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+[{"task_id": "mmlu-11351", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] In a large city littering is always a problem. The state anti-littering statute forbids throwing trash and other matter from any vehicle onto the public roads. It's a summary offense carrying a $50 fine and no imprisonment. On the third offense, the fine is $500 and there is a 5-day jail sentence. The statute does not mention any requirement of criminal intent. John and his family are coming back from a weekend picnic when his children throw bags of refuse and the remains of their lunch out of the rear window of the moving vehicle. John is stopped and given a $50 ticket. Can he succeed with a defense that he didn't know what his children were doing and that he had no criminal intent to break any laws?\nA) No, because this is likely a strict liability law that does not provide for defenses based on mental state.\nB) Yes, because he didn't know what his children were doing in the back seat and he had not participated in the violation nor did he know that they did it or were going to do it.\nC) Yes, because the police have no way of proving who in the car threw the garbage out the window.\nD) No, because his criminal intent is clearly established by the circumstances of the events.\n\nAnswer with the letter only.", "response": "A", "cost_usd": 0.0014925, "tokens_in": 280, "tokens_out": 143, "latency_s": 2.521}, {"task_id": "mmlu-7359", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] Which of the following statements about Hirschsprung disease is incorrect?\nA) It shows an association with Down syndrome.\nB) It is more common in girls than in boys.\nC) RET is a major susceptibility gene.\nD) Recurrence risks are greater for long segment disease than for short segment disease.\n\nAnswer with the letter only.", "response": "B", "cost_usd": 0.0008970000000000002, "tokens_in": 78, "tokens_out": 104, "latency_s": 1.273}, {"task_id": "gsm8k-437", "model": "google/gemini-3.6-flash", "prompt": "Sitti and Juris bought 34 and 22 oranges, respectively. If both of them decide to share them equally with their 6 other friends, how many oranges will everyone get?\n\nReason step by step, then give the final answer as a single number.", "response": "To find out how many oranges everyone will get, we can follow these steps:\n\n1. **Find the total number of oranges:** \n   Sitti has 34 oranges and Juris has 22 oranges.\n   $34 + 22 = 56\\text{ oranges}$\n\n2. **Find the total number of people:** \n   Sitti, Juris, and their 6 other friends make up the group.\n   $1 + 1 + 6 = 8\\text{ people}$\n\n3. **Divide the total oranges by the total number of people:** \n   $56 \\div 8 = 7\\text{ oranges per person}$\n\n7", "cost_usd": 0.0022440000000000003, "tokens_in": 56, "tokens_out": 288, "latency_s": 1.902}, {"task_id": "gsm8k-227", "model": "google/gemini-3.6-flash", "prompt": "Chad ordered a build-your-own burrito for lunch.  The base burrito is $6.50.  He adds extra meat for $2.00, extra cheese for $1.00, avocado for $1.00 and 2 sauces for $0.25 each.  He decides to upgrade his meal for an extra $3.00 which will add chips and a drink.  He has a gift card for $5.00 that he uses at check out.  How much does he still owe?\n\nReason step by step, then give the final answer as a single number.", "response": "To calculate how much Chad still owes, we need to add up the cost of all the items and then subtract the value of his gift card.\n\n1. **Base burrito:** $6.50\n2. **Extra meat:** $2.00\n3. **Extra cheese:** $1.00\n4. **Avocado:** $1.00\n5. **2 sauces:** 2 \u00d7 $0.25 = $0.50\n6. **Meal upgrade:** $3.00\n\n**Total cost before gift card:**\n$6.50 + $2.00 + $1.00 + $1.00 + $0.50 + $3.00 = $14.00\n\n**Subtract the gift card:**\n$14.00 - $5.00 = $9.00\n\n9", "cost_usd": 0.0027075, "tokens_in": 130, "tokens_out": 335, "latency_s": 2.216}, {"task_id": "lcb-abc400_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given two positive integers N and M.\nLet X = \\displaystyle\\sum_{i = 0}^{M} N^i. If X \\leq 10^9, print the value of X. If X > 10^9, print inf.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\n\nOutput\n\nPrint the value of X or inf as specified by the problem statement.\n\nConstraints\n\n\n- 1 \\leq N \\leq 10^9\n- 1 \\leq M \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n400\r\n\nX = 1 + 7 + 49 + 343 = 400. Since 400 \\leq 10^9, print 400.\n\nSample Input 2\n\n1000000 2\n\nSample Output 2\n\ninf\r\n\nX = 1000001000001 > 10^9, so print inf.\n\nSample Input 3\n\n999999999 1\n\nSample Output 3\n\n1000000000\n\nSample Input 4\n\n998244353 99\n\nSample Output 4\n\ninf\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "n, m = map(int, input().split())\n\ntotal = 0\npower = 1\nlimit = 10**9\n\nfor _ in range(m + 1):\n    total += power\n    if total > limit:\n        print(\"inf\")\n        break\n    power *= n\nelse:\n    print(total)\n", "cost_usd": 0.00010290000000000039, "tokens_in": 339, "tokens_out": 115, "latency_s": 3.835}, {"task_id": "lcb-abc394_d", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S consisting of six types of characters: (, ), [, ], <, >.\nA string T is called a colorful bracket sequence if it satisfies the following condition:\n\nIt is possible to turn T into an empty string by repeating the following operation any number of times (possibly zero):\n\n- If there exists a contiguous substring of T that is one of (), [], or <>, choose one such substring and delete it.\n- If the deleted substring was at the beginning or end of T, the remainder becomes the new T.\n- Otherwise, concatenate the part before the deleted substring and the part after the deleted substring, and that becomes the new T.\n\n\nDetermine whether S is a colorful bracket sequence.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nIf S is a colorful bracket sequence, print Yes; otherwise, print No.\n\nConstraints\n\n\n- S is a string of length between 1 and 2\\times 10^5, inclusive.\n- S consists of (, ), [, ], <, >.\n\nSample Input 1\n\n([])<>()\n\nSample Output 1\n\nYes\n\nFor S=([])<>(), it is possible to turn it into an empty string by repeating the operation as follows:\n\n- Delete the substring [] from the 2nd to the 3rd character in ([])<>(), then concatenate the parts before and after it. The string becomes ()<>().\n- Delete the substring () from the 1st to the 2nd character in ()<>(). The string becomes <>().\n- Delete the substring <> from the 1st to the 2nd character in <>(). The string becomes ().\n- Delete the substring () from the 1st to the 2nd character in (). The string becomes empty.\n\nThus, S=([])<>() is a colorful bracket sequence, so print Yes.\n\nSample Input 2\n\n([<)]>\n\nSample Output 2\n\nNo\n\nSince S=([<)]> does not contain (), [], or <> as a contiguous substring, we cannot perform the 1st operation, and in particular S is not a colorful bracket sequence. Therefore, print No.\n\nSample Input 3\n\n())\n\nSample Output 3\n\nNo\n\nIt is impossible to turn S into an empty string by repeating the operations.\nTherefore, S is not a colorful bracket sequence, so print No.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "s = input().strip()\n\npairs = {')': '(', ']': '[', '>': '<'}\nstack = []\n\nfor ch in s:\n    if ch in '([{<':\n        stack.append(ch)\n    else:\n        if not stack or stack[-1] != pairs[ch]:\n            print(\"No\")\n            break\n        stack.pop()\nelse:\n    print(\"Yes\" if not stack else \"No\")", "cost_usd": 0.0001811, "tokens_in": 569, "tokens_out": 207, "latency_s": 4.21}]