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+[{"task_id": "mmlu-13108", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Which traditional news criterion would you expect to be most important in public relations messages distributed through the mass media?\nA) Proximity\nB) Timeliness\nC) Prominence\nD) Impact\n\nAnswer with the letter only.", "response": "B", "cost_usd": 0.0002164, "tokens_in": 56, "tokens_out": 171, "latency_s": 4.477}, {"task_id": "mmlu-13108", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] Which traditional news criterion would you expect to be most important in public relations messages distributed through the mass media?\nA) Proximity\nB) Timeliness\nC) Prominence\nD) Impact\n\nAnswer with the letter only.\n\nIndependently solve the question from its stated facts and options. Recompute any arithmetic or definition instead of trusting another solver. Return exactly one option letter A, B, C, or D and no other text.", "response": "D", "cost_usd": 0.00179025, "tokens_in": 97, "tokens_out": 458, "latency_s": 3.827}, {"task_id": "mmlu-13108", "model": "deepseek/deepseek-v4-flash", "prompt": "[MMLU] Which traditional news criterion would you expect to be most important in public relations messages distributed through the mass media?\nA) Proximity\nB) Timeliness\nC) Prominence\nD) Impact\n\nAnswer with the letter only.\n\nIndependently solve the question from its stated facts and options. Recompute any arithmetic or definition instead of trusting another solver. Return exactly one option letter A, B, C, or D and no other text.", "response": "B", "cost_usd": 0.00020901999999999987, "tokens_in": 98, "tokens_out": 701, "latency_s": 20.418}, {"task_id": "mmlu-2347", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A tank is in the shape of a triangular prism. If the triangular base has an area of 116 square feet, and the tank is 30 feet tall, how much water would the tank contain when it is full?\nA) 1725 ft^3\nB) 1740 ft^3\nC) 3480 ft^3\nD) 6960 ft^3\n\nAnswer with the letter only.", "response": "B", "cost_usd": 2.5400000000000075e-05, "tokens_in": 97, "tokens_out": 5, "latency_s": 0.568}, {"task_id": "mmlu-2347", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] A tank is in the shape of a triangular prism. If the triangular base has an area of 116 square feet, and the tank is 30 feet tall, how much water would the tank contain when it is full?\nA) 1725 ft^3\nB) 1740 ft^3\nC) 3480 ft^3\nD) 6960 ft^3\n\nAnswer with the letter only.\n\nIndependently solve the question from its stated facts and options. Recompute any arithmetic or definition instead of trusting another solver. Return exactly one option letter A, B, C, or D and no other text.", "response": "C", "cost_usd": 0.00042675000000000005, "tokens_in": 149, "tokens_out": 84, "latency_s": 1.185}, {"task_id": "mmlu-2347", "model": "deepseek/deepseek-v4-flash", "prompt": "[MMLU] A tank is in the shape of a triangular prism. If the triangular base has an area of 116 square feet, and the tank is 30 feet tall, how much water would the tank contain when it is full?\nA) 1725 ft^3\nB) 1740 ft^3\nC) 3480 ft^3\nD) 6960 ft^3\n\nAnswer with the letter only.\n\nIndependently solve the question from its stated facts and options. Recompute any arithmetic or definition instead of trusting another solver. Return exactly one option letter A, B, C, or D and no other text.", "response": "C", "cost_usd": 5.628000000000013e-05, "tokens_in": 138, "tokens_out": 132, "latency_s": 1.781}, {"task_id": "gsm8k-1051", "model": "openai/gpt-5.6-luna", "prompt": "Ingrid drinks 8 cups of water every day.  If there are 16 cups in a gallon, how many gallons of water does she drink in 30 days?\n\nReason step by step, then give the final answer as a single number.\n\nDerive the answer strictly from the question and return only the answer.", "response": "15", "cost_usd": 6.799999999999992e-05, "tokens_in": 70, "tokens_out": 45, "latency_s": 2.401}, {"task_id": "gsm8k-1175", "model": "openai/gpt-5.6-luna", "prompt": "In the first half of a soccer match, team A scores 4 goals while team B scores 2 goals fewer than team A. In the second half, team A scores 1/4 of the number of goals scored by team B, which scores 4 times the number of goals it scored in the first half. What's the total number of goals scored in the match?\n\nReason step by step, then give the final answer as a single number.\n\nDerive the answer strictly from the question and return only the answer.", "response": "16", "cost_usd": 0.00013260000000000008, "tokens_in": 111, "tokens_out": 92, "latency_s": 1.677}, {"task_id": "lcb-abc389_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer X not less than 2.\nFind the positive integer N such that N! = X.\nHere, N! denotes the factorial of N, and it is guaranteed that there is exactly one such N.\n\nInput\n\nThe input is given from Standard Input in the following format:\nX\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 2 \\leq X \\leq 3 \\times 10^{18}\n- There is exactly one positive integer N such that N!=X.\n- All input values are integers.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\r\n\nFrom 3!=3\\times2\\times1=6, print 3.\n\nSample Input 2\n\n2432902008176640000\n\nSample Output 2\n\n20\r\n\nFrom 20!=2432902008176640000, print 20.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nGeneral reliability protocol: Derive the algorithm only from the statement and constraints. The checker compares stdout tokens exactly, so match the required token count, order, and formatting. Use Python 3 and buffered whole-input parsing and output assembly. Instantiate the largest stated constraints and derive concrete time and memory bounds before coding. Reject repeated rescans, slicing, convolutions, or state tables that exceed them. The largest case must retain substantial runtime margin rather than merely finish at the limit. Check indexing, duplicates, boundaries, precision, and all statement samples. During pairwise loops keep operands in fresh local names, and test compressed or greedy invariants against literal exhaustive reasoning on the smallest legal instances.\n\nOutput protocol:\nFirst instantiate the largest stated constraints and derive a concrete time and memory bound. Reject any recurrence, convolution, state table, or repeated scan that cannot meet that bound. Then return only one complete efficient Python 3 program as raw source: no prose, fences, reference implementation, or sample-specific branch.", "response": "import sys\n\nx = int(sys.stdin.buffer.read())\nfactorial = 1\nn = 1\n\nwhile factorial < x:\n    n += 1\n    factorial *= n\n\nprint(n)\n", "cost_usd": 0.00022019999999999982, "tokens_in": 417, "tokens_out": 114, "latency_s": 3.094}, {"task_id": "lcb-abc389_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer X not less than 2.\nFind the positive integer N such that N! = X.\nHere, N! denotes the factorial of N, and it is guaranteed that there is exactly one such N.\n\nInput\n\nThe input is given from Standard Input in the following format:\nX\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 2 \\leq X \\leq 3 \\times 10^{18}\n- There is exactly one positive integer N such that N!=X.\n- All input values are integers.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\r\n\nFrom 3!=3\\times2\\times1=6, print 3.\n\nSample Input 2\n\n2432902008176640000\n\nSample Output 2\n\n20\r\n\nFrom 20!=2432902008176640000, print 20.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nGeneral reliability protocol: Derive the algorithm only from the statement and constraints. The checker compares stdout tokens exactly, so match the required token count, order, and formatting. Use Python 3 and buffered whole-input parsing and output assembly. Instantiate the largest stated constraints and derive concrete time and memory bounds before coding. Reject repeated rescans, slicing, convolutions, or state tables that exceed them. The largest case must retain substantial runtime margin rather than merely finish at the limit. Check indexing, duplicates, boundaries, precision, and all statement samples. During pairwise loops keep operands in fresh local names, and test compressed or greedy invariants against literal exhaustive reasoning on the smallest legal instances.\n\nEfficient program under test:\nimport sys\n\nx = int(sys.stdin.buffer.read())\nfactorial = 1\nn = 1\n\nwhile factorial < x:\n    n += 1\n    factorial *= n\n\nprint(n)\n\n\nBuild independent executable test tooling; do not rewrite the efficient program or assume its invariant.\nReturn exactly two fenced blocks and no prose. Generator accepts integer seed and size command-line arguments, calls random.seed(seed), and prints one legal input. Reference is a literal exhaustive solver for small legal inputs and must not use an optimized invariant.\nUse literal tiny inputs when size is at most 5, but for larger values grow a main dimension toward the statement constraints instead of capping every case at toy size. The reference may reject larger smoke-test inputs.\nConstruct and verify every promised input property inside the generator instead of guessing values. In particular validate primality when a field must be prime, construct permutations by shuffling a complete range, and construct required graph properties by design.\n```generator\n<program>\n```\n```reference\n<program>\n```", "response": "```generator\nimport sys\nimport random\nimport math\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nif size <= 5:\n    choices = [2, 3, 4, 5, 6]\n    n = choices[size - 1]\nelse:\n    n = random.randint(2, min(20, size))\n\nx = math.factorial(n)\nassert 2 <= x <= 3 * 10**18\nassert math.factorial(n) == x\nassert math.factorial(n - 1) != x\nassert math.factorial(n + 1) != x\n\nprint(x)\n```\n\n```reference\nimport sys\n\nx = int(sys.stdin.buffer.read())\n\nfor n in range(1, 22):\n    value = 1\n    for k in range(1, n + 1):\n        value *= k\n    if value == x:\n        print(n)\n        break\n```", "cost_usd": 0.0011708000000000005, "tokens_in": 568, "tokens_out": 881, "latency_s": 9.899}, {"task_id": "lcb-abc389_b", "model": "google/gemini-3.6-flash", "prompt": "You are given an integer X not less than 2.\nFind the positive integer N such that N! = X.\nHere, N! denotes the factorial of N, and it is guaranteed that there is exactly one such N.\n\nInput\n\nThe input is given from Standard Input in the following format:\nX\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 2 \\leq X \\leq 3 \\times 10^{18}\n- There is exactly one positive integer N such that N!=X.\n- All input values are integers.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\r\n\nFrom 3!=3\\times2\\times1=6, print 3.\n\nSample Input 2\n\n2432902008176640000\n\nSample Output 2\n\n20\r\n\nFrom 20!=2432902008176640000, print 20.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nGeneral reliability protocol: Derive the algorithm only from the statement and constraints. The checker compares stdout tokens exactly, so match the required token count, order, and formatting. Use Python 3 and buffered whole-input parsing and output assembly. Instantiate the largest stated constraints and derive concrete time and memory bounds before coding. Reject repeated rescans, slicing, convolutions, or state tables that exceed them. The largest case must retain substantial runtime margin rather than merely finish at the limit. Check indexing, duplicates, boundaries, precision, and all statement samples. During pairwise loops keep operands in fresh local names, and test compressed or greedy invariants against literal exhaustive reasoning on the smallest legal instances.\n\nA separate solver proposed this program:\nimport sys\n\nx = int(sys.stdin.buffer.read())\nfactorial = 1\nn = 1\n\nwhile factorial < x:\n    n += 1\n    factorial *= n\n\nprint(n)\n\n\nIndependently derive a competing efficient solution and executable test tooling. Do not copy its invariant.\nSolve independently without copying the prior candidate. Return exactly three fenced blocks and no prose. The candidate block must contain a complete Python 3 solution. The generator block must contain a Python program accepting integer seed and size command-line arguments, calling random.seed(seed), and printing one small legal input derived only from the statement. Vary ties, duplicates, boundaries, operation order, and branch combinations. For size values up to 5, emit literal tiny cases suitable for the reference. For larger size values, grow at least one main input dimension toward the stated constraints so the efficient candidate receives a performance smoke test; do not cap every output at a toy size. The generated input must remain legal.\nThe reference block must be a literal exhaustive solver for only small legal inputs and must not reuse the candidate invariant. The first candidate fence must be labeled python so the validator extracts exactly the executable candidate used by the selector.\n```python\n<program>\n```\n```generator\n<program>\n```\n```reference\n<program>\n```", "response": "```python\nimport sys\n\ndef main():\n    x = int(sys.stdin.read().strip())\n    \n    n = 2\n    curr = x\n    while curr > 1:\n        if curr % n != 0:\n            break\n        curr //= n\n        if curr == 1:\n            print(n)\n            return\n        n += 1\n\nif __name__ == '__main__':\n    main()\n```\n\n```generator\nimport sys\nimport random\n\ndef main():\n    if len(sys.argv) < 3:\n        return\n    seed = int(sys.argv[1])\n    size = int(sys.argv[2])\n    random.seed(seed)\n\n    # Pre-calculated max factorials up to around 3e18\n    # 20! = 2432902008176640000 <= 3e18\n    # 21! = 51090942171709440000 > 3e18\n    # So max N is 20.\n    \n    if size <= 5:\n        n = random.randint(2, 5)\n    else:\n        n = random.randint(2, 20)\n\n    x = 1\n    for i in range(1, n + 1):\n        x *= i\n\n    print(x)\n\nif __name__ == '__main__':\n    main()\n```\n\n```reference\nimport sys\n\ndef main():\n    x = int(sys.stdin.read().strip())\n    \n    # Precompute factorials up to N=20\n    facts = {}\n    f = 1\n    for i in range(1, 21):\n        f *= i\n        facts[f] = i\n        \n    print(facts[x])\n\nif __name__ == '__main__':\n    main()\n```", "cost_usd": 0.0021795, "tokens_in": 671, "tokens_out": 447, "latency_s": 2.891}, {"task_id": "lcb-abc395_c", "model": "openai/gpt-5.6-luna", "prompt": "You are given a positive integer N and an integer sequence A = (A_1,A_2,\\dots,A_N) of length N.\nDetermine whether there exists a non-empty (contiguous) subarray of A that has a repeated value, occurring multiple times in A. If such a subarray exists, find the length of the shortest such subarray.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\dots A_N\n\nOutput\n\nIf there is no (contiguous) subarray satisfying the condition in the problem statement, print -1. Otherwise, print the length of the shortest such subarray.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- 1 \\leq A_i \\leq 10^6 \\ (1 \\leq i \\leq N)\n- All input values are integers.\n\nSample Input 1\n\n5\r\n3 9 5 3 1\n\nSample Output 1\n\n4\r\n\n(3,9,5,3) and (3,9,5,3,1) satisfy the condition. The shorter one is (3,9,5,3), which has length 4.\n\nSample Input 2\n\n4\r\n2 5 3 1\n\nSample Output 2\n\n-1\r\n\nThere is no subarray that satisfies the condition.\n\nSample Input 3\n\n10\r\n1 1 2 3 5 8 13 21 34 55\n\nSample Output 3\n\n2\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nGeneral reliability protocol: Derive the algorithm only from the statement and constraints. The checker compares stdout tokens exactly, so match the required token count, order, and formatting. Use Python 3 and buffered whole-input parsing and output assembly. Instantiate the largest stated constraints and derive concrete time and memory bounds before coding. Reject repeated rescans, slicing, convolutions, or state tables that exceed them. The largest case must retain substantial runtime margin rather than merely finish at the limit. Check indexing, duplicates, boundaries, precision, and all statement samples. During pairwise loops keep operands in fresh local names, and test compressed or greedy invariants against literal exhaustive reasoning on the smallest legal instances.\n\nOutput protocol:\nFirst instantiate the largest stated constraints and derive a concrete time and memory bound. Reject any recurrence, convolution, state table, or repeated scan that cannot meet that bound. Then return only one complete efficient Python 3 program as raw source: no prose, fences, reference implementation, or sample-specific branch.", "response": "import sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nn = data[0]\na = data[1:1 + n]\n\nlast = {}\nanswer = n + 1\n\nfor i, value in enumerate(a):\n    previous = last.get(value)\n    if previous is not None:\n        length = i - previous + 1\n        if length < answer:\n            answer = length\n    last[value] = i\n\nsys.stdout.write(str(-1 if answer == n + 1 else answer))", "cost_usd": 0.00040339999999999994, "tokens_in": 565, "tokens_out": 242, "latency_s": 3.175}, {"task_id": "lcb-abc395_c", "model": "openai/gpt-5.6-luna", "prompt": "You are given a positive integer N and an integer sequence A = (A_1,A_2,\\dots,A_N) of length N.\nDetermine whether there exists a non-empty (contiguous) subarray of A that has a repeated value, occurring multiple times in A. If such a subarray exists, find the length of the shortest such subarray.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\dots A_N\n\nOutput\n\nIf there is no (contiguous) subarray satisfying the condition in the problem statement, print -1. Otherwise, print the length of the shortest such subarray.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- 1 \\leq A_i \\leq 10^6 \\ (1 \\leq i \\leq N)\n- All input values are integers.\n\nSample Input 1\n\n5\r\n3 9 5 3 1\n\nSample Output 1\n\n4\r\n\n(3,9,5,3) and (3,9,5,3,1) satisfy the condition. The shorter one is (3,9,5,3), which has length 4.\n\nSample Input 2\n\n4\r\n2 5 3 1\n\nSample Output 2\n\n-1\r\n\nThere is no subarray that satisfies the condition.\n\nSample Input 3\n\n10\r\n1 1 2 3 5 8 13 21 34 55\n\nSample Output 3\n\n2\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nGeneral reliability protocol: Derive the algorithm only from the statement and constraints. The checker compares stdout tokens exactly, so match the required token count, order, and formatting. Use Python 3 and buffered whole-input parsing and output assembly. Instantiate the largest stated constraints and derive concrete time and memory bounds before coding. Reject repeated rescans, slicing, convolutions, or state tables that exceed them. The largest case must retain substantial runtime margin rather than merely finish at the limit. Check indexing, duplicates, boundaries, precision, and all statement samples. During pairwise loops keep operands in fresh local names, and test compressed or greedy invariants against literal exhaustive reasoning on the smallest legal instances.\n\nEfficient program under test:\nimport sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nn = data[0]\na = data[1:1 + n]\n\nlast = {}\nanswer = n + 1\n\nfor i, value in enumerate(a):\n    previous = last.get(value)\n    if previous is not None:\n        length = i - previous + 1\n        if length < answer:\n            answer = length\n    last[value] = i\n\nsys.stdout.write(str(-1 if answer == n + 1 else answer))\n\n\nBuild independent executable test tooling; do not rewrite the efficient program or assume its invariant.\nReturn exactly two fenced blocks and no prose. Generator accepts integer seed and size command-line arguments, calls random.seed(seed), and prints one legal input. Reference is a literal exhaustive solver for small legal inputs and must not use an optimized invariant.\nUse literal tiny inputs when size is at most 5, but for larger values grow a main dimension toward the statement constraints instead of capping every case at toy size. The reference may reject larger smoke-test inputs.\nConstruct and verify every promised input property inside the generator instead of guessing values. In particular validate primality when a field must be prime, construct permutations by shuffling a complete range, and construct required graph properties by design.\n```generator\n<program>\n```\n```reference\n<program>\n```", "response": "```generator\nimport sys\nimport random\n\ndef main():\n    if len(sys.argv) != 3:\n        raise SystemExit(\"usage: generator SEED SIZE\")\n\n    seed = int(sys.argv[1])\n    size = int(sys.argv[2])\n    random.seed(seed)\n\n    if size < 1 or size > 200000:\n        raise SystemExit(\"size must be between 1 and 200000\")\n\n    tiny = {\n        1: [[1]],\n        2: [[1, 1], [1, 2]],\n        3: [[1, 2, 1], [1, 2, 3], [5, 5, 5]],\n        4: [[1, 2, 3, 1], [1, 2, 2, 3], [1, 2, 3, 4]],\n        5: [[3, 9, 5, 3, 1], [1, 1, 2, 3, 5], [1, 2, 3, 4, 5]],\n    }\n\n    if size <= 5:\n        values = tiny[size][seed % len(tiny[size])].copy()\n    else:\n        mode = seed % 5\n        if mode == 0:\n            values = [random.randint(1, 10**6) for _ in range(size)]\n        elif mode == 1:\n            values = [(i % 997) + 1 for i in range(size)]\n            random.shuffle(values)\n        elif mode == 2:\n            values = [random.randint(1, max(1, size // 20)) for _ in range(size)]\n        elif mode == 3:\n            values = list(range(1, size + 1))\n            random.shuffle(values)\n        else:\n            values = [random.randint(1, 10**6) for _ in range(size)]\n            if size >= 2:\n                p = random.randrange(size - 1)\n                values[p + 1] = values[p]\n\n    assert len(values) == size\n    assert all(1 <= x <= 10**6 for x in values)\n\n    out = [str(size), \" \".join(map(str, values))]\n    sys.stdout.write(\"\\n\".join(out) + \"\\n\")\n\nif __name__ == \"__main__\":\n    main()\n```\n\n```reference\nimport sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    if not data:\n        return\n\n    n = data[0]\n    a = data[1:1 + n]\n\n    if n > 2000:\n        raise SystemExit(\"reference solver accepts n <= 2000\")\n\n    best = n + 1\n\n    for left in range(n):\n        seen = set()\n        for right in range(left, n):\n            value = a[right]\n            if value in seen:\n                length = right - left + 1\n                if length < best:\n                    best = length\n                break\n            seen.add(value)\n\n    sys.stdout.write(str(-1 if best == n + 1 else best))\n\nif __name__ == \"__main__\":\n    main()\n```", "cost_usd": 0.001569, "tokens_in": 783, "tokens_out": 1177, "latency_s": 9.707}, {"task_id": "lcb-abc395_c", "model": "google/gemini-3.6-flash", "prompt": "You are given a positive integer N and an integer sequence A = (A_1,A_2,\\dots,A_N) of length N.\nDetermine whether there exists a non-empty (contiguous) subarray of A that has a repeated value, occurring multiple times in A. If such a subarray exists, find the length of the shortest such subarray.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\dots A_N\n\nOutput\n\nIf there is no (contiguous) subarray satisfying the condition in the problem statement, print -1. Otherwise, print the length of the shortest such subarray.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- 1 \\leq A_i \\leq 10^6 \\ (1 \\leq i \\leq N)\n- All input values are integers.\n\nSample Input 1\n\n5\r\n3 9 5 3 1\n\nSample Output 1\n\n4\r\n\n(3,9,5,3) and (3,9,5,3,1) satisfy the condition. The shorter one is (3,9,5,3), which has length 4.\n\nSample Input 2\n\n4\r\n2 5 3 1\n\nSample Output 2\n\n-1\r\n\nThere is no subarray that satisfies the condition.\n\nSample Input 3\n\n10\r\n1 1 2 3 5 8 13 21 34 55\n\nSample Output 3\n\n2\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nGeneral reliability protocol: Derive the algorithm only from the statement and constraints. The checker compares stdout tokens exactly, so match the required token count, order, and formatting. Use Python 3 and buffered whole-input parsing and output assembly. Instantiate the largest stated constraints and derive concrete time and memory bounds before coding. Reject repeated rescans, slicing, convolutions, or state tables that exceed them. The largest case must retain substantial runtime margin rather than merely finish at the limit. Check indexing, duplicates, boundaries, precision, and all statement samples. During pairwise loops keep operands in fresh local names, and test compressed or greedy invariants against literal exhaustive reasoning on the smallest legal instances.\n\nA separate solver proposed this program:\nimport sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nn = data[0]\na = data[1:1 + n]\n\nlast = {}\nanswer = n + 1\n\nfor i, value in enumerate(a):\n    previous = last.get(value)\n    if previous is not None:\n        length = i - previous + 1\n        if length < answer:\n            answer = length\n    last[value] = i\n\nsys.stdout.write(str(-1 if answer == n + 1 else answer))\n\n\nIndependently derive a competing efficient solution and executable test tooling. Do not copy its invariant.\nSolve independently without copying the prior candidate. Return exactly three fenced blocks and no prose. The candidate block must contain a complete Python 3 solution. The generator block must contain a Python program accepting integer seed and size command-line arguments, calling random.seed(seed), and printing one small legal input derived only from the statement. Vary ties, duplicates, boundaries, operation order, and branch combinations. For size values up to 5, emit literal tiny cases suitable for the reference. For larger size values, grow at least one main input dimension toward the stated constraints so the efficient candidate receives a performance smoke test; do not cap every output at a toy size. The generated input must remain legal.\nThe reference block must be a literal exhaustive solver for only small legal inputs and must not reuse the candidate invariant. The first candidate fence must be labeled python so the validator extracts exactly the executable candidate used by the selector.\n```python\n<program>\n```\n```generator\n<program>\n```\n```reference\n<program>\n```", "response": "```python\nimport sys\n\ndef main():\n    input_data = sys.stdin.read().split()\n    if not input_data:\n        return\n    n = int(input_data[0])\n    a = [int(x) for x in input_data[1:n+1]]\n    \n    last_pos = {}\n    min_len = n + 1\n    \n    for idx, val in enumerate(a):\n        if val in last_pos:\n            length = idx - last_pos[val] + 1\n            if length < min_len:\n                min_len = length\n        last_pos[val] = idx\n        \n    if min_len > n:\n        print(-1)\n    else:\n        print(min_len)\n\nif __name__ == '__main__':\n    main()\n```\n\n```generator\nimport sys\nimport random\n\ndef main():\n    if len(sys.argv) < 3:\n        return\n    seed = int(sys.argv[1])\n    size = int(sys.argv[2])\n    random.seed(seed)\n    \n    if size <= 5:\n        n = random.randint(1, 10)\n        max_v = random.choice([2, 5, 10, 100])\n    else:\n        n = random.randint(150000, 200000)\n        max_v = random.choice([5, 1000, 1000000])\n        \n    a = [random.randint(1, max_v) for _ in range(n)]\n    print(n)\n    print(*(a))\n\nif __name__ == '__main__':\n    main()\n```\n\n```reference\nimport sys\n\ndef main():\n    input_data = sys.stdin.read().split()\n    if not input_data:\n        return\n    n = int(input_data[0])\n    a = [int(x) for x in input_data[1:n+1]]\n    \n    best = float('inf')\n    for l in range(n):\n        seen = set()\n        for r in range(l, n):\n            if a[r] in seen:\n                length = r - l + 1\n                if length < best:\n                    best = length\n                break\n            seen.add(a[r])\n            \n    if best == float('inf'):\n        print(-1)\n    else:\n        print(best)\n\nif __name__ == '__main__':\n    main()\n```", "cost_usd": 0.004732499999999999, "tokens_in": 870, "tokens_out": 1088, "latency_s": 5.705}]