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+ [{"task_id": "mmlu-4000", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Of the following choices the most direct exchange in the circular flow model of a private closed economy is when\nA) households provide goods to firms in exchange for wage payments.\nB) households provide resources to firms in exchange for goods.\nC) households provide revenues to firms in exchange for wage payments.\nD) firms supply goods to households in exchange for revenues.\n\nAnswer with the letter only.", "response": "D", "cost_usd": 6.15e-05, "tokens_in": 87, "tokens_out": 88, "latency_s": 2.695}, {"task_id": "mmlu-13037", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] In the context of research design, external validity refers to the researcher\u2019s ability to:\nA) manipulate the independent variable.\nB) randomly assign participants to treatment groups.\nC) determine whether there is a causal relationship between variables.\nD) generalize the results of the study to other individuals, settings, and conditions.\n\nAnswer with the letter only.", "response": "D", "cost_usd": 1.0899999999999994e-05, "tokens_in": 79, "tokens_out": 5, "latency_s": 0.51}, {"task_id": "gsm8k-820", "model": "deepseek/deepseek-v4-flash", "prompt": "Sandy walked from Holloway Shores to Sun Valley Shores for 8 hours on a particular day. She also walked half as many hours on the second day as she walked on the first day, to Hollock valley shores. Calculate the total time Sandy took to walk in the two days in minutes.\n\nReason step by step, then give the final answer as a single number.", "response": "Sandy walked 8 hours on the first day. On the second day, she walked half that amount, which is 4 hours. The total time is 12 hours. Converting to minutes gives 12 \u00d7 60 = 720 minutes.\n\n720", "cost_usd": 4.0768e-05, "tokens_in": 81, "tokens_out": 187, "latency_s": 5.388}, {"task_id": "gsm8k-879", "model": "deepseek/deepseek-v4-flash", "prompt": "At a spa, Iris spent $400 to do her hair, 1/4 as much to do a manicure, and 3/4 as much money as a manicure to do a pedicure. How much money did she spend at the spa?\n\nReason step by step, then give the final answer as a single number.", "response": "Iris spent $400 on her hair. The manicure cost 1/4 of that, which is $100. The pedicure cost 3/4 of the manicure, which is $75. The total spent is $400 + $100 + $75 = $575.\n\n575", "cost_usd": 5.286599999999999e-05, "tokens_in": 73, "tokens_out": 270, "latency_s": 4.142}, {"task_id": "lcb-abc396_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer sequence of length N: A = (A_1,A_2,\\ldots,A_N).\nDetermine whether there is a place in A where the same element appears three or more times in a row.\nMore formally, determine whether there exists an integer i with 1 \\le i \\le N-2 such that A_i = A_{i+1} = A_{i+2}.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nIf there is a place in A where the same element appears three or more times in a row, print Yes. Otherwise, print No.\n\nConstraints\n\n\n- 3 \\le N \\le 100\n- 1 \\le A_i \\le 100\n- All input values are integers.\n\nSample Input 1\n\n5\r\n1 4 4 4 2\n\nSample Output 1\n\nYes\r\n\nWe have A=(1,4,4,4,2). There is a place where 4 appears three times in a row, so print Yes.\n\nSample Input 2\n\n6\r\n2 4 4 2 2 4\n\nSample Output 2\n\nNo\r\n\nWe have A=(2,4,4,2,2,4). There is no place where the same element appears three or more times in a row, so print No.\n\nSample Input 3\n\n8\r\n1 4 2 5 7 7 7 2\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n10\r\n1 2 3 4 5 6 7 8 9 10\n\nSample Output 4\n\nNo\n\nSample Input 5\n\n13\r\n1 1 1 1 1 1 1 1 1 1 1 1 1\n\nSample Output 5\n\nYes\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n data = list(map(int, sys.stdin.read().split()))\n n = data[0]\n a = data[1:1 + n]\n\n for i in range(n - 2):\n if a[i] == a[i + 1] == a[i + 2]:\n print(\"Yes\")\n return\n\n print(\"No\")\n\nif __name__ == \"__main__\":\n main()\n", "cost_usd": 0.00010020000000000002, "tokens_in": 438, "tokens_out": 94, "latency_s": 0.923}, {"task_id": "lcb-abc388_c", "model": "openai/gpt-5.6-luna", "prompt": "There are N mochi (rice cakes) arranged in ascending order of size.\r\nThe size of the i-th mochi (1 \\leq i \\leq N) is A_i.\nGiven two mochi A and B, with sizes a and b respectively, you can make one kagamimochi (a stacked rice cake) by placing mochi A on top of mochi B if and only if a is at most half of b.\nYou choose two mochi out of the N mochi, and place one on top of the other to form one kagamimochi.\nFind how many different kinds of kagamimochi can be made.\nTwo kagamimochi are distinguished if at least one of the mochi is different, even if the sizes of the mochi are the same.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\cdots A_N\n\nOutput\n\nPrint the number of different kinds of kagamimochi that can be made.\n\nConstraints\n\n\n- 2 \\leq N \\leq 5 \\times 10^5\n- 1 \\leq A_i \\leq 10^9 \\ (1 \\leq i \\leq N)\n- A_i \\leq A_{i+1} \\ (1 \\leq i < N)\n- All input values are integers.\n\nSample Input 1\n\n6\r\n2 3 4 4 7 10\n\nSample Output 1\n\n8\r\n\nThe sizes of the given mochi are as follows:\n\nIn this case, you can make the following eight kinds of kagamimochi:\n\nNote that there are two kinds of kagamimochi where a mochi of size 4 is topped by a mochi of size 2, and two kinds where a mochi of size 10 is topped by a mochi of size 4.\n\nSample Input 2\n\n3\r\n387 388 389\n\nSample Output 2\n\n0\r\n\nIt is possible that you cannot make any kagamimochi.\n\nSample Input 3\n\n32\r\n1 2 4 5 8 10 12 16 19 25 33 40 50 64 87 101 149 175 202 211 278 314 355 405 412 420 442 481 512 582 600 641\n\nSample Output 3\n\n388\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n data = list(map(int, sys.stdin.buffer.read().split()))\n n = data[0]\n a = data[1:]\n\n p = 0\n ans = 0\n\n for j in range(n):\n while p < j and 2 * a[p] <= a[j]:\n p += 1\n ans += p\n\n print(ans)\n\nif __name__ == \"__main__\":\n main()\n", "cost_usd": 0.00042440000000000007, "tokens_in": 542, "tokens_out": 617, "latency_s": 5.932}]