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Migrate legacy reasoning data from model repository

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  1. .gitattributes +4 -0
  2. legacy/processed_40k_repaired_v3/._.gitignore +0 -0
  3. legacy/processed_40k_repaired_v3/._README.md +0 -0
  4. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate1_repaired_v3.audit.json +0 -0
  5. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate1_repaired_v3.jsonl +0 -0
  6. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate1_repaired_v3.manual_review.jsonl +0 -0
  7. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate1_repaired_v3.summary.json +0 -0
  8. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate1_repaired_v3.validation.json +0 -0
  9. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate2_repaired_v3.audit.json +0 -0
  10. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate2_repaired_v3.jsonl +0 -0
  11. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate2_repaired_v3.manual_review.jsonl +0 -0
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  13. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate2_repaired_v3.validation.json +0 -0
  14. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate3_repaired_v3.audit.json +0 -0
  15. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate3_repaired_v3.jsonl +0 -0
  16. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate3_repaired_v3.manual_review.jsonl +0 -0
  17. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate3_repaired_v3.summary.json +0 -0
  18. legacy/processed_40k_repaired_v3/._openmathinstruct2_plans_40k_candidate3_repaired_v3.validation.json +0 -0
  19. legacy/processed_40k_repaired_v3/.gitignore +3 -0
  20. legacy/processed_40k_repaired_v3/README.md +42 -0
  21. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate1_repaired_v3.audit.json +22 -0
  22. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate1_repaired_v3.jsonl +3 -0
  23. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate1_repaired_v3.manual_review.jsonl +6 -0
  24. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate1_repaired_v3.summary.json +41 -0
  25. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate1_repaired_v3.validation.json +127 -0
  26. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate2_repaired_v3.audit.json +26 -0
  27. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate2_repaired_v3.jsonl +3 -0
  28. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate2_repaired_v3.manual_review.jsonl +0 -0
  29. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate2_repaired_v3.summary.json +47 -0
  30. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate2_repaired_v3.validation.json +264 -0
  31. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate3_repaired_v3.audit.json +27 -0
  32. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate3_repaired_v3.jsonl +3 -0
  33. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate3_repaired_v3.manual_review.jsonl +201 -0
  34. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate3_repaired_v3.summary.json +53 -0
  35. legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate3_repaired_v3.validation.json +273 -0
  36. legacy/source_40k/._.gitignore +0 -0
  37. legacy/source_40k/._README.md +0 -0
  38. legacy/source_40k/._openmathinstruct2_plans_40k.jsonl +0 -0
  39. legacy/source_40k/._openmathinstruct2_plans_40k.metadata.json +0 -0
  40. legacy/source_40k/.gitignore +3 -0
  41. legacy/source_40k/README.md +31 -0
  42. legacy/source_40k/openmathinstruct2_plans_40k.jsonl +3 -0
  43. legacy/source_40k/openmathinstruct2_plans_40k.metadata.json +92 -0
.gitattributes CHANGED
@@ -59,3 +59,7 @@ saved_model/**/* filter=lfs diff=lfs merge=lfs -text
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  *.mp4 filter=lfs diff=lfs merge=lfs -text
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  *.webm filter=lfs diff=lfs merge=lfs -text
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  openmathreasoning_questions_ws_v1_20260908/questions.jsonl filter=lfs diff=lfs merge=lfs -text
 
 
 
 
 
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  *.mp4 filter=lfs diff=lfs merge=lfs -text
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  *.webm filter=lfs diff=lfs merge=lfs -text
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  openmathreasoning_questions_ws_v1_20260908/questions.jsonl filter=lfs diff=lfs merge=lfs -text
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+ legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate1_repaired_v3.jsonl filter=lfs diff=lfs merge=lfs -text
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+ legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate2_repaired_v3.jsonl filter=lfs diff=lfs merge=lfs -text
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+ legacy/processed_40k_repaired_v3/openmathinstruct2_plans_40k_candidate3_repaired_v3.jsonl filter=lfs diff=lfs merge=lfs -text
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+ legacy/source_40k/openmathinstruct2_plans_40k.jsonl filter=lfs diff=lfs merge=lfs -text
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legacy/processed_40k_repaired_v3/.gitignore ADDED
@@ -0,0 +1,3 @@
 
 
 
 
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+ # Downloaded production data and sidecars; keep large artifacts out of Git.
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+ *.jsonl
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+ *.json
legacy/processed_40k_repaired_v3/README.md ADDED
@@ -0,0 +1,42 @@
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
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+ # Processed 40k candidate datasets (repaired v3)
2
+
3
+ These are the historical **OpenMathInstruct-2-derived** datasets, not the new
4
+ deduplicated OpenMathReasoning trace collection. They were downloaded from NRP
5
+ (`nautilus`, namespace `wcsng-log`, PVC `reasoning-test`) on 2026-09-11.
6
+ Source files live under `/data/datasets/` with the same basenames as the local files.
7
+ The remote files were not modified. Superseded v1/v2 repairs are not included.
8
+
9
+ Each `openmathinstruct2_plans_40k_candidateN_repaired_v3.jsonl` contains 40,000
10
+ records, including the original generation fields and the derived `repaired_output`
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+ field. Each dataset has `.summary.json`, `.validation.json`, `.audit.json`, and
12
+ `.manual_review.jsonl` sidecars. No rows have been filtered from these downloads.
13
+
14
+ | Candidate | Format | Historically strict-valid rows | Unrecoverable rows |
15
+ |---|---|---:|---:|
16
+ | 1 | One-line plan | 39,999 | 1 |
17
+ | 2 | Summarized working | 39,995 | 5 |
18
+ | 3 | Action-state trajectory | 39,994 | 6 |
19
+
20
+ Structural validity and a successful generation request do not establish
21
+ mathematical correctness or semantic fidelity. Review the repair and validation
22
+ sidecars before selecting training rows.
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+
24
+ ## Frozen content identities
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+
26
+ All three local dataset SHA-256 hashes and byte sizes were verified against the
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+ repository's historical freeze manifest after download on 2026-09-11. Each local
28
+ dataset also has exactly 40,000 lines. The compressed transfer completed normally
29
+ and included all 12 sidecars; structural validation was not rerun during download.
30
+
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+ | Candidate | Bytes | SHA-256 |
32
+ |---|---:|---|
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+ | 1 | 1316722574 | `2043422dd55aa1b506a0ed53bbae232218cf1850d652c2014a7c4fc041da5fbb` |
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+ | 2 | 1387069920 | `152e84f999ed271fa6d54e6aadecdac65d47dbcaef1e99889f9c7a46c65b4e5b` |
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+ | 3 | 1430324162 | `86013a9548a987d964fc1074c570f2c5f5577592bcf1b5b8a4c69d2f74110898` |
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+
37
+ Reference: [historical freeze manifest](../../openmathreasoning/reports/openmath_target_freeze_v1_20260829.json)
38
+ and [repair report](../../openmathreasoning/reports/openmath_repair_v3_20260828.md).
39
+ Those historical reports use OpenMathReasoning terminology in places; the actual
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+ dataset provenance here is OpenMathInstruct-2.
41
+
42
+ The downloaded JSON/JSONL artifacts are ignored by the directory's `.gitignore`.
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+ "output_preview": "<plan>\n1. **Determine Configuration:** Identify the minimal circular arrangement satisfying the constraints.\nLet $N$ be the total number of lily pads and $L$ be the distance between adjacent flowers. Flowers are at $0, L, 2L$.\nA pad is \"not adjacent\" to a flower if its distance to the nearest flower is $\\ge 2$.\nIn the segment between flowers $0$ and $L$, the pads are $1, \\dots, L-1$.\nPad $1$ is adjacent to $0$; pad $L-1$ is adjacent to $L$.\nFor a non-adjacent pad to exist, we need an index $k$ s"
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+ {
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+ "line_number": 25279,
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+ "id": "omi2-train_1M-0025129",
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+ "output_preview": "<plan>\n1. **MODEL GENERATION:** Define $S$ via operations $L(n)=2n+1$ and $R(n)=3n+1$ starting from $1$.\n$S$ is the set of all numbers reachable from $1$ by applying sequences of $L$ and $R$.\nSince $L(n) > n$ and $R(n) > n$ for $n \\ge 1$, the generation process is acyclic and values strictly increase.\nWe seek $|S \\cap \\{1, 2, \\dots, 1023\\}|$.\n\n2. **EXECUTE BFS LAYER 0-1:** Generate initial elements.\nLevel 0: $\\{1\\}$.\nLevel 1: $L(1)=3, R(1)=4$. Set $S_1 = \\{1, 3, 4\\}$. Count: 3.\n\n3. **EXECUTE BFS"
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+ "output_preview": "<plan>\n1. **Define Variables and Probability Model:**\nLet $n$ be the total number of boxes and $r$ be the number of boxes containing red crayons. The number of blue boxes is $n-r$. The probability of selecting one red and one blue box from $n$ boxes is $P = \\frac{r(n-r)}{\\binom{n}{2}}$.\n\n2. **Test Given Parameters ($n=10$):**\nSubstitute $n=10$ and $P=\\frac{15}{34}$ into the model:\n$$ \\frac{r(10-r)}{\\binom{10}{2}} = \\frac{15}{34} \\implies \\frac{10r - r^2}{45} = \\frac{15}{34} $$\n$$ 34(10r - r^2) ="
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+ "id": "omi2-train_1M-0509157",
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+ "line_number": 11467,
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+ "output_preview": "<plan>\n1. **Determine Configuration:** Identify the minimal circular arrangement satisfying the constraints.\nLet $N$ be the total number of lily pads and $L$ be the distance between adjacent flowers. Flowers are at $0, L, 2L$.\nA pad is \"not adjacent\" to a flower if its distance to the nearest flower is $\\ge 2$.\nIn the segment between flowers $0$ and $L$, the pads are $1, \\dots, L-1$.\nPad $1$ is adjacent to $0$; pad $L-1$ is adjacent to $L$.\nFor a non-adjacent pad to exist, we need an index $k$ s"
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+ {
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+ "line_number": 25279,
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+ "id": "omi2-train_1M-0025129",
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+ "output_preview": "<plan>\n1. **MODEL GENERATION:** Define $S$ via operations $L(n)=2n+1$ and $R(n)=3n+1$ starting from $1$.\n$S$ is the set of all numbers reachable from $1$ by applying sequences of $L$ and $R$.\nSince $L(n) > n$ and $R(n) > n$ for $n \\ge 1$, the generation process is acyclic and values strictly increase.\nWe seek $|S \\cap \\{1, 2, \\dots, 1023\\}|$.\n\n2. **EXECUTE BFS LAYER 0-1:** Generate initial elements.\nLevel 0: $\\{1\\}$.\nLevel 1: $L(1)=3, R(1)=4$. Set $S_1 = \\{1, 3, 4\\}$. Count: 3.\n\n3. **EXECUTE BFS"
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+ "line_number": 25665,
66
+ "id": "omi2-train_1M-0025665",
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+ "output_preview": "<plan>\n1. **Define Variables and Probability Model:**\nLet $n$ be the total number of boxes and $r$ be the number of boxes containing red crayons. The number of blue boxes is $n-r$. The probability of selecting one red and one blue box from $n$ boxes is $P = \\frac{r(n-r)}{\\binom{n}{2}}$.\n\n2. **Test Given Parameters ($n=10$):**\nSubstitute $n=10$ and $P=\\frac{15}{34}$ into the model:\n$$ \\frac{r(10-r)}{\\binom{10}{2}} = \\frac{15}{34} \\implies \\frac{10r - r^2}{45} = \\frac{15}{34} $$\n$$ 34(10r - r^2) ="
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69
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70
+ "line_number": 35161,
71
+ "id": "omi2-train_1M-0509157",
72
+ "output_preview": "<plan>\n1. **Factor and Analyze Domain:**\nFactor $f(x) = \\frac{(x-5)(x+3)}{(x+2)(x-1)}$. The domain of $f$ is $\\mathbb{R} \\setminus \\{-2, 1\\}$. For $f(f(x))$ to be defined, we require $x \\in \\text{dom}(f)$ and $f(x) \\in \\text{dom}(f)$, i.e., $f(x) \\neq -2$ and $f(x) \\neq 1$.\n\n<latent>\n2. **Solve Outer Inequality:**\nLet $y = f(x)$. Solve $f(y) > 0 \\iff \\frac{(y-5)(y+3)}{(y+2)(y-1)} > 0$.\nCritical points for $y$ are $-3, -2, 1, 5$. Sign analysis yields the solution set for $y$:\n$S_y = (-\\infty, -3)"
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+ "output_preview": "<plan>\n1. **Identify integer range:** The range of $\\cos(x)$ is $[-1, 1]$, so $\\cos(n\\pi/2)$ is an integer if and only if $\\cos(n\\pi/2) \\in \\{-1, 0, 1\\}$.\n<latent>\n2. **Evaluate for smallest $n$:$ The smallest positive integer is $n=1$. Substituting $n=1$ gives $\\cos(\\pi/2) = 0$.\n<latent>\n3. **Verify condition:** Since $0 \\in \\{-1, 0, 1\\}$, the condition is satisfied for $n=1$.\n</plan>"
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+ "output_preview": "<plan>\n1. **Identify integer range:** The range of $\\cos(x)$ is $[-1, 1]$, so $\\cos(n\\pi/2)$ is an integer if and only if $\\cos(n\\pi/2) \\in \\{-1, 0, 1\\}$.\n<latent>\n2. **Evaluate for smallest $n$:$ The smallest positive integer is $n=1$. Substituting $n=1$ gives $\\cos(\\pi/2) = 0$.\n<latent>\n3. **Verify condition:** Since $0 \\in \\{-1, 0, 1\\}$, the condition is satisfied for $n=1$.\n</plan>"
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89
+ "line_number": 25665,
90
+ "id": "omi2-train_1M-0025665",
91
+ "output_preview": "<plan>\n1. **Define Variables and Probability Model:**\nLet $n$ be the total number of boxes and $r$ be the number of boxes containing red crayons. The number of blue boxes is $n-r$. The probability of selecting one red and one blue box from $n$ boxes is $P = \\frac{r(n-r)}{\\binom{n}{2}}$.\n\n2. **Test Given Parameters ($n=10$):**\nSubstitute $n=10$ and $P=\\frac{15}{34}$ into the model:\n$$ \\frac{r(10-r)}{\\binom{10}{2}} = \\frac{15}{34} \\implies \\frac{10r - r^2}{45} = \\frac{15}{34} $$\n$$ 34(10r - r^2) ="
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95
+ "id": "omi2-train_1M-0509157",
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+ "output_preview": "<plan>\n1. **Identify integer range:** The range of $\\cos(x)$ is $[-1, 1]$, so $\\cos(n\\pi/2)$ is an integer if and only if $\\cos(n\\pi/2) \\in \\{-1, 0, 1\\}$.\n<latent>\n2. **Evaluate for smallest $n$:$ The smallest positive integer is $n=1$. Substituting $n=1$ gives $\\cos(\\pi/2) = 0$.\n<latent>\n3. **Verify condition:** Since $0 \\in \\{-1, 0, 1\\}$, the condition is satisfied for $n=1$.\n</plan>"
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107
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108
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120
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121
+ "output_preview": "<plan>\n1. **Determine Configuration:** Identify the minimal circular arrangement satisfying the constraints.\nLet $N$ be the total number of lily pads and $L$ be the distance between adjacent flowers. Flowers are at $0, L, 2L$.\nA pad is \"not adjacent\" to a flower if its distance to the nearest flower is $\\ge 2$.\nIn the segment between flowers $0$ and $L$, the pads are $1, \\dots, L-1$.\nPad $1$ is adjacent to $0$; pad $L-1$ is adjacent to $L$.\nFor a non-adjacent pad to exist, we need an index $k$ s"
122
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123
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124
+ "line_number": 25279,
125
+ "id": "omi2-train_1M-0025129",
126
+ "output_preview": "<plan>\n1. **MODEL GENERATION:** Define $S$ via operations $L(n)=2n+1$ and $R(n)=3n+1$ starting from $1$.\n$S$ is the set of all numbers reachable from $1$ by applying sequences of $L$ and $R$.\nSince $L(n) > n$ and $R(n) > n$ for $n \\ge 1$, the generation process is acyclic and values strictly increase.\nWe seek $|S \\cap \\{1, 2, \\dots, 1023\\}|$.\n\n2. **EXECUTE BFS LAYER 0-1:** Generate initial elements.\nLevel 0: $\\{1\\}$.\nLevel 1: $L(1)=3, R(1)=4$. Set $S_1 = \\{1, 3, 4\\}$. Count: 3.\n\n3. **EXECUTE BFS"
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129
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130
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131
+ "output_preview": "<plan>\n1. **Define Variables and Probability Model:**\nLet $n$ be the total number of boxes and $r$ be the number of boxes containing red crayons. The number of blue boxes is $n-r$. The probability of selecting one red and one blue box from $n$ boxes is $P = \\frac{r(n-r)}{\\binom{n}{2}}$.\n\n2. **Test Given Parameters ($n=10$):**\nSubstitute $n=10$ and $P=\\frac{15}{34}$ into the model:\n$$ \\frac{r(10-r)}{\\binom{10}{2}} = \\frac{15}{34} \\implies \\frac{10r - r^2}{45} = \\frac{15}{34} $$\n$$ 34(10r - r^2) ="
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135
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+ "output_preview": "<plan>\n1. **Identify integer range:** The range of $\\cos(x)$ is $[-1, 1]$, so $\\cos(n\\pi/2)$ is an integer if and only if $\\cos(n\\pi/2) \\in \\{-1, 0, 1\\}$.\n<latent>\n2. **Evaluate for smallest $n$:$ The smallest positive integer is $n=1$. Substituting $n=1$ gives $\\cos(\\pi/2) = 0$.\n<latent>\n3. **Verify condition:** Since $0 \\in \\{-1, 0, 1\\}$, the condition is satisfied for $n=1$.\n</plan>"
144
+ },
145
+ {
146
+ "line_number": 25665,
147
+ "id": "omi2-train_1M-0025665",
148
+ "output_preview": "<plan>\n1. **Define Variables and Probability Model:**\nLet $n$ be the total number of boxes and $r$ be the number of boxes containing red crayons. The number of blue boxes is $n-r$. The probability of selecting one red and one blue box from $n$ boxes is $P = \\frac{r(n-r)}{\\binom{n}{2}}$.\n\n2. **Test Given Parameters ($n=10$):**\nSubstitute $n=10$ and $P=\\frac{15}{34}$ into the model:\n$$ \\frac{r(10-r)}{\\binom{10}{2}} = \\frac{15}{34} \\implies \\frac{10r - r^2}{45} = \\frac{15}{34} $$\n$$ 34(10r - r^2) ="
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+ {
165
+ "line_number": 11467,
166
+ "id": "omi2-train_1M-0011450",
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+ "output_preview": "<plan>\n1. **Determine Configuration:** Identify the minimal circular arrangement satisfying the constraints.\nLet $N$ be the total number of lily pads and $L$ be the distance between adjacent flowers. Flowers are at $0, L, 2L$.\nA pad is \"not adjacent\" to a flower if its distance to the nearest flower is $\\ge 2$.\nIn the segment between flowers $0$ and $L$, the pads are $1, \\dots, L-1$.\nPad $1$ is adjacent to $0$; pad $L-1$ is adjacent to $L$.\nFor a non-adjacent pad to exist, we need an index $k$ s"
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+ {
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+ "line_number": 25279,
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+ "id": "omi2-train_1M-0025129",
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+ "output_preview": "<plan>\n1. **MODEL GENERATION:** Define $S$ via operations $L(n)=2n+1$ and $R(n)=3n+1$ starting from $1$.\n$S$ is the set of all numbers reachable from $1$ by applying sequences of $L$ and $R$.\nSince $L(n) > n$ and $R(n) > n$ for $n \\ge 1$, the generation process is acyclic and values strictly increase.\nWe seek $|S \\cap \\{1, 2, \\dots, 1023\\}|$.\n\n2. **EXECUTE BFS LAYER 0-1:** Generate initial elements.\nLevel 0: $\\{1\\}$.\nLevel 1: $L(1)=3, R(1)=4$. Set $S_1 = \\{1, 3, 4\\}$. Count: 3.\n\n3. **EXECUTE BFS"
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+ {
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+ "line_number": 25665,
176
+ "id": "omi2-train_1M-0025665",
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+ "output_preview": "<plan>\n1. **Define Variables and Probability Model:**\nLet $n$ be the total number of boxes and $r$ be the number of boxes containing red crayons. The number of blue boxes is $n-r$. The probability of selecting one red and one blue box from $n$ boxes is $P = \\frac{r(n-r)}{\\binom{n}{2}}$.\n\n2. **Test Given Parameters ($n=10$):**\nSubstitute $n=10$ and $P=\\frac{15}{34}$ into the model:\n$$ \\frac{r(10-r)}{\\binom{10}{2}} = \\frac{15}{34} \\implies \\frac{10r - r^2}{45} = \\frac{15}{34} $$\n$$ 34(10r - r^2) ="
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+ },
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+ {
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+ "line_number": 35161,
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+ "id": "omi2-train_1M-0509157",
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+ "output_preview": "<plan>\n1. **Factor and Analyze Domain:**\nFactor $f(x) = \\frac{(x-5)(x+3)}{(x+2)(x-1)}$. The domain of $f$ is $\\mathbb{R} \\setminus \\{-2, 1\\}$. For $f(f(x))$ to be defined, we require $x \\in \\text{dom}(f)$ and $f(x) \\in \\text{dom}(f)$, i.e., $f(x) \\neq -2$ and $f(x) \\neq 1$.\n\n<latent>\n2. **Solve Outer Inequality:**\nLet $y = f(x)$. Solve $f(y) > 0 \\iff \\frac{(y-5)(y+3)}{(y+2)(y-1)} > 0$.\nCritical points for $y$ are $-3, -2, 1, 5$. Sign analysis yields the solution set for $y$:\n$S_y = (-\\infty, -3)"
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+ "line_number": 18503,
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+ *.jsonl
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+ *.json
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+ # Original 40k source records before candidate rewriting
2
+
3
+ Downloaded on 2026-09-11 from the NRP `nautilus` context, namespace `wcsng-log`,
4
+ PVC `reasoning-test`. Remote source files were not modified:
5
+
6
+ - `/data/datasets/openmathinstruct2_plans_40k.jsonl`
7
+ - `/data/datasets/openmathinstruct2_plans_40k.metadata.json`
8
+
9
+ This is the historical **OpenMathInstruct-2-derived** 40k source snapshot used
10
+ before rewriting into Candidates 1/2/3, not the ongoing OpenMathReasoning collection.
11
+ It contains the original problems/user prompts, reference answers, original model
12
+ responses, extracted plan blocks, source indices and generation provenance.
13
+ It is not merely a questions-only file, and no candidate rewrites are added here.
14
+
15
+ The metadata records 26,000 selected source records from the first collector and
16
+ 14,000 from the second. Selection required transport success and a parseable initial
17
+ plan; it does not establish mathematical correctness. The metadata reports 613
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+ source responses with a length-limit finish reason; no additional filtering was
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+ applied to this download.
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+
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+ ## Download verification
22
+
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+ The local JSONL has exactly 40,000 lines and 1,378,472,461 bytes. Both local SHA-256
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+ hashes match hashes computed directly on NRP at download time; the JSONL hash also
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+
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+ Downloaded JSON/JSONL files are Git-ignored. The candidate datasets are in the
31
+ adjacent `processed_40k_repaired_v3/` directory.
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