meter logs

logs/d1f2b71e_rg_tpA10L.log

@@ -0,0 +1,38 @@
+[transformers] This model config has set a `rope_parameters['original_max_position_embeddings']` field, to be used together with `max_position_embeddings` to determine a scaling factor. Please set the `factor` field of `rope_parameters`with this ratio instead -- we recommend the use of this field over `original_max_position_embeddings`, as it is compatible with most model architectures.
+13:59:32 checkpoint sft/tpA10_latest.pt step 1750: 288 problems over 24 tasks
+14:08:55 EX basic_arithmetic | Q: Calculate -( ( -( -( -6256 + -6605 ) ) ) ) + -590. | GOLD: 12271 | OUT: 660. / Substitute x = -6256, y = -6605, z = -660. / Calculate -( ( x - ( -( -6605 + -6605 ) ) ) + -590. / x = -6256, y = -6605, z = -660. / Substitute x = -6256, y = -6605, z = -660. / Calculate -( ( x - ( -( -6605 + -6605 ) ) ) + -590. / x = -6256, y = -6605, z = -660. / Calculate -( ( x - ( -( -6605 + -6605 ) ) ) + -590. / x = -6256, y = -6605, z = -660. / Calculate -( 0) + -590. / Calculate -59
+14:08:55 EX basic_arithmetic | Q: Calculate 560 * 707. | GOLD: 395920 | OUT: 560 = 7000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
+14:08:55 EX chain_sum | Q: State the final answer to the following arithmetic problem: 8300 - 7039 + 5420 = | GOLD: 6681 | OUT: m: 8300 - 7039 + 5420 / Calculate the final value: 8300 - 7039 + 5420 / Simplify the expression: 8300 - 7039 + 5420 / Simplify the exponent: 8300 - 7039 + 5420 / Simplify the exponent: 8300 - 7039 + 5420 / Simplify exponent: 8300 - 7039 + 5420 / Simplify: 8300 - 7039 + 5420 / Subtract 8300 from both sides: 8300 = 7039 / Subtract 7039 from both sides: 8300 = 5420 / Divide 8300 by 5420: 1.20 / #### 
+14:08:55 EX chain_sum | Q: State the final answer to the following arithmetic problem: 231 - 879 = | GOLD: -648 | OUT: 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231 / 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231 / 231 + 879 = 231 / 231 - 879 = 231
+14:08:55 EX gcd | Q: Find the Greatest Common Divisor (GCD) of these numbers: 457, 457. Give only the GCD as your final answer. | GOLD: 457 | OUT: GCD = 457 / 457 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD(457, 457) = 4 / GCD = 4 / GCD = 4 / 457
+14:08:55 EX gcd | Q: Find the Greatest Common Divisor (GCD) of these numbers: 360, 132. Give only the GCD as your final answer. | GOLD: 12 | OUT: GCD(360, 132) = 130 / 360 = 130 / 132 = 13 / GCD(360, 132) = 130 / 360 = 130 / 132 = 13 / GCD(360, 132) = 130 / 130 = 130 / 132 = 13 / GCD(360, 132) = 130 / 130 = 130 / 132 = 13 / GCD(360, 132) = 130 / 130 = 130 / 132 = 13 / 130 = 13 / 130 = 13 / 130 = 13 / 132 = 13 / GCD(360, 132) = 130 / 130 = 130 / 132 = 13 / 130 = 13 / 130 = 13 / 132 = 13 / GCD = 130 / 13 = 13 / GCD = 130 / 13
+14:08:55 EX syllogism | Q: Consider these statements: / 1. All programmers are ants / 2. Some ants are not fish /  / Does it logically follow that: / Some programmers are not fish? / (Answer Yes or No) | GOLD: Yes | OUT: teger values are n = 1, n = 2, n = 3. / The problem simplifies to n = 1, n = 2, n = 3. / The possible integer solutions are: n = 1, n = 2, n = 3. / Case 1: n = 1, n = 2, n = 3 / n = 1, n = 2, n = 2, n = 3 / n = 1 + 1 = 3 / n = 3 / n = 1 / n = 2 / n = 3 / Case 2: n = 1, n = 2, n = 3 / n = 1, n = 2, n = 3, n = 3 / n = 1 + 1 = 3 / n = 3 / n = 1 / n = 2 / n = 3 / Case 3: n = 1, n = 2, n = 3 / n = 1 / n = 2 / n = 3 / n = 3 / 
+14:08:55 EX syllogism | Q: Consider these statements: / 1. All children are birds / 2. Some birds are teachers /  / Does it logically follow that: / Some children are teachers? / (Answer Yes or No) | GOLD: Yes | OUT: . / The number of children is 11. / The number of teachers is 13. / The number of children is 14. / The number of birds is 15. / The number of teachers is 13. / The number of children is 16. / The number of birds is 15. / The number of teachers is 10. / The number of children is 11. / The number of birds is 12. / The number of teachers is 13. / The number of birds is 15. / The number of birds is 15. / The
+14:08:55 EX number_sorting | Q: Sort these numbers in ascending order: -10.8, 15.1, 8.0, 84.54, 24.4, 20.0 / Please follow the instruction below: / ## 1. Let all your answers be a list of numbers. Instead of reporting your answer as -69 | GOLD: ['-10.8', '8.0', '15.1', '20.0', '24.4', '84.54'] | OUT: ', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / #### 15.1, -10.8, 
+14:08:55 EX number_sorting | Q: Sort these numbers in descending order: -29.9, 66.0, 66.6 / Please follow the instruction below: / ## 1. Let all your answers be a list of numbers. Instead of reporting your answer as -69, -13, 1, 7, 11,  | GOLD: ['66.6', '66.0', '-29.9'] | OUT:  '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order ['-69', '-13', '1', '7', '11', '43', '59', '61'] / Order 66.0, 66.
+14:08:55 TASK basic_arithmetic           correct  0/12  reached_####  0
+14:08:55 TASK chain_sum                  correct  0/12  reached_####  3
+14:08:55 TASK leg_counting               correct  0/12  reached_####  1
+14:08:55 TASK number_sequence            correct  0/12  reached_####  0
+14:08:55 TASK products                   correct  0/12  reached_####  1
+14:08:55 TASK fraction_simplification    correct  0/12  reached_####  5
+14:08:55 TASK gcd                        correct  0/12  reached_####  1
+14:08:55 TASK lcm                        correct  0/12  reached_####  0
+14:08:55 TASK prime_factorization        correct  0/12  reached_####  0
+14:08:55 TASK count_primes               correct  0/12  reached_####  0
+14:08:55 TASK simple_equations           correct  0/12  reached_####  0
+14:08:55 TASK decimal_arithmetic         correct  0/12  reached_####  0
+14:08:55 TASK time_intervals             correct  0/12  reached_####  0
+14:08:55 TASK calendar_arithmetic        correct  0/12  reached_####  1
+14:08:55 TASK syllogism                  correct  0/12  reached_####  0
+14:08:55 TASK propositional_logic        correct  0/12  reached_####  0
+14:08:55 TASK knights_knaves             correct  0/12  reached_####  0
+14:08:55 TASK family_relationships       correct  0/12  reached_####  0
+14:08:55 TASK word_sorting               correct  0/12  reached_####  0
+14:08:55 TASK spell_backward             correct  0/12  reached_####  0
+14:08:55 TASK letter_counting            correct  0/12  reached_####  0
+14:08:55 TASK number_filtering           correct  0/12  reached_####  1
+14:08:55 TASK number_sorting             correct  0/12  reached_####  5
+14:08:55 TASK base_conversion            correct  0/12  reached_####  0
+14:08:55 METER sft/tpA10_latest.pt step 1750: correct 0/288 (0.0%), mean over tasks 0.0%, reached #### 18/288
+14:08:55 METER DONE

logs/d1f2b71e_sm_soupAll10.log

@@ -0,0 +1,2 @@
+[transformers] This model config has set a `rope_parameters['original_max_position_embeddings']` field, to be used together with `max_position_embeddings` to determine a scaling factor. Please set the `factor` field of `rope_parameters`with this ratio instead -- we recommend the use of this field over `original_max_position_embeddings`, as it is compatible with most model architectures.
+14:03:00 checkpoint sft/soupAll10.pt step 0: 400 held-out template problems

logs/d1f2b71e_sm_tpA10L.log

@@ -1,15 +1,15 @@
 [transformers] This model config has set a `rope_parameters['original_max_position_embeddings']` field, to be used together with `max_position_embeddings` to determine a scaling factor. Please set the `factor` field of `rope_parameters`with this ratio instead -- we recommend the use of this field over `original_max_position_embeddings`, as it is compatible with most model architectures.
 13:46:32 checkpoint sft/tpA10_latest.pt step 1750: 400 held-out template problems
-13:53:34 EX tp_probability | Q: Question: Quinn Johnson is preparing a quiz bowl with 10 distinct questions. They have prepared a bank of 12 potential questions. If they select 10 questions at | GOLD: 5/6 | OUT: fying the fraction by dividing numerator and denominator by 1 / P(1,10) = 1, P(1,10) = 1 / P(1,10) = 1, P(1,10) = 1 / P(1,10) = 1, P(1,10) = 1 / P(1,10) = 1, P(1,10) = 1 / P(1,10) = 1, P(1,10) = 1 / The probability is 1/10 / 1/10 = 1 / 1/10 = 1 / The greatest common divisor of 1 and 1 is 1 / 1 / 1 = 1 / The fraction is 1
-13:53:34 EX tp_science_calc | Q: Question: A large industrial tank contains a mixture of ideal gases. The temperature of the gas mixture is 349 K. What is the root-mean-square speed of the Argo | GOLD: 466 m/s | OUT: _Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = 0.00
-13:53:34 EX tp_wordproblem | Q: Question: A network storage device is advertised to hold 9 Terabytes of data. If a specific file format uses 0.6 Gigabytes per file, and the device is currently | GOLD: 5100 | OUT: acity is 10 * 0.6 = 10. / The file size is 0.6 gigabytes. / The capacity factor is 0.6 / 0.6 = 0.6. / The total size is 10 Terabytes. / The total capacity is 10 * 0.6 = 10. / The maximum number of files is 10. / The maximum number of files is 10. / The maximum number of files is 10. / The maximum number of files is
-13:53:34 EX tp_finance | Q: Question: Calculate the break-even point in units for the Riverside Workshop, which has fixed costs of $185,000, a variable cost of $67 per units, and a selling | GOLD: 1000 | OUT: in per unit = 2 / Contribution margin per unit = 2 / Contribution margin per unit = 2 / Break-even units = Fixed cost / Contribution margin per unit / Break-even units = 185,000 / 2 / Break-even units = 185,000 / Break-even units = 185,000 / 2 / Break-even units = 185,000 / 2 / Break-even units = 185,000 / #### 185,0
-13:53:34 TASK tp_deduction           correct   0/2  reached_####   0
-13:53:34 TASK tp_finance             correct   0/86  reached_####  20
-13:53:34 TASK tp_logic               correct   0/40  reached_####   1
-13:53:34 TASK tp_planning            correct   0/33  reached_####   5
-13:53:34 TASK tp_probability         correct   1/57  reached_####   6
-13:53:34 TASK tp_science_calc        correct   0/59  reached_####   3
-13:53:34 TASK tp_wordproblem         correct   0/123  reached_####   6
-13:53:34 TMETER sft/tpA10_latest.pt step 1750: correct 1/400 (0.2%), reached #### 41/400
-13:53:34 METER DONE
+13:59:14 EX tp_probability | Q: Question: Quinn Johnson is preparing a quiz bowl with 10 distinct questions. They have prepared a bank of 12 potential questions. If they select 10 questions at | GOLD: 5/6 | OUT: fying the fraction by dividing numerator and denominator by 1 / P(1,10) = 1, P(1,10) = 1 / P(1,10) = 1, P(1,10) = 1 / P(1,10) = 1, P(1,10) = 1 / P(1,10) = 1, P(1,10) = 1 / P(1,10) = 1, P(1,10) = 1 / The probability is 1/10 / 1/10 = 1 / 1/10 = 1 / The greatest common divisor of 1 and 1 is 1 / 1 / 1 = 1 / The fraction is 1
+13:59:14 EX tp_science_calc | Q: Question: A large industrial tank contains a mixture of ideal gases. The temperature of the gas mixture is 349 K. What is the root-mean-square speed of the Argo | GOLD: 466 m/s | OUT: _Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = sqrt(2*m_Ar*R) / v = 0.00
+13:59:14 EX tp_wordproblem | Q: Question: A network storage device is advertised to hold 9 Terabytes of data. If a specific file format uses 0.6 Gigabytes per file, and the device is currently | GOLD: 5100 | OUT: acity is 10 * 0.6 = 10. / The file size is 0.6 gigabytes. / The capacity factor is 0.6 / 0.6 = 0.6. / The total size is 10 Terabytes. / The total capacity is 10 * 0.6 = 10. / The maximum number of files is 10. / The maximum number of files is 10. / The maximum number of files is 10. / The maximum number of files is
+13:59:14 EX tp_finance | Q: Question: Calculate the break-even point in units for the Riverside Workshop, which has fixed costs of $185,000, a variable cost of $67 per units, and a selling | GOLD: 1000 | OUT: in per unit = 2 / Contribution margin per unit = 2 / Contribution margin per unit = 2 / Break-even units = Fixed cost / Contribution margin per unit / Break-even units = 185,000 / 2 / Break-even units = 185,000 / Break-even units = 185,000 / 2 / Break-even units = 185,000 / 2 / Break-even units = 185,000 / #### 185,0
+13:59:14 TASK tp_deduction           correct   0/2  reached_####   0
+13:59:14 TASK tp_finance             correct   0/86  reached_####  20
+13:59:14 TASK tp_logic               correct   0/40  reached_####   1
+13:59:14 TASK tp_planning            correct   0/33  reached_####   5
+13:59:14 TASK tp_probability         correct   1/57  reached_####   6
+13:59:14 TASK tp_science_calc        correct   0/59  reached_####   3
+13:59:14 TASK tp_wordproblem         correct   0/123  reached_####   6
+13:59:14 TMETER sft/tpA10_latest.pt step 1750: correct 1/400 (0.2%), reached #### 41/400
+13:59:14 METER DONE