message stringlengths 2 57.2k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 61 108k | cluster float64 22 22 | __index_level_0__ int64 122 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input
The first line contains integers n, p, k (2 ≤... | instruction | 0 | 29,201 | 22 | 58,402 |
Tags: math, matrices, number theory, two pointers
Correct Solution:
```
# ========= /\ /| |====/|
# | / \ | | / |
# | /____\ | | / |
# | / \ | | / |
# ========= / \ ===== |/====|
# code
if __name__ == "__main__":
from c... | output | 1 | 29,201 | 22 | 58,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input
The first line contains integers n, p, k (2 ≤... | instruction | 0 | 29,202 | 22 | 58,404 |
Tags: math, matrices, number theory, two pointers
Correct Solution:
```
# |
# _` | __ \ _` | __| _ \ __ \ _` | _` |
# ( | | | ( | ( ( | | | ( | ( |
# \__,_| _| _| \__,_| \___| \___/ _| _| \__,_| \__,_|
import sys
import math
de... | output | 1 | 29,202 | 22 | 58,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input
The first line contains integers n, p, k (2 ≤... | instruction | 0 | 29,203 | 22 | 58,406 |
Tags: math, matrices, number theory, two pointers
Correct Solution:
```
from collections import defaultdict as dc
n,p,k=map(int,input().split())
a=list(map(int,input().split()))
b=[]
for i in range(n):
x=((a[i]**2)%p)**2%p-(k*a[i])%p
if(x<0):
b.append(x+p)
else:
b.append(x)
d=dc(int)
for i i... | output | 1 | 29,203 | 22 | 58,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input
The first line contains integers n, p, k (2 ≤... | instruction | 0 | 29,204 | 22 | 58,408 |
Tags: math, matrices, number theory, two pointers
Correct Solution:
```
from collections import Counter
n, p, k = map(int, input().split())
arr = list(map(int, input().split()))
arr = [ (x ** 4 - k * x) % p for x in arr ]
ans = 0
for x in Counter(arr).values():
ans += (x * (x - 1)) // 2
print(ans)
``` | output | 1 | 29,204 | 22 | 58,409 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input
The first line contains integers n, p, k (2 ≤... | instruction | 0 | 29,205 | 22 | 58,410 |
Tags: math, matrices, number theory, two pointers
Correct Solution:
```
n,p,k = map(int,input().split())
l = list(map(int,input().split()))
d = dict()
for y in range(n):
x = pow(l[y],4) - l[y]*(k)
if(x%p not in d):
d[x%p] = 1
else:
d[x%p] += 1
ct = 0
#print(d)
for k,v in d.items():
ct += v*(v-1)//2
print(ct)
``... | output | 1 | 29,205 | 22 | 58,411 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input
The first line contains integers n, p, k (2 ≤... | instruction | 0 | 29,206 | 22 | 58,412 |
Tags: math, matrices, number theory, two pointers
Correct Solution:
```
from collections import defaultdict
n, p, k = map(int, input().split())
cnt = defaultdict(lambda: 0)
for x in map(int, input().split()):
cnt[(x*(x**3 - k)) % p] += 1
print(sum((x * (x - 1)) // 2 for x in cnt.values()))
``` | output | 1 | 29,206 | 22 | 58,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input... | instruction | 0 | 29,207 | 22 | 58,414 |
Yes | output | 1 | 29,207 | 22 | 58,415 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input... | instruction | 0 | 29,208 | 22 | 58,416 |
Yes | output | 1 | 29,208 | 22 | 58,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input... | instruction | 0 | 29,209 | 22 | 58,418 |
Yes | output | 1 | 29,209 | 22 | 58,419 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input... | instruction | 0 | 29,210 | 22 | 58,420 |
Yes | output | 1 | 29,210 | 22 | 58,421 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input... | instruction | 0 | 29,211 | 22 | 58,422 |
No | output | 1 | 29,211 | 22 | 58,423 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input... | instruction | 0 | 29,212 | 22 | 58,424 |
No | output | 1 | 29,212 | 22 | 58,425 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input... | instruction | 0 | 29,213 | 22 | 58,426 |
No | output | 1 | 29,213 | 22 | 58,427 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a prime number p, n integers a_1, a_2, …, a_n, and an integer k.
Find the number of pairs of indexes (i, j) (1 ≤ i < j ≤ n) for which (a_i + a_j)(a_i^2 + a_j^2) ≡ k mod p.
Input... | instruction | 0 | 29,214 | 22 | 58,428 |
No | output | 1 | 29,214 | 22 | 58,429 |
Provide a correct Python 3 solution for this coding contest problem.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer obtained by concatenating the terms written in base ten ... | instruction | 0 | 29,791 | 22 | 59,582 |
"Correct Solution:
```
# coding: utf-8
# Your code here!
def matmul(A, B, mod): # A,B: 行列
res = [[0] * len(B[0]) for _ in range(len(A))]
for i in range(len(A)):
for k, aik in enumerate(A[i]):
for j,bkj in enumerate(B[k]):
res[i][j] += aik*bkj
res[i][j] %= mod... | output | 1 | 29,791 | 22 | 59,583 |
Provide a correct Python 3 solution for this coding contest problem.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer obtained by concatenating the terms written in base ten ... | instruction | 0 | 29,792 | 22 | 59,584 |
"Correct Solution:
```
l,a,b,m = map(int,input().split())
# c111 -> 1001001001みたいなやつを求める
# n : 塊の数
# l : 一つの塊(00..001)の長さ
# m : mod
# ex) n=3, l=2 -> 10101
def c111(n, l, m):
if n <= 0:
return 0
if n == 1:
return 1
if n % 2 == 1:
return (c111(n - 1, l, m) * pow(10, l, m) + 1) % m
... | output | 1 | 29,792 | 22 | 59,585 |
Provide a correct Python 3 solution for this coding contest problem.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer obtained by concatenating the terms written in base ten ... | instruction | 0 | 29,793 | 22 | 59,586 |
"Correct Solution:
```
import sys
from math import log10
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range... | output | 1 | 29,793 | 22 | 59,587 |
Provide a correct Python 3 solution for this coding contest problem.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer obtained by concatenating the terms written in base ten ... | instruction | 0 | 29,794 | 22 | 59,588 |
"Correct Solution:
```
import copy
import sys
stdin = sys.stdin
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
ns = lambda: stdin.readline().rstrip() # ignore trailing spaces
L,A,B,mod = na()
low = 1
high = 10
def matpow(M, v, e, mod):
A = copy.deepcopy(M)
w = copy.deepcopy(... | output | 1 | 29,794 | 22 | 59,589 |
Provide a correct Python 3 solution for this coding contest problem.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer obtained by concatenating the terms written in base ten ... | instruction | 0 | 29,795 | 22 | 59,590 |
"Correct Solution:
```
l,a,b,m = map(int,input().split())
# c111 -> 1001001001みたいなやつを求める
# n : 塊の数
# l : 一つの塊(00..001)の長さ
# m : mod
# ex) n=3, l=2 -> 10101
def c111(n, l, m):
if n <= 1:
return 1
if n % 2 == 1:
return (c111(n - 1, l, m) * pow(10, l, m) + 1) % m
half = c111(n // 2, l, m)
... | output | 1 | 29,795 | 22 | 59,591 |
Provide a correct Python 3 solution for this coding contest problem.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer obtained by concatenating the terms written in base ten ... | instruction | 0 | 29,796 | 22 | 59,592 |
"Correct Solution:
```
L,A,B,mod=map(int,input().split())
def keta(k):# k-桁の数の初項、末項、項数を求める
if A>=10**k:
return 0,0,0
begin=10**(k-1)
end=10**k
if begin>A+B*(L-1):
return 0,0,0
sh=A+max(-1,(begin-1-A)//B)*B+B
ma=min(A+max(0,(end-1-A)//B)*B,A+B*(L-1))
kou=(ma-sh)//B+1
... | output | 1 | 29,796 | 22 | 59,593 |
Provide a correct Python 3 solution for this coding contest problem.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer obtained by concatenating the terms written in base ten ... | instruction | 0 | 29,797 | 22 | 59,594 |
"Correct Solution:
```
#import sys
#input = sys.stdin.readline
#from numpy import matrix, eye, dot
def productMatrix(N, A, B):
Ret = [[0]*N for _ in range(N)]
for i in range(N):
for j in range(N):
for k in range(N):
Ret[i][j] += A[i][k]*B[k][j]
return Ret
def modMatrix(N,... | output | 1 | 29,797 | 22 | 59,595 |
Provide a correct Python 3 solution for this coding contest problem.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer obtained by concatenating the terms written in base ten ... | instruction | 0 | 29,798 | 22 | 59,596 |
"Correct Solution:
```
import math, itertools
L, A, B, mod = [int(_) for _ in input().split()]
def sum_ri(r, n, mod):
#1,r,...,r**(n-1)
if r == 1:
return n % mod
else:
#(r**n-1)/(r-1)=Q*mod+R
#R**n-1=Q*mod*(r-1)+R*(r-1)
return (pow(r, n, mod * (r - 1)) - 1) // (r - 1) % mo... | output | 1 | 29,798 | 22 | 59,597 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer ... | instruction | 0 | 29,799 | 22 | 59,598 |
Yes | output | 1 | 29,799 | 22 | 59,599 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer ... | instruction | 0 | 29,802 | 22 | 59,604 |
Yes | output | 1 | 29,802 | 22 | 59,605 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is an arithmetic progression with L terms: s_0, s_1, s_2, ... , s_{L-1}.
The initial term is A, and the common difference is B. That is, s_i = A + B \times i holds.
Consider the integer ... | instruction | 0 | 29,803 | 22 | 59,606 |
No | output | 1 | 29,803 | 22 | 59,607 |
Provide a correct Python 3 solution for this coding contest problem.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abundant number. Create a program that determines whether a g... | instruction | 0 | 29,964 | 22 | 59,928 |
"Correct Solution:
```
def make_division(n:int):
divisors = []
for i in range(1,int(n**0.5)+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n//i)
divisors.sort()
divisors.pop(-1)
return sum(divisors)
if __name__ == '__main__':
while True:
n = int(input())
if n == 0:
bre... | output | 1 | 29,964 | 22 | 59,929 |
Provide a correct Python 3 solution for this coding contest problem.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abundant number. Create a program that determines whether a g... | instruction | 0 | 29,965 | 22 | 59,930 |
"Correct Solution:
```
import sys
p="perfect number"
d="deficient number"
a="abundant number"
number_list=[]
while True:
N=int(input())
if N==0:
break
else:
number_list.append(N)
maximum=int(max(number_list)**0.5)
prime_table=[i for i in range(maximum+1)]
prime_table[1]=0
for i... | output | 1 | 29,965 | 22 | 59,931 |
Provide a correct Python 3 solution for this coding contest problem.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abundant number. Create a program that determines whether a g... | instruction | 0 | 29,966 | 22 | 59,932 |
"Correct Solution:
```
while 1:
m=n=int(input())
if n==0:break
i=2
a=1
while i*i<=n:
c=0
while n%i==0:
n//=i
c+=1
if c:
a*=(i**(c+1)-1)//(i-1)
i+=1
if n>1:
a*=1+n
if a==2*m:
print("perfect number")
elif a... | output | 1 | 29,966 | 22 | 59,933 |
Provide a correct Python 3 solution for this coding contest problem.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abundant number. Create a program that determines whether a g... | instruction | 0 | 29,967 | 22 | 59,934 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:break
solvers = set()
for i in range(1, int(n ** (1 / 2)) + 2):
if n % i == 0:
solvers.add(i)
solvers.add(n // i)
score = sum(solvers) - n
if n < score:
print("abundant number")
elif n == score:
print("perfect number")
... | output | 1 | 29,967 | 22 | 59,935 |
Provide a correct Python 3 solution for this coding contest problem.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abundant number. Create a program that determines whether a g... | instruction | 0 | 29,968 | 22 | 59,936 |
"Correct Solution:
```
while 1:
n=int(input())
if n==0:break
s=[]
for i in range(1,int(n**0.5)+1):
if n%i==0:
s.append(i)
s.append(n//i)
s=list(set(s))
s.remove(n)
if sum(s)==n:
print("perfect number")
elif sum(s)<n:
print("deficient number... | output | 1 | 29,968 | 22 | 59,937 |
Provide a correct Python 3 solution for this coding contest problem.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abundant number. Create a program that determines whether a g... | instruction | 0 | 29,969 | 22 | 59,938 |
"Correct Solution:
```
import math
while True:
N = int(input())
if N == 0:
break
elif N == 1:
print("deficient number")
else:
sum = 1
for i in range(2, int(math.sqrt(N)) + 1):
if N % i == 0 and i**2 !=N:
sum += N / i + i
elif i**2 ==... | output | 1 | 29,969 | 22 | 59,939 |
Provide a correct Python 3 solution for this coding contest problem.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abundant number. Create a program that determines whether a g... | instruction | 0 | 29,970 | 22 | 59,940 |
"Correct Solution:
```
def f(p):
ans=1
if p<=5: return 0
for n in range(2,int(p**0.5)+1):
if p%n==0:
if n!=p//n:ans+=n+p//n
else:ans+=n
return ans
while 1:
n=int(input())
if n==0:break
m=f(n)
if n==m:print('perfect number')
else: print('deficient numb... | output | 1 | 29,970 | 22 | 59,941 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abund... | instruction | 0 | 29,971 | 22 | 59,942 |
No | output | 1 | 29,971 | 22 | 59,943 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abund... | instruction | 0 | 29,972 | 22 | 59,944 |
No | output | 1 | 29,972 | 22 | 59,945 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abund... | instruction | 0 | 29,973 | 22 | 59,946 |
No | output | 1 | 29,973 | 22 | 59,947 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let S be the sum of divisors of an integer N excluding the number itself. When N = S, N is called a perfect number, when N> S, N is called a defendant number, and when N <S, N is called an abund... | instruction | 0 | 29,974 | 22 | 59,948 |
No | output | 1 | 29,974 | 22 | 59,949 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three positive (greater than zero) integers c, d and x.
You have to find the number of pairs of positive integers (a, b) such that equality c ⋅ lcm(a, b) - d ⋅ gcd(a, b) = x hold... | instruction | 0 | 30,313 | 22 | 60,626 |
No | output | 1 | 30,313 | 22 | 60,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three positive (greater than zero) integers c, d and x.
You have to find the number of pairs of positive integers (a, b) such that equality c ⋅ lcm(a, b) - d ⋅ gcd(a, b) = x hold... | instruction | 0 | 30,314 | 22 | 60,628 |
No | output | 1 | 30,314 | 22 | 60,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three positive (greater than zero) integers c, d and x.
You have to find the number of pairs of positive integers (a, b) such that equality c ⋅ lcm(a, b) - d ⋅ gcd(a, b) = x hold... | instruction | 0 | 30,315 | 22 | 60,630 |
No | output | 1 | 30,315 | 22 | 60,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three positive (greater than zero) integers c, d and x.
You have to find the number of pairs of positive integers (a, b) such that equality c ⋅ lcm(a, b) - d ⋅ gcd(a, b) = x hold... | instruction | 0 | 30,316 | 22 | 60,632 |
No | output | 1 | 30,316 | 22 | 60,633 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [greatest common divisor (GCD)](https://en.wikipedia... | instruction | 0 | 30,317 | 22 | 60,634 |
Tags: constructive algorithms, math, number theory
Correct Solution:
```
import sys
from sys import stdout
input = lambda: sys.stdin.readline().rstrip('\r\n')
P = lambda: list(map(int, input().split()))
from math import factorial as f, log2, gcd
import random
mod = 10**9+7
tc = int(input())
p = 2
for _ in range(tc):
... | output | 1 | 30,317 | 22 | 60,635 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [greatest common divisor (GCD)](https://en.wikipedia... | instruction | 0 | 30,318 | 22 | 60,636 |
Tags: constructive algorithms, math, number theory
Correct Solution:
```
import math
def gcd(a,b):
if a<b:
a,b=b,a
while a%b!=0:
a,b=b,a%b
return b
t=int(input())
for _ in range(t):
n=int(input())
a=list(map(int,input().split()))
if n==1:
print(0)
continue
... | output | 1 | 30,318 | 22 | 60,637 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [greatest common divisor (GCD)](https://en.wikipedia... | instruction | 0 | 30,319 | 22 | 60,638 |
Tags: constructive algorithms, math, number theory
Correct Solution:
```
from math import gcd
for t in range(int(input())):
pn = 10**9 + 7
N = int(input())
arr = list(map(int,input().split()))
ans = []
for i in range(0,len(arr)-1,2):
ans.append([i+1,i+2,min(arr[i],arr[i+1]),pn])
... | output | 1 | 30,319 | 22 | 60,639 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [greatest common divisor (GCD)](https://en.wikipedia... | instruction | 0 | 30,320 | 22 | 60,640 |
Tags: constructive algorithms, math, number theory
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
import math
from queue import Queue
import itertools
import bisect
import heapq
#sys.setrecursionlimit(100000)
#^^^TAKE CARE FOR MEMORY LIMIT^^^
import random
def main():
pass
BUFSIZE = 8192
... | output | 1 | 30,320 | 22 | 60,641 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [greatest common divisor (GCD)](https://en.wikipedia... | instruction | 0 | 30,321 | 22 | 60,642 |
Tags: constructive algorithms, math, number theory
Correct Solution:
```
if __name__=="__main__":
t=int(input())
for i in range(t):
n=int(input())
arr=list(map(int,input().split(' ')))
prm=1000000009
mn=float('inf')
for i in range(n):
if arr[i]<mn:
mn=arr[i]
... | output | 1 | 30,321 | 22 | 60,643 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [greatest common divisor (GCD)](https://en.wikipedia... | instruction | 0 | 30,322 | 22 | 60,644 |
Tags: constructive algorithms, math, number theory
Correct Solution:
```
from sys import stdin,stdout
import math,bisect,heapq
from collections import Counter,deque,defaultdict
L = lambda:list(map(int, stdin.readline().strip().split()))
I = lambda:int(stdin.readline().strip())
S = lambda:stdin.readline().strip()
C = la... | output | 1 | 30,322 | 22 | 60,645 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [greatest common divisor (GCD)](https://en.wikipedia... | instruction | 0 | 30,323 | 22 | 60,646 |
Tags: constructive algorithms, math, number theory
Correct Solution:
```
# ------------------- fast io --------------------
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.wr... | output | 1 | 30,323 | 22 | 60,647 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [greatest common divisor (GCD)](https://en.wikipedia... | instruction | 0 | 30,324 | 22 | 60,648 |
Tags: constructive algorithms, math, number theory
Correct Solution:
```
import sys
input=sys.stdin.readline
I = lambda : list(map(int,input().split()))
t,=I()
for _ in range(t):
n,=I()
l=I()
an=[]
ix = l.index(min(l))
k=1
for i in range(n):
if i!=ix:
an.append([ix+1,i+1,l[ix],l[ix]+abs(i-ix)])
l[i]=l[ix... | output | 1 | 30,324 | 22 | 60,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [grea... | instruction | 0 | 30,325 | 22 | 60,650 |
Yes | output | 1 | 30,325 | 22 | 60,651 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nastia has received an array of n positive integers as a gift.
She calls such an array a good that for all i (2 ≤ i ≤ n) takes place gcd(a_{i - 1}, a_{i}) = 1, where gcd(u, v) denotes the [grea... | instruction | 0 | 30,326 | 22 | 60,652 |
Yes | output | 1 | 30,326 | 22 | 60,653 |
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