message stringlengths 2 57.2k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 61 108k | cluster float64 22 22 | __index_level_0__ int64 122 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention an... | instruction | 0 | 52,490 | 22 | 104,980 |
No | output | 1 | 52,490 | 22 | 104,981 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some progra... | instruction | 0 | 52,560 | 22 | 105,120 |
Tags: combinatorics, dp, number theory
Correct Solution:
```
import math
from collections import defaultdict
MOD = 10**9 + 7
def printDivisors(n) :
i = 1
Factors = []
while i <= math.sqrt(n):
if (n % i == 0) :
if (n / i == i) :
Factors.append(i)
... | output | 1 | 52,560 | 22 | 105,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's ... | instruction | 0 | 52,569 | 22 | 105,138 |
No | output | 1 | 52,569 | 22 | 105,139 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given three integers k, pa and pb.
You will construct a sequence with the following algorithm: Initially, start with the empty sequence. Each second, you do the following. With probability pa / (pa + pb), add 'a' to the end of the s... | instruction | 0 | 52,790 | 22 | 105,580 |
Tags: dp, math, probabilities
Correct Solution:
```
from collections import defaultdict as di
import sys
sys.setreqursiondepth = 1000000
MOD = int(1e9+7)
def modinvEuler(x,mod):
# if mod is prime
return pow(x, mod-2, mod)
# otherwise exponent should be totient(mod)-1
k,pa,pb = [int(x) for x in input().spli... | output | 1 | 52,790 | 22 | 105,581 |
Provide a correct Python 3 solution for this coding contest problem.
We will define Ginkgo numbers and multiplication on Ginkgo numbers.
A Ginkgo number is a pair <m, n> where m and n are integers. For example, <1, 1>, <-2, 1> and <-3,-1> are Ginkgo numbers.
The multiplication on Ginkgo numbers is defined by <m, n> ... | instruction | 0 | 53,009 | 22 | 106,018 |
"Correct Solution:
```
for _ in range(int(input())):
p,q=map(int,input().split())
c=0
for i in range(142):
for j in range(142):
if (i>0 or j>0)and(j*p+i*q)%(j*j+i*i)==0 and (j*q-i*p)%(j*j+i*i)==0:c+=1
print('P' if c<5 else 'C')
``` | output | 1 | 53,009 | 22 | 106,019 |
Provide a correct Python 3 solution for this coding contest problem.
We will define Ginkgo numbers and multiplication on Ginkgo numbers.
A Ginkgo number is a pair <m, n> where m and n are integers. For example, <1, 1>, <-2, 1> and <-3,-1> are Ginkgo numbers.
The multiplication on Ginkgo numbers is defined by <m, n> ... | instruction | 0 | 53,010 | 22 | 106,020 |
"Correct Solution:
```
for i in range(int(input())):
m, n = map(int, input().split())
if m*n < 0:
m, n = -n, m
m = abs(m); n = abs(n)
l = max(abs(m), abs(n))
cnt = 0
for p in range(l+1):
for q in range(l+1):
if p == 0: continue
if (p*m + q*n) % (p**2 + q*... | output | 1 | 53,010 | 22 | 106,021 |
Provide a correct Python 3 solution for this coding contest problem.
We will define Ginkgo numbers and multiplication on Ginkgo numbers.
A Ginkgo number is a pair <m, n> where m and n are integers. For example, <1, 1>, <-2, 1> and <-3,-1> are Ginkgo numbers.
The multiplication on Ginkgo numbers is defined by <m, n> ... | instruction | 0 | 53,011 | 22 | 106,022 |
"Correct Solution:
```
for _ in range(int(input())):
p,q=map(int,input().split())
c=0
for i in range(143):
for j in range(143):
if (i>0 or j>0)and(j*p+i*q)%(j*j+i*i)==0 and (j*q-i*p)%(j*j+i*i)==0:c+=1
print('P' if c<5 else 'C')
``` | output | 1 | 53,011 | 22 | 106,023 |
Provide a correct Python 3 solution for this coding contest problem.
We will define Ginkgo numbers and multiplication on Ginkgo numbers.
A Ginkgo number is a pair <m, n> where m and n are integers. For example, <1, 1>, <-2, 1> and <-3,-1> are Ginkgo numbers.
The multiplication on Ginkgo numbers is defined by <m, n> ... | instruction | 0 | 53,012 | 22 | 106,024 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
dd = [(0,-1),(1,0),(0,1),(-1,0)]
ddn = [(0,-1),(1,-1),(1,0),(1,1),(0,1),(-1,-1),(-1,0),(-1,1)]
def LI(): return [i... | output | 1 | 53,012 | 22 | 106,025 |
Provide a correct Python 3 solution for this coding contest problem.
We will define Ginkgo numbers and multiplication on Ginkgo numbers.
A Ginkgo number is a pair <m, n> where m and n are integers. For example, <1, 1>, <-2, 1> and <-3,-1> are Ginkgo numbers.
The multiplication on Ginkgo numbers is defined by <m, n> ... | instruction | 0 | 53,013 | 22 | 106,026 |
"Correct Solution:
```
def divisor(a):
ret = []
for i in range(1, int(a ** 0.5) + 1):
if not a % i:
ret.append(i)
ret.append(a // i)
return ret
def make_lists():
ret = [[] for i in range(20000)]
for i in range(0, int(20000 ** 0.5) + 1):
for j in range(0... | output | 1 | 53,013 | 22 | 106,027 |
Provide a correct Python 3 solution for this coding contest problem.
We will define Ginkgo numbers and multiplication on Ginkgo numbers.
A Ginkgo number is a pair <m, n> where m and n are integers. For example, <1, 1>, <-2, 1> and <-3,-1> are Ginkgo numbers.
The multiplication on Ginkgo numbers is defined by <m, n> ... | instruction | 0 | 53,014 | 22 | 106,028 |
"Correct Solution:
```
for i in range(int(input())):
m, n = map(int, input().split())
count = 0
for p in range(142):
for q in range(142):
if p == q == 0:
continue
pq = p * p + q * q
if pq > 20000:
break
if (m * p + n *... | output | 1 | 53,014 | 22 | 106,029 |
Provide a correct Python 3 solution for this coding contest problem.
We will define Ginkgo numbers and multiplication on Ginkgo numbers.
A Ginkgo number is a pair <m, n> where m and n are integers. For example, <1, 1>, <-2, 1> and <-3,-1> are Ginkgo numbers.
The multiplication on Ginkgo numbers is defined by <m, n> ... | instruction | 0 | 53,015 | 22 | 106,030 |
"Correct Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""
Problems 1325
Problem A: Ginkgo Numbers
"""
for _ in range(int(input())):
m, n = map(int,input().split())
count = 0
for p in range(142):
for q in range(142):
if (p > 0 or q > 0) and ((m*q + n*p) % (p*p + q*q) == 0) ... | output | 1 | 53,015 | 22 | 106,031 |
Provide a correct Python 3 solution for this coding contest problem.
B: Twice as own
problem
You will be given Q queries. Since one positive integer N is given for each query, find the number of positive integers M that satisfy the following two conditions.
* 2 Satisfy \ leq M \ leq N
* Of the divisors of M, exclud... | instruction | 0 | 53,034 | 22 | 106,068 |
"Correct Solution:
```
Q = int(input())
N = list(int(input()) for i in range(Q))
m = [0]*(max(N)+1)
N_max = max(N)
r = 320
for i in range(2,r):
for j in range(2,r):
for k in range(2,100000//(i*j)+1):
if i*j*k < N_max+1 and (i!=j or j!=k or k!=i):
m[i*j*k] = 1
for i in range(1,len... | output | 1 | 53,034 | 22 | 106,069 |
Provide a correct Python 3 solution for this coding contest problem.
B: Twice as own
problem
You will be given Q queries. Since one positive integer N is given for each query, find the number of positive integers M that satisfy the following two conditions.
* 2 Satisfy \ leq M \ leq N
* Of the divisors of M, exclud... | instruction | 0 | 53,035 | 22 | 106,070 |
"Correct Solution:
```
import math
def get_sieve_of_eratosthenes(n):
if not isinstance(n, int):
raise TypeError('n is int type.')
if n < 2:
raise ValueError('n is more than 2')
prime = []
limit = math.sqrt(n)
data = [i + 1 for i in range(1, n)]
while True:
p = data[0]
... | output | 1 | 53,035 | 22 | 106,071 |
Provide a correct Python 3 solution for this coding contest problem.
B: Twice as own
problem
You will be given Q queries. Since one positive integer N is given for each query, find the number of positive integers M that satisfy the following two conditions.
* 2 Satisfy \ leq M \ leq N
* Of the divisors of M, exclud... | instruction | 0 | 53,036 | 22 | 106,072 |
"Correct Solution:
```
#import sys
#input = sys.stdin.readline
def eratosthenes(N):
from collections import deque
work = [True] * (N+1)
work[0] = False
work[1] = False
ret = []
for i in range(N+1):
if work[i]:
ret.append(i)
for j in range(2* i, N+1, i):
... | output | 1 | 53,036 | 22 | 106,073 |
Provide a correct Python 3 solution for this coding contest problem.
B: Twice as own
problem
You will be given Q queries. Since one positive integer N is given for each query, find the number of positive integers M that satisfy the following two conditions.
* 2 Satisfy \ leq M \ leq N
* Of the divisors of M, exclud... | instruction | 0 | 53,037 | 22 | 106,074 |
"Correct Solution:
```
import bisect
MAX_N=2*10**5
isdmore5=[1 for i in range(MAX_N+1)]
isprime=[1 for i in range(MAX_N+1)]
i=2
isprime[0]=0;isprime[1]=0
isdmore5[0]=0;isdmore5[1]=0
while(i*i<=MAX_N):
if isprime[i]!=0:
for j in range(2*i,MAX_N+1,i):
isprime[j]=0
i+=1
prime=[]
for i in range(... | output | 1 | 53,037 | 22 | 106,075 |
Provide a correct Python 3 solution for this coding contest problem.
B: Twice as own
problem
You will be given Q queries. Since one positive integer N is given for each query, find the number of positive integers M that satisfy the following two conditions.
* 2 Satisfy \ leq M \ leq N
* Of the divisors of M, exclud... | instruction | 0 | 53,038 | 22 | 106,076 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
from itertools import product, accumulate
from math import gcd
from bisect import bisect
import sys
from sys import setrecursionlimit
setrecursionlimit(10**9)
input = sys.stdin.readline
def inpl(): return list(map(int, input().split()))
def primes(N):
sieve = [1]*(N+1... | output | 1 | 53,038 | 22 | 106,077 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer k is... | instruction | 0 | 53,539 | 22 | 107,078 |
Tags: greedy, implementation, math, number theory
Correct Solution:
```
n = int(input())
if n&1:
print((n-3)//2+1)
n-=3
for i in range(n//2):
print(2,end=' ')
print(3)
else:
print(n//2)
for i in range(n//2):
print(2,end=' ')
``` | output | 1 | 53,539 | 22 | 107,079 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer k is... | instruction | 0 | 53,540 | 22 | 107,080 |
Tags: greedy, implementation, math, number theory
Correct Solution:
```
n = int(input())
if n % 2 == 0:
print(n // 2)
s = ''
for i in range(n // 2 - 1):
s += '2 '
s += '2'
print(s)
else:
print(n // 2)
s = ''
for i in range(n // 2 - 1):
s += '2 '
s += '3'
print(s)
... | output | 1 | 53,540 | 22 | 107,081 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer k is... | instruction | 0 | 53,541 | 22 | 107,082 |
Tags: greedy, implementation, math, number theory
Correct Solution:
```
n = int(input())
print(n//2)
if n%2:
print(3,end= ' ')
n -= 3
while n:
print(2,end=' ')
n -= 2
``` | output | 1 | 53,541 | 22 | 107,083 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer k is... | instruction | 0 | 53,542 | 22 | 107,084 |
Tags: greedy, implementation, math, number theory
Correct Solution:
```
n=int(input())
if n%2==0:
print(int(n/2))
for i in range(int(n/2)):
print(2)
else:
print(int((n-3)/2+1))
for i in range(int((n-3)/2)):
print(2)
print(3)
``` | output | 1 | 53,542 | 22 | 107,085 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer k is... | instruction | 0 | 53,543 | 22 | 107,086 |
Tags: greedy, implementation, math, number theory
Correct Solution:
```
import sys
input = sys.stdin.readline
n=int(input())
if n%2 == 0:
ans1 = n//2
ans2 = [2]*ans1
else:
ans1=n//2
ans2 = [2]*(ans1-1)
ans2.append(3)
print(ans1)
print(*ans2)
``` | output | 1 | 53,543 | 22 | 107,087 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer k is... | instruction | 0 | 53,544 | 22 | 107,088 |
Tags: greedy, implementation, math, number theory
Correct Solution:
```
x = int(input())
print(int(x/2))
for i in range(int(x/2)-1):
print(2, end=" ")
print([2,3][x%2])
``` | output | 1 | 53,544 | 22 | 107,089 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer k is... | instruction | 0 | 53,545 | 22 | 107,090 |
Tags: greedy, implementation, math, number theory
Correct Solution:
```
n = int(input())
if n % 2 == 0:
print(n // 2)
print('2 ' * (n // 2))
else:
print((n - 3) // 2 + 1)
print('3 ' + (n - 3) // 2 * '2 ')
``` | output | 1 | 53,545 | 22 | 107,091 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer k is... | instruction | 0 | 53,546 | 22 | 107,092 |
Tags: greedy, implementation, math, number theory
Correct Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
from collections import defaultdict
BUFSIZE = 8192
clas... | output | 1 | 53,546 | 22 | 107,093 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any in... | instruction | 0 | 53,547 | 22 | 107,094 |
Yes | output | 1 | 53,547 | 22 | 107,095 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any in... | instruction | 0 | 53,548 | 22 | 107,096 |
Yes | output | 1 | 53,548 | 22 | 107,097 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any in... | instruction | 0 | 53,549 | 22 | 107,098 |
Yes | output | 1 | 53,549 | 22 | 107,099 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any in... | instruction | 0 | 53,550 | 22 | 107,100 |
Yes | output | 1 | 53,550 | 22 | 107,101 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any in... | instruction | 0 | 53,551 | 22 | 107,102 |
No | output | 1 | 53,551 | 22 | 107,103 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any in... | instruction | 0 | 53,552 | 22 | 107,104 |
No | output | 1 | 53,552 | 22 | 107,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any in... | instruction | 0 | 53,553 | 22 | 107,106 |
No | output | 1 | 53,553 | 22 | 107,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bachgold problem is very easy to formulate. Given a positive integer n represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any in... | instruction | 0 | 53,554 | 22 | 107,108 |
No | output | 1 | 53,554 | 22 | 107,109 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 53,621 | 22 | 107,242 |
Tags: math
Correct Solution:
```
p, k = map(int, input().split())
if p < k:
print(1)
print(p)
else:
ans = [p]
cur = p
while cur < 0 or cur >= k:
cur = - (cur // k)
ans.append(cur)
arr = []
for i in range(1, len(ans)):
arr.append(str(k*ans[i]+ans[i-1]))
a... | output | 1 | 53,621 | 22 | 107,243 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 53,622 | 22 | 107,244 |
Tags: math
Correct Solution:
```
p,k = map(int,input().split())
a = []
while p != 0:
t = p % k
a.append(t)
p = -((p-t)//k)
print(len(a))
a = list(map(str,a))
print(' '.join(a))
``` | output | 1 | 53,622 | 22 | 107,245 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 53,623 | 22 | 107,246 |
Tags: math
Correct Solution:
```
def solve(n, k):
if n == 0:
return []
x = n%k
return [x] + solve(-(n-x)//k, k)
n, k = map(int, input().split())
a = solve(n, k)
print(len(a))
print(*a)
``` | output | 1 | 53,623 | 22 | 107,247 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 53,624 | 22 | 107,248 |
Tags: math
Correct Solution:
```
s = input()
# s = '46 2'
p, k = list(map(int, s.split()))
res = []
f = True
while p != 0:
if f:
n = p % k
m = (p - n) // k
f = False
else:
n = (-p) % k
m = (p + n) // k
f = True
res.append(n)
p = m
print(len(res))
print(... | output | 1 | 53,624 | 22 | 107,249 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 53,625 | 22 | 107,250 |
Tags: math
Correct Solution:
```
l = []
def f(p, k):
if p == 0:
return
r = p % k
q = (p-r)//(-k)
l.append(r)
f(q, k)
p, k = map(int, input().split())
f(p, k)
print(len(l))
print(*l)
``` | output | 1 | 53,625 | 22 | 107,251 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 53,626 | 22 | 107,252 |
Tags: math
Correct Solution:
```
p, k = map(int, input().split())
a = ''
cnt = 0
while p != 0:
cnt += 1
a += str(p % k) + ' '
p -= p % k
p //= -k
print(cnt)
print(a)
``` | output | 1 | 53,626 | 22 | 107,253 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 53,627 | 22 | 107,254 |
Tags: math
Correct Solution:
```
p, k = map(int, input().split())
r = []
while p:
r.append(p % k)
p = -(p // k)
print(len(r))
print(*r, sep=' ')
# Made By Mostafa_Khaled
``` | output | 1 | 53,627 | 22 | 107,255 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But now he regrets doing this...
Given two intege... | instruction | 0 | 53,628 | 22 | 107,256 |
Tags: math
Correct Solution:
```
p, k = map(int, input().split())
t = []
while p:
t.append(p % k)
p = -(p // k)
print(len(t), *t)
``` | output | 1 | 53,628 | 22 | 107,257 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 53,629 | 22 | 107,258 |
Yes | output | 1 | 53,629 | 22 | 107,259 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 53,630 | 22 | 107,260 |
Yes | output | 1 | 53,630 | 22 | 107,261 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 53,631 | 22 | 107,262 |
Yes | output | 1 | 53,631 | 22 | 107,263 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 53,632 | 22 | 107,264 |
Yes | output | 1 | 53,632 | 22 | 107,265 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 53,633 | 22 | 107,266 |
No | output | 1 | 53,633 | 22 | 107,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 53,634 | 22 | 107,268 |
No | output | 1 | 53,634 | 22 | 107,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 53,635 | 22 | 107,270 |
No | output | 1 | 53,635 | 22 | 107,271 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to put away old things and welcome a fresh new year, a thorough cleaning of the house is a must.
Little Tommy finds an old polynomial and cleaned it up by taking it modulo another. But... | instruction | 0 | 53,636 | 22 | 107,272 |
No | output | 1 | 53,636 | 22 | 107,273 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four pr... | instruction | 0 | 53,805 | 22 | 107,610 |
"Correct Solution:
```
import sys
import math
M = 1000000
B = int(math.sqrt(M)+1)
N = M//6
N1 = N+1 if M % 6 == 5 else N
N2 = N+1 if M % 6 >= 1 else N
l = [1] * N1
m = [1] * N2
for i in range(5,B,6):
p = (i-5)//6
ini = (i*5-1)//6
if l[p] == 1:
l[p+i::i] = [0] * len(l[p+i::i])
m[ini-1::i] = [... | output | 1 | 53,805 | 22 | 107,611 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which reads an integer n and prints the number of prime numbers which are less than or equal to n. A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four pr... | instruction | 0 | 53,806 | 22 | 107,612 |
"Correct Solution:
```
import sys
def primes(n):
is_prime = [True] * (n + 1)
is_prime[0] = False
is_prime[1] = False
for i in range(2, int(n**0.5) + 1):
if not is_prime[i]:
continue
for j in range(i * 2, n + 1, i):
is_prime[j] = False
return [i for i in range... | output | 1 | 53,806 | 22 | 107,613 |
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