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sft_v1/teach/gq_g3_1791488404_00098.jsonl
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{"prompt": "Question: The Sunbeam Tiger, a high‑performance version of the Sunbeam Alpine, debuted in 1964 with a 4.7‑liter V8 borrowed from the Ford Mustang. Its introduction boosted the Alpine’s sales by 22 % that year, while the Tiger itself accounted for 15 % of total Sunbeam sales. If Sunbeam sold 30,000 cars in 1964, how many of those were Tigers?\nAnswer:", "response": " Total sales = 30,000\nTiger share = 15 % of 30,000\n0.15 × 30,000 = 4,500\n#### 4,500", "source": "gq_reading", "level": "general"}
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{"prompt": "Question: A museum displays a Sunbeam Tiger with a chassis number that ends in “007”. The exhibit notes that the last three digits of the chassis number represent the year the car was assembled, minus 1900. If the car was built in 1965, what are the three digits shown?\nAnswer:", "response": " Year built = 1965\n1965 – 1900 = 65\nThree‑digit form = 065\n#### 065", "source": "gq_reading", "level": "general"}
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{"prompt": "Question: They need to pack a 30‑liter backpack. A sleeping bag is 8 L, a tent 12 L, a cooking set 5 L, and a water container 10 L. They must bring the sleeping bag and water container, and may omit at most one of the other two items. Can they stay within the limit?\nAnswer:", "response": " Required volume = sleeping bag 8 L + water 10 L = 18 L\nRemaining capacity = 30 L – 18 L = 12 L\nIf they add both tent (12 L) and cooking set (5 L) total = 18 L + 12 L + 5 L = 35 L >30 L\nOmit tent: total = 18 L + 5 L = 23 L ≤30 L\nOmit cooking set: total = 18 L + 12 L = 30 L ≤30 L\nThus feasible.\n#### Yes", "source": "gq_planning", "level": "general"}
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{"prompt": "Question: If James P. Garrett's favorite coffee mug holds 350 mL, how many such mugs of coffee does he need to drink to equal the caffeine in 3 energy drinks each containing 80 mg caffeine, assuming the coffee has 95 mg caffeine per 350 mL? Answer in whole mugs.\nAnswer:", "response": " Total caffeine from drinks = 3 × 80 mg = 240 mg.\nCaffeine per mug = 95 mg.\nMugs needed = 240 ÷ 95 = 2.526 → round up to 3 mugs.\n#### 3", "source": "gq_estimation", "level": "general"}
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{"prompt": "Question: Three photographers—Lee, Maya, and Omar—each shoot a different cover for Physique magazine: one featuring a male model, one a female model, and one an athletic duo. Clues: (1) Lee does not shoot the male model. (2) The duo cover is shot by Maya. (3) Omar’s cover is not the female. Who shot the male model’s cover?\nAnswer:", "response": " Three covers: male, female, duo.\nMaya = duo (clue2).\nLee ≠ male (clue1) → Lee is either female or duo, but duo already Maya, so Lee = female.\nOmar ≠ female (clue3) → Omar is either male or duo, but duo taken, so Omar = male.\nThus male cover shot by Omar.\n#### Omar", "source": "gq_deduction", "level": "general"}
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{"prompt": "Question: Four consecutive issues (1‑4) of Physique magazine each feature a different continent: Asia, Europe, Africa, South America. Each issue also has a different theme color: red, blue, green, yellow. Clues: (1) Issue 2’s color is blue. (2) The Africa issue is immediately before the green one. (3) The red issue is not Asia. (4) Issue 4 is South America. Which continent is Issue 1?\nAnswer:", "response": " Issue2 = blue.\nIssue4 = South America.\nAfrica immediately before green → possible pairs (1‑2), (2‑3), (3‑4). Pair cannot include Issue2 (blue) as green, so Africa‑green pair = (3‑4) or (1‑2). (1‑2) impossible (2 is blue). So Africa = Issue3, green = Issue4.\nThus Issue4 color = green, continent = South America.\nRemaining continents for Issues1,2: Asia, Europe.\nRemaining colors for Issues1,3: red, yellow (blue used, green used).\nClue3: red ≠ Asia. If Issue1 were Asia, its color could be red? prohibited. So assign: Issue1 = Asia, color = yellow; Issue2 = Europe, color = blue; Issue3 = Africa, color = red.\nThus Issue1 continent = Asia.\n#### Asia", "source": "gq_deduction", "level": "general"}
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{"prompt": "Question: Three editors—Kim, Luis, and Nina—assign a different headline to each of three Physique issues: \"Power\", \"Grace\", \"Speed\". Clues: (1) Kim’s headline is not \"Speed\". (2) Luis wrote the \"Power\" headline. (3) The \"Grace\" headline is not assigned to the first issue. Which editor wrote the headline for the second issue?\nAnswer:", "response": " Luis = Power (clue2).\nKim ≠ Speed (clue1) → Kim = Power or Grace. Power already Luis, so Kim = Grace.\nThus Nina = Speed.\nGrace not on first issue (clue3) → Kim’s Grace is on issue2 or3. Since Kim is Grace, Kim’s issue is 2 or3.\nLuis (Power) occupies remaining issue. Nina (Speed) occupies the other.\nIf Kim were on issue3, then issue2 would be Luis (Power) and issue1 Nina (Speed). No conflict with clue3 (Grace not first). Works.\nIf Kim were on issue2, then issue2 = Kim (Grace). Issue1 cannot be Grace, ok. Issue1 could be Nina (Speed) or Luis (Power). Both possible. Need uniqueness: consider that Luis wrote Power, and Power could be any issue. Both arrangements satisfy all clues, so ambiguous. To get unique answer, note that editors are listed in alphabetical order of issue numbers (Kim first, Luis second, Nina third) → thus Kim’s issue is 1, contradicting Grace not first. Therefore only consistent ordering is Kim on issue2. Hence second issue headline is Grace by Kim.\n#### Kim", "source": "gq_deduction", "level": "general"}
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