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Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 50 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 280 m/s = 271.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 271.60 / (3 x 10^8) = 9.05e-07.
The relativistic length contraction factor is sqrt(1 - (9.05e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 300 m/s. If the aircraft has a wingspan of 30 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 300 m/s = 216.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 216.00 / (3 x 10^8) = 7.20e-07.
The relativistic length contraction factor is sqrt(1 - (7.20e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.99 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 39 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.99, which is 0.99 * 340 m/s = 336.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 336.60 / (3 x 10^8) = 1.12e-06.
The relativistic length contraction factor is sqrt(1 - (1.12e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 320 m/s. If the aircraft has a wingspan of 39 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 320 m/s = 310.40 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 310.40 / (3 x 10^8) = 1.03e-06.
The relativistic length contraction factor is sqrt(1 - (1.03e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 59 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 280 m/s = 271.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 271.60 / (3 x 10^8) = 9.05e-07.
The relativistic length contraction factor is sqrt(1 - (9.05e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 59 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 340 m/s = 329.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 329.80 / (3 x 10^8) = 1.10e-06.
The relativistic length contraction factor is sqrt(1 - (1.10e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.93 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 39 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.93, which is 0.93 * 280 m/s = 260.40 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 260.40 / (3 x 10^8) = 8.68e-07.
The relativistic length contraction factor is sqrt(1 - (8.68e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 300 m/s. If the aircraft has a wingspan of 44 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 300 m/s = 216.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 216.00 / (3 x 10^8) = 7.20e-07.
The relativistic length contraction factor is sqrt(1 - (7.20e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.99 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 46 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.99, which is 0.99 * 340 m/s = 336.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 336.60 / (3 x 10^8) = 1.12e-06.
The relativistic length contraction factor is sqrt(1 - (1.12e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.85 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 56 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.85, which is 0.85 * 280 m/s = 238.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 238.00 / (3 x 10^8) = 7.93e-07.
The relativistic length contraction factor is sqrt(1 - (7.93e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.99 through the lower stratosphere where the speed of sound is 300 m/s. If the aircraft has a wingspan of 59 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.99, which is 0.99 * 300 m/s = 297.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 297.00 / (3 x 10^8) = 9.90e-07.
The relativistic length contraction factor is sqrt(1 - (9.90e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.93 through the lower stratosphere where the speed of sound is 320 m/s. If the aircraft has a wingspan of 26 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.93, which is 0.93 * 320 m/s = 297.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 297.60 / (3 x 10^8) = 9.92e-07.
The relativistic length contraction factor is sqrt(1 - (9.92e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.93 through the lower stratosphere where the speed of sound is 300 m/s. If the aircraft has a wingspan of 34 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.93, which is 0.93 * 300 m/s = 279.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 279.00 / (3 x 10^8) = 9.30e-07.
The relativistic length contraction factor is sqrt(1 - (9.30e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 320 m/s. If the aircraft has a wingspan of 36 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 320 m/s = 310.40 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 310.40 / (3 x 10^8) = 1.03e-06.
The relativistic length contraction factor is sqrt(1 - (1.03e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.99 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 40 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.99, which is 0.99 * 280 m/s = 277.20 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 277.20 / (3 x 10^8) = 9.24e-07.
The relativistic length contraction factor is sqrt(1 - (9.24e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 320 m/s. If the aircraft has a wingspan of 56 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 320 m/s = 230.40 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 230.40 / (3 x 10^8) = 7.68e-07.
The relativistic length contraction factor is sqrt(1 - (7.68e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.93 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 59 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.93, which is 0.93 * 340 m/s = 316.20 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 316.20 / (3 x 10^8) = 1.05e-06.
The relativistic length contraction factor is sqrt(1 - (1.05e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 37 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 340 m/s = 329.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 329.80 / (3 x 10^8) = 1.10e-06.
The relativistic length contraction factor is sqrt(1 - (1.10e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 31 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 340 m/s = 329.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 329.80 / (3 x 10^8) = 1.10e-06.
The relativistic length contraction factor is sqrt(1 - (1.10e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 320 m/s. If the aircraft has a wingspan of 38 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 320 m/s = 230.40 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 230.40 / (3 x 10^8) = 7.68e-07.
The relativistic length contraction factor is sqrt(1 - (7.68e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 54 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 280 m/s = 201.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 201.60 / (3 x 10^8) = 6.72e-07.
The relativistic length contraction factor is sqrt(1 - (6.72e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.99 through the lower stratosphere where the speed of sound is 300 m/s. If the aircraft has a wingspan of 40 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.99, which is 0.99 * 300 m/s = 297.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 297.00 / (3 x 10^8) = 9.90e-07.
The relativistic length contraction factor is sqrt(1 - (9.90e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.85 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 48 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.85, which is 0.85 * 340 m/s = 289.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 289.00 / (3 x 10^8) = 9.63e-07.
The relativistic length contraction factor is sqrt(1 - (9.63e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 55 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 340 m/s = 329.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 329.80 / (3 x 10^8) = 1.10e-06.
The relativistic length contraction factor is sqrt(1 - (1.10e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 49 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 340 m/s = 244.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 244.80 / (3 x 10^8) = 8.16e-07.
The relativistic length contraction factor is sqrt(1 - (8.16e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.85 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 27 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.85, which is 0.85 * 280 m/s = 238.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 238.00 / (3 x 10^8) = 7.93e-07.
The relativistic length contraction factor is sqrt(1 - (7.93e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 42 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 340 m/s = 244.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 244.80 / (3 x 10^8) = 8.16e-07.
The relativistic length contraction factor is sqrt(1 - (8.16e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 30 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 280 m/s = 201.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 201.60 / (3 x 10^8) = 6.72e-07.
The relativistic length contraction factor is sqrt(1 - (6.72e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 41 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 340 m/s = 329.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 329.80 / (3 x 10^8) = 1.10e-06.
The relativistic length contraction factor is sqrt(1 - (1.10e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.99 through the lower stratosphere where the speed of sound is 320 m/s. If the aircraft has a wingspan of 58 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.99, which is 0.99 * 320 m/s = 316.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 316.80 / (3 x 10^8) = 1.06e-06.
The relativistic length contraction factor is sqrt(1 - (1.06e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 35 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 340 m/s = 244.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 244.80 / (3 x 10^8) = 8.16e-07.
The relativistic length contraction factor is sqrt(1 - (8.16e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.99 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 27 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.99, which is 0.99 * 280 m/s = 277.20 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 277.20 / (3 x 10^8) = 9.24e-07.
The relativistic length contraction factor is sqrt(1 - (9.24e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 35 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 340 m/s = 329.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 329.80 / (3 x 10^8) = 1.10e-06.
The relativistic length contraction factor is sqrt(1 - (1.10e-06)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.85 through the lower stratosphere where the speed of sound is 320 m/s. If the aircraft has a wingspan of 54 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.85, which is 0.85 * 320 m/s = 272.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 272.00 / (3 x 10^8) = 9.07e-07.
The relativistic length contraction factor is sqrt(1 - (9.07e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 300 m/s. If the aircraft has a wingspan of 41 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 300 m/s = 291.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 291.00 / (3 x 10^8) = 9.70e-07.
The relativistic length contraction factor is sqrt(1 - (9.70e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.97 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 29 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.97, which is 0.97 * 280 m/s = 271.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 271.60 / (3 x 10^8) = 9.05e-07.
The relativistic length contraction factor is sqrt(1 - (9.05e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 340 m/s. If the aircraft has a wingspan of 56 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 340 m/s = 244.80 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 244.80 / (3 x 10^8) = 8.16e-07.
The relativistic length contraction factor is sqrt(1 - (8.16e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.72 through the lower stratosphere where the speed of sound is 280 m/s. If the aircraft has a wingspan of 41 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.72, which is 0.72 * 280 m/s = 201.60 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 201.60 / (3 x 10^8) = 6.72e-07.
The relativistic length contraction factor is sqrt(1 - (6.72e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.85 through the lower stratosphere where the speed of sound is 300 m/s. If the aircraft has a wingspan of 31 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.85, which is 0.85 * 300 m/s = 255.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 255.00 / (3 x 10^8) = 8.50e-07.
The relativistic length contraction factor is sqrt(1 - (8.50e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: A commercial jet travels at Mach 0.93 through the lower stratosphere where the speed of sound is 300 m/s. If the aircraft has a wingspan of 40 m and is passing a stationary observer on the ground, what is the length of the shadow cast by the wingspan on the ground, assuming the light source is directly overhe... | The aircraft's speed is Mach 0.93, which is 0.93 * 300 m/s = 279.00 m/s.
The speed of light is approximately 3 x 10^8 m/s.
The ratio of the aircraft's speed to the speed of light is 279.00 / (3 x 10^8) = 9.30e-07.
The relativistic length contraction factor is sqrt(1 - (9.30e-07)^2) ≈ 1.0000000000.
The length of the wi... | tp_science_calc | 0841364796 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 12 degrees for every 4 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 64 centimeters per minute, how many degre... | The mechanical crank travels at a speed of 64 cm/min.
The time duration is 2 minutes.
The total distance traveled is 64 cm/min * 2 min = 128 cm.
The rotation rate is 12 degrees per 4 cm.
The total rotation is 128 cm * (12 degrees / 4 cm).
The total rotation is 128 * 3.0 degrees.
The total rotation is 384 degrees.
####... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 18 degrees for every 1 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 17 centimeters per minute, how many degrees will the out... | The drive arm travels at a speed of 17 cm/min.
The time duration is 4 minutes.
The total distance traveled is 17 cm/min * 4 min = 68 cm.
The rotation rate is 18 degrees per 1 cm.
The total rotation is 68 cm * (18 degrees / 1 cm).
The total rotation is 68 * 18.0 degrees.
The total rotation is 1224 degrees.
#### 1224 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 29 degrees for every 4 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 76 centimeters per minute, how many deg... | The mechanical crank travels at a speed of 76 cm/min.
The time duration is 10 minutes.
The total distance traveled is 76 cm/min * 10 min = 760 cm.
The rotation rate is 29 degrees per 4 cm.
The total rotation is 760 cm * (29 degrees / 4 cm).
The total rotation is 760 * 7.25 degrees.
The total rotation is 5510 degrees.
... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 8 degrees for every 3 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 73 centimeters per minute, how many degrees wil... | The rotation lever travels at a speed of 73 cm/min.
The time duration is 9 minutes.
The total distance traveled is 73 cm/min * 9 min = 657 cm.
The rotation rate is 8 degrees per 3 cm.
The total rotation is 657 cm * (8 degrees / 3 cm).
The total rotation is 657 * 2.6666666666666665 degrees.
The total rotation is 1752 d... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 15 degrees for every 2 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 54 centimeters per minute, how many degrees w... | The rotation lever travels at a speed of 54 cm/min.
The time duration is 1 minutes.
The total distance traveled is 54 cm/min * 1 min = 54 cm.
The rotation rate is 15 degrees per 2 cm.
The total rotation is 54 cm * (15 degrees / 2 cm).
The total rotation is 54 * 7.5 degrees.
The total rotation is 405 degrees.
#### 405 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of CipherQuest, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 29 degrees for every 2 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 14 centimeters per minute, how many degrees wi... | The rotation lever travels at a speed of 14 cm/min.
The time duration is 10 minutes.
The total distance traveled is 14 cm/min * 10 min = 140 cm.
The rotation rate is 29 degrees per 2 cm.
The total rotation is 140 cm * (29 degrees / 2 cm).
The total rotation is 140 * 14.5 degrees.
The total rotation is 2030 degrees.
##... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 3 degrees for every 3 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 76 centimeters per minute, how many degrees wi... | The rotation lever travels at a speed of 76 cm/min.
The time duration is 8 minutes.
The total distance traveled is 76 cm/min * 8 min = 608 cm.
The rotation rate is 3 degrees per 3 cm.
The total rotation is 608 cm * (3 degrees / 3 cm).
The total rotation is 608 * 1.0 degrees.
The total rotation is 608 degrees.
#### 608 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 18 degrees for every 2 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 95 centimeters per minute, how many degrees will the in... | The drive arm travels at a speed of 95 cm/min.
The time duration is 10 minutes.
The total distance traveled is 95 cm/min * 10 min = 950 cm.
The rotation rate is 18 degrees per 2 cm.
The total rotation is 950 cm * (18 degrees / 2 cm).
The total rotation is 950 * 9.0 degrees.
The total rotation is 8550 degrees.
#### 855... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 14 degrees for every 1 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 56 centimeters per minute, how many degrees will the rotor... | The drive arm travels at a speed of 56 cm/min.
The time duration is 5 minutes.
The total distance traveled is 56 cm/min * 5 min = 280 cm.
The rotation rate is 14 degrees per 1 cm.
The total rotation is 280 cm * (14 degrees / 1 cm).
The total rotation is 280 * 14.0 degrees.
The total rotation is 3920 degrees.
#### 3920 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 19 degrees for every 2 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 72 centimeters per minute, how many degre... | The mechanical crank travels at a speed of 72 cm/min.
The time duration is 5 minutes.
The total distance traveled is 72 cm/min * 5 min = 360 cm.
The rotation rate is 19 degrees per 2 cm.
The total rotation is 360 cm * (19 degrees / 2 cm).
The total rotation is 360 * 9.5 degrees.
The total rotation is 3420 degrees.
###... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 26 degrees for every 2 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 71 centimeters per minute, how many degrees will the in... | The drive arm travels at a speed of 71 cm/min.
The time duration is 7 minutes.
The total distance traveled is 71 cm/min * 7 min = 497 cm.
The rotation rate is 26 degrees per 2 cm.
The total rotation is 497 cm * (26 degrees / 2 cm).
The total rotation is 497 * 13.0 degrees.
The total rotation is 6461 degrees.
#### 6461 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 22 degrees for every 1 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 60 centimeters per minute, how many degrees will the rotor... | The drive arm travels at a speed of 60 cm/min.
The time duration is 7 minutes.
The total distance traveled is 60 cm/min * 7 min = 420 cm.
The rotation rate is 22 degrees per 1 cm.
The total rotation is 420 cm * (22 degrees / 1 cm).
The total rotation is 420 * 22.0 degrees.
The total rotation is 9240 degrees.
#### 9240 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 4 degrees for every 2 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 14 centimeters per minute, how many degrees ... | The rotation lever travels at a speed of 14 cm/min.
The time duration is 6 minutes.
The total distance traveled is 14 cm/min * 6 min = 84 cm.
The rotation rate is 4 degrees per 2 cm.
The total rotation is 84 cm * (4 degrees / 2 cm).
The total rotation is 84 * 2.0 degrees.
The total rotation is 168 degrees.
#### 168 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 25 degrees for every 4 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 24 centimeters per minute, how many degrees wil... | The mechanical crank travels at a speed of 24 cm/min.
The time duration is 1 minutes.
The total distance traveled is 24 cm/min * 1 min = 24 cm.
The rotation rate is 25 degrees per 4 cm.
The total rotation is 24 cm * (25 degrees / 4 cm).
The total rotation is 24 * 6.25 degrees.
The total rotation is 150 degrees.
#### 1... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 5 degrees for every 4 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 72 centimeters per minute, how many degrees... | The mechanical crank travels at a speed of 72 cm/min.
The time duration is 8 minutes.
The total distance traveled is 72 cm/min * 8 min = 576 cm.
The rotation rate is 5 degrees per 4 cm.
The total rotation is 576 cm * (5 degrees / 4 cm).
The total rotation is 576 * 1.25 degrees.
The total rotation is 720 degrees.
#### ... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 11 degrees for every 4 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 12 centimeters per minute, how many degrees w... | The rotation lever travels at a speed of 12 cm/min.
The time duration is 8 minutes.
The total distance traveled is 12 cm/min * 8 min = 96 cm.
The rotation rate is 11 degrees per 4 cm.
The total rotation is 96 cm * (11 degrees / 4 cm).
The total rotation is 96 * 2.75 degrees.
The total rotation is 264 degrees.
#### 264 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of CipherQuest, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 7 degrees for every 1 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 36 centimeters per minute, how many degree... | The rotation lever travels at a speed of 36 cm/min.
The time duration is 1 minutes.
The total distance traveled is 36 cm/min * 1 min = 36 cm.
The rotation rate is 7 degrees per 1 cm.
The total rotation is 36 cm * (7 degrees / 1 cm).
The total rotation is 36 * 7.0 degrees.
The total rotation is 252 degrees.
#### 252 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 18 degrees for every 1 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 12 centimeters per minute, how many degree... | The mechanical crank travels at a speed of 12 cm/min.
The time duration is 2 minutes.
The total distance traveled is 12 cm/min * 2 min = 24 cm.
The rotation rate is 18 degrees per 1 cm.
The total rotation is 24 cm * (18 degrees / 1 cm).
The total rotation is 24 * 18.0 degrees.
The total rotation is 432 degrees.
#### 4... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of CipherQuest, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 28 degrees for every 4 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 69 centimeters per minute, how many degrees will th... | The drive arm travels at a speed of 69 cm/min.
The time duration is 10 minutes.
The total distance traveled is 69 cm/min * 10 min = 690 cm.
The rotation rate is 28 degrees per 4 cm.
The total rotation is 690 cm * (28 degrees / 4 cm).
The total rotation is 690 * 7.0 degrees.
The total rotation is 4830 degrees.
#### 483... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 17 degrees for every 5 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 87 centimeters per minute, how many degrees will... | The rotation lever travels at a speed of 87 cm/min.
The time duration is 5 minutes.
The total distance traveled is 87 cm/min * 5 min = 435 cm.
The rotation rate is 17 degrees per 5 cm.
The total rotation is 435 cm * (17 degrees / 5 cm).
The total rotation is 435 * 3.4 degrees.
The total rotation is 1479 degrees.
#### ... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 2 degrees for every 5 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 99 centimeters per minute, how many degrees will the inn... | The drive arm travels at a speed of 99 cm/min.
The time duration is 10 minutes.
The total distance traveled is 99 cm/min * 10 min = 990 cm.
The rotation rate is 2 degrees per 5 cm.
The total rotation is 990 cm * (2 degrees / 5 cm).
The total rotation is 990 * 0.4 degrees.
The total rotation is 396 degrees.
#### 396 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 15 degrees for every 3 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 92 centimeters per minute, how many degrees wi... | The mechanical crank travels at a speed of 92 cm/min.
The time duration is 4 minutes.
The total distance traveled is 92 cm/min * 4 min = 368 cm.
The rotation rate is 15 degrees per 3 cm.
The total rotation is 368 cm * (15 degrees / 3 cm).
The total rotation is 368 * 5.0 degrees.
The total rotation is 1840 degrees.
###... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 4 degrees for every 1 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 14 centimeters per minute, how many degrees... | The mechanical crank travels at a speed of 14 cm/min.
The time duration is 2 minutes.
The total distance traveled is 14 cm/min * 2 min = 28 cm.
The rotation rate is 4 degrees per 1 cm.
The total rotation is 28 cm * (4 degrees / 1 cm).
The total rotation is 28 * 4.0 degrees.
The total rotation is 112 degrees.
#### 112 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 9 degrees for every 2 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 93 centimeters per minute, how many degr... | The mechanical crank travels at a speed of 93 cm/min.
The time duration is 8 minutes.
The total distance traveled is 93 cm/min * 8 min = 744 cm.
The rotation rate is 9 degrees per 2 cm.
The total rotation is 744 cm * (9 degrees / 2 cm).
The total rotation is 744 * 4.5 degrees.
The total rotation is 3348 degrees.
#### ... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 2 degrees for every 1 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 63 centimeters per minute, how many degrees will the inn... | The drive arm travels at a speed of 63 cm/min.
The time duration is 2 minutes.
The total distance traveled is 63 cm/min * 2 min = 126 cm.
The rotation rate is 2 degrees per 1 cm.
The total rotation is 126 cm * (2 degrees / 1 cm).
The total rotation is 126 * 2.0 degrees.
The total rotation is 252 degrees.
#### 252 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 22 degrees for every 4 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 20 centimeters per minute, how many degre... | The mechanical crank travels at a speed of 20 cm/min.
The time duration is 8 minutes.
The total distance traveled is 20 cm/min * 8 min = 160 cm.
The rotation rate is 22 degrees per 4 cm.
The total rotation is 160 cm * (22 degrees / 4 cm).
The total rotation is 160 * 5.5 degrees.
The total rotation is 880 degrees.
####... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 5 degrees for every 3 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 24 centimeters per minute, how many degrees will the inn... | The drive arm travels at a speed of 24 cm/min.
The time duration is 2 minutes.
The total distance traveled is 24 cm/min * 2 min = 48 cm.
The rotation rate is 5 degrees per 3 cm.
The total rotation is 48 cm * (5 degrees / 3 cm).
The total rotation is 48 * 1.6666666666666667 degrees.
The total rotation is 80 degrees.
##... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 22 degrees for every 2 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 96 centimeters per minute, how many degre... | The mechanical crank travels at a speed of 96 cm/min.
The time duration is 3 minutes.
The total distance traveled is 96 cm/min * 3 min = 288 cm.
The rotation rate is 22 degrees per 2 cm.
The total rotation is 288 cm * (22 degrees / 2 cm).
The total rotation is 288 * 11.0 degrees.
The total rotation is 3168 degrees.
##... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of CipherQuest, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 2 degrees for every 3 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 41 centimeters per minute, how many degrees will the... | The drive arm travels at a speed of 41 cm/min.
The time duration is 3 minutes.
The total distance traveled is 41 cm/min * 3 min = 123 cm.
The rotation rate is 2 degrees per 3 cm.
The total rotation is 123 cm * (2 degrees / 3 cm).
The total rotation is 123 * 0.6666666666666666 degrees.
The total rotation is 82 degrees.... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 16 degrees for every 3 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 84 centimeters per minute, how many degrees ... | The mechanical crank travels at a speed of 84 cm/min.
The time duration is 6 minutes.
The total distance traveled is 84 cm/min * 6 min = 504 cm.
The rotation rate is 16 degrees per 3 cm.
The total rotation is 504 cm * (16 degrees / 3 cm).
The total rotation is 504 * 5.333333333333333 degrees.
The total rotation is 268... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 25 degrees for every 4 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 38 centimeters per minute, how many degrees will th... | The rotation lever travels at a speed of 38 cm/min.
The time duration is 6 minutes.
The total distance traveled is 38 cm/min * 6 min = 228 cm.
The rotation rate is 25 degrees per 4 cm.
The total rotation is 228 cm * (25 degrees / 4 cm).
The total rotation is 228 * 6.25 degrees.
The total rotation is 1425 degrees.
####... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 15 degrees for every 4 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 96 centimeters per minute, how many degrees will the out... | The drive arm travels at a speed of 96 cm/min.
The time duration is 1 minutes.
The total distance traveled is 96 cm/min * 1 min = 96 cm.
The rotation rate is 15 degrees per 4 cm.
The total rotation is 96 cm * (15 degrees / 4 cm).
The total rotation is 96 * 3.75 degrees.
The total rotation is 360 degrees.
#### 360 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of AgentX, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 9 degrees for every 4 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 20 centimeters per minute, how many degrees will the inne... | The drive arm travels at a speed of 20 cm/min.
The time duration is 5 minutes.
The total distance traveled is 20 cm/min * 5 min = 100 cm.
The rotation rate is 9 degrees per 4 cm.
The total rotation is 100 cm * (9 degrees / 4 cm).
The total rotation is 100 * 2.25 degrees.
The total rotation is 225 degrees.
#### 225 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The rotor of the wheel rotates 7 degrees for every 2 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 44 centimeters per minute, how many degrees wil... | The mechanical crank travels at a speed of 44 cm/min.
The time duration is 5 minutes.
The total distance traveled is 44 cm/min * 5 min = 220 cm.
The rotation rate is 7 degrees per 2 cm.
The total rotation is 220 cm * (7 degrees / 2 cm).
The total rotation is 220 * 3.5 degrees.
The total rotation is 770 degrees.
#### 7... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Spyfall, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 26 degrees for every 4 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 97 centimeters per minute, how many degrees will the ou... | The drive arm travels at a speed of 97 cm/min.
The time duration is 10 minutes.
The total distance traveled is 97 cm/min * 10 min = 970 cm.
The rotation rate is 26 degrees per 4 cm.
The total rotation is 970 cm * (26 degrees / 4 cm).
The total rotation is 970 * 6.5 degrees.
The total rotation is 6305 degrees.
#### 630... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 21 degrees for every 3 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 54 centimeters per minute, how many degrees will the ... | The drive arm travels at a speed of 54 cm/min.
The time duration is 6 minutes.
The total distance traveled is 54 cm/min * 6 min = 324 cm.
The rotation rate is 21 degrees per 3 cm.
The total rotation is 324 cm * (21 degrees / 3 cm).
The total rotation is 324 * 7.0 degrees.
The total rotation is 2268 degrees.
#### 2268 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 26 degrees for every 1 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 25 centimeters per minute, how many degrees will the ... | The drive arm travels at a speed of 25 cm/min.
The time duration is 9 minutes.
The total distance traveled is 25 cm/min * 9 min = 225 cm.
The rotation rate is 26 degrees per 1 cm.
The total rotation is 225 cm * (26 degrees / 1 cm).
The total rotation is 225 * 26.0 degrees.
The total rotation is 5850 degrees.
#### 5850 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of Codebreak, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 30 degrees for every 3 centimeters of distance traveled by a drive arm. If the drive arm travels at a constant speed of 21 centimeters per minute, how many degrees will the ... | The drive arm travels at a speed of 21 cm/min.
The time duration is 2 minutes.
The total distance traveled is 21 cm/min * 2 min = 42 cm.
The rotation rate is 30 degrees per 3 cm.
The total rotation is 42 cm * (30 degrees / 3 cm).
The total rotation is 42 * 10.0 degrees.
The total rotation is 420 degrees.
#### 420 | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of CipherQuest, a team of agents must decrypt a signal using a cipher wheel. The inner disk of the wheel rotates 7 degrees for every 3 centimeters of distance traveled by a rotation lever. If the rotation lever travels at a constant speed of 24 centimeters per minute, how many degree... | The rotation lever travels at a speed of 24 cm/min.
The time duration is 3 minutes.
The total distance traveled is 24 cm/min * 3 min = 72 cm.
The rotation rate is 7 degrees per 3 cm.
The total rotation is 72 cm * (7 degrees / 3 cm).
The total rotation is 72 * 2.3333333333333335 degrees.
The total rotation is 168 degre... | tp_wordproblem | 8d2c649324 | general |
Question: In the fictional scenario of CipherQuest, a team of agents must decrypt a signal using a cipher wheel. The outer ring of the wheel rotates 14 degrees for every 2 centimeters of distance traveled by a mechanical crank. If the mechanical crank travels at a constant speed of 81 centimeters per minute, how many d... | The mechanical crank travels at a speed of 81 cm/min.
The time duration is 9 minutes.
The total distance traveled is 81 cm/min * 9 min = 729 cm.
The rotation rate is 14 degrees per 2 cm.
The total rotation is 729 cm * (14 degrees / 2 cm).
The total rotation is 729 * 7.0 degrees.
The total rotation is 5103 degrees.
###... | tp_wordproblem | 8d2c649324 | general |
Question: A contestant participates in a classic cinema competition with 200 questions. Each correct answer earns 12 points, while each incorrect answer deducts 4 points. The correct answers made up 25% of all questions. What is the contestant's final score?
Answer: | 0.25 × 200 = 50
200 − 50 = 150
50 × 12 = 600
150 × 4 = 600
600 − 600 = 0
#### 0 | tp_wordproblem | 245393e8ee | general |
Question: In a quiz about music theory, a player answers 120 questions. The player gains 5 points per correct answer and loses 6 points per incorrect answer. The correct answers made up 40% of all questions. What is the contestant's final score?
Answer: | 0.4 × 120 = 48
120 − 48 = 72
48 × 5 = 240
72 × 6 = 432
240 − 432 = -192
#### -192 | tp_wordproblem | 245393e8ee | general |
Question: A contestant participates in a world history competition with 220 questions. The player gains 8 points per correct answer and loses 3 points per incorrect answer. The contestant answered 75% of the questions correctly. What is the contestant's final score?
Answer: | 0.75 × 220 = 165
220 − 165 = 55
165 × 8 = 1320
55 × 3 = 165
1320 − 165 = 1155
#### 1155 | tp_wordproblem | 245393e8ee | general |
Question: For a geography trivia challenge, 200 questions are presented to a contestant. Correct answers are worth 20 points and incorrect answers cost 6 points. The correct answers made up 25% of all questions. What is the contestant's final score?
Answer: | 0.25 × 200 = 50
200 − 50 = 150
50 × 20 = 1000
150 × 6 = 900
1000 − 900 = 100
#### 100 | tp_wordproblem | 245393e8ee | general |
Question: For a geography trivia challenge, 200 questions are presented to a contestant. The player gains 15 points per correct answer and loses 5 points per incorrect answer. A total of 70% of the questions were answered correctly. What is the contestant's final score?
Answer: | 0.7 × 200 = 140
200 − 140 = 60
140 × 15 = 2100
60 × 5 = 300
2100 − 300 = 1800
#### 1800 | tp_wordproblem | 245393e8ee | general |
Question: In a quiz about classic cinema, a player answers 180 questions. Correct answers are worth 8 points and incorrect answers cost 5 points. A total of 15% of the questions were answered correctly. What is the contestant's final score?
Answer: | 0.15 × 180 = 27
180 − 27 = 153
27 × 8 = 216
153 × 5 = 765
216 − 765 = -549
#### -549 | tp_wordproblem | 245393e8ee | general |
Question: In a quiz about world history, a player answers 120 questions. Correct answers are worth 10 points and incorrect answers cost 8 points. The contestant answered 35% of the questions correctly. What is the contestant's final score?
Answer: | 0.35 × 120 = 42
120 − 42 = 78
42 × 10 = 420
78 × 8 = 624
420 − 624 = -204
#### -204 | tp_wordproblem | 245393e8ee | general |
Question: In a quiz about classic cinema, a player answers 220 questions. Correct answers are worth 10 points and incorrect answers cost 2 points. The correct answers made up 80% of all questions. What is the contestant's final score?
Answer: | 0.8 × 220 = 176
220 − 176 = 44
176 × 10 = 1760
44 × 2 = 88
1760 − 88 = 1672
#### 1672 | tp_wordproblem | 245393e8ee | general |
Question: A contestant participates in a geography competition with 150 questions. Each correct answer earns 12 points, while each incorrect answer deducts 2 points. The correct answers made up 10% of all questions. What is the contestant's final score?
Answer: | 0.1 × 150 = 15
150 − 15 = 135
15 × 12 = 180
135 × 2 = 270
180 − 270 = -90
#### -90 | tp_wordproblem | 245393e8ee | general |
Question: For a world history trivia challenge, 180 questions are presented to a contestant. Each correct answer earns 8 points, while each incorrect answer deducts 5 points. A total of 35% of the questions were answered correctly. What is the contestant's final score?
Answer: | 0.35 × 180 = 63
180 − 63 = 117
63 × 8 = 504
117 × 5 = 585
504 − 585 = -81
#### -81 | tp_wordproblem | 245393e8ee | general |
Question: For a world history trivia challenge, 200 questions are presented to a contestant. Correct answers are worth 20 points and incorrect answers cost 8 points. The contestant answered 50% of the questions correctly. What is the contestant's final score?
Answer: | 0.5 × 200 = 100
200 − 100 = 100
100 × 20 = 2000
100 × 8 = 800
2000 − 800 = 1200
#### 1200 | tp_wordproblem | 245393e8ee | general |
Question: A contestant participates in a classic cinema competition with 220 questions. The player gains 8 points per correct answer and loses 4 points per incorrect answer. The correct answers made up 10% of all questions. What is the contestant's final score?
Answer: | 0.1 × 220 = 22
220 − 22 = 198
22 × 8 = 176
198 × 4 = 792
176 − 792 = -616
#### -616 | tp_wordproblem | 245393e8ee | general |
Question: A contestant participates in a music theory competition with 120 questions. The player gains 12 points per correct answer and loses 6 points per incorrect answer. The correct answers made up 55% of all questions. What is the contestant's final score?
Answer: | 0.55 × 120 = 66
120 − 66 = 54
66 × 12 = 792
54 × 6 = 324
792 − 324 = 468
#### 468 | tp_wordproblem | 245393e8ee | general |
Question: In a quiz about geography, a player answers 180 questions. Correct answers are worth 15 points and incorrect answers cost 4 points. The correct answers made up 70% of all questions. What is the contestant's final score?
Answer: | 0.7 × 180 = 126
180 − 126 = 54
126 × 15 = 1890
54 × 4 = 216
1890 − 216 = 1674
#### 1674 | tp_wordproblem | 245393e8ee | general |
Question: A contestant participates in a science fiction competition with 200 questions. Each correct answer earns 8 points, while each incorrect answer deducts 2 points. A total of 75% of the questions were answered correctly. What is the contestant's final score?
Answer: | 0.75 × 200 = 150
200 − 150 = 50
150 × 8 = 1200
50 × 2 = 100
1200 − 100 = 1100
#### 1100 | tp_wordproblem | 245393e8ee | general |
Question: For a world history trivia challenge, 200 questions are presented to a contestant. The player gains 20 points per correct answer and loses 2 points per incorrect answer. The contestant answered 70% of the questions correctly. What is the contestant's final score?
Answer: | 0.7 × 200 = 140
200 − 140 = 60
140 × 20 = 2800
60 × 2 = 120
2800 − 120 = 2680
#### 2680 | tp_wordproblem | 245393e8ee | general |
Question: A contestant participates in a world history competition with 120 questions. Correct answers are worth 8 points and incorrect answers cost 2 points. The correct answers made up 60% of all questions. What is the contestant's final score?
Answer: | 0.6 × 120 = 72
120 − 72 = 48
72 × 8 = 576
48 × 2 = 96
576 − 96 = 480
#### 480 | tp_wordproblem | 245393e8ee | general |
Question: In a quiz about geography, a player answers 120 questions. The player gains 12 points per correct answer and loses 5 points per incorrect answer. The contestant answered 10% of the questions correctly. What is the contestant's final score?
Answer: | 0.1 × 120 = 12
120 − 12 = 108
12 × 12 = 144
108 × 5 = 540
144 − 540 = -396
#### -396 | tp_wordproblem | 245393e8ee | general |
Question: A contestant participates in a world history competition with 220 questions. Correct answers are worth 8 points and incorrect answers cost 6 points. A total of 90% of the questions were answered correctly. What is the contestant's final score?
Answer: | 0.9 × 220 = 198
220 − 198 = 22
198 × 8 = 1584
22 × 6 = 132
1584 − 132 = 1452
#### 1452 | tp_wordproblem | 245393e8ee | general |
Question: A contestant participates in a music theory competition with 200 questions. Each correct answer earns 12 points, while each incorrect answer deducts 3 points. The correct answers made up 80% of all questions. What is the contestant's final score?
Answer: | 0.8 × 200 = 160
200 − 160 = 40
160 × 12 = 1920
40 × 3 = 120
1920 − 120 = 1800
#### 1800 | tp_wordproblem | 245393e8ee | general |
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