message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + 1]. You can apply this operation any number of ... | instruction | 0 | 89,406 | 12 | 178,812 |
Tags: dfs and similar, sortings
Correct Solution:
```
#### Using DSU..... best time complexity
def find(x):
while(x != link[x]):
link[x] = link[link[x]]
x = link[x]
return x
def union(x, y):
x = find(x)
y = find(y)
if x != y:
if size[x] > size[y]:
size[x] += siz... | output | 1 | 89,406 | 12 | 178,813 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + 1]. You can apply this operation any number of ... | instruction | 0 | 89,407 | 12 | 178,814 |
Tags: dfs and similar, sortings
Correct Solution:
```
# import sys
# sys.stdin = open("input.in","r")
# sys.stdout = open("output.out","w")
from collections import defaultdict
t = int(input())
for i in range(t):
n,m = map(int,input().split())
a = list(map(int,input().split()))
p = list(map(int,input().split()))
... | output | 1 | 89,407 | 12 | 178,815 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + 1]. You can apply this operation any number of ... | instruction | 0 | 89,408 | 12 | 178,816 |
Tags: dfs and similar, sortings
Correct Solution:
```
import sys
sys.setrecursionlimit(10 ** 6)
int1 = lambda x: int(x) - 1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.readline())
def MI(): return map(int, sys.stdin.readline().split())
def LI(): return list(map(int, sys.stdin.readline().split())... | output | 1 | 89,408 | 12 | 178,817 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + 1]. You can apply this operation any number of ... | instruction | 0 | 89,409 | 12 | 178,818 |
Tags: dfs and similar, sortings
Correct Solution:
```
from collections import defaultdict
t = int(input().strip())
class Graph:
def __init__(self, V):
self.V = V+1
self.edges = defaultdict(list)
def addEdge(self, u, v):
if v not in self.edges[u]:
self.edges[u].append(v)
... | output | 1 | 89,409 | 12 | 178,819 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + 1]. You can apply this operation any number of ... | instruction | 0 | 89,410 | 12 | 178,820 |
Tags: dfs and similar, sortings
Correct Solution:
```
for i in range(int(input())):
n,m = map(int,input().split())
arr1 = list(map(int,input().split()))
arr2 = list(map(int,input().split()))
sorted(arr2)
for k in range(n):
for j in arr2:
if arr1[j-1]>arr1[j]:
arr1[... | output | 1 | 89,410 | 12 | 178,821 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + 1]. You can apply this operation any number of ... | instruction | 0 | 89,411 | 12 | 178,822 |
Tags: dfs and similar, sortings
Correct Solution:
```
t = int(input())
for _ in range(t):
n, m = [int(i) for i in input().split()]
arr = [int(i) for i in input().split()]
p = [int(i) for i in input().split()]
p.sort()
i = 0
while i < m:
temp = p[i]
k = i+1
while k < m:
... | output | 1 | 89,411 | 12 | 178,823 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + 1]. You can apply this operation any number of ... | instruction | 0 | 89,412 | 12 | 178,824 |
Tags: dfs and similar, sortings
Correct Solution:
```
# import sys
# sys.stdin=open('input.txt', 'r')
# sys.stdout=open('output.txt', 'w')
n=int(input())
for i in range(n):
n, m=[int(k) for k in input().split()]
a=[int(k) for k in input().split()]
p=[int(k)-1 for k in input().split()]
sor=sorted(a)
... | output | 1 | 89,412 | 12 | 178,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + 1]. You can apply this operation any number of ... | instruction | 0 | 89,413 | 12 | 178,826 |
Tags: dfs and similar, sortings
Correct Solution:
```
for t in range(int(input())):
n,m=map(int,input().split())
a=list(map(int,input().split()))
p=list(map(int,input().split()))
mark=True
for i in range(n):
for j in range(n-i-1):
if a[j]>a[j+1]:
if j+1 in p:
... | output | 1 | 89,413 | 12 | 178,827 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + ... | instruction | 0 | 89,414 | 12 | 178,828 |
Yes | output | 1 | 89,414 | 12 | 178,829 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + ... | instruction | 0 | 89,415 | 12 | 178,830 |
Yes | output | 1 | 89,415 | 12 | 178,831 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + ... | instruction | 0 | 89,416 | 12 | 178,832 |
Yes | output | 1 | 89,416 | 12 | 178,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + ... | instruction | 0 | 89,417 | 12 | 178,834 |
Yes | output | 1 | 89,417 | 12 | 178,835 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + ... | instruction | 0 | 89,418 | 12 | 178,836 |
No | output | 1 | 89,418 | 12 | 178,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + ... | instruction | 0 | 89,419 | 12 | 178,838 |
No | output | 1 | 89,419 | 12 | 178,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + ... | instruction | 0 | 89,420 | 12 | 178,840 |
No | output | 1 | 89,420 | 12 | 178,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an array a of length n.
You are also given a set of distinct positions p_1, p_2, ..., p_m, where 1 ≤ p_i < n. The position p_i means that you can swap elements a[p_i] and a[p_i + ... | instruction | 0 | 89,421 | 12 | 178,842 |
No | output | 1 | 89,421 | 12 | 178,843 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integers a_0, a_1, ..., a_{n-1}, you are allowed to:
... | instruction | 0 | 89,471 | 12 | 178,942 |
Tags: brute force, math, number theory, sortings
Correct Solution:
```
import math as m
n = int(input())
x = list(map(int, input().split()))
x.sort()
a = m.floor(x[n-1]**(1/(n-1)))
b = 0
c = 0
for i in range(len(x)):
b += abs(x[i] - a**i)
for i in range(len(x)):
c += abs(x[i] - (a+1)**i)
print(min(c,b))
``` | output | 1 | 89,471 | 12 | 178,943 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integers a_0, a_1, ..., a_{n-1}, you are allowed to:
... | instruction | 0 | 89,472 | 12 | 178,944 |
Tags: brute force, math, number theory, sortings
Correct Solution:
```
import sys
import collections as cc
import random as rd
import math as mt
input = sys.stdin.readline
I = lambda : cc.deque(map(int,input().split()))
n,=I()
l=sorted(I())
if n==2:
print(l[0]-1)
sys.exit()
ans=sum(l)-n
for i in range(2,40000):... | output | 1 | 89,472 | 12 | 178,945 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integers a_0, a_1, ..., a_{n-1}, you are allowed to:
... | instruction | 0 | 89,473 | 12 | 178,946 |
Tags: brute force, math, number theory, sortings
Correct Solution:
```
n = int(input())
a = [int(x) for x in input().split()]
a.sort()
inf = 10**18
if n <= 2:
print(a[0] - 1)
else:
ans = sum(a) - n
for x in range(1, 10**9):
curPow = 1
curCost = 0
for i in range(n):
curC... | output | 1 | 89,473 | 12 | 178,947 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integers a_0, a_1, ..., a_{n-1}, you are allowed to:
... | instruction | 0 | 89,474 | 12 | 178,948 |
Tags: brute force, math, number theory, sortings
Correct Solution:
```
n = int(input())
A = [int(i) for i in input().split()]
A = sorted(A)
m=int(pow(A[-1],1/(n-1)))
_=0
x,y=0,0
for _ in range(n):
u=pow(m,_)
x+=abs(u-A[_])
for _ in range(n):
v=pow(m+1,_)
y+=abs(v-A[_])
print(min(x,y))
``` | output | 1 | 89,474 | 12 | 178,949 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integers a_0, a_1, ..., a_{n-1}, you are allowed to:
... | instruction | 0 | 89,475 | 12 | 178,950 |
Tags: brute force, math, number theory, sortings
Correct Solution:
```
import math
n=int(input())
a=list(map(int,input().split()))
a.sort()
max_r= int(math.ceil(pow(10,9/(n-1))))
lst=[]
for r in range(1,max_r+1):
cost=0
for i in range(n):
if a[i]!=pow(r,i):
cost+= abs(pow(r,i)-a[i])
lst.append(cost)
print(min(l... | output | 1 | 89,475 | 12 | 178,951 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integers a_0, a_1, ..., a_{n-1}, you are allowed to:
... | instruction | 0 | 89,476 | 12 | 178,952 |
Tags: brute force, math, number theory, sortings
Correct Solution:
```
import math
def calc(a,b):
s=0
for i in range(len(a)):
s+=abs(a[i]-b**i)
return s
n=int(input())
a=list(map(int,input().split()))
a.sort()
b=int(a[-1]**(1/(n-1)))
m=calc(a,b)
for i in range(1,10000):
mt=calc(a,b+i)
if mt<... | output | 1 | 89,476 | 12 | 178,953 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integers a_0, a_1, ..., a_{n-1}, you are allowed to:
... | instruction | 0 | 89,477 | 12 | 178,954 |
Tags: brute force, math, number theory, sortings
Correct Solution:
```
import sys
import time
# IO region
FIO = 10
def I(): return input()
def Iint(): return int(input())
def Ilist(): return list(map(int, input().split())) # int list
def Imap(): return map(int, input().split()) # int map
def Plist(li, s=... | output | 1 | 89,477 | 12 | 178,955 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integers a_0, a_1, ..., a_{n-1}, you are allowed to:
... | instruction | 0 | 89,478 | 12 | 178,956 |
Tags: brute force, math, number theory, sortings
Correct Solution:
```
from math import *
from collections import *
from random import *
from decimal import Decimal
from heapq import *
from bisect import *
import sys
input=sys.stdin.readline
sys.setrecursionlimit(10**5)
def lis():
return list(map(int,input().split(... | output | 1 | 89,478 | 12 | 178,957 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integer... | instruction | 0 | 89,479 | 12 | 178,958 |
Yes | output | 1 | 89,479 | 12 | 178,959 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integer... | instruction | 0 | 89,480 | 12 | 178,960 |
Yes | output | 1 | 89,480 | 12 | 178,961 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integer... | instruction | 0 | 89,481 | 12 | 178,962 |
Yes | output | 1 | 89,481 | 12 | 178,963 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integer... | instruction | 0 | 89,482 | 12 | 178,964 |
Yes | output | 1 | 89,482 | 12 | 178,965 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integer... | instruction | 0 | 89,483 | 12 | 178,966 |
No | output | 1 | 89,483 | 12 | 178,967 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integer... | instruction | 0 | 89,484 | 12 | 178,968 |
No | output | 1 | 89,484 | 12 | 178,969 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integer... | instruction | 0 | 89,485 | 12 | 178,970 |
No | output | 1 | 89,485 | 12 | 178,971 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call a list of positive integers a_0, a_1, ..., a_{n-1} a power sequence if there is a positive integer c, so that for every 0 ≤ i ≤ n-1 then a_i = c^i.
Given a list of n positive integer... | instruction | 0 | 89,486 | 12 | 178,972 |
No | output | 1 | 89,486 | 12 | 178,973 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 89,487 | 12 | 178,974 |
Tags: data structures, divide and conquer, dp, greedy, implementation
Correct Solution:
```
import sys
import math
import collections
import bisect
import itertools
import decimal
import copy
import heapq
# import numpy as np
# sys.setrecursionlimit(10 ** 6)
INF = 10 **20
# MOD = 10 ** 9 + 7
MOD = 998244353
# ni = l... | output | 1 | 89,487 | 12 | 178,975 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 89,488 | 12 | 178,976 |
Tags: data structures, divide and conquer, dp, greedy, implementation
Correct Solution:
```
import sys
import math
import collections
import bisect
import itertools
import decimal
import copy
import heapq
# import numpy as np
# sys.setrecursionlimit(10 ** 6)
INF = 10 **20
# MOD = 10 ** 9 + 7
MOD = 998244353
# ni = l... | output | 1 | 89,488 | 12 | 178,977 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 89,489 | 12 | 178,978 |
Tags: data structures, divide and conquer, dp, greedy, implementation
Correct Solution:
```
import sys
import array
input=sys.stdin.readline
t=int(input())
for _ in range(t):
n,q=map(int,input().split())
a=array.array("i",[-1]+list(map(int,input().split()))+[-1])
def f(i):
if i<=0 or i>=n+1:
... | output | 1 | 89,489 | 12 | 178,979 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 89,490 | 12 | 178,980 |
Tags: data structures, divide and conquer, dp, greedy, implementation
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
s... | output | 1 | 89,490 | 12 | 178,981 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 89,491 | 12 | 178,982 |
Tags: data structures, divide and conquer, dp, greedy, implementation
Correct Solution:
```
from sys import stdin, stdout
input = stdin.readline
c = 0
a = []
b = []
def f(i):
if a[i] == 0:
return 0
if a[i - 1] < a[i] > a[i + 1]:
return 1
if a[i - 1] > a[i] < a[i + 1]:
return -1
return 0
def relax(i):
glob... | output | 1 | 89,491 | 12 | 178,983 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 89,492 | 12 | 178,984 |
Tags: data structures, divide and conquer, dp, greedy, implementation
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
s... | output | 1 | 89,492 | 12 | 178,985 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 89,493 | 12 | 178,986 |
Tags: data structures, divide and conquer, dp, greedy, implementation
Correct Solution:
```
# Author : -pratyay-
import sys
inp=sys.stdin.buffer.readline
inar=lambda: list(map(int,inp().split()))
inin=lambda: int(inp())
inst=lambda: inp().decode().strip()
def pr(*args,end='\n'):
for _arg in args:
sys.stdout.write(st... | output | 1 | 89,493 | 12 | 178,987 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 89,494 | 12 | 178,988 |
Tags: data structures, divide and conquer, dp, greedy, implementation
Correct Solution:
```
import sys;z=sys.stdin.readline;o=[];y=lambda a,b:a-b if a-b>0 else 0
for _ in range(int(z())):
n,q=map(int,z().split());p=[0]+[*map(int,z().split())];s=m=0
for i in p:
if i>m:s+=i-m
m=i
o.append(s)
... | output | 1 | 89,494 | 12 | 178,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 89,495 | 12 | 178,990 |
Yes | output | 1 | 89,495 | 12 | 178,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 89,496 | 12 | 178,992 |
Yes | output | 1 | 89,496 | 12 | 178,993 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 89,497 | 12 | 178,994 |
Yes | output | 1 | 89,497 | 12 | 178,995 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 89,498 | 12 | 178,996 |
Yes | output | 1 | 89,498 | 12 | 178,997 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 89,499 | 12 | 178,998 |
No | output | 1 | 89,499 | 12 | 178,999 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 89,500 | 12 | 179,000 |
No | output | 1 | 89,500 | 12 | 179,001 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 89,501 | 12 | 179,002 |
No | output | 1 | 89,501 | 12 | 179,003 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the hard version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 89,502 | 12 | 179,004 |
No | output | 1 | 89,502 | 12 | 179,005 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One spring day on his way to university Lesha found an array A. Lesha likes to split arrays into several parts. This time Lesha decided to split the array A into several, possibly one, new arrays so that the sum of elements in each of the ne... | instruction | 0 | 89,759 | 12 | 179,518 |
Tags: constructive algorithms, greedy, implementation
Correct Solution:
```
import io, os
import sys
from atexit import register
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
sys.stdout = io.BytesIO()
register(lambda: os.write(1, sys.stdout.getvalue()))
tokens = []
tokens_next = 0
def nextStr():
... | output | 1 | 89,759 | 12 | 179,519 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One spring day on his way to university Lesha found an array A. Lesha likes to split arrays into several parts. This time Lesha decided to split the array A into several, possibly one, new arrays so that the sum of elements in each of the ne... | instruction | 0 | 89,760 | 12 | 179,520 |
Tags: constructive algorithms, greedy, implementation
Correct Solution:
```
def main():
i=j=0
n = int(input())
ara = list(map(int, input().split()))
if any(ara):
print("YES")
if sum(ara)!=0:
print(1)
print(1, n)
else:
for i, j in enumerate(ara)... | output | 1 | 89,760 | 12 | 179,521 |
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