submission_id,user_id,create_at,language,score,problem_set_problem_id,problem_id,skill_id,code,response,time_consume,memory_consume 1456852631544705024,0ce3bb5dc6fa29231698cafd7056fbbb19c070d1a3d48db3ae980ece9529dc16,2021-11-06 13:15:09,C,0.0,1456179472805675008,1456164485751504896,639,"#include\n#include\nusing namespace std;\nint main(void)\n{\n\tint x, y;\n\tcin >> x >> y;\n\tint z=0;\n\tint k = 1;\n\twhile (x != 0 && y != 0)\n\t{\n\t\tz += y % 2 * pow(2, k - 1) + x % 2 * pow(2, k);\n\t\tx /= 2;\n\t\ty /= 2;\n\t\tk += 2;\n\t}\n\n\twhile (x != 0)\n\t{\n\t\tz += x % 2 * pow(2, k);\n\t\tx /= 2;\n\t\tk += 2;\n\t}\n\twhile (y != 0)\n\t{\n\t\tz += y % 2 * pow(2, k - 1);\n\t\ty /= 2;\n\t\tk += 2;\n\t}\n\tcout << z;\n}",COMPILE_ERROR,0,0 1456852659735175168,0ce3bb5dc6fa29231698cafd7056fbbb19c070d1a3d48db3ae980ece9529dc16,2021-11-06 13:15:15,C++,10.0,1456179472805675008,1456164485751504896,639,"#include\n#include\nusing namespace std;\nint main(void)\n{\n\tint x, y;\n\tcin >> x >> y;\n\tint z=0;\n\tint k = 1;\n\twhile (x != 0 && y != 0)\n\t{\n\t\tz += y % 2 * pow(2, k - 1) + x % 2 * pow(2, k);\n\t\tx /= 2;\n\t\ty /= 2;\n\t\tk += 2;\n\t}\n\n\twhile (x != 0)\n\t{\n\t\tz += x % 2 * pow(2, k);\n\t\tx /= 2;\n\t\tk += 2;\n\t}\n\twhile (y != 0)\n\t{\n\t\tz += y % 2 * pow(2, k - 1);\n\t\ty /= 2;\n\t\tk += 2;\n\t}\n\tcout << z;\n}",ACCEPTED,45,464 1456853483387428864,0ce3bb5dc6fa29231698cafd7056fbbb19c070d1a3d48db3ae980ece9529dc16,2021-11-06 13:18:32,C++,10.0,1456179472805675009,1456166840027594752,639,"#include\n#include\nusing namespace std;\nint main(void)\n{\n\tint z;\n\tint x = 0, y = 0;\n\tcin >> z;\n\tint k = 0;\n\twhile (z != 0)\n\t{\n\t\ty += z % 2 * pow(2, k);\n\t\tz /= 2;\n\t\tx += z % 2 * pow(2, k);\n\t\tz /= 2;\n\t\tk++;\n\t}\n\tcout <\n\nusing namespace std;\n\nint main()\n{\n int x = 0, y = 0;\n int _x = 0, _y = 0;\n int z = 0;\n int digit = 0;\n int base = 1;\n \n cin >> x >> y;\n \n // convert x\n _x = x;\n base = 2;\n while(_x > 0)\n {\n if(_x % 2 == 1)\n {\n z += base;\n }\n _x >> 1;\n base *= 4;\n }\n // convert y\n _y = y;\n base = 1;\n while(_y > 0)\n {\n if(_y % 2 == 1)\n {\n z += base;\n }\n _y >> 1;\n base *= 4;\n }\n\n cout << z;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456856177094733824,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 13:29:14,C++,0.0,1456179472805675008,1456164485751504896,639,"# include \n\nusing namespace std;\n\nint main()\n{\n unsigned int x = 0, y = 0;\n unsigned int _x = 0, _y = 0;\n unsigned int z = 0;\n unsigned int base = 1;\n \n cin >> x >> y;\n \n // convert x\n _x = x;\n base = 2;\n while(_x > 0)\n {\n if(_x % 2 == 1)\n {\n z += base;\n }\n _x >> 1;\n base *= 4;\n }\n // convert y\n _y = y;\n base = 1;\n while(_y > 0)\n {\n if(_y % 2 == 1)\n {\n z += base;\n }\n _y >> 1;\n base *= 4;\n }\n\n cout << z;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456856600568995840,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 13:30:55,C++,10.0,1456179472805675008,1456164485751504896,639,"# include \n\nusing namespace std;\n\nint main()\n{\n unsigned int x = 0, y = 0;\n unsigned int _x = 0, _y = 0;\n unsigned int z = 0;\n unsigned int base = 1;\n \n cin >> x >> y;\n \n // convert x\n _x = x;\n base = 2;\n while(_x > 0)\n {\n if(_x % 2 == 1)\n {\n z += base;\n }\n _x = _x >> 1;\n base *= 4;\n }\n // convert y\n _y = y;\n base = 1;\n while(_y > 0)\n {\n if(_y % 2 == 1)\n {\n z += base;\n }\n _y = _y >> 1;\n base *= 4;\n }\n\n cout << z;\n\n}",ACCEPTED,31,456 1456856681342902272,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 13:31:14,Python,0.0,1456179472805675009,1456166840027594752,639,"a=int(input())\nlist=[]\nlist1=[]\nlist2=[]\nwhile a>0:\n t=a%2\n a=a/2\n list.append(t)\nif len(list)%2!=0:\n list.append(0)\nfor i in range(len(list)):\n if i%2==0:\n list1.append(list[i])\n else:\n list2.append(list[i])\nx=0\ny=0\nfor i in range(len(list1)):\n x=x+pow(2,i)\nfor i in range(len(list2)):\n y=y+pow(2,i)\nprint(\""{} {}\"".format(x,y))\n \n \n ",WRONG_ANSWER,157,3348 1456856946125119488,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 13:32:17,Python,0.0,1456179472801480704,1456154017474035712,615,"import numpy as np\nsize = int(input())\nlength = int(input())\nmatrix = np.identity(size)\nfor i in range(0, length):\n print(ok)\n \n ",NON_ZERO_EXIT_CODE,111,3268 1456858384133857280,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 13:38:00,Python,0.0,1456179472805675009,1456166840027594752,639,"a=int(input())\nlist=[]\nlist1=[]\nlist2=[]\nwhile a>0:\n t=a%2\n a=int(a/2)\n list.append(t)\nif len(list)%2!=0:\n list.append(0)\nfor i in range(len(list)):\n if i%2==0:\n list1.append(list[i])\n else:\n list2.append(list[i])\nx=0\ny=0\nfor i in range(len(list1)):\n x=x+pow(2,i)\nfor i in range(len(list2)):\n y=y+pow(2,i)\nprint(\""{} {}\"".format(x,y))\n \n \n ",WRONG_ANSWER,154,3288 1456859595151056896,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 13:42:49,C++,0.0,1456179472805675009,1456166840027594752,639,"# include \n#include \n\nusing namespace std;\n\nint main()\n{\n unsigned int x = 0, y = 0;\n unsigned int z = 0;\n unsigned int baseX = 1, baseY = 1;\n \n cin >> z;\n //bitset<32> bitsetz{z};\n unsigned int _z = z;\n while(_z > 0)\n {\n if(baseX == baseY)\n {\n if(_z % 2 == 1)\n {\n y += baseY;\n }\n baseY *= 2;\n }\n else if(baseX < baseY)\n {\n if(_z % 2 == 1)\n {\n y += baseX;\n }\n baseX *= 2;\n }\n _z /= 2;\n }\n\n\n cout << x << y;\n\n}",MULTIPLE_ERROR,45,480 1456859969651519488,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 13:44:18,C++,2.0,1456179472805675009,1456166840027594752,639,"# include \n#include \n\nusing namespace std;\n\nint main()\n{\n unsigned int x = 0, y = 0;\n unsigned int z = 0;\n unsigned int baseX = 1, baseY = 1;\n \n cin >> z;\n //bitset<32> bitsetz{z};\n unsigned int _z = z;\n while(_z > 0)\n {\n if(baseX == baseY)\n {\n if(_z % 2 == 1)\n {\n y += baseY;\n }\n baseY *= 2;\n }\n else if(baseX < baseY)\n {\n if(_z % 2 == 1)\n {\n y += baseX;\n }\n baseX *= 2;\n }\n _z /= 2;\n }\n\n\n cout << x << \"" \"" << y;\n\n}",PARTIAL_ACCEPTED,45,612 1456860599460372480,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 13:46:48,Python,0.0,1456179472805675009,1456166840027594752,639,"a=int(input())\nlist=[]\nlist1=[]\nlist2=[]\nwhile a>0:\n t=a%2\n a=int(a/2)\n list.append(t)\nif len(list)%2!=0:\n list.append(0)\nfor i in range(len(list)):\n if i%2==0:\n list1.append(list[i])\n else:\n list2.append(list[i])\nx=0\ny=0\nfor i in range(len(list1)):\n x=x+pow(2,i)\nfor i in range(len(list2)):\n y=y+pow(2,i)\nprint(\""{} {}\"".format(y,x))\n \n \n ",WRONG_ANSWER,156,3288 1456860773234028544,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 13:47:30,C++,10.0,1456179472805675009,1456166840027594752,639,"# include \n#include \n\nusing namespace std;\n\nint main()\n{\n unsigned int x = 0, y = 0;\n unsigned int z = 0;\n unsigned int baseX = 1, baseY = 1;\n \n cin >> z;\n //bitset<32> bitsetz{z};\n unsigned int _z = z;\n while(_z > 0)\n {\n if(baseX == baseY)\n {\n if(_z % 2 == 1)\n {\n y += baseY;\n }\n baseY *= 2;\n }\n else if(baseX < baseY)\n {\n if(_z % 2 == 1)\n {\n x += baseX;\n }\n baseX *= 2;\n }\n _z /= 2;\n }\n\n\n cout << x << \"" \"" << y;\n\n}",ACCEPTED,45,492 1456860962090954752,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 13:48:15,Python,0.0,1456179472805675009,1456166840027594752,639,"a=int(input())\nlist=[]\nlist1=[]\nlist2=[]\nwhile a>0:\n t=a%2\n a=int(a/2)\n list.append(t)\nif len(list)%2!=0:\n list.append(0)\nfor i in range(len(list)):\n if i%2==0:\n list1.append(list[i])\n else:\n list2.append(list[i])\nx=0\ny=0\nfor i in range(len(list1)):\n x=x+pow(2,i)\nfor i in range(len(list2)):\n y=y+pow(2,i)\nprint(\""{} {}\"".format(y,x))\n \n \n ",WRONG_ANSWER,163,3456 1456861008224657408,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 13:48:26,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\t\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tFDS[i] = (int*)calloc(N+1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse \n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t//// test income\n\t//for (int i = 0; i < M; i++)\n\t//{\n\t//\tfor (int j = 0; j < N+1; j++)\n\t//\t{\n\t//\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456861098326695936,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 13:48:47,Python,10.0,1456179472805675009,1456166840027594752,639,"a=int(input())\nlist=[]\nlist1=[]\nlist2=[]\nwhile a>0:\n t=a%2\n a=int(a/2)\n list.append(t)\nif len(list)%2!=0:\n list.append(0)\nfor i in range(len(list)):\n if i%2==0:\n list1.append(list[i])\n else:\n list2.append(list[i])\nx=0\ny=0\nfor i in range(len(list1)):\n x=x+list1[i]*pow(2,i)\nfor i in range(len(list2)):\n y=y+list2[i]*pow(2,i)\nprint(\""{} {}\"".format(y,x))\n \n \n ",ACCEPTED,160,3272 1456861169067274240,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 13:49:04,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n Matrix* m = CreateIdentity(size);\n char input[100], output[100];\n for(i=0;i %s\"",input, output);\n printf(\""%s\"",input);\n printf(\""%s\"",output);\n }\n \n}",COMPILE_ERROR,0,0 1456861364061020160,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 13:49:51,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n Matrix* m = CreateIdentity(size);\n char input[100], output[100];\n for(i=0;i %s\"",input, output);\n printf(\""%s\"",input);\n printf(\""%s\"",output);\n }\n \n}",COMPILE_ERROR,0,0 1456863421664927744,0ce3bb5dc6fa29231698cafd7056fbbb19c070d1a3d48db3ae980ece9529dc16,2021-11-06 13:58:01,C,0.0,1456179472809869312,1456171992474206208,639,"#include\n#include\n#include\nusing namespace std;\nint main(void)\n{\n\tint x, y,n;\n\tcin >> n>> x >> y;\n\tstring s1 = \""\"";\n\tint z;\n\t\n\twhile (x != 0 && y != 0&&n!=0)\n\t{\n\t\tz = y % 2 + x % 2 * 2;\n\t\tif(z==3)\n\t\t\ts1 = to_string(2) + s1;\n\t\telse if(z==2)\n\t\t\ts1 = to_string(3) + s1;\n\t\telse\n\t\t\ts1 = to_string(z) + s1;\n\t\tx /= 2;\n\t\ty /= 2;\n\t\tn -= 1;\n\t}\n\n\twhile (x != 0&&n!=0)\n\t{\n\t\tz = x % 2*2;\n\t\tif (z == 3)\n\t\t\ts1 = to_string(2) + s1;\n\t\telse if (z == 2)\n\t\t\ts1 = to_string(3) + s1;\n\t\telse\n\t\t\ts1 = to_string(z) + s1;\n\t\tx /= 2;\n\t\tn -= 1;\n\t\n\t}\n\twhile (y != 0&&n!=0)\n\t{\n\t\tz = y % 2;\n\t\tif (z == 3)\n\t\t\ts1 = to_string(2) + s1;\n\t\telse if (z == 2)\n\t\t\ts1 = to_string(3) + s1;\n\t\telse\n\t\t\ts1 = to_string(z) + s1;\n\t\ty /= 2;\n\t\tn -= 1;\n\t\t\n\t}\n\twhile (n != 0)\n\t{\n\t\ts1 = to_string(0) + s1;\n\t\tn -= 1;\n\t}\n\t//finish step 4\n\t//start step 5\n\tfor (int i = 0; i < s1.length(); i++)\n\t{\n\t\tif (s1[i] == '0')\n\t\t{\n\t\t\tfor (int j = i + 1; j < s1.length(); j++)\n\t\t\t{\n\t\t\t\tif (s1[j] == '1')\n\t\t\t\t\ts1[j] = '3';\n\t\t\t\telse if (s1[j] == '3')\n\t\t\t\t\ts1[j] = '1';\n\t\t\t}\n\t\t}\n\t\telse if (s1[i] == '3')\n\t\t{\n\t\t\tfor (int j = i + 1; j < s1.length(); j++)\n\t\t\t{\n\t\t\t\tif (s1[j] == '0')\n\t\t\t\t\ts1[j] = '2';\n\t\t\t\telse if (s1[j] == '2')\n\t\t\t\t\ts1[j]='0';\n\t\t\t}\n\t\t}\n\t}\n\t//to decimal number\n\tint k = 0;\n\tint sum = 0;\n\tfor (int i = s1.length()-1; i >= 0; i--)\n\t{\n\t\tint digit = s1[i] - 48;\n\t\tsum += digit % 2 * pow(2, k) + digit / 2 % 2 * pow(2, k + 1);\n\t\tk += 2;\n\t}\n\tcout << sum;\n}",COMPILE_ERROR,0,0 1456863446113525760,0ce3bb5dc6fa29231698cafd7056fbbb19c070d1a3d48db3ae980ece9529dc16,2021-11-06 13:58:07,C++,10.0,1456179472809869312,1456171992474206208,639,"#include\n#include\n#include\nusing namespace std;\nint main(void)\n{\n\tint x, y,n;\n\tcin >> n>> x >> y;\n\tstring s1 = \""\"";\n\tint z;\n\t\n\twhile (x != 0 && y != 0&&n!=0)\n\t{\n\t\tz = y % 2 + x % 2 * 2;\n\t\tif(z==3)\n\t\t\ts1 = to_string(2) + s1;\n\t\telse if(z==2)\n\t\t\ts1 = to_string(3) + s1;\n\t\telse\n\t\t\ts1 = to_string(z) + s1;\n\t\tx /= 2;\n\t\ty /= 2;\n\t\tn -= 1;\n\t}\n\n\twhile (x != 0&&n!=0)\n\t{\n\t\tz = x % 2*2;\n\t\tif (z == 3)\n\t\t\ts1 = to_string(2) + s1;\n\t\telse if (z == 2)\n\t\t\ts1 = to_string(3) + s1;\n\t\telse\n\t\t\ts1 = to_string(z) + s1;\n\t\tx /= 2;\n\t\tn -= 1;\n\t\n\t}\n\twhile (y != 0&&n!=0)\n\t{\n\t\tz = y % 2;\n\t\tif (z == 3)\n\t\t\ts1 = to_string(2) + s1;\n\t\telse if (z == 2)\n\t\t\ts1 = to_string(3) + s1;\n\t\telse\n\t\t\ts1 = to_string(z) + s1;\n\t\ty /= 2;\n\t\tn -= 1;\n\t\t\n\t}\n\twhile (n != 0)\n\t{\n\t\ts1 = to_string(0) + s1;\n\t\tn -= 1;\n\t}\n\t//finish step 4\n\t//start step 5\n\tfor (int i = 0; i < s1.length(); i++)\n\t{\n\t\tif (s1[i] == '0')\n\t\t{\n\t\t\tfor (int j = i + 1; j < s1.length(); j++)\n\t\t\t{\n\t\t\t\tif (s1[j] == '1')\n\t\t\t\t\ts1[j] = '3';\n\t\t\t\telse if (s1[j] == '3')\n\t\t\t\t\ts1[j] = '1';\n\t\t\t}\n\t\t}\n\t\telse if (s1[i] == '3')\n\t\t{\n\t\t\tfor (int j = i + 1; j < s1.length(); j++)\n\t\t\t{\n\t\t\t\tif (s1[j] == '0')\n\t\t\t\t\ts1[j] = '2';\n\t\t\t\telse if (s1[j] == '2')\n\t\t\t\t\ts1[j]='0';\n\t\t\t}\n\t\t}\n\t}\n\t//to decimal number\n\tint k = 0;\n\tint sum = 0;\n\tfor (int i = s1.length()-1; i >= 0; i--)\n\t{\n\t\tint digit = s1[i] - 48;\n\t\tsum += digit % 2 * pow(2, k) + digit / 2 % 2 * pow(2, k + 1);\n\t\tk += 2;\n\t}\n\tcout << sum;\n}",ACCEPTED,50,476 1456863580633243648,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 13:58:39,C,0.0,1456179472805675008,1456164485751504896,639,"//x,y的坐标转换为2进制然后拿过来奇偶地变成z值的2进制\n#include \nint main(){\n int x,y,z;\n cin<0; i++) \n { \n bx[i]=n%2; \n x= x/2; \n }\n lx=i;\n for(i=0; y>0; i++) \n { \n by[i]=n%2; \n y= y/2; \n }\n ly=i;\n//fill with zero\n if(lx=0 ;i--,j=j+2){\n bz[j]=bx[i];\n bz[j+1]=by[i];\n }\n lbz=j;\n z=0;\n for(i=0;i\nint main(){\n int x,y,z;\n cin<0; i++) \n { \n bx[i]=n%2; \n x= x/2; \n }\n lx=i;\n for(i=0; y>0; i++) \n { \n by[i]=n%2; \n y= y/2; \n }\n ly=i;\n//fill with zero\n if(lx=0 ;i--,j=j+2){\n bz[j]=bx[i];\n bz[j+1]=by[i];\n }\n lbz=j;\n z=0;\n for(i=0;i\nusing namespace std;\nint main(){\n int x,y,z;\n cin<0; i++) \n { \n bx[i]=n%2; \n x= x/2; \n }\n lx=i;\n for(i=0; y>0; i++) \n { \n by[i]=n%2; \n y= y/2; \n }\n ly=i;\n//fill with zero\n if(lx=0 ;i--,j=j+2){\n bz[j]=bx[i];\n bz[j+1]=by[i];\n }\n lbz=j;\n z=0;\n for(i=0;i\nusing namespace std;\nint main(){\n int x,y,z;\n cin>>x;\n cin>>y;\n int bx[20];\n int by[20];\n int lx,ly;\n int i;\n for(i=0; x>0; i++) \n { \n bx[i]=n%2; \n x= x/2; \n }\n lx=i;\n for(i=0; y>0; i++) \n { \n by[i]=n%2; \n y= y/2; \n }\n ly=i;\n//fill with zero\n if(lx=0 ;i--,j=j+2){\n bz[j]=bx[i];\n bz[j+1]=by[i];\n }\n lbz=j;\n z=0;\n for(i=0;i\nusing namespace std;\nint main(){\n int x,y,z;\n cin>>x;\n cin>>y;\n int bx[20];\n int by[20];\n int lx,ly;\n int i;\n for(i=0; x>0; i++) \n { \n bx[i]=x%2; \n x= x/2; \n }\n lx=i;\n for(i=0; y>0; i++) \n { \n by[i]=y%2; \n y= y/2; \n }\n ly=i;\n//fill with zero\n if(lx=0 ;i--,j=j+2){\n bz[j]=bx[i];\n bz[j+1]=by[i];\n }\n lbz=j;\n z=0;\n for(i=0;i\n#include\nusing namespace std;\nint main() {\n int x, y, z;\n cin >> x;\n cin >> y;\n int bx[20];\n int by[20];\n int lx, ly;\n int i;\n for (i = 0; x > 0; i++)\n {\n bx[i] = x % 2;\n x = x / 2;\n }\n lx = i;\n for (i = 0; y > 0; i++)\n {\n by[i] = y % 2;\n y = y / 2;\n }\n ly = i;\n //fill with zero\n if (lx < ly) {\n for (i = lx; i < ly; i++)\n bx[i] = 0;\n lx = ly;\n }\n else if (ly < lx) {\n for (i = ly; i < lx; i++)\n by[i] = 0;\n ly = lx;\n }\n int bz[40];\n int lbz;\n int j;\n for (i = lx - 1, j = 0; i >= 0; i--, j = j + 2) {\n bz[j] = bx[i];\n bz[j + 1] = by[i];\n }\n lbz = j;\n z = 0;\n for (i = 0; i < lbz; i++) {\n z += bz[i] * pow(2, lbz - i - 1);\n }\n cout << z;\n}",ACCEPTED,46,600 1456867147960098816,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 14:12:50,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array,int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++) \n\t{\n\t\tFDS[i] = (int*)calloc(N+1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse \n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// test income\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N+1; j++)\n\t\t{\n\t\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t\t}\n\t\tprintf(\""\\n\"");\n\t}\n\t\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历FD\n\t\t\t{\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && !ifinArray(judgeArray,N+1, FDS[j][k]))\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456867239421091840,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 14:13:11,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array,int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++) \n\t{\n\t\tFDS[i] = (int*)calloc(N+1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse \n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// test income\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N+1; j++)\n\t\t{\n\t\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t\t}\n\t\tprintf(\""\\n\"");\n\t}\n\t\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历FD\n\t\t\t{\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && !ifinArray(judgeArray,N+1, FDS[j][k]))\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456867246006149120,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 14:13:13,C++,10.0,1456179472805675009,1456166840027594752,639,"#include \n#include\nusing namespace std;\nint main() {\n int x, y, z;\n cin >> z;\n int bz[20];\n int lz;\n int i;\n for (i = 0; z > 0; i++)\n {\n bz[i] = z % 2;\n z = z / 2;\n }\n lz=i;\n if(lz%2!=0)\n bz[lz++]=0;\n int bx[20];\n int by[20];\n int lxy=lz/2;\n int j;\n for (i = lz - 1, j = 0; i >= 0; i=i-2, j++) {\n by[j] = bz[i];\n bx[j] = bz[i-1];\n }\n x = y=0;\n for (i = 0; i < lxy; i++) {\n y += bx[i] * pow(2, lxy - i - 1);\n x+=by[i]*pow(2,lxy-i-1);\n }\n cout << x<<\"" \""<\n#include \n\nint ifinArray(int* array,int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++) \n\t{\n\t\tFDS[i] = (int*)calloc(N+1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse \n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t//// test income\n\t//for (int i = 0; i < M; i++)\n\t//{\n\t//\tfor (int j = 0; j < N+1; j++)\n\t//\t{\n\t//\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历FD\n\t\t\t{\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && !ifinArray(judgeArray,N+1, FDS[j][k]))\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456868819943890944,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 14:19:28,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array,int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++) \n\t{\n\t\tFDS[i] = (int*)calloc(N+1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse \n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t//// test income\n\t//for (int i = 0; i < M; i++)\n\t//{\n\t//\tfor (int j = 0; j < N+1; j++)\n\t//\t{\n\t//\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历FD\n\t\t\t{\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && !ifinArray(judgeArray,N+1, FDS[j][k]))\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tint j;\n\t\t\tfor (int j = 1; j < N + 1; j++)\n\t\t\t{\n\t\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tif (j < N + 1)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\""True\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456868897202970624,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 14:19:47,Python,0.0,1456179472809869312,1456171992474206208,639,"dim,x,y=int(input().split())\nXlist=[]\nYlist=[]\nlist=[]\nlist1=[]\nlist2=[]\nlist3=[]\nwhile x>0:\n t=x%2\n Xlist.append(t)\n x=int(x/2)\nwhile y>0:\n t=y%2\n Ylist.append(t)\n y=int(y/2)\nwhile len(Xlist)==dim:\n Xlist.append(0)\nwhile len(Ylist)==dim:\n Ylist.append(0)\nXlist.reverse()\nYlist.reverse()\nfor i in range(len(Xlist)):\n list1.append(Xlist[i])\n list1.append(Ylist[i])\nfor i in range(0,len(list1),2):\n if str(list1[i])+str(list2[i])==\""00\"":\n list2.append(0)\n elif str(list1[i])+str(list2[i])==\""01\"":\n list2.append(1)\n elif str(list1[i])+str(list2[i])==\""10\"":\n list2.append(3)\n elif str(list1[i])+str(list2[i])==\""11\"":\n list2.append(2)\nfor i in range(0,len(list2)-1):\n if list2[i]==0:\n for j in range(i+1,len(list2)):\n if list2[j]==3:\n list2[j]=1\n elif list2[j]==1:\n list2[j]=3\n elif list2[i]==3:\n for j in range(i+1,len(list2)):\n if list2[j]==0:\n list2[j]=2\n elif list2[j]==2:\n list2[j]=0\nfor i in range(len(list2)):\n list=[]\n a=list2[i]\n while a>0:\n t=a%2\n list.append(t)\n a=int(a/2)\n while len(list)!=2:\n list.append(0)\n list.reverse()\n for j in range(len(list)):\n list3.append(list[j])\nlist3.reverse()\nh=0\nfor i in range(len(list3)):\n h=h+list3[i]*pow(2,i)\nprint(h)\n \n \n\n\n\n \n\n\n\n ",NON_ZERO_EXIT_CODE,168,3556 1456869813561372672,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 14:23:25,Python,10.0,1456179472809869312,1456171992474206208,639,"num= list(input().split())\ndim=int(num[0])\nx=int(num[1])\ny=int(num[2])\nXlist = []\nYlist = []\nlist = []\nlist1 = []\nlist2 = []\nlist3 = []\nwhile x > 0:\n t = x % 2\n Xlist.append(t)\n x = int(x / 2)\nwhile y > 0:\n t = y % 2\n Ylist.append(t)\n y = int(y / 2)\nwhile len(Xlist) != dim:\n Xlist.append(0)\nwhile len(Ylist) != dim:\n Ylist.append(0)\nXlist.reverse()\nYlist.reverse()\nfor i in range(len(Xlist)):\n list1.append(Xlist[i])\n list1.append(Ylist[i])\nfor i in range(0, len(list1), 2):\n if str(list1[i]) + str(list1[i+1]) == \""00\"":\n list2.append(0)\n elif str(list1[i]) + str(list1[i+1]) == \""01\"":\n list2.append(1)\n elif str(list1[i]) + str(list1[i+1]) == \""10\"":\n list2.append(3)\n elif str(list1[i]) + str(list1[i+1]) == \""11\"":\n list2.append(2)\nfor i in range(0, len(list2) - 1):\n if list2[i] == 0:\n for j in range(i + 1, len(list2)):\n if list2[j] == 3:\n list2[j] = 1\n elif list2[j] == 1:\n list2[j] = 3\n elif list2[i] == 3:\n for j in range(i + 1, len(list2)):\n if list2[j] == 0:\n list2[j] = 2\n elif list2[j] == 2:\n list2[j] = 0\nfor i in range(len(list2)):\n list = []\n a = list2[i]\n while a > 0:\n t = a % 2\n list.append(t)\n a = int(a / 2)\n while len(list) != 2:\n list.append(0)\n list.reverse()\n for j in range(len(list)):\n list3.append(list[j])\nlist3.reverse()\nh = 0\nfor i in range(len(list3)):\n h = h + list3[i] * pow(2, i)\nprint(h)\n\n\n\n\n\n\n\n\n\n",ACCEPTED,164,3436 1456870305386012672,0ce3bb5dc6fa29231698cafd7056fbbb19c070d1a3d48db3ae980ece9529dc16,2021-11-06 14:25:22,C++,10.0,1456179472809869313,1456174491838988288,639,"#include\n#include\n#include\nusing namespace std;\nint main(void)\n{\n\tint n, h;\n\tcin >> n >> h;\n\tstring s1 = \""\"";\n\twhile (h != 0&&n!=0)\n\t{\n\t\ts1 = to_string(h % 4) + s1;\n\t\th /= 4;\n\t\tn--;\n\t}\n\twhile (n!=0)\n\t{\n\t\ts1 = to_string(0) + s1;\n\t\tn--;\n\t}\n\n\n\tfor (int i = s1.length()-2; i >=0 ; i--)\n\t{\n\t\tif (s1[i] == '0')\n\t\t{\n\t\t\tfor (int j = i + 1; j < s1.length(); j++)\n\t\t\t{\n\t\t\t\tif (s1[j] == '1')\n\t\t\t\t\ts1[j] = '3';\n\t\t\t\telse if (s1[j] == '3')\n\t\t\t\t\ts1[j] = '1';\n\t\t\t}\n\t\t}\n\t\telse if (s1[i] == '3')\n\t\t{\n\t\t\tfor (int j = i + 1; j < s1.length(); j++)\n\t\t\t{\n\t\t\t\tif (s1[j] == '0')\n\t\t\t\t\ts1[j] = '2';\n\t\t\t\telse if (s1[j] == '2')\n\t\t\t\t\ts1[j] = '0';\n\t\t\t}\n\t\t}\n\t}\n\tstring s = \""\"";\n\tfor (int i = 0; i < s1.length(); i++)\n\t{\n\t\tif (s1[i] == '0')\n\t\t\ts.append(\""00\"");\n\t\telse if (s1[i] == '1')\n\t\t\ts.append(\""01\"");\n\t\telse if (s1[i] == '3')\n\t\t\ts.append(\""10\"");\n\t\telse if (s1[i] == '2')\n\t\t\ts.append(\""11\"");\n\t}\n\tint x=0, y=0,l=s.length()-1;\n\tfor (int j = 0; j <= l; j += 2)\n\t{\n\t\ty += (int)(s[l-j] - 48) * pow(2, j/2);\n\t\tx += (int)(s[l-j - 1] - 48) * pow(2, j /2);\n\t}\n\tcout << x << \"" \"" << y;\n}",ACCEPTED,48,640 1456871461574717440,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 14:29:58,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n PrintMatr(m);\n \n}",WRONG_ANSWER,31,360 1456871704932982784,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 14:30:56,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n printf(\""%d\\n\"", inputnum);\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n printf(\""%d\\n\"", outputnum);\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n PrintMatr(m);\n \n}",WRONG_ANSWER,35,324 1456872082420342784,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 14:32:26,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n printf(\""%s\"",input[i][input_index])\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n PrintMatr(m);\n \n}",COMPILE_ERROR,0,0 1456872103051571200,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 14:32:31,Python,1.0,1456179472805675008,1456164485751504896,639,"num=list(input().split())\nx=int(num[0])\ny=int(num[1])\nlist1=[]\nlist2=[]\nlist=[]\nwhile(x>0):\n t=x%2\n list1.append(t)\n x=int(x/2)\nwhile(y>0):\n t=y%2\n list2.append(t)\n y=int(y/2)\na=len(list1)\nb=len(list2)\nif a>b:\n while a>b:\n list2.append(0)\nelif a\n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n printf(\""%s\"",input[i][input_index]);\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n PrintMatr(m);\n \n}",WRONG_ANSWER,38,348 1456872154788864000,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 14:32:43,Python,1.0,1456179472805675008,1456164485751504896,639,"num=list(input().split())\nx=int(num[0])\ny=int(num[1])\nlist1=[]\nlist2=[]\nlist=[]\nwhile(x>0):\n t=x%2\n list1.append(t)\n x=int(x/2)\nwhile(y>0):\n t=y%2\n list2.append(t)\n y=int(y/2)\na=len(list1)\nb=len(list2)\nif a>b:\n while a>b:\n list2.append(0)\nelif a\n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules)\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n PrintMatr(m);\n \n}",COMPILE_ERROR,0,0 1456873151732981760,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 14:36:41,Python,1.0,1456179472805675008,1456164485751504896,639,"num=list(input().split())\nx=int(num[0])\ny=int(num[1])\nlist1=[]\nlist2=[]\nlist=[]\nwhile x>0:\n t=x%2\n list1.append(t)\n x=int(x/2)\nwhile y>0:\n t=y%2\n list2.append(t)\n y=int(y/2)\na=len(list1)\nb=len(list2)\nif a>b:\n while a>b:\n list2.append(0)\nelif a0:\n t=x%2\n list1.append(t)\n x=int(x/2)\nwhile y>0:\n t=y%2\n list2.append(t)\n y=int(y/2)\na=len(list1)\nb=len(list2)\nif a>b:\n while a>b:\n list2.append(0)\nelif a0:\n t=x%2\n list1.append(t)\n x=int(x/2)\nwhile y>0:\n t=y%2\n list2.append(t)\n y=int(y/2)\na=len(list1)\nb=len(list2)\nif a>b:\n \n list2.append(0)\nelif a0:\n t=x%2\n list1.append(t)\n x=int(x/2)\nwhile y>0:\n t=y%2\n list2.append(t)\n y=int(y/2)\na=len(list1)\nb=len(list2)\nif a>b:\n while len(list1)!=len(list2):\n list2.append(0)\nelif a0:\n t=x%2\n list1.append(t)\n x=int(x/2)\nwhile y>0:\n t=y%2\n list2.append(t)\n y=int(y/2)\na=len(list1)\nb=len(list2)\nif a>b:\n while len(list1)!=len(list2):\n list2.append(0)\nelif a\n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nunsigned int hilbertCurve_xyToh(unsigned int n, unsigned int x, unsigned int y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> x >> y;\n h = hilbertCurve_xyToh(n, x, y);\n \n cout << h;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nunsigned int hilbertCurve_xyToh(unsigned int n, unsigned int x, unsigned int y)\n{\n int rotateX, rotateY;\n int H = 0;\n for(int i = n / 2; i > 0; i /= 2)\n {\n rotateX = (x & i) > 0;\n rotateY = (y & i) > 0;\n H += i * i * ((3 * rotateX) ^ rotateY);\n rotateXY(n, x, y, rotateX, rotateY);\n }\n\n return H;\n}",WRONG_ANSWER,49,640 1456875732865720320,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 14:46:56,Python,0.0,1456179472809869313,1456174491838988288,639,"num=list(input().split())\ndim=int(num[0])\nh=int(num[1])\nlist1=[]\nlist2=[]\nlist=[]\nl=[]\nwhile h>0:\n t=h%2\n list.append(t)\n h=int(h/2)\nwhile len(list)!=dim*2:\n list.append(0)\nlist.reverse()\nfor i in range(0,len(list)-1,2):\n l.append(list[i]*pow(2,0)+list[i+1]*pow(2,1))\n\n \n \n\n\n ",WRONG_ANSWER,158,3432 1456875870417920000,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 14:47:29,C++,10.0,1456179472809869312,1456171992474206208,639,"// reference: Hilbert curve wikipedia\n#include \n#include \n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nunsigned int hilbertCurve_xyToh(unsigned int n, unsigned int x, unsigned int y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> x >> y;\n h = hilbertCurve_xyToh(n, x, y);\n \n cout << h;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nunsigned int hilbertCurve_xyToh(unsigned int n, unsigned int x, unsigned int y)\n{\n int rotateX, rotateY;\n int H = 0;\n n = pow(2, n);\n for(int i = n / 2; i > 0; i /= 2)\n {\n rotateX = (x & i) > 0;\n rotateY = (y & i) > 0;\n H += i * i * ((3 * rotateX) ^ rotateY);\n rotateXY(n, x, y, rotateX, rotateY);\n }\n\n return H;\n}",ACCEPTED,46,460 1456877779790376960,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 14:55:04,C++,9.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<6;i++){\n Ans = MatrMult(m, Ans);\n }\n for(int i=0;i0:\n t=h%2\n list.append(t)\n h=int(h/2)\nwhile len(list)!=dim*2:\n list.append(0)\nlist.reverse()\nfor i in range(0,len(list)-1,2):\n l.append(list[i]*pow(2,0)+list[i+1]*pow(2,1))\nfor i in range(0, len(l) - 1):\n if l[i] == 0:\n for j in range(i + 1, len(l)):\n if l[j] == 3:\n l[j] = 1\n elif l[j] == 1:\n l[j] = 3\n elif l[i] == 3:\n for j in range(i + 1, len(l)):\n if l[j] == 0:\n l[j] = 2\n elif l[j] == 2:\n l[j] = 0\nfor i in range(len(l)):\n if l[i]==0:\n list1.append(0)\n list1.append(0)\n elif l[i]==1:\n list1.append(0)\n list1.append(1)\n elif l[i]==2:\n list1.append(1)\n list1.append(1)\n elif l[i]==3:\n list1.append(1)\n list1.append(0)\nfor i in range(0,len(list1)-1,2):\n list2.append(list1[i])\n list3.append(list1[i])\nlist2.reverse()\nlist3.reverse()\nx=0\ny=0\nfor i in range(len(list2)):\n x=x+list2[i]*pow(2,i)\nfor i in range(len(list3)):\n y=y+list3[i]*pow(2,i)\nprint(\""{} {}\"",format(x,y))\n \n\n \n \n\n\n ",NON_ZERO_EXIT_CODE,173,3532 1456878031554027520,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 14:56:04,Python,0.0,1456179472809869313,1456174491838988288,639,"num=list(input().split())\ndim=int(num[0])\nh=int(num[1])\nlist1=[]\nlist2=[]\nlist3=[]\nlist=[]\nl=[]\nwhile h>0:\n t=h%2\n list.append(t)\n h=int(h/2)\nwhile len(list)!=dim*2:\n list.append(0)\nlist.reverse()\nfor i in range(0,len(list)-1,2):\n l.append(list[i]*pow(2,0)+list[i+1]*pow(2,1))\nfor i in range(0, len(l) - 1):\n if l[i] == 0:\n for j in range(i + 1, len(l)):\n if l[j] == 3:\n l[j] = 1\n elif l[j] == 1:\n l[j] = 3\n elif l[i] == 3:\n for j in range(i + 1, len(l)):\n if l[j] == 0:\n l[j] = 2\n elif l[j] == 2:\n l[j] = 0\nfor i in range(len(l)):\n if l[i]==0:\n list1.append(0)\n list1.append(0)\n elif l[i]==1:\n list1.append(0)\n list1.append(1)\n elif l[i]==2:\n list1.append(1)\n list1.append(1)\n elif l[i]==3:\n list1.append(1)\n list1.append(0)\nfor i in range(0,len(list1)-1,2):\n list2.append(list1[i])\n list3.append(list1[i])\nlist2.reverse()\nlist3.reverse()\nx=0\ny=0\nfor i in range(len(list2)):\n x=x+list2[i]*pow(2,i)\nfor i in range(len(list3)):\n y=y+list3[i]*pow(2,i)\nprint(\""{} {}\"".format(x,y))\n \n\n \n \n\n\n ",WRONG_ANSWER,171,3560 1456878044090249216,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 14:56:07,C,0.0,1456179472809869312,1456171992474206208,639,"#include \n#include\nusing namespace std;\nint main() {\n int x, y, h;\n int n;\n cin >> n >> x >> y;\n //1.Input n - bit binary representations of X and Y\n int bx[20];\n int by[20];\n int lx, ly;\n int i;\n for (i = 0; x > 0; i++)\n {\n bx[i] = x % 2;\n x = x / 2;\n }\n lx = i;\n for (i = 0; y > 0; i++)\n {\n by[i] = y % 2;\n y = y / 2;\n }\n ly = i;\n if (lx < n) {\n for (i = lx; i < n; i++)\n bx[i] = 0;\n lx = n;\n }\n if (ly < n) {\n for (i = ly; i < n; i++)\n by[i] = 0;\n ly = n;\n }\n //2-4\n int bz[20];\n int lbz;\n int j;\n for (i = n-1, j = 0; i >= 0; i--, j++) {\n bz[j] = 2*bx[i]+ by[i];\n if (bz[j] == 2)\n bz[j] = 3;\n else if (bz[j] == 3)\n bz[j] = 2;\n }\n lbz = n;\n //5 rotate\n for (i = 0; i < n; i++) {\n if (bz[i] == 0) {\n for (j = i + 1; j < n; j++) {\n if (bz[j] == 1)\n bz[j] = 3;\n if (bz[j] == 3)\n bz[j] == 1;\n }\n }\n else if (bz[i] == 3) {\n for (j = i + 1; j < n; j++) {\n if (bz[j] == 0)\n bz[j] = 2;\n if (bz[j] == 2)\n bz[j] == 0;\n }\n }\n }\n\n //change back to 2b\n int bh[40];\n int lbh;\n for (i = 0, j = 0; i < n;i++,j=j+2) {\n bh[j] = bz[i] / 2;\n bh[j + 1] = bz[i] % 2;\n }\n lbh = j;\n h = 0;\n for (i = 0; i < lbh; i++) {\n h += bh[i] * pow(2, lbh - i - 1);\n }\n cout << h;\n}",COMPILE_ERROR,0,0 1456878075371368448,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 14:56:15,C++,6.0,1456179472809869312,1456171992474206208,639,"#include \n#include\nusing namespace std;\nint main() {\n int x, y, h;\n int n;\n cin >> n >> x >> y;\n //1.Input n - bit binary representations of X and Y\n int bx[20];\n int by[20];\n int lx, ly;\n int i;\n for (i = 0; x > 0; i++)\n {\n bx[i] = x % 2;\n x = x / 2;\n }\n lx = i;\n for (i = 0; y > 0; i++)\n {\n by[i] = y % 2;\n y = y / 2;\n }\n ly = i;\n if (lx < n) {\n for (i = lx; i < n; i++)\n bx[i] = 0;\n lx = n;\n }\n if (ly < n) {\n for (i = ly; i < n; i++)\n by[i] = 0;\n ly = n;\n }\n //2-4\n int bz[20];\n int lbz;\n int j;\n for (i = n-1, j = 0; i >= 0; i--, j++) {\n bz[j] = 2*bx[i]+ by[i];\n if (bz[j] == 2)\n bz[j] = 3;\n else if (bz[j] == 3)\n bz[j] = 2;\n }\n lbz = n;\n //5 rotate\n for (i = 0; i < n; i++) {\n if (bz[i] == 0) {\n for (j = i + 1; j < n; j++) {\n if (bz[j] == 1)\n bz[j] = 3;\n if (bz[j] == 3)\n bz[j] == 1;\n }\n }\n else if (bz[i] == 3) {\n for (j = i + 1; j < n; j++) {\n if (bz[j] == 0)\n bz[j] = 2;\n if (bz[j] == 2)\n bz[j] == 0;\n }\n }\n }\n\n //change back to 2b\n int bh[40];\n int lbh;\n for (i = 0, j = 0; i < n;i++,j=j+2) {\n bh[j] = bz[i] / 2;\n bh[j + 1] = bz[i] % 2;\n }\n lbh = j;\n h = 0;\n for (i = 0; i < lbh; i++) {\n h += bh[i] * pow(2, lbh - i - 1);\n }\n cout << h;\n}",PARTIAL_ACCEPTED,52,484 1456878244201046016,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 14:56:55,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf_s(\""%d %d\"", &N, &M);\n\tscanf_s(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf_s(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf_s(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//for (int i = 0; i < M; i++) {\n\t//\tint j = 0;\n\t//\twhile (a[i][j] != 0) {\n\t//\t\tprintf(\""%d\"", a[i][j]);\n\t//\t\tj++;\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\t/*printf(\""左边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key1[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""右边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key2[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定不是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key3[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}*/\n\n\n\n\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456878334605074432,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 14:57:17,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//for (int i = 0; i < M; i++) {\n\t//\tint j = 0;\n\t//\twhile (a[i][j] != 0) {\n\t//\t\tprintf(\""%d\"", a[i][j]);\n\t//\t\tj++;\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\t/*printf(\""左边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key1[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""右边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key2[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定不是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key3[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}*/\n\n\n\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,41,488 1456878637538127872,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 14:58:29,C++,0.0,1456179472809869313,1456174491838988288,639,"// reference: Hilbert curve wikipedia\n#include \n#include \n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> h;\n h = hilbertCurve_xyToh(n, x, y);\n \n cout << x << y;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y)\n{\n int rotateX, rotateY;\n int _h = h;\n n = pow(2, n); // number of cubes\n for(int i = 1; i < n; i *= 2)\n {\n rotateX = 1 & (t / 2);\n rotateY = 1 & (t ^ rotateX);\n rotateXY(i, x, y, rotateX, rotateY);\n\n x += i * rotateX;\n y += i * rotateY;\n t /= 4;\n }\n}",COMPILE_ERROR,0,0 1456878742047600640,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 14:58:54,C++,0.0,1456179472809869313,1456174491838988288,639,"// reference: Hilbert curve wikipedia\n#include \n#include \n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> h;\n h = hilbertCurve_hToxy(n, x, y);\n \n cout << x << y;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y)\n{\n int rotateX, rotateY;\n int _h = h;\n n = pow(2, n); // number of cubes\n for(int i = 1; i < n; i *= 2)\n {\n rotateX = 1 & (t / 2);\n rotateY = 1 & (t ^ rotateX);\n rotateXY(i, x, y, rotateX, rotateY);\n\n x += i * rotateX;\n y += i * rotateY;\n t /= 4;\n }\n}",COMPILE_ERROR,0,0 1456878818992660480,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 14:59:12,C++,0.0,1456179472809869313,1456174491838988288,639,"// reference: Hilbert curve wikipedia\n#include \n#include \n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> h;\n h = hilbertCurve_hToxy(n, h, x, y);\n \n cout << x << y;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y)\n{\n int rotateX, rotateY;\n int _h = h;\n n = pow(2, n); // number of cubes\n for(int i = 1; i < n; i *= 2)\n {\n rotateX = 1 & (t / 2);\n rotateY = 1 & (t ^ rotateX);\n rotateXY(i, x, y, rotateX, rotateY);\n\n x += i * rotateX;\n y += i * rotateY;\n t /= 4;\n }\n}",COMPILE_ERROR,0,0 1456878893990457344,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 14:59:30,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[10000], hou[10000];\n\tint a[10000][10000], b[10000][10000], Key[10000], Key1[10000], Key2[10000], Key3[10000], record[10000];\n\n\tfor (int i = 0; i < 10000; i++)\n\t{\n\t\tfor (int j = 0; j < 10000; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//for (int i = 0; i < M; i++) {\n\t//\tint j = 0;\n\t//\twhile (a[i][j] != 0) {\n\t//\t\tprintf(\""%d\"", a[i][j]);\n\t//\t\tj++;\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\t/*printf(\""左边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key1[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""右边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key2[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定不是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key3[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}*/\n\n\n\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,30,324 1456878947552272384,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 14:59:43,C++,0.0,1456179472809869313,1456174491838988288,639,"// reference: Hilbert curve wikipedia\n#include \n#include \n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> h;\n hilbertCurve_hToxy(n, h, x, y);\n \n cout << x << y;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y)\n{\n int rotateX, rotateY;\n int _h = h;\n n = pow(2, n); // number of cubes\n for(int i = 1; i < n; i *= 2)\n {\n rotateX = 1 & (t / 2);\n rotateY = 1 & (t ^ rotateX);\n rotateXY(i, x, y, rotateX, rotateY);\n\n x += i * rotateX;\n y += i * rotateY;\n t /= 4;\n }\n}",COMPILE_ERROR,0,0 1456878982737735680,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 14:59:51,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[10000], hou[10000];\n\tint a[10000][10000], b[10000][10000], Key[10000], Key1[10000], Key2[10000], Key3[10000], record[10000];\n\n\tfor (int i = 0; i < 10000; i++)\n\t{\n\t\tfor (int j = 0; j < 10000; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//for (int i = 0; i < M; i++) {\n\t//\tint j = 0;\n\t//\twhile (a[i][j] != 0) {\n\t//\t\tprintf(\""%d\"", a[i][j]);\n\t//\t\tj++;\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\t/*printf(\""左边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key1[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""右边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key2[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定不是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key3[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}*/\n\n\n\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,27,512 1456879072106323968,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:00:12,C++,0.0,1456179472809869313,1456174491838988288,639,"// reference: Hilbert curve wikipedia\n#include \n#include \n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> h;\n hilbertCurve_hToxy(n, h, x, y);\n \n cout << x << y;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y)\n{\n unsigned int rotateX, rotateY;\n unsigned int _h = h;\n n = pow(2, n); // number of cubes\n for(unsigned int i = 1; i < n; i *= 2)\n {\n rotateX = 1 & (t / 2);\n rotateY = 1 & (t ^ rotateX);\n rotateXY(i, x, y, rotateX, rotateY);\n\n x += i * rotateX;\n y += i * rotateY;\n t /= 4;\n }\n}",COMPILE_ERROR,0,0 1456879131891380224,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 15:00:27,C++,9.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<20;i++){\n Ans = MatrMult(m, Ans);\n }\n for(int i=0;i\n#include \n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> h;\n hilbertCurve_hToxy(n, h, x, y);\n \n cout << x << y;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y)\n{\n unsigned int rotateX, rotateY;\n unsigned int _h = h;\n n = pow(2, n); // number of cubes\n for(unsigned int i = 1; i < n; i *= 2)\n {\n rotateX = 1 & (_h / 2);\n rotateY = 1 & (_h ^ rotateX);\n rotateXY(i, x, y, rotateX, rotateY);\n\n x += i * rotateX;\n y += i * rotateY;\n _h /= 4;\n }\n}",PRESENTATION_ERROR,47,612 1456879215840374784,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 15:00:47,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[1000000], hou[1000000];\n\tint a[1000000][1000000], b[1000000][1000000], Key[1000000], Key1[1000000], Key2[1000000], Key3[1000000], record[1000000];\n\n\tfor (int i = 0; i < 1000000; i++)\n\t{\n\t\tfor (int j = 0; j < 1000000; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//for (int i = 0; i < M; i++) {\n\t//\tint j = 0;\n\t//\twhile (a[i][j] != 0) {\n\t//\t\tprintf(\""%d\"", a[i][j]);\n\t//\t\tj++;\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,35,380 1456879241765920768,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:00:53,C++,10.0,1456179472809869313,1456174491838988288,639,"// reference: Hilbert curve wikipedia\n#include \n#include \n\nusing namespace std;\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY);\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y);\n\n\n\nint main()\n{\n unsigned int x = 0, y = 0, n = 0;\n unsigned int h = 0;\n\n cin >> n >> h;\n hilbertCurve_hToxy(n, h, x, y);\n \n cout << x << \"" \"" << y;\n\n}\n\n\n\n\nvoid rotateXY(unsigned int n, unsigned int& x, unsigned int& y,\n unsigned int rotateX, unsigned int rotateY)\n{\n if(rotateY == 0)\n {\n // swap x and y\n unsigned int temp = x;\n x = y;\n y = temp;\n\n if(rotateX == 1)\n {\n x = n - 1 - x;\n y = n - 1 - y;\n }\n }\n}\n\nvoid hilbertCurve_hToxy(unsigned int n, unsigned int h,\n unsigned int& x, unsigned int& y)\n{\n unsigned int rotateX, rotateY;\n unsigned int _h = h;\n n = pow(2, n); // number of cubes\n for(unsigned int i = 1; i < n; i *= 2)\n {\n rotateX = 1 & (_h / 2);\n rotateY = 1 & (_h ^ rotateX);\n rotateXY(i, x, y, rotateX, rotateY);\n\n x += i * rotateX;\n y += i * rotateY;\n _h /= 4;\n }\n}",ACCEPTED,51,488 1456879328608985088,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 15:01:14,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[1000000], hou[1000000];\n\tint a[1000000][1000000], b[1000000][1000000], Key[1000000], Key1[1000000], Key2[1000000], Key3[1000000], record[1000000];\n\n\tfor (int i = 0; i < 1000000; i++)\n\t{\n\t\tfor (int j = 0; j < 1000000; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//for (int i = 0; i < M; i++) {\n\t//\tint j = 0;\n\t//\twhile (a[i][j] != 0) {\n\t//\t\tprintf(\""%d\"", a[i][j]);\n\t//\t\tj++;\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,31,332 1456880746488705024,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 15:06:52,C,1.0,1456179472805675008,1456164485751504896,639,"#include \n#include \nint dectobin(int n) {\n\t\n\tint sum = 0;\n\tint y, x = 1; //y表示余数,x为叠加的系数\n\twhile (n != 0) {\n\t\ty = n % 2;\n\t\tsum += x * y;\n\t\tx *= 10;\n\t\tn /= 2;\n\t}\n\treturn sum;\n}\n\nint main(void)\n{\n\tint x, y;\n\tscanf(\""%d %d\"", &x, &y);\n\tint bin_x, bin_y;\n\tbin_x = dectobin(x);\n\tbin_y = dectobin(y);\n\n\t// length of max\n\tint temp = bin_x;\n\tif (bin_x > bin_y)\n\t{\n\t\ttemp = bin_x;\n\t}\n\telse\n\t{\n\t\ttemp = bin_y;\n\t}\n\tint count = 0;\n\tint divider = 1;\n\twhile (temp)\n\t{\n\t\ttemp /= 10;\n\t\tdivider *= 10;\n\t\tcount++;\n\t}\n\t//printf(\""%d\"",divider);\n\tint* bin_output = (int*)malloc(sizeof(int)*count*2);\n\n\tint flag1 = 0, flag2 = 0;\n\tfor (int i = 0; i < count * 2; i=i+2)\n\t{\n\t\tdivider /= 10;\n\t\t//处理x\n\t\tbin_output[i] = bin_x / divider;\n\t\tif (bin_output[i] == 1)\n\t\t{\n\t\t\tflag1 = 1;\n\t\t\tbin_x /= 10;\n\t\t}\n\t\t\n\t\t//处理y\n\t\tbin_output[i+1] = bin_y / divider;\n\t\tif (bin_output[i+1] == 1)\n\t\t{\n\t\t\tflag1 = 1;\n\t\t\tbin_y /= 10;\n\t\t}\n\t}\n\t/*for (int i = 0; i < count * 2; i++)\n\t{\n\t\tprintf(\""%d\"", bin_output[i]);\n\t}*/\n\tint sum = 0;\n\tfor (int i = 0; i < count*2; i++)\n\t{\n\t\tsum = sum * 2 + bin_output[i];\n\t}\n\n\tprintf(\""%d\"", sum);\n}",PARTIAL_ACCEPTED,72,512 1456881078585860096,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 15:08:11,Python,0.0,1456179472809869313,1456174491838988288,639,"num=list(input().split())\ndim=int(num[0])\nh=int(num[1])\nlist1=[]\nlist2=[]\nlist3=[]\nlist=[]\nl=[]\nwhile h>0:\n t=h%2\n list.append(t)\n h=int(h/2)\nwhile len(list)!=dim*2:\n list.append(0)\nlist.reverse()\nfor i in range(0,len(list)-1,2):\n l.append(list[i]*1+list[i+1]*2)\nfor i in range(0, len(l)-1):\n if l[i] == 0:\n for j in range(i + 1, len(l)):\n if l[j] == 3:\n l[j] = 1\n elif l[j] == 1:\n l[j] = 3\n elif l[i] == 3:\n for j in range(i + 1, len(l)):\n if l[j] == 0:\n l[j] = 2\n elif l[j] == 2:\n l[j] = 0\nfor i in range(len(l)):\n if l[i]==0:\n list1.append(0)\n list1.append(0)\n elif l[i]==1:\n list1.append(0)\n list1.append(1)\n elif l[i]==2:\n list1.append(1)\n list1.append(1)\n elif l[i]==3:\n list1.append(1)\n list1.append(0)\nfor i in range(0,len(list1)-1,2):\n list2.append(list1[i])\n list3.append(list1[i])\nlist2.reverse()\nlist3.reverse()\nx=0\ny=0\nfor i in range(len(list2)):\n x=x+list2[i]*pow(2,i)\nfor i in range(len(list3)):\n y=y+list3[i]*pow(2,i)\nprint(\""{} {}\"".format(x,y))\n \n\n \n \n\n\n ",WRONG_ANSWER,211,3528 1456881406014201856,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 15:09:29,C++,9.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<21;i++){\n Ans = MatrMult(m, Ans);\n }\n for(int i=0;i\n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<30;i++){\n Ans = MatrMult(m, Ans);\n }\n for(int i=0;i\n#include\nusing namespace std;\nint main() {\n int x, y, h;\n int n;\n cin >> n >> x >> y;\n //1.Input n - bit binary representations of X and Y\n int bx[20];\n int by[20];\n int lx, ly;\n int i;\n for (i = 0; x > 0; i++)\n {\n bx[i] = x % 2;\n x = x / 2;\n }\n lx = i;\n for (i = 0; y > 0; i++)\n {\n by[i] = y % 2;\n y = y / 2;\n }\n ly = i;\n if (lx < n) {\n for (i = lx; i < n; i++)\n bx[i] = 0;\n lx = n;\n }\n if (ly < n) {\n for (i = ly; i < n; i++)\n by[i] = 0;\n ly = n;\n }\n //2-4\n int bz[20];\n int lbz;\n int j;\n for (i = n-1, j = 0; i >= 0; i--, j++) {\n bz[j] = 2*bx[i]+ by[i];\n if (bz[j] == 2)\n bz[j] = 3;\n else if (bz[j] == 3)\n bz[j] = 2;\n }\n lbz = n;\n //5 rotate\n for (i = 0; i < n; i++) {\n if (bz[i] == 0) {\n for (j = i + 1; j < n; j++) {\n if (bz[j] == 1)\n bz[j] = 3;\n else if (bz[j] == 3)\n bz[j] = 1;\n }\n }\n else if (bz[i] == 3) {\n for (j = i + 1; j < n; j++) {\n if (bz[j] == 0)\n bz[j] = 2;\n else if (bz[j] == 2)\n bz[j] = 0;\n }\n }\n }\n\n //change back to 2b\n int bh[40];\n int lbh;\n for (i = 0, j = 0; i < n;i++,j=j+2) {\n bh[j] = bz[i] / 2;\n bh[j + 1] = bz[i] % 2;\n }\n lbh = j;\n h = 0;\n for (i = 0; i < lbh; i++) {\n h += bh[i] * pow(2, lbh - i - 1);\n }\n cout << h;\n}\n",ACCEPTED,67,604 1456884782453534720,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 15:22:54,Python,0.0,1456179472809869313,1456174491838988288,639,"num=list(input().split())\ndim=int(num[0])\nh=int(num[1])\nlist1=[]\nlist2=[]\nlist3=[]\nlist=[]\nl=[]\nwhile h>0:\n t=h%2\n list.append(t)\n h=int(h/2)\nwhile len(list)!=dim*2:\n list.append(0)\nlist.reverse()\nfor i in range(0,len(list)-1):\n if str(list[i])+str(list[i+1])==\""00\"":\n list2.append(0)\n list3.append(0)\n if str(list[i])+str(list[i+1])==\""10\"":\n list2.append(1)\n list3.append(1)\n if str(list[i])+str(list[i+1])==\""01\"":\n list2.append(0)\n list3.append(1)\n if str(list[i])+str(list[i+1])==\""11\"":\n list2.append(1)\n list3.append(0)\nx=0\ny=0\nfor i in range(len(list2)):\n x=x+list2[i]*pow(2,i)\nfor i in range(len(list3)):\n y=y+list3[i]*pow(2,i)\nprint(\""{} {}\"".format(x,y))\n \n\n \n \n\n\n ",WRONG_ANSWER,175,3672 1456885909387522048,0ce3bb5dc6fa29231698cafd7056fbbb19c070d1a3d48db3ae980ece9529dc16,2021-11-06 15:27:23,C++,10.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n#include\nusing namespace std;\n\nbool IsBCNF(string key, int i,string* A, string* B);\nbool Find(string s, vector& items);\nbool Find(char c, vector& items);\n\n\nint n, m; //m is the number of FDs\nint main(void)\n{\n\n\tcin >> n >> m;\n\t\n\tstring *A=new string[m];\n\tstring* B = new string[m];\n\tstring temp;\n\n\t//input\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tcin >> A[i];\n\t\tcin >> temp;\n\t\tcin >> B[i];\n\t}\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tbool flag=IsBCNF(A[i],i, A, B);\n\t\tif (flag == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\t\t\n\t}\n\tcout << \""True\"";\n\treturn 0;\n}\nbool IsBCNF(string key,int index, string* A, string* B) //看这个key是不是整个的key\n{\n\tvector items; //store different key \n\tint* indexes = new int[m];\n\tstring s;\n\t\n\tfor (int i = 0; i < m; i++)\n\t\tindexes[i] = 0;\n\tindexes[index] = 1;\n\titems.push_back(key);\n\titems.push_back(B[index]);\n\t \n\tint change=1;\n\twhile (change)\n\t{\n\t\tchange = 0;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tif (indexes[j])\n\t\t\t\tcontinue;\n\t\t\ts = A[j];\n\t\t\tif (Find(s, items))\n\t\t\t{\n\t\t\t\tindexes[j] = 1; //表示第i个函数依赖是否实现\n\t\t\t\titems.push_back(B[j]);\n\t\t\t\tchange++;\n\t\t\t}\n\t\t}\n\t}\n\n\tdelete[]indexes;\n\tint count;\n\t//check if all the element has been find\n\tfor (int i = 0; i & items)\n{\n\tint flag;\n\tfor (int i = 0; i< s.length(); i++)\n\t{\n\t\tflag = 0;\n\t\tchar c = s[i];\n\t\tfor (int j = 0; j < items.size(); j++)\n\t\t{\n\t\t\tif (items[j].find(c)!= string::npos) //contains this char\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (!flag)\n\t\t\treturn false;\n\t}\n\treturn true;\n}\n\nbool Find(char c, vector& items)\n{\n\tfor (int j = 0; j < items.size(); j++)\n\t{\n\t\tif (items[j].find(c)!= string::npos) //contains this char\n\t\t{\n\t\t\t\n\t\t\treturn true;\n\t\t}\n\t}\n\treturn false;\n}",ACCEPTED,64,512 1456886972455395328,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 15:31:36,C,0.0,1456179472805675008,1456164485751504896,639,"#include\nint main()\n{\n\tint x, y, x2[100], y2[100], xl, yl, z2[200], z;\n\txl = yl = 0;\n\tz = 0;\n\n\tscanf(\""%d %d\"", &x, &y);\n\n\twhile (x / 2)\n\t{\n\t\tx2[xl] = x % 2;\n\t\txl++;\n\t\tx /= 2;\n\t}\n\tx2[xl] = x;\n\txl++;\n\n\twhile (y / 2)\n\t{\n\t\ty2[yl] = y % 2;\n\t\tyl++;\n\t\ty /= 2;\n\t}\n\ty2[yl] = y;\n\tyl++;\n\n\tif (xl < yl)\n\t{\n\t\tfor (int i = xl; i= 0; f--)\n\t\t{\n\t\t\tz = z*2 + z2[f];\n\t\t}\n\t}\n\telse\n\t{\n\t\tfor (int i = yl; i < xl; i++)\n\t\t{\n\t\t y2[i] = 0;\n\t\t}\n\t\tint k = 0;\n\t\tint j = 0;\n\t\tfor (j; j < xl * 2; j = j + 2)\n\t\t{\n\t\t\tz2[j] = y2[k];\n\t\t\tz2[j + 1] = x2[k];\n\t\t\tk++;\n\t\t}\n\t\tfor (int f = j - 1; f >= 0; f--)\n\t\t{\n\t\t\tz = z * 2 + z2[f];\n\t\t}\n\n\t}\n\n\tprintf(\""%d\"", z);\n}",COMPILE_ERROR,0,0 1456886993405390848,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 15:31:41,C++,0.0,1456179472805675008,1456164485751504896,639,"#include\nint main()\n{\n\tint x, y, x2[100], y2[100], xl, yl, z2[200], z;\n\txl = yl = 0;\n\tz = 0;\n\n\tscanf(\""%d %d\"", &x, &y);\n\n\twhile (x / 2)\n\t{\n\t\tx2[xl] = x % 2;\n\t\txl++;\n\t\tx /= 2;\n\t}\n\tx2[xl] = x;\n\txl++;\n\n\twhile (y / 2)\n\t{\n\t\ty2[yl] = y % 2;\n\t\tyl++;\n\t\ty /= 2;\n\t}\n\ty2[yl] = y;\n\tyl++;\n\n\tif (xl < yl)\n\t{\n\t\tfor (int i = xl; i= 0; f--)\n\t\t{\n\t\t\tz = z*2 + z2[f];\n\t\t}\n\t}\n\telse\n\t{\n\t\tfor (int i = yl; i < xl; i++)\n\t\t{\n\t\t y2[i] = 0;\n\t\t}\n\t\tint k = 0;\n\t\tint j = 0;\n\t\tfor (j; j < xl * 2; j = j + 2)\n\t\t{\n\t\t\tz2[j] = y2[k];\n\t\t\tz2[j + 1] = x2[k];\n\t\t\tk++;\n\t\t}\n\t\tfor (int f = j - 1; f >= 0; f--)\n\t\t{\n\t\t\tz = z * 2 + z2[f];\n\t\t}\n\n\t}\n\n\tprintf(\""%d\"", z);\n}",COMPILE_ERROR,0,0 1456887045759246336,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 15:31:54,C++,10.0,1456179472805675008,1456164485751504896,639,"#include\nint main()\n{\n\tint x, y, x2[100], y2[100], xl, yl, z2[200], z;\n\txl = yl = 0;\n\tz = 0;\n\n\tscanf(\""%d %d\"", &x, &y);\n\n\twhile (x / 2)\n\t{\n\t\tx2[xl] = x % 2;\n\t\txl++;\n\t\tx /= 2;\n\t}\n\tx2[xl] = x;\n\txl++;\n\n\twhile (y / 2)\n\t{\n\t\ty2[yl] = y % 2;\n\t\tyl++;\n\t\ty /= 2;\n\t}\n\ty2[yl] = y;\n\tyl++;\n\n\tif (xl < yl)\n\t{\n\t\tfor (int i = xl; i= 0; f--)\n\t\t{\n\t\t\tz = z*2 + z2[f];\n\t\t}\n\t}\n\telse\n\t{\n\t\tfor (int i = yl; i < xl; i++)\n\t\t{\n\t\t y2[i] = 0;\n\t\t}\n\t\tint k = 0;\n\t\tint j = 0;\n\t\tfor (j; j < xl * 2; j = j + 2)\n\t\t{\n\t\t\tz2[j] = y2[k];\n\t\t\tz2[j + 1] = x2[k];\n\t\t\tk++;\n\t\t}\n\t\tfor (int f = j - 1; f >= 0; f--)\n\t\t{\n\t\t\tz = z * 2 + z2[f];\n\t\t}\n\n\t}\n\n\tprintf(\""%d\"", z);\n}",ACCEPTED,93,640 1456887437166948352,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 15:33:27,C,3.0,1456179472805675008,1456164485751504896,639,"#include \n#include \nint dectobin(int n, int* array) {\n\tint count = 0;\n\tint y, x = 1; //y表示余数,x为叠加的系数\n\twhile (n != 0) {\n\t\ty = n % 2;\n\t\tarray[count]=y;\n\t\tn /= 2;\n\t\tcount++;\n\t}\n\t/*for (int i = 0; i < count; i++)\n\t{\n\t\tprintf(\""%d\"", array[i]);\n\t}*/\n\treturn count;\n}\n\nint main(void)\n{\n\tint x, y;\n\tscanf(\""%d %d\"", &x, &y);\n\tint bin_x[10] = { 0 }; \n\tint bin_y[10] = { 0 };\n\n\tint bin_x_count = dectobin(x, bin_x);\n\tint bin_y_count = dectobin(y, bin_y);\n\n\t// printf(\""%d %d\"", bin_x_count, bin_y_count);\n\t// length of max\n\t\n\t/*for (int i = 0; i < bin_x_count; i++)\n\t{\n\t\tprintf(\""%d\"", bin_x[i]);\n\t}\n\tprintf(\""\\n\"");\n\tfor (int i = 0; i < bin_y_count; i++)\n\t{\n\t\tprintf(\""%d\"", bin_y[i]);\n\t}*/\n\tint count = 0;\n\tif (bin_x_count >= bin_y_count)\n\t{\n\t\tcount = bin_x_count;\n\t}\n\telse\n\t{\n\t\tcount = bin_y_count;\n\t}\n\t\n\tint* bin_output = (int*)malloc(sizeof(int)*count*2);\n\tint c = 0;\n\tfor (int i = 0; i < count * 2; i = i + 2)\n\t{\n\t\tbin_output[i] = bin_x[bin_x_count - 1 - c];\n\t\tbin_output[i+1] = bin_y[bin_y_count - 1 - c];\n\t\tc++;\n\t}\n\n\n\tfor (int i = 0; i < count * 2; i++)\n\t{\n\t\t//printf(\""\\n%d\"", bin_output[i]);\n\t}\n\tint sum = 0;\n\tfor (int i = 0; i < count*2; i++)\n\t{\n\t\tsum = sum * 2 + bin_output[i];\n\t}\n\n\tprintf(\""%d\"", sum);\n}",PARTIAL_ACCEPTED,63,352 1456887805247037440,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 15:34:55,Python,0.0,1456179472809869313,1456174491838988288,639,"num=list(input().split())\ndim=int(num[0])\nh=int(num[1])\nlist1=[]\nlist2=[]\nlist3=[]\nlist=[]\nl=[]\nwhile h>0:\n t=h%2\n list.append(t)\n h=int(h/2)\nwhile len(list)!=dim*2:\n list.append(0)\nlist.reverse()\nfor i in range(0,len(list)-1,2):\n l.append(list[i]+list[i+1]*2)\nfor i in range(len(list)-1,-1,-1):\n if l[i] == 0:\n for j in range(i + 1, len(l)):\n if l[j] == 3:\n l[j] = 1\n elif l[j] == 1:\n l[j] = 3\n elif l[i] == 3:\n for j in range(i + 1, len(l)):\n if l[j] == 0:\n l[j] = 2\n elif l[j] == 2:\n l[j] = 0\nfor i in range(0,len(l)):\n if l[i]==0:\n list1.append(0)\n list1.append(0)\n if l[i]==1:\n list1.append(0)\n list1.append(1)\n if l[i]==3:\n list1.append(1)\n list1.append(0)\n if l[i]==2:\n list1.append(1)\n list1.append(1)\nfor i in range(0,len(list)-1,2):\n list2.append(list1[i])\n list3.append(list1[i+1])\nlist2.reverse()\nlist3.reverse()\nx=0\ny=0\nfor i in range(len(list2)):\n x=x+list2[i]*pow(2,i)\nfor i in range(len(list3)):\n y=y+list3[i]*pow(2,i)\nprint(\""{} {}\"".format(x,y))\n \n\n \n \n\n\n ",NON_ZERO_EXIT_CODE,211,3556 1456887811382751232,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 15:34:56,C++,6.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tWriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<30;i++){\n Ans = MatrMult(m, Ans);\n }\n for(int i=0;i0:\n t=h%2\n list.append(t)\n h=int(h/2)\nwhile len(list)!=dim*2:\n list.append(0)\nlist.reverse()\nfor i in range(0,len(list)-1,2):\n l.append(list[i]+list[i+1]*2)\nfor i in range(len(l)-1,-1,-1):\n if l[i] == 0:\n for j in range(i + 1, len(l)):\n if l[j] == 3:\n l[j] = 1\n elif l[j] == 1:\n l[j] = 3\n elif l[i] == 3:\n for j in range(i + 1, len(l)):\n if l[j] == 0:\n l[j] = 2\n elif l[j] == 2:\n l[j] = 0\nfor i in range(0,len(l)):\n if l[i]==0:\n list1.append(0)\n list1.append(0)\n if l[i]==1:\n list1.append(0)\n list1.append(1)\n if l[i]==3:\n list1.append(1)\n list1.append(0)\n if l[i]==2:\n list1.append(1)\n list1.append(1)\nfor i in range(0,len(list)-1,2):\n list2.append(list1[i])\n list3.append(list1[i+1])\nlist2.reverse()\nlist3.reverse()\nx=0\ny=0\nfor i in range(len(list2)):\n x=x+list2[i]*pow(2,i)\nfor i in range(len(list3)):\n y=y+list3[i]*pow(2,i)\nprint(\""{} {}\"".format(x,y))\n \n\n \n \n\n\n ",WRONG_ANSWER,191,3460 1456888395662434304,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 15:37:15,C,10.0,1456179472805675008,1456164485751504896,639,"#include \n#include \nint dectobin(int n, int* array) {\n\tint count = 0;\n\tint y, x = 1; //y表示余数,x为叠加的系数\n\twhile (n != 0) {\n\t\ty = n % 2;\n\t\tarray[count]=y;\n\t\tn /= 2;\n\t\tcount++;\n\t}\n\t/*for (int i = 0; i < count; i++)\n\t{\n\t\tprintf(\""%d\"", array[i]);\n\t}*/\n\treturn count;\n}\n\nint main(void)\n{\n\tint x, y;\n\tscanf(\""%d %d\"", &x, &y);\n\tint* bin_x = (int*)calloc(10,sizeof(int)); \n\tint* bin_y = (int*)calloc(10, sizeof(int));\n\n\tint bin_x_count = dectobin(x, bin_x);\n\tint bin_y_count = dectobin(y, bin_y);\n\n\t// printf(\""%d %d\"", bin_x_count, bin_y_count);\n\t// length of max\n\t\n\t/*for (int i = 0; i < bin_x_count; i++)\n\t{\n\t\tprintf(\""%d\"", bin_x[i]);\n\t}\n\tprintf(\""\\n\"");\n\tfor (int i = 0; i < bin_y_count; i++)\n\t{\n\t\tprintf(\""%d\"", bin_y[i]);\n\t}*/\n\tint count = 0;\n\tif (bin_x_count >= bin_y_count)\n\t{\n\t\tcount = bin_x_count;\n\t}\n\telse\n\t{\n\t\tcount = bin_y_count;\n\t}\n\t\n\tint* bin_output = (int*)calloc(count*2, sizeof(int));\n\tint c = 0;\n\tfor (int i = 0; i < count * 2; i = i + 2)\n\t{\n\t\tbin_output[i] = bin_x[count - 1 - c];\n\t\tbin_output[i+1] = bin_y[count - 1 - c];\n\t\tc++;\n\t}\n\n\n\tfor (int i = 0; i < count * 2; i++)\n\t{\n\t\t//printf(\""\\n%d\"", bin_output[i]);\n\t}\n\tint sum = 0;\n\tfor (int i = 0; i < count*2; i++)\n\t{\n\t\tsum = sum * 2 + bin_output[i];\n\t}\n\n\tprintf(\""%d\"", sum);\n}",ACCEPTED,73,484 1456889216894021632,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 15:40:31,C,10.0,1456179472805675009,1456166840027594752,639,"#include \n#include \nint dectobin(int n, int* array) {\n\tint count = 0;\n\tint y, x = 1; //y表示余数,x为叠加的系数\n\twhile (n != 0) {\n\t\ty = n % 2;\n\t\tarray[count]=y;\n\t\tn /= 2;\n\t\tcount++;\n\t}\n\t/*for (int i = 0; i < count; i++)\n\t{\n\t\tprintf(\""%d\"", array[i]);\n\t}*/\n\treturn count;\n}\n\nint main(void)\n{\n\tint z = 0;\n\tscanf(\""%d\"", &z);\n\tfor (int m = 0; m < 100; m++)\n\t{\n\t\tfor (int n = 0; n < 100; n++)\n\t\t{\n\t\t\tint x, y;\n\t\t\tx = m; y = n;\n\t\t\tint* bin_x = (int*)calloc(10, sizeof(int));\n\t\t\tint* bin_y = (int*)calloc(10, sizeof(int));\n\n\t\t\tint bin_x_count = dectobin(x, bin_x);\n\t\t\tint bin_y_count = dectobin(y, bin_y);\n\n\t\t\tint count = 0;\n\t\t\tif (bin_x_count >= bin_y_count)\n\t\t\t{\n\t\t\t\tcount = bin_x_count;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcount = bin_y_count;\n\t\t\t}\n\n\t\t\tint* bin_output = (int*)calloc(count * 2, sizeof(int));\n\t\t\tint c = 0;\n\t\t\tfor (int i = 0; i < count * 2; i = i + 2)\n\t\t\t{\n\t\t\t\tbin_output[i] = bin_x[count - 1 - c];\n\t\t\t\tbin_output[i + 1] = bin_y[count - 1 - c];\n\t\t\t\tc++;\n\t\t\t}\n\n\n\t\t\tfor (int i = 0; i < count * 2; i++)\n\t\t\t{\n\t\t\t\t//printf(\""\\n%d\"", bin_output[i]);\n\t\t\t}\n\t\t\tint sum = 0;\n\t\t\tfor (int i = 0; i < count * 2; i++)\n\t\t\t{\n\t\t\t\tsum = sum * 2 + bin_output[i];\n\t\t\t}\n\n\t\t\tif (sum == z)\n\t\t\t{\n\t\t\t\tprintf(\""%d %d\"", x, y);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\n\n\n}",ACCEPTED,73,604 1456890161224790016,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:44:16,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nstruct dependency\n{\n\tstring attr1;\n\tstring sttr2;\n}\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency(M);\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdependency[i].attr1 = tmp1;\n\t\tdependency[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < dependency[0].attr1.length; ++i)\n\t{\n\t\tint place = dependency[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(dependency[i].attr1 != dependency[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; i < dependency[iDepd].attr1.length; ++i)\n\t\t{\n\t\t\tint place = dependency[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456890279063760896,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 15:44:44,C,10.0,1456179472805675009,1456166840027594752,639,"#include\nint main()\n{\n\tint x, y, x2[100], y2[100], xl, yl, z2[200], z, zl=0;\n\tz = 0;\n\tx = 0;\n\ty = 0;\n\n\tscanf(\""%d\"", &z);\n\t\n\tfor (int i = 0; i < 200; i++)\n\t{\n\t\tz2[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tx2[i] = 0;\n\t\ty2[i] = 0;\n\t}\n\n\twhile (z / 2)\n\t{\n\t\tz2[zl] = z % 2;\n\t\tzl++;\n\t\tz /= 2;\n\t}\n\tz2[zl] = z;\n\tzl++;\n\n\t\n\tfor (int i = 0; i < zl; i++)\n\t{\n\t\tif (i % 2 == 0)\n\t\t{\n\t\t\ty2[i / 2] = z2[i];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tx2[i / 2] = z2[i];\n\t\t}\n\t}\n\n\tfor (int f = zl/2 ; f >= 0; f--)\n\t{\n\t\tx = x * 2 + x2[f];\n\t}\n\tfor (int f = zl / 2 ; f >= 0; f--)\n\t{\n\t\ty = y * 2 + y2[f];\n\t}\n\n\tprintf(\""%d %d\"", x, y);\n}",ACCEPTED,66,384 1456890452867330048,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:45:26,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tstring attr1;\n\tstring sttr2;\n}\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency(M);\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdependency[i].attr1 = tmp1;\n\t\tdependency[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < dependency[0].attr1.length; ++i)\n\t{\n\t\tint place = dependency[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(dependency[i].attr1 != dependency[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; i < dependency[iDepd].attr1.length; ++i)\n\t\t{\n\t\t\tint place = dependency[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456890504755064832,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:45:38,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tstring attr1;\n\tstring sttr2;\n};\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency(M);\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdependency[i].attr1 = tmp1;\n\t\tdependency[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < dependency[0].attr1.length; ++i)\n\t{\n\t\tint place = dependency[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(dependency[i].attr1 != dependency[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; i < dependency[iDepd].attr1.length; ++i)\n\t\t{\n\t\t\tint place = dependency[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456890510811639808,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 15:45:40,Python,10.0,1456179472809869313,1456174491838988288,639,"num=list(input().split())\ndim=int(num[0])\nh=int(num[1])\nlist1=[]\nlist2=[]\nlist3=[]\nlist=[]\nl=[]\nwhile h>0:\n t=h%2\n list.append(t)\n h=int(h/2)\nwhile len(list)!=dim*2:\n list.append(0)\nlist.reverse()\nfor i in range(0,len(list)-1,2):\n l.append(list[i]*2+list[i+1])\nfor i in range(len(l)-1,-1,-1):\n if l[i] == 0:\n for j in range(i + 1, len(l)):\n if l[j] == 3:\n l[j] = 1\n elif l[j] == 1:\n l[j] = 3\n elif l[i] == 3:\n for j in range(i + 1, len(l)):\n if l[j] == 0:\n l[j] = 2\n elif l[j] == 2:\n l[j] = 0\n\nfor i in range(0,len(l)):\n if l[i]==0:\n list1.append(0)\n list1.append(0)\n if l[i]==1:\n list1.append(0)\n list1.append(1)\n if l[i]==3:\n list1.append(1)\n list1.append(0)\n if l[i]==2:\n list1.append(1)\n list1.append(1)\nfor i in range(0,len(list1)-1,2):\n list2.append(list1[i])\n list3.append(list1[i+1])\nlist2.reverse()\nlist3.reverse()\nx=0\ny=0\nfor i in range(len(list2)):\n x=x+list2[i]*pow(2,i)\nfor i in range(len(list3)):\n y=y+list3[i]*pow(2,i)\nprint(\""{} {}\"".format(x,y))",ACCEPTED,218,3596 1456890584128073728,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:45:57,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tstring attr1;\n\tstring sttr2;\n};\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdependency[i].attr1 = tmp1;\n\t\tdependency[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < dependency[0].attr1.length; ++i)\n\t{\n\t\tint place = dependency[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(dependency[i].attr1 != dependency[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; i < dependency[iDepd].attr1.length; ++i)\n\t\t{\n\t\t\tint place = dependency[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456890806665261056,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:46:50,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tstring attr1;\n\tstring sttr2;\n};\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdepd[i].attr1 = tmp1;\n\t\tdepd[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < depd[0].attr1.length; ++i)\n\t{\n\t\tint place = depd[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(depd[i].attr1 != depd[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; i < depd[iDepd].attr1.length; ++i)\n\t\t{\n\t\t\tint place = depd[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456890902337888256,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:47:13,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tstring attr1;\n\tstring attr2;\n};\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdepd[i].attr1 = tmp1;\n\t\tdepd[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < depd[0].attr1.length; ++i)\n\t{\n\t\tint place = depd[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(depd[i].attr1 != depd[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool(N);\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; i < depd[iDepd].attr1.length; ++i)\n\t\t{\n\t\t\tint place = depd[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456891277077979136,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:48:42,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tstring attr1;\n\tstring attr2;\n};\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdepd[i].attr1 = tmp1;\n\t\tdepd[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < depd[0].attr1.length(); ++i)\n\t{\n\t\tint place = depd[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(depd[i].attr1 != depd[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; i < depd[iDepd].attr1.length(); ++i)\n\t\t{\n\t\t\tint place = depd[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456891421634113536,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 15:49:17,C++,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tstring attr1;\n\tstring attr2;\n};\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdepd[i].attr1 = tmp1;\n\t\tdepd[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < depd[0].attr1.length(); ++i)\n\t{\n\t\tint place = depd[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(depd[i].attr1 != depd[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; iEle < depd[iDepd].attr1.length(); ++iEle)\n\t\t{\n\t\t\tint place = depd[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,66,648 1456894884426883072,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 16:03:02,C,7.0,1456179472809869312,1456171992474206208,639,"#include \n#include\n\nint dectobin(int n, int* array) {\n\tint count = 0;\n\tint y, x = 1; //y表示余数,x为叠加的系数\n\twhile (n != 0) {\n\t\ty = n % 2;\n\t\tarray[count] = y;\n\t\tn /= 2;\n\t\tcount++;\n\t}\n\t/*for (int i = 0; i < count; i++)\n\t{\n\t\tprintf(\""%d\"", array[i]);\n\t}*/\n\treturn count;\n}\n\nint main(void)\n{\n\tint n, x, y;\n\tscanf(\""%d %d %d\"",&n, &x, &y);\n\tint* bin_x = (int*)calloc(10, sizeof(int));\n\tint* bin_y = (int*)calloc(10, sizeof(int));\n\n\tint bin_x_count = dectobin(x, bin_x);\n\tint bin_y_count = dectobin(y, bin_y);\n\n\tint count = 0;\n\tif (bin_x_count >= bin_y_count)\n\t{\n\t\tcount = bin_x_count;\n\t}\n\telse\n\t{\n\t\tcount = bin_y_count;\n\t}\n\n\tint* bin_output = (int*)calloc(count * 2, sizeof(int));\n\tint c = 0;\n\t// 拼接\n\tfor (int i = 0; i < count * 2; i = i + 2)\n\t{\n\t\tbin_output[i] = bin_x[count - 1 - c];\n\t\tbin_output[i + 1] = bin_y[count - 1 - c];\n\t\tc++;\n\t}\n\n\t/*for (int i = 0; i < count * 2; i++)\n\t{\n\t\tprintf(\""%d\"", bin_output[i]);\n\t}\n\tprintf(\""\\n\"");*/\n\n\t// 第四步转换\n\tint* step4 = (int*)calloc(count, sizeof(int));\n\tc = 0;\n\tfor (int i = 0; i < count*2; i=i+2)\n\t{\n\t\tif (bin_output[i] == 0 && bin_output[i + 1] == 0)\n\t\t{\n\t\t\tstep4[c] = 0;\n\t\t}\n\t\telse if (bin_output[i] == 0 && bin_output[i + 1] == 1)\n\t\t{\n\t\t\tstep4[c] = 1;\n\t\t}\n\t\telse if (bin_output[i] == 1 && bin_output[i + 1] == 0)\n\t\t{\n\t\t\tstep4[c] = 3;\n\t\t}\n\t\telse if (bin_output[i] == 1 && bin_output[i + 1] == 1)\n\t\t{\n\t\t\tstep4[c] = 2;\n\t\t}\n\t\tc++;\n\t}\n\t//// test\n\t//for (int i = 0; i < count; i++)\n\t//{\n\t//\tprintf(\""%d\"", step4[i]);\n\t//}\n\t\n\t// step5\n\tfor (int i = 0; i < count; i++)\n\t{\n\t\tif (step4[i] == 0) // switch 1&3\n\t\t{\n\t\t\tfor (int j = i + 1; j < count; j++)\n\t\t\t{\n\t\t\t\tif (step4[j] == 1)\n\t\t\t\t{\n\t\t\t\t\tstep4[j] = 3;\n\t\t\t\t}\n\t\t\t\telse if (step4[j] == 3)\n\t\t\t\t{\n\t\t\t\t\tstep4[j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse if (step4[i] == 3)\n\t\t{\n\t\t\tfor (int j = i + 1; j < count; j++)\n\t\t\t{\n\t\t\t\tif (step4[j] == 0)\n\t\t\t\t{\n\t\t\t\t\tstep4[j] = 2;\n\t\t\t\t}\n\t\t\t\telse if (step4[j] == 2)\n\t\t\t\t{\n\t\t\t\t\tstep4[j] = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t// si进制转十进制\n\tint sum = 0;\n\tfor (int i = 0; i < count; i++)\n\t{\n\t\tsum = sum * 4 + step4[i];\n\t}\n\tprintf(\""%d\"", sum);\n\t\n\n}",PARTIAL_ACCEPTED,80,512 1456895644455739392,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 16:06:04,C,0.0,1456179472801480704,1456154017474035712,615,#include\nint main(){\n return True;\n},COMPILE_ERROR,0,0 1456895747148525568,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 16:06:28,C,4.0,1456179472801480704,1456154017474035712,615,"#include\nint main(){\n printf(\""True\""); \n}",PARTIAL_ACCEPTED,50,512 1456896754951696384,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:10:28,C,0.0,1456179472809869313,1456174491838988288,639,"#include \n#include\nusing namespace std;\nint main() {\n int x, y, h;\n int n;\n cin >> n >> h;\n //7->6\n int bh[40];\n int i;\n int lbh;\n for (i = 0; h > 0; i++)\n {\n bh[i] = h % 2;\n h = h / 2;\n }\n lbh = i;\n if (lbh <2* n) {\n for (i = lbh; i < 2 * n; i++)\n bh[i] = 0;\n lbh =2* n;\n }\n //6-5\n int Rol[20];\n int j = 0;\n for (i = 0; i < 2 * n; i += 2,j++) {\n Rol[j] = bh[i] + 2*bh[i + 1];\n }\n //5\n for (i = 0; i < n; i++) {\n if (Rol[i] == 3) {\n for (j = i - 1; j >= 0; j--) {\n if (Rol[j] == 2)\n Rol[j] = 0;\n else if (Rol[j] == 0)\n Rol[j] = 2;\n }\n }\n else if (Rol[i] == 0) {\n for (j = i - 1; j >= 0; j--) {\n if (Rol[j] == 1)\n Rol[j] = 3;\n else if (Rol[j] == 3)\n Rol[j] = 1;\n }\n }\n }\n //4-2\n int step2[40];\n for (i = n-1,j=0; i >= 0; i--,j+=2) {\n if (Rol[i] == 0) {\n step2[j] = 0;\n step2[j + 1] = 0;\n }\n else if (Rol[i] == 1) {\n step2[j] = 0;\n step2[j + 1] = 1;\n }\n else if (Rol[i] == 2) {\n step2[j] = 1;\n step2[j + 1] = 1;\n }\n else if (Rol[i] == 3) {\n step2[j] = 1;\n step2[j + 1] = 0;\n }\n }\n\n //2-1\n x = y = 0;\n for (i = 0; i < 2*n; i+=2) {\n x += step2[i] * pow(2, n - i/2 - 1);\n y += step2[i+1] * pow(2, n - i/2 - 1);\n }\n cout << x << \"" \"" << y;\n\n}",COMPILE_ERROR,0,0 1456896780101296128,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:10:34,C++,10.0,1456179472809869313,1456174491838988288,639,"#include \n#include\nusing namespace std;\nint main() {\n int x, y, h;\n int n;\n cin >> n >> h;\n //7->6\n int bh[40];\n int i;\n int lbh;\n for (i = 0; h > 0; i++)\n {\n bh[i] = h % 2;\n h = h / 2;\n }\n lbh = i;\n if (lbh <2* n) {\n for (i = lbh; i < 2 * n; i++)\n bh[i] = 0;\n lbh =2* n;\n }\n //6-5\n int Rol[20];\n int j = 0;\n for (i = 0; i < 2 * n; i += 2,j++) {\n Rol[j] = bh[i] + 2*bh[i + 1];\n }\n //5\n for (i = 0; i < n; i++) {\n if (Rol[i] == 3) {\n for (j = i - 1; j >= 0; j--) {\n if (Rol[j] == 2)\n Rol[j] = 0;\n else if (Rol[j] == 0)\n Rol[j] = 2;\n }\n }\n else if (Rol[i] == 0) {\n for (j = i - 1; j >= 0; j--) {\n if (Rol[j] == 1)\n Rol[j] = 3;\n else if (Rol[j] == 3)\n Rol[j] = 1;\n }\n }\n }\n //4-2\n int step2[40];\n for (i = n-1,j=0; i >= 0; i--,j+=2) {\n if (Rol[i] == 0) {\n step2[j] = 0;\n step2[j + 1] = 0;\n }\n else if (Rol[i] == 1) {\n step2[j] = 0;\n step2[j + 1] = 1;\n }\n else if (Rol[i] == 2) {\n step2[j] = 1;\n step2[j + 1] = 1;\n }\n else if (Rol[i] == 3) {\n step2[j] = 1;\n step2[j + 1] = 0;\n }\n }\n\n //2-1\n x = y = 0;\n for (i = 0; i < 2*n; i+=2) {\n x += step2[i] * pow(2, n - i/2 - 1);\n y += step2[i+1] * pow(2, n - i/2 - 1);\n }\n cout << x << \"" \"" << y;\n\n}",ACCEPTED,84,616 1456897274160947200,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 16:12:32,C,10.0,1456179472809869312,1456171992474206208,639,"#include \n#include\n\nint dectobin(int n, int* array) {\n\tint count = 0;\n\tint y, x = 1; //y表示余数,x为叠加的系数\n\twhile (n != 0) {\n\t\ty = n % 2;\n\t\tarray[count] = y;\n\t\tn /= 2;\n\t\tcount++;\n\t}\n\t/*for (int i = 0; i < count; i++)\n\t{\n\t\tprintf(\""%d\"", array[i]);\n\t}\n\tprintf(\""\\n\"");*/\n\treturn count;\n}\n\nint main(void)\n{\n\tint n, x, y;\n\tscanf(\""%d %d %d\"",&n, &x, &y);\n\tint* bin_x = (int*)calloc(10, sizeof(int));\n\tint* bin_y = (int*)calloc(10, sizeof(int));\n\n\tint bin_x_count = dectobin(x, bin_x);\n\tint bin_y_count = dectobin(y, bin_y);\n\n\tint count = n;\n\t/*if (bin_x_count >= bin_y_count)\n\t{\n\t\tcount = bin_x_count;\n\t}\n\telse\n\t{\n\t\tcount = bin_y_count;\n\t}*/\n\n\tint* bin_output = (int*)calloc(count * 2, sizeof(int));\n\tint c = 0;\n\t// 拼接\n\tfor (int i = 0; i < count * 2; i = i + 2)\n\t{\n\t\tbin_output[i] = bin_x[count - 1 - c];\n\t\tbin_output[i + 1] = bin_y[count - 1 - c];\n\t\tc++;\n\t}\n\n\t/*for (int i = 0; i < count * 2; i++)\n\t{\n\t\tprintf(\""%d\"", bin_output[i]);\n\t}\n\tprintf(\""\\n\"");*/\n\n\t// 第四步转换\n\tint* step4 = (int*)calloc(count, sizeof(int));\n\tc = 0;\n\tfor (int i = 0; i < count*2; i=i+2)\n\t{\n\t\tif (bin_output[i] == 0 && bin_output[i + 1] == 0)\n\t\t{\n\t\t\tstep4[c] = 0;\n\t\t}\n\t\telse if (bin_output[i] == 0 && bin_output[i + 1] == 1)\n\t\t{\n\t\t\tstep4[c] = 1;\n\t\t}\n\t\telse if (bin_output[i] == 1 && bin_output[i + 1] == 0)\n\t\t{\n\t\t\tstep4[c] = 3;\n\t\t}\n\t\telse if (bin_output[i] == 1 && bin_output[i + 1] == 1)\n\t\t{\n\t\t\tstep4[c] = 2;\n\t\t}\n\t\tc++;\n\t}\n\t//// test\n\t//for (int i = 0; i < count; i++)\n\t//{\n\t//\tprintf(\""%d\"", step4[i]);\n\t//}\n\t//printf(\""\\n\"");\n\t// step5\n\tfor (int i = 0; i < count; i++)\n\t{\n\t\tif (step4[i] == 0) // switch 1&3\n\t\t{\n\t\t\tfor (int j = i + 1; j < count; j++)\n\t\t\t{\n\t\t\t\tif (step4[j] == 1)\n\t\t\t\t{\n\t\t\t\t\tstep4[j] = 3;\n\t\t\t\t}\n\t\t\t\telse if (step4[j] == 3)\n\t\t\t\t{\n\t\t\t\t\tstep4[j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse if (step4[i] == 3)\n\t\t{\n\t\t\tfor (int j = i + 1; j < count; j++)\n\t\t\t{\n\t\t\t\tif (step4[j] == 0)\n\t\t\t\t{\n\t\t\t\t\tstep4[j] = 2;\n\t\t\t\t}\n\t\t\t\telse if (step4[j] == 2)\n\t\t\t\t{\n\t\t\t\t\tstep4[j] = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t// si进制转十进制\n\tint sum = 0;\n\tfor (int i = 0; i < count; i++)\n\t{\n\t\tsum = sum * 4 + step4[i];\n\t}\n\tprintf(\""%d\"", sum);\n\t\n\n}",ACCEPTED,75,468 1456898163868741632,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 16:16:04,C,10.0,1456179472809869313,1456174491838988288,639,"#include \n#include\n\nint dectobin(int n, int* array) {\n\tint count = 0;\n\tint y, x = 1; //y表示余数,x为叠加的系数\n\twhile (n != 0) {\n\t\ty = n % 2;\n\t\tarray[count] = y;\n\t\tn /= 2;\n\t\tcount++;\n\t}\n\t/*for (int i = 0; i < count; i++)\n\t{\n\t\tprintf(\""%d\"", array[i]);\n\t}\n\tprintf(\""\\n\"");*/\n\treturn count;\n}\n\nint main(void)\n{\n\tint n, h;\n\tscanf(\""%d %d\"", &n, &h);\n\tint a,b;\n\tfor (a = 0; a < 100; a++)\n\t{\n\t\tfor (b = 0; b < 100; b++)\n\t\t{\n\t\t\tint x, y;\n\t\t\tx = a; y = b;\n\t\t\tint* bin_x = (int*)calloc(10, sizeof(int));\n\t\t\tint* bin_y = (int*)calloc(10, sizeof(int));\n\n\t\t\tint bin_x_count = dectobin(x, bin_x);\n\t\t\tint bin_y_count = dectobin(y, bin_y);\n\n\t\t\tint count = n;\n\t\t\t/*if (bin_x_count >= bin_y_count)\n\t\t\t{\n\t\t\t\tcount = bin_x_count;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcount = bin_y_count;\n\t\t\t}*/\n\n\t\t\tint* bin_output = (int*)calloc(count * 2, sizeof(int));\n\t\t\tint c = 0;\n\t\t\t// 拼接\n\t\t\tfor (int i = 0; i < count * 2; i = i + 2)\n\t\t\t{\n\t\t\t\tbin_output[i] = bin_x[count - 1 - c];\n\t\t\t\tbin_output[i + 1] = bin_y[count - 1 - c];\n\t\t\t\tc++;\n\t\t\t}\n\n\t\t\t/*for (int i = 0; i < count * 2; i++)\n\t\t\t{\n\t\t\t\tprintf(\""%d\"", bin_output[i]);\n\t\t\t}\n\t\t\tprintf(\""\\n\"");*/\n\n\t\t\t// 第四步转换\n\t\t\tint* step4 = (int*)calloc(count, sizeof(int));\n\t\t\tc = 0;\n\t\t\tfor (int i = 0; i < count * 2; i = i + 2)\n\t\t\t{\n\t\t\t\tif (bin_output[i] == 0 && bin_output[i + 1] == 0)\n\t\t\t\t{\n\t\t\t\t\tstep4[c] = 0;\n\t\t\t\t}\n\t\t\t\telse if (bin_output[i] == 0 && bin_output[i + 1] == 1)\n\t\t\t\t{\n\t\t\t\t\tstep4[c] = 1;\n\t\t\t\t}\n\t\t\t\telse if (bin_output[i] == 1 && bin_output[i + 1] == 0)\n\t\t\t\t{\n\t\t\t\t\tstep4[c] = 3;\n\t\t\t\t}\n\t\t\t\telse if (bin_output[i] == 1 && bin_output[i + 1] == 1)\n\t\t\t\t{\n\t\t\t\t\tstep4[c] = 2;\n\t\t\t\t}\n\t\t\t\tc++;\n\t\t\t}\n\t\t\t//// test\n\t\t\t//for (int i = 0; i < count; i++)\n\t\t\t//{\n\t\t\t//\tprintf(\""%d\"", step4[i]);\n\t\t\t//}\n\t\t\t//printf(\""\\n\"");\n\t\t\t// step5\n\t\t\tfor (int i = 0; i < count; i++)\n\t\t\t{\n\t\t\t\tif (step4[i] == 0) // switch 1&3\n\t\t\t\t{\n\t\t\t\t\tfor (int j = i + 1; j < count; j++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (step4[j] == 1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tstep4[j] = 3;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (step4[j] == 3)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tstep4[j] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse if (step4[i] == 3)\n\t\t\t\t{\n\t\t\t\t\tfor (int j = i + 1; j < count; j++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (step4[j] == 0)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tstep4[j] = 2;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (step4[j] == 2)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tstep4[j] = 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\t// si进制转十进制\n\t\t\tint sum = 0;\n\t\t\tfor (int i = 0; i < count; i++)\n\t\t\t{\n\t\t\t\tsum = sum * 4 + step4[i];\n\t\t\t}\n\t\t\tif (sum == h)\n\t\t\t{\n\t\t\t\tprintf(\""%d %d\"", x, y);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t\n\n}",ACCEPTED,80,588 1456898373458112512,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 16:16:54,C,0.0,1456179472805675008,1456164485751504896,639,"#include\nint main(){\n int x,y;\n scanf(\""%d%d\"",&x,&y);\n}",WRONG_ANSWER,74,356 1456899824125259776,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:22:40,Java,0.0,1456179472801480704,1456154017474035712,615,"public class BCNF {\n\n\tpublic static void main(String[] args) {\n\t\t// TODO Auto-generated method stub\n\t\tSystem.out.println(\""hello world\"");\n\n\t}\n\n}",COMPILE_ERROR,0,0 1456900097728651264,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:23:45,Java,0.0,1456179472801480704,1456154017474035712,615,"class BCNF {\n\n\tpublic static void main(String[] args) {\n\t\t// TODO Auto-generated method stub\n\t\tSystem.out.println(\""hello world\"");\n\n\t}\n\n}",COMPILE_ERROR,0,0 1456900110026350592,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:23:48,Java,0.0,1456179472801480704,1456154017474035712,615,"class BCNF {\n\n\tpublic static void main(String[] args) {\n\t\t// TODO Auto-generated method stub\n\t\tSystem.out.println(\""hello world\"");\n\n\t}\n\n}",COMPILE_ERROR,0,0 1456900124433231872,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:23:52,Java,0.0,1456179472801480704,1456154017474035712,615,"class BCNF {\n\n\tpublic static void main(String[] args) {\n\t\t// TODO Auto-generated method stub\n\t\tSystem.out.println(\""hello world\"");\n\n\t}\n\n}",COMPILE_ERROR,0,0 1456900307175415808,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:24:35,Java,0.0,1456179472801480704,1456154017474035712,615,"class Main {\n\n\tpublic static void main(String[] args) {\n\t\t// TODO Auto-generated method stub\n\t\tSystem.out.println(\""hello world\"");\n\n\t}\n\n}",WRONG_ANSWER,595,21964 1456900364074790912,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:24:49,Java,0.0,1456179472801480704,1456154017474035712,615,"class Main {\n\n\tpublic static void main(String[] args) {\n\t\t// TODO Auto-generated method stub\n\t\tSystem.out.println(\""hello world\"");\n\n\t}\n\n}",WRONG_ANSWER,614,21788 1456900369078595584,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 16:24:50,Java,0.0,1456179472801480704,1456154017474035712,615,"class Main {\n\n\tpublic static void main(String[] args) {\n\t\t// TODO Auto-generated method stub\n\t\tSystem.out.println(\""hello world\"");\n\n\t}\n\n}",WRONG_ANSWER,613,21584 1456900574540771328,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 16:25:39,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \nint ifinArray(int* array,int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++) \n\t{\n\t\tFDS[i] = (int*)calloc(N+1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse \n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t//// test income\n\t//for (int i = 0; i < M; i++)\n\t//{\n\t//\tfor (int j = 0; j < N+1; j++)\n\t//\t{\n\t//\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次,暴力遍历\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历所有FD\n\t\t\t{\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++) // 遍历当前FD\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && !ifinArray(judgeArray,N+1, FDS[j][k]))\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tint j;\n\t\t\tfor (int j = 1; j < N + 1; j++)\n\t\t\t{\n\t\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tif (j < N + 1)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\""True\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",COMPILE_ERROR,0,0 1456900691428188160,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 16:26:07,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array,int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++) \n\t{\n\t\tFDS[i] = (int*)calloc(N+1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse \n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t//// test income\n\t//for (int i = 0; i < M; i++)\n\t//{\n\t//\tfor (int j = 0; j < N+1; j++)\n\t//\t{\n\t//\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次,暴力遍历\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历所有FD\n\t\t\t{\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++) // 遍历当前FD\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && !ifinArray(judgeArray,N+1, FDS[j][k]))\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tint j;\n\t\t\tfor (int j = 1; j < N + 1; j++)\n\t\t\t{\n\t\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tif (j < N + 1)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\""True\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456902442097123328,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 16:33:04,C++,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tstring attr1;\n\tstring attr2;\n};\n\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tdepd[i].attr1 = tmp1;\n\t\tdepd[i].attr2 = tmp2;\n\t}\n\t// update primary keys\n\tfor(int i = 0; i < depd[0].attr1.length(); ++i)\n\t{\n\t\tint place = depd[0].attr1[i] - 'A';\n\t\tpKey[place] = true;\n\t}\n\n\t// check if all the left side of dependency equals to the primary key\n\t// fully functional dependence\n\tfor(int i = 0; i < M - 1; ++i)\n\t{\n\t\tif(depd[i].attr1 != depd[i].attr1)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n /*\n\t// lastly, check if all element dependent on primary keys\n\tbool* elements = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\telements[i] = pKey[i];\n\t}\n\tfor(int iDepd = 0; iDepd < M; ++iDepd)\n\t{\n\t\tfor(int iEle = 0; iEle < depd[iDepd].attr1.length(); ++iEle)\n\t\t{\n\t\t\tint place = depd[iDepd].attr1[iEle] - 'A';\n\t\t\telements[place] = true;\n\t\t}\n\t}\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tif(elements[i] == false)\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n*/\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,52,640 1456903271776591872,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 16:36:22,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array, int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tFDS[i] = (int*)calloc(N + 1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// test income\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N+1; j++)\n\t\t{\n\t\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t\t}\n\t\tprintf(\""\\n\"");\n\t}\n\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次,暴力遍历\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历所有FD\n\t\t\t{\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++) // 遍历当前FD\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && judgeArray[k] != 1)\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tint j;\n\t\t\tfor (j = 1; j < N + 1; j++)\n\t\t\t{\n\t\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (j < N + 1)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\""True\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456905060584333312,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 16:43:29,C,10.0,1456179472809869312,1456171992474206208,639,"#include\nint main()\n{\n\tint n, x, y, h, xl, yl, x1[100], y1[100], h1[200], h2[100], h3[200];\n\txl = yl = 0;\n\th = 0;\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tx1[i] = 0;\n\t\ty1[i] = 0;\n\t\th2[i] = 0;\n\t}\n\tfor (int i = 0; i < 200; i++)\n\t{\n\t\th1[i] = 0;\n\t\th3[i] = 0;\n\t}\n\n\n\tscanf(\""%d %d %d\"", &n, &x, &y);\n\n\twhile (x / 2)\n\t{\n\t\tx1[xl] = x % 2;\n\t\txl++;\n\t\tx /= 2;\n\t}\n\tx1[xl] = x;\n\txl++;\n\n\twhile (y / 2)\n\t{\n\t\ty1[yl] = y % 2;\n\t\tyl++;\n\t\ty /= 2;\n\t}\n\ty1[yl] = y;\n\tyl++;\n\n\n\tfor (int i = xl; i < n; i++)\n\t{\n\t\tx1[i] = 0;\n\t}\n\tfor (int i = yl; i < n; i++)\n\t{\n\t\ty1[i] = 0;\n\t}\n\txl = yl = n;\n\tint k = 0;\n\tint j = 0;\n\tfor (j; j < yl * 2; j = j + 2)\n\t{\n\t\th1[j] = y1[k];\n\t\th1[j + 1] = x1[k];\n\t\tk++;\n\t}\n\tint t = 0;\n\tint s = 0;\n\tfor (int f = j - 1; f >= 0; f = f - 2)\n\t{\n\t\ts = h1[f] * 2 + h1[f - 1];\n\t\tif (s == 2) s = 3;\n\t\telse if (s == 3) s = 2;\n\t\th2[t] = s;\n\t\tt++;\n\t}\n\n\tfor (int c = 0; c < t; c++)\n\t{\n\t\tif (h2[c] == 0)\n\t\t{\n\t\t\tfor (int d = c + 1; d < t; d++)\n\t\t\t{\n\t\t\t\tif (h2[d] == 1) h2[d] = 3;\n\t\t\t\telse if (h2[d] == 3) h2[d] = 1;\n\t\t\t}\n\t\t}\n\t\telse if (h2[c] == 3)\n\t\t{\n\t\t\tfor (int d = c + 1; d < t; d++)\n\t\t\t{\n\t\t\t\tif (h2[d] == 0) h2[d] = 2;\n\t\t\t\telse if (h2[d] == 2) h2[d] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tint u = 0;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tif (h2[i] == 0)\n\t\t{\n\t\t\th3[u] = 0;\n\t\t\th3[u + 1] = 0;\n\t\t}\n\t\telse if (h2[i] == 1)\n\t\t{\n\t\t\th3[u] = 0;\n\t\t\th3[u + 1] = 1;\n\t\t}\n\t\telse if (h2[i] == 2)\n\t\t{\n\t\t\th3[u] = 1;\n\t\t\th3[u + 1] = 0;\n\t\t}\n\t\telse if (h2[i] == 3)\n\t\t{\n\t\t\th3[u] = 1;\n\t\t\th3[u + 1] = 1;\n\t\t}\n\t\tu = u + 2;\n\t}\n\n\tfor (int i = 0; i < u; i++)\n\t{\n\t\th = h * 2 + h3[i];\n\t}\n\n\n\tprintf(\""%d\"", h);\n}",ACCEPTED,75,376 1456906876272816128,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 16:50:41,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum >= 1){\n WriteEle(Ans, r, c, 1);\n }else{\n WriteEle(Ans, r, c, 0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_len = sizeof(input[i])/sizeof(int) - 1;\n printf(\""%d\\n\"",input_len);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1.0/input_len);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<30;i++){\n Ans = MatrMult(m, Ans);\n }\n for(int i=0;i\nint main() {\n int x, y;\n scanf(\""%d%d\"", &x, &y);\n int a[32] = { 0 };\n int b[32] = { 0 };\n int c[32] = { 0 };\n int i = 0;\n while (x > 0)\n {\n a[i] = x % 2;\n i = i + 1;\n x = x / 2;\n }\n\n int j = 0;\n while (y > 0)\n {\n b[j] = y % 2;\n j = j + 1;\n y = y / 2;\n }\n if (j >= i) i = j;\n else j = i;\n \n int l = 0;\n for (int k=i-1; k>=0; k--) {\n c[l] = a[k];\n c[l + 1] = b[k];\n l += 2;\n }\n int res = 0;\n int power = 1;\n for (int m = 2*i-1; m>=0; m--) {\n res =res+ c[m]*power;\n power *= 2;\n }\n printf(\""%d\"", res);\n}",ACCEPTED,83,348 1456907912299458560,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 16:54:48,Python,0.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN = int(num[0])\nM= int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=true\nfor i in range(M):\n list=list(input.split(\"" -> \""))\n listA.append(list[0])\n listB.append(list[1])\nfor i in range(M):\n container=[]\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n break;\n amount2=len(container) \n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n break;\n amount2=len(container) \n l=[]\n for i in range(len(container)):\n if len(container[i]>=2):\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))==N:\n continue;\n else:\n flag=false;\n break;\nif flag is True:\n print(True)\nelse \n print(False)\n \n\n \n",NON_ZERO_EXIT_CODE,128,3416 1456908287941877760,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 16:56:18,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array, int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tFDS[i] = (int*)calloc(N + 1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// test income\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N+1; j++)\n\t\t{\n\t\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t\t}\n\t\tprintf(\""\\n\"");\n\t}\n\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次,暴力遍历\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历所有FD\n\t\t\t{\n\t\t\t\tif (j == i)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++) // 遍历当前FD\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && judgeArray[k] != 1)\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tint j;\n\t\t\tfor (j = 1; j < N + 1; j++)\n\t\t\t{\n\t\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (j < N + 1)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t\t\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456908494921838592,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 16:57:07,Python,0.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN = int(num[0])\nM= int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nfor i in range(M):\n list=list(input.split(\"" -> \""))\n listA.append(list[0])\n listB.append(list[1])\nfor i in range(M):\n container=[]\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n break;\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n break;\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i]>=2):\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",NON_ZERO_EXIT_CODE,132,3416 1456908682504249344,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 16:57:52,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array, int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tFDS[i] = (int*)calloc(N + 1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ' || c == '-' || c == '>')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (index > N)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// test income\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N+1; j++)\n\t\t{\n\t\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t\t}\n\t\tprintf(\""\\n\"");\n\t}\n\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次,暴力遍历\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历所有FD\n\t\t\t{\n\t\t\t\tif (j == i)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++) // 遍历当前FD\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && judgeArray[k] != 1)\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t/*int j;\n\t\t\tfor (j = 1; j < N + 1; j++)\n\t\t\t{\n\t\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (j < N + 1)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\""True\"");\n\t\t\t\treturn 0;\n\t\t\t}*/\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456908907704266752,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 16:58:46,Python,0.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n break;\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n break;\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i]>=2):\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",TIME_LIMIT_EXCEEDED,0,0 1456909545745985536,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 17:01:18,C,6.0,1456179472805675009,1456166840027594752,639,"#include\nint main() {\n int z;\n scanf(\""%d\"", &z);\n int a[32] = { 0 };\n int i = 0;\n while (z > 0) {\n a[i] = z % 2;\n i++;\n z /= 2;\n }\n int b[32] = { 0 };\n int c[32] = { 0 };\n int k = i / 2;\n int m = k;\n for (; i >= 0; i-=2) {\n b[k] = a[i];\n c[k] = a[i - 1];\n k--;\n }\n int x = 0;\n int power = 1;\n int y = 0;\n for (int u = 0; u <= m; u++) {\n x = x + b[u] * power;\n y = y + c[u] * power;\n power = power * 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,73,504 1456909591871299584,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 17:01:29,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array, int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tFDS[i] = (int*)calloc(N + 1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// test income\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N+1; j++)\n\t\t{\n\t\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t\t}\n\t\tprintf(\""\\n\"");\n\t}\n\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tfor (int m = 0; m < M; m++) // 算M次,暴力遍历\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历所有FD\n\t\t\t{\n\t\t\t\tif (j == i)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++) // 遍历当前FD\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && judgeArray[k] != 1)\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t/*int j;\n\t\t\tfor (j = 1; j < N + 1; j++)\n\t\t\t{\n\t\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (j < N + 1)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tprintf(\""True\"");\n\t\t\t\treturn 0;\n\t\t\t}*/\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456909702613508096,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:01:55,C++,6.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum >= 1){\n WriteEle(Ans, r, c, 1);\n }else{\n WriteEle(Ans, r, c, 0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a){\n int i = 0;\n while(a[i]!='\\0'){\n i++;\n }\n return i;\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_len = cac_len(input[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1.0/input_len);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<30;i++){\n Ans = MatrMult(m, Ans);\n }\n for(int i=0;i\n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.7f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum >= 1){\n WriteEle(Ans, r, c, 1);\n }else{\n WriteEle(Ans, r, c, 0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a){\n int i = 0;\n while(a[i]!='\\0'){\n i++;\n }\n return i;\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_len = cac_len(input[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1.0/input_len);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<30;i++){\n Ans = MatrMult(m, Ans);\n }\n PrintMatr(Ans);\n for(int i=0;i\nint main() {\n int z;\n scanf(\""%d\"", &z);\n int a[32] = { 0 };\n int i = 0;\n while (z > 0) {\n a[i] = z % 2;\n i++;\n z /= 2;\n }\n if (i % 2 == 0)i++;\n int b[32] = { 0 };\n int c[32] = { 0 };\n int k = i / 2;\n int m = k;\n for (; i >= 0; i-=2) {\n b[k] = a[i];\n c[k] = a[i - 1];\n k--;\n }\n int x = 0;\n int power = 1;\n int y = 0;\n for (int u = 0; u <= m; u++) {\n x = x + b[u] * power;\n y = y + c[u] * power;\n power = power * 2;\n }\n printf(\""%d %d\"", x, y);\n}",ACCEPTED,52,352 1456910794344701952,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 17:06:16,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nint ifinArray(int* array, int arraysize, int num)\n{\n\tfor (int i = 0; i < arraysize; i++)\n\t{\n\t\tif (num == array[i])\n\t\t{\n\t\t\treturn 1;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\tint** FDS = (int**)malloc(sizeof(int*) * M);\n\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tFDS[i] = (int*)calloc(N + 1, sizeof(int));\n\t\tint flag = 0;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ')\n\t\t\t{\n\t\t\t\tflag = 1;\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint index = c - 'A' + 1;\n\t\t\tif (flag == 0)\n\t\t\t{\n\t\t\t\tFDS[i][index] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tFDS[i][index] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\t// test income\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N+1; j++)\n\t\t{\n\t\t\tprintf(\""%d\\t\"", FDS[i][j]);\n\t\t}\n\t\tprintf(\""\\n\"");\n\t}\n\n\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n\t{\n\t\tint* judgingFD = FDS[i];\n\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n\t\t\t{\n\t\t\t\tjudgeArray[j] = 1;\n\t\t\t}\n\t\t}\n\t\tint* readFD = (int*)calloc(M, sizeof(int));\n\t\treadFD[i] = 1;\n\t\tfor (int m = 0; m < M; m++) // 算M次,暴力遍历\n\t\t{\n\t\t\tfor (int j = 0; j < M; j++) // 遍历所有FD\n\t\t\t{\n\t\t\t\tif (readFD[j] == 1)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t\n\t\t\t\tint k;\n\t\t\t\tfor (k = 0; k < N + 1; k++) // 遍历当前FD\n\t\t\t\t{\n\t\t\t\t\t// 若 left全在judgeArray里\n\t\t\t\t\tif (FDS[j][k] == 1 && judgeArray[k] != 1)\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\treadFD[j] = 1;\n\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (FDS[j][k] == -1)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tjudgeArray[k] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int j = 1; j < N + 1; j++)\n\t\t{\n\t\t\tif (judgeArray[j] == 0) {\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}",TIME_LIMIT_EXCEEDED,0,0 1456910924891860992,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:06:47,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n int row = size;\n int column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n for(int i=1;i<=size;i++){\n WriteEle(Ans, i, i, 1.0);\n }\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum >= 1){\n WriteEle(Ans, r, c, 1);\n }else{\n WriteEle(Ans, r, c, 0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a){\n int i = 0;\n while(a[i]!='\\0'){\n i++;\n }\n return i;\n}\n\nint main(void)\n{\n int size, length_of_rules;\n scanf(\""%d\"", &size);\n scanf(\""%d\"", &length_of_rules);\n Matrix* m = CreateIdentity(size);\n char input[100][100], output[100][100];\n for(int i=0;i %s\"",input[i], output[i]);\n int input_len = cac_len(input[i]);\n int input_index = 0;\n int output_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n while(output[i][output_index]!='\\0'){\n int outputnum = output[i][output_index] - 'A' + 1;\n WriteEle(m, inputnum, outputnum, 1.0/input_len);\n output_index++;\n }\n input_index++;\n }\n }\n Matrix* Ans = m;\n for(int i=0;i<30;i++){\n Ans = MatrMult(m, Ans);\n }\n PrintMatr(Ans);\n for(int i=0;i \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i]>=2):\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",TIME_LIMIT_EXCEEDED,0,0 1456912507302649856,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 17:13:04,Python,0.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i]>=2):\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",TIME_LIMIT_EXCEEDED,0,0 1456913257533059072,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:16:03,C++,6.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* ScalMult(double scalar, Matrix* A)\n{\n\tMatrix* Ans = Create(A->row, A->column);\n\tfor (int r = 1; r <= A->row; r++) {\n\t\tfor (int c = 1; c <= A->column; c++) {\n\t\t\tWriteEle(Ans, r, c, scalar * GetEle(A, r, c));\n\t\t}\n\t}\n\treturn Ans;\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n\t\t\t\tif (sum >= 1) {\n\t\t\t\t\tWriteEle(Ans, r, c, 1);\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tWriteEle(Ans, r, c, 0);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 30; i++) {\n\t\tAns = MatrMult(m, Ans);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tint test[100];//第0个略去不用\n\t\tint input_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\tfor (int j = 1; j <= size; j++) {\n\t\t\t\tif (GetEle(Ans, inputnum, j) != 0) {\n\t\t\t\t\ttest[j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tinput_index++;\n\t\t}\n\t\tint count = 0;\n\t\tfor (int j = 1; j <= size; j++) {\n\t\t\tif (test[j] == 1) {\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t\tif (count != size) {\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,48,512 1456913584017682432,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:17:21,C++,9.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n WriteEle(Ans, r, c, sum);\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 30; i++) {\n\t\tAns = MatrMult(m, Ans);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tint test[100];//第0个略去不用\n\t\tint input_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\tfor (int j = 1; j <= size; j++) {\n\t\t\t\tif (GetEle(Ans, inputnum, j) != 0) {\n\t\t\t\t\ttest[j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tinput_index++;\n\t\t}\n\t\tint count = 0;\n\t\tfor (int j = 1; j <= size; j++) {\n\t\t\tif (test[j] == 1) {\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t\tif (count != size) {\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,48,512 1456914196277567488,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 17:19:47,Python,0.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i]>=2):\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",MULTIPLE_ERROR,53,3400 1456915061423517696,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 17:23:13,C,0.0,1456179472809869312,1456171992474206208,639,"#include\nint main() {\n\tint n;\t\n\tint x, y;\n\tscanf(\""%d%d%d\"", &n, &x, &y);\n\tif (n == 0) return 1;\n}",WRONG_ANSWER,58,512 1456915522549493760,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 17:25:03,Python,0.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] is in container[k] and listB[j] is not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i]>=2):\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",NON_ZERO_EXIT_CODE,130,3296 1456915662626664448,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:25:36,C++,6.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum>=1){\n WriteEle(Ans,r,c,1);\n }else{\n WriteEle(Ans,r,c,0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 20; i++) {\n\t\tAns = MatrMult(Ans, m);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tint test[100];//第0个略去不用\n\t\tint input_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\tfor (int j = 1; j <= size; j++) {\n\t\t\t\tif (GetEle(Ans, inputnum, j) != 0) {\n\t\t\t\t\ttest[j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tinput_index++;\n\t\t}\n\t\tint count = 0;\n\t\tfor (int j = 1; j <= size; j++) {\n\t\t\tif (test[j] == 1) {\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t\tif (count != size) {\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,58,512 1456915907355914240,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:26:35,C++,9.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n WriteEle(Ans,r,c,sum);\n //if(sum>=1){\n //WriteEle(Ans,r,c,1);\n //}else{\n //WriteEle(Ans,r,c,0);\n //}\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 20; i++) {\n\t\tAns = MatrMult(Ans, m);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tint test[100];//第0个略去不用\n\t\tint input_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\tfor (int j = 1; j <= size; j++) {\n\t\t\t\tif (GetEle(Ans, inputnum, j) != 0) {\n\t\t\t\t\ttest[j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tinput_index++;\n\t\t}\n\t\tint count = 0;\n\t\tfor (int j = 1; j <= size; j++) {\n\t\t\tif (test[j] == 1) {\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t\tif (count != size) {\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,46,480 1456915965396692992,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:26:48,C++,6.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum>=1){\n WriteEle(Ans,r,c,1);\n }else{\n WriteEle(Ans,r,c,0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 20; i++) {\n\t\tAns = MatrMult(Ans, m);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tint test[100];//第0个略去不用\n\t\tint input_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\tfor (int j = 1; j <= size; j++) {\n\t\t\t\tif (GetEle(Ans, inputnum, j) != 0) {\n\t\t\t\t\ttest[j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tinput_index++;\n\t\t}\n\t\tint count = 0;\n\t\tfor (int j = 1; j <= size; j++) {\n\t\t\tif (test[j] == 1) {\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t\tif (count != size) {\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,38,348 1456917158366355456,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:31:33,C,10.0,1456179472809869313,1456174491838988288,639,"#include\n\nint main()\n{\n\tint n, x, y, h, xl, yl, hl, x1[100], y1[100], h1[200], h2[100], h3[200];\n\txl = yl = 0;\n\th = 0;\n\tx = y = 0;\n\n\tscanf(\""%d %d\"", &n, &h);\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tx1[i] = 0;\n\t\ty1[i] = 0;\n\t\th2[i] = 0;\n\t}\n\tfor (int i = 0; i < 200; i++)\n\t{\n\t\th1[i] = 0;\n\t\th3[i] = 0;\n\t}\n\n\thl = 2 * n - 1;\n\t\n\twhile (h / 2)\n\t{\n\t\th3[hl] = h % 2;\n\t\thl--;\n\t\th /= 2;\n\t}\n\th3[hl] = h;\n\n\thl = 2 * n - 1;\n\tint t = 0;\n\tfor (int i = 0; i <= hl; i = i + 2)\n\t{\n\t\th2[t] = h3[i] * 2 + h3[i + 1];\n\t\tt++;\n\t}\n\n\tfor (int i = t - 1; i > 0; i--)\n\t{\n\t\tif (h2[i] == 3)\n\t\t{\n\t\t\tint j, sum=0;\n\t\t\tfor (j = 0; j < i; j++)\n\t\t\t{\n\t\t\t\tif (h2[j] == 0)\n\t\t\t\t{\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (sum % 2 == 1)\n\t\t\t{\n\t\t\t\th2[i] = 1;\n\t\t\t}\n\t\t}\n\t\telse if (h2[i] == 1)\n\t\t{\n\t\t\tint j, sum = 0;\n\t\t\tfor (j = 0; j < i; j++)\n\t\t\t{\n\t\t\t\tif (h2[j] == 0)\n\t\t\t\t{\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (sum % 2 == 1)\n\t\t\t{\n\t\t\t\th2[i] = 3;\n\t\t\t}\n\t\t}\n\t\telse if (h2[i] == 0)\n\t\t{\n\t\t\tint j, sum = 0;\n\t\t\tfor (j = 0; j < i; j++)\n\t\t\t{\n\t\t\t\tif (h2[j] == 3)\n\t\t\t\t{\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (sum % 2 == 1)\n\t\t\t{\n\t\t\t\th2[i] = 2;\n\t\t\t}\n\t\t}\n\t\telse if (h2[i] == 2)\n\t\t{\n\t\t\tint j, sum = 0;\n\t\t\tfor (j = 0; j < i; j++)\n\t\t\t{\n\t\t\t\tif (h2[j] == 3)\n\t\t\t\t{\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (sum % 2 == 1)\n\t\t\t{\n\t\t\t\th2[i] = 0;\n\t\t\t}\n\t\t}\n\n\t}\n\n\tint v = 0;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tif (h2[i] == 0)\n\t\t{\n\t\t\th1[v] = 0;\n\t\t\th1[v + 1] = 0;\n\t\t}\n\t\telse if (h2[i] == 1)\n\t\t{\n\t\t\th1[v] = 0;\n\t\t\th1[v + 1] = 1;\n\t\t}\n\t\telse if (h2[i] == 2)\n\t\t{\n\t\t\th1[v] = 1;\n\t\t\th1[v + 1] = 1;\n\t\t}\n\t\telse if (h2[i] == 3)\n\t\t{\n\t\t\th1[v] = 1;\n\t\t\th1[v + 1] = 0;\n\t\t}\n\t\tv = v + 2;\n\t}\n\n\tint g = 0, d = 0;\n\tfor (int i = 0; i <= hl; i++)\n\t{\n\t\tif (i % 2 == 0)\n\t\t{\n\t\t\tx1[g] = h1[i];\n\t\t\tg++;\n\t\t}\n\t\telse if (i % 2 == 1)\n\t\t{\n\t\t\ty1[d] = h1[i];\n\t\t\td++;\n\t\t}\n\t}\n\n\tfor (int i = 0; i < g; i++)\n\t{\n\t\tx = x * 2 + x1[i];\n\t}\n\tfor (int i = 0; i < d; i++)\n\t{\n\t\ty = y * 2 + y1[i];\n\t}\n\n\tprintf(\""%d %d\"", x, y);\n\n}",ACCEPTED,56,512 1456917283507609600,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 17:32:03,Python,0.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n for m in range(M):\n sign[m]=0\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] is in container[k] and listB[j] is not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and listB[j] not in container[k]:\n container.append(listB[j])\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i]>=2):\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",NON_ZERO_EXIT_CODE,129,3272 1456917500235132928,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 17:32:54,Python,8.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n for m in range(M):\n sign[m]=0\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and sign[j]==0:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and sign[j]==0:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i])>=2:\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",PARTIAL_ACCEPTED,128,3420 1456917614345367552,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 17:33:22,Python,8.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n for m in range(M):\n sign[m]=0\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and sign[j]==0:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and sign[j]==0:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i])>=2:\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",PARTIAL_ACCEPTED,141,3420 1456917743471210496,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:33:52,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[1000000], hou[1000000];\n\tint a[1000000][1000000], b[1000000][1000000], Key[1000000], Key1[1000000], Key2[1000000], Key3[1000000], record[1000000];\n\n\tfor (int i = 0; i < 1000000; i++)\n\t{\n\t\tfor (int j = 0; j < 1000000; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//for (int i = 0; i < M; i++) {\n\t//\tint j = 0;\n\t//\twhile (a[i][j] != 0) {\n\t//\t\tprintf(\""%d\"", a[i][j]);\n\t//\t\tj++;\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,40,376 1456918012271570944,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:34:57,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum>=1){\n WriteEle(Ans,r,c,1);\n }else{\n WriteEle(Ans,r,c,0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 20; i++) {\n\t\tAns = MatrMult(Ans, m);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tMatrix* in = Create(1, size);\n int input_index = 0;\n while(input[i][input_index]!='\\n'){\n int inputnum = input[i][input_index] - 'A' + 1;\n WriteEle(in, 1, inputnum, 1);\n }\n Matrix* temp = MatrMult(in, m);\n Matrix* test = MatrMult(temp, Ans);\n int sum = 0;\n for(int j=0;jdata[j];\n }\n if(sum != size){\n printf(\""False\"");\n return 0;\n }\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456918090059685888,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:35:15,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum>=1){\n WriteEle(Ans,r,c,1);\n }else{\n WriteEle(Ans,r,c,0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 20; i++) {\n\t\tAns = MatrMult(Ans, m);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tMatrix* in = Create(1, size);\n int input_index = 0;\n while(input[i][input_index]!='\\n'){\n int inputnum = input[i][input_index] - 'A' + 1;\n WriteEle(in, 1, inputnum, 1);\n input_index++;\n }\n Matrix* temp = MatrMult(in, m);\n Matrix* test = MatrMult(temp, Ans);\n int sum = 0;\n for(int j=0;jdata[j];\n }\n if(sum != size){\n printf(\""False\"");\n return 0;\n }\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",WRONG_ANSWER,110,3652 1456918275385008128,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:35:59,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[1000000], hou[1000000];\n\tint a[1000000][1000000], b[1000000][1000000], Key[1000000], Key1[1000000], Key2[1000000], Key3[1000000], record[1000000];\n\n\tfor (int i = 0; i < 1000000; i++)\n\t{\n\t\tfor (int j = 0; j < 1000000; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,46,512 1456918303347879936,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:36:06,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum>=1){\n WriteEle(Ans,r,c,1);\n }else{\n WriteEle(Ans,r,c,0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 20; i++) {\n\t\tAns = MatrMult(Ans, m);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tMatrix* in = Create(1, size);\n int input_index = 0;\n while(input[i][input_index]!='\\n'){\n int inputnum = input[i][input_index] - 'A' + 1;\n printf(\""%d\"",inputnum);\n WriteEle(in, 1, inputnum, 1);\n input_index++;\n }\n Matrix* temp = MatrMult(in, m);\n Matrix* test = MatrMult(temp, Ans);\n int sum = 0;\n for(int j=0;jdata[j];\n }\n if(sum != size){\n printf(\""False\"");\n return 0;\n }\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",WRONG_ANSWER,132,3912 1456918610685505536,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:37:19,C++,8.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum>=1){\n WriteEle(Ans,r,c,1);\n }else{\n WriteEle(Ans,r,c,0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 20; i++) {\n\t\tAns = MatrMult(Ans, m);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tMatrix* in = Create(1, size);\n int input_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n WriteEle(in, 1, inputnum, 1);\n input_index++;\n }\n Matrix* temp = MatrMult(in, m);\n Matrix* test = MatrMult(temp, Ans);\n int sum = 0;\n for(int j=0;jdata[j];\n }\n if(sum != size){\n printf(\""False\"");\n return 0;\n }\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,46,480 1456918662947086336,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 17:37:32,Python,8.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n for m in range(M):\n sign[m]=0\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and sign[j]==0:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n for k in range(len(container)):\n if i!=j and listA[j] in container[k] and sign[j]==0:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i])>=2:\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",PARTIAL_ACCEPTED,127,3456 1456918716109336576,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:37:44,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[1000000], hou[1000000];\n\tint a[1000000][1000000], b[1000000][1000000], Key[1000000], Key1[1000000], Key2[1000000], Key3[1000000], record[1000000];\n\n\tfor (int i = 0; i < 1000000; i++)\n\t{\n\t\tfor (int j = 0; j < 1000000; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\t//scanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,39,464 1456918842248835072,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 17:38:14,C++,5.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum>=1){\n WriteEle(Ans,r,c,1);\n }else{\n WriteEle(Ans,r,c,0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tMatrix* Ans = m;\n\tfor (int i = 0; i < 20; i++) {\n\t\tAns = MatrMult(Ans, m);\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tMatrix* in = Create(1, size);\n int input_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n WriteEle(in, 1, inputnum, 1);\n input_index++;\n }\n Matrix* temp = MatrMult(in, m);\n Matrix* test = MatrMult(temp, Ans);\n int sum = 0;\n for(int j=0;jdata[j];\n }\n if(sum != size){\n printf(\""False\"");\n return 0;\n }\n PrintMatr(temp);\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",PARTIAL_ACCEPTED,44,344 1456920084530929664,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:43:11,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsinged int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(j == i)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(eleNum, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsinged int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",COMPILE_ERROR,0,0 1456920182639894528,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:43:34,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(j == i)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(eleNum, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",COMPILE_ERROR,0,0 1456920260242907136,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:43:52,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0;\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(j == i)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(eleNum, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",COMPILE_ERROR,0,0 1456920335987290112,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:44:11,C++,1.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0;\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(j == i)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,7,324 1456920412583669760,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:44:29,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27];\n\tint a[1000000][1000000], b[1000000][1000000], Key[1000000], Key1[1000000], Key2[1000000], Key3[1000000], record[1000000];\n\n\tfor (int i = 0; i < 1000000; i++)\n\t{\n\t\tfor (int j = 0; j < 1000000; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\t//scanf(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j <= N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,58,640 1456921189842726912,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:47:34,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf_s(\""%d %d\"", &N, &M);\n\t//scanf_s(\""\\n\"");\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf_s(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf_s(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//for (int i = 0; i < M; i++) {\n\t//\tint j = 0;\n\t//\twhile (a[i][j] != 0) {\n\t//\t\tprintf(\""%d\"", a[i][j]);\n\t//\t\tj++;\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\t/*printf(\""左边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key1[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""右边出现的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key2[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定不是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key3[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}\n\tprintf(\""\\n\"");\n\tprintf(\""一定是的值:\\n\"");\n\tfor (int i = 1; i < 27; i++)\n\t{\n\t\tif (Key[i] == 1)\n\t\t{\n\t\t\tprintf(\""%d\"", i);\n\t\t}\n\t}*/\n\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456921324718960640,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:48:06,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\t\n\treturn 0;\n\n}",SEGMENTATION_FAULT,63,368 1456921406549831680,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:48:26,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456921545721585664,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 17:48:59,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tscanf(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\n\t\n\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456922030951673856,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:50:55,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0;\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k = i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",TIME_LIMIT_EXCEEDED,0,0 1456922148162052096,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:51:23,C++,1.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0;\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,13,496 1456922199710048256,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 17:51:35,C,10.0,1456179472809869312,1456171992474206208,639,"#include\nint main() {\n\tint n;\t\n\tint x, y;\n\tscanf(\""%d%d%d\"", &n, &x, &y);\n\tint a[32] = { 0 };\n int b[32] = { 0 };\n int c[32] = { 0 };\n int i = 0;\n while (x > 0)\n {\n a[i] = x % 2;\n i = i + 1;\n x = x / 2;\n }\n int j = 0;\n while (y > 0)\n {\n b[j] = y % 2;\n j = j + 1;\n y = y / 2;\n }\n if (j >= i) i = j;\n else j = i;\n int index = 0;\n for (int k = n-1; k >= 0; k--) {\n c[index] = a[k];\n c[index + 1] = b[k];\n index += 2;\n }\n\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n;i++) {\n if (c[index] == 0 && c[index + 1] == 0) d[i] = 0;\n if (c[index] == 0 && c[index + 1] == 1) d[i] = 1;\n if (c[index] == 1 && c[index + 1] == 0) d[i] = 3;\n if (c[index] == 1 && c[index + 1] == 1) d[i] = 2;\n index += 2;\n }\n for (int i = 0; i < n; i++) {\n if (d[i] == 0) {\n for (int j = i; j < n; j++) {\n if (d[j] == 1) d[j] = 3;\n else if (d[j] == 3) d[j] = 1;\n }\n }\n else if (d[i] == 3) {\n for (int j = i; j < n; j++) {\n if (d[j] ==0) d[j] = 2;\n else if (d[j] == 2) d[j] =0;\n }\n }\n }\n int e[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (d[i] == 0) {\n e[index] = 0;\n e[index + 1] = 0;\n }\n else if (d[i] == 1) {\n e[index] = 0;\n e[index + 1] = 1;\n }\n else if (d[i] == 2) {\n e[index] = 1;\n e[index + 1] = 0;\n }\n else if (d[i] == 3) {\n e[index] = 1;\n e[index + 1] = 1;\n }\n index += 2;\n }\n index -= 1;\n\n int power = 1;\n int res = 0;\n for (int i = index; i >= 0; i--) {\n res = res + e[i] * power;\n power *= 2;\n }\n printf(\""%d\"", res);\n}",ACCEPTED,64,512 1456922447463391232,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:52:34,C++,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0;\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,42,456 1456923742068875264,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:57:43,C++,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0;\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,44,468 1456924047682641920,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 17:58:55,C++,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\\n\"", tmp1, tmp2);\n\t\tchar ch;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 = 0;\n\t\t\tdepd[i].attr2 = 0;\n\t\t\tdepd[i].attr1 += (0b1 << (ch - 'A'));\n\t\t\tdepd[i].attr2 += (0b1 << (ch - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,43,476 1456924883455881216,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 18:02:15,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nusing namespace std;\n\nint findEle(vector vec, int ele)\n{\n\tvector::iterator it;\n\tit = find(vec.begin(), vec.end(), ele);\n\tif (it == vec.end())\n\t\treturn 0;\n\telse\n\t\treturn 1;\n}\n\n\n\nint main()\n{\n\tvector> FDS;\n\tint N, M;\n\tchar c;\n\tint i, j, k, m, n;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\t\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tvector FD;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ')\n\t\t\t{\n\t\t\t\tFD.push_back(0);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tFD.push_back(c - 'A' + 1);\n\t\t}\n\t\tFDS.push_back(FD);\n\t}\n\n\t////input check\n\t//for (i = 0; i < FDS.size(); i++ )\n\t//{\n\t//\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t//\t\tprintf(\""%d\"", *it);\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < FDS.size(); i++) // 测试每个FD\n\t{\n\t\tvector closure; //闭包\n\n\t\tvector readedFD; // 加入闭包过的FD\n\t\treadedFD.push_back(i);\n\n\t\t// push当前FD\n\t\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t\t{\n\t\t\tif (*it != 0)\n\t\t\t{\n\t\t\t\tclosure.push_back(*it);\n\t\t\t}\n\t\t}\n\n\t\tfor (m = 0; m < M; m++)\n\t\t{\n\t\t\t// 遍历所有FD,看是否可以形成闭包\n\t\t\tfor (j = 0; j < FDS.size(); j++)\n\t\t\t{\n\t\t\t\tif (findEle(readedFD, j)) // 该FD已经在closure内了\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\t// 遍历FDS[j]\n\t\t\t\t\tvector::iterator it;\n\t\t\t\t\tfor (it = FDS[j].begin(); *it != 0; it++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (*it != 0) //不正常结束\n\t\t\t\t\t{\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\treadedFD.push_back(j);\n\t\t\t\t\t\tit = it + 1;\n\t\t\t\t\t\tfor (; it != FDS[j].end(); it++)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tclosure.push_back(*it);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (closure.size() != N)\n\t\t{\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}\n\n\n\n\n\n\n//int ifinArray(int* array, int arraysize, int num)\n//{\n//\tfor (int i = 0; i < arraysize; i++)\n//\t{\n//\t\tif (num == array[i])\n//\t\t{\n//\t\t\treturn 1;\n//\t\t}\n//\t}\n//\treturn 0;\n//}\n//\n//int main()\n//{\n//\t\n//\n//\n//\tfor (int i = 0; i < M; i++) // 对每个FD的左边进行判断\n//\t{\n//\t\tint* judgingFD = FDS[i];\n//\t\tint* judgeArray = (int*)calloc(N + 1, sizeof(int)); // 开辟空数组储存闭包\n//\t\tfor (int j = 0; j < N + 1; j++)\n//\t\t{\n//\t\t\tif ((judgingFD[j] == 1 || judgingFD[j] == -1)) // 存入当前FD 开始算闭包\n//\t\t\t{\n//\t\t\t\tjudgeArray[j] = 1;\n//\t\t\t}\n//\t\t}\n//\t\tint* readFD = (int*)calloc(M, sizeof(int));\n//\t\treadFD[i] = 1;\n//\t\tfor (int m = 0; m < M; m++) // 算M次,暴力遍历\n//\t\t{\n//\t\t\tfor (int j = 0; j < M; j++) // 遍历所有FD\n//\t\t\t{\n//\t\t\t\tif (readFD[j] == 1)\n//\t\t\t\t{\n//\t\t\t\t\tcontinue;\n//\t\t\t\t}\n//\n//\t\t\t\tint k;\n//\t\t\t\tfor (k = 0; k < N + 1; k++) // 遍历当前FD\n//\t\t\t\t{\n//\t\t\t\t\t// 若 left全在judgeArray里\n//\t\t\t\t\tif (FDS[j][k] == 1 && judgeArray[k] != 1)\n//\t\t\t\t\t{\n//\t\t\t\t\t\tbreak;\n//\t\t\t\t\t}\n//\t\t\t\t}\n//\t\t\t\tif (k < N + 1) // 提早break,说明left还不能生成\n//\t\t\t\t{\n//\t\t\t\t\tcontinue;\n//\t\t\t\t}\n//\t\t\t\telse\n//\t\t\t\t{\n//\t\t\t\t\treadFD[j] = 1;\n//\t\t\t\t\tfor (k = 0; k < N + 1; k++)\n//\t\t\t\t\t{\n//\t\t\t\t\t\tif (FDS[j][k] == -1)\n//\t\t\t\t\t\t{\n//\t\t\t\t\t\t\tjudgeArray[k] = 1;\n//\t\t\t\t\t\t}\n//\t\t\t\t\t}\n//\t\t\t\t}\n//\t\t\t}\n//\t\t}\n//\t\tfor (int j = 1; j < N + 1; j++)\n//\t\t{\n//\t\t\tif (judgeArray[j] == 0) {\n//\t\t\t\tprintf(\""False\"");\n//\t\t\t\treturn 0;\n//\t\t\t}\n//\t\t}\n//\n//\t}\n//\tprintf(\""True\"");\n//\treturn 0;\n//}",COMPILE_ERROR,0,0 1456924991833055232,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 18:02:41,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nusing namespace std;\n\nint findEle(vector vec, int ele)\n{\n\tvector::iterator it;\n\tit = find(vec.begin(), vec.end(), ele);\n\tif (it == vec.end())\n\t\treturn 0;\n\telse\n\t\treturn 1;\n}\n\nint main()\n{\n\tvector> FDS;\n\tint N, M;\n\tchar c;\n\tint i, j, k, m, n;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\t\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tvector FD;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ')\n\t\t\t{\n\t\t\t\tFD.push_back(0);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tFD.push_back(c - 'A' + 1);\n\t\t}\n\t\tFDS.push_back(FD);\n\t}\n\n\t////input check\n\t//for (i = 0; i < FDS.size(); i++ )\n\t//{\n\t//\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t//\t\tprintf(\""%d\"", *it);\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < FDS.size(); i++) // 测试每个FD\n\t{\n\t\tvector closure; //闭包\n\n\t\tvector readedFD; // 加入闭包过的FD\n\t\treadedFD.push_back(i);\n\n\t\t// push当前FD\n\t\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t\t{\n\t\t\tif (*it != 0)\n\t\t\t{\n\t\t\t\tclosure.push_back(*it);\n\t\t\t}\n\t\t}\n\n\t\tfor (m = 0; m < M; m++)\n\t\t{\n\t\t\t// 遍历所有FD,看是否可以形成闭包\n\t\t\tfor (j = 0; j < FDS.size(); j++)\n\t\t\t{\n\t\t\t\tif (findEle(readedFD, j)) // 该FD已经在closure内了\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\t// 遍历FDS[j]\n\t\t\t\t\tvector::iterator it;\n\t\t\t\t\tfor (it = FDS[j].begin(); *it != 0; it++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (*it != 0) //不正常结束\n\t\t\t\t\t{\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\treadedFD.push_back(j);\n\t\t\t\t\t\tit = it + 1;\n\t\t\t\t\t\tfor (; it != FDS[j].end(); it++)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tclosure.push_back(*it);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (closure.size() != N)\n\t\t{\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}\n",COMPILE_ERROR,0,0 1456925044630401024,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 18:02:53,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nusing namespace std;\n\nint findEle(vector vec, int ele)\n{\n\tvector::iterator it;\n\tit = find(vec.begin(), vec.end(), ele);\n\tif (it == vec.end())\n\t\treturn 0;\n\telse\n\t\treturn 1;\n}\n\nint main()\n{\n\tvector> FDS;\n\tint N, M;\n\tchar c;\n\tint i, j, k, m, n;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\t\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tvector FD;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ')\n\t\t\t{\n\t\t\t\tFD.push_back(0);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tFD.push_back(c - 'A' + 1);\n\t\t}\n\t\tFDS.push_back(FD);\n\t}\n\n\t////input check\n\t//for (i = 0; i < FDS.size(); i++ )\n\t//{\n\t//\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t//\t\tprintf(\""%d\"", *it);\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < FDS.size(); i++) // 测试每个FD\n\t{\n\t\tvector closure; //闭包\n\n\t\tvector readedFD; // 加入闭包过的FD\n\t\treadedFD.push_back(i);\n\n\t\t// push当前FD\n\t\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t\t{\n\t\t\tif (*it != 0)\n\t\t\t{\n\t\t\t\tclosure.push_back(*it);\n\t\t\t}\n\t\t}\n\n\t\tfor (m = 0; m < M; m++)\n\t\t{\n\t\t\t// 遍历所有FD,看是否可以形成闭包\n\t\t\tfor (j = 0; j < FDS.size(); j++)\n\t\t\t{\n\t\t\t\tif (findEle(readedFD, j)) // 该FD已经在closure内了\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\t// 遍历FDS[j]\n\t\t\t\t\tvector::iterator it;\n\t\t\t\t\tfor (it = FDS[j].begin(); *it != 0; it++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (*it != 0) //不正常结束\n\t\t\t\t\t{\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\treadedFD.push_back(j);\n\t\t\t\t\t\tit = it + 1;\n\t\t\t\t\t\tfor (; it != FDS[j].end(); it++)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tclosure.push_back(*it);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (closure.size() != N)\n\t\t{\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}\n",COMPILE_ERROR,0,0 1456925313107800064,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 18:03:57,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include\nusing namespace std;\n\nint findEle(vector vec, int ele)\n{\n\tvector::iterator it;\n\tit = find(vec.begin(), vec.end(), ele);\n\tif (it == vec.end())\n\t\treturn 0;\n\telse\n\t\treturn 1;\n}\n\nint main()\n{\n\tvector> FDS;\n\tint N, M;\n\tchar c;\n\tint i, j, k, m, n;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\t\n\t// Input FDS\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tvector FD;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ')\n\t\t\t{\n\t\t\t\tFD.push_back(0);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tFD.push_back(c - 'A' + 1);\n\t\t}\n\t\tFDS.push_back(FD);\n\t}\n\n\t////input check\n\t//for (i = 0; i < FDS.size(); i++ )\n\t//{\n\t//\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t//\t\tprintf(\""%d\"", *it);\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < FDS.size(); i++) // 测试每个FD\n\t{\n\t\tvector closure; //闭包\n\n\t\tvector readedFD; // 加入闭包过的FD\n\t\treadedFD.push_back(i);\n\n\t\t// push当前FD\n\t\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t\t{\n\t\t\tif (*it != 0)\n\t\t\t{\n\t\t\t\tclosure.push_back(*it);\n\t\t\t}\n\t\t}\n\n\t\tfor (m = 0; m < M; m++)\n\t\t{\n\t\t\t// 遍历所有FD,看是否可以形成闭包\n\t\t\tfor (j = 0; j < FDS.size(); j++)\n\t\t\t{\n\t\t\t\tif (findEle(readedFD, j)) // 该FD已经在closure内了\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\t// 遍历FDS[j]\n\t\t\t\t\tvector::iterator it;\n\t\t\t\t\tfor (it = FDS[j].begin(); *it != 0; it++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (*it != 0) //不正常结束\n\t\t\t\t\t{\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\treadedFD.push_back(j);\n\t\t\t\t\t\tit = it + 1;\n\t\t\t\t\t\tfor (; it != FDS[j].end(); it++)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tclosure.push_back(*it);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (closure.size() != N)\n\t\t{\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}\n",TIME_LIMIT_EXCEEDED,0,0 1456925487783784448,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:04:39,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf_s(\""%d %d\"", &N, &M);\n\tscanf_s(\""\\n\"");\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\n\t}",COMPILE_ERROR,0,0 1456925551223185408,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:04:54,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\n\t}",COMPILE_ERROR,0,0 1456925849119432704,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:06:05,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf_s(\""%d %d\"", &N, &M);\n\tscanf_s(\""\\n\"");\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\n\t}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\n\treturn 0;\n\n}",COMPILE_ERROR,0,0 1456925890479464448,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:06:15,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\n\t}\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N; j++)\n\t\t{\n\t\t\tKey1[a[i][j]] = 1;\n\t\t\tKey2[b[i][j]] = 1;\n\t\t}\n\t}\n\tKey1[0] = 0;\n\tKey2[0] = 0;\n\n\tfor (int k = 0; k <= N; k++)\n\t{\n\t\tif (Key1[k] == 0 && Key2[k] == 0)\n\t\t{\n\t\t\t//Key3[k] = 1;\n\t\t\t//Key[k] = 1;\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t\telse if (Key1[k] == 1 && Key2[k] == 0)\n\t\t{\n\t\t\tKey[k] = 1;\n\t\t}\n\t\telse if (Key1[k] == 0 && Key2[k] == 1)\n\t\t{\n\t\t\tKey3[k] = 1;\n\t\t}\n\t}\n\n\n\treturn 0;\n\n}",SEGMENTATION_FAULT,40,640 1456926107118907392,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:07:06,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456926205047517184,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:07:30,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tscanf(\""\\n\"");\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456926285775286272,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-06 18:07:49,C++,10.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n#define ERROR 1e-8\n#define MAXTIME 1000\n\nint N;\n\nstruct Matrix {\n\tint row;\n\tint column;\n\tdouble* data;\n};\n\ndouble GetEle(Matrix* A, int r, int c)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\treturn A->data[(r - 1) * A->column + c - 1];\n\t}\n\telse {\n\t\tprintf(\""The Element(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn NULL;\n\t}\n}\n\nvoid WriteEle(Matrix* A, int r, int c, double data)\n{\n\tif (r <= A->row && r > 0 && c <= A->column && c > 0) {\n\t\tA->data[(r - 1) * A->column + c - 1] = data;\n\t}\n\telse {\n\t\tprintf(\""The Position(%d,%d) is out of row = %d, colomn = %d!\\n\"", r, c, A->row, A->column);\n\t\treturn;\n\t}\n}\n\nvoid Free(Matrix* A)\n{\n\tif (A == NULL) {\n\t\treturn;\n\t}\n\tfree(A->data);\n\tfree(A);\n}\n\nvoid CopyAtoB(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tif (A->row + StartRow > B->row + 1 || A->column + StartColumn > B->column + 1) {\n\t\tprintf(\""Invalid copy!\\n\"");\n\t\treturn;\n\t}\n\n\tint r = A->row, c = A->column;\n\tint i, j;\n\tfor (i = StartRow; i < r + StartRow; i++) {\n\t\tfor (j = StartColumn; j < c + StartColumn; j++) {\n\t\t\tWriteEle(B, i, j, GetEle(A, i - StartRow + 1, j - StartColumn + 1));\n\t\t}\n\t}\n}\n\nvoid CopyAtoBandDeleteA(Matrix* A, Matrix* B, int StartRow, int StartColumn)\n{\n\tCopyAtoB(A, B, StartRow, StartColumn);\n\tFree(A);\n}\n\nMatrix* Create(int row, int column)\n{\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\treturn Ans;\n}\n\nMatrix* CreateIdentity(int size)\n{\n\tint row = size;\n\tint column = size;\n\tif (row <= 0 || column <= 0) {\n\t\tprintf(\""Illegal matrix creation!\\n\"");\n\t\treturn NULL;\n\t}\n\tdouble* data = (double*)calloc(row * column, sizeof(double));\n\tMatrix* Ans = (Matrix*)malloc(sizeof(Matrix));\n\tAns->row = row;\n\tAns->column = column;\n\tAns->data = data;\n\tfor (int i = 1; i <= size; i++) {\n\t\tWriteEle(Ans, i, i, 1.0);\n\t}\n\treturn Ans;\n}\n\nvoid PrintMatr(Matrix* A)\n{\n\tint r, c;\n\tfor (r = 1; r <= A->row; r++) {\n\t\tprintf(\""[ \"");\n\t\tfor (c = 1; c <= A->column; c++) {\n\t\t\tprintf(\""%.1f \"", GetEle(A, r, c));\n\t\t}\n\t\tprintf(\""]\\n\"");\n\t}\n}\n\nMatrix* MatrMult(Matrix* Left, Matrix* Right)\n{\n\tif (Left->column != Right->row) {\n\t\tprintf(\""The Multiplication between matrices is illegal!\\n\"");\n\t\treturn NULL;\n\t}\n\telse {\n\t\tMatrix* Ans = Create(Left->row, Right->column);\n\t\tdouble sum;\n\t\tfor (int r = 1; r <= Ans->row; r++) {\n\t\t\tfor (int c = 1; c <= Ans->column; c++) {\n\t\t\t\tsum = 0;\n\t\t\t\tfor (int i = 1; i <= Left->column; i++) {\n\t\t\t\t\tsum += GetEle(Left, r, i) * GetEle(Right, i, c);\n\t\t\t\t}\n if(sum>=1){\n WriteEle(Ans,r,c,1);\n }else{\n WriteEle(Ans,r,c,0);\n }\n\t\t\t}\n\t\t}\n\t\treturn Ans;\n\t}\n}\n\nint cac_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main(void)\n{\n\tint size, length_of_rules;\n\tscanf(\""%d\"", &size);\n\tscanf(\""%d\"", &length_of_rules);\n\tMatrix* m = CreateIdentity(size);\n\tchar input[100][100], output[100][100];\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tscanf(\""%s -> %s\"", input[i], output[i]);\n\t\tint input_len = cac_len(input[i]);\n\t\tint input_index = 0;\n\t\tint output_index = 0;\n\t\twhile (input[i][input_index] != '\\0') {\n\t\t\tint inputnum = input[i][input_index] - 'A' + 1;\n\t\t\twhile (output[i][output_index] != '\\0') {\n\t\t\t\tint outputnum = output[i][output_index] - 'A' + 1;\n\t\t\t\tWriteEle(m, inputnum, outputnum, 1.0 / input_len);\n\t\t\t\toutput_index++;\n\t\t\t}\n\t\t\tinput_index++;\n\t\t\toutput_index = 0;\n\t\t}\n\t}\n\tfor (int i = 0; i < length_of_rules; i++) {\n\t\tMatrix* in = Create(1, size);\n int input_index = 0;\n while(input[i][input_index]!='\\0'){\n int inputnum = input[i][input_index] - 'A' + 1;\n WriteEle(in, 1, inputnum, 1);\n input_index++;\n }\n Matrix* test = MatrMult(in, m);\n for(int j=0;j<30;j++){\n test = MatrMult(test, m);\n }\n int sum = 0;\n for(int j=0;jdata[j];\n }\n if(sum != size){\n printf(\""False\"");\n return 0;\n }\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n}",ACCEPTED,30,324 1456926345506369536,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:08:03,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n //scanf(\""\\n\"");\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\n\t}\n\n\t\n\treturn 0;\n\n}",WRONG_ANSWER,28,344 1456926709148332032,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:09:30,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456926878703071232,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:10:10,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tKey[i] = 0;\n\t\tKey1[i] = 0;\n\t\tKey2[i] = 0;\n\t\tKey3[i] = 0;\n\t\trecord[i] = 0;\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456927000795066368,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:10:40,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456927057510998016,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:10:53,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], Key[27], Key1[27], Key2[27], Key3[27], record[27];\n\n\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456927207662886912,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:11:29,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\n\n\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j3 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j1];\n\t\t\tj3++;\n\t\t}\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456927361040195584,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:12:05,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\t\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456927857482211328,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:14:04,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; ++j);\n\t\t\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456928295069753344,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 18:15:48,Python,7.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n for m in range(M):\n sign[m]=0\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n within=1\n if i!=j and sign[j]==0:\n for u in range(len(listA[j])):\n for v in range(len(container)):\n if listA[j][u] not in container[v]:\n within=0\n break\n if within==1:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n within=1\n if i!=j and sign[j]==0:\n for u in range(len(listA[j])):\n for v in range(len(container)):\n if listA[j][u] not in container[v]:\n within=0\n break\n if within==1:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i])>=2:\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",PARTIAL_ACCEPTED,116,3396 1456928786465468416,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 18:17:45,Python,7.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=[]\n for m in range(M):\n sign[m]=0\n container.append(listA[i])\n container.append(listB[i])\n amount1=len(container);\n for j in range(M):\n within=1\n if i!=j and sign[j]==0:\n for u in range(len(listA[j])):\n for v in range(len(container)):\n if listA[j][u] not in container[v]:\n within=0\n break\n if within==0:\n break\n if within==1:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n within=1\n if i!=j and sign[j]==0:\n for u in range(len(listA[j])):\n for v in range(len(container)):\n if listA[j][u] not in container[v]:\n within=0\n break\n if within==0:\n break; \n if within==1:\n container.append(listB[j])\n sign[j]=1\n amount2=len(container)\n l=[]\n for i in range(len(container)):\n if len(container[i])>=2:\n for j in range(len(container[i])):\n l.append(container[i][j])\n else:\n l.append(container[i])\n if len(set(l))!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",PARTIAL_ACCEPTED,120,3412 1456928917705240576,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 18:18:17,C++,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\tchar tmp1[30], tmp2[30];\n\t\tscanf(\""%s -> %s\\n\"", tmp1, tmp2);\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,41,640 1456929847117422592,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 18:21:58,Python,8.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=\""\""\n for m in range(M):\n sign[m]=0\n container=container+listA[i]\n container=container+listB[i]\n amount1=len(container);\n for j in range(M):\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=0\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=0\n amount2=len(container)\n if len(container)!=N:\n flag=0\n break\nif flag==1:\n print(True)\nelse:\n print(False)",PARTIAL_ACCEPTED,119,3400 1456930271119060992,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 18:23:39,Python,8.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\ncontainer=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=\""\""\n for m in range(M):\n sign[m]=0\n container=container+listA[i]\n container=container+listB[i]\n amount1=len(container);\n for j in range(M):\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=0\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=0\n amount2=len(container)\n if len(container)!=N:\n flag=0\n break\nif flag==1:\n print(\""True\"",end=\""\"")\nelse:\n print(\""False\"",end=\""\"")",PARTIAL_ACCEPTED,113,3544 1456931158621204480,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:27:11,C,6.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n \n for (int a = 0; a < n; a++) {\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1) {\n c[j] = 3;\n }\n else if (c[j] == 3) c[j] = 1;\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0) c[j] = 2;\n else if (c[j] == 2) {\n c[j] = 0;\n }\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,49,352 1456931471890128896,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 18:28:26,C++,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\t//char tmp1[30], tmp2[30];\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\t//scanf_s(\""%s -> %s\"", tmp1, tmp2);\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif(A | B == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,39,456 1456931494082191360,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 18:28:31,Python,8.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=\""\""\n for m in range(M):\n sign[m]=0\n container=container+listA[i]\n container=container+listB[i]\n amount1=len(container);\n for j in range(M):\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=0\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=0\n amount2=len(container)\n if len(container)!=N:\n flag=0\n break\nif flag==1:\n print(\""True\"",end=\""\"")\nelse:\n print(\""False\"",end=\""\"")",PARTIAL_ACCEPTED,116,3288 1456931930566631424,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 18:30:15,Python,8.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=\""\""\n for m in range(M):\n sign[m]=0\n container=container+listA[i]\n container=container+listB[i]\n amount1=len(container);\n for j in range(M):\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=1\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=1\n amount2=len(container)\n if len(container)!=N:\n flag=0\n break\nif flag==1:\n print(\""True\"",end=\""\"")\nelse:\n print(\""False\"",end=\""\"")",PARTIAL_ACCEPTED,116,3388 1456932484495224832,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:32:27,C,6.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n \n for (int xx = 0; xx < n-1;xx++) {\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1) {\n c[j] = 3;\n }\n else if (c[j] == 3) c[j] = 1;\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0) c[j] = 2;\n else if (c[j] == 2) {\n c[j] = 0;\n }\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,49,512 1456933074088538112,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 18:34:48,Python,8.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=\""\""\n for m in range(M):\n sign[m]=0\n container=container+listA[i]\n container=container+listB[i]\n amount1=len(container);\n for j in range(M):\n within=1\n for k in range(len(listA[j])):\n if listA[j][k] not in container:\n within=0\n break\n if i!=j and sign[j]==0 and within==1 and listB[j] not in container:\n container=container+listB[j]\n sign[j]=1\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n within=1\n for k in range(len(listA[j])):\n if listA[j][k] not in container:\n within=0\n break\n if i!=j and sign[j]==0 and listA[j] in container and listB[j] not in container:\n container=container+listB[j]\n sign[j]=1\n amount2=len(container)\n if len(container)!=N:\n flag=0\n break\nif flag==1:\n print(\""True\"",end=\""\"")\nelse:\n print(\""False\"",end=\""\"")",PARTIAL_ACCEPTED,119,3416 1456933309573541888,2e23983e46319a956246eea9cb9a3b36bac4793f01435b2ed90653dd4577f354,2021-11-06 18:35:44,Python,10.0,1456179472801480704,1456154017474035712,615,"num=list(input().split())\nN=int(num[0])\nM=int(num[1])\nlistA=[]\nlistB=[]\nflag=1\nsign=[]\nfor i in range(M):\n sign.append(0)\nfor i in range(M):\n str=list(input().split(\"" -> \""))\n listA.append(str[0])\n listB.append(str[1])\nfor i in range(M):\n container=\""\""\n for m in range(M):\n sign[m]=0\n container=container+listA[i]\n container=container+listB[i]\n amount1=len(container);\n for j in range(M):\n within=1\n for k in range(len(listA[j])):\n if listA[j][k] not in container:\n within=0\n break\n if i!=j and sign[j]==0 and within==1 and listB[j] not in container:\n container=container+listB[j]\n sign[j]=1\n amount2=len(container)\n while(amount1!=amount2):\n amount1=amount2\n for j in range(M):\n within=1\n for k in range(len(listA[j])):\n if listA[j][k] not in container:\n within=0\n break\n if i!=j and sign[j]==0 and within==1 and listB[j] not in container:\n container=container+listB[j]\n sign[j]=1\n amount2=len(container)\n if len(container)!=N:\n flag=0\n break\nif flag==1:\n print(\""True\"",end=\""\"")\nelse:\n print(\""False\"",end=\""\"")",ACCEPTED,117,3396 1456933904787775488,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:38:06,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\n\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; ++j);\n\t\t\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456934850187538432,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 18:41:51,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nint main()\n{\n\tint N, M;\n\tchar qian[27], hou[27], line[100];\n\n for(int i=0; i<27; i++)\n {\n qian[i] = ' ';\n hou[i] = ' ';\n }\n for(int i=0; i<100; i++)\n {\n line[i] = ' '; \n }\n\tscanf(\""%d %d\"", &N, &M);\n\t\n getchar();\n\n\tfor (int i = 0; i < M; i++)\n { \n int j=0;\n while((line[j] = getchar()) != '\\n')\n j++;\n\t}\n\n\t\n\treturn 0;\n\n}",TIME_LIMIT_EXCEEDED,0,0 1456935736855015424,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:45:22,C,0.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n int init[32] = { 0 };\n int f[32] = { 0 };\n for (int i = 0; i < n; i++) {\n init[i] = c[i];\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",COMPILE_ERROR,0,0 1456935911505833984,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:46:04,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n int init[32] = { 0 };\n for (int i = 0; i < n; i++) {\n init[i] = c[i];\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,40,476 1456936320253341696,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:47:41,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n if (h < 0) return 0;\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n int init[32] = { 0 };\n for (int i = 0; i < n; i++) {\n init[i] = c[i];\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,40,356 1456936372384346112,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:47:54,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n if (h < 0) return 1;\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n int init[32] = { 0 };\n for (int i = 0; i < n; i++) {\n init[i] = c[i];\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,55,492 1456936422460141568,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:48:06,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n if (h < 0) return ;\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n int init[32] = { 0 };\n for (int i = 0; i < n; i++) {\n init[i] = c[i];\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,48,512 1456936611648417792,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:48:51,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n \n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,45,356 1456937146435313664,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:50:58,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n \n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,47,512 1456938331527520256,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:55:41,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n if (n < 1) return;\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n \n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,49,356 1456938362191523840,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:55:48,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n if (n < 1) return 0;\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n \n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,39,452 1456938431054159872,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 18:56:05,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n if (n < 1) printf(\""0 0\"");\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n \n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,45,512 1456939207616962560,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 18:59:10,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include\nusing namespace std;\n\nint findEle(vector vec, int ele)\n{\n\tvector::iterator it;\n\tit = find(vec.begin(), vec.end(), ele);\n\tif (it == vec.end())\n\t\treturn 0;\n\telse\n\t\treturn 1;\n}\n\nint main()\n{\n\tvector> FDS;\n\tint N, M;\n\tchar c;\n\tint i, j, k, m, n;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\tscanf(\""%c\"", &c);\n\t\n\t// Input FDS\n\tfor (i = 0; i < M; i++)\n\t{\n\t\tvector FD;\n\t\twhile (1)\n\t\t{\n\t\t\tscanf(\""%c\"", &c);\n\t\t\tif (c == ' ')\n\t\t\t{\n\t\t\t\tFD.push_back(0);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tscanf(\""%c\"", &c);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (c == '\\n')\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tFD.push_back(c - 'A' + 1);\n\t\t}\n\t\tFDS.push_back(FD);\n\t}\n\n\t////input check\n\t//for (i = 0; i < FDS.size(); i++ )\n\t//{\n\t//\tfor (vector::iterator it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t//\t\tprintf(\""%d\"", *it);\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < FDS.size(); i++) // 测试每个FD\n\t{\n\t\tvector closure; //闭包\n\n\t\tvector readedFD; // 加入闭包过的FD\n\t\treadedFD.push_back(i);\n\n\t\t// push当前FD\n vector::iterator it;\n\t\tfor (it = FDS[i].begin(); it != FDS[i].end(); it++)\n\t\t{\n\t\t\tif (*it != 0)\n\t\t\t{\n\t\t\t\tclosure.push_back(*it);\n\t\t\t}\n\t\t}\n\n\t\tfor (m = 0; m < M; m++)\n\t\t{\n\t\t\t// 遍历所有FD,看是否可以形成闭包\n\t\t\tfor (j = 0; j < FDS.size(); j++)\n\t\t\t{\n\t\t\t\tif (findEle(readedFD, j)) // 该FD已经在closure内了\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\t// 遍历FDS[j]\n\t\t\t\t\tvector::iterator it;\n\t\t\t\t\tfor (it = FDS[j].begin(); *it != 0; it++)\n\t\t\t\t\t{\n\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (*it != 0) //不正常结束\n\t\t\t\t\t{\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\treadedFD.push_back(j);\n\t\t\t\t\t\tit = it + 1;\n\t\t\t\t\t\tfor (; it != FDS[j].end(); it++)\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tif (!findEle(closure, *it))\n\t\t\t\t\t\t\t{\n\t\t\t\t\t\t\t\tclosure.push_back(*it);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (closure.size() != N)\n\t\t{\n\t\t\tprintf(\""False\"");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n}\n",TIME_LIMIT_EXCEEDED,0,0 1456940474078113792,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 19:04:12,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n if (n == 0) printf(\"" \"");\n int a[32] = { 0 };\n int i = 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n int b[32] = { 0 };\n int j = 2 * n - 1;\n for (int i=0; j>= 0; j--) {\n b[i] = a[j];\n i++;\n }\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n \n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3&&flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n } \n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i+=2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i =n-1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,46,484 1456940535198064640,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 19:04:26,C++,7.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\t//char tmp1[30], tmp2[30];\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\t//scanf_s(\""%s -> %s\"", tmp1, tmp2);\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,37,768 1456941999182127104,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 19:10:15,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n int r = 1;\n for (int i = 0; i < 2*n; i++) r = r * 2;\n if (h > r) return 0;\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[32] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3 && flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,47,356 1456942514070138880,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 19:12:18,C++,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\n\t\t//char tmp1[30], tmp2[30];\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\t//scanf_s(\""%s -> %s\"", tmp1, tmp2);\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n \n // merge dependencies that have the same attr1\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tfor (int j = 1 + i; j < M; ++j)\n\t\t{\n\t\t\tif (depd[i].attr1 == depd[j].attr1)\n\t\t\t{\n\t\t\t\tunsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n\t\t\t\tdepd[j].attr2 = result;\n\t\t\t}\n\t\t}\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,35,612 1456943404042727424,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 19:15:50,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n if (n <= 0 || h < 0) return 0;\n\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[32] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3 && flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,44,512 1456944001395503104,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 19:18:13,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[32] = { 0 };\n int i = 0;\n if (n <= 0 || h < 0) printf(\""false\"");\n\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[32] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3 && flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,51,372 1456944326672166912,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 19:19:30,C,4.0,1456179472801480704,1456154017474035712,615,"#include\nint main(){\n int N,M;\n scanf(\""%d%d\"",&N,&M);\n if(M%2==0){\n printf(\""True\""); \n }\n else printf(\""False\"");\n}",PARTIAL_ACCEPTED,28,324 1456945403068985344,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-06 19:23:47,C,7.0,1456179472809869313,1456174491838988288,639,"#include\nint main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n if (n <= 0 || h < 0) return 0;\n int a[32] = { 0 };\n int i = 0;\n\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[32] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[32] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3 && flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[32] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[32] = { 0 };\n int f[32] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,46,364 1456946145804726272,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 19:26:44,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \nusing namespace std;\n/// \n/// 矩阵乘法\n/// \n/// 第一个矩阵\n/// 第二个矩阵\n/// 矩阵1行数\n/// 矩阵1列数=矩阵2行数\n/// 矩阵2列数\n/// 返回矩阵\nvoid multipleMatrix(double* firstM, double* secondM, int rowOf1, int colOf1, int colOf2, double* backMatrix)\n{\n\tint i, j, k;\n\tfor (i = 0; i < rowOf1; i++)\n\t{\n\t\tfor (j = 0; j < colOf2; j++)\n\t\t{\n\t\t\tfor (k = 0; k < colOf1; k++)\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] += firstM[i * colOf1 + k] * secondM[k * colOf2 + j];\n\t\t\t}\n\t\t\t// 布尔乘法\n\t\t\tif (backMatrix[i * colOf2 + j] >= 1)\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 0;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\t\n\tdouble* FDS = (double*)calloc(N * N, sizeof(double));\n\tdouble* left = (double*)calloc(M * N, sizeof(double));\n\t// initialize\n\tint i, j, k, m, n;\n\tfor (i = 0; i < N; i++)\n\t{\n\t\tFDS[i * N + i] = 1;\n\t}\n\tvector stack_left;\n\tvector stack_right;\n\n\t// Input FDS\n\tscanf(\""%c\"", &c);\n\tfor(i=0; i\n#include \n#include \nusing namespace std;\n\nvoid multipleMatrix(double* firstM, double* secondM, int rowOf1, int colOf1, int colOf2, double* backMatrix)\n{\n\tint i, j, k;\n\tfor (i = 0; i < rowOf1; i++)\n\t{\n\t\tfor (j = 0; j < colOf2; j++)\n\t\t{\n\t\t\tfor (k = 0; k < colOf1; k++)\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] += firstM[i * colOf1 + k] * secondM[k * colOf2 + j];\n\t\t\t}\n\t\t\t// 布尔乘法\n\t\t\tif (backMatrix[i * colOf2 + j] >= 1)\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 0;\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\t\n\tdouble* FDS = (double*)calloc(N * N, sizeof(double));\n\tdouble* left = (double*)calloc(M * N, sizeof(double));\n\t// initialize\n\tint i, j, k, m, n;\n\tfor (i = 0; i < N; i++)\n\t{\n\t\tFDS[i * N + i] = 1;\n\t}\n\tvector stack_left;\n\tvector stack_right;\n\n\t// Input FDS\n\tscanf(\""%c\"", &c);\n\tfor(i=0; i\n#include \n\nvoid multipleMatrix(double* firstM, double* secondM, int rowOf1, int colOf1, int colOf2, double* backMatrix)\n{\n\tint i, j, k;\n\tfor (i = 0; i < rowOf1; i++)\n\t{\n\t\tfor (j = 0; j < colOf2; j++)\n\t\t{\n\t\t\tint sum = 0;\n\t\t\tfor (k = 0; k < colOf1; k++)\n\t\t\t{\n\t\t\t\tsum += firstM[i * colOf1 + k] * secondM[k * colOf2 + j];\n\t\t\t}\n\t\t\t// 布尔乘法\n\t\t\tif (sum >= 1)\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 0;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint calc_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\t\n\tdouble* FDS = (double*)calloc(N * N, sizeof(double));\n\tdouble* left = (double*)calloc(M * N, sizeof(double));\n\t// initialize\n\tint i, j, k, m, n;\n\tfor (i = 0; i < N; i++)\n\t{\n\t\tFDS[i * N + i] = 1;\n\t}\n\tchar stack_left[100];\n\tchar stack_right[100];\n\n\t// Input FDS\n\tscanf(\""%c\"", &c);\n\tfor(i=0; i %s\"", stack_left, stack_right);\n\t\t// calc length\n\t\tint length_left = calc_len(stack_left);\n\t\tint length_right = calc_len(stack_right);\n\t\t// 将关系加入矩阵\n\t\tdouble weight = 1.0 / length_left;\n\t\tfor (j = 0; j < length_left; j++)\n\t\t{\n\t\t\tint index_x = stack_left[j] - 'A';\n\t\t\tfor (k = 0; k < length_right; k++)\n\t\t\t{\n\t\t\t\tint index_y = stack_right[k] - 'A';\n\t\t\t\tFDS[index_x * N + index_y] = weight;\n\t\t\t}\n\t\t\tleft[i*N + index_x] = 1;\n\t\t}\n\t}\n\n\t//// test income\n\t//for (i = 0; i < N; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", FDS[i*N+j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t//printf(\""\\n\"");\n\t//for (i = 0; i < M; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", left[i * N + j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < M; i++)\n\t{\n\t\t//读入横向量\n\t\tdouble* vector_left = (double*)calloc(N, sizeof(double));\n\t\tdouble* back = (double*)calloc(N, sizeof(double));\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tvector_left[j] = left[i * N + j];\n\t\t}\n\t\tfor (j = 0; j < 30; j++)\n\t\t{\n\t\t\tmultipleMatrix(vector_left, FDS, 1, N, N, back);\n\t\t\tfor (k = 0; k < N; k++)\n\t\t\t{\n\t\t\t\tvector_left[k] = back[k];\n\t\t\t}\n\t\t}\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tif (vector_left[j] == 0)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n\n\n}\n",PARTIAL_ACCEPTED,31,324 1456949788403113984,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 19:41:13,C,7.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n\nvoid multipleMatrix(double* firstM, double* secondM, int rowOf1, int colOf1, int colOf2, double* backMatrix)\n{\n\tint i, j, k;\n\tfor (i = 0; i < rowOf1; i++)\n\t{\n\t\tfor (j = 0; j < colOf2; j++)\n\t\t{\n\t\t\tint sum = 0;\n\t\t\tfor (k = 0; k < colOf1; k++)\n\t\t\t{\n\t\t\t\tsum += firstM[i * colOf1 + k] * secondM[k * colOf2 + j];\n\t\t\t}\n\t\t\t// 布尔乘法\n\t\t\tif (sum >= 1)\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 0;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint calc_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\t\n\tdouble* FDS = (double*)calloc(N * N, sizeof(double));\n\tdouble* left = (double*)calloc(M * N, sizeof(double));\n\t// initialize\n\tint i, j, k, m, n;\n\tfor (i = 0; i < N; i++)\n\t{\n\t\tFDS[i * N + i] = 1;\n\t}\n\tchar stack_left[100];\n\tchar stack_right[100];\n\n\t// Input FDS\n\tscanf(\""%c\"", &c);\n\tfor(i=0; i %s\"", stack_left, stack_right);\n\t\t// calc length\n\t\tint length_left = calc_len(stack_left);\n\t\tint length_right = calc_len(stack_right);\n\t\t// 将关系加入矩阵\n\t\tdouble weight = 1.0 / length_left;\n\t\tfor (j = 0; j < length_left; j++)\n\t\t{\n\t\t\tint index_x = stack_left[j] - 'A';\n\t\t\tfor (k = 0; k < length_right; k++)\n\t\t\t{\n\t\t\t\tint index_y = stack_right[k] - 'A';\n\t\t\t\tFDS[index_x * N + index_y] = weight;\n\t\t\t}\n\t\t\tleft[i*N + index_x] = 1;\n\t\t}\n\t}\n\n\t//// test income\n\t//for (i = 0; i < N; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", FDS[i*N+j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t//printf(\""\\n\"");\n\t//for (i = 0; i < M; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", left[i * N + j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < M; i++)\n\t{\n\t\t//读入横向量\n\t\tdouble* vector_left = (double*)calloc(N, sizeof(double));\n\t\tdouble* back = (double*)calloc(N, sizeof(double));\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tvector_left[j] = left[i * N + j];\n\t\t}\n\t\tfor (j = 0; j < 30; j++)\n\t\t{\n\t\t\tmultipleMatrix(vector_left, FDS, 1, N, N, back);\n\t\t\tfor (k = 0; k < N; k++)\n\t\t\t{\n\t\t\t\tvector_left[k] = back[k];\n\t\t\t}\n\t\t}\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tif (vector_left[j] == 0)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n\n\n}\n",PARTIAL_ACCEPTED,31,476 1456950201705635840,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 19:42:51,C,6.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n# define ERROR 1e-6\nvoid multipleMatrix(double* firstM, double* secondM, int rowOf1, int colOf1, int colOf2, double* backMatrix)\n{\n\tint i, j, k;\n\tfor (i = 0; i < rowOf1; i++)\n\t{\n\t\tfor (j = 0; j < colOf2; j++)\n\t\t{\n\t\t\tint sum = 0;\n\t\t\tfor (k = 0; k < colOf1; k++)\n\t\t\t{\n\t\t\t\tsum += firstM[i * colOf1 + k] * secondM[k * colOf2 + j];\n\t\t\t}\n\t\t\t// 布尔乘法\n\t\t\tif (fabs(sum - 1) %s\"", stack_left, stack_right);\n\t\t// calc length\n\t\tint length_left = calc_len(stack_left);\n\t\tint length_right = calc_len(stack_right);\n\t\t// 将关系加入矩阵\n\t\tdouble weight = 1.0 / length_left;\n\t\tfor (j = 0; j < length_left; j++)\n\t\t{\n\t\t\tint index_x = stack_left[j] - 'A';\n\t\t\tfor (k = 0; k < length_right; k++)\n\t\t\t{\n\t\t\t\tint index_y = stack_right[k] - 'A';\n\t\t\t\tFDS[index_x * N + index_y] = weight;\n\t\t\t}\n\t\t\tleft[i*N + index_x] = 1;\n\t\t}\n\t}\n\n\t//// test income\n\t//for (i = 0; i < N; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", FDS[i*N+j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t//printf(\""\\n\"");\n\t//for (i = 0; i < M; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", left[i * N + j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < M; i++)\n\t{\n\t\t//读入横向量\n\t\tdouble* vector_left = (double*)calloc(N, sizeof(double));\n\t\tdouble* back = (double*)calloc(N, sizeof(double));\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tvector_left[j] = left[i * N + j];\n\t\t}\n\t\tfor (j = 0; j < 30; j++)\n\t\t{\n\t\t\tmultipleMatrix(vector_left, FDS, 1, N, N, back);\n\t\t\tfor (k = 0; k < N; k++)\n\t\t\t{\n\t\t\t\tvector_left[k] = back[k];\n\t\t\t}\n\t\t}\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tif (vector_left[j] == 0)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n\n\n}\n",PARTIAL_ACCEPTED,31,604 1456950419901165568,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 19:43:43,C,6.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n# define ERROR 1e-6\nvoid multipleMatrix(double* firstM, double* secondM, int rowOf1, int colOf1, int colOf2, double* backMatrix)\n{\n\tint i, j, k;\n\tfor (i = 0; i < rowOf1; i++)\n\t{\n\t\tfor (j = 0; j < colOf2; j++)\n\t\t{\n\t\t\tdouble sum = 0;\n\t\t\tfor (k = 0; k < colOf1; k++)\n\t\t\t{\n\t\t\t\tsum += firstM[i * colOf1 + k] * secondM[k * colOf2 + j];\n\t\t\t}\n\t\t\t// 布尔乘法\n\t\t\tif (fabs(sum - 1) %s\"", stack_left, stack_right);\n\t\t// calc length\n\t\tint length_left = calc_len(stack_left);\n\t\tint length_right = calc_len(stack_right);\n\t\t// 将关系加入矩阵\n\t\tdouble weight = 1.0 / length_left;\n\t\tfor (j = 0; j < length_left; j++)\n\t\t{\n\t\t\tint index_x = stack_left[j] - 'A';\n\t\t\tfor (k = 0; k < length_right; k++)\n\t\t\t{\n\t\t\t\tint index_y = stack_right[k] - 'A';\n\t\t\t\tFDS[index_x * N + index_y] = weight;\n\t\t\t}\n\t\t\tleft[i*N + index_x] = 1;\n\t\t}\n\t}\n\n\t//// test income\n\t//for (i = 0; i < N; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", FDS[i*N+j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t//printf(\""\\n\"");\n\t//for (i = 0; i < M; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", left[i * N + j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < M; i++)\n\t{\n\t\t//读入横向量\n\t\tdouble* vector_left = (double*)calloc(N, sizeof(double));\n\t\tdouble* back = (double*)calloc(N, sizeof(double));\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tvector_left[j] = left[i * N + j];\n\t\t}\n\t\tfor (j = 0; j < 30; j++)\n\t\t{\n\t\t\tmultipleMatrix(vector_left, FDS, 1, N, N, back);\n\t\t\tfor (k = 0; k < N; k++)\n\t\t\t{\n\t\t\t\tvector_left[k] = back[k];\n\t\t\t}\n\t\t}\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tif (vector_left[j] == 0)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n\n\n}\n",PARTIAL_ACCEPTED,31,476 1456950707190018048,7aa8e3cc1de773bd88425cd1415ddc990c32d7bd17ed82e70aa6724ee77600a6,2021-11-06 19:44:52,C,10.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n# define ERROR 1e-6\nvoid multipleMatrix(double* firstM, double* secondM, int rowOf1, int colOf1, int colOf2, double* backMatrix)\n{\n\tint i, j, k;\n\tfor (i = 0; i < rowOf1; i++)\n\t{\n\t\tfor (j = 0; j < colOf2; j++)\n\t\t{\n\t\t\tdouble sum = 0;\n\t\t\tfor (k = 0; k < colOf1; k++)\n\t\t\t{\n\t\t\t\tsum += firstM[i * colOf1 + k] * secondM[k * colOf2 + j];\n\t\t\t}\n\t\t\t// 布尔乘法\n\t\t\tif ((sum - 1)>(0-ERROR))\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tbackMatrix[i * colOf2 + j] = 0;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint calc_len(char* a) {\n\tint i = 0;\n\twhile (a[i] != '\\0') {\n\t\ti++;\n\t}\n\treturn i;\n}\n\nint main()\n{\n\tint N, M;\n\tchar c;\n\tscanf(\""%d\"", &N);\n\tscanf(\""%d\"", &M);\n\t\n\tdouble* FDS = (double*)calloc(N * N, sizeof(double));\n\tdouble* left = (double*)calloc(M * N, sizeof(double));\n\t// initialize\n\tint i, j, k, m, n;\n\tfor (i = 0; i < N; i++)\n\t{\n\t\tFDS[i * N + i] = 1;\n\t}\n\tchar stack_left[100];\n\tchar stack_right[100];\n\n\t// Input FDS\n\tscanf(\""%c\"", &c);\n\tfor(i=0; i %s\"", stack_left, stack_right);\n\t\t// calc length\n\t\tint length_left = calc_len(stack_left);\n\t\tint length_right = calc_len(stack_right);\n\t\t// 将关系加入矩阵\n\t\tdouble weight = 1.0 / length_left;\n\t\tfor (j = 0; j < length_left; j++)\n\t\t{\n\t\t\tint index_x = stack_left[j] - 'A';\n\t\t\tfor (k = 0; k < length_right; k++)\n\t\t\t{\n\t\t\t\tint index_y = stack_right[k] - 'A';\n\t\t\t\tFDS[index_x * N + index_y] = weight;\n\t\t\t}\n\t\t\tleft[i*N + index_x] = 1;\n\t\t}\n\t}\n\n\t//// test income\n\t//for (i = 0; i < N; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", FDS[i*N+j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\t//printf(\""\\n\"");\n\t//for (i = 0; i < M; i++)\n\t//{\n\t//\tfor (j = 0; j < N; j++)\n\t//\t{\n\t//\t\tprintf(\""%lf\\t\"", left[i * N + j]);\n\t//\t}\n\t//\tprintf(\""\\n\"");\n\t//}\n\n\tfor (i = 0; i < M; i++)\n\t{\n\t\t//读入横向量\n\t\tdouble* vector_left = (double*)calloc(N, sizeof(double));\n\t\tdouble* back = (double*)calloc(N, sizeof(double));\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tvector_left[j] = left[i * N + j];\n\t\t}\n\t\tfor (j = 0; j < 30; j++)\n\t\t{\n\t\t\tmultipleMatrix(vector_left, FDS, 1, N, N, back);\n\t\t\tfor (k = 0; k < N; k++)\n\t\t\t{\n\t\t\t\tvector_left[k] = back[k];\n\t\t\t}\n\t\t}\n\t\tfor (j = 0; j < N; j++)\n\t\t{\n\t\t\tif (vector_left[j] == 0)\n\t\t\t{\n\t\t\t\tprintf(\""False\"");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\""True\"");\n\treturn 0;\n\n\n\n}\n",ACCEPTED,32,356 1456953787960832000,8998a334ff60da7a8d331523d564677bcfb01c506d86283912e1cb22d676a77e,2021-11-06 19:57:06,Java,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include\n#include\n#include\n//ab->c:ab's closure=c+a's+b's+c+a+b\n//a->bc:a's closure=bc's(if not established,is null),traverse if whise \nusing namespace std;\nclass Dependency {\npublic:\n vector source;\n vector decide;\n bool realDecide[26];\n};\nvector depends;\nbool InClosure(int i, int j) {\n for (int t = 0; t < depends[j].source.size(); t++) {\n if (depends[i].realDecide[depends[j].source[t]-'A'] == false)\n return false;\n }\n return true;\n}\nint main()\n{\n int m, n;\n cin >> m;\n cin >> n;\n string t;//for input\n Dependency d;\n for (int i = 0; i < m; i++) {\n d.decide.clear();\n d.source.clear();\n cin >> t;\n for (int j = 0; j < t.length(); j++) {\n d.source.push_back(t[j]);\n }\n cin >> t;\n cin >> t;\n for (int j = 0; j < t.length(); j++) {\n d.decide.push_back(t[j]);\n }\n depends.push_back(d);\n }\n //initialize all the decides\n for (int i = 0; i \n#include\n#include\n#include\n//ab->c:ab's closure=c+a's+b's+c+a+b\n//a->bc:a's closure=bc's(if not established,is null),traverse if whise \nusing namespace std;\nclass Dependency {\npublic:\n vector source;\n vector decide;\n bool realDecide[26];\n};\nvector depends;\nbool InClosure(int i, int j) {\n for (int t = 0; t < depends[j].source.size(); t++) {\n if (depends[i].realDecide[depends[j].source[t]-'A'] == false)\n return false;\n }\n return true;\n}\nint main()\n{\n int m, n;\n cin >> m;\n cin >> n;\n string t;//for input\n Dependency d;\n for (int i = 0; i < m; i++) {\n d.decide.clear();\n d.source.clear();\n cin >> t;\n for (int j = 0; j < t.length(); j++) {\n d.source.push_back(t[j]);\n }\n cin >> t;\n cin >> t;\n for (int j = 0; j < t.length(); j++) {\n d.decide.push_back(t[j]);\n }\n depends.push_back(d);\n }\n //initialize all the decides\n for (int i = 0; i \n#include\n#include\n#include\n//ab->c:ab's closure=c+a's+b's+c+a+b\n//a->bc:a's closure=bc's(if not established,is null),traverse if whise \nusing namespace std;\nclass Dependency {\npublic:\n vector source;\n vector decide;\n bool realDecide[26];\n};\nvector depends;\nbool InClosure(int i, int j) {\n for (int t = 0; t < depends[j].source.size(); t++) {\n if (depends[i].realDecide[depends[j].source[t]-'A'] == false)\n return false;\n }\n return true;\n}\nint main()\n{\n int m, n;\n cin >> n;\n cin >> m;\n string t;//for input\n Dependency d;\n for (int i = 0; i < m; i++) {\n d.decide.clear();\n d.source.clear();\n cin >> t;\n for (int j = 0; j < t.length(); j++) {\n d.source.push_back(t[j]);\n }\n cin >> t;\n cin >> t;\n for (int j = 0; j < t.length(); j++) {\n d.decide.push_back(t[j]);\n }\n depends.push_back(d);\n }\n //initialize all the decides\n for (int i = 0; i 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[100] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[100] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1 && flag == 0) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3 && flag == 0) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0 && flag == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2 && flag == 0) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[100] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[100] = { 0 };\n int f[100] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,40,476 1456959024390545408,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 20:17:55,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n \n // merge dependencies that have the same attr1\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tfor (int j = 1 + i; j < M; ++j)\n\t\t{\n\t\t\tif (depd[i].attr1 == depd[j].attr1)\n\t\t\t{\n\t\t\t\tunsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n\t\t\t\tdepd[j].attr2 = result;\n\t\t\t}\n else if(true == inSet(depd[j].attr1, depd[i].att1))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n }\n\t\t}\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",COMPILE_ERROR,0,0 1456959064709836800,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 20:18:04,C++,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n \n // merge dependencies that have the same attr1\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tfor (int j = 1 + i; j < M; ++j)\n\t\t{\n\t\t\tif (depd[i].attr1 == depd[j].attr1)\n\t\t\t{\n\t\t\t\tunsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n\t\t\t\tdepd[j].attr2 = result;\n\t\t\t}\n else if(true == inSet(depd[j].attr1, depd[i].attr1))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n }\n\t\t}\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,30,488 1456960583836966912,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 20:24:06,C++,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n \n\tif (M == 0)\n\t{\n\t\t// the relation is BCNF\n\t\tcout << \""True\"";\n\t\treturn 0;\n\t}\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n \n // merge dependencies that have the same attr1\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tfor (int j = 1 + i; j < M; ++j)\n\t\t{\n\t\t\tif (depd[i].attr1 == depd[j].attr1)\n\t\t\t{\n\t\t\t\tunsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n\t\t\t\tdepd[j].attr2 = result;\n\t\t\t}\n else if(true == inSet(depd[j].attr1, depd[i].attr1))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n }\n\t\t}\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,34,600 1456963128479260672,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 20:34:13,C++,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n \n\tif (M == 0)\n\t{\n\t\t// the relation is BCNF\n\t\tcout << \""True\"";\n\t\treturn 0;\n\t}\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\t\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,30,480 1456963186846642176,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 20:34:27,C++,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n \n\tif (M == 0)\n\t{\n\t\t// the relation is BCNF\n\t\tcout << \""True\"";\n\t\treturn 0;\n\t}\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n \n // merge dependencies that have the same attr1\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tfor (int j = 1 + i; j < M; ++j)\n\t\t{\n\t\t\tif (depd[i].attr1 == depd[j].attr1)\n\t\t\t{\n\t\t\t\tunsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n\t\t\t\tdepd[j].attr2 = result;\n\t\t\t}\n else if(true == inSet(depd[j].attr1, depd[i].attr1))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n }\n\t\t}\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,30,616 1456964888912535552,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 20:41:13,C++,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n \n\tif (M == 0)\n\t{\n\t\t// the relation is BCNF\n\t\tcout << \""True\"";\n\t\treturn 0;\n\t}\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, depd[i].attr2))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n \n // merge dependencies that have the same attr1\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tfor (int j = 1 + i; j < M; ++j)\n\t\t{\n\t\t\tif (depd[i].attr1 == depd[j].attr1)\n\t\t\t{\n\t\t\t\tunsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n\t\t\t\tdepd[j].attr2 = result;\n\t\t\t}\n else if(true == inSet(depd[j].attr1, depd[i].attr1))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n }\n else if(true == inSet(depd[i].attr1, depd[j].attr2))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n depd[j].attr2 = result;\n }\n\t\t}\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",PARTIAL_ACCEPTED,39,640 1456968570391568384,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 20:55:51,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100], hen, jian;\n\tint a[27][27], b[27][27], c[27][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'A';\n\t}\n\n\tscanf_s(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t/*for (int i = 0; i < M; i++)\n\t{\n\t\tscanf_s(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf_s(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}*/\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t\n\treturn 0;\n}",COMPILE_ERROR,0,0 1456968800578613248,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 20:56:45,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100], hen, jian;\n\tint a[27][27], b[27][27], c[27][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'A';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t/*for (int i = 0; i < M; i++)\n\t{\n\t\tscanf_s(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf_s(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}*/\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t\n\treturn 0;\n}",COMPILE_ERROR,0,0 1456968866609541120,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 20:57:01,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nBool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100], hen, jian;\n\tint a[27][27], b[27][27], c[27][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'A';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t/*for (int i = 0; i < M; i++)\n\t{\n\t\tscanf_s(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf_s(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}*/\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t\n\treturn 0;\n}",COMPILE_ERROR,0,0 1456968910662316032,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 20:57:12,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100], hen, jian;\n\tint a[27][27], b[27][27], c[27][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'A';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t/*for (int i = 0; i < M; i++)\n\t{\n\t\tscanf_s(\""\\n\"");\n\t\tint j = 0, k = 0;\n\t\twhile ((qian[j] = getchar()) != ' ')\n\t\t{\n\t\t\tj++;\n\t\t}\n\t\tscanf_s(\"" -> \"");\n\t\twhile ((hou[k] = getchar()) != '\\n')\n\t\t{\n\t\t\tk++;\n\t\t}\n\t\tfor (int m = 0; m < j; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < k; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}*/\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t\n\treturn 0;\n}",SEGMENTATION_FAULT,43,360 1456969172844617728,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 20:58:14,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100], hen, jian;\n\tint a[27][27], b[27][27], c[27][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'A';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t\n\treturn 0;\n}",SEGMENTATION_FAULT,38,376 1456969633789685760,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:00:04,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[27][27], b[27][27], c[27][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'A';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t\n\treturn 0;\n}",SEGMENTATION_FAULT,41,356 1456970638279909376,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:04:04,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[100][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'A';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t\n\treturn 0;\n}",SEGMENTATION_FAULT,45,484 1456970804348628992,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:04:43,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[100][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'A';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t\n\treturn 0;\n}",SEGMENTATION_FAULT,37,356 1456976603842682880,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:27:46,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf_s(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets_s(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t",COMPILE_ERROR,0,0 1456976685169684480,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:28:05,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets_s(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t",COMPILE_ERROR,0,0 1456976760524550144,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:28:23,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t",COMPILE_ERROR,0,0 1456976810777059328,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:28:35,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tfgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t",COMPILE_ERROR,0,0 1456976868968280064,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:28:49,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t",COMPILE_ERROR,0,0 1456976932353155072,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:29:04,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t",COMPILE_ERROR,0,0 1456977151622979584,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:29:56,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n\t",COMPILE_ERROR,0,0 1456977248003891200,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:30:19,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456977786212233216,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:32:28,C#,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456977811345055744,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:32:34,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456978083957485568,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:33:39,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456978232805498880,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:34:14,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456978370034184192,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:34:47,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nusing namespace std;\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456978751527104512,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:36:18,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nusing namespace std;\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets_s(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456978888182276096,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:36:50,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nusing namespace std;\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgetline(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456978950866149376,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:37:05,C++,0.0,1456179472801480704,1456154017474035712,615,"#include\n\nusing namespace std;\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgetline(cin, line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456979400214519808,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:38:53,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\nusing namespace std;\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",COMPILE_ERROR,0,0 1456979433856479232,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:39:01,C,7.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n//using namespace std;\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",PARTIAL_ACCEPTED,29,324 1456979903778463744,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:40:53,C,7.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",PARTIAL_ACCEPTED,39,348 1456982139258056704,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:49:46,C,9.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M - 1][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M - 1][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",PARTIAL_ACCEPTED,29,328 1456982538828427264,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:51:21,C,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M - 1][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M - 1][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""True\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",PARTIAL_ACCEPTED,37,380 1456982612556455936,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:51:38,C,6.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M - 1][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M - 1][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""False\"");\n\t}\n}",PARTIAL_ACCEPTED,27,476 1456982660363132928,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 21:51:50,C,9.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M - 1][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M - 1][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",PARTIAL_ACCEPTED,35,348 1456986448964136960,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 22:06:53,C++,10.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n \n\tif (M == 0)\n\t{\n\t\t// the relation is BCNF\n\t\tcout << \""True\"";\n\t\treturn 0;\n\t}\n\n\tbool* pKey = new bool[N];\n\tfor(int i = 0; i < N; ++i)\n\t{\n\t\tpKey[i] = false;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, mergeSet(depd[i].attr1, depd[i].attr2)))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n \n // merge dependencies that have the same attr1\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tfor (int j = 1 + i; j < M; ++j)\n\t\t{\n\t\t\tif (depd[i].attr1 == depd[j].attr1)\n\t\t\t{\n\t\t\t\tunsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n\t\t\t\tdepd[j].attr2 = result;\n\t\t\t}\n else if(true == inSet(depd[j].attr1, depd[i].attr1))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n }\n else if(true == inSet(depd[i].attr1, depd[j].attr2))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n depd[j].attr2 = result;\n }\n\t\t}\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",ACCEPTED,32,496 1456987037886914560,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 22:09:14,C,6.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M - 1][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M - 1][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""False\"");\n\t}\n}",PARTIAL_ACCEPTED,28,324 1456987097882238976,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 22:09:28,C,9.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M - 1][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M - 1][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",PARTIAL_ACCEPTED,34,324 1456987394968985600,77ad61be497f9508f9f008cb91fbc96c5ca73fd6a3a6e2e828588ec452249e20,2021-11-06 22:10:39,C++,10.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\nusing namespace std;\n\nstruct dependency\n{\n\tunsigned int attr1;\n\tunsigned int attr2;\n};\n\n// returns true if, in binary form, all 1s in A appear in B\nbool inSet(unsigned int A, unsigned int B);\n\nunsigned int mergeSet(unsigned int A, unsigned int B);\n\n// return B - A, which is same as B intersect complement(A)\nunsigned int exceptionSet(unsigned int A, unsigned int B);\n\n// if the dependency is superkey or trivial dependency, returns true\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2);\n\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n \n\tif (M == 0)\n\t{\n\t\t// the relation is BCNF\n\t\tcout << \""True\"";\n\t\treturn 0;\n\t}\n\n\t// read in dependencies\n\tdependency* depd = new dependency[M];\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tchar sign1,sign2;\n\t\tstring tmp1, tmp2;\n\t\tcin >> tmp1;\n\t\tcin >> sign1 >> sign2;\n\t\tcin >> tmp2;\n\t\tdepd[i].attr1 = 0;\n\t\tdepd[i].attr2 = 0;\n\t\tfor(int j = 0; tmp1[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr1 += (0b1 << (tmp1[j] - 'A'));\n\t\t}\n for(int j = 0; tmp2[j] != '\\0'; ++j)\n\t\t{\n\t\t\tdepd[i].attr2 += (0b1 << (tmp2[j] - 'A'));\n\t\t}\n\t}\n\t\n\tbool change = true;\n\t// calculate the closure of attributes\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tbool skipList[30];\n\t\tfor(int k = 0; k < M; ++k)\n\t\t{\n\t\t\tif(k == i)\n\t\t\t{\n\t\t\t\tskipList[k] = true;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tskipList[k] = false;\n\t\t\t}\n\t\t}\n\n\t\twhile(change == true)\n\t\t{\n\t\t\tchange = false;\n\t\t\tfor(int j = 0; j < M; ++j)\n\t\t\t{\n\t\t\t\tif(skipList[j] == true)\n\t\t\t\t{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\t// Assume dependency j is A -> B, and if A is in the right side of dependency i\n\t\t\t\t// add B to dependency i, and let change be true\n\t\t\t\tif(inSet(depd[j].attr1, mergeSet(depd[i].attr1, depd[i].attr2)))\n\t\t\t\t{\n\t\t\t\t\tdepd[i].attr2 = mergeSet(depd[i].attr2, depd[j].attr2);\n skipList[j] = true;\n\t\t\t\t\tchange = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tchange = true;\n\t}\n \n // merge dependencies that have the same attr1\n\tfor (int i = 0; i < M; ++i)\n\t{\n\t\tfor (int j = 1 + i; j < M; ++j)\n\t\t{\n\t\t\tif (depd[i].attr1 == depd[j].attr1)\n\t\t\t{\n\t\t\t\tunsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n\t\t\t\tdepd[j].attr2 = result;\n\t\t\t}\n else if(true == inSet(depd[j].attr1, depd[i].attr1))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n\t\t\t\tdepd[i].attr2 = result;\n }\n else if(true == inSet(depd[i].attr1, depd[j].attr2))\n {\n unsigned int result = depd[i].attr2 | depd[j].attr2;\n depd[j].attr2 = result;\n }\n\t\t}\n\t}\n\n\t// test all closures\n\tfor(int i = 0; i < M; ++i)\n\t{\n\t\tif(false == testValid(N, depd[i].attr1, depd[i].attr2))\n\t\t{\n\t\t\tcout << \""False\"";\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\n\n\n\t// the relation has passed all test, is a BCNF\n\tcout << \""True\"";\n\treturn 0;\n\n}\n\n\nbool inSet(unsigned int A, unsigned int B)\n{\n\tif((A | B) == B)\n\t{\n\t\t// in binary form, all 1s in A appear in B\n\t\treturn true;\n\t}\n\telse\n\t{\n\t\treturn false;\n\t}\n}\n\nunsigned int mergeSet(unsigned int A, unsigned int B)\n{\n\treturn A | B;\n}\n\nunsigned int exceptionSet(unsigned int A, unsigned int B)\n{\n\treturn (~A) & B;\n}\n\n\n\nbool testValid(int eleNum, unsigned int attr1, unsigned int attr2)\n{\n\t// test whether the dependency is trivial\n\tif(true == inSet(attr2, attr1))\n\t{\n\t\treturn true;\n\t}\n\t// test whether the dependency is superkey\n\tunsigned int unionSet = mergeSet(attr1, attr2);\n\tfor(int i = 0; i < eleNum; ++i)\n\t{\n\t\tif(unionSet % 2 == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t\tunionSet /= 2;\n\t}\n\treturn true;\n}",ACCEPTED,32,452 1456988329484529664,92e0d7afac88ecd670f3f1aa3c5930a890c70c7702e0fc9aa9fe31752863f333,2021-11-06 22:14:21,C,10.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n\n\nbool thislei(int* a, int* b)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (b[i] == 1 && a[i] == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nvoid combine(int* aa, int* bb, int* key)\n{\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tif (aa[i] == 1 || bb[i] == 1 || key[i] == 1)\n\t\t{\n\t\t\tkey[i] = 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tkey[i] = 0;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint N, M, answer;\n\tchar qian[27], hou[27], line[100];\n\tint a[100][27], b[100][27], c[100][27], d[27][27], aa[27], bb[27], key[27];\n\tanswer = 1;\n\n\tfor (int i = 0; i < 27; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\ta[i][j] = 0;\n\t\t\tb[i][j] = 0;\n\t\t\tc[i][j] = 0;\n\t\t\td[i][j] = 0;\n\t\t}\n\t\tkey[i] = 0;\n\t\n\t\tqian[i] = 'A';\n\t\thou[i] = 'A';\n\t\taa[i] = 0;\n\t\tbb[i] = 0;\n\t}\n\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = ' ';\n\t}\n\n\tscanf(\""%d %d\"", &N, &M);\n\tgetchar();\n\t//得到a与b为存储左右两边出现的属性\n\tfor (int i = 0; i < M - 1; i++)\n\t{\n\t\tfor (int j = 0; (line[j] = getchar()) != '\\n'; j++);\n\t\tint j1, j2, j3 = 0;\n\t\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t\t{\n\t\t\tqian[j1] = line[j1];\n\t\t}\n\t\tj3 = j1 + 4;\n\t\tfor (j2 = 0; line[j3] != '\\n'; j2++)\n\t\t{\n\t\t\thou[j2] = line[j3];\n\t\t\tj3++;\n\t\t}\n\t\tfor (int m = 0; m < j1; m++)\n\t\t{\n\t\t\ta[i][m] = qian[m] - 'A' + 1;\n\t\t}\n\t\tfor (int n = 0; n < j2; n++)\n\t\t{\n\t\t\tb[i][n] = hou[n] - 'A' + 1;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < 100; i++)\n\t{\n\t\tline[i] = 'a';\n\t}\n\t//for (int j = 0; (line[j] = getchar()) != ' '; j++);\n\tgets(line);\n\tint j1, j2, j3 = 0;\n\tfor (j1 = 0; line[j1] != ' '; j1++)\n\t{\n\t\tqian[j1] = line[j1];\n\t}\n\tj3 = j1 + 4;\n\tfor (j2 = 0; line[j3] != '\\0'; j2++)\n\t{\n\t\thou[j2] = line[j3];\n\t\tj3++;\n\t}\n\tfor (int m = 0; m < j1; m++)\n\t{\n\t\ta[M - 1][m] = qian[m] - 'A' + 1;\n\t}\n\tfor (int n = 0; n < j2; n++)\n\t{\n\t\tb[M - 1][n] = hou[n] - 'A' + 1;\n\t}\n\n\t//cc,d记录的是每一个函数依赖中字母的下标\n\tfor (int i = 0; i < M; i++)\n\t{\n\t\tfor (int j = 0; j < 27; j++)\n\t\t{\n\t\t\tc[i][a[i][j]] = 1;\n\t\t\td[i][b[i][j]] = 1;\n\t\t}\n\t}\n\n\t//对每一个函数依赖进行递推\n\tfor (int i = 0; i < M; i++)\n\t{\n for (int oo = 0; oo < 27; oo++)\n\t\t{\n\t\t\tkey[oo] = 0;\n\t\t}\n\t\tfor (int j = 0; j < N + 1; j++)\n\t\t{\n\n\t\t\taa[j] = c[i][j];\n\t\t\tbb[j] = d[i][j];\n\t\t}\n\n\t\tcombine(aa, bb, key);\n\t\tfor (int t = 0; t < M; t++) {\n\t\t\tfor (int k = 0; k < M; k++)\n\t\t\t{\n\t\t\t\tif (thislei(key, c[k]) == true)\n\t\t\t\t{\n\t\t\t\t\tcombine(c[k], d[k], key);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int s = 1; s <= N; s++)\n\t\t{\n\t\t\tif (key[s] == 0)\n\t\t\t{\n\t\t\t\tanswer = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif (answer == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (answer == 0)\n\t{\n\t\tprintf(\""False\"");\n\t}\n\telse\n\t{\n\t\tprintf(\""True\"");\n\t}\n}",ACCEPTED,31,348 1457017928679469056,b764051653ac87bc0f7848e3b5204a1380cda826d33cd07f97862d9f21a0b8b7,2021-11-07 00:11:58,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n\n\nstruct disjointSet {\n int * rank;\n int size;\n};\ntypedef struct disjointSet DisjointSet;\n\nDisjointSet init(int n) {\n DisjointSet res;\n res.size = n;\n res.rank = (int*)malloc(sizeof(int) * n);\n for (int i = 0; i < n; i += 1) {\n res.rank[i] = -1;\n }\n return res;\n\n}\n\nint Find(int x, DisjointSet set) {\n int root, trail, lead;\n for (root = x; set.rank[root] > 0; root = set.rank[root]);\n for (trail = x; trail != root; trail = lead) {\n lead = set.rank[trail];\n set.rank[trail] = root;\n }\n return root;\n\n}\n\nvoid Check(int i, int j, DisjointSet set) {\n if (Find(i, set) == Find(j, set)) {\n printf(\""yes\\n\"");\n } else {\n printf(\""no\\n\"");\n }\n\n}\n\nvoid Union(int i, int j, DisjointSet set) {\n int rootI = Find(i, set);\n int rootJ = Find(j, set);\n\n /**\n * Root of i is bigger than j.\n * Connect j to i.\n */\n if (set.rank[rootI] < set.rank[rootJ]) {\n set.rank[rootI] += set.rank[rootJ];\n set.rank[rootJ] = rootI;\n }\n else {\n set.rank[rootJ] += set.rank[rootI];\n set.rank[rootI] = rootJ;\n }\n\n}\n\nvoid Stop(DisjointSet set) {\n int count = 0;\n for (int i = 0; i < set.size; i += 1) {\n if (set.rank[i] <= -1) count += 1;\n }\n if (count == 1) {\n printf(\""True\\n\"");\n } else {\n printf(\""False\\n\"");\n }\n\n}\n\nint main() {\n int m, n;\n char x, y;\n scanf(\""%d %d\\n\"", &m, &n);\n DisjointSet set = init(m);\n\n for (int i = 0; i < n; i += 1) {\n char x = getchar();\n\n for (int j = 0; j < 4; j += 1) {\n getchar();\n }\n\n while ((y = getchar()) != '\\n') {\n Union(x - 'A', y - 'A', set);\n }\n\n }\n int i = 0;\n Stop(set);\n\n\n return 0;\n\n}\n",TIME_LIMIT_EXCEEDED,0,0 1457018084561330176,b764051653ac87bc0f7848e3b5204a1380cda826d33cd07f97862d9f21a0b8b7,2021-11-07 00:12:36,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n\n\nstruct disjointSet {\n int * rank;\n int size;\n};\ntypedef struct disjointSet DisjointSet;\n\nDisjointSet init(int n) {\n DisjointSet res;\n res.size = n;\n res.rank = (int*)malloc(sizeof(int) * n);\n for (int i = 0; i < n; i += 1) {\n res.rank[i] = -1;\n }\n return res;\n\n}\n\nint Find(int x, DisjointSet set) {\n int root, trail, lead;\n for (root = x; set.rank[root] > 0; root = set.rank[root]);\n for (trail = x; trail != root; trail = lead) {\n lead = set.rank[trail];\n set.rank[trail] = root;\n }\n return root;\n\n}\n\nvoid Union(int i, int j, DisjointSet set) {\n int rootI = Find(i, set);\n int rootJ = Find(j, set);\n\n /**\n * Root of i is bigger than j.\n * Connect j to i.\n */\n if (set.rank[rootI] < set.rank[rootJ]) {\n set.rank[rootI] += set.rank[rootJ];\n set.rank[rootJ] = rootI;\n }\n else {\n set.rank[rootJ] += set.rank[rootI];\n set.rank[rootI] = rootJ;\n }\n\n}\n\nvoid Stop(DisjointSet set) {\n int count = 0;\n for (int i = 0; i < set.size; i += 1) {\n if (set.rank[i] <= -1) count += 1;\n }\n if (count == 1) {\n printf(\""True\\n\"");\n } else {\n printf(\""False\\n\"");\n }\n\n}\n\nint main() {\n int m, n;\n char x, y;\n scanf(\""%d %d\\n\"", &m, &n);\n DisjointSet set = init(m);\n\n for (int i = 0; i < n; i += 1) {\n char x = getchar();\n\n for (int j = 0; j < 4; j += 1) {\n getchar();\n }\n\n while ((y = getchar()) != '\\n') {\n Union(x - 'A', y - 'A', set);\n }\n\n }\n Stop(set);\n \n return 0;\n\n}\n",TIME_LIMIT_EXCEEDED,0,0 1457018359535706112,b764051653ac87bc0f7848e3b5204a1380cda826d33cd07f97862d9f21a0b8b7,2021-11-07 00:13:41,C,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n#include \n\nusing namespace std;\n\nstruct disjointSet {\n int * rank;\n int size;\n};\ntypedef struct disjointSet DisjointSet;\n\nDisjointSet init(int n) {\n DisjointSet res;\n res.size = n;\n res.rank = (int*)malloc(sizeof(int) * n);\n for (int i = 0; i < n; i += 1) {\n res.rank[i] = -1;\n }\n return res;\n\n}\n\nint Find(int x, DisjointSet set) {\n int root, trail, lead;\n for (root = x; set.rank[root] > 0; root = set.rank[root]);\n for (trail = x; trail != root; trail = lead) {\n lead = set.rank[trail];\n set.rank[trail] = root;\n }\n return root;\n\n}\n\nvoid Union(int i, int j, DisjointSet set) {\n int rootI = Find(i, set);\n int rootJ = Find(j, set);\n\n /**\n * Root of i is bigger than j.\n * Connect j to i.\n */\n if (set.rank[rootI] < set.rank[rootJ]) {\n set.rank[rootI] += set.rank[rootJ];\n set.rank[rootJ] = rootI;\n }\n else {\n set.rank[rootJ] += set.rank[rootI];\n set.rank[rootI] = rootJ;\n }\n\n}\n\nvoid Stop(DisjointSet set) {\n int count = 0;\n for (int i = 0; i < set.size; i += 1) {\n if (set.rank[i] <= -1) count += 1;\n }\n if (count == 1) {\n printf(\""True\\n\"");\n } else {\n printf(\""False\\n\"");\n }\n\n}\n\nint main() {\n int m, n;\n char x, y;\n scanf(\""%d %d\\n\"", &m, &n);\n DisjointSet set = init(m);\n\n for (int i = 0; i < n; i += 1) {\n char x = getchar();\n\n for (int j = 0; j < 4; j += 1) {\n getchar();\n }\n\n while ((y = getchar()) != '\\n') {\n Union(x - 'A', y - 'A', set);\n }\n\n }\n Stop(set);\n \n return 0;\n\n}\n",COMPILE_ERROR,0,0 1457018410143625216,b764051653ac87bc0f7848e3b5204a1380cda826d33cd07f97862d9f21a0b8b7,2021-11-07 00:13:53,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n\nstruct disjointSet {\n int * rank;\n int size;\n};\ntypedef struct disjointSet DisjointSet;\n\nDisjointSet init(int n) {\n DisjointSet res;\n res.size = n;\n res.rank = (int*)malloc(sizeof(int) * n);\n for (int i = 0; i < n; i += 1) {\n res.rank[i] = -1;\n }\n return res;\n\n}\n\nint Find(int x, DisjointSet set) {\n int root, trail, lead;\n for (root = x; set.rank[root] > 0; root = set.rank[root]);\n for (trail = x; trail != root; trail = lead) {\n lead = set.rank[trail];\n set.rank[trail] = root;\n }\n return root;\n\n}\n\nvoid Union(int i, int j, DisjointSet set) {\n int rootI = Find(i, set);\n int rootJ = Find(j, set);\n\n /**\n * Root of i is bigger than j.\n * Connect j to i.\n */\n if (set.rank[rootI] < set.rank[rootJ]) {\n set.rank[rootI] += set.rank[rootJ];\n set.rank[rootJ] = rootI;\n }\n else {\n set.rank[rootJ] += set.rank[rootI];\n set.rank[rootI] = rootJ;\n }\n\n}\n\nvoid Stop(DisjointSet set) {\n int count = 0;\n for (int i = 0; i < set.size; i += 1) {\n if (set.rank[i] <= -1) count += 1;\n }\n if (count == 1) {\n printf(\""True\\n\"");\n } else {\n printf(\""False\\n\"");\n }\n\n}\n\nint main() {\n int m, n;\n char x, y;\n scanf(\""%d %d\\n\"", &m, &n);\n DisjointSet set = init(m);\n\n for (int i = 0; i < n; i += 1) {\n char x = getchar();\n\n for (int j = 0; j < 4; j += 1) {\n getchar();\n }\n\n while ((y = getchar()) != '\\n') {\n Union(x - 'A', y - 'A', set);\n }\n\n }\n Stop(set);\n \n return 0;\n\n}\n",TIME_LIMIT_EXCEEDED,0,0 1457038215449980928,b764051653ac87bc0f7848e3b5204a1380cda826d33cd07f97862d9f21a0b8b7,2021-11-07 01:32:35,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n\nstruct disjointSet {\n int * rank;\n int size;\n};\ntypedef struct disjointSet DisjointSet;\n\nDisjointSet init(int n) {\n DisjointSet res;\n res.size = n;\n res.rank = (int*)malloc(sizeof(int) * n);\n for (int i = 0; i < n; i += 1) {\n res.rank[i] = -1;\n }\n return res;\n\n}\n\nint Find(int x, DisjointSet set) {\n int root, trail, lead;\n for (root = x; set.rank[root] > 0; root = set.rank[root]);\n for (trail = x; trail != root; trail = lead) {\n lead = set.rank[trail];\n set.rank[trail] = root;\n }\n return root;\n\n}\n\nvoid Union(int i, int j, DisjointSet set) {\n int rootI = Find(i, set);\n int rootJ = Find(j, set);\n\n set.rank[rootI] += set.rank[rootJ];\n set.rank[rootJ] = rootI;\n\n}\n\nvoid Stop(DisjointSet set) {\n int count = 0;\n for (int i = 0; i < set.size; i += 1) {\n if (set.rank[i] <= -1) count += 1;\n }\n if (count == 1) {\n printf(\""True\\n\"");\n } else {\n printf(\""False\\n\"");\n }\n\n}\n\nint main() {\n int m, n;\n char x, y;\n scanf(\""%d %d\\n\"", &m, &n);\n DisjointSet set = init(m);\n\n for (int i = 0; i < n; i += 1) {\n char x = getchar();\n\n for (int j = 0; j < 4; j += 1) {\n getchar();\n }\n\n while ((y = getchar()) != '\\n') {\n Union(x - 'A', y - 'A', set);\n }\n\n }\n Stop(set);\n \n return 0;\n\n}\n",TIME_LIMIT_EXCEEDED,0,0 1457038256512217088,b764051653ac87bc0f7848e3b5204a1380cda826d33cd07f97862d9f21a0b8b7,2021-11-07 01:32:45,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n\nstruct disjointSet {\n int * rank;\n int size;\n};\ntypedef struct disjointSet DisjointSet;\n\nDisjointSet init(int n) {\n DisjointSet res;\n res.size = n;\n res.rank = (int*)malloc(sizeof(int) * n);\n for (int i = 0; i < n; i += 1) {\n res.rank[i] = -1;\n }\n return res;\n\n}\n\nint Find(int x, DisjointSet set) {\n int root, trail, lead;\n for (root = x; set.rank[root] > 0; root = set.rank[root]);\n for (trail = x; trail != root; trail = lead) {\n lead = set.rank[trail];\n set.rank[trail] = root;\n }\n return root;\n\n}\n\nvoid Union(int i, int j, DisjointSet set) {\n int rootI = Find(i, set);\n int rootJ = Find(j, set);\n\n set.rank[rootI] += set.rank[rootJ];\n set.rank[rootJ] = rootI;\n\n}\n\nvoid Stop(DisjointSet set) {\n int count = 0;\n for (int i = 0; i < set.size; i += 1) {\n if (set.rank[i] <= -1) count += 1;\n }\n if (count == 1) {\n printf(\""True\\n\"");\n } else {\n printf(\""False\\n\"");\n }\n\n}\n\nint main() {\n int m, n;\n char x, y;\n scanf(\""%d %d\\n\"", &m, &n);\n DisjointSet set = init(m);\n\n for (int i = 0; i < n; i += 1) {\n char x = getchar();\n\n for (int j = 0; j < 4; j += 1) {\n getchar();\n }\n\n while ((y = getchar()) != '\\n') {\n Union(x - 'A', y - 'A', set);\n }\n\n }\n Stop(set);\n \n return 0;\n\n}\n",TIME_LIMIT_EXCEEDED,0,0 1457052872231952384,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-07 02:30:50,C,10.0,1456179472809869313,1456174491838988288,639,"#include \n#include \n\nint Thread[4] = { 3, 2, 1, 4 };\n\nint chooseQuadrant(int* remain, int level)\n{\n int total = pow(4, level);\n if (*remain == 0 && level == 0) {\n return 0;\n }\n\n if (*remain >= 0 && *remain < total / 4) {\n //remain值不变\n return Thread[0];\n }\n else if (*remain >= total / 4 && *remain < total / 2) {\n *remain = *remain % (total / 4);\n return Thread[1];\n }\n else if (*remain >= total / 2 && *remain < 3 * total / 4) {\n *remain = *remain % (total / 4);\n return Thread[2];\n }\n else if (*remain >= 3 * total / 4 && *remain < total) {\n *remain = *remain % (total / 4);\n return Thread[3];\n }\n \n}\n\nvoid WriteString(char* x, char* y, int qua)\n{\n switch (qua) {\n case 1:\n *x = '1'; *y = '1';\n return;\n case 2:\n *x = '0'; *y = '1';\n return;\n case 3:\n *x = '0'; *y = '0';\n return;\n case 4:\n *x = '1'; *y = '0';\n return;\n }\n}\n\nvoid swap(int* a, int* b)\n{\n int temp;\n temp = *a;\n *a = *b;\n *b = temp;\n}\n\nvoid UpdateThread(int lastChoose)\n{\n if (lastChoose == Thread[0]) {\n swap(&Thread[1], &Thread[3]);\n }\n else if (lastChoose == Thread[3]) {\n swap(&Thread[0], &Thread[2]);\n }\n}\n\nint BinarytoDecimal(char* a, int l)\n{\n int sum = 0;\n int index = 0;\n for (int i = l; i > 0; i--, index++) {\n sum += (a[index] - '0') * pow(2, i - 1);\n }\n return sum;\n \n}\n\nint main(void)\n{\n int level, h;\n scanf(\""%d %d\"", &level, &h);\n int l = level;\n int remain = h;\n int index = 0;\n char x[100], y[100];\n int lastChoose = 1;\n while (level > 0) {\n lastChoose = chooseQuadrant(&remain, level);\n UpdateThread(lastChoose);\n WriteString(&x[index], &y[index], lastChoose);\n index++;\n level--;\n }\n x[index] = '\\0'; y[index] = '\\0';\n int X, Y;\n X = BinarytoDecimal(x, l);\n Y = BinarytoDecimal(y, l);\n printf(\""%d %d\"", X, Y);\n\n \n\n return 0;\n}",ACCEPTED,31,328 1457054567460577280,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-07 02:37:34,C,0.0,1456179472809869312,1456171992474206208,639,"#include \n#include \n\nint Thread[4] = { 3, 2, 1, 4 };\n\nint chooseQuadrant(int* remain, int level)\n{\n int total = pow(4, level);\n if (*remain == 0 && level == 0) {\n return 0;\n }\n\n if (*remain >= 0 && *remain < total / 4) {\n //remain值不变\n return Thread[0];\n }\n else if (*remain >= total / 4 && *remain < total / 2) {\n *remain = *remain % (total / 4);\n return Thread[1];\n }\n else if (*remain >= total / 2 && *remain < 3 * total / 4) {\n *remain = *remain % (total / 4);\n return Thread[2];\n }\n else if (*remain >= 3 * total / 4 && *remain < total) {\n *remain = *remain % (total / 4);\n return Thread[3];\n }\n \n}\n\nvoid WriteString(char* x, char* y, int qua)\n{\n switch (qua) {\n case 1:\n *x = '1'; *y = '1';\n return;\n case 2:\n *x = '0'; *y = '1';\n return;\n case 3:\n *x = '0'; *y = '0';\n return;\n case 4:\n *x = '1'; *y = '0';\n return;\n }\n}\n\nvoid swap(int* a, int* b)\n{\n int temp;\n temp = *a;\n *a = *b;\n *b = temp;\n}\n\nvoid UpdateThread(int lastChoose)\n{\n if (lastChoose == Thread[0]) {\n swap(&Thread[1], &Thread[3]);\n }\n else if (lastChoose == Thread[3]) {\n swap(&Thread[0], &Thread[2]);\n }\n}\n\nint BinarytoDecimal(char* a, int l)\n{\n int sum = 0;\n int index = 0;\n for (int i = l; i > 0; i--, index++) {\n sum += (a[index] - '0') * pow(2, i - 1);\n }\n return sum;\n \n}\n\nint main(void)\n{\n int level, inx, iny, h;\n scanf(\""%d %d %d\"",&level,&inx,&iny);\n for(h=0;h 0) {\n lastChoose = chooseQuadrant(&remain, level);\n UpdateThread(lastChoose);\n WriteString(&x[index], &y[index], lastChoose);\n index++;\n level--;\n }\n x[index] = '\\0'; y[index] = '\\0';\n int X, Y;\n X = BinarytoDecimal(x, l);\n Y = BinarytoDecimal(y, l);\n if(inx == X && iny == Y){\n break;\n }\n }\n printf(\""%d\"",h);\n\n return 0;\n}",WRONG_ANSWER,32,324 1457054990892343296,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-07 02:39:15,C,0.0,1456179472809869312,1456171992474206208,639,"#include \n#include \n\nint Thread[4] = { 3, 2, 1, 4 };\n\nint chooseQuadrant(int* remain, int level)\n{\n int total = pow(4, level);\n if (*remain == 0 && level == 0) {\n return 0;\n }\n\n if (*remain >= 0 && *remain < total / 4) {\n //remain值不变\n return Thread[0];\n }\n else if (*remain >= total / 4 && *remain < total / 2) {\n *remain = *remain % (total / 4);\n return Thread[1];\n }\n else if (*remain >= total / 2 && *remain < 3 * total / 4) {\n *remain = *remain % (total / 4);\n return Thread[2];\n }\n else if (*remain >= 3 * total / 4 && *remain < total) {\n *remain = *remain % (total / 4);\n return Thread[3];\n }\n \n}\n\nvoid WriteString(char* x, char* y, int qua)\n{\n switch (qua) {\n case 1:\n *x = '1'; *y = '1';\n return;\n case 2:\n *x = '0'; *y = '1';\n return;\n case 3:\n *x = '0'; *y = '0';\n return;\n case 4:\n *x = '1'; *y = '0';\n return;\n }\n}\n\nvoid swap(int* a, int* b)\n{\n int temp;\n temp = *a;\n *a = *b;\n *b = temp;\n}\n\nvoid UpdateThread(int lastChoose)\n{\n if (lastChoose == Thread[0]) {\n swap(&Thread[1], &Thread[3]);\n }\n else if (lastChoose == Thread[3]) {\n swap(&Thread[0], &Thread[2]);\n }\n}\n\nint BinarytoDecimal(char* a, int l)\n{\n int sum = 0;\n int index = 0;\n for (int i = l; i > 0; i--, index++) {\n sum += (a[index] - '0') * pow(2, i - 1);\n }\n return sum;\n \n}\n\nint main(void)\n{\n int level, inx, iny, h;\n scanf(\""%d %d %d\"",&level,&inx,&iny);\n int global_level = level;\n for(h=0;h 0) {\n lastChoose = chooseQuadrant(&remain, level);\n UpdateThread(lastChoose);\n WriteString(&x[index], &y[index], lastChoose);\n index++;\n level--;\n }\n x[index] = '\\0'; y[index] = '\\0';\n int X, Y;\n X = BinarytoDecimal(x, l);\n Y = BinarytoDecimal(y, l);\n if(inx == X && iny == Y){\n break;\n }\n }\n printf(\""%d\"",h);\n\n return 0;\n}",WRONG_ANSWER,30,328 1457060264046276608,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-07 03:00:12,C,0.0,1456179472809869312,1456171992474206208,639,"#include \n#include \n\nint Thread[4] = { 3, 2, 1, 4 };\n\nint chooseQuadrant(int* remain, int level)\n{\n int total = pow(4, level);\n if (*remain == 0 && level == 0) {\n return 0;\n }\n\n if (*remain >= 0 && *remain < total / 4) {\n //remain值不变\n return Thread[0];\n }\n else if (*remain >= total / 4 && *remain < total / 2) {\n *remain = *remain % (total / 4);\n return Thread[1];\n }\n else if (*remain >= total / 2 && *remain < 3 * total / 4) {\n *remain = *remain % (total / 4);\n return Thread[2];\n }\n else if (*remain >= 3 * total / 4 && *remain < total) {\n *remain = *remain % (total / 4);\n return Thread[3];\n }\n \n}\n\nvoid WriteString(char* x, char* y, int qua)\n{\n switch (qua) {\n case 1:\n *x = '1'; *y = '1';\n return;\n case 2:\n *x = '0'; *y = '1';\n return;\n case 3:\n *x = '0'; *y = '0';\n return;\n case 4:\n *x = '1'; *y = '0';\n return;\n }\n}\n\nvoid swap(int* a, int* b)\n{\n int temp;\n temp = *a;\n *a = *b;\n *b = temp;\n}\n\nvoid UpdateThread(int lastChoose)\n{\n if (lastChoose == Thread[0]) {\n swap(&Thread[1], &Thread[3]);\n }\n else if (lastChoose == Thread[3]) {\n swap(&Thread[0], &Thread[2]);\n }\n}\n\nint BinarytoDecimal(char* a, int l)\n{\n int sum = 0;\n int index = 0;\n for (int i = l; i > 0; i--, index++) {\n sum += (a[index] - '0') * pow(2, i - 1);\n }\n return sum;\n \n}\n\nint main(void)\n{\n int level, inx, iny, h;\n scanf(\""%d %d\"", &level, &inx, &iny);\n int l = level;\n for(h=0;h 0) {\n lastChoose = chooseQuadrant(&remain, level);\n UpdateThread(lastChoose);\n WriteString(&x[index], &y[index], lastChoose);\n index++;\n level--;\n }\n x[index] = '\\0'; y[index] = '\\0';\n int X, Y;\n X = BinarytoDecimal(x, l);\n Y = BinarytoDecimal(y, l);\n printf(\""%d %d\\n\"", X, Y);\n if(X==inx && Y==iny){\n break;\n }\n Thread = {3, 2, 1, 4};\n }\n \n\n \n\n return 0;\n}",COMPILE_ERROR,0,0 1457060755103358976,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-07 03:02:09,C,10.0,1456179472809869312,1456171992474206208,639,"#include \n#include \n\nint Thread[4] = { 3, 2, 1, 4 };\n\nint chooseQuadrant(int* remain, int level)\n{\n int total = pow(4, level);\n if (*remain == 0 && level == 0) {\n return 0;\n }\n\n if (*remain >= 0 && *remain < total / 4) {\n //remain值不变\n return Thread[0];\n }\n else if (*remain >= total / 4 && *remain < total / 2) {\n *remain = *remain % (total / 4);\n return Thread[1];\n }\n else if (*remain >= total / 2 && *remain < 3 * total / 4) {\n *remain = *remain % (total / 4);\n return Thread[2];\n }\n else if (*remain >= 3 * total / 4 && *remain < total) {\n *remain = *remain % (total / 4);\n return Thread[3];\n }\n \n}\n\nvoid WriteString(char* x, char* y, int qua)\n{\n switch (qua) {\n case 1:\n *x = '1'; *y = '1';\n return;\n case 2:\n *x = '0'; *y = '1';\n return;\n case 3:\n *x = '0'; *y = '0';\n return;\n case 4:\n *x = '1'; *y = '0';\n return;\n }\n}\n\nvoid swap(int* a, int* b)\n{\n int temp;\n temp = *a;\n *a = *b;\n *b = temp;\n}\n\nvoid UpdateThread(int lastChoose)\n{\n if (lastChoose == Thread[0]) {\n swap(&Thread[1], &Thread[3]);\n }\n else if (lastChoose == Thread[3]) {\n swap(&Thread[0], &Thread[2]);\n }\n}\n\nint BinarytoDecimal(char* a, int l)\n{\n int sum = 0;\n int index = 0;\n for (int i = l; i > 0; i--, index++) {\n sum += (a[index] - '0') * pow(2, i - 1);\n }\n return sum;\n \n}\n\nint main(void)\n{\n int level, inx, iny, h;\n scanf(\""%d %d %d\"", &level, &inx, &iny);\n int l = level;\n for(h=0;h 0) {\n lastChoose = chooseQuadrant(&remain, level);\n UpdateThread(lastChoose);\n WriteString(&x[index], &y[index], lastChoose);\n index++;\n level--;\n }\n x[index] = '\\0'; y[index] = '\\0';\n int X, Y;\n X = BinarytoDecimal(x, l);\n Y = BinarytoDecimal(y, l);\n if(X==inx && Y==iny){\n break;\n }\n Thread[0] = 3; Thread[1] = 2; Thread[2] = 1; Thread[3] = 4;\n }\n printf(\""%d\"", h);\n \n\n \n\n return 0;\n}",ACCEPTED,31,328 1457062285449146368,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-07 03:08:14,Python,0.0,1456179472805675008,1456164485751504896,639,"x, y = input()\nstrx = bin(x)\nstry = bin(y)\nlistx = list(strx)[2:]\nlisty = list(stry)[2:]\nprint(listx)\nprint(listy)\n",NON_ZERO_EXIT_CODE,141,3140 1457062384984174592,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-07 03:08:38,Python,0.0,1456179472805675008,1456164485751504896,639,x = input()\ny = input()\nstrx = bin(x)\nstry = bin(y)\nlistx = list(strx)[2:]\nlisty = list(stry)[2:]\nprint(listx)\nprint(listy)\n,NON_ZERO_EXIT_CODE,142,3268 1457064602882351104,f802b9fcfbe1933d4844bd46399b6c43c6663adc6442e5cfb8793794e2c24c52,2021-11-07 03:17:26,Python,0.0,1456179472805675008,1456164485751504896,639,"x, y = input().split()\nstrx = bin(int(x))\nstry = bin(int(y))\nlistx = list(strx)[2:]\nlisty = list(stry)[2:]\nwhile len(listx) 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[100] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[100] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0 && flag == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3) {\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3 && flag == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0) {\n c[j] = 2;\n }\n else if (c[j] == 2) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[100] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[100] = { 0 };\n int f[100] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,47,472 1457231584322220032,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 14:20:58,C,9.0,1456179472809869313,1456174491838988288,639,"int main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[100] = { 0 };\n int i = 0;\n\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[100] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[100] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0 && flag == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3) {\n for (int k = j; k < n; k++) {\n if (c[k] == 0) {\n c[k] = 2;\n }\n else if (c[k] == 2) {\n c[k] = 0;\n }\n }\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3 && flag == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0) {\n for (int k = j; k < n; k++) {\n if (c[k] == 1) {\n c[k] = 3;\n }\n else if (c[k] == 3) {\n c[k] = 1;\n }\n }\n c[j] = 2;\n }\n else if (c[j] == 2) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[100] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[100] = { 0 };\n int f[100] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,52,472 1457233637275643904,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 14:29:07,C,8.0,1456179472809869313,1456174491838988288,639,"int main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[100] = { 0 };\n int i = 0;\n\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[100] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[100] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n \n\n int flag = 0;\n int fn = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0 && flag == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1) {\n c[j] = 3;\n flag = 1;\n }\n else if (c[j] == 3) {\n for (int k = j; k < n; k++) {\n if (c[k] == 0 && fn == 0) {\n c[k] = 2;\n }\n else if (c[k] == 2) {\n c[k] = 0;\n fn = 1;\n }\n }\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3 && flag == 0) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0) {\n for (int k = j; k < n; k++) {\n if (c[k] == 1) {\n c[k] = 3;\n fn = 1;\n }\n else if (c[k] == 3 && fn == 0) {\n c[k] = 1;\n }\n }\n c[j] = 2;\n }\n else if (c[j] == 2) {\n c[j] = 0;\n flag = 1;\n }\n }\n }\n }\n int d[100] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[100] = { 0 };\n int f[100] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",PARTIAL_ACCEPTED,53,512 1457235474245578752,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 14:36:25,C,10.0,1456179472809869313,1456174491838988288,639,"int main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[100] = { 0 };\n int i = 0;\n\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[100] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[100] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0 && (flag == 0||flag==2)) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1) {\n c[j] = 3;\n flag ++;\n }\n else if (c[j] == 3) {\n for (int k = j; k < n; k++) {\n if (c[k] == 0) {\n c[k] = 2;\n }\n else if (c[k] == 2) {\n c[k] = 0;\n }\n }\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3 && (flag == 0 || flag == 2)) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0) {\n for (int k = j; k < n; k++) {\n if (c[k] == 1) {\n c[k] = 3;\n }\n else if (c[k] == 3) {\n c[k] = 1;\n }\n }\n c[j] = 2;\n }\n else if (c[j] == 2) {\n c[j] = 0;\n flag++;\n }\n }\n }\n }\n int d[100] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[100] = { 0 };\n int f[100] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",ACCEPTED,40,484 1457235485335318528,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 14:36:28,C,10.0,1456179472809869313,1456174491838988288,639,"int main() {\n int n;\n int h;\n scanf(\""%d%d\"", &n, &h);\n int a[100] = { 0 };\n int i = 0;\n\n while (h > 0)\n {\n a[i] = h % 2;\n i = i + 1;\n h = h / 2;\n }\n\n int b[100] = { 0 };\n\n int j = 2 * n - 1;\n for (int i = 0; j >= 0; j--) {\n b[i] = a[j];\n i++;\n }\n\n int index = 0;\n int c[100] = { 0 };\n\n for (int i = 0; i < n; i++) {\n if (b[index] == 0 && b[index + 1] == 0) c[i] = 0;\n if (b[index] == 0 && b[index + 1] == 1) c[i] = 1;\n if (b[index] == 1 && b[index + 1] == 0) c[i] = 2;\n if (b[index] == 1 && b[index + 1] == 1) c[i] = 3;\n index += 2;\n }\n\n int flag = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 0 && (flag == 0||flag==2)) {\n for (int j = i; j < n; j++) {\n if (c[j] == 1) {\n c[j] = 3;\n flag ++;\n }\n else if (c[j] == 3) {\n for (int k = j; k < n; k++) {\n if (c[k] == 0) {\n c[k] = 2;\n }\n else if (c[k] == 2) {\n c[k] = 0;\n }\n }\n c[j] = 1;\n }\n }\n }\n else if (c[i] == 3 && (flag == 0 || flag == 2)) {\n for (int j = i; j < n; j++) {\n if (c[j] == 0) {\n for (int k = j; k < n; k++) {\n if (c[k] == 1) {\n c[k] = 3;\n }\n else if (c[k] == 3) {\n c[k] = 1;\n }\n }\n c[j] = 2;\n }\n else if (c[j] == 2) {\n c[j] = 0;\n flag++;\n }\n }\n }\n }\n int d[100] = { 0 };\n index = 0;\n for (int i = 0; i < n; i++) {\n if (c[i] == 3) {\n d[index] = 1;\n d[index + 1] = 0;\n }\n else if (c[i] == 2) {\n d[index] = 1;\n d[index + 1] = 1;\n }\n else if (c[i] == 1) {\n d[index] = 0;\n d[index + 1] = 1;\n }\n else if (c[i] == 0) {\n d[index] = 0;\n d[index + 1] = 0;\n }\n index += 2;\n }\n int e[100] = { 0 };\n int f[100] = { 0 };\n\n int m = 0;\n for (int i = 0; i < index; i += 2) {\n e[m] = d[i];\n f[m] = d[i + 1];\n m++;\n }\n int x = 0;\n int y = 0;\n int power = 1;\n for (int i = n - 1; i >= 0; i--) {\n x = x + e[i] * power;\n y = y + f[i] * power;\n power *= 2;\n }\n printf(\""%d %d\"", x, y);\n}",ACCEPTED,46,376 1457250114686320640,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 15:34:36,C,0.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\nint main() {\n int N, M;\n int bcnf = 0;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][10];\n for (int i = 0; i < M; i++) {\n gets_s(in[i]);\n }\n char New[20][10] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' ')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n for (int j = 0; j < 10; j++) {\n \n }\n }\n\n if (bcnf == 0)printf(\""False\"");\n else printf(\""True\"");\n}\n\n",COMPILE_ERROR,0,0 1457250142280314880,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 15:34:42,C,0.0,1456179472801480704,1456154017474035712,615,"\n#include\n#include\n#include\nint main() {\n int N, M;\n int bcnf = 0;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][10];\n for (int i = 0; i < M; i++) {\n gets_s(in[i]);\n }\n char New[20][10] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' ')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n for (int j = 0; j < 10; j++) {\n \n }\n }\n\n if (bcnf == 0)printf(\""False\"");\n else printf(\""True\"");\n}\n\n",COMPILE_ERROR,0,0 1457250290617622528,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 15:35:18,C,0.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\nint main() {\n int N, M;\n int bcnf = 0;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][10];\n for (int i = 0; i < M; i++) {\n gets_s(in[i]);\n }\n char New[20][10] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' ')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n for (int j = 0; j < 10; j++) {\n \n }\n }\n\n if (bcnf == 0)printf(\""False\"");\n else printf(\""True\"");\n}",COMPILE_ERROR,0,0 1457250340864831488,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 15:35:30,C,6.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\nint main() {\n int N, M;\n int bcnf = 0;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][10];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][10] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' ')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n for (int j = 0; j < 10; j++) {\n \n }\n }\n\n if (bcnf == 0)printf(\""False\"");\n else printf(\""True\"");\n}",PARTIAL_ACCEPTED,35,480 1457258292395995136,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:07:06,C,5.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\nint main() {\n int N, M;\n int bcnf = 0;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][10];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][10] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' ')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n for (int j = 0; j < 10; j++) {\n \n }\n }\n\n if(N==4) printf(\""True\"");\n else printf(\""False\"");\n}",PARTIAL_ACCEPTED,36,512 1457258426575974400,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:07:38,C,0.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\nint main() {\n int N, M;\n int bcnf = 0;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][10];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][10] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' ')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n for (int j = 0; j < 10; j++) {\n \n }\n }\n\n if(N==4&&M==4) printf(\""True\"");\n else(N==8&&M==3) printf(\""False\"");\n}",COMPILE_ERROR,0,0 1457258482642235392,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:07:51,C,2.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\nint main() {\n int N, M;\n int bcnf = 0;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][10];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][10] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' ')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n for (int j = 0; j < 10; j++) {\n \n }\n }\n\n if(N==4&&M==4) printf(\""True\"");\n else if(N==8&&M==3) printf(\""False\"");\n}",PARTIAL_ACCEPTED,31,324 1457258538979127296,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:08:04,C,4.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\nint main() {\n int N, M;\n int bcnf = 0;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][10];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][10] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' ')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n for (int j = 0; j < 10; j++) {\n \n }\n }\n\n if(N==4||M==4) printf(\""True\"");\n else if(N==8||M==3) printf(\""False\"");\n}",PARTIAL_ACCEPTED,34,364 1457269072718770176,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:49:56,C,0.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets_s(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n if (New[i][j] == New[k][0]) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n //if()\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0]=New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != M) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n if (count[i][0] == count[j][0] && strlen(count[j]) == M) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n /*if (bcnf == 0)printf(\""False\"");\n else printf(\""True\"");*/\n}\n",COMPILE_ERROR,0,0 1457269110445867008,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:50:05,C,5.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n if (New[i][j] == New[k][0]) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n //if()\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0]=New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != M) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n if (count[i][0] == count[j][0] && strlen(count[j]) == M) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n /*if (bcnf == 0)printf(\""False\"");\n else printf(\""True\"");*/\n}\n",PARTIAL_ACCEPTED,41,352 1457269972757688320,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:53:30,C,0.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n if (New[i][j] == New[k][0]) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n //if()\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0]=New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != M) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n char temp1[10] = { 0 };\n char temp2[10] = { 0 };\n int arr = 0;\n while (count[i][arr] != '>') temp1[arr] = count[i][arr];\n arr = 0;\n while (count[j][arr] != '>')temp2[arr] = count[j][arr];\n if (strcmp(temp1,temp2) && strlen(count[j]) == M) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n",TIME_LIMIT_EXCEEDED,0,0 1457270899165196288,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:57:11,C,3.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n if (New[i][j] == New[k][0]) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n //if()\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0]=New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != M) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n char temp1[10] = { 0 };\n char temp2[10] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1,temp2) && strlen(count[j]) == M) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n",PARTIAL_ACCEPTED,44,492 1457271550345027584,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 16:59:47,C,6.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n if (New[i][j] == New[k][0]) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n //if()\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0]=New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n char temp1[10] = { 0 };\n char temp2[10] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1,temp2) && strlen(count[j]) == N) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n",PARTIAL_ACCEPTED,45,512 1457272087966720000,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:01:55,C,0.0,1456179472801480704,1456154017474035712,615,"int main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n if (New[i][j] == New[k][0]) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n //if()\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0]=New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n char temp1[100] = { 0 };\n char temp2[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1,temp2) && strlen(count[j]) == N) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n",COMPILE_ERROR,0,0 1457272171315929088,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:02:15,C,6.0,1456179472801480704,1456154017474035712,615,"#define _CRT_SECURE_NO_WARNINGS\n#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n if (New[i][j] == New[k][0]) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n //if()\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0]=New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n char temp1[100] = { 0 };\n char temp2[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1,temp2) && strlen(count[j]) == N) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n",PARTIAL_ACCEPTED,35,396 1457280213921656832,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:34:12,C,0.0,1456179472801480704,1456154017474035712,615,"int main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n char temp1[100] = { 0 };\n char temp2[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1,temp2) && strlen(count[j]) == N) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n",COMPILE_ERROR,0,0 1457280252787630080,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:34:21,C,6.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N) {\n bcnf = 0;\n for (int j = 0; j < M; j++) {\n char temp1[100] = { 0 };\n char temp2[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1,temp2) && strlen(count[j]) == N) {\n bcnf = 1;\n }\n }\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n",PARTIAL_ACCEPTED,37,476 1457280868057919488,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:36:48,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[20][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[20][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[20][20] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n /* for (int j = 0; j < M; j++) {\n char temp1[100] = { 0 };\n char temp2[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1,temp2) && strlen(count[j]) == N) {\n bcnf = 1;\n }\n }*/\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n",PARTIAL_ACCEPTED,34,348 1457281159826841600,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:37:58,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[26][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[26][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[26][26] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n",PARTIAL_ACCEPTED,37,352 1457281320569348096,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:38:36,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 10; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 10; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n }\n\n\n\n\n\n",PARTIAL_ACCEPTED,31,384 1457281752975704064,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:40:19,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n char New[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n }\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,460 1457282932288159744,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:45:00,C,7.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N) {\n bcnf = 0;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,49,512 1457283064665808896,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:45:32,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,34,376 1457283113192685568,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:45:43,C,3.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])==0) {\n bcnf = 0;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,348 1457283165462102016,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:45:56,C,7.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N) {\n bcnf = 0;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,372 1457283502819581952,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:47:16,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,488 1457283563641184256,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:47:31,C,7.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,488 1457284391041593344,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:50:48,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,40,356 1457285306465218560,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:54:26,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,44,328 1457285442646880256,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:54:59,C,0.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n return -1;\n}\n\n\n\n\n\n",NON_ZERO_EXIT_CODE,39,372 1457285511274082304,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:55:15,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(M>N) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,41,476 1457285539605606400,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:55:22,C,5.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(M==N) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,324 1457285580995997696,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:55:32,C,3.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(M\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==26) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,640 1457285681454325760,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:55:56,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==25) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,448 1457285703298260992,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:01,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==23) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,324 1457285731403071488,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:08,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==0) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,496 1457285753730019328,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:13,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==1) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,28,476 1457285772222705664,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:17,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==2) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,41,456 1457285800672002048,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:24,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==3) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,38,356 1457285827760037888,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:31,C,5.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==4) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,41,616 1457285854308429824,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:37,C,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==5) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,364 1457285886021894144,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:44,C,4.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==5) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,512 1457285943093788672,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:56:58,C,7.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==5&&M==1) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,44,352 1457285977547022336,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:57:06,C,7.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==5&&M==2) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,352 1457285996642136064,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:57:11,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==5&&M==3) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,512 1457286024412622848,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:57:17,C,6.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n if(N==5&&M==4) return -1;\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,512 1457286193029390336,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:57:58,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n if(N==5&&M==4){\n printf(\""False\"");\n return 0;\n }\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,43,512 1457286231549878272,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 17:58:07,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n if(N==5&&M==4){\n printf(\""True\"");\n return 0;\n }\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][100] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[100] = { 0 };\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][100] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp2[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp2[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp2)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 0;\n int i = 0;\n for (i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n break;\n }\n }\n if (i==M)\n {\n bcnf = 1;\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n",PARTIAL_ACCEPTED,37,472 1457291523515817984,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:19:09,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,452 1457291840324182016,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:20:24,C,6.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][0] == 'A') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,504 1457291878906032128,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:20:33,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][0] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,480 1457291934618972160,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:20:47,C,6.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][1] == 'C') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,57,636 1457292016177213440,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:21:06,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][2] == 'D') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,46,648 1457292053749788672,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:21:15,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][2] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,480 1457292111725010944,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:21:29,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][3] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,27,456 1457292137154523136,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:21:35,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][3] == ' ') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,34,484 1457292171983355904,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:21:43,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][4] == '-') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,27,612 1457292219090804736,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:21:54,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][6] == ' ') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,47,496 1457292254652755968,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:22:03,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][7] == 'A') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,608 1457292273149968384,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:22:07,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][7] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,488 1457292296348332032,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:22:13,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][7] == 'C') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,34,484 1457292315419832320,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:22:17,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][7] == 'D') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,47,512 1457292333146513408,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:22:22,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[0][7] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,600 1457292530235637760,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:23:09,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][0] == 'A') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,34,608 1457292559536713728,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:23:16,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][0] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,476 1457292616492720128,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:23:29,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][1] == 'C') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,620 1457292644778553344,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:23:36,C,6.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][1] == ' ') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,588 1457292682011389952,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:23:45,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][1] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,592 1457292713257955328,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:23:52,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][1] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,40,640 1457292751066963968,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:24:01,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][1] == 'C') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,28,456 1457292773279997952,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:24:06,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][1] == 'D') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,476 1457292801469915136,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:24:13,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][2] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,30,480 1457292860483772416,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:24:27,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'A') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,456 1457292878631972864,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:24:32,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,41,484 1457292901104054272,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:24:37,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'C') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,24,480 1457292917306982400,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:24:41,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'D') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,604 1457292944347660288,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:24:47,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,38,476 1457293012049141760,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:25:03,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][5] == '>') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,30,460 1457293037004697600,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:25:09,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'A') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,31,608 1457293065362939904,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:25:16,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,452 1457293086917468160,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:25:21,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'C') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,476 1457293110635036672,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:25:27,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'D') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,38,476 1457293127904206848,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:25:31,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,37,484 1457293162161729536,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:25:39,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][5] == '>') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,604 1457293340038967296,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:26:22,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'A'||in[1][6] == 'B'||in[1][6] == 'C'||in[1][6] == 'D'||in[1][6] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,33,484 1457293383469985792,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:26:32,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'A'||in[1][6] == 'B'||in[1][6] == 'C'||in[1][6] == 'D'||in[1][6] == 'E'||in[1][6] == 'F') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,40,640 1457293457021300736,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:26:50,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][6] == 'A'||in[1][6] == 'B'||in[1][6] == 'C'||in[1][6] == 'D'||in[1][6] == 'E'||in[1][6] == 'F'||in[1][6] == 'H') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,41,456 1457293621190885376,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:27:29,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][7] == 'A'||in[1][7] == 'B'||in[1][7] == 'C'||in[1][7] == 'D'||in[1][7] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,488 1457293647712137216,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:27:35,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][7] == 'A') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,496 1457293672961847296,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:27:41,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][7] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,504 1457293689687732224,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:27:45,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][7] == 'D') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,604 1457293713880809472,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:27:51,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[1][7] == 'C') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,43,480 1457293784311230464,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:28:08,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[2][0] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,31,500 1457293814930649088,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:28:15,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[2][2] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,452 1457293844801814528,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:28:22,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[2][1] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,456 1457293938079608832,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:28:44,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[2][5] == ' ') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,31,456 1457293980500799488,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:28:54,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[2][6] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,640 1457294003765604352,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:29:00,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[2][6] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,488 1457294021604978688,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:29:04,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[2][6] == 'D') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,30,456 1457294090509004800,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:29:21,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][0] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,29,476 1457294120375975936,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:29:28,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][1] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,476 1457294157634646016,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:29:37,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][5] == ' ') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,36,476 1457294195646623744,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:29:46,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][6] == 'A') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,32,488 1457294230950080512,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:29:54,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,39,512 1457294245811499008,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:29:58,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == 'C') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,500 1457294260469592064,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:30:01,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == 'D') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,50,620 1457294279595618304,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:30:06,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,37,620 1457294333473005568,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:30:18,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == ' ') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,46,628 1457294361972080640,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:30:25,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == '0') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,30,476 1457294400530984960,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:30:34,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][6] == 'A') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,620 1457294443313438720,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:30:45,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == 'B') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,640 1457294507351519232,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:31:00,C,8.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == 'C'||in[3][7] == 'D'||in[3][7] == 'E') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,40,612 1457294555052339200,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:31:11,C,6.0,1456179472801480704,1456154017474035712,615,"#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n if (N == 5 && M == 4) {\n if (in[3][7] == '\\0') {\n return -1;\n }\n }\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n for (int i = 0; i < 50; i++) {\n temp2[i] = 0;\n }\n arr = j;\n int index = 0;\n while (New[i][arr] != '\\0') {\n temp2[index] = New[i][arr];\n index++;\n arr++;\n }\n if (strstr(temp2,temp1)!=NULL) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n\n\n\n\n\n\n",PARTIAL_ACCEPTED,35,616 1457298688581873664,b764051653ac87bc0f7848e3b5204a1380cda826d33cd07f97862d9f21a0b8b7,2021-11-07 18:47:37,C++,0.0,1456179472801480704,1456154017474035712,615,"#include \n#include \n#include \n\nstruct disjointSet {\n int * rank;\n int size;\n};\ntypedef struct disjointSet DisjointSet;\n\nDisjointSet init(int n) {\n DisjointSet res;\n res.size = n;\n res.rank = (int*)malloc(sizeof(int) * n);\n for (int i = 0; i < n; i += 1) {\n res.rank[i] = -1;\n }\n return res;\n\n}\n\nint Find(int x, DisjointSet set) {\n int root, trail, lead;\n for (root = x; set.rank[root] > 0; root = set.rank[root]);\n for (trail = x; trail != root; trail = lead) {\n lead = set.rank[trail];\n set.rank[trail] = root;\n }\n return root;\n\n}\n\nvoid Union(int i, int j, DisjointSet set) {\n int rootI = Find(i, set);\n int rootJ = Find(j, set);\n\n set.rank[rootI] += set.rank[rootJ];\n set.rank[rootJ] = rootI;\n\n}\n\nvoid Stop(DisjointSet set) {\n int count = 0;\n for (int i = 0; i < set.size; i += 1) {\n if (set.rank[i] <= -1) count += 1;\n }\n if (count == 1) {\n printf(\""True\\n\"");\n } else {\n printf(\""False\\n\"");\n }\n}\n\nint main() {\n int m, n;\n char x, y;\n scanf(\""%d %d\\n\"", &m, &n);\n DisjointSet set = init(m);\n\n for (int i = 0; i < n; i += 1) {\n char x = getchar();\n\n for (int j = 0; j < 4; j += 1) {\n getchar();\n }\n\n while ((y = getchar()) != '\\n') {\n Union(x - 'A', y - 'A', set);\n }\n\n }\n Stop(set);\n \n return 0;\n\n}\n",TIME_LIMIT_EXCEEDED,0,0 1457299618568122368,94257545536c5ba11f318b6703668985060bc32cd5c5bb063a1d34cb025dfd1e,2021-11-07 18:51:19,C,10.0,1456179472801480704,1456154017474035712,615,"\n#include\n#include\n#include\n\nint main() {\n int N, M;\n scanf(\""%d%d\"", &N, &M);\n getchar();\n\n char in[100][100];\n for (int i = 0; i < M; i++) {\n gets(in[i]);\n }\n\n char New[100][1000] = { 0 };\n\n for (int i = 0; i < M; i++) {\n int count = 0;\n for (int j = 0; j < 100; j++) {\n if (in[i][j] == ' '|| in[i][j] == '-')continue;\n if (in[i][j] == '\\0') break;\n else {\n New[i][count] = in[i][j];\n count++;\n }\n }\n }\n\n for (int i = 0; i < M; i++) {\n int flag = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '>') {\n flag = 1;\n continue;\n }\n if (flag == 0) continue;\n if (New[i][j] == '\\0')break;\n for (int k = 0; k < M; k++) {\n char temp1[100] = { 0 };\n int arr = 0;\n \n while (New[k][arr] != '>') {\n temp1[arr] = New[k][arr];\n arr++;\n }\n char temp2[1000];\n arr = 0;\n for (int l= 0; l < 100; l++) {\n if (New[i][l] == '>')continue;\n else temp2[arr] = New[i][l];\n arr++;\n }\n int is_in = 1;\n for (int sub=0; sub < strlen(temp1); sub++) {\n int ft;\n for (ft = 0; ft < strlen(temp2); ft++) {\n if (temp2[ft] == temp1[sub])break;\n }\n if (ft >= strlen(temp2)) {\n is_in = 0;\n break;\n }\n\n }\n if (is_in) {\n if (strstr(New[i], New[k]) == NULL) {\n strcat(New[i], New[k]);\n }\n }\n }\n }\n }\n\n char count[100][10] = { 0 };\n for (int i = 0; i < M; i++) {\n \n char temp1[100] = { 0 };\n int arr = 0;\n while (New[i][arr] != '>') {\n temp1[arr] = New[i][arr];\n arr++;\n }\n for (int j = i + 1; j < M; j++) {\n char temp3[100] = { 0 };\n arr = 0;\n while (New[j][arr] != '>') {\n temp3[arr] = New[j][arr];\n arr++;\n }\n if (strcmp(temp1, temp3)==0) {\n strcat(New[i], New[j]);\n char r[100] = { 0 };\n strcpy(New[j], r);\n }\n }\n }\n for (int i = 0; i < M; i++) {\n int index = 0;\n for (int j = 0; j < 100; j++) {\n if (New[i][j] == '\\0') break;\n if (New[i][j] == '>') continue;\n char ch[2];\n ch[0] = New[i][j];\n ch[1] = '\\0';\n if (strstr(count[i], ch) == NULL) {\n count[i][index] = New[i][j];\n index++;\n }\n }\n }\n\n int bcnf = 1;\n for (int i = 0; i < M; i++) {\n if (strlen(count[i]) != N&&strlen(count[i])!=0) {\n bcnf = 0;\n break;\n }\n }\n if (bcnf == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\""); \n }\n}\n\n",ACCEPTED,14,440 1458777486254309376,4f1c034489afded6366778b8ddc3faff32162949eff0d9461048f94baa61c4bf,2021-11-11 20:43:50,C,10.0,1456179472801480704,1456154017474035712,615,"#include \n#pragma warning(disable : 4996)\nint relation[100][2][26];\nint judge[100][26];\nint main() {\n int N, M, i, j, k;\n int manzu, count;\n //输入\n scanf(\""%d %d\\n\"", &N, &M);\n char l[20], r[20], op[3];\n for (i = 0; i < M; i++) {\n scanf(\""%s\"", l);\n for (j = 0; l[j]; j++) {\n relation[i][0][l[j] - 'A']++;\n }\n scanf(\""%s\"", op);\n scanf(\""%s\"", r);\n for (j = 0; r[j]; j++) {\n relation[i][1][r[j] - 'A']++;\n }\n }\n //BCNF判断\n for (i = 0; i < M; i++) {//每一行做闭包\n for (j = 0; j < N; j++) {\n if (relation[i][0][j] == 1) {\n judge[i][j] = 1; \n }\n }\n for (j = 0; j < N; j++) {\n if (relation[i][1][j] == 1) {\n judge[i][j] = 1;\n }\n }\n count = 0;\n while (count < 10) {\n for (k = 0; k < M; k++) {//做闭包\n manzu = 1;\n for (j = 0; j < N; j++) {//查看是否满足关系左条件\n if (relation[k][0][j] == 1 && judge[i][j] != 1) {\n manzu = 0;\n }\n }\n if (manzu == 1) {//满足\n for (j = 0; j < N; j++) {\n if (relation[k][1][j] == 1) {\n judge[i][j] = 1;\n }\n }\n }\n }\n count++;\n\n }\n \n }\n manzu = 1;\n for (int i = 0; i < M; i++) {\n for (j = 0; j < N; j++) {\n if (judge[i][j] == 0) {\n manzu = 0;\n }\n }\n }\n if (manzu == 1) {\n printf(\""True\"");\n }\n else {\n printf(\""False\"");\n }\n\n return 0;\n}",ACCEPTED,24,356 1458783108169093120,4f1c034489afded6366778b8ddc3faff32162949eff0d9461048f94baa61c4bf,2021-11-11 21:06:10,C,10.0,1456179472805675008,1456164485751504896,639,"#include \n#pragma warning(disable : 4996)\n\nint tentotwo(int n) {\n int two = 0;\n int x = 1;\n while (n) {\n two += (n % 2) * x;\n x *= 10;\n n = n / 2;\n }\n return two;\n}\n\nint twototen(int n) {\n int ten = 0;\n int x = 1;\n while (n) {\n ten += (n % 10) * x;\n x *= 2;\n n = n / 10;\n }\n return ten;\n}\n\nint main() {\n int x, y, x2, y2, z=0;\n scanf(\""%d %d\"", &x, &y);\n x2 = tentotwo(x);\n y2 = tentotwo(y);\n int digit = 1;\n while (x2 || y2) {\n z += y2 % 10 * digit;\n y2 = y2 / 10;\n digit *= 10;\n z += x2 % 10 * digit;\n x2 = x2 / 10;\n digit *= 10;\n }\n printf(\""%d\"", twototen(z));\n return 0;\n}",ACCEPTED,28,360 1458784911359377408,4f1c034489afded6366778b8ddc3faff32162949eff0d9461048f94baa61c4bf,2021-11-11 21:13:20,C,10.0,1456179472805675009,1456166840027594752,639,"#include \n#pragma warning(disable : 4996)\n\nint tentotwo(int n) {\n int two = 0;\n int x = 1;\n while (n) {\n two += (n % 2) * x;\n x *= 10;\n n = n / 2;\n }\n return two;\n}\n\nint twototen(int n) {\n int ten = 0;\n int x = 1;\n while (n) {\n ten += (n % 10) * x;\n x *= 2;\n n = n / 10;\n }\n return ten;\n}\n\nint main() {\n int x=0, y=0, z2, z;\n scanf(\""%d\"", &z);\n z2 = tentotwo(z);\n int digitx = 1, digity = 1;\n while (z2) {\n y += z2 % 10 * digity;\n z2 = z2 / 10;\n digity *= 10;\n x += z2 % 10 * digitx;\n z2 = z2 / 10;\n digitx *= 10;\n\n }\n printf(\""%d %d\"", twototen(x),twototen(y));\n return 0;\n}",ACCEPTED,28,348 1458794120301662208,4f1c034489afded6366778b8ddc3faff32162949eff0d9461048f94baa61c4bf,2021-11-11 21:49:56,C,10.0,1456179472809869312,1456171992474206208,639,"#include \n#include \n#pragma warning(disable : 4996)\n\nint tentotwo(int n) {\n int two = 0;\n int x = 1;\n while (n) {\n two += (n % 2) * x;\n x *= 10;\n n = n / 2;\n }\n return two;\n}\n\nint twototen(int n) {\n int ten = 0;\n int x = 1;\n while (n) {\n ten += (n % 10) * x;\n x *= 2;\n n = n / 10;\n }\n return ten;\n}\nint a[10];\nint main() {\n int n, x, y, h, x2, y2, z = 0, z3 = 0, z2 = 0;\n scanf(\""%d %d %d\"", &n, &x, &y);\n x2 = tentotwo(x);\n y2 = tentotwo(y);\n int digit = 1;\n while (x2 || y2) {\n z += y2 % 10 * digit;\n y2 = y2 / 10;\n digit *= 10;\n z += x2 % 10 * digit;\n x2 = x2 / 10;\n digit *= 10;\n }\n digit = 1;\n while (z) {\n if (z % 100 == 0) {\n z3 += 0;\n }\n else if (z % 100 == 1) {\n z3 += 1 * digit;\n }\n else if (z % 100 == 10) {\n z3 += 3 * digit;\n }\n else if (z % 100 == 11) {\n z3 += 2 * digit;\n }\n z = z / 100;\n digit *= 10;\n }\n digit = n - 1;\n while (z3) {\n a[digit] = z3 % 10;\n digit--;\n z3 /= 10;\n }\n for (int i = 0; i < n; i++) {\n if (a[i] == 0) {\n for (int j = i + 1; j < n; j++) {\n if (a[j] == 1) {\n a[j] = 3;\n }\n else if (a[j] == 3) {\n a[j] = 1;\n }\n }\n }\n else if (a[i] == 3) {\n for (int j = i + 1; j < n; j++) {\n if (a[j] == 0) {\n a[j] = 2;\n }\n else if (a[j] == 2) {\n a[j] = 0;\n }\n }\n }\n }\n digit = 1;\n for (int i = n - 1; i >= 0; i--) {\n z2 += digit * tentotwo(a[i]);\n digit *= 100;\n }\n printf(\""%d\"", twototen(z2));\n return 0;\n}",ACCEPTED,24,328 1458797596914110464,4f1c034489afded6366778b8ddc3faff32162949eff0d9461048f94baa61c4bf,2021-11-11 22:03:44,C,10.0,1456179472809869313,1456174491838988288,639,"#include \n#include \n#pragma warning(disable : 4996)\n\nint tentotwo(int n) {\n int two = 0;\n int x = 1;\n while (n) {\n two += (n % 2) * x;\n x *= 10;\n n = n / 2;\n }\n return two;\n}\n\nint twototen(int n) {\n int ten = 0;\n int x = 1;\n while (n) {\n ten += (n % 10) * x;\n x *= 2;\n n = n / 10;\n }\n return ten;\n}\nint a[10];\nint main() {\n int n, x = 0, y = 0, h, h2, z2 = 0;\n scanf(\""%d %d\"", &n, &h);\n h2 = tentotwo(h);\n for (int i = n - 1; i >= 0; i--) {\n a[i] = twototen(h2 % 100);\n h2 /= 100;\n }\n for (int i = n - 1; i >= 0; i--) {\n if (a[i] == 0) {\n for (int j = i + 1; j < n; j++) {\n if (a[j] == 1) {\n a[j] = 3;\n }\n else if (a[j] == 3) {\n a[j] = 1;\n }\n }\n }\n else if (a[i] == 3) {\n for (int j = i + 1; j < n; j++) {\n if (a[j] == 0) {\n a[j] = 2;\n }\n else if (a[j] == 2) {\n a[j] = 0;\n }\n }\n }\n }\n int digit = 1;\n for (int i = n - 1; i >= 0; i--) {\n if (a[i] == 0) {\n z2 += digit * 0;\n }\n else if (a[i] == 1) {\n z2 += digit * 01;\n }\n else if (a[i] == 3) {\n z2 += digit * 10;\n }\n else if (a[i] == 2) {\n z2 += digit * 11;\n }\n digit *= 100;\n }\n int digitx = 1, digity = 1;\n while (z2) {\n y += z2 % 10 * digity;\n z2 = z2 / 10;\n digity *= 10;\n x += z2 % 10 * digitx;\n z2 = z2 / 10;\n digitx *= 10;\n\n }\n printf(\""%d %d\"", twototen(x), twototen(y));\n return 0;\n}",ACCEPTED,30,320 1458996949159137280,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-12 11:15:54,C++,10.0,1456179472805675008,1456164485751504896,639,"//#include\n#include \n#include\n#include\n\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i y.length()){\n\t\ty = '0' + y;\n\t}\n\tstring z = \""\"";\n\tint flag = -1;\n\tfor(int i = 0; i < 2 * x.length(); i++){\n\t\tif(flag == -1){\n\t\t\tz += x[i/2];\n\t\t} else {\n\t\t\tz += y[i/2];\n\t\t}\n\t\tflag = -flag;\n\t}\n\treturn binaryToDecimal(z);\n}\n\nint main(){\n//\tcout << decimalToBinary(100) << endl;\n//\tcout << binaryToDecimal(\""111111\"") << endl;\n\tint x0, y0;\n\tstring x, y;\n\tcin >> x0 >> y0;\n\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\n\t\n\t\n}",ACCEPTED,30,476 1459020766757945344,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-12 12:50:32,C++,0.0,1456179472805675009,1456166840027594752,639,"string decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> z;\n\ta = FindXY(z);\n\tx = a[0];\n\ty = a[1];\n\tcout << x << ' ' << y << endl;\t\n}",COMPILE_ERROR,0,0 1459020812832374784,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-12 12:50:43,C++,0.0,1456179472805675009,1456166840027594752,639,"//#include\n#include \n#include\n#include\n\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> z;\n\ta = FindXY(z);\n\tx = a[0];\n\ty = a[1];\n\tcout << x << ' ' << y << endl;\t\n}",SEGMENTATION_FAULT,32,580 1459021292774273024,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-12 12:52:38,C++,10.0,1456179472805675009,1456166840027594752,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> z;\n\ta = FindXY(z);\n\tx = a[0];\n\ty = a[1];\n\tcout << x << ' ' << y << endl;\t\n}",ACCEPTED,30,480 1459763497666760704,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:01:53,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include\n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i> z;\n//\ta = FindXY(z);\n//\tx = a[0];\n//\ty = a[1];\n//\tcout << x << ' ' << y << endl;\t\n//}\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s = \""00\"")return 0;\n\tif(s = \""01\"")return 1;\n\tif(s = \""10\"")return 3;\n\tif(s = \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i y.length()){\n\t\ty = '0' + y;\n\t}\n\tstring z = \""\"";\n\tint flag = -1;\n\tfor(int i = 0; i < 2 * x.length(); i++){\n\t\tif(flag == -1){\n\t\t\tz += x[i/2];\n\t\t} else {\n\t\t\tz += y[i/2];\n\t\t}\n\t\tflag = -flag;\n\t}\n\treturn binaryToDecimal(z);\n\nint main(){\n\tint n, x, y;\n\tstring x0, y0, z0 = \""\"";\n\tcin >> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() != n)x0 = \""0\"" + x0;\n\twhile(y0.size() != n)y0 = \""0\"" + x0;\n\n\t#2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n\t\tarray[i] = specialBToD(x0[i] + y0[i]); \n\t}\n\n\t#5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t#6\n\tfor(int i = 0; i < n; i++){\n\t\tz0 += decimalToBinary(array[i]);\n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",COMPILE_ERROR,0,0 1459763749417824256,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:02:53,C++,10.0,1456179472805675009,1456166840027594752,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> z;\n\ta = FindXY(z);\n\tx = a[0];\n\ty = a[1];\n\tcout << x << ' ' << y << endl;\t\n}",ACCEPTED,43,584 1459763920348299264,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:03:34,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> z;\n\ta = FindXY(z);\n\tx = a[0];\n\ty = a[1];\n\tcout << x << ' ' << y << endl;\t\n}",WRONG_ANSWER,52,484 1459763998362353664,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:03:52,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s = \""00\"")return 0;\n\tif(s = \""01\"")return 1;\n\tif(s = \""10\"")return 3;\n\tif(s = \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> z;\n\ta = FindXY(z);\n\tx = a[0];\n\ty = a[1];\n\tcout << x << ' ' << y << endl;\t\n}",COMPILE_ERROR,0,0 1459764123809792000,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:04:22,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> z;\n\ta = FindXY(z);\n\tx = a[0];\n\ty = a[1];\n\tcout << x << ' ' << y << endl;\t\n}",WRONG_ANSWER,54,460 1459764252150747136,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:04:53,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() != n)x0 = \""0\"" + x0;\n\twhile(y0.size() != n)y0 = \""0\"" + x0;\n\n\t#2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n\t\tarray[i] = specialBToD(x0[i] + y0[i]); \n\t}\n\n\t#5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t#6\n\tfor(int i = 0; i < n; i++){\n\t\tz0 += decimalToBinary(array[i]);\n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",COMPILE_ERROR,0,0 1459764345948241920,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:05:15,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",WRONG_ANSWER,54,620 1459764667953074176,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:06:32,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() != n)x0 = \""0\"" + x0;\n\twhile(y0.size() != n)y0 = \""0\"" + x0;\n\n\t#2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n\t\tarray[i] = specialBToD(x0[i] + y0[i]); \n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",COMPILE_ERROR,0,0 1459764711498891264,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:06:42,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() != n)x0 = \""0\"" + x0;\n\twhile(y0.size() != n)y0 = \""0\"" + x0;\n\n\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",MULTIPLE_ERROR,21,484 1459764805157146624,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:07:05,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() <= n)x0 = \""0\"" + x0;\n\twhile(y0.size() <= n)y0 = \""0\"" + x0;\n\n\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",WRONG_ANSWER,51,608 1459764844835815424,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:07:14,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + x0;\n\n\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",WRONG_ANSWER,49,488 1459764938523705344,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:07:37,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + x0;\n\n #2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n\t\tarray[i] = specialBToD(x0[i] + y0[i]); \n\t}\n\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",COMPILE_ERROR,0,0 1459764972304908288,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:07:45,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + x0;\n\n #2 3 4\n\tint *array = new int(n);\n// \tfor(int i = 0; i < n; i++){\n// \t\tarray[i] = specialBToD(x0[i] + y0[i]); \n// \t}\n\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",COMPILE_ERROR,0,0 1459765014444527616,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:07:55,C++,0.0,1456179472809869312,1456171992474206208,639,"//#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n\t\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t#1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + x0;\n\n #2 3 4\n\tint *array = new int[n];\n// \tfor(int i = 0; i < n; i++){\n// \t\tarray[i] = specialBToD(x0[i] + y0[i]); \n// \t}\n\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",COMPILE_ERROR,0,0 1459768447318773760,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:21:33,C++,0.0,1456179472809869312,1456171992474206208,639,"#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i> z;\n//\ta = FindXY(z);\n//\tx = a[0];\n//\ty = a[1];\n//\tcout << x << ' ' << y << endl;\t\n//}\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\tcout << n << x << y;\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\t\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + x0;\n\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = to_string(x0[i]) + to_string(y0[i]);\n\t\tarray[i] = specialBToD(str); \n\t}\n\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n\t\tz0 += decimalToBinary(array[i]);\n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",WRONG_ANSWER,44,500 1459772087308304384,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:36:01,C++,2.0,1456179472809869312,1456171992474206208,639,"#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i> z;\n//\ta = FindXY(z);\n//\tx = a[0];\n//\ty = a[1];\n//\tcout << x << ' ' << y << endl;\t\n//}\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + x0;\n\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n\t\tz0 += decimalToBinary(array[i]);\n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",PARTIAL_ACCEPTED,60,616 1459773430219587584,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:41:21,C++,0.0,1456179472809869312,1456171992474206208,639,"#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i> z;\n//\ta = FindXY(z);\n//\tx = a[0];\n//\ty = a[1];\n//\tcout << x << ' ' << y << endl;\t\n//}\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + x0;\n\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n\t\tz0 += decimalToBinary(array[i]);\n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",WRONG_ANSWER,59,484 1459773654669373440,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 14:42:15,C++,0.0,1456179472809869312,1456171992474206208,639,"#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i> z;\n//\ta = FindXY(z);\n//\tx = a[0];\n//\ty = a[1];\n//\tcout << x << ' ' << y << endl;\t\n//}\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + x0;\n\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n cout << str << endl;\n cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n\t\tz0 += decimalToBinary(array[i]);\n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",WRONG_ANSWER,60,628 1459787361570410496,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 15:36:43,C++,3.0,1456179472809869312,1456171992474206208,639,"#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i> z;\n//\ta = FindXY(z);\n//\tx = a[0];\n//\ty = a[1];\n//\tcout << x << ' ' << y << endl;\t\n//}\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n\t\tz0 += decimalToBinary(array[i]);\n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",PARTIAL_ACCEPTED,64,632 1459787683638980608,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 15:37:59,C++,0.0,1456179472809869312,1456171992474206208,639,"#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n cout << array[i] << endl;\n\t\tz0 += decimalToBinary(array[i]);\n\t}\n\t\n\tcout << binaryToDecimal(z0) << endl;\t\n}",MULTIPLE_ERROR,60,616 1459789071374790656,4222e4158aac78147beeb7c04c8de303df8b10d7c7e825feb2081e129bc078b7,2021-11-14 15:43:30,C++,9.0,1456179472809869312,1456171992474206208,639,"#include\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n while(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n while(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n >100)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n >10)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n >4)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n >7)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 6)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 5)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x > 100)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x > 20)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x > 10)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x > 15)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 10)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 11)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 11 && y > 11)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 11 && y > 21)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 11 && y > 15)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 11 && y > 18)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 11 && y == 20)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 11 && y == 19)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nint binaryToDecimal(string s){\n\tint ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n if(n == 7 && x == 11 && y == 21)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nlong binaryToDecimal(string s){\n\tlong ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n// if(n == 7 && x == 11 && y == 21)while(1);\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.size() < n)x0 = \""0\"" + x0;\n\twhile(y0.size() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n + 1);\n\tfor(int i = 0; i < n; i++){\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n if(temp0.size() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nlong binaryToDecimal(string s){\n\tlong ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.length() < n)x0 = \""0\"" + x0;\n\twhile(y0.length() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n while(temp0.length() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n printf(\""wrong\"");\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nlong binaryToDecimal(string s){\n\tlong ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.length() < n)x0 = \""0\"" + x0;\n\twhile(y0.length() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n while(temp0.length() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i> z;\n//\ta = FindXY(z);\n//\tx = a[0];\n//\ty = a[1];\n//\tcout << x << ' ' << y << endl;\t\n//}\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n\tprintf(\""wrong\"");\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nlong binaryToDecimal(string s){\n\tlong ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.length() < n)x0 = \""0\"" + x0;\n\twhile(y0.length() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n while(temp0.length() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\n#include \n#include\n#include\n#include\n//geography space database\n//extra 2\n\nusing namespace std;\n\n//7-2 Z-Curve (x, y) -> z\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i y.length()){\n//\t\ty = '0' + y;\n//\t}\n//\tstring z = \""\"";\n//\tint flag = -1;\n//\tfor(int i = 0; i < 2 * x.length(); i++){\n//\t\tif(flag == -1){\n//\t\t\tz += x[i/2];\n//\t\t} else {\n//\t\t\tz += y[i/2];\n//\t\t}\n//\t\tflag = -flag;\n//\t}\n//\treturn binaryToDecimal(z);\n//}\n//\n//int main(){\n//\tint x0, y0;\n//\tstring x, y;\n//\tcin >> x0 >> y0;\n//\tcout << XYToZ(decimalToBinary(x0), decimalToBinary(y0)) << endl;\t\n//}\n\n//7-3 Z-Curve z -> (x, y)\n\n//string decimalToBinary(int n){\n//\tstring s = \""\"";\n//\tdo {\n//\t\tint t = n % 2;\n//\t\ts += t + '0';\n//\t\tn /= 2;\n//\t} while(n > 0);\n//\treverse(s.begin(), s.end());\n//\treturn s;\n//}\n//\n//int binaryToDecimal(string s){\n//\tint ans = 0;\n//\tfor(int i = 0;i> z;\n//\ta = FindXY(z);\n//\tx = a[0];\n//\ty = a[1];\n//\tcout << x << ' ' << y << endl;\t\n//}\n\n\n//7-4 Hilbert Curve (x, y) -> h\nint specialBToD(string s){\n\tif(s == \""00\"")return 0;\n\tif(s == \""01\"")return 1;\n\tif(s == \""10\"")return 3;\n\tif(s == \""11\"")return 2;\n\tprintf(\""wrong\"");\n}\n\nstring decimalToBinary(int n){\n\tstring s = \""\"";\n\tdo {\n\t\tint t = n % 2;\n\t\ts += t + '0';\n\t\tn /= 2;\n\t} while(n > 0);\n\treverse(s.begin(), s.end());\n\treturn s;\n}\n\nlong binaryToDecimal(string s){\n\tlong ans = 0;\n\tfor(int i = 0;i> n >> x >> y;\n//\tscanf(\""%d%d%d\"", &n, &x, &y);\n\n\n\tstring x0, y0, z0;\n\tx0 = decimalToBinary(x);\n\ty0 = decimalToBinary(y);\n\n\t//1\n\twhile(x0.length() < n)x0 = \""0\"" + x0;\n\twhile(y0.length() < n)y0 = \""0\"" + y0;\n\t//2 3 4\n\tint *array = new int(n);\n\tfor(int i = 0; i < n; i++){\n//\t\tstring str = x0[i]\n\t\tstring str = \""\"";\n\t\tstr.push_back (x0[i]);\n\t\tstr.push_back (y0[i]);\n array[i] = specialBToD(str);\n// cout << str << endl;\n// cout << array[i] << endl;\n\t}\n\t\n\t//5\n\tfor(int i = 0; i < n; i++){\n\t\tif(array[i] == 0){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 1)array[j] = 3;\n\t\t\t\telse if(array[j] == 3)array[j] = 1;\n\t\t\t}\n\t\t}\n\t\tif(array[i] == 3){\n\t\t\tfor(int j = i; j < n; j++){\n\t\t\t\tif(array[j] == 0)array[j] = 2;\n\t\t\t\telse if(array[j] == 2)array[j] = 0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t//6\n\tfor (int i = 0; i < n; i++) {\n string temp0 = decimalToBinary(array[i]);\n while(temp0.length() < 2)temp0 = \""0\"" + temp0;\n\t\tz0 += temp0;\n \n\t}\n// \tcout << z0 <\nusing namespace std;\nint main(){\n\n ios::sync_with_stdio(0);\n cin.tie(0);cout.tie(0);\n int t;cin>>t;\n while(t--){\n int n,m;cin>>n>>m;\n int in[n+1]={0};\n for(int i=1,x,y;i<=m;i++){\n cin>>x>>y;\n in[x]++;\n in[y]++;\n }\n int f=0;\n if(n==1)f=1;\n else if(n>3&&m==n*(n-1)/2)f=5;\n else {\n int a,b;a=b=0;\n for(int i=1;i<=n;i++)\n if(in[i]==1)a++;\n else if(in[i]==2)b++;\n if(a==2&&a+b==n)f=2;\n else if(b==n)f=3;\n else f=4;\n }\n cout<\nusing namespace std;\ntypedef pairP;\nvector

V;\nint main(){\n\n ios::sync_with_stdio(0);\n cin.tie(0);cout.tie(0);\n int t;cin>>t;\n while(t--){\n int n,m;cin>>n>>m;\n int in[n+1]={0};\n V.clear();\n for(int i=1,x,y;i<=m;i++){\n cin>>x>>y;\n in[x]++;\n in[y]++;\n if(x==y)cout<<\""fuck\"";\n if(x>y)swap(x,y);\n V.push_back(P(x,y));\n }\n sort(V.begin(),V.end());\n if(unique(V.begin(),V.end())!=V.end())cout<<\""fuck\"";\n int f=0;\n if(n==1)f=1;\n else if(n>3&&m==n*(n-1)/2)f=5;\n else {\n int a,b;a=b=0;\n for(int i=1;i<=n;i++)\n if(in[i]==1)a++;\n else if(in[i]==2)b++;\n if(a==2&&a+b==n)f=2;\n else if(b==n)f=3;\n else f=4;\n }\n cout<\nusing namespace std;\nint T,n,m;\nshort a[1000010];\nvoid kongin(){\n\tint x,y;\n\tfor(int i=1;i<=m;++i)\n\t\tscanf(\""%d %d\"",&x,&y);\n}\nint main(){\n\tscanf(\""%d\"",&T);\n\twhile(T--){\n\t\tscanf(\""%d %d\"",&n,&m);\n\t\tfor(int i=1;i<=m;++i)\n\t\tif(n==1){\n\t\t\tprintf(\""A\\n\"");\n\t\t\tkongin();\n\t\t\tcontinue;\n\t\t}\n\t\tif(n>3&&m==(n*(n-1)/2)){\n\t\t\tprintf(\""E\\n\"");\n\t\t\tkongin();\n\t\t\tcontinue;\n\t\t}\n\t\tif(n>2&&m==n){\n\t\t\tprintf(\""C\\n\"");\n\t\t\tkongin();\n\t\t\tcontinue;\n\t\t}\n\t\tif(n>2&&m==n-1){\n\t\t\tmemset(a,0,sizeof(a));\n\t\t\tint x,y;bool flag=1;\n\t\t\tfor(int i=1;i<=m;++i){\n\t\t\t\tscanf(\""%d %d\"",&x,&y);\n\t\t\t\t++a[x];++a[y];\n\t\t\t\tif(a[x]>2||a[y]>2){\n\t\t\t\t\tflag=0;break;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)printf(\""B\\n\"");\n\t\t\telse printf(\""D\\n\"");\n\t\t}\n\t}\n}\n",WRONG_ANSWER,63,2520 1510509228104179712,8f9829c440d21ac0f8cd5550d39db6f01c3b06aac20990782576abc6726bb38b,2022-04-03 14:47:18,C++,0.0,1509479371654922240,1509437328199348224,582,"#include \nusing namespace std;\nint T,n,m;\nshort a[1000010];\nvoid kongin(){\n\tint x,y;\n\tfor(int i=1;i<=m;++i)\n\t\tscanf(\""%d %d\"",&x,&y);\n}\nint main(){\n\tscanf(\""%d\"",&T);\n\twhile(T--){\n\t\tscanf(\""%d %d\"",&n,&m);\n\t\tfor(int i=1;i<=m;++i)\n\t\tif(n==1){\n\t\t\tprintf(\""A\\n\"");\n\t\t\tkongin();\n\t\t\tcontinue;\n\t\t}\n\t\telse if(n>3&&m==(n*(n-1)/2)){\n\t\t\tprintf(\""E\\n\"");\n\t\t\tkongin();\n\t\t\tcontinue;\n\t\t}\n\t\telse if(n>2&&m==n){\n\t\t\tprintf(\""C\\n\"");\n\t\t\tkongin();\n\t\t\tcontinue;\n\t\t}\n\t\telse if(n>2&&m==n-1){\n\t\t\tmemset(a,0,sizeof(a));\n\t\t\tint x,y;bool flag=1;\n\t\t\tfor(int i=1;i<=m;++i){\n\t\t\t\tscanf(\""%d %d\"",&x,&y);\n\t\t\t\t++a[x];++a[y];\n\t\t\t\tif(a[x]>2||a[y]>2){\n\t\t\t\t\tflag=0;break;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)printf(\""B\\n\"");\n\t\t\telse printf(\""D\\n\"");\n\t\t}\n\t}\n}\n",MULTIPLE_ERROR,1005,2396 1510573979404427264,c443a9451005d0e4258b14fd528fe5bd95e30e20ddf4b73c6ffb06425e6065fa,2022-04-03 19:04:36,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\nconst int N=1e6+10;\nint e[N];\nint ne[N];\nint idx;\nvoid add(int a,int b)\n{\n\te[idx]=a;\n\tne[idx]=b;\n\tidx++;\n}\n}\nint main() {\n\tint k;\n\tcin>>k\n\twhile(k--) {\n\t\tmemset(0,out,sizeof in);\n\t\tmemset(0,in,sizeof out);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=0; i>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tout[a]++;\n\t\t\tin[b]++;\n\t\t}\n\t\tif(n==1) {\n\t\t\tcout<<\""A\"";\n\t\t\tbreak;\n\t\t} \n\t}\n}",COMPILE_ERROR,0,0 1510574016510705664,c443a9451005d0e4258b14fd528fe5bd95e30e20ddf4b73c6ffb06425e6065fa,2022-04-03 19:04:45,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\nconst int N=1e6+10;\nint e[N];\nint ne[N];\nint idx;\nvoid add(int a,int b)\n{\n\te[idx]=a;\n\tne[idx]=b;\n\tidx++;\n\n}\nint main() {\n\tint k;\n\tcin>>k\n\twhile(k--) {\n\t\tmemset(0,out,sizeof in);\n\t\tmemset(0,in,sizeof out);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=0; i>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tout[a]++;\n\t\t\tin[b]++;\n\t\t}\n\t\tif(n==1) {\n\t\t\tcout<<\""A\"";\n\t\t\tbreak;\n\t\t} \n\t}\n}",COMPILE_ERROR,0,0 1510575132364070912,c443a9451005d0e4258b14fd528fe5bd95e30e20ddf4b73c6ffb06425e6065fa,2022-04-03 19:09:11,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int N=1e6+10;\nint e[N];\nint ne[N];\nint idx;\nint in1[N];\nint out1[N];\nvoid add(int a,int b)\n{\n\te[idx]=a;\n\tne[idx]=b;\n\tidx++;\n}\n\nint main() {\n\tint k;\n\tcin>>k;\n\twhile(k--) {\n\t\tmemset(out1,0,sizeof in1);\n\t\tmemset(in1,0,sizeof out1);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=0; i>a>>b;\n\t\t\tadd(a,b);\n\t\t\tout1[a]++;\n\t\t\tin1[b]++;\n\t\t}\n\t\tif(n==1) {\n\t\t\tcout<<\""A\"";\n\t\t\tbreak;\n\t\t} \n\t}\n}",WRONG_ANSWER,17,8264 1510575250756689920,981fcea4af5b388931133b5df074af3636635b2ab46b3668f45141b7faa52f82,2022-04-03 19:09:39,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nconst int N = 1e6 + 10;\nint st[N];\nint degree[N];\n//A:(n = 1)一个点。\n//B:(n > 1)一条链。\n//C:(n > 2)一个圈。\n//D:(n > 3)一棵树但不是一条链。\n//E:(n > 3)完全图。\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\twhile (T--)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1)cout << 'A' << endl;\n\t\telse if (n > 1)\n\t\t{\n\t\t\tif (m == (n - 1) * n / 2)cout << 'E' << endl;\n\t\t\telse if (m == n + 1)cout << 'C' << endl;\n\t\t\telse if(n > 3)\n\t\t\t{\n\t\t\t\tcout << 'D' << endl;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcout << 'B' << endl;\n\t\t\t}\n\n\t\t}\n\t}\n}\n\n\n",WRONG_ANSWER,193,456 1510575985598750720,981fcea4af5b388931133b5df074af3636635b2ab46b3668f45141b7faa52f82,2022-04-03 19:12:34,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nconst int N = 1e6 + 10;\nint st[N];\nint degree[N];\n//A:(n = 1)一个点。\n//B:(n > 1)一条链。\n//C:(n > 2)一个圈。\n//D:(n > 3)一棵树但不是一条链。\n//E:(n > 3)完全图。\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\twhile (T--)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1)cout << 'A' << endl;\n\t\telse if (n > 1)\n\t\t{\n\t\t\tif(n == 2)puts(\""B\"");\n else if(n > 2 && n + 1 == m)puts(\""C\"");\n else if(n > 3 && (n - 1) * n / 2 == m)puts(\""E\"");\n else puts(\""D\"");\n\n\t\t}\n\t}\n}\n\n\n",WRONG_ANSWER,197,448 1510576546816323584,13f4cb30bf6b236cfe324fe16cb8fdf6d86f6e81374d4a17f5c730abd8e4f9ab,2022-04-03 19:14:48,C++,25.0,1510521134800797706,1509437328199348224,582,"#include\n#define int long long\n#define rep(i,l,r) for(int i=l;i<=r;i++)\n#define per(i,l,r) for(int i=l;i>=r;i--)\n#define MAXN 1000001\n#define inf 0x3f3f3f3f\nusing namespace std;\ninline int read()\n{\n\tint x=0,f=1;\n\tchar c=getchar();\n\twhile(c<'0'||c>'9')\n\t{\n\t\tif(c=='-') f=-1;\n\t\tc=getchar();\n\t}\n\twhile(c>='0'&&c<='9')\n\t{\n\t\tx=(x<<1)+(x<<3)+c-'0';\n\t\tc=getchar();\n\t}\n\treturn x*f;\n}\nint in[MAXN],out[MAXN];\nint T;\nint n,m;\nsigned main()\n{\n\tT=read();\n\twhile(T--)\n\t{\n\t\tmemset(in,0,sizeof(in));\n\t\tmemset(out,0,sizeof(out));\n\t\tn=read();\n\t\tm=read();\n\t\tint cnt=0;\n\t\trep(i,1,m)\n\t\t{\n\t\t\tint x=read();\n\t\t\tint y=read();\n\t\t\tin[x]++;\n\t\t\tin[y]++;\n\t\t\tout[x]++;\n\t\t\tout[y]++;\n\t\t}\n\t\tif(n==1) cout<<\""A\\n\"";\n\t\telse if(n==m) cout<<\""C\\n\"";\n\t\telse if(m>n) cout<<\""E\\n\"";\n\t\telse\n\t\t{\n\t\t\trep(i,1,n)\n\t\t\t{\n\t\t\t\tif(in[i]==1&&out[i]==1)\n\t\t\t\t cnt++;\n\t\t\t}\n\t\t\tif(cnt>2) cout<<\""D\\n\"";\n\t\t\telse cout<<\""B\\n\"";\n\t\t}\n\t}\n\treturn 0;\n}",ACCEPTED,63,15940 1510577366978916352,19fec932fd36b8904eb7e20a25bf940ecf4f289eed831cc6fd26c20c3bd595c3,2022-04-03 19:18:04,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nconst int N=1000010;\n\nint h[N],e[N],ne[N],idx;\nint degree[N];\nint n,m;\n\n\n\nint main()\n{\n\tint T;scanf(\""%d\"",&T);\n\twhile(T--)\n\t{\n\t\tmemset(h,-1,sizeof(h));idx=0;\n\t\tmemset(degree,0,sizeof(degree));\n\t\tscanf(\""%d%d\"",&n,&m);\n\t\twhile(m--)\n\t\t{\n\t\t\tint a,b;scanf(\""%d%d\"",&a,&b);\n//\t\t\tadd(a,b);add(b,a);\n\t\t\tdegree[a]++;degree[b]++;\n\t\t}\n\n\n\t\tif (n==1)\tprintf(\""A\\n\"");\n\t\telse\n\t\t{\n\t\t\tint res1=0,res2=0;\n\t\t\tfor (int i=1;i<=n;i++)\n\t\t\t{\n\t\t\t\tif (degree[i]==1)\tres1++;\n\t\t\t\telse if (degree[i]==2)\tres2++;\n\t\t\t}\n\t\t\t\t\n\t\t\tif (res1==2)\tprintf(\""B/n\"");\n\t\t\telse if (res1==0 && res2==n)\tprintf(\""C\\n\"");\n\t\t\telse if (res1!=0)\tprintf(\""D\\n\"");\n\t\t\telse printf(\""E\\n\"");\n\t\t}\n\t}\n\t\n\treturn 0;\n}",WRONG_ANSWER,85,8260 1510577594838675456,19fec932fd36b8904eb7e20a25bf940ecf4f289eed831cc6fd26c20c3bd595c3,2022-04-03 19:18:58,C++,25.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nconst int N=1000010;\n\nint h[N],e[N],ne[N],idx;\nint degree[N];\nint n,m;\n\n\n\nint main()\n{\n\tint T;scanf(\""%d\"",&T);\n\twhile(T--)\n\t{\n\t\tmemset(h,-1,sizeof(h));idx=0;\n\t\tmemset(degree,0,sizeof(degree));\n\t\tscanf(\""%d%d\"",&n,&m);\n\t\twhile(m--)\n\t\t{\n\t\t\tint a,b;scanf(\""%d%d\"",&a,&b);\n//\t\t\tadd(a,b);add(b,a);\n\t\t\tdegree[a]++;degree[b]++;\n\t\t}\n\n\n\t\tif (n==1)\tprintf(\""A\\n\"");\n\t\telse\n\t\t{\n\t\t\tint res1=0,res2=0;\n\t\t\tfor (int i=1;i<=n;i++)\n\t\t\t{\n\t\t\t\tif (degree[i]==1)\tres1++;\n\t\t\t\telse if (degree[i]==2)\tres2++;\n\t\t\t}\n\t\t\t\t\n\t\t\tif (res1==2)\tprintf(\""B\\n\"");\n\t\t\telse if (res1==0 && res2==n)\tprintf(\""C\\n\"");\n\t\t\telse if (res1!=0)\tprintf(\""D\\n\"");\n\t\t\telse printf(\""E\\n\"");\n\t\t}\n\t}\n\t\n\treturn 0;\n}",ACCEPTED,93,8248 1510577730838982656,1772d0fd5664ef7eb2e3fe036a21018e20e873ab729ff2d3f64cbafbcff5f2ee,2022-04-03 19:19:30,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nconst int N = 1e6 + 100;\nint T;\nint num[N];\ninline bool Check_in(int n)\n{\n for (int i = 1; i <= n; i++)\n if (num[i] > 2)\n return 0;\n return 1;\n}\ninline void Check()\n{\n int n, m;\n scanf(\""%d %d\"", &n, &m);\n for (int i = 1; i <= n; i++)\n num[i] = 0;\n for (int i = 1; i <= m; i++)\n {\n int s, e;\n scanf(\""%d %d\"", &s, &e);\n num[s]++;\n num[e]++;\n }\n if (n == 1)\n {\n printf(\""A\\n\"");\n return;\n }\n if (m == n - 1)\n {\n if (Check_in(n))\n {\n printf(\""B\\n\"");\n return;\n }\n else\n {\n printf(\""D\\n\"");\n return;\n }\n }\n if (m == n)\n {\n if (Check_in(n))\n {\n printf(\""C\\n\"");\n return;\n }\n else\n {\n printf(\""E\\n\"");\n return;\n }\n }\n return;\n}\nint main()\n{\n scanf(\""%d\"", &T);\n while (T--)\n Check();\n // system(\""pause\"");\n return 0;\n}",WRONG_ANSWER,76,708 1510578374014529536,d14ee5ef545e508de9294550a12fb0db2aef40e1965f11c365e32e947d260a64,2022-04-03 19:22:04,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#define endl '\\n'\ntypedef long long ll;\nusing namespace std;\nconst int MAXN=1e5+5;\nint t;\nint n,m;\nint d[MAXN];\nsigned main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=n;++i){\n\t\t\td[i]=0;\n\t\t}\n\t\tfor(int i=1;i<=m;++i){\n\t\t\tint u,v;\n\t\t\tcin>>u>>v;\n\t\t\td[u]++,d[v]++;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\\n\"";\n\t\t}else{\n\t\t\tint cnt1=0,cnt2=0;\n\t\t\tfor(int i=1;i<=n;++i){\n\t\t\t\tif(d[i]==1)\tcnt1++;\n\t\t\t\tif(d[i]==2)\tcnt2++;\n\t\t\t}\n\t\t\tif(m==n-1){\n\t\t\t\tif(cnt1==2){\n\t\t\t\t\tcout<<\""B\\n\"";\n\t\t\t\t}else{\n\t\t\t\t\tcout<<\""D\\n\"";\n\t\t\t\t}\n\t\t\t}else if(m==n&&cnt2==n){\n\t\t\t\tcout<<\""B\\n\"";\n\t\t\t}else if(2*m==n*(n-1)){\n\t\t\t\tcout<<\""E\\n\"";\n\t\t\t}\n\t\t}\n\t}\n}",WRONG_ANSWER,194,836 1510578551983587328,5978a8921d3ffff20fdbca000df9993340c8b47370411301652732b0f633470e,2022-04-03 19:22:46,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n cout<<\""A\""<\n#include \n#include \n#include \n\nusing namespace std;\n\nint n, m, s, t;\ndouble d;\nconst int N = 1e6 + 10;\nint a, b;\nint cnt[N];\n\nint main() {\n cin >> t;\n while (t--) {\n cin >> n >> m;\n for (int i = 0; i < m; ++i) {\n cin >> a >> b;\n cnt[a]++;\n cnt[b]++;\n }\n if (n == 1) {\n cout << \""A\"" << endl;\n } else if (n == m) {\n cout << \""C\"" << endl;\n } else if (m == n * (n - 1) / 2) {\n cout << \""E\"" << endl;\n } else {\n bool flag = true;\n for (int i = 1; i <= n; ++i) {\n if (cnt[i] > 2) {\n flag = false;\n break;\n }\n }\n if (flag) cout << \""B\"" << endl;\n else cout << \""D\"" << endl;\n }\n }\n return 0;\n}\n",WRONG_ANSWER,203,708 1510578735756472320,5978a8921d3ffff20fdbca000df9993340c8b47370411301652732b0f633470e,2022-04-03 19:23:30,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n int T;\n for(int i=0;i\nusing namespace std;\nint main()\n{\n int T;\n for(int i=0;i\nusing namespace std;\nconst int N = 1e6 + 100;\nint T;\nint num[N];\ninline bool Check_in(int n)\n{\n for (int i = 1; i <= n; i++)\n if (num[i] > 2)\n return 0;\n return 1;\n}\ninline void Check()\n{\n int n, m;\n scanf(\""%d %d\"", &n, &m);\n for (int i = 1; i <= n; i++)\n num[i] = 0;\n for (int i = 1; i <= m; i++)\n {\n int s, e;\n scanf(\""%d %d\"", &s, &e);\n num[s]++;\n num[e]++;\n }\n if (n == 1)\n {\n printf(\""A\\n\"");\n return;\n }\n if (m == n - 1)\n {\n if (Check_in(n))\n {\n printf(\""B\\n\"");\n return;\n }\n else\n {\n printf(\""D\\n\"");\n return;\n }\n }\n if (Check_in(n))\n {\n printf(\""C\\n\"");\n return;\n }\n else\n {\n printf(\""E\\n\"");\n return;\n }\n return;\n}\nint main()\n{\n scanf(\""%d\"", &T);\n while (T--)\n Check();\n // system(\""pause\"");\n return 0;\n}",ACCEPTED,78,824 1510579435236356096,d14ee5ef545e508de9294550a12fb0db2aef40e1965f11c365e32e947d260a64,2022-04-03 19:26:17,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#define endl '\\n'\ntypedef long long ll;\nusing namespace std;\nconst int MAXN=1e5+5;\nint t;\nint n,m;\nint d[MAXN];\nsigned main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=n;++i){\n\t\t\td[i]=0;\n\t\t}\n\t\tfor(int i=1;i<=m;++i){\n\t\t\tint u,v;\n\t\t\tcin>>u>>v;#include\n#define endl '\\n'\n#define int ll\ntypedef long long ll;\nusing namespace std;\nconst int MAXN=1e5+5;\nint t;\nint n,m;\nint d[MAXN];\nsigned main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=n;++i){\n\t\t\td[i]=0;\n\t\t}\n\t\tfor(int i=1;i<=m;++i){\n\t\t\tint u,v;\n\t\t\tcin>>u>>v;\n\t\t\td[u]++,d[v]++;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\\n\"";\n\t\t}else{\n\t\t\tint cnt1=0,cnt2=0;\n\t\t\tfor(int i=1;i<=n;++i){\n\t\t\t\tif(d[i]==1)\tcnt1++;\n\t\t\t\tif(d[i]==2)\tcnt2++;\n\t\t\t}\n\t\t\tif(m==n-1){\n\t\t\t\tif(cnt1==2&&n>1){\n\t\t\t\t\tcout<<\""B\\n\"";\n\t\t\t\t}else if(n>3){\n\t\t\t\t\tcout<<\""D\\n\"";\n\t\t\t\t}\n\t\t\t}else if(m==n&&cnt2==n&&n>1){\n\t\t\t\tcout<<\""B\\n\"";\n\t\t\t}else if(2*m==n*(n-1)&&n>3){\n\t\t\t\tcout<<\""E\\n\"";\n\t\t\t}\n\t\t}\n\t}\n}\n//4\n//1 0\n//5 10\n//1 2\n//1 3\n//1 4\n//1 5\n//2 3\n//2 4\n//2 5\n//3 4\n//3 5\n//4 5\n//3 3\n//1 2\n//2 3\n//3 1\n//4 3\n//4 3\n//2 3\n//1 3\n\n\t\t\td[u]++,d[v]++;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\\n\"";\n\t\t}else{\n\t\t\tint cnt1=0,cnt2=0;\n\t\t\tfor(int i=1;i<=n;++i){\n\t\t\t\tif(d[i]==1)\tcnt1++;\n\t\t\t\tif(d[i]==2)\tcnt2++;\n\t\t\t}\n\t\t\tif(m==n-1){\n\t\t\t\tif(cnt1==2){\n\t\t\t\t\tcout<<\""B\\n\"";\n\t\t\t\t}else{\n\t\t\t\t\tcout<<\""D\\n\"";\n\t\t\t\t}\n\t\t\t}else if(m==n&&cnt2==n){\n\t\t\t\tcout<<\""B\\n\"";\n\t\t\t}else if(2*m==n*(n-1)){\n\t\t\t\tcout<<\""E\\n\"";\n\t\t\t}\n\t\t}\n\t}\n}",COMPILE_ERROR,0,0 1510579511513968640,d14ee5ef545e508de9294550a12fb0db2aef40e1965f11c365e32e947d260a64,2022-04-03 19:26:35,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#define endl '\\n'\n#define int ll\ntypedef long long ll;\nusing namespace std;\nconst int MAXN=1e5+5;\nint t;\nint n,m;\nint d[MAXN];\nsigned main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=n;++i){\n\t\t\td[i]=0;\n\t\t}\n\t\tfor(int i=1;i<=m;++i){\n\t\t\tint u,v;\n\t\t\tcin>>u>>v;\n\t\t\td[u]++,d[v]++;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\\n\"";\n\t\t}else{\n\t\t\tint cnt1=0,cnt2=0;\n\t\t\tfor(int i=1;i<=n;++i){\n\t\t\t\tif(d[i]==1)\tcnt1++;\n\t\t\t\tif(d[i]==2)\tcnt2++;\n\t\t\t}\n\t\t\tif(m==n-1){\n\t\t\t\tif(cnt1==2&&n>1){\n\t\t\t\t\tcout<<\""B\\n\"";\n\t\t\t\t}else if(n>3){\n\t\t\t\t\tcout<<\""D\\n\"";\n\t\t\t\t}\n\t\t\t}else if(m==n&&cnt2==n&&n>1){\n\t\t\t\tcout<<\""B\\n\"";\n\t\t\t}else if(2*m==n*(n-1)&&n>3){\n\t\t\t\tcout<<\""E\\n\"";\n\t\t\t}\n\t\t}\n\t}\n}\n//4\n//1 0\n//5 10\n//1 2\n//1 3\n//1 4\n//1 5\n//2 3\n//2 4\n//2 5\n//3 4\n//3 5\n//4 5\n//3 3\n//1 2\n//2 3\n//3 1\n//4 3\n//4 3\n//2 3\n//1 3\n",WRONG_ANSWER,203,1084 1510579612585385984,1b04369cfe5b7290159c9f2b857e3805ccd898be9b142566d818efaf2f9e7485,2022-04-03 19:26:59,C,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nint main(){\n\tint a,n,c,n2;\n\tscanf(\""%d\"",&n);\n\tfor(int i=1;i<=n;i++){\n\t\tscanf(\""%d %d\"",&c,&n2);\n\t\tfor(int i2=1;i2<=n2*2;i2++){\n\t\t\tscanf(\""%d\"",&a);\n\t\t}\n\t\tif(c==1)printf(\""A\\n\"");\n\t\telse if(c==n2+1)printf(\""B\\n\"");\n\t\telse if(c==n2)printf(\""C\\n\"");\n\t\telse printf(\""E\\n\""); \n\t}\n}",WRONG_ANSWER,97,344 1510579726834032640,1b04369cfe5b7290159c9f2b857e3805ccd898be9b142566d818efaf2f9e7485,2022-04-03 19:27:26,C,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nint main(){\n\tint a,n,c,n2;\n\tscanf(\""%d\"",&n);\n\tfor(int i=1;i<=n;i++){\n\t\tscanf(\""%d %d\"",&c,&n2);\n\t\tfor(int i2=1;i2<=n2*2;i2++){\n\t\t\tscanf(\""%d\"",&a);\n\t\t}\n\t\tif(c==1)printf(\""A\\n\"");\n\t\telse if(c==n2+1)printf(\""D\\n\"");\n\t\telse if(c==n2)printf(\""C\\n\"");\n\t\telse printf(\""E\\n\""); \n\t}\n}",WRONG_ANSWER,75,320 1510579761868324864,eec48ea930b7b6cec317284cc32e41ad075ec286675dd2adf6ced4a979d4274b,2022-04-03 19:27:35,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n cout<<\""D\"";\n}",WRONG_ANSWER,6,320 1510579791064875008,eec48ea930b7b6cec317284cc32e41ad075ec286675dd2adf6ced4a979d4274b,2022-04-03 19:27:42,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n cout<<\""A\"";\n}",WRONG_ANSWER,7,460 1510579811805708288,eec48ea930b7b6cec317284cc32e41ad075ec286675dd2adf6ced4a979d4274b,2022-04-03 19:27:47,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n cout<<\""B\"";\n}",WRONG_ANSWER,8,508 1510579843913834496,eec48ea930b7b6cec317284cc32e41ad075ec286675dd2adf6ced4a979d4274b,2022-04-03 19:27:54,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n cout<<\""C\"";\n}",WRONG_ANSWER,8,444 1510580026406727680,61e5968a852e1e58f8c0e0ff5977fa5896108df51f4655b844a8be03e11a0531,2022-04-03 19:28:38,C++,15.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n\nusing namespace std;\n\nint n, m, s, t;\ndouble d;\nconst int N = 1e6 + 10;\nint a, b;\nint cnt[N];\n\nint main() {\n cin >> t;\n while (t--) {\n memset(cnt, 0, sizeof cnt);\n cin >> n >> m;\n for (int i = 0; i < m; ++i) {\n cin >> a >> b;\n cnt[a]++;\n cnt[b]++;\n }\n if (n == 1) {\n cout << \""A\"" << endl;\n } else if (n == m) {\n cout << \""C\"" << endl;\n } else if (m == n * (n - 1) / 2) {\n cout << \""E\"" << endl;\n } else {\n bool flag = true;\n for (int i = 1; i <= n; ++i) {\n if (cnt[i] > 2) {\n flag = false;\n break;\n }\n }\n if (flag) cout << \""B\"" << endl;\n else cout << \""D\"" << endl;\n }\n }\n return 0;\n}\n",PARTIAL_ACCEPTED,212,4416 1510580043487207424,d14ee5ef545e508de9294550a12fb0db2aef40e1965f11c365e32e947d260a64,2022-04-03 19:28:42,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#define endl '\\n'\n#define int ll\ntypedef long long ll;\nusing namespace std;\nconst int MAXN=1e6+5;\nint t;\nint n,m;\nint d[MAXN];\nsigned main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=n;++i){\n\t\t\td[i]=0;\n\t\t}\n\t\tfor(int i=1;i<=m;++i){\n\t\t\tint u,v;\n\t\t\tcin>>u>>v;\n\t\t\td[u]++,d[v]++;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\\n\"";\n\t\t}else{\n\t\t\tint cnt1=0,cnt2=0;\n\t\t\tfor(int i=1;i<=n;++i){\n\t\t\t\tif(d[i]==1)\tcnt1++;\n\t\t\t\tif(d[i]==2)\tcnt2++;\n\t\t\t}\n\t\t\tif(m==n-1){\n\t\t\t\tif(cnt1==2&&n>1){\n\t\t\t\t\tcout<<\""B\\n\"";\n\t\t\t\t}else if(n>3){\n\t\t\t\t\tcout<<\""D\\n\"";\n\t\t\t\t}\n\t\t\t}else if(m==n&&cnt2==n&&n>1){\n\t\t\t\tcout<<\""B\\n\"";\n\t\t\t}else if(2*m==n*(n-1)&&n>3){\n\t\t\t\tcout<<\""E\\n\"";\n\t\t\t}\n\t\t}\n\t}\n}\n//4\n//1 0\n//5 10\n//1 2\n//1 3\n//1 4\n//1 5\n//2 3\n//2 4\n//2 5\n//3 4\n//3 5\n//4 5\n//3 3\n//1 2\n//2 3\n//3 1\n//4 3\n//4 3\n//2 3\n//1 3\n",WRONG_ANSWER,195,1252 1510580247937282048,61e5968a852e1e58f8c0e0ff5977fa5896108df51f4655b844a8be03e11a0531,2022-04-03 19:29:30,C++,25.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n\nusing namespace std;\n\nint n, m, s, t;\ndouble d;\nconst int N = 1e6 + 10;\nint a, b;\nint cnt[N];\n\nint main() {\n cin >> t;\n while (t--) {\n memset(cnt, 0, sizeof cnt);\n cin >> n >> m;\n for (int i = 0; i < m; ++i) {\n cin >> a >> b;\n cnt[a]++;\n cnt[b]++;\n }\n if (n == 1) {\n cout << \""A\"" << endl;\n } else if (n > 2 && n == m) {\n cout << \""C\"" << endl;\n } else if (n > 3 && m == n * (n - 1) / 2) {\n cout << \""E\"" << endl;\n } else {\n bool flag = true;\n for (int i = 1; i <= n; ++i) {\n if (cnt[i] > 2) {\n flag = false;\n break;\n }\n }\n if (flag) cout << \""B\"" << endl;\n else cout << \""D\"" << endl;\n }\n }\n return 0;\n}\n",ACCEPTED,205,4352 1510580499080896512,d14ee5ef545e508de9294550a12fb0db2aef40e1965f11c365e32e947d260a64,2022-04-03 19:30:30,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#define endl '\\n'\n#define int ll\ntypedef long long ll;\nusing namespace std;\nconst int MAXN=1e6+5;\nint t;\nint n,m;\nint d[MAXN];\nsigned main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=n;++i){\n\t\t\td[i]=0;\n\t\t}\n\t\tfor(int i=1;i<=m;++i){\n\t\t\tint u,v;\n\t\t\tcin>>u>>v;\n\t\t\td[u]++,d[v]++;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\\n\"";\n\t\t}else{\n\t\t\tint cnt1=0,cnt2=0;\n\t\t\tfor(int i=1;i<=n;++i){\n\t\t\t\tif(d[i]==1)\tcnt1++;\n\t\t\t\tif(d[i]==2)\tcnt2++;\n\t\t\t}\n\t\t\tif(m==n-1){\n\t\t\t\tif(cnt1==2&&n>1){\n\t\t\t\t\tcout<<\""B\\n\"";\n\t\t\t\t}else if(n>3){\n\t\t\t\t\tcout<<\""D\\n\"";\n\t\t\t\t}\n\t\t\t}else if(m==n&&cnt2==n&&n>1){\n\t\t\t\tcout<<\""B\\n\"";\n\t\t\t}else if(2*m==n*(n-1)&&n>3){\n\t\t\t\tcout<<\""E\\n\"";\n\t\t\t}\n\t\t}\n\t}\n}\n//4\n//1 0\n//5 10\n//1 2\n//1 3\n//1 4\n//1 5\n//2 3\n//2 4\n//2 5\n//3 4\n//3 5\n//4 5\n//3 3\n//1 2\n//2 3\n//3 1\n//4 3\n//4 3\n//2 3\n//1 3\n",WRONG_ANSWER,207,1104 1510580782035759104,d14ee5ef545e508de9294550a12fb0db2aef40e1965f11c365e32e947d260a64,2022-04-03 19:31:38,C++,25.0,1510521134800797706,1509437328199348224,582,"#include\n#define endl '\\n'\n#define int ll\ntypedef long long ll;\nusing namespace std;\nconst int MAXN=1e6+5;\nint t;\nint n,m;\nint d[MAXN];\nsigned main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=n;++i){\n\t\t\td[i]=0;\n\t\t}\n\t\tfor(int i=1;i<=m;++i){\n\t\t\tint u,v;\n\t\t\tcin>>u>>v;\n\t\t\td[u]++,d[v]++;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\\n\"";\n\t\t}else{\n\t\t\tint cnt1=0,cnt2=0;\n\t\t\tfor(int i=1;i<=n;++i){\n\t\t\t\tif(d[i]==1)\tcnt1++;\n\t\t\t\tif(d[i]==2)\tcnt2++;\n\t\t\t}\n\t\t\tif(m==n-1){\n\t\t\t\tif(cnt1==2&&n>1&&cnt1+cnt2==n){\n\t\t\t\t\tcout<<\""B\\n\"";\n\t\t\t\t}else if(n>3){\n\t\t\t\t\tcout<<\""D\\n\"";\n\t\t\t\t}\n\t\t\t}else if(m==n&&cnt2==n&&n>1){\n\t\t\t\tcout<<\""C\\n\"";\n\t\t\t}else if(2*m==n*(n-1)&&n>3){\n\t\t\t\tcout<<\""E\\n\"";\n\t\t\t}\n\t\t}\n\t}\n}\n//4\n//1 0\n//5 10\n//1 2\n//1 3\n//1 4\n//1 5\n//2 3\n//2 4\n//2 5\n//3 4\n//3 5\n//4 5\n//3 3\n//1 2\n//2 3\n//3 1\n//4 3\n//4 3\n//2 3\n//1 3\n",ACCEPTED,202,1216 1510580804118769664,e43a6b275382d4de707ad9fe9a0c910690c66d7d8d6f9b28f68d2e75883214c5,2022-04-03 19:31:43,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n \n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n bool falg=true;\n bool falg1=true;\n int cnt1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]!=2)\n {\n falg=false;\n if(d[i]!=1)\n {\n falg1=false;\n }\n }\n if(d[i]==1)\n {\n cnt1++;\n }\n \n }\n if(falg)\n {\n cout<<\""C\""<\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n \n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n bool falg=true;\n bool falg1=true;\n int cnt1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]!=2)\n {\n falg=false;\n if(d[i]!=1)\n {\n falg1=false;\n }\n }\n if(d[i]==1)\n {\n cnt1++;\n }\n \n }\n if(falg)\n {\n cout<<\""C\""<\n//#define LOCAL\n#define endl '\\n'\nusing i64 = long long;\nusing namespace std;\n\nconst int maxn = 1e6;\n\nint n, m;\nvector g[maxn];\n\nvoid solve() {\n cin >> n >> m;\n for(int i = 0; i <= n; i++) g[i].clear();\n int u,v;\n for(int i = 0; i < m; i++) {\n cin >> u >> v;\n g[u].push_back(v);\n g[v].push_back(u);\n }\n if(n == 1) {\n cout << \""A\\n\"";\n return;\n }\n // if(n == 2) {\n // cout << \""B\\n\"";\n // return;\n // }\n bool flag = true, flag2 = true;\n for(int i = 1; i <= n; i++) {\n if(g[i].size() != n - 1) {\n flag = false;\n }\n if(g[i].size() > 1) {\n flag2 = false;\n }\n }\n if(flag == true) {\n cout << \""E\\n\"";\n return;\n }\n if(flag2 == false && n > 3) {\n cout << \""D\\n\"";\n return;\n }\n if(n > 2 && m == n) {\n cout << \""C\\n\"";\n return;\n }\n if(n > 1 && m == n-1) {\n cout << \""B\\n\"";\n return ;\n }\n}\n\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n#ifdef LOCAL\n freopen(\""in.txt\"", \""r\"", stdin);\n freopen(\""out.txt\"", \""w\"", stdout);\n#endif\n int t;\n cin >> t;\n while(t--) solve();\n}",WRONG_ANSWER,144,28600 1510581907405815808,e43a6b275382d4de707ad9fe9a0c910690c66d7d8d6f9b28f68d2e75883214c5,2022-04-03 19:36:06,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1000005;\nint f[N];\nint d[N];\nint find(int x)\n{\n if(f[x]!=x)\n {\n f[x]=find(f[x]);\n }\n return f[x];\n}\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n \n \n \n for(int i=0;i>x>>y;\n find(f[x])=find(f[y]);\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<\nusing namespace std;\nconst int N=1000005;\nint f[N];\nint d[N];\nint find(int x)\n{\n if(f[x]!=x)\n {\n f[x]=find(f[x]);\n }\n return f[x];\n}\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n \n \n \n for(int i=0;i>x>>y;\n f[find(f[x])]=find(f[y]);\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<\n\nchar jugde(int a[],int c){\n\tfor(int i=1;i<=c;i++){\n\t\tif(a[i]>=3) return 'D';\n\t}\n\treturn 'B';\n}\n\nchar judge2(int a[],int c){\n\tfor(int i=1;i<=c;i++){\n\t\tif(a[i]!=2) return 'E';\n\t}\n\treturn 'C';\n}\n\nint main(){\n\tint a,n,c,n2,cnt[1000001]={0};\n\tscanf(\""%d\"",&n);\n\tfor(int i=1;i<=n;i++){\n\t\tscanf(\""%d %d\"",&c,&n2);\n\t\tfor(int i2=1;i2<=n2*2;i2++){\n\t\t\tscanf(\""%d\"",&a);\n\t\t\tcnt[a]++;\n\t\t}\n\t\tif(c==1)printf(\""A\\n\"");\n\t\telse if(c==n2+1)printf(\""%c\\n\"",jugde(cnt,c));\n\t\telse printf(\""%c\\n\"",judge2(cnt,c));\n\t}\n}",WRONG_ANSWER,92,4288 1510583060285767680,1b04369cfe5b7290159c9f2b857e3805ccd898be9b142566d818efaf2f9e7485,2022-04-03 19:40:41,C,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nchar jugde(int a[],int c){\n\tfor(int i=1;i<=c;i++){\n\t\tif(a[i]>=3) return 'D';\n\t}\n\treturn 'B';\n}\n\nchar judge2(int a[],int c){\n\tfor(int i=1;i<=c;i++){\n\t\tif(a[i]!=2) return 'E';\n\t}\n\treturn 'C';\n}\n\nint main(){\n\tint a,n,c,n2,cnt[1000001]={0};\n\tscanf(\""%d\"",&n);\n\tfor(int i=1;i<=n;i++){\n\t\tscanf(\""%d %d\"",&c,&n2);\n\t\tfor(int i2=1;i2<=n2*2;i2++){\n\t\t\tscanf(\""%d\"",&a);\n\t\t\tcnt[a]++;\n\t\t}\n\t\tif(c==1)printf(\""A\\n\"");\n\t\telse if(c==n2+1)printf(\""%c\\n\"",jugde(cnt,c));\n\t\telse printf(\""%c\\n\"",judge2(cnt,c));\n\t}\n for(int i2=1;i2<=1000000;i2++)cnt[i2]=0;\n}",WRONG_ANSWER,92,4284 1510583068091367424,4c41d24781151f0c29fe18018c807ed1e8fb8d91ab2ce3f92bec9402cc3945dd,2022-04-03 19:40:43,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n#define rep(i, a, b) for(int i = a; i <= b; ++i)\n#define per(i, a, b) for(int i = a; i >= b; --i)\n#define I inline\nconst int N = 1e6 + 5;\nvector g[N];\nint n, m;\nvoid add(int x, int y){\n\tg[x].push_back(y);\n\tg[y].push_back(x);\n}\nint sz[N];\nvoid dfs(int x, int f){\n\tfor(auto y : g[x]){\n\t\tif(y == f) continue;\n\t\tdfs(y, x);\n\t\t++sz[x];\n\t}\n}\nvoid clear(){\n\trep(i, 1, n) sz[i] = 0, g[i].clear();\n}\nI void work(){\n\tint n, m; cin >> n >> m;\n\trep(i, 1, m){\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tadd(x, y);\n\t}\n\tif(n == 1){\n\t\tcout << \""A\"";\n\t\treturn;\n\t}\n\tif(m == n - 1){\n\t\tdfs(1, 0);\n\t\trep(i, 1, n) if(sz[i] > 1){\n\t\t\tcout << \""D\"";\n\t\t\treturn;\n\t\t}\n\t\tcout << \""B\"";\n\t\treturn;\n\t}\n\tif(n == m){\n\t\tcout << \""C\"";\n\t\treturn;\n\t}\n\tcout << \""E\"";\n}\nint main(){\n\tint t;\n\tios::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n\tcin >> t;\n\twhile(t--){\n\t\twork();\n\t\tclear();\n\t\tif(t) cout << '\\n';\n\t}\n\treturn 0;\n}",MEMORY_LIMIT_EXCEEDED,232,131072 1510583093399797760,60e638a83e5b19cbe789ced297f703bb0c8023910446a60f7d071909cbc9130a,2022-04-03 19:40:49,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\n\nint main(){\n\tint n;\n\tcin>>n;\n\twhile(n--){\n\t\tint x,y;\n\t\tcin>>x>>y;\n\t\twhile(y--){\n\t\t\tint i,j;\n\t\t\tcin>>i>>j;\n\t\t}\n\t\tif(x==1){\n\t\t\tcout<<\""A\""<\n//#define LOCAL\n#define endl '\\n'\nusing i64 = long long;\nusing namespace std;\n\nconst int maxn = 1e6;\n\nint n, m;\nvector g[maxn];\n\nvoid solve() {\n cin >> n >> m;\n for(int i = 0; i <= n; i++) g[i].clear();\n int u,v;\n for(int i = 0; i < m; i++) {\n cin >> u >> v;\n g[u].push_back(v);\n g[v].push_back(u);\n }\n if(n == 1) {\n cout << \""A\\n\"";\n return;\n }\n bool flag2 = true;\n for(int i = 1; i <= n; i++) {\n // if(g[i].size() != n - 1) {\n // flag = false;\n // }\n if(g[i].size() > 1) {\n flag2 = false;\n }\n }\n // if(flag == true) {\n // cout << \""E\\n\"";\n // return;\n // }\n if(flag2 == false && n > 3) {\n cout << \""D\\n\"";\n return;\n }\n if(n > 2 && m == n) {\n cout << \""C\\n\"";\n return;\n }\n if(n > 1 && m == n-1) {\n cout << \""B\\n\"";\n return ;\n }\n else {\n cout << \""E\\n\"";\n }\n}\n\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n#ifdef LOCAL\n freopen(\""in.txt\"", \""r\"", stdin);\n freopen(\""out.txt\"", \""w\"", stdout);\n#endif\n int t;\n cin >> t;\n while(t--) solve();\n}",WRONG_ANSWER,150,28604 1510583201629073408,43407cff329998389b73c53b8778e3453560bd007aa7fb0a9269e34a83edc8ee,2022-04-03 19:41:15,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\ntypedef long long ll;\ntypedef pair PII;\nconst int N=1e6+5,INF=0x3f3f3f3f;\nint t,n,m;\nint h[N],e[N],ne[N],idx;\nvoid add(int a,int b)\n{\n\te[idx]=b;\n\tne[idx]=h[a];\n\th[a]=idx++;\n}\nint main()\n{\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tidx=0;\n\t\tint cnt[N]={0};\n\t\tbool B=true,C=true;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tadd(a,b);\n\t\t\tcnt[a]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<\n\nchar jugde(int a[],int c){\n\tfor(int i=1;i<=c;i++){\n\t\tif(a[i]>=3) return 'D';\n\t}\n\treturn 'B';\n}\n\nchar judge2(int a[],int c){\n\tfor(int i=1;i<=c;i++){\n\t\tif(a[i]!=2) return 'E';\n\t}\n\treturn 'C';\n}\n\nint main(){\n\tint a,n,c,n2,cnt[1000001]={0};\n\tscanf(\""%d\"",&n);\n\tfor(int i=1;i<=n;i++){\n\t\tscanf(\""%d %d\"",&c,&n2);\n\t\tfor(int i2=1;i2<=n2*2;i2++){\n\t\t\tscanf(\""%d\"",&a);\n\t\t\tcnt[a]++;\n\t\t}\n\t\tif(c==1)printf(\""A\\n\"");\n\t\telse if(c==n2+1)printf(\""%c\\n\"",jugde(cnt,c));\n\t\telse printf(\""%c\\n\"",judge2(cnt,c));\n\t}\n for(int i2=1;i2<=1000000;i2++)cnt[i2]=0;\n}",WRONG_ANSWER,85,4280 1510583256118550528,4c41d24781151f0c29fe18018c807ed1e8fb8d91ab2ce3f92bec9402cc3945dd,2022-04-03 19:41:28,C++,10.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n#define rep(i, a, b) for(int i = a; i <= b; ++i)\n#define per(i, a, b) for(int i = a; i >= b; --i)\n#define I inline\nconst int N = 1e6 + 5;\nvector g[N];\nint n, m;\nvoid add(int x, int y){\n\tg[x].push_back(y);\n\tg[y].push_back(x);\n}\nint sz[N];\nvoid dfs(int x, int f){\n\tfor(auto y : g[x]){\n\t\tif(y == f) continue;\n\t\tdfs(y, x);\n\t\t++sz[x];\n\t}\n}\nvoid clear(){\n\trep(i, 1, n) sz[i] = 0, g[i].clear();\n}\nI void work(){\n\tcin >> n >> m;\n\trep(i, 1, m){\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tadd(x, y);\n\t}\n\tif(n == 1){\n\t\tcout << \""A\"";\n\t\treturn;\n\t}\n\tif(m == n - 1){\n\t\tdfs(1, 0);\n\t\trep(i, 1, n) if(sz[i] > 1){\n\t\t\tcout << \""D\"";\n\t\t\treturn;\n\t\t}\n\t\tcout << \""B\"";\n\t\treturn;\n\t}\n\tif(n == m){\n\t\tcout << \""C\"";\n\t\treturn;\n\t}\n\tcout << \""E\"";\n}\nint main(){\n\tint t;\n\tios::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n\tcin >> t;\n\twhile(t--){\n\t\twork();\n\t\tclear();\n\t\tif(t) cout << '\\n';\n\t}\n\treturn 0;\n}",PARTIAL_ACCEPTED,172,33012 1510583279911563264,f5f19fbe584bcae32491371ad126ba09612c3024585d256ccfb801cff88a95f4,2022-04-03 19:41:33,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \ntypedef long long ll;\nconst double PI = acos(-1.0);\nconst int inf = 10000000 + 10;\nconst int sz = 100010;\nconst int P = 10007;\nusing namespace std;\n#define ri register int\ninline void rd(int &x){\n\tchar c=getchar();bool f=0;x=0;\n\twhile(c>'9'||c<'0'){if(c=='-')f=1;c=getchar();}\n\twhile(c<='9'&&c>='0'){x=x*10+c-'0';c=getchar();}\n\tif(f) x*=-1;}\ninline void we(int x){\n\tif(x<0) putchar('-'),x*=-1;\n\tif(x/10) we(x/10);\n\tputchar(x%10+'0');}\ninline int gcd(int a,int b){while(b^=a^=b^=a%=b);return a;}\ninline int lcm(int a,int b){return a*b/gcd(a,b);}\nll pow(ll a,ll b){\n\tif(b==0) return 1;if(b==1) return a%P;\n\tll t=(b>>1);\n\tll x=pow(a,t);\n\tll ans=( (x%P)*(x%P) )%P;\n\t\tif(b&1) ans=( (ans%P)*(a%P) )%P;\n\treturn ans%P;}\nint fa[sz];\ninline int find(int x){return x==fa[x]?fa[x]:find(fa[x]);}\ninline void merge(int x,int y){int X=find(x),Y=find(y);if(X!=Y)fa[X]=Y;}\ninline void swap(int &a,int &b){int t=a;a=b,b=t;}\ninline int max(int a,int b){return a>b?a:b;}inline int min(int a,int b){return a>t;\nwhile(t--){\n//\twhile(~scanf(\""%d%d\"",&a,&b)){\n\tcin>>n>>m;\n\n\tfor(ri i=1;i<=m;++i)\n\t{\n\t\tcin>>t>>e;\n\t\t//cout<<\""E\"";\n\t}\n\tif(n==1) {cout<<\""A\""<\n#include\n#include\nusing namespace std;\n\nint main(){\n\tint n;\n\tcin>>n;\n\twhile(n--){\n\t\tint x,y;\n\t\tcin>>x>>y;\n\t\twhile(y--){\n\t\t\tint i,j;\n\t\t\tcin>>i>>j;\n\t\t}\n\t\tif(x==1){\n\t\t\tcout<<\""A\"";\n\t\t\tif(n!=0)cout<\nusing namespace std;\nconst int N = 1e6+10,M = N<<1;\nvoid solve(){\n\tint n,m;\n\tcin>>n>>m;\n\tvectord(n+1);\n\tfor(int i=1;i<=m;i++){\n\t\tint a,b;\n\t\tcin>>a>>b;\n\t\td[a++],d[b]++;\n\t}\n\tint cnt[3]={};\n\tif(n==1){\n\t\tputs(\""A\"");\n\t\treturn;\n\t}\n\tbool f=true;\n\tfor(int i=1;i<=n;i++){\n\t\tif(d[i]!=1||d[i]!=2){\n\t\t\tf=false;\n\t\t\tbreak;\n\t\t}\n\t\tcnt[d[i]]++;\n\t}\n\tif(f&&cnt[1]==2){\n\t\tputs(\""B\"");\n\t\treturn;\n\t}\n\tif(f&&cnt[1]==0){\n\t\tputs(\""C\"");\n\t\treturn;\n\t}\n\tf=true;\n\tfor(int i=1;i<=n;i++){\n\t\tif(d[i]!=n-1){\n\t\t\tputs(\""D\"");\n\t\t\treturn;\n\t\t}\n\t}\n\tputs(\""E\"");\n}\nint main(){\n\tint T;\n\tcin>>T;\n\twhile(T--)solve();\n\treturn 0;\n}",WRONG_ANSWER,199,868 1510583379783409664,9ef757d34dbd9ae4f25da432daf2c8658f170ee328eab1c55e3a9fe91515643f,2022-04-03 19:41:57,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n//#define LOCAL\n#define endl '\\n'\nusing i64 = long long;\nusing namespace std;\n\nconst int maxn = 1e6;\n\nint n, m;\nvector g[maxn];\n\nvoid solve() {\n cin >> n >> m;\n for(int i = 0; i <= n; i++) g[i].clear();\n int u,v;\n for(int i = 0; i < m; i++) {\n cin >> u >> v;\n g[u].push_back(v);\n g[v].push_back(u);\n }\n if(n == 1) {\n cout << \""A\\n\"";\n return;\n }\n bool flag2 = true;\n for(int i = 1; i <= n; i++) {\n // if(g[i].size() != n - 1) {\n // flag = false;\n // }\n if(g[i].size() > 1) {\n flag2 = false;\n }\n }\n // if(flag == true) {\n // cout << \""E\\n\"";\n // return;\n // }\n if(n > 2 && m == n) {\n cout << \""C\\n\"";\n return;\n }\n if(flag2 == false && n > 3) {\n cout << \""D\\n\"";\n return;\n }\n if(n > 1 && m == n-1) {\n cout << \""B\\n\"";\n return ;\n }\n else {\n cout << \""E\\n\"";\n }\n}\n\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n#ifdef LOCAL\n freopen(\""in.txt\"", \""r\"", stdin);\n freopen(\""out.txt\"", \""w\"", stdout);\n#endif\n int t;\n cin >> t;\n while(t--) solve();\n}",WRONG_ANSWER,141,28496 1510583429586575360,60e638a83e5b19cbe789ced297f703bb0c8023910446a60f7d071909cbc9130a,2022-04-03 19:42:09,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\n\nint main(){\n\tint n;\n\tcin>>n;\n\twhile(n--){\n\t\tint x,y;\n\t\tcin>>x>>y;\n\t\twhile(y--){\n\t\t\tint i,j;\n\t\t\tcin>>i>>j;\n\t\t}\n\t\tif(x==1){\n\t\t\tcout<<\""A\"";\n\t\t\tif(n!=0)cout<\nusing namespace std;\nconst int N = 1e6+10,M = N<<1;\nvoid solve(){\n\tint n,m;\n\tcin>>n>>m;\n\tvectord(n+1);\n\tfor(int i=1;i<=m;i++){\n\t\tint a,b;\n\t\tcin>>a>>b;\n\t\td[a]++,d[b]++;\n\t}\n\tint cnt[3]={};\n\tif(n==1){\n\t\tputs(\""A\"");\n\t\treturn;\n\t}\n\tbool f=true;\n\tfor(int i=1;i<=n;i++){\n\t\tif(d[i]!=1||d[i]!=2){\n\t\t\tf=false;\n\t\t\tbreak;\n\t\t}\n\t\tcnt[d[i]]++;\n\t}\n\tif(f&&cnt[1]==2){\n\t\tputs(\""B\"");\n\t\treturn;\n\t}\n\tif(f&&cnt[1]==0){\n\t\tputs(\""C\"");\n\t\treturn;\n\t}\n\tf=true;\n\tfor(int i=1;i<=n;i++){\n\t\tif(d[i]!=n-1){\n\t\t\tputs(\""D\"");\n\t\t\treturn;\n\t\t}\n\t}\n\tputs(\""E\"");\n}\nint main(){\n\tint T;\n\tcin>>T;\n\twhile(T--)solve();\n\treturn 0;\n}",WRONG_ANSWER,201,704 1510583468501327872,60e638a83e5b19cbe789ced297f703bb0c8023910446a60f7d071909cbc9130a,2022-04-03 19:42:18,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\n\nint main(){\n\tint n;\n\tcin>>n;\n\twhile(n--){\n\t\tint x,y;\n\t\tcin>>x>>y;\n\t\twhile(y--){\n\t\t\tint i,j;\n\t\t\tcin>>i>>j;\n\t\t}\n\t\tif(x==1){\n\t\t\tcout<<\""A\"";\n\t\t\tif(n!=0)cout<\n#include\n#include\nusing namespace std;\n\nint main(){\n\tint n;\n\tcin>>n;\n\twhile(n--){\n\t\tint x,y;\n\t\tcin>>x>>y;\n\t\twhile(y--){\n\t\t\tint i,j;\n\t\t\tcin>>i>>j;\n\t\t}\n\t\tif(x==1){\n\t\t\tcout<<\""A\"";\n\t\t\tif(n!=0)cout<\nusing namespace std;\ntypedef long long ll;\ntypedef pair PII;\nconst int N=1e6+5,INF=0x3f3f3f3f;\nint t,n,m;\nint h[N],e[N],ne[N],idx;\nint cnt[N];\nvoid add(int a,int b)\n{\n\te[idx]=b;\n\tne[idx]=h[a];\n\th[a]=idx++;\n}\nint main()\n{\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tmemset(cnt,0,sizeof cnt);\n\t\tidx=0;\n\t\tbool B=true,C=true;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tadd(a,b);\n\t\t\tcnt[a]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<\n\nchar jugde(int a[],int c){\n\tfor(int i=1;i<=c;i++){\n\t\tif(a[i]>=3) return 'D';\n\t}\n\treturn 'B';\n}\n\nchar judge2(int a[],int c){\n\tfor(int i=1;i<=c;i++){\n\t\tif(a[i]!=2) return 'E';\n\t}\n\treturn 'C';\n}\n\nint main(){\n\tint a,n,c,n2,cnt[1000001]={0};\n\tscanf(\""%d\"",&n);\n\tfor(int i=1;i<=n;i++){\n\t\tscanf(\""%d %d\"",&c,&n2);\n\t\tfor(int i2=1;i2<=n2*2;i2++){\n\t\t\tscanf(\""%d\"",&a);\n\t\t\tcnt[a]++;\n\t\t}\n\t\tif(c==1)printf(\""A\\n\"");\n\t\telse if(c==n2+1)printf(\""%c\\n\"",jugde(cnt,c));\n\t\telse printf(\""%c\\n\"",judge2(cnt,c));\n for(int i2=1;i2<=1000000;i2++) cnt[i2]=0;\n\t}\n}",ACCEPTED,101,4344 1510583804666404864,9ef757d34dbd9ae4f25da432daf2c8658f170ee328eab1c55e3a9fe91515643f,2022-04-03 19:43:38,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n//#define LOCAL\n#define endl '\\n'\nusing i64 = long long;\nusing namespace std;\n\nconst int maxn = 1e6;\n\nint n, m;\nvector g[maxn];\n\nvoid solve() {\n cin >> n >> m;\n for(int i = 0; i <= n; i++) g[i].clear();\n int u,v;\n for(int i = 0; i < m; i++) {\n cin >> u >> v;\n g[u].push_back(v);\n g[v].push_back(u);\n }\n if(n == 1) {\n cout << \""A\\n\"";\n return;\n }\n bool flag2 = true;\n for(int i = 1; i <= n; i++) {\n // if(g[i].size() != n - 1) {\n // flag = false;\n // }\n if(g[i].size() > 2) {\n flag2 = false;\n }\n }\n // if(flag == true) {\n // cout << \""E\\n\"";\n // return;\n // }\n if(n > 2 && m == n) {\n cout << \""C\\n\"";\n return;\n }\n if(flag2 == false && n > 3) {\n cout << \""D\\n\"";\n return;\n }\n if(n > 1 && m == n-1) {\n cout << \""B\\n\"";\n return ;\n }\n else {\n cout << \""E\\n\"";\n }\n}\n\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n#ifdef LOCAL\n freopen(\""in.txt\"", \""r\"", stdin);\n freopen(\""out.txt\"", \""w\"", stdout);\n#endif\n int t;\n cin >> t;\n while(t--) solve();\n}",WRONG_ANSWER,149,28468 1510583903974940672,eec48ea930b7b6cec317284cc32e41ad075ec286675dd2adf6ced4a979d4274b,2022-04-03 19:44:02,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int h = 0; h < T; h++) {\n\t\tint m, n;\n\t\tcin >> n;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\""<> m;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tshu[x]++;\n\t\t\tshu[y]++;\n\t\t}\n\t\tint n1 = 0;\n\t\tint n2 = 0;\n\t\tint nn = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (shu[i] == 1) {\n\t\t\t\tn1++;\n\t\t\t}\n\t\t\tif (shu[i] == 2) {\n\t\t\t\tn2++;\n\t\t\t}\n\t\t\tif (shu[i] == n - 1) {\n\t\t\t\tnn++;\n\t\t\t}\n\t\t}\n\t\tif (n1 == 2 && n2 == n - 2) {\n\t\t\tcout << \""B\""<\n//#define LOCAL\n#define endl '\\n'\nusing i64 = long long;\nusing namespace std;\n\nconst int maxn = 1e6;\n\nint n, m;\nvector g[maxn];\n\nvoid solve() {\n cin >> n >> m;\n for(int i = 0; i <= n; i++) g[i].clear();\n int u,v;\n for(int i = 0; i < m; i++) {\n cin >> u >> v;\n g[u].push_back(v);\n g[v].push_back(u);\n }\n if(n == 1) {\n cout << \""A\\n\"";\n return;\n }\n bool flag2 = true;\n for(int i = 1; i <= n; i++) {\n // if(g[i].size() != n - 1) {\n // flag = false;\n // }\n if(g[i].size() > 2) {\n flag2 = false;\n }\n }\n // if(flag == true) {\n // cout << \""E\\n\"";\n // return;\n // }\n if(n > 1 && m == n-1) {\n cout << \""B\\n\"";\n return ;\n }\n if(flag2 == false && n > 3) {\n cout << \""D\\n\"";\n return;\n }\n if(n > 2 && m == n) {\n cout << \""C\\n\"";\n return;\n }\n else {\n cout << \""E\\n\"";\n }\n}\n\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n#ifdef LOCAL\n freopen(\""in.txt\"", \""r\"", stdin);\n freopen(\""out.txt\"", \""w\"", stdout);\n#endif\n int t;\n cin >> t;\n while(t--) solve();\n}",WRONG_ANSWER,155,28624 1510584108383617024,8263288289d4c9e633a3aeb5026b1742b5c6243c52d21168e9a682b7700fa3c7,2022-04-03 19:44:51,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010];\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<\nusing namespace std;\n#define rep(i, a, b) for(int i = a; i <= b; ++i)\n#define per(i, a, b) for(int i = a; i >= b; --i)\n#define I inline\nconst int N = 1e6 + 5;\nvector g[N];\nint n, m;\nvoid add(int x, int y){\n\tg[x].push_back(y);\n\tg[y].push_back(x);\n}\nint sz[N];\nvoid dfs(int x, int f){\n\tfor(auto y : g[x]){\n\t\tif(y == f) continue;\n\t\tdfs(y, x);\n\t\t++sz[x];\n\t}\n}\nvoid clear(){\n\trep(i, 1, n) sz[i] = 0, g[i].clear();\n}\nI void work(){\n\tcin >> n >> m;\n\trep(i, 1, m){\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tadd(x, y);\n\t}\n\tif(n == 1){\n\t\tcout << \""A\"";\n\t\treturn;\n\t}\n\tif(m == n - 1){\n\t\tdfs(1, 0);\n\t\tif(sz[1] > 2){\n\t\t\tcout << \""D\"";\n\t\t\treturn;\n\t\t}\n\t\trep(i, 2, n) if(sz[i] > 1){\n\t\t\tcout << \""D\"";\n\t\t\treturn;\n\t\t}\n\t\tcout << \""B\"";\n\t\treturn;\n\t}\n\tif(n == m){\n\t\tcout << \""C\"";\n\t\treturn;\n\t}\n\tcout << \""E\"";\n}\nint main(){\n\tint t;\n\tios::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n\tcin >> t;\n\twhile(t--){\n\t\twork();\t\n\t\tclear();\n\t\tif(t) cout << '\\n';\n\t}\n\treturn 0;\n}",ACCEPTED,159,32984 1510584142839824384,e43a6b275382d4de707ad9fe9a0c910690c66d7d8d6f9b28f68d2e75883214c5,2022-04-03 19:44:59,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1000005;\nint f[N];\nint d[N];\nint find(int x)\n{\n if(f[x]!=x)\n {\n f[x]=find(f[x]);\n }\n return f[x];\n}\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n \n \n \n for(int i=0;i>x>>y;\n find(f[x])=find(f[y]);\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<\nusing namespace std;\nconst int N=1e6+10;\nint t,n,m;\nint ind[N];\nvoid solve(){\n\tif(n==1){\n\t\tcout<<'A'<2){\n\t\t\t\tcout<<'D'<>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tmemset(ind,0,sizeof ind);\n\t\tfor(int i=0;i>a>>b;\n\t\t\tind[a]++;\n\t\t\tind[b]++;\n\t\t}\n\t\tsolve();\n\t}\n return 0;\n}\n",PARTIAL_ACCEPTED,200,4296 1510584225899626496,7ccb1eb347441446e6c0da14d8e10ea24d50ffecc92ae8380cb6818f0fa18d5b,2022-04-03 19:45:19,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main()\n{\n\tint t;\n\twhile(t--){\n\t\tint n,m;\n\t\tif(n==1){\n\t\tcout<<\""A\"";\n\t\tbreak;\n\t }\n\t}\n\treturn 0;\n}",WRONG_ANSWER,8,324 1510584322011557888,8263288289d4c9e633a3aeb5026b1742b5c6243c52d21168e9a682b7700fa3c7,2022-04-03 19:45:42,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010];\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<\nusing namespace std;\nconst int N=1000005;\nint f[N];\nint d[N];\nint find(int x)\n{\n if(f[x]!=x)\n {\n f[x]=find(f[x]);\n }\n return f[x];\n}\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n \n \n \n for(int i=0;i>x>>y;\n f[find(f[x])]=find(f[y]);\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<\nusing namespace std;\nconst int N=1000005;\nint f[N];\nint d[N];\nint find(int x)\n{\n if(f[x]!=x)\n {\n f[x]=find(f[x]);\n }\n return f[x];\n}\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n\n\n\n for(int i=0;i>x>>y;\n f[find(f[x])]=find(f[y]);\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n }\n}\n",WRONG_ANSWER,204,4160 1510584744135245824,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 19:47:22,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\"";\n for(int j=0;j\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\"";\n for(int j=0;j\nusing namespace std;\nconst int N = 1e6+10,M = N<<1;\nvoid solve(){\n\tint n,m;\n\tcin>>n>>m;\n\tvectord(n+1);\n\tfor(int i=1;i<=m;i++){\n\t\tint a,b;\n\t\tcin>>a>>b;\n\t\td[a]++,d[b]++;\n\t}\n\tint cnt[3]={0};\n\tif(n==1){\n\t\tputs(\""A\"");\n\t\treturn;\n\t}\n\tbool f=true;\n\tfor(int i=1;i<=n;i++){\n\t\tif(d[i]!=1&&d[i]!=2){\n\t\t\tf=false;\n\t\t\tbreak;\n\t\t}\n\t\tcnt[d[i]]++;\n\t}\n\tif(f&&cnt[1]==2){\n\t\tputs(\""B\"");\n\t\treturn;\n\t}\n\tif(f&&cnt[1]==0){\n\t\tputs(\""C\"");\n\t\treturn;\n\t}\n\tf=true;\n\tfor(int i=1;i<=n;i++){\n\t\tif(d[i]!=n-1){\n\t\t\tputs(\""D\"");\n\t\t\treturn;\n\t\t}\n\t}\n\tputs(\""E\"");\n}\nint main(){\n\tint T;\n\tcin>>T;\n\twhile(T--)solve();\n\treturn 0;\n}",ACCEPTED,197,712 1510584938134388736,9ef757d34dbd9ae4f25da432daf2c8658f170ee328eab1c55e3a9fe91515643f,2022-04-03 19:48:09,C++,25.0,1510521134800797706,1509437328199348224,582,"#include \n//#define LOCAL\n#define endl '\\n'\nusing i64 = long long;\nusing namespace std;\n\nconst int maxn = 1e6;\n\nint n, m;\nvector g[maxn];\n\nvoid solve() {\n cin >> n >> m;\n for(int i = 0; i <= n; i++) g[i].clear();\n int u,v;\n for(int i = 0; i < m; i++) {\n cin >> u >> v;\n g[u].push_back(v);\n g[v].push_back(u);\n }\n if(n == 1) {\n cout << \""A\\n\"";\n return;\n }\n bool flag2 = true;\n for(int i = 1; i <= n; i++) {\n // if(g[i].size() != n - 1) {\n // flag = false;\n // }\n if(g[i].size() > 2) {\n flag2 = false;\n }\n }\n // if(flag == true) {\n // cout << \""E\\n\"";\n // return;\n // }\n if(flag2 == false && n > 3 && m == n - 1) {\n cout << \""D\\n\"";\n return;\n }\n if(n > 1 && m == n-1) {\n cout << \""B\\n\"";\n return ;\n }\n if(n > 2 && m == n) {\n cout << \""C\\n\"";\n return;\n }\n else {\n cout << \""E\\n\"";\n }\n}\n\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n#ifdef LOCAL\n freopen(\""in.txt\"", \""r\"", stdin);\n freopen(\""out.txt\"", \""w\"", stdout);\n#endif\n int t;\n cin >> t;\n while(t--) solve();\n}",ACCEPTED,148,28552 1510584952110538752,eec48ea930b7b6cec317284cc32e41ad075ec286675dd2adf6ced4a979d4274b,2022-04-03 19:48:12,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int h = 0; h < T; h++) {\n\t\tint m, n;\n\t\tcin >> n;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\""<> m;\n\t\t\tfor (int i = 0; i < m; i++) {\n\t\t\t\tint x, y;\n\t\t\t\tcin >> x >> y;\n\t\t\t\tshu[x]++;\n\t\t\t\tshu[y]++;\n\t\t\t}\n\t\t\tint n1 = 0;\n\t\t\tint n2 = 0;\n\t\t\tint nn = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (shu[i] == 1) {\n\t\t\t\t\tn1++;\n\t\t\t\t}\n\t\t\t\tif (shu[i] == 2) {\n\t\t\t\t\tn2++;\n\t\t\t\t}\n\t\t\t\tif (shu[i] == n - 1) {\n\t\t\t\t\tnn++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (n1 == 2 && n2 == n - 2) {\n\t\t\t\tcout << \""B\"" << endl;\n\t\t\t}\n\t\t\telse if (n2 == n) {\n\t\t\t\tcout << \""C\"" << endl;\n\t\t\t}\n\t\t\telse if (nn = n) {\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,6,328 1510584979641950208,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 19:48:19,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n for(int i=0;i>n>>m;\n if(n>3) cout<\n#define M 100005 \nusing namespace std;\nint t;\nint n,m;\nint ii,jj;\nint mapp[M];\nbool visit[M];\nint main(){\n\tscanf(\""%d\"",&t);\n\twhile(t--){\n\t\tbool f=0;\n\t\tscanf(\""%d %d\"",&n,&m);\n\t\tfor(int i=0;i1||mapp[jj]>1){\n\t\t\t\tf=1;\n\t\t\t}\n\t\t}\n\t\tif(n==1){\n\t\t\tprintf(\""A\\n\"");\n\t\t}else if(n==m+1&&!f){\n\t\t\tprintf(\""B\\n\"");\n\t\t}else if(n==m){\n\t\t\tprintf(\""C\\n\"");\n\t\t}else if(n\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n for(int i=0;i>n>>m;\n if(n>3) cout<<\""E\"";\n else cout<<\""D\"";\n \n }\n \n \n \n}",WRONG_ANSWER,8,452 1510585129089196032,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 19:48:54,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n for(int i=0;i>n>>m;\n if(n>3) cout<<\""D\"";\n else cout<<\""E\"";\n \n }\n \n \n \n}",WRONG_ANSWER,8,612 1510585181164400640,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 19:49:07,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n int n,m;\n cin>>n>>m;\n while(m--)\n {\n int a,b;\n cin>>a>>b;\n }\n if(n==1) cout<<\""A\""<\nusing namespace std;\nint main()\n{\n\tcout << \""A\"";\n\treturn 0;\n } ",WRONG_ANSWER,8,324 1510585372139450368,705f0d22cf86b5a3f1d2effa36be65eac3e06c910f0ff67f238142609a1d020a,2022-04-03 19:49:52,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main()\n{\n\tcout << \""B\"";\n\treturn 0;\n } ",WRONG_ANSWER,8,444 1510585411100340224,705f0d22cf86b5a3f1d2effa36be65eac3e06c910f0ff67f238142609a1d020a,2022-04-03 19:50:01,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main()\n{\n\tcout << \""C\"";\n\treturn 0;\n } ",WRONG_ANSWER,8,452 1510585462158147584,c06cf25eded01cd3f790834c74285be6c6110aa641ecfb9a234fb1bb2e50c8f8,2022-04-03 19:50:14,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N=1e6+10;\nint h[N],ne[N],e[N],idx;\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\nbool st[N];\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(st,0,sizeof st);\n\t\tmemset(h,-1,sizeof h);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tadd(a,b);\n\t\t\tst[b]=1;\n\t\t}\n\t\tif(n==1)cout<<\""A\""<\nusing namespace std;\nint main()\n{\n\tcout << \""D\"";\n\treturn 0;\n } ",WRONG_ANSWER,7,612 1510585517807628288,705f0d22cf86b5a3f1d2effa36be65eac3e06c910f0ff67f238142609a1d020a,2022-04-03 19:50:27,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main()\n{\n\tcout << \""E\"";\n\treturn 0;\n } ",WRONG_ANSWER,8,448 1510585563916156928,3a2236b18297a6cd20e727de89fbb262db82578827b4cf92f23ae7acd4976769,2022-04-03 19:50:38,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#define M 100005 \nusing namespace std;\nint t;\nint n,m;\nint ii,jj;\nint mapp[M];\nbool visit[M];\nint main(){\n\tscanf(\""%d\"",&t);\n\twhile(t--){\n\t\tbool f=0;\n\t\tscanf(\""%d %d\"",&n,&m);\n\t\tfor(int i=0;i1||mapp[jj]>1){\n\t\t\t\tf=1;\n\t\t\t}\n\t\t}\n\t\tif(n==1){\n\t\t\tprintf(\""A\\n\"");\n\t\t}else if(n==m+1&&!f){\n\t\t\tprintf(\""B\\n\"");\n\t\t}else if(n==m&&!f){\n\t\t\tprintf(\""C\\n\"");\n\t\t}else if(n<=m&&f){\n\t\t\tprintf(\""E\\n\"");\n\t\t}else if(n==m+1&&f){\n\t\t\tprintf(\""D\\n\"");\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,64,716 1510585628101591041,e43a6b275382d4de707ad9fe9a0c910690c66d7d8d6f9b28f68d2e75883214c5,2022-04-03 19:50:53,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1000005;\nint f[N];\nint d[N];\nint find(int x)\n{\n if(f[x]!=x)\n {\n f[x]=find(f[x]);\n }\n return f[x];\n}\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n\n\n\n for(int i=0;i>x>>y;\n f[find(f[x])]=find(f[y]);\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n }\n}\n",WRONG_ANSWER,200,4276 1510585712624660480,705f0d22cf86b5a3f1d2effa36be65eac3e06c910f0ff67f238142609a1d020a,2022-04-03 19:51:13,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main()\n{\n\tcout << \""E\"";\n cout << \""D\"";\n\treturn 0;\n } ",WRONG_ANSWER,8,448 1510585782795366400,f5f19fbe584bcae32491371ad126ba09612c3024585d256ccfb801cff88a95f4,2022-04-03 19:51:30,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \ntypedef long long ll;\nconst double PI = acos(-1.0);\nconst int inf = 10000000 + 10;\nconst int sz = 100010;\nconst int P = 10007;\nusing namespace std;\n#define ri register int\ninline void rd(int &x){\n\tchar c=getchar();bool f=0;x=0;\n\twhile(c>'9'||c<'0'){if(c=='-')f=1;c=getchar();}\n\twhile(c<='9'&&c>='0'){x=x*10+c-'0';c=getchar();}\n\tif(f) x*=-1;}\ninline void we(int x){\n\tif(x<0) putchar('-'),x*=-1;\n\tif(x/10) we(x/10);\n\tputchar(x%10+'0');}\ninline int gcd(int a,int b){while(b^=a^=b^=a%=b);return a;}\ninline int lcm(int a,int b){return a*b/gcd(a,b);}\nll pow(ll a,ll b){\n\tif(b==0) return 1;if(b==1) return a%P;\n\tll t=(b>>1);\n\tll x=pow(a,t);\n\tll ans=( (x%P)*(x%P) )%P;\n\t\tif(b&1) ans=( (ans%P)*(a%P) )%P;\n\treturn ans%P;}\nint fa[sz];\ninline int find(int x){return x==fa[x]?fa[x]:find(fa[x]);}\ninline void merge(int x,int y){int X=find(x),Y=find(y);if(X!=Y)fa[X]=Y;}\ninline void swap(int &a,int &b){int t=a;a=b,b=t;}\ninline int max(int a,int b){return a>b?a:b;}inline int min(int a,int b){return a>t;\nwhile(t--){\n//\twhile(~scanf(\""%d%d\"",&a,&b)){\n\tcin>>n>>m;\n\n\tfor(ri i=1;i<=m;++i)\n\t{\n\t\tcin>>t>>e;\n\t\tl[t].num++;\n\t\tl[e].num++;\n\t}\n\tif(n==1) {cout<<\""A\""<2) f=1;\n\t\tif(f==0) cout<<\""B\""<\n#define M 100005 \nusing namespace std;\nint t;\nint n,m;\nint ii,jj;\nint mapp[M];\nbool visit[M];\nint main(){\n\tscanf(\""%d\"",&t);\n\twhile(t--){\n\t\tbool f=0;\n\t\tscanf(\""%d %d\"",&n,&m);\n\t\tfor(int i=0;i2||mapp[jj]>2){\n\t\t\t\tf=1;\n\t\t\t}\n\t\t}\n\t\tif(n==1){\n\t\t\tprintf(\""A\\n\"");\n\t\t}else if(n==m+1&&!f){\n\t\t\tprintf(\""B\\n\"");\n\t\t}else if(n==m&&!f){\n\t\t\tprintf(\""C\\n\"");\n\t\t}else if(n<=m&&f){\n\t\t\tprintf(\""E\\n\"");\n\t\t}else if(n==m+1&&f){\n\t\t\tprintf(\""D\\n\"");\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,80,824 1510586059082559488,f79bfe33e7a57654a82d9827c3e8d05f63d3090c815baeb3672fd2c9e9d83900,2022-04-03 19:52:36,Python,0.0,1510521134800797706,1509437328199348224,582,x=input()\n\n,WRONG_ANSWER,29,3008 1510586095758827520,eec48ea930b7b6cec317284cc32e41ad075ec286675dd2adf6ced4a979d4274b,2022-04-03 19:52:45,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int h = 0; h < T; h++) {\n\t\tint m, n;\n\t\tcin >> n;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\""<> m;\n\t\t\tfor (int i = 0; i < m; i++) {\n\t\t\t\tint x, y;\n\t\t\t\tcin >> x >> y;\n\t\t\t\tshu[x]++;\n\t\t\t\tshu[y]++;\n\t\t\t}\n\t\t\tint n1 = 0;\n\t\t\tint n2 = 0;\n\t\t\tint nn = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (shu[i] == 1) {\n\t\t\t\t\tn1++;\n\t\t\t\t}\n\t\t\t\tif (shu[i] == 2) {\n\t\t\t\t\tn2++;\n\t\t\t\t}\n\t\t\t\tif (shu[i] == n - 1) {\n\t\t\t\t\tnn++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (n1 == 2 && n2 == n - 2) {\n\t\t\t\tcout << \""B\"" << endl;\n\t\t\t}\n\t\t\telse if (n2 == n) {\n\t\t\t\tcout << \""C\"" << endl;\n\t\t\t}\n\t\t\telse if (nn == n) {\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,18,4416 1510586240277766144,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 19:53:19,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n int n,m;\n cin>>n>>m;\n while(m--)\n {\n int a,b;\n cin>>a>>b;\n }\n if(n==1) cout<<\""A\""<\nusing namespace std;\n#define ll long long\nconst int maxn=1e5+10;\nconst int inf=0x3f3f3f3f;\n\n\nint main(){\n\tmap mp;\n\tint flag=0;\n\tint n,m,t;\n\tcin>>t;\n\twhile(t--){\n\t\tflag=0;\n\t\tmp.clear();\n\t\tcin>>n>>m;\n\t\tint a,b;\n\t\tfor(int i=0;i>a>>b;\n\t\t\tmp[a]++;\n\t\t\tmp[b]++;\n\t\t\tif(mp[a]>2||mp[b]>2)flag=1;\n\t\t}\n\t\tif(n==1) cout<<\""A\"";\n\t\telse if(n>2&&m==n) cout<<\""C\"";\n\t\telse if(n>3&&m==n*(n-1)/2) cout<<\""E\"";\n\t\telse{\t//判断树和链 \n\t\t\tif(n>1&&!flag) cout<<\""B\"";\n\t\t\tif(n>3&&flag)cout<<\""D\"";\n\t\t}\n\t\tcout<\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int h = 0; h < T; h++) {\n\t\tint m, n;\n\t\tcin >> n;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\""<> m;\n\t\t\tfor (int i = 0; i < m; i++) {\n\t\t\t\tint x, y;\n\t\t\t\tcin >> x >> y;\n\t\t\t\tshu[x]++;\n\t\t\t\tshu[y]++;\n\t\t\t}\n\t\t\tint n1 = 0;\n\t\t\tint n2 = 0;\n\t\t\tint nn = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (shu[i] == 1) {\n\t\t\t\t\tn1++;\n\t\t\t\t}\n\t\t\t\tif (shu[i] == 2) {\n\t\t\t\t\tn2++;\n\t\t\t\t}\n\t\t\t\tif (shu[i] == n - 1) {\n\t\t\t\t\tnn++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (n1 == 2 && n2 == n - 2) {\n\t\t\t\tcout << \""B\"" << endl;\n\t\t\t}\n\t\t\telse if (n2 == n) {\n\t\t\t\tcout << \""C\"" << endl;\n\t\t\t}\n\t\t\telse if (nn == n) {\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t\t\n\t}\n}",MULTIPLE_ERROR,8,624 1510586382429843456,3a2236b18297a6cd20e727de89fbb262db82578827b4cf92f23ae7acd4976769,2022-04-03 19:53:53,C++,25.0,1510521134800797706,1509437328199348224,582,"#include \n#define M 100005 \nusing namespace std;\nint t;\nint n,m;\nint ii,jj;\nint mapp[M];\nbool visit[M];\nint main(){\n\tscanf(\""%d\"",&t);\n\twhile(t--){\n\t\tfor(int i=0;i2||mapp[jj]>2){\n\t\t\t\tf=1;\n\t\t\t}\n\t\t}\n\t\tif(n==1){\n\t\t\tprintf(\""A\\n\"");\n\t\t}else if(n==m+1&&!f){\n\t\t\tprintf(\""B\\n\"");\n\t\t}else if(n==m&&!f){\n\t\t\tprintf(\""C\\n\"");\n\t\t}else if(n<=m&&f){\n\t\t\tprintf(\""E\\n\"");\n\t\t}else if(n==m+1&&f){\n\t\t\tprintf(\""D\\n\"");\n\t\t}\n\t\t\n\t}\n}",ACCEPTED,72,836 1510586401745887232,c06cf25eded01cd3f790834c74285be6c6110aa641ecfb9a234fb1bb2e50c8f8,2022-04-03 19:53:58,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N=1e6+10;\nint h[N],ne[N],e[N],idx;\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\nbool st[N];\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(st,0,sizeof st);\n\t\tmemset(h,-1,sizeof h);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tadd(a,b);\n\t\t\tst[b]=1;\n\t\t}\n\t\tif(n==1)cout<<\""A\""<3)cout<<\""E\""<2)cout<<\""C\""<\nusing namespace std;\ntypedef long long ll;\ntypedef pair PII;\nconst int N=1e6+5,INF=0x3f3f3f3f;\nint t,n,m;\nint h[N],e[N],ne[N],idx;\nint cnt[N];\nvoid add(int a,int b)\n{\n\te[idx]=b;\n\tne[idx]=h[a];\n\th[a]=idx++;\n}\nint fc[N];\nint main()\n{\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tmemset(cnt,0,sizeof cnt);\n\t\t//memset(f,-1,sizeof f);\n\t\tidx=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tadd(a,b),add(b,a);\n\t\t\tcnt[a]++,cnt[b]++;\n\t\t\tfc[b]++,fc[a]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<\nusing namespace std;\ntypedef long long ll;\ntypedef pair PII;\nconst int N=1e6+5,INF=0x3f3f3f3f;\nint t,n,m;\nint h[N],e[N],ne[N],idx;\nint cnt[N];\nvoid add(int a,int b)\n{\n\te[idx]=b;\n\tne[idx]=h[a];\n\th[a]=idx++;\n}\nint fc[N];\nint main()\n{\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tmemset(cnt,0,sizeof cnt);\n\t\t//memset(f,-1,sizeof f);\n\t\tidx=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tadd(a,b),add(b,a);\n\t\t\tcnt[a]++,cnt[b]++;\n\t\t\tfc[b]++,fc[a]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t}\n\tif ((n == 2 && m == 1) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tbool bo;\n\tfor (int i = 1; i <= n; i++) {\n\t\tbo = true;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1)bo = false;\n\t\t}\n\t\tif (bo) {\n\t\t\tint k = 0;\n\t\t\tfor (int j = 1; j < n + 1; j++) {\n\t\t\t\tif (arr[i][j])k++;\n\t\t\t}\n\t\t\tif (k == 1) {\n\t\t\t\tcout << \""B\"" << endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tbool flag = true;\n\tbool quan = true;\n\tfor (int i = 1; i <= n; i++) {\n\t\tint k = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[i][j]) {\n\t\t\t\tk++;\n\t\t\t}\n\t\t}\n\t\tif (k != n-1) {\n\t\t\tflag = false;\n\t\t}\n\t\tif (k != 2)quan = false;\n\t}\n\tif (quan) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (!flag)cout << \""D\"" << endl;\n\telse cout << \""E\"" << endl;\n}",WRONG_ANSWER,7,456 1510586694667689984,eec48ea930b7b6cec317284cc32e41ad075ec286675dd2adf6ced4a979d4274b,2022-04-03 19:55:08,C++,25.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int h = 0; h < T; h++) {\n\t\tint m, n;\n\t\tcin >> n>>m;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\""<> x >> y;\n\t\t\t\tshu[x]++;\n\t\t\t\tshu[y]++;\n\t\t\t}\n\t\t\tint n1 = 0;\n\t\t\tint n2 = 0;\n\t\t\tint nn = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (shu[i] == 1) {\n\t\t\t\t\tn1++;\n\t\t\t\t}\n\t\t\t\tif (shu[i] == 2) {\n\t\t\t\t\tn2++;\n\t\t\t\t}\n\t\t\t\tif (shu[i] == n - 1) {\n\t\t\t\t\tnn++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (n1 == 2 && n2 == n - 2) {\n\t\t\t\tcout << \""B\"" << endl;\n\t\t\t}\n\t\t\telse if (n2 == n) {\n\t\t\t\tcout << \""C\"" << endl;\n\t\t\t}\n\t\t\telse if (nn == n) {\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t\t\n\t}\n}",ACCEPTED,198,1476 1510586721670619136,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 19:55:14,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n int n,m;\n cin>>n>>m;\n while(m--)\n {\n int a,b;\n cin>>a>>b;\n }\n if(n==1) cout<<\""A\""<\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010];\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<\nusing namespace std;\nconst int N=1e6+4;\nvectore[N];\nint n,m;\n\nint main()\n{\n int we; cin>>we;\n while(we--)\n {\n cin>>n>>m;\n if(n==1)\n {cout<<'A'<<\""\\n\""; continue;}\n for(int i=1;i<=n;i++)e[i].clear();\n for(int i=0;i>a>>b;\n e[a].push_back(b); e[b].push_back(a); \n }\n \n bool full=0;\n if(n>3)full=1;\n if(full)\n for(int i=1;i<=n;i++)\n if(e[i].size()!=n-1){full=0; break;}\n if(full){cout<<'E'<<\""\\n\""; continue;}\n \n int single=0;\n for(int i=1;i<=n;i++)\n if(e[i].size()==1)single++;\n if(single>=3)cout<<'D'<<\""\\n\"";\n else if(single==2)cout<<'B'<<\""\\n\"";\n else if(!single)cout<<'C'<<\""\\n\"";\n \n \n }\n}",ACCEPTED,272,28600 1510587101305462784,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 19:56:44,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n int n,m;\n cin>>n>>m;\n for(int i = 0;i\nusing namespace std;\ntypedef long long ll;\ntypedef pair PII;\nconst int N=1e6+5,INF=0x3f3f3f3f;\nint t,n,m;\nint h[N],e[N],ne[N],idx;\nint cnt[N];\nvoid add(int a,int b)\n{\n\te[idx]=b;\n\tne[idx]=h[a];\n\th[a]=idx++;\n}\nint fc[N];\nint main()\n{\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tmemset(cnt,0,sizeof cnt);\n\t\t//memset(f,-1,sizeof f);\n\t\tidx=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tadd(a,b),add(b,a);\n\t\t\tcnt[a]++,cnt[b]++;\n\t\t\t//fc[b]++,fc[a]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<\nusing namespace std;\ntypedef long long ll;\ntypedef pair PII;\nconst int N=1e6+5,INF=0x3f3f3f3f;\nint t,n,m;\nint h[N],e[N],ne[N],idx;\nint cnt[N];\nvoid add(int a,int b)\n{\n\te[idx]=b;\n\tne[idx]=h[a];\n\th[a]=idx++;\n}\nint fc[N];\nint main()\n{\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tmemset(cnt,0,sizeof cnt);\n\t\t//memset(f,-1,sizeof f);\n\t\tidx=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tadd(a,b),add(b,a);\n\t\t\tcnt[a]++,cnt[b]++;\n\t\t\t//fc[b]++,fc[a]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<3&&E)\n\t\t{\n\t\t\tcout<<\""E\""<\nusing namespace std;\nlong long t;\nvectorp[1005000];\nint a[1005000];\nint main()\n{\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(a,0,sizeof(a));\n\t\tlong long n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\tint x,y;\n\t\tcin>>x>>y;\n\t\ta[x]++;\n\t\ta[y]++;\n\t\t}\n\t\tbool flag=0;\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(a[i]>2)\n\t\t\t{\n\t\t\t\tflag=1;\n\t\t\t}\n\t\t}\n\t\tint flag1=0;\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(a[i]==1)\n\t\t\t{\n\t\t\t\tflag1++;\n\t\t\t}\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<<\""\\n\"";\n\t\t\tcontinue;\n\t\t}\n\t\telse if(n==2)\n\t\t{\n\t\t\tcout<<'B'<<\""\\n\"";\n\t\t}\n\t\telse if(n>2)\n\t\t{\n\t\t\tif(m==n-1&&flag1!=2)//B或 D \n\t\t\t{\n\t\t\t\tcout<<'D'<<\""\\n\"";\n\t\t\t}\n\t\t\telse if(m==n-1&&flag1==2)\n\t\t\t{\n\t\t\t\tcout<<'B'<<\""\\n\"";\n\t\t\t}\n\t\t\telse if(m==n&&flag==0)\n\t\t\t{\n\t\t\t\tcout<<'C'<<\""\\n\"";\n\t\t\t}\n\t\t\telse if(m==n&&flag==1)\n\t\t\t{\n\t\t\t\tcout<<'E'<<\""\\n\"";\n\t\t\t}\n\t\t\telse if(m>n)\n\t\t\t{\n\t\t\t\tcout<<'E'<<\""\\n\"";\n\t\t\t}\n\t\t}\n\t}\n return 0;\n}",ACCEPTED,241,27972 1510587401708630016,8263288289d4c9e633a3aeb5026b1742b5c6243c52d21168e9a682b7700fa3c7,2022-04-03 19:57:56,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[10000];\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<\n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n int n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n cin>>a>>b;\n }\n if(n==1) cout<<\""A\""<\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t}\n\tif ((n == 2 && m == 1) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tint sum,num;\n\tbool ff = true;\n\tnum = 0;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[i][j] == 1) { \n\t\t\t\tnum++;\n\t\t\t\tsum++; }\n\t\t}\n\t\tif (sum > 1)ff = false;\n\t}\n\tif (num == n - 1 && ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tbool flag = true;\n\tbool quan = true;\n\tfor (int i = 1; i <= n; i++) {\n\t\tint k = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[i][j]) {\n\t\t\t\tk++;\n\t\t\t}\n\t\t}\n\t\tif (k != n-1) {\n\t\t\tflag = false;\n\t\t}\n\t\tif (k != 2)quan = false;\n\t}\n\tif (quan) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (!flag)cout << \""D\"" << endl;\n\telse cout << \""E\"" << endl;\n}",WRONG_ANSWER,7,472 1510587833348648960,c5ac2b8ea5388f1d21649ee6b998761be42ffed19cbdf6a199a56dafca66883a,2022-04-03 19:59:39,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n\n\nint main() {\n int t=0;\n cin>>t;\n char t1[t];\n if(t==1)\n {\n \tcout<<\""A\"";\n }\n \n \n \n \n \n\n \n \n \n\n\n\t\n}\n\t\n\n\t\n \n \t\n \n\t \n\t\n\t\n\t\n\n\n\n",WRONG_ANSWER,8,444 1510587835378692096,1a28a58367da9fd50ad3061a9cfb14c1c14608907febb8d15680988474ea83c5,2022-04-03 19:59:39,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint a[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n cin>>n>>m;\n if(n==1)\n {cout<<\""A\"";\n continue;\n }\n while(m--)\n {\n int i,j;\n cin>>i>>j;\n a[i]++;\n a[j]++;\n }\n int sum1=0;//xian\n int sum2=0;//huan\n int sum3=0;//shu\n int sum4=0;\n for(int i=1;i<=n;i++)\n {\n if(a[i]==2){\n sum2++;\n }\n if(a[i]==1)sum1++;\n if(a[i]==3)sum3++;\n if(a[i]==4)sum4++;\n }\n if(sum2==n)cout<<\""C\""<\nusing namespace std;\nconst int N=1e6+10;\nint a[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n cin>>n>>m;\n if(n==1)\n {cout<<\""A\"";\n continue;\n }\n while(m--)\n {\n int i,j;\n cin>>i>>j;\n a[i]++;\n a[j]++;\n }\n int sum1=0;//xian\n int sum2=0;//huan\n int sum3=0;//shu\n int sum4=0;\n for(int i=1;i<=n;i++)\n {\n if(a[i]==2){\n sum2++;\n }\n if(a[i]==1)sum1++;\n if(a[i]==3)sum3++;\n if(a[i]==4)sum4++;\n }\n if(sum2==n)cout<<\""C\""<\n#include \n#include \n#include\n#include\n#include\nusing namespace std;\nstruct edge {\n\tint i;\n\tint j;\n};\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int i = 0; i < T; i++) {\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (((n - 1) * 2) - 1 == m&&n>3) {\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse if (n > 1 && n + 1 == m) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse if (n > 2 && n == m) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \""D\"" << endl;\n\t\t}\n\t}\n\n}",WRONG_ANSWER,202,448 1510588014815211520,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 20:00:22,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n int a[100000]={0},b[1000]={0};\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<=sqrt(n)) cout<<\""D\"";\n else cout<<\""E\"";\n }\n \n \n \n}",WRONG_ANSWER,197,832 1510588066960072704,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 20:00:35,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n int n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n cin>>a>>b;\n }\n if(n==1) cout<<\""A\""<\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010];\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n int a[100000]={0},b[1000]={0};\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<=sqrt(n)) cout<<\""D\""<\nusing namespace std;\nint n;\nconst int N = 1e6 + 10;\nint a[N];\n//int e[N],ne[N],h[N],idx;\nint cnt[N];\nint p[N];\nbool find(int x)\n{\n if(p[x] != x) p[x] = find(p[x]);\n}\n//void add(int a,int b)\n//{\n// e[idx] = b,ne[idx] = h[a], h[a] = idx ++;\n//}\nchar solve()\n{\n\n memset(cnt,0 ,sizeof cnt);\n\n int n,m;\n cin >> n >> m;\n for (int i =1; i <= n ; i ++) p[i] = i;\n if (n == 1) return 'A'; \n if (n == m) return 'C';\n bool flag = false;\n while (m --)\n {\n int a, b;\n cin >> a >> b;\n// add(a, b);\n cnt[a] ++, cnt[b] ++;\n if(find(a) == find(b))\n {\n flag = 1;\n }\n p[find(a)] = find(b);\n\n }\n int ff1 = 0,ff2 = 0;\n \n for (int i = 1; i <= n - 1 ; i ++)\n {\n if(cnt[i] == 1) ff1 ++;\n if (cnt[i] == 2) ff2 ++;\n }\n if(ff1 == 2 && ff2 == n - 2) return 'B';\n if (flag) return 'D';\n return 'E';\n\n\n}\nint main ()\n{\n int T;\n cin >> T;\n while (T --)\n {\n cout << solve() << endl;\n }\n\n}",WRONG_ANSWER,116,4796 1510588448822091776,1a28a58367da9fd50ad3061a9cfb14c1c14608907febb8d15680988474ea83c5,2022-04-03 20:02:06,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint a[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n cin>>n>>m;\n if(n==1)\n {cout<<\""A\"";\n continue;\n }\n while(m--)\n {\n int i,j;\n cin>>i>>j;\n a[i]++;\n a[j]++;\n }\n int sum1=0;//xian\n int sum2=0;//huan\n int sum3=0;//shu\n int sum4=0;\n for(int i=1;i<=n;i++)\n {\n if(a[i]==2){\n sum2++;\n }\n if(a[i]==1)sum1++;\n if(a[i]==3)sum3++;\n if(a[i]==4)sum4++;\n }\n if(sum2==n)cout<<\""C\""<\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010];\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<=n){\n\t\t\t\tcout<<'D'<\nusing namespace std;\n\nint main()\n{\n\tcout<<\""A\"";\n}\n",WRONG_ANSWER,7,324 1510588646293389312,210d966c7cc6eda883f0ecf83f877b3b3b48f3e324dd4ce6c350bfe3e17e44d5,2022-04-03 20:02:53,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main()\n{\n\tcout<<\""B\"";\n}\n",WRONG_ANSWER,7,460 1510588665473941504,4d7ac4adf8fca7f84f99420f803aa7a7a62246711a70cc7b950aa5f0c0ce4273,2022-04-03 20:02:57,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n\n\nint main()\n{\n\tint t,n,m,p,q;\n\tcin>>t;\n\tcin>>n>>m;\n\tfor(int i=0;i>p>>q;\n\t}\n\tif(n==1) cout<<\""A\""<\n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nconst int N = 1e6 + 10;\nint st[N];\nint degree[N];\n//A:(n = 1)一个点。\n//B:(n > 1)一条链。\n//C:(n > 2)一个圈。\n//D:(n > 3)一棵树但不是一条链。\n//E:(n > 3)完全图。\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\twhile (T--)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1)cout << 'A' << endl;\n\t\telse if (n )\n\t\t{\n\t\t\tif(n == 2)puts(\""B\"");\n else if(n > 2 && n + 1 == m)puts(\""C\"");\n else if(n > 3)puts(\""E\"");\n else puts(\""D\"");\n\n\t\t}\n\t}\n}\n\n\n",WRONG_ANSWER,202,500 1510588846403633152,5fcdf37c98df44ecf444022f7b9ee6b9636687d9a60cf095ef664c71c39f0f74,2022-04-03 20:03:41,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main()\n{\n\tcout<<\""D\""<\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tint sum,num;\n\tbool ff = true;\n\tnum = 0;\n\tbool flag = true;\n\tbool quan = true;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[i][j] == 1) { \n\t\t\t\tnum++;\n\t\t\t\tsum++; }\n\t\t}\n\t\tif (sum > 1)ff = false;\n\t\tif (sum != 2)quan = false;\n\t\tif (sum != n - 1)flag = false;\n\t}\n\tif (num == n - 1 && ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (quan) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (!flag)cout << \""D\"" << endl;\n\telse cout << \""E\"" << endl;\n}",WRONG_ANSWER,7,460 1510588996974952448,8263288289d4c9e633a3aeb5026b1742b5c6243c52d21168e9a682b7700fa3c7,2022-04-03 20:04:16,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010]={0};\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n int a[100000]={0},b[1000]={0};\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<=sqrt(n)-1) cout<<\""D\""<\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010]={0};\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<=n){\n\t\t\t\tcout<<'D'<\nusing namespace std;\nint main()\n{\n\tint n;\n\tcin>>n;\n\tif(n==1)\n\t{\n\t\tcout<<\""A\""<\n#include \n#include \n#include\n#include\n#include\nusing namespace std;\nstruct edge {\n\tint i;\n\tint j;\n};\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int i = 0; i < T; i++) {\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if ((((n - 1) * n)/2 == m) && n>3) {\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse if (n > 1 && n + 1 == m) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse if (n > 2 && n == m) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \""D\"" << endl;\n\t\t}\n\t}\n\n}",WRONG_ANSWER,308,472 1510589135097032704,379cd087fd67d450b4f64e11856a5205da0d4420df5dffe780fc92e629cc0f4e,2022-04-03 20:04:49,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint n;\nconst int N = 1e6 + 10;\nint a[N];\n//int e[N],ne[N],h[N],idx;\nint cnt[N];\nint p[N];\nbool find(int x)\n{\n if(p[x] != x) p[x] = find(p[x]);\n}\n//void add(int a,int b)\n//{\n// e[idx] = b,ne[idx] = h[a], h[a] = idx ++;\n//}\nchar solve()\n{\n\n memset(cnt,0 ,sizeof cnt);\n\n int n,m;\n cin >> n >> m;\n for (int i =1; i <= n ; i ++) p[i] = i;\n if (n == 1) return 'A';\n if (n == m) return 'C';\n bool flag = false;\n while (m --)\n {\n int a, b;\n cin >> a >> b;\n// add(a, b);\n cnt[a] ++, cnt[b] ++;\n if(find(a) == find(b))\n {\n flag = 1;\n }\n p[find(a)] = find(b);\n\n }\n int ff1 = 0,ff2 = 0;\n\n for (int i = 1; i <= n ; i ++)\n {\n if(cnt[i] == 1) ff1 ++;\n if (cnt[i] == 2) ff2 ++;\n }\n// cout << ff1 <<\"" \"" <> T;\n while (T --)\n {\n cout << solve() << endl;\n }\n\n}",WRONG_ANSWER,113,4680 1510589136448143360,ffe115b35dddd386f46bef80246c2a0a2802b47f59fe19e7b951a9e92aac0414,2022-04-03 20:04:50,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N = 1000010;\nint sz[N];\nint main(){\n\tint t;cin>>t;\n\twhile(t--){\n\t\tmemset(sz,0,sizeof(sz));\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\twhile(m--){\n\t\t\tint i,j;cin>>i>>j;\n\t\t\tsz[i]++;\n\t\t\tsz[j]++;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<1){\n\t\t\tint dd = 2;\n\t\t\tbool pd = true;\n\t\t\tfor(int i=1;i<=n;i++){\n\t\t\t\tif(sz[i]==1){\n\t\t\t\t\tdd--;\n\t\t\t\t\tif(dd<0){\n\t\t\t\t\t\tpd = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse if(sz[i]==2){\n\t\t\t\t\t\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tpd = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(pd){\n\t\t\t\tcout<<\""B\""<2){\n\t\t\t\tbool pdC = true;\n\t\t\t\tfor(int i=1;i<=n;i++){\n\t\t\t\t\tif(sz[i]==2){\n\t\t\t\t\t\t\n\t\t\t\t\t}\n\t\t\t\t\telse{\n\t\t\t\t\t\tpdC = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(pdC){\n\t\t\t\t\tcout<<\""C\""<3){\n\t\t\t\t\tbool pdE = true;\n\t\t\t\t\tfor(int i=1;i<=n;i++){\n\t\t\t\t\t\tif(sz[i]==n-1){\n\t\t\t\t\t\t\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse{\n\t\t\t\t\t\t\tpdE = false;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif(pdE){\n\t\t\t\t\t\tcout<<\""E\""<\n#include\nusing namespace std;\nint main()\n{\n\tcout << \""D\"" << endl;\n\treturn 0;}",WRONG_ANSWER,8,324 1510589178638102528,981fcea4af5b388931133b5df074af3636635b2ab46b3668f45141b7faa52f82,2022-04-03 20:05:00,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nconst int N = 1e6 + 10;\nint st[N];\nint degree[N];\n//A:(n = 1)一个点。\n//B:(n > 1)一条链。\n//C:(n > 2)一个圈。\n//D:(n > 3)一棵树但不是一条链。\n//E:(n > 3)完全图。\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\twhile (T--)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1)cout << 'A' << endl;\n\t\telse if (n > 3 && (n - 1) * n == m)puts(\""E\"");\n\t\telse if(n > 3)puts(\""D\"");\n else if(n > 2 && n + 1 == m)puts(\""C\"");\n else puts(\""B\"");\n\t}\n}\n\n\n",WRONG_ANSWER,198,320 1510589212746727424,302676f1d93b0b9ea5341903f1122dd5351359f89da3895ad7f12ee42c7dc6cb,2022-04-03 20:05:08,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nint main()\n{\n\tcout << \""A\"" << endl;\n\treturn 0;}",WRONG_ANSWER,9,448 1510589244317253632,302676f1d93b0b9ea5341903f1122dd5351359f89da3895ad7f12ee42c7dc6cb,2022-04-03 20:05:15,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nint main()\n{\n\tcout << \""C\"" << endl;\n\treturn 0;}",WRONG_ANSWER,7,452 1510589286377734144,981fcea4af5b388931133b5df074af3636635b2ab46b3668f45141b7faa52f82,2022-04-03 20:05:25,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nconst int N = 1e6 + 10;\nint st[N];\nint degree[N];\n//A:(n = 1)一个点。\n//B:(n > 1)一条链。\n//C:(n > 2)一个圈。\n//D:(n > 3)一棵树但不是一条链。\n//E:(n > 3)完全图。\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\twhile (T--)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1)cout << 'A' << endl;\n\t\telse if (n > 3 && (n - 1) * n == m)puts(\""E\"");\n\t\telse if(n > 3 && n == m - 1)puts(\""D\"");\n else if(n > 2 && n + 1 == m)puts(\""C\"");\n else puts(\""B\"");\n\t}\n}\n\n\n",WRONG_ANSWER,194,456 1510589328630607872,379cd087fd67d450b4f64e11856a5205da0d4420df5dffe780fc92e629cc0f4e,2022-04-03 20:05:35,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint n;\nconst int N = 1e6 + 10;\nint a[N];\n//int e[N],ne[N],h[N],idx;\nint cnt[N];\nint p[N];\nbool find(int x)\n{\n if(p[x] != x) p[x] = find(p[x]);\n return p[x];\n}\n//void add(int a,int b)\n//{\n// e[idx] = b,ne[idx] = h[a], h[a] = idx ++;\n//}\nchar solve()\n{\n\n memset(cnt,0 ,sizeof cnt);\n\n int n,m;\n cin >> n >> m;\n for (int i =1; i <= n ; i ++) p[i] = i;\n if (n == 1) return 'A';\n if (n == m) return 'C';\n bool flag = false;\n while (m --)\n {\n int a, b;\n cin >> a >> b;\n// add(a, b);\n cnt[a] ++, cnt[b] ++;\n if(find(a) == find(b))\n {\n flag = 1;\n }\n p[find(a)] = find(b);\n\n }\n int ff1 = 0,ff2 = 0;\n\n for (int i = 1; i <= n ; i ++)\n {\n if(cnt[i] == 1) ff1 ++;\n if (cnt[i] == 2) ff2 ++;\n }\n// cout << ff1 <<\"" \"" <> T;\n while (T --)\n {\n cout << solve() << endl;\n }\n\n}",WRONG_ANSWER,122,4704 1510589478925647872,302676f1d93b0b9ea5341903f1122dd5351359f89da3895ad7f12ee42c7dc6cb,2022-04-03 20:06:11,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nint main()\n{\n\tcout << \""E\"" << endl;\n\treturn 0;}",WRONG_ANSWER,7,616 1510589778370322432,dfec8198309c1c9fbbf22492bcb1fb30935dbe0905a50669c485c6f9402910e1,2022-04-03 20:07:23,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N = 1e6+10;\nint t;\nint cnt[N];\nint n,m;\n\nint main()\n{\n\tcin>>t;\n\twhile (t--)\n\t{\n\t\tcin>>n>>m;\n\t\tif (n == 1)\n\t\t{\n\t\t\tfor (int i=0; i>a>>b;\n\t\t\t}\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\t\tcnt[a]++;\n\t\t\t\tcnt[b]++;\n\t\t\t}\n\t\t\tlong long ma=n*(n-1)/2;\n\t\t\tif (n == 2)\n\t\t\t{\n\t\t\t\tcout<<\""C\""<= 3)\n\t\t\t\t{\n\t\t\t\t\tf=3;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif (cnt[i] == 1)\n\t\t\t\t{\n\t\t\t\t\tcnt1++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (f == 3)\n\t\t\t{\n\t\t\t\tcout<<\""D\""< 2) f=3;\n\t\t\telse if (cnt1 == 0) f=2;\n\t\t\tif (f == 3) cout<<\""D\""<\n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nconst int N = 1e6 + 10;\nint st[N];\nint degree[N];\n//A:(n = 1)一个点。\n//B:(n > 1)一条链。\n//C:(n > 2)一个圈。\n//D:(n > 3)一棵树但不是一条链。\n//E:(n > 3)完全图。\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\twhile (T--)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1)cout << 'A' << endl;\n\t\telse if (n > 3 && (n - 1) * n == m)puts(\""E\"");\n\t\telse if (n > 3 && n == m + 1)puts(\""D\"");\n\t\telse if (n > 2 && n + 1 == m)puts(\""C\"");\n\t\telse puts(\""B\"");\n\t}\n}\n\n\n",WRONG_ANSWER,192,476 1510589931335315456,a691f6a06fa04e55abc32f49dec60bfae3321c72fb5c31593e614307af37dab3,2022-04-03 20:07:59,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include\n#include\n#include\nusing namespace std;\nstruct edge {\n\tint i;\n\tint j;\n};\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int i = 0; i < T; i++) {\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if ((((n - 1) * n)/2 == m) && n>3) {\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse if (n > 1 && n - 1 == m) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse if (n > 2 && n == m) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \""D\"" << endl;\n\t\t}\n\t}\n\n}",WRONG_ANSWER,198,452 1510589988550361088,d15c4f44862d36f832c9dba6eeb6df8bebf72f46f794e024fed3f4e11c03324f,2022-04-03 20:08:13,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() \n{\n\tint t;\n\tcin >> t;\n\tint n, m;\n\tcin >> n >> m;\n\tint** a = new int*[n + 1];\n\tfor (int i = 0; i < n+1; i++) {\n\t\ta[i] = new int[n + 1];\n\t}\n\tfor (int i = 0; i < n + 1; i++) {\n\t\tfor (int j = 0; j < n + 1; j++) {\n\t\t\ta[i][j] = 0;\n\t\t}\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\ta[x][y] = 1;\n\t\ta[y][x] = 1;\n\t}\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t}\n\telse\n\t{\n\t\tcout << \""B\"" << endl;\n\t}\n}",WRONG_ANSWER,8,600 1510590053037785088,8263288289d4c9e633a3aeb5026b1742b5c6243c52d21168e9a682b7700fa3c7,2022-04-03 20:08:28,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010]={0};\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<=n){\n\t\t\t\tcout<<'D'<\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() \n{\n\tint t;\n\tcin >> t;\n\tint n, m;\n\tcin >> n >> m;\n\tint** a = new int*[n + 1];\n\tfor (int i = 0; i < n+1; i++) {\n\t\ta[i] = new int[n + 1];\n\t}\n\tfor (int i = 0; i < n + 1; i++) {\n\t\tfor (int j = 0; j < n + 1; j++) {\n\t\t\ta[i][j] = 0;\n\t\t}\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\ta[x][y] = 1;\n\t\ta[y][x] = 1;\n\t}\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t}\n\telse\n\t{\n\t\tcout << \""C\"" << endl;\n\t}\n}",WRONG_ANSWER,8,320 1510590157761167360,d15c4f44862d36f832c9dba6eeb6df8bebf72f46f794e024fed3f4e11c03324f,2022-04-03 20:08:53,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() \n{\n\tint t;\n\tcin >> t;\n\tint n, m;\n\tcin >> n >> m;\n\tint** a = new int*[n + 1];\n\tfor (int i = 0; i < n+1; i++) {\n\t\ta[i] = new int[n + 1];\n\t}\n\tfor (int i = 0; i < n + 1; i++) {\n\t\tfor (int j = 0; j < n + 1; j++) {\n\t\t\ta[i][j] = 0;\n\t\t}\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\ta[x][y] = 1;\n\t\ta[y][x] = 1;\n\t}\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t}\n\telse\n\t{\n\t\tcout << \""D\"" << endl;\n\t}\n}",WRONG_ANSWER,7,332 1510590207534428160,dfec8198309c1c9fbbf22492bcb1fb30935dbe0905a50669c485c6f9402910e1,2022-04-03 20:09:05,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N = 1e6+10;\nint t;\nint cnt[N];\nint n,m;\n\nint main()\n{\n\tcin>>t;\n\twhile (t--)\n\t{\n\t\tcin>>n>>m;\n\t\tif (n == 1)\n\t\t{\n\t\t\tfor (int i=0; i>a>>b;\n\t\t\t}\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\t\tcnt[a]++;\n\t\t\t\tcnt[b]++;\n\t\t\t}\n\t\t\tlong long ma=n*(n-1)/2;\n\t\t\tif (n == 2)\n\t\t\t{\n\t\t\t\tcout<<\""C\""<= 3)\n\t\t\t\t{\n\t\t\t\t\tf=3;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif (cnt[i] == 1)\n\t\t\t\t{\n\t\t\t\t\tcnt1++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (f == 3)\n\t\t\t{\n\t\t\t\tcout<<\""D\""< 2) f=3;\n\t\t\telse if (cnt1 == 0) f=2;\n\t\t\tif (f == 3) cout<<\""D\""<\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() \n{\n\tint t;\n\tcin >> t;\n\tint n, m;\n\tcin >> n >> m;\n\tint** a = new int*[n + 1];\n\tfor (int i = 0; i < n+1; i++) {\n\t\ta[i] = new int[n + 1];\n\t}\n\tfor (int i = 0; i < n + 1; i++) {\n\t\tfor (int j = 0; j < n + 1; j++) {\n\t\t\ta[i][j] = 0;\n\t\t}\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\ta[x][y] = 1;\n\t\ta[y][x] = 1;\n\t}\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t}\n\telse\n\t{\n\t\tcout << \""E\"" << endl;\n\t}\n}",WRONG_ANSWER,8,460 1510590501773242368,dfec8198309c1c9fbbf22492bcb1fb30935dbe0905a50669c485c6f9402910e1,2022-04-03 20:10:15,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N = 1e6+10;\nint t;\nint cnt[N];\nint n,m;\n\nint main()\n{\n\tcin>>t;\n\twhile (t--)\n\t{\n\t\tcin>>n>>m;\n\t\tif (n == 1)\n\t\t{\n\t\t\tfor (int i=0; i>a>>b;\n\t\t\t}\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\t\tcnt[a]++;\n\t\t\t\tcnt[b]++;\n\t\t\t}\n\t\t\tlong long ma=n*(n-1)/2;\n\t\t\tif (n == 2)\n\t\t\t{\n\t\t\t\tcout<<\""C\""<= 3)\n\t\t\t\t{\n\t\t\t\t\tf=3;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif (cnt[i] == 1)\n\t\t\t\t{\n\t\t\t\t\tcnt1++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (f == 3)\n\t\t\t{\n\t\t\t\tcout<<\""D\""< 2) f=3;\n\t\t\telse if (cnt1 == 0) f=2;\n\t\t\tif (f == 3) cout<<\""D\""<\n#include\n#include\nusing namespace std;\n/* run this program using the console pauser or add your own getch, system(\""pause\"") or input loop */\n\nint main(int argc, char** argv) {\n\t/*int n1;\n\tcin>>n1;\n\tstring aa[16];\n\tstring aa1[16];\n\tint bb[n1];\n\tint cc[10000];\n\tfor(int i=0;i>bb[i];\n\t\tcc[bb[i]]++;\n\t}\n\tfor(int i=0;i<16;i++)\n\t{\n\t\tgetline(cin,aa1[i]);\n\t}\n\tint temp=0;\n\tint max=0;\n\tfor(int i=0;i<10000;i++)\n\t{\n\t\tif(cc[i]>max)\n\t\t{\n\t\t\t\n\t\t\ttemp=i;\n\t\t}\n\t}\n\tcout<>t;\n\tint n,m;\n\tcin>>n>>m;\n\tint aa[m][2];\n\t\n\tfor(int i=0;i>aa[j][k];\n\t\t\t}\n\t\t}\n\t}\n\tcout<<\""D\""<\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() \n{\n\tint t;\n\tcin >> t;\n\tfor (int i = 0; i < t; i++) {\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tint** a = new int* [n + 1];\n\t\tfor (int i = 0; i < n + 1; i++) {\n\t\t\ta[i] = new int[n + 1];\n\t\t}\n\t\tfor (int i = 0; i < n + 1; i++) {\n\t\t\tfor (int j = 0; j < n + 1; j++) {\n\t\t\t\ta[i][j] = 0;\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\ta[x][y] = 1;\n\t\t\ta[y][x] = 1;\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t}\n\t\n}",MULTIPLE_ERROR,122,131072 1510590627238002688,97ea9a48cdc0383c90869ad787023a657383a0d9beec07d2471fce6407b4306d,2022-04-03 20:10:45,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\n/* run this program using the console pauser or add your own getch, system(\""pause\"") or input loop */\n\nint main(int argc, char** argv) {\n\t/*int n1;\n\tcin>>n1;\n\tstring aa[16];\n\tstring aa1[16];\n\tint bb[n1];\n\tint cc[10000];\n\tfor(int i=0;i>bb[i];\n\t\tcc[bb[i]]++;\n\t}\n\tfor(int i=0;i<16;i++)\n\t{\n\t\tgetline(cin,aa1[i]);\n\t}\n\tint temp=0;\n\tint max=0;\n\tfor(int i=0;i<10000;i++)\n\t{\n\t\tif(cc[i]>max)\n\t\t{\n\t\t\t\n\t\t\ttemp=i;\n\t\t}\n\t}\n\tcout<>t;\n\tint n,m;\n\tcin>>n>>m;\n\tint aa[m][2];\n\t\n\tfor(int i=0;i>aa[j][k];\n\t\t\t}\n\t\t}\n\t}\n\tcout<<\""D\""<\n#include\nusing namespace std;\nconst int N = 1e6+10;\nint t;\nint cnt[N];\nint n,m;\n\nint main()\n{\n\tcin>>t;\n\twhile (t--)\n\t{\n\t\tcin>>n>>m;\n\t\tif (n == 1)\n\t\t{\n\t\t\tfor (int i=0; i>a>>b;\n\t\t\t}\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\t\tcnt[a]++;\n\t\t\t\tcnt[b]++;\n\t\t\t}\n\t\t\tlong long ma=n*(n-1)/2;\n\t\t\tif (n == 2 || n == (m-1))\n\t\t\t{\n\t\t\t\tcout<<\""B\""<= 3)\n\t\t\t\t{\n\t\t\t\t\tf=3;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif (cnt[i] == 1)\n\t\t\t\t{\n\t\t\t\t\tcnt1++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (f == 3)\n\t\t\t{\n\t\t\t\tcout<<\""D\""< 2) f=3;\n\t\t\telse if (cnt1 == 0) f=2;\n\t\t\tif (f == 3) cout<<\""D\""<\nusing namespace std;\nint main(){\n cout<<\""A\"";\n}",WRONG_ANSWER,9,448 1510590731281907712,8263288289d4c9e633a3aeb5026b1742b5c6243c52d21168e9a682b7700fa3c7,2022-04-03 20:11:10,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint n,m,t;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010]={0};\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<=n){\n\t\t\t\tcout<<'D'<\nusing namespace std;\nconst int N=1e6+10;\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n for(int i=1;i<=m;i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n \n d[a]++,d[b]++;\n if(d[a]>=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<\""A\""<\n#include\n#include\nusing namespace std;\nint main() {\n\tint t; cin >> t;\n\tint m, n; cin >> m >> n;\n\tif (m == n)cout << \""A\"";\n}",WRONG_ANSWER,8,464 1510591343021875200,dfec8198309c1c9fbbf22492bcb1fb30935dbe0905a50669c485c6f9402910e1,2022-04-03 20:13:36,C++,25.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N = 1e6+10;\nint t;\nint cnt[N];\nint n,m;\n\nint main()\n{\n\tcin>>t;\n\twhile (t--)\n\t{\n\t\tcin>>n>>m;\n\t\tif (n == 1)\n\t\t{\n\t\t\tfor (int i=0; i>a>>b;\n\t\t\t}\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\t\tcnt[a]++;\n\t\t\t\tcnt[b]++;\n\t\t\t}\n\t\t\tlong long ma=n*(n-1)/2;\n\t\t\tif (n == 2)\n\t\t\t{\n\t\t\t\tcout<<\""B\""< 3)\n\t\t\t{\n\t\t\t\tcout<<\""E\""<= 3)\n\t\t\t\t{\n\t\t\t\t\tf=3;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif (cnt[i] == 1)\n\t\t\t\t{\n\t\t\t\t\tcnt1++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (f == 3)\n\t\t\t{\n\t\t\t\tcout<<\""D\""< 2) f=3;\n\t\t\telse if (cnt1 == 0) f=2;\n\t\t\tif (f == 3) cout<<\""D\""<\n#include\n#include\n\nusing namespace std;\n\nint main(){\n/*\tchar key[14][100]={\""DaDan\"",\""HuJia\"",\""GuaA\"",\""I'm speechless Maybe double kill\"",\""100% winning rate, playing wild without rules\"",\n\t \""Dragonfly skimming the water\"",\""Don't break my 1-game winning streak\"",\""I even want to fight back\"",\n\t\t \""It's not without experts\"",\""HuLuGay\"",\""I really can't stand it\"",\""JiXianLa\"",\""Crab step\"",\""Real c\""};\n\tint N;\n\tcin>>N;\n\tfor(int i=0;i<14;i++)\n\t cout<\n#include\n#include\n#include\nusing namespace std; \nint main()\n{\n\tint n;\n\tcin>>n;\n if(n==1)\n cout<<\""A\""<\n#include\n#include\n#include\nusing namespace std; \nint main()\n{\n\tint n;\n\tcin>>n;\n if(n==1)\n cout<<\""A\""<\n\nusing namespace std;\ntypedef pair PII;\nconst int N = 1e6+10;\n\nint d[N],c[N];\nint e[N],h[N],ne[N],idx;\nint n,m;\n\nvoid add(int a,int b)\n{\n\te[idx] = b;\n\tne[idx] = h[a];\n\th[a] = idx++;\n}\n\nbool dfs()\n{\n\tfor(int j=h[1];j!=-1;j=ne[j])\n\t{\n\t\t\tint k=e[j];\n\t\t\tif(k == 1){\n\t\t\t\treturn false ;\n\t\t\t}\n\t}\n\treturn true;\n}\n\nint main()\n{\n\t//#define Dubug\n\t#ifdef Dubug\n\tfreopen(\""in.txt\"",\""r\"",stdin);\n\t#endif\n\t\n\t\n\tint t;\n\tcin>>t;\n\t\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\td[b]++;\n\t\t\tif(d[b]>1){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tc[a]++;\n\t\t\tif(c[a] > 1){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tadd(a,b);\n\t\t\t//add(b,a);\n\t\t}\n\t\tif(st== false){\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(d[i] == 0){\n\t\t\t\tcout<<\""B\""<\n#include\n#include\nusing namespace std;\nint main() {\n\tint t; cin >> t;\n\tint m, n; cin >> m >> n;\n\twhile(t--){\n cout<<\""A\""<\nusing namespace std;\n#define A 1000000\nint main(){\n\tint T;\n\tcin>>T;\n\tfor(int i=0;i>n>>m;\n\t\tfor(int j=0;j>q[j]>>w[j];\n\t\t}\n\t\tswitch(n){\n\t\t\n\t\tcase 1: cout<<\""A\""<\n#include\n#include\n#include\nusing namespace std; \nint main()\n{\n\t\n\t\tcout<<\""D\""<\n\nusing namespace std;\ntypedef pair PII;\nconst int N = 1e6+10;\n\nint d[N],c[N];\nint e[N],h[N],ne[N],idx;\nint n,m;\n\nvoid add(int a,int b)\n{\n\te[idx] = b;\n\tne[idx] = h[a];\n\th[a] = idx++;\n}\n\nbool dfs()\n{\n\tfor(int i=1;i<=1;i++)\n\t{\n\t\tfor(int j=h[i];j!=-1;j=ne[j])\n\t\t{\n\t\t\tint k=e[j];\n\t\t\tif(k == i){\n\t\t\t\treturn false ;\n\t\t\t}\n\t\t}\n\t}\n\treturn true;\n}\n\nint main()\n{\n\n\t\n\t\n\tint t;\n\tcin>>t;\n\t\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\td[b]++;\n\t\t\tif(d[b]>1){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tc[a]++;\n\t\t\tif(c[a] > 1){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tadd(a,b);\n\t\t\tadd(b,a);\n\t\t}\n\t\tif(st== false){\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(d[i] == 0){\n\t\t\t\tcout<<\""B\""<\n#include\n#include\n#include\nusing namespace std; \nint main()\n{\n\t\n\t\tcout<<\""C\""<\n#include\n#include\n#include\nusing namespace std; \nint main()\n{\n\t\n\t\tcout<<\""E\""<\n#include\n#include\n#include\nusing namespace std; \nint main()\n{\n\t\n\t\tcout<<\""B\""<\n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nconst int N = 1e6 + 10;\nint st[N];\nint degree[N];\n//A:(n = 1)一个点。\n//B:(n > 1)一条链。\n//C:(n > 2)一个圈。\n//D:(n > 3)一棵树但不是一条链。\n//E:(n > 3)完全图。\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\twhile (T--)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tmemset(degree, 0, sizeof(int) * (n + 5));\n\t\tint is_list = true;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t}\n\t\tint cnt = 0;\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif(degree[i])cnt++;\n\t\t\tif (degree[i] > 2)\n\t\t\t{\n\t\t\t\tis_list = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (n == 1)cout << 'A' << endl;\n\t\telse if (n > 1 && is_list)puts(\""B\"");\n\t\telse if (n > 2 && n + 1 == m)puts(\""C\"");\n\t\telse if (n > 3 && (n - 1) * n / 2 == m)puts(\""E\"");\n\t\telse puts(\""D\"");\n\t}\n}\n\n\n",WRONG_ANSWER,203,836 1510592230602436608,7ccf23ee3266f9b786815ca430f53f9680449726d22de0aaa1be8ab1c3e24c19,2022-04-03 20:17:07,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include \n#include\n#include\n#include\n#include\nusing namespace std;\n\nint main()\n{ \n\tint t;\n\tcin >> t;\n\tint n, m;\n\tcin >> n >> m;\n\tif (n == 1)\n\t\tcout << \""A\"" << endl;\n\telse\n\t{\n\n\t}\n\treturn 0;\n}\n\n",WRONG_ANSWER,7,456 1510592742236766208,02d3e37513bd79df8bf329f2fc11a150d2e5cadd69331325bd3fa42def0037fa,2022-04-03 20:19:09,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tint sum,num,qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum==1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tsum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum!=n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1&&av[i]==0) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) { ff = false;\n\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum==n&&ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tnum = 0;\n\tbool flag = true;\n\tbool quan = true;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[i][j] == 1) { \n\t\t\t\tnum++;\n\t\t\t\tsum++; }\n\t\t}\n\t\tif (sum != 2)quan = false;\n\t\tif (sum != n - 1)flag = false;\n\t}\n\tif (num == n - 1 && ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (quan) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (!flag)cout << \""D\"" << endl;\n\telse cout << \""E\"" << endl;\n}",WRONG_ANSWER,7,456 1510592804493549568,fbb2f0c603242b0fd46bf10128c91f572cbd038ef9f8aa5e3aa5bc99ae9cc89e,2022-04-03 20:19:24,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<\""A\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n int a[100000]={0},b[1000]={0};\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<=sqrt(n)-2) cout<<\""D\""<\nusing namespace std;\n\nint main() \n{\n\tint t;\n\tcin>>t;\n\tfor(int i=1;i<=t;i++)\n\t{\n\t\t\n\t\tint n;\n\t\tint m;\n\t\tcin>>n>>m;\n\t\tvector vec[n];\n\t\tfor(int j=1;j<=m;j++)\n\t\t{\n\t\t\tint x,y;\n\t\t\tcin>>x>>y;\n\t\t\tvec[x].push_back(y);\n\t\t\tvec[y].push_back(x);\t\n\t\t}\n\t\tif(n==1) cout<<\""A\""<2)\n\t\t\t{\n\t\t\t\n\t\t\t\tif(n>3)\n\t\t\t\t{\n\t\t\t\t\t//if(m==n-1) cout<<\""B\""<\nusing namespace std;\nconst int N=1e6+10;\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n for(int i=1;i<=m;i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n \n d[a]++,d[b]++;\n if(d[a]>=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<\""A\""<\n#include \nusing namespace std;\nint main()\n{\n int t;cin>>t;\n int n,m,_a,_b;\n for(int i=0;i>n>>m;\n if(n==1)cout<<\""A\""<\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=110;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n\t\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\"";\n\t\telse\n\t\t{\n\t\t\tfor(int i=1;i<=n;i++)\n\t\t\t{\n\t\t\t\tdfs(i,-1,i);\n\t\t\t\tif(flag)break;\n\t\t\t}\n\t\t\tif(flag)\n\t\t\t{\n\t\t\t\tif(n==m)\n\t\t\t\tcout<<\""C\""<\n\nusing namespace std;\n\nint main()\n{\n int t,n,m;\n cin>>t>>n>>m;\n if(t==1&&n==1) cout<<\""A\"";\n return 0;\n}",WRONG_ANSWER,9,452 1510593090111795200,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 20:20:32,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=110;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n\t\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\"";\n\t\telse\n\t\t{\n\t\t\tfor(int i=1;i<=n;i++)\n\t\t\t{\n\t\t\t\tdfs(i,-1,i);\n\t\t\t\tif(flag)break;\n\t\t\t}\n\t\t\tif(flag)\n\t\t\t{\n\t\t\t\tif(n==m)\n\t\t\t\tcout<<\""C\"";\n\t\t\t\telse\n\t\t\t\tcout<<\""E\"";\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif(maxd<=2)\n\t\t\t\tcout<<\""B\"";\n\t\t\t\telse\n\t\t\t\tcout<<\""D\"";\n\t\t\t}\n\t\t}\n\t}\n}",MULTIPLE_ERROR,8,572 1510593177216180224,981fcea4af5b388931133b5df074af3636635b2ab46b3668f45141b7faa52f82,2022-04-03 20:20:53,C++,25.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nconst int N = 1e6 + 10;\nint st[N];\nint degree[N];\n//A:(n = 1)一个点。\n//B:(n > 1)一条链。\n//C:(n > 2)一个圈。\n//D:(n > 3)一棵树但不是一条链。\n//E:(n > 3)完全图。\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\twhile (T--)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tmemset(degree, 0, sizeof(int) * (n + 5));\n\t\tint is_list = true;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t}\n\t\tint cnt = 0;\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif(degree[i])cnt++;\n\t\t\tif (degree[i] > 2)\n\t\t\t{\n\t\t\t\tis_list = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (n == 1)cout << 'A' << endl;\n\t\telse if (n > 1 && is_list && m < n )puts(\""B\"");\n\t\telse if (n > 2 && n == m)puts(\""C\"");\n\t\telse if (n > 3 && (n - 1) * n / 2 == m)puts(\""E\"");\n\t\telse puts(\""D\"");\n\t}\n}\n\n\n",ACCEPTED,197,704 1510593180171890688,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 20:20:54,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=110;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n\t\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\""<\ntypedef long long ll;\nconst double PI = acos(-1.0);\nconst int inf = 10000000 + 10;\nconst int sz = 100010;\nconst int P = 10007;\nusing namespace std;\n#define ri register int\ninline void rd(int &x){\n\tchar c=getchar();bool f=0;x=0;\n\twhile(c>'9'||c<'0'){if(c=='-')f=1;c=getchar();}\n\twhile(c<='9'&&c>='0'){x=x*10+c-'0';c=getchar();}\n\tif(f) x*=-1;}\ninline void we(int x){\n\tif(x<0) putchar('-'),x*=-1;\n\tif(x/10) we(x/10);\n\tputchar(x%10+'0');}\ninline int gcd(int a,int b){while(b^=a^=b^=a%=b);return a;}\ninline int lcm(int a,int b){return a*b/gcd(a,b);}\nll pow(ll a,ll b){\n\tif(b==0) return 1;if(b==1) return a%P;\n\tll t=(b>>1);\n\tll x=pow(a,t);\n\tll ans=( (x%P)*(x%P) )%P;\n\t\tif(b&1) ans=( (ans%P)*(a%P) )%P;\n\treturn ans%P;}\nint fa[sz];\ninline int find(int x){return x==fa[x]?fa[x]:find(fa[x]);}\ninline void merge(int x,int y){int X=find(x),Y=find(y);if(X!=Y)fa[X]=Y;}\ninline void swap(int &a,int &b){int t=a;a=b,b=t;}\ninline int max(int a,int b){return a>b?a:b;}inline int min(int a,int b){return a\nusing namespace std;\nconst int N=1e6+10;\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<'A'<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int N = 100;\nbool vis[N] = {false};\n//vector graph[N];\nint graph[N][N];\nint a, b;\nbool f = false;\nint dfs(int nowVisit,int t)\n{\n\tvis[nowVisit] = true; //标记,已经访问\n\tfor (int i = 1; i <= a; i++)\n\t{\t//依次遍历nowVisit的相邻顶点,从小到大\n\t //顶点i未访问 && graph[nowVisit][i]=1存在边\n\t\tif (i == t&&f)\n\t\t\treturn 1;\n\t\telse if (!vis[i] && graph[nowVisit][i])\n\t\t{\n\t\t\tdfs(i,t);\n\t\t\tf = true;\n\t\t}\n\t}\n}\nint circle()\n{\n\tfor (int i = 1; i <= a; i++)\n\t{\n\t\tint m = i;\n\t\tint t= dfs(i,m);\n\t\tf = false;\n\t\tif (t == 1)\n\t\t\treturn 1;\n\t\telse\n\t\t\treturn 0;\n\n\n\t}\n\t\n\n}\nint main()\n{\n\tint x;\n\tcin >> x; //x组数据\n\tfor (int i = 0; i < x; i++)\n\t{\n\t\t\n\t\tcin >> a >> b; //点数,边数\n\t\t\n\t\tfor (int i = 1; i <= a; i++)\n\t\t\tfor (int j = 1; j <= a; j++)\n\t\t\t\tgraph[i][j] = 0;\n\t\tfor (int j = 0; j < b; j++)\n\t\t{\n\t\t\tint m, n;\n\t\t\tcin >> m >> n;\n\t\t\tgraph[m][n] = 1;\n\t\t\tgraph[n][m] = 1;\n\t\t}\n\t\tif (a == 1)\n\t\t\tcout << \""A\"";\n\t\telse if (a == b + 1)\n\t\t\tcout << \""B\"";\n\t\telse if (a*(a - 1) / 2 == b)\n\t\t\tcout << \""E\"";\n\t\telse if (circle() == 1)\n\t\t\tcout << \""C\"";\n\t\telse\n\t\t\tcout << \""D\"";\n\n\t}\n}",MULTIPLE_ERROR,8,452 1510593483840774144,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 20:22:06,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=1000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\""<\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=10000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\""<\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tint sum,num,qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum==1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tsum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum!=n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1&&av[i]!=1) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) { ff = false;\n\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum==n&&ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tnum = 0;\n\tbool flag = true;\n\tbool quan = true;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[i][j] == 1) { \n\t\t\t\tnum++;\n\t\t\t\tsum++; }\n\t\t}\n\t\tif (sum != 2)quan = false;\n\t\tif (sum != n - 1)flag = false;\n\t}\n\tif (num == n - 1 && ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (quan) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (!flag)cout << \""D\"" << endl;\n\telse cout << \""E\"" << endl;\n}",WRONG_ANSWER,7,452 1510593564953145344,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 20:22:26,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\""<\nusing namespace std;\nconst int N=1e6+10;\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<'A'<\nusing namespace std;\nint main(void)\n{\n\tint t;cin>>t;\n\tfor(int i=1;i<=t;i++)\n\t{\n\t\tlong long n,m,sum,a,b;\n\t\tsum=0;\n\t\tcin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\"";\n\t\t\treturn 0;\n\t\t}\n\t\tif(m==n-1)\n\t\t{\n\t\t\tfor(int j=1;j<=m;j++)\n\t\t\t{\n\t\t\t\tcin>>a>>b;\n\t\t\t\tif(a-b==1||a-b==-1)\n\t\t\t\t\tsum++;\n\t\t\t}\n\t\t\tsum=0;\n\t\t\tif(sum==m)\n\t\t\t{\n\t\t\t\tcout<<\""B\"";\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse\n\t\t\t\tcout<<\""D\"";\n\t\t\treturn 0;\n\t\t}\n\t\tif(m==n)\n\t\t{\n\t\t\tfor(int j=1;j<=m;j++)\n\t\t\t{\n\t\t\t\tcin>>a>>b;\n\t\t\t\tif(a-b==1||a-b==-1||a-b==n-1||a-b==1-n)\n\t\t\t\t\tsum++;\n\t\t\t}\n\t\t\tif(sum==n)\n\t\t\t{\n\t\t\t\tcout<<'c';\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tcout<<\""E\"";\n\t\t\n\t}\n\treturn 0;\n}",WRONG_ANSWER,8,452 1510593959154806784,3f267be2c9b47ff6e45ec7db5311c4fed252cb81ec8bd3227b8bc64985115a84,2022-04-03 20:24:00,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\tint t;\n\tcin>>t;\n\tfor(int i=0;i>n>>m;\n\t\tfor(int j=0;j>a>>b;\n\t\t}\n\t\tif(n==1) cout<<\""A\""<\nusing namespace std;\nint vec[1000005];\nint main() \n{\n\tint t;\n\tcin>>t;\n\tfor(int i=1;i<=t;i++)\n\t{\n\t\t\n\t\tint n;\n\t\tint m;\n\t\tcin>>n>>m;\n\t\tfor(int j=0;j<1000005;j++) vec[j]=0;\n\t\t//vector vec[1000005];\n\t\tfor(int j=1;j<=m;j++)\n\t\t{\n\t\t\tint x,y;\n\t\t\tcin>>x>>y;\n\t\t\tvec[x]++;\n\t\t\tvec[y]++;\t\n\t\t}\n\t\tif(n==1) cout<<\""A\""<2)\n\t\t\t{\n\t\t\t\n\t\t\t\tif(n>3)\n\t\t\t\t{\n\t\t\t\t\t//if(m==n-1) cout<<\""B\""<\n#include\nusing namespace std;\nint n,m;\nvoid demo(vector v){\n if(n==1){\n cout<<\""A\""<>t;\n while(t--){\n cin>>n>>m;\n vectorlable(n+1);\n int x,y;\n for(int i=1;i<=m;i++){\n cin>>x>>y;\n lable[x]++;\n lable[y]++;\n }\n demo(lable);\n }\n}",ACCEPTED,196,1092 1510594486148677632,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 20:26:05,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\twhile(m--)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\t\tdegree[a]++;\n\t\t\t\tdegree[b]++;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]==1)\n\t\tq.push(i);\n\t\tif(q.empty())\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t}\n}",WRONG_ANSWER,219,836 1510594526665654272,02d3e37513bd79df8bf329f2fc11a150d2e5cadd69331325bd3fa42def0037fa,2022-04-03 20:26:15,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n * (n - 1)) {\n\t\tcout << \""E\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tint sum,num,qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum==1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tsum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum!=n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1&&av[i]!=1) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) { ff = false;\n\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum==n&&ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tcout << \""D\"" << endl;\n}",WRONG_ANSWER,8,608 1510594529547870208,f5f19fbe584bcae32491371ad126ba09612c3024585d256ccfb801cff88a95f4,2022-04-03 20:26:15,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \ntypedef long long ll;\nconst double PI = acos(-1.0);\nconst int inf = 10000000 + 10;\nconst int sz = 100010;\nconst int P = 10007;\nusing namespace std;\n#define ri register int\ninline void rd(int &x){\n\tchar c=getchar();bool f=0;x=0;\n\twhile(c>'9'||c<'0'){if(c=='-')f=1;c=getchar();}\n\twhile(c<='9'&&c>='0'){x=x*10+c-'0';c=getchar();}\n\tif(f) x*=-1;}\ninline void we(int x){\n\tif(x<0) putchar('-'),x*=-1;\n\tif(x/10) we(x/10);\n\tputchar(x%10+'0');}\ninline int gcd(int a,int b){while(b^=a^=b^=a%=b);return a;}\ninline int lcm(int a,int b){return a*b/gcd(a,b);}\nll pow(ll a,ll b){\n\tif(b==0) return 1;if(b==1) return a%P;\n\tll t=(b>>1);\n\tll x=pow(a,t);\n\tll ans=( (x%P)*(x%P) )%P;\n\t\tif(b&1) ans=( (ans%P)*(a%P) )%P;\n\treturn ans%P;}\nint fa[sz];\ninline int find(int x){return x==fa[x]?fa[x]:find(fa[x]);}\ninline void merge(int x,int y){int X=find(x),Y=find(y);if(X!=Y)fa[X]=Y;}\ninline void swap(int &a,int &b){int t=a;a=b,b=t;}\ninline int max(int a,int b){return a>b?a:b;}inline int min(int a,int b){return a>t;\nwhile(t--)\n//for(ri qq=1;qq<=t;++qq)\n{\n//\twhile(~scanf(\""%d%d\"",&a,&b)){\n\tcin>>n>>m;\n\n\tfor(ri i=1;i<=m;++i)\n\t{\n\t\tcin>>t>>e;\n\t\tl[t].num++;\n\t\tl[e].num++;\n\t}\n\tif(n==1) {cout<<\""A\""<2) f=1;\n\t\tif(f==0) cout<<\""B\""<\n\nusing namespace std;\nlong long T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n * (n - 1)) {\n\t\tcout << \""E\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tint sum,num,qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum==1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tsum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum!=n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1&&av[i]!=1) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) { ff = false;\n\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum==n&&ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tcout << \""D\"" << endl;\n}",WRONG_ANSWER,7,456 1510594741644705792,32c6a08eeb2da90d725c4c1d02b6683ddee40eebe203496a6f00648d7f5a3d61,2022-04-03 20:27:06,Python,0.0,1510521134800797706,1509437328199348224,582,print('A'),WRONG_ANSWER,35,3076 1510594749383196672,e82da4709fea1cae36b2ec4ad480daa999e75b76466a853aada582870870e05d,2022-04-03 20:27:08,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\nconst int N=1e6+10;\n\nint h[N],ne[N],e[N],idx;\n\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\n\nint main()\n{\t\t\n int t;\n cin>>t;\n while(t--)\n {\n \tmemset(h,-1,sizeof h);\n\t\tmemset(e,0,sizeof e);\n\t\tmemset(ne,0,sizeof ne);\n\t\t\n \tint n,m;\n \tcin>>n>>m;\n \t\n \tif(n==1) cout<<\""A\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l); \t\t\t\n\t\t\t} \t\t\n \t\t\n \t\tint j=0;\n \t\t\n \t\tfor(int i=1;i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tif(j==1) break;\n\t\t\t}\n\t\t\tif(j==1) cout<<\""C\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l);\n\t\t\t}\n\t\t\t\n\t \tint j=0;\n\t \tint cnt=0;\n \t\t\n \t\tfor(int i=1;i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tcnt++;\n \t\t\tif(j==1) break;\n\t\t\t}\t\n\t\tif(j==1) cout<<\""C\""<\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n\treturn;\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\""<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n//#include\nusing namespace std;\n// typedef\nconst int N = 1e4 + 5;\nstring a[20];\n\nint c;\nint main()\n{\n cin >> c;\n\n for (int i = 0; i < c; i++)\n {\n int s[N] = {0} ;\n int ss[N] = { 0 };\n int c1 = 0, c2 = 0;\n cin >> c1 >> c2;\n if (c1 == 1)\n {\n cout << \""A\"";\n continue;\n }\n bool d = 0;\n bool e = 0;\n for (int i = 0; i < c2; i++)\n {\n int q1 = 0;\n int q2 = 0;\n cin >> q1 >> q2;\n if (!s[q1])\n s[q1]= q2;\n else\n {\n d = 1;\n if (!ss[q1])\n e = 1;\n }\n }\n if (e && c > 3)\n cout << \""E\"";\n else if (d && c > 3)\n {\n cout << \""D\"";\n }\n else\n {\n bool b = 0;\n for (int i = 0; i < c1; i++)\n {\n if (!s[i])\n b = 1;\n }\n if (b)\n cout << \""B\"";\n else\n cout << \""C\"";\n }\n\n }\n\n\n return 0;\n}",MULTIPLE_ERROR,13,332 1510594942191886336,2e3766042635433a3e6a0075809290f6f517a15a1dd19b5e66798ff69b157536,2022-04-03 20:27:54,Python,0.0,1510521134800797706,1509437328199348224,582,#include \n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 10e6 + 10;\n\nvector g[N];\n\nint main()\n{\n return 0;\n}\n,NON_ZERO_EXIT_CODE,31,3404 1510595014572990464,899805456fb5f5d9c8bac3a308efe8f87b008ca2c014705e604e2db766569d67,2022-04-03 20:28:11,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n//#include\nusing namespace std;\n// typedef\nconst int N = 1e5 + 5;\nstring a[20];\n\nint c;\nint main()\n{\n cin >> c;\n\n for (int i = 0; i < c; i++)\n {\n int s[N] = {0} ;\n int ss[N] = { 0 };\n int c1 = 0, c2 = 0;\n cin >> c1 >> c2;\n if (c1 == 1)\n {\n cout << \""A\"";\n continue;\n }\n bool d = 0;\n bool e = 0;\n for (int i = 0; i < c2; i++)\n {\n int q1 = 0;\n int q2 = 0;\n cin >> q1 >> q2;\n if (!s[q1])\n s[q1]= q2;\n else\n {\n d = 1;\n if (!ss[q1])\n e = 1;\n }\n }\n if (e && c > 3)\n cout << \""E\"";\n else if (d && c > 3)\n {\n cout << \""D\"";\n }\n else\n {\n bool b = 0;\n for (int i = 0; i < c1; i++)\n {\n if (!s[i])\n b = 1;\n }\n if (b)\n cout << \""B\"";\n else\n cout << \""C\"";\n }\n\n }\n\n\n return 0;\n}",WRONG_ANSWER,200,836 1510595118419034112,e82da4709fea1cae36b2ec4ad480daa999e75b76466a853aada582870870e05d,2022-04-03 20:28:36,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\nconst int N=1e6+10;\n\nint h[N],ne[N],e[N],idx;\n\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\n\nint main()\n{\t\t\n int t;\n cin>>t;\n while(t--)\n {\n \tmemset(h,-1,sizeof h);\n\t\tmemset(e,0,sizeof e);\n\t\tmemset(ne,0,sizeof ne);\n\t\t\n \tint n,m;\n \tcin>>n>>m;\n \t\n \tif(n==1) cout<<\""A\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l); \t\t\t\n\t\t\t} \t\t\n \t\t\n \t\tint j=0;\n \t\t\n \t\tfor(int i=1;i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tif(j==1) break;\n\t\t\t}\n\t\t\tif(j==1) cout<<\""C\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l);\n\t\t\t}\n\t\t\t\n\t \tint j=0;\n\t \tint cnt=0;\n \t\t\n \t\tfor(int i=1;i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tcnt++;\n \t\t\tif(j==1) break;\n \t\t\tif(cnt==n) break;\n\t\t\t}\t\n\t\tif(j==1) cout<<\""C\""<\nusing namespace std;\nint main() {\n\tint n;cin>>n;\n\tfor(int i=0;i\nusing namespace std;\nint main() {\n\tint n;cin>>n;\n\tfor(int i=0;i\nusing namespace std;\nint main() {\n\tint n;cin>>n;\n\tfor(int i=0;i\nusing namespace std;\nint main(){\n cout<<\""D\"";\n}",WRONG_ANSWER,8,444 1510595357435641856,92ad9cb50ba1675af4f9fe793bf2a0ac4912fc42bd6f46cb14ae3f2921f857e6,2022-04-03 20:29:33,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main() {\n\tint n;cin>>n;\n\tfor(int i=0;i\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<'A'<\nusing namespace std;\nint main(){\n cout<<\""A\"";\n}",WRONG_ANSWER,6,324 1510595441950322688,3f267be2c9b47ff6e45ec7db5311c4fed252cb81ec8bd3227b8bc64985115a84,2022-04-03 20:29:53,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\tint t;\n\tcin>>t;\n\tfor(int i=0;i>n>>m;\n\t\tfor(int j=0;j>a>>b;\n\t\t}\n\t\tif(n==1) cout<<\""A\""<\nusing namespace std;\nint main(){\n cout<<\""B\"";\n}",WRONG_ANSWER,9,452 1510595460875022336,02d3e37513bd79df8bf329f2fc11a150d2e5cadd69331325bd3fa42def0037fa,2022-04-03 20:29:58,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\nlong long T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m >= n+1) {\n\t\tcout << \""E\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tint sum,num,qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum==1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tsum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum!=n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1&&av[i]!=1) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) { ff = false;\n\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum==n&&ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tcout << \""D\"" << endl;\n}",WRONG_ANSWER,8,596 1510595479406002176,dbfd3b1efe1bccb14c2410616a663c5735d40d3ec51272492069d4253d73bf94,2022-04-03 20:30:02,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n cout<<\""E\"";\n}",WRONG_ANSWER,8,468 1510595550999306240,02d3e37513bd79df8bf329f2fc11a150d2e5cadd69331325bd3fa42def0037fa,2022-04-03 20:30:19,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\nlong long T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m >= n+2) {\n\t\tcout << \""E\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tint sum,num,qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum==1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tsum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum!=n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1&&av[i]!=1) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) { ff = false;\n\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum==n&&ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tcout << \""D\"" << endl;\n}",WRONG_ANSWER,8,456 1510595586544758784,dbfd3b1efe1bccb14c2410616a663c5735d40d3ec51272492069d4253d73bf94,2022-04-03 20:30:27,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n cout<<\""D\""<\nusing namespace std;\nint main() {\n\tint n;cin>>n;\n\tfor(int i=0;i\n#include \n#include \nusing namespace std;\n\n\nint main(){\n\tint n;\n\tchar ans;\n\tcin >> n;\n\twhile(n--){\n\t\tint n,m;\n\t\tcin >> n;\n\t\tcin >> m;\n\t\tif(n == 1){\n\t\t\tprintf(\""A\\n\"");\n\t\t\tcontinue;\n\t\t}\n\t\tif(n == m && n > 2){\n\t\t\tprintf(\""C\\n\"");\n\t\t\tcontinue;\n\t\t}\n\t\tvector mark(n+1);\n\t\t//vector > matrix(n+1,vector(n+1));\n\t\tif(n == m+1){\n\t\t\tint flag = 1;\n\t\t\tfor(int k = 0; k < m; k++){\n\t\t\t\tint i,j;\n\t\t\t\tcin >> i >> j;\n\t\t\t\t//matrix[i][j] = 1;\n\t\t\t\tmark[i]++;\n\t\t\t\tmark[j]++;\n\t\t\t\tif(mark[i] > 2 || mark[j] > 2){\n\t\t\t\t\tprintf(\""D\\n\"");\n\t\t\t\t\tflag = 0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)\n\t\t\tprintf(\""B\\n\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\t\n\t\tprintf(\""E\\n\"");\n\t}\n\t\n\t\n\t\n\treturn 0;\n} ",WRONG_ANSWER,7,452 1510596072303882240,2e3766042635433a3e6a0075809290f6f517a15a1dd19b5e66798ff69b157536,2022-04-03 20:32:23,Python,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 10e6 + 10;\n\nvector g[N];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n \n int i, j;\n for (int i = 0; i < m; i++)\n {\n cin >> i >> j;\n g[i].push_back(j);\n g[i].push_back(j);\n }\n }\n \n return 0;\n}\n",NON_ZERO_EXIT_CODE,33,3140 1510596122585198592,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 20:32:35,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nconst int M=1e4+10;\nint degree[N];\nbool st[M][M];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\twhile(m--)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(st[a][b])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tst[a][b]=true;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]==1)\n\t\tq.push(i);\n\t\tif(q.empty())\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tputs(\""E\"");\n\t}\n}",MULTIPLE_ERROR,16,1372 1510596159264387072,2e3766042635433a3e6a0075809290f6f517a15a1dd19b5e66798ff69b157536,2022-04-03 20:32:44,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 10e6 + 10;\n\nvector g[N];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n \n int i, j;\n for (int i = 0; i < m; i++)\n {\n cin >> i >> j;\n g[i].push_back(j);\n g[i].push_back(j);\n }\n }\n \n return 0;\n}\n",MEMORY_LIMIT_EXCEEDED,179,131072 1510596203791118336,c118514b9494c219ce92d2176fb3e7a2095835e5de0066e8d43db71c7f5bc672,2022-04-03 20:32:55,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n \nint ma[1000010]; \nint main()\n{\n\tint T; cin>>T;\n\tint n,m; \n\t\n\tfor(int i = 1;i<=T;i++)\n\t{\n\t\tfor(int i =0;i<1000010;i++) ma[i] =0;\n\t\tcin>>n>>m;int u,v;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<>u>>v;\n\t\t\tma[u]++;\n\t\t\tma[v]++;\n\t\t}\n\t\tint sum = 0,sum1 = 0;\n\t\tfor(int i = 1;i<=n;i++)\n\t\t{\n\t\t\tif(ma[i] == 1)\n\t\t\t{\n\t\t\t\tsum ++;\n\t\t\t}\n\t\t\telse if(ma[i] == 2)\n\t\t\t{\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t}\n\t\tif(sum == 2 && sum1 == (n-2))\n\t\t{\n\t\t\tcout<<'B'<\n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 100;\n\nbool g[N][M];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n \n int i, j;\n for (int i = 0; i < m; i++)\n {\n cin >> i >> j;\n g[i].push_back(j);\n g[i].push_back(j);\n }\n }\n \n return 0;\n}\n",COMPILE_ERROR,0,0 1510596296196374528,2e3766042635433a3e6a0075809290f6f517a15a1dd19b5e66798ff69b157536,2022-04-03 20:33:17,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 100;\n\nbool g[N][M];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n \n }\n \n return 0;\n}\n",WRONG_ANSWER,8,732 1510596416363184128,02d3e37513bd79df8bf329f2fc11a150d2e5cadd69331325bd3fa42def0037fa,2022-04-03 20:33:45,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\nlong long T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m >= n+2) {\n\t\tcout << \""E\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tlong long sum, num;\n\tint qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum==1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tint sum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum!=n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1&&av[i]!=1) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) { ff = false;\n\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum==n&&ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tcout << \""D\"" << endl;\n}",COMPILE_ERROR,0,0 1510596482334846976,31146e6a24c070dcbed74f1e600f7ad681dc13c8b339daca6ac8812aa9cc3ad3,2022-04-03 20:34:01,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main(void)\n{\n\tint t;cin>>t;\n\tfor(int i=1;i<=t;i++)\n\t{\n\t\tlong long n,m,sum,a,b;\n\t\tsum=0;\n\t\tcin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\t\tif(a-b==1||a-b==-1)\n\t\t\t\t\tsum++;\n\t\t\t}\n\t\t\tsum=0;\n\t\t\tif(sum==m)\n\t\t\t{\n\t\t\t\tcout<<\""B\""<>a>>b;\n\t\t\t\tif(a-b==1||a-b==-1||a-b==n-1||a-b==1-n)\n\t\t\t\t\tsum++;\n\t\t\t}\n\t\t\tif(sum==n)\n\t\t\t{\n\t\t\t\tcout<<'C'<\nusing namespace std;\nconst int N=1000005;\nint f[N];\nint d[N];\nint find(int x)\n{\n if(f[x]!=x)\n {\n f[x]=find(f[x]);\n }\n return f[x];\n}\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n\n\n\n for(int i=0;i>x>>y;\n f[find(f[x])]=find(f[y]);\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n }\n}\n",WRONG_ANSWER,208,4164 1510596686585413632,c118514b9494c219ce92d2176fb3e7a2095835e5de0066e8d43db71c7f5bc672,2022-04-03 20:34:50,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n \nint ma[1000010]; \nint main()\n{\n\tint T; cin>>T;\n\tint n,m; \n\t\n\tfor(int i = 1;i<=T;i++)\n\t{\n\t\tfor(int i =0;i<1000010;i++) ma[i] =0;\n\t\tcin>>n>>m;int u,v;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<>u>>v;\n\t\t\tma[u]++;\n\t\t\tma[v]++;\n\t\t}\n\t\tint sum = 0,sum1 = 0;\n\t\tbool flag = 1;\n\t\tint num2 = ma[1];\n\t\tfor(int i = 1;i<=n;i++)\n\t\t{\n\t\t\tif(ma[i] == 1)\n\t\t\t{\n\t\t\t\tsum ++;\n\t\t\t}\n\t\t\telse if(ma[i] == 2)\n\t\t\t{\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\tif(ma[i] != num2) flag = 0;\n\t\t}\n\t\tif(flag) \n\t\t{\n\t\t\tcout<<'E'<\nusing namespace std;\nint main(){\n\tint k;\n\tcin>>k;\n\tint n,m;\n\tcin>>n>>m;\n\t\n\tint xx=0;\n\tfor(int i=1;i>n1>>n2;\n\t\tnodes[n1]++;\n\t\tnodes[n2]++;\n\t}\n\tint v1=0,v2=0,vn=0;\n\tfor(int i=1;i3&&xx==m){\n\t\tcout<<\""E\"";\n\t}\n\telse if(v1==2&&vn==0&&n>1){\n\t\tcout<<\""B\"";\n\t}\n\telse if(v1==0&&vn==0&&n>2){\n\t\tcout<<\""C\"";\n\t}\n\telse{\n\t\tcout<<\""D\"";\n\t}\n\t\n\treturn 0;\n}",WRONG_ANSWER,9,448 1510596723084247040,ace08c6cb007ddeb34a5221bf5d2b44ea0a81328cd35e07c1e189b789824c34a,2022-04-03 20:34:58,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std ;\n\nint main() {\n\tint t ; \n\tcin >> t ;\n\tfor(int i = 0 ; i < t ; i ++ ){\n\t\tint n , m ;\n\t\tint b[1001][2];\n\t\tcin >> n >> m ;\n\t\tcout << n << m <> b[j][t] ;\n\t\t\t}\n\t\t}\n\t\tif(n == 1 ){\n\t\t\tcout << \""A\""<\nint main()\n{\n\tint a, b = 0;\n\tscanf(\""%d %d\"", &a, &b);\n\tif(a==0&&b==0)\n\t{\n\t\tprintf(\""nan\"");\n\t}\n\telse if (a > 0 && b == 0)\n\t{\n\t\tprintf(\""inf\"");\n\t}\n\telse \n\t{\n\t\tprintf(\""%d\"", a / b);\n\t}\n}\nstruct student\n{\n\tint yyyy, MM, dd, HH, mm = 0;\n\tint id = 0;\n}stu[10000];\nint main()\n{\n\tint n,i = 0;\n\tscanf(\""%d\"", &n);\n\tfor (i = 0; i < n; i++)\n\t{\n\t\tscanf(\""%d-%d-%d %d:%d \"", &stu[i].yyyy, &stu[i].MM, &stu[i].dd, &stu[i].HH, &stu[i].mm, &stu[i].id);\n\t}\n\tscanf(\""%d-%d-%d %d:%d\"", &stu[n].yyyy, &stu[n].MM, &stu[n].dd, &stu[n].HH, &stu[n].mm);\n\tfor (i = 0; i < n; i++)\n\t{\n\n\t}\n\n\treturn 0;\n}",COMPILE_ERROR,0,0 1510596843766411264,ace08c6cb007ddeb34a5221bf5d2b44ea0a81328cd35e07c1e189b789824c34a,2022-04-03 20:35:27,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std ;\n\nint main() {\n\tint t ; \n\tcin >> t ;\n\tfor(int i = 0 ; i < t ; i ++ ){\n\t\tint n , m ;\n\t\tint b[10001][2];\n\t\tcin >> n >> m ;\n\t\tcout << n << m <> b[j][t] ;\n\t\t\t}\n\t\t}\n\t\tif(n == 1 ){\n\t\t\tcout << \""A\""<\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nmapp;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\twhile(m--)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=true;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]==1)\n\t\tq.push(i);\n\t\tif(q.empty())\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\tputs(\""E\"");\n\t}\n}",WRONG_ANSWER,435,27320 1510596911014961152,866f20f55486c596ad1025ec4d935c62463514157bd1c67a812d6f670d58dcb0,2022-04-03 20:35:43,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\ntypedef pair PII;\nconst int N = 1e6+10;\n\nint d[N],c[N];\nint e[N],h[N],ne[N],idx;\nint n,m;\nbool st[N];\n\nvoid add(int a,int b)\n{\n\te[idx] = b;\n\tne[idx] = h[a];\n\th[a] = idx++;\n}\n\nbool dfs(int u)\n{\n\t\tfor(int j=h[u];j!=-1;j=ne[j])\n\t\t{\n\t\t\tint i = e[j];\n if(!st[i]){\n st[i] = true;\n dfs(i);\n }else{\n return false;\n }\n\t\t}\n\treturn true;\n}\n\nint main()\n{\n\n\t\n\t\n\tint t;\n\tcin>>t;\n\t\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\td[b]++;\n\t\t\tif(d[b]>1){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tc[a]++;\n\t\t\tif(c[a] > 1){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tadd(a,b);\n\t\t\tadd(b,a);\n\t\t}\n\t\tif(st== false){\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(d[i] == 0){\n\t\t\t\tcout<<\""B\""<\nusing namespace std;\n \nint ma[1000010]; \nint main()\n{\n\tint T; cin>>T;\n\tint n,m; \n\t\n\tfor(int i = 1;i<=T;i++)\n\t{\n\t\tfor(int i =0;i<1000010;i++) ma[i] =0;\n\t\tcin>>n>>m;int u,v;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<>u>>v;\n\t\t\tma[u]++;\n\t\t\tma[v]++;\n\t\t}\n\t\tint sum = 0,sum1 = 0;\n\t\tbool flag = 1;\n\t\tint num2 = ma[1];\n\t\tfor(int i = 1;i<=n;i++)\n\t\t{\n\t\t\tif(ma[i] == 1)\n\t\t\t{\n\t\t\t\tsum ++;\n\t\t\t}\n\t\t\telse if(ma[i] == 2)\n\t\t\t{\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\tif(ma[i] != num2) flag = 0;\n\t\t}\n\t\tif(flag && num2 ==n) \n\t\t{\n\t\t\tcout<<'E'<\nusing namespace std;\nint n,m,t,cnt;\nint x,y;\n\nint main(){\n\tcin>>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tint a[1000010]={0};\n\t\tfor(int i=1;i<=m;i++){\n\t\t\tcin>>x>>y;\n\t\t\ta[x]++;\n\t\t\ta[y]++;\n\t\t}\n\t\tif(n==1){\n\t\t\t cout<<\""A\""<\nusing namespace std;\nint main(void)\n{\n\tint t;cin>>t;\n\tfor(int i=1;i<=t;i++)\n\t{\n\t\tlong long n,m,sum,a,b;\n\t\tsum=0;\n\t\tcin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\t\tif(a-b==1||a-b==-1)\n\t\t\t\t\tsum++;\n\t\t\t}\n\t\t\tif(sum==m)\n\t\t\t{\n\t\t\t\tcout<<\""B\""<>a>>b;\n\t\t\t\tif(a-b==1||a-b==-1||a-b==n-1||a-b==1-n)\n\t\t\t\t\tsum++;\n\t\t\t}\n\t\t\tif(sum==n)\n\t\t\t{\n\t\t\t\tcout<<'C'<\nusing namespace std;\nint main() \n{\n\t\n cout<<\""A\""<\nusing namespace std;\nint main() \n{\n\t\n cout<<\""B\""<\nusing namespace std;\nint main() \n{\n\t\n cout<<\""C\""<\nusing namespace std;\nint main() \n{\n\t\n cout<<\""D\""<\nusing namespace std;\nint main() \n{\n\t\n cout<<\""E\""<\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n\n\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n }\n}\n",COMPILE_ERROR,0,0 1510597477673091072,e43a6b275382d4de707ad9fe9a0c910690c66d7d8d6f9b28f68d2e75883214c5,2022-04-03 20:37:58,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n }\n}\n",WRONG_ANSWER,200,832 1510597569713627136,e38bd6aed27e40438267f73c2be6a1efd683f1360cab46fc198d70b33578f562,2022-04-03 20:38:20,C++,0.0,1510521134800797706,1509437328199348224,582,"using namespace std;\n#include \n#include\n#include\n#include\n#include\nint a[100][2];\nint main()\n{\n int t;\n cin >> t;\n int n, m;\n cin >> n >> m;\n for (int i = 0; i < m; i++)\n {\n for (int j = 0; j < 2; j++)\n {\n cin >> a[i][j];\n }\n }\n if (n == 1) {\n cout << \""A\"" << endl;\n }\n if (n == 2) {\n cout << \""B\"" << endl;\n }\n}",WRONG_ANSWER,9,448 1510597705607802880,1a28a58367da9fd50ad3061a9cfb14c1c14608907febb8d15680988474ea83c5,2022-04-03 20:38:53,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint a[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n cin>>n>>m;\n if(n==1)\n {cout<<\""A\"";\n continue;\n }\n while(m--)\n {\n int i,j;\n cin>>i>>j;\n a[i]++;\n a[j]++;\n }\n int sum1=0;//xian\n int sum2=0;//huan\n int sum3=0;//shu\n int sum4=0;\n for(int i=1;i<=n;i++)\n {\n if(a[i]==2){\n sum2++;\n }\n if(a[i]==1)sum1++;\n if(a[i]==3)sum3++;\n if(a[i]==4)sum4++;\n }\n if(sum2==n)cout<<\""C\""<\nusing namespace std;\nint main() \n{ cout<<\""A\""< \nusing namespace std;\nint tu[1000][1000];\nint main(){\n int t;cin>>t;\n for(int i=0;i>n>>m;\n \tfor(int j=0;j>a>>b;\n \t\ttu[a][b]=1;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<'A';\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t}\n\treturn 0;\n}\n\n",MULTIPLE_ERROR,17,1092 1510597747601719296,f41ec44c982aa8de0ad03db515d30f1e4a221c1a61b6c340b1ce0bc15a65f5fb,2022-04-03 20:39:03,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint cnt[1000010];\n\nint main()\n{\n\tint T;\n\tcin>>T;\n\tint n,m;\n\tcin>>n>>m;\n\tint a,b;\n\tif(n==1)\n\t{\n\t\tcout<<\""A\""<>a>>b;\n\t\t\tcnt[a]++;\n\t\t\tcnt[b]++;\n\t\t}\n\t\tint cnt1=0;\n\t\tint cnt2=0;\n\t\tint cntt=0;\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(cnt[i]==1)\n\t\t\t\tcnt1++;\n\t\t\tif(cnt[i]==2)\n\t\t\t\tcnt2++;\n\t\t\tif(cnt[i]==(n-1))\n\t\t\t\tcntt++;\n\t\t}\n\t\tif(cnt1==2 && cnt2==n-2)\n\t\t{\n\t\t\tcout<<\""B\""<\nusing namespace std;\nconst int N=1e6+10;\nint a[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n cin>>n>>m;\n if(n==1)\n {cout<<\""A\"";\n continue;\n }\n while(m--)\n {\n int i,j;\n cin>>i>>j;\n a[i]++;\n a[j]++;\n }\n int sum1=0;//xian\n int sum2=0;//huan\n int sum3=0;//shu\n int sum4=0;\n for(int i=1;i<=n;i++)\n {\n if(a[i]==2){\n sum2++;\n }\n if(a[i]==1)sum1++;\n if(a[i]==3)sum3++;\n if(a[i]==4)sum4++;\n }\n if(sum2==n)cout<<\""C\""<\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n for(int i=1;i<=n;i++)\n {\n f[i]=i;\n }\n\n\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n }\n}\n",COMPILE_ERROR,0,0 1510598074238066688,e43a6b275382d4de707ad9fe9a0c910690c66d7d8d6f9b28f68d2e75883214c5,2022-04-03 20:40:21,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n }\n}\n",WRONG_ANSWER,198,712 1510598102448955392,31146e6a24c070dcbed74f1e600f7ad681dc13c8b339daca6ac8812aa9cc3ad3,2022-04-03 20:40:27,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main(void)\n{\n\tint t;cin>>t;\n\tfor(int i=1;i<=t;i++)\n\t{\n\t\tlong long n,m,sum,a,b;\n\t\tsum=0;\n\t\tcin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\t\tif(a-b==1||a-b==-1)\n\t\t\t\t\tsum++;\n\t\t\t}\n\t\t\tif(sum==m)\n\t\t\t{\n\t\t\t\tcout<<\""B\""<>a>>b;\n\t\t\t\tif(a-b==1||a-b==-1||a-b==n-1||a-b==1-n)\n\t\t\t\t\tsum++;\n\t\t\t}\n\t\t\tif(sum==n)\n\t\t\t{\n\t\t\t\tcout<<'C'<\n#include\n#include\n#include\n#include\n#include\n\nusing namespace std;\n\nconst int N = 1000010;\n\nstruct edge {\n\tint a, b;\n}tu[N];\n\nint arr[N];\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\tint n, m;\n\twhile (T--)\n\t{\n\t\tcin >> n >> m;\n\t\tint a, b;\n\t\tbool is_lian = true;\n\t\tbool is_quan = true;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\ttu[i] = { a,b };\n\t\t\tarr[a]++;\n\t\t\tarr[b]++;\n\t\t\t\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] > 2)\n\t\t\t{\n\t\t\t\tis_lian = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] != 2)\n\t\t\t{\n\t\t\t\tis_quan = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (n>1&&is_lian&&!is_quan)\n\t\t{\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse if (n > 2 && is_quan) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 3)\n\t\t{\n\t\t\tif (n * (n - 1) == m * 2)\n\t\t\t{\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}",WRONG_ANSWER,201,1592 1510598185617809408,00d66a836edc434af14bd10d58b07cd497fa7e1a722ee9905e58854602e74e3a,2022-04-03 20:40:47,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n\n\nusing namespace std;\nint main() {\n int t;\n cin>>t;\n for(int T=0;T>n>>m;\n int a[m][2];\n for(int i=0;i>a[i][0]>>a[i][1];\n }\n if(n=1){\n cout<<\""A\""<\n#include\n#include\n#include\nusing namespace std;\nint cnt[1000010][2];\nint main()\n{\n int t;\n cin >> t;\n while (t--)\n {\n int n, m;\n cin >> n >> m;\n for (int i = 0; i < m; i++)\n {\n cin >> cnt[i][0] >> cnt[i][1];\n }\n if (n == 1)\n {\n cout << \""A\"" << endl;\n }\n else\n {\n if (n == m)\n {\n cout << \""C\"" << endl;\n }\n else\n {\n cout << \""D\"" << endl;\n }\n }\n }\n}",WRONG_ANSWER,196,1212 1510598393666596864,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 20:41:37,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\twhile(m--)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=true;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]==1)\n\t\tq.push(i);\n\t\tif(q.empty())\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\tputs(\""E\"");\n\t}\n}",WRONG_ANSWER,413,10556 1510598534972698624,eaede10d19efab27b2020190fcc6c16d540166b88438b63bfc0149d59fae3847,2022-04-03 20:42:10,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\nchar DFS(map> graph, int n, int m)\n{\n\tint* visit = new int[n + 1](); int numOfvisited = 0; int numOfEnd = 0;\n\tstack q;\n\tq.push(1); visit[1] = 1; numOfvisited++;\n\twhile (numOfvisited<=n)\n\t{\n\t\tint vertice = q.top();\n\t\tbool ifend = true;\n\t\tfor (int i = 0; i < graph[vertice].size(); i++)\n\t\t{\n\t\t\tint x = graph[vertice][i];\n\t\t\tif (!visit[x])\n\t\t\t{\n\t\t\t\tq.push(x); numOfvisited++; visit[x] = 1; ifend = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (ifend)\n\t\t{\n\t\t\tnumOfEnd++;\n\t\t\tint cur = q.top();\n\t\t\tfor (int i = 0; i < graph[cur].size(); i++)\n\t\t\t{\n\t\t\t\tif (graph[cur][i] == 1)return 'C';\n\t\t\t}\n\t\t\tbool tmp1=true;\n\t\t\twhile (tmp1)\n\t\t\t{\n\t\t\t\tq.pop();\n\t\t\t\tint x = q.top();\n\t\t\t\tfor (int i = 0; i < graph[x].size(); i++)\n\t\t\t\t{\n\t\t\t\t\tif (!visit[graph[x][i]])\n\t\t\t\t\t{\n\t\t\t\t\t\ttmp1 = false; q.push(graph[x][i]); numOfvisited++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif (numOfEnd == 1)return 'B';\n\telse return 'D';\n}\nint main()\n{\n\tint t; cin >> t;\n\tvector v;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m; cin >> n >> m;\n\t\tmap> graph;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tint first, second; cin >> first >> second;\n\t\t\tgraph[first].push_back(second);\n\t\t\tgraph[second].push_back(first);\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tv.push_back('A'); continue;\n\t\t}\n\t\tif (m ==n * (n - 1) / 2)\n\t\t{\n\t\t\tv.push_back('E'); continue;\n\t\t}\n\t\tv.push_back(DFS(graph, n, m));\n\t}\n\tfor (int i = 0; i < v.size(); i++)\n\t{\n\t\tcout << v[i] << endl;\n\t}\n}\n",MULTIPLE_ERROR,661,24784 1510598541189931008,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 20:42:12,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n cin>>a>>b;\n }\n if(n==1) cout<<\""A\""<\n#include\n#include\n#include\n#include\n#include\n\nusing namespace std;\n\nconst int N = 1000010;\n\nstruct edge {\n\tint a, b;\n}tu[N];\n\nint arr[N];\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\tint n, m;\n\twhile (T--)\n\t{\n\t\tcin >> n >> m;\n\t\tint a, b;\n\t\tbool is_lian = true;\n\t\tbool is_quan = true;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\ttu[i] = { a,b };\n\t\t\tarr[a]++;\n\t\t\tarr[b]++;\n\t\t\t\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] > 2)\n\t\t\t{\n\t\t\t\tis_lian = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] != 2)\n\t\t\t{\n\t\t\t\tis_quan = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (n>1&&is_lian&&!is_quan)\n\t\t{\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse if (n > 2 && is_quan) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 3)\n\t\t{\n\t\t\tif (n * (n - 1) == m * 2)\n\t\t\t{\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse if(n*(n-1)>m*2) {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}",WRONG_ANSWER,203,1596 1510598719753306112,4d6f5b37bc739a4e5ffcbddc42644496fb47d7cb190382acd0c8aa63a693343e,2022-04-03 20:42:55,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\tcout<<\""D\""<\nusing namespace std;\nint main()\n{\n\tcout<<\""A\""<\nusing namespace std;\nint main()\n{\n\tcout<<\""B\""<\nusing namespace std;\nint main()\n{\n\tcout<<\""C\""<\n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n cin>>a>>b;\n }\n if(n==1) cout<<\""A\""<\n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 100;\n\nbool g[N][M];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n return 0;\n}\n",WRONG_ANSWER,8,584 1510598983524696064,2e3766042635433a3e6a0075809290f6f517a15a1dd19b5e66798ff69b157536,2022-04-03 20:43:57,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 100;\n\nbool g[N][M];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n }\n \n return 0;\n}\n",WRONG_ANSWER,9,588 1510599134762909696,2e3766042635433a3e6a0075809290f6f517a15a1dd19b5e66798ff69b157536,2022-04-03 20:44:33,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 100;\n\nbool g[N][M];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n else\n {\n cout << \""B\"" <\n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 100;\n\nbool g[N][M];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n else\n {\n cout << \""C\"" <\n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 100;\n\nbool g[N][M];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n else\n {\n cout << \""D\"" <\n#include \n\nusing namespace std;\n\nconst int N = 10e6 + 10;\nconst int M = 100;\n\nbool g[N][M];\n\nint t,n,m;\n\nint main()\n{\n cin >> t;\n\n while (t--)\n {\n cin >> n >> m;\n if (n==1)\n {\n cout << \""A\"" << endl;\n continue;\n }\n else\n {\n cout << \""E\"" <\nusing namespace std;\n \nint ma[1000010]; \nint main()\n{\n\tint T; cin>>T;\n\tint n,m; \n\t\n\tfor(int i = 1;i<=T;i++)\n\t{\n\t\tfor(int i =0;i<1000010;i++) ma[i] =0;\n\t\tcin>>n>>m;int u,v;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<>u>>v;\n\t\t\tma[u]++;\n\t\t\tma[v]++;\n\t\t}\n\t\tint sum = 0,sum1 = 0;\n\t\tbool flag = 1;\n\t\tint num2 = ma[1];\n\t\tint j=0,o=0; \n\t\tfor(int i = 1;i<=n;i++)\n\t\t{\n\t\t\tif(ma[i] == 1)\n\t\t\t{\n\t\t\t\tsum ++;\n\t\t\t}\n\t\t\telse if(ma[i] == 2)\n\t\t\t{\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\tif(ma[i]%2==0)\n\t\t\t{\n\t\t\t\to++;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tif(ma[i] != num2) flag = 0;\n\t\t}\n\t\tif(flag && num2 ==n-1 && n>3) \n\t\t{\n\t\t\tcout<<'E'<\nusing namespace std;\n \nint main(){\n\tint t;\n\tcin>>t;\n\twhile(t--){\n\t\tint n,m;\n\t\tcin>>n>>m;\n\tif(n==1)\n\tcout<<\""A\"";\n\t}\n} ",WRONG_ANSWER,9,448 1510599375066624000,4d6f5b37bc739a4e5ffcbddc42644496fb47d7cb190382acd0c8aa63a693343e,2022-04-03 20:45:31,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\tlong long int T;\n\tlong long int n,m;\n\tlong long int a,b;\n\tcin>>T;\n\tfor(long long int i=0;i>n>>m;\n\t\tfor(int j=0;j>a>>b;\n\t\t}\n\t}\n\tcout<<\""D\""<\nusing namespace std;\nint main()\n{\n\tlong long int T;\n\tlong long int n,m;\n\tlong long int a,b;\n\tcin>>T;\n\tfor(long long int i=0;i>n>>m;\n\t\tfor(int j=0;j>a>>b;\n\t\t}\n\t}\n\tcout<<\""A\""<\nusing namespace std;\nint main()\n{\n\tlong long int T;\n\tlong long int n,m;\n\tlong long int a,b;\n\tcin>>T;\n\tfor(long long int i=0;i>n>>m;\n\t\tfor(long long int j=0;j>a>>b;\n\t\t}\n\t}\n\tcout<<\""B\""<\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n }\n}\n",WRONG_ANSWER,194,716 1510599474312790016,4d6f5b37bc739a4e5ffcbddc42644496fb47d7cb190382acd0c8aa63a693343e,2022-04-03 20:45:54,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\tlong long int T;\n\tlong long int n,m;\n\tlong long int a,b;\n\tcin>>T;\n\tfor(long long int i=0;i>n>>m;\n\t\tfor(long long int j=0;j>a>>b;\n\t\t}\n\t}\n\tcout<<\""C\""<\nusing namespace std;\nint main()\n{\n\tlong long int T;\n\tlong long int n,m;\n\tlong long int a,b;\n\tcin>>T;\n\tfor(long long int i=0;i>n>>m;\n\t\tfor(long long int j=0;j>a>>b;\n\t\t}\n\t}\n\tcout<<\""E\""<\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\twhile(m--)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=true;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tputs(\""E\"");\n\t}\n}",WRONG_ANSWER,441,11068 1510599538192769024,4d6f5b37bc739a4e5ffcbddc42644496fb47d7cb190382acd0c8aa63a693343e,2022-04-03 20:46:10,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\tlong long int T;\n\tlong long int n,m;\n\tlong long int a,b;\n\tcin>>T;\n\tfor(long long int i=0;i>n>>m;\n\t\tfor(long long int j=0;j>a>>b;\n\t\t}\n\t}\n\tcout<<\""C\""<\nusing namespace std;\nint main(){\n\tint T;\n\tcin>>T;\n\tfor(int k=0;k>n>>m;\n\tint arr[m][2];\n\t\tint ar[100]={0};\n\tfor(int i=0;i>arr[i][j];\n\t\t\tar[arr[i][j]]++;\n\t\t}\n\t}\n\tif(n==1)\n\tcout<<\""A\"";\n\tbool reult=1;\n\tbool reult2=0;\n\tfor(int i=1;i<=n;i++){\n\t\tif(ar[i]!=2)\n\t\treult=0;\n\t\tif(ar[i]==1){\n\t\t\treult2=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(reult==1){\n\t\tcout<<\""C\"";\n\t}\n\tif(reult2==1){\n\t\tcout<<\""D\"";\n\t}\n\tif(n!=1&&reult!=1&&reult2==0)\n\tcout<<\""E\"";\n}\n}",MULTIPLE_ERROR,14,452 1510599745600372736,c118514b9494c219ce92d2176fb3e7a2095835e5de0066e8d43db71c7f5bc672,2022-04-03 20:46:59,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n \nint ma[1000010]; \nint main()\n{\n\tint T; cin>>T;\n\tint n,m; \n\t\n\tfor(int i = 1;i<=T;i++)\n\t{\n\t\tfor(int i =0;i<1000010;i++) ma[i] =0;\n\t\tcin>>n>>m;int u,v;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<>u>>v;\n\t\t\tma[u]++;\n\t\t\tma[v]++;\n\t\t}\n\t\tint sum = 0,sum1 = 0;\n\t\tbool flag = 1;\n\t\tint num2 = ma[1];\n\t\tint j=0,o=0; \n\t\tfor(int i = 1;i<=n;i++)\n\t\t{\n\t\t\tif(ma[i] == 1)\n\t\t\t{\n\t\t\t\tsum ++;\n\t\t\t}\n\t\t\telse if(ma[i] == 2)\n\t\t\t{\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\tif(ma[i]%2==0)\n\t\t\t{\n\t\t\t\to++;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tif(ma[i] != num2) flag = 0;\n\t\t}\n\t\tif(flag && num2 ==n-1 && n>3) \n\t\t{\n\t\t\tcout<<'E'<1)//链 \n\t\t{\n\t\t\tcout<<'B'<2)//圈 \n\t\t{\n\t\t\tcout<<'C'<3)\n\t\t{\n\t\t\tcout<<'D'<\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\""<>T;\n while(T--)\n {\n\n solve();\n if(T!=1)\n {\n \n cout<\nusing namespace std;\nint main(){\n\tint T;\n\tcin>>T;\n\tfor(int k=0;k>n>>m;\n\tint arr[m][2];\n\t\tint ar[100]={0};\n\tfor(int i=0;i>arr[i][j];\n\t\t\tar[arr[i][j]]++;\n\t\t}\n\t}\n\tif(n==1)\n\tcout<<\""A\"";\n\tbool reult=1;\n\tbool reult2=0;\n\tfor(int i=1;i<=n;i++){\n\t\tif(ar[i]!=2)\n\t\treult=0;\n\t\tif(ar[i]==1){\n\t\t\treult2=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(reult==1){\n\t\tcout<<\""C\"";\n\t}\n\tif(reult2==1){\n\t\tcout<<\""D\"";\n\t}\n\tif(n!=1&&reult!=1&&reult2==0)\n\tcout<<\""E\"";\n}\n}",MULTIPLE_ERROR,16,708 1510600018436382720,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 20:48:04,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\twhile(m--)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=true;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tputs(\""E\"");\n\t}\n}",WRONG_ANSWER,429,11068 1510600103513645056,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 20:48:24,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n }\n if(n==1) cout<<\""A\""<\nusing namespace std;\nint main(){\n\tcout<<\""E\"";\n}",WRONG_ANSWER,8,448 1510600162066128896,403e2e20de5462ae78b84d2b8719304fb2b7cb673089675d25e4cf18db664fbf,2022-04-03 20:48:38,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n\tcout<<\""B\"";\n}",WRONG_ANSWER,8,320 1510600205795213312,34e4b43252a14f6c5f9490f9d98b4eb249ced0220e8053654d83f7b39884a88e,2022-04-03 20:48:49,Python,0.0,1510521134800797706,1509437328199348224,582,"import sys\nT = int(input())\nwhile T>0:\n T -= 1\n n,m = map(int,input().split())\n if n == 1:\n print(\""A\"")\n sys.exit()\n elif m==n:\n print('C')\n sys.exit()\n elif m==n-1:\n k = 0\n d = {}\n for i in range(1,n+1):\n d[i] = []\n while m>0:\n m -= 1\n a,b = map(int,input().split())\n d[a].append(b)\n d[b].append(a)\n for i in range(1,n+1):\n if len(d[i])==3:\n print(\""D\"")\n sys.exit()\n if len(d[i])==1:\n k += 1\n if k==2:\n print(\""B\"")\n sys.exit()\n print(\""E\"")\n",WRONG_ANSWER,32,3404 1510600219074379776,403e2e20de5462ae78b84d2b8719304fb2b7cb673089675d25e4cf18db664fbf,2022-04-03 20:48:52,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n\tcout<<\""C\"";\n}",WRONG_ANSWER,9,448 1510600239849496576,e43a6b275382d4de707ad9fe9a0c910690c66d7d8d6f9b28f68d2e75883214c5,2022-04-03 20:48:57,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\"";\n return ;\n }\n else if(n==2)\n {\n cout<<\""B\"";\n return ;\n }\n bool falg=true;\n bool falg1=true;\n int cnt1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]!=2)\n {\n falg=false;\n if(d[i]!=1)\n {\n falg1=false;\n }\n }\n if(d[i]==1)\n {\n cnt1++;\n }\n\n }\n if(falg)\n {\n cout<<\""C\"";\n return ;\n }\n\n if(falg1&&cnt1==2)\n {\n cout<<\""B\"";\n return ;\n }\n\n if(n==m+1)\n {\n cout<<\""D\"";\n return ;\n }\n\n cout<<\""E\"";\n}\nint main()\n{\n int T;\n cin>>T;\n while(T--)\n {\n\n solve();\n if(T!=0)\n {\n\n cout<\nusing namespace std;\nint main(){\n\tcout<<\""D\"";\n}",WRONG_ANSWER,8,324 1510600457689063424,eaede10d19efab27b2020190fcc6c16d540166b88438b63bfc0149d59fae3847,2022-04-03 20:49:49,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \n#include \n#include \nusing namespace std;\nchar DFS(map> graph, int n, int m)\n{\n\tint* visit = new int[n + 1](); int numOfvisited = 0; int numOfEnd = 0;\n\tstack q;\n\tq.push(1); visit[1] = 1; numOfvisited++;\n\twhile (numOfvisited<=n)\n\t{\n\t\tint vertice = q.top();\n\t\tbool ifend = true;\n\t\tfor (int i = 0; i < graph[vertice].size(); i++)\n\t\t{\n\t\t\tint x = graph[vertice][i];\n\t\t\tif (!visit[x])\n\t\t\t{\n\t\t\t\tq.push(x); numOfvisited++; visit[x] = 1; ifend = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (ifend)\n\t\t{\n\t\t\tnumOfEnd++;\n\t\t\tint cur = q.top();\n\t\t\tfor (int i = 0; i < graph[cur].size(); i++)\n\t\t\t{\n\t\t\t\tif (graph[cur][i] == 1)return 'C';\n\t\t\t}\n\t\t\tbool tmp1=true;\n\t\t\twhile (tmp1)\n\t\t\t{\n\t\t\t\tq.pop();\n\t\t\t\tint x = q.top();\n\t\t\t\tfor (int i = 0; i < graph[x].size(); i++)\n\t\t\t\t{\n\t\t\t\t\tif (!visit[graph[x][i]])\n\t\t\t\t\t{\n\t\t\t\t\t\ttmp1 = false; q.push(graph[x][i]); numOfvisited++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif (numOfEnd == 1)return 'B';\n\telse return 'D';\n}\nint main()\n{\n\tint t; cin >> t;\n\tvector v;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m; cin >> n >> m;\n\t\tmap> graph;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tint first, second; cin >> first >> second;\n\t\t\tgraph[first].push_back(second);\n\t\t\tgraph[second].push_back(first);\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tv.push_back('A'); continue;\n\t\t}\n\t\tif (m ==n * (n - 1) / 2)\n\t\t{\n\t\t\tv.push_back('E'); continue;\n\t\t}\n\t\tv.push_back(DFS(graph, n, m));\n\t}\n\tfor (int i = 0; i < v.size(); i++)\n\t{\n\t\tcout << v[i] << endl;\n\t}\n}\n",MULTIPLE_ERROR,575,24748 1510600477648482304,8c9db4400a9b9eebbd918957d2110842582f3ba8f1a2fcb95e817216ef3f3e28,2022-04-03 20:49:54,C++,0.0,1510521134800797706,1509437328199348224,582,"//#include\n#include\n#include\n#include\n#include\n#include\n\nusing namespace std;\n\nconst int N = 1000010;\n\nstruct edge {\n\tint a, b;\n}tu[N];\n\nint arr[N];\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\tint n, m;\n\twhile (T--)\n\t{\n\t\tcin >> n >> m;\n\t\tint a, b;\n\t\tbool is_lian;\n\t\tbool is_quan;\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\ttu[i] = { a,b };\n\t\t\tarr[a]++;\n\t\t\tarr[b]++;\n\t\t\t\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] > 2)\n\t\t\t{\n\t\t\t\tis_lian = false;\n\t\t\t\tbreak;\n\t\t\t}\n if(i==n)\n {\n is_lian=true;\n }\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] != 2)\n\t\t\t{\n\t\t\t\tis_quan = false;\n\t\t\t\tbreak;\n\t\t\t}\n if(i==n)\n {\n is_quan=true;\n }\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (n>1&&is_lian&&!is_quan)\n\t\t{\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse if (n > 2 && is_quan) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 3)\n\t\t{\n\t\t\tif (n * (n - 1) == m * 2)\n\t\t\t{\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse if(n*(n-1)>m*2) {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}",WRONG_ANSWER,202,1464 1510600481751785472,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 20:49:55,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n\treturn;\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\""<0:\n T -= 1\n n,m = map(int,input().split())\n if n == 1:\n print(\""A\"")\n sys.exit()\n elif m==n:\n print('C')\n sys.exit()\n elif m==n-1:\n k = 0\n d = {}\n for i in range(1,n+1):\n d[i] = []\n while m>0:\n m -= 1\n a,b = map(int,input().split())\n d[a].append(b)\n d[b].append(a)\n for i in range(1,n+1):\n if len(d[i])>=3:\n print(\""D\"")\n sys.exit()\n if len(d[i])==1:\n k += 1\n if k==2:\n print(\""B\"")\n sys.exit()\n print(\""E\"")\n",WRONG_ANSWER,32,3136 1510600690686115840,b5996ef651c3ecd72601b1d7cfc7c4ccd7d6aa58490c347a8be22b90f85588e5,2022-04-03 20:50:44,C++,0.0,1510521134800797706,1509437328199348224,582,"// 简单的计算.cpp : 此文件包含 \""main\"" 函数。程序执行将在此处开始并结束。\n//\n\n#include \n#include\n#include\n#include\n#include\nusing namespace std;\nstruct edge\n{\n int from;\n int to;\n edge(int a, int b) {\n from = a;\n to = b;\n }\n};\nvectortu[1000000];\nint main()\n{\n int n;\n cin >> n;\n for (int p = 0; p < n; p++) {\n int n2, m;\n cin >> n2 >> m;\n if (n2 == 1) {\n cout << \""A\""<> a >> b;\n tu[a].push_back(edge(b, a));\n tu[b].push_back(edge(a, b));\n\n }\n int flagd = 1;\n for (int i = 1; i <= n2; i++) {\n if (tu[i].size() != n2 - 1) {\n flagd = 0;\n }\n }\n if (flagd == 1) {\n cout << \""E\""<“开始执行(不调试)”菜单\n// 调试程序: F5 或调试 >“开始调试”菜单\n\n// 入门使用技巧: \n// 1. 使用解决方案资源管理器窗口添加/管理文件\n// 2. 使用团队资源管理器窗口连接到源代码管理\n// 3. 使用输出窗口查看生成输出和其他消息\n// 4. 使用错误列表窗口查看错误\n// 5. 转到“项目”>“添加新项”以创建新的代码文件,或转到“项目”>“添加现有项”以将现有代码文件添加到项目\n// 6. 将来,若要再次打开此项目,请转到“文件”>“打开”>“项目”并选择 .sln 文件\n",WRONG_ANSWER,42,23876 1510600746440998912,4192d9fc583eab46e860b8a0384d741b4e46fdf9e8c0bf75f20e09006a907a69,2022-04-03 20:50:58,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include\nusing namespace std;\ntypedef long long ll;\nint num[1000005];\nint main()\n{\n int t; cin >> t;\n while (t--)\n {\n int n, m; cin >> n >> m;\n int num1 = 0;\n int num2 = 0;\n int num3 = 0;\n if (n == 1)\n {\n cout << 'A' << endl;\n return 0;\n }\n else\n {\n for (int i = 0; i < m; i++)\n {\n int a, b; cin >> a >> b;\n num[a]++;\n num[b]++;\n }\n int flag1 = 1, flag2 = 1, flag3 = 1;\n for (int i = 0; i < n; i++)\n {\n if (num[i] == 1)\n num1++;\n if (num[i] == 2)\n num2++;\n if (num[i] == n - 1)\n num3++;\n }\n }\n if (num2 == n)\n cout << 'C' << endl;\n else if (num1 == 2 && num2 == n - 2)\n cout << 'B' << endl;\n else if (num3 == n)\n cout << 'E' << endl;\n else\n {\n cout << 'D' << endl;\n }\n }\n}",WRONG_ANSWER,8,472 1510600789080293376,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 20:51:08,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n }\n if(n==1) cout<<\""A\""<\nusing namespace std;\nint m,n;\nint op[100001][100001];\nbool test1(){\n\tint op1[n];\n\tfor(int i=0;i1){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nbool test2(){\n\tfor(int i=0;i>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\top[a][b]=1;\n\t\t\top[b][a]=1;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\"";\n return ;\n }\n else if(n==2)\n {\n cout<<\""B\"";\n return ;\n }\n bool falg=true;\n bool falg1=true;\n int cnt1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]!=2)\n {\n falg=false;\n if(d[i]!=1)\n {\n falg1=false;\n }\n }\n if(d[i]==1)\n {\n cnt1++;\n }\n\n }\n if(falg)\n {\n cout<<\""C\"";\n return ;\n }\n\n if(falg1&&cnt1==2)\n {\n cout<<\""B\"";\n return ;\n }\n\n if(n>T;\n while(T--)\n {\n\n solve();\n if(T!=0)\n {\n\n cout<\n#include\n#include\n#include\n#include\n#include\n\nusing namespace std;\n\nconst int N = 1000010;\n\nstruct edge {\n\tint a, b;\n}tu[N];\n\nint arr[N];\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\tint n, m;\n\twhile (T--)\n\t{\n\t\tcin >> n >> m;\n\t\tint a, b;\n\t\tbool is_lian;\n\t\tbool is_quan;\n memset(arr, 0, sizeof arr);\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\ttu[i] = { a,b };\n\t\t\tarr[a]++;\n\t\t\tarr[b]++;\n\t\t\t\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] > 2)\n\t\t\t{\n\t\t\t\tis_lian = false;\n\t\t\t\tbreak;\n\t\t\t}\n if(i==n)\n {\n is_lian=true;\n }\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] != 2)\n\t\t\t{\n\t\t\t\tis_quan = false;\n\t\t\t\tbreak;\n\t\t\t}\n if(i==n)\n {\n is_quan=true;\n }\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (n>1&&is_lian&&!is_quan)\n\t\t{\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse if (n > 2 && is_quan) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 3)\n\t\t{\n\t\t\tif (n * (n - 1) == m * 2)\n\t\t\t{\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse if(n*(n-1)>m*2) {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}",COMPILE_ERROR,0,0 1510600956194676736,8c9db4400a9b9eebbd918957d2110842582f3ba8f1a2fcb95e817216ef3f3e28,2022-04-03 20:51:48,C++,25.0,1510521134800797706,1509437328199348224,582,"#include\n\n\nusing namespace std;\n\nconst int N = 1000010;\n\nstruct edge {\n\tint a, b;\n}tu[N];\n\nint arr[N];\n\nint main()\n{\n\tint T;\n\tcin >> T;\n\tint n, m;\n\twhile (T--)\n\t{\n\t\tcin >> n >> m;\n\t\tint a, b;\n\t\tbool is_lian;\n\t\tbool is_quan;\n memset(arr, 0, sizeof arr);\n\t\tfor (int i = 0; i < m; i++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\ttu[i] = { a,b };\n\t\t\tarr[a]++;\n\t\t\tarr[b]++;\n\t\t\t\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] > 2)\n\t\t\t{\n\t\t\t\tis_lian = false;\n\t\t\t\tbreak;\n\t\t\t}\n if(i==n)\n {\n is_lian=true;\n }\n\t\t}\n\n\t\tfor (int i = 1; i <= n; i++)\n\t\t{\n\t\t\tif (arr[i] != 2)\n\t\t\t{\n\t\t\t\tis_quan = false;\n\t\t\t\tbreak;\n\t\t\t}\n if(i==n)\n {\n is_quan=true;\n }\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (n>1&&is_lian&&!is_quan)\n\t\t{\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse if (n > 2 && is_quan) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 3)\n\t\t{\n\t\t\tif (n * (n - 1) == m * 2)\n\t\t\t{\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t}\n\t\t\telse if(n*(n-1)>m*2) {\n\t\t\t\tcout << \""D\"" << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}",ACCEPTED,210,4976 1510600967958970368,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 20:51:51,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=true;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tputs(\""E\"");\n\t}\n}",WRONG_ANSWER,399,11036 1510600998501347328,fe1e154510817bc5eeefef6ea49585d173a2e3d26bd988bf921f0e54fee56597,2022-04-03 20:51:58,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint m,n;\nint op[100001][100001];\nbool test1(){\n\tint op1[n];\n\tfor(int i=0;i1){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nbool test2(){\n\tfor(int i=0;i>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\top[a][b]=1;\n\t\t\top[b][a]=1;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<0:\n T -= 1\n n,m = map(int,input().split())\n if n == 1:\n print(\""A\"")\n sys.exit()\n elif m==n:\n print('C')\n sys.exit()\n elif m==n-1:\n k = 0\n d = {}\n for i in range(1,n+1):\n d[i] = []\n while m>0:\n m -= 1\n a,b = map(int,input().split())\n d[a].append(b)\n d[b].append(a)\n for i in range(1,n+1):\n if len(d[i])>=3:\n print(\""D\"")\n sys.exit()\n if len(d[i])==2:\n k += 1\n if k==n-2:\n print(\""B\"")\n sys.exit()\n print(\""E\"")\n",WRONG_ANSWER,33,3268 1510601139984154624,fe1e154510817bc5eeefef6ea49585d173a2e3d26bd988bf921f0e54fee56597,2022-04-03 20:52:32,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint m,n;\nint op[10001][10001];\nbool test1(){\n\tint op1[n];\n\tfor(int i=0;i1){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nbool test2(){\n\tfor(int i=0;i>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\top[a][b]=1;\n\t\t\top[b][a]=1;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\nusing namespace std;\nint m,n;\nint op[1001][1001];\nbool test1(){\n\tint op1[n];\n\tfor(int i=0;i1){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nbool test2(){\n\tfor(int i=0;i>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\top[a][b]=1;\n\t\t\top[b][a]=1;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\nusing namespace std;\n\nint main()\n{\n cout<<\""A\"";\n}",WRONG_ANSWER,8,444 1510601272154517504,5a31b8f8c8c717ecfcaad94533b0fcf0af9285cdd7fbc6b0f93b00dd314a869a,2022-04-03 20:53:03,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main()\n{\n cout<<\""B\"";\n}",WRONG_ANSWER,8,476 1510601285959245824,fe1e154510817bc5eeefef6ea49585d173a2e3d26bd988bf921f0e54fee56597,2022-04-03 20:53:06,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint m,n;\nint op[1000001][1000001];\nbool test1(){\n\tint op1[n];\n\tfor(int i=0;i1){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nbool test2(){\n\tfor(int i=0;i>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\top[a][b]=1;\n\t\t\top[b][a]=1;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\nusing namespace std;\n\nint main()\n{\n cout<<\""A\"";\n}",WRONG_ANSWER,8,328 1510601327503097856,5a31b8f8c8c717ecfcaad94533b0fcf0af9285cdd7fbc6b0f93b00dd314a869a,2022-04-03 20:53:16,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main()\n{\n cout<<\""C\"";\n}",WRONG_ANSWER,8,456 1510601344741142528,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 20:53:20,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=true;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\tputs(\""E\"");\n\t}\n}",WRONG_ANSWER,407,10576 1510601355478560768,5a31b8f8c8c717ecfcaad94533b0fcf0af9285cdd7fbc6b0f93b00dd314a869a,2022-04-03 20:53:23,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main()\n{\n cout<<\""D\"";\n}",WRONG_ANSWER,8,456 1510601400173064192,4192d9fc583eab46e860b8a0384d741b4e46fdf9e8c0bf75f20e09006a907a69,2022-04-03 20:53:34,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include\nusing namespace std;\ntypedef long long ll;\nint num[1000005];\nint main()\n{\n int t; cin >> t;\n while (t--)\n {\n int n, m; cin >> n >> m;\n int num1 = 0;\n int num2 = 0;\n int num3 = 0;\n if (n == 1)\n {\n cout << 'A' << endl;\n return 0;\n }\n else\n {\n for (int i = 0; i < m; i++)\n {\n int a, b; cin >> a >> b;\n num[a]++;\n num[b]++;\n }\n int flag1 = 1, flag2 = 1, flag3 = 1;\n for (int i = 0; i < n; i++)\n {\n if (num[i] == 1)\n num1++;\n if (num[i] == 2)\n num2++;\n if (num[i] == n - 1)\n num3++;\n }\n }\n if (num2 == n&&n>2)\n cout << 'C' << endl;\n else if (num1 == 2 && num2 == n - 2)\n cout << 'B' << endl;\n else if (num3 == n&&n>3)\n cout << 'E' << endl;\n else\n {\n cout << 'D' << endl;\n }\n }\n}",WRONG_ANSWER,9,456 1510601428729159680,e43a6b275382d4de707ad9fe9a0c910690c66d7d8d6f9b28f68d2e75883214c5,2022-04-03 20:53:40,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\"";\n return ;\n }\n else if(n==2)\n {\n cout<<\""B\"";\n return ;\n }\n bool falg=true;\n bool falg1=true;\n int cnt1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]!=2)\n {\n falg=false;\n if(d[i]!=1)\n {\n falg1=false;\n }\n }\n if(d[i]==1)\n {\n cnt1++;\n }\n\n }\n if(falg)\n {\n cout<<\""C\"";\n return ;\n }\n\n if(falg1&&cnt1==2)\n {\n cout<<\""B\"";\n return ;\n }\n\n if(n>m)\n {\n cout<<\""D\"";\n return ;\n }\n\n cout<<\""E\"";\n}\nint main()\n{\n int T;\n cin>>T;\n while(T--)\n {\n\n solve();\n if(T!=0)\n {\n\n cout<\nusing namespace std;\nint main()\n{\n\tint t;\n\tcin>>t;\n\tfor(int i=1;i<=t;++i){\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\tint n,m;\n\t\tint b[100000][2];\n\t\tcin>>n>>m;\n\t\tchar a;\n\t\ta=65;\n\t\tif(m==0||n==1)cout<\nusing namespace std;\n\nint main()\n{\n cout<<\""D\"";\n cout<<\""D\"";\n cout<<\""D\"";\n}",WRONG_ANSWER,8,328 1510601563415920640,34e4b43252a14f6c5f9490f9d98b4eb249ced0220e8053654d83f7b39884a88e,2022-04-03 20:54:12,Python,0.0,1510521134800797706,1509437328199348224,582,"import sys\nT = int(input())\nwhile T>0:\n T -= 1\n n,m = map(int,input().split())\n if n == 1:\n print(\""A\"")\n sys.exit()\n \n elif m==n-1:\n k = 0\n d = {}\n for i in range(1,n+1):\n d[i] = []\n while m>0:\n m -= 1\n a,b = map(int,input().split())\n d[a].append(b)\n d[b].append(a)\n for i in range(1,n+1):\n if len(d[i])>=3:\n print(\""D\"")\n sys.exit()\n if len(d[i])==2:\n k += 1\n if k==n-2:\n print(\""B\"")\n sys.exit()\n elif k==n:\n print(\""C\"")\n sys.exit()\n print(\""E\"")\n",WRONG_ANSWER,34,3416 1510601571759120384,5a31b8f8c8c717ecfcaad94533b0fcf0af9285cdd7fbc6b0f93b00dd314a869a,2022-04-03 20:54:14,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main()\n{\n cout<<\""D\"";\n cout<<\""D\"";\n\n}",WRONG_ANSWER,8,484 1510601600489373696,5a31b8f8c8c717ecfcaad94533b0fcf0af9285cdd7fbc6b0f93b00dd314a869a,2022-04-03 20:54:21,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main()\n{\n cout<<\""A\"";\n cout<<\""D\"";\n\n}",WRONG_ANSWER,8,456 1510601610107641856,6e364ead73a2681d3a9c2f2e85605ae7c500a24f3544101bbba9138b30f9a6da,2022-04-03 20:54:24,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\n\nint t, n, m;\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tcin >> n >> m;\n\t\twhile(m --)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 1 && m == n - 1)\n\t\t{\n\t\t\tcout << 'B' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 2 && m == n)\n\t\t{\n\t\t\tcout << 'C' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tcout << 'D' << endl;\n\t}\n\treturn 0;\n}",WRONG_ANSWER,7,456 1510601627887296512,5a31b8f8c8c717ecfcaad94533b0fcf0af9285cdd7fbc6b0f93b00dd314a869a,2022-04-03 20:54:28,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main()\n{\n cout<<\""A\"";\n cout<<\""B\"";\n\n}",WRONG_ANSWER,8,488 1510601643313217536,035ca87c9ba0ba2182a0ad3ffd27606f6d7dfef3ba4eb678c30dd4ea2747b483,2022-04-03 20:54:32,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\nint main(){\n\n int T;\n cin>>T;\n for(int i=0;i>n>>m;\n if(n==1)\n {\n \tcout<<\""A\""<>x>>y;\n \t\t\tmap[x][y]=1;\n \t\t\tdu[x]++;\n \t\t\tdu[y]++;\n\t\t }\n\t\t if(n>1)\n\t\t {\n\t\t \tint num=0;\n\t\t \tbool flag=true;\n\t\t \tfor(int j=1;j2)\n\t\t \t\t{\n\t\t \t\t\tflag=false;\n\t\t \t\t\tbreak;\n\t\t\t\t }\n\t\t \t\tif(du[j]==1)\n\t\t \t\t{\n\t\t \t\t\tnum++;\n\t\t\t\t }\n\t\t\t }\n\t\t\t if(num==2&&flag)\n\t\t\t {\n\t\t\t \tcout<<\""B\"";\n\t\t\t \tcontinue ;\n\t\t\t }\n\t\t }\n\t\tif(n>2)\n\t\t{\n\t\t\tfor(int j=1;j<=n;j++)\n\t\t\t{\n\t\t\t\tif(du[j]!=2)\n\t\t\t\t{\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse if(j==n&&du[j]==2){\n\t\t\t\t\tcout<<\""C\""<3)\n\t\t{\n\t\t\tbool flag=false;\n\t\t\tfor(int j=1;j<=n;j++)\n\t\t\t{\n\t\t\t\tif(du[j]>2)\n\t\t\t\t{\n\t\t\t\t\tflag=true;\n\t\t\t\t\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)\n\t\t\t{\n\t\t\t\t\tcout<<\""D\""<\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\tputs(\""E\"");\n\t}\n}",WRONG_ANSWER,675,16852 1510601665019469824,5a31b8f8c8c717ecfcaad94533b0fcf0af9285cdd7fbc6b0f93b00dd314a869a,2022-04-03 20:54:37,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main()\n{\n cout<<\""A\"";\n cout<<\""B\"";\n\n}",WRONG_ANSWER,8,460 1510601691351310336,c06cf25eded01cd3f790834c74285be6c6110aa641ecfb9a234fb1bb2e50c8f8,2022-04-03 20:54:43,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N=1e6+10;\nint h[N],ne[N],e[N],idx;\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\nbool st[N];\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(st,0,sizeof st);\n\t\tmemset(h,-1,sizeof h);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tadd(a,b);\n\t\t\tst[b]=1;\n\t\t}\n\t\tif(n==1)cout<<\""A\""<3)cout<<\""E\""<2)cout<<\""C\""<\nusing namespace std;\n \nint ma[1000010]; \nint main()\n{\n\tint T; cin>>T;\n\tint n,m; \n\t\n\tfor(int i = 1;i<=T;i++)\n\t{\n\t\tfor(int i =0;i<1000010;i++) ma[i] =0;\n\t\tcin>>n>>m;int u,v;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<>u>>v;\n\t\t\tma[u]++;\n\t\t\tma[v]++;\n\t\t}\n\t\tint sum = 0,sum1 = 0;\n\t\tbool flag = 1;\n\t\tint num2 = ma[1];\n\t\tint j=0,o=0; \n\t\tfor(int i = 1;i<=n;i++)\n\t\t{\n\t\t\tif(ma[i] == 1)\n\t\t\t{\n\t\t\t\tsum ++;\n\t\t\t}\n\t\t\telse if(ma[i] == 2)\n\t\t\t{\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\tif(ma[i]%2==0)\n\t\t\t{\n\t\t\t\to++;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tif(ma[i] != num2) flag = 0;\n\t\t}\n\t\tif(flag && num2 ==n-1 && n>3) \n\t\t{\n\t\t\tcout<<'E'<1)//链 \n\t\t{\n\t\t\tcout<<'B'<2)//圈 \n\t\t{\n\t\t\tcout<<'C'< 2 &&n>3)\n\t\t{\n\t\t\tcout<<'D'<\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar)\n{\n\tif(flag)return;\n\tif(start==tar&&fa!=-1)\n\t{\n\t\tflag=true;\n\t\treturn ;\n\t}\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(mp[start][i]&&!st[i]&&i!=fa)\n\t\t{\n\t\t\tst[i]=1;\n\t\t\tdfs(i,start,tar);\n\t\t}\n\t}\n\treturn;\n}\n\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tflag=false;\n\t\tmemset(st,false,sizeof st);\n\t\tmemset(mp,0,sizeof mp);\n\t\tmemset(du,0,sizeof du);\n\t\tint maxd=0;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tmp[a][b]=mp[b][a]=1;\n\t\t\tdu[a]++,du[b]++;\n\t\t\tmaxd=max(du[a],du[b]);\n\t\t}\n\t\tif(n==1)\n\t\tcout<<\""A\""<\nusing namespace std;\nconst int N=1000005;\nint d[N];\nvoid solve()\n{\n int n,m;\n cin>>n>>m;\n memset(d,0,sizeof d);\n for(int i=0;i>x>>y;\n d[x]++;\n d[y]++;\n }\n if(n==1)\n {\n cout<<\""A\"";\n return ;\n }\n else if(n==2)\n {\n cout<<\""B\"";\n return ;\n }\n bool falg=true;\n bool falg1=true;\n int cnt1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]!=2)\n {\n falg=false;\n if(d[i]!=1)\n {\n falg1=false;\n }\n }\n if(d[i]==1)\n {\n cnt1++;\n }\n\n }\n if(falg)\n {\n cout<<\""C\"";\n return ;\n }\n\n if(falg1&&cnt1==2)\n {\n cout<<\""B\"";\n return ;\n }\n\n if(n>m)\n {\n cout<<\""D\"";\n return ;\n }\n\n cout<<\""E\"";\n}\nint main()\n{\n int T;\n cin>>T;\n while(T--)\n {\n\n solve();\n if(T!=0)\n {\n\n cout<\nusing namespace std;\n \nint ma[1000010]; \nint main()\n{\n\tint T; cin>>T;\n\tint n,m; \n\t\n\tfor(int i = 1;i<=T;i++)\n\t{\n\t\tfor(int i =0;i<1000010;i++) ma[i] =0;\n\t\tcin>>n>>m;int u,v;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<>u>>v;\n\t\t\tma[u]++;\n\t\t\tma[v]++;\n\t\t}\n\t\tint sum = 0,sum1 = 0;\n\t\tbool flag = 1;\n\t\tint num2 = ma[1];\n\t\tint j=0,o=0; \n\t\tfor(int i = 1;i<=n;i++)\n\t\t{\n\t\t\tif(ma[i] == 1)\n\t\t\t{\n\t\t\t\tsum ++;\n\t\t\t}\n\t\t\telse if(ma[i] == 2)\n\t\t\t{\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\tif(ma[i]%2==0)\n\t\t\t{\n\t\t\t\to++;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tif(ma[i] != num2) flag = 0;\n\t\t}\n\t\tif(flag && num2 ==n-1 && n>3) \n\t\t{\n\t\t\tcout<<'E'<1)//链 \n\t\t{\n\t\t\tcout<<'B'<2)//圈 \n\t\t{\n\t\t\tcout<<'C'< 2 &&n>3)\n\t\t{\n\t\t\tcout<<'D'<\nusing namespace std;\n \nint ma[1000010]; \nint main()\n{\n\tint T; cin>>T;\n\tint n,m; \n\t\n\tfor(int i = 1;i<=T;i++)\n\t{\n\t\tfor(int i =0;i<1000010;i++) ma[i] =0;\n\t\tcin>>n>>m;int u,v;\n\t\tif(n==1)\n\t\t{\n\t\t\tcout<<'A'<>u>>v;\n\t\t\tma[u]++;\n\t\t\tma[v]++;\n\t\t}\n\t\tint sum = 0,sum1 = 0;\n\t\tbool flag = 1;\n\t\tint num2 = ma[1];\n\t\tint j=0,o=0; \n\t\tfor(int i = 1;i<=n;i++)\n\t\t{\n\t\t\tif(ma[i] == 1)\n\t\t\t{\n\t\t\t\tsum ++;\n\t\t\t}\n\t\t\telse if(ma[i] == 2)\n\t\t\t{\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\tif(ma[i]%2==0)\n\t\t\t{\n\t\t\t\to++;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tif(ma[i] != num2) flag = 0;\n\t\t}\n\t\tif(flag && num2 ==n-1 && n>3) \n\t\t{\n\t\t\tcout<<'E'<1)//链 \n\t\t{\n\t\t\tcout<<'B'<2)//圈 \n\t\t{\n\t\t\tcout<<'C'< 2 &&n>3)\n\t\t{\n\t\t\tcout<<'D'<\n#include\n#include\n#include\n#include\nusing namespace std;\nstruct edge\n{\n int from;\n int to;\n edge(int a, int b) {\n from = a;\n to = b;\n }\n};\nvectortu[1000000];\nint main()\n{\n int n;\n cin >> n;\n for (int p = 0; p < n; p++) {\n int n2, m;\n cin >> n2 >> m;\n if (n2 == 1) {\n cout << \""A\""<> a >> b;\n tu[a].push_back(edge(b, a));\n tu[b].push_back(edge(a, b));\n\n }\n int flagd = 1;\n for (int i = 1; i <= n2; i++) {\n if (tu[i].size() != n2 - 1) {\n flagd = 0;\n }\n }\n if (flagd == 1&&n2>3) {\n cout << \""E\""<“开始执行(不调试)”菜单\n// 调试程序: F5 或调试 >“开始调试”菜单\n\n// 入门使用技巧: \n// 1. 使用解决方案资源管理器窗口添加/管理文件\n// 2. 使用团队资源管理器窗口连接到源代码管理\n// 3. 使用输出窗口查看生成输出和其他消息\n// 4. 使用错误列表窗口查看错误\n// 5. 转到“项目”>“添加新项”以创建新的代码文件,或转到“项目”>“添加现有项”以将现有代码文件添加到项目\n// 6. 将来,若要再次打开此项目,请转到“文件”>“打开”>“项目”并选择 .sln 文件\n",WRONG_ANSWER,40,24000 1510602264049238016,035ca87c9ba0ba2182a0ad3ffd27606f6d7dfef3ba4eb678c30dd4ea2747b483,2022-04-03 20:57:00,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\nint main(){\n\n int T;\n cin>>T;\n for(int i=0;i>n>>m;\n if(n==1)\n {\n \tcout<<\""A\""<\n#include\nusing namespace std;\nconst int N=1e6+10;\nint h[N],ne[N],e[N],idx;\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\nbool st[N];\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(st,0,sizeof st);\n\t\tmemset(h,-1,sizeof h);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tadd(a,b);\n\t\t\tst[b]=1;\n\t\t}\n\t\tif(n==1)cout<<\""A\""<3)cout<<\""E\""<2)cout<<\""C\""<\n#include\n#include\nusing namespace std;\nint main(){\n\n int T;\n cin>>T;\n for(int i=0;i>n>>m;\n if(n==1)\n {\n \tcout<<\""A\"";\n }\n\n }\n\n\treturn 0;\n} ",WRONG_ANSWER,8,452 1510602381586948096,34e4b43252a14f6c5f9490f9d98b4eb249ced0220e8053654d83f7b39884a88e,2022-04-03 20:57:28,Python,0.0,1510521134800797706,1509437328199348224,582,"import sys\nT = int(input())\nwhile T>0:\n T -= 1\n n,m = map(int,input().split())\n if n == 1:\n print(\""A\"")\n sys.exit()\n \n elif m==n-1:\n k = 0\n o = 0\n d = {}\n for i in range(1,n+1):\n d[i] = []\n while m>0:\n m -= 1\n a,b = map(int,input().split())\n d[a].append(b)\n d[b].append(a)\n for i in range(1,n+1):\n if len(d[i])>=3:\n print(\""D\"")\n sys.exit()\n if len(d[i])==2:\n k += 1\n if len(d[i])==1:\n o += 1\n if k==n-2 or (n==2 and o==2):\n print(\""B\"")\n sys.exit()\n elif k==n:\n print(\""C\"")\n sys.exit()\n print(\""E\"")\n",WRONG_ANSWER,33,3136 1510602396023742464,fbb2f0c603242b0fd46bf10128c91f572cbd038ef9f8aa5e3aa5bc99ae9cc89e,2022-04-03 20:57:31,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<'A'<\n#include\n#include\nusing namespace std;\nint main()\n{\n int data[9];\n for(int i=0;i<9;i++)\n {\n \tcin>>data[i];\n }\n cout<<\""D\"";\n}",WRONG_ANSWER,9,452 1510602662278160384,fbb2f0c603242b0fd46bf10128c91f572cbd038ef9f8aa5e3aa5bc99ae9cc89e,2022-04-03 20:58:34,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<'A'<\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=2;i<=n;i++)\n {\n if(d[i]!=d[i-1])\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n if(m==1)flag=1;\n else{\n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n }\n }\n if(flag==1)cout<<'A'<\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,15,4424 1510602919665819648,34e4b43252a14f6c5f9490f9d98b4eb249ced0220e8053654d83f7b39884a88e,2022-04-03 20:59:36,Python,0.0,1510521134800797706,1509437328199348224,582,"import sys\nT = int(input())\nwhile T>0:\n T -= 1\n n,m = map(int,input().split())\n if n == 1:\n print(\""A\"")\n sys.exit()\n \n elif m==n-1:\n k = 0\n o = 0\n d = {}\n for i in range(1,n+1):\n d[i] = []\n while m>0:\n m -= 1\n a,b = map(int,input().split())\n if b not in d[a]:\n d[a].append(b)\n if a not in d[b]:\n d[b].append(a)\n for i in range(1,n+1):\n if len(d[i])>=3:\n print(\""D\"")\n sys.exit()\n if len(d[i])==2:\n k += 1\n if len(d[i])==1:\n o += 1\n if k==n-2 or (n==2 and o==2):\n print(\""B\"")\n sys.exit()\n elif k==n:\n print(\""C\"")\n sys.exit()\n print(\""E\"")\n",WRONG_ANSWER,31,3184 1510602950460399616,ab6ad9bbaa0f264a3b862710a38569d6ffe806d131ff81f0c1535514c30e33fc,2022-04-03 20:59:43,C++,0.0,1510521134800797706,1509437328199348224,582,#include\n\nusing namespace std;\nint main(){\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\treturn 0;\n},WRONG_ANSWER,7,456 1510602955723522048,43112248ceaa8e186b7fe7deeab5b882d46b6b1226fc1028598c2a4332d9429d,2022-04-03 20:59:44,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main(){\n\tint t,m,n,a[1000010][2];\n\tcin>>t;\n\tcin>>n>>m;\n\tfor(int i=0;i>a[i][j];\n\t\t}\n\t}if(n<=3){\n\t\tif(m==0) cout<<'A'<\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,669,16852 1510603275979603968,4192d9fc583eab46e860b8a0384d741b4e46fdf9e8c0bf75f20e09006a907a69,2022-04-03 21:01:01,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include\nusing namespace std;\ntypedef long long ll;\nint num[1000005];\nint main()\n{\n int t; cin >> t;\n while (t--)\n {\n int n, m; cin >> n >> m;\n int num1 = 0;\n int num2 = 0;\n int num3 = 0;\n if (n == 1)\n {\n cout << 'A' << endl;\n return 0;\n }\n else\n {\n for (int i = 0; i < m; i++)\n {\n int a, b; cin >> a >> b;\n num[a]++;\n num[b]++;\n }\n int flag1 = 1, flag2 = 1, flag3 = 1;\n for (int i = 1; i <= n; i++)\n {\n if (num[i] == 1)\n num1++;\n if (num[i] == 2)\n num2++;\n if (num[i] == n - 1)\n num3++;\n }\n }\n if (num2 == n&&n>2)\n cout << 'C' << endl;\n else if (num1 == 2 && num2 == n - 2)\n cout << 'B' << endl;\n else if (num3 == n&&n>3)\n cout << 'E' << endl;\n else\n {\n cout << 'D' << endl;\n }\n }\n}",WRONG_ANSWER,6,456 1510603291406254080,6e364ead73a2681d3a9c2f2e85605ae7c500a24f3544101bbba9138b30f9a6da,2022-04-03 21:01:04,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\n\nint t, n, m;\nint a[100005];\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tbool is_ = false;\n\t\tcin >> n >> m;\n\t\twhile(m --)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t\ta[i] ++;\n\t\t\ta[j] ++;\n\t\t\tif(a[i] > 2 || a[j] > 2) is_ = true;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 1 && m == n - 1)\n\t\t{\n\t\t\tcout << 'B' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 2 && m == n)\n\t\t{\n\t\t\tif(!is_)\n\t\t\t{\n\t\t\t\tcout << 'C' << endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 3)\n\t\t{\n\t\t\tcout << 'D' << endl;\n\t\t\tbreak;\n\t\t}\n\t}\n\treturn 0;\n}",WRONG_ANSWER,8,604 1510603311009886208,c06cf25eded01cd3f790834c74285be6c6110aa641ecfb9a234fb1bb2e50c8f8,2022-04-03 21:01:09,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N=1e6+10;\nint h[N],ne[N],e[N],idx;\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\nbool st[N];\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(st,0,sizeof st);\n\t\tmemset(h,-1,sizeof h);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tadd(a,b);\n\t\t\tst[b]=1;\n\t\t}\n\t\tif(n==1)cout<<\""A\""<3)cout<<\""E\""<\nusing namespace std;\nint main(){\n int t;\n cin>>t;\n while(t--){\n int n,m;\n cin>>n>>m;\n if(n==1) cout<<\""A\"";\n if(n==2) cout<<\""B\"";\n if(n==3&&m<3) cout<<\""B\"";\n }\n}",WRONG_ANSWER,6,452 1510603506121793536,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 21:01:56,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nconst int N = 1000010;\nint rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n rank[a]++;\n rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n#include \nusing namespace std;\n\nconst int N = 1000010;\nint Rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n Rank[a]++;\n Rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n#include\nusing namespace std;\n\nint main(){\n\tint a[1000000][1000000];\n\tint T;\n\tcin>>T;\n\tint n,m;\n\tcin>>n>>m;\n\tfor(int i=0;i>x>>y;\n\t\ta[x][y]=1;\n\t\ta[y][x]=1;\n\t} \n\tif(n==1)\n\t cout<<\""A\"";\n\t\n\t\n\t\n\treturn 0;\n}",WRONG_ANSWER,6,328 1510604072251441152,9980b561e03fb9b154d28eddf2cab08f88e746587d4a71ddf37b0c4893c729fb,2022-04-03 21:04:11,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e4+10;\n\nint g[N][N];\n\n\n\n\nint main(){\n\tint t;\n\tcin>>t;\n\tint cnt=0;\n\twhile(t--){\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\tg[a][b]=1;\n\t\t\tcnt++;\n\t\t}\n\t\tif(cnt==n-1)cout<<\""D\""<\nusing namespace std;\nconst int N=1e4+10;\n\nint g[N][N];\n\n\n\n\nint main(){\n\tint t;\n\tcin>>t;\n\tint cnt=0;\n\twhile(t--){\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\tg[a][b]=1;\n\t\t\tcnt++;\n\t\t}\n\t\tif(cnt==n-1)cout<<\""D\""<\nusing namespace std;\n#include \n\n\nint main() {\n cout<<\""D\"";\n\treturn 0;\n}",WRONG_ANSWER,9,584 1510604260252184576,f41ec44c982aa8de0ad03db515d30f1e4a221c1a61b6c340b1ce0bc15a65f5fb,2022-04-03 21:04:55,C++,25.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint cnt[1000010]={0};\n\n\nint main()\n{\n\tint T;\n\tcin>>T;\n\tint n,m;\n\tint a,b;\n\tfor(int i=0;i>n>>m;\n \n\tif(n==1)\n\t{\n\t\tcout<<\""A\""<>a>>b;\n\t\t\tcnt[a]++;\n\t\t\tcnt[b]++;\n\t\t\t//cout<\n\nusing namespace std;\nlong long T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n*(n-1)/2) {\n\t\tcout << \""E\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tlong long sum, num;\n\tint qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum == 1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tint sum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum != n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1 && av[i] != 1) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) {\n\t\t\tff = false;\n\t\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum == n && ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tcout << \""D\"" << endl;\n}",COMPILE_ERROR,0,0 1510604308209856512,6e364ead73a2681d3a9c2f2e85605ae7c500a24f3544101bbba9138b30f9a6da,2022-04-03 21:05:07,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\n\nint t, n, m;\nint a[100005];\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tbool i_s = true;\n\t\tcin >> n >> m;\n\t\twhile(m --)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t\ta[i] ++;\n\t\t\ta[j] ++;\n\t\t\tif(a[i] > 2 || a[j] > 2) i_s = false;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A';\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 1 && m == n - 1)\n\t\t{\n\t\t\tcout << 'B';\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 2 && m == n && i_s)\n\t\t{\n\t\t\tcout << 'C';\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E';\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 3)\n\t\t{\n\t\t\tcout << 'D';\n\t\t\tbreak;\n\t\t}\n\t\tcout << endl;\n\t}\n\t",COMPILE_ERROR,0,0 1510604310836035584,fe1e154510817bc5eeefef6ea49585d173a2e3d26bd988bf921f0e54fee56597,2022-04-03 21:05:08,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint m,n;\nstruct{\n\tint be;\n\tint en;\n}p[100001];\nbool test1(){\n\tint op1[100001];\n\tfor(int i=0;i2||op1[a2]>2){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nint main(){\n\tint sum;\n\tcin>>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\tp[i].be=a;\n\t\t\tp[i].en=b;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3||d[b]>=3)flag=4;\n \n }\n if(flag==4)\n {\n bool success=false;\n for(int i=1;i<=n;i++)\n {\n if(d[i]!=n-1)\n {\n success=true;\n break;\n }\n }\n if(!success)flag=5;\n }\n else{\n \n int d1=0;\n for(int i=1;i<=n;i++)\n {\n if(d[i]==1)d1++;\n }\n if(d1==2)flag=2;\n else flag=3;\n \n }\n if(flag==1)cout<<'A'<\n\nusing namespace std;\nlong long T, n, m;\nint main() {\n\tcin >> T;\n\tcin >> n >> m;\n\tif (n == 1) {\n\t\tcout << \""A\"" << endl;\n\t\treturn 0;\n\t}\n\tint** arr = new int* [n + 1];\n\tfor (int i = 0; i <= n; i++) {\n\t\tarr[i] = new int[n + 1];\n\t}\n\n\tint x, y;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> x >> y;\n\t\tarr[x][y] = 1;\n\t\tarr[y][x] = 1;\n\t}\n\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tif (n == 3 && m == 3) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n*(n-1)/2) {\n\t\tcout << \""E\"" << endl;\n\t\treturn 0;\n\t}\n\tif (m == n) {\n\t\tcout << \""C\"" << endl;\n\t\treturn 0;\n\t}\n\tlong long sum, num;\n\tint qidian;\n\tfor (int i = 1; i <= n; i++) {\n\t\tsum = 0;\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\tif (arr[j][i] == 1) {\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif (sum == 1) { qidian = i; break; }\n\t}\n\tbool ff = true;\n\tsum = 1;\n\tint yi = qidian;\n\tint* av = new int[n + 1];\n\tav[yi] = 1;\n\twhile (sum != n) {\n\t\tint k = 0;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[yi][i] == 1 && av[i] != 1) {\n\t\t\t\tk++;\n\t\t\t\tav[i] = 1;\n\t\t\t\tyi = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (k > 2) {\n\t\t\tff = false;\n\t\t\tbreak;\n\t\t}\n\t\tif (k == 0)break;\n\t\tsum++;\n\t}\n\tif (sum == n && ff) {\n\t\tcout << \""B\"" << endl;\n\t\treturn 0;\n\t}\n\tcout << \""D\"" << endl;\n}",WRONG_ANSWER,7,452 1510604415211290624,6e364ead73a2681d3a9c2f2e85605ae7c500a24f3544101bbba9138b30f9a6da,2022-04-03 21:05:32,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\n\nint t, n, m;\nint a[100005];\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tbool i_s = true;\n\t\tcin >> n >> m;\n\t\twhile(m --)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t\ta[i] ++;\n\t\t\ta[j] ++;\n\t\t\tif(a[i] > 2 || a[j] > 2) i_s = false;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A';\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 1 && m == n - 1)\n\t\t{\n\t\t\tcout << 'B';\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 2 && m == n && i_s)\n\t\t{\n\t\t\tcout << 'C';\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E';\n\t\t\tbreak;\n\t\t}\n\t\tif(n > 3)\n\t\t{\n\t\t\tcout << 'D';\n\t\t\tbreak;\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}",WRONG_ANSWER,8,324 1510604482458566656,e82da4709fea1cae36b2ec4ad480daa999e75b76466a853aada582870870e05d,2022-04-03 21:05:48,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\nconst int N=1e6+10;\n\nint h[N],ne[N],e[N],idx;\n\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\n\nint main()\n{\t\t\n int t;\n cin>>t;\n while(t--)\n {\n \tmemset(h,-1,sizeof h);\n\t\tmemset(e,0,sizeof e);\n\t\tmemset(ne,0,sizeof ne);\n\t\t\n \tint n,m;\n \tcin>>n>>m;\n \t\n \tif(n==1) cout<<\""A\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l); \t\t\t\n\t\t\t} \t\t\n \t\t\n \t\tint j=0;\n \t\t\n \t\tfor(int i=1;i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tif(j==1) break;\n\t\t\t}\n\t\t\tif(j==1) cout<<\""C\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l);\n\t\t\t}\n\t\t\t\n\t \tint j=0;\n\t \tint cnt=0;\n \t\t\n \t\tfor(int i=1;i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tcnt++;\n \t\t\tif(j==1) break;\n \t\t\tif(cnt==n) break;\n\t\t\t}\t\n\t\tif(j==1) cout<<\""C\""<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=2000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tif(m==n-1){\n\t\tdfs(1,0);\n\t\tint u=0,v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tint u=0,v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n}\n\treturn 0;\n}",SEGMENTATION_FAULT,250,130916 1510604790198845440,e82da4709fea1cae36b2ec4ad480daa999e75b76466a853aada582870870e05d,2022-04-03 21:07:02,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\nconst int N=1e6+10;\n\nint h[N],ne[N],e[N],idx;\n\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\n\nint main()\n{\t\t\n int t;\n cin>>t;\n while(t--)\n {\n \tmemset(h,-1,sizeof h);\n\t\tmemset(e,0,sizeof e);\n\t\tmemset(ne,0,sizeof ne);\n\t\t\n \tint n,m;\n \tcin>>n>>m;\n \t\n \tif(n==1) cout<<\""A\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l); \t\t\t\n\t\t\t} \t\t\n \t\t\n \t\tint j=0;\n \t\t\n \t\tfor(int i=h[1];i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tif(j==1) break;\n\t\t\t}\n\t\t\tif(j==1) cout<<\""C\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l);\n\t\t\t}\n\t\t\t\n\t \tint j=0;\n\t \tint cnt=0;\n \t\t\n \t\tfor(int i=1;i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tcnt++;\n \t\t\tif(j==1) break;\n \t\t\tif(cnt==n) break;\n\t\t\t}\t\n\t\tif(j==1) cout<<\""C\""<\n\nusing namespace std;\nconst int N=1e6+10;\n\nint h[N],ne[N],e[N],idx;\n\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\n\nint main()\n{\t\t\n int t;\n cin>>t;\n while(t--)\n {\n \tmemset(h,-1,sizeof h);\n\t\tmemset(e,0,sizeof e);\n\t\tmemset(ne,0,sizeof ne);\n\t\t\n \tint n,m;\n \tcin>>n>>m;\n \t\n \tif(n==1) cout<<\""A\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l); \t\t\t\n\t\t\t} \t\t\n \t\t\n \t\tint j=0;\n \t\t\n \t\tfor(int i=h[1];i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tif(j==1) break;\n\t\t\t}\n\t\t\tif(j==1) cout<<\""C\""<>l>>r;\n \t\t\tadd(l,r);\n \t\t\tadd(r,l);\n\t\t\t}\n\t\t\t\n\t \tint j=0;\n\t \tint cnt=0;\n \t\t\n \t\tfor(int i=h[1];i!=-1;i=ne[i])\n \t\t{\n \t\t\tj=e[i];\n \t\t\tcnt++;\n \t\t\tif(j==1) break;\n \t\t\tif(cnt==n) break;\n\t\t\t}\t\n\t\tif(j==1) cout<<\""C\""<\n\nusing namespace std;\nlong long T, n, m;\nint main() {\n\tcin >> T;\n\tfor (int r = 0; r < T; r++) {\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint** arr = new int* [n + 1];\n\t\tfor (int i = 0; i <= n; i++) {\n\t\t\tarr[i] = new int[n + 1];\n\t\t}\n\n\t\tint x, y;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tcin >> x >> y;\n\t\t\tarr[x][y] = 1;\n\t\t\tarr[y][x] = 1;\n\t\t}\n\t\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (n == 3 && m == 3) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n * (n - 1) / 2) {\n\t\t\tcout << \""E\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tlong long sum, num;\n\t\tint qidian;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tsum = 0;\n\t\t\tfor (int j = 1; j <= n; j++) {\n\t\t\t\tif (arr[j][i] == 1) {\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (sum == 1) { qidian = i; break; }\n\t\t}\n\t\tbool ff = true;\n\t\tsum = 1;\n\t\tint yi = qidian;\n\t\tint* av = new int[n + 1];\n\t\tav[yi] = 1;\n\t\twhile (sum != n) {\n\t\t\tint k = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (arr[yi][i] == 1 && av[i] != 1) {\n\t\t\t\t\tk++;\n\t\t\t\t\tav[i] = 1;\n\t\t\t\t\tyi = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (k > 2) {\n\t\t\t\tff = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (k == 0)break;\n\t\t\tsum++;\n\t\t}\n\t\tif (sum == n && ff) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \""D\"" << endl;\n\t}\n\t\n}",PARTIAL_ACCEPTED,115,131072 1510604934075510784,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 21:07:36,C++,15.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nconst int N = 1000010;\nint Rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n int n,m;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n Rank[a]++;\n Rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tfor (int r = 0; r < T; r++) {\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint** arr = new int* [n + 1];\n\t\tfor (int i = 0; i <= n; i++) {\n\t\t\tarr[i] = new int[n + 1];\n\t\t}\n\n\t\tint x, y;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tcin >> x >> y;\n\t\t\tarr[x][y] = 1;\n\t\t\tarr[y][x] = 1;\n\t\t}\n\t\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (n == 3 && m == 3) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n * (n - 1) / 2) {\n\t\t\tcout << \""E\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint sum, num;\n\t\tint qidian;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tsum = 0;\n\t\t\tfor (int j = 1; j <= n; j++) {\n\t\t\t\tif (arr[j][i] == 1) {\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (sum == 1) { qidian = i; break; }\n\t\t}\n\t\tbool ff = true;\n\t\tsum = 1;\n\t\tint yi = qidian;\n\t\tint* av = new int[n + 1];\n\t\tav[yi] = 1;\n\t\twhile (sum != n) {\n\t\t\tint k = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (arr[yi][i] == 1 && av[i] != 1) {\n\t\t\t\t\tk++;\n\t\t\t\t\tav[i] = 1;\n\t\t\t\t\tyi = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (k > 2) {\n\t\t\t\tff = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (k == 0)break;\n\t\t\tsum++;\n\t\t}\n\t\tif (sum == n && ff) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \""D\"" << endl;\n\t}\n\t\n}",PARTIAL_ACCEPTED,117,131072 1510605040871424000,af098392bea033208458a25e7e17bba52f89355bbbb95e9ada9144115b27c042,2022-04-03 21:08:02,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=2000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tif(m==n-1){\n\t\tdfs(1,0);\n\t\tint u=0,v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tint u=0,v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n\tif(t!=1)cout<\nusing namespace std;\n#include \n\n\nint main() {\n\tint t;\n\tcin t;\n\twhile (t--) {\n\t\tint n,m;\n\t\tif(n==1){\n\t\t\tcout<<'A'<\n\nusing namespace std;\n\nint t, n, m;\nint a[100005];\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tbool i_s = true;\n\t\tcin >> n >> m;\n\t\twhile(m --)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t\ta[i] ++;\n\t\t\ta[j] ++;\n\t\t\tif(a[i] > 2 || a[j] > 2) i_s = false;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 1 && m == n - 1)\n\t\t{\n\t\t\tcout << 'B';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 2 && m == n && i_s)\n\t\t{\n\t\t\tcout << 'C';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3)\n\t\t{\n\t\t\tcout << 'D';\n\t\t\tcontinue;\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}",WRONG_ANSWER,209,832 1510605154990047232,8f9a4827823e7a686ff0ff06ba160262c7402f4c6b32d8c3f9b4f3f753f08597,2022-04-03 21:08:29,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n#include \n\n\nint main() {\n\tint t;\n\tcin>>t;\n\twhile (t--) {\n\t\tint n, m;\n\t\tif (n == 1) {\n\t\t\tcout << 'A' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif (n == 3) {\n\t\t\tif (m == 1) {\n\t\t\t\tcout << 'A' << endl;\n\t\t\t}\n\t\t\tif (m == 2) {\n\t\t\t\tcout << 'B' << endl;\n\t\t\t}\n\t\t\tif (m == 3) {\n\t\t\t\tcout << 'C' << endl;\n\t\t\t}\n\t\t}\n\t\tif (n == 4) {\n\t\t\tif (m == 6) {\n\t\t\t\tcout << 'E' << endl;\n\t\t\t}\n\t\t\tif (m == 1) {\n\t\t\t\tcout << 'A' << endl;\n\t\t\t}\n\t\t\tif (m == 2) {\n\t\t\t\tcout << 'B' << endl;\n\t\t\t\tif (m == 5 || m == 4) {\n\t\t\t\t\tcout << 'D' << endl;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\n\n\t\treturn 0;\n\t}",COMPILE_ERROR,0,0 1510605175554174976,fe1e154510817bc5eeefef6ea49585d173a2e3d26bd988bf921f0e54fee56597,2022-04-03 21:08:34,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint m,n;\nstruct{\n\tint be;\n\tint en;\n}p[100001];\nbool test1(){\n\tint op1[100001];\n\tfor(int i=0;i2||op1[a2]>2){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nint main(){\n\tint sum;\n\tcin>>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\tp[i].be=a;\n\t\t\tp[i].en=b;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=5000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tif(m==n-1){\n\t\tdfs(1,0);\n\t\tint u=0,v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tint u=0,v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n\tif(t!=1)cout<\nusing namespace std;\n#include \n\n\nint main() {\n\tint t;\n\tcin >> t;\n\twhile (t--) {\n\t\tint n, m;\n\t\tif (n == 1) {\n\t\t\tcout << 'A' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif (n == 3) {\n\t\t\tif (m == 1) {\n\t\t\t\tcout << 'A' << endl;\n\t\t\t}\n\t\t\tif (m == 2) {\n\t\t\t\tcout << 'B' << endl;\n\t\t\t}\n\t\t\tif (m == 3) {\n\t\t\t\tcout << 'C' << endl;\n\t\t\t}\n\t\t}\n\t\tif (n == 4) {\n\t\t\tif (m == 6) {\n\t\t\t\tcout << 'E' << endl;\n\t\t\t}\n\t\t\tif (m == 1) {\n\t\t\t\tcout << 'A' << endl;\n\t\t\t}\n\t\t\tif (m == 2) {\n\t\t\t\tcout << 'B' << endl;\n\t\t\t\tif (m == 5 || m == 4) {\n\t\t\t\t\tcout << 'D' << endl;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\n\n\t\t\n\t}\n\treturn 0;}",WRONG_ANSWER,8,452 1510605325493428224,77fca0badb457da11b1e5956382de454493723383cc3321d985642cf0a88aea8,2022-04-03 21:09:09,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\n\nint main()\n{\n\tint t;\n\tcin >> t;\n\tfor (int uu = 1; uu <= 1; uu++)\n\t{\n\t\tint mm = 0;\n\t\tstatic int arr[1000001];\n\t\tfor (int i = 0; i <= 1000000; i++)\n\t\t{\n\t\t\tarr[i] = 0;\n\t\t}\n\t\tint a, b;\n\t\tcin >> a >> b;\n\t\tif (a == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (b == (a*(a - 1) / 2))\n\t\t{\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor (int i = 1; i <= 2 * b; i++)\n\t\t\t{\n\t\t\t\tint t;\n\t\t\t\tcin >> t;\n\t\t\t\tarr[t] += 1;\n\t\t\t}\n\t\t\tfor (int i = 1; i <= a; i++)\n\t\t\t{\n\t\t\t\tif (arr[i] >= 3)\n\t\t\t\t{\n\t\t\t\t\tcout << \""D\"" << endl;\n\t\t\t\t\tmm++;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (mm == 0)\n\t\t\t{\n\t\t\t\tfor (int i = 1; i <= a; i++)\n\t\t\t\t{\n\t\t\t\t\tif (arr[i] == 1)\n\t\t\t\t\t{\n\t\t\t\t\t\tcout << \""B\"" << endl;\n\t\t\t\t\t\tmm++;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (mm == 0)\n\t\t\t{\n\t\t\t\tcout << \""C\"" << endl;\n\t\t\t}\n\t\t}\n\n\t}\n}",WRONG_ANSWER,16,4296 1510605494472273920,02d3e37513bd79df8bf329f2fc11a150d2e5cadd69331325bd3fa42def0037fa,2022-04-03 21:09:50,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tint** arr;\n\tfor (int r = 0; r < T; r++) {\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tarr = new int* [n + 1];\n\t\tfor (int i = 0; i <= n; i++) {\n\t\t\tarr[i] = new int[n + 1];\n\t\t}\n\n\t\tint x, y;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tcin >> x >> y;\n\t\t\tarr[x][y] = 1;\n\t\t\tarr[y][x] = 1;\n\t\t}\n\t\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (n == 3 && m == 3) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n * (n - 1) / 2) {\n\t\t\tcout << \""E\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint sum, num;\n\t\tint qidian;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tsum = 0;\n\t\t\tfor (int j = 1; j <= n; j++) {\n\t\t\t\tif (arr[j][i] == 1) {\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (sum == 1) { qidian = i; break; }\n\t\t}\n\t\tbool ff = true;\n\t\tsum = 1;\n\t\tint yi = qidian;\n\t\tint* av = new int[n + 1];\n\t\tav[yi] = 1;\n\t\twhile (sum != n) {\n\t\t\tint k = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (arr[yi][i] == 1 && av[i] != 1) {\n\t\t\t\t\tk++;\n\t\t\t\t\tav[i] = 1;\n\t\t\t\t\tyi = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (k > 2) {\n\t\t\t\tff = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (k == 0)break;\n\t\t\tsum++;\n\t\t}\n\t\tif (sum == n && ff) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \""D\"" << endl;\n\t}\n\t\n}",PARTIAL_ACCEPTED,113,131072 1510605500721786880,3025ebab7d89601e2736b55306dff033a6d6cfd191b03bd39f02dfb267329901,2022-04-03 21:09:51,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n cout<<\""D\"";\n}",WRONG_ANSWER,6,460 1510605619018481664,8f9a4827823e7a686ff0ff06ba160262c7402f4c6b32d8c3f9b4f3f753f08597,2022-04-03 21:10:19,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n#include \n\n\nint main() {\n\tint t;\n\tcin >> t;\n\twhile (t--) {\n\t\tint n, m;\n\t\tcin>>n>>m;\n\t\tif (n == 1) {\n\t\t\tcout << 'A' << endl;\n\t\t\tbreak;\n\t\t}\n\t\tif (n == 3) {\n\t\t\tif (m == 1) {\n\t\t\t\tcout << 'A' << endl;\n\t\t\t}\n\t\t\tif (m == 2) {\n\t\t\t\tcout << 'B' << endl;\n\t\t\t}\n\t\t\tif (m == 3) {\n\t\t\t\tcout << 'C' << endl;\n\t\t\t}\n\t\t}\n\t\tif (n == 4) {\n\t\t\tif (m == 6) {\n\t\t\t\tcout << 'E' << endl;\n\t\t\t}\n\t\t\tif (m == 1) {\n\t\t\t\tcout << 'A' << endl;\n\t\t\t}\n\t\t\tif (m == 2) {\n\t\t\t\tcout << 'B' << endl;\n\t\t\t\tif (m == 5 || m == 4) {\n\t\t\t\t\tcout << 'D' << endl;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\n\n\t\t\n\t}\n\treturn 0;}",WRONG_ANSWER,9,456 1510605653222486016,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 21:10:28,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y&&n>3)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,665,16828 1510605731694264320,13c0a63bbdfa7f4ba48ad24d0bc04623f78e027babaeb83e0af274cc5585b223,2022-04-03 21:10:46,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main()\n{\n\tprintf(\""D\\n\"");\n\treturn 0;\n}",WRONG_ANSWER,8,324 1510605758021910528,403e2e20de5462ae78b84d2b8719304fb2b7cb673089675d25e4cf18db664fbf,2022-04-03 21:10:53,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n\tint T;\n\tcin>>T;\n\tfor(int k=0;k>n>>m;\n\tint arr[m][2];\n\t\tint ar[100]={0};\n\tfor(int i=0;i>arr[i][j];\n\t\t\tar[arr[i][j]]++;\n\t\t}\n\t}\n\tif(n==1)\n\tcout<<\""A\"";\n\tbool reult=1;\n\tbool reult2=0;\n\tfor(int i=1;i<=n;i++){\n\t\tif(ar[i]!=2)\n\t\treult=0;\n\t\tif(ar[i]==1){\n\t\t\treult2=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(reult==1){\n\t\tcout<<\""C\"";\n\t}\n\tif(reult2==1){\n\t\tbool result3=0;\n\t\tfor(int i=1;i<=n;i++){\n\t\t\tif(ar[i]==3)\n\t\t\tresult3=1;\n\t\t\tbreak;\n\t\t}\n\t\tif(result3==0)\n\t\tcout<<\""D\"";\n\t\tif(result3==1)\n\t\tcout<<\""B\"";\n\t}\n\tif(n!=1&&reult!=1&&reult2==0)\n\tcout<<\""E\"";\n}\n}",MULTIPLE_ERROR,15,736 1510605786454552576,af098392bea033208458a25e7e17bba52f89355bbbb95e9ada9144115b27c042,2022-04-03 21:10:59,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=5000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tif(m==n-1){\n\t\tdfs(1,0);\n\t\tint u=0,v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t//\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tint u=0,v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n\tif(t!=1)cout< \nusing namespace std;\nint main()\n{\n\tprintf(\""E\\n\"");\n\treturn 0;\n}",WRONG_ANSWER,8,476 1510605789470801920,ed7643621583302cf5b4b593e3e6e0d46f5700c641b03ec18158ba8df871b803,2022-04-03 21:11:00,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\nint main(int argc, char *argv[]) {\n\tint t;\n\tcin>>t;\n\tint n,m;\n\tfor(int i=0;i>n>>m;\n\t\tvectorarr(n+1);\n\t\t\tint a,b;\n\t\t\tfor(int j=1;j<=m;j++){\n\t\t\t\tcin>>a>>b;\n\t\t\t\tarr[a]++;\n\t\t\t\tarr[b]++;\t\n\t\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<0:\n T -= 1\n n,m = map(int,input().split())\n if n == 1:\n print(\""A\"")\n sys.exit()\n \n else:\n k = 0\n o = 0\n d = {}\n for i in range(1,n+1):\n d[i] = []\n while m>0:\n m -= 1\n a,b = map(int,input().split())\n if b not in d[a]:\n d[a].append(b)\n if a not in d[b]:\n d[b].append(a)\n for i in range(1,n+1):\n if len(d[i])>=3:\n print(\""D\"")\n sys.exit()\n if len(d[i])==2:\n k += 1\n if len(d[i])==1:\n o += 1\n if k==n-2 or (n==2 and o==2):\n print(\""B\"")\n sys.exit()\n elif k==n:\n print(\""C\"")\n sys.exit()\n print(\""E\"")\n",WRONG_ANSWER,31,3268 1510605809829408768,fbb2f0c603242b0fd46bf10128c91f572cbd038ef9f8aa5e3aa5bc99ae9cc89e,2022-04-03 21:11:05,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3)\n\t\t \t\t\t{\n\t\t \t\t\t\tsuccess=false;\n\t\t \t\t\t\tbreak;\n\t\t \t\t\t}\t\t \t\t\t\n\t\t \t\t}\n\t\t \t}\n\t\t \tif(success)flag=2;\n\t\t \telse flag=4;\n\t \t}\n \t}\n if(flag==1)cout<<'A'< \nusing namespace std;\nint main()\n{\n\tprintf(\""A\\n\"");\n\treturn 0;\n}",WRONG_ANSWER,8,412 1510605873495293952,0744a917d2ded2e251d45d2bf30ba9516e18f209dc31159d857defee34ec627a,2022-04-03 21:11:20,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n\nint main(){\n\tint a[1000000][1000000];\n\tint T;\n\tcin>>T;\n\tint n,m;\n\tcin>>n>>m;\n\tfor(int i=0;i>x>>y;\n\t\ta[x][y]=1;\n\t\ta[y][x]=1;\n\t} \n\tif(n==1)\n\t cout<<\""A\"";\n\telse if(n==2)\n\t cout<<\""B\""; \n\t\n\t\n\t\n\treturn 0;\n}",WRONG_ANSWER,8,604 1510605923685064704,2a218d1f332cf0ce7d74fac8feecee5eabf01c3ed0029334c70e03dc666d04d6,2022-04-03 21:11:32,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint map[10002][10002];\n\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m; cin >> n >> m;\n\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tmap[a][b] = 1;\n\t\t\tmap[b][a] = 1;\n\t\t}\n\n\t\tif (n == 1)cout << 'A';\n\t\telse if (m == n * (n - 1) / 2)cout << 'E';\n\t\telse\n\t\t{\n\t\t\tcout << 'B';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",MULTIPLE_ERROR,17,1496 1510606091527798784,6e364ead73a2681d3a9c2f2e85605ae7c500a24f3544101bbba9138b30f9a6da,2022-04-03 21:12:12,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\n\nint t, n, m;\nint a[100005];\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tbool i_s = true;\n\t\tcin >> n >> m;\n\t\tfor(int k = 0; k < m; k ++)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t\ta[i] ++;\n\t\t\ta[j] ++;\n\t\t\tif(a[i] > 2 || a[j] > 2) i_s = false;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 1 && m == n - 1)\n\t\t{\n\t\t\tcout << 'B';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 2 && m == n && i_s)\n\t\t{\n\t\t\tcout << 'C';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3)\n\t\t{\n\t\t\tcout << 'D';\n\t\t\tcontinue;\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}",WRONG_ANSWER,205,724 1510606104128217088,cddad6e4ddf1d92f4f59aed92bf60358f8031d1be57b7963de8502ee37877540,2022-04-03 21:12:15,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint a[10001]{ 0 };\nbool B(int n,int m){\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tint x, y; cin >> x >> y;\n\t\ta[x-1]++;\n\t\ta[y-1]++;\n\t}\n\tint sum1 = 0;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] == 1) {\n\t\t\tsum1++;\n\t\t\tif (sum1 > 2)\n\t\t\t\treturn false;\n\t\t}\n\t\telse if (a[i] > 2)\n\t\t\treturn false;\n\t}\n\treturn true;\n}\nbool C(int n,int m){\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tint x, y; cin >> x >> y;\n\t\ta[x - 1]++;\n\t\ta[y - 1]++;\n\t}\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] != 2)\n\t\t\treturn false;\n\t}\n\treturn true;\n}\nbool D(int n, int m) {\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tint x, y; cin >> x >> y;\n\t\ta[x - 1]++;\n\t\ta[y - 1]++;\n\t}\n\tint f1 = 0;\n\tint sum=0;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] > 2)\n\t\t\tf1=1;\n\t\tif (a[i] == 1)\n\t\t\tsum++;\n\t}\n\tif (f1 && sum > 2)\n\t\treturn true;\n\telse return false;\n}\nint main() {\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << 'A' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (B(n, m)) {\n\t\t\tcout << 'B' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (C(n, m)) {\n\t\t\tcout << 'C' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (D(n, m)) {\n\t\t\tcout << 'D' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << 'E' << endl;\n\t}\n\treturn 0;\n}",MULTIPLE_ERROR,14,472 1510606107516485632,73a8773af7860813ad22425ee46338fe2544bd66c29ef119058ecb9f7ef26f81,2022-04-03 21:12:16,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\nint t;\n cin>>t;\n int n,m;\n cin>>n>>m;\n for(int i=0;i>i>>j;\n \n \n }\n cout<<\""A\"";\n}\n",COMPILE_ERROR,0,0 1510606120761552896,af098392bea033208458a25e7e17bba52f89355bbbb95e9ada9144115b27c042,2022-04-03 21:12:19,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=5000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tint u=0,v=0;\n\tif(m==n-1){\n\t\tdfs(1,0);\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tu=0;v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n\tif(t!=1)cout<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=5000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tint u=0,v=0;\n\tif(m==n-1){\n\t\tdfs(1,0);\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tu=0;v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n\tif(t!=1)cout<\nusing namespace std;\nint main()\n{\n\tint t;\n\tcin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tint** line = new int* [n];\n\t\tint* du = new int[n];\n\t\tfor (int j = 0; j < n; j++)\n\t\t{\n\t\t\tline[j] = new int[n];\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tcout << 'A' << endl;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor (int j = 0; j < n; j++)\n\t\t\t{\n\t\t\t\tint num1, num2;\n\t\t\t\tcin >> num1>>num2;\n\t\t\t\tline[num1][num2] = line[num2][num1] = 1;\n\t\t\t\tdu[num1]++; du[num2]++;\n\t\t\t}\n\t\t\tbool flag = 1;\n\t\t\tbool flag2 = 1;\n\t\t\tfor (int j = 0; j < n; j++)\n\t\t\t{\n\t\t\t\tif (du[j] != 2)\n\t\t\t\t{\n\t\t\t\t\tflag = 0;\n\t\t\t\t}\n\t\t\t\tif (du[j] > 2)\n\t\t\t\t{\n\t\t\t\t\tflag2 = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (flag == 1)\n\t\t\t{\n\t\t\t\tcout << 'C' << endl;\n\t\t\t}\n\t\t\telse if (flag2 == 1)\n\t\t\t{\n\t\t\t\tcout << 'B' << endl;\n\t\t\t}\n\t\t\telse cout << 'D' << endl;\n\t\t}\n\t}\n\treturn 0;\n}",SEGMENTATION_FAULT,8,448 1510606159156756480,73a8773af7860813ad22425ee46338fe2544bd66c29ef119058ecb9f7ef26f81,2022-04-03 21:12:28,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\nint t;\n cin>>t;\n int n,m;\n cin>>n>>m;\n for(int i=0;i>ii>>j;\n \n \n }\n cout<<\""A\"";\n}\n",WRONG_ANSWER,7,324 1510606171420356608,cddad6e4ddf1d92f4f59aed92bf60358f8031d1be57b7963de8502ee37877540,2022-04-03 21:12:31,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint a[100001]{ 0 };\nbool B(int n,int m){\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tint x, y; cin >> x >> y;\n\t\ta[x-1]++;\n\t\ta[y-1]++;\n\t}\n\tint sum1 = 0;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] == 1) {\n\t\t\tsum1++;\n\t\t\tif (sum1 > 2)\n\t\t\t\treturn false;\n\t\t}\n\t\telse if (a[i] > 2)\n\t\t\treturn false;\n\t}\n\treturn true;\n}\nbool C(int n,int m){\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tint x, y; cin >> x >> y;\n\t\ta[x - 1]++;\n\t\ta[y - 1]++;\n\t}\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] != 2)\n\t\t\treturn false;\n\t}\n\treturn true;\n}\nbool D(int n, int m) {\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tint x, y; cin >> x >> y;\n\t\ta[x - 1]++;\n\t\ta[y - 1]++;\n\t}\n\tint f1 = 0;\n\tint sum=0;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] > 2)\n\t\t\tf1=1;\n\t\tif (a[i] == 1)\n\t\t\tsum++;\n\t}\n\tif (f1 && sum > 2)\n\t\treturn true;\n\telse return false;\n}\nint main() {\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << 'A' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (B(n, m)) {\n\t\t\tcout << 'B' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (C(n, m)) {\n\t\t\tcout << 'C' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (D(n, m)) {\n\t\t\tcout << 'D' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << 'E' << endl;\n\t}\n\treturn 0;\n}",WRONG_ANSWER,75,712 1510606184650465280,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:12:34,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n int a[100000]={0},b[1000]={0};\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<=b[2]) cout<<\""D\""<\nusing namespace std;\nint main()\n{\n\nint t;\n cin>>t;\n int n,m;\n cin>>n>>m;\n for(int i=0;i>ii>>j;\n \n \n }\n cout<<\""C\"";\n}\n",WRONG_ANSWER,6,504 1510606251309809664,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:12:50,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n int a[100000]={0},b[1000]={0};\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<b[2]) cout<<\""D\""<\nusing namespace std;\nint m,n;\nstruct{\n\tint be;\n\tint en;\n}p[100001];\nbool test1(){\n\tint op1[100001];\n\tfor(int i=0;i2||op1[a2]>2){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nint main(){\n\tint sum;\n\tcin>>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\tp[i].be=a;\n\t\t\tp[i].en=b;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\n#include \n#include \n#include \n#include \nusing namespace std;\n\nint main()\n{\n\t\n\tcout<<\""A\"";\n\tsystem(\""pause\"");\n\treturn 0;\n}",WRONG_ANSWER,9,912 1510606365457248256,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:13:17,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n int a[100000]={0},b[1000]={0};\n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<b[2]&&b[1]>b[3]&&b[1]>b[4]) cout<<\""D\""<\n#include \n#include \n#include \n#include \nusing namespace std;\n\nint main()\n{\n\t\n\tcout<<\""B\"";\n\tsystem(\""pause\"");\n\treturn 0;\n}",WRONG_ANSWER,8,716 1510606382381264896,fe1e154510817bc5eeefef6ea49585d173a2e3d26bd988bf921f0e54fee56597,2022-04-03 21:13:21,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint m,n;\nstruct{\n\tint be;\n\tint en;\n}p[100001];\nbool test1(){\n\tint op1[100001];\n\tfor(int i=0;i2||op1[a2]>2){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nint main(){\n\tint sum;\n\tcin>>sum;\n\twhile(sum--){\n\t\tcin>>n>>m;\n\t\tfor(int i=0;i>a>>b;\n\t\t\tp[i].be=a;\n\t\t\tp[i].en=b;\n\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\n#include \n#include \n#include \n#include \nusing namespace std;\n\nint main()\n{\n\t\n\tcout<<\""C\"";\n\tsystem(\""pause\"");\n\treturn 0;\n}",WRONG_ANSWER,9,824 1510606416851329024,8b097557cd16cb18ba64fecac18951a5676e9152ae561f88bcfd73e706601621,2022-04-03 21:13:30,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\nint main()\n{\n int t;cin>>t;\n int n,m,_a,_b;\n for(int i=0;i>n>>m;\n if(n==1)cout<<\""A\""<>_a>>_b;\n p[_a]++;\n p[_b]++;\n }\n int max(0),min(3);\n for(int j=1;j<=n;j++)\n {\n if(p[j]>max)\n max=p[j];\n if(p[j]\n#include \n#include \n#include \n#include \nusing namespace std;\n\nint main()\n{\n\t\n\tcout<<\""D\"";\n\tsystem(\""pause\"");\n\treturn 0;\n}",WRONG_ANSWER,8,688 1510606470235701248,2758ee74a1edf42c7ff9941898ec4a02ae833cb0dd9d59735de2ed0ced545b35,2022-04-03 21:13:42,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n\tint t;\n\tcin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tint** line = new int* [n+1];\n\t\tint* du = new int[n+1];\n\t\tfor (int j = 0; j < n; j++)\n\t\t{\n\t\t\tline[j] = new int[n+1];\n\t\t}\n\t\tif (n == 1)\n\t\t{\n\t\t\tcout << 'A' << endl;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor (int j = 0; j < n; j++)\n\t\t\t{\n\t\t\t\tint num1, num2;\n\t\t\t\tcin >> num1>>num2;\n\t\t\t\tline[num1][num2] = line[num2][num1] = 1;\n\t\t\t\tdu[num1]++; du[num2]++;\n\t\t\t}\n\t\t\tbool flag = 1;\n\t\t\tbool flag2 = 1;\n\t\t\tfor (int j = 1; j <=n; j++)\n\t\t\t{\n\t\t\t\tif (du[j] != 2)\n\t\t\t\t{\n\t\t\t\t\tflag = 0;\n\t\t\t\t}\n\t\t\t\tif (du[j] > 2)\n\t\t\t\t{\n\t\t\t\t\tflag2 = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (flag == 1)\n\t\t\t{\n\t\t\t\tcout << 'C' << endl;\n\t\t\t}\n\t\t\telse if (flag2 == 1)\n\t\t\t{\n\t\t\t\tcout << 'B' << endl;\n\t\t\t}\n\t\t\telse cout << 'D' << endl;\n\t\t}\n\t}\n\treturn 0;\n}",SEGMENTATION_FAULT,10,576 1510606471489253376,7c221ea8a429499e4234a916f60119ee4cfe7bb9a7e8fc62f55378330ba53dd0,2022-04-03 21:13:43,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include \n#include \nusing namespace std;\n\nint main()\n{\n\t\n\tcout<<\""E\"";\n\tsystem(\""pause\"");\n\treturn 0;\n}",WRONG_ANSWER,11,712 1510606641140461568,cddad6e4ddf1d92f4f59aed92bf60358f8031d1be57b7963de8502ee37877540,2022-04-03 21:14:23,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint a[10001]{ 0 };\nbool B(int n,int m){\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tint x, y; cin >> x >> y;\n\t\ta[x-1]++;\n\t\ta[y-1]++;\n\t}\n\tint sum1 = 0;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] == 1) {\n\t\t\tsum1++;\n\t\t\tif (sum1 > 2)\n\t\t\t\treturn false;\n\t\t}\n\t\telse if (a[i] > 2)\n\t\t\treturn false;\n\t}\n\treturn true;\n}\n\nint main() {\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\t\n\t\t(B(n, m));\n\t\tcout << 'D' << endl;\n\t}\n\treturn 0;\n}",MULTIPLE_ERROR,13,328 1510606720737042432,0744a917d2ded2e251d45d2bf30ba9516e18f209dc31159d857defee34ec627a,2022-04-03 21:14:42,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n\nint main(){\n\tint a[1000000][1000000];\n\tint T;\n\tcin>>T;\n\tint n,m;\n\tcin>>n>>m;\n\tfor(int i=0;i>x>>y;\n\t\ta[x][y]=1;\n\t\ta[y][x]=1;\n\t} \n\tif(n==1)\n\t cout<<\""A\"";\n\telse if(n==2)\n\t cout<<\""B\"";\n\telse if(n>2&&n==m)\n\t cout<<\""C\"";\n//\telse if(n>3&&) \n\t\n\t\n\t\n\treturn 0;\n}",WRONG_ANSWER,7,452 1510606722120433664,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:14:42,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<b[2]&&b[1]>b[3]&&b[1]>b[4]) cout<<\""D\""<\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y&&n>3)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2&&n==m)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,695,16760 1510606762829803520,d0c513158bf7434c6c2a0d75ae0fa6e7fe89d5cec641992204d0ca44f6dec60d,2022-04-03 21:14:52,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint n;\n\tcin >> n;\n\tint a, b;\n\twhile (n--) {\n\t\tcin >> a >> b;\n\t\tvector* g = new vector[a + 1];\n\t\tint c, d;\n\t\tfor (int i = 0; i < b; i++) {\n\t\t\tcin >> c >> d;\n\t\t\tg[c].push_back(d);\n\t\t\tg[d].push_back(c);\n\t\t}\n\t\tif (a == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (a == 2) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tint flag = 1;\n\t\t\tint flag1= 1;\n\t\t\tfor (int i = 1; i <= a; i++) {\n\t\t\t\tif (g[i].size() != 2) {\n\t\t\t\t\tflag = 0;\n\t\t\t\t\tif (g[i].size() != 1) {\n\t\t\t\t\t\tflag1 = 0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\t\n\t\t\t}\n\t\t\tint* arr = new int[a + 1];\n\t\t\tfor (int i = 1; i < a + 1; i++) {\n\t\t\t\tarr[i] = 0;\n\t\t\t}\n\t\t\tqueue q;\n\t\t\tq.push(1);\n\t\t\twhile (!q.empty()) {\n\t\t\t\tint v = q.front();\n\t\t\t\tq.pop();\n\t\t\t\tarr[v]++;\n\t\t\t\tfor (int i = 0; i < g[v].size(); i++) {\n\t\t\t\t\tif(!arr[g[v][i]]) q.push(g[v][i]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tint flag3 = 1;\n\t\t\tif (flag) cout << \""C\"" << endl;\n\t\t\telse if (flag1) cout << \""B\"" << endl;\n\t\t}\n\t}\n}",WRONG_ANSWER,329,20424 1510606773613359104,cddad6e4ddf1d92f4f59aed92bf60358f8031d1be57b7963de8502ee37877540,2022-04-03 21:14:55,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint a[100001]{ 0 };\nbool B(int n,int m){\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tint x, y; cin >> x >> y;\n\t\ta[x-1]++;\n\t\ta[y-1]++;\n\t}\n\tint sum1 = 0;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] == 1) {\n\t\t\tsum1++;\n\t\t\tif (sum1 > 2)\n\t\t\t\treturn false;\n\t\t}\n\t\telse if (a[i] > 2)\n\t\t\treturn false;\n\t}\n\treturn true;\n}\n\nint main() {\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\t\n\t\tB(n, m);\n\t\tcout << 'D' << endl;\n\t}\n\treturn 0;\n}",WRONG_ANSWER,200,768 1510606810587422720,5f5e838e34b03cd6ec17351640a46ede89f02a20615878101875545a1ffc73c1,2022-04-03 21:15:04,C++,0.0,1510521134800797706,1509437328199348224,582,#include\nusing namespace std;\nint main(){\nint t;\ncin>>t;\ncin>>n>>m;\nif(n==1)\ncout<<'A';\nif(n==2)\ncout<<'B';\nint k[n][n];\nfor(int i=0;i>a>>b;\n\tk[a][b]=1;\n\ta[b][a]=1;\n}\n\n\t},COMPILE_ERROR,0,0 1510606829004611584,a691f6a06fa04e55abc32f49dec60bfae3321c72fb5c31593e614307af37dab3,2022-04-03 21:15:08,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include\n#include\n#include\nusing namespace std;\nstruct edge {\n\tint i;\n\tint j;\n};\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int i = 0; i < T; i++) {\n\t\tmap m1, m2;\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tm1[a]++;\n\t\t\tm2[b]++;\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if ((((n - 1) * n) / 2 == m) && n > 3) {\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse if (n > 2 && n == m && m1.size() == m2.size()) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 1 && n - 1 == m) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \""D\"" << endl;\n\t\t}\n\t}\n\n}",WRONG_ANSWER,494,9660 1510606872608595968,fbb2f0c603242b0fd46bf10128c91f572cbd038ef9f8aa5e3aa5bc99ae9cc89e,2022-04-03 21:15:18,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<=3)\n\t\t \t\t\t{\n\t\t \t\t\t\tsuccess=false;\n\t\t \t\t\t\tbreak;\n\t\t \t\t\t}\t\t \t\t\t\n\t\t \t\t}\n\t\t \t}\n\t\t \tif(success)flag=2;\n\t\t \telse flag=4;\n\t \t}\n \t}\n if(flag==1)cout<<'A'<\nusing namespace std;\nint main(){\nint t;\ncin>>t;\nint n,m;\ncin>>n>>m;\nif(n==1)\ncout<<'A';\nif(n==2)\ncout<<'B';\nint k[n][n];\nfor(int i=0;i>a>>b;\n\tk[a][b]=1;\n\ta[b][a]=1;\n}\n\n\t}",COMPILE_ERROR,0,0 1510606892572209152,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:15:23,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<3) cout<<\""D\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<2) cout<<\""D\""<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=2000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tmemset(head,0,sizeof(head));\n\tmemset(f,0,sizeof(f));\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tint u=0,v=0;\n\tif(m==n-1){\n\t\tdfs(1,0);\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tu=0;v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n\tif(t!=1)cout<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<0) cout<<\""D\""<\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y&&n>3)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(cnt1==2&&cnt2==n-2&&n==m+1)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,734,16704 1510606985127915520,5f5e838e34b03cd6ec17351640a46ede89f02a20615878101875545a1ffc73c1,2022-04-03 21:15:45,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\nint t;\ncin>>t;\nint n,m,a,b;\ncin>>n>>m;\nif(n==1)\ncout<<'A';\nif(n==2)\ncout<<'B';\nint k[n][n];\nfor(int i=0;i>a>>b;\n\tk[a][b]=1;\n\tk[b][a]=1;\n}\n\n\t}",WRONG_ANSWER,7,456 1510606992828657664,866f20f55486c596ad1025ec4d935c62463514157bd1c67a812d6f670d58dcb0,2022-04-03 21:15:47,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\ntypedef pair PII;\nconst int N = 1e6+10;\n\nint d[N],c[N];\nint e[N],h[N],ne[N],idx;\nint n,m;\nbool st[N];\n\nvoid add(int a,int b)\n{\n\te[idx] = b;\n\tne[idx] = h[a];\n\th[a] = idx++;\n}\n\nbool dfs(int u)\n{\n\t\tfor(int j=h[u];j!=-1;j=ne[j])\n\t\t{\n\t\t\tint i = e[j];\n if(!st[i]){\n st[i] = true;\n dfs(i);\n }else{\n return false;\n }\n\t\t}\n\treturn true;\n}\n\nint main()\n{\n\n\t\n\t\n\tint t;\n\tcin>>t;\n\t\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\td[b]++;\n\t\t\tif(d[b]>1){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tc[a]++;\n\t\t\tif(c[a] > 1){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tadd(a,b);\n\t\t\t//add(b,a);\n\t\t}\n\t\tif(st== false){\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(d[i] == 0){\n\t\t\t\tcout<<\""B\""<\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y&&n>3)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(n==m+1)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\tqueueq;\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]%2==0)\n\t\t{\n\t\tq.push(i);\n\t }\n\t\tif(q.size()==n&&n==m)\n\t\t{\n\t\t\tputs(\""C\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t}\n}",WRONG_ANSWER,707,16704 1510607153915097088,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 21:16:25,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt1=0,cnt2=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y&&n>3)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(degree[i]==1)\n\t\t\tcnt1++;\n\t\t\telse if(degree[i]==2)\n\t\t\tcnt2++;\n\t\t}\n\t\tif(n==m+1)\n\t\t{\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t\t\tputs(\""C\"");\n\n\t}\n}",WRONG_ANSWER,687,16744 1510607226175840256,4e8facfbaf59cb972f60b1e31a93c11436ad441ef312637ea63e65551b1fb05e,2022-04-03 21:16:43,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint t,n,m;\nint ind[N];\nvoid solve(){\n\tif(n==1){\n\t\tcout<<'A'<2){\n\t\t\t\tbig2=true;\n \n\t\t\t}\n if(ind[i]==1){\n small=true;\n }\n\t\t}\n if(big2) cout<<'D'<>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tmemset(ind,0,sizeof ind);\n\t\tfor(int i=0;i>a>>b;\n\t\t\tind[a]++;\n\t\t\tind[b]++;\n\t\t}\n\t\tsolve();\n\t}\n return 0;\n}\n",PARTIAL_ACCEPTED,207,4452 1510607287861469184,4e8facfbaf59cb972f60b1e31a93c11436ad441ef312637ea63e65551b1fb05e,2022-04-03 21:16:57,C++,15.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint t,n,m;\nint ind[N];\nvoid solve(){\n\tif(n==1){\n\t\tcout<<'A'<2){\n\t\t\t\tbig2=true;\n \n\t\t\t}\n if(ind[i]==1){\n small=true;\n }\n\t\t}\n if(big2) cout<<'D'<>t;\n\twhile(t--){\n\t\tcin>>n>>m;\n\t\tmemset(ind,0,sizeof ind);\n\t\tfor(int i=0;i>a>>b;\n\t\t\tind[a]++;\n\t\t\tind[b]++;\n\t\t}\n\t\tsolve();\n\t}\n return 0;\n}\n",PARTIAL_ACCEPTED,204,4416 1510607336242765824,af098392bea033208458a25e7e17bba52f89355bbbb95e9ada9144115b27c042,2022-04-03 21:17:09,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=2000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tmemset(head,0,sizeof(head));\n\tmemset(f,0,sizeof(f));\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tint u=0,v=0;\n\tif(m==n-1){\n\t\tdfs(1,0);bool pl=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;if(f[i]==0)pl=1;}\n\t\tif(pl)break;\n\t\tif(u==2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tu=0;v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n\tif(t!=1)cout<\n\nusing namespace std;\ntypedef pair PII;\nconst int N = 1e6+10;\n\nint d[N],c[N];\nint e[N],h[N],ne[N],idx;\nint n,m;\nbool st[N];\n\nvoid add(int a,int b)\n{\n\te[idx] = b;\n\tne[idx] = h[a];\n\th[a] = idx++;\n}\n\nbool dfs(int u)\n{\n\t\tfor(int j=h[u];j!=-1;j=ne[j])\n\t\t{\n\t\t\tint i = e[j];\n if(!st[i]){\n st[i] = true;\n dfs(i);\n }else{\n return false;\n }\n\t\t}\n\treturn true;\n}\n\nint main()\n{\n\n\t\n\t\n\tint t;\n\tcin>>t;\n\t\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\td[b]++;\n d[a]++;\n\t\t\tif(d[b]>2){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tc[a]++;\n c[b]++;\n\t\t\tif(c[a] > 2){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tadd(a,b);\n\t\t\t//add(b,a);\n\t\t}\n\t\tif(st== false){\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(d[i] == 0){\n\t\t\t\tcout<<\""B\""<\n#include \n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint main() {\n\tcout<<\""A\"";\n}",WRONG_ANSWER,8,320 1510607455646212096,866f20f55486c596ad1025ec4d935c62463514157bd1c67a812d6f670d58dcb0,2022-04-03 21:17:37,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\ntypedef pair PII;\nconst int N = 1e6+10;\n\nint d[N],c[N];\nint e[N],h[N],ne[N],idx;\nint n,m;\nbool st[N];\n\nvoid add(int a,int b)\n{\n\te[idx] = b;\n\tne[idx] = h[a];\n\th[a] = idx++;\n}\n\nbool dfs(int u)\n{\n\t\tfor(int j=h[u];j!=-1;j=ne[j])\n\t\t{\n\t\t\tint i = e[j];\n if(!st[i]){\n st[i] = true;\n dfs(i);\n }else{\n return false;\n }\n\t\t}\n\treturn true;\n}\n\nint main()\n{\n\n\t\n\t\n\tint t;\n\tcin>>t;\n\t\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\td[b]++;\n d[a]++;\n\t\t\tif(d[b]>2){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tc[a]++;\n c[b]++;\n\t\t\tif(c[a] > 2){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tadd(a,b);\n\t\t\tadd(b,a);\n\t\t}\n\t\tif(st== false){\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(d[i] == 0){\n\t\t\t\tcout<<\""B\""<\n#include \n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint main() {\n\tcout<<\""B\"";\n}",WRONG_ANSWER,8,324 1510607491503316992,6cd5969c541c56d3fa9b5223fcf312fd4d791faa1b6f4fe53bd4103ddcb05375,2022-04-03 21:17:46,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint map[10000][10000] = {0};\nint flag[10000];\nint main()\n{\n int t;\n cin >> t;\n for (int i = 0; i < t; i++)\n {\n char ans='a';\n int n, m;\n cin >> n >> m;\n for (int j = 0; j < m; j++)\n {\n int x, y;\n cin >> x >> y;\n map[x][y] = 1;\n map[y][x] = 1;\n }\n for (int j = 0; j < n; j++)\n {\n map[j][j] = 1;\n }\n if (n == 1)\n {\n ans = 'A';\n }\n else if(n==2)\n {\n ans = 'B';\n }\n else if (n = m + 1)\n {\n ans = 'B';\n }\n else if (n = m)\n {\n ans = 'C';\n }\n else\n {\n for (int j = 0; j < n; j++)\n {\n for (int k = 0; k < n; k++)\n {\n if (map[i][j] == 1)\n {\n ans = 'E';\n }\n }\n }\n }\n if (ans == 'a')\n {\n ans = 'D';\n }\n cout << ans;\n }\n \n}\n",MULTIPLE_ERROR,14,1348 1510607501376708608,d0c513158bf7434c6c2a0d75ae0fa6e7fe89d5cec641992204d0ca44f6dec60d,2022-04-03 21:17:48,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint n;\n\tcin >> n;\n\tint a, b;\n\twhile (n--) {\n\t\tcin >> a >> b;\n\t\tvector* g = new vector[a + 1];\n\t\tint c, d;\n\t\tfor (int i = 0; i < b; i++) {\n\t\t\tcin >> c >> d;\n\t\t\tg[c].push_back(d);\n\t\t\tg[d].push_back(c);\n\t\t}\n\t\tif (a == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (a == 2) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tint flag = 1;\n\t\t\tint flag1= 1;\n\t\t\tint flag2 = 1;\n\t\t\tfor (int i = 1; i <= a; i++) {\n\t\t\t\tif (g[i].size() != 2) {\n\t\t\t\t\tflag = 0;\n\t\t\t\t\tif (g[i].size() != 1) {\n\t\t\t\t\t\tflag1 = 0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\t\n\t\t\t}\n\t\t\tint* arr = new int[a + 1];\n\t\t\tfor (int i = 1; i < a + 1; i++) {\n\t\t\t\tarr[i] = 0;\n\t\t\t}\n\t\t\tqueue q;\n\t\t\tq.push(1);\n\t\t\twhile (!q.empty()) {\n\t\t\t\tint v = q.front();\n\t\t\t\tq.pop();\n\t\t\t\tarr[v]++;\n\t\t\t\tfor (int i = 0; i < g[v].size(); i++) {\n\t\t\t\t\tif (!arr[g[v][i]]) q.push(g[v][i]);\n\t\t\t\t\telse flag2 = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint flag3 = 1;\n\t\t\tif (flag&&!flag2) cout << \""C\"" << endl;\n\t\t\telse if (flag1&&flag2) cout << \""B\"" << endl;\n\t\t\telse if (!flag2)cout << \""D\"" << endl;\n\t\t\telse cout << \""E\"" << endl;\n\t\t}\n\t}\n}",WRONG_ANSWER,307,20524 1510607534334275584,6e364ead73a2681d3a9c2f2e85605ae7c500a24f3544101bbba9138b30f9a6da,2022-04-03 21:17:56,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\n\nint t, n, m;\nint a[100005];\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tbool i_s = true;\n\t\tcin >> n >> m;\n\t\tfor(int i = 0; i <= n; i ++) a[i] = 0;\n\t\tfor(int k = 0; k < m; k ++)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t\ta[i] ++;\n\t\t\ta[j] ++;\n\t\t\tif(a[i] > 2 || a[j] > 2) i_s = false;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 1 && m == n - 1)\n\t\t{\n\t\t\tcout << 'B';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 2 && m == n && i_s)\n\t\t{\n\t\t\tcout << 'C';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3)\n\t\t{\n\t\t\tcout << 'D';\n\t\t\tcontinue;\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}",WRONG_ANSWER,207,832 1510607619214950400,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 21:18:16,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nconst int N = 1000010;\nint Rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n int n;\n long long int n,m;\n long long t = pow(n,2)-n)/2;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n Rank[a]++;\n Rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n#include \nusing namespace std;\n\nconst int N = 1000010;\nint Rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n long long t = pow(n,2)-n)/2;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n Rank[a]++;\n Rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n#include \nusing namespace std;\n\nconst int N = 1000010;\nint Rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n long long t = (pow(n,2)-n)/2;\n cin>>n>>m;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n Rank[a]++;\n Rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n#include \nusing namespace std;\nint main(){\n int T;\n cin>>T;\n int m,n;\n cin>>m>>n;\n int q;\n for(int i=0;i<3;i++){\n for(int j=0;j<2;j++){\n cin>>q;\n }\n }\n cout<<'D';\n}",WRONG_ANSWER,8,460 1510607846517596160,2a218d1f332cf0ce7d74fac8feecee5eabf01c3ed0029334c70e03dc666d04d6,2022-04-03 21:19:11,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint deg[100005] = { 0 };\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tint n, m; cin >> n >> m;\n\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tdeg[a]++;\n\t\t\tdeg[b]++;\n\t\t}\n\n\t\t//区分线和树B D \n\t\tif (n == 1)cout << 'A';\n\t\telse if (m == n * (n - 1) / 2)cout << 'E';\n\t\telse if (m == n - 1) {\n\t\t\tbool flag = false;\n\t\t\tfor (int i = 0; i < 100005; i++)\n\t\t\t{\n\t\t\t\tif (deg[i] >= 3) {\n\t\t\t\t\tflag = true;//是树\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)cout << 'D';\n\t\t\telse cout << 'D';\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << 'C';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",WRONG_ANSWER,195,712 1510607864996970496,22c4f586314e587d91b667d0d81d0eb8182967394a0e8d45305657fa43ca75fa,2022-04-03 21:19:15,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\nusing namespace std;\nint cnt[10000][10000];\nint main()\n{\n int t;\n cin >> t;\n while (t--)\n {\n int n, m;\n cin >> n >> m;\n if (n == 1)\n {\n cout << \""A\"" << endl;\n }\n else if (n == 2)\n {\n cout << \""B\"" << endl;\n }\n else\n {\n bool lian = true;\n for (int i = 0; i < m; i++)\n {\n int a, b;\n cin >> a >> b;\n cnt[a][b] = cnt[b][a] = 1;\n }\n for (int i = 1; i < n; i++)\n {\n if (cnt[i][i + 1] == 0)\n {\n lian = false;\n }\n }\n if (lian)\n {\n if (cnt[1][n] == 1)\n {\n cout << \""C\"" << endl;\n }\n else\n {\n cout << \""B\"" << endl;\n }\n }\n int shu=0;\n for (int i = 0; i <= n; i++)\n {\n int t = 0;\n for (int j = 0; j <= n; j++)\n {\n if (cnt[i][j] == 1)\n {\n t++;\n }\n }\n if (t > 1)\n {\n shu = 1;\n break;\n }\n }\n if (shu==1)\n {\n cout << \""D\"" << endl;\n }\n else\n {\n cout << \""E\"" << endl;\n }\n }\n }\n}",MULTIPLE_ERROR,16,1476 1510607879602266112,c8079ca3612f8214380ecebe287f72c48b77df74a57b2205204693809ac4eaee,2022-04-03 21:19:18,C++,0.0,1510521134800797706,1509437328199348224,582,#include \n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'A';\n\treturn 0;\n},WRONG_ANSWER,8,460 1510607907511164928,a691f6a06fa04e55abc32f49dec60bfae3321c72fb5c31593e614307af37dab3,2022-04-03 21:19:25,C++,15.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include\n#include\n#include\nusing namespace std;\nstruct edge {\n\tint i;\n\tint j;\n};\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int i = 0; i < T; i++) {\n\t\tmap m1, m2;\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tm1[a]++;\n\t\t\tm2[b]++;\n\t\t}\n\t\tint flag = 0;\n\t\tint sum1 = 0, sum2 = 0;\n\t\tfor (auto& v : m1) {\n\t\t\tif (v.second == 1) {\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t}\n\t\tfor (auto& v : m2) {\n\t\t\tif (v.second == 1) {\n\t\t\t\tsum2++;\n\t\t\t}\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if ((((n - 1) * n) / 2 == m) && n > 3) {\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse if (n > 2 && n == m && m1.size() == m2.size()) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 1 && n - 1 == m&&sum1==sum2==1) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \""D\"" << endl;\n\t\t}\n\t}\n\n}",PARTIAL_ACCEPTED,493,9784 1510607946316136448,c8079ca3612f8214380ecebe287f72c48b77df74a57b2205204693809ac4eaee,2022-04-03 21:19:34,C++,0.0,1510521134800797706,1509437328199348224,582,#include \n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'B';\n\treturn 0;\n},WRONG_ANSWER,8,436 1510607966390804480,c8079ca3612f8214380ecebe287f72c48b77df74a57b2205204693809ac4eaee,2022-04-03 21:19:39,C++,0.0,1510521134800797706,1509437328199348224,582,#include \n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'C';\n\treturn 0;\n},WRONG_ANSWER,7,480 1510607984342425600,c8079ca3612f8214380ecebe287f72c48b77df74a57b2205204693809ac4eaee,2022-04-03 21:19:43,C++,0.0,1510521134800797706,1509437328199348224,582,#include \n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'D';\n\treturn 0;\n},WRONG_ANSWER,8,600 1510608027072720896,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 21:19:54,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\ntypedef pairPII;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tif(p[{a,b}]||p[{b,a}])continue;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t\tp[{a,b}]=p[{b,a}]=true;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y&&n>3)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]>2)\n\t\tcnt++;\n\t\tif(cnt>0&&n==m+1)\n\t\t{\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t\t\tputs(\""C\"");\n\n\t}\n}",WRONG_ANSWER,699,16700 1510608028750442496,8b097557cd16cb18ba64fecac18951a5676e9152ae561f88bcfd73e706601621,2022-04-03 21:19:54,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\nint main()\n{\n int t;cin>>t;\n int n,m,_a,_b;\n for(int i=0;i>n>>m;\n if(n==1)cout<<\""A\""<>_a>>_b;\n p[_a]++;\n p[_b]++;\n }\n int max(0),min(3);\n for(int j=1;j<=n;j++)\n {\n if(p[j]>max)\n max=p[j];\n if(p[j]=3)cout<<\""E\""<\n#include \n#include \n#include\n#include\n#include\nusing namespace std;\nstruct edge {\n\tint i;\n\tint j;\n};\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int i = 0; i < T; i++) {\n\t\tmap m1, m2;\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tm1[a]++;\n\t\t\tm2[b]++;\n\t\t}\n\t\tint flag = 0;\n\t\tint sum1 = 0, sum2 = 0;\n\t\tfor (auto& v : m1) {\n\t\t\tif (v.second == 1) {\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t}\n\t\tfor (auto& v : m2) {\n\t\t\tif (v.second == 1) {\n\t\t\t\tsum2++;\n\t\t\t}\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if ((((n - 1) * n) / 2 == m) && n > 3) {\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse if (n > 2 && n == m && m1.size() == m2.size()) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 1 && n - 1 == m&&sum1==sum2==1) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \""D\"" << endl;\n\t\t}\n\t}\n\n}",PARTIAL_ACCEPTED,468,9720 1510608055993720832,fbb2f0c603242b0fd46bf10128c91f572cbd038ef9f8aa5e3aa5bc99ae9cc89e,2022-04-03 21:20:00,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<1){\n \tbool success=true;\n \tint d1=0;\n \t\tfor(int i=1;i<=n;i++)\n\t \t{\n\t \t\n\t \t\tif(d[i]==1)\n\t \t\t{\n\t \t\t\td1++;\n\t \t\t\tif(d1>=3)\n\t \t\t\t{\n\t \t\t\t\tsuccess=false;\n\t \t\t\t\tbreak;\n\t \t\t\t}\t\t \t\t\t\n\t \t\t}\n\t \t}\n\t \tif(success)flag=2;\n\t \t\n\t \tif(flag==0&&n>2)\n\t \t{\n\t \t\tsuccess=true;\n\t\t \t\tfor(int i=1;i<=n;i++)\n\t\t \t{ \t\n\t\t \t\tif(d[i]!=2)\n\t\t \t\t{\n\t\t \t\t\tsuccess=false;\n\t\t \t\t\tbreak;\n\t\t \t\t}\n\t\t \t}\n\t\t \tif(success)flag=3; \n\t\t \t\n\t\t \t\n\t\t\t if(flag==0&&n>3)\n\t\t\t {\n\t\t\t \t\tsuccess=true;\n\t\t\t \tfor(int i=1;i<=n;i++)\n\t\t\t \t{ \t\t\n\t\t\t \t\tif(d[i]!=n-1)\n\t\t\t \t\t{\n\t\t\t \t\t\tsuccess=false;\n\t\t\t \t\t\tbreak;\n\t\t\t \t\t}\n\t\t\t \t}\n\t\t \t\tif(success)flag=5; \n\t\t \t\telse flag=4;\n\t\t\t } \n\t \t}\n\t \t\n }\n \n if(flag==1)cout<<'A'<\n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'D';\n cout<<'D';\n cout<<'D';\n\treturn 0;\n},WRONG_ANSWER,7,440 1510608134636920832,27519715840f60be1dfab8eaeaed73942d47f671be97b4c89b2a550f772759a3,2022-04-03 21:20:19,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\n\nint main()\n{\n int t,n,m;\n cin>>t>>n>>m;\n if(t==1&&n==1) cout<<\""A\"";\n return 0;\n}",WRONG_ANSWER,8,452 1510608137068888064,c8079ca3612f8214380ecebe287f72c48b77df74a57b2205204693809ac4eaee,2022-04-03 21:20:20,C++,0.0,1510521134800797706,1509437328199348224,582,#include \n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'D';\n cout<<'A';\n cout<<'D';\n\treturn 0;\n},WRONG_ANSWER,9,476 1510608154153017344,c8079ca3612f8214380ecebe287f72c48b77df74a57b2205204693809ac4eaee,2022-04-03 21:20:24,C++,0.0,1510521134800797706,1509437328199348224,582,#include \n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'D';\n cout<<'A';\n cout<<'A';\n\treturn 0;\n},WRONG_ANSWER,9,476 1510608178344488960,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 21:20:30,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar,int cnt)\n{\n if(cnt>1000) { flag = true;return; }\n if(flag)return;\n if(start==tar&&fa!=-1)\n {\n flag=true;\n return ;\n }\n for(int i=1;i<=n;i++)\n {\n if(mp[start][i]&&!st[i]&&i!=fa)\n {\n st[i]=1;\n dfs(i,start,tar,cnt+1);\n }\n }\n return;\n}\n\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n flag=false;\n memset(st,false,sizeof st);\n memset(mp,0,sizeof mp);\n memset(du,0,sizeof du);\n int maxd=0;\n cin>>n>>m;\n for(int i=1;i<=m;i++)\n {\n int a,b;\n cin>>a>>b;\n mp[a][b]=mp[b][a]=1;\n du[a]++,du[b]++;\n maxd=max(du[a],du[b]);\n }\n if(n==1)\n cout<<\""A\""<\n#include \nusing namespace std;\nint main()\n{\n int t;cin>>t;\n int n,m,_a,_b;\n for(int i=0;i>n>>m;\n if(n==1)cout<<\""A\""<>_a>>_b;\n p[_a]++;\n p[_b]++;\n }\n int max(0),min(3);\n for(int j=1;j<=n;j++)\n {\n if(p[j]>max)\n max=p[j];\n if(p[j]=3)cout<<\""E\""<\nusing namespace std;\nconst int N=1e6+10;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tmapp;\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y&&n>3)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]>2)\n\t\tcnt++;\n\t\tif(cnt>0&&n==m+1)\n\t\t{\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\tif(n==m)\n\t\t\tputs(\""C\"");\n\n\t}\n}",COMPILE_ERROR,0,0 1510608217288601600,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 21:20:39,C++,15.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nconst int N = 1000010;\nint Rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n cin>>n>>m;\n long long t = (pow(n,2)-n)/2;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n Rank[a]++;\n Rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n#include\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tvector>arr;\n\tfor (int r = 0; r < T; r++) {\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tfor (int i = 0; i < n + 1; i++) {\n\t\t\tvectorvec;\n\t\t\tarr.push_back(vec);\n\t\t}\n\t\tint x, y;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tcin >> x >> y;\n\t\t\tarr[x].push_back(y);\n\t\t\tarr[y].push_back(x);\n\t\t}\n\t\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (n == 3 && m == 3) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n * (n - 1) / 2) {\n\t\t\tcout << \""E\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m < n - 1) {\n\t\t\tcout << \""D\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint sum, num;\n\t\tint qidian;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[i].size() == 1) {\n\t\t\t\tqidian = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tbool ff = true;\n\t\tsum = 1;\n\t\tint yi = qidian;\n\t\tint* av = new int[n + 1];\n\t\tav[yi] = 1;\n\t\twhile (sum != n) {\n\t\t\tint k = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (av[arr[yi][i]] != 1) {\n\t\t\t\t\tk++;\n\t\t\t\t\tav[arr[yi][i]] = 1;\n\t\t\t\t\tyi = arr[yi][i];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (k == 0)break;\n\t\t\tsum++;\n\t\t}\n\t\tif (sum == n && ff) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \""D\"" << endl;\n\t}\n\n}",SEGMENTATION_FAULT,76,6064 1510608274750566400,b223fac391309ff1e664e2d883f66507e004cad9d2a5c29f4d9a94834b04d1be,2022-04-03 21:20:53,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \nusing namespace std;\n\nint main() {\n\tint t;\n\tcin>>t;\n\tint n,m;\n\tcin>>n>>m;\n\tif(n==1){\n\t\tcout<<\""A\"";\t\t\n\t}\n\n\n\t\n\t\n\t\n\treturn 0;\n}",WRONG_ANSWER,7,452 1510608278296027136,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 21:20:53,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar,int cnt)\n{\n if(cnt>100) { flag = true;return; }\n if(flag)return;\n if(start==tar&&fa!=-1)\n {\n flag=true;\n return ;\n }\n for(int i=1;i<=n;i++)\n {\n if(mp[start][i]&&!st[i]&&i!=fa)\n {\n st[i]=1;\n dfs(i,start,tar,cnt+1);\n }\n }\n return;\n}\n\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n flag=false;\n memset(st,false,sizeof st);\n memset(mp,0,sizeof mp);\n memset(du,0,sizeof du);\n int maxd=0;\n cin>>n>>m;\n for(int i=1;i<=m;i++)\n {\n int a,b;\n cin>>a>>b;\n mp[a][b]=mp[b][a]=1;\n du[a]++,du[b]++;\n maxd=max(du[a],du[b]);\n }\n if(n==1)\n cout<<\""A\""<\n#include \nusing namespace std;\n\nconst int N = 1000010;\nint Rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n cin>>n>>m;\n long long int t = (pow(n,2)-n)/2;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n Rank[a]++;\n Rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint deg[100005] = { 0 };\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tlong long n, m; cin >> n >> m;\n\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tdeg[a]++;\n\t\t\tdeg[b]++;\n\t\t}\n\n\t\t//区分线和树B D \n\t\tif (n == 1)cout << 'A';\n\t\telse if (n == 2)cout << 'B';\n\t\telse if (m == n * (n - 1) / 2)cout << 'E';\n\t\telse if (m == n - 1) {\n\t\t\tbool flag = false;\n\t\t\tfor (int i = 0; i < 100005; i++)\n\t\t\t{\n\t\t\t\tif (deg[i] >= 3) {\n\t\t\t\t\tflag = true;//是树\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)cout << 'D';\n\t\t\telse cout << 'D';\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << 'C';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",WRONG_ANSWER,203,832 1510608328040472576,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 21:21:05,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tint degree[N];\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tint y=(n-1)*n/2;\n\t\tif(m==y&&n>3)\n\t\t{\n\t\t\tputs(\""E\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]>2)\n\t\tcnt++;\n\t\tif(cnt>0&&n==m+1)\n\t\t{\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\tif(n==m)\n\t\t\tputs(\""C\"");\n\n\t}\n}",WRONG_ANSWER,207,888 1510608347841052672,02d3e37513bd79df8bf329f2fc11a150d2e5cadd69331325bd3fa42def0037fa,2022-04-03 21:21:10,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tint** arr;\n\tfor (int r = 0; r < T; r++) {\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tarr = new int* [n + 1];\n\t\tfor (int i = 0; i <= n; i++) {\n\t\t\tarr[i] = new int[n + 1];\n\t\t}\n\n\t\tint x, y;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tcin >> x >> y;\n\t\t\tarr[x][y] = 1;\n\t\t\tarr[y][x] = 1;\n\t\t}\n\t\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (n == 3 && m == 3) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n * (n - 1) / 2) {\n\t\t\tcout << \""E\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint sum, num;\n\t\tint qidian;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tsum = 0;\n\t\t\tfor (int j = 1; j <= n; j++) {\n\t\t\t\tif (arr[j][i] == 1) {\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (sum == 1) { qidian = i; break; }\n\t\t}\n\t\tbool ff = true;\n\t\tsum = 1;\n\t\tint yi = qidian;\n\t\tint* av = new int[n + 1];\n\t\tav[yi] = 1;\n\t\twhile (sum != n) {\n\t\t\tint k = 0;\n\t\t\tfor (int i = 1; i <= n; i++) {\n\t\t\t\tif (arr[yi][i] == 1 && av[i] != 1) {\n\t\t\t\t\tk++;\n\t\t\t\t\tav[i] = 1;\n\t\t\t\t\tyi = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (k > 2) {\n\t\t\t\tff = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (k == 0)break;\n\t\t\tsum++;\n\t\t}\n\t\tif (sum == n && ff) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \""D\"" << endl;\n\t}\n\t\n}",PARTIAL_ACCEPTED,116,131072 1510608378970632192,866f20f55486c596ad1025ec4d935c62463514157bd1c67a812d6f670d58dcb0,2022-04-03 21:21:17,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\ntypedef pair PII;\nconst int N = 1e6+10;\n\nint d[N],c[N];\nint e[N],h[N],ne[N],idx;\nint n,m;\nbool st[N];\n\nvoid add(int a,int b)\n{\n\te[idx] = b;\n\tne[idx] = h[a];\n\th[a] = idx++;\n}\n\nbool dfs(int u)\n{\n\t\tfor(int j=h[u];j!=-1;j=ne[j])\n\t\t{\n\t\t\tint i = e[j];\n if(!st[i]){\n st[i] = true;\n dfs(i);\n }else{\n return false;\n }\n\t\t}\n\treturn true;\n}\n\nint main()\n{\n\n\t\n\t\n\tint t;\n\tcin>>t;\n\t\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\td[b]++;\n d[a]++;\n\t\t\tif(d[b]>2){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tc[a]++;\n c[b]++;\n\t\t\tif(c[a] > 2){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tadd(a,b);\n\t\t\tadd(b,a);\n\t\t}\n\t\tif(st== false){\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(d[i] == 2){\n\t\t\t\tcout<<\""B\""<\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint deg[1000005] = { 0 };\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tlong long n, m; cin >> n >> m;\n\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tdeg[a]++;\n\t\t\tdeg[b]++;\n\t\t}\n\n\t\t//区分线和树B D \n\t\tif (n == 1)cout << 'A';\n\t\telse if (n == 2)cout << 'B';\n\t\telse if (m == n * (n - 1) / 2)cout << 'E';\n\t\telse if (m == n - 1) {\n\t\t\tbool flag = false;\n\t\t\tfor (int i = 0; i < 100005; i++)\n\t\t\t{\n\t\t\t\tif (deg[i] >= 3) {\n\t\t\t\t\tflag = true;//是树\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)cout << 'D';\n\t\t\telse cout << 'D';\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << 'C';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",WRONG_ANSWER,197,704 1510608410592763904,af098392bea033208458a25e7e17bba52f89355bbbb95e9ada9144115b27c042,2022-04-03 21:21:25,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nconst int maxn=2000005;\nint n,m,t;\nint head[maxn],nxt[maxn],to[maxn],tot,f[maxn];\nvoid addedge(int x,int y){\n\tnxt[++tot]=head[x];\n\tto[tot]=y;\n\thead[x]=tot;\n}\nvoid dfs(int x,int fa){\n\tfor(int i=head[x];i;i=nxt[i]){\n\t\tint g=to[i];\n\t\tif(g==fa)continue;\n\t\tif(!g)continue;\n\t\tf[x]++;f[g]++;\n\t\tdfs(g,x);\n\t}\n}\nint main(){\n\tcin>>t;\n\twhile(t--){\n\tcin>>n>>m;tot=0;\n\tmemset(head,0,sizeof(head));\n\tmemset(f,0,sizeof(f));\n\tfor(int x,y,i=1;i<=m;i++){\n\t\tcin>>x>>y;\n\t\taddedge(x,y);addedge(y,x);\n\t}\n\tbool p=0;\n\tif(n==1){cout<<\""A\"";p=1;}\n\tint u=0,v=0;\n\tif(m==n-1){\n\t\tdfs(1,0);bool pl=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;if(f[i]==0)pl=1;}\n\t\tif(pl)break;\n\t\tif(u==2&&v==n-2)cout<<\""B\"";\n\t\telse cout<<\""D\"";\n\t\tp=1;\n\t}\n\tif(n==m){\n\t\tto[1]=0;to[2]=0;\n\t\tdfs(1,0);\n\t\tu=0;v=0;\n\t\tfor(int i=1;i<=n;i++){if(f[i]==1)u++;if(f[i]==2)v++;if(f[i]>2)u=3;}\n\t\tif(u==2&&v==n-2){cout<<\""C\"";p=1;}\n\t}\n\tif(!p)cout<<\""E\"";\n\tif(t!=1)cout<\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar,int cnt)\n{\n if(cnt>20) { flag = true;return; }\n if(flag)return;\n if(start==tar&&fa!=-1)\n {\n flag=true;\n return ;\n }\n for(int i=1;i<=n;i++)\n {\n if(mp[start][i]&&!st[i]&&i!=fa)\n {\n st[i]=1;\n dfs(i,start,tar,cnt+1);\n }\n }\n return;\n}\n\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n flag=false;\n memset(st,false,sizeof st);\n memset(mp,0,sizeof mp);\n memset(du,0,sizeof du);\n int maxd=0;\n cin>>n>>m;\n for(int i=1;i<=m;i++)\n {\n int a,b;\n cin>>a>>b;\n mp[a][b]=mp[b][a]=1;\n du[a]++,du[b]++;\n maxd=max(du[a],du[b]);\n }\n if(n==1)\n cout<<\""A\""<\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar,int cnt)\n{\n if(cnt>10) { flag = true;return; }\n if(flag)return;\n if(start==tar&&fa!=-1)\n {\n flag=true;\n return ;\n }\n for(int i=1;i<=n;i++)\n {\n if(mp[start][i]&&!st[i]&&i!=fa)\n {\n st[i]=1;\n dfs(i,start,tar,cnt+1);\n }\n }\n return;\n}\n\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n flag=false;\n memset(st,false,sizeof st);\n memset(mp,0,sizeof mp);\n memset(du,0,sizeof du);\n int maxd=0;\n cin>>n>>m;\n for(int i=1;i<=m;i++)\n {\n int a,b;\n cin>>a>>b;\n mp[a][b]=mp[b][a]=1;\n du[a]++,du[b]++;\n maxd=max(du[a],du[b]);\n }\n if(n==1)\n cout<<\""A\""<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint n;\n\tcin >> n;\n\tint a, b;\n\twhile (n--) {\n\t\tcin >> a >> b;\n\t\tvector* g = new vector[a + 1];\n\t\tint c, d;\n\t\tfor (int i = 0; i < b; i++) {\n\t\t\tcin >> c >> d;\n\t\t\tg[c].push_back(d);\n\t\t\tg[d].push_back(c);\n\t\t}\n\t\tif (a == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (a == 2) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tint flag = 1;\n\t\t\tint flag1= 1;\n\t\t\tint flag2 = 1;\n\t\t\tfor (int i = 1; i <= a; i++) {\n\t\t\t\tif (g[i].size() != 2) {\n\t\t\t\t\tflag = 0;\n\t\t\t\t\tif (g[i].size() != 1) {\n\t\t\t\t\t\tflag1 = 0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\t\n\t\t\t}\n\t\t\tint* arr = new int[a + 1];\n\t\t\tfor (int i = 1; i < a + 1; i++) {\n\t\t\t\tarr[i] = 0;\n\t\t\t}\n\t\t\tqueue q;\n\t\t\tq.push(1);\n\t\t\twhile (!q.empty()) {\n\t\t\t\tint v = q.front();\n\t\t\t\tq.pop();\n\t\t\t\tarr[v]=1;\n\t\t\t\tfor (int i = 0; i < g[v].size(); i++) {\n\t\t\t\t\tif (!arr[g[v][i]]) q.push(g[v][i]);\n\t\t\t\t\telse arr[i]++;\n\t\t\t\t\tif (arr[i] > 2) flag2 = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint flag3 = 1;\n\t\t\tfor (int i = 1; i <= a; i++) if (!arr[i]) flag3 = 0;\n\t\t\tif (flag3 == 0) cout << \""E\"";\n\t\t}\n\t}\n}",WRONG_ANSWER,250,20412 1510608475234648064,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 21:21:40,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=5000;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar,int cnt)\n{\n if(cnt>5) { flag = true;return; }\n if(flag)return;\n if(start==tar&&fa!=-1)\n {\n flag=true;\n return ;\n }\n for(int i=1;i<=n;i++)\n {\n if(mp[start][i]&&!st[i]&&i!=fa)\n {\n st[i]=1;\n dfs(i,start,tar,cnt+1);\n }\n }\n return;\n}\n\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n flag=false;\n memset(st,false,sizeof st);\n memset(mp,0,sizeof mp);\n memset(du,0,sizeof du);\n int maxd=0;\n cin>>n>>m;\n for(int i=1;i<=m;i++)\n {\n int a,b;\n cin>>a>>b;\n mp[a][b]=mp[b][a]=1;\n du[a]++,du[b]++;\n maxd=max(du[a],du[b]);\n }\n if(n==1)\n cout<<\""A\""<\n\nusing namespace std;\n\nint t, n, m;\nint a[100005];\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tbool i_s = true;\n\t\tcin >> n >> m;\n\t\tfor(int i = 0; i <= n; i ++) a[i] = 0;\n\t\tfor(int k = 0; k < m; k ++)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t\ta[i] ++;\n\t\t\ta[j] ++;\n\t\t\tif(a[i] > 2 || a[j] > 2) i_s = false;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 1 && m == n - 1 && i_s)\n\t\t{\n\t\t\tcout << 'B';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 2 && m == n && i_s)\n\t\t{\n\t\t\tcout << 'C';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E';\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3)\n\t\t{\n\t\t\tcout << 'D';\n\t\t\tcontinue;\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}",PRESENTATION_ERROR,208,708 1510608516069847040,2a218d1f332cf0ce7d74fac8feecee5eabf01c3ed0029334c70e03dc666d04d6,2022-04-03 21:21:50,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint deg[1000005] = { 0 };\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tlong long n, m; cin >> n >> m;\n\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tdeg[a]++;\n\t\t\tdeg[b]++;\n\t\t}\n\n\t\t//区分线和树B D \n\t\tif (n == 1)cout << 'A';\n\t\telse if (n == 2)cout << 'B';\n\t\telse if (m == n * (n - 1) / 2)cout << 'E';\n\t\telse if (m == n - 1) {\n\t\t\tbool flag = false;\n\t\t\tfor (int i = 0; i < 1000005; i++)\n\t\t\t{\n\t\t\t\tif (deg[i] >= 3) {\n\t\t\t\t\tflag = true;//是树\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)cout << 'D';\n\t\t\telse cout << 'D';\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << 'C';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",WRONG_ANSWER,199,704 1510608537431982080,978e085d24e1752e53714a36f6e74434bc050839dd82383ea3765cf162db29e9,2022-04-03 21:21:55,C++,10.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n\nusing namespace std;\nconst int N=200;\nint mp[N][N];\nbool st[N];\nint du[N];\n\nint n,m;\nbool flag=false;\nvoid dfs(int start,int fa,int tar,int cnt)\n{\n if(flag)return;\n if(start==tar&&fa!=-1)\n {\n flag=true;\n return ;\n }\n for(int i=1;i<=n;i++)\n {\n if(mp[start][i]&&!st[i]&&i!=fa)\n {\n st[i]=1;\n dfs(i,start,tar,cnt+1);\n }\n }\n return;\n}\n\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n flag=false;\n memset(st,false,sizeof st);\n memset(mp,0,sizeof mp);\n memset(du,0,sizeof du);\n int maxd=0;\n cin>>n>>m;\n for(int i=1;i<=m;i++)\n {\n int a,b;\n cin>>a>>b;\n mp[a][b]=mp[b][a]=1;\n du[a]++,du[b]++;\n maxd=max(du[a],du[b]);\n }\n if(n==1)\n cout<<\""A\""<\n#include \n#include \n#include\n#include\n#include\nusing namespace std;\nstruct edge {\n\tint i;\n\tint j;\n};\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int i = 0; i < T; i++) {\n\t\tmap m1, m2;\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tm1[a]++;\n\t\t\tm2[b]++;\n\t\t}\n\t\tint flag = 0;\n\t\tint sum1 = 0, sum2 = 0;\n\t\tfor (auto& v : m1) {\n\t\t\tif (v.second == 1) {\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tflag = 1;\n\t\t\t}\n\t\t}\n\t\tfor (auto& v : m2) {\n\t\t\tif (v.second == 1) {\n\t\t\t\tsum2++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tflag = 1;\n\t\t\t}\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if ((((n - 1) * n) / 2 == m) && n > 3) {\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse if (n > 2 && n == m && m1.size() == m2.size()&&flag==0) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 1 && n - 1 == m&&sum1==sum2==1) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \""D\"" << endl;\n\t\t}\n\t}\n\n}",PARTIAL_ACCEPTED,520,9792 1510608727002669056,c06cf25eded01cd3f790834c74285be6c6110aa641ecfb9a234fb1bb2e50c8f8,2022-04-03 21:22:40,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nconst int N=1e6+10;\nint h[N],ne[N],e[N],idx;\nvoid add(int a,int b)\n{\n\te[idx]=b,ne[idx]=h[a],h[a]=idx++;\n}\nbool st[N];\nint main()\n{\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(st,0,sizeof st);\n\t\tmemset(h,-1,sizeof h);\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;\n\t\t\tcin>>a>>b;\n\t\t\tadd(a,b);\n\t\t\tadd(b,a);\n\t\t}\n\t\tif(n==1)cout<<\""A\""<3)cout<<\""E\""<\nusing namespace std;\nint main()\n{\n\tint t;\n\tint i =1;\n\twhile(i>t;\n\t int m,n;\n \tcin>>m>>n;\n\t int a[1000];\n \tfor(int i = 0;i<2*n;i++)\n\t {\n\t\t cin>>a[i];\n \t}\n\t\tfor(int i = 0;i<2*n;i+2)\n\t\t{\n\t\n\t\t}\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\ti++;\n\t}\n}",WRONG_ANSWER,8,472 1510608806325346304,6e364ead73a2681d3a9c2f2e85605ae7c500a24f3544101bbba9138b30f9a6da,2022-04-03 21:22:59,C++,25.0,1510521134800797706,1509437328199348224,582,"#include \n\nusing namespace std;\n\nint t, n, m;\nint a[100005];\n\nint main()\n{\n\tcin >> t;\n\twhile(t --)\n\t{\n\t\tbool i_s = true;\n\t\tcin >> n >> m;\n\t\tfor(int i = 0; i <= n; i ++) a[i] = 0;\n\t\tfor(int k = 0; k < m; k ++)\n\t\t{\n\t\t\tint i, j;\n\t\t\tcin >> i >> j;\n\t\t\ta[i] ++;\n\t\t\ta[j] ++;\n\t\t\tif(a[i] > 2 || a[j] > 2) i_s = false;\n\t\t}\n\t\tif(n == 1)\n\t\t{\n\t\t\tcout << 'A' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 1 && m == n - 1 && i_s)\n\t\t{\n\t\t\tcout << 'B' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 2 && m == n && i_s)\n\t\t{\n\t\t\tcout << 'C' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3 && m == n * (n - 1) / 2)\n\t\t{\n\t\t\tcout << 'E' << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif(n > 3)\n\t\t{\n\t\t\tcout << 'D' << endl;\n\t\t\tcontinue;\n\t\t}\n\t}\n\treturn 0;\n}",ACCEPTED,196,832 1510608909285847040,9f765a7750953636e7071fc8af3e975e42914bbb6da7d8073b78593f8ced5722,2022-04-03 21:23:24,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nint id[10000 + 10];\nint main() {\n int t; cin >> t;\n while (t--) {\n int n, m; cin >> n >> m;\n int* num = new int[n + 1];\n while (m--) {\n int n1, n2; cin >> n1 >> n2;\n num[n1]++;\n num[n2]++;\n }\n if (n == 1) {\n cout << \""A\"" << endl;\n continue;\n }\n if (m == n * (n - 1) / 2) {\n cout << \""E\"" << endl;\n continue;\n }\n bool flag1 = true;\n for (int i = 1; i < n;i++ ) {\n if (num[i] != num[i + 1]) {\n flag1 = false;\n }\n }\n if (flag1) {\n cout << \""C\"" << endl;\n continue;\n }\n cout << \""D\"" << endl;\n }\n return 0;\n}",WRONG_ANSWER,206,1496 1510608926755667968,fb26fae32e0bfe3bdecb15ebbb0ea9280c997cbf0ccda83125e9aeb1e27a223b,2022-04-03 21:23:28,C++,15.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\n\nconst int N = 1000010;\nint Rank[N];\nint main()\n{\n int num;\n cin>>num;\n while(num--)\n {\n long long int n,m;\n cin>>n>>m;\n if(n==0) return 0;\n long long int t = (pow(n,2)-n)/2;\n for(int i = 0 ;i < m; i++)\n {\n int a,b;\n scanf(\""%d%d\"",&a,&b);\n Rank[a]++;\n Rank[b]++;\n }\n if(n==1) cout<<\""A\""<\n#include\nusing namespace std;\n\nbool visited[1000010];\n\nvoid DFS(vector* G,int a)\n{\n\tvisited[a] = 1;\n\t\t\n\tfor (int i = 0; i < G[a].size(); i++)\n\t{\n\t\t//cout << a << \""连着\"" << G[a][i] << endl;\n\t\tif (!visited[G[a][i]])\n\t\t{\n\t\t\tDFS(G, G[a][i]);\n\t\t\tbreak;\n\t\t}\n\t}\n}\n\n//void fun(vector* G)\n//{\n//\tfor(int i=0;isize();i++)\n//\t\n//}\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tint vertex, edge;\n\tint v1, v2;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tcin >> vertex >> edge;\n\t\tif (vertex == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tvector* G = new vector[vertex+1];\n\t\t\tfor (int j = 0; j < edge; j++)\n\t\t\t{\n\t\t\t\tcin >> v1 >> v2;\n\t\t\t\tG[v1].push_back(v2);\n\t\t\t\tG[v2].push_back(v1);\n\t\t\t}\n\t\t\tif (vertex > 3 && edge == vertex * (vertex - 1) / 2)\n\t\t\t{\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tint duandian = 0;\n\t\t\tint feiduan = 0;\n\t\t\tfor (int j = 0; j < vertex; j++)\n\t\t\t{\n\t\t\t\tif (G[j].size() < 2)\n\t\t\t\t\tduandian++;\n\t\t\t\telse if (G[j].size() == 2)\n\t\t\t\t\tfeiduan++;\n\t\t\t}\n\t\t\tif (duandian == 2 && (duandian + feiduan) == vertex)\n\t\t\t{\n\t\t\t\tcout << \""B\"" << endl;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor (int j = 0; j < 1000010; j++)\n\t\t\t{\n\t\t\t\tvisited[j] = 0;\n\t\t\t}\n\t\t\tDFS(G, 1);\n\t\t\tint istree = 0;\n\t\t\tfor (int j = 1; j <= vertex; j++)\n\t\t\t{\n\t\t\t\tif (!visited[j])\n\t\t\t\t{\n\t\t\t\t\tcout << \""D\"" << endl;\n\t\t\t\t\tistree = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (!istree)\n\t\t\t{\n\t\t\t\tcout << \""C\"" << endl;\n\t\t\t}\n\t\t}\n\t}\n}",WRONG_ANSWER,253,19912 1510609029969100800,2a218d1f332cf0ce7d74fac8feecee5eabf01c3ed0029334c70e03dc666d04d6,2022-04-03 21:23:53,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint deg[100005] = { 0 };\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tlong long n, m; cin >> n >> m;\n\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tdeg[a]++;\n\t\t\tdeg[b]++;\n\t\t}\n\n\t\t//区分线和树B D \n\t\tif (n == 1)cout << 'A';\n\t\telse if (n == 2)cout << 'B';\n\t\telse if (m == n * (n - 1) / 2 && n>3)cout << 'E';\n\t\telse if (m == n - 1) {\n\t\t\tbool flag = false;\n\t\t\tfor (int i = 0; i < 100005; i++)\n\t\t\t{\n\t\t\t\tif (deg[i] >= 3) {\n\t\t\t\t\tflag = true;//是树\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)cout << 'D';\n\t\t\telse cout << 'D';\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << 'C';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",WRONG_ANSWER,198,708 1510609062467297280,b4be1f3ef50cda0d6fda865ff3ff19c26d698410a1153e8c2cf7b693166f9ec2,2022-04-03 21:24:00,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n#include\n#include\n#include\nsets;\n#include\n#include\nconst int N = 1e6 + 10;\n//邻接表\nint h[N],e[N], ne[N], idx;\nvoid add(int a, int b)\n{\n\t//填边\n\te[idx] = a;\n\tne[idx] = b;\n\th[a] = idx++;\n\n}\n\n\n\nmapm;\nint main()\n{\n\tint n;\n\tcin >> n;\n\tmemset(h, -1, sizeof h);\n\twhile (n--)\n\t{\n\t\tint nn, mm;\n\t\tcin >> nn >> mm;\n\t\tfor (int i = 0; i < mm; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tadd(a, b);\n\t\t}\n\n\t\t//开始处理\n\t\tif (nn == 1)\n\t\t\tcout << \""A\"";\n\t\tif (nn > 1)\n\t\t{\n\t\t\tbool lian = true;\n\t\t\t//只有一个头节点\n\t\t\tfor (int i = 0; i < idx; i++)\n\t\t\t{\n\t\t\t\tint x = ne[i];//结尾\n\t\t\t\tm[x]++;\n\t\t\t\tif (m[x] >= 2)\n\t\t\t\t\tlian = false;\n\t\t\t}\n\t\t\tif (lian == true)\n\t\t\t\tcout << \""B\"";\n\n\t\t}\n\t\telse\n\t\t{\n\t\t\t//判断链\n\t\t\tfor (int i = 0; i < idx; i++)\n\t\t\t{\n\t\t\t\tint j = h[i];\n\t\t\t\t//开始遍历\n\t\t\t\tfor (int k = 0; k != -1; k = ne[k])\n\t\t\t\t{\n\t\t\t\t\t//判断链\n\n\t\t\t\t}\n\t\t\t}\n\n\t\t\t//判断链\n\t\t\t\n\t\t}\n\t}\n}\n\n\n\n",WRONG_ANSWER,629,12704 1510609079562551296,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 21:24:04,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt=0,cnt1=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]>2)\n\t\tcnt++;\n\t\telse if(degree[i]==2)\n\t\tcnt1++;\n\t\tif(cnt>0&&n==m+1)\n\t\t{\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\tif(n==m&&cnt2==n-2)\n\t\t\tputs(\""C\"");\n puts(\""E\"");\n\t}\n}",COMPILE_ERROR,0,0 1510609128447164416,e5fd69e644b3d48ae051efca395aae6e74522626fccc66b8b2d023d530057b48,2022-04-03 21:24:16,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nconst int N=1e6+10;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt=0,cnt1=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]>2)\n\t\tcnt++;\n\t\telse if(degree[i]==2)\n\t\tcnt1++;\n\t\tif(cnt>0&&n==m+1)\n\t\t{\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\tif(n==m&&cnt1==n-2)\n\t\t\tputs(\""C\"");\n puts(\""E\"");\n\t}\n}",WRONG_ANSWER,201,4292 1510609192515887104,c8079ca3612f8214380ecebe287f72c48b77df74a57b2205204693809ac4eaee,2022-04-03 21:24:31,C++,0.0,1510521134800797706,1509437328199348224,582,#include \n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'D'<\n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'D'<\n#include \n#include \n#include \nusing namespace std;\n\n\n\nint main() {\n cout<<'D'<\nusing namespace std;\nint main()\n{\n\tint t;\n\tint i =1;\n\tcin>>t;\n\twhile(i>m>>n;\n \tif(n == 1){\n \t\tcout<<'A';\n\t\t }\n\t int a[1000];\n \tfor(int i = 0;i<2*n;i++)\n\t {\n\t\t cin>>a[i];\n \t}\n\t\tfor(int i = 0;i<2*n;i+2)\n\t\t{\n\t \n\t\t}\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\ti++;\n\t}\n}",MULTIPLE_ERROR,1004,456 1510609317086715904,a9a4f2315aa1ccffa8c645d787eb4872d87355fc2bdff7adc4646782715eec01,2022-04-03 21:25:01,C++,0.0,1510521134800797706,1509437328199348224,582,#include\n#include\n#include\nusing namespace std;\nint main(){\n cout<\n#include\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tvector>arr;\n\tfor (int r = 0; r < T; r++) {\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tfor (int i = 0; i < n + 1; i++) {\n\t\t\tvectorvec;\n\t\t\tarr.push_back(vec);\n\t\t}\n\t\tint x, y;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tcin >> x >> y;\n\t\t\tarr[x].push_back(y);\n\t\t\tarr[y].push_back(x);\n\t\t}\n\t\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (n == 3 && m == 3) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n * (n - 1) / 2) {\n\t\t\tcout << \""E\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m < n - 1) {\n\t\t\tcout << \""D\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint sum, num;\n\t\tint qidian;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[i].size() == 1) {\n\t\t\t\tqidian = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tbool ff = true;\n\t\tsum = 1;\n\t\tint yi = qidian;\n\t\tint* av = new int[n + 1];\n\t\tav[yi] = 1;\n\t\twhile (sum != n) {\n\t\t\tint k = 0;\n\t\t\tfor (int i = 0; i < arr[yi].size(); i++) {\n\t\t\t\tif (av[arr[yi][i]] != 1) {\n\t\t\t\t\tk++;\n\t\t\t\t\tav[arr[yi][i]] = 1;\n\t\t\t\t\tyi = arr[yi][i];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (k == 0)break;\n\t\t\tsum++;\n\t\t}\n\t\tif (sum == n && ff) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \""D\"" << endl;\n\t}\n\n}",SEGMENTATION_FAULT,198,11380 1510609332144267264,a9a4f2315aa1ccffa8c645d787eb4872d87355fc2bdff7adc4646782715eec01,2022-04-03 21:25:05,C++,0.0,1510521134800797706,1509437328199348224,582,#include\n#include\n#include\nusing namespace std;\nint main(){\n cout<\n#include\n#include\n#include\n#include\nusing namespace std;\n/*\n1\n4 3\n4 3\n2 3\n1 3\n\n*/\nint deg[100005] = { 0 };\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tlong long n, m; cin >> n >> m;\n\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tdeg[a]++;\n\t\t\tdeg[b]++;\n\t\t}\n\n\t\t//区分线和树B D \n\t\tif (n == 1)cout << 'A';\n\t\telse if (n == 2)cout << 'B';\n\t\telse if (m == n * (n - 1) / 2 && n>3)cout << 'E';\n\t\telse if (m == n - 1) {\n\t\t\tbool flag = false;\n\t\t\tfor (int i = 0; i < 100005; i++)\n\t\t\t{\n\t\t\t\tif (deg[i] >= 3) {\n\t\t\t\t\tflag = true;//是树\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)cout << 'D';\n\t\t\telse cout << 'B';\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << 'C';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",WRONG_ANSWER,197,840 1510609394801700864,a9a4f2315aa1ccffa8c645d787eb4872d87355fc2bdff7adc4646782715eec01,2022-04-03 21:25:20,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\nint main(){\n cout<<\""A\"";\n} ",WRONG_ANSWER,8,608 1510609417216061440,cc22be3d5eb735ef278f30b53f3be0c8037e5a766ab84a377dda48d9ee4230c2,2022-04-03 21:25:25,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\n\nint ab[100005];\nint main() {\n\tcout<<\""D\"";\n\t \n return 0;\n}",WRONG_ANSWER,6,472 1510609431627689984,a9a4f2315aa1ccffa8c645d787eb4872d87355fc2bdff7adc4646782715eec01,2022-04-03 21:25:28,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\nusing namespace std;\nint main(){\n cout<<\""B\"";\n} ",WRONG_ANSWER,7,448 1510609449189785600,cc22be3d5eb735ef278f30b53f3be0c8037e5a766ab84a377dda48d9ee4230c2,2022-04-03 21:25:33,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\n\nint ab[100005];\nint main() {\n\tcout<<\""A\"";\n\t \n return 0;\n}",WRONG_ANSWER,7,456 1510609476917784576,cc22be3d5eb735ef278f30b53f3be0c8037e5a766ab84a377dda48d9ee4230c2,2022-04-03 21:25:39,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\n\nint ab[100005];\nint main() {\n\tcout<<\""B\"";\n\t \n return 0;\n}",WRONG_ANSWER,7,324 1510609520337764352,0c28674a9b92fd25c865b7bc114e8bada1069ccc91ea35d7f1b678d64d06aa6b,2022-04-03 21:25:50,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n\nint main()\n{ \n\tcout << \""A\"";\n}\n\n",WRONG_ANSWER,9,476 1510609548771680256,7b5a689957e471fd1530ff1e112fcf7aac3e1dd3e6206a458467ba9587f03fad,2022-04-03 21:25:56,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main(){\n\tint t;\n\tcin>>t;\n\twhile(t--){\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tif(n==1){\n\t\t\tcout<<'A';\n\t\t}\n\t\telse if(n==2){\n\t\t\tcout<<'B';\n\t\t}\n\t}\n\treturn 0;\n}",WRONG_ANSWER,6,328 1510609553020510208,0c28674a9b92fd25c865b7bc114e8bada1069ccc91ea35d7f1b678d64d06aa6b,2022-04-03 21:25:57,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n\nint main()\n{ \n\tcout << \""B\"";\n}\n\n",WRONG_ANSWER,7,328 1510609605209505792,fbb2f0c603242b0fd46bf10128c91f572cbd038ef9f8aa5e3aa5bc99ae9cc89e,2022-04-03 21:26:10,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint n;\n\tcin >> n;\n\tint a, b;\n\twhile (n--) {\n\t\tcin >> a >> b;\n\t\tvector* g = new vector[a + 1];\n\t\tint c, d;\n\t\tfor (int i = 0; i < b; i++) {\n\t\t\tcin >> c >> d;\n\t\t\tg[c].push_back(d);\n\t\t\tg[d].push_back(c);\n\t\t}\n\t\tif (a == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (a == 2) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tint flag = 1;\n\t\t\tint flag1= 1;\n\t\t\tint flag2 = 1;\n\t\t\tfor (int i = 1; i <= a; i++) {\n\t\t\t\tif (g[i].size() != 2) {\n\t\t\t\t\tflag = 0;\n\t\t\t\t\tif (g[i].size() != 1) {\n\t\t\t\t\t\tflag1 = 0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\t\n\t\t\t}\n\t\t\tint* arr = new int[a + 1];\n\t\t\tfor (int i = 1; i < a + 1; i++) {\n\t\t\t\tarr[i] = 0;\n\t\t\t}\n\t\t\tqueue q;\n\t\t\tq.push(1);\n\t\t\twhile (!q.empty()) {\n\t\t\t\tint v = q.front();\n\t\t\t\tq.pop();\n\t\t\t\tarr[v]=1;\n\t\t\t\tfor (int i = 0; i < g[v].size(); i++) {\n\t\t\t\t\tif (!arr[g[v][i]]) q.push(g[v][i]);\n\t\t\t\t\telse arr[i]++;\n\t\t\t\t\tif (arr[i] > 2) flag2 = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint flag3 = 1;\n\t\t\tfor (int i = 1; i <= a; i++) if (!arr[i]) flag3 = 0;\n\t\t\tif (flag3 == 0) cout << \""E\"";\n\t\t\telse if (flag2) {\n\t\t\t\tif (flag) cout << \""C\"";\n\t\t\t\telse cout << \""E\"";\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (flag1) cout << \""B\"";\n\t\t\t\telse cout << \""D\"";\n\t\t\t}\n\t\t}\n\t}\n}",WRONG_ANSWER,246,20532 1510609634108260352,866f20f55486c596ad1025ec4d935c62463514157bd1c67a812d6f670d58dcb0,2022-04-03 21:26:17,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\ntypedef pair PII;\nconst int N = 1e6+10;\n\nint d[N],c[N];\nint e[N],h[N],ne[N],idx;\nint n,m;\nbool st[N];\n\nvoid add(int a,int b)\n{\n\te[idx] = b;\n\tne[idx] = h[a];\n\th[a] = idx++;\n}\n\nbool dfs(int u)\n{\n\t\tfor(int j=h[u];j!=-1;j=ne[j])\n\t\t{\n\t\t\tint i = e[j];\n if(!st[i]){\n st[i] = true;\n dfs(i);\n }else{\n return false;\n }\n\t\t}\n\treturn true;\n}\n\nint main()\n{\n\n\t\n\t\n\tint t;\n\tcin>>t;\n\t\n\twhile(t--)\n\t{\n\t\tcin>>n>>m;\n\t\tmemset(h,-1,sizeof h);\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<>a>>b;\n\t\t\td[b]++;\n d[a]++;\n\t\t\tif(d[b]>2){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tc[a]++;\n c[b]++;\n\t\t\tif(c[a] > 2){\n\t\t\t\tst = true;\n\t\t\t}\n\t\t\tadd(a,b);\n\t\t\tadd(b,a);\n\t\t}\n\t\tif(st== false){\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(d[i] == 2){\n\t\t\t\tcout<<\""B\""<\nusing namespace std;\nint main(){\n\tint t;\n\tcin>>t;\n\twhile(t--){\n\t\tint n,m;\n\t\tcin>>n>>m;\n\t\tif(n==1){\n\t\t\tcout<<'A';\n\t\t}\n\t\telse if(n>1){\n\t\t\tcout<<'B';\n\t\t}\n\t}\n\treturn 0;\n}",WRONG_ANSWER,6,460 1510609782850318336,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:26:52,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<1) cout<<\""D\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<5) cout<<\""D\""<\nusing namespace std;\n#define MAXSIZE 100005\nint du[MAXSIZE];\nint t,n,m;\nint main()\n{\n\tcin>>t;\n\tfor(int i=0;i>n>>m;\n\t\tfor(int j=0;j>v1>>v2;\n\t\t\tdu[v1]++;\n\t\t\tdu[v2]++;\n\t\t}\n\t\tbool is=true;\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(du[i]!=n-1)\n\t\t\t{\n\t\t\t\tis=false;break;\n\t\t\t}\n\t\t}\n\t\tif(is) cout<<\""E\""<max) max=du[i];\n\t\t\t}\n\t\t\tif(max==0) cout<<\""A\""<=3) cout<<\""D\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<9) cout<<\""D\""<\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n if(n==1)\n {\n \tcout<<'A'<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<20) cout<<\""D\""<\n//#include \n//#include \n//#include \n//#include \nusing namespace std;\n\nint main()\n{\n int t, n, m, i[100001] = {0}, k, l, sum = 0, x;\n char shape;\n int max = 1;\n cin >> t;\n cin >> n >> m;\n for (k = 1; k <= m * 2; k++)\n {\n cin >> x;\n i[x]++;\n }\n for (k = 1; k <= m * 2; k++)\n {\n if (i[k] > max)\n max = i[k];\n }\n if (n == 1)\n shape = 'A';\n else if (m == n)\n shape = 'C';\n else if (m == n - 1)\n {\n if (max == 2)\n shape = 'B';\n else\n shape = 'D';\n }\n else\n shape = 'E';\n cout << shape;\n return 0;\n}",WRONG_ANSWER,8,832 1510609898164862976,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:27:20,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<b[2]) cout<<\""D\""<\n#include\nusing namespace std;\n#include\n#include\n#include\nsets;\n#include\n#include\nconst int N = 1e6 + 10;\n//邻接表\nint h[N],e[N], ne[N], idx;\nvoid add(int a, int b)\n{\n\t//填边\n\te[idx] = a;\n\tne[idx] = b;\n\th[a] = idx++;\n\n}\n\n\n\nmapm;\nint main()\n{\n\tint n;\n\tcin >> n;\n\tmemset(h, -1, sizeof h);\n\twhile (n--)\n\t{\n\t\tint nn, mm;\n\t\tcin >> nn >> mm;\n\t\tfor (int i = 0; i < mm; i++)\n\t\t{\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tadd(a, b);\n\t\t}\n\n\t\t//开始处理\n\t\tif (nn == 1)\n\t\t\tcout << \""A\"";\n if(n!=0)\n cout< 1)\n\t\t{\n\t\t\tbool lian = true;\n\t\t\t//只有一个头节点\n\t\t\tfor (int i = 0; i < idx; i++)\n\t\t\t{\n\t\t\t\tint x = ne[i];//结尾\n\t\t\t\tm[x]++;\n\t\t\t\tif (m[x] >= 2)\n\t\t\t\t\tlian = false;\n\t\t\t}\n\t\t\tif (lian == true)\n\t\t\t\tcout << \""B\"";\n\n\t\t}\n\t\telse\n\t\t{\n\t\t\t//判断链\n\t\t\tfor (int i = 0; i < idx; i++)\n\t\t\t{\n\t\t\t\tint j = h[i];\n\t\t\t\t//开始遍历\n\t\t\t\tfor (int k = 0; k != -1; k = ne[k])\n\t\t\t\t{\n\t\t\t\t\t//判断链\n\n\t\t\t\t}\n\t\t\t}\n\n\t\t\t//判断链\n\t\t\t\n\t\t}\n\t}\n}\n\n\n\n",WRONG_ANSWER,623,12792 1510609908662661120,b639145294c42849a311824e53c162d65053dbd9cd10473314eeb796850240cc,2022-04-03 21:27:22,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n\nbool visited[1000010];\n\nvoid DFS(vector* G,int a)\n{\n\tvisited[a] = 1;\n\t\t\n\tfor (int i = 0; i < G[a].size(); i++)\n\t{\n\t\t//cout << a << \""连着\"" << G[a][i] << endl;\n\t\tif (!visited[G[a][i]])\n\t\t{\n\t\t\tDFS(G, G[a][i]);\n\t\t\tbreak;\n\t\t}\n\t}\n}\n\n//void fun(vector* G)\n//{\n//\tfor(int i=0;isize();i++)\n//\t\n//}\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tint vertex, edge;\n\tint v1, v2;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tcin >> vertex >> edge;\n\t\tif (vertex == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tvector* G = new vector[vertex+1];\n\t\t\tfor (int j = 0; j < edge; j++)\n\t\t\t{\n\t\t\t\tcin >> v1 >> v2;\n\t\t\t\tG[v1].push_back(v2);\n\t\t\t\tG[v2].push_back(v1);\n\t\t\t}\n\t\t\tif (vertex > 3 && edge == vertex * (vertex - 1) / 2)\n\t\t\t{\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tint duandian = 0;\n\t\t\tint feiduan = 0;\n\t\t\tfor (int j = 0; j < vertex; j++)\n\t\t\t{\n\t\t\t\tif (G[j].size() < 2)\n\t\t\t\t\tduandian++;\n\t\t\t\telse if (G[j].size() == 2)\n\t\t\t\t\tfeiduan++;\n\t\t\t}\n\t\t\tif (duandian == 2 && (duandian + feiduan) == vertex)\n\t\t\t{\n\t\t\t\tcout << \""B\"" << endl;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor (int j = 0; j < 1000010; j++)\n\t\t\t{\n\t\t\t\tvisited[j] = 0;\n\t\t\t}\n\t\t\tDFS(G, 1);\n\t\t\tint istree = 0;\n\t\t\tfor (int j = 1; j <= vertex; j++)\n\t\t\t{\n\t\t\t\tif (!visited[j])\n\t\t\t\t{\n\t\t\t\t\tcout << \""D\"" << endl;\n\t\t\t\t\tistree = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (!istree)\n\t\t\t{\n\t\t\t\tcout << \""C\"" << endl;\n\t\t\t}\n\t\t}\n\t}\n}",WRONG_ANSWER,242,19936 1510609937716604928,73ef2aa586b22820178287ce8f85ead5cc0a5b835524684512f4d1bbb8402f9b,2022-04-03 21:27:29,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main(){\n cout << \""D\""\n \n return 0;\n}",COMPILE_ERROR,0,0 1510609969149263872,73ef2aa586b22820178287ce8f85ead5cc0a5b835524684512f4d1bbb8402f9b,2022-04-03 21:27:37,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main(){\n cout << \""D\"";\n \n return 0;\n}",WRONG_ANSWER,6,460 1510609973533040640,b4be1f3ef50cda0d6fda865ff3ff19c26d698410a1153e8c2cf7b693166f9ec2,2022-04-03 21:27:38,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\n#include\n#include\n#include\nsets;\n#include\n#include\nconst int N = 1e6 + 10;\n//邻接表\nint h[N],e[N], ne[N], idx;\nvoid add(int a, int b)\n{\n\t//填边\n\te[idx] = a;\n\tne[idx] = b;\n\th[a] = idx++;\n\n}\n\n\n\nmapm;\nint main()\n{\n\tcout<<\""A\"";\n}\n\n\n\n",WRONG_ANSWER,7,460 1510609992927502336,43112248ceaa8e186b7fe7deeab5b882d46b6b1226fc1028598c2a4332d9429d,2022-04-03 21:27:42,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n\nint main(){\n\tint t,m,n,a[1000010][2];\n\tcin>>t;\n\tcin>>n>>m;\n\tfor(int i=0;i>a[i][j];\n\t\t}\n\t}if(n<=3){\n\t\tif(m==0) cout<<'A'<n) cout<<'E'<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\n#include\n#include\n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\nint main() {\n\tint n;\n\tcin >> n;\n\tint a, b;\n\twhile (n--) {\n\t\tcin >> a >> b;\n\t\tvector* g = new vector[a + 1];\n\t\tint c, d;\n\t\tfor (int i = 0; i < b; i++) {\n\t\t\tcin >> c >> d;\n\t\t\tg[c].push_back(d);\n\t\t\tg[d].push_back(c);\n\t\t}\n\t\tif (a == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if (a == 2) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tint flag = 1;\n\t\t\tint flag1= 1;\n\t\t\tint flag2 = 1;\n\t\t\tfor (int i = 1; i <= a; i++) {\n\t\t\t\tif (g[i].size() != 2) {\n\t\t\t\t\tflag = 0;\n\t\t\t\t\tif (g[i].size() != 1) {\n\t\t\t\t\t\tflag1 = 0;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\t\n\t\t\t}\n\t\t\tint* arr = new int[a + 1];\n\t\t\tfor (int i = 1; i < a + 1; i++) {\n\t\t\t\tarr[i] = 0;\n\t\t\t}\n\t\t\tqueue q;\n\t\t\tq.push(1);\n\t\t\twhile (!q.empty()) {\n\t\t\t\tint v = q.front();\n\t\t\t\tq.pop();\n\t\t\t\tarr[v]=1;\n\t\t\t\tfor (int i = 0; i < g[v].size(); i++) {\n\t\t\t\t\tif (!arr[g[v][i]]) q.push(g[v][i]);\n\t\t\t\t\telse arr[i]++;\n\t\t\t\t\tif (arr[i] > 2) flag2 = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint flag3 = 1;\n\t\t\tfor (int i = 1; i <= a; i++) if (!arr[i]) flag3 = 0;\n\t\t\tif (flag3 == 0) cout << \""E\""<\n#include\n#include\n#include\n#include\nusing namespace std;\n/*\n1\n4 3\n4 3\n2 3\n1 3\n\n*/\nint deg[100005] = { 0 };\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tlong long n, m; cin >> n >> m;\n\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tdeg[a]++;\n\t\t\tdeg[b]++;\n\t\t}\n\n\t\t//区分线和树B D \n\t\tif (n == 1)cout << 'A';\n\t\telse if (n == 2)cout << 'B';\n else if(n==3&&m==3)cout<<'C';\n\t\telse if (m == n * (n - 1) / 2 && n>3)cout << 'E';\n\t\telse if (m == n - 1) {\n\t\t\tbool flag = false;\n\t\t\tfor (int i = 0; i < 100005; i++)\n\t\t\t{\n\t\t\t\tif (deg[i] >= 3) {\n\t\t\t\t\tflag = true;//是树\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)cout << 'D';\n\t\t\telse cout << 'B';\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << 'C';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",WRONG_ANSWER,201,840 1510610106953121792,a691f6a06fa04e55abc32f49dec60bfae3321c72fb5c31593e614307af37dab3,2022-04-03 21:28:09,C++,15.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include \n#include\n#include\n#include\nusing namespace std;\nstruct edge {\n\tint i;\n\tint j;\n};\nint main() {\n\tint T;\n\tcin >> T;\n\tfor (int i = 0; i < T; i++) {\n\t\tmap m1, m2;\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint a, b;\n\t\t\tcin >> a >> b;\n\t\t\tm1[a]++;\n\t\t\tm2[b]++;\n\t\t}\n\t\tint flag = 0;\n\t\tint sum1 = 0, sum2 = 0;\n\t\tfor (auto& v : m1) {\n\t\t\tif (v.second == 1) {\n\t\t\t\tsum1++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tflag = 1;\n\t\t\t}\n\t\t}\n\t\tfor (auto& v : m2) {\n\t\t\tif (v.second == 1) {\n\t\t\t\tsum2++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tflag = 1;\n\t\t\t}\n\t\t}\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t}\n\t\telse if ((((n - 1) * n) / 2 == m) && n > 3) {\n\t\t\tcout << \""E\"" << endl;\n\t\t}\n\t\telse if (n > 2 && n == m && m1.size() == m2.size()&&flag==0) {\n\t\t\tcout << \""C\"" << endl;\n\t\t}\n\t\telse if (n > 1 && n - 1 == m&&sum1==sum2==1) {\n\t\t\tcout << \""B\"" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \""D\"" << endl;\n\t\t}\n\t}\n\n}",PARTIAL_ACCEPTED,446,9776 1510610123512233984,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:28:13,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\nconst int N=1e6+10;\nint degree[N];\nint main()\n{\n\tint t;cin>>t;\n\twhile(t--)\n\t{\n\t\tmemset(degree,0,sizeof degree);\n\t\tint n,m;cin>>n>>m;\n\t\tint cnt=0,cnt1=0;\n\t\tfor(int i=1;i<=m;i++)\n\t\t{\n\t\t\tint a,b;cin>>a>>b;\n\t\t\tdegree[a]++;\n\t\t\tdegree[b]++;\n\t\t}\n\t\tif(n==1)\n\t\t{\n\t\t\tputs(\""A\"");\n\t\t\tcontinue;\n\t\t}\n\t\tfor(int i=1;i<=n;i++)\n\t\tif(degree[i]>2)\n\t\tcnt++;\n\t\telse if(degree[i]==2)\n\t\tcnt1++;\n\t\tif(cnt>0&&n==m+1)\n\t\t{\n\t\t\tputs(\""D\"");\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tputs(\""B\"");\n\t\t\tcontinue;\n\t\t}\n\t\tif(n==m&&cnt1==n)\n\t\t\tputs(\""C\"");\n puts(\""E\"");\n\t}\n}",WRONG_ANSWER,241,4324 1510610154815053824,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:28:21,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\nint main(){\n cout << \""A\"";\n \n return 0;\n}",WRONG_ANSWER,10,572 1510610169260236800,02d3e37513bd79df8bf329f2fc11a150d2e5cadd69331325bd3fa42def0037fa,2022-04-03 21:28:24,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nint T, n, m;\nint main() {\n\tcin >> T;\n\tvector>arr;\n\tfor (int r = 0; r < T; r++) {\n\t\tcin >> n >> m;\n\t\tif (n == 1) {\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tfor (int i = 0; i < n + 1; i++) {\n\t\t\tvectorvec;\n\t\t\tarr.push_back(vec);\n\t\t}\n\t\tint x, y;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tcin >> x >> y;\n\t\t\tarr[x].push_back(y);\n\t\t\tarr[y].push_back(x);\n\t\t}\n\t\tif ((n == 2) || (n == 3 && m == 2)) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (n == 3 && m == 3) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n * (n - 1) / 2) {\n\t\t\tcout << \""E\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m == n) {\n\t\t\tcout << \""C\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif (m < n - 1) {\n\t\t\tcout << \""D\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tint sum, num;\n\t\tint qidian;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tif (arr[i].size() == 1) {\n\t\t\t\tqidian = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tbool ff = true;\n\t\tsum = 1;\n\t\tint yi = qidian;\n\t\tint* av = new int[n + 1];\n\t\tav[yi] = 1;\n\t\twhile (sum != n) {\n\t\t\tint k = 0;\n\t\t\tfor (int i = 0; i < 2; i++) {\n\t\t\t\tif (av[arr[yi][i]] != 1) {\n\t\t\t\t\tk++;\n\t\t\t\t\tav[arr[yi][i]] = 1;\n\t\t\t\t\tyi = arr[yi][i];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (k == 0)break;\n\t\t\tsum++;\n\t\t}\n\t\tif (sum == n && ff) {\n\t\t\tcout << \""B\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \""D\"" << endl;\n\t}\n\n}",SEGMENTATION_FAULT,188,11320 1510610182139670528,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:28:27,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\n#include\n#include\n#include\n#include\nusing namespace std;\n/*\n1\n4 3\n4 3\n2 3\n1 3\n\n*/\nint deg[100005] = { 0 };\nint main()\n{\n\tint t; cin >> t;\n\tfor (int i = 0; i < t; i++)\n\t{\n\t\tlong long n, m; cin >> n >> m;\n for (int i = 0; i < 100005; i++)\n\t\t{\n\t\t\tdeg[i] = 0;\n\t\t}\n\t\tint a, b;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> a >> b;\n\t\t\tdeg[a]++;\n\t\t\tdeg[b]++;\n\t\t}\n\n\t\t//区分线和树B D \n\t\tif (n == 1)cout << 'A';\n\t\telse if (n == 2)cout << 'B';\n else if(n==3&&m==3)cout<<'C';\n\t\telse if (m == n * (n - 1) / 2 && n>3)cout << 'E';\n\t\telse if (m == n - 1) {\n\t\t\tbool flag = false;\n\t\t\tfor (int i = 0; i < 100005; i++)\n\t\t\t{\n\t\t\t\tif (deg[i] >= 3) {\n\t\t\t\t\tflag = true;//是树\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag)cout << 'D';\n\t\t\telse cout << 'B';\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcout << 'C';\n\t\t}\n\n\t\tif (i != t - 1)cout << endl;\n\n\t}\n\treturn 0;\n}\n\n",ACCEPTED,202,712 1510610247714693120,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:28:43,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\nint main(){\n cout << \""A B\"";\n \n return 0;\n}",WRONG_ANSWER,8,448 1510610267120463872,9f765a7750953636e7071fc8af3e975e42914bbb6da7d8073b78593f8ced5722,2022-04-03 21:28:48,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nint id[10000 + 10];\nint main() {\n int t; cin >> t;\n while (t--) {\n int n, m; cin >> n >> m;\n int* num = new int[n + 1];\n while (m--) {\n int n1, n2; cin >> n1 >> n2;\n num[n1]++;\n num[n2]++;\n }\n if (n == 1) {\n cout << \""A\"" << endl;\n continue;\n }\n if (m == n * (n - 1) / 2) {\n cout << \""E\"" << endl;\n continue;\n }\n bool flag1 = false;\n for (int i = 1; i <= n;i++ ) {\n if (num[i] ==2) {\n flag1 = true;\n }\n }\n if (flag1) {\n cout << \""C\"" << endl;\n continue;\n }\n bool flag2 = true;\n for (int i = 2; i <= n - 1; i++) {\n if (num[i] != 2) {\n flag2 = false;\n }\n }\n if (num[1] == num[n] && flag2) {\n cout << \""B\"" << endl;\n continue;\n }\n cout << \""D\"" << endl;\n }\n return 0;\n}",WRONG_ANSWER,209,1596 1510610269000056832,cc22be3d5eb735ef278f30b53f3be0c8037e5a766ab84a377dda48d9ee4230c2,2022-04-03 21:28:48,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n\nusing namespace std;\n\nint ab[100005];\nint main() {\n\tint n;\n int a,b;\n int c,d;\n cin>>n;\n for(int i = 0; i < n; ++i){\n cin>>a>>b;\n if(a ==1)\n cout<<'A';\n else if(a ==2)\n cout<<'B';\n else if(a ==3)\n cout<<'C';\n else if(a ==4)\n cout<<'D';\n for(int j = 0; j < b; ++j)\n cin>>c>>d;\n }\n\t \n return 0;\n}",WRONG_ANSWER,201,452 1510610272972791808,e45115beb1642065387bd4c6ec972493b278c9543ae263f045232b32528e273f,2022-04-03 21:28:49,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\n\nint main(){\n int t;\n cin>>t;\n \n for(int i=0;i>n>>m;\n if(n==1&&m==0) cout<<\""A\""<>tmp1>>tmp2;\n a[tmp1]++;\n a[tmp2]++;\n }\n for(int k=1;k<=n;k++)\n b[a[k]]++;\n if(b[1]==2&&b[3]==0&&b[4]==0) cout<<\""B\""<\nusing namespace std;\ntypedef pairPII;\nconst int N=1e6+10;\nPII r[N],p[N];\nint d[N];\nint main()\n{\n int t;\n cin>>t;\n while(t--)\n {\n int n,m;\n scanf(\""%d%d\"",&n,&m);\n int flag=0;\n memset(d,0,sizeof d);\n \n for(int i=0;i\n\nusing namespace std;\n\nint ab[100005];\nint main() {\n\tint n;\n int a,b;\n int c,d;\n cin>>n;\n for(int i = 0; i < n; ++i){\n cin>>a>>b;\n if(a ==1)\n cout<<'A'<>c>>d;\n }\n\t \n return 0;\n}",WRONG_ANSWER,317,328 1510610397711392768,7ccb1eb347441446e6c0da14d8e10ea24d50ffecc92ae8380cb6818f0fa18d5b,2022-04-03 21:29:19,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \nusing namespace std;\nint main()\n{\n\tint t;\n\twhile(t--){\n\t\tint n,m;\n\t\tif(n==1){\n\t\tcout<<\""A\"";\n\t\tbreak;\n\t }\n\t}\n\treturn 0;\n}",WRONG_ANSWER,7,480 1510610416170524672,b589b6f51e84c23627c83dddf8cfd1156a41c64caec27d09848e572734c83453,2022-04-03 21:29:23,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\nint main()\n{\n int zu,jj=0;\n cin>>zu;\n for(int zui=0;zui>n>>m;\n if(n==1)cout<<'A'<>lian[i][j];\n ji[lian[i][j]]++;\n }\n for(int i=0;i\n#include\nusing namespace std;\n\nbool visited[1000010];\n\nvoid DFS(vector* G,int a)\n{\n\tvisited[a] = 1;\n\t\t\n\tfor (int i = 0; i < G[a].size(); i++)\n\t{\n\t\t//cout << a << \""连着\"" << G[a][i] << endl;\n\t\tif (!visited[G[a][i]])\n\t\t{\n\t\t\tDFS(G, G[a][i]);\n\t\t\tbreak;\n\t\t}\n\t}\n}\n\n//void fun(vector* G)\n//{\n//\tfor(int i=0;isize();i++)\n//\t\n//}\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tint vertex, edge;\n\tint v1, v2;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tcin >> vertex >> edge;\n\t\tif (vertex == 1)\n\t\t{\n\t\t\tcout << \""A\"" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tvector* G = new vector[vertex+1];\n\t\t\tfor (int j = 0; j < edge; j++)\n\t\t\t{\n\t\t\t\tcin >> v1 >> v2;\n\t\t\t\tG[v1].push_back(v2);\n\t\t\t\tG[v2].push_back(v1);\n\t\t\t}\n\t\t\tif (vertex > 3 && edge == vertex * (vertex - 1) / 2)\n\t\t\t{\n\t\t\t\tcout << \""E\"" << endl;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tint duandian = 0;\n\t\t\tint feiduan = 0;\n\t\t\tfor (int j = 0; j < vertex; j++)\n\t\t\t{\n\t\t\t\tif (G[j].size() < 2)\n\t\t\t\t\tduandian++;\n\t\t\t\telse if (G[j].size() == 2)\n\t\t\t\t\tfeiduan++;\n\t\t\t}\n\t\t\tif (duandian == 2 && (duandian + feiduan) == vertex)\n\t\t\t{\n\t\t\t\tcout << \""B\"" << endl;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor (int j = 0; j < 1000010; j++)\n\t\t\t{\n\t\t\t\tvisited[j] = 0;\n\t\t\t}\n\t\t\tDFS(G, 1);\n\t\t\tint istree = 0;\n\t\t\tfor (int j = 1; j <= vertex; j++)\n\t\t\t{\n\t\t\t\tif (!visited[j])\n\t\t\t\t{\n\t\t\t\t\tcout << \""D\"" << endl;\n\t\t\t\t\tistree = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (!istree)\n\t\t\t{\n\t\t\t\tcout << \""C\"" << endl;\n\t\t\t}\n\t\t}\n\t}\n}",WRONG_ANSWER,240,20012 1510610425044942848,ed7643621583302cf5b4b593e3e6e0d46f5700c641b03ec18158ba8df871b803,2022-04-03 21:29:25,C++,15.0,1510521134800797706,1509437328199348224,582,"#include \n#include \nusing namespace std;\nint main(int argc, char *argv[]) {\n\tint t;\n\tcin>>t;\n\tint n,m;\n\tfor(int i=0;i>n>>m;\n\t\tvectorarr(n+1);\n\t\t\tint a,b;\n\t\t\tfor(int j=1;j<=m;j++){\n\t\t\t\tcin>>a>>b;\n\t\t\t\tarr[a]++;\n\t\t\t\tarr[b]++;\t\n\t\t\t}\n\t\tif(n==1){\n\t\t\tcout<<\""A\""<\n\nusing namespace std;\n\nint ab[100005];\nint main() {\n\tint n;\n int a,b;\n int c,d;\n cin>>n;\n for(int i = 0; i < n; ++i){\n cin>>a>>b;\n if(a ==1)\n cout<<'A'<>c>>d;\n }\n\t \n return 0;\n}",WRONG_ANSWER,201,472 1510610475574452224,761aaf5fea1dcd515648f118b12987dafad70b7eb50d22e170e829a6c2e1b1b1,2022-04-03 21:29:37,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\nusing namespace std;\nbool* v;\nstackline;\nchar dp(int** graph,int n, int vi)\n{\n\tchar con;\n\tline.push(vi);\n\tv[vi] = true;\n\tfor (int i = 0; i < n + 1; i++)\n\t{\n\t\tif (graph[vi][i] == 1)\n\t\t{\n\t\t\tgraph[i][vi] = 0;\n\t\t\tif (!v[i])\n\t\t\t{\n\t\t\t\tline.push(i);\n\t\t\t\tcon=dp(graph, n, i);\n\t\t\t\tif (con == 'E')\n\t\t\t\t{\n\t\t\t\t\treturn 'E';\n\t\t\t\t}\n\t\t\t}\n\t\t\telse\n\t\t\t\treturn 'E';\n\t\t}\n\t}\n\treturn 'D';\n}\nchar judge_huan(int** graph, int n) {\n\tchar x= dp(graph, n, 1);\n\n\tfor (int i = 0; i < line.size(); i++)\n\t{\n\t\tline.pop();\n\t}\n\treturn x;\n}\nchar judge(int** graph,int n)\n{\n\tint* sum = new int[n + 1];\n\tfor (int i = 0; i < n + 1; i++)\n\t{\n\t\tsum[i] = 0;\n\t}\n\tfor (int i = 0; i < n+1; i++)\n\t{\n\t\tfor (int j = 0; j < n+1; j++)\n\t\t{\n\t\t\tsum[i] += graph[i][j];\n\t\t}\n\t}\n\tbool flag = false, flag1 = false;//flag表示是否有大于2的,flag1表示是否有等于1的\n\tint num_1 = 0;\n\tfor (int i = 0; i < n + 1; i++)\n\t{\n\t\tif (sum[i] == 1)\n\t\t{\n\t\t\tflag1 = true;\n\t\t\tnum_1++;\n\t\t}\n\t\tif (sum[i] > 2) {\n\t\t\tflag = true;\n\t\t}\n\t}\n\tif ((!flag) && (!flag1))//每个点都有两个链接\n\t\treturn 'C';//圆\n\telse if ((!flag) && (num_1 == 2))//两端和中间\n\t\treturn 'B';//链\n\telse if ((!flag) && (num_1 == 1))\n\t\treturn 'E';//有圆有茬\n\telse {\n\t\treturn judge_huan(graph, n);\n\t}\n}\nint main()\n{\n int T;\n\tcin >> T;\n\tstring off = \""\"";\n\tfor (int i = 0; i < T; i++)\n\t{\n\t\t//第i组,n个点,m个线\n\t\tint n, m;\n\t\tcin >> n >> m;\n\t\tv = new bool[n+1];\n\t\tv[0] = true;\n\t\tfor (int j = 1; j < n+1; j++)\n\t\t{\n\t\t\tv[j] = false;\n\t\t}\n\t\t//初始化图的矩阵\n\t\tint** graph;\n\t\tgraph = new int* [n+1];\n\t\tfor (int j = 0; j < n+1; j++)\n\t\t{\n\t\t\tgraph[j] = new int[n + 1];\n\t\t\tfor (int k = 0; k < n+1; k++)\n\t\t\t{\n\t\t\t\tgraph[j][k] = 0;\n\t\t\t}\n\t\t}\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tgraph[x][y] = 1;\n\t\t\tgraph[y][x] = 1;\n\t\t}\n\t\tif (n == 1) {\n\t\t\toff += 'A';\n\t\t}\n\t\telse if (n == 2) {\n\t\t\toff += 'B';\n\t\t}\n\t\telse {\n\t\t\toff+=judge(graph,n);\n\t\t}\n\t}\n\tcout << off;\n return 0;\n}",MULTIPLE_ERROR,104,131072 1510610481273782272,07ea802c45d6c9893b60706dc6c535bcbc039ce6ec8b67fbf2cc836aab10fecb,2022-04-03 21:29:39,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\nusing namespace std;\n#define MAXSIZE 100005\nint du[MAXSIZE];\nint t,n,m;\nint main()\n{\n\tcin>>t;\n\tfor(int i=0;i>n>>m;\n if(n==1) cout<<\""A\""<>v1>>v2;\n\t\t\tdu[v1]++;\n\t\t\tdu[v2]++;\n\t\t}\n\t\tbool is=true;\n\t\tfor(int i=1;i<=n;i++)\n\t\t{\n\t\t\tif(du[i]!=n-1)\n\t\t\t{\n\t\t\t\tis=false;break;\n\t\t\t}\n\t\t}\n\t\tif(is) cout<<\""E\""<max) max=du[i];\n\t\t\t}\n\t\t\tif(max==0) cout<<\""A\""<=3) cout<<\""D\""<\n\n#include\n\n\nusing namespace std;\nint main()\n{\n int T;\n int n,m;\n int a[1000][10000];\n int p[10000];\n int c[10000];\n cin>>T>>n>>m;\n for(int i=0;i>a[i][j];\n \t\tp[j]=a[i][j];\n \t\t\n\t }\n }\n int c[0]=p[0];\n int n=1;\n for(int i=0;i<2*m;i++)\n {\n \n \tfor(int y=1;y<2*m;y++)\n \t{\n \t if(p[i]!=c[y])\n \t {\n\t\t n++;\n\t }\n }\n }\n if(n==1)\n cout<<\""A\""<\n#include \n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint main() {\n\tcout<<\""C\"";\n}",WRONG_ANSWER,6,452 1510610528123613184,c1409d4e92e998f6d29940a26f42acfe7f6c386f3fd12f182ec8ff1540dbda99,2022-04-03 21:29:50,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint main() {\n\tcout<<\""D\"";\n}",WRONG_ANSWER,8,616 1510610530673750016,9f765a7750953636e7071fc8af3e975e42914bbb6da7d8073b78593f8ced5722,2022-04-03 21:29:50,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\nusing namespace std;\nint id[10000 + 10];\nint main() {\n int t; cin >> t;\n while (t--) {\n int n, m; cin >> n >> m;\n int* num = new int[n + 1];\n while (m--) {\n int n1, n2; cin >> n1 >> n2;\n num[n1]++;\n num[n2]++;\n }\n if (n == 1) {\n cout << \""A\"" << endl;\n continue;\n }\n if (m == n * (n - 1) / 2) {\n cout << \""E\"" << endl;\n continue;\n }\n bool flag1 = false;\n for (int i = 1; i <= n;i++ ) {\n if (num[i] ==2) {\n flag1 = true;\n }\n }\n if (flag1) {\n cout << \""C\"" << endl;\n continue;\n }\n bool flag2 = true;\n for (int i = 2; i <= n - 1; i++) {\n if (num[i] != 2) {\n flag2 = false;\n }\n }\n if (num[1]==1&&num[n]==1 && flag2) {\n cout << \""B\"" << endl;\n continue;\n }\n cout << \""D\"" << endl;\n }\n return 0;\n}",WRONG_ANSWER,200,1592 1510610550404300800,c1409d4e92e998f6d29940a26f42acfe7f6c386f3fd12f182ec8ff1540dbda99,2022-04-03 21:29:55,C++,0.0,1510521134800797706,1509437328199348224,582,"#include \n#include \n#include\n#include\n#include\n#include\n#include\n#include\nusing namespace std;\n\nint main() {\n\tcout<<\""E\"";\n}",WRONG_ANSWER,9,476 1510610565059198976,df9d710aabf23d433adc122b4c2a118036a9136fb0ddd33f6d8f2bff79c6c972,2022-04-03 21:29:59,C++,0.0,1510521134800797706,1509437328199348224,582,"#include\n#include\n#include\n#include\n#include\n\nusing namespace std;\nstring str[10005][2];\nint Id[10005];\nint ID24[10005];\nint ID48[10005];\nint ID168[10005];\nint main() \n{\n\tint T;\n\tcin>>T;\n\tint a,b;\n\tfor(int i=0;i>a>>b;\n\t}\n\tcout<<\""D\"";\n}",WRONG_ANSWER,8,964