[User] List each patient's active insurance policy and the number of prescriptions they have during that policy. Show patient_id, plan_id, policy_number, and prescription_count.

[Assistant]
SELECT pi.patient_id, pi.plan_id, pi.policy_number, COUNT(p.prescription_id) AS prescription_count
FROM healthcare.patient_insurance pi
LEFT JOIN healthcare.prescriptions p
  ON pi.patient_id = p.patient_id
  AND DATE(p.prescription_date) BETWEEN pi.effective_date AND COALESCE(pi.expiration_date, CURRENT_DATE)
GROUP BY pi.patient_id, pi.plan_id, pi.policy_number;

[User] Only include patients with more than 5 prescriptions.

[Assistant]
SELECT pi.patient_id, pi.plan_id, pi.policy_number, COUNT(p.prescription_id) AS prescription_count
FROM healthcare.patient_insurance pi
LEFT JOIN healthcare.prescriptions p
  ON pi.patient_id = p.patient_id
  AND DATE(p.prescription_date) BETWEEN pi.effective_date AND COALESCE(pi.expiration_date, CURRENT_DATE)
GROUP BY pi.patient_id, pi.plan_id, pi.policy_number
HAVING COUNT(p.prescription_id) > 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.appointments ( appointment_id text, patient_id text, doctor_id text, appointment_time timestamp, duration_minutes integer, reason text, status text, location_id text, notes text, created_at timestamp )
CREATE TABLE healthcare.medications ( medication_id text, medication_name text, generic_name text, manufacturer text, ndc_code text, description text )
CREATE TABLE healthcare.prescriptions ( prescription_id.text, record_id.text, patient_id.text, doctor_id.text, medication_id.text, dosage.text, frequency.text, route.text, start_date.date, end_date.date, quantity_dispensed.numeric, refills_allowed.integer, prescription_date.timestamp )
CREATE TABLE healthcare.patient_insurance ( patient_insurance_id character varying(64) NOT NULL, patient_id character varying(64) NOT NULL, plan_id character varying(64) NOT NULL, policy_number character varying(100) NOT NULL, group_number character varying(100), subscriber_name character varying(200), effective_date date NOT NULL, expiration_date date, is_primary boolean NOT NULL DEFAULT true, PRIMARY KEY (patient_insurance_id), UNIQUE (patient_id, plan_id, policy_number) )


[User] List all users who have deployed contracts, along with their email addresses and the count of contracts they've deployed.

[Assistant] SELECT u.user_id, u.email, COUNT(c.contract_id) AS contract_count FROM web3.users u JOIN web3.contracts c ON u.user_id = c.deployer_address GROUP BY u.user_id, u.email;

[User] Actually, I only want to see users who have deployed more than 3 contracts.

[Assistant] SELECT u.user_id, u.email, COUNT(c.contract_id) AS contract_count FROM web3.users u JOIN web3.contracts c ON u.user_id = c.deployer_address GROUP BY u.user_id, u.email HAVING COUNT(c.contract_id) > 3;

[User] There's an error in your SQL, it should be 'deployer_address' not 'user_id' in the JOIN condition.

[Assistant] SELECT u.user_id, u.email, COUNT(c.contract_id) AS contract_count FROM web3.users u JOIN web3.contracts c ON u.user_id = c.deployer_address GROUP BY u.user_id, u.email HAVING COUNT(c.contract_id) > 3;

[User] Now sort the results by contract_count in descending order.

[Assistant] SELECT u.user_id, u.email, COUNT(c.contract_id) AS contract_count FROM web3.users u JOIN web3.contracts c ON u.user_id = c.deployer_address GROUP BY u.user_id, u.email HAVING COUNT(c.contract_id) > 3 ORDER BY contract_count DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.contracts ( contract_id.text, address.text, abi.text, bytecode.text, deployer_address.text, deployed_at.timestamp, network_id.text, status.text )
CREATE TABLE web3.transactions ( transaction_id text PRIMARY KEY, from_address text, to_address text, value numeric, gas_used int, gas_price numeric, block_number int, timestamp timestamp, input_data text, status text, nonce int )
CREATE TABLE web3.users ( user_id character varying(64) NOT NULL, username character varying(128) NOT NULL, email character varying(128) NOT NULL, password_hash text NOT NULL, created_at timestamp NOT NULL, PRIMARY KEY (user_id) )


[User] Find all non-smoking rooms that have not been cleaned in the last 7 days.

[Assistant]
SELECT room_id, room_number, last_cleaned_at
FROM hospitality_technology.rooms
WHERE is_smoking = false
  AND last_cleaned_at < NOW() - INTERVAL '7 days';

[User] Now also include only those rooms with 'Balcony' in the features.

[Assistant]
SELECT room_id, room_number, last_cleaned_at, features
FROM hospitality_technology.rooms
WHERE is_smoking = false
  AND last_cleaned_at < NOW() - INTERVAL '7 days'
  AND features ILIKE '%Balcony%';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.rooms (
    room_id character varying(64) NOT NULL,  -- unique identifier for the room
    property_id character varying(64) NOT NULL, -- FK to properties table
    room_number character varying(10) NOT NULL, -- room number identifier (e.g., '101', 'Suite 2B')
    room_type_id character varying(64) NOT NULL, -- FK to room_types table
    floor integer, -- floor number the room is on
    status character varying(50) NOT NULL, -- e.g., Available, Occupied, Cleaning, OutOfOrder, Maintenance
    is_smoking boolean NOT NULL DEFAULT false, -- smoking allowed flag
    features text, -- description of features (e.g., Balcony, Sea View, Jacuzzi)
    current_condition text, -- notes on room condition
    last_cleaned_at timestamp with time zone, -- timestamp of last cleaning
    PRIMARY KEY (room_id),
    FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id),
    FOREIGN KEY (room_type_id) REFERENCES hospitality_technology.room_types(room_type_id)
)
CREATE TABLE hospitality_technology.payments ( payment_id text, reservation_id text, guest_id text, bill_id text, amount numeric, currency_code text, payment_method text, card_type text, card_last_four text, transaction_ref text, payment_timestamp timestamp, status text, staff_id_processed text, notes text )


[User] Show me the top 5 narratives by market cap, along with their 24-hour trading volume and 7-day price change percentage.

[Assistant] SELECT narrative.text, volume_24h.numeric, price_change_percentage_7d.numeric FROM narrative_info ORDER BY market_cap.numeric DESC LIMIT 5;

[User] Can you also include the top 3 coins for each of these narratives?

[Assistant] SELECT narrative.text, volume_24h.numeric, price_change_percentage_7d.numeric, top_3_coins.text FROM narrative_info ORDER BY market_cap.numeric DESC LIMIT 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE narrative_info ( narrative.text, top_3_coins.text, price_change_percentage_1h.numeric, price_change_percentage_24h.numeric, price_change_percentage_7d.numeric, market_cap.numeric, volume_24h.numeric, trend_rank.numeric, token_num.numeric )


[User] Find all nodes that were last seen in the last 30 days and have port numbers between 8000 and 9000.

[Assistant] SELECT node_id, ip_address, port FROM blockchain.nodes WHERE last_seen >= NOW() - INTERVAL '30 days' AND port BETWEEN 8000 AND 9000

[User] Can you also show the count of transactions sent from wallet addresses that share the same IP as these nodes?

[Assistant] This query isn't possible with the current schema as there's no relationship between nodes IP addresses and wallet addresses.

[User] Then just show me nodes that share the same IP address along with how many nodes share each IP.

[Assistant] SELECT ip_address, COUNT(*) as node_count FROM blockchain.nodes GROUP BY ip_address HAVING COUNT(*) > 1

[User] Now filter this to only show IP addresses with more than 3 nodes and include the earliest and latest last_seen timestamps.

[Assistant] SELECT ip_address, COUNT(*) as node_count, MIN(last_seen) as earliest_seen, MAX(last_seen) as latest_seen FROM blockchain.nodes GROUP BY ip_address HAVING COUNT(*) > 3

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE blockchain.transactions ( transaction_id text, block_id text, sender_address text, receiver_address text, amount numeric, timestamp timestamp, signature text )
CREATE TABLE blockchain.nodes ( node_id text, ip_address text, port integer, last_seen timestamp )
CREATE TABLE blockchain.wallets ( wallet_id text, user_id text, address_id text, private_key text )
CREATE TABLE blockchain.smart_contracts ( contract_id text, creator_address text, code text, timestamp timestamp )


[User] List each payment method, the total amount paid, and the number of payments for each method for services in the 'Education' category.

[Assistant]
SELECT p.payment_method, SUM(p.amount) AS total_amount, COUNT(p.payment_id) AS payment_count
FROM government_services.payments p
JOIN government_services.services s ON p.service_id = s.service_id
WHERE s.category = 'Education'
GROUP BY p.payment_method;

[User] Only include payment methods with total amounts greater than 1000.

[Assistant]
SELECT p.payment_method, SUM(p.amount) AS total_amount, COUNT(p.payment_id) AS payment_count
FROM government_services.payments p
JOIN government_services.services s ON p.service_id = s.service_id
WHERE s.category = 'Education'
GROUP BY p.payment_method
HAVING SUM(p.amount) > 1000;

[User] Exclude payments that are not completed.

[Assistant]
SELECT p.payment_method, SUM(p.amount) AS total_amount, COUNT(p.payment_id) AS payment_count
FROM government_services.payments p
JOIN government_services.services s ON p.service_id = s.service_id
WHERE s.category = 'Education' AND p.status = 'Completed'
GROUP BY p.payment_method
HAVING SUM(p.amount) > 1000;

[User] Show only the payment method with the highest total paid.

[Assistant]
SELECT payment_method, total_amount, payment_count FROM (
  SELECT p.payment_method, SUM(p.amount) AS total_amount, COUNT(p.payment_id) AS payment_count,
         RANK() OVER (ORDER BY SUM(p.amount) DESC) AS method_rank
  FROM government_services.payments p
  JOIN government_services.services s ON p.service_id = s.service_id
  WHERE s.category = 'Education' AND p.status = 'Completed'
  GROUP BY p.payment_method
  HAVING SUM(p.amount) > 1000
) ranked
WHERE method_rank = 1;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.agencies ( agency_id.text, agency_name.text, jurisdiction_level.text, primary_contact_email.text, main_phone_number.text, website_url.text, established_date.date, parent_agency_id.text )
CREATE TABLE government_services.services ( service_id.text, agency_id.text, service_name.text, description.text, category.text, eligibility_criteria.text, standard_fee.numeric, average_processing_time_days.integer, is_active.boolean, online_application_url.text )
CREATE TABLE government_services.applications ( application_id.text, citizen_id.text, service_id.text, submitted_at.timestamp, status.text, last_updated_at.timestamp, assigned_employee_id.text, decision_date.date, notes.text, reference_number.text )
CREATE TABLE government_services.documents ( document_id.text, application_id.text, citizen_id.text, document_type.text, file_reference.text, upload_timestamp.timestamp, expiry_date.date, verification_status.text, verified_by_employee_id.text, verification_timestamp.timestamp )
CREATE TABLE government_services.payments ( payment_id.text, application_id.text, citizen_id.text, service_id.text, amount.numeric, currency.text, payment_method.text, payment_provider_reference.text, payment_timestamp.timestamp, status.text, notes.text )
CREATE TABLE government_services.employees ( employee_id.text, agency_id.text, first_name.text, last_name.text, job_title.text, department.text, work_email.text, work_phone.text, hire_date.date, termination_date.date, access_level.text, manager_employee_id.text )
CREATE TABLE government_services.service_locations ( location_id.text, agency_id.text, location_name.text, address.text, city.text, state.text, postal_code.text, latitude.numeric, longitude.numeric, operating_hours.text, contact_phone.text, is_accessible.boolean )
CREATE TABLE government_services.appointments ( appointment_id.text, citizen_id.text, employee_id.text, location_id.text, service_id.text, scheduled_start_time.timestamp, scheduled_end_time.timestamp, purpose.text, status.text, booking_method.text, created_at.timestamp, notes.text )
CREATE TABLE government_services.notifications ( notification_id.text, citizen_id.text, application_id.text, message_subject.text, message_body.text, channel.text, sent_at.timestamp, status.text, related_entity_type.text, related_entity_id.text )


[User] For each recipient address, count how many token transfers they have received.

[Assistant] SELECT to_address, COUNT(*) AS received_transfer_count FROM web3.token_transfers GROUP BY to_address;

[User] Only show addresses that have received more than 100 transfers.

[Assistant] SELECT to_address, COUNT(*) AS received_transfer_count FROM web3.token_transfers GROUP BY to_address HAVING COUNT(*) > 100;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.token_transfers ( transfer_id text PRIMARY KEY, token_id text, from_address text, to_address text, value numeric, transaction_id text, log_index int )


[User] List the latest version of each document (identified by case_id and document_name), showing the version number and its upload_timestamp.

[Assistant]
SELECT d.case_id,
       d.document_name,
       d.version   AS latest_version,
       d.upload_timestamp
FROM legal_services.documents d
JOIN (
  SELECT case_id, document_name, MAX(version) AS max_version
  FROM legal_services.documents
  GROUP BY case_id, document_name
) m ON d.case_id = m.case_id
    AND d.document_name = m.document_name
    AND d.version = m.max_version;

[User] Actually, I also want to see the upload_timestamp of the previous version for each document.

[Assistant]
SELECT m.case_id,
       m.document_name,
       m.max_version         AS latest_version,
       d_latest.upload_timestamp  AS latest_timestamp,
       d_prev.upload_timestamp    AS previous_timestamp
FROM (
  SELECT case_id, document_name, MAX(version) AS max_version
  FROM legal_services.documents
  GROUP BY case_id, document_name
) m
JOIN legal_services.documents d_latest
  ON d_latest.case_id = m.case_id
 AND d_latest.document_name = m.document_name
 AND d_latest.version = m.max_version
LEFT JOIN legal_services.documents d_prev
  ON d_prev.case_id = m.case_id
 AND d_prev.document_name = m.document_name
 AND d_prev.version = m.max_version - 1;

[User] Also, only include documents whose first version (version = 1) was uploaded in 2024.

[Assistant]
SELECT m.case_id,
       m.document_name,
       m.max_version          AS latest_version,
       d_latest.upload_timestamp   AS latest_timestamp,
       d_prev.upload_timestamp     AS previous_timestamp
FROM (
  SELECT case_id, document_name, MAX(version) AS max_version
  FROM legal_services.documents
  GROUP BY case_id, document_name
) m
JOIN legal_services.documents d_first
  ON d_first.case_id = m.case_id
 AND d_first.document_name = m.document_name
 AND d_first.version = 1
 AND d_first.upload_timestamp >= '2024-01-01'
 AND d_first.upload_timestamp < '2025-01-01'
JOIN legal_services.documents d_latest
  ON d_latest.case_id = m.case_id
 AND d_latest.document_name = m.document_name
 AND d_latest.version = m.max_version
LEFT JOIN legal_services.documents d_prev
  ON d_prev.case_id = m.case_id
 AND d_prev.document_name = m.document_name
 AND d_prev.version = m.max_version - 1;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.documents ( document_id.text, case_id.text, document_name.text, document_type.text, storage_path.text, uploaded_by_lawyer_id.text, upload_timestamp.timestamp, version.integer, description.text )


[User] Show me the top 5 projects by valuation that completed fundraising rounds in the last 3 months, along with their narrative information if available.

[Assistant] SELECT pfr.project_name, pfr.valuation, pfr.rounds_name, pfr.investment_date, ni.narrative, ni.trend_rank FROM project_fundraising_record pfr LEFT JOIN token_basic_info tbi ON pfr.project_name = tbi.token_name LEFT JOIN narrative_info ni ON tbi.narrative = ni.narrative WHERE pfr.investment_date >= DATE_SUB(CURRENT_DATE, INTERVAL 3 MONTH) ORDER BY pfr.valuation DESC LIMIT 5;

[User] Can you also include the 24-hour trading volume for these projects' narratives and filter to only include projects with valuation over $50 million?

[Assistant] SELECT pfr.project_name, pfr.valuation, pfr.rounds_name, pfr.investment_date, ni.narrative, ni.trend_rank, ni.volume_24h FROM project_fundraising_record pfr LEFT JOIN token_basic_info tbi ON pfr.project_name = tbi.token_name LEFT JOIN narrative_info ni ON tbi.narrative = ni.narrative WHERE pfr.investment_date >= DATE_SUB(CURRENT_DATE, INTERVAL 3 MONTH) AND pfr.valuation > 50000000 ORDER BY pfr.valuation DESC LIMIT 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE project_fundraising_record ( id character varying(32) NOT NULL,  -- fundraising record id project_id character varying(32) NOT NULL, -- the invested project's id project_name character varying(128) NOT NULL, -- name of the invested project rounds_name character varying(32), -- name of the fundraising round investment_value numeric(38,14), -- amount of the fundraising in USD investment_date character varying(128), -- the date of the investment happened introduction character varying(128), -- the introduction of the invested project valuation numeric(38,14), -- the valuation of the project in USD when invested )
CREATE TABLE token_basic_info ( coin_id character varying(100) NOT NULL, token_name character varying(100) NOT NULL, token_symbol character varying(100) NOT NULL, token_address character varying(100) NOT NULL, chain text, price double precision, price_change_percentage_1h double precision, price_change_percentage_24h double precision, price_change_percentage_7d double precision, highest_price_24h double precision, lowest_price_24h double precision, market_cap double precision, market_cap_rank bigint, market_cap_change_percentage_24h text, total_volume text, narrative text, trend_rank bigint )
 "CREATE TABLE narrative_info (",
    "narrative character varying(512) NOT NULL, -- the id of narrative",
    "top_3_coins text, -- the top 3 tokens in the narrative",
    "price_change_percentage_1h double precision, -- change in value divided by the absolute price value of the original token price in 1 hour in the narrative",
    "price_change_percentage_24h double precision, -- change in value divided by the absolute price value of the original token price in 24 hours in the narrative",
    "price_change_percentage_7d double precision, -- change in value divided by the absolute price value of the original token price in 7 days in the narrative",
    "market_cap double precision, -- the market cap of the narrative",
    "volume_24h double precision, -- the trade volume of the narrative",
    "trend_rank bigint, -- the trending rank of the narrative, value 1 expresses the most popular narrative",
    "token_num bigint, -- total token number in the narrative",
    ",PRIMARY KEY (narrative));"

CREATE TABLE cex_token_balance ( snapshot_time character varying(32) NOT NULL, chain character varying(128) NOT NULL, address character varying(128) NOT NULL, exchange character varying(512) NOT NULL, token_address character varying(128) NOT NULL, token_symbol character varying(512), balance numeric(38,10), usd_value numeric(38,14), price double precision )
CREATE TABLE smart_money_profit ( address character varying(100) NOT NULL, rank INT, profit numeric(38,6), roi numeric(38,2), realized_ratio numeric(38,2), most_profit_token character varying(100), last_trade_time character varying(100), chain character varying(100) )
CREATE TABLE smart_money_token_performance ( token_address character varying(100) NOT NULL, token_symbol character varying(100), pnl numeric(38,2), net_flow numeric(38,2), avg_cost numeric(38,16), price double precision, realized_ratio numeric(10,2), roi numeric(10,2), chain character varying(100) )


[User] Count the number of law firms founded in each decade. Show the decade (e.g., 1990s, 2000s) and the count.

[Assistant] SELECT CONCAT(FLOOR(EXTRACT(YEAR FROM founded_date) / 10) * 10, 's') AS decade, COUNT(*) AS firm_count FROM law_firms WHERE founded_date IS NOT NULL GROUP BY decade ORDER BY decade;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.clients ( client_id text PRIMARY KEY, first_name text, last_name text, company_name text, email text UNIQUE, phone text, address text, date_registered timestamp, status text )
CREATE TABLE legal_services.law_firms ( firm_id text PRIMARY KEY, firm_name text, address text, phone text, website text, founded_date date, managing_partner_id text )
CREATE TABLE legal_services.documents ( document_id text PRIMARY KEY, case_id text, document_name text, document_type text, storage_path text, uploaded_by_lawyer_id text, upload_timestamp timestamp, version int, description text )


[User] Show me the count of service orders for each distinct status.

[Assistant] SELECT status, COUNT(order_id) FROM hospitality_technology.service_orders GROUP BY status;

[User] Also, include the total quantity of items ordered for each status.

[Assistant] SELECT status, COUNT(order_id), SUM(quantity) FROM hospitality_technology.service_orders GROUP BY status;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.reservations ( reservation_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, guest_id character varying(64) NOT NULL, room_id character varying(64), room_type_id character varying(64) NOT NULL, check_in_date date NOT NULL, check_out_date date NOT NULL, actual_check_in_ts timestamp with time zone, actual_check_out_ts timestamp with time zone, num_adults integer NOT NULL, num_children integer DEFAULT 0, status character varying(50) NOT NULL, booking_source character varying(100), rate_plan_id character varying(64), total_amount numeric(12, 2), amount_paid numeric(12, 2) DEFAULT 0.00, special_requests text, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (reservation_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (room_id) REFERENCES hospitality_technology.rooms(room_id), FOREIGN KEY (room_type_id) REFERENCES hospitality_technology.room_types(room_type_id) )
CREATE TABLE hospitality_technology.service_orders ( order_id text PRIMARY KEY, reservation_id text, guest_id text, service_id text, staff_id_ordered text, staff_id_delivered text, order_timestamp timestamp, delivery_timestamp timestamp, quantity int, unit_price numeric, total_price numeric, status text, notes text, bill_id text )


[User] Show me each product_type along with the count of products for that type, but only include types where the average base_premium exceeds 500. Order the results by the product count in descending order.

[Assistant]
SELECT product_type,
       COUNT(*) AS product_count
FROM insurance.insurance_products
GROUP BY product_type
HAVING AVG(base_premium) > 500
ORDER BY product_count DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.insurance_products ( product_id.text, product_name.text, product_type.text, description.text, base_premium.numeric, coverage_details.text, underwriting_rules.text, is_active.boolean, created_at.timestamp, updated_at.timestamp )


[User] List all lawyers who have never had a time entry that was billed, showing lawyer_id, first_name, and last_name.

[Assistant]
SELECT l.lawyer_id, l.first_name, l.last_name
FROM legal_services.lawyers l
LEFT JOIN legal_services.time_entries te
  ON l.lawyer_id = te.lawyer_id
 AND te.is_billed = true
WHERE te.entry_id IS NULL;

[User] Actually, I only want lawyers who have at least one time entry overall but none of those entries are billed.

[Assistant]
SELECT l.lawyer_id, l.first_name, l.last_name
FROM legal_services.lawyers l
JOIN legal_services.time_entries te ON l.lawyer_id = te.lawyer_id
GROUP BY l.lawyer_id, l.first_name, l.last_name
HAVING COUNT(te.entry_id) > 0
   AND SUM(CASE WHEN te.is_billed = true THEN 1 ELSE 0 END) = 0;

[User] Now also include the count of unbilled entries and total unbilled hours for each lawyer.

[Assistant]
SELECT l.lawyer_id,
       l.first_name,
       l.last_name,
       COUNT(te.entry_id) FILTER (WHERE te.is_billed = false) AS unbilled_entries,
       SUM(te.hours_spent) FILTER (WHERE te.is_billed = false) AS total_unbilled_hours
FROM legal_services.lawyers l
JOIN legal_services.time_entries te ON l.lawyer_id = te.lawyer_id
GROUP BY l.lawyer_id, l.first_name, l.last_name
HAVING COUNT(te.entry_id) > 0
   AND SUM(CASE WHEN te.is_billed = true THEN 1 ELSE 0 END) = 0;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.lawyers ( lawyer_id.text, first_name.text, last_name.text, bar_number.text, firm_id.text, email.text, phone.text, specialization.text, hire_date.timestamp, is_partner.boolean )
CREATE TABLE legal_services.cases ( case_id.text, case_number.text, case_name.text, client_id.text, lead_lawyer_id.text, case_type.text, status.text, date_opened.timestamp, date_closed.timestamp, description.text, court_jurisdiction.text )
CREATE TABLE legal_services.time_entries ( entry_id character varying(64) NOT NULL, case_id character varying(64) NOT NULL, lawyer_id character varying(64) NOT NULL, date_worked date NOT NULL, hours_spent numeric(5, 2) NOT NULL CHECK (hours_spent > 0), billing_rate numeric(10, 2) NOT NULL, description text NOT NULL, is_billable boolean DEFAULT true, is_billed boolean DEFAULT false, invoice_id character varying(64), created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (entry_id) )
CREATE TABLE legal_services.appointments ( appointment_id text, client_id text, lawyer_id text, case_id text, start_time timestamp, end_time timestamp, location text, subject text, notes text, status text, created_at timestamp )


[User] How many diagnoses does each status have grouped by is_chronic flag?

[Assistant] SELECT is_chronic, status, COUNT(*) AS count FROM healthcare.diagnoses GROUP BY is_chronic, status;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.diagnoses ( diagnosis_id text, record_id text, patient_id text, doctor_id text, diagnosis_code text, code_type text, description text, diagnosis_date date, status text, is_chronic boolean )


[User] Show me the user_id and number of conversations they have joined. Only include users who joined more than one conversation.

[Assistant]
SELECT user_id, COUNT(DISTINCT conversation_id) AS conversations_joined
FROM social_media.conversation_participants
GROUP BY user_id
HAVING COUNT(DISTINCT conversation_id) > 1;

[User] Add the time they joined their most recent conversation as latest_joined_at.

[Assistant]
SELECT user_id, COUNT(DISTINCT conversation_id) AS conversations_joined, MAX(joined_at) AS latest_joined_at
FROM social_media.conversation_participants
GROUP BY user_id
HAVING COUNT(DISTINCT conversation_id) > 1;

[User] Also, show the IDs of the conversations for each user as a comma-separated list.

[Assistant]
SELECT user_id,
  COUNT(DISTINCT conversation_id) AS conversations_joined,
  MAX(joined_at) AS latest_joined_at,
  STRING_AGG(DISTINCT conversation_id, ',') AS conversation_ids
FROM social_media.conversation_participants
GROUP BY user_id
HAVING COUNT(DISTINCT conversation_id) > 1;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.post_hashtags ( post_hashtag_id text, post_id text, hashtag_id text )
CREATE TABLE social_media.conversation_participants ( participant_id text, conversation_id text, user_id text, joined_at timestamp, last_read_at timestamp )


[User] Show me the total fuel quantity and cost for each route, grouped by route number, only for trips that have associated fuel logs.

[Assistant]
SELECT r.route_number, SUM(f.quantity) AS total_quantity, SUM(f.total_cost) AS total_cost
FROM transportation.fuel_logs f
JOIN transportation.routes r ON f.trip_id IS NOT NULL AND f.trip_id IN (
    SELECT DISTINCT trip_id FROM transportation.fuel_logs
)
JOIN transportation.bookings b ON f.trip_id = b.trip_id
WHERE r.route_id = b.trip_id
GROUP BY r.route_number;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.routes ( route_id text, route_number text, description text, origin_location_id text, destination_location_id text, distance_km numeric, estimated_duration_minutes integer, type text )
CREATE TABLE transportation.locations ( location_id text, name text, type text, address_line1 text, city text, state_province text, postal_code text, country text, latitude numeric, longitude numeric, timezone text )
CREATE TABLE transportation.fuel_logs ( fuel_log_id text, vehicle_id text, trip_id text, log_timestamp timestamp, fuel_type text, quantity numeric, unit text, cost_per_unit numeric, total_cost numeric, odometer_reading integer, location_id text )
CREATE TABLE transportation.bookings ( booking_id text, passenger_id text, trip_id text, seat_number text, booking_time timestamp, status text, fare numeric, payment_transaction_id text, special_requests text )


[User] How many notifications have been sent for comments in total?

[Assistant]
SELECT COUNT(*)
FROM social_media.notifications
WHERE target_entity_type = 'comment';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id.text, username.text, email.text, password_hash.text, full_name.text, profile_picture_url.text, bio.text, location.text, created_at.timestamp, updated_at.timestamp, is_verified.boolean )
CREATE TABLE social_media.likes ( like_id.text, user_id.text, post_id.text, comment_id.text, created_at.timestamp )
CREATE TABLE social_media.follows ( follow_id.text, follower_user_id.text, following_user_id.text, created_at.timestamp )
CREATE TABLE social_media.hashtags ( hashtag_id.text, tag_name.text, created_at.timestamp )
CREATE TABLE social_media.notifications ( notification_id.text, recipient_user_id.text, sender_user_id.text, notification_type.text, target_entity_id.text, target_entity_type.text, created_at.timestamp, read_at.timestamp )


[User] List all pairs of wallets that were created within 10 minutes of each other, showing both wallet IDs, the user_id, and both creation timestamps.

[Assistant]
SELECT
  w1.wallet_id AS wallet1_id,
  w2.wallet_id AS wallet2_id,
  w1.user_id,
  w1.created_at AS created_at1,
  w2.created_at AS created_at2
FROM web3.wallets w1
JOIN web3.wallets w2
  ON w1.user_id = w2.user_id
  AND w1.wallet_id < w2.wallet_id
  AND ABS(EXTRACT(EPOCH FROM (w1.created_at - w2.created_at))) <= 600;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.wallets ( wallet_id text, user_id text, address text, private_key text, created_at timestamp )


[User] What is the average daily trading volume for each security_id in the market_data table from the last 30 days?

[Assistant] SELECT security_id, AVG(volume) as avg_daily_volume FROM financial_services.market_data WHERE data_timestamp >= CURRENT_DATE - INTERVAL '30 days' GROUP BY security_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE financial_services.accounts ( account_id text, customer_id text, account_number text, account_type text, balance numeric, currency text, opened_date date, status text, interest_rate numeric, last_updated_at timestamp )
CREATE TABLE financial_services.securities ( security_id.text, ticker_symbol.text, isin_code.text, cusip_code.text, security_name.text, security_type.text, exchange.text, currency.text, issuer_name.text, sector.text, last_updated.timestamp )
CREATE TABLE financial_services.trades ( trade_id text, account_id text, security_id text, order_id text, trade_type text, quantity numeric, price_per_unit numeric, total_amount numeric, commission numeric, trade_timestamp timestamp, settlement_date date, status text, execution_venue text )
CREATE TABLE financial_services.market_data ( data_point_id.bigint, security_id.text, data_timestamp.timestamp, open_price.numeric, high_price.numeric, low_price.numeric, close_price.numeric, adjusted_close_price.numeric, volume.bigint, source.text )
CREATE TABLE financial_services.employees ( employee_id text, first_name text, last_name text, job_title text, department text, branch_id text, email text, phone_extension text, hire_date date, termination_date date, manager_id text, status text )


[User] Show me all insurance plans that cover more than 10 patients as their primary insurance, along with the provider name and contact information.

[Assistant] SELECT ip.plan_name, ip.insurance_provider, ip.contact_phone, ip.website, COUNT(pi.patient_id) AS patient_count FROM healthcare.insurance_plans ip JOIN healthcare.patient_insurance pi ON ip.plan_id = pi.plan_id WHERE pi.is_primary = true GROUP BY ip.plan_id HAVING COUNT(pi.patient_id) > 10;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.patients (
    patient_id character varying(64) NOT NULL,  -- unique identifier for the patient
    first_name character varying(100) NOT NULL, -- patient's first name
    last_name character varying(100) NOT NULL, -- patient's last name
    date_of_birth date NOT NULL, -- patient's date of birth
    gender character varying(10), -- patient's gender (e.g., Male, Female, Other)
    address text, -- patient's home address
    phone_number character varying(20), -- patient's phone number
    email character varying(128) UNIQUE, -- patient's email address
    emergency_contact_name character varying(200), -- name of emergency contact
    emergency_contact_phone character varying(20), -- phone number of emergency contact
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, -- record creation time
    updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, -- record last update time
    PRIMARY KEY (patient_id)
)
CREATE TABLE healthcare.doctors (
    doctor_id character varying(64) NOT NULL,  -- unique identifier for the doctor
    first_name character varying(100) NOT NULL, -- doctor's first name
    last_name character varying(100) NOT NULL, -- doctor's last name
    specialty character varying(100) NOT NULL, -- doctor's medical specialty
    license_number character varying(50) UNIQUE NOT NULL, -- doctor's medical license number
    phone_number character varying(20), -- doctor's contact phone
    email character varying(128) UNIQUE, -- doctor's contact email
    hospital_affiliation_id character varying(64), -- FK to hospitals table (optional)
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (doctor_id)
)
CREATE TABLE healthcare.appointments (
    appointment_id character varying(64) NOT NULL, -- unique identifier for the appointment
    patient_id character varying(64) NOT NULL, -- FK to patients table
    doctor_id character varying(64) NOT NULL, -- FK to doctors table
    appointment_time timestamp with time zone NOT NULL, -- date and time of the appointment
    duration_minutes integer NOT NULL, -- expected duration in minutes
    reason text, -- reason for the visit
    status character varying(32) NOT NULL, -- e.g., Scheduled, Completed, Cancelled, No-show
    location_id character varying(64), -- FK to a potential locations/clinics table
    notes text, -- notes related to scheduling
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (appointment_id)
)
CREATE TABLE healthcare.diagnoses (
    diagnosis_id character varying(64) NOT NULL, -- unique identifier for the diagnosis entry
    record_id character varying(64) NOT NULL, -- FK linking to the specific medical record entry
    patient_id character varying(64) NOT NULL, -- FK to patients table
    doctor_id character varying(64) NOT NULL, -- FK to doctors table (diagnosing doctor)
    diagnosis_code character varying(20) NOT NULL, -- standard code (e.g., ICD-10)
    code_type character varying(10) NOT NULL DEFAULT 'ICD-10', -- type of code used
    description text, -- textual description of the diagnosis
    diagnosis_date date NOT NULL, -- date the diagnosis was made
    status character varying(32) NOT NULL, -- e.g., Active, Resolved, Ruled Out
    is_chronic boolean DEFAULT false, -- flag for chronic conditions
    PRIMARY KEY (diagnosis_id)
)
CREATE TABLE healthcare.medications (
    medication_id character varying(64) NOT NULL, -- unique identifier for the medication type
    medication_name character varying(255) NOT NULL, -- common or brand name
    generic_name character varying(255), -- generic chemical name
    manufacturer character varying(100), -- drug manufacturer
    ndc_code character varying(20) UNIQUE, -- National Drug Code (optional but useful)
    description text, -- description of the medication
    PRIMARY KEY (medication_id)
)
CREATE TABLE healthcare.prescriptions (
    prescription_id character varying(64) NOT NULL, -- unique identifier for the prescription
    record_id character varying(64) NOT NULL, -- FK linking to the medical record where it was prescribed
    patient_id character varying(64) NOT NULL, -- FK to patients table
    doctor_id character varying(64) NOT NULL, -- FK to prescribing doctor
    medication_id character varying(64) NOT NULL, -- FK to medications table
    dosage character varying(100) NOT NULL, -- e.g., '100mg', '1 tablet'
    frequency character varying(100) NOT NULL, -- e.g., 'Once daily', 'Twice a day with meals'
    route character varying(50), -- e.g., 'Oral', 'Topical', 'Intravenous'
    start_date date NOT NULL, -- date prescription begins
    end_date date, -- date prescription ends (if applicable)
    quantity_dispensed numeric(10,2), -- amount dispensed (e.g., number of tablets)
    refills_allowed integer NOT NULL DEFAULT 0, -- number of allowed refills
    prescription_date timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (prescription_id)
)
CREATE TABLE healthcare.insurance_plans (
    plan_id character varying(64) NOT NULL, -- unique identifier for the insurance plan
    plan_name character varying(200) NOT NULL, -- name of the insurance plan
    insurance_provider character varying(100) NOT NULL, -- name of the insurance company
    plan_type character varying(50), -- e.g., PPO, HMO, EPO
    contact_phone character varying(20), -- provider contact number
    website character varying(255), -- provider website
    PRIMARY KEY (plan_id)
)
CREATE TABLE healthcare.patient_insurance (
    patient_insurance_id character varying(64) NOT NULL, -- unique identifier for this patient-plan link
    patient_id character varying(64) NOT NULL, -- FK to patients table
    plan_id character varying(64) NOT NULL, -- FK to insurance_plans table
    policy_number character varying(100) NOT NULL, -- patient's policy number
    group_number character varying(100), -- group number, if applicable
    subscriber_name character varying(200), -- name of the primary policy holder
    effective_date date NOT NULL, -- date the coverage begins
    expiration_date date, -- date the coverage ends (if known)
    is_primary boolean NOT NULL DEFAULT true, -- indicates if this is the primary insurance
    PRIMARY KEY (patient_insurance_id),
    UNIQUE (patient_id, plan_id, policy_number) -- ensure a patient doesn't have the same policy twice
)


[User] List the names of services for which documents are set to expire in the next 90 days.

[Assistant] SELECT DISTINCT T1.service_name FROM government_services.services AS T1 JOIN applications AS T2 ON T1.service_id = T2.service_id JOIN government_services.documents AS T3 ON T2.application_id = T3.application_id WHERE T3.expiry_date IS NOT NULL AND T3.expiry_date BETWEEN CURRENT_DATE AND CURRENT_DATE + INTERVAL '90 days'

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.services ( service_id text PRIMARY KEY, agency_id text, service_name text, description text, category text, eligibility_criteria text, standard_fee numeric, average_processing_time_days int, is_active boolean, online_application_url text )
CREATE TABLE government_services.documents ( document_id text PRIMARY KEY, application_id text, citizen_id text, document_type text, file_reference text, upload_timestamp timestamp, expiry_date date, verification_status text, verified_by_employee_id text, verification_timestamp timestamp )


[User] Find all wallets created by users in the last 7 days along with any tokens that have a total supply greater than 10 million, showing the wallet address and token details.

[Assistant] SELECT w.address AS wallet_address, t.token_name, t.token_symbol, t.total_supply, t.contract_address FROM web3.wallets w JOIN web3.tokens t ON t.total_supply > 10000000 WHERE w.created_at >= CURRENT_DATE - INTERVAL '7 days';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.tokens ( token_id character varying(64) NOT NULL, contract_address character varying(128) NOT NULL, token_name character varying(128) NOT NULL, token_symbol character varying(32) NOT NULL, decimals integer NOT NULL, total_supply numeric(38,14) NOT NULL, PRIMARY KEY (token_id) )
CREATE TABLE web3.wallets ( wallet_id character varying(64) NOT NULL, user_id character varying(64) NOT NULL, address character varying(128) NOT NULL, private_key text NOT NULL, created_at timestamp NOT NULL, PRIMARY KEY (wallet_id) )


[User] Provide a count of how many peers were last seen on each distinct day recorded in the system.

[Assistant] SELECT DATE(last_seen), COUNT(*) FROM trading_platform.peers GROUP BY DATE(last_seen) ORDER BY DATE(last_seen);

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE trading_platform.users ( user_id text, username text, email text, password_hash text, created_at timestamp )
CREATE TABLE trading_platform.wallets ( wallet_id text, user_id text, address text, private_key text, created_at timestamp )
CREATE TABLE trading_platform.orders ( order_id text, user_id text, wallet_id text, asset_id text, order_type text, quantity numeric, price numeric, status text, created_at timestamp )
CREATE TABLE trading_platform.trades ( trade_id text, order_id text, buyer_id text, seller_id text, asset_id text, quantity numeric, price numeric, traded_at timestamp )
CREATE TABLE trading_platform.assets ( asset_id text, name text, symbol text, type text )
CREATE TABLE trading_platform.utxos ( utxo_id text, transaction_id text, output_index integer, address text, amount numeric, spent boolean )
CREATE TABLE trading_platform.dapps ( dapp_id text, name text, description text, url text )
CREATE TABLE trading_platform.peers ( peer_id text, ip_address text, port integer, last_seen timestamp )
CREATE TABLE trading_platform.kyc_audit ( kyc_audit_id text, user_id text, status text, reviewed_at timestamp )
CREATE TABLE trading_platform.logs ( log_id text, user_id text, action text, details text, logged_at timestamp )
CREATE TABLE trading_platform.notifications ( notification_id text, user_id text, message text, sent_at timestamp, read_at timestamp )