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+[{"task_id": "mmlu-6013", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] This question refers to the following information.\nBut the decline of Rome was the natural and inevitable effect of immoderate greatness. Prosperity ripened the principle of decay; the causes of destruction multiplied with the extent of conquest; and, as soon as time or accident had removed the artificial supports, the stupendous fabric yielded to the pressure of its own weight. . . . The victorious legions, who, in distant wars, acquired the vices of strangers and mercenaries, first oppressed the freedom of the republic, and afterwards violated the majesty of the purple. The emperors, anxious for their personal safety and the public peace, were reduced to the base expedient of corrupting the discipline which rendered them alike formidable to their sovereign and to the enemy; the vigour of the military . . . was relaxed . . . ; and the Roman world was overwhelmed by a deluge of Barbarians.\n\u2014Adapted from Decline and Fall of the Roman Empire, by Edward Gibbon\nThe decline of the Roman Empire and that of its Chinese counterpart resulted in which of the following?\nA) A decline in the appeal of religions of salvation\nB) A shift from trade along the Silk Roads to sea routes in the Indian Ocean\nC) An increased importance of the role of the father as the head of the household\nD) A decline in the rights of women\n\nAnswer with the letter only.", "response": "B", "cost_usd": 0.004476, "tokens_in": 279, "tokens_out": 541, "latency_s": 5.403}, {"task_id": "mmlu-7643", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] Which of these is not one of the 3 methods of heat transfer?\nA) Conduction\nB) Radiation\nC) Convection\nD) Induction\n\nAnswer with the letter only.", "response": "D", "cost_usd": 0.00045149999999999964, "tokens_in": 46, "tokens_out": 51, "latency_s": 1.18}, {"task_id": "gsm8k-850", "model": "google/gemini-3.6-flash", "prompt": "Mr. Smith has two farms, Farm X and Farm Y. He has 55 goats in Farm X and 45 goats in Farm Y. He sold 10 goats from Farm X and twice as many goats from Farm Y. How many goats are left in the two farms altogether?\n\nReason step by step, then give the final answer as a single number.", "response": "Step 1: Find the total number of goats initially across both farms.\nTotal initial goats = 55 (Farm X) + 45 (Farm Y) = 100 goats.\n\nStep 2: Calculate how many goats were sold from Farm Y.\nSince he sold twice as many goats from Farm Y as he did from Farm X, he sold 10 \u00d7 2 = 20 goats from Farm Y.\n\nStep 3: Calculate the total number of goats sold.\nTotal sold = 10 (Farm X) + 20 (Farm Y) = 30 goats.\n\nStep 4: Subtract the total goats sold from the total initial goats to find how many are left.\nGoats left = 100 - 30 = 70 goats.\n\n70", "cost_usd": 0.0044565, "tokens_in": 76, "tokens_out": 579, "latency_s": 3.365}, {"task_id": "gsm8k-187", "model": "google/gemini-3.6-flash", "prompt": "Mandy owes Benedict $100. They agreed to have monthly interest of 2%. If Mandy was able to pay it after 3 months, how much should she give to Benedict?\n\nReason step by step, then give the final answer as a single number.", "response": "To find the total amount Mandy needs to give Benedict after 3 months, we calculate the interest accrued over that period using simple interest.\n\n1. **Calculate the monthly interest amount:**\n   $$\\text{Monthly Interest} = \\text{Principal} \\times \\text{Monthly Rate}$$\n   $$\\text{Monthly Interest} = \\$100 \\times 0.02 = \\$2$$\n\n2. **Calculate the total interest for 3 months:**\n   $$\\text{Total Interest} = \\$2 \\times 3 = \\$6$$\n\n3. **Calculate the total amount to pay back:**\n   $$\\text{Total Amount} = \\text{Principal} + \\text{Total Interest}$$\n   $$\\text{Total Amount} = \\$100 + \\$6 = \\$106$$\n\n*(Note: If using compound interest, the total would be $\\$100 \\times (1.02)^3 \\approx \\$106.12$, but simple interest is standard unless specified otherwise).*\n\n106", "cost_usd": 0.003804, "tokens_in": 56, "tokens_out": 496, "latency_s": 3.169}, {"task_id": "lcb-abc388_b", "model": "openai/gpt-5.6-luna", "prompt": "There are N snakes.\nInitially, the thickness of the i-th snake is T_i, and its length is L_i.\nThe weight of a snake is defined as the product of its thickness and length.\nFor each integer k satisfying 1 \\leq k \\leq D, find the weight of the heaviest snake when every snake's length has increased by k.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN D\r\nT_1 L_1\r\nT_2 L_2\r\n\\vdots\r\nT_N L_N\n\nOutput\n\nPrint D lines. The k-th line should contain the weight of the heaviest snake when every snake's length has increased by k.\n\nConstraints\n\n\n- 1 \\leq N, D \\leq 100\n- 1 \\leq T_i, L_i \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n4 3\r\n3 3\r\n5 1\r\n2 4\r\n1 10\n\nSample Output 1\n\n12\r\n15\r\n20\r\n\nWhen every snake\u2019s length has increased by 1, the snakes' weights become 12, 10, 10, 11, so print 12 on the first line.\nWhen every snake\u2019s length has increased by 2, the snakes' weights become 15, 15, 12, 12, so print 15 on the second line.\nWhen every snake\u2019s length has increased by 3, the snakes' weights become 18, 20, 14, 13, so print 20 on the third line.\n\nSample Input 2\n\n1 4\r\n100 100\n\nSample Output 2\n\n10100\r\n10200\r\n10300\r\n10400\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "import sys\n\ndef main():\n    input = sys.stdin.readline\n    n, d = map(int, input().split())\n    snakes = [tuple(map(int, input().split())) for _ in range(n)]\n\n    results = []\n    for k in range(1, d + 1):\n        results.append(str(max(t * (l + k) for t, l in snakes)))\n\n    sys.stdout.write(\"\\n\".join(results))\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.00010759999999999936, "tokens_in": 452, "tokens_out": 104, "latency_s": 1.515}, {"task_id": "lcb-abc400_d", "model": "openai/gpt-5.6-luna", "prompt": "Takahashi is about to go buy eel at a fish shop.\nThe town where he lives is divided into a grid of H rows and W columns. Each cell is either a road or a wall.\r\nLet us denote the cell at the i-th row from the top (1\\leq i \\leq H) and the j-th column from the left (1\\leq j \\leq W) as cell (i,j).\r\nInformation about each cell is given by H strings S_1,S_2,\\ldots,S_H, each of length W. Specifically, if the j-th character of S_i (1\\leq i \\leq H,1\\leq j\\leq W) is ., cell (i,j) is a road; if it is #, cell (i,j) is a wall.\nHe can repeatedly perform the following two types of actions in any order:\n\n- Move to an adjacent cell (up, down, left, or right) that is within the town and is a road.\n- Choose one of the four directions (up, down, left, or right) and perform a front kick in that direction.\r\n  When he performs a front kick, for each of the cells at most 2 steps away in that direction from the cell he is currently in, if that cell is a wall, it becomes a road.\r\n  If some of the cells at most 2 steps away are outside the town, a front kick can still be performed, but anything outside the town does not change.\n\nHe starts in cell (A,B), and he wants to move to the fish shop in cell (C,D).\r\nIt is guaranteed that both the cell where he starts and the cell with the fish shop are roads.\r\nFind the minimum number of front kicks he needs in order to reach the fish shop.\n\nInput\n\nThe input is given from Standard Input in the following format:\nH W\r\nS_1\r\nS_2\r\n\\vdots\r\nS_H\r\nA B C D\n\nOutput\n\nPrint the minimum number of front kicks needed for Takahashi to reach the fish shop.\n\nConstraints\n\n\n- 1\\leq H\\leq 1000\n- 1\\leq W\\leq 1000\n- Each S_i is a string of length W consisting of . and #.\n- 1\\leq A,C\\leq H\n- 1\\leq B,D\\leq W\n- (A,B)\\neq (C,D)\n- H, W, A, B, C, and D are integers.\n- The cell where Takahashi starts and the cell with the fish shop are roads.\n\nSample Input 1\n\n10 10\r\n..........\r\n#########.\r\n#.......#.\r\n#..####.#.\r\n##....#.#.\r\n#####.#.#.\r\n.##.#.#.#.\r\n###.#.#.#.\r\n###.#.#.#.\r\n#.....#...\r\n1 1 7 1\n\nSample Output 1\n\n1\r\n\nTakahashi starts in cell (1,1).\r\nBy repeatedly moving to adjacent road cells, he can reach cell (7,4).\r\nIf he performs a front kick to the left from cell (7,4), cells (7,3) and (7,2) turn from walls to roads.\r\nThen, by continuing to move through road cells (including those that have become roads), he can reach the fish shop in cell (7,1).\nIn this case, the number of front kicks performed is 1, and it is impossible to reach the fish shop without performing any front kicks, so print 1.\n\nSample Input 2\n\n2 2\r\n.#\r\n#.\r\n1 1 2 2\n\nSample Output 2\n\n1\r\n\nTakahashi starts in cell (1,1).\r\nWhen he performs a front kick to the right, cell (1,2) turns from a wall to a road.\r\nThe cell two steps to the right of (1,1) is outside the town, so it does not change.\r\nThen, he can move to cell (1,2) and then to the fish shop in cell (2,2).\nIn this case, the number of front kicks performed is 1, and it is impossible to reach the fish shop without performing any front kicks, so print 1.\n\nSample Input 3\n\n1 3\r\n.#.\r\n1 1 1 3\n\nSample Output 3\n\n1\r\n\nWhen performing a front kick, it is fine if the fish shop\u2019s cell is within the cells that could be turned into a road. Specifically, the fish shop\u2019s cell is a road from the beginning, so it remains unchanged; particularly, the shop is not destroyed by the front kick.\n\nSample Input 4\n\n20 20\r\n####################\r\n##...##....###...###\r\n#.....#.....#.....##\r\n#..#..#..#..#..#..##\r\n#..#..#....##..#####\r\n#.....#.....#..#####\r\n#.....#..#..#..#..##\r\n#..#..#.....#.....##\r\n#..#..#....###...###\r\n####################\r\n####################\r\n##..#..##...###...##\r\n##..#..#.....#.....#\r\n##..#..#..#..#..#..#\r\n##..#..#..#..#..#..#\r\n##.....#..#..#..#..#\r\n###....#..#..#..#..#\r\n#####..#.....#.....#\r\n#####..##...###...##\r\n####################\r\n3 3 18 18\n\nSample Output 4\n\n3\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "import sys\nfrom collections import deque\nfrom array import array\n\ndef main():\n    input = sys.stdin.buffer.readline\n    H, W = map(int, input().split())\n    grid = [input().strip() for _ in range(H)]\n    A, B, C, D = map(int, input().split())\n    A -= 1\n    B -= 1\n    C -= 1\n    D -= 1\n\n    n = H * W\n    start = A * W + B\n    goal = C * W + D\n\n    dist = array('i', [-1]) * n\n    used = bytearray(n)\n    dist[start] = 0\n    q = deque([start])\n\n    while q:\n        v = q.popleft()\n        if used[v]:\n            continue\n        used[v] = 1\n\n        if v == goal:\n            print(dist[v])\n            return\n\n        r, c = divmod(v, W)\n        d = dist[v]\n\n        if r > 0:\n            u = v - W\n            if (grid[r - 1][c] == 46 or dist[u] != -1) and not used[u] and (dist[u] == -1 or dist[u] > d):\n                dist[u] = d\n                q.appendleft(u)\n        if r + 1 < H:\n            u = v + W\n            if (grid[r + 1][c] == 46 or dist[u] != -1) and not used[u] and (dist[u] == -1 or dist[u] > d):\n                dist[u] = d\n                q.appendleft(u)\n        if c > 0:\n            u = v - 1\n            if (grid[r][c - 1] == 46 or dist[u] != -1) and not used[u] and (dist[u] == -1 or dist[u] > d):\n                dist[u] = d\n                q.appendleft(u)\n        if c + 1 < W:\n            u = v + 1\n            if (grid[r][c + 1] == 46 or dist[u] != -1) and not used[u] and (dist[u] == -1 or dist[u] > d):\n                dist[u] = d\n                q.appendleft(u)\n\n        nd = d + 1\n\n        for dr, dc in ((-1, 0), (1, 0), (0, -1), (0, 1)):\n            nr, nc = r + dr, c + dc\n            for _ in range(2):\n                if not (0 <= nr < H and 0 <= nc < W):\n                    break\n                u = nr * W + nc\n                if not used[u] and (dist[u] == -1 or dist[u] > nd):\n                    dist[u] = nd\n                    q.append(u)\n                nr += dr\n                nc += dc\n\n    print(dist[goal])\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.0012074500000000005, "tokens_in": 1258, "tokens_out": 1991, "latency_s": 18.085}]