meter logs

logs/c13083f2_sm_tpA8L.log

@@ -1,2 +1,15 @@
 [transformers] This model config has set a `rope_parameters['original_max_position_embeddings']` field, to be used together with `max_position_embeddings` to determine a scaling factor. Please set the `factor` field of `rope_parameters`with this ratio instead -- we recommend the use of this field over `original_max_position_embeddings`, as it is compatible with most model architectures.
 13:15:02 checkpoint sft/tpA8_latest.pt step 2000: 400 held-out template problems
+13:23:48 EX tp_probability | Q: Question: Quinn Johnson is preparing a quiz bowl with 10 distinct questions. They have prepared a bank of 12 potential questions. If they select 10 questions at | GOLD: 5/6 | OUT:  10 / GCD of 10 and 12 = 1 / GCD(10, 12) = 1 / 1 / 10 = 1 / Probability = 1 / 10 / GCD(10, 12) = 1 / 1 / 12 = 1 / GCD(10, 12) = 1 / 1 / 12 = 1 / GCD(10, 12) = 1 / 1 / 12 = 1 / Probability = 1 / 10 / GCD(10, 12) = 1 / 1 / 12 = 1 / Probability = 1 / 10 / Simplified fraction = 1 / 10 / Simplify 1 / 10 = 10 / 1 = 10 / Probability = 1/10
+13:23:48 EX tp_science_calc | Q: Question: A large industrial tank contains a mixture of ideal gases. The temperature of the gas mixture is 349 K. What is the root-mean-square speed of the Argo | GOLD: 466 m/s | OUT: ). / Substituting the given values gives v_Ar = sqrt(40.0 / 8.314). / Calculating the square root gives v_Ar = sqrt(40.000 / 8.314). / Simplifying the square root gives v_Ar = sqrt(1.0000000). / Dividing the square root gives v_Ar = sqrt(1.0000000). / Calculating the square root gives v_Ar ≈ 1.0000 m/s. / #### 
+13:23:48 EX tp_wordproblem | Q: Question: A network storage device is advertised to hold 9 Terabytes of data. If a specific file format uses 0.6 Gigabytes per file, and the device is currently | GOLD: 5100 | OUT: .66 0 = 0.66 / 0.6 = 0 / Full capacity = 9 - 0.6 = 16 / Full capacity = 16 / File size = 16 - 0.6 = 0.66 / Files per gig = 0.6 / Total files per gig = 0.6 * 0.6 = 0.6 / Full capacity = 16 / 16 = 16 / Full capacity = 16 / Full size = 16 - 16 = 16 / File size = 0.66 * 0.6 File = 0.66 / Maximum = 0.66 - 0.66 / Maximum = 0.6
+13:23:48 EX tp_finance | Q: Question: Calculate the break-even point in units for the Riverside Workshop, which has fixed costs of $185,000, a variable cost of $67 per units, and a selling | GOLD: 1000 | OUT:  x = 1,000.00 / x = 1,000.00 / x = 1,000.00 / Solving for x gives x = 1,000.00 / 1,000.00 / x = 1,000.00 / Solving for x gives x = 1,000.00 / x = 1,000.00 / Solving for x gives x = 1,000.00 / 25 / x = 1,000.00 / The required units are: / Break-even units = 1,000.00 / Substituting the given values: / x = 1,000.00 / #### 1,000
+13:23:48 TASK tp_deduction           correct   0/2  reached_####   1
+13:23:48 TASK tp_finance             correct   2/86  reached_####  31
+13:23:48 TASK tp_logic               correct   2/40  reached_####  21
+13:23:48 TASK tp_planning            correct   0/33  reached_####  12
+13:23:48 TASK tp_probability         correct   0/57  reached_####  25
+13:23:48 TASK tp_science_calc        correct   0/59  reached_####  13
+13:23:48 TASK tp_wordproblem         correct   0/123  reached_####  41
+13:23:48 TMETER sft/tpA8_latest.pt step 2000: correct 4/400 (1.0%), reached #### 144/400
+13:23:48 METER DONE

logs/c13083f2_sm_tpA9L.log

@@ -0,0 +1,15 @@
+[transformers] This model config has set a `rope_parameters['original_max_position_embeddings']` field, to be used together with `max_position_embeddings` to determine a scaling factor. Please set the `factor` field of `rope_parameters`with this ratio instead -- we recommend the use of this field over `original_max_position_embeddings`, as it is compatible with most model architectures.
+13:24:14 checkpoint sft/tpA9_latest.pt step 2000: 400 held-out template problems
+13:33:00 EX tp_probability | Q: Question: Quinn Johnson is preparing a quiz bowl with 10 distinct questions. They have prepared a bank of 12 potential questions. If they select 10 questions at | GOLD: 5/6 | OUT: 10) / C(12, 10) = 12 / Probability = 12 / 10 / Simplify by dividing numerator and denominator by 10 / 12 / 10 = 12 / 10 / 10 = 1 / GCD of 12 and 10 / (12, 10) = 1 / (12, 10) = 1 / GCD of 1 and 12 / 1 / 12 = 1 / 1 / 12 = 1 / GCD of 12 and 10 / 12 / 10 = 1 / 12 / 10 = 1 / GCD of 12 and 10 / 12 / 10 = 1 / 1 / 10 / 1 / 10 / 1 / 10 / 1 / 10 / 1/
+13:33:00 EX tp_science_calc | Q: Question: A large industrial tank contains a mixture of ideal gases. The temperature of the gas mixture is 349 K. What is the root-mean-square speed of the Argo | GOLD: 466 m/s | OUT: = 349 K / T = 349 K / M_Ar = 40.0 g/mol / R = 8.314 J/(mol*K) / T = 349 K / T = 349 K / T_T = 349 K / T = sqrt(T_T) / T = sqrt(349) / T = sqrt(349) / T = sqrt(349) / T = sqrt(349) / T = sqrt(349) / T = sqrt(349) / T = sqrt(349) / T = sqrt(349) / T_T = sqrt(349) / T = sqrt(349) / T = sqrt(349) / T = sqrt(349) / T = 0.000000 m/s / #### 0.0000
+13:33:00 EX tp_wordproblem | Q: Question: A network storage device is advertised to hold 9 Terabytes of data. If a specific file format uses 0.6 Gigabytes per file, and the device is currently | GOLD: 5100 | OUT: .6 = 0.6 MB / Required file size: 0.6 MB / Required remaining size: 0.6 / 0.6 = 0.6 / Remaining capacity: 0.6 - 0.6 = 0.6 / Required file size: 0.6 MB / Required remaining size: 0.6 / 0.6 = 0.6 / Remaining capacity: 0.6 - 0.6 = 0.6 / Required file size: 0.6 MB / Maximum remaining size: 0.6 / 0.6 = 0.6 / Maximum files
+13:33:00 EX tp_finance | Q: Question: Calculate the break-even point in units for the Riverside Workshop, which has fixed costs of $185,000, a variable cost of $67 per units, and a selling | GOLD: 1000 | OUT: al fixed costs = $185,000 / Contribution margin per unit = $252 / Final fixed costs = $185,000 / Contribution margin per unit = $252 / Break-even units = $185000 / $252 / Break-even units = 5.0000 / Break-even units = 5.0000 / Break-even units = 5.0000 / 5.0000 / Break-even units = 5.0000 / Break-even units = 5.0000 / 
+13:33:00 TASK tp_deduction           correct   0/2  reached_####   1
+13:33:00 TASK tp_finance             correct   1/86  reached_####  28
+13:33:00 TASK tp_logic               correct   1/40  reached_####  15
+13:33:00 TASK tp_planning            correct   1/33  reached_####  10
+13:33:00 TASK tp_probability         correct   0/57  reached_####  19
+13:33:00 TASK tp_science_calc        correct   0/59  reached_####  11
+13:33:00 TASK tp_wordproblem         correct   0/123  reached_####  46
+13:33:00 TMETER sft/tpA9_latest.pt step 2000: correct 3/400 (0.8%), reached #### 130/400
+13:33:00 METER DONE