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+[{"task_id": "mmlu-8163", "model": "deepseek/deepseek-v4-flash", "prompt": "[MMLU] Which two planets are most similar in size diameter wise?\nA) Mars and Mercury\nB) Venus and Earth\nC) Uranus and Neptune\nD) Jupiter and Saturn\n\nAnswer with the letter only.\n\nEnd with one final line of exactly the form 'Answer: X' and nothing afterwards \u2014 X is the option letter when options are listed, otherwise the final value.", "response": "B", "cost_usd": 0.0001127518, "tokens_in": 82, "tokens_out": 638, "latency_s": 214.958}, {"task_id": "mmlu-6540", "model": "deepseek/deepseek-v4-flash", "prompt": "[MMLU] What does the doctrine of incorporation suggest in respect of treaties?\nA) The doctrine of incorporation requires that all treaties undergo legislative transformation before they become domestic law\nB) The doctrine of incorporation does not require any further action at the domestic level\nC) The doctrine of incorporation treats treaties as inferior to domestic law\nD) The doctrine of incorporation suggests that ratified treaties automatically pass into the sphere of domestic law\n\nAnswer with the letter only.\n\nEnd with one final line of exactly the form 'Answer: X' and nothing afterwards \u2014 X is the option letter when options are listed, otherwise the final value.", "response": "D", "cost_usd": 3.6179999999999996e-05, "tokens_in": 128, "tokens_out": 137, "latency_s": 4.995}, {"task_id": "gsm8k-788", "model": "openai/gpt-5.6-luna", "prompt": "John is raising money for a school trip. He has applied for help from the school, which has decided to cover half the cost of the trip. How much money is John missing if he has $50 and the trip costs $300?\n\nReason step by step, then give the final answer as a single number.\n\nEnd with one final line of exactly the form 'Answer: X' and nothing afterwards \u2014 X is the option letter when options are listed, otherwise the final value.", "response": "The trip costs $300.\n\nThe school covers half: $300 \u00f7 2 = $150.\n\nJohn needs to pay the remaining $150. He has $50, so he is missing $150 \u2212 $50 = $100.\n\nAnswer: 100", "cost_usd": 0.000132, "tokens_in": 102, "tokens_out": 93, "latency_s": 2.427}, {"task_id": "gsm8k-1245", "model": "openai/gpt-5.6-luna", "prompt": "Mary is making ice cubes with fruit frozen in them for a cocktail party. She makes some strawberry cubes, and a number of blueberry cubes equal to 5 times the number of strawberry cubes minus 4. If she makes 116 ice cubes total, how many blueberry cubes does she make?\n\nReason step by step, then give the final answer as a single number.\n\nEnd with one final line of exactly the form 'Answer: X' and nothing afterwards \u2014 X is the option letter when options are listed, otherwise the final value.", "response": "Let \\(s\\) be the number of strawberry cubes.\n\nThe number of blueberry cubes is \\(5s-4\\), and the total is 116:\n\n\\[\ns+(5s-4)=116\n\\]\n\n\\[\n6s=120\n\\]\n\n\\[\ns=20\n\\]\n\nThus, the number of blueberry cubes is:\n\n\\[\n5(20)-4=96\n\\]\n\nAnswer: 96", "cost_usd": 0.0002048, "tokens_in": 112, "tokens_out": 152, "latency_s": 3.037}, {"task_id": "lcb-abc400_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given two positive integers N and M.\nLet X = \\displaystyle\\sum_{i = 0}^{M} N^i. If X \\leq 10^9, print the value of X. If X > 10^9, print inf.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\n\nOutput\n\nPrint the value of X or inf as specified by the problem statement.\n\nConstraints\n\n\n- 1 \\leq N \\leq 10^9\n- 1 \\leq M \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n400\r\n\nX = 1 + 7 + 49 + 343 = 400. Since 400 \\leq 10^9, print 400.\n\nSample Input 2\n\n1000000 2\n\nSample Output 2\n\ninf\r\n\nX = 1000001000001 > 10^9, so print inf.\n\nSample Input 3\n\n999999999 1\n\nSample Output 3\n\n1000000000\n\nSample Input 4\n\n998244353 99\n\nSample Output 4\n\ninf\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nThe checker compares stdout token by token; anything but an exact match scores zero. Mirror the published sample outputs literally \u2014 identical lines, and identical decimal digit counts wherever the samples print decimals.\n\nUse Python 3. Read the whole of stdin with one buffered read before parsing; assemble the entire output first and emit it with a single write. Prefer exact integer or Fraction arithmetic over floats for counting and comparison. Reply with the program alone: no commentary, no code fences.\n\nBefore finishing: when a loop compares or swaps two picked items, store them in fresh local names instead of rebinding the loop variables, or later iterations read corrupted state. Duplicated elements count once per occurrence \u2014 never deduplicate through a set unless the statement says distinct.\n\nTake the largest stated constraints and derive the required complexity before writing code. Long inputs demand a near-linear pass without repeated slicing or rescanning; tiny object counts may instead allow exhaustive enumeration over canonical states.", "response": "import sys\n\ndata = sys.stdin.buffer.read().split()\nn = int(data[0])\nm = int(data[1])\n\nlimit = 10**9\ntotal = 0\npower = 1\n\nfor _ in range(m + 1):\n    total += power\n    if total > limit:\n        answer = \"inf\"\n        break\n    power *= n\nelse:\n    answer = str(total)\n\nsys.stdout.write(answer + \"\\n\")", "cost_usd": 0.0006556000000000001, "tokens_in": 476, "tokens_out": 467, "latency_s": 4.647}, {"task_id": "lcb-abc400_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given two positive integers N and M.\nLet X = \\displaystyle\\sum_{i = 0}^{M} N^i. If X \\leq 10^9, print the value of X. If X > 10^9, print inf.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\n\nOutput\n\nPrint the value of X or inf as specified by the problem statement.\n\nConstraints\n\n\n- 1 \\leq N \\leq 10^9\n- 1 \\leq M \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n400\r\n\nX = 1 + 7 + 49 + 343 = 400. Since 400 \\leq 10^9, print 400.\n\nSample Input 2\n\n1000000 2\n\nSample Output 2\n\ninf\r\n\nX = 1000001000001 > 10^9, so print inf.\n\nSample Input 3\n\n999999999 1\n\nSample Output 3\n\n1000000000\n\nSample Input 4\n\n998244353 99\n\nSample Output 4\n\ninf\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nThe checker compares stdout token by token; anything but an exact match scores zero. Mirror the published sample outputs literally \u2014 identical lines, and identical decimal digit counts wherever the samples print decimals.\n\nUse Python 3. Read the whole of stdin with one buffered read before parsing; assemble the entire output first and emit it with a single write. Prefer exact integer or Fraction arithmetic over floats for counting and comparison. Reply with the program alone: no commentary, no code fences.\n\nBefore finishing: when a loop compares or swaps two picked items, store them in fresh local names instead of rebinding the loop variables, or later iterations read corrupted state. Duplicated elements count once per occurrence \u2014 never deduplicate through a set unless the statement says distinct.\n\nTake the largest stated constraints and derive the required complexity before writing code. Long inputs demand a near-linear pass without repeated slicing or rescanning; tiny object counts may instead allow exhaustive enumeration over canonical states.\n\nNow build test tooling for that solution and output nothing else. First a REFERENCE program: obviously correct, allowed to be very slow \u2014 simulate directly or enumerate every possibility, and deliberately avoid the algorithmic idea used above so the two can disagree. It reads the same stdin format and prints the same output format; handling small inputs only is fine. Second a GENERATOR program: it takes two command line integers, seed and size, calls random.seed(seed), and prints one random valid input in exactly the statement's input format, size being a rough magnitude clamped to the constraints. At size 2 print the smallest legal input. At maximum size, every seed must produce genuinely independent high-entropy values, while smaller sizes should also cover repeats, range extremes and adversarial orderings. Never draw most maximum-size values from a tiny pool. Also write a second BOUNDARY GENERATOR with a different construction strategy. It has the same seed and size interface, but concentrates on valid maximum-size, high-diversity and worst-case-shaped inputs rather than ordinary random cases. Respond with exactly three fenced blocks:\n```reference\n<program>\n```\n```generator\n<program>\n```\n```boundary_generator\n<program>\n```", "response": "```reference\nimport sys\n\ndata = sys.stdin.buffer.read().split()\nn = int(data[0])\nm = int(data[1])\n\ntotal = 0\nfor i in range(m + 1):\n    total += n ** i\n\nif total <= 10**9:\n    sys.stdout.write(str(total))\nelse:\n    sys.stdout.write(\"inf\")\n```\n\n```generator\nimport random\nimport sys\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nk = max(2, min(100, size))\n\nif k == 2:\n    n, m = 1, 1\nelif k == 100:\n    n = random.randint(1, 10**9)\n    m = random.randint(1, 100)\nelse:\n    mode = random.randrange(8)\n    if mode == 0:\n        n = 1\n        m = random.randint(1, k)\n    elif mode == 1:\n        n = random.randint(1, min(10**9, 10 ** min(9, k - 1)))\n        m = 1\n    elif mode == 2:\n        n = 10**9\n        m = random.randint(1, k)\n    elif mode == 3:\n        n = random.randint(max(1, 10**9 - 10**6), 10**9)\n        m = random.randint(1, k)\n    elif mode == 4:\n        n = random.randint(1, 10)\n        m = random.randint(1, k)\n    elif mode == 5:\n        n = random.choice([1, 2, 999999999, 10**9])\n        m = random.randint(1, k)\n    elif mode == 6:\n        n = random.randint(1, min(10**9, 10 ** min(9, k)))\n        m = k\n    else:\n        n = random.randint(1, min(10**9, 10 ** min(9, k)))\n        m = random.randint(1, k)\n\nsys.stdout.write(f\"{n} {m}\\n\")\n```\n\n```boundary_generator\nimport random\nimport sys\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nk = max(2, min(100, size))\n\nif k == 2:\n    n, m = 1, 1\nelif k == 100:\n    m = 1 + (random.getrandbits(7) % 100)\n    if m == 1:\n        n = 999900000 + (random.getrandbits(20) % 100000)\n    elif m == 2:\n        n = 28000 + (random.getrandbits(14) % 8001)\n    elif m == 3:\n        n = 800 + (random.getrandbits(12) % 1201)\n    else:\n        n = 1 + (random.getrandbits(30) % 10**9)\nelse:\n    mode = random.randrange(7)\n    if mode == 0:\n        n, m = 999999999, 1\n    elif mode == 1:\n        n, m = 10**9, 1\n    elif mode == 2:\n        n, m = random.randint(999900000, 10**9), 1\n    elif mode == 3:\n        n, m = random.randint(28000, 36000), min(2, k)\n    elif mode == 4:\n        n, m = random.randint(800, 2000), min(3, k)\n    elif mode == 5:\n        n, m = random.randint(1, 3), k\n    else:\n        n = random.randint(1, min(10**9, 10 ** min(9, k)))\n        m = random.randint(1, k)\n\nsys.stdout.write(f\"{n} {m}\\n\")\n```", "cost_usd": 0.0035126000000000003, "tokens_in": 721, "tokens_out": 2807, "latency_s": 26.129}, {"task_id": "lcb-abc395_c", "model": "openai/gpt-5.6-luna", "prompt": "You are given a positive integer N and an integer sequence A = (A_1,A_2,\\dots,A_N) of length N.\nDetermine whether there exists a non-empty (contiguous) subarray of A that has a repeated value, occurring multiple times in A. If such a subarray exists, find the length of the shortest such subarray.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\dots A_N\n\nOutput\n\nIf there is no (contiguous) subarray satisfying the condition in the problem statement, print -1. Otherwise, print the length of the shortest such subarray.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- 1 \\leq A_i \\leq 10^6 \\ (1 \\leq i \\leq N)\n- All input values are integers.\n\nSample Input 1\n\n5\r\n3 9 5 3 1\n\nSample Output 1\n\n4\r\n\n(3,9,5,3) and (3,9,5,3,1) satisfy the condition. The shorter one is (3,9,5,3), which has length 4.\n\nSample Input 2\n\n4\r\n2 5 3 1\n\nSample Output 2\n\n-1\r\n\nThere is no subarray that satisfies the condition.\n\nSample Input 3\n\n10\r\n1 1 2 3 5 8 13 21 34 55\n\nSample Output 3\n\n2\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nThe checker compares stdout token by token; anything but an exact match scores zero. Mirror the published sample outputs literally \u2014 identical lines, and identical decimal digit counts wherever the samples print decimals.\n\nUse Python 3. Read the whole of stdin with one buffered read before parsing; assemble the entire output first and emit it with a single write. Prefer exact integer or Fraction arithmetic over floats for counting and comparison. Reply with the program alone: no commentary, no code fences.\n\nBefore finishing: when a loop compares or swaps two picked items, store them in fresh local names instead of rebinding the loop variables, or later iterations read corrupted state. Duplicated elements count once per occurrence \u2014 never deduplicate through a set unless the statement says distinct.\n\nTake the largest stated constraints and derive the required complexity before writing code. Long inputs demand a near-linear pass without repeated slicing or rescanning; tiny object counts may instead allow exhaustive enumeration over canonical states.", "response": "import sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nn = data[0]\nlast = {}\nbest = n + 1\n\nfor i in range(n):\n    value = data[i + 1]\n    if value in last:\n        length = i - last[value] + 1\n        if length < best:\n            best = length\n    last[value] = i\n\nanswer = str(best if best <= n else -1) + \"\\n\"\nsys.stdout.write(answer)\n", "cost_usd": 0.0006002000000000004, "tokens_in": 553, "tokens_out": 408, "latency_s": 5.081}, {"task_id": "lcb-abc395_c", "model": "openai/gpt-5.6-luna", "prompt": "You are given a positive integer N and an integer sequence A = (A_1,A_2,\\dots,A_N) of length N.\nDetermine whether there exists a non-empty (contiguous) subarray of A that has a repeated value, occurring multiple times in A. If such a subarray exists, find the length of the shortest such subarray.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\dots A_N\n\nOutput\n\nIf there is no (contiguous) subarray satisfying the condition in the problem statement, print -1. Otherwise, print the length of the shortest such subarray.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- 1 \\leq A_i \\leq 10^6 \\ (1 \\leq i \\leq N)\n- All input values are integers.\n\nSample Input 1\n\n5\r\n3 9 5 3 1\n\nSample Output 1\n\n4\r\n\n(3,9,5,3) and (3,9,5,3,1) satisfy the condition. The shorter one is (3,9,5,3), which has length 4.\n\nSample Input 2\n\n4\r\n2 5 3 1\n\nSample Output 2\n\n-1\r\n\nThere is no subarray that satisfies the condition.\n\nSample Input 3\n\n10\r\n1 1 2 3 5 8 13 21 34 55\n\nSample Output 3\n\n2\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nThe checker compares stdout token by token; anything but an exact match scores zero. Mirror the published sample outputs literally \u2014 identical lines, and identical decimal digit counts wherever the samples print decimals.\n\nUse Python 3. Read the whole of stdin with one buffered read before parsing; assemble the entire output first and emit it with a single write. Prefer exact integer or Fraction arithmetic over floats for counting and comparison. Reply with the program alone: no commentary, no code fences.\n\nBefore finishing: when a loop compares or swaps two picked items, store them in fresh local names instead of rebinding the loop variables, or later iterations read corrupted state. Duplicated elements count once per occurrence \u2014 never deduplicate through a set unless the statement says distinct.\n\nTake the largest stated constraints and derive the required complexity before writing code. Long inputs demand a near-linear pass without repeated slicing or rescanning; tiny object counts may instead allow exhaustive enumeration over canonical states.\n\nNow build test tooling for that solution and output nothing else. First a REFERENCE program: obviously correct, allowed to be very slow \u2014 simulate directly or enumerate every possibility, and deliberately avoid the algorithmic idea used above so the two can disagree. It reads the same stdin format and prints the same output format; handling small inputs only is fine. Second a GENERATOR program: it takes two command line integers, seed and size, calls random.seed(seed), and prints one random valid input in exactly the statement's input format, size being a rough magnitude clamped to the constraints. At size 2 print the smallest legal input. At maximum size, every seed must produce genuinely independent high-entropy values, while smaller sizes should also cover repeats, range extremes and adversarial orderings. Never draw most maximum-size values from a tiny pool. Also write a second BOUNDARY GENERATOR with a different construction strategy. It has the same seed and size interface, but concentrates on valid maximum-size, high-diversity and worst-case-shaped inputs rather than ordinary random cases. Respond with exactly three fenced blocks:\n```reference\n<program>\n```\n```generator\n<program>\n```\n```boundary_generator\n<program>\n```", "response": "```reference\nimport sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nif not data:\n    sys.exit()\n\nn = data[0]\na = data[1:1 + n]\nbest = n + 1\n\nfor left in range(n):\n    counts = {}\n    for right in range(left, n):\n        value = a[right]\n        counts[value] = counts.get(value, 0) + 1\n        if counts[value] >= 2:\n            length = right - left + 1\n            if length < best:\n                best = length\n            break\n\nif best == n + 1:\n    sys.stdout.write(\"-1\\n\")\nelse:\n    sys.stdout.write(str(best) + \"\\n\")\n```\n\n```generator\nimport random\nimport sys\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nif size == 2:\n    sys.stdout.write(\"1\\n1\\n\")\n    sys.exit()\n\nn = max(1, min(size, 200000))\n\nif n == 1:\n    values = [random.randint(1, 1000000)]\nelif n >= 10000:\n    values = [random.randint(1, 1000000) for _ in range(n)]\n    mode = random.randrange(5)\n    if mode == 0:\n        values[0] = 1\n        values[-1] = 1000000\n    elif mode == 1:\n        values[-1] = values[0]\n    elif mode == 2:\n        values[1] = values[0]\n    elif mode == 3:\n        values[n // 2] = values[0]\n    else:\n        values[0] = 1000000\n        values[-1] = 1\nelse:\n    mode = random.randrange(7)\n    if mode == 0:\n        values = [random.randint(1, 1000000) for _ in range(n)]\n    elif mode == 1:\n        values = [random.randint(1, max(1, n // 2 + 1)) for _ in range(n)]\n    elif mode == 2:\n        values = [1 if i % 2 == 0 else 1000000 for i in range(n)]\n    elif mode == 3:\n        values = sorted(random.randint(1, 1000000) for _ in range(n))\n    elif mode == 4:\n        values = [1, 1000000] * ((n + 1) // 2)\n        values = values[:n]\n    elif mode == 5:\n        values = [random.randint(1, 1000000) for _ in range(n)]\n        if n >= 2:\n            values[-1] = values[0]\n    else:\n        values = [random.randint(1, 1000000) for _ in range(n)]\n        if n >= 2:\n            values[1] = values[0]\n\nout = str(n) + \"\\n\" + \" \".join(map(str, values)) + \"\\n\"\nsys.stdout.write(out)\n```\n\n```boundary_generator\nimport math\nimport random\nimport sys\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nif size == 2:\n    sys.stdout.write(\"1\\n1\\n\")\n    sys.exit()\n\nn = max(1, min(size, 200000))\n\nif n == 1:\n    sys.stdout.write(\"1\\n\" + str(random.randint(1, 1000000)) + \"\\n\")\n    sys.exit()\n\nmodulus = 1000000\nstart = random.randrange(modulus)\nstep = random.randrange(1, modulus)\nwhile math.gcd(step, modulus) != 1:\n    step = random.randrange(1, modulus)\n\nbase = [((start + i * step) % modulus) + 1 for i in range(n)]\nmode = seed % 6\n\nif mode == 0:\n    values = base\nelif mode == 1:\n    values = base[:]\n    values[-1] = values[0]\nelif mode == 2:\n    values = base[:]\n    values[1] = values[0]\nelif mode == 3:\n    values = base[:]\n    values[n // 2] = values[0]\nelif mode == 4:\n    values = []\n    lo = 0\n    hi = n - 1\n    while lo <= hi:\n        values.append(base[lo])\n        lo += 1\n        if lo <= hi:\n            values.append(base[hi])\n            hi -= 1\n    values[-1] = values[0]\nelse:\n    values = list(reversed(base))\n    values[-1] = values[0]\n\nout = str(n) + \"\\n\" + \" \".join(map(str, values)) + \"\\n\"\nsys.stdout.write(out)\n```", "cost_usd": 0.0028091999999999995, "tokens_in": 798, "tokens_out": 2208, "latency_s": 21.02}]