File size: 2,067 Bytes
eb970af 99de2e5 eb970af 99de2e5 eb970af 99de2e5 eb970af 99de2e5 eb970af | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 | """Join dictated single-letter runs before the text model, never after it."""
import re
NORMALIZATION_VERSION = "spelled-letter-runs-v2"
# Horizontal whitespace only: distinct lines/paragraphs are not one spelling run.
_RUN = re.compile(r'(?<![A-Za-z0-9_./:@+\-])(?>[A-Za-z](?:(?:[-‐‑‒–—]|[ \t\u00a0]+)[A-Za-z])+)(?![A-Za-z0-9_./:@+\-])')
_LITERAL = re.compile(
r'```[\s\S]*?(?:```|\Z)|`[^`\n]*(?:`|\Z)'
r'|https?://[^\s，。！？；、）]+'
r'|[A-Za-z0-9._%+\-]+@[A-Za-z0-9.\-]+\.[A-Za-z]{2,}'
r'|(?:~/|/)[A-Za-z0-9_./~\-]+'
r'|\b[A-Za-z_]\w*\s*(?:==|!=|<=|>=|:=|[+*/\-]?=)\s*[^;\n，。]+'
)
def spelled_letter_runs(text):
"""Yield unambiguous-enough spelling spans, preserving letter order.
Three or more separate letters, or two uppercase space-separated letters.
A two-letter hyphenated expression such as X-Y is left alone.
Literal code, paths, URLs and emails are not interpreted as dictation.
"""
literals=[m.span() for m in _LITERAL.finditer(text)]
for match in _RUN.finditer(text):
a,b=match.span()
if any(a<end and b>start for start,end in literals):continue
letters=re.findall('[A-Za-z]',match[0])
if len(letters)<3 and not (all(c.isupper() for c in letters) and re.search('[ \t\u00a0]',match[0])):continue
yield a,b,''.join(letters).lower()
def sentence_start(text,position):
prefix=text[:position]
line=prefix.rsplit('\n',1)[-1]
if re.fullmatch(r"[ \t]*(?:(?:[-*•]|\d+[.)、])[ \t]+)?[“‘\"'「（(\[]*[ \t]*",line):return True
prefix=prefix.rstrip()
while prefix and prefix[-1] in '“‘"\'「（([':
prefix=prefix[:-1].rstrip()
return not prefix or prefix[-1] in '.!?。！？'
def normalize_spelled_letters(text):
pieces=[];position=0;count=0
for start,end,word in spelled_letter_runs(text):
if sentence_start(text,start):word=word.capitalize()
pieces.extend([text[position:start],word]);position=end;count+=1
pieces.append(text[position:])
return ''.join(pieces),count
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