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+[{"task_id": "mmlu-4173", "model": "deepseek/deepseek-v4-flash", "prompt": "[MMLU] Which of the following would reduce economic growth?\nA) A decline in investment.\nB) An increase in immigration from abroad.\nC) A technological advance.\nD) An increase in the labor force.\n\nAnswer with the letter only.\n\nEnd with one final line of exactly the form 'Answer: X' and nothing afterwards \u2014 X is the option letter when options are listed, otherwise the final value.", "response": "Answer: A", "cost_usd": 3.14e-05, "tokens_in": 87, "tokens_out": 35, "latency_s": 3.525}, {"task_id": "mmlu-2304", "model": "deepseek/deepseek-v4-flash", "prompt": "[MMLU] A dime has a radius of about 0.85 cm. Which measurement is closest to the circumference of a dime?\nA) 1.33 cm\nB) 1.70 cm\nC) 2.67 cm\nD) 5.34 cm\n\nAnswer with the letter only.\n\nEnd with one final line of exactly the form 'Answer: X' and nothing afterwards \u2014 X is the option letter when options are listed, otherwise the final value.", "response": "Answer: D", "cost_usd": 3.16897e-05, "tokens_in": 103, "tokens_out": 147, "latency_s": 15.126}, {"task_id": "gsm8k-288", "model": "openai/gpt-5.6-luna", "prompt": "A landscaping company is delivering flagstones to a customer\u2019s yard. Each flagstone weighs 75 pounds. If the delivery trucks can carry a total weight of 2000 pounds, how many trucks will be needed to transport 80 flagstones in one trip?\n\nReason step by step, then give the final answer as a single number.\n\nEnd with one final line of exactly the form 'Answer: X' and nothing afterwards \u2014 X is the option letter when options are listed, otherwise the final value.", "response": "Each truck can carry 2000 pounds.\n\n80 flagstones weigh:\n80 \u00d7 75 = 6000 pounds\n\nNumber of trucks needed:\n6000 \u00f7 2000 = 3\n\nAnswer: 3", "cost_usd": 0.0001352, "tokens_in": 106, "tokens_out": 95, "latency_s": 2.417}, {"task_id": "gsm8k-809", "model": "openai/gpt-5.6-luna", "prompt": "Dale is selling butterscotch candies to raise money for his club at school. He doesn't have the candies yet and is instead just taking orders. He started off with 100 total that he ordered and wanted to sell, but he ended up selling 150 butterscotch candies. Then he ordered 100 more. How many does Dale still need to sell to sell all of his candy?\n\nReason step by step, then give the final answer as a single number.\n\nEnd with one final line of exactly the form 'Answer: X' and nothing afterwards \u2014 X is the option letter when options are listed, otherwise the final value.", "response": "Dale ordered 100 candies initially and then ordered 100 more, for a total of 200 candies.\n\nHe sold 150 candies, so:\n\n200 \u2212 150 = 50\n\nAnswer: 50", "cost_usd": 0.00020219999999999998, "tokens_in": 135, "tokens_out": 146, "latency_s": 2.657}, {"task_id": "lcb-abc390_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer sequence A=(A_1,A_2,A_3,A_4,A_5) obtained by permuting (1,2,3,4,5).\nDetermine whether A can be sorted in ascending order by performing exactly one operation of swapping two adjacent elements in A.\n\nInput\n\nThe input is given from Standard Input in the following format:\nA_1 A_2 A_3 A_4 A_5\n\nOutput\n\nIf A can be sorted in ascending order by exactly one operation, print Yes; otherwise, print No.\n\nConstraints\n\n\n- A is an integer sequence of length 5 obtained by permuting (1,2,3,4,5).\n\nSample Input 1\n\n1 2 4 3 5\n\nSample Output 1\n\nYes\r\n\nBy swapping A_3 and A_4, A becomes (1,2,3,4,5), so it can be sorted in ascending order. Therefore, print Yes.\n\nSample Input 2\n\n5 3 2 4 1\n\nSample Output 2\n\nNo\r\n\nNo matter what operation is performed, it is impossible to sort A in ascending order.\n\nSample Input 3\n\n1 2 3 4 5\n\nSample Output 3\n\nNo\r\n\nYou must perform exactly one operation.\n\nSample Input 4\n\n2 1 3 4 5\n\nSample Output 4\n\nYes\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nThe checker compares stdout token by token; anything but an exact match scores zero. Mirror the published sample outputs literally \u2014 identical lines, and identical decimal digit counts wherever the samples print decimals.\n\nUse Python 3. Read the whole of stdin with one buffered read before parsing; assemble the entire output first and emit it with a single write. Prefer exact integer or Fraction arithmetic over floats for counting and comparison. Reply with the program alone: no commentary, no code fences.\n\nBefore finishing: when a loop compares or swaps two picked items, store them in fresh local names instead of rebinding the loop variables, or later iterations read corrupted state. Duplicated elements count once per occurrence \u2014 never deduplicate through a set unless the statement says distinct.", "response": "import sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\ntarget = sorted(data)\nresult = \"No\"\n\nfor i in range(4):\n    swapped = data.copy()\n    left_value = data[i]\n    right_value = data[i + 1]\n    swapped[i] = right_value\n    swapped[i + 1] = left_value\n    if swapped == target:\n        result = \"Yes\"\n        break\n\nsys.stdout.write(result + \"\\n\")\n", "cost_usd": 0.00043979999999999996, "tokens_in": 477, "tokens_out": 287, "latency_s": 3.552}, {"task_id": "lcb-abc390_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer sequence A=(A_1,A_2,A_3,A_4,A_5) obtained by permuting (1,2,3,4,5).\nDetermine whether A can be sorted in ascending order by performing exactly one operation of swapping two adjacent elements in A.\n\nInput\n\nThe input is given from Standard Input in the following format:\nA_1 A_2 A_3 A_4 A_5\n\nOutput\n\nIf A can be sorted in ascending order by exactly one operation, print Yes; otherwise, print No.\n\nConstraints\n\n\n- A is an integer sequence of length 5 obtained by permuting (1,2,3,4,5).\n\nSample Input 1\n\n1 2 4 3 5\n\nSample Output 1\n\nYes\r\n\nBy swapping A_3 and A_4, A becomes (1,2,3,4,5), so it can be sorted in ascending order. Therefore, print Yes.\n\nSample Input 2\n\n5 3 2 4 1\n\nSample Output 2\n\nNo\r\n\nNo matter what operation is performed, it is impossible to sort A in ascending order.\n\nSample Input 3\n\n1 2 3 4 5\n\nSample Output 3\n\nNo\r\n\nYou must perform exactly one operation.\n\nSample Input 4\n\n2 1 3 4 5\n\nSample Output 4\n\nYes\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nThe checker compares stdout token by token; anything but an exact match scores zero. Mirror the published sample outputs literally \u2014 identical lines, and identical decimal digit counts wherever the samples print decimals.\n\nUse Python 3. Read the whole of stdin with one buffered read before parsing; assemble the entire output first and emit it with a single write. Prefer exact integer or Fraction arithmetic over floats for counting and comparison. Reply with the program alone: no commentary, no code fences.\n\nBefore finishing: when a loop compares or swaps two picked items, store them in fresh local names instead of rebinding the loop variables, or later iterations read corrupted state. Duplicated elements count once per occurrence \u2014 never deduplicate through a set unless the statement says distinct.\n\nNow build test tooling for that solution and output nothing else. First a REFERENCE program: obviously correct, allowed to be very slow \u2014 simulate directly or enumerate every possibility, and deliberately avoid the algorithmic idea used above so the two can disagree. It reads the same stdin format and prints the same output format; handling small inputs only is fine. Second a GENERATOR program: it takes two command line integers, seed and size, calls random.seed(seed), and prints one random valid input in exactly the statement's input format, size being a rough magnitude clamped to the constraints. At size 2 print the smallest legal input. At maximum size, every seed must produce genuinely independent high-entropy values, while smaller sizes should also cover repeats, range extremes and adversarial orderings. Never draw most maximum-size values from a tiny pool. Also write a second BOUNDARY GENERATOR with a different construction strategy. It has the same seed and size interface, but concentrates on valid maximum-size, high-diversity and worst-case-shaped inputs rather than ordinary random cases. Respond with exactly three fenced blocks:\n```reference\n<program>\n```\n```generator\n<program>\n```\n```boundary_generator\n<program>\n```", "response": "```reference\nimport sys\n\ndata = sys.stdin.buffer.read().split()\na = [int(x) for x in data]\ntarget = [1, 2, 3, 4, 5]\n\nanswer = \"No\"\nfor i in range(4):\n    b = a[:]\n    left = b[i]\n    right = b[i + 1]\n    b[i] = right\n    b[i + 1] = left\n    if b == target:\n        answer = \"Yes\"\n        break\n\nsys.stdout.write(answer + \"\\n\")\n```\n\n```generator\nimport sys\nimport random\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nsize = max(2, min(5, size))\na = [1, 2, 3, 4, 5]\n\nif size == 2:\n    pass\nelif size == 3:\n    mode = random.randrange(4)\n    if mode == 1:\n        a[0], a[1] = a[1], a[0]\n    elif mode == 2:\n        a[1], a[2] = a[2], a[1]\n    elif mode == 3:\n        random.shuffle(a)\nelif size == 4:\n    mode = random.randrange(3)\n    if mode == 0:\n        random.shuffle(a)\n    elif mode == 1:\n        i = random.randrange(4)\n        a[i], a[i + 1] = a[i + 1], a[i]\n    else:\n        a.reverse()\nelse:\n    random.shuffle(a)\n\nsys.stdout.write(\" \".join(map(str, a)) + \"\\n\")\n```\n\n```boundary_generator\nimport sys\nimport random\nimport itertools\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nsize = max(2, min(5, size))\n\nif size == 2:\n    result = [1, 2, 3, 4, 5]\nelif size < 5:\n    patterns = [\n        [1, 2, 3, 4, 5],\n        [2, 1, 3, 4, 5],\n        [1, 3, 2, 4, 5],\n        [5, 4, 3, 2, 1],\n        [2, 3, 4, 5, 1],\n    ]\n    result = patterns[random.randrange(len(patterns))][:]\nelse:\n    permutations = list(itertools.permutations(range(1, 6)))\n\n    def inversions(p):\n        total = 0\n        for i in range(5):\n            for j in range(i + 1, 5):\n                first = p[i]\n                second = p[j]\n                if first > second:\n                    total += 1\n        return total\n\n    difficult = [p for p in permutations if inversions(p) >= 5]\n    result = list(difficult[random.randrange(len(difficult))])\n\nsys.stdout.write(\" \".join(map(str, result)) + \"\\n\")\n```", "cost_usd": 0.0019324, "tokens_in": 722, "tokens_out": 1490, "latency_s": 14.5}, {"task_id": "lcb-arc194_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer sequence of length N: (A_1, A_2, \\ldots, A_N). There is also a sequence S, which is initially empty.\nFor each i = 1, 2, \\ldots, N in this order, you perform exactly one of the following two operations:\n\n- Append A_i as an element to the end of S.\n- Delete the last element of S. You cannot choose this operation if S is empty.\n\nPrint the maximum possible value of the sum of the elements of S after all operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- -10^9 \\leq A_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n6\r\n3 -1 -4 5 -9 2\n\nSample Output 1\n\n8\r\n\nStarting from the initial state where S is an empty sequence, consider the following operations:\n\n- For i = 1, append A_1 = 3 to the end of S. Now, S = (3).\n- For i = 2, append A_2 = -1 to the end of S. Now, S = (3, -1).\n- For i = 3, delete the last element of S. Now, S = (3).\n- For i = 4, append A_4 = 5 to the end of S. Now, S = (3, 5).\n- For i = 5, append A_5 = -9 to the end of S. Now, S = (3, 5, -9).\n- For i = 6, delete the last element of S. Now, S = (3, 5).\n\nHere, the sum of the elements of S after all operations is 3 + 5 = 8, which is the maximum possible value.\n\nSample Input 2\n\n1\r\n-1\n\nSample Output 2\n\n-1\r\n\nNote that if S is empty, you must choose to append an element.\n\nSample Input 3\n\n20\r\n-14 74 -48 38 -51 43 5 37 -39 -29 80 -44 -55 59 17 89 -37 -68 38 -16\n\nSample Output 3\n\n369\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nThe checker compares stdout token by token; anything but an exact match scores zero. Mirror the published sample outputs literally \u2014 identical lines, and identical decimal digit counts wherever the samples print decimals.\n\nUse Python 3. Read the whole of stdin with one buffered read before parsing; assemble the entire output first and emit it with a single write. Prefer exact integer or Fraction arithmetic over floats for counting and comparison. Reply with the program alone: no commentary, no code fences.\n\nBefore finishing: when a loop compares or swaps two picked items, store them in fresh local names instead of rebinding the loop variables, or later iterations read corrupted state. Duplicated elements count once per occurrence \u2014 never deduplicate through a set unless the statement says distinct.\n\nTake the largest stated constraints and derive the required complexity before writing code. Long inputs demand a near-linear pass without repeated slicing or rescanning; tiny object counts may instead allow exhaustive enumeration over canonical states.", "response": "import sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nn = data[0]\na = data[1:]\n\nneg_inf = -10**30\nbest_odd = neg_inf\nbest_even = neg_inf\n\nfor i, x in enumerate(a, 1):\n    if i & 1:\n        candidate = x\n        if best_even != neg_inf:\n            candidate = max(candidate, best_even + x)\n        if candidate > best_odd:\n            best_odd = candidate\n    else:\n        if best_odd != neg_inf:\n            candidate = best_odd + x\n            if candidate > best_even:\n                best_even = candidate\n\nanswer = best_odd if n & 1 else max(0, best_even)\nsys.stdout.write(str(answer) + \"\\n\")", "cost_usd": 0.0059502, "tokens_in": 747, "tokens_out": 4834, "latency_s": 54.965}, {"task_id": "lcb-arc194_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer sequence of length N: (A_1, A_2, \\ldots, A_N). There is also a sequence S, which is initially empty.\nFor each i = 1, 2, \\ldots, N in this order, you perform exactly one of the following two operations:\n\n- Append A_i as an element to the end of S.\n- Delete the last element of S. You cannot choose this operation if S is empty.\n\nPrint the maximum possible value of the sum of the elements of S after all operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- -10^9 \\leq A_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n6\r\n3 -1 -4 5 -9 2\n\nSample Output 1\n\n8\r\n\nStarting from the initial state where S is an empty sequence, consider the following operations:\n\n- For i = 1, append A_1 = 3 to the end of S. Now, S = (3).\n- For i = 2, append A_2 = -1 to the end of S. Now, S = (3, -1).\n- For i = 3, delete the last element of S. Now, S = (3).\n- For i = 4, append A_4 = 5 to the end of S. Now, S = (3, 5).\n- For i = 5, append A_5 = -9 to the end of S. Now, S = (3, 5, -9).\n- For i = 6, delete the last element of S. Now, S = (3, 5).\n\nHere, the sum of the elements of S after all operations is 3 + 5 = 8, which is the maximum possible value.\n\nSample Input 2\n\n1\r\n-1\n\nSample Output 2\n\n-1\r\n\nNote that if S is empty, you must choose to append an element.\n\nSample Input 3\n\n20\r\n-14 74 -48 38 -51 43 5 37 -39 -29 80 -44 -55 59 17 89 -37 -68 38 -16\n\nSample Output 3\n\n369\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nThe checker compares stdout token by token; anything but an exact match scores zero. Mirror the published sample outputs literally \u2014 identical lines, and identical decimal digit counts wherever the samples print decimals.\n\nUse Python 3. Read the whole of stdin with one buffered read before parsing; assemble the entire output first and emit it with a single write. Prefer exact integer or Fraction arithmetic over floats for counting and comparison. Reply with the program alone: no commentary, no code fences.\n\nBefore finishing: when a loop compares or swaps two picked items, store them in fresh local names instead of rebinding the loop variables, or later iterations read corrupted state. Duplicated elements count once per occurrence \u2014 never deduplicate through a set unless the statement says distinct.\n\nTake the largest stated constraints and derive the required complexity before writing code. Long inputs demand a near-linear pass without repeated slicing or rescanning; tiny object counts may instead allow exhaustive enumeration over canonical states.\n\nNow build test tooling for that solution and output nothing else. First a REFERENCE program: obviously correct, allowed to be very slow \u2014 simulate directly or enumerate every possibility, and deliberately avoid the algorithmic idea used above so the two can disagree. It reads the same stdin format and prints the same output format; handling small inputs only is fine. Second a GENERATOR program: it takes two command line integers, seed and size, calls random.seed(seed), and prints one random valid input in exactly the statement's input format, size being a rough magnitude clamped to the constraints. At size 2 print the smallest legal input. At maximum size, every seed must produce genuinely independent high-entropy values, while smaller sizes should also cover repeats, range extremes and adversarial orderings. Never draw most maximum-size values from a tiny pool. Also write a second BOUNDARY GENERATOR with a different construction strategy. It has the same seed and size interface, but concentrates on valid maximum-size, high-diversity and worst-case-shaped inputs rather than ordinary random cases. Respond with exactly three fenced blocks:\n```reference\n<program>\n```\n```generator\n<program>\n```\n```boundary_generator\n<program>\n```", "response": "```reference\nimport sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    if not data:\n        return\n    n = data[0]\n    a = data[1:1 + n]\n    sys.setrecursionlimit(max(1000, n + 100))\n\n    stack = []\n    best = None\n\n    def dfs(i, total):\n        nonlocal best\n        if i == n:\n            if best is None or total > best:\n                best = total\n            return\n\n        value = a[i]\n\n        stack.append(value)\n        dfs(i + 1, total + value)\n        stack.pop()\n\n        if stack:\n            removed = stack.pop()\n            dfs(i + 1, total - removed)\n            stack.append(removed)\n\n    dfs(0, 0)\n    sys.stdout.write(str(best) + \"\\n\")\n\nif __name__ == \"__main__\":\n    main()\n```\n\n```generator\nimport random\nimport sys\n\ndef main():\n    seed = int(sys.argv[1])\n    size = int(sys.argv[2])\n    random.seed(seed)\n\n    if size == 2:\n        sys.stdout.write(\"1\\n-1\\n\")\n        return\n\n    n = max(1, min(200000, size))\n    mode = seed % 6\n\n    if n == 200000:\n        values = [random.randint(-10**9, 10**9) for _ in range(n)]\n        for i in range(0, n, 9973):\n            values[i] = 10**9 if (i // 9973 + seed) % 2 == 0 else -10**9\n    elif mode == 0:\n        values = [random.randint(-10**9, 10**9) for _ in range(n)]\n    elif mode == 1:\n        values = []\n        for i in range(n):\n            if i % 4 == 0:\n                values.append(10**9)\n            elif i % 4 == 1:\n                values.append(-10**9)\n            else:\n                values.append(random.randint(-100, 100))\n    elif mode == 2:\n        pool = [-10**9, -1000, -1, 0, 1, 7, 1000, 10**9]\n        values = [random.choice(pool) for _ in range(n)]\n    elif mode == 3:\n        values = sorted(random.randint(-10**9, 10**9) for _ in range(n))\n        if seed & 1:\n            values.reverse()\n    elif mode == 4:\n        values = []\n        for i in range(n):\n            block = (i // max(1, n // 8)) % 2\n            if block == 0:\n                values.append(random.randint(1, 10**9))\n            else:\n                values.append(random.randint(-10**9, -1))\n    else:\n        values = [random.randint(-10**9, 10**9) for _ in range(n)]\n        for i in range(0, n, 11):\n            values[i] = -10**9\n        for i in range(5, n, 17):\n            values[i] = 10**9\n\n    out = str(n) + \"\\n\" + \" \".join(map(str, values)) + \"\\n\"\n    sys.stdout.write(out)\n\nif __name__ == \"__main__\":\n    main()\n```\n\n```boundary_generator\nimport random\nimport sys\n\ndef splitmix64(x):\n    x = (x + 0x9E3779B97F4A7C15) & ((1 << 64) - 1)\n    x = (x ^ (x >> 30)) * 0xBF58476D1CE4E5B9 & ((1 << 64) - 1)\n    x = (x ^ (x >> 27)) * 0x94D049BB133111EB & ((1 << 64) - 1)\n    return x ^ (x >> 31)\n\ndef main():\n    seed = int(sys.argv[1])\n    size = int(sys.argv[2])\n    random.seed(seed)\n\n    if size == 2:\n        sys.stdout.write(\"1\\n-1\\n\")\n        return\n\n    n = max(1, min(200000, size))\n\n    if n == 200000:\n        values = []\n        state = seed & ((1 << 64) - 1)\n        for i in range(n):\n            state = splitmix64(state + i * 0xD1342543DE82EF95)\n            magnitude = state % 1000000000 + 1\n            phase = i % 32\n            if i % 9973 == 0:\n                value = 1000000000 if (i // 9973 + seed) % 2 == 0 else -1000000000\n            elif phase < 16:\n                value = magnitude\n            else:\n                value = -magnitude\n            values.append(value)\n    else:\n        mode = (seed // 7) % 5\n        if mode == 0:\n            values = []\n            for i in range(n):\n                if i % 2 == 0:\n                    values.append(10**9 - (i % 1000))\n                else:\n                    values.append(-10**9 + (i % 1000))\n        elif mode == 1:\n            values = [((i * 7919 + seed) % 2000000001) - 1000000000\n                      for i in range(n)]\n        elif mode == 2:\n            values = []\n            for i in range(n):\n                magnitude = (i * i + 31 * seed + 17) % 1000000001\n                values.append(magnitude if i % 3 else -magnitude)\n        elif mode == 3:\n            values = [random.randint(-10**9, 10**9) for _ in range(n)]\n            values.sort(key=lambda x: abs(x), reverse=True)\n        else:\n            values = []\n            for i in range(n):\n                if i % 8 < 5:\n                    values.append(random.randint(1, 10**9))\n                else:\n                    values.append(random.randint(-10**9, -1))\n\n    out = str(n) + \"\\n\" + \" \".join(map(str, values)) + \"\\n\"\n    sys.stdout.write(out)\n\nif __name__ == \"__main__\":\n    main()\n```", "cost_usd": 0.004338399999999999, "tokens_in": 992, "tokens_out": 3450, "latency_s": 31.454}]