{"id": "arith-0", "prompt": "Add 5 and 96.", "completion": "This is an addition problem over the numbers 5 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 95, and the remaining 6 gives 101. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 101 returns 5, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 101.", "meta": {"a": 5, "b": 96, "result": 101, "style": "long"}}
{"id": "arith-1", "prompt": "What is 30 minus 19?", "completion": "This is a subtraction problem over the numbers 30 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 20, and removing the last 9 leaves 11. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 19 back to 11 returns 30, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 11.", "meta": {"a": 30, "b": 19, "result": 11, "style": "long"}}
{"id": "arith-2", "prompt": "Add 77 and 56.", "completion": "This is an addition problem over the numbers 77 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 127, and the remaining 6 gives 133. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 56 from 133 returns 77, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 133.", "meta": {"a": 77, "b": 56, "result": 133, "style": "long"}}
{"id": "arith-3", "prompt": "What is 13 plus 29?", "completion": "This is an addition problem over the numbers 13 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 33, and the remaining 9 gives 42. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 29 from 42 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 42.", "meta": {"a": 13, "b": 29, "result": 42, "style": "long"}}
{"id": "arith-4", "prompt": "What is 73 plus 27?", "completion": "This is an addition problem over the numbers 73 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 93, and the remaining 7 gives 100. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 27 from 100 returns 73, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 100.", "meta": {"a": 73, "b": 27, "result": 100, "style": "long"}}
{"id": "arith-5", "prompt": "What is 59 minus 77?", "completion": "This is a subtraction problem over the numbers 59 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -11, and removing the last 7 leaves -18. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 77 back to -18 returns 59, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -18.", "meta": {"a": 59, "b": 77, "result": -18, "style": "long"}}
{"id": "arith-6", "prompt": "What is 99 plus 22?", "completion": "This is an addition problem over the numbers 99 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 119, and the remaining 2 gives 121. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 22 from 121 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 121.", "meta": {"a": 99, "b": 22, "result": 121, "style": "long"}}
{"id": "arith-7", "prompt": "What is 37 times 21?", "completion": "This is a multiplication problem over the numbers 37 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 740, and by the remaining 1 gives 37, which sum to 777. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 21 times 37 is also 777, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 777.", "meta": {"a": 37, "b": 21, "result": 777, "style": "long"}}
{"id": "arith-8", "prompt": "What is 15 times 13?", "completion": "This is a multiplication problem over the numbers 15 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 150, and by the remaining 3 gives 45, which sum to 195. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 13 times 15 is also 195, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 195.", "meta": {"a": 15, "b": 13, "result": 195, "style": "long"}}
{"id": "arith-9", "prompt": "Add 47 and 46.", "completion": "This is an addition problem over the numbers 47 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 87, and the remaining 6 gives 93. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 46 from 93 returns 47, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 93.", "meta": {"a": 47, "b": 46, "result": 93, "style": "long"}}
{"id": "arith-10", "prompt": "What is 95 plus 60?", "completion": "This is an addition problem over the numbers 95 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 155, and the remaining 0 gives 155. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 60 from 155 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 155.", "meta": {"a": 95, "b": 60, "result": 155, "style": "long"}}
{"id": "arith-11", "prompt": "Multiply 12 by 72.", "completion": "This is a multiplication problem over the numbers 12 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 840, and by the remaining 2 gives 24, which sum to 864. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 72 times 12 is also 864, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 864.", "meta": {"a": 12, "b": 72, "result": 864, "style": "long"}}
{"id": "arith-12", "prompt": "What is 75 times 26?", "completion": "This is a multiplication problem over the numbers 75 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1500, and by the remaining 6 gives 450, which sum to 1950. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 26 times 75 is also 1950, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1950.", "meta": {"a": 75, "b": 26, "result": 1950, "style": "long"}}
{"id": "arith-13", "prompt": "What is 86 plus 31?", "completion": "This is an addition problem over the numbers 86 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 116, and the remaining 1 gives 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 31 from 117 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 86, "b": 31, "result": 117, "style": "long"}}
{"id": "arith-14", "prompt": "Add 31 and 14.", "completion": "This is an addition problem over the numbers 31 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 41, and the remaining 4 gives 45. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 14 from 45 returns 31, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 45.", "meta": {"a": 31, "b": 14, "result": 45, "style": "long"}}
{"id": "arith-15", "prompt": "Subtract 83 from 60.", "completion": "This is a subtraction problem over the numbers 60 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -20, and removing the last 3 leaves -23. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 83 back to -23 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -23.", "meta": {"a": 60, "b": 83, "result": -23, "style": "long"}}
{"id": "arith-16", "prompt": "What do you get when you add 49 to 47?", "completion": "This is an addition problem over the numbers 49 and 47, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 89, and the remaining 7 gives 96. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 47 from 96 returns 49, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 96.", "meta": {"a": 49, "b": 47, "result": 96, "style": "long"}}
{"id": "arith-17", "prompt": "Subtract 89 from 91.", "completion": "This is a subtraction problem over the numbers 91 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 11, and removing the last 9 leaves 2. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 89 back to 2 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2.", "meta": {"a": 91, "b": 89, "result": 2, "style": "long"}}
{"id": "arith-18", "prompt": "What do you get when you add 70 to 95?", "completion": "This is an addition problem over the numbers 70 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 160, and the remaining 5 gives 165. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 95 from 165 returns 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 165.", "meta": {"a": 70, "b": 95, "result": 165, "style": "long"}}
{"id": "arith-19", "prompt": "What do you get when you add 61 to 50?", "completion": "This is an addition problem over the numbers 61 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 111, and the remaining 0 gives 111. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 50 from 111 returns 61, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 111.", "meta": {"a": 61, "b": 50, "result": 111, "style": "long"}}
{"id": "arith-20", "prompt": "What is 89 minus 43?", "completion": "This is a subtraction problem over the numbers 89 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 49, and removing the last 3 leaves 46. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 43 back to 46 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 46.", "meta": {"a": 89, "b": 43, "result": 46, "style": "long"}}
{"id": "arith-21", "prompt": "What is 6 minus 42?", "completion": "This is a subtraction problem over the numbers 6 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -34, and removing the last 2 leaves -36. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 42 back to -36 returns 6, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -36.", "meta": {"a": 6, "b": 42, "result": -36, "style": "long"}}
{"id": "arith-22", "prompt": "Subtract 29 from 10.", "completion": "This is a subtraction problem over the numbers 10 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves -10, and removing the last 9 leaves -19. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 29 back to -19 returns 10, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -19.", "meta": {"a": 10, "b": 29, "result": -19, "style": "long"}}
{"id": "arith-23", "prompt": "What is 85 minus 65?", "completion": "This is a subtraction problem over the numbers 85 and 65, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves 25, and removing the last 5 leaves 20. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 65 back to 20 returns 85, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 20.", "meta": {"a": 85, "b": 65, "result": 20, "style": "long"}}
{"id": "arith-24", "prompt": "What is the product of 20 and 35?", "completion": "This is a multiplication problem over the numbers 20 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 600, and by the remaining 5 gives 100, which sum to 700. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 35 times 20 is also 700, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 700.", "meta": {"a": 20, "b": 35, "result": 700, "style": "long"}}
{"id": "arith-25", "prompt": "What is 97 minus 73?", "completion": "This is a subtraction problem over the numbers 97 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 27, and removing the last 3 leaves 24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 73 back to 24 returns 97, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 24.", "meta": {"a": 97, "b": 73, "result": 24, "style": "long"}}
{"id": "arith-26", "prompt": "Multiply 76 by 53.", "completion": "This is a multiplication problem over the numbers 76 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3800, and by the remaining 3 gives 228, which sum to 4028. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 53 times 76 is also 4028, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4028.", "meta": {"a": 76, "b": 53, "result": 4028, "style": "long"}}
{"id": "arith-27", "prompt": "What is 19 minus 67?", "completion": "This is a subtraction problem over the numbers 19 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -41, and removing the last 7 leaves -48. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 67 back to -48 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -48.", "meta": {"a": 19, "b": 67, "result": -48, "style": "long"}}
{"id": "arith-28", "prompt": "Add 98 and 8.", "completion": "This is an addition problem over the numbers 98 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 98, and the remaining 8 gives 106. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 8 from 106 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 106.", "meta": {"a": 98, "b": 8, "result": 106, "style": "long"}}
{"id": "arith-29", "prompt": "What do you get when you add 82 to 22?", "completion": "This is an addition problem over the numbers 82 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 102, and the remaining 2 gives 104. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 22 from 104 returns 82, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 104.", "meta": {"a": 82, "b": 22, "result": 104, "style": "long"}}
{"id": "arith-30", "prompt": "Add 51 and 50.", "completion": "This is an addition problem over the numbers 51 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 101, and the remaining 0 gives 101. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 50 from 101 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 101.", "meta": {"a": 51, "b": 50, "result": 101, "style": "long"}}
{"id": "arith-31", "prompt": "Subtract 3 from 72.", "completion": "This is a subtraction problem over the numbers 72 and 3, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 72, and removing the last 3 leaves 69. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 3 back to 69 returns 72, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 69.", "meta": {"a": 72, "b": 3, "result": 69, "style": "long"}}
{"id": "arith-32", "prompt": "Subtract 45 from 84.", "completion": "This is a subtraction problem over the numbers 84 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 44, and removing the last 5 leaves 39. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 45 back to 39 returns 84, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 39.", "meta": {"a": 84, "b": 45, "result": 39, "style": "long"}}
{"id": "arith-33", "prompt": "Subtract 22 from 57.", "completion": "This is a subtraction problem over the numbers 57 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 37, and removing the last 2 leaves 35. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 22 back to 35 returns 57, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 35.", "meta": {"a": 57, "b": 22, "result": 35, "style": "long"}}
{"id": "arith-34", "prompt": "What is 94 plus 94?", "completion": "This is an addition problem over the numbers 94 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 184, and the remaining 4 gives 188. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 94 from 188 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 188.", "meta": {"a": 94, "b": 94, "result": 188, "style": "long"}}
{"id": "arith-35", "prompt": "What do you get when you add 66 to 15?", "completion": "This is an addition problem over the numbers 66 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 76, and the remaining 5 gives 81. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 15 from 81 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 81.", "meta": {"a": 66, "b": 15, "result": 81, "style": "long"}}
{"id": "arith-36", "prompt": "What is 21 minus 49?", "completion": "This is a subtraction problem over the numbers 21 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -19, and removing the last 9 leaves -28. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 49 back to -28 returns 21, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -28.", "meta": {"a": 21, "b": 49, "result": -28, "style": "long"}}
{"id": "arith-37", "prompt": "What is 78 plus 43?", "completion": "This is an addition problem over the numbers 78 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 118, and the remaining 3 gives 121. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 43 from 121 returns 78, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 121.", "meta": {"a": 78, "b": 43, "result": 121, "style": "long"}}
{"id": "arith-38", "prompt": "What is 16 plus 48?", "completion": "This is an addition problem over the numbers 16 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 56, and the remaining 8 gives 64. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 48 from 64 returns 16, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 64.", "meta": {"a": 16, "b": 48, "result": 64, "style": "long"}}
{"id": "arith-39", "prompt": "What is 9 minus 32?", "completion": "This is a subtraction problem over the numbers 9 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves -21, and removing the last 2 leaves -23. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 32 back to -23 returns 9, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -23.", "meta": {"a": 9, "b": 32, "result": -23, "style": "long"}}
{"id": "arith-40", "prompt": "Add 95 and 64.", "completion": "This is an addition problem over the numbers 95 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 155, and the remaining 4 gives 159. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 64 from 159 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 159.", "meta": {"a": 95, "b": 64, "result": 159, "style": "long"}}
{"id": "arith-41", "prompt": "What do you get when you add 18 to 86?", "completion": "This is an addition problem over the numbers 18 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 98, and the remaining 6 gives 104. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 86 from 104 returns 18, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 104.", "meta": {"a": 18, "b": 86, "result": 104, "style": "long"}}
{"id": "arith-42", "prompt": "What do you get when you add 35 to 69?", "completion": "This is an addition problem over the numbers 35 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 95, and the remaining 9 gives 104. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 69 from 104 returns 35, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 104.", "meta": {"a": 35, "b": 69, "result": 104, "style": "long"}}
{"id": "arith-43", "prompt": "What is 71 minus 98?", "completion": "This is a subtraction problem over the numbers 71 and 98, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -19, and removing the last 8 leaves -27. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 98 back to -27 returns 71, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -27.", "meta": {"a": 71, "b": 98, "result": -27, "style": "long"}}
{"id": "arith-44", "prompt": "Subtract 87 from 53.", "completion": "This is a subtraction problem over the numbers 53 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -27, and removing the last 7 leaves -34. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 87 back to -34 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -34.", "meta": {"a": 53, "b": 87, "result": -34, "style": "long"}}
{"id": "arith-45", "prompt": "What is the product of 68 and 59?", "completion": "This is a multiplication problem over the numbers 68 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3400, and by the remaining 9 gives 612, which sum to 4012. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 59 times 68 is also 4012, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4012.", "meta": {"a": 68, "b": 59, "result": 4012, "style": "long"}}
{"id": "arith-46", "prompt": "What is 30 minus 10?", "completion": "This is a subtraction problem over the numbers 30 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 20, and removing the last 0 leaves 20. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 10 back to 20 returns 30, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 20.", "meta": {"a": 30, "b": 10, "result": 20, "style": "long"}}
{"id": "arith-47", "prompt": "What is 77 plus 72?", "completion": "This is an addition problem over the numbers 77 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 147, and the remaining 2 gives 149. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 72 from 149 returns 77, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 149.", "meta": {"a": 77, "b": 72, "result": 149, "style": "long"}}
{"id": "arith-48", "prompt": "What is 2 minus 11?", "completion": "This is a subtraction problem over the numbers 2 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves -8, and removing the last 1 leaves -9. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 11 back to -9 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -9.", "meta": {"a": 2, "b": 11, "result": -9, "style": "long"}}
{"id": "arith-49", "prompt": "What is 10 minus 6?", "completion": "This is a subtraction problem over the numbers 10 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 10, and removing the last 6 leaves 4. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 6 back to 4 returns 10, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4.", "meta": {"a": 10, "b": 6, "result": 4, "style": "long"}}
{"id": "arith-50", "prompt": "Add 67 and 32.", "completion": "This is an addition problem over the numbers 67 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 97, and the remaining 2 gives 99. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 32 from 99 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 99.", "meta": {"a": 67, "b": 32, "result": 99, "style": "long"}}
{"id": "arith-51", "prompt": "What is the product of 29 and 71?", "completion": "This is a multiplication problem over the numbers 29 and 71, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 2030, and by the remaining 1 gives 29, which sum to 2059. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 71 times 29 is also 2059, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2059.", "meta": {"a": 29, "b": 71, "result": 2059, "style": "long"}}
{"id": "arith-52", "prompt": "What is the product of 33 and 62?", "completion": "This is a multiplication problem over the numbers 33 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1980, and by the remaining 2 gives 66, which sum to 2046. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 33 is also 2046, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2046.", "meta": {"a": 33, "b": 62, "result": 2046, "style": "long"}}
{"id": "arith-53", "prompt": "What is 14 minus 14?", "completion": "This is a subtraction problem over the numbers 14 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 4, and removing the last 4 leaves 0. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 14 back to 0 returns 14, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 0.", "meta": {"a": 14, "b": 14, "result": 0, "style": "long"}}
{"id": "arith-54", "prompt": "What is 56 times 54?", "completion": "This is a multiplication problem over the numbers 56 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2800, and by the remaining 4 gives 224, which sum to 3024. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 54 times 56 is also 3024, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3024.", "meta": {"a": 56, "b": 54, "result": 3024, "style": "long"}}
{"id": "arith-55", "prompt": "What is 88 plus 85?", "completion": "This is an addition problem over the numbers 88 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 168, and the remaining 5 gives 173. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 85 from 173 returns 88, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 173.", "meta": {"a": 88, "b": 85, "result": 173, "style": "long"}}
{"id": "arith-56", "prompt": "What is 53 plus 95?", "completion": "This is an addition problem over the numbers 53 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 143, and the remaining 5 gives 148. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 95 from 148 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 148.", "meta": {"a": 53, "b": 95, "result": 148, "style": "long"}}
{"id": "arith-57", "prompt": "Add 33 and 26.", "completion": "This is an addition problem over the numbers 33 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 53, and the remaining 6 gives 59. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 26 from 59 returns 33, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 59.", "meta": {"a": 33, "b": 26, "result": 59, "style": "long"}}
{"id": "arith-58", "prompt": "What is the product of 19 and 56?", "completion": "This is a multiplication problem over the numbers 19 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 950, and by the remaining 6 gives 114, which sum to 1064. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 56 times 19 is also 1064, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1064.", "meta": {"a": 19, "b": 56, "result": 1064, "style": "long"}}
{"id": "arith-59", "prompt": "Subtract 33 from 61.", "completion": "This is a subtraction problem over the numbers 61 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 31, and removing the last 3 leaves 28. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 33 back to 28 returns 61, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 28.", "meta": {"a": 61, "b": 33, "result": 28, "style": "long"}}
{"id": "arith-60", "prompt": "What is the product of 72 and 14?", "completion": "This is a multiplication problem over the numbers 72 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 720, and by the remaining 4 gives 288, which sum to 1008. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 14 times 72 is also 1008, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1008.", "meta": {"a": 72, "b": 14, "result": 1008, "style": "long"}}
{"id": "arith-61", "prompt": "What is 13 plus 98?", "completion": "This is an addition problem over the numbers 13 and 98, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 103, and the remaining 8 gives 111. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 98 from 111 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 111.", "meta": {"a": 13, "b": 98, "result": 111, "style": "long"}}
{"id": "arith-62", "prompt": "What do you get when you add 54 to 64?", "completion": "This is an addition problem over the numbers 54 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 114, and the remaining 4 gives 118. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 64 from 118 returns 54, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 118.", "meta": {"a": 54, "b": 64, "result": 118, "style": "long"}}
{"id": "arith-63", "prompt": "What is 53 minus 9?", "completion": "This is a subtraction problem over the numbers 53 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 53, and removing the last 9 leaves 44. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 9 back to 44 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 44.", "meta": {"a": 53, "b": 9, "result": 44, "style": "long"}}
{"id": "arith-64", "prompt": "Multiply 2 by 51.", "completion": "This is a multiplication problem over the numbers 2 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 100, and by the remaining 1 gives 2, which sum to 102. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 51 times 2 is also 102, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 102.", "meta": {"a": 2, "b": 51, "result": 102, "style": "long"}}
{"id": "arith-65", "prompt": "What is the product of 38 and 56?", "completion": "This is a multiplication problem over the numbers 38 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 1900, and by the remaining 6 gives 228, which sum to 2128. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 56 times 38 is also 2128, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2128.", "meta": {"a": 38, "b": 56, "result": 2128, "style": "long"}}
{"id": "arith-66", "prompt": "What do you get when you add 26 to 39?", "completion": "This is an addition problem over the numbers 26 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 56, and the remaining 9 gives 65. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 39 from 65 returns 26, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 65.", "meta": {"a": 26, "b": 39, "result": 65, "style": "long"}}
{"id": "arith-67", "prompt": "What is 76 plus 96?", "completion": "This is an addition problem over the numbers 76 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 166, and the remaining 6 gives 172. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 172 returns 76, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 172.", "meta": {"a": 76, "b": 96, "result": 172, "style": "long"}}
{"id": "arith-68", "prompt": "What is 9 times 8?", "completion": "This is a multiplication problem over the numbers 9 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 72, which sum to 72. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 9 is also 72, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 72.", "meta": {"a": 9, "b": 8, "result": 72, "style": "long"}}
{"id": "arith-69", "prompt": "What do you get when you add 9 to 67?", "completion": "This is an addition problem over the numbers 9 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 69, and the remaining 7 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 67 from 76 returns 9, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 9, "b": 67, "result": 76, "style": "long"}}
{"id": "arith-70", "prompt": "What do you get when you add 10 to 78?", "completion": "This is an addition problem over the numbers 10 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 80, and the remaining 8 gives 88. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 78 from 88 returns 10, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 88.", "meta": {"a": 10, "b": 78, "result": 88, "style": "long"}}
{"id": "arith-71", "prompt": "What is 53 minus 17?", "completion": "This is a subtraction problem over the numbers 53 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 43, and removing the last 7 leaves 36. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 17 back to 36 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 36.", "meta": {"a": 53, "b": 17, "result": 36, "style": "long"}}
{"id": "arith-72", "prompt": "What is 81 plus 12?", "completion": "This is an addition problem over the numbers 81 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 91, and the remaining 2 gives 93. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 12 from 93 returns 81, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 93.", "meta": {"a": 81, "b": 12, "result": 93, "style": "long"}}
{"id": "arith-73", "prompt": "What is 35 times 28?", "completion": "This is a multiplication problem over the numbers 35 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 700, and by the remaining 8 gives 280, which sum to 980. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 28 times 35 is also 980, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 980.", "meta": {"a": 35, "b": 28, "result": 980, "style": "long"}}
{"id": "arith-74", "prompt": "What is 35 minus 52?", "completion": "This is a subtraction problem over the numbers 35 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -15, and removing the last 2 leaves -17. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 52 back to -17 returns 35, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -17.", "meta": {"a": 35, "b": 52, "result": -17, "style": "long"}}
{"id": "arith-75", "prompt": "Subtract 42 from 60.", "completion": "This is a subtraction problem over the numbers 60 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 20, and removing the last 2 leaves 18. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 42 back to 18 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 18.", "meta": {"a": 60, "b": 42, "result": 18, "style": "long"}}
{"id": "arith-76", "prompt": "What is 60 plus 81?", "completion": "This is an addition problem over the numbers 60 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 140, and the remaining 1 gives 141. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 81 from 141 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 141.", "meta": {"a": 60, "b": 81, "result": 141, "style": "long"}}
{"id": "arith-77", "prompt": "Add 70 and 29.", "completion": "This is an addition problem over the numbers 70 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 90, and the remaining 9 gives 99. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 29 from 99 returns 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 99.", "meta": {"a": 70, "b": 29, "result": 99, "style": "long"}}
{"id": "arith-78", "prompt": "What do you get when you add 46 to 10?", "completion": "This is an addition problem over the numbers 46 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 56, and the remaining 0 gives 56. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 10 from 56 returns 46, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 56.", "meta": {"a": 46, "b": 10, "result": 56, "style": "long"}}
{"id": "arith-79", "prompt": "What is 38 times 22?", "completion": "This is a multiplication problem over the numbers 38 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 760, and by the remaining 2 gives 76, which sum to 836. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 22 times 38 is also 836, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 836.", "meta": {"a": 38, "b": 22, "result": 836, "style": "long"}}
{"id": "arith-80", "prompt": "Subtract 85 from 80.", "completion": "This is a subtraction problem over the numbers 80 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 0, and removing the last 5 leaves -5. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 85 back to -5 returns 80, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -5.", "meta": {"a": 80, "b": 85, "result": -5, "style": "long"}}
{"id": "arith-81", "prompt": "Subtract 15 from 86.", "completion": "This is a subtraction problem over the numbers 86 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 76, and removing the last 5 leaves 71. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 15 back to 71 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 71.", "meta": {"a": 86, "b": 15, "result": 71, "style": "long"}}
{"id": "arith-82", "prompt": "Subtract 15 from 16.", "completion": "This is a subtraction problem over the numbers 16 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 6, and removing the last 5 leaves 1. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 15 back to 1 returns 16, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1.", "meta": {"a": 16, "b": 15, "result": 1, "style": "long"}}
{"id": "arith-83", "prompt": "Subtract 79 from 38.", "completion": "This is a subtraction problem over the numbers 38 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -32, and removing the last 9 leaves -41. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 79 back to -41 returns 38, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -41.", "meta": {"a": 38, "b": 79, "result": -41, "style": "long"}}
{"id": "arith-84", "prompt": "What is 28 times 89?", "completion": "This is a multiplication problem over the numbers 28 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 2240, and by the remaining 9 gives 252, which sum to 2492. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 89 times 28 is also 2492, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2492.", "meta": {"a": 28, "b": 89, "result": 2492, "style": "long"}}
{"id": "arith-85", "prompt": "What is the product of 34 and 8?", "completion": "This is a multiplication problem over the numbers 34 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 272, which sum to 272. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 34 is also 272, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 272.", "meta": {"a": 34, "b": 8, "result": 272, "style": "long"}}
{"id": "arith-86", "prompt": "Multiply 37 by 7.", "completion": "This is a multiplication problem over the numbers 37 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 7 gives 259, which sum to 259. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 7 times 37 is also 259, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 259.", "meta": {"a": 37, "b": 7, "result": 259, "style": "long"}}
{"id": "arith-87", "prompt": "What is 18 times 83?", "completion": "This is a multiplication problem over the numbers 18 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1440, and by the remaining 3 gives 54, which sum to 1494. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 83 times 18 is also 1494, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1494.", "meta": {"a": 18, "b": 83, "result": 1494, "style": "long"}}
{"id": "arith-88", "prompt": "What do you get when you add 96 to 58?", "completion": "This is an addition problem over the numbers 96 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 146, and the remaining 8 gives 154. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 58 from 154 returns 96, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 154.", "meta": {"a": 96, "b": 58, "result": 154, "style": "long"}}
{"id": "arith-89", "prompt": "What is 16 plus 11?", "completion": "This is an addition problem over the numbers 16 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 26, and the remaining 1 gives 27. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 11 from 27 returns 16, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 27.", "meta": {"a": 16, "b": 11, "result": 27, "style": "long"}}
{"id": "arith-90", "prompt": "What is 49 plus 76?", "completion": "This is an addition problem over the numbers 49 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 119, and the remaining 6 gives 125. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 76 from 125 returns 49, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 125.", "meta": {"a": 49, "b": 76, "result": 125, "style": "long"}}
{"id": "arith-91", "prompt": "Multiply 18 by 7.", "completion": "This is a multiplication problem over the numbers 18 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 7 gives 126, which sum to 126. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 7 times 18 is also 126, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 126.", "meta": {"a": 18, "b": 7, "result": 126, "style": "long"}}
{"id": "arith-92", "prompt": "What is 7 times 47?", "completion": "This is a multiplication problem over the numbers 7 and 47, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 280, and by the remaining 7 gives 49, which sum to 329. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 47 times 7 is also 329, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 329.", "meta": {"a": 7, "b": 47, "result": 329, "style": "long"}}
{"id": "arith-93", "prompt": "What is 87 minus 15?", "completion": "This is a subtraction problem over the numbers 87 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 77, and removing the last 5 leaves 72. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 15 back to 72 returns 87, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 72.", "meta": {"a": 87, "b": 15, "result": 72, "style": "long"}}
{"id": "arith-94", "prompt": "Multiply 81 by 97.", "completion": "This is a multiplication problem over the numbers 81 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7290, and by the remaining 7 gives 567, which sum to 7857. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 81 is also 7857, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7857.", "meta": {"a": 81, "b": 97, "result": 7857, "style": "long"}}
{"id": "arith-95", "prompt": "What is 22 minus 24?", "completion": "This is a subtraction problem over the numbers 22 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 2, and removing the last 4 leaves -2. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 24 back to -2 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -2.", "meta": {"a": 22, "b": 24, "result": -2, "style": "long"}}
{"id": "arith-96", "prompt": "What is 24 plus 96?", "completion": "This is an addition problem over the numbers 24 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 114, and the remaining 6 gives 120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 120 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 120.", "meta": {"a": 24, "b": 96, "result": 120, "style": "long"}}
{"id": "arith-97", "prompt": "Multiply 87 by 96.", "completion": "This is a multiplication problem over the numbers 87 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7830, and by the remaining 6 gives 522, which sum to 8352. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 96 times 87 is also 8352, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8352.", "meta": {"a": 87, "b": 96, "result": 8352, "style": "long"}}
{"id": "arith-98", "prompt": "Subtract 91 from 22.", "completion": "This is a subtraction problem over the numbers 22 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -68, and removing the last 1 leaves -69. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 91 back to -69 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -69.", "meta": {"a": 22, "b": 91, "result": -69, "style": "long"}}
{"id": "arith-99", "prompt": "Multiply 6 by 62.", "completion": "This is a multiplication problem over the numbers 6 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 360, and by the remaining 2 gives 12, which sum to 372. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 6 is also 372, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 372.", "meta": {"a": 6, "b": 62, "result": 372, "style": "long"}}
{"id": "arith-100", "prompt": "What is 60 minus 46?", "completion": "This is a subtraction problem over the numbers 60 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 20, and removing the last 6 leaves 14. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 46 back to 14 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 14.", "meta": {"a": 60, "b": 46, "result": 14, "style": "long"}}
{"id": "arith-101", "prompt": "What is 30 minus 5?", "completion": "This is a subtraction problem over the numbers 30 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 30, and removing the last 5 leaves 25. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 5 back to 25 returns 30, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 25.", "meta": {"a": 30, "b": 5, "result": 25, "style": "long"}}
{"id": "arith-102", "prompt": "Multiply 44 by 37.", "completion": "This is a multiplication problem over the numbers 44 and 37, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1320, and by the remaining 7 gives 308, which sum to 1628. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 37 times 44 is also 1628, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1628.", "meta": {"a": 44, "b": 37, "result": 1628, "style": "long"}}
{"id": "arith-103", "prompt": "Subtract 84 from 46.", "completion": "This is a subtraction problem over the numbers 46 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -34, and removing the last 4 leaves -38. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 84 back to -38 returns 46, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -38.", "meta": {"a": 46, "b": 84, "result": -38, "style": "long"}}
{"id": "arith-104", "prompt": "What is 5 times 16?", "completion": "This is a multiplication problem over the numbers 5 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 50, and by the remaining 6 gives 30, which sum to 80. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 16 times 5 is also 80, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 80.", "meta": {"a": 5, "b": 16, "result": 80, "style": "long"}}
{"id": "arith-105", "prompt": "What do you get when you add 76 to 35?", "completion": "This is an addition problem over the numbers 76 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 106, and the remaining 5 gives 111. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 35 from 111 returns 76, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 111.", "meta": {"a": 76, "b": 35, "result": 111, "style": "long"}}
{"id": "arith-106", "prompt": "Add 78 and 57.", "completion": "This is an addition problem over the numbers 78 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 128, and the remaining 7 gives 135. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 57 from 135 returns 78, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 135.", "meta": {"a": 78, "b": 57, "result": 135, "style": "long"}}
{"id": "arith-107", "prompt": "What is 57 times 79?", "completion": "This is a multiplication problem over the numbers 57 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3990, and by the remaining 9 gives 513, which sum to 4503. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 79 times 57 is also 4503, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4503.", "meta": {"a": 57, "b": 79, "result": 4503, "style": "long"}}
{"id": "arith-108", "prompt": "Multiply 75 by 26.", "completion": "This is a multiplication problem over the numbers 75 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1500, and by the remaining 6 gives 450, which sum to 1950. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 26 times 75 is also 1950, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1950.", "meta": {"a": 75, "b": 26, "result": 1950, "style": "long"}}
{"id": "arith-109", "prompt": "What is 92 plus 57?", "completion": "This is an addition problem over the numbers 92 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 142, and the remaining 7 gives 149. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 57 from 149 returns 92, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 149.", "meta": {"a": 92, "b": 57, "result": 149, "style": "long"}}
{"id": "arith-110", "prompt": "What is 48 minus 57?", "completion": "This is a subtraction problem over the numbers 48 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -2, and removing the last 7 leaves -9. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 57 back to -9 returns 48, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -9.", "meta": {"a": 48, "b": 57, "result": -9, "style": "long"}}
{"id": "arith-111", "prompt": "What is 81 times 42?", "completion": "This is a multiplication problem over the numbers 81 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3240, and by the remaining 2 gives 162, which sum to 3402. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 81 is also 3402, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3402.", "meta": {"a": 81, "b": 42, "result": 3402, "style": "long"}}
{"id": "arith-112", "prompt": "Subtract 41 from 66.", "completion": "This is a subtraction problem over the numbers 66 and 41, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 26, and removing the last 1 leaves 25. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 41 back to 25 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 25.", "meta": {"a": 66, "b": 41, "result": 25, "style": "long"}}
{"id": "arith-113", "prompt": "What is 53 times 91?", "completion": "This is a multiplication problem over the numbers 53 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 4770, and by the remaining 1 gives 53, which sum to 4823. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 91 times 53 is also 4823, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4823.", "meta": {"a": 53, "b": 91, "result": 4823, "style": "long"}}
{"id": "arith-114", "prompt": "What do you get when you add 26 to 55?", "completion": "This is an addition problem over the numbers 26 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 76, and the remaining 5 gives 81. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 55 from 81 returns 26, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 81.", "meta": {"a": 26, "b": 55, "result": 81, "style": "long"}}
{"id": "arith-115", "prompt": "What do you get when you add 80 to 74?", "completion": "This is an addition problem over the numbers 80 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 150, and the remaining 4 gives 154. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 74 from 154 returns 80, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 154.", "meta": {"a": 80, "b": 74, "result": 154, "style": "long"}}
{"id": "arith-116", "prompt": "Multiply 72 by 2.", "completion": "This is a multiplication problem over the numbers 72 and 2, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 2 gives 144, which sum to 144. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 2 times 72 is also 144, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 144.", "meta": {"a": 72, "b": 2, "result": 144, "style": "long"}}
{"id": "arith-117", "prompt": "Subtract 57 from 28.", "completion": "This is a subtraction problem over the numbers 28 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -22, and removing the last 7 leaves -29. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 57 back to -29 returns 28, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -29.", "meta": {"a": 28, "b": 57, "result": -29, "style": "long"}}
{"id": "arith-118", "prompt": "What is the product of 58 and 58?", "completion": "This is a multiplication problem over the numbers 58 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2900, and by the remaining 8 gives 464, which sum to 3364. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 58 times 58 is also 3364, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3364.", "meta": {"a": 58, "b": 58, "result": 3364, "style": "long"}}
{"id": "arith-119", "prompt": "What is the product of 96 and 23?", "completion": "This is a multiplication problem over the numbers 96 and 23, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1920, and by the remaining 3 gives 288, which sum to 2208. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 23 times 96 is also 2208, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2208.", "meta": {"a": 96, "b": 23, "result": 2208, "style": "long"}}
{"id": "arith-120", "prompt": "Subtract 86 from 67.", "completion": "This is a subtraction problem over the numbers 67 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -13, and removing the last 6 leaves -19. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 86 back to -19 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -19.", "meta": {"a": 67, "b": 86, "result": -19, "style": "long"}}
{"id": "arith-121", "prompt": "Add 98 and 32.", "completion": "This is an addition problem over the numbers 98 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 128, and the remaining 2 gives 130. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 32 from 130 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 130.", "meta": {"a": 98, "b": 32, "result": 130, "style": "long"}}
{"id": "arith-122", "prompt": "What is 27 minus 20?", "completion": "This is a subtraction problem over the numbers 27 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 7, and removing the last 0 leaves 7. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 20 back to 7 returns 27, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7.", "meta": {"a": 27, "b": 20, "result": 7, "style": "long"}}
{"id": "arith-123", "prompt": "What is 33 plus 62?", "completion": "This is an addition problem over the numbers 33 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 93, and the remaining 2 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 62 from 95 returns 33, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 33, "b": 62, "result": 95, "style": "long"}}
{"id": "arith-124", "prompt": "What is the product of 55 and 82?", "completion": "This is a multiplication problem over the numbers 55 and 82, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 4400, and by the remaining 2 gives 110, which sum to 4510. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 82 times 55 is also 4510, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4510.", "meta": {"a": 55, "b": 82, "result": 4510, "style": "long"}}
{"id": "arith-125", "prompt": "Multiply 65 by 53.", "completion": "This is a multiplication problem over the numbers 65 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3250, and by the remaining 3 gives 195, which sum to 3445. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 53 times 65 is also 3445, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3445.", "meta": {"a": 65, "b": 53, "result": 3445, "style": "long"}}
{"id": "arith-126", "prompt": "What do you get when you add 85 to 90?", "completion": "This is an addition problem over the numbers 85 and 90, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 175, and the remaining 0 gives 175. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 90 from 175 returns 85, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 175.", "meta": {"a": 85, "b": 90, "result": 175, "style": "long"}}
{"id": "arith-127", "prompt": "Add 56 and 30.", "completion": "This is an addition problem over the numbers 56 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 86, and the remaining 0 gives 86. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 30 from 86 returns 56, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 86.", "meta": {"a": 56, "b": 30, "result": 86, "style": "long"}}
{"id": "arith-128", "prompt": "What is the product of 8 and 73?", "completion": "This is a multiplication problem over the numbers 8 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 560, and by the remaining 3 gives 24, which sum to 584. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 73 times 8 is also 584, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 584.", "meta": {"a": 8, "b": 73, "result": 584, "style": "long"}}
{"id": "arith-129", "prompt": "Add 60 and 19.", "completion": "This is an addition problem over the numbers 60 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 70, and the remaining 9 gives 79. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 19 from 79 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 79.", "meta": {"a": 60, "b": 19, "result": 79, "style": "long"}}
{"id": "arith-130", "prompt": "What is 98 times 58?", "completion": "This is a multiplication problem over the numbers 98 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4900, and by the remaining 8 gives 784, which sum to 5684. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 58 times 98 is also 5684, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5684.", "meta": {"a": 98, "b": 58, "result": 5684, "style": "long"}}
{"id": "arith-131", "prompt": "What is the product of 22 and 97?", "completion": "This is a multiplication problem over the numbers 22 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 1980, and by the remaining 7 gives 154, which sum to 2134. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 22 is also 2134, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2134.", "meta": {"a": 22, "b": 97, "result": 2134, "style": "long"}}
{"id": "arith-132", "prompt": "What is the product of 35 and 98?", "completion": "This is a multiplication problem over the numbers 35 and 98, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 3150, and by the remaining 8 gives 280, which sum to 3430. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 98 times 35 is also 3430, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3430.", "meta": {"a": 35, "b": 98, "result": 3430, "style": "long"}}
{"id": "arith-133", "prompt": "Subtract 64 from 68.", "completion": "This is a subtraction problem over the numbers 68 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves 8, and removing the last 4 leaves 4. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 64 back to 4 returns 68, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4.", "meta": {"a": 68, "b": 64, "result": 4, "style": "long"}}
{"id": "arith-134", "prompt": "Subtract 11 from 58.", "completion": "This is a subtraction problem over the numbers 58 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 48, and removing the last 1 leaves 47. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 11 back to 47 returns 58, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 47.", "meta": {"a": 58, "b": 11, "result": 47, "style": "long"}}
{"id": "arith-135", "prompt": "What is 36 minus 44?", "completion": "This is a subtraction problem over the numbers 36 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -4, and removing the last 4 leaves -8. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 44 back to -8 returns 36, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -8.", "meta": {"a": 36, "b": 44, "result": -8, "style": "long"}}
{"id": "arith-136", "prompt": "Add 19 and 21.", "completion": "This is an addition problem over the numbers 19 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 39, and the remaining 1 gives 40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 21 from 40 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 40.", "meta": {"a": 19, "b": 21, "result": 40, "style": "long"}}
{"id": "arith-137", "prompt": "Multiply 90 by 21.", "completion": "This is a multiplication problem over the numbers 90 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1800, and by the remaining 1 gives 90, which sum to 1890. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 21 times 90 is also 1890, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1890.", "meta": {"a": 90, "b": 21, "result": 1890, "style": "long"}}
{"id": "arith-138", "prompt": "Add 55 and 54.", "completion": "This is an addition problem over the numbers 55 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 105, and the remaining 4 gives 109. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 54 from 109 returns 55, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 109.", "meta": {"a": 55, "b": 54, "result": 109, "style": "long"}}
{"id": "arith-139", "prompt": "What is the product of 55 and 9?", "completion": "This is a multiplication problem over the numbers 55 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 9 gives 495, which sum to 495. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 9 times 55 is also 495, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 495.", "meta": {"a": 55, "b": 9, "result": 495, "style": "long"}}
{"id": "arith-140", "prompt": "Multiply 51 by 76.", "completion": "This is a multiplication problem over the numbers 51 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3570, and by the remaining 6 gives 306, which sum to 3876. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 76 times 51 is also 3876, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3876.", "meta": {"a": 51, "b": 76, "result": 3876, "style": "long"}}
{"id": "arith-141", "prompt": "Multiply 63 by 2.", "completion": "This is a multiplication problem over the numbers 63 and 2, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 2 gives 126, which sum to 126. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 2 times 63 is also 126, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 126.", "meta": {"a": 63, "b": 2, "result": 126, "style": "long"}}
{"id": "arith-142", "prompt": "Subtract 51 from 98.", "completion": "This is a subtraction problem over the numbers 98 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 48, and removing the last 1 leaves 47. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 51 back to 47 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 47.", "meta": {"a": 98, "b": 51, "result": 47, "style": "long"}}
{"id": "arith-143", "prompt": "What is 64 minus 30?", "completion": "This is a subtraction problem over the numbers 64 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 34, and removing the last 0 leaves 34. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 30 back to 34 returns 64, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 34.", "meta": {"a": 64, "b": 30, "result": 34, "style": "long"}}
{"id": "arith-144", "prompt": "Multiply 64 by 5.", "completion": "This is a multiplication problem over the numbers 64 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 5 gives 320, which sum to 320. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 5 times 64 is also 320, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 320.", "meta": {"a": 64, "b": 5, "result": 320, "style": "long"}}
{"id": "arith-145", "prompt": "What is 87 times 88?", "completion": "This is a multiplication problem over the numbers 87 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 6960, and by the remaining 8 gives 696, which sum to 7656. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 88 times 87 is also 7656, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7656.", "meta": {"a": 87, "b": 88, "result": 7656, "style": "long"}}
{"id": "arith-146", "prompt": "What do you get when you add 61 to 18?", "completion": "This is an addition problem over the numbers 61 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 71, and the remaining 8 gives 79. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 18 from 79 returns 61, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 79.", "meta": {"a": 61, "b": 18, "result": 79, "style": "long"}}
{"id": "arith-147", "prompt": "Multiply 77 by 74.", "completion": "This is a multiplication problem over the numbers 77 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 5390, and by the remaining 4 gives 308, which sum to 5698. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 74 times 77 is also 5698, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5698.", "meta": {"a": 77, "b": 74, "result": 5698, "style": "long"}}
{"id": "arith-148", "prompt": "Add 84 and 56.", "completion": "This is an addition problem over the numbers 84 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 134, and the remaining 6 gives 140. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 56 from 140 returns 84, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 140.", "meta": {"a": 84, "b": 56, "result": 140, "style": "long"}}
{"id": "arith-149", "prompt": "What is the product of 25 and 8?", "completion": "This is a multiplication problem over the numbers 25 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 200, which sum to 200. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 25 is also 200, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 200.", "meta": {"a": 25, "b": 8, "result": 200, "style": "long"}}
{"id": "arith-150", "prompt": "Multiply 43 by 29.", "completion": "This is a multiplication problem over the numbers 43 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 860, and by the remaining 9 gives 387, which sum to 1247. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 29 times 43 is also 1247, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1247.", "meta": {"a": 43, "b": 29, "result": 1247, "style": "long"}}
{"id": "arith-151", "prompt": "What is 45 times 99?", "completion": "This is a multiplication problem over the numbers 45 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 4050, and by the remaining 9 gives 405, which sum to 4455. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 99 times 45 is also 4455, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4455.", "meta": {"a": 45, "b": 99, "result": 4455, "style": "long"}}
{"id": "arith-152", "prompt": "Subtract 55 from 98.", "completion": "This is a subtraction problem over the numbers 98 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 48, and removing the last 5 leaves 43. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 55 back to 43 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 43.", "meta": {"a": 98, "b": 55, "result": 43, "style": "long"}}
{"id": "arith-153", "prompt": "Add 62 and 4.", "completion": "This is an addition problem over the numbers 62 and 4, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 62, and the remaining 4 gives 66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 4 from 66 returns 62, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 66.", "meta": {"a": 62, "b": 4, "result": 66, "style": "long"}}
{"id": "arith-154", "prompt": "What is 30 times 85?", "completion": "This is a multiplication problem over the numbers 30 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 2400, and by the remaining 5 gives 150, which sum to 2550. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 30 is also 2550, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2550.", "meta": {"a": 30, "b": 85, "result": 2550, "style": "long"}}
{"id": "arith-155", "prompt": "What is 98 plus 5?", "completion": "This is an addition problem over the numbers 98 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 98, and the remaining 5 gives 103. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 5 from 103 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 103.", "meta": {"a": 98, "b": 5, "result": 103, "style": "long"}}
{"id": "arith-156", "prompt": "What is 4 minus 81?", "completion": "This is a subtraction problem over the numbers 4 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -76, and removing the last 1 leaves -77. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 81 back to -77 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -77.", "meta": {"a": 4, "b": 81, "result": -77, "style": "long"}}
{"id": "arith-157", "prompt": "What is 18 minus 62?", "completion": "This is a subtraction problem over the numbers 18 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -42, and removing the last 2 leaves -44. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 62 back to -44 returns 18, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -44.", "meta": {"a": 18, "b": 62, "result": -44, "style": "long"}}
{"id": "arith-158", "prompt": "What is 61 minus 91?", "completion": "This is a subtraction problem over the numbers 61 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -29, and removing the last 1 leaves -30. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 91 back to -30 returns 61, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -30.", "meta": {"a": 61, "b": 91, "result": -30, "style": "long"}}
{"id": "arith-159", "prompt": "What is 23 times 79?", "completion": "This is a multiplication problem over the numbers 23 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 1610, and by the remaining 9 gives 207, which sum to 1817. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 79 times 23 is also 1817, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1817.", "meta": {"a": 23, "b": 79, "result": 1817, "style": "long"}}
{"id": "arith-160", "prompt": "What do you get when you add 41 to 15?", "completion": "This is an addition problem over the numbers 41 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 51, and the remaining 5 gives 56. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 15 from 56 returns 41, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 56.", "meta": {"a": 41, "b": 15, "result": 56, "style": "long"}}
{"id": "arith-161", "prompt": "Subtract 88 from 75.", "completion": "This is a subtraction problem over the numbers 75 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -5, and removing the last 8 leaves -13. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 88 back to -13 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -13.", "meta": {"a": 75, "b": 88, "result": -13, "style": "long"}}
{"id": "arith-162", "prompt": "Multiply 93 by 27.", "completion": "This is a multiplication problem over the numbers 93 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1860, and by the remaining 7 gives 651, which sum to 2511. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 27 times 93 is also 2511, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2511.", "meta": {"a": 93, "b": 27, "result": 2511, "style": "long"}}
{"id": "arith-163", "prompt": "What is 15 minus 91?", "completion": "This is a subtraction problem over the numbers 15 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -75, and removing the last 1 leaves -76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 91 back to -76 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -76.", "meta": {"a": 15, "b": 91, "result": -76, "style": "long"}}
{"id": "arith-164", "prompt": "Add 74 and 7.", "completion": "This is an addition problem over the numbers 74 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 74, and the remaining 7 gives 81. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 7 from 81 returns 74, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 81.", "meta": {"a": 74, "b": 7, "result": 81, "style": "long"}}
{"id": "arith-165", "prompt": "Multiply 86 by 49.", "completion": "This is a multiplication problem over the numbers 86 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3440, and by the remaining 9 gives 774, which sum to 4214. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 49 times 86 is also 4214, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4214.", "meta": {"a": 86, "b": 49, "result": 4214, "style": "long"}}
{"id": "arith-166", "prompt": "What is 3 times 55?", "completion": "This is a multiplication problem over the numbers 3 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 150, and by the remaining 5 gives 15, which sum to 165. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 55 times 3 is also 165, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 165.", "meta": {"a": 3, "b": 55, "result": 165, "style": "long"}}
{"id": "arith-167", "prompt": "Add 57 and 48.", "completion": "This is an addition problem over the numbers 57 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 97, and the remaining 8 gives 105. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 48 from 105 returns 57, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 105.", "meta": {"a": 57, "b": 48, "result": 105, "style": "long"}}
{"id": "arith-168", "prompt": "What do you get when you add 57 to 24?", "completion": "This is an addition problem over the numbers 57 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 77, and the remaining 4 gives 81. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 24 from 81 returns 57, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 81.", "meta": {"a": 57, "b": 24, "result": 81, "style": "long"}}
{"id": "arith-169", "prompt": "What is the product of 61 and 57?", "completion": "This is a multiplication problem over the numbers 61 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3050, and by the remaining 7 gives 427, which sum to 3477. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 57 times 61 is also 3477, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3477.", "meta": {"a": 61, "b": 57, "result": 3477, "style": "long"}}
{"id": "arith-170", "prompt": "What is 33 times 13?", "completion": "This is a multiplication problem over the numbers 33 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 330, and by the remaining 3 gives 99, which sum to 429. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 13 times 33 is also 429, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 429.", "meta": {"a": 33, "b": 13, "result": 429, "style": "long"}}
{"id": "arith-171", "prompt": "What is the product of 33 and 98?", "completion": "This is a multiplication problem over the numbers 33 and 98, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 2970, and by the remaining 8 gives 264, which sum to 3234. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 98 times 33 is also 3234, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3234.", "meta": {"a": 33, "b": 98, "result": 3234, "style": "long"}}
{"id": "arith-172", "prompt": "Multiply 45 by 5.", "completion": "This is a multiplication problem over the numbers 45 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 5 gives 225, which sum to 225. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 5 times 45 is also 225, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 225.", "meta": {"a": 45, "b": 5, "result": 225, "style": "long"}}
{"id": "arith-173", "prompt": "What is 25 times 64?", "completion": "This is a multiplication problem over the numbers 25 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1500, and by the remaining 4 gives 100, which sum to 1600. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 64 times 25 is also 1600, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1600.", "meta": {"a": 25, "b": 64, "result": 1600, "style": "long"}}
{"id": "arith-174", "prompt": "What is 35 times 45?", "completion": "This is a multiplication problem over the numbers 35 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1400, and by the remaining 5 gives 175, which sum to 1575. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 45 times 35 is also 1575, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1575.", "meta": {"a": 35, "b": 45, "result": 1575, "style": "long"}}
{"id": "arith-175", "prompt": "Subtract 3 from 73.", "completion": "This is a subtraction problem over the numbers 73 and 3, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 73, and removing the last 3 leaves 70. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 3 back to 70 returns 73, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 70.", "meta": {"a": 73, "b": 3, "result": 70, "style": "long"}}
{"id": "arith-176", "prompt": "Add 32 and 94.", "completion": "This is an addition problem over the numbers 32 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 122, and the remaining 4 gives 126. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 94 from 126 returns 32, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 126.", "meta": {"a": 32, "b": 94, "result": 126, "style": "long"}}
{"id": "arith-177", "prompt": "What is the product of 73 and 99?", "completion": "This is a multiplication problem over the numbers 73 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 6570, and by the remaining 9 gives 657, which sum to 7227. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 99 times 73 is also 7227, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7227.", "meta": {"a": 73, "b": 99, "result": 7227, "style": "long"}}
{"id": "arith-178", "prompt": "What is the product of 84 and 93?", "completion": "This is a multiplication problem over the numbers 84 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7560, and by the remaining 3 gives 252, which sum to 7812. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 93 times 84 is also 7812, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7812.", "meta": {"a": 84, "b": 93, "result": 7812, "style": "long"}}
{"id": "arith-179", "prompt": "What is the product of 4 and 13?", "completion": "This is a multiplication problem over the numbers 4 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 40, and by the remaining 3 gives 12, which sum to 52. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 13 times 4 is also 52, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 52.", "meta": {"a": 4, "b": 13, "result": 52, "style": "long"}}
{"id": "arith-180", "prompt": "What is 53 minus 90?", "completion": "This is a subtraction problem over the numbers 53 and 90, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -37, and removing the last 0 leaves -37. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 90 back to -37 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -37.", "meta": {"a": 53, "b": 90, "result": -37, "style": "long"}}
{"id": "arith-181", "prompt": "Subtract 76 from 86.", "completion": "This is a subtraction problem over the numbers 86 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 16, and removing the last 6 leaves 10. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 76 back to 10 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 10.", "meta": {"a": 86, "b": 76, "result": 10, "style": "long"}}
{"id": "arith-182", "prompt": "What is the product of 72 and 69?", "completion": "This is a multiplication problem over the numbers 72 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4320, and by the remaining 9 gives 648, which sum to 4968. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 69 times 72 is also 4968, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4968.", "meta": {"a": 72, "b": 69, "result": 4968, "style": "long"}}
{"id": "arith-183", "prompt": "Multiply 97 by 72.", "completion": "This is a multiplication problem over the numbers 97 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 6790, and by the remaining 2 gives 194, which sum to 6984. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 72 times 97 is also 6984, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6984.", "meta": {"a": 97, "b": 72, "result": 6984, "style": "long"}}
{"id": "arith-184", "prompt": "What is 91 times 60?", "completion": "This is a multiplication problem over the numbers 91 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 5460, and by the remaining 0 gives 0, which sum to 5460. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 91 is also 5460, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5460.", "meta": {"a": 91, "b": 60, "result": 5460, "style": "long"}}
{"id": "arith-185", "prompt": "Subtract 31 from 34.", "completion": "This is a subtraction problem over the numbers 34 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 4, and removing the last 1 leaves 3. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 31 back to 3 returns 34, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3.", "meta": {"a": 34, "b": 31, "result": 3, "style": "long"}}
{"id": "arith-186", "prompt": "What is 42 minus 17?", "completion": "This is a subtraction problem over the numbers 42 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 32, and removing the last 7 leaves 25. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 17 back to 25 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 25.", "meta": {"a": 42, "b": 17, "result": 25, "style": "long"}}
{"id": "arith-187", "prompt": "What is 29 minus 96?", "completion": "This is a subtraction problem over the numbers 29 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -61, and removing the last 6 leaves -67. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 96 back to -67 returns 29, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -67.", "meta": {"a": 29, "b": 96, "result": -67, "style": "long"}}
{"id": "arith-188", "prompt": "Subtract 77 from 94.", "completion": "This is a subtraction problem over the numbers 94 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 24, and removing the last 7 leaves 17. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 77 back to 17 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 17.", "meta": {"a": 94, "b": 77, "result": 17, "style": "long"}}
{"id": "arith-189", "prompt": "Add 26 and 39.", "completion": "This is an addition problem over the numbers 26 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 56, and the remaining 9 gives 65. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 39 from 65 returns 26, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 65.", "meta": {"a": 26, "b": 39, "result": 65, "style": "long"}}
{"id": "arith-190", "prompt": "What is 24 times 40?", "completion": "This is a multiplication problem over the numbers 24 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 960, and by the remaining 0 gives 0, which sum to 960. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 40 times 24 is also 960, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 960.", "meta": {"a": 24, "b": 40, "result": 960, "style": "long"}}
{"id": "arith-191", "prompt": "What do you get when you add 37 to 7?", "completion": "This is an addition problem over the numbers 37 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 37, and the remaining 7 gives 44. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 7 from 44 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 44.", "meta": {"a": 37, "b": 7, "result": 44, "style": "long"}}
{"id": "arith-192", "prompt": "Subtract 18 from 91.", "completion": "This is a subtraction problem over the numbers 91 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 81, and removing the last 8 leaves 73. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 18 back to 73 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 73.", "meta": {"a": 91, "b": 18, "result": 73, "style": "long"}}
{"id": "arith-193", "prompt": "Add 3 and 75.", "completion": "This is an addition problem over the numbers 3 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 73, and the remaining 5 gives 78. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 75 from 78 returns 3, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 78.", "meta": {"a": 3, "b": 75, "result": 78, "style": "long"}}
{"id": "arith-194", "prompt": "What is the product of 63 and 58?", "completion": "This is a multiplication problem over the numbers 63 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3150, and by the remaining 8 gives 504, which sum to 3654. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 58 times 63 is also 3654, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3654.", "meta": {"a": 63, "b": 58, "result": 3654, "style": "long"}}
{"id": "arith-195", "prompt": "What do you get when you add 8 to 34?", "completion": "This is an addition problem over the numbers 8 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 38, and the remaining 4 gives 42. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 34 from 42 returns 8, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 42.", "meta": {"a": 8, "b": 34, "result": 42, "style": "long"}}
{"id": "arith-196", "prompt": "Add 10 and 53.", "completion": "This is an addition problem over the numbers 10 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 60, and the remaining 3 gives 63. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 53 from 63 returns 10, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 63.", "meta": {"a": 10, "b": 53, "result": 63, "style": "long"}}
{"id": "arith-197", "prompt": "Add 75 and 82.", "completion": "This is an addition problem over the numbers 75 and 82, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 155, and the remaining 2 gives 157. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 82 from 157 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 157.", "meta": {"a": 75, "b": 82, "result": 157, "style": "long"}}
{"id": "arith-198", "prompt": "What do you get when you add 21 to 74?", "completion": "This is an addition problem over the numbers 21 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 91, and the remaining 4 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 74 from 95 returns 21, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 21, "b": 74, "result": 95, "style": "long"}}
{"id": "arith-199", "prompt": "Add 33 and 17.", "completion": "This is an addition problem over the numbers 33 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 43, and the remaining 7 gives 50. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 17 from 50 returns 33, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 50.", "meta": {"a": 33, "b": 17, "result": 50, "style": "long"}}
{"id": "arith-200", "prompt": "What is 68 minus 50?", "completion": "This is a subtraction problem over the numbers 68 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 18, and removing the last 0 leaves 18. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 50 back to 18 returns 68, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 18.", "meta": {"a": 68, "b": 50, "result": 18, "style": "long"}}
{"id": "arith-201", "prompt": "What is the product of 40 and 77?", "completion": "This is a multiplication problem over the numbers 40 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 2800, and by the remaining 7 gives 280, which sum to 3080. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 77 times 40 is also 3080, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3080.", "meta": {"a": 40, "b": 77, "result": 3080, "style": "long"}}
{"id": "arith-202", "prompt": "Subtract 81 from 74.", "completion": "This is a subtraction problem over the numbers 74 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -6, and removing the last 1 leaves -7. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 81 back to -7 returns 74, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -7.", "meta": {"a": 74, "b": 81, "result": -7, "style": "long"}}
{"id": "arith-203", "prompt": "Add 99 and 28.", "completion": "This is an addition problem over the numbers 99 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 119, and the remaining 8 gives 127. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 28 from 127 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 127.", "meta": {"a": 99, "b": 28, "result": 127, "style": "long"}}
{"id": "arith-204", "prompt": "Subtract 12 from 86.", "completion": "This is a subtraction problem over the numbers 86 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 76, and removing the last 2 leaves 74. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 12 back to 74 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 74.", "meta": {"a": 86, "b": 12, "result": 74, "style": "long"}}
{"id": "arith-205", "prompt": "What is 24 minus 72?", "completion": "This is a subtraction problem over the numbers 24 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -46, and removing the last 2 leaves -48. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 72 back to -48 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -48.", "meta": {"a": 24, "b": 72, "result": -48, "style": "long"}}
{"id": "arith-206", "prompt": "What do you get when you add 2 to 54?", "completion": "This is an addition problem over the numbers 2 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 52, and the remaining 4 gives 56. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 54 from 56 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 56.", "meta": {"a": 2, "b": 54, "result": 56, "style": "long"}}
{"id": "arith-207", "prompt": "What is the product of 39 and 6?", "completion": "This is a multiplication problem over the numbers 39 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 6 gives 234, which sum to 234. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 6 times 39 is also 234, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 234.", "meta": {"a": 39, "b": 6, "result": 234, "style": "long"}}
{"id": "arith-208", "prompt": "Subtract 38 from 92.", "completion": "This is a subtraction problem over the numbers 92 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 62, and removing the last 8 leaves 54. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 38 back to 54 returns 92, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 54.", "meta": {"a": 92, "b": 38, "result": 54, "style": "long"}}
{"id": "arith-209", "prompt": "Add 89 and 31.", "completion": "This is an addition problem over the numbers 89 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 119, and the remaining 1 gives 120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 31 from 120 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 120.", "meta": {"a": 89, "b": 31, "result": 120, "style": "long"}}
{"id": "arith-210", "prompt": "What is 56 minus 16?", "completion": "This is a subtraction problem over the numbers 56 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 46, and removing the last 6 leaves 40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 16 back to 40 returns 56, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 40.", "meta": {"a": 56, "b": 16, "result": 40, "style": "long"}}
{"id": "arith-211", "prompt": "What do you get when you add 36 to 20?", "completion": "This is an addition problem over the numbers 36 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 56, and the remaining 0 gives 56. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 20 from 56 returns 36, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 56.", "meta": {"a": 36, "b": 20, "result": 56, "style": "long"}}
{"id": "arith-212", "prompt": "What is 23 plus 41?", "completion": "This is an addition problem over the numbers 23 and 41, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 63, and the remaining 1 gives 64. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 41 from 64 returns 23, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 64.", "meta": {"a": 23, "b": 41, "result": 64, "style": "long"}}
{"id": "arith-213", "prompt": "What is the product of 17 and 61?", "completion": "This is a multiplication problem over the numbers 17 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1020, and by the remaining 1 gives 17, which sum to 1037. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 61 times 17 is also 1037, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1037.", "meta": {"a": 17, "b": 61, "result": 1037, "style": "long"}}
{"id": "arith-214", "prompt": "Multiply 36 by 66.", "completion": "This is a multiplication problem over the numbers 36 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 2160, and by the remaining 6 gives 216, which sum to 2376. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 66 times 36 is also 2376, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2376.", "meta": {"a": 36, "b": 66, "result": 2376, "style": "long"}}
{"id": "arith-215", "prompt": "What is the product of 12 and 78?", "completion": "This is a multiplication problem over the numbers 12 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 840, and by the remaining 8 gives 96, which sum to 936. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 78 times 12 is also 936, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 936.", "meta": {"a": 12, "b": 78, "result": 936, "style": "long"}}
{"id": "arith-216", "prompt": "Multiply 96 by 43.", "completion": "This is a multiplication problem over the numbers 96 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3840, and by the remaining 3 gives 288, which sum to 4128. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 43 times 96 is also 4128, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4128.", "meta": {"a": 96, "b": 43, "result": 4128, "style": "long"}}
{"id": "arith-217", "prompt": "What is 13 plus 31?", "completion": "This is an addition problem over the numbers 13 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 43, and the remaining 1 gives 44. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 31 from 44 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 44.", "meta": {"a": 13, "b": 31, "result": 44, "style": "long"}}
{"id": "arith-218", "prompt": "Subtract 7 from 75.", "completion": "This is a subtraction problem over the numbers 75 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 75, and removing the last 7 leaves 68. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 7 back to 68 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 68.", "meta": {"a": 75, "b": 7, "result": 68, "style": "long"}}
{"id": "arith-219", "prompt": "What is the product of 68 and 85?", "completion": "This is a multiplication problem over the numbers 68 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 5440, and by the remaining 5 gives 340, which sum to 5780. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 68 is also 5780, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5780.", "meta": {"a": 68, "b": 85, "result": 5780, "style": "long"}}
{"id": "arith-220", "prompt": "Subtract 76 from 25.", "completion": "This is a subtraction problem over the numbers 25 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -45, and removing the last 6 leaves -51. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 76 back to -51 returns 25, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -51.", "meta": {"a": 25, "b": 76, "result": -51, "style": "long"}}
{"id": "arith-221", "prompt": "What is the product of 13 and 62?", "completion": "This is a multiplication problem over the numbers 13 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 780, and by the remaining 2 gives 26, which sum to 806. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 13 is also 806, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 806.", "meta": {"a": 13, "b": 62, "result": 806, "style": "long"}}
{"id": "arith-222", "prompt": "Multiply 44 by 43.", "completion": "This is a multiplication problem over the numbers 44 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1760, and by the remaining 3 gives 132, which sum to 1892. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 43 times 44 is also 1892, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1892.", "meta": {"a": 44, "b": 43, "result": 1892, "style": "long"}}
{"id": "arith-223", "prompt": "What do you get when you add 44 to 54?", "completion": "This is an addition problem over the numbers 44 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 94, and the remaining 4 gives 98. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 54 from 98 returns 44, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 98.", "meta": {"a": 44, "b": 54, "result": 98, "style": "long"}}
{"id": "arith-224", "prompt": "Subtract 53 from 86.", "completion": "This is a subtraction problem over the numbers 86 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 36, and removing the last 3 leaves 33. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 53 back to 33 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 33.", "meta": {"a": 86, "b": 53, "result": 33, "style": "long"}}
{"id": "arith-225", "prompt": "What is the product of 13 and 42?", "completion": "This is a multiplication problem over the numbers 13 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 520, and by the remaining 2 gives 26, which sum to 546. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 13 is also 546, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 546.", "meta": {"a": 13, "b": 42, "result": 546, "style": "long"}}
{"id": "arith-226", "prompt": "What is 16 times 53?", "completion": "This is a multiplication problem over the numbers 16 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 800, and by the remaining 3 gives 48, which sum to 848. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 53 times 16 is also 848, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 848.", "meta": {"a": 16, "b": 53, "result": 848, "style": "long"}}
{"id": "arith-227", "prompt": "What is the product of 54 and 8?", "completion": "This is a multiplication problem over the numbers 54 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 432, which sum to 432. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 54 is also 432, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 432.", "meta": {"a": 54, "b": 8, "result": 432, "style": "long"}}
{"id": "arith-228", "prompt": "What is 81 times 98?", "completion": "This is a multiplication problem over the numbers 81 and 98, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7290, and by the remaining 8 gives 648, which sum to 7938. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 98 times 81 is also 7938, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7938.", "meta": {"a": 81, "b": 98, "result": 7938, "style": "long"}}
{"id": "arith-229", "prompt": "What is the product of 99 and 8?", "completion": "This is a multiplication problem over the numbers 99 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 792, which sum to 792. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 99 is also 792, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 792.", "meta": {"a": 99, "b": 8, "result": 792, "style": "long"}}
{"id": "arith-230", "prompt": "Subtract 18 from 72.", "completion": "This is a subtraction problem over the numbers 72 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 62, and removing the last 8 leaves 54. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 18 back to 54 returns 72, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 54.", "meta": {"a": 72, "b": 18, "result": 54, "style": "long"}}
{"id": "arith-231", "prompt": "What is the product of 91 and 64?", "completion": "This is a multiplication problem over the numbers 91 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 5460, and by the remaining 4 gives 364, which sum to 5824. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 64 times 91 is also 5824, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5824.", "meta": {"a": 91, "b": 64, "result": 5824, "style": "long"}}
{"id": "arith-232", "prompt": "What is 82 plus 79?", "completion": "This is an addition problem over the numbers 82 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 152, and the remaining 9 gives 161. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 79 from 161 returns 82, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 161.", "meta": {"a": 82, "b": 79, "result": 161, "style": "long"}}
{"id": "arith-233", "prompt": "What do you get when you add 41 to 72?", "completion": "This is an addition problem over the numbers 41 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 111, and the remaining 2 gives 113. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 72 from 113 returns 41, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 113.", "meta": {"a": 41, "b": 72, "result": 113, "style": "long"}}
{"id": "arith-234", "prompt": "Multiply 13 by 30.", "completion": "This is a multiplication problem over the numbers 13 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 390, and by the remaining 0 gives 0, which sum to 390. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 30 times 13 is also 390, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 390.", "meta": {"a": 13, "b": 30, "result": 390, "style": "long"}}
{"id": "arith-235", "prompt": "What is the product of 17 and 84?", "completion": "This is a multiplication problem over the numbers 17 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1360, and by the remaining 4 gives 68, which sum to 1428. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 84 times 17 is also 1428, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1428.", "meta": {"a": 17, "b": 84, "result": 1428, "style": "long"}}
{"id": "arith-236", "prompt": "What is the product of 93 and 39?", "completion": "This is a multiplication problem over the numbers 93 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2790, and by the remaining 9 gives 837, which sum to 3627. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 39 times 93 is also 3627, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3627.", "meta": {"a": 93, "b": 39, "result": 3627, "style": "long"}}
{"id": "arith-237", "prompt": "Multiply 63 by 62.", "completion": "This is a multiplication problem over the numbers 63 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3780, and by the remaining 2 gives 126, which sum to 3906. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 63 is also 3906, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3906.", "meta": {"a": 63, "b": 62, "result": 3906, "style": "long"}}
{"id": "arith-238", "prompt": "What is the product of 72 and 20?", "completion": "This is a multiplication problem over the numbers 72 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1440, and by the remaining 0 gives 0, which sum to 1440. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 20 times 72 is also 1440, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1440.", "meta": {"a": 72, "b": 20, "result": 1440, "style": "long"}}
{"id": "arith-239", "prompt": "What is 78 minus 67?", "completion": "This is a subtraction problem over the numbers 78 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves 18, and removing the last 7 leaves 11. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 67 back to 11 returns 78, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 11.", "meta": {"a": 78, "b": 67, "result": 11, "style": "long"}}
{"id": "arith-240", "prompt": "Add 37 and 55.", "completion": "This is an addition problem over the numbers 37 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 87, and the remaining 5 gives 92. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 55 from 92 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 92.", "meta": {"a": 37, "b": 55, "result": 92, "style": "long"}}
{"id": "arith-241", "prompt": "Subtract 38 from 2.", "completion": "This is a subtraction problem over the numbers 2 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves -28, and removing the last 8 leaves -36. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 38 back to -36 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -36.", "meta": {"a": 2, "b": 38, "result": -36, "style": "long"}}
{"id": "arith-242", "prompt": "What is the product of 21 and 59?", "completion": "This is a multiplication problem over the numbers 21 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 1050, and by the remaining 9 gives 189, which sum to 1239. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 59 times 21 is also 1239, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1239.", "meta": {"a": 21, "b": 59, "result": 1239, "style": "long"}}
{"id": "arith-243", "prompt": "What is 44 times 72?", "completion": "This is a multiplication problem over the numbers 44 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3080, and by the remaining 2 gives 88, which sum to 3168. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 72 times 44 is also 3168, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3168.", "meta": {"a": 44, "b": 72, "result": 3168, "style": "long"}}
{"id": "arith-244", "prompt": "What is the product of 43 and 26?", "completion": "This is a multiplication problem over the numbers 43 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 860, and by the remaining 6 gives 258, which sum to 1118. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 26 times 43 is also 1118, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1118.", "meta": {"a": 43, "b": 26, "result": 1118, "style": "long"}}
{"id": "arith-245", "prompt": "Multiply 31 by 54.", "completion": "This is a multiplication problem over the numbers 31 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 1550, and by the remaining 4 gives 124, which sum to 1674. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 54 times 31 is also 1674, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1674.", "meta": {"a": 31, "b": 54, "result": 1674, "style": "long"}}
{"id": "arith-246", "prompt": "What is 97 times 62?", "completion": "This is a multiplication problem over the numbers 97 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 5820, and by the remaining 2 gives 194, which sum to 6014. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 97 is also 6014, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6014.", "meta": {"a": 97, "b": 62, "result": 6014, "style": "long"}}
{"id": "arith-247", "prompt": "Multiply 86 by 85.", "completion": "This is a multiplication problem over the numbers 86 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 6880, and by the remaining 5 gives 430, which sum to 7310. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 86 is also 7310, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7310.", "meta": {"a": 86, "b": 85, "result": 7310, "style": "long"}}
{"id": "arith-248", "prompt": "What is the product of 6 and 18?", "completion": "This is a multiplication problem over the numbers 6 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 60, and by the remaining 8 gives 48, which sum to 108. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 18 times 6 is also 108, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 108.", "meta": {"a": 6, "b": 18, "result": 108, "style": "long"}}
{"id": "arith-249", "prompt": "Add 58 and 14.", "completion": "This is an addition problem over the numbers 58 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 68, and the remaining 4 gives 72. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 14 from 72 returns 58, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 72.", "meta": {"a": 58, "b": 14, "result": 72, "style": "long"}}
{"id": "arith-250", "prompt": "What is 94 plus 20?", "completion": "This is an addition problem over the numbers 94 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 114, and the remaining 0 gives 114. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 20 from 114 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 114.", "meta": {"a": 94, "b": 20, "result": 114, "style": "long"}}
{"id": "arith-251", "prompt": "What do you get when you add 11 to 62?", "completion": "This is an addition problem over the numbers 11 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 71, and the remaining 2 gives 73. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 62 from 73 returns 11, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 73.", "meta": {"a": 11, "b": 62, "result": 73, "style": "long"}}
{"id": "arith-252", "prompt": "What is 81 times 90?", "completion": "This is a multiplication problem over the numbers 81 and 90, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7290, and by the remaining 0 gives 0, which sum to 7290. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 90 times 81 is also 7290, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7290.", "meta": {"a": 81, "b": 90, "result": 7290, "style": "long"}}
{"id": "arith-253", "prompt": "Add 44 and 88.", "completion": "This is an addition problem over the numbers 44 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 124, and the remaining 8 gives 132. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 88 from 132 returns 44, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 132.", "meta": {"a": 44, "b": 88, "result": 132, "style": "long"}}
{"id": "arith-254", "prompt": "What is 82 times 93?", "completion": "This is a multiplication problem over the numbers 82 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7380, and by the remaining 3 gives 246, which sum to 7626. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 93 times 82 is also 7626, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7626.", "meta": {"a": 82, "b": 93, "result": 7626, "style": "long"}}
{"id": "arith-255", "prompt": "What is 81 plus 10?", "completion": "This is an addition problem over the numbers 81 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 91, and the remaining 0 gives 91. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 10 from 91 returns 81, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 91.", "meta": {"a": 81, "b": 10, "result": 91, "style": "long"}}
{"id": "arith-256", "prompt": "Subtract 97 from 31.", "completion": "This is a subtraction problem over the numbers 31 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -59, and removing the last 7 leaves -66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 97 back to -66 returns 31, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -66.", "meta": {"a": 31, "b": 97, "result": -66, "style": "long"}}
{"id": "arith-257", "prompt": "Multiply 14 by 99.", "completion": "This is a multiplication problem over the numbers 14 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 1260, and by the remaining 9 gives 126, which sum to 1386. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 99 times 14 is also 1386, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1386.", "meta": {"a": 14, "b": 99, "result": 1386, "style": "long"}}
{"id": "arith-258", "prompt": "What is the product of 23 and 90?", "completion": "This is a multiplication problem over the numbers 23 and 90, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 2070, and by the remaining 0 gives 0, which sum to 2070. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 90 times 23 is also 2070, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2070.", "meta": {"a": 23, "b": 90, "result": 2070, "style": "long"}}
{"id": "arith-259", "prompt": "What is 7 plus 43?", "completion": "This is an addition problem over the numbers 7 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 47, and the remaining 3 gives 50. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 43 from 50 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 50.", "meta": {"a": 7, "b": 43, "result": 50, "style": "long"}}
{"id": "arith-260", "prompt": "Subtract 49 from 47.", "completion": "This is a subtraction problem over the numbers 47 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 7, and removing the last 9 leaves -2. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 49 back to -2 returns 47, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -2.", "meta": {"a": 47, "b": 49, "result": -2, "style": "long"}}
{"id": "arith-261", "prompt": "What do you get when you add 33 to 69?", "completion": "This is an addition problem over the numbers 33 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 93, and the remaining 9 gives 102. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 69 from 102 returns 33, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 102.", "meta": {"a": 33, "b": 69, "result": 102, "style": "long"}}
{"id": "arith-262", "prompt": "What do you get when you add 23 to 24?", "completion": "This is an addition problem over the numbers 23 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 43, and the remaining 4 gives 47. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 24 from 47 returns 23, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 47.", "meta": {"a": 23, "b": 24, "result": 47, "style": "long"}}
{"id": "arith-263", "prompt": "Multiply 81 by 89.", "completion": "This is a multiplication problem over the numbers 81 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 6480, and by the remaining 9 gives 729, which sum to 7209. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 89 times 81 is also 7209, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7209.", "meta": {"a": 81, "b": 89, "result": 7209, "style": "long"}}
{"id": "arith-264", "prompt": "What is the product of 76 and 20?", "completion": "This is a multiplication problem over the numbers 76 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1520, and by the remaining 0 gives 0, which sum to 1520. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 20 times 76 is also 1520, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1520.", "meta": {"a": 76, "b": 20, "result": 1520, "style": "long"}}
{"id": "arith-265", "prompt": "What is the product of 83 and 34?", "completion": "This is a multiplication problem over the numbers 83 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2490, and by the remaining 4 gives 332, which sum to 2822. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 34 times 83 is also 2822, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2822.", "meta": {"a": 83, "b": 34, "result": 2822, "style": "long"}}
{"id": "arith-266", "prompt": "Subtract 3 from 87.", "completion": "This is a subtraction problem over the numbers 87 and 3, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 87, and removing the last 3 leaves 84. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 3 back to 84 returns 87, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 84.", "meta": {"a": 87, "b": 3, "result": 84, "style": "long"}}
{"id": "arith-267", "prompt": "Subtract 71 from 88.", "completion": "This is a subtraction problem over the numbers 88 and 71, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 18, and removing the last 1 leaves 17. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 71 back to 17 returns 88, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 17.", "meta": {"a": 88, "b": 71, "result": 17, "style": "long"}}
{"id": "arith-268", "prompt": "Add 58 and 46.", "completion": "This is an addition problem over the numbers 58 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 98, and the remaining 6 gives 104. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 46 from 104 returns 58, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 104.", "meta": {"a": 58, "b": 46, "result": 104, "style": "long"}}
{"id": "arith-269", "prompt": "Multiply 90 by 34.", "completion": "This is a multiplication problem over the numbers 90 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2700, and by the remaining 4 gives 360, which sum to 3060. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 34 times 90 is also 3060, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3060.", "meta": {"a": 90, "b": 34, "result": 3060, "style": "long"}}
{"id": "arith-270", "prompt": "Subtract 51 from 27.", "completion": "This is a subtraction problem over the numbers 27 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -23, and removing the last 1 leaves -24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 51 back to -24 returns 27, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -24.", "meta": {"a": 27, "b": 51, "result": -24, "style": "long"}}
{"id": "arith-271", "prompt": "Add 32 and 50.", "completion": "This is an addition problem over the numbers 32 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 82, and the remaining 0 gives 82. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 50 from 82 returns 32, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 82.", "meta": {"a": 32, "b": 50, "result": 82, "style": "long"}}
{"id": "arith-272", "prompt": "Subtract 39 from 91.", "completion": "This is a subtraction problem over the numbers 91 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 61, and removing the last 9 leaves 52. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 39 back to 52 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 52.", "meta": {"a": 91, "b": 39, "result": 52, "style": "long"}}
{"id": "arith-273", "prompt": "Multiply 37 by 3.", "completion": "This is a multiplication problem over the numbers 37 and 3, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 3 gives 111, which sum to 111. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 3 times 37 is also 111, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 111.", "meta": {"a": 37, "b": 3, "result": 111, "style": "long"}}
{"id": "arith-274", "prompt": "What is the product of 38 and 31?", "completion": "This is a multiplication problem over the numbers 38 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1140, and by the remaining 1 gives 38, which sum to 1178. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 31 times 38 is also 1178, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1178.", "meta": {"a": 38, "b": 31, "result": 1178, "style": "long"}}
{"id": "arith-275", "prompt": "What is 83 minus 26?", "completion": "This is a subtraction problem over the numbers 83 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 63, and removing the last 6 leaves 57. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 26 back to 57 returns 83, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 57.", "meta": {"a": 83, "b": 26, "result": 57, "style": "long"}}
{"id": "arith-276", "prompt": "What do you get when you add 82 to 14?", "completion": "This is an addition problem over the numbers 82 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 92, and the remaining 4 gives 96. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 14 from 96 returns 82, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 96.", "meta": {"a": 82, "b": 14, "result": 96, "style": "long"}}
{"id": "arith-277", "prompt": "Subtract 6 from 58.", "completion": "This is a subtraction problem over the numbers 58 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 58, and removing the last 6 leaves 52. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 6 back to 52 returns 58, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 52.", "meta": {"a": 58, "b": 6, "result": 52, "style": "long"}}
{"id": "arith-278", "prompt": "What do you get when you add 13 to 39?", "completion": "This is an addition problem over the numbers 13 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 43, and the remaining 9 gives 52. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 39 from 52 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 52.", "meta": {"a": 13, "b": 39, "result": 52, "style": "long"}}
{"id": "arith-279", "prompt": "Multiply 24 by 27.", "completion": "This is a multiplication problem over the numbers 24 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 480, and by the remaining 7 gives 168, which sum to 648. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 27 times 24 is also 648, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 648.", "meta": {"a": 24, "b": 27, "result": 648, "style": "long"}}
{"id": "arith-280", "prompt": "What is 69 times 66?", "completion": "This is a multiplication problem over the numbers 69 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4140, and by the remaining 6 gives 414, which sum to 4554. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 66 times 69 is also 4554, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4554.", "meta": {"a": 69, "b": 66, "result": 4554, "style": "long"}}
{"id": "arith-281", "prompt": "What do you get when you add 34 to 63?", "completion": "This is an addition problem over the numbers 34 and 63, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 94, and the remaining 3 gives 97. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 63 from 97 returns 34, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 97.", "meta": {"a": 34, "b": 63, "result": 97, "style": "long"}}
{"id": "arith-282", "prompt": "What is 16 times 61?", "completion": "This is a multiplication problem over the numbers 16 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 960, and by the remaining 1 gives 16, which sum to 976. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 61 times 16 is also 976, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 976.", "meta": {"a": 16, "b": 61, "result": 976, "style": "long"}}
{"id": "arith-283", "prompt": "What do you get when you add 98 to 30?", "completion": "This is an addition problem over the numbers 98 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 128, and the remaining 0 gives 128. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 30 from 128 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 128.", "meta": {"a": 98, "b": 30, "result": 128, "style": "long"}}
{"id": "arith-284", "prompt": "What is 13 times 52?", "completion": "This is a multiplication problem over the numbers 13 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 650, and by the remaining 2 gives 26, which sum to 676. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 52 times 13 is also 676, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 676.", "meta": {"a": 13, "b": 52, "result": 676, "style": "long"}}
{"id": "arith-285", "prompt": "Subtract 17 from 70.", "completion": "This is a subtraction problem over the numbers 70 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 60, and removing the last 7 leaves 53. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 17 back to 53 returns 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 53.", "meta": {"a": 70, "b": 17, "result": 53, "style": "long"}}
{"id": "arith-286", "prompt": "What is 88 times 97?", "completion": "This is a multiplication problem over the numbers 88 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7920, and by the remaining 7 gives 616, which sum to 8536. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 88 is also 8536, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8536.", "meta": {"a": 88, "b": 97, "result": 8536, "style": "long"}}
{"id": "arith-287", "prompt": "Multiply 83 by 49.", "completion": "This is a multiplication problem over the numbers 83 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3320, and by the remaining 9 gives 747, which sum to 4067. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 49 times 83 is also 4067, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4067.", "meta": {"a": 83, "b": 49, "result": 4067, "style": "long"}}
{"id": "arith-288", "prompt": "What is 62 minus 5?", "completion": "This is a subtraction problem over the numbers 62 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 62, and removing the last 5 leaves 57. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 5 back to 57 returns 62, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 57.", "meta": {"a": 62, "b": 5, "result": 57, "style": "long"}}
{"id": "arith-289", "prompt": "What is 84 minus 10?", "completion": "This is a subtraction problem over the numbers 84 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 74, and removing the last 0 leaves 74. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 10 back to 74 returns 84, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 74.", "meta": {"a": 84, "b": 10, "result": 74, "style": "long"}}
{"id": "arith-290", "prompt": "Subtract 54 from 85.", "completion": "This is a subtraction problem over the numbers 85 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 35, and removing the last 4 leaves 31. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 54 back to 31 returns 85, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 31.", "meta": {"a": 85, "b": 54, "result": 31, "style": "long"}}
{"id": "arith-291", "prompt": "What do you get when you add 7 to 6?", "completion": "This is an addition problem over the numbers 7 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 7, and the remaining 6 gives 13. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 6 from 13 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 13.", "meta": {"a": 7, "b": 6, "result": 13, "style": "long"}}
{"id": "arith-292", "prompt": "What is the product of 16 and 14?", "completion": "This is a multiplication problem over the numbers 16 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 160, and by the remaining 4 gives 64, which sum to 224. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 14 times 16 is also 224, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 224.", "meta": {"a": 16, "b": 14, "result": 224, "style": "long"}}
{"id": "arith-293", "prompt": "What do you get when you add 51 to 60?", "completion": "This is an addition problem over the numbers 51 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 111, and the remaining 0 gives 111. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 60 from 111 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 111.", "meta": {"a": 51, "b": 60, "result": 111, "style": "long"}}
{"id": "arith-294", "prompt": "Multiply 77 by 97.", "completion": "This is a multiplication problem over the numbers 77 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 6930, and by the remaining 7 gives 539, which sum to 7469. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 77 is also 7469, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7469.", "meta": {"a": 77, "b": 97, "result": 7469, "style": "long"}}
{"id": "arith-295", "prompt": "Multiply 85 by 14.", "completion": "This is a multiplication problem over the numbers 85 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 850, and by the remaining 4 gives 340, which sum to 1190. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 14 times 85 is also 1190, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1190.", "meta": {"a": 85, "b": 14, "result": 1190, "style": "long"}}
{"id": "arith-296", "prompt": "Multiply 37 by 6.", "completion": "This is a multiplication problem over the numbers 37 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 6 gives 222, which sum to 222. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 6 times 37 is also 222, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 222.", "meta": {"a": 37, "b": 6, "result": 222, "style": "long"}}
{"id": "arith-297", "prompt": "What is 58 minus 58?", "completion": "This is a subtraction problem over the numbers 58 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 8, and removing the last 8 leaves 0. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 58 back to 0 returns 58, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 0.", "meta": {"a": 58, "b": 58, "result": 0, "style": "long"}}
{"id": "arith-298", "prompt": "What is 14 times 89?", "completion": "This is a multiplication problem over the numbers 14 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1120, and by the remaining 9 gives 126, which sum to 1246. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 89 times 14 is also 1246, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1246.", "meta": {"a": 14, "b": 89, "result": 1246, "style": "long"}}
{"id": "arith-299", "prompt": "What is 9 times 52?", "completion": "This is a multiplication problem over the numbers 9 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 450, and by the remaining 2 gives 18, which sum to 468. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 52 times 9 is also 468, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 468.", "meta": {"a": 9, "b": 52, "result": 468, "style": "long"}}
{"id": "arith-300", "prompt": "What is 17 minus 60?", "completion": "This is a subtraction problem over the numbers 17 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -43, and removing the last 0 leaves -43. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 60 back to -43 returns 17, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -43.", "meta": {"a": 17, "b": 60, "result": -43, "style": "long"}}
{"id": "arith-301", "prompt": "What is 84 minus 83?", "completion": "This is a subtraction problem over the numbers 84 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 4, and removing the last 3 leaves 1. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 83 back to 1 returns 84, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1.", "meta": {"a": 84, "b": 83, "result": 1, "style": "long"}}
{"id": "arith-302", "prompt": "What is 44 plus 33?", "completion": "This is an addition problem over the numbers 44 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 74, and the remaining 3 gives 77. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 33 from 77 returns 44, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 77.", "meta": {"a": 44, "b": 33, "result": 77, "style": "long"}}
{"id": "arith-303", "prompt": "What is 10 minus 99?", "completion": "This is a subtraction problem over the numbers 10 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -80, and removing the last 9 leaves -89. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 99 back to -89 returns 10, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -89.", "meta": {"a": 10, "b": 99, "result": -89, "style": "long"}}
{"id": "arith-304", "prompt": "What is 31 minus 44?", "completion": "This is a subtraction problem over the numbers 31 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -9, and removing the last 4 leaves -13. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 44 back to -13 returns 31, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -13.", "meta": {"a": 31, "b": 44, "result": -13, "style": "long"}}
{"id": "arith-305", "prompt": "What is 37 plus 20?", "completion": "This is an addition problem over the numbers 37 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 57, and the remaining 0 gives 57. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 20 from 57 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 57.", "meta": {"a": 37, "b": 20, "result": 57, "style": "long"}}
{"id": "arith-306", "prompt": "Subtract 16 from 24.", "completion": "This is a subtraction problem over the numbers 24 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 14, and removing the last 6 leaves 8. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 16 back to 8 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8.", "meta": {"a": 24, "b": 16, "result": 8, "style": "long"}}
{"id": "arith-307", "prompt": "What do you get when you add 3 to 47?", "completion": "This is an addition problem over the numbers 3 and 47, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 43, and the remaining 7 gives 50. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 47 from 50 returns 3, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 50.", "meta": {"a": 3, "b": 47, "result": 50, "style": "long"}}
{"id": "arith-308", "prompt": "What is 4 times 24?", "completion": "This is a multiplication problem over the numbers 4 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 80, and by the remaining 4 gives 16, which sum to 96. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 24 times 4 is also 96, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 96.", "meta": {"a": 4, "b": 24, "result": 96, "style": "long"}}
{"id": "arith-309", "prompt": "What is 18 plus 96?", "completion": "This is an addition problem over the numbers 18 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 108, and the remaining 6 gives 114. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 114 returns 18, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 114.", "meta": {"a": 18, "b": 96, "result": 114, "style": "long"}}
{"id": "arith-310", "prompt": "Add 97 and 10.", "completion": "This is an addition problem over the numbers 97 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 107, and the remaining 0 gives 107. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 10 from 107 returns 97, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 107.", "meta": {"a": 97, "b": 10, "result": 107, "style": "long"}}
{"id": "arith-311", "prompt": "What is the product of 48 and 67?", "completion": "This is a multiplication problem over the numbers 48 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 2880, and by the remaining 7 gives 336, which sum to 3216. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 67 times 48 is also 3216, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3216.", "meta": {"a": 48, "b": 67, "result": 3216, "style": "long"}}
{"id": "arith-312", "prompt": "What is the product of 66 and 30?", "completion": "This is a multiplication problem over the numbers 66 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1980, and by the remaining 0 gives 0, which sum to 1980. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 30 times 66 is also 1980, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1980.", "meta": {"a": 66, "b": 30, "result": 1980, "style": "long"}}
{"id": "arith-313", "prompt": "Subtract 84 from 60.", "completion": "This is a subtraction problem over the numbers 60 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -20, and removing the last 4 leaves -24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 84 back to -24 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -24.", "meta": {"a": 60, "b": 84, "result": -24, "style": "long"}}
{"id": "arith-314", "prompt": "What is 63 plus 53?", "completion": "This is an addition problem over the numbers 63 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 113, and the remaining 3 gives 116. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 53 from 116 returns 63, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 116.", "meta": {"a": 63, "b": 53, "result": 116, "style": "long"}}
{"id": "arith-315", "prompt": "Add 64 and 93.", "completion": "This is an addition problem over the numbers 64 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 154, and the remaining 3 gives 157. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 93 from 157 returns 64, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 157.", "meta": {"a": 64, "b": 93, "result": 157, "style": "long"}}
{"id": "arith-316", "prompt": "Add 12 and 43.", "completion": "This is an addition problem over the numbers 12 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 52, and the remaining 3 gives 55. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 43 from 55 returns 12, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 55.", "meta": {"a": 12, "b": 43, "result": 55, "style": "long"}}
{"id": "arith-317", "prompt": "Add 18 and 37.", "completion": "This is an addition problem over the numbers 18 and 37, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 48, and the remaining 7 gives 55. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 37 from 55 returns 18, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 55.", "meta": {"a": 18, "b": 37, "result": 55, "style": "long"}}
{"id": "arith-318", "prompt": "Multiply 78 by 69.", "completion": "This is a multiplication problem over the numbers 78 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4680, and by the remaining 9 gives 702, which sum to 5382. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 69 times 78 is also 5382, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5382.", "meta": {"a": 78, "b": 69, "result": 5382, "style": "long"}}
{"id": "arith-319", "prompt": "What is the product of 66 and 79?", "completion": "This is a multiplication problem over the numbers 66 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 4620, and by the remaining 9 gives 594, which sum to 5214. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 79 times 66 is also 5214, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5214.", "meta": {"a": 66, "b": 79, "result": 5214, "style": "long"}}
{"id": "arith-320", "prompt": "Add 91 and 16.", "completion": "This is an addition problem over the numbers 91 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 101, and the remaining 6 gives 107. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 16 from 107 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 107.", "meta": {"a": 91, "b": 16, "result": 107, "style": "long"}}
{"id": "arith-321", "prompt": "Multiply 59 by 31.", "completion": "This is a multiplication problem over the numbers 59 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1770, and by the remaining 1 gives 59, which sum to 1829. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 31 times 59 is also 1829, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1829.", "meta": {"a": 59, "b": 31, "result": 1829, "style": "long"}}
{"id": "arith-322", "prompt": "What is 60 times 53?", "completion": "This is a multiplication problem over the numbers 60 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3000, and by the remaining 3 gives 180, which sum to 3180. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 53 times 60 is also 3180, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3180.", "meta": {"a": 60, "b": 53, "result": 3180, "style": "long"}}
{"id": "arith-323", "prompt": "Add 42 and 56.", "completion": "This is an addition problem over the numbers 42 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 92, and the remaining 6 gives 98. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 56 from 98 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 98.", "meta": {"a": 42, "b": 56, "result": 98, "style": "long"}}
{"id": "arith-324", "prompt": "Subtract 21 from 49.", "completion": "This is a subtraction problem over the numbers 49 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 29, and removing the last 1 leaves 28. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 21 back to 28 returns 49, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 28.", "meta": {"a": 49, "b": 21, "result": 28, "style": "long"}}
{"id": "arith-325", "prompt": "Add 13 and 12.", "completion": "This is an addition problem over the numbers 13 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 23, and the remaining 2 gives 25. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 12 from 25 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 25.", "meta": {"a": 13, "b": 12, "result": 25, "style": "long"}}
{"id": "arith-326", "prompt": "Multiply 14 by 97.", "completion": "This is a multiplication problem over the numbers 14 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 1260, and by the remaining 7 gives 98, which sum to 1358. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 14 is also 1358, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1358.", "meta": {"a": 14, "b": 97, "result": 1358, "style": "long"}}
{"id": "arith-327", "prompt": "What do you get when you add 73 to 9?", "completion": "This is an addition problem over the numbers 73 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 73, and the remaining 9 gives 82. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 9 from 82 returns 73, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 82.", "meta": {"a": 73, "b": 9, "result": 82, "style": "long"}}
{"id": "arith-328", "prompt": "Add 54 and 47.", "completion": "This is an addition problem over the numbers 54 and 47, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 94, and the remaining 7 gives 101. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 47 from 101 returns 54, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 101.", "meta": {"a": 54, "b": 47, "result": 101, "style": "long"}}
{"id": "arith-329", "prompt": "What is 38 plus 78?", "completion": "This is an addition problem over the numbers 38 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 108, and the remaining 8 gives 116. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 78 from 116 returns 38, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 116.", "meta": {"a": 38, "b": 78, "result": 116, "style": "long"}}
{"id": "arith-330", "prompt": "What is 15 times 75?", "completion": "This is a multiplication problem over the numbers 15 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 1050, and by the remaining 5 gives 75, which sum to 1125. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 75 times 15 is also 1125, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1125.", "meta": {"a": 15, "b": 75, "result": 1125, "style": "long"}}
{"id": "arith-331", "prompt": "What do you get when you add 86 to 63?", "completion": "This is an addition problem over the numbers 86 and 63, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 146, and the remaining 3 gives 149. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 63 from 149 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 149.", "meta": {"a": 86, "b": 63, "result": 149, "style": "long"}}
{"id": "arith-332", "prompt": "Add 46 and 73.", "completion": "This is an addition problem over the numbers 46 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 116, and the remaining 3 gives 119. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 73 from 119 returns 46, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 119.", "meta": {"a": 46, "b": 73, "result": 119, "style": "long"}}
{"id": "arith-333", "prompt": "Add 99 and 37.", "completion": "This is an addition problem over the numbers 99 and 37, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 129, and the remaining 7 gives 136. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 37 from 136 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 136.", "meta": {"a": 99, "b": 37, "result": 136, "style": "long"}}
{"id": "arith-334", "prompt": "Multiply 73 by 81.", "completion": "This is a multiplication problem over the numbers 73 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 5840, and by the remaining 1 gives 73, which sum to 5913. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 81 times 73 is also 5913, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5913.", "meta": {"a": 73, "b": 81, "result": 5913, "style": "long"}}
{"id": "arith-335", "prompt": "Subtract 25 from 5.", "completion": "This is a subtraction problem over the numbers 5 and 25, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves -15, and removing the last 5 leaves -20. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 25 back to -20 returns 5, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -20.", "meta": {"a": 5, "b": 25, "result": -20, "style": "long"}}
{"id": "arith-336", "prompt": "Subtract 46 from 45.", "completion": "This is a subtraction problem over the numbers 45 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 5, and removing the last 6 leaves -1. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 46 back to -1 returns 45, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -1.", "meta": {"a": 45, "b": 46, "result": -1, "style": "long"}}
{"id": "arith-337", "prompt": "What do you get when you add 20 to 74?", "completion": "This is an addition problem over the numbers 20 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 90, and the remaining 4 gives 94. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 74 from 94 returns 20, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 94.", "meta": {"a": 20, "b": 74, "result": 94, "style": "long"}}
{"id": "arith-338", "prompt": "Add 20 and 96.", "completion": "This is an addition problem over the numbers 20 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 110, and the remaining 6 gives 116. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 116 returns 20, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 116.", "meta": {"a": 20, "b": 96, "result": 116, "style": "long"}}
{"id": "arith-339", "prompt": "Add 97 and 69.", "completion": "This is an addition problem over the numbers 97 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 157, and the remaining 9 gives 166. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 69 from 166 returns 97, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 166.", "meta": {"a": 97, "b": 69, "result": 166, "style": "long"}}
{"id": "arith-340", "prompt": "Multiply 55 by 60.", "completion": "This is a multiplication problem over the numbers 55 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3300, and by the remaining 0 gives 0, which sum to 3300. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 55 is also 3300, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3300.", "meta": {"a": 55, "b": 60, "result": 3300, "style": "long"}}
{"id": "arith-341", "prompt": "What do you get when you add 49 to 41?", "completion": "This is an addition problem over the numbers 49 and 41, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 89, and the remaining 1 gives 90. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 41 from 90 returns 49, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 90.", "meta": {"a": 49, "b": 41, "result": 90, "style": "long"}}
{"id": "arith-342", "prompt": "Add 8 and 21.", "completion": "This is an addition problem over the numbers 8 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 28, and the remaining 1 gives 29. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 21 from 29 returns 8, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 29.", "meta": {"a": 8, "b": 21, "result": 29, "style": "long"}}
{"id": "arith-343", "prompt": "What is 88 plus 12?", "completion": "This is an addition problem over the numbers 88 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 98, and the remaining 2 gives 100. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 12 from 100 returns 88, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 100.", "meta": {"a": 88, "b": 12, "result": 100, "style": "long"}}
{"id": "arith-344", "prompt": "What is the product of 86 and 56?", "completion": "This is a multiplication problem over the numbers 86 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4300, and by the remaining 6 gives 516, which sum to 4816. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 56 times 86 is also 4816, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4816.", "meta": {"a": 86, "b": 56, "result": 4816, "style": "long"}}
{"id": "arith-345", "prompt": "What is the product of 55 and 36?", "completion": "This is a multiplication problem over the numbers 55 and 36, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1650, and by the remaining 6 gives 330, which sum to 1980. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 36 times 55 is also 1980, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1980.", "meta": {"a": 55, "b": 36, "result": 1980, "style": "long"}}
{"id": "arith-346", "prompt": "Add 46 and 57.", "completion": "This is an addition problem over the numbers 46 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 96, and the remaining 7 gives 103. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 57 from 103 returns 46, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 103.", "meta": {"a": 46, "b": 57, "result": 103, "style": "long"}}
{"id": "arith-347", "prompt": "Subtract 88 from 88.", "completion": "This is a subtraction problem over the numbers 88 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 8, and removing the last 8 leaves 0. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 88 back to 0 returns 88, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 0.", "meta": {"a": 88, "b": 88, "result": 0, "style": "long"}}
{"id": "arith-348", "prompt": "Subtract 30 from 7.", "completion": "This is a subtraction problem over the numbers 7 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves -23, and removing the last 0 leaves -23. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 30 back to -23 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -23.", "meta": {"a": 7, "b": 30, "result": -23, "style": "long"}}
{"id": "arith-349", "prompt": "What is 2 plus 28?", "completion": "This is an addition problem over the numbers 2 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 22, and the remaining 8 gives 30. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 28 from 30 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 30.", "meta": {"a": 2, "b": 28, "result": 30, "style": "long"}}
{"id": "arith-350", "prompt": "What is 19 minus 99?", "completion": "This is a subtraction problem over the numbers 19 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -71, and removing the last 9 leaves -80. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 99 back to -80 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -80.", "meta": {"a": 19, "b": 99, "result": -80, "style": "long"}}
{"id": "arith-351", "prompt": "Subtract 17 from 43.", "completion": "This is a subtraction problem over the numbers 43 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 33, and removing the last 7 leaves 26. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 17 back to 26 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 26.", "meta": {"a": 43, "b": 17, "result": 26, "style": "long"}}
{"id": "arith-352", "prompt": "What is the product of 97 and 57?", "completion": "This is a multiplication problem over the numbers 97 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4850, and by the remaining 7 gives 679, which sum to 5529. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 57 times 97 is also 5529, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5529.", "meta": {"a": 97, "b": 57, "result": 5529, "style": "long"}}
{"id": "arith-353", "prompt": "What do you get when you add 50 to 70?", "completion": "This is an addition problem over the numbers 50 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 120, and the remaining 0 gives 120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 70 from 120 returns 50, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 120.", "meta": {"a": 50, "b": 70, "result": 120, "style": "long"}}
{"id": "arith-354", "prompt": "What is 11 times 52?", "completion": "This is a multiplication problem over the numbers 11 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 550, and by the remaining 2 gives 22, which sum to 572. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 52 times 11 is also 572, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 572.", "meta": {"a": 11, "b": 52, "result": 572, "style": "long"}}
{"id": "arith-355", "prompt": "Multiply 4 by 60.", "completion": "This is a multiplication problem over the numbers 4 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 240, and by the remaining 0 gives 0, which sum to 240. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 4 is also 240, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 240.", "meta": {"a": 4, "b": 60, "result": 240, "style": "long"}}
{"id": "arith-356", "prompt": "What is 75 times 56?", "completion": "This is a multiplication problem over the numbers 75 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3750, and by the remaining 6 gives 450, which sum to 4200. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 56 times 75 is also 4200, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4200.", "meta": {"a": 75, "b": 56, "result": 4200, "style": "long"}}
{"id": "arith-357", "prompt": "Multiply 39 by 16.", "completion": "This is a multiplication problem over the numbers 39 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 390, and by the remaining 6 gives 234, which sum to 624. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 16 times 39 is also 624, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 624.", "meta": {"a": 39, "b": 16, "result": 624, "style": "long"}}
{"id": "arith-358", "prompt": "What is 43 plus 23?", "completion": "This is an addition problem over the numbers 43 and 23, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 63, and the remaining 3 gives 66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 23 from 66 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 66.", "meta": {"a": 43, "b": 23, "result": 66, "style": "long"}}
{"id": "arith-359", "prompt": "What is 13 times 57?", "completion": "This is a multiplication problem over the numbers 13 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 650, and by the remaining 7 gives 91, which sum to 741. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 57 times 13 is also 741, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 741.", "meta": {"a": 13, "b": 57, "result": 741, "style": "long"}}
{"id": "arith-360", "prompt": "What is 57 minus 77?", "completion": "This is a subtraction problem over the numbers 57 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -13, and removing the last 7 leaves -20. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 77 back to -20 returns 57, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -20.", "meta": {"a": 57, "b": 77, "result": -20, "style": "long"}}
{"id": "arith-361", "prompt": "Add 52 and 41.", "completion": "This is an addition problem over the numbers 52 and 41, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 92, and the remaining 1 gives 93. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 41 from 93 returns 52, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 93.", "meta": {"a": 52, "b": 41, "result": 93, "style": "long"}}
{"id": "arith-362", "prompt": "What is 44 minus 23?", "completion": "This is a subtraction problem over the numbers 44 and 23, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 24, and removing the last 3 leaves 21. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 23 back to 21 returns 44, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 21.", "meta": {"a": 44, "b": 23, "result": 21, "style": "long"}}
{"id": "arith-363", "prompt": "Add 69 and 67.", "completion": "This is an addition problem over the numbers 69 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 129, and the remaining 7 gives 136. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 67 from 136 returns 69, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 136.", "meta": {"a": 69, "b": 67, "result": 136, "style": "long"}}
{"id": "arith-364", "prompt": "What is 46 times 95?", "completion": "This is a multiplication problem over the numbers 46 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 4140, and by the remaining 5 gives 230, which sum to 4370. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 95 times 46 is also 4370, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4370.", "meta": {"a": 46, "b": 95, "result": 4370, "style": "long"}}
{"id": "arith-365", "prompt": "What is 15 minus 20?", "completion": "This is a subtraction problem over the numbers 15 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves -5, and removing the last 0 leaves -5. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 20 back to -5 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -5.", "meta": {"a": 15, "b": 20, "result": -5, "style": "long"}}
{"id": "arith-366", "prompt": "What is 24 minus 79?", "completion": "This is a subtraction problem over the numbers 24 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -46, and removing the last 9 leaves -55. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 79 back to -55 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -55.", "meta": {"a": 24, "b": 79, "result": -55, "style": "long"}}
{"id": "arith-367", "prompt": "Add 24 and 82.", "completion": "This is an addition problem over the numbers 24 and 82, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 104, and the remaining 2 gives 106. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 82 from 106 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 106.", "meta": {"a": 24, "b": 82, "result": 106, "style": "long"}}
{"id": "arith-368", "prompt": "What is the product of 98 and 74?", "completion": "This is a multiplication problem over the numbers 98 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 6860, and by the remaining 4 gives 392, which sum to 7252. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 74 times 98 is also 7252, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7252.", "meta": {"a": 98, "b": 74, "result": 7252, "style": "long"}}
{"id": "arith-369", "prompt": "What is 82 times 42?", "completion": "This is a multiplication problem over the numbers 82 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3280, and by the remaining 2 gives 164, which sum to 3444. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 82 is also 3444, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3444.", "meta": {"a": 82, "b": 42, "result": 3444, "style": "long"}}
{"id": "arith-370", "prompt": "What is the product of 10 and 62?", "completion": "This is a multiplication problem over the numbers 10 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 600, and by the remaining 2 gives 20, which sum to 620. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 10 is also 620, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 620.", "meta": {"a": 10, "b": 62, "result": 620, "style": "long"}}
{"id": "arith-371", "prompt": "Subtract 77 from 37.", "completion": "This is a subtraction problem over the numbers 37 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -33, and removing the last 7 leaves -40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 77 back to -40 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -40.", "meta": {"a": 37, "b": 77, "result": -40, "style": "long"}}
{"id": "arith-372", "prompt": "What is 66 times 11?", "completion": "This is a multiplication problem over the numbers 66 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 660, and by the remaining 1 gives 66, which sum to 726. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 11 times 66 is also 726, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 726.", "meta": {"a": 66, "b": 11, "result": 726, "style": "long"}}
{"id": "arith-373", "prompt": "What is the product of 59 and 6?", "completion": "This is a multiplication problem over the numbers 59 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 6 gives 354, which sum to 354. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 6 times 59 is also 354, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 354.", "meta": {"a": 59, "b": 6, "result": 354, "style": "long"}}
{"id": "arith-374", "prompt": "What is 38 times 11?", "completion": "This is a multiplication problem over the numbers 38 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 380, and by the remaining 1 gives 38, which sum to 418. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 11 times 38 is also 418, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 418.", "meta": {"a": 38, "b": 11, "result": 418, "style": "long"}}
{"id": "arith-375", "prompt": "Multiply 61 by 76.", "completion": "This is a multiplication problem over the numbers 61 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 4270, and by the remaining 6 gives 366, which sum to 4636. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 76 times 61 is also 4636, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4636.", "meta": {"a": 61, "b": 76, "result": 4636, "style": "long"}}
{"id": "arith-376", "prompt": "What is the product of 75 and 85?", "completion": "This is a multiplication problem over the numbers 75 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 6000, and by the remaining 5 gives 375, which sum to 6375. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 75 is also 6375, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6375.", "meta": {"a": 75, "b": 85, "result": 6375, "style": "long"}}
{"id": "arith-377", "prompt": "What is 79 times 62?", "completion": "This is a multiplication problem over the numbers 79 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4740, and by the remaining 2 gives 158, which sum to 4898. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 79 is also 4898, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4898.", "meta": {"a": 79, "b": 62, "result": 4898, "style": "long"}}
{"id": "arith-378", "prompt": "What is 59 plus 15?", "completion": "This is an addition problem over the numbers 59 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 69, and the remaining 5 gives 74. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 15 from 74 returns 59, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 74.", "meta": {"a": 59, "b": 15, "result": 74, "style": "long"}}
{"id": "arith-379", "prompt": "Add 66 and 84.", "completion": "This is an addition problem over the numbers 66 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 146, and the remaining 4 gives 150. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 84 from 150 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 150.", "meta": {"a": 66, "b": 84, "result": 150, "style": "long"}}
{"id": "arith-380", "prompt": "What is 33 plus 92?", "completion": "This is an addition problem over the numbers 33 and 92, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 123, and the remaining 2 gives 125. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 92 from 125 returns 33, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 125.", "meta": {"a": 33, "b": 92, "result": 125, "style": "long"}}
{"id": "arith-381", "prompt": "What is the product of 69 and 68?", "completion": "This is a multiplication problem over the numbers 69 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4140, and by the remaining 8 gives 552, which sum to 4692. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 68 times 69 is also 4692, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4692.", "meta": {"a": 69, "b": 68, "result": 4692, "style": "long"}}
{"id": "arith-382", "prompt": "What is 49 times 38?", "completion": "This is a multiplication problem over the numbers 49 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1470, and by the remaining 8 gives 392, which sum to 1862. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 38 times 49 is also 1862, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1862.", "meta": {"a": 49, "b": 38, "result": 1862, "style": "long"}}
{"id": "arith-383", "prompt": "Multiply 45 by 88.", "completion": "This is a multiplication problem over the numbers 45 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 3600, and by the remaining 8 gives 360, which sum to 3960. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 88 times 45 is also 3960, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3960.", "meta": {"a": 45, "b": 88, "result": 3960, "style": "long"}}
{"id": "arith-384", "prompt": "What is 10 times 44?", "completion": "This is a multiplication problem over the numbers 10 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 400, and by the remaining 4 gives 40, which sum to 440. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 44 times 10 is also 440, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 440.", "meta": {"a": 10, "b": 44, "result": 440, "style": "long"}}
{"id": "arith-385", "prompt": "Multiply 38 by 34.", "completion": "This is a multiplication problem over the numbers 38 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1140, and by the remaining 4 gives 152, which sum to 1292. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 34 times 38 is also 1292, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1292.", "meta": {"a": 38, "b": 34, "result": 1292, "style": "long"}}
{"id": "arith-386", "prompt": "What is 12 times 76?", "completion": "This is a multiplication problem over the numbers 12 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 840, and by the remaining 6 gives 72, which sum to 912. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 76 times 12 is also 912, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 912.", "meta": {"a": 12, "b": 76, "result": 912, "style": "long"}}
{"id": "arith-387", "prompt": "What is 41 times 85?", "completion": "This is a multiplication problem over the numbers 41 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 3280, and by the remaining 5 gives 205, which sum to 3485. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 41 is also 3485, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3485.", "meta": {"a": 41, "b": 85, "result": 3485, "style": "long"}}
{"id": "arith-388", "prompt": "What do you get when you add 78 to 92?", "completion": "This is an addition problem over the numbers 78 and 92, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 168, and the remaining 2 gives 170. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 92 from 170 returns 78, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 170.", "meta": {"a": 78, "b": 92, "result": 170, "style": "long"}}
{"id": "arith-389", "prompt": "Subtract 50 from 73.", "completion": "This is a subtraction problem over the numbers 73 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 23, and removing the last 0 leaves 23. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 50 back to 23 returns 73, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 23.", "meta": {"a": 73, "b": 50, "result": 23, "style": "long"}}
{"id": "arith-390", "prompt": "What do you get when you add 87 to 91?", "completion": "This is an addition problem over the numbers 87 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 177, and the remaining 1 gives 178. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 91 from 178 returns 87, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 178.", "meta": {"a": 87, "b": 91, "result": 178, "style": "long"}}
{"id": "arith-391", "prompt": "Multiply 67 by 48.", "completion": "This is a multiplication problem over the numbers 67 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 2680, and by the remaining 8 gives 536, which sum to 3216. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 48 times 67 is also 3216, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3216.", "meta": {"a": 67, "b": 48, "result": 3216, "style": "long"}}
{"id": "arith-392", "prompt": "What is 41 times 25?", "completion": "This is a multiplication problem over the numbers 41 and 25, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 820, and by the remaining 5 gives 205, which sum to 1025. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 25 times 41 is also 1025, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1025.", "meta": {"a": 41, "b": 25, "result": 1025, "style": "long"}}
{"id": "arith-393", "prompt": "What is 64 times 26?", "completion": "This is a multiplication problem over the numbers 64 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1280, and by the remaining 6 gives 384, which sum to 1664. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 26 times 64 is also 1664, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1664.", "meta": {"a": 64, "b": 26, "result": 1664, "style": "long"}}
{"id": "arith-394", "prompt": "What do you get when you add 21 to 11?", "completion": "This is an addition problem over the numbers 21 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 31, and the remaining 1 gives 32. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 11 from 32 returns 21, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 32.", "meta": {"a": 21, "b": 11, "result": 32, "style": "long"}}
{"id": "arith-395", "prompt": "Add 66 and 71.", "completion": "This is an addition problem over the numbers 66 and 71, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 136, and the remaining 1 gives 137. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 71 from 137 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 137.", "meta": {"a": 66, "b": 71, "result": 137, "style": "long"}}
{"id": "arith-396", "prompt": "What is 81 times 18?", "completion": "This is a multiplication problem over the numbers 81 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 810, and by the remaining 8 gives 648, which sum to 1458. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 18 times 81 is also 1458, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1458.", "meta": {"a": 81, "b": 18, "result": 1458, "style": "long"}}
{"id": "arith-397", "prompt": "What do you get when you add 22 to 25?", "completion": "This is an addition problem over the numbers 22 and 25, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 42, and the remaining 5 gives 47. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 25 from 47 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 47.", "meta": {"a": 22, "b": 25, "result": 47, "style": "long"}}
{"id": "arith-398", "prompt": "What is the product of 7 and 54?", "completion": "This is a multiplication problem over the numbers 7 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 350, and by the remaining 4 gives 28, which sum to 378. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 54 times 7 is also 378, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 378.", "meta": {"a": 7, "b": 54, "result": 378, "style": "long"}}
{"id": "arith-399", "prompt": "What is 58 minus 80?", "completion": "This is a subtraction problem over the numbers 58 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -22, and removing the last 0 leaves -22. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 80 back to -22 returns 58, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -22.", "meta": {"a": 58, "b": 80, "result": -22, "style": "long"}}
{"id": "arith-400", "prompt": "What is the product of 31 and 70?", "completion": "This is a multiplication problem over the numbers 31 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 2170, and by the remaining 0 gives 0, which sum to 2170. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 70 times 31 is also 2170, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2170.", "meta": {"a": 31, "b": 70, "result": 2170, "style": "long"}}
{"id": "arith-401", "prompt": "Subtract 26 from 62.", "completion": "This is a subtraction problem over the numbers 62 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 42, and removing the last 6 leaves 36. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 26 back to 36 returns 62, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 36.", "meta": {"a": 62, "b": 26, "result": 36, "style": "long"}}
{"id": "arith-402", "prompt": "What is the product of 61 and 38?", "completion": "This is a multiplication problem over the numbers 61 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1830, and by the remaining 8 gives 488, which sum to 2318. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 38 times 61 is also 2318, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2318.", "meta": {"a": 61, "b": 38, "result": 2318, "style": "long"}}
{"id": "arith-403", "prompt": "Multiply 22 by 27.", "completion": "This is a multiplication problem over the numbers 22 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 440, and by the remaining 7 gives 154, which sum to 594. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 27 times 22 is also 594, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 594.", "meta": {"a": 22, "b": 27, "result": 594, "style": "long"}}
{"id": "arith-404", "prompt": "Subtract 84 from 8.", "completion": "This is a subtraction problem over the numbers 8 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -72, and removing the last 4 leaves -76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 84 back to -76 returns 8, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -76.", "meta": {"a": 8, "b": 84, "result": -76, "style": "long"}}
{"id": "arith-405", "prompt": "What is 72 times 15?", "completion": "This is a multiplication problem over the numbers 72 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 720, and by the remaining 5 gives 360, which sum to 1080. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 15 times 72 is also 1080, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1080.", "meta": {"a": 72, "b": 15, "result": 1080, "style": "long"}}
{"id": "arith-406", "prompt": "Subtract 99 from 12.", "completion": "This is a subtraction problem over the numbers 12 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -78, and removing the last 9 leaves -87. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 99 back to -87 returns 12, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -87.", "meta": {"a": 12, "b": 99, "result": -87, "style": "long"}}
{"id": "arith-407", "prompt": "Subtract 67 from 59.", "completion": "This is a subtraction problem over the numbers 59 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -1, and removing the last 7 leaves -8. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 67 back to -8 returns 59, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -8.", "meta": {"a": 59, "b": 67, "result": -8, "style": "long"}}
{"id": "arith-408", "prompt": "What is the product of 46 and 5?", "completion": "This is a multiplication problem over the numbers 46 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 5 gives 230, which sum to 230. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 5 times 46 is also 230, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 230.", "meta": {"a": 46, "b": 5, "result": 230, "style": "long"}}
{"id": "arith-409", "prompt": "What is 52 plus 66?", "completion": "This is an addition problem over the numbers 52 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 112, and the remaining 6 gives 118. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 66 from 118 returns 52, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 118.", "meta": {"a": 52, "b": 66, "result": 118, "style": "long"}}
{"id": "arith-410", "prompt": "What is 51 minus 12?", "completion": "This is a subtraction problem over the numbers 51 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 41, and removing the last 2 leaves 39. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 12 back to 39 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 39.", "meta": {"a": 51, "b": 12, "result": 39, "style": "long"}}
{"id": "arith-411", "prompt": "What is 5 minus 42?", "completion": "This is a subtraction problem over the numbers 5 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -35, and removing the last 2 leaves -37. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 42 back to -37 returns 5, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -37.", "meta": {"a": 5, "b": 42, "result": -37, "style": "long"}}
{"id": "arith-412", "prompt": "What is 20 times 19?", "completion": "This is a multiplication problem over the numbers 20 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 200, and by the remaining 9 gives 180, which sum to 380. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 19 times 20 is also 380, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 380.", "meta": {"a": 20, "b": 19, "result": 380, "style": "long"}}
{"id": "arith-413", "prompt": "Subtract 91 from 62.", "completion": "This is a subtraction problem over the numbers 62 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -28, and removing the last 1 leaves -29. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 91 back to -29 returns 62, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -29.", "meta": {"a": 62, "b": 91, "result": -29, "style": "long"}}
{"id": "arith-414", "prompt": "What is the product of 59 and 80?", "completion": "This is a multiplication problem over the numbers 59 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 4720, and by the remaining 0 gives 0, which sum to 4720. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 80 times 59 is also 4720, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4720.", "meta": {"a": 59, "b": 80, "result": 4720, "style": "long"}}
{"id": "arith-415", "prompt": "Add 4 and 34.", "completion": "This is an addition problem over the numbers 4 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 34, and the remaining 4 gives 38. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 34 from 38 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 38.", "meta": {"a": 4, "b": 34, "result": 38, "style": "long"}}
{"id": "arith-416", "prompt": "What do you get when you add 72 to 95?", "completion": "This is an addition problem over the numbers 72 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 162, and the remaining 5 gives 167. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 95 from 167 returns 72, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 167.", "meta": {"a": 72, "b": 95, "result": 167, "style": "long"}}
{"id": "arith-417", "prompt": "Add 38 and 32.", "completion": "This is an addition problem over the numbers 38 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 68, and the remaining 2 gives 70. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 32 from 70 returns 38, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 70.", "meta": {"a": 38, "b": 32, "result": 70, "style": "long"}}
{"id": "arith-418", "prompt": "Add 8 and 32.", "completion": "This is an addition problem over the numbers 8 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 38, and the remaining 2 gives 40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 32 from 40 returns 8, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 40.", "meta": {"a": 8, "b": 32, "result": 40, "style": "long"}}
{"id": "arith-419", "prompt": "What is the product of 10 and 16?", "completion": "This is a multiplication problem over the numbers 10 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 100, and by the remaining 6 gives 60, which sum to 160. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 16 times 10 is also 160, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 160.", "meta": {"a": 10, "b": 16, "result": 160, "style": "long"}}
{"id": "arith-420", "prompt": "What is 82 plus 67?", "completion": "This is an addition problem over the numbers 82 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 142, and the remaining 7 gives 149. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 67 from 149 returns 82, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 149.", "meta": {"a": 82, "b": 67, "result": 149, "style": "long"}}
{"id": "arith-421", "prompt": "What do you get when you add 39 to 56?", "completion": "This is an addition problem over the numbers 39 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 89, and the remaining 6 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 56 from 95 returns 39, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 39, "b": 56, "result": 95, "style": "long"}}
{"id": "arith-422", "prompt": "What is 32 times 75?", "completion": "This is a multiplication problem over the numbers 32 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 2240, and by the remaining 5 gives 160, which sum to 2400. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 75 times 32 is also 2400, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2400.", "meta": {"a": 32, "b": 75, "result": 2400, "style": "long"}}
{"id": "arith-423", "prompt": "What do you get when you add 87 to 87?", "completion": "This is an addition problem over the numbers 87 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 167, and the remaining 7 gives 174. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 87 from 174 returns 87, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 174.", "meta": {"a": 87, "b": 87, "result": 174, "style": "long"}}
{"id": "arith-424", "prompt": "What is 10 times 69?", "completion": "This is a multiplication problem over the numbers 10 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 600, and by the remaining 9 gives 90, which sum to 690. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 69 times 10 is also 690, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 690.", "meta": {"a": 10, "b": 69, "result": 690, "style": "long"}}
{"id": "arith-425", "prompt": "Multiply 62 by 7.", "completion": "This is a multiplication problem over the numbers 62 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 7 gives 434, which sum to 434. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 7 times 62 is also 434, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 434.", "meta": {"a": 62, "b": 7, "result": 434, "style": "long"}}
{"id": "arith-426", "prompt": "What is 34 times 97?", "completion": "This is a multiplication problem over the numbers 34 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 3060, and by the remaining 7 gives 238, which sum to 3298. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 34 is also 3298, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3298.", "meta": {"a": 34, "b": 97, "result": 3298, "style": "long"}}
{"id": "arith-427", "prompt": "What is 10 times 46?", "completion": "This is a multiplication problem over the numbers 10 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 400, and by the remaining 6 gives 60, which sum to 460. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 46 times 10 is also 460, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 460.", "meta": {"a": 10, "b": 46, "result": 460, "style": "long"}}
{"id": "arith-428", "prompt": "Add 76 and 96.", "completion": "This is an addition problem over the numbers 76 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 166, and the remaining 6 gives 172. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 172 returns 76, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 172.", "meta": {"a": 76, "b": 96, "result": 172, "style": "long"}}
{"id": "arith-429", "prompt": "What do you get when you add 7 to 47?", "completion": "This is an addition problem over the numbers 7 and 47, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 47, and the remaining 7 gives 54. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 47 from 54 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 54.", "meta": {"a": 7, "b": 47, "result": 54, "style": "long"}}
{"id": "arith-430", "prompt": "What do you get when you add 89 to 61?", "completion": "This is an addition problem over the numbers 89 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 149, and the remaining 1 gives 150. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 61 from 150 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 150.", "meta": {"a": 89, "b": 61, "result": 150, "style": "long"}}
{"id": "arith-431", "prompt": "What do you get when you add 19 to 10?", "completion": "This is an addition problem over the numbers 19 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 29, and the remaining 0 gives 29. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 10 from 29 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 29.", "meta": {"a": 19, "b": 10, "result": 29, "style": "long"}}
{"id": "arith-432", "prompt": "What is 39 plus 27?", "completion": "This is an addition problem over the numbers 39 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 59, and the remaining 7 gives 66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 27 from 66 returns 39, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 66.", "meta": {"a": 39, "b": 27, "result": 66, "style": "long"}}
{"id": "arith-433", "prompt": "What is 7 minus 42?", "completion": "This is a subtraction problem over the numbers 7 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -33, and removing the last 2 leaves -35. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 42 back to -35 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -35.", "meta": {"a": 7, "b": 42, "result": -35, "style": "long"}}
{"id": "arith-434", "prompt": "Multiply 71 by 62.", "completion": "This is a multiplication problem over the numbers 71 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4260, and by the remaining 2 gives 142, which sum to 4402. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 71 is also 4402, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4402.", "meta": {"a": 71, "b": 62, "result": 4402, "style": "long"}}
{"id": "arith-435", "prompt": "What is 98 plus 84?", "completion": "This is an addition problem over the numbers 98 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 178, and the remaining 4 gives 182. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 84 from 182 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 182.", "meta": {"a": 98, "b": 84, "result": 182, "style": "long"}}
{"id": "arith-436", "prompt": "Subtract 8 from 47.", "completion": "This is a subtraction problem over the numbers 47 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 47, and removing the last 8 leaves 39. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 8 back to 39 returns 47, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 39.", "meta": {"a": 47, "b": 8, "result": 39, "style": "long"}}
{"id": "arith-437", "prompt": "Subtract 49 from 17.", "completion": "This is a subtraction problem over the numbers 17 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -23, and removing the last 9 leaves -32. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 49 back to -32 returns 17, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -32.", "meta": {"a": 17, "b": 49, "result": -32, "style": "long"}}
{"id": "arith-438", "prompt": "Multiply 97 by 58.", "completion": "This is a multiplication problem over the numbers 97 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4850, and by the remaining 8 gives 776, which sum to 5626. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 58 times 97 is also 5626, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5626.", "meta": {"a": 97, "b": 58, "result": 5626, "style": "long"}}
{"id": "arith-439", "prompt": "What is 25 times 65?", "completion": "This is a multiplication problem over the numbers 25 and 65, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1500, and by the remaining 5 gives 125, which sum to 1625. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 65 times 25 is also 1625, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1625.", "meta": {"a": 25, "b": 65, "result": 1625, "style": "long"}}
{"id": "arith-440", "prompt": "What is 68 times 36?", "completion": "This is a multiplication problem over the numbers 68 and 36, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2040, and by the remaining 6 gives 408, which sum to 2448. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 36 times 68 is also 2448, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2448.", "meta": {"a": 68, "b": 36, "result": 2448, "style": "long"}}
{"id": "arith-441", "prompt": "Multiply 12 by 57.", "completion": "This is a multiplication problem over the numbers 12 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 600, and by the remaining 7 gives 84, which sum to 684. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 57 times 12 is also 684, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 684.", "meta": {"a": 12, "b": 57, "result": 684, "style": "long"}}
{"id": "arith-442", "prompt": "Subtract 15 from 43.", "completion": "This is a subtraction problem over the numbers 43 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 33, and removing the last 5 leaves 28. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 15 back to 28 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 28.", "meta": {"a": 43, "b": 15, "result": 28, "style": "long"}}
{"id": "arith-443", "prompt": "What is 86 times 39?", "completion": "This is a multiplication problem over the numbers 86 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2580, and by the remaining 9 gives 774, which sum to 3354. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 39 times 86 is also 3354, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3354.", "meta": {"a": 86, "b": 39, "result": 3354, "style": "long"}}
{"id": "arith-444", "prompt": "What is the product of 79 and 93?", "completion": "This is a multiplication problem over the numbers 79 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7110, and by the remaining 3 gives 237, which sum to 7347. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 93 times 79 is also 7347, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7347.", "meta": {"a": 79, "b": 93, "result": 7347, "style": "long"}}
{"id": "arith-445", "prompt": "What do you get when you add 90 to 58?", "completion": "This is an addition problem over the numbers 90 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 140, and the remaining 8 gives 148. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 58 from 148 returns 90, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 148.", "meta": {"a": 90, "b": 58, "result": 148, "style": "long"}}
{"id": "arith-446", "prompt": "What is the product of 7 and 95?", "completion": "This is a multiplication problem over the numbers 7 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 630, and by the remaining 5 gives 35, which sum to 665. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 95 times 7 is also 665, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 665.", "meta": {"a": 7, "b": 95, "result": 665, "style": "long"}}
{"id": "arith-447", "prompt": "Multiply 37 by 83.", "completion": "This is a multiplication problem over the numbers 37 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 2960, and by the remaining 3 gives 111, which sum to 3071. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 83 times 37 is also 3071, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3071.", "meta": {"a": 37, "b": 83, "result": 3071, "style": "long"}}
{"id": "arith-448", "prompt": "Add 87 and 83.", "completion": "This is an addition problem over the numbers 87 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 167, and the remaining 3 gives 170. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 83 from 170 returns 87, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 170.", "meta": {"a": 87, "b": 83, "result": 170, "style": "long"}}
{"id": "arith-449", "prompt": "What is 67 times 97?", "completion": "This is a multiplication problem over the numbers 67 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 6030, and by the remaining 7 gives 469, which sum to 6499. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 67 is also 6499, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6499.", "meta": {"a": 67, "b": 97, "result": 6499, "style": "long"}}
{"id": "arith-450", "prompt": "What is 20 plus 79?", "completion": "This is an addition problem over the numbers 20 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 90, and the remaining 9 gives 99. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 79 from 99 returns 20, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 99.", "meta": {"a": 20, "b": 79, "result": 99, "style": "long"}}
{"id": "arith-451", "prompt": "What is 18 plus 10?", "completion": "This is an addition problem over the numbers 18 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 28, and the remaining 0 gives 28. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 10 from 28 returns 18, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 28.", "meta": {"a": 18, "b": 10, "result": 28, "style": "long"}}
{"id": "arith-452", "prompt": "What is 48 times 51?", "completion": "This is a multiplication problem over the numbers 48 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2400, and by the remaining 1 gives 48, which sum to 2448. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 51 times 48 is also 2448, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2448.", "meta": {"a": 48, "b": 51, "result": 2448, "style": "long"}}
{"id": "arith-453", "prompt": "What do you get when you add 88 to 59?", "completion": "This is an addition problem over the numbers 88 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 138, and the remaining 9 gives 147. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 59 from 147 returns 88, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 147.", "meta": {"a": 88, "b": 59, "result": 147, "style": "long"}}
{"id": "arith-454", "prompt": "What is 58 times 99?", "completion": "This is a multiplication problem over the numbers 58 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 5220, and by the remaining 9 gives 522, which sum to 5742. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 99 times 58 is also 5742, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5742.", "meta": {"a": 58, "b": 99, "result": 5742, "style": "long"}}
{"id": "arith-455", "prompt": "What do you get when you add 69 to 48?", "completion": "This is an addition problem over the numbers 69 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 109, and the remaining 8 gives 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 48 from 117 returns 69, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 69, "b": 48, "result": 117, "style": "long"}}
{"id": "arith-456", "prompt": "What is 85 times 37?", "completion": "This is a multiplication problem over the numbers 85 and 37, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2550, and by the remaining 7 gives 595, which sum to 3145. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 37 times 85 is also 3145, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3145.", "meta": {"a": 85, "b": 37, "result": 3145, "style": "long"}}
{"id": "arith-457", "prompt": "What do you get when you add 65 to 68?", "completion": "This is an addition problem over the numbers 65 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 125, and the remaining 8 gives 133. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 68 from 133 returns 65, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 133.", "meta": {"a": 65, "b": 68, "result": 133, "style": "long"}}
{"id": "arith-458", "prompt": "Add 35 and 35.", "completion": "This is an addition problem over the numbers 35 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 65, and the remaining 5 gives 70. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 35 from 70 returns 35, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 70.", "meta": {"a": 35, "b": 35, "result": 70, "style": "long"}}
{"id": "arith-459", "prompt": "What is 80 minus 38?", "completion": "This is a subtraction problem over the numbers 80 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 50, and removing the last 8 leaves 42. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 38 back to 42 returns 80, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 42.", "meta": {"a": 80, "b": 38, "result": 42, "style": "long"}}
{"id": "arith-460", "prompt": "What is 17 minus 19?", "completion": "This is a subtraction problem over the numbers 17 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 7, and removing the last 9 leaves -2. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 19 back to -2 returns 17, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -2.", "meta": {"a": 17, "b": 19, "result": -2, "style": "long"}}
{"id": "arith-461", "prompt": "What is the product of 24 and 93?", "completion": "This is a multiplication problem over the numbers 24 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 2160, and by the remaining 3 gives 72, which sum to 2232. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 93 times 24 is also 2232, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2232.", "meta": {"a": 24, "b": 93, "result": 2232, "style": "long"}}
{"id": "arith-462", "prompt": "Add 89 and 42.", "completion": "This is an addition problem over the numbers 89 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 129, and the remaining 2 gives 131. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 42 from 131 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 131.", "meta": {"a": 89, "b": 42, "result": 131, "style": "long"}}
{"id": "arith-463", "prompt": "Add 72 and 71.", "completion": "This is an addition problem over the numbers 72 and 71, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 142, and the remaining 1 gives 143. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 71 from 143 returns 72, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 143.", "meta": {"a": 72, "b": 71, "result": 143, "style": "long"}}
{"id": "arith-464", "prompt": "Subtract 93 from 22.", "completion": "This is a subtraction problem over the numbers 22 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -68, and removing the last 3 leaves -71. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 93 back to -71 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -71.", "meta": {"a": 22, "b": 93, "result": -71, "style": "long"}}
{"id": "arith-465", "prompt": "What is 67 times 30?", "completion": "This is a multiplication problem over the numbers 67 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2010, and by the remaining 0 gives 0, which sum to 2010. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 30 times 67 is also 2010, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2010.", "meta": {"a": 67, "b": 30, "result": 2010, "style": "long"}}
{"id": "arith-466", "prompt": "What is 19 minus 32?", "completion": "This is a subtraction problem over the numbers 19 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves -11, and removing the last 2 leaves -13. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 32 back to -13 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -13.", "meta": {"a": 19, "b": 32, "result": -13, "style": "long"}}
{"id": "arith-467", "prompt": "What is 48 plus 72?", "completion": "This is an addition problem over the numbers 48 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 118, and the remaining 2 gives 120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 72 from 120 returns 48, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 120.", "meta": {"a": 48, "b": 72, "result": 120, "style": "long"}}
{"id": "arith-468", "prompt": "What is the product of 72 and 18?", "completion": "This is a multiplication problem over the numbers 72 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 720, and by the remaining 8 gives 576, which sum to 1296. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 18 times 72 is also 1296, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1296.", "meta": {"a": 72, "b": 18, "result": 1296, "style": "long"}}
{"id": "arith-469", "prompt": "Add 41 and 52.", "completion": "This is an addition problem over the numbers 41 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 91, and the remaining 2 gives 93. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 52 from 93 returns 41, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 93.", "meta": {"a": 41, "b": 52, "result": 93, "style": "long"}}
{"id": "arith-470", "prompt": "Multiply 54 by 75.", "completion": "This is a multiplication problem over the numbers 54 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3780, and by the remaining 5 gives 270, which sum to 4050. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 75 times 54 is also 4050, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4050.", "meta": {"a": 54, "b": 75, "result": 4050, "style": "long"}}
{"id": "arith-471", "prompt": "What do you get when you add 42 to 84?", "completion": "This is an addition problem over the numbers 42 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 122, and the remaining 4 gives 126. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 84 from 126 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 126.", "meta": {"a": 42, "b": 84, "result": 126, "style": "long"}}
{"id": "arith-472", "prompt": "What is the product of 61 and 89?", "completion": "This is a multiplication problem over the numbers 61 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 4880, and by the remaining 9 gives 549, which sum to 5429. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 89 times 61 is also 5429, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5429.", "meta": {"a": 61, "b": 89, "result": 5429, "style": "long"}}
{"id": "arith-473", "prompt": "What do you get when you add 72 to 83?", "completion": "This is an addition problem over the numbers 72 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 152, and the remaining 3 gives 155. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 83 from 155 returns 72, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 155.", "meta": {"a": 72, "b": 83, "result": 155, "style": "long"}}
{"id": "arith-474", "prompt": "What do you get when you add 57 to 66?", "completion": "This is an addition problem over the numbers 57 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 117, and the remaining 6 gives 123. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 66 from 123 returns 57, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 123.", "meta": {"a": 57, "b": 66, "result": 123, "style": "long"}}
{"id": "arith-475", "prompt": "Add 68 and 21.", "completion": "This is an addition problem over the numbers 68 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 88, and the remaining 1 gives 89. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 21 from 89 returns 68, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 89.", "meta": {"a": 68, "b": 21, "result": 89, "style": "long"}}
{"id": "arith-476", "prompt": "What do you get when you add 22 to 43?", "completion": "This is an addition problem over the numbers 22 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 62, and the remaining 3 gives 65. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 43 from 65 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 65.", "meta": {"a": 22, "b": 43, "result": 65, "style": "long"}}
{"id": "arith-477", "prompt": "What is 68 times 38?", "completion": "This is a multiplication problem over the numbers 68 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2040, and by the remaining 8 gives 544, which sum to 2584. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 38 times 68 is also 2584, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2584.", "meta": {"a": 68, "b": 38, "result": 2584, "style": "long"}}
{"id": "arith-478", "prompt": "Subtract 83 from 27.", "completion": "This is a subtraction problem over the numbers 27 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -53, and removing the last 3 leaves -56. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 83 back to -56 returns 27, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -56.", "meta": {"a": 27, "b": 83, "result": -56, "style": "long"}}
{"id": "arith-479", "prompt": "What do you get when you add 82 to 40?", "completion": "This is an addition problem over the numbers 82 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 122, and the remaining 0 gives 122. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 40 from 122 returns 82, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 122.", "meta": {"a": 82, "b": 40, "result": 122, "style": "long"}}
{"id": "arith-480", "prompt": "What do you get when you add 77 to 76?", "completion": "This is an addition problem over the numbers 77 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 147, and the remaining 6 gives 153. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 76 from 153 returns 77, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 153.", "meta": {"a": 77, "b": 76, "result": 153, "style": "long"}}
{"id": "arith-481", "prompt": "What do you get when you add 86 to 81?", "completion": "This is an addition problem over the numbers 86 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 166, and the remaining 1 gives 167. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 81 from 167 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 167.", "meta": {"a": 86, "b": 81, "result": 167, "style": "long"}}
{"id": "arith-482", "prompt": "What is 5 plus 12?", "completion": "This is an addition problem over the numbers 5 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 15, and the remaining 2 gives 17. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 12 from 17 returns 5, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 17.", "meta": {"a": 5, "b": 12, "result": 17, "style": "long"}}
{"id": "arith-483", "prompt": "Subtract 28 from 85.", "completion": "This is a subtraction problem over the numbers 85 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 65, and removing the last 8 leaves 57. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 28 back to 57 returns 85, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 57.", "meta": {"a": 85, "b": 28, "result": 57, "style": "long"}}
{"id": "arith-484", "prompt": "What is 65 plus 82?", "completion": "This is an addition problem over the numbers 65 and 82, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 145, and the remaining 2 gives 147. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 82 from 147 returns 65, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 147.", "meta": {"a": 65, "b": 82, "result": 147, "style": "long"}}
{"id": "arith-485", "prompt": "Subtract 33 from 63.", "completion": "This is a subtraction problem over the numbers 63 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 33, and removing the last 3 leaves 30. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 33 back to 30 returns 63, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 30.", "meta": {"a": 63, "b": 33, "result": 30, "style": "long"}}
{"id": "arith-486", "prompt": "Subtract 11 from 60.", "completion": "This is a subtraction problem over the numbers 60 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 50, and removing the last 1 leaves 49. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 11 back to 49 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 49.", "meta": {"a": 60, "b": 11, "result": 49, "style": "long"}}
{"id": "arith-487", "prompt": "What do you get when you add 58 to 55?", "completion": "This is an addition problem over the numbers 58 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 108, and the remaining 5 gives 113. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 55 from 113 returns 58, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 113.", "meta": {"a": 58, "b": 55, "result": 113, "style": "long"}}
{"id": "arith-488", "prompt": "What is the product of 28 and 45?", "completion": "This is a multiplication problem over the numbers 28 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1120, and by the remaining 5 gives 140, which sum to 1260. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 45 times 28 is also 1260, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1260.", "meta": {"a": 28, "b": 45, "result": 1260, "style": "long"}}
{"id": "arith-489", "prompt": "What is 93 times 42?", "completion": "This is a multiplication problem over the numbers 93 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3720, and by the remaining 2 gives 186, which sum to 3906. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 93 is also 3906, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3906.", "meta": {"a": 93, "b": 42, "result": 3906, "style": "long"}}
{"id": "arith-490", "prompt": "Multiply 18 by 99.", "completion": "This is a multiplication problem over the numbers 18 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 1620, and by the remaining 9 gives 162, which sum to 1782. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 99 times 18 is also 1782, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1782.", "meta": {"a": 18, "b": 99, "result": 1782, "style": "long"}}
{"id": "arith-491", "prompt": "Add 42 and 32.", "completion": "This is an addition problem over the numbers 42 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 72, and the remaining 2 gives 74. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 32 from 74 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 74.", "meta": {"a": 42, "b": 32, "result": 74, "style": "long"}}
{"id": "arith-492", "prompt": "Add 36 and 59.", "completion": "This is an addition problem over the numbers 36 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 86, and the remaining 9 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 59 from 95 returns 36, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 36, "b": 59, "result": 95, "style": "long"}}
{"id": "arith-493", "prompt": "What do you get when you add 14 to 8?", "completion": "This is an addition problem over the numbers 14 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 14, and the remaining 8 gives 22. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 8 from 22 returns 14, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 22.", "meta": {"a": 14, "b": 8, "result": 22, "style": "long"}}
{"id": "arith-494", "prompt": "Multiply 80 by 55.", "completion": "This is a multiplication problem over the numbers 80 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4000, and by the remaining 5 gives 400, which sum to 4400. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 55 times 80 is also 4400, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4400.", "meta": {"a": 80, "b": 55, "result": 4400, "style": "long"}}
{"id": "arith-495", "prompt": "What do you get when you add 43 to 75?", "completion": "This is an addition problem over the numbers 43 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 113, and the remaining 5 gives 118. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 75 from 118 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 118.", "meta": {"a": 43, "b": 75, "result": 118, "style": "long"}}
{"id": "arith-496", "prompt": "What is 99 minus 22?", "completion": "This is a subtraction problem over the numbers 99 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 79, and removing the last 2 leaves 77. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 22 back to 77 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 77.", "meta": {"a": 99, "b": 22, "result": 77, "style": "long"}}
{"id": "arith-497", "prompt": "What is the product of 65 and 41?", "completion": "This is a multiplication problem over the numbers 65 and 41, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 2600, and by the remaining 1 gives 65, which sum to 2665. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 41 times 65 is also 2665, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2665.", "meta": {"a": 65, "b": 41, "result": 2665, "style": "long"}}
{"id": "arith-498", "prompt": "What is 13 plus 52?", "completion": "This is an addition problem over the numbers 13 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 63, and the remaining 2 gives 65. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 52 from 65 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 65.", "meta": {"a": 13, "b": 52, "result": 65, "style": "long"}}
{"id": "arith-499", "prompt": "What is 29 minus 76?", "completion": "This is a subtraction problem over the numbers 29 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -41, and removing the last 6 leaves -47. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 76 back to -47 returns 29, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -47.", "meta": {"a": 29, "b": 76, "result": -47, "style": "long"}}
{"id": "arith-500", "prompt": "What is 8 plus 38?", "completion": "This is an addition problem over the numbers 8 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 38, and the remaining 8 gives 46. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 38 from 46 returns 8, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 46.", "meta": {"a": 8, "b": 38, "result": 46, "style": "long"}}
{"id": "arith-501", "prompt": "What is the product of 38 and 70?", "completion": "This is a multiplication problem over the numbers 38 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 2660, and by the remaining 0 gives 0, which sum to 2660. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 70 times 38 is also 2660, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2660.", "meta": {"a": 38, "b": 70, "result": 2660, "style": "long"}}
{"id": "arith-502", "prompt": "Add 57 and 19.", "completion": "This is an addition problem over the numbers 57 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 67, and the remaining 9 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 19 from 76 returns 57, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 57, "b": 19, "result": 76, "style": "long"}}
{"id": "arith-503", "prompt": "What is 99 times 53?", "completion": "This is a multiplication problem over the numbers 99 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4950, and by the remaining 3 gives 297, which sum to 5247. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 53 times 99 is also 5247, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5247.", "meta": {"a": 99, "b": 53, "result": 5247, "style": "long"}}
{"id": "arith-504", "prompt": "What is 53 plus 8?", "completion": "This is an addition problem over the numbers 53 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 53, and the remaining 8 gives 61. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 8 from 61 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 61.", "meta": {"a": 53, "b": 8, "result": 61, "style": "long"}}
{"id": "arith-505", "prompt": "What is 72 times 38?", "completion": "This is a multiplication problem over the numbers 72 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2160, and by the remaining 8 gives 576, which sum to 2736. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 38 times 72 is also 2736, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2736.", "meta": {"a": 72, "b": 38, "result": 2736, "style": "long"}}
{"id": "arith-506", "prompt": "Multiply 66 by 59.", "completion": "This is a multiplication problem over the numbers 66 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3300, and by the remaining 9 gives 594, which sum to 3894. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 59 times 66 is also 3894, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3894.", "meta": {"a": 66, "b": 59, "result": 3894, "style": "long"}}
{"id": "arith-507", "prompt": "Add 18 and 14.", "completion": "This is an addition problem over the numbers 18 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 28, and the remaining 4 gives 32. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 14 from 32 returns 18, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 32.", "meta": {"a": 18, "b": 14, "result": 32, "style": "long"}}
{"id": "arith-508", "prompt": "What is 45 times 73?", "completion": "This is a multiplication problem over the numbers 45 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3150, and by the remaining 3 gives 135, which sum to 3285. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 73 times 45 is also 3285, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3285.", "meta": {"a": 45, "b": 73, "result": 3285, "style": "long"}}
{"id": "arith-509", "prompt": "What do you get when you add 27 to 79?", "completion": "This is an addition problem over the numbers 27 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 97, and the remaining 9 gives 106. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 79 from 106 returns 27, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 106.", "meta": {"a": 27, "b": 79, "result": 106, "style": "long"}}
{"id": "arith-510", "prompt": "What is 7 plus 6?", "completion": "This is an addition problem over the numbers 7 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 7, and the remaining 6 gives 13. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 6 from 13 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 13.", "meta": {"a": 7, "b": 6, "result": 13, "style": "long"}}
{"id": "arith-511", "prompt": "What is 62 times 68?", "completion": "This is a multiplication problem over the numbers 62 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3720, and by the remaining 8 gives 496, which sum to 4216. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 68 times 62 is also 4216, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4216.", "meta": {"a": 62, "b": 68, "result": 4216, "style": "long"}}
{"id": "arith-512", "prompt": "What do you get when you add 79 to 67?", "completion": "This is an addition problem over the numbers 79 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 139, and the remaining 7 gives 146. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 67 from 146 returns 79, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 146.", "meta": {"a": 79, "b": 67, "result": 146, "style": "long"}}
{"id": "arith-513", "prompt": "What is 80 times 42?", "completion": "This is a multiplication problem over the numbers 80 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3200, and by the remaining 2 gives 160, which sum to 3360. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 80 is also 3360, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3360.", "meta": {"a": 80, "b": 42, "result": 3360, "style": "long"}}
{"id": "arith-514", "prompt": "Multiply 80 by 96.", "completion": "This is a multiplication problem over the numbers 80 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7200, and by the remaining 6 gives 480, which sum to 7680. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 96 times 80 is also 7680, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7680.", "meta": {"a": 80, "b": 96, "result": 7680, "style": "long"}}
{"id": "arith-515", "prompt": "What is 66 times 67?", "completion": "This is a multiplication problem over the numbers 66 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3960, and by the remaining 7 gives 462, which sum to 4422. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 67 times 66 is also 4422, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4422.", "meta": {"a": 66, "b": 67, "result": 4422, "style": "long"}}
{"id": "arith-516", "prompt": "Subtract 4 from 62.", "completion": "This is a subtraction problem over the numbers 62 and 4, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 62, and removing the last 4 leaves 58. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 4 back to 58 returns 62, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 58.", "meta": {"a": 62, "b": 4, "result": 58, "style": "long"}}
{"id": "arith-517", "prompt": "What is 88 times 16?", "completion": "This is a multiplication problem over the numbers 88 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 880, and by the remaining 6 gives 528, which sum to 1408. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 16 times 88 is also 1408, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1408.", "meta": {"a": 88, "b": 16, "result": 1408, "style": "long"}}
{"id": "arith-518", "prompt": "Subtract 90 from 94.", "completion": "This is a subtraction problem over the numbers 94 and 90, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves 4, and removing the last 0 leaves 4. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 90 back to 4 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4.", "meta": {"a": 94, "b": 90, "result": 4, "style": "long"}}
{"id": "arith-519", "prompt": "What is the product of 35 and 85?", "completion": "This is a multiplication problem over the numbers 35 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 2800, and by the remaining 5 gives 175, which sum to 2975. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 35 is also 2975, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2975.", "meta": {"a": 35, "b": 85, "result": 2975, "style": "long"}}
{"id": "arith-520", "prompt": "What is 76 plus 63?", "completion": "This is an addition problem over the numbers 76 and 63, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 136, and the remaining 3 gives 139. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 63 from 139 returns 76, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 139.", "meta": {"a": 76, "b": 63, "result": 139, "style": "long"}}
{"id": "arith-521", "prompt": "Multiply 20 by 89.", "completion": "This is a multiplication problem over the numbers 20 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1600, and by the remaining 9 gives 180, which sum to 1780. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 89 times 20 is also 1780, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1780.", "meta": {"a": 20, "b": 89, "result": 1780, "style": "long"}}
{"id": "arith-522", "prompt": "What is 75 plus 91?", "completion": "This is an addition problem over the numbers 75 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 165, and the remaining 1 gives 166. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 91 from 166 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 166.", "meta": {"a": 75, "b": 91, "result": 166, "style": "long"}}
{"id": "arith-523", "prompt": "What is 4 minus 58?", "completion": "This is a subtraction problem over the numbers 4 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -46, and removing the last 8 leaves -54. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 58 back to -54 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -54.", "meta": {"a": 4, "b": 58, "result": -54, "style": "long"}}
{"id": "arith-524", "prompt": "Multiply 21 by 54.", "completion": "This is a multiplication problem over the numbers 21 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 1050, and by the remaining 4 gives 84, which sum to 1134. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 54 times 21 is also 1134, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1134.", "meta": {"a": 21, "b": 54, "result": 1134, "style": "long"}}
{"id": "arith-525", "prompt": "Multiply 66 by 80.", "completion": "This is a multiplication problem over the numbers 66 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 5280, and by the remaining 0 gives 0, which sum to 5280. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 80 times 66 is also 5280, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5280.", "meta": {"a": 66, "b": 80, "result": 5280, "style": "long"}}
{"id": "arith-526", "prompt": "What is 92 plus 19?", "completion": "This is an addition problem over the numbers 92 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 102, and the remaining 9 gives 111. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 19 from 111 returns 92, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 111.", "meta": {"a": 92, "b": 19, "result": 111, "style": "long"}}
{"id": "arith-527", "prompt": "What is 86 times 63?", "completion": "This is a multiplication problem over the numbers 86 and 63, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 5160, and by the remaining 3 gives 258, which sum to 5418. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 63 times 86 is also 5418, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5418.", "meta": {"a": 86, "b": 63, "result": 5418, "style": "long"}}
{"id": "arith-528", "prompt": "What is 24 times 60?", "completion": "This is a multiplication problem over the numbers 24 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1440, and by the remaining 0 gives 0, which sum to 1440. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 24 is also 1440, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1440.", "meta": {"a": 24, "b": 60, "result": 1440, "style": "long"}}
{"id": "arith-529", "prompt": "What is 88 times 94?", "completion": "This is a multiplication problem over the numbers 88 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7920, and by the remaining 4 gives 352, which sum to 8272. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 94 times 88 is also 8272, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8272.", "meta": {"a": 88, "b": 94, "result": 8272, "style": "long"}}
{"id": "arith-530", "prompt": "What is the product of 26 and 33?", "completion": "This is a multiplication problem over the numbers 26 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 780, and by the remaining 3 gives 78, which sum to 858. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 33 times 26 is also 858, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 858.", "meta": {"a": 26, "b": 33, "result": 858, "style": "long"}}
{"id": "arith-531", "prompt": "Subtract 40 from 30.", "completion": "This is a subtraction problem over the numbers 30 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -10, and removing the last 0 leaves -10. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 40 back to -10 returns 30, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -10.", "meta": {"a": 30, "b": 40, "result": -10, "style": "long"}}
{"id": "arith-532", "prompt": "What is 90 minus 92?", "completion": "This is a subtraction problem over the numbers 90 and 92, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves 0, and removing the last 2 leaves -2. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 92 back to -2 returns 90, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -2.", "meta": {"a": 90, "b": 92, "result": -2, "style": "long"}}
{"id": "arith-533", "prompt": "What is 63 times 46?", "completion": "This is a multiplication problem over the numbers 63 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 2520, and by the remaining 6 gives 378, which sum to 2898. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 46 times 63 is also 2898, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2898.", "meta": {"a": 63, "b": 46, "result": 2898, "style": "long"}}
{"id": "arith-534", "prompt": "Subtract 75 from 17.", "completion": "This is a subtraction problem over the numbers 17 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -53, and removing the last 5 leaves -58. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 75 back to -58 returns 17, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -58.", "meta": {"a": 17, "b": 75, "result": -58, "style": "long"}}
{"id": "arith-535", "prompt": "Multiply 46 by 20.", "completion": "This is a multiplication problem over the numbers 46 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 920, and by the remaining 0 gives 0, which sum to 920. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 20 times 46 is also 920, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 920.", "meta": {"a": 46, "b": 20, "result": 920, "style": "long"}}
{"id": "arith-536", "prompt": "What is 38 plus 93?", "completion": "This is an addition problem over the numbers 38 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 128, and the remaining 3 gives 131. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 93 from 131 returns 38, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 131.", "meta": {"a": 38, "b": 93, "result": 131, "style": "long"}}
{"id": "arith-537", "prompt": "What is 58 times 85?", "completion": "This is a multiplication problem over the numbers 58 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 4640, and by the remaining 5 gives 290, which sum to 4930. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 58 is also 4930, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4930.", "meta": {"a": 58, "b": 85, "result": 4930, "style": "long"}}
{"id": "arith-538", "prompt": "What is the product of 29 and 27?", "completion": "This is a multiplication problem over the numbers 29 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 580, and by the remaining 7 gives 203, which sum to 783. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 27 times 29 is also 783, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 783.", "meta": {"a": 29, "b": 27, "result": 783, "style": "long"}}
{"id": "arith-539", "prompt": "Subtract 15 from 19.", "completion": "This is a subtraction problem over the numbers 19 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 9, and removing the last 5 leaves 4. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 15 back to 4 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4.", "meta": {"a": 19, "b": 15, "result": 4, "style": "long"}}
{"id": "arith-540", "prompt": "What is 8 minus 87?", "completion": "This is a subtraction problem over the numbers 8 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -72, and removing the last 7 leaves -79. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 87 back to -79 returns 8, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -79.", "meta": {"a": 8, "b": 87, "result": -79, "style": "long"}}
{"id": "arith-541", "prompt": "What is 8 minus 14?", "completion": "This is a subtraction problem over the numbers 8 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves -2, and removing the last 4 leaves -6. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 14 back to -6 returns 8, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -6.", "meta": {"a": 8, "b": 14, "result": -6, "style": "long"}}
{"id": "arith-542", "prompt": "What is 93 times 62?", "completion": "This is a multiplication problem over the numbers 93 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 5580, and by the remaining 2 gives 186, which sum to 5766. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 93 is also 5766, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5766.", "meta": {"a": 93, "b": 62, "result": 5766, "style": "long"}}
{"id": "arith-543", "prompt": "What do you get when you add 2 to 72?", "completion": "This is an addition problem over the numbers 2 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 72, and the remaining 2 gives 74. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 72 from 74 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 74.", "meta": {"a": 2, "b": 72, "result": 74, "style": "long"}}
{"id": "arith-544", "prompt": "Multiply 85 by 62.", "completion": "This is a multiplication problem over the numbers 85 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 5100, and by the remaining 2 gives 170, which sum to 5270. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 85 is also 5270, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5270.", "meta": {"a": 85, "b": 62, "result": 5270, "style": "long"}}
{"id": "arith-545", "prompt": "What is 98 minus 38?", "completion": "This is a subtraction problem over the numbers 98 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 68, and removing the last 8 leaves 60. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 38 back to 60 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 60.", "meta": {"a": 98, "b": 38, "result": 60, "style": "long"}}
{"id": "arith-546", "prompt": "Subtract 9 from 84.", "completion": "This is a subtraction problem over the numbers 84 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 84, and removing the last 9 leaves 75. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 9 back to 75 returns 84, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 75.", "meta": {"a": 84, "b": 9, "result": 75, "style": "long"}}
{"id": "arith-547", "prompt": "What is 70 minus 96?", "completion": "This is a subtraction problem over the numbers 70 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -20, and removing the last 6 leaves -26. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 96 back to -26 returns 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -26.", "meta": {"a": 70, "b": 96, "result": -26, "style": "long"}}
{"id": "arith-548", "prompt": "What do you get when you add 55 to 24?", "completion": "This is an addition problem over the numbers 55 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 75, and the remaining 4 gives 79. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 24 from 79 returns 55, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 79.", "meta": {"a": 55, "b": 24, "result": 79, "style": "long"}}
{"id": "arith-549", "prompt": "Multiply 65 by 25.", "completion": "This is a multiplication problem over the numbers 65 and 25, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1300, and by the remaining 5 gives 325, which sum to 1625. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 25 times 65 is also 1625, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1625.", "meta": {"a": 65, "b": 25, "result": 1625, "style": "long"}}
{"id": "arith-550", "prompt": "What is 3 plus 40?", "completion": "This is an addition problem over the numbers 3 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 43, and the remaining 0 gives 43. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 40 from 43 returns 3, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 43.", "meta": {"a": 3, "b": 40, "result": 43, "style": "long"}}
{"id": "arith-551", "prompt": "What is 38 times 60?", "completion": "This is a multiplication problem over the numbers 38 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 2280, and by the remaining 0 gives 0, which sum to 2280. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 38 is also 2280, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2280.", "meta": {"a": 38, "b": 60, "result": 2280, "style": "long"}}
{"id": "arith-552", "prompt": "What do you get when you add 66 to 61?", "completion": "This is an addition problem over the numbers 66 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 126, and the remaining 1 gives 127. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 61 from 127 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 127.", "meta": {"a": 66, "b": 61, "result": 127, "style": "long"}}
{"id": "arith-553", "prompt": "What is 16 minus 44?", "completion": "This is a subtraction problem over the numbers 16 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -24, and removing the last 4 leaves -28. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 44 back to -28 returns 16, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -28.", "meta": {"a": 16, "b": 44, "result": -28, "style": "long"}}
{"id": "arith-554", "prompt": "What is the product of 84 and 34?", "completion": "This is a multiplication problem over the numbers 84 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2520, and by the remaining 4 gives 336, which sum to 2856. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 34 times 84 is also 2856, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2856.", "meta": {"a": 84, "b": 34, "result": 2856, "style": "long"}}
{"id": "arith-555", "prompt": "What is 96 plus 45?", "completion": "This is an addition problem over the numbers 96 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 136, and the remaining 5 gives 141. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 45 from 141 returns 96, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 141.", "meta": {"a": 96, "b": 45, "result": 141, "style": "long"}}
{"id": "arith-556", "prompt": "What is 24 minus 80?", "completion": "This is a subtraction problem over the numbers 24 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -56, and removing the last 0 leaves -56. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 80 back to -56 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -56.", "meta": {"a": 24, "b": 80, "result": -56, "style": "long"}}
{"id": "arith-557", "prompt": "Multiply 67 by 43.", "completion": "This is a multiplication problem over the numbers 67 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 2680, and by the remaining 3 gives 201, which sum to 2881. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 43 times 67 is also 2881, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2881.", "meta": {"a": 67, "b": 43, "result": 2881, "style": "long"}}
{"id": "arith-558", "prompt": "Multiply 87 by 14.", "completion": "This is a multiplication problem over the numbers 87 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 870, and by the remaining 4 gives 348, which sum to 1218. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 14 times 87 is also 1218, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1218.", "meta": {"a": 87, "b": 14, "result": 1218, "style": "long"}}
{"id": "arith-559", "prompt": "What do you get when you add 63 to 43?", "completion": "This is an addition problem over the numbers 63 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 103, and the remaining 3 gives 106. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 43 from 106 returns 63, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 106.", "meta": {"a": 63, "b": 43, "result": 106, "style": "long"}}
{"id": "arith-560", "prompt": "What is 35 plus 51?", "completion": "This is an addition problem over the numbers 35 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 85, and the remaining 1 gives 86. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 51 from 86 returns 35, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 86.", "meta": {"a": 35, "b": 51, "result": 86, "style": "long"}}
{"id": "arith-561", "prompt": "What is the product of 98 and 36?", "completion": "This is a multiplication problem over the numbers 98 and 36, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2940, and by the remaining 6 gives 588, which sum to 3528. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 36 times 98 is also 3528, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3528.", "meta": {"a": 98, "b": 36, "result": 3528, "style": "long"}}
{"id": "arith-562", "prompt": "Subtract 94 from 76.", "completion": "This is a subtraction problem over the numbers 76 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -14, and removing the last 4 leaves -18. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 94 back to -18 returns 76, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -18.", "meta": {"a": 76, "b": 94, "result": -18, "style": "long"}}
{"id": "arith-563", "prompt": "Subtract 48 from 85.", "completion": "This is a subtraction problem over the numbers 85 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 45, and removing the last 8 leaves 37. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 48 back to 37 returns 85, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 37.", "meta": {"a": 85, "b": 48, "result": 37, "style": "long"}}
{"id": "arith-564", "prompt": "What is 87 plus 17?", "completion": "This is an addition problem over the numbers 87 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 97, and the remaining 7 gives 104. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 17 from 104 returns 87, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 104.", "meta": {"a": 87, "b": 17, "result": 104, "style": "long"}}
{"id": "arith-565", "prompt": "Subtract 53 from 22.", "completion": "This is a subtraction problem over the numbers 22 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -28, and removing the last 3 leaves -31. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 53 back to -31 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -31.", "meta": {"a": 22, "b": 53, "result": -31, "style": "long"}}
{"id": "arith-566", "prompt": "Add 83 and 39.", "completion": "This is an addition problem over the numbers 83 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 113, and the remaining 9 gives 122. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 39 from 122 returns 83, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 122.", "meta": {"a": 83, "b": 39, "result": 122, "style": "long"}}
{"id": "arith-567", "prompt": "What is the product of 21 and 60?", "completion": "This is a multiplication problem over the numbers 21 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1260, and by the remaining 0 gives 0, which sum to 1260. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 21 is also 1260, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1260.", "meta": {"a": 21, "b": 60, "result": 1260, "style": "long"}}
{"id": "arith-568", "prompt": "Multiply 91 by 72.", "completion": "This is a multiplication problem over the numbers 91 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 6370, and by the remaining 2 gives 182, which sum to 6552. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 72 times 91 is also 6552, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6552.", "meta": {"a": 91, "b": 72, "result": 6552, "style": "long"}}
{"id": "arith-569", "prompt": "What is 99 minus 33?", "completion": "This is a subtraction problem over the numbers 99 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 69, and removing the last 3 leaves 66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 33 back to 66 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 66.", "meta": {"a": 99, "b": 33, "result": 66, "style": "long"}}
{"id": "arith-570", "prompt": "What is the product of 69 and 92?", "completion": "This is a multiplication problem over the numbers 69 and 92, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 6210, and by the remaining 2 gives 138, which sum to 6348. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 92 times 69 is also 6348, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6348.", "meta": {"a": 69, "b": 92, "result": 6348, "style": "long"}}
{"id": "arith-571", "prompt": "Add 74 and 16.", "completion": "This is an addition problem over the numbers 74 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 84, and the remaining 6 gives 90. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 16 from 90 returns 74, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 90.", "meta": {"a": 74, "b": 16, "result": 90, "style": "long"}}
{"id": "arith-572", "prompt": "What is 75 minus 70?", "completion": "This is a subtraction problem over the numbers 75 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 5, and removing the last 0 leaves 5. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 70 back to 5 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5.", "meta": {"a": 75, "b": 70, "result": 5, "style": "long"}}
{"id": "arith-573", "prompt": "What do you get when you add 43 to 68?", "completion": "This is an addition problem over the numbers 43 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 103, and the remaining 8 gives 111. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 68 from 111 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 111.", "meta": {"a": 43, "b": 68, "result": 111, "style": "long"}}
{"id": "arith-574", "prompt": "Add 89 and 28.", "completion": "This is an addition problem over the numbers 89 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 109, and the remaining 8 gives 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 28 from 117 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 89, "b": 28, "result": 117, "style": "long"}}
{"id": "arith-575", "prompt": "Add 67 and 59.", "completion": "This is an addition problem over the numbers 67 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 117, and the remaining 9 gives 126. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 59 from 126 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 126.", "meta": {"a": 67, "b": 59, "result": 126, "style": "long"}}
{"id": "arith-576", "prompt": "What is the product of 18 and 67?", "completion": "This is a multiplication problem over the numbers 18 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1080, and by the remaining 7 gives 126, which sum to 1206. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 67 times 18 is also 1206, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1206.", "meta": {"a": 18, "b": 67, "result": 1206, "style": "long"}}
{"id": "arith-577", "prompt": "What is the product of 74 and 9?", "completion": "This is a multiplication problem over the numbers 74 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 9 gives 666, which sum to 666. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 9 times 74 is also 666, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 666.", "meta": {"a": 74, "b": 9, "result": 666, "style": "long"}}
{"id": "arith-578", "prompt": "Subtract 4 from 94.", "completion": "This is a subtraction problem over the numbers 94 and 4, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 94, and removing the last 4 leaves 90. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 4 back to 90 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 90.", "meta": {"a": 94, "b": 4, "result": 90, "style": "long"}}
{"id": "arith-579", "prompt": "Subtract 97 from 2.", "completion": "This is a subtraction problem over the numbers 2 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -88, and removing the last 7 leaves -95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 97 back to -95 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -95.", "meta": {"a": 2, "b": 97, "result": -95, "style": "long"}}
{"id": "arith-580", "prompt": "Add 7 and 56.", "completion": "This is an addition problem over the numbers 7 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 57, and the remaining 6 gives 63. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 56 from 63 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 63.", "meta": {"a": 7, "b": 56, "result": 63, "style": "long"}}
{"id": "arith-581", "prompt": "Add 71 and 9.", "completion": "This is an addition problem over the numbers 71 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 71, and the remaining 9 gives 80. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 9 from 80 returns 71, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 80.", "meta": {"a": 71, "b": 9, "result": 80, "style": "long"}}
{"id": "arith-582", "prompt": "What is the product of 6 and 38?", "completion": "This is a multiplication problem over the numbers 6 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 180, and by the remaining 8 gives 48, which sum to 228. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 38 times 6 is also 228, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 228.", "meta": {"a": 6, "b": 38, "result": 228, "style": "long"}}
{"id": "arith-583", "prompt": "What do you get when you add 19 to 84?", "completion": "This is an addition problem over the numbers 19 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 99, and the remaining 4 gives 103. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 84 from 103 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 103.", "meta": {"a": 19, "b": 84, "result": 103, "style": "long"}}
{"id": "arith-584", "prompt": "What is 50 times 59?", "completion": "This is a multiplication problem over the numbers 50 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2500, and by the remaining 9 gives 450, which sum to 2950. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 59 times 50 is also 2950, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2950.", "meta": {"a": 50, "b": 59, "result": 2950, "style": "long"}}
{"id": "arith-585", "prompt": "Multiply 12 by 89.", "completion": "This is a multiplication problem over the numbers 12 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 960, and by the remaining 9 gives 108, which sum to 1068. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 89 times 12 is also 1068, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1068.", "meta": {"a": 12, "b": 89, "result": 1068, "style": "long"}}
{"id": "arith-586", "prompt": "What is 17 times 24?", "completion": "This is a multiplication problem over the numbers 17 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 340, and by the remaining 4 gives 68, which sum to 408. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 24 times 17 is also 408, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 408.", "meta": {"a": 17, "b": 24, "result": 408, "style": "long"}}
{"id": "arith-587", "prompt": "What do you get when you add 95 to 30?", "completion": "This is an addition problem over the numbers 95 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 125, and the remaining 0 gives 125. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 30 from 125 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 125.", "meta": {"a": 95, "b": 30, "result": 125, "style": "long"}}
{"id": "arith-588", "prompt": "What is 40 plus 61?", "completion": "This is an addition problem over the numbers 40 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 100, and the remaining 1 gives 101. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 61 from 101 returns 40, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 101.", "meta": {"a": 40, "b": 61, "result": 101, "style": "long"}}
{"id": "arith-589", "prompt": "Multiply 31 by 33.", "completion": "This is a multiplication problem over the numbers 31 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 930, and by the remaining 3 gives 93, which sum to 1023. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 33 times 31 is also 1023, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1023.", "meta": {"a": 31, "b": 33, "result": 1023, "style": "long"}}
{"id": "arith-590", "prompt": "What is 21 times 37?", "completion": "This is a multiplication problem over the numbers 21 and 37, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 630, and by the remaining 7 gives 147, which sum to 777. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 37 times 21 is also 777, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 777.", "meta": {"a": 21, "b": 37, "result": 777, "style": "long"}}
{"id": "arith-591", "prompt": "Add 6 and 86.", "completion": "This is an addition problem over the numbers 6 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 86, and the remaining 6 gives 92. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 86 from 92 returns 6, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 92.", "meta": {"a": 6, "b": 86, "result": 92, "style": "long"}}
{"id": "arith-592", "prompt": "What is 32 plus 28?", "completion": "This is an addition problem over the numbers 32 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 52, and the remaining 8 gives 60. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 28 from 60 returns 32, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 60.", "meta": {"a": 32, "b": 28, "result": 60, "style": "long"}}
{"id": "arith-593", "prompt": "Add 78 and 6.", "completion": "This is an addition problem over the numbers 78 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 78, and the remaining 6 gives 84. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 6 from 84 returns 78, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 84.", "meta": {"a": 78, "b": 6, "result": 84, "style": "long"}}
{"id": "arith-594", "prompt": "What is 33 plus 96?", "completion": "This is an addition problem over the numbers 33 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 123, and the remaining 6 gives 129. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 129 returns 33, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 129.", "meta": {"a": 33, "b": 96, "result": 129, "style": "long"}}
{"id": "arith-595", "prompt": "Multiply 58 by 31.", "completion": "This is a multiplication problem over the numbers 58 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1740, and by the remaining 1 gives 58, which sum to 1798. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 31 times 58 is also 1798, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1798.", "meta": {"a": 58, "b": 31, "result": 1798, "style": "long"}}
{"id": "arith-596", "prompt": "What is 19 plus 66?", "completion": "This is an addition problem over the numbers 19 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 79, and the remaining 6 gives 85. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 66 from 85 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 85.", "meta": {"a": 19, "b": 66, "result": 85, "style": "long"}}
{"id": "arith-597", "prompt": "What is 95 minus 75?", "completion": "This is a subtraction problem over the numbers 95 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 25, and removing the last 5 leaves 20. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 75 back to 20 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 20.", "meta": {"a": 95, "b": 75, "result": 20, "style": "long"}}
{"id": "arith-598", "prompt": "What is 32 times 40?", "completion": "This is a multiplication problem over the numbers 32 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1280, and by the remaining 0 gives 0, which sum to 1280. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 40 times 32 is also 1280, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1280.", "meta": {"a": 32, "b": 40, "result": 1280, "style": "long"}}
{"id": "arith-599", "prompt": "What is 54 minus 40?", "completion": "This is a subtraction problem over the numbers 54 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 14, and removing the last 0 leaves 14. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 40 back to 14 returns 54, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 14.", "meta": {"a": 54, "b": 40, "result": 14, "style": "long"}}
{"id": "arith-600", "prompt": "What is 73 plus 77?", "completion": "This is an addition problem over the numbers 73 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 143, and the remaining 7 gives 150. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 77 from 150 returns 73, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 150.", "meta": {"a": 73, "b": 77, "result": 150, "style": "long"}}
{"id": "arith-601", "prompt": "Multiply 73 by 65.", "completion": "This is a multiplication problem over the numbers 73 and 65, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4380, and by the remaining 5 gives 365, which sum to 4745. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 65 times 73 is also 4745, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4745.", "meta": {"a": 73, "b": 65, "result": 4745, "style": "long"}}
{"id": "arith-602", "prompt": "What is 84 times 87?", "completion": "This is a multiplication problem over the numbers 84 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 6720, and by the remaining 7 gives 588, which sum to 7308. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 87 times 84 is also 7308, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7308.", "meta": {"a": 84, "b": 87, "result": 7308, "style": "long"}}
{"id": "arith-603", "prompt": "What is 91 times 55?", "completion": "This is a multiplication problem over the numbers 91 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4550, and by the remaining 5 gives 455, which sum to 5005. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 55 times 91 is also 5005, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5005.", "meta": {"a": 91, "b": 55, "result": 5005, "style": "long"}}
{"id": "arith-604", "prompt": "What do you get when you add 40 to 50?", "completion": "This is an addition problem over the numbers 40 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 90, and the remaining 0 gives 90. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 50 from 90 returns 40, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 90.", "meta": {"a": 40, "b": 50, "result": 90, "style": "long"}}
{"id": "arith-605", "prompt": "What is the product of 32 and 30?", "completion": "This is a multiplication problem over the numbers 32 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 960, and by the remaining 0 gives 0, which sum to 960. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 30 times 32 is also 960, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 960.", "meta": {"a": 32, "b": 30, "result": 960, "style": "long"}}
{"id": "arith-606", "prompt": "What do you get when you add 61 to 9?", "completion": "This is an addition problem over the numbers 61 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 61, and the remaining 9 gives 70. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 9 from 70 returns 61, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 70.", "meta": {"a": 61, "b": 9, "result": 70, "style": "long"}}
{"id": "arith-607", "prompt": "Multiply 73 by 69.", "completion": "This is a multiplication problem over the numbers 73 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4380, and by the remaining 9 gives 657, which sum to 5037. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 69 times 73 is also 5037, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5037.", "meta": {"a": 73, "b": 69, "result": 5037, "style": "long"}}
{"id": "arith-608", "prompt": "Multiply 33 by 34.", "completion": "This is a multiplication problem over the numbers 33 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 990, and by the remaining 4 gives 132, which sum to 1122. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 34 times 33 is also 1122, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1122.", "meta": {"a": 33, "b": 34, "result": 1122, "style": "long"}}
{"id": "arith-609", "prompt": "What is 84 times 12?", "completion": "This is a multiplication problem over the numbers 84 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 840, and by the remaining 2 gives 168, which sum to 1008. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 12 times 84 is also 1008, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1008.", "meta": {"a": 84, "b": 12, "result": 1008, "style": "long"}}
{"id": "arith-610", "prompt": "What is 13 times 70?", "completion": "This is a multiplication problem over the numbers 13 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 910, and by the remaining 0 gives 0, which sum to 910. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 70 times 13 is also 910, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 910.", "meta": {"a": 13, "b": 70, "result": 910, "style": "long"}}
{"id": "arith-611", "prompt": "What is 36 plus 50?", "completion": "This is an addition problem over the numbers 36 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 86, and the remaining 0 gives 86. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 50 from 86 returns 36, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 86.", "meta": {"a": 36, "b": 50, "result": 86, "style": "long"}}
{"id": "arith-612", "prompt": "Add 26 and 99.", "completion": "This is an addition problem over the numbers 26 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 116, and the remaining 9 gives 125. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 99 from 125 returns 26, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 125.", "meta": {"a": 26, "b": 99, "result": 125, "style": "long"}}
{"id": "arith-613", "prompt": "What is the product of 28 and 44?", "completion": "This is a multiplication problem over the numbers 28 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1120, and by the remaining 4 gives 112, which sum to 1232. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 44 times 28 is also 1232, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1232.", "meta": {"a": 28, "b": 44, "result": 1232, "style": "long"}}
{"id": "arith-614", "prompt": "What is 29 plus 26?", "completion": "This is an addition problem over the numbers 29 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 49, and the remaining 6 gives 55. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 26 from 55 returns 29, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 55.", "meta": {"a": 29, "b": 26, "result": 55, "style": "long"}}
{"id": "arith-615", "prompt": "What is the product of 33 and 91?", "completion": "This is a multiplication problem over the numbers 33 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 2970, and by the remaining 1 gives 33, which sum to 3003. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 91 times 33 is also 3003, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3003.", "meta": {"a": 33, "b": 91, "result": 3003, "style": "long"}}
{"id": "arith-616", "prompt": "Multiply 32 by 72.", "completion": "This is a multiplication problem over the numbers 32 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 2240, and by the remaining 2 gives 64, which sum to 2304. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 72 times 32 is also 2304, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2304.", "meta": {"a": 32, "b": 72, "result": 2304, "style": "long"}}
{"id": "arith-617", "prompt": "Subtract 61 from 50.", "completion": "This is a subtraction problem over the numbers 50 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -10, and removing the last 1 leaves -11. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 61 back to -11 returns 50, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -11.", "meta": {"a": 50, "b": 61, "result": -11, "style": "long"}}
{"id": "arith-618", "prompt": "Subtract 48 from 35.", "completion": "This is a subtraction problem over the numbers 35 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -5, and removing the last 8 leaves -13. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 48 back to -13 returns 35, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -13.", "meta": {"a": 35, "b": 48, "result": -13, "style": "long"}}
{"id": "arith-619", "prompt": "What is the product of 14 and 94?", "completion": "This is a multiplication problem over the numbers 14 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 1260, and by the remaining 4 gives 56, which sum to 1316. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 94 times 14 is also 1316, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1316.", "meta": {"a": 14, "b": 94, "result": 1316, "style": "long"}}
{"id": "arith-620", "prompt": "What is 28 times 49?", "completion": "This is a multiplication problem over the numbers 28 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1120, and by the remaining 9 gives 252, which sum to 1372. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 49 times 28 is also 1372, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1372.", "meta": {"a": 28, "b": 49, "result": 1372, "style": "long"}}
{"id": "arith-621", "prompt": "Multiply 7 by 74.", "completion": "This is a multiplication problem over the numbers 7 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 490, and by the remaining 4 gives 28, which sum to 518. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 74 times 7 is also 518, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 518.", "meta": {"a": 7, "b": 74, "result": 518, "style": "long"}}
{"id": "arith-622", "prompt": "What do you get when you add 4 to 35?", "completion": "This is an addition problem over the numbers 4 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 34, and the remaining 5 gives 39. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 35 from 39 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 39.", "meta": {"a": 4, "b": 35, "result": 39, "style": "long"}}
{"id": "arith-623", "prompt": "Subtract 27 from 21.", "completion": "This is a subtraction problem over the numbers 21 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 1, and removing the last 7 leaves -6. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 27 back to -6 returns 21, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -6.", "meta": {"a": 21, "b": 27, "result": -6, "style": "long"}}
{"id": "arith-624", "prompt": "What is 50 minus 74?", "completion": "This is a subtraction problem over the numbers 50 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -20, and removing the last 4 leaves -24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 74 back to -24 returns 50, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -24.", "meta": {"a": 50, "b": 74, "result": -24, "style": "long"}}
{"id": "arith-625", "prompt": "What is the product of 72 and 85?", "completion": "This is a multiplication problem over the numbers 72 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 5760, and by the remaining 5 gives 360, which sum to 6120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 72 is also 6120, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6120.", "meta": {"a": 72, "b": 85, "result": 6120, "style": "long"}}
{"id": "arith-626", "prompt": "Subtract 64 from 99.", "completion": "This is a subtraction problem over the numbers 99 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves 39, and removing the last 4 leaves 35. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 64 back to 35 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 35.", "meta": {"a": 99, "b": 64, "result": 35, "style": "long"}}
{"id": "arith-627", "prompt": "What is the product of 23 and 95?", "completion": "This is a multiplication problem over the numbers 23 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 2070, and by the remaining 5 gives 115, which sum to 2185. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 95 times 23 is also 2185, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2185.", "meta": {"a": 23, "b": 95, "result": 2185, "style": "long"}}
{"id": "arith-628", "prompt": "What do you get when you add 19 to 94?", "completion": "This is an addition problem over the numbers 19 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 109, and the remaining 4 gives 113. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 94 from 113 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 113.", "meta": {"a": 19, "b": 94, "result": 113, "style": "long"}}
{"id": "arith-629", "prompt": "What do you get when you add 71 to 84?", "completion": "This is an addition problem over the numbers 71 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 151, and the remaining 4 gives 155. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 84 from 155 returns 71, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 155.", "meta": {"a": 71, "b": 84, "result": 155, "style": "long"}}
{"id": "arith-630", "prompt": "What is 11 plus 87?", "completion": "This is an addition problem over the numbers 11 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 91, and the remaining 7 gives 98. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 87 from 98 returns 11, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 98.", "meta": {"a": 11, "b": 87, "result": 98, "style": "long"}}
{"id": "arith-631", "prompt": "What is 54 plus 19?", "completion": "This is an addition problem over the numbers 54 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 64, and the remaining 9 gives 73. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 19 from 73 returns 54, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 73.", "meta": {"a": 54, "b": 19, "result": 73, "style": "long"}}
{"id": "arith-632", "prompt": "Add 92 and 21.", "completion": "This is an addition problem over the numbers 92 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 112, and the remaining 1 gives 113. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 21 from 113 returns 92, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 113.", "meta": {"a": 92, "b": 21, "result": 113, "style": "long"}}
{"id": "arith-633", "prompt": "What is 66 minus 60?", "completion": "This is a subtraction problem over the numbers 66 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves 6, and removing the last 0 leaves 6. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 60 back to 6 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6.", "meta": {"a": 66, "b": 60, "result": 6, "style": "long"}}
{"id": "arith-634", "prompt": "What is 81 plus 83?", "completion": "This is an addition problem over the numbers 81 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 161, and the remaining 3 gives 164. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 83 from 164 returns 81, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 164.", "meta": {"a": 81, "b": 83, "result": 164, "style": "long"}}
{"id": "arith-635", "prompt": "What is the product of 4 and 2?", "completion": "This is a multiplication problem over the numbers 4 and 2, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 2 gives 8, which sum to 8. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 2 times 4 is also 8, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8.", "meta": {"a": 4, "b": 2, "result": 8, "style": "long"}}
{"id": "arith-636", "prompt": "What is 4 plus 69?", "completion": "This is an addition problem over the numbers 4 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 64, and the remaining 9 gives 73. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 69 from 73 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 73.", "meta": {"a": 4, "b": 69, "result": 73, "style": "long"}}
{"id": "arith-637", "prompt": "Subtract 66 from 4.", "completion": "This is a subtraction problem over the numbers 4 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -56, and removing the last 6 leaves -62. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 66 back to -62 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -62.", "meta": {"a": 4, "b": 66, "result": -62, "style": "long"}}
{"id": "arith-638", "prompt": "What do you get when you add 15 to 14?", "completion": "This is an addition problem over the numbers 15 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 25, and the remaining 4 gives 29. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 14 from 29 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 29.", "meta": {"a": 15, "b": 14, "result": 29, "style": "long"}}
{"id": "arith-639", "prompt": "What is 26 minus 81?", "completion": "This is a subtraction problem over the numbers 26 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -54, and removing the last 1 leaves -55. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 81 back to -55 returns 26, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -55.", "meta": {"a": 26, "b": 81, "result": -55, "style": "long"}}
{"id": "arith-640", "prompt": "What is 36 times 52?", "completion": "This is a multiplication problem over the numbers 36 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 1800, and by the remaining 2 gives 72, which sum to 1872. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 52 times 36 is also 1872, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1872.", "meta": {"a": 36, "b": 52, "result": 1872, "style": "long"}}
{"id": "arith-641", "prompt": "What is 53 times 60?", "completion": "This is a multiplication problem over the numbers 53 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3180, and by the remaining 0 gives 0, which sum to 3180. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 53 is also 3180, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3180.", "meta": {"a": 53, "b": 60, "result": 3180, "style": "long"}}
{"id": "arith-642", "prompt": "What is 40 minus 89?", "completion": "This is a subtraction problem over the numbers 40 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -40, and removing the last 9 leaves -49. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 89 back to -49 returns 40, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -49.", "meta": {"a": 40, "b": 89, "result": -49, "style": "long"}}
{"id": "arith-643", "prompt": "What is 13 plus 53?", "completion": "This is an addition problem over the numbers 13 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 63, and the remaining 3 gives 66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 53 from 66 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 66.", "meta": {"a": 13, "b": 53, "result": 66, "style": "long"}}
{"id": "arith-644", "prompt": "Multiply 72 by 62.", "completion": "This is a multiplication problem over the numbers 72 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4320, and by the remaining 2 gives 144, which sum to 4464. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 72 is also 4464, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4464.", "meta": {"a": 72, "b": 62, "result": 4464, "style": "long"}}
{"id": "arith-645", "prompt": "What is 91 plus 23?", "completion": "This is an addition problem over the numbers 91 and 23, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 111, and the remaining 3 gives 114. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 23 from 114 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 114.", "meta": {"a": 91, "b": 23, "result": 114, "style": "long"}}
{"id": "arith-646", "prompt": "What is the product of 57 and 84?", "completion": "This is a multiplication problem over the numbers 57 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 4560, and by the remaining 4 gives 228, which sum to 4788. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 84 times 57 is also 4788, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4788.", "meta": {"a": 57, "b": 84, "result": 4788, "style": "long"}}
{"id": "arith-647", "prompt": "Add 69 and 7.", "completion": "This is an addition problem over the numbers 69 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 69, and the remaining 7 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 7 from 76 returns 69, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 69, "b": 7, "result": 76, "style": "long"}}
{"id": "arith-648", "prompt": "What is 90 minus 74?", "completion": "This is a subtraction problem over the numbers 90 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 20, and removing the last 4 leaves 16. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 74 back to 16 returns 90, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 16.", "meta": {"a": 90, "b": 74, "result": 16, "style": "long"}}
{"id": "arith-649", "prompt": "Subtract 11 from 7.", "completion": "This is a subtraction problem over the numbers 7 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves -3, and removing the last 1 leaves -4. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 11 back to -4 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -4.", "meta": {"a": 7, "b": 11, "result": -4, "style": "long"}}
{"id": "arith-650", "prompt": "What is 24 plus 42?", "completion": "This is an addition problem over the numbers 24 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 64, and the remaining 2 gives 66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 42 from 66 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 66.", "meta": {"a": 24, "b": 42, "result": 66, "style": "long"}}
{"id": "arith-651", "prompt": "What is 77 minus 20?", "completion": "This is a subtraction problem over the numbers 77 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 57, and removing the last 0 leaves 57. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 20 back to 57 returns 77, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 57.", "meta": {"a": 77, "b": 20, "result": 57, "style": "long"}}
{"id": "arith-652", "prompt": "Add 40 and 22.", "completion": "This is an addition problem over the numbers 40 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 60, and the remaining 2 gives 62. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 22 from 62 returns 40, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 62.", "meta": {"a": 40, "b": 22, "result": 62, "style": "long"}}
{"id": "arith-653", "prompt": "Multiply 88 by 71.", "completion": "This is a multiplication problem over the numbers 88 and 71, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 6160, and by the remaining 1 gives 88, which sum to 6248. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 71 times 88 is also 6248, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6248.", "meta": {"a": 88, "b": 71, "result": 6248, "style": "long"}}
{"id": "arith-654", "prompt": "Multiply 98 by 96.", "completion": "This is a multiplication problem over the numbers 98 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 8820, and by the remaining 6 gives 588, which sum to 9408. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 96 times 98 is also 9408, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 9408.", "meta": {"a": 98, "b": 96, "result": 9408, "style": "long"}}
{"id": "arith-655", "prompt": "Add 66 and 97.", "completion": "This is an addition problem over the numbers 66 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 156, and the remaining 7 gives 163. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 97 from 163 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 163.", "meta": {"a": 66, "b": 97, "result": 163, "style": "long"}}
{"id": "arith-656", "prompt": "What is 14 plus 57?", "completion": "This is an addition problem over the numbers 14 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 64, and the remaining 7 gives 71. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 57 from 71 returns 14, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 71.", "meta": {"a": 14, "b": 57, "result": 71, "style": "long"}}
{"id": "arith-657", "prompt": "Add 45 and 79.", "completion": "This is an addition problem over the numbers 45 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 115, and the remaining 9 gives 124. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 79 from 124 returns 45, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 124.", "meta": {"a": 45, "b": 79, "result": 124, "style": "long"}}
{"id": "arith-658", "prompt": "What is 5 times 83?", "completion": "This is a multiplication problem over the numbers 5 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 400, and by the remaining 3 gives 15, which sum to 415. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 83 times 5 is also 415, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 415.", "meta": {"a": 5, "b": 83, "result": 415, "style": "long"}}
{"id": "arith-659", "prompt": "What is the product of 64 and 31?", "completion": "This is a multiplication problem over the numbers 64 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1920, and by the remaining 1 gives 64, which sum to 1984. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 31 times 64 is also 1984, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1984.", "meta": {"a": 64, "b": 31, "result": 1984, "style": "long"}}
{"id": "arith-660", "prompt": "Multiply 57 by 25.", "completion": "This is a multiplication problem over the numbers 57 and 25, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1140, and by the remaining 5 gives 285, which sum to 1425. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 25 times 57 is also 1425, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1425.", "meta": {"a": 57, "b": 25, "result": 1425, "style": "long"}}
{"id": "arith-661", "prompt": "Add 81 and 39.", "completion": "This is an addition problem over the numbers 81 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 111, and the remaining 9 gives 120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 39 from 120 returns 81, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 120.", "meta": {"a": 81, "b": 39, "result": 120, "style": "long"}}
{"id": "arith-662", "prompt": "Add 12 and 36.", "completion": "This is an addition problem over the numbers 12 and 36, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 42, and the remaining 6 gives 48. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 36 from 48 returns 12, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 48.", "meta": {"a": 12, "b": 36, "result": 48, "style": "long"}}
{"id": "arith-663", "prompt": "Multiply 93 by 83.", "completion": "This is a multiplication problem over the numbers 93 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 7440, and by the remaining 3 gives 279, which sum to 7719. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 83 times 93 is also 7719, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7719.", "meta": {"a": 93, "b": 83, "result": 7719, "style": "long"}}
{"id": "arith-664", "prompt": "Multiply 42 by 48.", "completion": "This is a multiplication problem over the numbers 42 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1680, and by the remaining 8 gives 336, which sum to 2016. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 48 times 42 is also 2016, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2016.", "meta": {"a": 42, "b": 48, "result": 2016, "style": "long"}}
{"id": "arith-665", "prompt": "Add 2 and 41.", "completion": "This is an addition problem over the numbers 2 and 41, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 42, and the remaining 1 gives 43. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 41 from 43 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 43.", "meta": {"a": 2, "b": 41, "result": 43, "style": "long"}}
{"id": "arith-666", "prompt": "What is 99 times 36?", "completion": "This is a multiplication problem over the numbers 99 and 36, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2970, and by the remaining 6 gives 594, which sum to 3564. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 36 times 99 is also 3564, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3564.", "meta": {"a": 99, "b": 36, "result": 3564, "style": "long"}}
{"id": "arith-667", "prompt": "What do you get when you add 13 to 25?", "completion": "This is an addition problem over the numbers 13 and 25, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 33, and the remaining 5 gives 38. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 25 from 38 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 38.", "meta": {"a": 13, "b": 25, "result": 38, "style": "long"}}
{"id": "arith-668", "prompt": "What is the product of 73 and 73?", "completion": "This is a multiplication problem over the numbers 73 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 5110, and by the remaining 3 gives 219, which sum to 5329. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 73 times 73 is also 5329, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5329.", "meta": {"a": 73, "b": 73, "result": 5329, "style": "long"}}
{"id": "arith-669", "prompt": "Add 5 and 13.", "completion": "This is an addition problem over the numbers 5 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 15, and the remaining 3 gives 18. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 13 from 18 returns 5, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 18.", "meta": {"a": 5, "b": 13, "result": 18, "style": "long"}}
{"id": "arith-670", "prompt": "Add 78 and 78.", "completion": "This is an addition problem over the numbers 78 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 148, and the remaining 8 gives 156. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 78 from 156 returns 78, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 156.", "meta": {"a": 78, "b": 78, "result": 156, "style": "long"}}
{"id": "arith-671", "prompt": "Multiply 3 by 39.", "completion": "This is a multiplication problem over the numbers 3 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 90, and by the remaining 9 gives 27, which sum to 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 39 times 3 is also 117, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 3, "b": 39, "result": 117, "style": "long"}}
{"id": "arith-672", "prompt": "Multiply 12 by 94.", "completion": "This is a multiplication problem over the numbers 12 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 1080, and by the remaining 4 gives 48, which sum to 1128. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 94 times 12 is also 1128, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1128.", "meta": {"a": 12, "b": 94, "result": 1128, "style": "long"}}
{"id": "arith-673", "prompt": "What do you get when you add 89 to 50?", "completion": "This is an addition problem over the numbers 89 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 139, and the remaining 0 gives 139. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 50 from 139 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 139.", "meta": {"a": 89, "b": 50, "result": 139, "style": "long"}}
{"id": "arith-674", "prompt": "What do you get when you add 36 to 40?", "completion": "This is an addition problem over the numbers 36 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 76, and the remaining 0 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 40 from 76 returns 36, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 36, "b": 40, "result": 76, "style": "long"}}
{"id": "arith-675", "prompt": "What is the product of 20 and 10?", "completion": "This is a multiplication problem over the numbers 20 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 200, and by the remaining 0 gives 0, which sum to 200. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 10 times 20 is also 200, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 200.", "meta": {"a": 20, "b": 10, "result": 200, "style": "long"}}
{"id": "arith-676", "prompt": "Multiply 37 by 55.", "completion": "This is a multiplication problem over the numbers 37 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 1850, and by the remaining 5 gives 185, which sum to 2035. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 55 times 37 is also 2035, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2035.", "meta": {"a": 37, "b": 55, "result": 2035, "style": "long"}}
{"id": "arith-677", "prompt": "What is the product of 11 and 48?", "completion": "This is a multiplication problem over the numbers 11 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 440, and by the remaining 8 gives 88, which sum to 528. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 48 times 11 is also 528, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 528.", "meta": {"a": 11, "b": 48, "result": 528, "style": "long"}}
{"id": "arith-678", "prompt": "What is 94 minus 82?", "completion": "This is a subtraction problem over the numbers 94 and 82, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 14, and removing the last 2 leaves 12. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 82 back to 12 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 12.", "meta": {"a": 94, "b": 82, "result": 12, "style": "long"}}
{"id": "arith-679", "prompt": "What is 60 minus 15?", "completion": "This is a subtraction problem over the numbers 60 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 50, and removing the last 5 leaves 45. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 15 back to 45 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 45.", "meta": {"a": 60, "b": 15, "result": 45, "style": "long"}}
{"id": "arith-680", "prompt": "Subtract 52 from 2.", "completion": "This is a subtraction problem over the numbers 2 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -48, and removing the last 2 leaves -50. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 52 back to -50 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -50.", "meta": {"a": 2, "b": 52, "result": -50, "style": "long"}}
{"id": "arith-681", "prompt": "Multiply 44 by 58.", "completion": "This is a multiplication problem over the numbers 44 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2200, and by the remaining 8 gives 352, which sum to 2552. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 58 times 44 is also 2552, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2552.", "meta": {"a": 44, "b": 58, "result": 2552, "style": "long"}}
{"id": "arith-682", "prompt": "Multiply 85 by 78.", "completion": "This is a multiplication problem over the numbers 85 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 5950, and by the remaining 8 gives 680, which sum to 6630. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 78 times 85 is also 6630, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6630.", "meta": {"a": 85, "b": 78, "result": 6630, "style": "long"}}
{"id": "arith-683", "prompt": "Subtract 79 from 43.", "completion": "This is a subtraction problem over the numbers 43 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -27, and removing the last 9 leaves -36. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 79 back to -36 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -36.", "meta": {"a": 43, "b": 79, "result": -36, "style": "long"}}
{"id": "arith-684", "prompt": "What is the product of 42 and 24?", "completion": "This is a multiplication problem over the numbers 42 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 840, and by the remaining 4 gives 168, which sum to 1008. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 24 times 42 is also 1008, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1008.", "meta": {"a": 42, "b": 24, "result": 1008, "style": "long"}}
{"id": "arith-685", "prompt": "What is 39 times 96?", "completion": "This is a multiplication problem over the numbers 39 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 3510, and by the remaining 6 gives 234, which sum to 3744. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 96 times 39 is also 3744, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3744.", "meta": {"a": 39, "b": 96, "result": 3744, "style": "long"}}
{"id": "arith-686", "prompt": "What is 43 minus 50?", "completion": "This is a subtraction problem over the numbers 43 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -7, and removing the last 0 leaves -7. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 50 back to -7 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -7.", "meta": {"a": 43, "b": 50, "result": -7, "style": "long"}}
{"id": "arith-687", "prompt": "Multiply 48 by 16.", "completion": "This is a multiplication problem over the numbers 48 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 480, and by the remaining 6 gives 288, which sum to 768. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 16 times 48 is also 768, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 768.", "meta": {"a": 48, "b": 16, "result": 768, "style": "long"}}
{"id": "arith-688", "prompt": "What do you get when you add 89 to 72?", "completion": "This is an addition problem over the numbers 89 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 159, and the remaining 2 gives 161. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 72 from 161 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 161.", "meta": {"a": 89, "b": 72, "result": 161, "style": "long"}}
{"id": "arith-689", "prompt": "What is the product of 92 and 28?", "completion": "This is a multiplication problem over the numbers 92 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1840, and by the remaining 8 gives 736, which sum to 2576. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 28 times 92 is also 2576, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2576.", "meta": {"a": 92, "b": 28, "result": 2576, "style": "long"}}
{"id": "arith-690", "prompt": "Subtract 10 from 90.", "completion": "This is a subtraction problem over the numbers 90 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 80, and removing the last 0 leaves 80. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 10 back to 80 returns 90, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 80.", "meta": {"a": 90, "b": 10, "result": 80, "style": "long"}}
{"id": "arith-691", "prompt": "What is the product of 19 and 83?", "completion": "This is a multiplication problem over the numbers 19 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1520, and by the remaining 3 gives 57, which sum to 1577. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 83 times 19 is also 1577, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1577.", "meta": {"a": 19, "b": 83, "result": 1577, "style": "long"}}
{"id": "arith-692", "prompt": "What is 34 minus 86?", "completion": "This is a subtraction problem over the numbers 34 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -46, and removing the last 6 leaves -52. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 86 back to -52 returns 34, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -52.", "meta": {"a": 34, "b": 86, "result": -52, "style": "long"}}
{"id": "arith-693", "prompt": "Multiply 50 by 11.", "completion": "This is a multiplication problem over the numbers 50 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 500, and by the remaining 1 gives 50, which sum to 550. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 11 times 50 is also 550, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 550.", "meta": {"a": 50, "b": 11, "result": 550, "style": "long"}}
{"id": "arith-694", "prompt": "What is the product of 76 and 53?", "completion": "This is a multiplication problem over the numbers 76 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3800, and by the remaining 3 gives 228, which sum to 4028. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 53 times 76 is also 4028, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4028.", "meta": {"a": 76, "b": 53, "result": 4028, "style": "long"}}
{"id": "arith-695", "prompt": "What is 48 plus 91?", "completion": "This is an addition problem over the numbers 48 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 138, and the remaining 1 gives 139. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 91 from 139 returns 48, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 139.", "meta": {"a": 48, "b": 91, "result": 139, "style": "long"}}
{"id": "arith-696", "prompt": "Add 33 and 86.", "completion": "This is an addition problem over the numbers 33 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 113, and the remaining 6 gives 119. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 86 from 119 returns 33, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 119.", "meta": {"a": 33, "b": 86, "result": 119, "style": "long"}}
{"id": "arith-697", "prompt": "What do you get when you add 84 to 80?", "completion": "This is an addition problem over the numbers 84 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 164, and the remaining 0 gives 164. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 80 from 164 returns 84, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 164.", "meta": {"a": 84, "b": 80, "result": 164, "style": "long"}}
{"id": "arith-698", "prompt": "Multiply 98 by 44.", "completion": "This is a multiplication problem over the numbers 98 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3920, and by the remaining 4 gives 392, which sum to 4312. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 44 times 98 is also 4312, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4312.", "meta": {"a": 98, "b": 44, "result": 4312, "style": "long"}}
{"id": "arith-699", "prompt": "Add 3 and 14.", "completion": "This is an addition problem over the numbers 3 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 13, and the remaining 4 gives 17. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 14 from 17 returns 3, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 17.", "meta": {"a": 3, "b": 14, "result": 17, "style": "long"}}
{"id": "arith-700", "prompt": "What is 67 minus 97?", "completion": "This is a subtraction problem over the numbers 67 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -23, and removing the last 7 leaves -30. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 97 back to -30 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -30.", "meta": {"a": 67, "b": 97, "result": -30, "style": "long"}}
{"id": "arith-701", "prompt": "What is the product of 49 and 52?", "completion": "This is a multiplication problem over the numbers 49 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2450, and by the remaining 2 gives 98, which sum to 2548. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 52 times 49 is also 2548, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2548.", "meta": {"a": 49, "b": 52, "result": 2548, "style": "long"}}
{"id": "arith-702", "prompt": "What do you get when you add 46 to 5?", "completion": "This is an addition problem over the numbers 46 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 46, and the remaining 5 gives 51. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 5 from 51 returns 46, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 51.", "meta": {"a": 46, "b": 5, "result": 51, "style": "long"}}
{"id": "arith-703", "prompt": "Add 39 and 55.", "completion": "This is an addition problem over the numbers 39 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 89, and the remaining 5 gives 94. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 55 from 94 returns 39, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 94.", "meta": {"a": 39, "b": 55, "result": 94, "style": "long"}}
{"id": "arith-704", "prompt": "Add 95 and 20.", "completion": "This is an addition problem over the numbers 95 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 115, and the remaining 0 gives 115. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 20 from 115 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 115.", "meta": {"a": 95, "b": 20, "result": 115, "style": "long"}}
{"id": "arith-705", "prompt": "Subtract 60 from 45.", "completion": "This is a subtraction problem over the numbers 45 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -15, and removing the last 0 leaves -15. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 60 back to -15 returns 45, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -15.", "meta": {"a": 45, "b": 60, "result": -15, "style": "long"}}
{"id": "arith-706", "prompt": "What is the product of 46 and 62?", "completion": "This is a multiplication problem over the numbers 46 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 2760, and by the remaining 2 gives 92, which sum to 2852. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 62 times 46 is also 2852, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2852.", "meta": {"a": 46, "b": 62, "result": 2852, "style": "long"}}
{"id": "arith-707", "prompt": "What is the product of 94 and 91?", "completion": "This is a multiplication problem over the numbers 94 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 8460, and by the remaining 1 gives 94, which sum to 8554. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 91 times 94 is also 8554, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8554.", "meta": {"a": 94, "b": 91, "result": 8554, "style": "long"}}
{"id": "arith-708", "prompt": "What is 10 times 40?", "completion": "This is a multiplication problem over the numbers 10 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 400, and by the remaining 0 gives 0, which sum to 400. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 40 times 10 is also 400, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 400.", "meta": {"a": 10, "b": 40, "result": 400, "style": "long"}}
{"id": "arith-709", "prompt": "Add 4 and 45.", "completion": "This is an addition problem over the numbers 4 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 44, and the remaining 5 gives 49. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 45 from 49 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 49.", "meta": {"a": 4, "b": 45, "result": 49, "style": "long"}}
{"id": "arith-710", "prompt": "What do you get when you add 96 to 33?", "completion": "This is an addition problem over the numbers 96 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 126, and the remaining 3 gives 129. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 33 from 129 returns 96, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 129.", "meta": {"a": 96, "b": 33, "result": 129, "style": "long"}}
{"id": "arith-711", "prompt": "What do you get when you add 44 to 73?", "completion": "This is an addition problem over the numbers 44 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 114, and the remaining 3 gives 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 73 from 117 returns 44, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 44, "b": 73, "result": 117, "style": "long"}}
{"id": "arith-712", "prompt": "What is the product of 31 and 53?", "completion": "This is a multiplication problem over the numbers 31 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 1550, and by the remaining 3 gives 93, which sum to 1643. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 53 times 31 is also 1643, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1643.", "meta": {"a": 31, "b": 53, "result": 1643, "style": "long"}}
{"id": "arith-713", "prompt": "What do you get when you add 83 to 86?", "completion": "This is an addition problem over the numbers 83 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 163, and the remaining 6 gives 169. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 86 from 169 returns 83, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 169.", "meta": {"a": 83, "b": 86, "result": 169, "style": "long"}}
{"id": "arith-714", "prompt": "Multiply 5 by 96.", "completion": "This is a multiplication problem over the numbers 5 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 450, and by the remaining 6 gives 30, which sum to 480. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 96 times 5 is also 480, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 480.", "meta": {"a": 5, "b": 96, "result": 480, "style": "long"}}
{"id": "arith-715", "prompt": "What is the product of 77 and 56?", "completion": "This is a multiplication problem over the numbers 77 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3850, and by the remaining 6 gives 462, which sum to 4312. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 56 times 77 is also 4312, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4312.", "meta": {"a": 77, "b": 56, "result": 4312, "style": "long"}}
{"id": "arith-716", "prompt": "What is 92 plus 29?", "completion": "This is an addition problem over the numbers 92 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 112, and the remaining 9 gives 121. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 29 from 121 returns 92, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 121.", "meta": {"a": 92, "b": 29, "result": 121, "style": "long"}}
{"id": "arith-717", "prompt": "Subtract 92 from 98.", "completion": "This is a subtraction problem over the numbers 98 and 92, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves 8, and removing the last 2 leaves 6. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 92 back to 6 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6.", "meta": {"a": 98, "b": 92, "result": 6, "style": "long"}}
{"id": "arith-718", "prompt": "Add 70 and 25.", "completion": "This is an addition problem over the numbers 70 and 25, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 90, and the remaining 5 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 25 from 95 returns 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 70, "b": 25, "result": 95, "style": "long"}}
{"id": "arith-719", "prompt": "What is 27 times 60?", "completion": "This is a multiplication problem over the numbers 27 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1620, and by the remaining 0 gives 0, which sum to 1620. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 27 is also 1620, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1620.", "meta": {"a": 27, "b": 60, "result": 1620, "style": "long"}}
{"id": "arith-720", "prompt": "Subtract 64 from 87.", "completion": "This is a subtraction problem over the numbers 87 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves 27, and removing the last 4 leaves 23. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 64 back to 23 returns 87, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 23.", "meta": {"a": 87, "b": 64, "result": 23, "style": "long"}}
{"id": "arith-721", "prompt": "Multiply 80 by 52.", "completion": "This is a multiplication problem over the numbers 80 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4000, and by the remaining 2 gives 160, which sum to 4160. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 52 times 80 is also 4160, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4160.", "meta": {"a": 80, "b": 52, "result": 4160, "style": "long"}}
{"id": "arith-722", "prompt": "What is 47 times 60?", "completion": "This is a multiplication problem over the numbers 47 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 2820, and by the remaining 0 gives 0, which sum to 2820. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 60 times 47 is also 2820, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2820.", "meta": {"a": 47, "b": 60, "result": 2820, "style": "long"}}
{"id": "arith-723", "prompt": "Subtract 77 from 80.", "completion": "This is a subtraction problem over the numbers 80 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 10, and removing the last 7 leaves 3. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 77 back to 3 returns 80, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3.", "meta": {"a": 80, "b": 77, "result": 3, "style": "long"}}
{"id": "arith-724", "prompt": "What do you get when you add 42 to 17?", "completion": "This is an addition problem over the numbers 42 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 52, and the remaining 7 gives 59. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 17 from 59 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 59.", "meta": {"a": 42, "b": 17, "result": 59, "style": "long"}}
{"id": "arith-725", "prompt": "Subtract 25 from 16.", "completion": "This is a subtraction problem over the numbers 16 and 25, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves -4, and removing the last 5 leaves -9. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 25 back to -9 returns 16, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -9.", "meta": {"a": 16, "b": 25, "result": -9, "style": "long"}}
{"id": "arith-726", "prompt": "What do you get when you add 67 to 51?", "completion": "This is an addition problem over the numbers 67 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 117, and the remaining 1 gives 118. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 51 from 118 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 118.", "meta": {"a": 67, "b": 51, "result": 118, "style": "long"}}
{"id": "arith-727", "prompt": "What do you get when you add 75 to 51?", "completion": "This is an addition problem over the numbers 75 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 125, and the remaining 1 gives 126. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 51 from 126 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 126.", "meta": {"a": 75, "b": 51, "result": 126, "style": "long"}}
{"id": "arith-728", "prompt": "What do you get when you add 64 to 83?", "completion": "This is an addition problem over the numbers 64 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 144, and the remaining 3 gives 147. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 83 from 147 returns 64, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 147.", "meta": {"a": 64, "b": 83, "result": 147, "style": "long"}}
{"id": "arith-729", "prompt": "What do you get when you add 64 to 38?", "completion": "This is an addition problem over the numbers 64 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 94, and the remaining 8 gives 102. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 38 from 102 returns 64, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 102.", "meta": {"a": 64, "b": 38, "result": 102, "style": "long"}}
{"id": "arith-730", "prompt": "What do you get when you add 42 to 59?", "completion": "This is an addition problem over the numbers 42 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 92, and the remaining 9 gives 101. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 59 from 101 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 101.", "meta": {"a": 42, "b": 59, "result": 101, "style": "long"}}
{"id": "arith-731", "prompt": "What is 3 times 64?", "completion": "This is a multiplication problem over the numbers 3 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 180, and by the remaining 4 gives 12, which sum to 192. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 64 times 3 is also 192, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 192.", "meta": {"a": 3, "b": 64, "result": 192, "style": "long"}}
{"id": "arith-732", "prompt": "What is 51 minus 73?", "completion": "This is a subtraction problem over the numbers 51 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -19, and removing the last 3 leaves -22. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 73 back to -22 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -22.", "meta": {"a": 51, "b": 73, "result": -22, "style": "long"}}
{"id": "arith-733", "prompt": "Multiply 89 by 64.", "completion": "This is a multiplication problem over the numbers 89 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 5340, and by the remaining 4 gives 356, which sum to 5696. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 64 times 89 is also 5696, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5696.", "meta": {"a": 89, "b": 64, "result": 5696, "style": "long"}}
{"id": "arith-734", "prompt": "What is the product of 64 and 23?", "completion": "This is a multiplication problem over the numbers 64 and 23, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1280, and by the remaining 3 gives 192, which sum to 1472. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 23 times 64 is also 1472, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1472.", "meta": {"a": 64, "b": 23, "result": 1472, "style": "long"}}
{"id": "arith-735", "prompt": "What is 99 plus 30?", "completion": "This is an addition problem over the numbers 99 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 129, and the remaining 0 gives 129. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 30 from 129 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 129.", "meta": {"a": 99, "b": 30, "result": 129, "style": "long"}}
{"id": "arith-736", "prompt": "What is 37 plus 30?", "completion": "This is an addition problem over the numbers 37 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 67, and the remaining 0 gives 67. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 30 from 67 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 67.", "meta": {"a": 37, "b": 30, "result": 67, "style": "long"}}
{"id": "arith-737", "prompt": "What do you get when you add 60 to 74?", "completion": "This is an addition problem over the numbers 60 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 130, and the remaining 4 gives 134. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 74 from 134 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 134.", "meta": {"a": 60, "b": 74, "result": 134, "style": "long"}}
{"id": "arith-738", "prompt": "Add 75 and 16.", "completion": "This is an addition problem over the numbers 75 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 85, and the remaining 6 gives 91. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 16 from 91 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 91.", "meta": {"a": 75, "b": 16, "result": 91, "style": "long"}}
{"id": "arith-739", "prompt": "What is 71 times 98?", "completion": "This is a multiplication problem over the numbers 71 and 98, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 6390, and by the remaining 8 gives 568, which sum to 6958. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 98 times 71 is also 6958, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6958.", "meta": {"a": 71, "b": 98, "result": 6958, "style": "long"}}
{"id": "arith-740", "prompt": "What is the product of 71 and 29?", "completion": "This is a multiplication problem over the numbers 71 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1420, and by the remaining 9 gives 639, which sum to 2059. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 29 times 71 is also 2059, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2059.", "meta": {"a": 71, "b": 29, "result": 2059, "style": "long"}}
{"id": "arith-741", "prompt": "Add 96 and 85.", "completion": "This is an addition problem over the numbers 96 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 176, and the remaining 5 gives 181. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 85 from 181 returns 96, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 181.", "meta": {"a": 96, "b": 85, "result": 181, "style": "long"}}
{"id": "arith-742", "prompt": "Subtract 59 from 6.", "completion": "This is a subtraction problem over the numbers 6 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -44, and removing the last 9 leaves -53. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 59 back to -53 returns 6, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -53.", "meta": {"a": 6, "b": 59, "result": -53, "style": "long"}}
{"id": "arith-743", "prompt": "What is 13 times 58?", "completion": "This is a multiplication problem over the numbers 13 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 650, and by the remaining 8 gives 104, which sum to 754. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 58 times 13 is also 754, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 754.", "meta": {"a": 13, "b": 58, "result": 754, "style": "long"}}
{"id": "arith-744", "prompt": "What is 28 minus 96?", "completion": "This is a subtraction problem over the numbers 28 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -62, and removing the last 6 leaves -68. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 96 back to -68 returns 28, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -68.", "meta": {"a": 28, "b": 96, "result": -68, "style": "long"}}
{"id": "arith-745", "prompt": "Multiply 23 by 80.", "completion": "This is a multiplication problem over the numbers 23 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1840, and by the remaining 0 gives 0, which sum to 1840. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 80 times 23 is also 1840, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1840.", "meta": {"a": 23, "b": 80, "result": 1840, "style": "long"}}
{"id": "arith-746", "prompt": "What is 28 minus 9?", "completion": "This is a subtraction problem over the numbers 28 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 28, and removing the last 9 leaves 19. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 9 back to 19 returns 28, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 19.", "meta": {"a": 28, "b": 9, "result": 19, "style": "long"}}
{"id": "arith-747", "prompt": "Subtract 70 from 78.", "completion": "This is a subtraction problem over the numbers 78 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 8, and removing the last 0 leaves 8. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 70 back to 8 returns 78, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8.", "meta": {"a": 78, "b": 70, "result": 8, "style": "long"}}
{"id": "arith-748", "prompt": "What is 92 times 39?", "completion": "This is a multiplication problem over the numbers 92 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2760, and by the remaining 9 gives 828, which sum to 3588. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 39 times 92 is also 3588, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3588.", "meta": {"a": 92, "b": 39, "result": 3588, "style": "long"}}
{"id": "arith-749", "prompt": "Subtract 88 from 67.", "completion": "This is a subtraction problem over the numbers 67 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -13, and removing the last 8 leaves -21. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 88 back to -21 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -21.", "meta": {"a": 67, "b": 88, "result": -21, "style": "long"}}
{"id": "arith-750", "prompt": "What do you get when you add 98 to 54?", "completion": "This is an addition problem over the numbers 98 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 148, and the remaining 4 gives 152. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 54 from 152 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 152.", "meta": {"a": 98, "b": 54, "result": 152, "style": "long"}}
{"id": "arith-751", "prompt": "Subtract 18 from 85.", "completion": "This is a subtraction problem over the numbers 85 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 75, and removing the last 8 leaves 67. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 18 back to 67 returns 85, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 67.", "meta": {"a": 85, "b": 18, "result": 67, "style": "long"}}
{"id": "arith-752", "prompt": "What is 20 minus 93?", "completion": "This is a subtraction problem over the numbers 20 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -70, and removing the last 3 leaves -73. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 93 back to -73 returns 20, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -73.", "meta": {"a": 20, "b": 93, "result": -73, "style": "long"}}
{"id": "arith-753", "prompt": "What is 99 minus 88?", "completion": "This is a subtraction problem over the numbers 99 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 19, and removing the last 8 leaves 11. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 88 back to 11 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 11.", "meta": {"a": 99, "b": 88, "result": 11, "style": "long"}}
{"id": "arith-754", "prompt": "What is the product of 20 and 75?", "completion": "This is a multiplication problem over the numbers 20 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 1400, and by the remaining 5 gives 100, which sum to 1500. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 75 times 20 is also 1500, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1500.", "meta": {"a": 20, "b": 75, "result": 1500, "style": "long"}}
{"id": "arith-755", "prompt": "Multiply 50 by 59.", "completion": "This is a multiplication problem over the numbers 50 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2500, and by the remaining 9 gives 450, which sum to 2950. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 59 times 50 is also 2950, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2950.", "meta": {"a": 50, "b": 59, "result": 2950, "style": "long"}}
{"id": "arith-756", "prompt": "Add 53 and 67.", "completion": "This is an addition problem over the numbers 53 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 113, and the remaining 7 gives 120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 67 from 120 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 120.", "meta": {"a": 53, "b": 67, "result": 120, "style": "long"}}
{"id": "arith-757", "prompt": "What is 60 times 64?", "completion": "This is a multiplication problem over the numbers 60 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3600, and by the remaining 4 gives 240, which sum to 3840. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 64 times 60 is also 3840, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3840.", "meta": {"a": 60, "b": 64, "result": 3840, "style": "long"}}
{"id": "arith-758", "prompt": "What is 95 plus 13?", "completion": "This is an addition problem over the numbers 95 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 105, and the remaining 3 gives 108. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 13 from 108 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 108.", "meta": {"a": 95, "b": 13, "result": 108, "style": "long"}}
{"id": "arith-759", "prompt": "What is 10 times 70?", "completion": "This is a multiplication problem over the numbers 10 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 700, and by the remaining 0 gives 0, which sum to 700. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 70 times 10 is also 700, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 700.", "meta": {"a": 10, "b": 70, "result": 700, "style": "long"}}
{"id": "arith-760", "prompt": "What is 56 minus 29?", "completion": "This is a subtraction problem over the numbers 56 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 36, and removing the last 9 leaves 27. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 29 back to 27 returns 56, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 27.", "meta": {"a": 56, "b": 29, "result": 27, "style": "long"}}
{"id": "arith-761", "prompt": "Subtract 38 from 43.", "completion": "This is a subtraction problem over the numbers 43 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 13, and removing the last 8 leaves 5. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 38 back to 5 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5.", "meta": {"a": 43, "b": 38, "result": 5, "style": "long"}}
{"id": "arith-762", "prompt": "What do you get when you add 74 to 64?", "completion": "This is an addition problem over the numbers 74 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 134, and the remaining 4 gives 138. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 64 from 138 returns 74, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 138.", "meta": {"a": 74, "b": 64, "result": 138, "style": "long"}}
{"id": "arith-763", "prompt": "What is 7 plus 14?", "completion": "This is an addition problem over the numbers 7 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 17, and the remaining 4 gives 21. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 14 from 21 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 21.", "meta": {"a": 7, "b": 14, "result": 21, "style": "long"}}
{"id": "arith-764", "prompt": "What is 17 plus 22?", "completion": "This is an addition problem over the numbers 17 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 37, and the remaining 2 gives 39. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 22 from 39 returns 17, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 39.", "meta": {"a": 17, "b": 22, "result": 39, "style": "long"}}
{"id": "arith-765", "prompt": "What is the product of 2 and 56?", "completion": "This is a multiplication problem over the numbers 2 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 100, and by the remaining 6 gives 12, which sum to 112. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 56 times 2 is also 112, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 112.", "meta": {"a": 2, "b": 56, "result": 112, "style": "long"}}
{"id": "arith-766", "prompt": "What do you get when you add 85 to 40?", "completion": "This is an addition problem over the numbers 85 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 125, and the remaining 0 gives 125. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 40 from 125 returns 85, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 125.", "meta": {"a": 85, "b": 40, "result": 125, "style": "long"}}
{"id": "arith-767", "prompt": "Subtract 85 from 13.", "completion": "This is a subtraction problem over the numbers 13 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -67, and removing the last 5 leaves -72. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 85 back to -72 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -72.", "meta": {"a": 13, "b": 85, "result": -72, "style": "long"}}
{"id": "arith-768", "prompt": "Subtract 49 from 12.", "completion": "This is a subtraction problem over the numbers 12 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -28, and removing the last 9 leaves -37. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 49 back to -37 returns 12, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -37.", "meta": {"a": 12, "b": 49, "result": -37, "style": "long"}}
{"id": "arith-769", "prompt": "What is 52 plus 82?", "completion": "This is an addition problem over the numbers 52 and 82, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 132, and the remaining 2 gives 134. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 82 from 134 returns 52, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 134.", "meta": {"a": 52, "b": 82, "result": 134, "style": "long"}}
{"id": "arith-770", "prompt": "What is 56 minus 85?", "completion": "This is a subtraction problem over the numbers 56 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -24, and removing the last 5 leaves -29. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 85 back to -29 returns 56, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -29.", "meta": {"a": 56, "b": 85, "result": -29, "style": "long"}}
{"id": "arith-771", "prompt": "Add 2 and 29.", "completion": "This is an addition problem over the numbers 2 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 22, and the remaining 9 gives 31. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 29 from 31 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 31.", "meta": {"a": 2, "b": 29, "result": 31, "style": "long"}}
{"id": "arith-772", "prompt": "Add 18 and 77.", "completion": "This is an addition problem over the numbers 18 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 88, and the remaining 7 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 77 from 95 returns 18, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 18, "b": 77, "result": 95, "style": "long"}}
{"id": "arith-773", "prompt": "What is the product of 3 and 3?", "completion": "This is a multiplication problem over the numbers 3 and 3, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 3 gives 9, which sum to 9. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 3 times 3 is also 9, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 9.", "meta": {"a": 3, "b": 3, "result": 9, "style": "long"}}
{"id": "arith-774", "prompt": "Add 56 and 90.", "completion": "This is an addition problem over the numbers 56 and 90, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 146, and the remaining 0 gives 146. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 90 from 146 returns 56, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 146.", "meta": {"a": 56, "b": 90, "result": 146, "style": "long"}}
{"id": "arith-775", "prompt": "What is the product of 11 and 31?", "completion": "This is a multiplication problem over the numbers 11 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 330, and by the remaining 1 gives 11, which sum to 341. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 31 times 11 is also 341, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 341.", "meta": {"a": 11, "b": 31, "result": 341, "style": "long"}}
{"id": "arith-776", "prompt": "Add 95 and 15.", "completion": "This is an addition problem over the numbers 95 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 105, and the remaining 5 gives 110. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 15 from 110 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 110.", "meta": {"a": 95, "b": 15, "result": 110, "style": "long"}}
{"id": "arith-777", "prompt": "What is 49 times 40?", "completion": "This is a multiplication problem over the numbers 49 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1960, and by the remaining 0 gives 0, which sum to 1960. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 40 times 49 is also 1960, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1960.", "meta": {"a": 49, "b": 40, "result": 1960, "style": "long"}}
{"id": "arith-778", "prompt": "Multiply 98 by 19.", "completion": "This is a multiplication problem over the numbers 98 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 980, and by the remaining 9 gives 882, which sum to 1862. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 19 times 98 is also 1862, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1862.", "meta": {"a": 98, "b": 19, "result": 1862, "style": "long"}}
{"id": "arith-779", "prompt": "Add 69 and 74.", "completion": "This is an addition problem over the numbers 69 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 139, and the remaining 4 gives 143. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 74 from 143 returns 69, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 143.", "meta": {"a": 69, "b": 74, "result": 143, "style": "long"}}
{"id": "arith-780", "prompt": "What do you get when you add 58 to 46?", "completion": "This is an addition problem over the numbers 58 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 98, and the remaining 6 gives 104. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 46 from 104 returns 58, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 104.", "meta": {"a": 58, "b": 46, "result": 104, "style": "long"}}
{"id": "arith-781", "prompt": "What do you get when you add 54 to 80?", "completion": "This is an addition problem over the numbers 54 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 134, and the remaining 0 gives 134. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 80 from 134 returns 54, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 134.", "meta": {"a": 54, "b": 80, "result": 134, "style": "long"}}
{"id": "arith-782", "prompt": "What is 13 minus 14?", "completion": "This is a subtraction problem over the numbers 13 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 3, and removing the last 4 leaves -1. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 14 back to -1 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -1.", "meta": {"a": 13, "b": 14, "result": -1, "style": "long"}}
{"id": "arith-783", "prompt": "Add 77 and 95.", "completion": "This is an addition problem over the numbers 77 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 167, and the remaining 5 gives 172. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 95 from 172 returns 77, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 172.", "meta": {"a": 77, "b": 95, "result": 172, "style": "long"}}
{"id": "arith-784", "prompt": "What is 56 times 42?", "completion": "This is a multiplication problem over the numbers 56 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 2240, and by the remaining 2 gives 112, which sum to 2352. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 56 is also 2352, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2352.", "meta": {"a": 56, "b": 42, "result": 2352, "style": "long"}}
{"id": "arith-785", "prompt": "What is 37 minus 84?", "completion": "This is a subtraction problem over the numbers 37 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -43, and removing the last 4 leaves -47. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 84 back to -47 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -47.", "meta": {"a": 37, "b": 84, "result": -47, "style": "long"}}
{"id": "arith-786", "prompt": "What is 72 minus 78?", "completion": "This is a subtraction problem over the numbers 72 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 2, and removing the last 8 leaves -6. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 78 back to -6 returns 72, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -6.", "meta": {"a": 72, "b": 78, "result": -6, "style": "long"}}
{"id": "arith-787", "prompt": "What is 86 plus 40?", "completion": "This is an addition problem over the numbers 86 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 126, and the remaining 0 gives 126. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 40 from 126 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 126.", "meta": {"a": 86, "b": 40, "result": 126, "style": "long"}}
{"id": "arith-788", "prompt": "What is 97 minus 52?", "completion": "This is a subtraction problem over the numbers 97 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 47, and removing the last 2 leaves 45. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 52 back to 45 returns 97, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 45.", "meta": {"a": 97, "b": 52, "result": 45, "style": "long"}}
{"id": "arith-789", "prompt": "What is 32 plus 65?", "completion": "This is an addition problem over the numbers 32 and 65, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 92, and the remaining 5 gives 97. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 65 from 97 returns 32, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 97.", "meta": {"a": 32, "b": 65, "result": 97, "style": "long"}}
{"id": "arith-790", "prompt": "Add 32 and 65.", "completion": "This is an addition problem over the numbers 32 and 65, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 92, and the remaining 5 gives 97. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 65 from 97 returns 32, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 97.", "meta": {"a": 32, "b": 65, "result": 97, "style": "long"}}
{"id": "arith-791", "prompt": "What is 48 plus 42?", "completion": "This is an addition problem over the numbers 48 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 88, and the remaining 2 gives 90. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 42 from 90 returns 48, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 90.", "meta": {"a": 48, "b": 42, "result": 90, "style": "long"}}
{"id": "arith-792", "prompt": "Multiply 74 by 55.", "completion": "This is a multiplication problem over the numbers 74 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3700, and by the remaining 5 gives 370, which sum to 4070. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 55 times 74 is also 4070, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4070.", "meta": {"a": 74, "b": 55, "result": 4070, "style": "long"}}
{"id": "arith-793", "prompt": "What do you get when you add 99 to 62?", "completion": "This is an addition problem over the numbers 99 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 159, and the remaining 2 gives 161. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 62 from 161 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 161.", "meta": {"a": 99, "b": 62, "result": 161, "style": "long"}}
{"id": "arith-794", "prompt": "What is 77 plus 10?", "completion": "This is an addition problem over the numbers 77 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 87, and the remaining 0 gives 87. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 10 from 87 returns 77, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 87.", "meta": {"a": 77, "b": 10, "result": 87, "style": "long"}}
{"id": "arith-795", "prompt": "Subtract 7 from 29.", "completion": "This is a subtraction problem over the numbers 29 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 29, and removing the last 7 leaves 22. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 7 back to 22 returns 29, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 22.", "meta": {"a": 29, "b": 7, "result": 22, "style": "long"}}
{"id": "arith-796", "prompt": "Multiply 66 by 38.", "completion": "This is a multiplication problem over the numbers 66 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1980, and by the remaining 8 gives 528, which sum to 2508. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 38 times 66 is also 2508, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2508.", "meta": {"a": 66, "b": 38, "result": 2508, "style": "long"}}
{"id": "arith-797", "prompt": "Multiply 91 by 53.", "completion": "This is a multiplication problem over the numbers 91 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4550, and by the remaining 3 gives 273, which sum to 4823. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 53 times 91 is also 4823, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4823.", "meta": {"a": 91, "b": 53, "result": 4823, "style": "long"}}
{"id": "arith-798", "prompt": "What do you get when you add 37 to 12?", "completion": "This is an addition problem over the numbers 37 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 47, and the remaining 2 gives 49. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 12 from 49 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 49.", "meta": {"a": 37, "b": 12, "result": 49, "style": "long"}}
{"id": "arith-799", "prompt": "Add 67 and 28.", "completion": "This is an addition problem over the numbers 67 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 87, and the remaining 8 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 28 from 95 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 67, "b": 28, "result": 95, "style": "long"}}
{"id": "arith-800", "prompt": "What is 52 times 77?", "completion": "This is a multiplication problem over the numbers 52 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3640, and by the remaining 7 gives 364, which sum to 4004. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 77 times 52 is also 4004, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4004.", "meta": {"a": 52, "b": 77, "result": 4004, "style": "long"}}
{"id": "arith-801", "prompt": "Subtract 57 from 91.", "completion": "This is a subtraction problem over the numbers 91 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 41, and removing the last 7 leaves 34. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 57 back to 34 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 34.", "meta": {"a": 91, "b": 57, "result": 34, "style": "long"}}
{"id": "arith-802", "prompt": "What is 33 plus 13?", "completion": "This is an addition problem over the numbers 33 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 43, and the remaining 3 gives 46. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 13 from 46 returns 33, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 46.", "meta": {"a": 33, "b": 13, "result": 46, "style": "long"}}
{"id": "arith-803", "prompt": "Add 60 and 80.", "completion": "This is an addition problem over the numbers 60 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 140, and the remaining 0 gives 140. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 80 from 140 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 140.", "meta": {"a": 60, "b": 80, "result": 140, "style": "long"}}
{"id": "arith-804", "prompt": "Subtract 96 from 87.", "completion": "This is a subtraction problem over the numbers 87 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -3, and removing the last 6 leaves -9. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 96 back to -9 returns 87, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -9.", "meta": {"a": 87, "b": 96, "result": -9, "style": "long"}}
{"id": "arith-805", "prompt": "Add 3 and 92.", "completion": "This is an addition problem over the numbers 3 and 92, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 93, and the remaining 2 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 92 from 95 returns 3, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 3, "b": 92, "result": 95, "style": "long"}}
{"id": "arith-806", "prompt": "What is 22 plus 65?", "completion": "This is an addition problem over the numbers 22 and 65, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 82, and the remaining 5 gives 87. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 65 from 87 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 87.", "meta": {"a": 22, "b": 65, "result": 87, "style": "long"}}
{"id": "arith-807", "prompt": "Subtract 49 from 23.", "completion": "This is a subtraction problem over the numbers 23 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -17, and removing the last 9 leaves -26. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 49 back to -26 returns 23, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -26.", "meta": {"a": 23, "b": 49, "result": -26, "style": "long"}}
{"id": "arith-808", "prompt": "Subtract 17 from 95.", "completion": "This is a subtraction problem over the numbers 95 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 85, and removing the last 7 leaves 78. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 17 back to 78 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 78.", "meta": {"a": 95, "b": 17, "result": 78, "style": "long"}}
{"id": "arith-809", "prompt": "What is 56 times 36?", "completion": "This is a multiplication problem over the numbers 56 and 36, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1680, and by the remaining 6 gives 336, which sum to 2016. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 36 times 56 is also 2016, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2016.", "meta": {"a": 56, "b": 36, "result": 2016, "style": "long"}}
{"id": "arith-810", "prompt": "Subtract 75 from 93.", "completion": "This is a subtraction problem over the numbers 93 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 23, and removing the last 5 leaves 18. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 75 back to 18 returns 93, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 18.", "meta": {"a": 93, "b": 75, "result": 18, "style": "long"}}
{"id": "arith-811", "prompt": "What is the product of 60 and 67?", "completion": "This is a multiplication problem over the numbers 60 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3600, and by the remaining 7 gives 420, which sum to 4020. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 67 times 60 is also 4020, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4020.", "meta": {"a": 60, "b": 67, "result": 4020, "style": "long"}}
{"id": "arith-812", "prompt": "What is 65 plus 74?", "completion": "This is an addition problem over the numbers 65 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 135, and the remaining 4 gives 139. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 74 from 139 returns 65, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 139.", "meta": {"a": 65, "b": 74, "result": 139, "style": "long"}}
{"id": "arith-813", "prompt": "What is 22 times 34?", "completion": "This is a multiplication problem over the numbers 22 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 660, and by the remaining 4 gives 88, which sum to 748. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 34 times 22 is also 748, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 748.", "meta": {"a": 22, "b": 34, "result": 748, "style": "long"}}
{"id": "arith-814", "prompt": "Add 31 and 96.", "completion": "This is an addition problem over the numbers 31 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 121, and the remaining 6 gives 127. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 127 returns 31, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 127.", "meta": {"a": 31, "b": 96, "result": 127, "style": "long"}}
{"id": "arith-815", "prompt": "What is 3 plus 33?", "completion": "This is an addition problem over the numbers 3 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 33, and the remaining 3 gives 36. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 33 from 36 returns 3, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 36.", "meta": {"a": 3, "b": 33, "result": 36, "style": "long"}}
{"id": "arith-816", "prompt": "What is the product of 48 and 51?", "completion": "This is a multiplication problem over the numbers 48 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2400, and by the remaining 1 gives 48, which sum to 2448. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 51 times 48 is also 2448, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2448.", "meta": {"a": 48, "b": 51, "result": 2448, "style": "long"}}
{"id": "arith-817", "prompt": "What do you get when you add 6 to 72?", "completion": "This is an addition problem over the numbers 6 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 76, and the remaining 2 gives 78. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 72 from 78 returns 6, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 78.", "meta": {"a": 6, "b": 72, "result": 78, "style": "long"}}
{"id": "arith-818", "prompt": "What is 43 minus 33?", "completion": "This is a subtraction problem over the numbers 43 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 13, and removing the last 3 leaves 10. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 33 back to 10 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 10.", "meta": {"a": 43, "b": 33, "result": 10, "style": "long"}}
{"id": "arith-819", "prompt": "What is 36 times 11?", "completion": "This is a multiplication problem over the numbers 36 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 360, and by the remaining 1 gives 36, which sum to 396. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 11 times 36 is also 396, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 396.", "meta": {"a": 36, "b": 11, "result": 396, "style": "long"}}
{"id": "arith-820", "prompt": "Add 66 and 88.", "completion": "This is an addition problem over the numbers 66 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 146, and the remaining 8 gives 154. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 88 from 154 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 154.", "meta": {"a": 66, "b": 88, "result": 154, "style": "long"}}
{"id": "arith-821", "prompt": "What do you get when you add 30 to 68?", "completion": "This is an addition problem over the numbers 30 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 90, and the remaining 8 gives 98. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 68 from 98 returns 30, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 98.", "meta": {"a": 30, "b": 68, "result": 98, "style": "long"}}
{"id": "arith-822", "prompt": "Multiply 10 by 61.", "completion": "This is a multiplication problem over the numbers 10 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 600, and by the remaining 1 gives 10, which sum to 610. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 61 times 10 is also 610, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 610.", "meta": {"a": 10, "b": 61, "result": 610, "style": "long"}}
{"id": "arith-823", "prompt": "Subtract 13 from 43.", "completion": "This is a subtraction problem over the numbers 43 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 33, and removing the last 3 leaves 30. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 13 back to 30 returns 43, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 30.", "meta": {"a": 43, "b": 13, "result": 30, "style": "long"}}
{"id": "arith-824", "prompt": "What is 49 plus 27?", "completion": "This is an addition problem over the numbers 49 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 69, and the remaining 7 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 27 from 76 returns 49, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 49, "b": 27, "result": 76, "style": "long"}}
{"id": "arith-825", "prompt": "Subtract 81 from 96.", "completion": "This is a subtraction problem over the numbers 96 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 16, and removing the last 1 leaves 15. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 81 back to 15 returns 96, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 15.", "meta": {"a": 96, "b": 81, "result": 15, "style": "long"}}
{"id": "arith-826", "prompt": "What is the product of 49 and 77?", "completion": "This is a multiplication problem over the numbers 49 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3430, and by the remaining 7 gives 343, which sum to 3773. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 77 times 49 is also 3773, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3773.", "meta": {"a": 49, "b": 77, "result": 3773, "style": "long"}}
{"id": "arith-827", "prompt": "What is 95 minus 71?", "completion": "This is a subtraction problem over the numbers 95 and 71, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 25, and removing the last 1 leaves 24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 71 back to 24 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 24.", "meta": {"a": 95, "b": 71, "result": 24, "style": "long"}}
{"id": "arith-828", "prompt": "What is 31 plus 71?", "completion": "This is an addition problem over the numbers 31 and 71, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 101, and the remaining 1 gives 102. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 71 from 102 returns 31, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 102.", "meta": {"a": 31, "b": 71, "result": 102, "style": "long"}}
{"id": "arith-829", "prompt": "What is 44 plus 2?", "completion": "This is an addition problem over the numbers 44 and 2, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 44, and the remaining 2 gives 46. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 2 from 46 returns 44, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 46.", "meta": {"a": 44, "b": 2, "result": 46, "style": "long"}}
{"id": "arith-830", "prompt": "Subtract 28 from 15.", "completion": "This is a subtraction problem over the numbers 15 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves -5, and removing the last 8 leaves -13. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 28 back to -13 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -13.", "meta": {"a": 15, "b": 28, "result": -13, "style": "long"}}
{"id": "arith-831", "prompt": "Multiply 64 by 9.", "completion": "This is a multiplication problem over the numbers 64 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 9 gives 576, which sum to 576. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 9 times 64 is also 576, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 576.", "meta": {"a": 64, "b": 9, "result": 576, "style": "long"}}
{"id": "arith-832", "prompt": "Subtract 7 from 13.", "completion": "This is a subtraction problem over the numbers 13 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 13, and removing the last 7 leaves 6. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 7 back to 6 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6.", "meta": {"a": 13, "b": 7, "result": 6, "style": "long"}}
{"id": "arith-833", "prompt": "Multiply 91 by 49.", "completion": "This is a multiplication problem over the numbers 91 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3640, and by the remaining 9 gives 819, which sum to 4459. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 49 times 91 is also 4459, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4459.", "meta": {"a": 91, "b": 49, "result": 4459, "style": "long"}}
{"id": "arith-834", "prompt": "Add 76 and 14.", "completion": "This is an addition problem over the numbers 76 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 86, and the remaining 4 gives 90. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 14 from 90 returns 76, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 90.", "meta": {"a": 76, "b": 14, "result": 90, "style": "long"}}
{"id": "arith-835", "prompt": "Multiply 11 by 77.", "completion": "This is a multiplication problem over the numbers 11 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 770, and by the remaining 7 gives 77, which sum to 847. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 77 times 11 is also 847, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 847.", "meta": {"a": 11, "b": 77, "result": 847, "style": "long"}}
{"id": "arith-836", "prompt": "Multiply 86 by 18.", "completion": "This is a multiplication problem over the numbers 86 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 860, and by the remaining 8 gives 688, which sum to 1548. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 18 times 86 is also 1548, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1548.", "meta": {"a": 86, "b": 18, "result": 1548, "style": "long"}}
{"id": "arith-837", "prompt": "Subtract 42 from 35.", "completion": "This is a subtraction problem over the numbers 35 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -5, and removing the last 2 leaves -7. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 42 back to -7 returns 35, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -7.", "meta": {"a": 35, "b": 42, "result": -7, "style": "long"}}
{"id": "arith-838", "prompt": "What is 42 times 59?", "completion": "This is a multiplication problem over the numbers 42 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2100, and by the remaining 9 gives 378, which sum to 2478. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 59 times 42 is also 2478, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2478.", "meta": {"a": 42, "b": 59, "result": 2478, "style": "long"}}
{"id": "arith-839", "prompt": "What is 11 minus 27?", "completion": "This is a subtraction problem over the numbers 11 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves -9, and removing the last 7 leaves -16. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 27 back to -16 returns 11, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -16.", "meta": {"a": 11, "b": 27, "result": -16, "style": "long"}}
{"id": "arith-840", "prompt": "Add 21 and 15.", "completion": "This is an addition problem over the numbers 21 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 31, and the remaining 5 gives 36. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 15 from 36 returns 21, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 36.", "meta": {"a": 21, "b": 15, "result": 36, "style": "long"}}
{"id": "arith-841", "prompt": "What is the product of 61 and 42?", "completion": "This is a multiplication problem over the numbers 61 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 2440, and by the remaining 2 gives 122, which sum to 2562. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 61 is also 2562, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2562.", "meta": {"a": 61, "b": 42, "result": 2562, "style": "long"}}
{"id": "arith-842", "prompt": "Add 70 and 47.", "completion": "This is an addition problem over the numbers 70 and 47, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 110, and the remaining 7 gives 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 47 from 117 returns 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 70, "b": 47, "result": 117, "style": "long"}}
{"id": "arith-843", "prompt": "What is the product of 41 and 61?", "completion": "This is a multiplication problem over the numbers 41 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 2460, and by the remaining 1 gives 41, which sum to 2501. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 61 times 41 is also 2501, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2501.", "meta": {"a": 41, "b": 61, "result": 2501, "style": "long"}}
{"id": "arith-844", "prompt": "Add 13 and 22.", "completion": "This is an addition problem over the numbers 13 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 33, and the remaining 2 gives 35. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 22 from 35 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 35.", "meta": {"a": 13, "b": 22, "result": 35, "style": "long"}}
{"id": "arith-845", "prompt": "What is 29 plus 43?", "completion": "This is an addition problem over the numbers 29 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 69, and the remaining 3 gives 72. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 43 from 72 returns 29, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 72.", "meta": {"a": 29, "b": 43, "result": 72, "style": "long"}}
{"id": "arith-846", "prompt": "Add 93 and 33.", "completion": "This is an addition problem over the numbers 93 and 33, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 123, and the remaining 3 gives 126. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 33 from 126 returns 93, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 126.", "meta": {"a": 93, "b": 33, "result": 126, "style": "long"}}
{"id": "arith-847", "prompt": "Multiply 67 by 8.", "completion": "This is a multiplication problem over the numbers 67 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 536, which sum to 536. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 67 is also 536, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 536.", "meta": {"a": 67, "b": 8, "result": 536, "style": "long"}}
{"id": "arith-848", "prompt": "Subtract 5 from 24.", "completion": "This is a subtraction problem over the numbers 24 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 24, and removing the last 5 leaves 19. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 5 back to 19 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 19.", "meta": {"a": 24, "b": 5, "result": 19, "style": "long"}}
{"id": "arith-849", "prompt": "What is the product of 73 and 97?", "completion": "This is a multiplication problem over the numbers 73 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 6570, and by the remaining 7 gives 511, which sum to 7081. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 73 is also 7081, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7081.", "meta": {"a": 73, "b": 97, "result": 7081, "style": "long"}}
{"id": "arith-850", "prompt": "Add 61 and 15.", "completion": "This is an addition problem over the numbers 61 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 71, and the remaining 5 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 15 from 76 returns 61, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 61, "b": 15, "result": 76, "style": "long"}}
{"id": "arith-851", "prompt": "Add 3 and 9.", "completion": "This is an addition problem over the numbers 3 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 3, and the remaining 9 gives 12. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 9 from 12 returns 3, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 12.", "meta": {"a": 3, "b": 9, "result": 12, "style": "long"}}
{"id": "arith-852", "prompt": "What do you get when you add 27 to 53?", "completion": "This is an addition problem over the numbers 27 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 77, and the remaining 3 gives 80. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 53 from 80 returns 27, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 80.", "meta": {"a": 27, "b": 53, "result": 80, "style": "long"}}
{"id": "arith-853", "prompt": "Add 76 and 77.", "completion": "This is an addition problem over the numbers 76 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 146, and the remaining 7 gives 153. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 77 from 153 returns 76, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 153.", "meta": {"a": 76, "b": 77, "result": 153, "style": "long"}}
{"id": "arith-854", "prompt": "Add 4 and 10.", "completion": "This is an addition problem over the numbers 4 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 14, and the remaining 0 gives 14. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 10 from 14 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 14.", "meta": {"a": 4, "b": 10, "result": 14, "style": "long"}}
{"id": "arith-855", "prompt": "What is the product of 18 and 13?", "completion": "This is a multiplication problem over the numbers 18 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 180, and by the remaining 3 gives 54, which sum to 234. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 13 times 18 is also 234, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 234.", "meta": {"a": 18, "b": 13, "result": 234, "style": "long"}}
{"id": "arith-856", "prompt": "Add 7 and 61.", "completion": "This is an addition problem over the numbers 7 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 67, and the remaining 1 gives 68. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 61 from 68 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 68.", "meta": {"a": 7, "b": 61, "result": 68, "style": "long"}}
{"id": "arith-857", "prompt": "What do you get when you add 75 to 57?", "completion": "This is an addition problem over the numbers 75 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 125, and the remaining 7 gives 132. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 57 from 132 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 132.", "meta": {"a": 75, "b": 57, "result": 132, "style": "long"}}
{"id": "arith-858", "prompt": "What is the product of 5 and 50?", "completion": "This is a multiplication problem over the numbers 5 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 250, and by the remaining 0 gives 0, which sum to 250. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 50 times 5 is also 250, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 250.", "meta": {"a": 5, "b": 50, "result": 250, "style": "long"}}
{"id": "arith-859", "prompt": "What do you get when you add 47 to 29?", "completion": "This is an addition problem over the numbers 47 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 67, and the remaining 9 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 29 from 76 returns 47, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 47, "b": 29, "result": 76, "style": "long"}}
{"id": "arith-860", "prompt": "Subtract 59 from 37.", "completion": "This is a subtraction problem over the numbers 37 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -13, and removing the last 9 leaves -22. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 59 back to -22 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -22.", "meta": {"a": 37, "b": 59, "result": -22, "style": "long"}}
{"id": "arith-861", "prompt": "What is 80 plus 81?", "completion": "This is an addition problem over the numbers 80 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 160, and the remaining 1 gives 161. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 81 from 161 returns 80, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 161.", "meta": {"a": 80, "b": 81, "result": 161, "style": "long"}}
{"id": "arith-862", "prompt": "Subtract 54 from 65.", "completion": "This is a subtraction problem over the numbers 65 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 15, and removing the last 4 leaves 11. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 54 back to 11 returns 65, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 11.", "meta": {"a": 65, "b": 54, "result": 11, "style": "long"}}
{"id": "arith-863", "prompt": "What is 13 plus 37?", "completion": "This is an addition problem over the numbers 13 and 37, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 43, and the remaining 7 gives 50. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 37 from 50 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 50.", "meta": {"a": 13, "b": 37, "result": 50, "style": "long"}}
{"id": "arith-864", "prompt": "What do you get when you add 55 to 27?", "completion": "This is an addition problem over the numbers 55 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 75, and the remaining 7 gives 82. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 27 from 82 returns 55, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 82.", "meta": {"a": 55, "b": 27, "result": 82, "style": "long"}}
{"id": "arith-865", "prompt": "What is 50 plus 93?", "completion": "This is an addition problem over the numbers 50 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 140, and the remaining 3 gives 143. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 93 from 143 returns 50, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 143.", "meta": {"a": 50, "b": 93, "result": 143, "style": "long"}}
{"id": "arith-866", "prompt": "What is the product of 71 and 64?", "completion": "This is a multiplication problem over the numbers 71 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4260, and by the remaining 4 gives 284, which sum to 4544. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 64 times 71 is also 4544, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4544.", "meta": {"a": 71, "b": 64, "result": 4544, "style": "long"}}
{"id": "arith-867", "prompt": "What is 51 times 36?", "completion": "This is a multiplication problem over the numbers 51 and 36, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1530, and by the remaining 6 gives 306, which sum to 1836. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 36 times 51 is also 1836, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1836.", "meta": {"a": 51, "b": 36, "result": 1836, "style": "long"}}
{"id": "arith-868", "prompt": "What is 42 plus 78?", "completion": "This is an addition problem over the numbers 42 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 112, and the remaining 8 gives 120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 78 from 120 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 120.", "meta": {"a": 42, "b": 78, "result": 120, "style": "long"}}
{"id": "arith-869", "prompt": "What is 37 plus 9?", "completion": "This is an addition problem over the numbers 37 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 37, and the remaining 9 gives 46. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 9 from 46 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 46.", "meta": {"a": 37, "b": 9, "result": 46, "style": "long"}}
{"id": "arith-870", "prompt": "What is 76 times 31?", "completion": "This is a multiplication problem over the numbers 76 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2280, and by the remaining 1 gives 76, which sum to 2356. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 31 times 76 is also 2356, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2356.", "meta": {"a": 76, "b": 31, "result": 2356, "style": "long"}}
{"id": "arith-871", "prompt": "What is 36 minus 70?", "completion": "This is a subtraction problem over the numbers 36 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -34, and removing the last 0 leaves -34. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 70 back to -34 returns 36, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -34.", "meta": {"a": 36, "b": 70, "result": -34, "style": "long"}}
{"id": "arith-872", "prompt": "What is 75 minus 51?", "completion": "This is a subtraction problem over the numbers 75 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 25, and removing the last 1 leaves 24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 51 back to 24 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 24.", "meta": {"a": 75, "b": 51, "result": 24, "style": "long"}}
{"id": "arith-873", "prompt": "What do you get when you add 24 to 32?", "completion": "This is an addition problem over the numbers 24 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 54, and the remaining 2 gives 56. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 32 from 56 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 56.", "meta": {"a": 24, "b": 32, "result": 56, "style": "long"}}
{"id": "arith-874", "prompt": "What is 77 times 5?", "completion": "This is a multiplication problem over the numbers 77 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 5 gives 385, which sum to 385. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 5 times 77 is also 385, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 385.", "meta": {"a": 77, "b": 5, "result": 385, "style": "long"}}
{"id": "arith-875", "prompt": "What do you get when you add 74 to 26?", "completion": "This is an addition problem over the numbers 74 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 94, and the remaining 6 gives 100. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 26 from 100 returns 74, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 100.", "meta": {"a": 74, "b": 26, "result": 100, "style": "long"}}
{"id": "arith-876", "prompt": "Subtract 64 from 24.", "completion": "This is a subtraction problem over the numbers 24 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -36, and removing the last 4 leaves -40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 64 back to -40 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -40.", "meta": {"a": 24, "b": 64, "result": -40, "style": "long"}}
{"id": "arith-877", "prompt": "Add 9 and 31.", "completion": "This is an addition problem over the numbers 9 and 31, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 39, and the remaining 1 gives 40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 31 from 40 returns 9, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 40.", "meta": {"a": 9, "b": 31, "result": 40, "style": "long"}}
{"id": "arith-878", "prompt": "What is 69 plus 63?", "completion": "This is an addition problem over the numbers 69 and 63, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 129, and the remaining 3 gives 132. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 63 from 132 returns 69, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 132.", "meta": {"a": 69, "b": 63, "result": 132, "style": "long"}}
{"id": "arith-879", "prompt": "What is 80 times 27?", "completion": "This is a multiplication problem over the numbers 80 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1600, and by the remaining 7 gives 560, which sum to 2160. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 27 times 80 is also 2160, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2160.", "meta": {"a": 80, "b": 27, "result": 2160, "style": "long"}}
{"id": "arith-880", "prompt": "What is 93 times 24?", "completion": "This is a multiplication problem over the numbers 93 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1860, and by the remaining 4 gives 372, which sum to 2232. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 24 times 93 is also 2232, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2232.", "meta": {"a": 93, "b": 24, "result": 2232, "style": "long"}}
{"id": "arith-881", "prompt": "What is 4 plus 20?", "completion": "This is an addition problem over the numbers 4 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 24, and the remaining 0 gives 24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 20 from 24 returns 4, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 24.", "meta": {"a": 4, "b": 20, "result": 24, "style": "long"}}
{"id": "arith-882", "prompt": "Add 69 and 48.", "completion": "This is an addition problem over the numbers 69 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 109, and the remaining 8 gives 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 48 from 117 returns 69, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 69, "b": 48, "result": 117, "style": "long"}}
{"id": "arith-883", "prompt": "What is 92 times 86?", "completion": "This is a multiplication problem over the numbers 92 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 7360, and by the remaining 6 gives 552, which sum to 7912. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 86 times 92 is also 7912, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7912.", "meta": {"a": 92, "b": 86, "result": 7912, "style": "long"}}
{"id": "arith-884", "prompt": "Add 45 and 40.", "completion": "This is an addition problem over the numbers 45 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 85, and the remaining 0 gives 85. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 40 from 85 returns 45, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 85.", "meta": {"a": 45, "b": 40, "result": 85, "style": "long"}}
{"id": "arith-885", "prompt": "What do you get when you add 22 to 95?", "completion": "This is an addition problem over the numbers 22 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 112, and the remaining 5 gives 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 95 from 117 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 22, "b": 95, "result": 117, "style": "long"}}
{"id": "arith-886", "prompt": "What is the product of 85 and 42?", "completion": "This is a multiplication problem over the numbers 85 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3400, and by the remaining 2 gives 170, which sum to 3570. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 85 is also 3570, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3570.", "meta": {"a": 85, "b": 42, "result": 3570, "style": "long"}}
{"id": "arith-887", "prompt": "What is 30 times 87?", "completion": "This is a multiplication problem over the numbers 30 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 2400, and by the remaining 7 gives 210, which sum to 2610. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 87 times 30 is also 2610, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2610.", "meta": {"a": 30, "b": 87, "result": 2610, "style": "long"}}
{"id": "arith-888", "prompt": "Multiply 41 by 95.", "completion": "This is a multiplication problem over the numbers 41 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 3690, and by the remaining 5 gives 205, which sum to 3895. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 95 times 41 is also 3895, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3895.", "meta": {"a": 41, "b": 95, "result": 3895, "style": "long"}}
{"id": "arith-889", "prompt": "What do you get when you add 24 to 95?", "completion": "This is an addition problem over the numbers 24 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 114, and the remaining 5 gives 119. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 95 from 119 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 119.", "meta": {"a": 24, "b": 95, "result": 119, "style": "long"}}
{"id": "arith-890", "prompt": "Multiply 74 by 6.", "completion": "This is a multiplication problem over the numbers 74 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 6 gives 444, which sum to 444. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 6 times 74 is also 444, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 444.", "meta": {"a": 74, "b": 6, "result": 444, "style": "long"}}
{"id": "arith-891", "prompt": "What is 80 times 30?", "completion": "This is a multiplication problem over the numbers 80 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2400, and by the remaining 0 gives 0, which sum to 2400. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 30 times 80 is also 2400, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2400.", "meta": {"a": 80, "b": 30, "result": 2400, "style": "long"}}
{"id": "arith-892", "prompt": "What is the product of 20 and 44?", "completion": "This is a multiplication problem over the numbers 20 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 800, and by the remaining 4 gives 80, which sum to 880. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 44 times 20 is also 880, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 880.", "meta": {"a": 20, "b": 44, "result": 880, "style": "long"}}
{"id": "arith-893", "prompt": "What is 46 minus 42?", "completion": "This is a subtraction problem over the numbers 46 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 6, and removing the last 2 leaves 4. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 42 back to 4 returns 46, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4.", "meta": {"a": 46, "b": 42, "result": 4, "style": "long"}}
{"id": "arith-894", "prompt": "Add 92 and 87.", "completion": "This is an addition problem over the numbers 92 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 172, and the remaining 7 gives 179. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 87 from 179 returns 92, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 179.", "meta": {"a": 92, "b": 87, "result": 179, "style": "long"}}
{"id": "arith-895", "prompt": "What is the product of 3 and 35?", "completion": "This is a multiplication problem over the numbers 3 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 90, and by the remaining 5 gives 15, which sum to 105. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 35 times 3 is also 105, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 105.", "meta": {"a": 3, "b": 35, "result": 105, "style": "long"}}
{"id": "arith-896", "prompt": "What is 90 minus 10?", "completion": "This is a subtraction problem over the numbers 90 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 80, and removing the last 0 leaves 80. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 10 back to 80 returns 90, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 80.", "meta": {"a": 90, "b": 10, "result": 80, "style": "long"}}
{"id": "arith-897", "prompt": "Subtract 94 from 15.", "completion": "This is a subtraction problem over the numbers 15 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -75, and removing the last 4 leaves -79. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 94 back to -79 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -79.", "meta": {"a": 15, "b": 94, "result": -79, "style": "long"}}
{"id": "arith-898", "prompt": "What is 51 plus 58?", "completion": "This is an addition problem over the numbers 51 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 101, and the remaining 8 gives 109. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 58 from 109 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 109.", "meta": {"a": 51, "b": 58, "result": 109, "style": "long"}}
{"id": "arith-899", "prompt": "What do you get when you add 54 to 65?", "completion": "This is an addition problem over the numbers 54 and 65, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 114, and the remaining 5 gives 119. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 65 from 119 returns 54, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 119.", "meta": {"a": 54, "b": 65, "result": 119, "style": "long"}}
{"id": "arith-900", "prompt": "What is 71 times 50?", "completion": "This is a multiplication problem over the numbers 71 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3550, and by the remaining 0 gives 0, which sum to 3550. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 50 times 71 is also 3550, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3550.", "meta": {"a": 71, "b": 50, "result": 3550, "style": "long"}}
{"id": "arith-901", "prompt": "What is 22 minus 59?", "completion": "This is a subtraction problem over the numbers 22 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -28, and removing the last 9 leaves -37. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 59 back to -37 returns 22, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -37.", "meta": {"a": 22, "b": 59, "result": -37, "style": "long"}}
{"id": "arith-902", "prompt": "What is 39 plus 4?", "completion": "This is an addition problem over the numbers 39 and 4, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 39, and the remaining 4 gives 43. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 4 from 43 returns 39, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 43.", "meta": {"a": 39, "b": 4, "result": 43, "style": "long"}}
{"id": "arith-903", "prompt": "Subtract 11 from 15.", "completion": "This is a subtraction problem over the numbers 15 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 5, and removing the last 1 leaves 4. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 11 back to 4 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4.", "meta": {"a": 15, "b": 11, "result": 4, "style": "long"}}
{"id": "arith-904", "prompt": "What do you get when you add 50 to 22?", "completion": "This is an addition problem over the numbers 50 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 70, and the remaining 2 gives 72. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 22 from 72 returns 50, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 72.", "meta": {"a": 50, "b": 22, "result": 72, "style": "long"}}
{"id": "arith-905", "prompt": "Add 45 and 78.", "completion": "This is an addition problem over the numbers 45 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 115, and the remaining 8 gives 123. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 78 from 123 returns 45, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 123.", "meta": {"a": 45, "b": 78, "result": 123, "style": "long"}}
{"id": "arith-906", "prompt": "What is 57 plus 85?", "completion": "This is an addition problem over the numbers 57 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 137, and the remaining 5 gives 142. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 85 from 142 returns 57, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 142.", "meta": {"a": 57, "b": 85, "result": 142, "style": "long"}}
{"id": "arith-907", "prompt": "Multiply 22 by 8.", "completion": "This is a multiplication problem over the numbers 22 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 176, which sum to 176. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 22 is also 176, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 176.", "meta": {"a": 22, "b": 8, "result": 176, "style": "long"}}
{"id": "arith-908", "prompt": "What is 28 times 26?", "completion": "This is a multiplication problem over the numbers 28 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 560, and by the remaining 6 gives 168, which sum to 728. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 26 times 28 is also 728, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 728.", "meta": {"a": 28, "b": 26, "result": 728, "style": "long"}}
{"id": "arith-909", "prompt": "Subtract 38 from 86.", "completion": "This is a subtraction problem over the numbers 86 and 38, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 56, and removing the last 8 leaves 48. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 38 back to 48 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 48.", "meta": {"a": 86, "b": 38, "result": 48, "style": "long"}}
{"id": "arith-910", "prompt": "What is 14 minus 8?", "completion": "This is a subtraction problem over the numbers 14 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 14, and removing the last 8 leaves 6. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 8 back to 6 returns 14, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6.", "meta": {"a": 14, "b": 8, "result": 6, "style": "long"}}
{"id": "arith-911", "prompt": "What is the product of 21 and 8?", "completion": "This is a multiplication problem over the numbers 21 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 168, which sum to 168. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 21 is also 168, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 168.", "meta": {"a": 21, "b": 8, "result": 168, "style": "long"}}
{"id": "arith-912", "prompt": "What is 56 plus 13?", "completion": "This is an addition problem over the numbers 56 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 66, and the remaining 3 gives 69. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 13 from 69 returns 56, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 69.", "meta": {"a": 56, "b": 13, "result": 69, "style": "long"}}
{"id": "arith-913", "prompt": "What is the product of 27 and 14?", "completion": "This is a multiplication problem over the numbers 27 and 14, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 270, and by the remaining 4 gives 108, which sum to 378. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 14 times 27 is also 378, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 378.", "meta": {"a": 27, "b": 14, "result": 378, "style": "long"}}
{"id": "arith-914", "prompt": "What is 23 minus 83?", "completion": "This is a subtraction problem over the numbers 23 and 83, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -57, and removing the last 3 leaves -60. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 83 back to -60 returns 23, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -60.", "meta": {"a": 23, "b": 83, "result": -60, "style": "long"}}
{"id": "arith-915", "prompt": "Add 62 and 16.", "completion": "This is an addition problem over the numbers 62 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 72, and the remaining 6 gives 78. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 16 from 78 returns 62, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 78.", "meta": {"a": 62, "b": 16, "result": 78, "style": "long"}}
{"id": "arith-916", "prompt": "Multiply 62 by 64.", "completion": "This is a multiplication problem over the numbers 62 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3720, and by the remaining 4 gives 248, which sum to 3968. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 64 times 62 is also 3968, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3968.", "meta": {"a": 62, "b": 64, "result": 3968, "style": "long"}}
{"id": "arith-917", "prompt": "Add 84 and 71.", "completion": "This is an addition problem over the numbers 84 and 71, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 154, and the remaining 1 gives 155. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 71 from 155 returns 84, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 155.", "meta": {"a": 84, "b": 71, "result": 155, "style": "long"}}
{"id": "arith-918", "prompt": "What do you get when you add 49 to 50?", "completion": "This is an addition problem over the numbers 49 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 99, and the remaining 0 gives 99. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 50 from 99 returns 49, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 99.", "meta": {"a": 49, "b": 50, "result": 99, "style": "long"}}
{"id": "arith-919", "prompt": "What do you get when you add 59 to 7?", "completion": "This is an addition problem over the numbers 59 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 59, and the remaining 7 gives 66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 7 from 66 returns 59, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 66.", "meta": {"a": 59, "b": 7, "result": 66, "style": "long"}}
{"id": "arith-920", "prompt": "What is the product of 61 and 35?", "completion": "This is a multiplication problem over the numbers 61 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1830, and by the remaining 5 gives 305, which sum to 2135. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 35 times 61 is also 2135, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2135.", "meta": {"a": 61, "b": 35, "result": 2135, "style": "long"}}
{"id": "arith-921", "prompt": "Subtract 9 from 74.", "completion": "This is a subtraction problem over the numbers 74 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 74, and removing the last 9 leaves 65. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 9 back to 65 returns 74, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 65.", "meta": {"a": 74, "b": 9, "result": 65, "style": "long"}}
{"id": "arith-922", "prompt": "Add 12 and 87.", "completion": "This is an addition problem over the numbers 12 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 92, and the remaining 7 gives 99. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 87 from 99 returns 12, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 99.", "meta": {"a": 12, "b": 87, "result": 99, "style": "long"}}
{"id": "arith-923", "prompt": "Multiply 98 by 77.", "completion": "This is a multiplication problem over the numbers 98 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 6860, and by the remaining 7 gives 686, which sum to 7546. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 77 times 98 is also 7546, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7546.", "meta": {"a": 98, "b": 77, "result": 7546, "style": "long"}}
{"id": "arith-924", "prompt": "What is 51 plus 68?", "completion": "This is an addition problem over the numbers 51 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 111, and the remaining 8 gives 119. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 68 from 119 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 119.", "meta": {"a": 51, "b": 68, "result": 119, "style": "long"}}
{"id": "arith-925", "prompt": "What is the product of 75 and 32?", "completion": "This is a multiplication problem over the numbers 75 and 32, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2250, and by the remaining 2 gives 150, which sum to 2400. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 32 times 75 is also 2400, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2400.", "meta": {"a": 75, "b": 32, "result": 2400, "style": "long"}}
{"id": "arith-926", "prompt": "Subtract 52 from 12.", "completion": "This is a subtraction problem over the numbers 12 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -38, and removing the last 2 leaves -40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 52 back to -40 returns 12, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -40.", "meta": {"a": 12, "b": 52, "result": -40, "style": "long"}}
{"id": "arith-927", "prompt": "What do you get when you add 17 to 98?", "completion": "This is an addition problem over the numbers 17 and 98, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 107, and the remaining 8 gives 115. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 98 from 115 returns 17, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 115.", "meta": {"a": 17, "b": 98, "result": 115, "style": "long"}}
{"id": "arith-928", "prompt": "What do you get when you add 23 to 29?", "completion": "This is an addition problem over the numbers 23 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 43, and the remaining 9 gives 52. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 29 from 52 returns 23, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 52.", "meta": {"a": 23, "b": 29, "result": 52, "style": "long"}}
{"id": "arith-929", "prompt": "What do you get when you add 7 to 56?", "completion": "This is an addition problem over the numbers 7 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 57, and the remaining 6 gives 63. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 56 from 63 returns 7, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 63.", "meta": {"a": 7, "b": 56, "result": 63, "style": "long"}}
{"id": "arith-930", "prompt": "Multiply 27 by 82.", "completion": "This is a multiplication problem over the numbers 27 and 82, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 2160, and by the remaining 2 gives 54, which sum to 2214. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 82 times 27 is also 2214, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2214.", "meta": {"a": 27, "b": 82, "result": 2214, "style": "long"}}
{"id": "arith-931", "prompt": "Subtract 95 from 42.", "completion": "This is a subtraction problem over the numbers 42 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -48, and removing the last 5 leaves -53. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 95 back to -53 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -53.", "meta": {"a": 42, "b": 95, "result": -53, "style": "long"}}
{"id": "arith-932", "prompt": "Add 51 and 73.", "completion": "This is an addition problem over the numbers 51 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 121, and the remaining 3 gives 124. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 73 from 124 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 124.", "meta": {"a": 51, "b": 73, "result": 124, "style": "long"}}
{"id": "arith-933", "prompt": "What is 37 times 68?", "completion": "This is a multiplication problem over the numbers 37 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 2220, and by the remaining 8 gives 296, which sum to 2516. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 68 times 37 is also 2516, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2516.", "meta": {"a": 37, "b": 68, "result": 2516, "style": "long"}}
{"id": "arith-934", "prompt": "What is 91 plus 81?", "completion": "This is an addition problem over the numbers 91 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 171, and the remaining 1 gives 172. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 81 from 172 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 172.", "meta": {"a": 91, "b": 81, "result": 172, "style": "long"}}
{"id": "arith-935", "prompt": "Add 55 and 21.", "completion": "This is an addition problem over the numbers 55 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 75, and the remaining 1 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 21 from 76 returns 55, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 55, "b": 21, "result": 76, "style": "long"}}
{"id": "arith-936", "prompt": "Add 15 and 74.", "completion": "This is an addition problem over the numbers 15 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 85, and the remaining 4 gives 89. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 74 from 89 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 89.", "meta": {"a": 15, "b": 74, "result": 89, "style": "long"}}
{"id": "arith-937", "prompt": "Subtract 46 from 70.", "completion": "This is a subtraction problem over the numbers 70 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 30, and removing the last 6 leaves 24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 46 back to 24 returns 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 24.", "meta": {"a": 70, "b": 46, "result": 24, "style": "long"}}
{"id": "arith-938", "prompt": "Subtract 85 from 51.", "completion": "This is a subtraction problem over the numbers 51 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -29, and removing the last 5 leaves -34. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 85 back to -34 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -34.", "meta": {"a": 51, "b": 85, "result": -34, "style": "long"}}
{"id": "arith-939", "prompt": "What is the product of 6 and 24?", "completion": "This is a multiplication problem over the numbers 6 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 120, and by the remaining 4 gives 24, which sum to 144. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 24 times 6 is also 144, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 144.", "meta": {"a": 6, "b": 24, "result": 144, "style": "long"}}
{"id": "arith-940", "prompt": "Multiply 20 by 81.", "completion": "This is a multiplication problem over the numbers 20 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1600, and by the remaining 1 gives 20, which sum to 1620. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 81 times 20 is also 1620, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1620.", "meta": {"a": 20, "b": 81, "result": 1620, "style": "long"}}
{"id": "arith-941", "prompt": "What is 52 plus 44?", "completion": "This is an addition problem over the numbers 52 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 92, and the remaining 4 gives 96. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 44 from 96 returns 52, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 96.", "meta": {"a": 52, "b": 44, "result": 96, "style": "long"}}
{"id": "arith-942", "prompt": "What is 97 plus 62?", "completion": "This is an addition problem over the numbers 97 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 157, and the remaining 2 gives 159. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 62 from 159 returns 97, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 159.", "meta": {"a": 97, "b": 62, "result": 159, "style": "long"}}
{"id": "arith-943", "prompt": "What is 4 times 45?", "completion": "This is a multiplication problem over the numbers 4 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 160, and by the remaining 5 gives 20, which sum to 180. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 45 times 4 is also 180, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 180.", "meta": {"a": 4, "b": 45, "result": 180, "style": "long"}}
{"id": "arith-944", "prompt": "Subtract 64 from 37.", "completion": "This is a subtraction problem over the numbers 37 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -23, and removing the last 4 leaves -27. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 64 back to -27 returns 37, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -27.", "meta": {"a": 37, "b": 64, "result": -27, "style": "long"}}
{"id": "arith-945", "prompt": "What is 19 minus 40?", "completion": "This is a subtraction problem over the numbers 19 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves -21, and removing the last 0 leaves -21. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 40 back to -21 returns 19, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -21.", "meta": {"a": 19, "b": 40, "result": -21, "style": "long"}}
{"id": "arith-946", "prompt": "What is 36 times 95?", "completion": "This is a multiplication problem over the numbers 36 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 3240, and by the remaining 5 gives 180, which sum to 3420. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 95 times 36 is also 3420, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3420.", "meta": {"a": 36, "b": 95, "result": 3420, "style": "long"}}
{"id": "arith-947", "prompt": "Add 26 and 58.", "completion": "This is an addition problem over the numbers 26 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 76, and the remaining 8 gives 84. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 58 from 84 returns 26, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 84.", "meta": {"a": 26, "b": 58, "result": 84, "style": "long"}}
{"id": "arith-948", "prompt": "Multiply 96 by 64.", "completion": "This is a multiplication problem over the numbers 96 and 64, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 5760, and by the remaining 4 gives 384, which sum to 6144. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 64 times 96 is also 6144, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6144.", "meta": {"a": 96, "b": 64, "result": 6144, "style": "long"}}
{"id": "arith-949", "prompt": "What is 67 plus 22?", "completion": "This is an addition problem over the numbers 67 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 87, and the remaining 2 gives 89. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 22 from 89 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 89.", "meta": {"a": 67, "b": 22, "result": 89, "style": "long"}}
{"id": "arith-950", "prompt": "Subtract 66 from 92.", "completion": "This is a subtraction problem over the numbers 92 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves 32, and removing the last 6 leaves 26. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 66 back to 26 returns 92, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 26.", "meta": {"a": 92, "b": 66, "result": 26, "style": "long"}}
{"id": "arith-951", "prompt": "What do you get when you add 69 to 74?", "completion": "This is an addition problem over the numbers 69 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 139, and the remaining 4 gives 143. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 74 from 143 returns 69, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 143.", "meta": {"a": 69, "b": 74, "result": 143, "style": "long"}}
{"id": "arith-952", "prompt": "What do you get when you add 26 to 27?", "completion": "This is an addition problem over the numbers 26 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 46, and the remaining 7 gives 53. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 27 from 53 returns 26, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 53.", "meta": {"a": 26, "b": 27, "result": 53, "style": "long"}}
{"id": "arith-953", "prompt": "What is 6 minus 60?", "completion": "This is a subtraction problem over the numbers 6 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -54, and removing the last 0 leaves -54. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 60 back to -54 returns 6, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -54.", "meta": {"a": 6, "b": 60, "result": -54, "style": "long"}}
{"id": "arith-954", "prompt": "What is 92 times 27?", "completion": "This is a multiplication problem over the numbers 92 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1840, and by the remaining 7 gives 644, which sum to 2484. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 27 times 92 is also 2484, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2484.", "meta": {"a": 92, "b": 27, "result": 2484, "style": "long"}}
{"id": "arith-955", "prompt": "What is 61 times 66?", "completion": "This is a multiplication problem over the numbers 61 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3660, and by the remaining 6 gives 366, which sum to 4026. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 66 times 61 is also 4026, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4026.", "meta": {"a": 61, "b": 66, "result": 4026, "style": "long"}}
{"id": "arith-956", "prompt": "Add 89 and 5.", "completion": "This is an addition problem over the numbers 89 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 89, and the remaining 5 gives 94. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 5 from 94 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 94.", "meta": {"a": 89, "b": 5, "result": 94, "style": "long"}}
{"id": "arith-957", "prompt": "What is 64 times 78?", "completion": "This is a multiplication problem over the numbers 64 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 4480, and by the remaining 8 gives 512, which sum to 4992. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 78 times 64 is also 4992, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4992.", "meta": {"a": 64, "b": 78, "result": 4992, "style": "long"}}
{"id": "arith-958", "prompt": "What do you get when you add 62 to 77?", "completion": "This is an addition problem over the numbers 62 and 77, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 132, and the remaining 7 gives 139. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 77 from 139 returns 62, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 139.", "meta": {"a": 62, "b": 77, "result": 139, "style": "long"}}
{"id": "arith-959", "prompt": "What is 22 times 35?", "completion": "This is a multiplication problem over the numbers 22 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 660, and by the remaining 5 gives 110, which sum to 770. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 35 times 22 is also 770, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 770.", "meta": {"a": 22, "b": 35, "result": 770, "style": "long"}}
{"id": "arith-960", "prompt": "Subtract 51 from 5.", "completion": "This is a subtraction problem over the numbers 5 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -45, and removing the last 1 leaves -46. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 51 back to -46 returns 5, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -46.", "meta": {"a": 5, "b": 51, "result": -46, "style": "long"}}
{"id": "arith-961", "prompt": "What do you get when you add 75 to 29?", "completion": "This is an addition problem over the numbers 75 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 95, and the remaining 9 gives 104. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 29 from 104 returns 75, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 104.", "meta": {"a": 75, "b": 29, "result": 104, "style": "long"}}
{"id": "arith-962", "prompt": "What is 88 minus 28?", "completion": "This is a subtraction problem over the numbers 88 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 68, and removing the last 8 leaves 60. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 28 back to 60 returns 88, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 60.", "meta": {"a": 88, "b": 28, "result": 60, "style": "long"}}
{"id": "arith-963", "prompt": "Multiply 67 by 4.", "completion": "This is a multiplication problem over the numbers 67 and 4, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 4 gives 268, which sum to 268. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 4 times 67 is also 268, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 268.", "meta": {"a": 67, "b": 4, "result": 268, "style": "long"}}
{"id": "arith-964", "prompt": "What is the product of 18 and 84?", "completion": "This is a multiplication problem over the numbers 18 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1440, and by the remaining 4 gives 72, which sum to 1512. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 84 times 18 is also 1512, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1512.", "meta": {"a": 18, "b": 84, "result": 1512, "style": "long"}}
{"id": "arith-965", "prompt": "What is 30 plus 34?", "completion": "This is an addition problem over the numbers 30 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 60, and the remaining 4 gives 64. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 34 from 64 returns 30, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 64.", "meta": {"a": 30, "b": 34, "result": 64, "style": "long"}}
{"id": "arith-966", "prompt": "Subtract 50 from 56.", "completion": "This is a subtraction problem over the numbers 56 and 50, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves 6, and removing the last 0 leaves 6. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 50 back to 6 returns 56, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6.", "meta": {"a": 56, "b": 50, "result": 6, "style": "long"}}
{"id": "arith-967", "prompt": "What is the product of 34 and 29?", "completion": "This is a multiplication problem over the numbers 34 and 29, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 680, and by the remaining 9 gives 306, which sum to 986. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 29 times 34 is also 986, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 986.", "meta": {"a": 34, "b": 29, "result": 986, "style": "long"}}
{"id": "arith-968", "prompt": "Subtract 68 from 88.", "completion": "This is a subtraction problem over the numbers 88 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves 28, and removing the last 8 leaves 20. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 68 back to 20 returns 88, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 20.", "meta": {"a": 88, "b": 68, "result": 20, "style": "long"}}
{"id": "arith-969", "prompt": "Add 2 and 67.", "completion": "This is an addition problem over the numbers 2 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 62, and the remaining 7 gives 69. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 67 from 69 returns 2, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 69.", "meta": {"a": 2, "b": 67, "result": 69, "style": "long"}}
{"id": "arith-970", "prompt": "Subtract 89 from 40.", "completion": "This is a subtraction problem over the numbers 40 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -40, and removing the last 9 leaves -49. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 89 back to -49 returns 40, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -49.", "meta": {"a": 40, "b": 89, "result": -49, "style": "long"}}
{"id": "arith-971", "prompt": "What is the product of 10 and 45?", "completion": "This is a multiplication problem over the numbers 10 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 400, and by the remaining 5 gives 50, which sum to 450. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 45 times 10 is also 450, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 450.", "meta": {"a": 10, "b": 45, "result": 450, "style": "long"}}
{"id": "arith-972", "prompt": "What is 37 times 35?", "completion": "This is a multiplication problem over the numbers 37 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1110, and by the remaining 5 gives 185, which sum to 1295. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 35 times 37 is also 1295, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1295.", "meta": {"a": 37, "b": 35, "result": 1295, "style": "long"}}
{"id": "arith-973", "prompt": "What is 21 minus 68?", "completion": "This is a subtraction problem over the numbers 21 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -39, and removing the last 8 leaves -47. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 68 back to -47 returns 21, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -47.", "meta": {"a": 21, "b": 68, "result": -47, "style": "long"}}
{"id": "arith-974", "prompt": "What is 78 plus 53?", "completion": "This is an addition problem over the numbers 78 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 128, and the remaining 3 gives 131. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 53 from 131 returns 78, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 131.", "meta": {"a": 78, "b": 53, "result": 131, "style": "long"}}
{"id": "arith-975", "prompt": "What do you get when you add 94 to 5?", "completion": "This is an addition problem over the numbers 94 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 94, and the remaining 5 gives 99. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 5 from 99 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 99.", "meta": {"a": 94, "b": 5, "result": 99, "style": "long"}}
{"id": "arith-976", "prompt": "Subtract 55 from 35.", "completion": "This is a subtraction problem over the numbers 35 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -15, and removing the last 5 leaves -20. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 55 back to -20 returns 35, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -20.", "meta": {"a": 35, "b": 55, "result": -20, "style": "long"}}
{"id": "arith-977", "prompt": "Multiply 96 by 6.", "completion": "This is a multiplication problem over the numbers 96 and 6, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 6 gives 576, which sum to 576. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 6 times 96 is also 576, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 576.", "meta": {"a": 96, "b": 6, "result": 576, "style": "long"}}
{"id": "arith-978", "prompt": "What is 94 times 93?", "completion": "This is a multiplication problem over the numbers 94 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 8460, and by the remaining 3 gives 282, which sum to 8742. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 93 times 94 is also 8742, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8742.", "meta": {"a": 94, "b": 93, "result": 8742, "style": "long"}}
{"id": "arith-979", "prompt": "What is the product of 87 and 47?", "completion": "This is a multiplication problem over the numbers 87 and 47, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 3480, and by the remaining 7 gives 609, which sum to 4089. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 47 times 87 is also 4089, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4089.", "meta": {"a": 87, "b": 47, "result": 4089, "style": "long"}}
{"id": "arith-980", "prompt": "What do you get when you add 86 to 73?", "completion": "This is an addition problem over the numbers 86 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 156, and the remaining 3 gives 159. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 73 from 159 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 159.", "meta": {"a": 86, "b": 73, "result": 159, "style": "long"}}
{"id": "arith-981", "prompt": "Subtract 62 from 14.", "completion": "This is a subtraction problem over the numbers 14 and 62, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 60 leaves -46, and removing the last 2 leaves -48. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 62 back to -48 returns 14, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -48.", "meta": {"a": 14, "b": 62, "result": -48, "style": "long"}}
{"id": "arith-982", "prompt": "Subtract 73 from 94.", "completion": "This is a subtraction problem over the numbers 94 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 24, and removing the last 3 leaves 21. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 73 back to 21 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 21.", "meta": {"a": 94, "b": 73, "result": 21, "style": "long"}}
{"id": "arith-983", "prompt": "What is 85 times 13?", "completion": "This is a multiplication problem over the numbers 85 and 13, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 850, and by the remaining 3 gives 255, which sum to 1105. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 13 times 85 is also 1105, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1105.", "meta": {"a": 85, "b": 13, "result": 1105, "style": "long"}}
{"id": "arith-984", "prompt": "What is 30 times 97?", "completion": "This is a multiplication problem over the numbers 30 and 97, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 2700, and by the remaining 7 gives 210, which sum to 2910. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 97 times 30 is also 2910, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2910.", "meta": {"a": 30, "b": 97, "result": 2910, "style": "long"}}
{"id": "arith-985", "prompt": "Multiply 44 by 49.", "completion": "This is a multiplication problem over the numbers 44 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1760, and by the remaining 9 gives 396, which sum to 2156. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 49 times 44 is also 2156, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2156.", "meta": {"a": 44, "b": 49, "result": 2156, "style": "long"}}
{"id": "arith-986", "prompt": "Subtract 17 from 61.", "completion": "This is a subtraction problem over the numbers 61 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 51, and removing the last 7 leaves 44. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 17 back to 44 returns 61, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 44.", "meta": {"a": 61, "b": 17, "result": 44, "style": "long"}}
{"id": "arith-987", "prompt": "What is 83 plus 76?", "completion": "This is an addition problem over the numbers 83 and 76, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 153, and the remaining 6 gives 159. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 76 from 159 returns 83, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 159.", "meta": {"a": 83, "b": 76, "result": 159, "style": "long"}}
{"id": "arith-988", "prompt": "What is the product of 26 and 66?", "completion": "This is a multiplication problem over the numbers 26 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 1560, and by the remaining 6 gives 156, which sum to 1716. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 66 times 26 is also 1716, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1716.", "meta": {"a": 26, "b": 66, "result": 1716, "style": "long"}}
{"id": "arith-989", "prompt": "Multiply 69 by 40.", "completion": "This is a multiplication problem over the numbers 69 and 40, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 2760, and by the remaining 0 gives 0, which sum to 2760. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 40 times 69 is also 2760, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2760.", "meta": {"a": 69, "b": 40, "result": 2760, "style": "long"}}
{"id": "arith-990", "prompt": "What is 21 plus 19?", "completion": "This is an addition problem over the numbers 21 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 31, and the remaining 9 gives 40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 19 from 40 returns 21, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 40.", "meta": {"a": 21, "b": 19, "result": 40, "style": "long"}}
{"id": "arith-991", "prompt": "What is 54 times 74?", "completion": "This is a multiplication problem over the numbers 54 and 74, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3780, and by the remaining 4 gives 216, which sum to 3996. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 74 times 54 is also 3996, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3996.", "meta": {"a": 54, "b": 74, "result": 3996, "style": "long"}}
{"id": "arith-992", "prompt": "What do you get when you add 42 to 93?", "completion": "This is an addition problem over the numbers 42 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 132, and the remaining 3 gives 135. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 93 from 135 returns 42, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 135.", "meta": {"a": 42, "b": 93, "result": 135, "style": "long"}}
{"id": "arith-993", "prompt": "Add 64 and 44.", "completion": "This is an addition problem over the numbers 64 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 104, and the remaining 4 gives 108. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 44 from 108 returns 64, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 108.", "meta": {"a": 64, "b": 44, "result": 108, "style": "long"}}
{"id": "arith-994", "prompt": "What is 83 times 9?", "completion": "This is a multiplication problem over the numbers 83 and 9, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 9 gives 747, which sum to 747. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 9 times 83 is also 747, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 747.", "meta": {"a": 83, "b": 9, "result": 747, "style": "long"}}
{"id": "arith-995", "prompt": "What is the product of 37 and 28?", "completion": "This is a multiplication problem over the numbers 37 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 740, and by the remaining 8 gives 296, which sum to 1036. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 28 times 37 is also 1036, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1036.", "meta": {"a": 37, "b": 28, "result": 1036, "style": "long"}}
{"id": "arith-996", "prompt": "What do you get when you add 64 to 99?", "completion": "This is an addition problem over the numbers 64 and 99, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 154, and the remaining 9 gives 163. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 99 from 163 returns 64, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 163.", "meta": {"a": 64, "b": 99, "result": 163, "style": "long"}}
{"id": "arith-997", "prompt": "What do you get when you add 80 to 57?", "completion": "This is an addition problem over the numbers 80 and 57, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 130, and the remaining 7 gives 137. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 57 from 137 returns 80, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 137.", "meta": {"a": 80, "b": 57, "result": 137, "style": "long"}}
{"id": "arith-998", "prompt": "Multiply 56 by 63.", "completion": "This is a multiplication problem over the numbers 56 and 63, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 3360, and by the remaining 3 gives 168, which sum to 3528. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 63 times 56 is also 3528, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3528.", "meta": {"a": 56, "b": 63, "result": 3528, "style": "long"}}
{"id": "arith-999", "prompt": "What is 6 plus 70?", "completion": "This is an addition problem over the numbers 6 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 76, and the remaining 0 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 70 from 76 returns 6, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 6, "b": 70, "result": 76, "style": "long"}}
{"id": "arith-1000", "prompt": "What is 3 times 43?", "completion": "This is a multiplication problem over the numbers 3 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 120, and by the remaining 3 gives 9, which sum to 129. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 43 times 3 is also 129, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 129.", "meta": {"a": 3, "b": 43, "result": 129, "style": "long"}}
{"id": "arith-1001", "prompt": "What is 88 plus 2?", "completion": "This is an addition problem over the numbers 88 and 2, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 88, and the remaining 2 gives 90. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 2 from 90 returns 88, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 90.", "meta": {"a": 88, "b": 2, "result": 90, "style": "long"}}
{"id": "arith-1002", "prompt": "What is 90 minus 46?", "completion": "This is a subtraction problem over the numbers 90 and 46, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 50, and removing the last 6 leaves 44. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 46 back to 44 returns 90, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 44.", "meta": {"a": 90, "b": 46, "result": 44, "style": "long"}}
{"id": "arith-1003", "prompt": "What do you get when you add 15 to 51?", "completion": "This is an addition problem over the numbers 15 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 65, and the remaining 1 gives 66. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 51 from 66 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 66.", "meta": {"a": 15, "b": 51, "result": 66, "style": "long"}}
{"id": "arith-1004", "prompt": "What do you get when you add 10 to 7?", "completion": "This is an addition problem over the numbers 10 and 7, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 10, and the remaining 7 gives 17. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 7 from 17 returns 10, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 17.", "meta": {"a": 10, "b": 7, "result": 17, "style": "long"}}
{"id": "arith-1005", "prompt": "Subtract 95 from 60.", "completion": "This is a subtraction problem over the numbers 60 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -30, and removing the last 5 leaves -35. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 95 back to -35 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -35.", "meta": {"a": 60, "b": 95, "result": -35, "style": "long"}}
{"id": "arith-1006", "prompt": "Multiply 89 by 19.", "completion": "This is a multiplication problem over the numbers 89 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 890, and by the remaining 9 gives 801, which sum to 1691. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 19 times 89 is also 1691, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1691.", "meta": {"a": 89, "b": 19, "result": 1691, "style": "long"}}
{"id": "arith-1007", "prompt": "What is the product of 47 and 98?", "completion": "This is a multiplication problem over the numbers 47 and 98, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 4230, and by the remaining 8 gives 376, which sum to 4606. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 98 times 47 is also 4606, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4606.", "meta": {"a": 47, "b": 98, "result": 4606, "style": "long"}}
{"id": "arith-1008", "prompt": "What do you get when you add 53 to 4?", "completion": "This is an addition problem over the numbers 53 and 4, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 0 first gives 53, and the remaining 4 gives 57. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 4 from 57 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 57.", "meta": {"a": 53, "b": 4, "result": 57, "style": "long"}}
{"id": "arith-1009", "prompt": "What is 95 minus 18?", "completion": "This is a subtraction problem over the numbers 95 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 10 leaves 85, and removing the last 8 leaves 77. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 18 back to 77 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 77.", "meta": {"a": 95, "b": 18, "result": 77, "style": "long"}}
{"id": "arith-1010", "prompt": "What is 77 plus 66?", "completion": "This is an addition problem over the numbers 77 and 66, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 137, and the remaining 6 gives 143. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 66 from 143 returns 77, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 143.", "meta": {"a": 77, "b": 66, "result": 143, "style": "long"}}
{"id": "arith-1011", "prompt": "Add 48 and 93.", "completion": "This is an addition problem over the numbers 48 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 138, and the remaining 3 gives 141. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 93 from 141 returns 48, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 141.", "meta": {"a": 48, "b": 93, "result": 141, "style": "long"}}
{"id": "arith-1012", "prompt": "Multiply 83 by 34.", "completion": "This is a multiplication problem over the numbers 83 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 2490, and by the remaining 4 gives 332, which sum to 2822. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 34 times 83 is also 2822, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2822.", "meta": {"a": 83, "b": 34, "result": 2822, "style": "long"}}
{"id": "arith-1013", "prompt": "What is 86 plus 15?", "completion": "This is an addition problem over the numbers 86 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 96, and the remaining 5 gives 101. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 15 from 101 returns 86, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 101.", "meta": {"a": 86, "b": 15, "result": 101, "style": "long"}}
{"id": "arith-1014", "prompt": "What is 90 plus 16?", "completion": "This is an addition problem over the numbers 90 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 100, and the remaining 6 gives 106. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 16 from 106 returns 90, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 106.", "meta": {"a": 90, "b": 16, "result": 106, "style": "long"}}
{"id": "arith-1015", "prompt": "What is the product of 50 and 17?", "completion": "This is a multiplication problem over the numbers 50 and 17, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 500, and by the remaining 7 gives 350, which sum to 850. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 17 times 50 is also 850, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 850.", "meta": {"a": 50, "b": 17, "result": 850, "style": "long"}}
{"id": "arith-1016", "prompt": "What is the product of 91 and 21?", "completion": "This is a multiplication problem over the numbers 91 and 21, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1820, and by the remaining 1 gives 91, which sum to 1911. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 21 times 91 is also 1911, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1911.", "meta": {"a": 91, "b": 21, "result": 1911, "style": "long"}}
{"id": "arith-1017", "prompt": "What is 40 plus 55?", "completion": "This is an addition problem over the numbers 40 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 90, and the remaining 5 gives 95. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 55 from 95 returns 40, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 95.", "meta": {"a": 40, "b": 55, "result": 95, "style": "long"}}
{"id": "arith-1018", "prompt": "Subtract 79 from 81.", "completion": "This is a subtraction problem over the numbers 81 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 11, and removing the last 9 leaves 2. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 79 back to 2 returns 81, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2.", "meta": {"a": 81, "b": 79, "result": 2, "style": "long"}}
{"id": "arith-1019", "prompt": "Multiply 15 by 67.", "completion": "This is a multiplication problem over the numbers 15 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 900, and by the remaining 7 gives 105, which sum to 1005. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 67 times 15 is also 1005, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1005.", "meta": {"a": 15, "b": 67, "result": 1005, "style": "long"}}
{"id": "arith-1020", "prompt": "What is the product of 27 and 79?", "completion": "This is a multiplication problem over the numbers 27 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 1890, and by the remaining 9 gives 243, which sum to 2133. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 79 times 27 is also 2133, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2133.", "meta": {"a": 27, "b": 79, "result": 2133, "style": "long"}}
{"id": "arith-1021", "prompt": "Subtract 27 from 68.", "completion": "This is a subtraction problem over the numbers 68 and 27, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 48, and removing the last 7 leaves 41. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 27 back to 41 returns 68, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 41.", "meta": {"a": 68, "b": 27, "result": 41, "style": "long"}}
{"id": "arith-1022", "prompt": "Multiply 39 by 22.", "completion": "This is a multiplication problem over the numbers 39 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 780, and by the remaining 2 gives 78, which sum to 858. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 22 times 39 is also 858, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 858.", "meta": {"a": 39, "b": 22, "result": 858, "style": "long"}}
{"id": "arith-1023", "prompt": "What is the product of 28 and 90?", "completion": "This is a multiplication problem over the numbers 28 and 90, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 2520, and by the remaining 0 gives 0, which sum to 2520. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 90 times 28 is also 2520, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2520.", "meta": {"a": 28, "b": 90, "result": 2520, "style": "long"}}
{"id": "arith-1024", "prompt": "What is 32 times 2?", "completion": "This is a multiplication problem over the numbers 32 and 2, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 2 gives 64, which sum to 64. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 2 times 32 is also 64, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 64.", "meta": {"a": 32, "b": 2, "result": 64, "style": "long"}}
{"id": "arith-1025", "prompt": "Add 16 and 75.", "completion": "This is an addition problem over the numbers 16 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 86, and the remaining 5 gives 91. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 75 from 91 returns 16, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 91.", "meta": {"a": 16, "b": 75, "result": 91, "style": "long"}}
{"id": "arith-1026", "prompt": "What do you get when you add 13 to 67?", "completion": "This is an addition problem over the numbers 13 and 67, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 73, and the remaining 7 gives 80. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 67 from 80 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 80.", "meta": {"a": 13, "b": 67, "result": 80, "style": "long"}}
{"id": "arith-1027", "prompt": "Add 34 and 84.", "completion": "This is an addition problem over the numbers 34 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 114, and the remaining 4 gives 118. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 84 from 118 returns 34, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 118.", "meta": {"a": 34, "b": 84, "result": 118, "style": "long"}}
{"id": "arith-1028", "prompt": "What is the product of 39 and 35?", "completion": "This is a multiplication problem over the numbers 39 and 35, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 1170, and by the remaining 5 gives 195, which sum to 1365. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 35 times 39 is also 1365, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1365.", "meta": {"a": 39, "b": 35, "result": 1365, "style": "long"}}
{"id": "arith-1029", "prompt": "What is 14 plus 24?", "completion": "This is an addition problem over the numbers 14 and 24, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 34, and the remaining 4 gives 38. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 24 from 38 returns 14, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 38.", "meta": {"a": 14, "b": 24, "result": 38, "style": "long"}}
{"id": "arith-1030", "prompt": "Subtract 88 from 48.", "completion": "This is a subtraction problem over the numbers 48 and 88, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -32, and removing the last 8 leaves -40. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 88 back to -40 returns 48, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -40.", "meta": {"a": 48, "b": 88, "result": -40, "style": "long"}}
{"id": "arith-1031", "prompt": "Multiply 96 by 16.", "completion": "This is a multiplication problem over the numbers 96 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 960, and by the remaining 6 gives 576, which sum to 1536. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 16 times 96 is also 1536, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1536.", "meta": {"a": 96, "b": 16, "result": 1536, "style": "long"}}
{"id": "arith-1032", "prompt": "What is 3 plus 19?", "completion": "This is an addition problem over the numbers 3 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 13, and the remaining 9 gives 22. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 19 from 22 returns 3, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 22.", "meta": {"a": 3, "b": 19, "result": 22, "style": "long"}}
{"id": "arith-1033", "prompt": "What is 47 times 58?", "completion": "This is a multiplication problem over the numbers 47 and 58, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 2350, and by the remaining 8 gives 376, which sum to 2726. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 58 times 47 is also 2726, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2726.", "meta": {"a": 47, "b": 58, "result": 2726, "style": "long"}}
{"id": "arith-1034", "prompt": "Add 49 and 45.", "completion": "This is an addition problem over the numbers 49 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 89, and the remaining 5 gives 94. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 45 from 94 returns 49, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 94.", "meta": {"a": 49, "b": 45, "result": 94, "style": "long"}}
{"id": "arith-1035", "prompt": "Add 53 and 53.", "completion": "This is an addition problem over the numbers 53 and 53, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 103, and the remaining 3 gives 106. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 53 from 106 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 106.", "meta": {"a": 53, "b": 53, "result": 106, "style": "long"}}
{"id": "arith-1036", "prompt": "Subtract 90 from 51.", "completion": "This is a subtraction problem over the numbers 51 and 90, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -39, and removing the last 0 leaves -39. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 90 back to -39 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -39.", "meta": {"a": 51, "b": 90, "result": -39, "style": "long"}}
{"id": "arith-1037", "prompt": "Multiply 85 by 23.", "completion": "This is a multiplication problem over the numbers 85 and 23, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 1700, and by the remaining 3 gives 255, which sum to 1955. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 23 times 85 is also 1955, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1955.", "meta": {"a": 85, "b": 23, "result": 1955, "style": "long"}}
{"id": "arith-1038", "prompt": "What do you get when you add 91 to 94?", "completion": "This is an addition problem over the numbers 91 and 94, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 181, and the remaining 4 gives 185. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 94 from 185 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 185.", "meta": {"a": 91, "b": 94, "result": 185, "style": "long"}}
{"id": "arith-1039", "prompt": "What do you get when you add 15 to 55?", "completion": "This is an addition problem over the numbers 15 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 65, and the remaining 5 gives 70. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 55 from 70 returns 15, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 70.", "meta": {"a": 15, "b": 55, "result": 70, "style": "long"}}
{"id": "arith-1040", "prompt": "What is the product of 25 and 80?", "completion": "This is a multiplication problem over the numbers 25 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 2000, and by the remaining 0 gives 0, which sum to 2000. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 80 times 25 is also 2000, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2000.", "meta": {"a": 25, "b": 80, "result": 2000, "style": "long"}}
{"id": "arith-1041", "prompt": "What is 80 times 5?", "completion": "This is a multiplication problem over the numbers 80 and 5, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 5 gives 400, which sum to 400. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 5 times 80 is also 400, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 400.", "meta": {"a": 80, "b": 5, "result": 400, "style": "long"}}
{"id": "arith-1042", "prompt": "What is the product of 64 and 16?", "completion": "This is a multiplication problem over the numbers 64 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 640, and by the remaining 6 gives 384, which sum to 1024. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 16 times 64 is also 1024, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1024.", "meta": {"a": 64, "b": 16, "result": 1024, "style": "long"}}
{"id": "arith-1043", "prompt": "What is the product of 7 and 10?", "completion": "This is a multiplication problem over the numbers 7 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 70, and by the remaining 0 gives 0, which sum to 70. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 10 times 7 is also 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 70.", "meta": {"a": 7, "b": 10, "result": 70, "style": "long"}}
{"id": "arith-1044", "prompt": "What is 3 times 92?", "completion": "This is a multiplication problem over the numbers 3 and 92, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 270, and by the remaining 2 gives 6, which sum to 276. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 92 times 3 is also 276, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 276.", "meta": {"a": 3, "b": 92, "result": 276, "style": "long"}}
{"id": "arith-1045", "prompt": "What is 68 times 68?", "completion": "This is a multiplication problem over the numbers 68 and 68, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4080, and by the remaining 8 gives 544, which sum to 4624. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 68 times 68 is also 4624, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4624.", "meta": {"a": 68, "b": 68, "result": 4624, "style": "long"}}
{"id": "arith-1046", "prompt": "Multiply 86 by 95.", "completion": "This is a multiplication problem over the numbers 86 and 95, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 7740, and by the remaining 5 gives 430, which sum to 8170. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 95 times 86 is also 8170, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8170.", "meta": {"a": 86, "b": 95, "result": 8170, "style": "long"}}
{"id": "arith-1047", "prompt": "What is the product of 46 and 86?", "completion": "This is a multiplication problem over the numbers 46 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 3680, and by the remaining 6 gives 276, which sum to 3956. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 86 times 46 is also 3956, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3956.", "meta": {"a": 46, "b": 86, "result": 3956, "style": "long"}}
{"id": "arith-1048", "prompt": "What do you get when you add 73 to 80?", "completion": "This is an addition problem over the numbers 73 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 153, and the remaining 0 gives 153. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 80 from 153 returns 73, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 153.", "meta": {"a": 73, "b": 80, "result": 153, "style": "long"}}
{"id": "arith-1049", "prompt": "What is 84 plus 22?", "completion": "This is an addition problem over the numbers 84 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 104, and the remaining 2 gives 106. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 22 from 106 returns 84, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 106.", "meta": {"a": 84, "b": 22, "result": 106, "style": "long"}}
{"id": "arith-1050", "prompt": "What is the product of 23 and 11?", "completion": "This is a multiplication problem over the numbers 23 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 230, and by the remaining 1 gives 23, which sum to 253. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 11 times 23 is also 253, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 253.", "meta": {"a": 23, "b": 11, "result": 253, "style": "long"}}
{"id": "arith-1051", "prompt": "What is 32 times 44?", "completion": "This is a multiplication problem over the numbers 32 and 44, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1280, and by the remaining 4 gives 128, which sum to 1408. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 44 times 32 is also 1408, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1408.", "meta": {"a": 32, "b": 44, "result": 1408, "style": "long"}}
{"id": "arith-1052", "prompt": "What is 66 plus 30?", "completion": "This is an addition problem over the numbers 66 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 96, and the remaining 0 gives 96. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 30 from 96 returns 66, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 96.", "meta": {"a": 66, "b": 30, "result": 96, "style": "long"}}
{"id": "arith-1053", "prompt": "Multiply 32 by 12.", "completion": "This is a multiplication problem over the numbers 32 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 320, and by the remaining 2 gives 64, which sum to 384. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 12 times 32 is also 384, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 384.", "meta": {"a": 32, "b": 12, "result": 384, "style": "long"}}
{"id": "arith-1054", "prompt": "What is the product of 75 and 59?", "completion": "This is a multiplication problem over the numbers 75 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 3750, and by the remaining 9 gives 675, which sum to 4425. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 59 times 75 is also 4425, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4425.", "meta": {"a": 75, "b": 59, "result": 4425, "style": "long"}}
{"id": "arith-1055", "prompt": "What is the product of 59 and 42?", "completion": "This is a multiplication problem over the numbers 59 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 2360, and by the remaining 2 gives 118, which sum to 2478. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 42 times 59 is also 2478, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2478.", "meta": {"a": 59, "b": 42, "result": 2478, "style": "long"}}
{"id": "arith-1056", "prompt": "What is the product of 97 and 85?", "completion": "This is a multiplication problem over the numbers 97 and 85, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 7760, and by the remaining 5 gives 485, which sum to 8245. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 85 times 97 is also 8245, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 8245.", "meta": {"a": 97, "b": 85, "result": 8245, "style": "long"}}
{"id": "arith-1057", "prompt": "Add 53 and 54.", "completion": "This is an addition problem over the numbers 53 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 103, and the remaining 4 gives 107. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 54 from 107 returns 53, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 107.", "meta": {"a": 53, "b": 54, "result": 107, "style": "long"}}
{"id": "arith-1058", "prompt": "What is 13 plus 79?", "completion": "This is an addition problem over the numbers 13 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 83, and the remaining 9 gives 92. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 79 from 92 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 92.", "meta": {"a": 13, "b": 79, "result": 92, "style": "long"}}
{"id": "arith-1059", "prompt": "What is 85 minus 87?", "completion": "This is a subtraction problem over the numbers 85 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 5, and removing the last 7 leaves -2. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 87 back to -2 returns 85, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -2.", "meta": {"a": 85, "b": 87, "result": -2, "style": "long"}}
{"id": "arith-1060", "prompt": "What is 48 times 8?", "completion": "This is a multiplication problem over the numbers 48 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 384, which sum to 384. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 48 is also 384, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 384.", "meta": {"a": 48, "b": 8, "result": 384, "style": "long"}}
{"id": "arith-1061", "prompt": "What is the product of 44 and 73?", "completion": "This is a multiplication problem over the numbers 44 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3080, and by the remaining 3 gives 132, which sum to 3212. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 73 times 44 is also 3212, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 3212.", "meta": {"a": 44, "b": 73, "result": 3212, "style": "long"}}
{"id": "arith-1062", "prompt": "What is 93 times 59?", "completion": "This is a multiplication problem over the numbers 93 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 4650, and by the remaining 9 gives 837, which sum to 5487. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 59 times 93 is also 5487, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5487.", "meta": {"a": 93, "b": 59, "result": 5487, "style": "long"}}
{"id": "arith-1063", "prompt": "Add 99 and 86.", "completion": "This is an addition problem over the numbers 99 and 86, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 179, and the remaining 6 gives 185. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 86 from 185 returns 99, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 185.", "meta": {"a": 99, "b": 86, "result": 185, "style": "long"}}
{"id": "arith-1064", "prompt": "What is 45 plus 47?", "completion": "This is an addition problem over the numbers 45 and 47, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 85, and the remaining 7 gives 92. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 47 from 92 returns 45, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 92.", "meta": {"a": 45, "b": 47, "result": 92, "style": "long"}}
{"id": "arith-1065", "prompt": "What is 91 times 15?", "completion": "This is a multiplication problem over the numbers 91 and 15, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 910, and by the remaining 5 gives 455, which sum to 1365. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 15 times 91 is also 1365, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1365.", "meta": {"a": 91, "b": 15, "result": 1365, "style": "long"}}
{"id": "arith-1066", "prompt": "What do you get when you add 65 to 19?", "completion": "This is an addition problem over the numbers 65 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 75, and the remaining 9 gives 84. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 19 from 84 returns 65, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 84.", "meta": {"a": 65, "b": 19, "result": 84, "style": "long"}}
{"id": "arith-1067", "prompt": "Add 34 and 80.", "completion": "This is an addition problem over the numbers 34 and 80, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 114, and the remaining 0 gives 114. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 80 from 114 returns 34, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 114.", "meta": {"a": 34, "b": 80, "result": 114, "style": "long"}}
{"id": "arith-1068", "prompt": "What is 17 minus 52?", "completion": "This is a subtraction problem over the numbers 17 and 52, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -33, and removing the last 2 leaves -35. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 52 back to -35 returns 17, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -35.", "meta": {"a": 17, "b": 52, "result": -35, "style": "long"}}
{"id": "arith-1069", "prompt": "What is the product of 26 and 93?", "completion": "This is a multiplication problem over the numbers 26 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 90 gives 2340, and by the remaining 3 gives 78, which sum to 2418. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 93 times 26 is also 2418, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2418.", "meta": {"a": 26, "b": 93, "result": 2418, "style": "long"}}
{"id": "arith-1070", "prompt": "Add 98 and 55.", "completion": "This is an addition problem over the numbers 98 and 55, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 148, and the remaining 5 gives 153. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 55 from 153 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 153.", "meta": {"a": 98, "b": 55, "result": 153, "style": "long"}}
{"id": "arith-1071", "prompt": "Add 59 and 60.", "completion": "This is an addition problem over the numbers 59 and 60, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 119, and the remaining 0 gives 119. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 60 from 119 returns 59, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 119.", "meta": {"a": 59, "b": 60, "result": 119, "style": "long"}}
{"id": "arith-1072", "prompt": "What is the product of 2 and 69?", "completion": "This is a multiplication problem over the numbers 2 and 69, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 120, and by the remaining 9 gives 18, which sum to 138. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 69 times 2 is also 138, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 138.", "meta": {"a": 2, "b": 69, "result": 138, "style": "long"}}
{"id": "arith-1073", "prompt": "Multiply 76 by 63.", "completion": "This is a multiplication problem over the numbers 76 and 63, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 60 gives 4560, and by the remaining 3 gives 228, which sum to 4788. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 63 times 76 is also 4788, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4788.", "meta": {"a": 76, "b": 63, "result": 4788, "style": "long"}}
{"id": "arith-1074", "prompt": "What do you get when you add 95 to 18?", "completion": "This is an addition problem over the numbers 95 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 105, and the remaining 8 gives 113. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 18 from 113 returns 95, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 113.", "meta": {"a": 95, "b": 18, "result": 113, "style": "long"}}
{"id": "arith-1075", "prompt": "Multiply 86 by 78.", "completion": "This is a multiplication problem over the numbers 86 and 78, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 6020, and by the remaining 8 gives 688, which sum to 6708. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 78 times 86 is also 6708, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 6708.", "meta": {"a": 86, "b": 78, "result": 6708, "style": "long"}}
{"id": "arith-1076", "prompt": "Multiply 55 by 79.", "completion": "This is a multiplication problem over the numbers 55 and 79, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 3850, and by the remaining 9 gives 495, which sum to 4345. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 79 times 55 is also 4345, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4345.", "meta": {"a": 55, "b": 79, "result": 4345, "style": "long"}}
{"id": "arith-1077", "prompt": "Subtract 45 from 52.", "completion": "This is a subtraction problem over the numbers 52 and 45, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 40 leaves 12, and removing the last 5 leaves 7. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 45 back to 7 returns 52, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 7.", "meta": {"a": 52, "b": 45, "result": 7, "style": "long"}}
{"id": "arith-1078", "prompt": "What is the product of 19 and 19?", "completion": "This is a multiplication problem over the numbers 19 and 19, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 190, and by the remaining 9 gives 171, which sum to 361. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 19 times 19 is also 361, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 361.", "meta": {"a": 19, "b": 19, "result": 361, "style": "long"}}
{"id": "arith-1079", "prompt": "Subtract 72 from 91.", "completion": "This is a subtraction problem over the numbers 91 and 72, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves 21, and removing the last 2 leaves 19. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 72 back to 19 returns 91, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 19.", "meta": {"a": 91, "b": 72, "result": 19, "style": "long"}}
{"id": "arith-1080", "prompt": "What is 27 minus 28?", "completion": "This is a subtraction problem over the numbers 27 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 7, and removing the last 8 leaves -1. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 28 back to -1 returns 27, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -1.", "meta": {"a": 27, "b": 28, "result": -1, "style": "long"}}
{"id": "arith-1081", "prompt": "What is 88 times 18?", "completion": "This is a multiplication problem over the numbers 88 and 18, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 880, and by the remaining 8 gives 704, which sum to 1584. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 18 times 88 is also 1584, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1584.", "meta": {"a": 88, "b": 18, "result": 1584, "style": "long"}}
{"id": "arith-1082", "prompt": "What is 92 times 16?", "completion": "This is a multiplication problem over the numbers 92 and 16, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 920, and by the remaining 6 gives 552, which sum to 1472. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 16 times 92 is also 1472, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 1472.", "meta": {"a": 92, "b": 16, "result": 1472, "style": "long"}}
{"id": "arith-1083", "prompt": "What is the product of 76 and 75?", "completion": "This is a multiplication problem over the numbers 76 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 5320, and by the remaining 5 gives 380, which sum to 5700. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 75 times 76 is also 5700, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 5700.", "meta": {"a": 76, "b": 75, "result": 5700, "style": "long"}}
{"id": "arith-1084", "prompt": "Subtract 3 from 56.", "completion": "This is a subtraction problem over the numbers 56 and 3, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 0 leaves 56, and removing the last 3 leaves 53. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 3 back to 53 returns 56, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 53.", "meta": {"a": 56, "b": 3, "result": 53, "style": "long"}}
{"id": "arith-1085", "prompt": "What is 50 plus 20?", "completion": "This is an addition problem over the numbers 50 and 20, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 20 first gives 70, and the remaining 0 gives 70. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 20 from 70 returns 50, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 70.", "meta": {"a": 50, "b": 20, "result": 70, "style": "long"}}
{"id": "arith-1086", "prompt": "What is 27 plus 36?", "completion": "This is an addition problem over the numbers 27 and 36, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 57, and the remaining 6 gives 63. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 36 from 63 returns 27, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 63.", "meta": {"a": 27, "b": 36, "result": 63, "style": "long"}}
{"id": "arith-1087", "prompt": "Subtract 34 from 89.", "completion": "This is a subtraction problem over the numbers 89 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 30 leaves 59, and removing the last 4 leaves 55. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 34 back to 55 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 55.", "meta": {"a": 89, "b": 34, "result": 55, "style": "long"}}
{"id": "arith-1088", "prompt": "What is 90 plus 39?", "completion": "This is an addition problem over the numbers 90 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 120, and the remaining 9 gives 129. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 39 from 129 returns 90, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 129.", "meta": {"a": 90, "b": 39, "result": 129, "style": "long"}}
{"id": "arith-1089", "prompt": "What is 47 plus 59?", "completion": "This is an addition problem over the numbers 47 and 59, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 97, and the remaining 9 gives 106. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 59 from 106 returns 47, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 106.", "meta": {"a": 47, "b": 59, "result": 106, "style": "long"}}
{"id": "arith-1090", "prompt": "What is 97 minus 84?", "completion": "This is a subtraction problem over the numbers 97 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 17, and removing the last 4 leaves 13. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 84 back to 13 returns 97, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 13.", "meta": {"a": 97, "b": 84, "result": 13, "style": "long"}}
{"id": "arith-1091", "prompt": "What is 67 minus 91?", "completion": "This is a subtraction problem over the numbers 67 and 91, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -23, and removing the last 1 leaves -24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 91 back to -24 returns 67, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -24.", "meta": {"a": 67, "b": 91, "result": -24, "style": "long"}}
{"id": "arith-1092", "prompt": "What is 50 plus 51?", "completion": "This is an addition problem over the numbers 50 and 51, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 50 first gives 100, and the remaining 1 gives 101. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 51 from 101 returns 50, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 101.", "meta": {"a": 50, "b": 51, "result": 101, "style": "long"}}
{"id": "arith-1093", "prompt": "What is 72 times 8?", "completion": "This is a multiplication problem over the numbers 72 and 8, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 0 gives 0, and by the remaining 8 gives 576, which sum to 576. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 8 times 72 is also 576, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 576.", "meta": {"a": 72, "b": 8, "result": 576, "style": "long"}}
{"id": "arith-1094", "prompt": "Subtract 81 from 27.", "completion": "This is a subtraction problem over the numbers 27 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves -53, and removing the last 1 leaves -54. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 81 back to -54 returns 27, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -54.", "meta": {"a": 27, "b": 81, "result": -54, "style": "long"}}
{"id": "arith-1095", "prompt": "What is 83 minus 92?", "completion": "This is a subtraction problem over the numbers 83 and 92, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 90 leaves -7, and removing the last 2 leaves -9. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 92 back to -9 returns 83, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -9.", "meta": {"a": 83, "b": 92, "result": -9, "style": "long"}}
{"id": "arith-1096", "prompt": "What is 94 minus 26?", "completion": "This is a subtraction problem over the numbers 94 and 26, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves 74, and removing the last 6 leaves 68. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 26 back to 68 returns 94, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 68.", "meta": {"a": 94, "b": 26, "result": 68, "style": "long"}}
{"id": "arith-1097", "prompt": "What is the product of 24 and 89?", "completion": "This is a multiplication problem over the numbers 24 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 1920, and by the remaining 9 gives 216, which sum to 2136. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 89 times 24 is also 2136, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2136.", "meta": {"a": 24, "b": 89, "result": 2136, "style": "long"}}
{"id": "arith-1098", "prompt": "What do you get when you add 24 to 96?", "completion": "This is an addition problem over the numbers 24 and 96, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 114, and the remaining 6 gives 120. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 96 from 120 returns 24, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 120.", "meta": {"a": 24, "b": 96, "result": 120, "style": "long"}}
{"id": "arith-1099", "prompt": "Multiply 7 by 56.", "completion": "This is a multiplication problem over the numbers 7 and 56, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 50 gives 350, and by the remaining 6 gives 42, which sum to 392. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 56 times 7 is also 392, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 392.", "meta": {"a": 7, "b": 56, "result": 392, "style": "long"}}
{"id": "arith-1100", "prompt": "Subtract 22 from 18.", "completion": "This is a subtraction problem over the numbers 18 and 22, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 20 leaves -2, and removing the last 2 leaves -4. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 22 back to -4 returns 18, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -4.", "meta": {"a": 18, "b": 22, "result": -4, "style": "long"}}
{"id": "arith-1101", "prompt": "What is 44 plus 61?", "completion": "This is an addition problem over the numbers 44 and 61, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 60 first gives 104, and the remaining 1 gives 105. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 61 from 105 returns 44, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 105.", "meta": {"a": 44, "b": 61, "result": 105, "style": "long"}}
{"id": "arith-1102", "prompt": "What is 21 plus 43?", "completion": "This is an addition problem over the numbers 21 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 61, and the remaining 3 gives 64. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 43 from 64 returns 21, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 64.", "meta": {"a": 21, "b": 43, "result": 64, "style": "long"}}
{"id": "arith-1103", "prompt": "Subtract 75 from 64.", "completion": "This is a subtraction problem over the numbers 64 and 75, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 70 leaves -6, and removing the last 5 leaves -11. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 75 back to -11 returns 64, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -11.", "meta": {"a": 64, "b": 75, "result": -11, "style": "long"}}
{"id": "arith-1104", "prompt": "Add 92 and 42.", "completion": "This is an addition problem over the numbers 92 and 42, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 132, and the remaining 2 gives 134. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 42 from 134 returns 92, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 134.", "meta": {"a": 92, "b": 42, "result": 134, "style": "long"}}
{"id": "arith-1105", "prompt": "What do you get when you add 68 to 10?", "completion": "This is an addition problem over the numbers 68 and 10, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 78, and the remaining 0 gives 78. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 10 from 78 returns 68, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 78.", "meta": {"a": 68, "b": 10, "result": 78, "style": "long"}}
{"id": "arith-1106", "prompt": "Multiply 71 by 70.", "completion": "This is a multiplication problem over the numbers 71 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 70 gives 4970, and by the remaining 0 gives 0, which sum to 4970. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 70 times 71 is also 4970, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 4970.", "meta": {"a": 71, "b": 70, "result": 4970, "style": "long"}}
{"id": "arith-1107", "prompt": "Add 46 and 30.", "completion": "This is an addition problem over the numbers 46 and 30, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 76, and the remaining 0 gives 76. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 30 from 76 returns 46, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 76.", "meta": {"a": 46, "b": 30, "result": 76, "style": "long"}}
{"id": "arith-1108", "prompt": "What is 44 times 48?", "completion": "This is a multiplication problem over the numbers 44 and 48, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 40 gives 1760, and by the remaining 8 gives 352, which sum to 2112. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 48 times 44 is also 2112, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2112.", "meta": {"a": 44, "b": 48, "result": 2112, "style": "long"}}
{"id": "arith-1109", "prompt": "What is 98 minus 81?", "completion": "This is a subtraction problem over the numbers 98 and 81, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 80 leaves 18, and removing the last 1 leaves 17. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 81 back to 17 returns 98, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 17.", "meta": {"a": 98, "b": 81, "result": 17, "style": "long"}}
{"id": "arith-1110", "prompt": "What is 16 plus 87?", "completion": "This is an addition problem over the numbers 16 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 96, and the remaining 7 gives 103. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 87 from 103 returns 16, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 103.", "meta": {"a": 16, "b": 87, "result": 103, "style": "long"}}
{"id": "arith-1111", "prompt": "What is the product of 32 and 84?", "completion": "This is a multiplication problem over the numbers 32 and 84, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 80 gives 2560, and by the remaining 4 gives 128, which sum to 2688. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 84 times 32 is also 2688, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 2688.", "meta": {"a": 32, "b": 84, "result": 2688, "style": "long"}}
{"id": "arith-1112", "prompt": "What is 89 plus 43?", "completion": "This is an addition problem over the numbers 89 and 43, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 129, and the remaining 3 gives 132. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 43 from 132 returns 89, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 132.", "meta": {"a": 89, "b": 43, "result": 132, "style": "long"}}
{"id": "arith-1113", "prompt": "Add 51 and 34.", "completion": "This is an addition problem over the numbers 51 and 34, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 30 first gives 81, and the remaining 4 gives 85. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 34 from 85 returns 51, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 85.", "meta": {"a": 51, "b": 34, "result": 85, "style": "long"}}
{"id": "arith-1114", "prompt": "What is 68 plus 49?", "completion": "This is an addition problem over the numbers 68 and 49, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 40 first gives 108, and the remaining 9 gives 117. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 49 from 117 returns 68, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 117.", "meta": {"a": 68, "b": 49, "result": 117, "style": "long"}}
{"id": "arith-1115", "prompt": "What is the product of 7 and 39?", "completion": "This is a multiplication problem over the numbers 7 and 39, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 30 gives 210, and by the remaining 9 gives 63, which sum to 273. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 39 times 7 is also 273, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 273.", "meta": {"a": 7, "b": 39, "result": 273, "style": "long"}}
{"id": "arith-1116", "prompt": "What is 67 times 12?", "completion": "This is a multiplication problem over the numbers 67 and 12, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 10 gives 670, and by the remaining 2 gives 134, which sum to 804. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 12 times 67 is also 804, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 804.", "meta": {"a": 67, "b": 12, "result": 804, "style": "long"}}
{"id": "arith-1117", "prompt": "What do you get when you add 70 to 70?", "completion": "This is an addition problem over the numbers 70 and 70, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 140, and the remaining 0 gives 140. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 70 from 140 returns 70, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 140.", "meta": {"a": 70, "b": 70, "result": 140, "style": "long"}}
{"id": "arith-1118", "prompt": "Add 28 and 87.", "completion": "This is an addition problem over the numbers 28 and 87, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 108, and the remaining 7 gives 115. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 87 from 115 returns 28, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 115.", "meta": {"a": 28, "b": 87, "result": 115, "style": "long"}}
{"id": "arith-1119", "prompt": "Multiply 15 by 28.", "completion": "This is a multiplication problem over the numbers 15 and 28, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Multiplying by 20 gives 300, and by the remaining 8 gives 120, which sum to 420. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: the same product appears if the two numbers are exchanged, since 28 times 15 is also 420, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 420.", "meta": {"a": 15, "b": 28, "result": 420, "style": "long"}}
{"id": "arith-1120", "prompt": "Add 97 and 89.", "completion": "This is an addition problem over the numbers 97 and 89, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 80 first gives 177, and the remaining 9 gives 186. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 89 from 186 returns 97, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 186.", "meta": {"a": 97, "b": 89, "result": 186, "style": "long"}}
{"id": "arith-1121", "prompt": "What is 60 plus 93?", "completion": "This is an addition problem over the numbers 60 and 93, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 90 first gives 150, and the remaining 3 gives 153. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 93 from 153 returns 60, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 153.", "meta": {"a": 60, "b": 93, "result": 153, "style": "long"}}
{"id": "arith-1122", "prompt": "What is 13 plus 11?", "completion": "This is an addition problem over the numbers 13 and 11, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 10 first gives 23, and the remaining 1 gives 24. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 11 from 24 returns 13, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 24.", "meta": {"a": 13, "b": 11, "result": 24, "style": "long"}}
{"id": "arith-1123", "prompt": "What do you get when you add 34 to 73?", "completion": "This is an addition problem over the numbers 34 and 73, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Adding the 70 first gives 104, and the remaining 3 gives 107. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: subtracting 73 from 107 returns 34, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is 107.", "meta": {"a": 34, "b": 73, "result": 107, "style": "long"}}
{"id": "arith-1124", "prompt": "What is 35 minus 54?", "completion": "This is a subtraction problem over the numbers 35 and 54, and it is worth working through one step at a time rather than reaching for the answer directly. The usual approach is to break the second number into a part that is easy to handle and a small remainder, then deal with each in turn. Taking away 50 leaves -15, and removing the last 4 leaves -19. That decomposition is not the only route to the answer, but it keeps every intermediate quantity small enough to carry without writing anything down, which is why it is the method most people fall back on. It is worth checking the result rather than trusting the first pass: adding 54 back to -19 returns 35, which is what the inverse operation should produce and confirms the arithmetic held. The answer, then, is -19.", "meta": {"a": 35, "b": 54, "result": -19, "style": "long"}}