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[{"task_id": "mmlu-13118", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] A 2008 survey showed that what percentage of the world's largest companies are reporting their corporate responsibility?\nA) 50%\nB) 60%\nC) 70%\nD) 80%\n\nAnswer with the letter only.", "response": "D", "cost_usd": 0.001161, "tokens_in": 64, "tokens_out": 142, "latency_s": 2.425}, {"task_id": "mmlu-6095", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] Which of the following does NOT usually occur to the lens of the eye as one grows older?\nA) It becomes thicker\nB) It yellows\nC) It becomes clouded\nD) It fills with fluid\n\nAnswer with the letter only.", "response": "D", "cost_usd": 0.000639, "tokens_in": 56, "tokens_out": 74, "latency_s": 1.057}, {"task_id": "gsm8k-11", "model": "google/gemini-3.6-flash", "prompt": "Toula went to the bakery and bought various types of pastries. She bought 3 dozen donuts which cost $68 per dozen, 2 dozen mini cupcakes which cost $80 per dozen, and 6 dozen mini cheesecakes for $55 per dozen. How much was the total cost?\n\nReason step by step, then give the final answer as a single number.", "response": "To find the total cost, we calculate the cost for each type of pastry and add them together:\n\n1. **Donuts:** \n 3 dozen \u00d7 $68 per dozen = $204\n\n2. **Mini cupcakes:** \n 2 dozen \u00d7 $80 per dozen = $160\n\n3. **Mini cheesecakes:** \n 6 dozen \u00d7 $55 per dozen = $330\n\nNow, add the costs together:\n$204 + $160 + $330 = $694\n\n694", "cost_usd": 0.0022470000000000003, "tokens_in": 78, "tokens_out": 284, "latency_s": 2.01}, {"task_id": "gsm8k-940", "model": "google/gemini-3.6-flash", "prompt": "For the children's day celebration, children are to perform mass drills in the presence of the President of the country. They stand 8 in a row and there are 7 rows each for 5 different Schools. How many children can there be in the drill?\n\nReason step by step, then give the final answer as a single number.", "response": "To find the total number of children in the drill, we can calculate step by step:\n\n1. **Calculate the number of children in one school:** \n Each school has 7 rows, and each row has 8 children.\n $8 \\text{ children/row} \\times 7 \\text{ rows} = 56 \\text{ children per school}$\n\n2. **Calculate the total number of children for all schools:** \n There are 5 different schools participating.\n $56 \\text{ children/school} \\times 5 \\text{ schools} = 280 \\text{ children}$\n\n280", "cost_usd": 0.00168, "tokens_in": 70, "tokens_out": 210, "latency_s": 1.67}, {"task_id": "lcb-abc388_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S. Here, the first character of S is an uppercase English letter, and the second and subsequent characters are lowercase English letters.\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nConstraints\n\n\n- S is a string of length between 1 and 100, inclusive.\n- The first character of S is an uppercase English letter.\n- The second and subsequent characters of S are lowercase English letters.\n\nSample Input 1\n\nKyoto\n\nSample Output 1\n\nKUPC\r\n\nThe first character of Kyoto is K, so concatenate K and UPC, and print KUPC.\n\nSample Input 2\n\nTohoku\n\nSample Output 2\n\nTUPC\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "import sys\n\ns = sys.stdin.readline().strip()\nprint(s[0] + \"UPC\")", "cost_usd": 4.13999999999996e-05, "tokens_in": 270, "tokens_out": 24, "latency_s": 0.945}, {"task_id": "lcb-abc392_d", "model": "openai/gpt-5.6-luna", "prompt": "There are N dice.\r\nThe i-th die has K_i faces, with the numbers A_{i,1}, A_{i,2}, \\ldots, A_{i,K_i} written on them.\r\nWhen you roll this die, each face appears with probability \\frac{1}{K_i}.\nYou choose two dice from the N dice and roll them.\r\nDetermine the maximum probability that the two dice show the same number, when the dice are chosen optimally.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nK_1 A_{1,1} A_{1,2} \\dots A_{1,K_1}\r\n\\vdots\r\nK_N A_{N,1} A_{N,2} \\dots A_{N,K_N}\n\nOutput\n\nPrint the answer.\r\nYour answer is considered correct if the absolute or relative error from the true solution does not exceed 10^{-8}.\n\nConstraints\n\n\n- 2 \\leq N \\leq 100\n- 1 \\leq K_i\n- K_1 + K_2 + \\dots + K_N \\leq 10^5\n- 1 \\leq A_{i,j} \\leq 10^5\n- All input values are integers.\n\nSample Input 1\n\n3\r\n3 1 2 3\r\n4 1 2 2 1\r\n6 1 2 3 4 5 6\n\nSample Output 1\n\n0.333333333333333\r\n\n\n- When choosing the 1st and 2nd dice, the probability that the outcomes are the same is \\frac{1}{3}.\n- When choosing the 1st and 3rd dice, the probability is \\frac{1}{6}.\n- When choosing the 2nd and 3rd dice, the probability is \\frac{1}{6}.\n\nTherefore, the maximum probability is \\frac{1}{3} = 0.3333333333\\ldots.\n\nSample Input 2\n\n3\r\n5 1 1 1 1 1\r\n4 2 2 2 2\r\n3 1 1 2\n\nSample Output 2\n\n0.666666666666667\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "import sys\nfrom collections import Counter\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nn = data[0]\nidx = 1\ndice = []\n\nfor _ in range(n):\n k = data[idx]\n idx += 1\n counts = Counter(data[idx:idx + k])\n idx += k\n dice.append((k, counts))\n\nbest_num = 0\nbest_den = 1\n\nfor i in range(n):\n k1, c1 = dice[i]\n for j in range(i + 1, n):\n k2, c2 = dice[j]\n if len(c1) > len(c2):\n c1, c2 = c2, c1\n numerator = sum(v * c2.get(x, 0) for x, v in c1.items())\n denominator = k1 * k2\n if numerator * best_den > best_num * denominator:\n best_num = numerator\n best_den = denominator\n\nprint(f\"{best_num / best_den:.15f}\")", "cost_usd": 0.0005003000000000004, "tokens_in": 557, "tokens_out": 741, "latency_s": 12.105}]
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