DEPTH* should be included within the macro.
(declaim (type (integer 0 #.most-positive-fixnum) *recursion-depth*))
(defparameter *recursion-depth* 0)

(eval-when (:compile-toplevel :load-toplevel :execute)
  (defun %enclose-with-trace (fname args form)
    (let ((value (gensym)))
      `(progn
         (format t "~&~A~A: (~A ~{~A~^ ~}) =>"
                 (make-string *recursion-depth*
                              :element-type 'base-char
                              :initial-element #\ )
                 *recursion-depth*
                 ',fname
                 (list ,@args))
         (let ((,value (let ((*recursion-depth* (1+ *recursion-depth*)))
                         ,form)))
           (format t "~&~A~A: (~A ~{~A~^ ~}) => ~A"
                   (make-string *recursion-depth*
                                :element-type 'base-char
                                :initial-element #\ )
                   *recursion-depth*
                   ',fname
                   (list ,@args)
                   ,value)
           ,value))))

  (defun %extract-declarations (body)
    (remove-if-not (lambda (form) (and (consp form) (eql 'declare (car form))))
                   body))

  (defun %parse-cache-form (cache-specifier)
    (let ((cache-type (car cache-specifier))
          (cache-attribs (cdr cache-specifier)))
      (assert (member cache-type '(:hash-table :array)))
      (let* ((dims-with-* (when (eql cache-type :array) (first cache-attribs)))
             (dims (remove '* dims-with-*))
             (rank (length dims))
             (rest-attribs (ecase cache-type
                             (:hash-table cache-attribs)
                             (:array (cdr cache-attribs))))
             (key (prog1 (getf rest-attribs :key) (remf rest-attribs :key)))
             (trace-p (prog1 (getf rest-attribs :trace) (remf rest-attribs :trace)))
             (cache-form (case cache-type
                           (:hash-table `(make-hash-table ,@rest-attribs))
                           (:array `(make-array (list ,@dims) ,@rest-attribs))))
             (initial-element (when (eql cache-type :array)
                                (assert (member :initial-element rest-attribs))
                                (getf rest-attribs :initial-element))))
        (let ((cache (gensym "CACHE"))
              (value (gensym))
	      (present-p (gensym))
              (name-alias (gensym))
	      (args-lst (gensym))
              (indices (loop repeat rank collect (gensym))))
          (labels
              ((make-cache-querier (cache-type name args)
                 (let ((res (case cache-type
                              (:hash-table
                               `(let ((,args-lst (funcall ,(or key '#'list) ,@args)))
                                  (multiple-value-bind (,value ,present-p)
                                      (gethash ,args-lst ,cache)
                                    (if ,present-p
                                        ,value
                                        (setf (gethash ,args-lst ,cache)
                                              (,name-alias ,@args))))))
                              (:array
                               (assert (= (length args) (length dims-with-*)))
                               (let ((memoized-args (loop for dimension in dims-with-*
                                                          for arg in args
                                                          unless (eql dimension '*)
                                                          collect arg)))
                                 (if key
                                     `(multiple-value-bind ,indices
                                          (funcall ,key ,@memoized-args)
                                        (let ((,value (aref ,cache ,@indices)))
                                          (if (eql ,initial-element ,value)
                                              (setf (aref ,cache ,@indices)
                                                    (,name-alias ,@args))
                                              ,value)))
                                     `(let ((,value (aref ,cache ,@memoized-args)))
                                        (if (eql ,initial-element ,value)
                                            (setf (aref ,cache ,@memoized-args)
                                                  (,name-alias ,@args))
                                            ,value))))))))
                   (if trace-p
                       (%enclose-with-trace name args res)
                       res)))
               (make-reset-form (cache-type)
                 (case cache-type
                   (:hash-table `(setf ,cache (make-hash-table ,@rest-attribs)))
                   (:array `(prog1 nil
                              ;; TODO: portable fill
                              (fill (array-storage-vector ,cache) ,initial-element)))))
               (make-reset-name (name)
                 (intern (format nil "RESET-~A" (symbol-name name)))))
            (values cache cache-form cache-type name-alias
                    #'make-reset-name
                    #'make-reset-form
                    #'make-cache-querier)))))))

(defmacro with-cache ((cache-type &rest cache-attribs) def-form)
  "CACHE-TYPE := :HASH-TABLE | :ARRAY.
DEF-FORM := definition form with DEFUN, LABELS, FLET, or SB-INT:NAMED-LET."
  (multiple-value-bind (cache-symbol cache-form cache-type name-alias
                        make-reset-name make-reset-form
                        make-cache-querier)
      (%parse-cache-form (cons cache-type cache-attribs))
    (ecase (car def-form)
      ((defun)
       (destructuring-bind (_ name args &body body) def-form
         (declare (ignore _))
         `(let ((,cache-symbol ,cache-form))
            (defun ,(funcall make-reset-name name) ()
              ,(funcall make-reset-form cache-type))
            (defun ,name ,args
              ,@(%extract-declarations body)
              (labels ((,name-alias ,args ,@body))
                (declare (inline ,name-alias))
                ,(funcall make-cache-querier cache-type name args))))))
      ((labels flet)
       (destructuring-bind (_ definitions &body labels-body) def-form
         (declare (ignore _))
         (destructuring-bind (name args &body body) (car definitions)
           `(let ((,cache-symbol ,cache-form))
              (,(car def-form)
               ((,(funcall make-reset-name name) ()
                 ,(funcall make-reset-form cache-type))
                (,name ,args
                       ,@(%extract-declarations body)
                       (labels ((,name-alias ,args ,@body))
                         (declare (inline ,name-alias))
                         ,(funcall make-cache-querier cache-type name args)))
                ,@(cdr definitions))
               (declare (ignorable #',(funcall make-reset-name name)))
               ,@labels-body)))))
      ((nlet #+sbcl sb-int:named-let)
       (destructuring-bind (_ name bindings &body body) def-form
         (declare (ignore _))
         `(let ((,cache-symbol ,cache-form))
            (,(car def-form) ,name ,bindings
             ,@(%extract-declarations body)
             ,(let ((args (mapcar (lambda (x) (if (atom x) x (car x))) bindings)))
                `(labels ((,name-alias ,args ,@body))
                   (declare (inline ,name-alias))
                   ,(funcall make-cache-querier cache-type name args))))))))))

(defmacro with-caches (cache-specs def-form)
  "DEF-FORM := definition form by LABELS or FLET.

 (with-caches (cache-spec1 cache-spec2)
   (labels ((f (x) ...) (g (y) ...))))
is equivalent to the line up of
 (with-cache cache-spec1 (labels ((f (x) ...))))
and
 (with-cache cache-spec2 (labels ((g (y) ...))))

This macro will be useful to do mutual recursion between memoized local
functions."
  (assert (member (car def-form) '(labels flet)))
  (let (cache-symbol-list cache-form-list cache-type-list name-alias-list make-reset-name-list make-reset-form-list make-cache-querier-list)
    (dolist (cache-spec (reverse cache-specs))
      (multiple-value-bind (cache-symbol cache-form cache-type name-alias
                            make-reset-name make-reset-form make-cache-querier)
          (%parse-cache-form cache-spec)
        (push cache-symbol cache-symbol-list)
        (push cache-form cache-form-list)
        (push cache-type cache-type-list)
        (push name-alias name-alias-list)
        (push make-reset-name make-reset-name-list)
        (push make-reset-form make-reset-form-list)
        (push make-cache-querier make-cache-querier-list)))
    (labels ((def-name (def) (first def))
             (def-args (def) (second def))
             (def-body (def) (cddr def)))
      (destructuring-bind (_ definitions &body labels-body) def-form
        (declare (ignore _))
        `(let ,(loop for cache-symbol in cache-symbol-list
                     for cache-form in cache-form-list
                     collect `(,cache-symbol ,cache-form))
           (,(car def-form)
            (,@(loop for def in definitions
                     for cache-type in cache-type-list
                     for make-reset-name in make-reset-name-list
                     for make-reset-form in make-reset-form-list
                     collect `(,(funcall make-reset-name (def-name def)) ()
                               ,(funcall make-reset-form cache-type)))
             ,@(loop for def in definitions
                     for cache-type in cache-type-list
                     for name-alias in name-alias-list
                     for make-cache-querier in make-cache-querier-list
                     collect `(,(def-name def) ,(def-args def)
                               ,@(%extract-declarations (def-body def))
                               (labels ((,name-alias ,(def-args def) ,@(def-body def)))
                                 (declare (inline ,name-alias))
                                 ,(funcall make-cache-querier cache-type (def-name def) (def-args def))))))
            (declare (ignorable ,@(loop for def in definitions
                                        for make-reset-name in make-reset-name-list
                                        collect `#',(funcall make-reset-name
                                                             (def-name def)))))
            ,@labels-body))))))

(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;;;
;;; Body
;;;

(defun main ()
  (let* ((n (read))
         (graph (make-array n :element-type 'list :initial-element nil)))
    (loop for i from 1 below n
          for a = (- (read-fixnum) 1)
          do (push i (aref graph a)))
    (println
     (with-cache (:array (100001) :element-type 'uint32 :initial-element #xffffffff)
       (sb-int:named-let recur ((v 0))
         (let ((values (sort (loop for child in (aref graph v)
                                   collect (recur child))
                             #'>)))
           (loop for value in values
                 for i from 1
                 maximize (+ value i))))))))

#-swank (main)

;;;
;;; Test and benchmark
;;;

#+swank
(defun io-equal (in-string out-string &key (function #'main) (test #'equal))
  "Passes IN-STRING to *STANDARD-INPUT*, executes FUNCTION, and returns true if
the string output to *STANDARD-OUTPUT* is equal to OUT-STRING."
  (labels ((ensure-last-lf (s)
             (if (eql (uiop:last-char s) #\Linefeed)
                 s
                 (uiop:strcat s uiop:+lf+))))
    (funcall test
             (ensure-last-lf out-string)
             (with-output-to-string (out)
               (let ((*standard-output* out))
                 (with-input-from-string (*standard-input* (ensure-last-lf in-string))
                   (funcall function)))))))

#+swank
(defun get-clipbrd ()
  (with-output-to-string (out)
    (run-program "powershell.exe" '("-Command" "Get-Clipboard") :output out :search t)))

#+swank (defparameter *this-pathname* (uiop:current-lisp-file-pathname))
#+swank (defparameter *dat-pathname* (uiop:merge-pathnames* "test.dat" *this-pathname*))

#+swank
(defun run (&optional thing (out *standard-output*))
  "THING := null | string | symbol | pathname

null: run #'MAIN using the text on clipboard as input.
string: run #'MAIN using the string as input.
symbol: alias of FIVEAM:RUN!.
pathname: run #'MAIN using the text file as input."
  (let ((*standard-output* out))
    (etypecase thing
      (null
       (with-input-from-string (*standard-input* (delete #\Return (get-clipbrd)))
         (main)))
      (string
       (with-input-from-string (*standard-input* (delete #\Return thing))
         (main)))
      (symbol (5am:run! thing))
      (pathname
       (with-open-file (*standard-input* thing)
         (main))))))

#+swank
(defun gen-dat ()
  (uiop:with-output-file (out *dat-pathname* :if-exists :supersede)
    (format out "")))

#+swank
(defun bench (&optional (out (make-broadcast-stream)))
  (time (run *dat-pathname* out)))

;; To run: (5am:run! :sample)
#+swank
(it.bese.fiveam:test :sample
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "5
1
1
2
4
"
    "3
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "7
1
2
1
3
1
4
"
    "3
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "4
4
4
1
"
    "3
")))

Score : 800 points

Problem Statement

N contestants participated in a competition. The total of N-1 matches were played in a knockout tournament.
For some reasons, the tournament may not be "fair" for all the contestants.
That is, the number of the matches that must be played in order to win the championship may be different for each contestant. The structure of the tournament is formally described at the end of this statement.

After each match, there were always one winner and one loser. The last contestant standing was declared the champion.

Figure: an example of a tournament

For convenience, the contestants were numbered 1 through N. The contestant numbered 1 was the champion, and the contestant numbered i(2 ≦ i ≦ N) was defeated in a match against the contestant numbered a_i.

We will define the depth of the tournament as the maximum number of the matches that must be played in order to win the championship over all the contestants.

Find the minimum possible depth of the tournament.

The formal description of the structure of the tournament is as follows. In the i-th match, one of the following played against each other:

Two predetermined contestants

One predetermined contestant and the winner of the j-th match, where j(j<i) was predetermined

The winner of the j-th match and the winner of the k-th match, where j and k (j,k<i, j ≠ k) were predetermined

Such structure is valid structure of the tournament, if and only if no contestant who has already been defeated in a match will never play in a match, regardless of the outcome of the matches.

Constraints

2 ≦ N ≦ 10^5

1 ≦ a_i ≦ N(2 ≦ i ≦ N)

It is guaranteed that the input is consistent (that is, there exists at least one tournament that matches the given information).

Input

The input is given from Standard Input in the following format:

N
a_2
:
a_N

Output

Print the minimum possible depth of the tournament.

Sample Input 1

5
1
1
2
4

Sample Output 1

3

The following tournament and the result of the matches are consistent with the given information:

In the first match, contestants 4 and 5 played against each other, and contestant 4 won.

In the second match, contestants 2 and 4 played against each other, and contestant 2 won.

In the third match, contestants 1 and 3 played against each other, and contestant 1 won.

In the fourth match, contestants 1 and 2 played against each other, and contestant 1 won.

The depth of this tournament is 3, since contestant 5 must play three matches in order to win the championship.
There is no tournament with depth 2 or less that is consistent with the given information, thus the output should be 3.

Sample Input 2

7
1
2
1
3
1
4

Sample Output 2

3

Sample Input 3

4
4
4
1

Sample Output 3

3


(defun area (h w) (* h w))
(write (max (area (read) (read))
            (area (read) (read))))

Score : 100 points

Problem Statement

There are two rectangles.
The lengths of the vertical sides of the first rectangle are A, and the lengths of the horizontal sides of the first rectangle are B.
The lengths of the vertical sides of the second rectangle are C, and the lengths of the horizontal sides of the second rectangle are D.

Print the area of the rectangle with the larger area.
If the two rectangles have equal areas, print that area.

Constraints

All input values are integers.

1≤A≤10^4

1≤B≤10^4

1≤C≤10^4

1≤D≤10^4

Input

The input is given from Standard Input in the following format:

A B C D

Output

Print the area of the rectangle with the larger area.
If the two rectangles have equal areas, print that area.

Sample Input 1

3 5 2 7

Sample Output 1

15

The first rectangle has an area of 3×5=15, and the second rectangle has an area of 2×7=14.
Thus, the output should be 15, the larger area.

Sample Input 2

100 600 200 300

Sample Output 2

60000


(setq n(read))
(setq s(read-line))
(setq a 0)
(setq u 0)
(dotimes(i n)(if(char=(char s i)#\I)(incf u)(decf u))(setq a(max a u)))
(princ a)

Score : 200 points

Problem Statement

You have an integer variable x.
Initially, x=0.

Some person gave you a string S of length N, and using the string you performed the following operation N times.
In the i-th operation, you incremented the value of x by 1 if S_i=I, and decremented the value of x by 1 if S_i=D.

Find the maximum value taken by x during the operations (including before the first operation, and after the last operation).

Constraints

1≤N≤100

|S|=N

No characters except I and D occur in S.

Input

The input is given from Standard Input in the following format:

N
S

Output

Print the maximum value taken by x during the operations.

Sample Input 1

5
IIDID

Sample Output 1

2

After each operation, the value of x becomes 1, 2, 1, 2 and 1, respectively. Thus, the output should be 2, the maximum value.

Sample Input 2

7
DDIDDII

Sample Output 2

0

The initial value x=0 is the maximum value taken by x, thus the output should be 0.


;; -*- coding: utf-8 -*-
(eval-when (:compile-toplevel :load-toplevel :execute)
  (defparameter OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0)))
  #+swank (progn (ql:quickload '(:cl-debug-print :fiveam))
                 (shadow :run)
                 (use-package :fiveam))
  #-swank (set-dispatch-macro-character #\# #\> (lambda (s c p) (declare (ignore c p)) (read s nil (values) t))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)

;; BEGIN_INSERTED_CONTENTS
(declaim (ftype (function * (values fixnum &optional)) read-fixnum))
(defun read-fixnum (&optional (in *standard-input*))
  (macrolet ((%read-byte ()
               `(the (unsigned-byte 8)
                     #+swank (char-code (read-char in nil #\Nul))
                     #-swank (sb-impl::ansi-stream-read-byte in nil #.(char-code #\Nul) nil))))
    (let* ((minus nil)
           (result (loop (let ((byte (%read-byte)))
                           (cond ((<= 48 byte 57)
                                  (return (- byte 48)))
                                 ((zerop byte) ; #\Nul
                                  (error "Read EOF or #\Nul."))
                                 ((= byte #.(char-code #\-))
                                  (setf minus t)))))))
      (declare ((integer 0 #.most-positive-fixnum) result))
      (loop
        (let* ((byte (%read-byte)))
          (if (<= 48 byte 57)
              (setq result (+ (- byte 48) (* 10 (the (integer 0 #.(floor most-positive-fixnum 10)) result))))
              (return (if minus (- result) result))))))))

(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;; Body

(defun main ()
  (let* ((n (read))
         (a (read))
         (b (read))
         (xs (make-array n :element-type 'uint32))
         (res 0))
    (dotimes (i n) (setf (aref xs i) (read-fixnum)))
    (loop for i from 1 below n
          do (incf res (min b (* (- (aref xs i) (aref xs (- i 1))) a))))
    (println res)))

#-swank(main)

;; For Test
#+swank
(defun io-equal (in-string out-string &optional (func #'main))
  "Passes IN-STRING to *STANDARD-INPUT*, executes FUNC, and returns true if the
string output to *STANDARD-OUTPUT* is equal to OUT-STRING."
  (labels ((ensure-last-lf (s)
             (if (and (> (length s) 0)
                      (eql (char s (- (length s) 1)) #\Linefeed))
                 s
                 (uiop:strcat s uiop:+lf+))))
    (equal (ensure-last-lf out-string)
           (with-output-to-string (out)
             (let ((*standard-output* out))
               (with-input-from-string (*standard-input* (ensure-last-lf in-string))
                 (funcall func)))))))

#+swank
(defun get-clipbrd ()
  (with-output-to-string (out)
    (run-program "C:/msys64/usr/bin/cat.exe" '("/dev/clipboard") :output out)))

#+swank (defparameter *this-pathname* (uiop:current-lisp-file-pathname))
#+swank (defparameter *dat-pathname* (uiop:merge-pathnames* "test.dat" *this-pathname*))

#+swank
(defun run (&optional thing (out *standard-output*))
  (let ((*standard-output* out))
    (etypecase thing
      (null ; Runs #'MAIN with the string on clipboard
       (with-input-from-string (*standard-input* (delete #\Return (get-clipbrd)))
         (main)))
      (string
       (with-input-from-string (*standard-input* (delete #\Return thing))
         (main)))
      (symbol (5am:run! thing))
      (pathname ; Runs #'MAIN with the string in a text file
       (with-open-file (*standard-input* thing)
         (main))))))

#+swank
(defun gen-dat ()
  (uiop:with-output-file (out *dat-pathname* :if-exists :supersede)
    (format out "")))

#+swank
(defun bench (&optional (out (make-broadcast-stream)))
  (time (run *dat-pathname* out)))

;; To run: (5am:run! :sample)
#+swank
(it.bese.fiveam:test :sample
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "4 2 5
1 2 5 7
"
    "11
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "7 1 100
40 43 45 105 108 115 124
"
    "84
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "7 1 2
24 35 40 68 72 99 103
"
    "12
")))

Score : 500 points

Problem Statement

There are N towns on a line running east-west.
The towns are numbered 1 through N, in order from west to east.
Each point on the line has a one-dimensional coordinate, and a point that is farther east has a greater coordinate value.
The coordinate of town i is X_i.

You are now at town 1, and you want to visit all the other towns.
You have two ways to travel:

Walk on the line.
Your fatigue level increases by A each time you travel a distance of 1, regardless of direction.

Teleport to any location of your choice.
Your fatigue level increases by B, regardless of the distance covered.

Find the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.

Constraints

All input values are integers.

2≤N≤10^5

1≤X_i≤10^9

For all i(1≤i≤N-1), X_i<X_{i+1}.

1≤A≤10^9

1≤B≤10^9

Input

The input is given from Standard Input in the following format:

N A B
X_1 X_2 ... X_N

Output

Print the minimum possible total increase of your fatigue level when you visit all the towns.

Sample Input 1

4 2 5
1 2 5 7

Sample Output 1

11

From town 1, walk a distance of 1 to town 2, then teleport to town 3, then walk a distance of 2 to town 4.
The total increase of your fatigue level in this case is 2×1+5+2×2=11, which is the minimum possible value.

Sample Input 2

7 1 100
40 43 45 105 108 115 124

Sample Output 2

84

From town 1, walk all the way to town 7.
The total increase of your fatigue level in this case is 84, which is the minimum possible value.

Sample Input 3

7 1 2
24 35 40 68 72 99 103

Sample Output 3

12

Visit all the towns in any order by teleporting six times.
The total increase of your fatigue level in this case is 12, which is the minimum possible value.


#|
------------------------------------
|               Utils               |
------------------------------------
|#

(eval-when (:compile-toplevel :load-toplevel :execute)
  (defparameter OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0)))
  #+swank (progn (ql:quickload '(:cl-debug-print :fiveam))
                 (shadow :run)
                 (use-package :fiveam)))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)

#-swank
(unless (member :child-sbcl *features*)
  (quit
   :unix-status
   (process-exit-code
    (run-program *runtime-pathname*
                 `("--control-stack-size" "128MB"
                   "--noinform" "--disable-ldb" "--lose-on-corruption" "--end-runtime-options"
                   "--eval" "(push :child-sbcl *features*)"
                   "--script" ,(namestring *load-pathname*))
                 :output t :error t :input t))))

(defconstant +mod+ 1000000007)

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~a" b)) () '(signed-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~a" b)) () '(unsigned-byte ,b))) bits)))

(define-int-types 2 4 8 16 32 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1
        (write obj :stream stream)
      (fresh-line stream))))

(defmacro safe-sort (list test &key (key #'identity))
  `(progn
    (declaim (inline sort sb-impl::stable-sort-list))
    (sort (copy-seq ,list) ,test :key ,key)))

(defmacro read-numbers-to-list (size)
  `(loop repeat ,size collect (read)))

(defmacro read-numbers-to-array (size)
  (let ((i (gensym))
        (arr (gensym)))
    `(let ((,arr (make-array ,size
                             :element-type 'fixnum)))
       (declare ((array fixnum 1) ,arr))
       (loop for ,i of-type fixnum below ,size do
            (setf (aref ,arr ,i) (read))
          finally
            (return ,arr)))))

(defmacro read-characters-to-board (row-size column-size)
  (let ((board (gensym))
        (r (gensym))
        (c (gensym))
        (tmp (gensym)))
    `(let ((,board (make-array '(,row-size ,column-size) :element-type 'character :adjustable nil)))
       (dotimes (,r ,row-size ,board)
         (let ((,tmp (read-line)))
           (dotimes (,c ,column-size)
             (setf (aref ,board ,r ,c) (char ,tmp ,c))))))))

(defmethod princ-for-each-line ((sequence list))
  (format t "~{~a~&~}" sequence))

(defmethod princ-for-each-line ((sequence vector))
  (loop for i below (length sequence) do
       (princ (aref sequence i))
       (fresh-line)))

(declaim (inline unwrap))
(defun unwrap (list)
  (the string
       (format nil "~{~a~^ ~}" list)))

(defmacro with-buffered-stdout (&body body)
  (let ((out (gensym)))
    `(let ((,out (make-string-output-stream :element-type 'base-char)))
       (let ((*standard-output* ,out))
         ,@body)
       (write-string (get-output-stream-string ,out)))))

(defmacro maxf (place cand)
  `(setf ,place (max ,place ,cand)))

(defmacro minf (place cand)
  `(setf ,place (min ,place ,cand)))

(defmacro alambda (parms &body body)
  `(labels ((self ,parms ,@body))
     #'self))

(defun iota (count &optional (start 0) (step 1))
  (loop for i from 0 below count collect (+ start (* i step))))

#|
------------------------------------
|               Body               |
------------------------------------
|#

(defun solve (sx sy gx gy)
  (let ((dx (- gx sx))
        (dy (- gy sy)))
    (concatenate 'string
                 (loop repeat dx collect #\R)
                 (loop repeat dy collect #\U)
                 (loop repeat dy collect #\L)
                 (loop repeat dy collect #\D)
                 '(#\D)
                 (loop repeat (+ dx 1) collect #\R)
                 (loop repeat (+ dy 1) collect #\U)
                 '(#\L)
                 '(#\U)
                 (loop repeat (+ dx 1) collect #\L)
                 (loop repeat (+ dy 1) collect #\D)
                 '(#\R))))

(defun main ()
  (declare #.OPT)
  (destructuring-bind (sx sy gx gy) (loop repeat 4 collect (read))
    (princ (solve sx sy gx gy))
    (fresh-line)))

#-swank (main)

Score : 300 points

Problem Statement

Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.

Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.

Here, both the x- and y-coordinates before and after each movement must be integers.

He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).

Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).

Under this condition, find a shortest path for him.

Constraints

-1000 ≤ sx < tx ≤ 1000

-1000 ≤ sy < ty ≤ 1000

sx,sy,tx and ty are integers.

Input

The input is given from Standard Input in the following format:

sx sy tx ty

Output

Print a string S that represents a shortest path for Dolphin.

The i-th character in S should correspond to his i-th movement.

The directions of the movements should be indicated by the following characters:

U: Up

D: Down

L: Left

R: Right

If there exist multiple shortest paths under the condition, print any of them.

Sample Input 1

0 0 1 2

Sample Output 1

UURDDLLUUURRDRDDDLLU

One possible shortest path is:

Going from (sx,sy) to (tx,ty) for the first time: (0,0) → (0,1) → (0,2) → (1,2)

Going from (tx,ty) to (sx,sy) for the first time: (1,2) → (1,1) → (1,0) → (0,0)

Going from (sx,sy) to (tx,ty) for the second time: (0,0) → (-1,0) → (-1,1) → (-1,2) → (-1,3) → (0,3) → (1,3) → (1,2)

Going from (tx,ty) to (sx,sy) for the second time: (1,2) → (2,2) → (2,1) → (2,0) → (2,-1) → (1,-1) → (0,-1) → (0,0)

Sample Input 2

-2 -2 1 1

Sample Output 2

UURRURRDDDLLDLLULUUURRURRDDDLLDL


(defun split (str delim)
  (let ((res (make-array 1 :element-type 'string
                           :fill-pointer 0
                           :adjustable t)))
    (loop for i from 0 below (length str)
          with start = 0
          when (eq (char str i) delim)
          do (vector-push-extend (subseq str start i) res)
             (setf start (1+ i))
          finally (let ((tail (subseq str start)))
                    (when tail
                      (vector-push-extend tail res))))
    res))

(let* ((in (map 'vector #'parse-integer (split (read-line) #\Space)))
       (x (aref in 0))
       (y (aref in 1))
       (xplus (plusp x))
       (yplus (plusp y)))
  (if (= x y)
      (format t "~A~%" 0)
      (if (= x 0)
          (if yplus
              (format t "~A~%" y)
              (format t "~A~%" (1+ y)))
          (if (= y 0)
              (if xplus
                  (format t "~A~%" (1+ x))
                  (format t "~A~%" x))
              (if (eq xplus yplus)
                  (if (> x y)
                      (format t "~A~%" (+ (- x y) 2))
                      (format t "~A~%" (- y x)))
                  (if xplus
                      (if (> (abs x) (abs y))
                          (format t "~A~%" (1+ (+ x y)))
                          (format t "~A~%" (1+ (-(+ x y)))))
                      (if (> (abs x) (abs y))
                          (format t "~A~%" (1+ (- (+ x y))))
                          (format t "~A~%" (1+ (+ x y))))))))))

Score : 300 points

Problem Statement

Snuke has a calculator. It has a display and two buttons.

Initially, the display shows an integer x.
Snuke wants to change this value into another integer y, by pressing the following two buttons some number of times in arbitrary order:

Button A: When pressed, the value on the display is incremented by 1.

Button B: When pressed, the sign of the value on the display is reversed.

Find the minimum number of times Snuke needs to press the buttons to achieve his objective.
It can be shown that the objective is always achievable regardless of the values of the integers x and y.

Constraints

x and y are integers.

|x|, |y| ≤ 10^9

x and y are different.

Input

The input is given from Standard Input in the following format:

x y

Output

Print the minimum number of times Snuke needs to press the buttons to achieve his objective.

Sample Input 1

10 20

Sample Output 1

10

Press button A ten times.

Sample Input 2

10 -10

Sample Output 2

1

Press button B once.

Sample Input 3

-10 -20

Sample Output 3

12

Press the buttons as follows:

Press button B once.

Press button A ten times.

Press button B once.


;; -*- coding: utf-8 -*-
(eval-when (:compile-toplevel :load-toplevel :execute)
  (defparameter OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0)))
  #+swank (progn (ql:quickload '(:cl-debug-print :fiveam))
                 (shadow :run)
                 (use-package :fiveam))
  #-swank (set-dispatch-macro-character #\# #\> (lambda (s c p) (declare (ignore c p)) (read s nil (values) t))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)

;; BEGIN_INSERTED_CONTENTS
(declaim (ftype (function * (values fixnum &optional)) read-fixnum))
(defun read-fixnum (&optional (in *standard-input*))
  (macrolet ((%read-byte ()
               `(the (unsigned-byte 8)
                     #+swank (char-code (read-char in nil #\Nul))
                     #-swank (sb-impl::ansi-stream-read-byte in nil #.(char-code #\Nul) nil))))
    (let* ((minus nil)
           (result (loop (let ((byte (%read-byte)))
                           (cond ((<= 48 byte 57)
                                  (return (- byte 48)))
                                 ((zerop byte) ; #\Nul
                                  (error "Read EOF or #\Nul."))
                                 ((= byte #.(char-code #\-))
                                  (setf minus t)))))))
      (declare ((integer 0 #.most-positive-fixnum) result))
      (loop
        (let* ((byte (%read-byte)))
          (if (<= 48 byte 57)
              (setq result (+ (- byte 48) (* 10 (the (integer 0 #.(floor most-positive-fixnum 10)) result))))
              (return (if minus (- result) result))))))))

(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;; Body

(defun main ()
  (let* ((n (read))
         (k (read))
         (cumuls+ (make-array (+ 1 n) :element-type 'fixnum :initial-element 0))
         (cumuls (make-array (+ 1 n) :element-type 'fixnum :initial-element 0)))
    (declare (uint32 n k))
    (dotimes (i n)
      (let ((a (read-fixnum)))
        (setf (aref cumuls+ (+ i 1)) (+ (max 0 a) (aref cumuls+ i))
              (aref cumuls (+ i 1)) (+ a (aref cumuls i)))))
    (println
      (loop for cept from 0 to (- n k)
            maximize (+ (aref cumuls+ cept)
                        (- (aref cumuls+ n)
                           (aref cumuls+ (+ cept k)))
                        (max 0 (- (aref cumuls (+ cept k))
                                  (aref cumuls cept))))
            of-type fixnum))))

#-swank(main)

Score : 400 points

Problem Statement

There are N squares aligned in a row.
The i-th square from the left contains an integer a_i.

Initially, all the squares are white.
Snuke will perform the following operation some number of times:

Select K consecutive squares. Then, paint all of them white, or paint all of them black. Here, the colors of the squares are overwritten.

After Snuke finishes performing the operation, the score will be calculated as the sum of the integers contained in the black squares.
Find the maximum possible score.

Constraints

1≤N≤10^5

1≤K≤N

a_i is an integer.

|a_i|≤10^9

Input

The input is given from Standard Input in the following format:

N K
a_1 a_2 ... a_N

Output

Print the maximum possible score.

Sample Input 1

5 3
-10 10 -10 10 -10

Sample Output 1

10

Paint the following squares black: the second, third and fourth squares from the left.

Sample Input 2

4 2
10 -10 -10 10

Sample Output 2

20

One possible way to obtain the maximum score is as follows:

Paint the following squares black: the first and second squares from the left.

Paint the following squares black: the third and fourth squares from the left.

Paint the following squares white: the second and third squares from the left.

Sample Input 3

1 1
-10

Sample Output 3

0

Sample Input 4

10 5
5 -4 -5 -8 -4 7 2 -4 0 7

Sample Output 4

17


;; -*- coding: utf-8 -*-
(eval-when (:compile-toplevel :load-toplevel :execute)
  (sb-int:defconstant-eqx OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0))
    #'equal)
  #+swank (ql:quickload '(:cl-debug-print :fiveam) :silent t)
  #-swank (set-dispatch-macro-character
           #\# #\> (lambda (s c p) (declare (ignore c p)) (read s nil nil t))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)
#-swank (disable-debugger) ; for CS Academy

;; BEGIN_INSERTED_CONTENTS
(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;;;
;;; Body
;;;

(define-condition fin () ())

(defun main ()
  (let* ((ai (read))
         (ao (read))
         (at (read))
         (aj (read))
         (al (read))
         (as (read))
         (az (read))
         (res 0))
    (declare (ignore at as az))
    (incf res (* ao 2))
    (when (or (zerop ai) (zerop aj) (zerop al))
      (incf res (* 4 (floor ai 2)))
      (incf res (* 4 (floor aj 2)))
      (incf res (* 4 (floor al 2)))
      (println (floor res 2))
      (return-from main))
    (assert (and (>= ai 1) (>= aj 1) (>= al 1)))
    (if (oddp ai)
        (progn (incf res (* 2 (- ai 1)))
               (setf ai 1))
        (progn (incf res (* 2 (- ai 2)))
               (setf ai 2)))
    (if (oddp aj)
        (progn (incf res (* 2 (- aj 1)))
               (setf aj 1))
        (progn (incf res (* 2 (- aj 2)))
               (setf aj 2)))
    (if (oddp al)
        (progn (incf res (* 2 (- al 1)))
               (setf al 1))
        (progn (incf res (* 2 (- al 2)))
               (setf al 2)))
    (cond ((and (= ai 2) (= aj 2) (= al 2))
           (incf res 12))
          ((and (= ai 2) (= aj 2) (= al 1))
           (incf res 8))
          ((and (= ai 2) (= aj 1) (= al 2))
           (incf res 8))
          ((and (= ai 2) (= aj 1) (= al 1))
           (incf res 6))
          ((and (= ai 1) (= aj 2) (= al 2))
           (incf res 8))
          ((and (= ai 1) (= aj 2) (= al 1))
           (incf res 6))
          ((and (= ai 1) (= aj 1) (= al 2))
           (incf res 6))
          ((and (= ai 1) (= aj 1) (= al 1))
           (incf res 6))
          (t (error "Huh?")))
    (println (floor res 2))))

#-swank (main)

;;;
;;; Test and benchmark
;;;

#+swank
(defun io-equal (in-string out-string &key (function #'main) (test #'equal))
  "Passes IN-STRING to *STANDARD-INPUT*, executes FUNCTION, and returns true if
the string output to *STANDARD-OUTPUT* is equal to OUT-STRING."
  (labels ((ensure-last-lf (s)
             (if (eql (uiop:last-char s) #\Linefeed)
                 s
                 (uiop:strcat s uiop:+lf+))))
    (funcall test
             (ensure-last-lf out-string)
             (with-output-to-string (out)
               (let ((*standard-output* out))
                 (with-input-from-string (*standard-input* (ensure-last-lf in-string))
                   (funcall function)))))))

#+swank
(defun get-clipbrd ()
  (with-output-to-string (out)
    (run-program "C:/msys64/usr/bin/cat.exe" '("/dev/clipboard") :output out)))

#+swank (defparameter *this-pathname* (uiop:current-lisp-file-pathname))
#+swank (defparameter *dat-pathname* (uiop:merge-pathnames* "test.dat" *this-pathname*))

#+swank
(defun run (&optional thing (out *standard-output*))
  "THING := null | string | symbol | pathname

null: run #'MAIN using the text on clipboard as input.
string: run #'MAIN using the string as input.
symbol: alias of FIVEAM:RUN!.
pathname: run #'MAIN using the text file as input."
  (let ((*standard-output* out))
    (etypecase thing
      (null
       (with-input-from-string (*standard-input* (delete #\Return (get-clipbrd)))
         (main)))
      (string
       (with-input-from-string (*standard-input* (delete #\Return thing))
         (main)))
      (symbol (5am:run! thing))
      (pathname
       (with-open-file (*standard-input* thing)
         (main))))))

#+swank
(defun gen-dat ()
  (uiop:with-output-file (out *dat-pathname* :if-exists :supersede)
    (format out "")))

#+swank
(defun bench (&optional (out (make-broadcast-stream)))
  (time (run *dat-pathname* out)))

;; To run: (5am:run! :sample)
#+swank
(it.bese.fiveam:test :sample
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "2 1 1 0 0 0 0
"
    "3
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "0 0 10 0 0 0 0
"
    "0
")))

Score : 600 points

Problem Statement

A tetromino is a figure formed by joining four squares edge to edge.
We will refer to the following seven kinds of tetromino as I-, O-, T-, J-, L-, S- and Z-tetrominos, respectively:

Snuke has many tetrominos. The number of I-, O-, T-, J-, L-, S- and Z-tetrominos in his possession are a_I, a_O, a_T, a_J, a_L, a_S and a_Z, respectively.
Snuke will join K of his tetrominos to form a rectangle that is two squares tall and 2K squares wide.
Here, the following rules must be followed:

When placing each tetromino, rotation is allowed, but reflection is not.

Each square in the rectangle must be covered by exactly one tetromino.

No part of each tetromino may be outside the rectangle.

Snuke wants to form as large a rectangle as possible.
Find the maximum possible value of K.

Constraints

0≤a_I,a_O,a_T,a_J,a_L,a_S,a_Z≤10^9

a_I+a_O+a_T+a_J+a_L+a_S+a_Z≥1

Input

The input is given from Standard Input in the following format:

a_I a_O a_T a_J a_L a_S a_Z

Output

Print the maximum possible value of K. If no rectangle can be formed, print 0.

Sample Input 1

2 1 1 0 0 0 0

Sample Output 1

3

One possible way to form the largest rectangle is shown in the following figure:

Sample Input 2

0 0 10 0 0 0 0

Sample Output 2

0

No rectangle can be formed.


(eval-when (:compile-toplevel :load-toplevel :execute)
  (sb-int:defconstant-eqx OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0))
    #'equal)
  #+swank (ql:quickload '(:cl-debug-print :fiveam) :silent t)
  #-swank (set-dispatch-macro-character
           ;; enclose the form with VALUES to avoid being captured by LOOP macro
           #\# #\> (lambda (s c p) (declare (ignore c p)) `(values ,(read s nil nil t)))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)
#-swank (disable-debugger) ; for CS Academy

;; BEGIN_INSERTED_CONTENTS
(declaim (inline println-sequence))
(defun println-sequence (sequence &key (out *standard-output*) (key #'identity))
  (let ((init t))
    (sequence:dosequence (x sequence)
      (if init
          (setq init nil)
          (write-char #\  out))
      (princ (funcall key x) out))
    (terpri out)))

(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;;;
;;; Body
;;;

(defun main ()
  (let* ((n (read))
         ;; number . position
         (nodes (make-array n :element-type 'list))
         (as (make-array (* n n) :element-type 'uint32))
         (reserved (make-array (* n n) :element-type 'bit :initial-element 0)))
    (dotimes (i n)
      (let ((x (- (read) 1)))
        (setf (aref nodes i) (cons (+ i 1) x)
              (aref reserved x) 1)))
    (setq nodes (sort nodes #'< :key #'cdr))
    #>nodes
    (let ((indices (loop for i below (* n n)
                         when (zerop (aref reserved i))
                         collect i)))
      (let (rest)
        (loop for (num . pivot) across nodes
              do (setf (aref as pivot) num)
                 (loop repeat (- num 1)
                       for i = (pop indices)
                       do (when (> i pivot)
                            (write-line "No")
                            (return-from main))
                          (setf (aref as i) num))
                 (loop repeat (- n num)
                       do (push (cons num pivot) rest)))
        #>as
        (loop for (num . pivot) in (reverse rest)
              for idx = (pop indices)
              do (when (< idx pivot)
                   (write-line "No")
                   (return-from main))
                 (setf (aref as idx) num))))
    (write-line "Yes")
    (println-sequence as)))

#-swank (main)

;;;
;;; Test and benchmark
;;;

#+swank
(defun io-equal (in-string out-string &key (function #'main) (test #'equal))
  "Passes IN-STRING to *STANDARD-INPUT*, executes FUNCTION, and returns true if
the string output to *STANDARD-OUTPUT* is equal to OUT-STRING."
  (labels ((ensure-last-lf (s)
             (if (eql (uiop:last-char s) #\Linefeed)
                 s
                 (uiop:strcat s uiop:+lf+))))
    (funcall test
             (ensure-last-lf out-string)
             (with-output-to-string (out)
               (let ((*standard-output* out))
                 (with-input-from-string (*standard-input* (ensure-last-lf in-string))
                   (funcall function)))))))

#+swank
(defun get-clipbrd ()
  (with-output-to-string (out)
    (run-program "powershell.exe" '("-Command" "Get-Clipboard") :output out :search t)))

#+swank (defparameter *this-pathname* (uiop:current-lisp-file-pathname))
#+swank (defparameter *dat-pathname* (uiop:merge-pathnames* "test.dat" *this-pathname*))

#+swank
(defun run (&optional thing (out *standard-output*))
  "THING := null | string | symbol | pathname

null: run #'MAIN using the text on clipboard as input.
string: run #'MAIN using the string as input.
symbol: alias of FIVEAM:RUN!.
pathname: run #'MAIN using the text file as input."
  (let ((*standard-output* out))
    (etypecase thing
      (null
       (with-input-from-string (*standard-input* (delete #\Return (get-clipbrd)))
         (main)))
      (string
       (with-input-from-string (*standard-input* (delete #\Return thing))
         (main)))
      (symbol (5am:run! thing))
      (pathname
       (with-open-file (*standard-input* thing)
         (main))))))

#+swank
(defun gen-dat ()
  (uiop:with-output-file (out *dat-pathname* :if-exists :supersede)
    (format out "")))

#+swank
(defun bench (&optional (out (make-broadcast-stream)))
  (time (run *dat-pathname* out)))

;; To run: (5am:run! :sample)
#+swank
(it.bese.fiveam:test :sample
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "3
1 5 9
"
    "Yes
1 1 1 2 2 2 3 3 3
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "2
4 1
"
    "No
")))

Score : 800 points

Problem Statement

You are given an integer sequence x of length N.
Determine if there exists an integer sequence a that satisfies all of the following conditions, and if it exists, construct an instance of a.

a is N^2 in length, containing N copies of each of the integers 1, 2, ..., N.

For each 1 ≤ i ≤ N, the i-th occurrence of the integer i from the left in a is the x_i-th element of a from the left.

Constraints

1 ≤ N ≤ 500

1 ≤ x_i ≤ N^2

All x_i are distinct.

Input

The input is given from Standard Input in the following format:

N
x_1 x_2 ... x_N

Output

If there does not exist an integer sequence a that satisfies all the conditions, print No.
If there does exist such an sequence a, print Yes in the first line, then print an instance of a in the second line, with spaces inbetween.

Sample Input 1

3
1 5 9

Sample Output 1

Yes
1 1 1 2 2 2 3 3 3

For example, the second occurrence of the integer 2 from the left in a in the output is the fifth element of a from the left.
Similarly, the condition is satisfied for the integers 1 and 3.

Sample Input 2

2
4 1

Sample Output 2

No


(defun split (string &key (delimiterp #'delimiterp))
  (loop :for beg = (position-if-not delimiterp string)
    :then (position-if-not delimiterp string :start (1+ end))
    :for end = (and beg (position-if delimiterp string :start beg))
    :when beg :collect (subseq string beg end)
    :while end))
(defun delimiterp (c) (position c " ,.;/"))

(defun make-array-from-list (l)
  (make-array (list (length l)) :initial-contents l)
  )

(defun main()
  (let* ((n (read))
        (ts (make-array-from-list (map 'list #'parse-integer (split (read-line)))))
        (m (read))
        (sum (reduce #'+ ts)))

    (loop :for i :below m :do
          (let ((p (read)) (x (read)))
            (princ (+ (- sum (aref ts (1- p))) x))
            (princ #\newline))))
)
(main)

Score : 200 points

Problem Statement

Joisino is about to compete in the final round of a certain programming competition.
In this contest, there are N problems, numbered 1 through N.
Joisino knows that it takes her T_i seconds to solve problem i(1≦i≦N).

Also, there are M kinds of drinks offered to the contestants, numbered 1 through M.
If Joisino takes drink i(1≦i≦M), her brain will be stimulated and the time it takes for her to solve problem P_i will become X_i seconds.
It does not affect the time to solve the other problems.

A contestant is allowed to take exactly one of the drinks before the start of the contest.
For each drink, Joisino wants to know how many seconds it takes her to solve all the problems if she takes that drink.
Here, assume that the time it takes her to solve all the problems is equal to the sum of the time it takes for her to solve individual problems.
Your task is to write a program to calculate it instead of her.

Constraints

All input values are integers.

1≦N≦100

1≦T_i≦10^5

1≦M≦100

1≦P_i≦N

1≦X_i≦10^5

Input

The input is given from Standard Input in the following format:

N
T_1 T_2 ... T_N
M
P_1 X_1
P_2 X_2
:
P_M X_M

Output

For each drink, calculate how many seconds it takes Joisino to solve all the problems if she takes that drink, and print the results, one per line.

Sample Input 1

3
2 1 4
2
1 1
2 3

Sample Output 1

6
9

If Joisino takes drink 1, the time it takes her to solve each problem will be 1, 1 and 4 seconds, respectively, totaling 6 seconds.

If Joisino takes drink 2, the time it takes her to solve each problem will be 2, 3 and 4 seconds, respectively, totaling 9 seconds.

Sample Input 2

5
7 2 3 8 5
3
4 2
1 7
4 13

Sample Output 2

19
25
30


(defparameter *vowels* '(#\a #\e #\i #\o #\u))
(defun result ()
  (if (find (read-char) *vowels*)
    (princ "vowel\n")
    (princ "consonant\n")))
(result)

Score : 100 points

Problem Statement

Given a lowercase English letter c, determine whether it is a vowel. Here, there are five vowels in the English alphabet: a, e, i, o and u.

Constraints

c is a lowercase English letter.

Input

The input is given from Standard Input in the following format:

c

Output

If c is a vowel, print vowel. Otherwise, print consonant.

Sample Input 1

a

Sample Output 1

vowel

Since a is a vowel, print vowel.

Sample Input 2

z

Sample Output 2

consonant

Sample Input 3

s

Sample Output 3

consonant


(let* ((h (read))
    (w (read))
    (c (make-array h)))
    (loop for i below h do
        (setf (aref c i) (read-line))
    )
    (loop for i below h do
        (format t "~A~%~A~%" (aref c i) (aref c i))
    )
)


(let ((h (read)) (w (read)))
  (dotimes (i h)
	(let ((s (read-line)))
	  (progn
		(princ s)
		(princ #\newline)
		(princ s)
		(princ #\newline)))))


(declaim (optimize (speed 3) (debug 0) (safety 0)))

(defun make-union-find (n)
  (let ((x (make-array n)))
    (loop for i from 0 below n
       do (setf (aref x i) i))
    x))

(defun lookup (uf n)
  (if (= (aref uf n) n)
      n
      (setf (aref uf n)
	    (lookup uf (aref uf n)))))

(defun unite (uf n m)
  (setf (aref uf (lookup uf n))
	(lookup uf m)))

(defun force (uf)
  (loop for x from 0 below (length uf)
     do (lookup uf x)))

(defun main ()
  (let* ((n (read))
	 (k (read))
	 (l (read))
	 (road (make-union-find n))
	 (rail (make-union-find n)))
    (loop repeat k
       do (let ((p (1- (read)))
		(q (1- (read))))
	    (unite road p q)))
    (loop repeat l
       do (let ((r (1- (read)))
		(s (1- (read))))
	    (unite rail r s)))
    (force road)
    (force rail)

    (let ((table (make-hash-table)))
      (labels ((idx (i) (+ (* (lookup road i) n)
			   (lookup rail i))))
	(loop for i from 0 below n
	   do (if (gethash (idx i) table)
		  (incf (gethash (idx i) table))
		  (setf (gethash (idx i) table) 1)))
	(loop for i from 0 below n
	   do (format t "~a " (gethash (idx i) table)))
	(terpri)))))

(main)

Score : 400 points

Problem Statement

There are N cities. There are also K roads and L railways, extending between the cities.
The i-th road bidirectionally connects the p_i-th and q_i-th cities, and the i-th railway bidirectionally connects the r_i-th and s_i-th cities.
No two roads connect the same pair of cities. Similarly, no two railways connect the same pair of cities.

We will say city A and B are connected by roads if city B is reachable from city A by traversing some number of roads. Here, any city is considered to be connected to itself by roads.
We will also define connectivity by railways similarly.

For each city, find the number of the cities connected to that city by both roads and railways.

Constraints

2 ≦ N ≦ 2*10^5

1 ≦ K, L≦ 10^5

1 ≦ p_i, q_i, r_i, s_i ≦ N

p_i < q_i

r_i < s_i

When i ≠ j, (p_i, q_i) ≠ (p_j, q_j)

When i ≠ j, (r_i, s_i) ≠ (r_j, s_j)

Input

The input is given from Standard Input in the following format:

N K L
p_1 q_1
:
p_K q_K
r_1 s_1
:
r_L s_L

Output

Print N integers. The i-th of them should represent the number of the cities connected to the i-th city by both roads and railways.

Sample Input 1

4 3 1
1 2
2 3
3 4
2 3

Sample Output 1

1 2 2 1

All the four cities are connected to each other by roads.

By railways, only the second and third cities are connected. Thus, the answers for the cities are 1, 2, 2 and 1, respectively.

Sample Input 2

4 2 2
1 2
2 3
1 4
2 3

Sample Output 2

1 2 2 1

Sample Input 3

7 4 4
1 2
2 3
2 5
6 7
3 5
4 5
3 4
6 7

Sample Output 3

1 1 2 1 2 2 2


(let* ((a (read))
       (b (read))
       (x (read))
       (z (floor (- b a) x)))

  (format t "~A~%"
          (max
            (cond ((and (zerop (mod a x)) (zerop (mod b x))) (1+ z))
                  ((or (zerop (floor a x)) (zerop (floor b x))) z)
                  (t (1- z)))
            0)))

Score : 200 points

Problem Statement

You are given nonnegative integers a and b (a ≤ b), and a positive integer x.
Among the integers between a and b, inclusive, how many are divisible by x?

Constraints

0 ≤ a ≤ b ≤ 10^{18}

1 ≤ x ≤ 10^{18}

Input

The input is given from Standard Input in the following format:

a b x

Output

Print the number of the integers between a and b, inclusive, that are divisible by x.

Sample Input 1

4 8 2

Sample Output 1

3

There are three integers between 4 and 8, inclusive, that are divisible by 2: 4, 6 and 8.

Sample Input 2

0 5 1

Sample Output 2

6

There are six integers between 0 and 5, inclusive, that are divisible by 1: 0, 1, 2, 3, 4 and 5.

Sample Input 3

9 9 2

Sample Output 3

0

There are no integer between 9 and 9, inclusive, that is divisible by 2.

Sample Input 4

1 1000000000000000000 3

Sample Output 4

333333333333333333

Watch out for integer overflows.


(defun split (str delim)
  (let ((res (make-array 1 :element-type 'string
                           :fill-pointer 0
                           :adjustable t)))
    (loop for i from 0 below (length str)
          with start = 0
          when (eq (char str i) delim)
          do (vector-push-extend (subseq str start i) res)
             (setf start (1+ i))
          finally (let ((tail (subseq str start)))
                    (when tail
                      (vector-push-extend tail res))))
    res))

(let* ((in (split (read-line) #\Space))
       (a (parse-integer (aref in 0)))
       (b (parse-integer (aref in 1)))
       (x (parse-integer (aref in 2)))
       (cnt 0))
  (loop for i from a upto b
        when (integerp (/ i x))
        do (incf cnt))
  (format t "~A~%" cnt))


(defun sqr (x) (* x x))

(defun dist (m n)
  (destructuring-bind (x1 y1 r1) m
    (destructuring-bind (x2 y2 r2) n
      (max 0 (- (sqrt (coerce (+ (sqr (- x1 x2)) (sqr (- y1 y2)))
			      'double-float)) r1 r2)))))

(defun main ()
  (let ((nodes `((,(read) ,(read) 0) (,(read) ,(read) 0)))
	(n (read)))
    (dotimes (_ n) (push `(,(read) ,(read) ,(read)) nodes))
    (setf nodes (nreverse nodes))

    (let* ((s (+ n 2))
	   (table (make-array (list s s) :initial-element 0)))
      (loop for i from 0
	 for x in nodes
	 do (loop for j from 0
	       for y in nodes
	       unless (= i j)
	       do (setf (aref table i j) (dist y x))))
      (dotimes (k s)
	(dotimes (i s)
	  (dotimes (j s)
	    (let ((cand (+ (aref table i k)
			   (aref table k j))))
	      (when (> (aref table i j) cand)
		(setf (aref table i j)
		      cand))))))
      (format t "~,10f~%" (aref table 0 1)))))

(main)

Score : 600 points

Problem Statement

On the xy-plane, Snuke is going to travel from the point (x_s, y_s) to the point (x_t, y_t).
He can move in arbitrary directions with speed 1.
Here, we will consider him as a point without size.

There are N circular barriers deployed on the plane.
The center and the radius of the i-th barrier are (x_i, y_i) and r_i, respectively.
The barriers may overlap or contain each other.

A point on the plane is exposed to cosmic rays if the point is not within any of the barriers.

Snuke wants to avoid exposure to cosmic rays as much as possible during the travel.
Find the minimum possible duration of time he is exposed to cosmic rays during the travel.

Constraints

All input values are integers.

-10^9 ≤ x_s, y_s, x_t, y_t ≤ 10^9

(x_s, y_s) ≠ (x_t, y_t)

1≤N≤1,000

-10^9 ≤ x_i, y_i ≤ 10^9

1 ≤ r_i ≤ 10^9

Input

The input is given from Standard Input in the following format:

x_s y_s x_t y_t
N
x_1 y_1 r_1
x_2 y_2 r_2
:
x_N y_N r_N

Output

Print the minimum possible duration of time Snuke is exposed to cosmic rays during the travel.
The output is considered correct if the absolute or relative error is at most 10^{-9}.

Sample Input 1

-2 -2 2 2
1
0 0 1

Sample Output 1

3.6568542495

An optimal route is as follows:

Sample Input 2

-2 0 2 0
2
-1 0 2
1 0 2

Sample Output 2

0.0000000000

An optimal route is as follows:

Sample Input 3

4 -2 -2 4
3
0 0 2
4 0 1
0 4 1

Sample Output 3

4.0000000000

An optimal route is as follows:


;; -*- coding: utf-8 -*-
(eval-when (:compile-toplevel :load-toplevel :execute)
  (sb-int:defconstant-eqx OPT
    #+swank '(optimize (speed 3) (safety 2))
    #-swank '(optimize (speed 3) (safety 0) (debug 0))
    #'equal)
  #+swank (ql:quickload '(:cl-debug-print :fiveam) :silent t)
  #-swank (set-dispatch-macro-character
           #\# #\> (lambda (s c p) (declare (ignore c p)) (read s nil nil t))))
#+swank (cl-syntax:use-syntax cl-debug-print:debug-print-syntax)
#-swank (disable-debugger) ; for CS Academy

;; BEGIN_INSERTED_CONTENTS
;;;
;;; Arithmetic operations with static modulus
;;;

(defmacro define-mod-operations (divisor)
  `(progn
     (defun mod* (&rest args)
       (reduce (lambda (x y) (mod (* x y) ,divisor)) args))

     (sb-c:define-source-transform mod* (&rest args)
       (if (null args)
           1
           (reduce (lambda (x y) `(mod (* ,x ,y) ,',divisor)) args)))

     (defun mod+ (&rest args)
       (reduce (lambda (x y) (mod (+ x y) ,divisor)) args))

     (sb-c:define-source-transform mod+ (&rest args)
       (if (null args)
           0
           (reduce (lambda (x y) `(mod (+ ,x ,y) ,',divisor)) args)))

     (define-modify-macro incfmod (delta)
       (lambda (x y) (mod (+ x y) ,divisor)))

     (define-modify-macro decfmod (delta)
       (lambda (x y) (mod (- x y) ,divisor)))

     (define-modify-macro mulfmod (multiplier)
       (lambda (x y) (mod (* x y) ,divisor)))))

(declaim (ftype (function * (values fixnum &optional)) read-fixnum))
(defun read-fixnum (&optional (in *standard-input*))
  (declare #.OPT)
  (macrolet ((%read-byte ()
               `(the (unsigned-byte 8)
                     #+swank (char-code (read-char in nil #\Nul))
                     #-swank (sb-impl::ansi-stream-read-byte in nil #.(char-code #\Nul) nil))))
    (let* ((minus nil)
           (result (loop (let ((byte (%read-byte)))
                           (cond ((<= 48 byte 57)
                                  (return (- byte 48)))
                                 ((zerop byte) ; #\Nul
                                  (error "Read EOF or #\Nul."))
                                 ((= byte #.(char-code #\-))
                                  (setf minus t)))))))
      (declare ((integer 0 #.most-positive-fixnum) result))
      (loop
        (let* ((byte (%read-byte)))
          (if (<= 48 byte 57)
              (setq result (+ (- byte 48)
                              (* 10 (the (integer 0 #.(floor most-positive-fixnum 10)) result))))
              (return (if minus (- result) result))))))))

(defmacro dbg (&rest forms)
  #+swank
  (if (= (length forms) 1)
      `(format *error-output* "~A => ~A~%" ',(car forms) ,(car forms))
      `(format *error-output* "~A => ~A~%" ',forms `(,,@forms)))
  #-swank (declare (ignore forms)))

(defmacro define-int-types (&rest bits)
  `(progn
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "UINT~A" b)) () '(unsigned-byte ,b))) bits)
     ,@(mapcar (lambda (b) `(deftype ,(intern (format nil "INT~A" b)) () '(signed-byte ,b))) bits)))
(define-int-types 2 4 7 8 15 16 31 32 62 63 64)

(declaim (inline println))
(defun println (obj &optional (stream *standard-output*))
  (let ((*read-default-float-format* 'double-float))
    (prog1 (princ obj stream) (terpri stream))))

(defconstant +mod+ 1000000007)

;;;
;;; Body
;;;

(define-mod-operations +mod+)

(declaim (inline pophash))
(defun pophash (hash-table)
  (maphash (lambda (key _)
             (declare (ignore _))
             (remhash key hash-table)
             (return-from pophash key))
           hash-table))

(declaim (inline hash-table-empty-p))
(defun hash-table-empty-p (hash-table)
  (zerop (hash-table-count hash-table)))

(declaim (inline uint32<))
(defun uint32< (x y)
  (< (the uint32 x) (the uint32 y)))

(defun main ()
  (declare #.OPT
           (inline sort))
  (let* ((n (read))
         (as (loop repeat n collect (read-fixnum)))
         (bs (loop repeat n collect (read-fixnum)))
         (res 1))
    (declare (uint31 n res))
    (setf as (sort as #'uint32<)
          bs (sort bs #'uint32<))
    (let ((set-a (make-array n :fill-pointer 0 :element-type 'uint31))
          (set-b (make-array n :fill-pointer 0 :element-type 'uint31)))
      (sb-int:named-let recur ((as as) (bs bs))
        (cond ((and (null as) (null bs)))
              ((null as)
               (mulfmod res (the uint31 (length set-a)))
               (vector-pop set-a)
               (recur as (cdr bs)))
              ((null bs)
               (mulfmod res (the uint31 (length set-b)))
               (vector-pop set-b)
               (recur (cdr as) bs))
              ((uint32< (car as) (car bs))
               (if (zerop (length set-b))
                   (vector-push (car as) set-a)
                   (progn (mulfmod res (the uint31 (length set-b)))
                          (vector-pop set-b)))
               (recur (cdr as) bs))
              (t
               (if (zerop (length set-a))
                   (vector-push (car bs) set-b)
                   (progn (mulfmod res (the uint31 (length set-a)))
                          (vector-pop set-a)))
               (recur as (cdr bs))))))
    (println res)))

#-swank (main)

;;;
;;; Test and benchmark
;;;

#+swank
(defun io-equal (in-string out-string &key (function #'main) (test #'equal))
  "Passes IN-STRING to *STANDARD-INPUT*, executes FUNCTION, and returns true if
the string output to *STANDARD-OUTPUT* is equal to OUT-STRING."
  (labels ((ensure-last-lf (s)
             (if (eql (uiop:last-char s) #\Linefeed)
                 s
                 (uiop:strcat s uiop:+lf+))))
    (funcall test
             (ensure-last-lf out-string)
             (with-output-to-string (out)
               (let ((*standard-output* out))
                 (with-input-from-string (*standard-input* (ensure-last-lf in-string))
                   (funcall function)))))))

#+swank
(defun get-clipbrd ()
  (with-output-to-string (out)
    (run-program "C:/msys64/usr/bin/cat.exe" '("/dev/clipboard") :output out)))

#+swank (defparameter *this-pathname* (uiop:current-lisp-file-pathname))
#+swank (defparameter *dat-pathname* (uiop:merge-pathnames* "test.dat" *this-pathname*))

#+swank
(defun run (&optional thing (out *standard-output*))
  "THING := null | string | symbol | pathname

null: run #'MAIN using the text on clipboard as input.
string: run #'MAIN using the string as input.
symbol: alias of FIVEAM:RUN!.
pathname: run #'MAIN using the text file as input."
  (let ((*standard-output* out))
    (etypecase thing
      (null
       (with-input-from-string (*standard-input* (delete #\Return (get-clipbrd)))
         (main)))
      (string
       (with-input-from-string (*standard-input* (delete #\Return thing))
         (main)))
      (symbol (5am:run! thing))
      (pathname
       (with-open-file (*standard-input* thing)
         (main))))))

#+swank
(defun gen-dat ()
  (uiop:with-output-file (out *dat-pathname* :if-exists :supersede)
    (format out "")))

#+swank
(defun bench (&optional (out (make-broadcast-stream)))
  (time (run *dat-pathname* out)))

;; To run: (5am:run! :sample)
#+swank
(it.bese.fiveam:test :sample
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "2
0
10
20
30
"
    "2
"))
  (it.bese.fiveam:is
   (common-lisp-user::io-equal "3
3
10
8
7
12
5
"
    "1
")))

Score : 500 points

Problem Statement

#nck {
width: 30px;
height: auto;
}

There are N computers and N sockets in a one-dimensional world.
The coordinate of the i-th computer is a_i, and the coordinate of the i-th socket is b_i.
It is guaranteed that these 2N coordinates are pairwise distinct.

Snuke wants to connect each computer to a socket using a cable.
Each socket can be connected to only one computer.

In how many ways can he minimize the total length of the cables?
Compute the answer modulo 10^9+7.

Constraints

1 ≤ N ≤ 10^5

0 ≤ a_i, b_i ≤ 10^9

The coordinates are integers.

The coordinates are pairwise distinct.

Input

The input is given from Standard Input in the following format:

N
a_1
:
a_N
b_1
:
b_N

Output

Print the number of ways to minimize the total length of the cables, modulo 10^9+7.

Sample Input 1

2
0
10
20
30

Sample Output 1

2

There are two optimal connections: 0-20, 10-30 and 0-30, 10-20.
In both connections the total length of the cables is 40.

Sample Input 2

3
3
10
8
7
12
5

Sample Output 2

1