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Add CodeWalk verus-proof-completion benchmark
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use vstd::prelude::*;
fn main() {}
verus!{
fn f1_split_and_append(list: &Vec<i32>, n: usize) -> (new_list: Vec<i32>)
requires
list@.len() > 0,
0 < n < list@.len(),
{
let mut new_list = Vec::new();
let mut index = n;
while index < list.len()
{
new_list.push(list[index]);
index += 1;
}
let mut index = 0;
while index < n
{
new_list.push(list[index]);
index += 1;
}
new_list
}
fn f2_find_negative_numbers(arr: &Vec<i32>) -> (negative_list: Vec<i32>)
{
let mut negative_list: Vec<i32> = Vec::new();
let input_len = arr.len();
let mut index = 0;
while index < arr.len()
{
if (arr[index] < 0) {
negative_list.push(arr[index]);
}
index += 1;
}
negative_list
}
proof fn f3_lemma_vec_push<T>(vec: Seq<T>, i: T, l: usize)
requires
l == vec.len(),
ensures
forall|k: int| 0 <= k < vec.len() ==> #[trigger] vec[k] == vec.push(i)[k],
vec.push(i).index(l as int) == i,
{
}
fn f3_contains(arr: &Vec<i32>, key: i32) -> (result: bool)
{
let mut index = 0;
while index < arr.len()
{
if (arr[index] == key) {
return true;
}
index += 1;
}
false
}
fn f3_difference(arr1: &Vec<i32>, arr2: &Vec<i32>) -> (result: Vec<i32>)
{
let mut result = Vec::new();
let mut index = 0;
while index < arr1.len()
{
if (!f3_contains(arr2, arr1[index]) && !f3_contains(&result, arr1[index])) {
result.push(arr1[index]);
}
index += 1;
}
index = 0;
while index < arr2.len()
{
if (!f3_contains(arr1, arr2[index]) && !f3_contains(&result, arr2[index])) {
result.push(arr2[index]);
}
index += 1;
}
result
}
spec fn step1(__hp0: Seq<i32>, __hp1: usize, outp: Seq<i32>) -> bool {
(outp == __hp0.subrange(__hp1 as int, __hp0.len() as int).add(__hp0.subrange(0, __hp1 as int)))
}
spec fn step2(inp: Seq<i32>, outp: Seq<i32>) -> bool {
(outp == inp.filter(|x: i32| x < 0))
}
spec fn step3(inp: Seq<i32>, p3_key: i32, outp: bool) -> bool {
(outp == (exists|i: int| 0 <= i < inp.len() && (inp[i] == p3_key)))
}
fn chain_driver(list: &Vec<i32>, n: usize, p3_key: i32) -> (r_final: bool)
requires
list@.len() > 0,
0 < n < list@.len(),
ensures
exists|v1: Seq<i32>, v2: Seq<i32>| #[trigger] step1(list@, n, v1) && #[trigger] step2(v1, v2) && step3(v2, p3_key, r_final),
{
let x1 = f1_split_and_append(list, n);
let x2 = f2_find_negative_numbers(&x1);
let x3 = f3_contains(&x2, p3_key);
proof {
assert(step1(list@, n, x1@));
assert(step2(x1@, x2@));
assert(step3(x2@, p3_key, x3));
}
x3
}
} // verus!