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+[{"task_id": "mmlu-10805", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] Believing she was pregnant, a woman went to see a doctor, a licensed gynecologist, because she wanted an abortion. The doctor examined her and determined that she was not pregnant, but decided that he would tell her she was, in order to earn his $500 fee. After receiving the $500, the doctor proceeded to have the woman admitted to a hospital by falsely informing the hospital authorities that she had a benign tumor on her uterus, which he was going to remove. He performed all the surgical procedures appropriate for an abortion under adequate hygienic conditions, but the woman began hemorrhaging and died. The doctor should be found guilty of\nA) murder and larceny by trick.\nB) manslaughter and false pretenses.\nC) battery and larceny by trick.\nD) murder, battery, and false pretenses.\n\nAnswer with the letter only.", "response": "D", "cost_usd": 0.0038205, "tokens_in": 182, "tokens_out": 473, "latency_s": 5.576}, {"task_id": "mmlu-13012", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] One of the key features for making a differential diagnosis between bulimia nervosa and anorexia nervosa is:\nA) Purging\nB) Maintaining a normal body weight\nC) Bingeing\nD) All of the above\n\nAnswer with the letter only.", "response": "B", "cost_usd": 0.0012675000000000004, "tokens_in": 60, "tokens_out": 157, "latency_s": 1.546}, {"task_id": "gsm8k-1270", "model": "google/gemini-3.6-flash", "prompt": "Gary bought a boat for $9000.  Over the first year it depreciated 30%.  The second year it depreciated another 30%.  The third year it depreciated 20%.  How much is the boat worth after the three years?\n\nReason step by step, then give the final answer as a single number.", "response": "To find the value of the boat after three years, we calculate the depreciation step by step for each year:\n\n1. **Initial Value:** $9,000\n\n2. **Year 1 Depreciation (30%):**\n   * Depreciation amount = $9,000 \\times 0.30 = $2,700\n   * Value after Year 1 = $9,000 - $2,700 = $6,300\n\n3. **Year 2 Depreciation (30%):**\n   * Depreciation amount = $6,300 \\times 0.30 = $1,890\n   * Value after Year 2 = $6,300 - $1,890 = $4,410\n\n4. **Year 3 Depreciation (20%):**\n   * Depreciation amount = $4,410 \\times 0.20 = $882\n   * Value after Year 3 = $4,410 - $882 = $3,528\n\n3528", "cost_usd": 0.003771, "tokens_in": 74, "tokens_out": 488, "latency_s": 2.759}, {"task_id": "gsm8k-597", "model": "google/gemini-3.6-flash", "prompt": "The three angles in a triangle add up to 180 degrees. One angle is twice the smallest angle, and one angle is three times the smallest angle. What is the measure of the largest angle in the triangle, in degrees?\n\nReason step by step, then give the final answer as a single number.", "response": "To find the measure of the largest angle, we can set up an equation using the information given:\n\n1. Let the smallest angle be $x$.\n2. The second angle is twice the smallest angle, so it is $2x$.\n3. The third angle is three times the smallest angle, so it is $3x$.\n\nThe sum of all three angles in a triangle is always 180 degrees:\n$$x + 2x + 3x = 180$$\n\nCombine like terms:\n$$6x = 180$$\n\nSolve for $x$:\n$$x = 30$$\n\nNow, calculate the measure of each angle:\n- Smallest angle: $30^\\circ$\n- Middle angle: $2 \\times 30^\\circ = 60^\\circ$\n- Largest angle: $3 \\times 30^\\circ = 90^\\circ$\n\nThe measure of the largest angle is 90 degrees.\n\n90", "cost_usd": 0.0028109999999999993, "tokens_in": 64, "tokens_out": 362, "latency_s": 2.575}, {"task_id": "lcb-abc388_b", "model": "openai/gpt-5.6-luna", "prompt": "There are N snakes.\nInitially, the thickness of the i-th snake is T_i, and its length is L_i.\nThe weight of a snake is defined as the product of its thickness and length.\nFor each integer k satisfying 1 \\leq k \\leq D, find the weight of the heaviest snake when every snake's length has increased by k.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN D\r\nT_1 L_1\r\nT_2 L_2\r\n\\vdots\r\nT_N L_N\n\nOutput\n\nPrint D lines. The k-th line should contain the weight of the heaviest snake when every snake's length has increased by k.\n\nConstraints\n\n\n- 1 \\leq N, D \\leq 100\n- 1 \\leq T_i, L_i \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n4 3\r\n3 3\r\n5 1\r\n2 4\r\n1 10\n\nSample Output 1\n\n12\r\n15\r\n20\r\n\nWhen every snake\u2019s length has increased by 1, the snakes' weights become 12, 10, 10, 11, so print 12 on the first line.\nWhen every snake\u2019s length has increased by 2, the snakes' weights become 15, 15, 12, 12, so print 15 on the second line.\nWhen every snake\u2019s length has increased by 3, the snakes' weights become 18, 20, 14, 13, so print 20 on the third line.\n\nSample Input 2\n\n1 4\r\n100 100\n\nSample Output 2\n\n10100\r\n10200\r\n10300\r\n10400\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "import sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    n, d = data[0], data[1]\n    snakes = [(data[i], data[i + 1]) for i in range(2, 2 + 2 * n, 2)]\n\n    out = []\n    for k in range(1, d + 1):\n        out.append(str(max(t * (l + k) for t, l in snakes)))\n\n    sys.stdout.write(\"\\n\".join(out))\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.00012020000000000086, "tokens_in": 452, "tokens_out": 125, "latency_s": 1.521}, {"task_id": "lcb-arc191_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S of length N and a string T of length M, both consisting of digits from 1 to 9.\nYou will perform the following operation for k=1,2,\\ldots,M in order:\n\n- Choose an integer i such that 1 \\le i \\le N. Then, replace the i-th character of S with the k-th character of T.\n\nFind the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nS\nT\n\nOutput\n\nPrint the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nConstraints\n\n\n- 1 \\le N,M \\le 10^6\n- N and M are integers.\n- S is a string of length N consisting of digits from 1 through 9.\n- T is a string of length M consisting of digits from 1 through 9.\n\nSample Input 1\n\n3 3\n191\n325\n\nSample Output 1\n\n593\n\nThe following sequence of operations is optimal:\n\n- For k=1: Choose i=3. Then, S = 193.\n- For k=2: Choose i=1. Then, S = 293.\n- For k=3: Choose i=1. Then, S = 593.\n\nIn this case, the value of S interpreted as an integer is 593, which is the maximum.\n\nSample Input 2\n\n3 9\n191\n998244353\n\nSample Output 2\n\n993\n\nSample Input 3\n\n11 13\n31415926535\n2718281828459\n\nSample Output 3\n\n98888976555\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "import sys\n\ndef main():\n    input = sys.stdin.readline\n    N, M = map(int, input().split())\n    S = list(input().strip())\n    T = input().strip()\n\n    counts = [0] * 10\n    for c in T:\n        counts[ord(c) - 48] += 1\n\n    digits = []\n    for d in range(9, 0, -1):\n        digits.extend([str(d)] * counts[d])\n\n    j = 0\n    for i in range(N):\n        while j < len(digits) and digits[j] <= S[i]:\n            j += 1\n        if j == len(digits):\n            break\n        S[i] = digits[j]\n        j += 1\n\n    sys.stdout.write(''.join(S))\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.0013977, "tokens_in": 447, "tokens_out": 2255, "latency_s": 25.927}]