message stringlengths 2 65.1k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 0 108k | cluster float64 14 14 | __index_level_0__ int64 0 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not greater than n/2.
For some reason, you would li... | instruction | 0 | 59,978 | 14 | 119,956 |
Tags: dp, flows, graph matchings, greedy
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
p = []
for i in range(n):
if a[i] == 1:
p += [i]
dp = [[float('inf')]*(len(p)+1) for i in range(n+1)]
for i in range(n+1):
dp[i][0] = 0
for i in range(1, n+1):
for j in range(1, len(... | output | 1 | 59,978 | 14 | 119,957 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not greater than n/2.
For some reason, you would li... | instruction | 0 | 59,979 | 14 | 119,958 |
Tags: dp, flows, graph matchings, greedy
Correct Solution:
```
n,*a = map(int, open(0).read().split())
ones = [i for i in range(n) if a[i]]
needed_zeros = len(ones)
dp = [[1e9]*(needed_zeros+1) for i in range(n+1)]
for i in range(n+1):dp[i][0] = 0
for i in range(1, n+1):
for j in range(1, needed_zeros+1):
d... | output | 1 | 59,979 | 14 | 119,959 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not greater than n/2.
For some reason, you would li... | instruction | 0 | 59,980 | 14 | 119,960 |
Tags: dp, flows, graph matchings, greedy
Correct Solution:
```
# ---------------------------iye ha aam zindegi---------------------------------------------
import math
import random
import heapq,bisect
import sys
from collections import deque, defaultdict
from fractions import Fraction
import sys
import threading
from ... | output | 1 | 59,980 | 14 | 119,961 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not greater than n/2.
For some reason, you would li... | instruction | 0 | 59,981 | 14 | 119,962 |
Tags: dp, flows, graph matchings, greedy
Correct Solution:
```
n=int(input())
aal=list(map(int, input().split()))
al=[]
bl=[]
k=0
emp=0
for i in range(n):
if aal[i]==0:
bl.append(i)
emp+=1
else:
al.append(i)
k+=1
if k==0:
print(0)
exit()
dp=[[10**10]*(emp+1) for _ in ra... | output | 1 | 59,981 | 14 | 119,963 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not greater than n/2.
For some reason, you would li... | instruction | 0 | 59,982 | 14 | 119,964 |
Tags: dp, flows, graph matchings, greedy
Correct Solution:
```
INF = 10 ** 9
N = int(input())
A = list(map(int, input().split()))
B = []
for i in range(N):
if A[i]: B.append(i)
M = len(B)
DP = [[INF] * (N + 1) for _ in range(M + 1)]
DP[0][0] = 0
for i in range(M):
for j in range(N):
if A[j] == 0:
... | output | 1 | 59,982 | 14 | 119,965 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not g... | instruction | 0 | 59,983 | 14 | 119,966 |
Yes | output | 1 | 59,983 | 14 | 119,967 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not g... | instruction | 0 | 59,984 | 14 | 119,968 |
Yes | output | 1 | 59,984 | 14 | 119,969 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not g... | instruction | 0 | 59,985 | 14 | 119,970 |
Yes | output | 1 | 59,985 | 14 | 119,971 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not g... | instruction | 0 | 59,986 | 14 | 119,972 |
Yes | output | 1 | 59,986 | 14 | 119,973 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not g... | instruction | 0 | 59,987 | 14 | 119,974 |
No | output | 1 | 59,987 | 14 | 119,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not g... | instruction | 0 | 59,988 | 14 | 119,976 |
No | output | 1 | 59,988 | 14 | 119,977 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not g... | instruction | 0 | 59,989 | 14 | 119,978 |
No | output | 1 | 59,989 | 14 | 119,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n armchairs, numbered from 1 to n from left to right. Some armchairs are occupied by people (at most one person per armchair), others are not. The number of occupied armchairs is not g... | instruction | 0 | 59,990 | 14 | 119,980 |
No | output | 1 | 59,990 | 14 | 119,981 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho m... | instruction | 0 | 60,071 | 14 | 120,142 |
Tags: data structures, implementation
Correct Solution:
```
n, t = int(input()), list(map(int, input().split()))
p, s, r = [0] * n, [0] * n, t[0]
for i in range(n - 1):
j = i + 1
x = t[j]
if x > r: r = x
else:
while t[i] < x: s[j], i = max(s[j], s[i]), p[i]
p[j] = i
s[j]... | output | 1 | 60,071 | 14 | 120,143 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho m... | instruction | 0 | 60,072 | 14 | 120,144 |
Tags: data structures, implementation
Correct Solution:
```
n = int(input())
A = list(map(int,input().strip().split()))[::-1]
p = 0
p_max = 0
X = []
for i in A:
# print(X)
while(len(X)>0 and X[-1][0]<i):
p = max((p+1,X[-1][1]))
X.pop()
X.append((i,p))
if p>p_max:
p_max = p
p=... | output | 1 | 60,072 | 14 | 120,145 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho m... | instruction | 0 | 60,073 | 14 | 120,146 |
Tags: data structures, implementation
Correct Solution:
```
n = int(input())
aa = list(map(int,input().split()))
live = []
ans=0
for i in range(n-1,-1,-1):
c = 0
while len(live)!=0 and live[-1][0]<aa[i]:
c = max(c+1,live[-1][1])
live.pop()
if c>ans: ans =c
live.append((aa[i],c))
print(an... | output | 1 | 60,073 | 14 | 120,147 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho m... | instruction | 0 | 60,074 | 14 | 120,148 |
Tags: data structures, implementation
Correct Solution:
```
N=int(input())
psychos=list(map(int, input().split(" ")))
time_of_death=[0 for i in range(N)]
stack=[(psychos[0], 0)]
for index, p in enumerate(psychos):
if index==0:
continue
if p<stack[-1][0]:
stack.append((p, 1))
time_of_dea... | output | 1 | 60,074 | 14 | 120,149 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho m... | instruction | 0 | 60,075 | 14 | 120,150 |
Tags: data structures, implementation
Correct Solution:
```
n = int(input())
A = [int(i) for i in input().split()]
ans = 0
st = [0]
tdeath = [-1 for i in range(n)]
for i in range(1, n):
tdeath[i] = 0
while len(st) > 0 and A[st[-1]] < A[i]:
tdeath[i] = max(tdeath[i], tdeath[st[-1]]+1)
st.pop()... | output | 1 | 60,075 | 14 | 120,151 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho m... | instruction | 0 | 60,076 | 14 | 120,152 |
Tags: data structures, implementation
Correct Solution:
```
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
# from math import *
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinations as comb, permutations as perm
from... | output | 1 | 60,076 | 14 | 120,153 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho m... | instruction | 0 | 60,077 | 14 | 120,154 |
Tags: data structures, implementation
Correct Solution:
```
def main():
from bisect import bisect_left as bl, bisect_right as br, insort
import sys,math
#from heapq import heapify, heappush, heappop
from collections import defaultdict as dd, deque
def data(): return sys.stdin.readline().strip()
... | output | 1 | 60,077 | 14 | 120,155 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his right neighbor in the line. Note that a psycho m... | instruction | 0 | 60,078 | 14 | 120,156 |
Tags: data structures, implementation
Correct Solution:
```
from sys import stdin,stdout
def main(n, a):
ans = 0
top = 0
t = [0 for i in range(n)]
f = [0 for i in range(n)]
for i in range(n - 1, -1, -1):
tt = 0
while top > 0 and a[t[top - 1]] < a[i]:
top -= 1
... | output | 1 | 60,078 | 14 | 120,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his r... | instruction | 0 | 60,079 | 14 | 120,158 |
Yes | output | 1 | 60,079 | 14 | 120,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his r... | instruction | 0 | 60,080 | 14 | 120,160 |
Yes | output | 1 | 60,080 | 14 | 120,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his r... | instruction | 0 | 60,081 | 14 | 120,162 |
Yes | output | 1 | 60,081 | 14 | 120,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his r... | instruction | 0 | 60,082 | 14 | 120,164 |
Yes | output | 1 | 60,082 | 14 | 120,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his r... | instruction | 0 | 60,083 | 14 | 120,166 |
No | output | 1 | 60,083 | 14 | 120,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his r... | instruction | 0 | 60,084 | 14 | 120,168 |
No | output | 1 | 60,084 | 14 | 120,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n psychos standing in a line. Each psycho is assigned a unique integer from 1 to n. At each step every psycho who has an id greater than the psycho to his right (if exists) kills his r... | instruction | 0 | 60,085 | 14 | 120,170 |
No | output | 1 | 60,085 | 14 | 120,171 |
Provide tags and a correct Python 2 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,238 | 14 | 120,476 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
from sys import stdin, stdout
from collections import Counter, defaultdict
from itertools import permutations, combinations
from bisect import bisect
raw_input = stdin.readline
pr = stdout.write
def in_num():
return int(raw_input())
def in... | output | 1 | 60,238 | 14 | 120,477 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,239 | 14 | 120,478 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
#! /usr/bin/env python3
def main():
n, a, b, t = map(int, input().split())
oris = input()
def get_time(front, rear, count_rot):
span = front - rear
offset = min(front, -rear)
return span, span * a + (span + 1)... | output | 1 | 60,239 | 14 | 120,479 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,240 | 14 | 120,480 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
def main():
n, a, b, t = map(int, input().split())
b += 1
l = [b if char == "w" else 1 for char in input()]
t -= sum(l) - a * (n + 2)
hi, n2 = n, n * 2
n3 = n2 + 1
lo = res = 0
l *= 2
while lo <= n and hi < n2:
... | output | 1 | 60,240 | 14 | 120,481 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,241 | 14 | 120,482 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
def main():
n, a, b, t = map(int, input().split())
b += 1
l = [b if char == "w" else 1 for char in input()]
t -= sum(l) - a * (n + 2)
hi, n2 = n, n * 2
n21 = n2 + 1
lo = res = 0
l *= 2
while lo <= n and hi < n2:... | output | 1 | 60,241 | 14 | 120,483 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,242 | 14 | 120,484 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
def main():
n, a, b, t = map(int, input().split())
b += 1
l = [b if char == "w" else 1 for char in input()]
t -= sum(l) - a * (n + 2)
hi, n2 = n, n * 2
n3 = n2 + 1
lo = res = 0
l *= 2
while lo <= n and hi < n2:
... | output | 1 | 60,242 | 14 | 120,485 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,243 | 14 | 120,486 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
import sys
INF = 10**20
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
from math import gcd
from math import ceil
from collections import defaultdict as dd, Counter
from bisect import bisect_left as bl, bisect_right as br
"""
Facts an... | output | 1 | 60,243 | 14 | 120,487 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,244 | 14 | 120,488 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
def main():
n, a, b, t = map(int, input().split())
b += 1
l = [b if char == "w" else 1 for char in input()]
t -= sum(l) - a * (n + 2)
hi, n2 = n, n * 2
n3 = n2 + 1
lo = res = 0
l *= 2
while lo <= n and hi < n2:
... | output | 1 | 60,244 | 14 | 120,489 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,245 | 14 | 120,490 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
# [https://codeforces.com/contest/650/submission/16709913]
(n, a, b, t) = map(int, input().split())
b += 1
l = [b if char == "w" else 1 for char in input()]
t -= sum(l) - a * (n + 2)
hi = n
n2 = n * 2
n3 = n2 + 1
lo = 0
res = 0
l *= 2
while lo <=... | output | 1 | 60,245 | 14 | 120,491 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe left from the first photo, you reach photo n. Si... | instruction | 0 | 60,246 | 14 | 120,492 |
Tags: binary search, brute force, dp, two pointers
Correct Solution:
```
read = lambda: map(int, input().split())
per = lambda L, R: R - L - 1 + min(R - n - 1, n - L)
n, a, b, T = read()
f = [1 + (i == 'w') * b for i in input()] * 2
L, R = 0, n
ans = 0
cur = sum(f) // 2
while L <= n and R < n * 2:
cur += f[R]; R +=... | output | 1 | 60,246 | 14 | 120,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe l... | instruction | 0 | 60,247 | 14 | 120,494 |
Yes | output | 1 | 60,247 | 14 | 120,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe l... | instruction | 0 | 60,248 | 14 | 120,496 |
Yes | output | 1 | 60,248 | 14 | 120,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe l... | instruction | 0 | 60,249 | 14 | 120,498 |
Yes | output | 1 | 60,249 | 14 | 120,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe l... | instruction | 0 | 60,250 | 14 | 120,500 |
Yes | output | 1 | 60,250 | 14 | 120,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe l... | instruction | 0 | 60,251 | 14 | 120,502 |
No | output | 1 | 60,251 | 14 | 120,503 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe l... | instruction | 0 | 60,252 | 14 | 120,504 |
No | output | 1 | 60,252 | 14 | 120,505 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe l... | instruction | 0 | 60,253 | 14 | 120,506 |
No | output | 1 | 60,253 | 14 | 120,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya's telephone contains n photos. Photo number 1 is currently opened on the phone. It is allowed to move left and right to the adjacent photo by swiping finger over the screen. If you swipe l... | instruction | 0 | 60,254 | 14 | 120,508 |
No | output | 1 | 60,254 | 14 | 120,509 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has o... | instruction | 0 | 60,284 | 14 | 120,568 |
Tags: implementation, math
Correct Solution:
```
n, k = map(int, input().split())
w = list(map(int, input().split()))
for i in range(n):
w[i] = w[i] // k + (1 if w[i] % k > 0 else 0)
t = sum(w)
print(t // 2 + t % 2)
``` | output | 1 | 60,284 | 14 | 120,569 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has o... | instruction | 0 | 60,285 | 14 | 120,570 |
Tags: implementation, math
Correct Solution:
```
_, cap = (int(x) for x in input().split())
items = [int(x) for x in input().split()]
res = 0
for item in items:
times = item//cap
res += times
if times*cap<item: res += 1
days = res // 2
print(days if days*2 == res else days + 1)
``` | output | 1 | 60,285 | 14 | 120,571 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has o... | instruction | 0 | 60,286 | 14 | 120,572 |
Tags: implementation, math
Correct Solution:
```
n, k = [int(i) for i in input().split()]
w = [int(i) for i in input().split()]
tot = 0
for wi in w:
tot += (wi+k-1)//k
ans = (tot+1)//2
print(ans)
``` | output | 1 | 60,286 | 14 | 120,573 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has o... | instruction | 0 | 60,287 | 14 | 120,574 |
Tags: implementation, math
Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Wed May 29 14:40:49 2019
@author: avina
"""
from math import ceil
n,m = map(int, input().split())
l = list(map(int, input().split()))
i = 0;u = 0
days = 0
while i <n:
if l[i] >= 2*m:
days+= l[i]//(2*m)
b = l[i... | output | 1 | 60,287 | 14 | 120,575 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has o... | instruction | 0 | 60,288 | 14 | 120,576 |
Tags: implementation, math
Correct Solution:
```
def solve():
n, k = map(int, input().split())
w = [int(i) for i in input().split()]
ans = sum((wi + k - 1) // k for wi in w)
ans = (ans + 1) // 2
print(ans)
if __name__ == '__main__':
solve()
``` | output | 1 | 60,288 | 14 | 120,577 |
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