prompt stringlengths 50 973 | response stringlengths 14 4.76k | source stringclasses 7
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Question: In a race across a finish line, four runners—B, A, C, and D—finished in distinct positions. C finished ahead of B. B finished ahead of A. A finished ahead of C. D finished last. What was the correct finishing order from first to last?
Answer: | B finished ahead of A, so B is before A.
A finished ahead of C, so A is before C.
C finished ahead of B, so C is before B.
Combining these gives B before A, A before C, and C before B, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, C, D, and A—finished in distinct positions. D finished ahead of B. C finished ahead of D. B finished ahead of C. A finished last. What was the correct finishing order from first to last?
Answer: | B finished ahead of C, so B is before C.
C finished ahead of D, so C is before D.
D finished ahead of B, so D is before B.
Combining these gives B before C, C before D, and D before B, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, C, A, and D—finished in distinct positions. B finished ahead of C. A finished ahead of B. D finished last. C finished ahead of A. What was the correct finishing order from first to last?
Answer: | B finished ahead of C, so B is before C.
C finished ahead of A, so C is before A.
A finished ahead of B, so A is before B.
Combining these gives B before C, C before A, and A before B, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, B, C, and D—finished in distinct positions. A finished ahead of B. D finished last. C finished ahead of A. B finished ahead of C. What was the correct finishing order from first to last?
Answer: | A finished ahead of B, so A is before B.
B finished ahead of C, so B is before C.
C finished ahead of A, so C is before A.
Combining these gives A before B, B before C, and C before A, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, C, A, and D—finished in distinct positions. A finished ahead of B. B finished ahead of C. D finished last. C finished ahead of A. What was the correct finishing order from first to last?
Answer: | B finished ahead of C, so B is before C.
C finished ahead of A, so C is before A.
A finished ahead of B, so A is before B.
Combining these gives B before C, C before A, and A before B, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, C, B, and D—finished in distinct positions. D finished last. A finished ahead of C. C finished ahead of B. B finished ahead of A. What was the correct finishing order from first to last?
Answer: | A finished ahead of C, so A is before C.
C finished ahead of B, so C is before B.
B finished ahead of A, so B is before A.
Combining these gives A before C, C before B, and B before A, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, D, A, and C—finished in distinct positions. D finished ahead of A. A finished ahead of B. B finished ahead of D. C finished last. What was the correct finishing order from first to last?
Answer: | B finished ahead of D, so B is before D.
D finished ahead of A, so D is before A.
A finished ahead of B, so A is before B.
Combining these gives B before D, D before A, and A before B, forming a cycle.
A cycle is impossible in a linear finishing order.
C finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, D, C, and A—finished in distinct positions. D finished ahead of C. B finished ahead of D. A finished last. C finished ahead of B. What was the correct finishing order from first to last?
Answer: | B finished ahead of D, so B is before D.
D finished ahead of C, so D is before C.
C finished ahead of B, so C is before B.
Combining these gives B before D, D before C, and C before B, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, A, B, and D—finished in distinct positions. A finished ahead of B. B finished ahead of C. D finished last. C finished ahead of A. What was the correct finishing order from first to last?
Answer: | C finished ahead of A, so C is before A.
A finished ahead of B, so A is before B.
B finished ahead of C, so B is before C.
Combining these gives C before A, A before B, and B before C, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, D, A, and B—finished in distinct positions. B finished last. D finished ahead of A. A finished ahead of C. C finished ahead of D. What was the correct finishing order from first to last?
Answer: | C finished ahead of D, so C is before D.
D finished ahead of A, so D is before A.
A finished ahead of C, so A is before C.
Combining these gives C before D, D before A, and A before C, forming a cycle.
A cycle is impossible in a linear finishing order.
B finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, A, C, and B—finished in distinct positions. D finished ahead of A. C finished ahead of D. A finished ahead of C. B finished last. What was the correct finishing order from first to last?
Answer: | D finished ahead of A, so D is before A.
A finished ahead of C, so A is before C.
C finished ahead of D, so C is before D.
Combining these gives D before A, A before C, and C before D, forming a cycle.
A cycle is impossible in a linear finishing order.
B finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, A, B, and C—finished in distinct positions. B finished ahead of D. A finished ahead of B. D finished ahead of A. C finished last. What was the correct finishing order from first to last?
Answer: | D finished ahead of A, so D is before A.
A finished ahead of B, so A is before B.
B finished ahead of D, so B is before D.
Combining these gives D before A, A before B, and B before D, forming a cycle.
A cycle is impossible in a linear finishing order.
C finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, A, B, and D—finished in distinct positions. B finished ahead of C. D finished last. A finished ahead of B. C finished ahead of A. What was the correct finishing order from first to last?
Answer: | C finished ahead of A, so C is before A.
A finished ahead of B, so A is before B.
B finished ahead of C, so B is before C.
Combining these gives C before A, A before B, and B before C, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, B, D, and A—finished in distinct positions. A finished last. D finished ahead of C. B finished ahead of D. C finished ahead of B. What was the correct finishing order from first to last?
Answer: | C finished ahead of B, so C is before B.
B finished ahead of D, so B is before D.
D finished ahead of C, so D is before C.
Combining these gives C before B, B before D, and D before C, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, C, B, and A—finished in distinct positions. D finished ahead of C. B finished ahead of D. C finished ahead of B. A finished last. What was the correct finishing order from first to last?
Answer: | D finished ahead of C, so D is before C.
C finished ahead of B, so C is before B.
B finished ahead of D, so B is before D.
Combining these gives D before C, C before B, and B before D, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, B, D, and C—finished in distinct positions. B finished ahead of D. A finished ahead of B. C finished last. D finished ahead of A. What was the correct finishing order from first to last?
Answer: | A finished ahead of B, so A is before B.
B finished ahead of D, so B is before D.
D finished ahead of A, so D is before A.
Combining these gives A before B, B before D, and D before A, forming a cycle.
A cycle is impossible in a linear finishing order.
C finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, B, C, and D—finished in distinct positions. C finished ahead of A. D finished last. A finished ahead of B. B finished ahead of C. What was the correct finishing order from first to last?
Answer: | A finished ahead of B, so A is before B.
B finished ahead of C, so B is before C.
C finished ahead of A, so C is before A.
Combining these gives A before B, B before C, and C before A, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, B, C, and D—finished in distinct positions. B finished ahead of C. D finished last. C finished ahead of A. A finished ahead of B. What was the correct finishing order from first to last?
Answer: | A finished ahead of B, so A is before B.
B finished ahead of C, so B is before C.
C finished ahead of A, so C is before A.
Combining these gives A before B, B before C, and C before A, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, D, B, and A—finished in distinct positions. B finished ahead of C. D finished ahead of B. A finished last. C finished ahead of D. What was the correct finishing order from first to last?
Answer: | C finished ahead of D, so C is before D.
D finished ahead of B, so D is before B.
B finished ahead of C, so B is before C.
Combining these gives C before D, D before B, and B before C, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, B, D, and A—finished in distinct positions. B finished ahead of D. C finished ahead of B. D finished ahead of C. A finished last. What was the correct finishing order from first to last?
Answer: | C finished ahead of B, so C is before B.
B finished ahead of D, so B is before D.
D finished ahead of C, so D is before C.
Combining these gives C before B, B before D, and D before C, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, A, C, and B—finished in distinct positions. D finished ahead of A. A finished ahead of C. B finished last. C finished ahead of D. What was the correct finishing order from first to last?
Answer: | D finished ahead of A, so D is before A.
A finished ahead of C, so A is before C.
C finished ahead of D, so C is before D.
Combining these gives D before A, A before C, and C before D, forming a cycle.
A cycle is impossible in a linear finishing order.
B finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, C, D, and B—finished in distinct positions. D finished ahead of A. B finished last. C finished ahead of D. A finished ahead of C. What was the correct finishing order from first to last?
Answer: | A finished ahead of C, so A is before C.
C finished ahead of D, so C is before D.
D finished ahead of A, so D is before A.
Combining these gives A before C, C before D, and D before A, forming a cycle.
A cycle is impossible in a linear finishing order.
B finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, B, C, and D—finished in distinct positions. C finished ahead of A. B finished ahead of C. A finished ahead of B. D finished last. What was the correct finishing order from first to last?
Answer: | A finished ahead of B, so A is before B.
B finished ahead of C, so B is before C.
C finished ahead of A, so C is before A.
Combining these gives A before B, B before C, and C before A, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, C, B, and A—finished in distinct positions. C finished ahead of B. D finished ahead of C. A finished last. B finished ahead of D. What was the correct finishing order from first to last?
Answer: | D finished ahead of C, so D is before C.
C finished ahead of B, so C is before B.
B finished ahead of D, so B is before D.
Combining these gives D before C, C before B, and B before D, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, C, A, and B—finished in distinct positions. A finished ahead of D. D finished ahead of C. B finished last. C finished ahead of A. What was the correct finishing order from first to last?
Answer: | D finished ahead of C, so D is before C.
C finished ahead of A, so C is before A.
A finished ahead of D, so A is before D.
Combining these gives D before C, C before A, and A before D, forming a cycle.
A cycle is impossible in a linear finishing order.
B finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, C, B, and A—finished in distinct positions. D finished ahead of C. C finished ahead of B. B finished ahead of D. A finished last. What was the correct finishing order from first to last?
Answer: | D finished ahead of C, so D is before C.
C finished ahead of B, so C is before B.
B finished ahead of D, so B is before D.
Combining these gives D before C, C before B, and B before D, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, C, D, and A—finished in distinct positions. C finished ahead of D. D finished ahead of B. B finished ahead of C. A finished last. What was the correct finishing order from first to last?
Answer: | B finished ahead of C, so B is before C.
C finished ahead of D, so C is before D.
D finished ahead of B, so D is before B.
Combining these gives B before C, C before D, and D before B, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, B, C, and D—finished in distinct positions. D finished last. B finished ahead of C. A finished ahead of B. C finished ahead of A. What was the correct finishing order from first to last?
Answer: | A finished ahead of B, so A is before B.
B finished ahead of C, so B is before C.
C finished ahead of A, so C is before A.
Combining these gives A before B, B before C, and C before A, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, A, D, and C—finished in distinct positions. B finished ahead of A. D finished ahead of B. A finished ahead of D. C finished last. What was the correct finishing order from first to last?
Answer: | B finished ahead of A, so B is before A.
A finished ahead of D, so A is before D.
D finished ahead of B, so D is before B.
Combining these gives B before A, A before D, and D before B, forming a cycle.
A cycle is impossible in a linear finishing order.
C finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, D, B, and A—finished in distinct positions. C finished ahead of D. B finished ahead of C. A finished last. D finished ahead of B. What was the correct finishing order from first to last?
Answer: | C finished ahead of D, so C is before D.
D finished ahead of B, so D is before B.
B finished ahead of C, so B is before C.
Combining these gives C before D, D before B, and B before C, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, B, D, and A—finished in distinct positions. A finished last. B finished ahead of D. C finished ahead of B. D finished ahead of C. What was the correct finishing order from first to last?
Answer: | C finished ahead of B, so C is before B.
B finished ahead of D, so B is before D.
D finished ahead of C, so D is before C.
Combining these gives C before B, B before D, and D before C, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, B, C, and D—finished in distinct positions. C finished ahead of A. A finished ahead of B. D finished last. B finished ahead of C. What was the correct finishing order from first to last?
Answer: | A finished ahead of B, so A is before B.
B finished ahead of C, so B is before C.
C finished ahead of A, so C is before A.
Combining these gives A before B, B before C, and C before A, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—A, D, C, and B—finished in distinct positions. D finished ahead of C. C finished ahead of A. A finished ahead of D. B finished last. What was the correct finishing order from first to last?
Answer: | A finished ahead of D, so A is before D.
D finished ahead of C, so D is before C.
C finished ahead of A, so C is before A.
Combining these gives A before D, D before C, and C before A, forming a cycle.
A cycle is impossible in a linear finishing order.
B finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, D, C, and A—finished in distinct positions. C finished ahead of B. D finished ahead of C. A finished last. B finished ahead of D. What was the correct finishing order from first to last?
Answer: | B finished ahead of D, so B is before D.
D finished ahead of C, so D is before C.
C finished ahead of B, so C is before B.
Combining these gives B before D, D before C, and C before B, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, B, A, and D—finished in distinct positions. D finished last. A finished ahead of C. C finished ahead of B. B finished ahead of A. What was the correct finishing order from first to last?
Answer: | C finished ahead of B, so C is before B.
B finished ahead of A, so B is before A.
A finished ahead of C, so A is before C.
Combining these gives C before B, B before A, and A before C, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, A, C, and D—finished in distinct positions. A finished ahead of C. C finished ahead of B. D finished last. B finished ahead of A. What was the correct finishing order from first to last?
Answer: | B finished ahead of A, so B is before A.
A finished ahead of C, so A is before C.
C finished ahead of B, so C is before B.
Combining these gives B before A, A before C, and C before B, forming a cycle.
A cycle is impossible in a linear finishing order.
D finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, C, B, and A—finished in distinct positions. C finished ahead of B. B finished ahead of D. A finished last. D finished ahead of C. What was the correct finishing order from first to last?
Answer: | D finished ahead of C, so D is before C.
C finished ahead of B, so C is before B.
B finished ahead of D, so B is before D.
Combining these gives D before C, C before B, and B before D, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—C, B, D, and A—finished in distinct positions. D finished ahead of C. A finished last. C finished ahead of B. B finished ahead of D. What was the correct finishing order from first to last?
Answer: | C finished ahead of B, so C is before B.
B finished ahead of D, so B is before D.
D finished ahead of C, so D is before C.
Combining these gives C before B, B before D, and D before C, forming a cycle.
A cycle is impossible in a linear finishing order.
A finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—D, C, A, and B—finished in distinct positions. A finished ahead of D. C finished ahead of A. B finished last. D finished ahead of C. What was the correct finishing order from first to last?
Answer: | D finished ahead of C, so D is before C.
C finished ahead of A, so C is before A.
A finished ahead of D, so A is before D.
Combining these gives D before C, C before A, and A before D, forming a cycle.
A cycle is impossible in a linear finishing order.
B finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: In a race across a finish line, four runners—B, D, A, and C—finished in distinct positions. C finished last. B finished ahead of D. D finished ahead of A. A finished ahead of B. What was the correct finishing order from first to last?
Answer: | B finished ahead of D, so B is before D.
D finished ahead of A, so D is before A.
A finished ahead of B, so A is before B.
Combining these gives B before D, D before A, and A before B, forming a cycle.
A cycle is impossible in a linear finishing order.
C finished last, which is consistent but does not resolve the cycl... | tp_logic | f07f807a1c | general |
Question: Given a company with EPS of NPR 32, BVPS of NPR 62, and a market price per share of NPR 42, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 42 / 32 = 1.31
P/B ratio = 42 / 62 = 0.68
Spread = 1.31 - 0.68 = 0.64
#### 0.64 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 8 and a book value per share (BVPS) of NPR 68. The market price per share is NPR 55. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 55 / 8 = 6.88
P/B ratio = 55 / 68 = 0.81
Spread = 6.88 - 0.81 = 6.07
#### 6.07 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 38 and a book value per share (BVPS) of NPR 58. The market price per share is NPR 83. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 83 / 38 = 2.18
P/B ratio = 83 / 58 = 1.43
Spread = 2.18 - 1.43 = 0.75
#### 0.75 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 36 and a book value per share (BVPS) of NPR 55. The market price per share is NPR 76. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 76 / 36 = 2.11
P/B ratio = 76 / 55 = 1.38
Spread = 2.11 - 1.38 = 0.73
#### 0.73 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 35, book value per share of NPR 70, and current price of NPR 81, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 81 / 35 = 2.31
P/B ratio = 81 / 70 = 1.16
Spread = 2.31 - 1.16 = 1.16
#### 1.16 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 7 and a book value per share (BVPS) of NPR 71. The market price per share is NPR 106. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 106 / 7 = 15.14
P/B ratio = 106 / 71 = 1.49
Spread = 15.14 - 1.49 = 13.65
#### 13.65 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 38 and a book value per share (BVPS) of NPR 48. The market price per share is NPR 73. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 73 / 38 = 1.92
P/B ratio = 73 / 48 = 1.52
Spread = 1.92 - 1.52 = 0.4
#### 0.4 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 16 and a book value per share (BVPS) of NPR 20. The market price per share is NPR 92. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 92 / 16 = 5.75
P/B ratio = 92 / 20 = 4.6
Spread = 5.75 - 4.6 = 1.15
#### 1.15 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 47, book value per share of NPR 58, and current price of NPR 61, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 61 / 47 = 1.3
P/B ratio = 61 / 58 = 1.05
Spread = 1.3 - 1.05 = 0.25
#### 0.25 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 28, BVPS of NPR 36, and a market price per share of NPR 33, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 33 / 28 = 1.18
P/B ratio = 33 / 36 = 0.92
Spread = 1.18 - 0.92 = 0.26
#### 0.26 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 26, BVPS of NPR 30, and a market price per share of NPR 48, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 48 / 26 = 1.85
P/B ratio = 48 / 30 = 1.6
Spread = 1.85 - 1.6 = 0.25
#### 0.25 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 36, book value per share of NPR 68, and current price of NPR 62, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 62 / 36 = 1.72
P/B ratio = 62 / 68 = 0.91
Spread = 1.72 - 0.91 = 0.81
#### 0.81 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 11, BVPS of NPR 68, and a market price per share of NPR 68, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 68 / 11 = 6.18
P/B ratio = 68 / 68 = 1.0
Spread = 6.18 - 1.0 = 5.18
#### 5.18 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 28, book value per share of NPR 66, and current price of NPR 79, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 79 / 28 = 2.82
P/B ratio = 79 / 66 = 1.2
Spread = 2.82 - 1.2 = 1.62
#### 1.62 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 35, BVPS of NPR 78, and a market price per share of NPR 111, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 111 / 35 = 3.17
P/B ratio = 111 / 78 = 1.42
Spread = 3.17 - 1.42 = 1.75
#### 1.75 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 30, book value per share of NPR 61, and current price of NPR 80, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 80 / 30 = 2.67
P/B ratio = 80 / 61 = 1.31
Spread = 2.67 - 1.31 = 1.36
#### 1.36 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 7 and a book value per share (BVPS) of NPR 41. The market price per share is NPR 57. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 57 / 7 = 8.14
P/B ratio = 57 / 41 = 1.39
Spread = 8.14 - 1.39 = 6.75
#### 6.75 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 12, BVPS of NPR 21, and a market price per share of NPR 89, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 89 / 12 = 7.42
P/B ratio = 89 / 21 = 4.24
Spread = 7.42 - 4.24 = 3.18
#### 3.18 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 38, book value per share of NPR 52, and current price of NPR 52, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 52 / 38 = 1.37
P/B ratio = 52 / 52 = 1.0
Spread = 1.37 - 1.0 = 0.37
#### 0.37 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 13, BVPS of NPR 46, and a market price per share of NPR 106, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 106 / 13 = 8.15
P/B ratio = 106 / 46 = 2.3
Spread = 8.15 - 2.3 = 5.85
#### 5.85 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 36, BVPS of NPR 65, and a market price per share of NPR 87, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 87 / 36 = 2.42
P/B ratio = 87 / 65 = 1.34
Spread = 2.42 - 1.34 = 1.08
#### 1.08 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 6, BVPS of NPR 50, and a market price per share of NPR 79, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 79 / 6 = 13.17
P/B ratio = 79 / 50 = 1.58
Spread = 13.17 - 1.58 = 11.59
#### 11.59 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 18 and a book value per share (BVPS) of NPR 23. The market price per share is NPR 35. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 35 / 18 = 1.94
P/B ratio = 35 / 23 = 1.52
Spread = 1.94 - 1.52 = 0.42
#### 0.42 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 6, BVPS of NPR 50, and a market price per share of NPR 64, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 64 / 6 = 10.67
P/B ratio = 64 / 50 = 1.28
Spread = 10.67 - 1.28 = 9.39
#### 9.39 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 6, book value per share of NPR 27, and current price of NPR 40, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 40 / 6 = 6.67
P/B ratio = 40 / 27 = 1.48
Spread = 6.67 - 1.48 = 5.19
#### 5.19 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 34, book value per share of NPR 58, and current price of NPR 80, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 80 / 34 = 2.35
P/B ratio = 80 / 58 = 1.38
Spread = 2.35 - 1.38 = 0.97
#### 0.97 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 8 and a book value per share (BVPS) of NPR 47. The market price per share is NPR 106. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 106 / 8 = 13.25
P/B ratio = 106 / 47 = 2.26
Spread = 13.25 - 2.26 = 10.99
#### 10.99 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 49 and a book value per share (BVPS) of NPR 56. The market price per share is NPR 100. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 100 / 49 = 2.04
P/B ratio = 100 / 56 = 1.79
Spread = 2.04 - 1.79 = 0.26
#### 0.26 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 29, BVPS of NPR 61, and a market price per share of NPR 99, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 99 / 29 = 3.41
P/B ratio = 99 / 61 = 1.62
Spread = 3.41 - 1.62 = 1.79
#### 1.79 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 7 and a book value per share (BVPS) of NPR 60. The market price per share is NPR 41. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 41 / 7 = 5.86
P/B ratio = 41 / 60 = 0.68
Spread = 5.86 - 0.68 = 5.17
#### 5.17 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 46 and a book value per share (BVPS) of NPR 76. The market price per share is NPR 86. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 86 / 46 = 1.87
P/B ratio = 86 / 76 = 1.13
Spread = 1.87 - 1.13 = 0.74
#### 0.74 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 31 and a book value per share (BVPS) of NPR 64. The market price per share is NPR 114. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 114 / 31 = 3.68
P/B ratio = 114 / 64 = 1.78
Spread = 3.68 - 1.78 = 1.9
#### 1.9 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 10, BVPS of NPR 48, and a market price per share of NPR 116, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 116 / 10 = 11.6
P/B ratio = 116 / 48 = 2.42
Spread = 11.6 - 2.42 = 9.18
#### 9.18 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 12 and a book value per share (BVPS) of NPR 24. The market price per share is NPR 62. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 62 / 12 = 5.17
P/B ratio = 62 / 24 = 2.58
Spread = 5.17 - 2.58 = 2.58
#### 2.58 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 48 and a book value per share (BVPS) of NPR 62. The market price per share is NPR 53. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 53 / 48 = 1.1
P/B ratio = 53 / 62 = 0.85
Spread = 1.1 - 0.85 = 0.25
#### 0.25 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 24, book value per share of NPR 31, and current price of NPR 102, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 102 / 24 = 4.25
P/B ratio = 102 / 31 = 3.29
Spread = 4.25 - 3.29 = 0.96
#### 0.96 | tp_finance | a0f02dadc0 | general |
Question: A company reports an earnings per share (EPS) of NPR 20 and a book value per share (BVPS) of NPR 29. The market price per share is NPR 75. Calculate the price-to-earnings (P/E) ratio and the price-to-book (P/B) ratio, then determine the spread between the P/E and P/B ratios.
Answer: | P/E ratio = 75 / 20 = 3.75
P/B ratio = 75 / 29 = 2.59
Spread = 3.75 - 2.59 = 1.16
#### 1.16 | tp_finance | a0f02dadc0 | general |
Question: Given a company with EPS of NPR 42, BVPS of NPR 43, and a market price per share of NPR 71, find the P/E ratio and P/B ratio. What is the difference between these two ratios?
Answer: | P/E ratio = 71 / 42 = 1.69
P/B ratio = 71 / 43 = 1.65
Spread = 1.69 - 1.65 = 0.04
#### 0.04 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 19, book value per share of NPR 42, and current price of NPR 87, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 87 / 19 = 4.58
P/B ratio = 87 / 42 = 2.07
Spread = 4.58 - 2.07 = 2.51
#### 2.51 | tp_finance | a0f02dadc0 | general |
Question: For a stock with earnings per share of NPR 48, book value per share of NPR 76, and current price of NPR 34, compute the P/E and P/B ratios. What is the spread between them?
Answer: | P/E ratio = 34 / 48 = 0.71
P/B ratio = 34 / 76 = 0.45
Spread = 0.71 - 0.45 = 0.26
#### 0.26 | tp_finance | a0f02dadc0 | general |
Question: A student is arranging the letters of the word "VYDMLCOF" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'Y' appears immediately after the letter 'O'?
Answer: | Total letters: 8
Total distinct permutations: 8! = 40320
Condition: Y immediately after O
Treat OY as a single block
Items to arrange: OY and the remaining 6 letters
Number of items: 7
Favorable permutations: 7! = 5040
Probability: 7! / 8! = 5040 / 40320
Simplify: 1/8
#### 1/8 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "YGCRM" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'R' appears immediately after the letter 'G'?
Answer: | Total letters: 5
Total distinct permutations: 5! = 120
Condition: R immediately after G
Treat GR as a single block
Items to arrange: GR and the remaining 3 letters
Number of items: 4
Favorable permutations: 4! = 24
Probability: 4! / 5! = 24 / 120
Simplify: 1/5
#### 1/5 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "TNHEWIPVC" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'T' appears immediately after the letter 'P'?
Answer: | Total letters: 9
Total distinct permutations: 9! = 362880
Condition: T immediately after P
Treat PT as a single block
Items to arrange: PT and the remaining 7 letters
Number of items: 8
Favorable permutations: 8! = 40320
Probability: 8! / 9! = 40320 / 362880
Simplify: 1/9
#### 1/9 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "RLHOWZVM" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'Z' appears immediately after the letter 'R'?
Answer: | Total letters: 8
Total distinct permutations: 8! = 40320
Condition: Z immediately after R
Treat RZ as a single block
Items to arrange: RZ and the remaining 6 letters
Number of items: 7
Favorable permutations: 7! = 5040
Probability: 7! / 8! = 5040 / 40320
Simplify: 1/8
#### 1/8 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "DXTRVQGY" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'Y' appears immediately after the letter 'Q'?
Answer: | Total letters: 8
Total distinct permutations: 8! = 40320
Condition: Y immediately after Q
Treat QY as a single block
Items to arrange: QY and the remaining 6 letters
Number of items: 7
Favorable permutations: 7! = 5040
Probability: 7! / 8! = 5040 / 40320
Simplify: 1/8
#### 1/8 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "ZMRNSUJL" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'N' appears immediately after the letter 'R'?
Answer: | Total letters: 8
Total distinct permutations: 8! = 40320
Condition: N immediately after R
Treat RN as a single block
Items to arrange: RN and the remaining 6 letters
Number of items: 7
Favorable permutations: 7! = 5040
Probability: 7! / 8! = 5040 / 40320
Simplify: 1/8
#### 1/8 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "BHOAGSK" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'B' appears immediately after the letter 'S'?
Answer: | Total letters: 7
Total distinct permutations: 7! = 5040
Condition: B immediately after S
Treat SB as a single block
Items to arrange: SB and the remaining 5 letters
Number of items: 6
Favorable permutations: 6! = 720
Probability: 6! / 7! = 720 / 5040
Simplify: 1/7
#### 1/7 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "ZTFJX" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'X' appears immediately after the letter 'T'?
Answer: | Total letters: 5
Total distinct permutations: 5! = 120
Condition: X immediately after T
Treat TX as a single block
Items to arrange: TX and the remaining 3 letters
Number of items: 4
Favorable permutations: 4! = 24
Probability: 4! / 5! = 24 / 120
Simplify: 1/5
#### 1/5 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "OKCWDBESV" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'O' appears immediately after the letter 'B'?
Answer: | Total letters: 9
Total distinct permutations: 9! = 362880
Condition: O immediately after B
Treat BO as a single block
Items to arrange: BO and the remaining 7 letters
Number of items: 8
Favorable permutations: 8! = 40320
Probability: 8! / 9! = 40320 / 362880
Simplify: 1/9
#### 1/9 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "APCQYF" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'P' appears immediately after the letter 'Y'?
Answer: | Total letters: 6
Total distinct permutations: 6! = 720
Condition: P immediately after Y
Treat YP as a single block
Items to arrange: YP and the remaining 4 letters
Number of items: 5
Favorable permutations: 5! = 120
Probability: 5! / 6! = 120 / 720
Simplify: 1/6
#### 1/6 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "HRCNWVFEU" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'R' appears immediately after the letter 'N'?
Answer: | Total letters: 9
Total distinct permutations: 9! = 362880
Condition: R immediately after N
Treat NR as a single block
Items to arrange: NR and the remaining 7 letters
Number of items: 8
Favorable permutations: 8! = 40320
Probability: 8! / 9! = 40320 / 362880
Simplify: 1/9
#### 1/9 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "IANFVOM" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'O' appears immediately after the letter 'M'?
Answer: | Total letters: 7
Total distinct permutations: 7! = 5040
Condition: O immediately after M
Treat MO as a single block
Items to arrange: MO and the remaining 5 letters
Number of items: 6
Favorable permutations: 6! = 720
Probability: 6! / 7! = 720 / 5040
Simplify: 1/7
#### 1/7 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "FEMGTAL" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'A' appears immediately after the letter 'M'?
Answer: | Total letters: 7
Total distinct permutations: 7! = 5040
Condition: A immediately after M
Treat MA as a single block
Items to arrange: MA and the remaining 5 letters
Number of items: 6
Favorable permutations: 6! = 720
Probability: 6! / 7! = 720 / 5040
Simplify: 1/7
#### 1/7 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "YIWXFSUA" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'A' appears immediately after the letter 'U'?
Answer: | Total letters: 8
Total distinct permutations: 8! = 40320
Condition: A immediately after U
Treat UA as a single block
Items to arrange: UA and the remaining 6 letters
Number of items: 7
Favorable permutations: 7! = 5040
Probability: 7! / 8! = 5040 / 40320
Simplify: 1/8
#### 1/8 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "AHIBNVTFO" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'F' appears immediately after the letter 'O'?
Answer: | Total letters: 9
Total distinct permutations: 9! = 362880
Condition: F immediately after O
Treat OF as a single block
Items to arrange: OF and the remaining 7 letters
Number of items: 8
Favorable permutations: 8! = 40320
Probability: 8! / 9! = 40320 / 362880
Simplify: 1/9
#### 1/9 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "YJPQW" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'P' appears immediately after the letter 'Q'?
Answer: | Total letters: 5
Total distinct permutations: 5! = 120
Condition: P immediately after Q
Treat QP as a single block
Items to arrange: QP and the remaining 3 letters
Number of items: 4
Favorable permutations: 4! = 24
Probability: 4! / 5! = 24 / 120
Simplify: 1/5
#### 1/5 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "XMRLZFC" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'L' appears immediately after the letter 'R'?
Answer: | Total letters: 7
Total distinct permutations: 7! = 5040
Condition: L immediately after R
Treat RL as a single block
Items to arrange: RL and the remaining 5 letters
Number of items: 6
Favorable permutations: 6! = 720
Probability: 6! / 7! = 720 / 5040
Simplify: 1/7
#### 1/7 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "UNGDLJWZ" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'W' appears immediately after the letter 'L'?
Answer: | Total letters: 8
Total distinct permutations: 8! = 40320
Condition: W immediately after L
Treat LW as a single block
Items to arrange: LW and the remaining 6 letters
Number of items: 7
Favorable permutations: 7! = 5040
Probability: 7! / 8! = 5040 / 40320
Simplify: 1/8
#### 1/8 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "UYMWDHSK" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'H' appears immediately after the letter 'W'?
Answer: | Total letters: 8
Total distinct permutations: 8! = 40320
Condition: H immediately after W
Treat WH as a single block
Items to arrange: WH and the remaining 6 letters
Number of items: 7
Favorable permutations: 7! = 5040
Probability: 7! / 8! = 5040 / 40320
Simplify: 1/8
#### 1/8 | tp_probability | 28e7e9b82f | general |
Question: A student is arranging the letters of the word "KGDYH" on a chalkboard. If the arrangement is chosen uniformly at random from all distinct permutations, what is the probability that the letter 'G' appears immediately after the letter 'Y'?
Answer: | Total letters: 5
Total distinct permutations: 5! = 120
Condition: G immediately after Y
Treat YG as a single block
Items to arrange: YG and the remaining 3 letters
Number of items: 4
Favorable permutations: 4! = 24
Probability: 4! / 5! = 24 / 120
Simplify: 1/5
#### 1/5 | tp_probability | 28e7e9b82f | general |
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