File size: 7,157 Bytes
224e773
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
/*

 * nand_filter.c — Stage 8: NAND Filter

 *

 * Resolves conflicts between active experts using Boolean logic.

 *

 * Core principle: NAND is functionally complete. Any Boolean predicate

 * can be built from NAND alone. By using NAND for all conflict resolution,

 * we minimize the trusted verification base.

 *

 * Truth table:

 *   NAND(0, 0) = 1

 *   NAND(0, 1) = 1

 *   NAND(1, 0) = 1

 *   NAND(1, 1) = 0

 *

 * NOT(a) = NAND(a, a)

 * AND(a, b) = NAND(NAND(a, b), NAND(a, b))

 * OR(a, b) = NAND(NOT(a), NOT(b)) = NAND(NAND(a, a), NAND(b, b))

 * a → b = OR(NOT(a), b)

 */

#include "hyperkitty/nand.h"
#include <stdlib.h>
#include <string.h>
#include <stdio.h>

/* ================================================================

 * NAND primitive

 * ================================================================ */

static int nand(int a, int b) {
    return !(a && b);
}

/* ================================================================

 * Derived Boolean operators (built from NAND)

 * ================================================================ */

static int not_op(int a) {
    return nand(a, a);
}

static int and_op(int a, int b) {
    return nand(nand(a, b), nand(a, b));
}

static int or_op(int a, int b) {
    return nand(not_op(a), not_op(b));
}

static int implies(int a, int b) {
    return or_op(not_op(a), b);
}

static int xor_op(int a, int b) {
    return and_op(nand(a, b), or_op(a, b));
}

/* ================================================================

 * Expert conflict matrix

 * ================================================================ */

typedef struct {
    int **conflicts;    /* conflicts[i][j] = 1 if experts i and j conflict */
    int expert_count;
} ConflictMatrix;

static ConflictMatrix *conflict_matrix_alloc(int expert_count) {
    ConflictMatrix *cm = malloc(sizeof(ConflictMatrix));
    if (!cm) return NULL;

    cm->conflicts = calloc(expert_count, sizeof(int *));
    if (!cm->conflicts) {
        free(cm);
        return NULL;
    }

    for (int i = 0; i < expert_count; i++) {
        cm->conflicts[i] = calloc(expert_count, sizeof(int));
        if (!cm->conflicts[i]) {
            for (int j = 0; j < i; j++) free(cm->conflicts[j]);
            free(cm->conflicts);
            free(cm);
            return NULL;
        }
    }

    cm->expert_count = expert_count;
    return cm;
}

static void conflict_matrix_free(ConflictMatrix *cm) {
    if (!cm) return;
    for (int i = 0; i < cm->expert_count; i++) {
        free(cm->conflicts[i]);
    }
    free(cm->conflicts);
    free(cm);
}

/* ================================================================

 * Example conflict definitions (compile-time)

 * ================================================================ */

static void populate_conflict_matrix(ConflictMatrix *cm) {
    if (!cm) return;

    /* Example: some experts have conflicting responsibilities */
    /* These would be domain-specific and calibrated per use case */

    /* Expert 0 and Expert 1 conflict: resource allocation vs. latency */
    cm->conflicts[0][1] = 1;
    cm->conflicts[1][0] = 1;

    /* Expert 3 and Expert 4 conflict: strict type checking vs. flexibility */
    cm->conflicts[3][4] = 1;
    cm->conflicts[4][3] = 1;
}

/* ================================================================

 * Conflict resolution via NAND

 * ================================================================ */

uint32_t hk_nand_filter(uint32_t active_experts) {
    /* For each pair of active experts, check for conflict */
    uint32_t result = active_experts;

    for (int i = 0; i < 32; i++) {
        if (!(active_experts & (1 << i))) continue;

        for (int j = i + 1; j < 32; j++) {
            if (!(active_experts & (1 << j))) continue;

            /* Both i and j are active */
            /* If they conflict, suppress the lower-weight one (higher index) */
            int conflict = (i % 2) ^ (j % 2);  /* Stub: XOR decides conflict */

            if (conflict) {
                /* Suppress higher-indexed expert */
                result &= ~(1 << j);
            }
        }
    }

    return result;
}

/* ================================================================

 * Multi-level conflict resolution

 * ================================================================ */

uint32_t hk_nand_filter_cascading(uint32_t active_experts) {
    /* Apply NAND filtering iteratively until stable */
    uint32_t current = active_experts;
    uint32_t previous;

    int iterations = 0;
    do {
        previous = current;
        current = hk_nand_filter(current);
        iterations++;
    } while (current != previous && iterations < 10);

    return current;
}

/* ================================================================

 * Authority predicate using NAND

 * ================================================================ */

int hk_nand_authority_check(int capability, int trusted, int approval) {
    /* Authority = capability ∧ trusted ∧ approval */
    /* Built from NAND: a ∧ b ∧ c = NAND(NAND(NAND(a,b),c), NAND(NAND(a,b),c)) */
    int nand_ab = nand(capability, trusted);
    int nand_nand_abc = nand(nand_ab, approval);
    int authority = nand(nand_nand_abc, nand_nand_abc);
    return authority;
}

/* ================================================================

 * Admissibility predicate

 * ================================================================ */

int hk_nand_admissible(int has_proof, int entropy_ok, int not_dangerous) {
    /* Admissible = proof ∧ entropy_ok ∧ ¬dangerous */
    /* = proof ∧ entropy_ok ∧ NOT(dangerous) */
    /* Built from NAND */
    int not_dangerous_gate = not_op(not_dangerous);  /* Double negation */
    int proof_and_entropy = nand(nand(has_proof, entropy_ok),
                                  nand(has_proof, entropy_ok));
    int result = nand(nand(proof_and_entropy, not_dangerous_gate),
                      nand(proof_and_entropy, not_dangerous_gate));
    return result;
}

/* ================================================================

 * Debug: print Boolean circuit diagram

 * ================================================================ */

void hk_nand_print_circuit(void) {
    printf("NAND-based Boolean Circuits:\n\n");

    printf("NOT(a) = NAND(a, a)\n");
    printf("  NOT(0) = %d, NOT(1) = %d\n", not_op(0), not_op(1));

    printf("\nAND(a, b) = NAND(NAND(a,b), NAND(a,b))\n");
    printf("  AND(0,0) = %d, AND(0,1) = %d, AND(1,0) = %d, AND(1,1) = %d\n",
           and_op(0, 0), and_op(0, 1), and_op(1, 0), and_op(1, 1));

    printf("\nOR(a, b) = NAND(NAND(a,a), NAND(b,b))\n");
    printf("  OR(0,0) = %d, OR(0,1) = %d, OR(1,0) = %d, OR(1,1) = %d\n",
           or_op(0, 0), or_op(0, 1), or_op(1, 0), or_op(1, 1));

    printf("\na → b = OR(¬a, b)\n");
    printf("  0→0 = %d, 0→1 = %d, 1→0 = %d, 1→1 = %d\n",
           implies(0, 0), implies(0, 1), implies(1, 0), implies(1, 1));
}