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+[{"task_id": "mmlu-10269", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] Which of the following is NOT an innovation of the Mesolithic?\nA) canoes\nB) domestication of animals\nC) European use of bow and arrow\nD) crop irrigation systems\n\nAnswer with the letter only.", "response": "D", "cost_usd": 0.0009855, "tokens_in": 52, "tokens_out": 121, "latency_s": 2.28}, {"task_id": "mmlu-10692", "model": "google/gemini-3.6-flash", "prompt": "[MMLU] Two co-defendants were investment brokers at a bank. They had been employed by the bank for ten years. One day, they were unexpectedly fired by the bank's new manager. Apparently, the co-defendants' investments had not been performing well in the economic downturn. The co-defendants, upset and humiliated by their firing, vowed to get back at the bank. As their revenge, they decided to plant a bomb in the bank and demand $2,000,000. After receiving the money, they would then reveal the location of the bomb and provide details for defusing it. The co-defendants agreed that the bank should be given adequate warning so that nobody would be injured. In accordance with their plan, the co-defendants consulted the Internet, where they found all the information they needed on how to build a bomb. They built the bomb and placed it in a supply closet. Shortly thereafter, they phoned the bank and made a demand for the money. They said a bomb was in the bank and that it would explode in 24 hours unless the money was paid. The bank refused to pay the money. Realizing that their plan had gone awry, they drove to the bank to attempt to defuse the bomb. As they were driving back to the bank, the bomb exploded, killing 30 people. If the co-defendants are charged with murder and conspiracy to commit murder, which of the following statements is correct?\nA) Both co-defendants are guilty of felony murder, but neither is guilty of conspiracy to commit murder.\nB) Both co-defendants are guilty of murder and conspiracy to commit murder.\nC) Both co-defendants are guilty of conspiracy to commit murder, but not murder.\nD) Both co-defendants are not guilty of murder and conspiracy to commit murder.\n\nAnswer with the letter only.", "response": "A", "cost_usd": 0.0021975, "tokens_in": 395, "tokens_out": 214, "latency_s": 1.99}, {"task_id": "gsm8k-973", "model": "google/gemini-3.6-flash", "prompt": "India has 4 more than half the number of states in the USA. What's the total number of states in both countries together?\n\nReason step by step, then give the final answer as a single number.", "response": "Here is the step-by-step calculation:\n\n1. **Number of states in the USA:** The USA has 50 states.\n2. **Find half the number of states in the USA:** 50 \u00f7 2 = 25.\n3. **Calculate the number of states in India:** 4 more than 25 is 25 + 4 = 29 states.\n4. **Calculate the total number of states in both countries combined:** 50 + 29 = 79.\n\n79", "cost_usd": 0.00258, "tokens_in": 45, "tokens_out": 335, "latency_s": 2.153}, {"task_id": "gsm8k-780", "model": "google/gemini-3.6-flash", "prompt": "Ava and Emma want to know who is better at the new video game Ava got for her birthday. They are each going to play one level and whoever has the highest score wins. They receive 10 points for every enemy they jump on, 5 points for each berry they collect, and 30 points for every second left on the timer when they finish the level. If Ava jumps on 8 more enemies than Emma and collects 3 more berries, but finishes the level 4 seconds slower, what is the difference between their two scores?\n\nReason step by step, then give the final answer as a single number.", "response": "To find the difference between Ava's and Emma's scores, we can calculate the point gains and losses for Ava relative to Emma:\n\n1. **Enemies jumped on:** Ava jumps on 8 more enemies than Emma.\n   $$8 \\times 10 \\text{ points} = +80 \\text{ points}$$\n\n2. **Berries collected:** Ava collects 3 more berries than Emma.\n   $$3 \\times 5 \\text{ points} = +15 \\text{ points}$$\n\n3. **Time left on the timer:** Ava finishes 4 seconds slower than Emma, which means she has 4 fewer seconds left on her timer.\n   $$-4 \\times 30 \\text{ points} = -120 \\text{ points}$$\n\nNow, combine these point values to find the net difference:\n$$80 + 15 - 120 = -25 \\text{ points}$$\n\nAva has 25 fewer points than Emma (meaning Emma beat Ava by 25 points). The absolute difference between their scores is 25.\n\n25", "cost_usd": 0.004233, "tokens_in": 127, "tokens_out": 539, "latency_s": 3.282}, {"task_id": "lcb-abc400_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given two positive integers N and M.\nLet X = \\displaystyle\\sum_{i = 0}^{M} N^i. If X \\leq 10^9, print the value of X. If X > 10^9, print inf.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\n\nOutput\n\nPrint the value of X or inf as specified by the problem statement.\n\nConstraints\n\n\n- 1 \\leq N \\leq 10^9\n- 1 \\leq M \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n400\r\n\nX = 1 + 7 + 49 + 343 = 400. Since 400 \\leq 10^9, print 400.\n\nSample Input 2\n\n1000000 2\n\nSample Output 2\n\ninf\r\n\nX = 1000001000001 > 10^9, so print inf.\n\nSample Input 3\n\n999999999 1\n\nSample Output 3\n\n1000000000\n\nSample Input 4\n\n998244353 99\n\nSample Output 4\n\ninf\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "n, m = map(int, input().split())\n\nlimit = 10**9\ntotal = 0\npower = 1\n\nfor _ in range(m + 1):\n    total += power\n    if total > limit:\n        print(\"inf\")\n        break\n    power *= n\nelse:\n    print(total)\n", "cost_usd": 7.650000000000018e-05, "tokens_in": 339, "tokens_out": 71, "latency_s": 1.438}, {"task_id": "lcb-abc400_d", "model": "openai/gpt-5.6-luna", "prompt": "Takahashi is about to go buy eel at a fish shop.\nThe town where he lives is divided into a grid of H rows and W columns. Each cell is either a road or a wall.\r\nLet us denote the cell at the i-th row from the top (1\\leq i \\leq H) and the j-th column from the left (1\\leq j \\leq W) as cell (i,j).\r\nInformation about each cell is given by H strings S_1,S_2,\\ldots,S_H, each of length W. Specifically, if the j-th character of S_i (1\\leq i \\leq H,1\\leq j\\leq W) is ., cell (i,j) is a road; if it is #, cell (i,j) is a wall.\nHe can repeatedly perform the following two types of actions in any order:\n\n- Move to an adjacent cell (up, down, left, or right) that is within the town and is a road.\n- Choose one of the four directions (up, down, left, or right) and perform a front kick in that direction.\r\n  When he performs a front kick, for each of the cells at most 2 steps away in that direction from the cell he is currently in, if that cell is a wall, it becomes a road.\r\n  If some of the cells at most 2 steps away are outside the town, a front kick can still be performed, but anything outside the town does not change.\n\nHe starts in cell (A,B), and he wants to move to the fish shop in cell (C,D).\r\nIt is guaranteed that both the cell where he starts and the cell with the fish shop are roads.\r\nFind the minimum number of front kicks he needs in order to reach the fish shop.\n\nInput\n\nThe input is given from Standard Input in the following format:\nH W\r\nS_1\r\nS_2\r\n\\vdots\r\nS_H\r\nA B C D\n\nOutput\n\nPrint the minimum number of front kicks needed for Takahashi to reach the fish shop.\n\nConstraints\n\n\n- 1\\leq H\\leq 1000\n- 1\\leq W\\leq 1000\n- Each S_i is a string of length W consisting of . and #.\n- 1\\leq A,C\\leq H\n- 1\\leq B,D\\leq W\n- (A,B)\\neq (C,D)\n- H, W, A, B, C, and D are integers.\n- The cell where Takahashi starts and the cell with the fish shop are roads.\n\nSample Input 1\n\n10 10\r\n..........\r\n#########.\r\n#.......#.\r\n#..####.#.\r\n##....#.#.\r\n#####.#.#.\r\n.##.#.#.#.\r\n###.#.#.#.\r\n###.#.#.#.\r\n#.....#...\r\n1 1 7 1\n\nSample Output 1\n\n1\r\n\nTakahashi starts in cell (1,1).\r\nBy repeatedly moving to adjacent road cells, he can reach cell (7,4).\r\nIf he performs a front kick to the left from cell (7,4), cells (7,3) and (7,2) turn from walls to roads.\r\nThen, by continuing to move through road cells (including those that have become roads), he can reach the fish shop in cell (7,1).\nIn this case, the number of front kicks performed is 1, and it is impossible to reach the fish shop without performing any front kicks, so print 1.\n\nSample Input 2\n\n2 2\r\n.#\r\n#.\r\n1 1 2 2\n\nSample Output 2\n\n1\r\n\nTakahashi starts in cell (1,1).\r\nWhen he performs a front kick to the right, cell (1,2) turns from a wall to a road.\r\nThe cell two steps to the right of (1,1) is outside the town, so it does not change.\r\nThen, he can move to cell (1,2) and then to the fish shop in cell (2,2).\nIn this case, the number of front kicks performed is 1, and it is impossible to reach the fish shop without performing any front kicks, so print 1.\n\nSample Input 3\n\n1 3\r\n.#.\r\n1 1 1 3\n\nSample Output 3\n\n1\r\n\nWhen performing a front kick, it is fine if the fish shop\u2019s cell is within the cells that could be turned into a road. Specifically, the fish shop\u2019s cell is a road from the beginning, so it remains unchanged; particularly, the shop is not destroyed by the front kick.\n\nSample Input 4\n\n20 20\r\n####################\r\n##...##....###...###\r\n#.....#.....#.....##\r\n#..#..#..#..#..#..##\r\n#..#..#....##..#####\r\n#.....#.....#..#####\r\n#.....#..#..#..#..##\r\n#..#..#.....#.....##\r\n#..#..#....###...###\r\n####################\r\n####################\r\n##..#..##...###...##\r\n##..#..#.....#.....#\r\n##..#..#..#..#..#..#\r\n##..#..#..#..#..#..#\r\n##.....#..#..#..#..#\r\n###....#..#..#..#..#\r\n#####..#.....#.....#\r\n#####..##...###...##\r\n####################\r\n3 3 18 18\n\nSample Output 4\n\n3\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nYour stdout is compared to the expected output token by token, with NO numeric tolerance, even if the statement mentions an allowed error. Match the sample output's exact notation and decimal count. Print nothing else: no prompts, no labels, no trailing text.", "response": "import sys\nfrom collections import deque\n\ninput = sys.stdin.buffer.readline\n\nH, W = map(int, input().split())\nrows = [input().strip() for _ in range(H)]\ngrid = b\"\".join(rows)\nroad = bytearray(1 if c == 46 else 0 for c in grid)\n\nA, B, C, D = map(int, input().split())\nstart = (A - 1) * W + (B - 1)\ngoal = (C - 1) * W + (D - 1)\n\nn = H * W\ndist = [-1] * n\ndist[start] = 0\ndq = deque([(start, 0)])\n\nwhile dq:\n    v, d = dq.popleft()\n    if dist[v] != d:\n        continue\n    if v == goal:\n        print(d)\n        break\n\n    r, c = divmod(v, W)\n\n    if r > 0:\n        u = v - W\n        nd = d if road[u] else d + 1\n        if dist[u] == -1 or nd < dist[u]:\n            dist[u] = nd\n            if nd == d:\n                dq.appendleft((u, nd))\n            else:\n                dq.append((u, nd))\n        if r > 1:\n            u = v - 2 * W\n            nd = d + 1\n            if dist[u] == -1 or nd < dist[u]:\n                dist[u] = nd\n                dq.append((u, nd))\n\n    if r + 1 < H:\n        u = v + W\n        nd = d if road[u] else d + 1\n        if dist[u] == -1 or nd < dist[u]:\n            dist[u] = nd\n            if nd == d:\n                dq.appendleft((u, nd))\n            else:\n                dq.append((u, nd))\n        if r + 2 < H:\n            u = v + 2 * W\n            nd = d + 1\n            if dist[u] == -1 or nd < dist[u]:\n                dist[u] = nd\n                dq.append((u, nd))\n\n    if c > 0:\n        u = v - 1\n        nd = d if road[u] else d + 1\n        if dist[u] == -1 or nd < dist[u]:\n            dist[u] = nd\n            if nd == d:\n                dq.appendleft((u, nd))\n            else:\n                dq.append((u, nd))\n        if c > 1:\n            u = v - 2\n            nd = d + 1\n            if dist[u] == -1 or nd < dist[u]:\n                dist[u] = nd\n                dq.append((u, nd))\n\n    if c + 1 < W:\n        u = v + 1\n        nd = d if road[u] else d + 1\n        if dist[u] == -1 or nd < dist[u]:\n            dist[u] = nd\n            if nd == d:\n                dq.appendleft((u, nd))\n            else:\n                dq.append((u, nd))\n        if c + 2 < W:\n            u = v + 2\n            nd = d + 1\n            if dist[u] == -1 or nd < dist[u]:\n                dist[u] = nd\n                dq.append((u, nd))\nelse:\n    print(dist[goal])", "cost_usd": 0.0015251750000000001, "tokens_in": 1258, "tokens_out": 2280, "latency_s": 20.657}]