Datasets:

PureOne
/

Evies-Pure-Form-RSI

"""Resource-accounted recursive verifier purification; no hardware claims.
The exact signal verifier is a q-ary symmetric channel. Two independent child
outputs are accepted when they agree; otherwise the pair is retried. The code
compares closed recursion against an independent absorbing Markov chain over
the recursive program's pending-symbol stack. A gate's saved acquisition cost
can fund stronger exported E_q(t,u) experiments at fixed expected cost.
The binary hierarchy is a classical SPRT realization. These calculations do
not establish a new sequential-testing principle or general intelligence RSI.
"""

from __future__ import annotations

import argparse
import itertools
import json
import math
from pathlib import Path

import numpy as np
from scipy.optimize import linprog


def _validate(q: int, u: float, level: int = 0, m: int = 2) -> None:
    if int(q) != q or q < 2:
        raise ValueError("q must be an integer >= 2")
    if not math.isfinite(u) or not 0 <= u <= 1:
        raise ValueError("u must be in [0,1]")
    if int(level) != level or level < 0:
        raise ValueError("level must be a nonnegative integer")
    if int(m) != m or m < 2:
        raise ValueError("m must be an integer >= 2")


def pure_level(q: int, u: float, level: int, m: int = 2) -> dict:
    """Closed distribution and expected raw SIGNAL calls for one level.
    Calls at each recursion node are independent conditional on the same
    hidden target. The recursion's depth is not its computational cost.
    """
    _validate(q, u, level, m)
    d = q - 1
    initial = u
    raw_calls = 1.0
    acceptance = []
    for _ in range(level):
        p = (1 + d * u) / q
        r = (1 - u) / q
        s = p ** m + d * r ** m
        acceptance.append(s)
        raw_calls *= m / s
        u = (p ** m - r ** m) / s
    # Use odds independently of the preceding contrast recursion to retain
    # very small errors and identify floating-point saturation explicitly.
    if initial == 1:
        log_error = None
        error = 0.0
    else:
        log_x = math.log((1 - initial) / (1 + d * initial))
        log_y = m ** level * log_x
        y = math.exp(log_y)
        log_error = math.log(d) + log_y - math.log1p(d * y)
        error = math.exp(log_error)
    contrast_from_odds = 1 - q * error / d
    return {
        "level": level,
        "m": m,
        "q": q,
        "initial_contrast": initial,
        "contrast": contrast_from_odds,
        "contrast_recursion": u,
        "accepted_signal_correct_probability": 1 - error,
        "accepted_signal_error_probability": error,
        "log_accepted_signal_error_probability": log_error,
        "contrast_rounded_to_one": contrast_from_odds == 1 and initial < 1,
        "expected_raw_signal_calls": raw_calls,
        "node_acceptance_probabilities": acceptance,
        "scope": "independent repeated signals of ONE fixed target",
    }


def stack_chain(q: int, u: float, level: int) -> dict:
    """Independent absorbing-chain computation for the actual binary tree.
    Each stack slot is empty (-1) or holds one pending child symbol. One raw
    signal is fed at the bottom. Agreeing pairs ripple upward; mismatches
    clear their slot and restart there. The transition matrix is constructed
    from raw symbols without using the closed purification or cost formula.
    """
    _validate(q, u, level)
    if level == 0:
        probs = np.full(q, (1 - u) / q)
        probs[0] += u
        return {"expected_raw_signal_calls": 1.0,
                "output_probabilities_given_target_zero": probs.tolist(),
                "transient_states": 0, "linear_residual": 0.0}
    states = list(itertools.product(range(-1, q), repeat=level))
    lookup = {state: index for index, state in enumerate(states)}
    nstates = len(states)
    transition = np.zeros((nstates, nstates))
    absorb = np.zeros((nstates, q))
    raw = np.full(q, (1 - u) / q)
    raw[0] += u
    for row, state in enumerate(states):
        for symbol, probability in enumerate(raw):
            if probability == 0:
                continue
            next_state = list(state)
            absorbed = True
            for slot in range(level):
                if next_state[slot] == -1:
                    next_state[slot] = symbol
                    absorbed = False
                    break
                if next_state[slot] == symbol:
                    next_state[slot] = -1
                    continue
                next_state[slot] = -1
                absorbed = False
                break
            if absorbed:
                absorb[row, symbol] += probability
            else:
                transition[row, lookup[tuple(next_state)]] += probability
    matrix = np.eye(nstates) - transition
    rhs = np.column_stack((np.ones(nstates), absorb))
    solution = np.linalg.solve(matrix, rhs)
    origin = lookup[(-1,) * level]
    return {
        "expected_raw_signal_calls": float(solution[origin, 0]),
        "output_probabilities_given_target_zero": solution[origin, 1:].tolist(),
        "transient_states": nstates,
        "linear_residual": float(np.max(np.abs(matrix @ solution - rhs))),
        "transition_row_sum_error": float(np.max(np.abs(
            transition.sum(axis=1) + absorb.sum(axis=1) - 1))),
    }


def exported_levels(q: int, u: float, t: float, overhead: float,
                    readout_cost: float = 1.0, max_level: int = 3) -> list[dict]:
    """Same outer retention t at every level; costs include all retries.
    overhead h must cover ALL nonreadout per-primitive-trial costs. An outer
    target-independent Bernoulli(t) requests a signal only on nonerasure.
    A raw accepted signal costs (h+tE)/t in expectation. Hence unconditional
    exported cost equals (h+tE)*expected_raw_signal_calls; t cancels.
    """
    if not 0 < t <= 1 or overhead < 0 or readout_cost <= 0:
        raise ValueError("Require 0<t<=1, h>=0, E>0")
    cg = overhead + t * readout_cost
    rows = []
    for k in range(max_level + 1):
        row = pure_level(q, u, k)
        row["outer_retention"] = t
        row["expected_logical_cost"] = cg * row["expected_raw_signal_calls"]
        row["uniform_prior_full_call_MAP_error"] = (
            (q - 1) / q * (1 - t * row["contrast"]))
        rows.append(row)
    return rows


def upper_concave_hull(levels: list[dict]) -> list[dict]:
    """Upper hull of (expected_cost,contrast), restricted to supplied levels."""
    points = sorted(levels, key=lambda row: row["expected_logical_cost"])
    hull = []
    for row in points:
        x, y = row["expected_logical_cost"], row["contrast"]
        if hull and x == hull[-1]["expected_logical_cost"]:
            if y <= hull[-1]["contrast"]:
                continue
            hull.pop()
        while len(hull) >= 2:
            a, b = hull[-2:]
            # Upper concavity requires nonincreasing consecutive slopes.
            cross = ((b["expected_logical_cost"] - a["expected_logical_cost"])
                     * (y - b["contrast"])
                     - (b["contrast"] - a["contrast"])
                     * (x - b["expected_logical_cost"]))
            if cross < 0:
                break
            hull.pop()
        hull.append(row)
    return hull


def budget_mixture(levels: list[dict], budget: float) -> dict:
    """Optimal contrast at budget among mixtures of the supplied levels.
    This is a finite-family optimum. It is not optimal over all possible
    sequential/posterior confidence acquisition programs.
    """
    hull = upper_concave_hull(levels)
    if not hull or budget < hull[0]["expected_logical_cost"]:
        raise ValueError("Budget cannot fund even the least costly supplied level")
    left = right = hull[-1]
    weight_right = 0.0
    for a, b in zip(hull, hull[1:]):
        if budget <= b["expected_logical_cost"]:
            left, right = a, b
            weight_right = ((budget - a["expected_logical_cost"])
                            / (b["expected_logical_cost"]
                               - a["expected_logical_cost"]))
            break
    contrast = (1 - weight_right) * left["contrast"] + weight_right * right["contrast"]
    cost = ((1 - weight_right) * left["expected_logical_cost"]
            + weight_right * right["expected_logical_cost"])
    q, t = left["q"], left["outer_retention"]
    error = (q - 1) / q * (1 - contrast)
    initial = left["initial_contrast"]
    original_error = (q - 1) / q * (1 - initial)
    return {
        "family": "finite-level recursive unanimous signal verifiers",
        "hull_levels": [row["level"] for row in hull],
        "left_level": left["level"],
        "right_level": right["level"],
        "right_probability": weight_right,
        "budget": budget,
        "expected_logical_cost": cost,
        "unused_budget": max(0.0, budget - cost),
        "contrast": contrast,
        "outer_retention": t,
        "accepted_signal_error_probability": error,
        "accepted_error_relative_reduction": (original_error - error) / original_error
        if original_error > 0 else 0.0,
        "original_uniform_prior_full_call_MAP_error": (q - 1) / q * (1 - t * initial),
        "uniform_prior_full_call_MAP_error": (q - 1) / q * (1 - t * contrast),
        "old_to_new_deficiency": (q - 1) / q * t * (contrast - initial),
        "new_to_old_deficiency": 0.0,
        "claims": "same outer retention and expected cost; not constant latency; not hardware evidence",
    }


def _independent_checks() -> dict:
    records = []
    max_cost_relative_error = max_prob_error = max_linear_residual = 0.0
    cases = [(q, u, k) for q in (2, 3, 5) for u in (0.2, 0.6, 0.9) for k in (1, 2)]
    cases += [(q, 0.6, 3) for q in (2, 3, 5)]
    for q, u, k in cases:
        closed = pure_level(q, u, k)
        chain = stack_chain(q, u, k)
        expected = np.full(q, closed["accepted_signal_error_probability"] / (q - 1))
        expected[0] = closed["accepted_signal_correct_probability"]
        cost_error = abs(chain["expected_raw_signal_calls"]
                         - closed["expected_raw_signal_calls"]) / closed["expected_raw_signal_calls"]
        probability_error = float(np.max(np.abs(np.asarray(
            chain["output_probabilities_given_target_zero"]) - expected)))
        max_cost_relative_error = max(max_cost_relative_error, cost_error)
        max_prob_error = max(max_prob_error, probability_error)
        max_linear_residual = max(max_linear_residual, chain["linear_residual"])
        records.append({"q": q, "u": u, "level": k,
                        "relative_expected_cost_error": cost_error,
                        "max_output_probability_error": probability_error,
                        "independent_absorbing_chain": chain})
    binary_error = 0.0
    for u, k in itertools.product((.1, .2, .6, .9), range(5)):
        row = pure_level(2, u, k)
        n = 2 ** k
        v = math.tanh(n * math.atanh(u))
        expected_cost = n * v / u
        binary_error = max(binary_error, abs(row["contrast"] - v),
                           abs(row["expected_raw_signal_calls"] - expected_cost) / expected_cost)
    passed = max(max_cost_relative_error, max_prob_error, max_linear_residual,
                 binary_error) < 1e-9
    return {"status": "PASS" if passed else "FAIL", "cases": len(cases),
            "method": "full raw-symbol absorbing Markov chain on recursive pending stack",
            "max_relative_cost_error": max_cost_relative_error,
            "max_output_probability_error": max_prob_error,
            "max_linear_system_residual": max_linear_residual,
            "binary_SPRT_identity_checks": 20,
            "max_binary_identity_error": binary_error, "records": records}


def _hull_lp_checks() -> dict:
    """Independent unrestricted mixture LP, with no hull assumptions."""
    records = []
    max_error = 0.0
    for q, u, t, h in ((2, .55, .25, .1), (3, .4, 1 / 9, .1),
                       (5, .6, .04, .1)):
        levels = exported_levels(q, u, t, h, max_level=3)
        costs = np.asarray([row["expected_logical_cost"] for row in levels])
        contrasts = np.asarray([row["contrast"] for row in levels])
        for budget in np.linspace(costs[0], costs[-1], 9):
            answer = budget_mixture(levels, float(budget))
            lp = linprog(-contrasts, A_ub=costs[None, :],
                         b_ub=[budget], A_eq=np.ones((1, len(levels))),
                         b_eq=[1.0], bounds=[(0, None)] * len(levels),
                         method="highs")
            if not lp.success:
                raise RuntimeError(lp.message)
            error = abs(answer["contrast"] + lp.fun)
            max_error = max(max_error, error)
            records.append({"q": q, "u": u, "budget": float(budget),
                            "hull_contrast": answer["contrast"],
                            "unrestricted_mixture_LP_contrast": float(-lp.fun),
                            "absolute_error": error})
    return {"status": "PASS" if max_error < 1e-9 else "FAIL",
            "cases": len(records), "max_contrast_error": max_error,
            "scope": "all mixtures of supplied finite levels, not all sequential programs",
            "records": records}


def run() -> dict:
    checks = _independent_checks()
    hull_checks = _hull_lp_checks()
    levels = exported_levels(5, .6, .04, .1, max_level=3)
    mixture = budget_mixture(levels, 1.1)
    old_map = mixture["original_uniform_prior_full_call_MAP_error"]
    new_map = mixture["uniform_prior_full_call_MAP_error"]
    mixture["full_call_MAP_error_absolute_reduction"] = old_map - new_map
    mixture["full_call_MAP_error_relative_reduction"] = (old_map - new_map) / old_map
    return {
        "status": "PASS" if checks["status"] == hull_checks["status"] == "PASS" else "FAIL",
        "research": "Evie's Pure Form RSI",
        "scope": "mathematical verifier-strengthening component under explicit conditional-independent channels",
        "physical_measurements": False,
        "general_intelligence_gain_established": False,
        "prior_art_boundary": "binary hierarchy equals classical SPRT; neither consensus nor sequential testing is claimed as invention",
        "cost_contract": "h includes every nonreadout cost per primitive trial; E is acquisition cost; expected cost, unbounded retry tails",
        "independent_checks": checks,
        "finite_mixture_LP_checks": hull_checks,
        "q5_example": {
            "q": 5, "base_retention": .04, "base_contrast": .6,
            "overhead_h_over_E": .1, "readout_E": 1.0,
            "ungated_expected_cost": 1.1,
            "gated_primitive_expected_cost": .14,
            "gate_saving_ratio": 1.1 / .14,
            "levels": levels, "fixed_budget_mixture": mixture,
        },
    }


if __name__ == "__main__":
    parser = argparse.ArgumentParser(description=__doc__)
    parser.add_argument("--output", default=str(Path(__file__).resolve().parent / "data" / "bootstrap.json"))
    args = parser.parse_args()
    report = run()
    path = Path(args.output)
    path.parent.mkdir(parents=True, exist_ok=True)
    path.write_text(json.dumps(report, indent=2) + "\n", encoding="utf-8")
    print(json.dumps({"status": report["status"],
                      "independent_checks": {k: v for k, v in report["independent_checks"].items() if k != "records"},
                      "fixed_budget_mixture": report["q5_example"]["fixed_budget_mixture"]}, indent=2))
    raise SystemExit(0 if report["status"] == "PASS" else 1)

	"""Resource-accounted recursive verifier purification; no hardware claims.

	The exact signal verifier is a q-ary symmetric channel. Two independent child
	outputs are accepted when they agree; otherwise the pair is retried. The code
	compares closed recursion against an independent absorbing Markov chain over
	the recursive program's pending-symbol stack. A gate's saved acquisition cost
	can fund stronger exported E_q(t,u) experiments at fixed expected cost.

	The binary hierarchy is a classical SPRT realization. These calculations do
	not establish a new sequential-testing principle or general intelligence RSI.
	"""

	from __future__ import annotations

	import argparse
	import itertools
	import json
	import math
	from pathlib import Path

	import numpy as np
	from scipy.optimize import linprog


	def _validate(q: int, u: float, level: int = 0, m: int = 2) -> None:
	if int(q) != q or q < 2:
	raise ValueError("q must be an integer >= 2")
	if not math.isfinite(u) or not 0 <= u <= 1:
	raise ValueError("u must be in [0,1]")
	if int(level) != level or level < 0:
	raise ValueError("level must be a nonnegative integer")
	if int(m) != m or m < 2:
	raise ValueError("m must be an integer >= 2")


	def pure_level(q: int, u: float, level: int, m: int = 2) -> dict:
	"""Closed distribution and expected raw SIGNAL calls for one level.

	Calls at each recursion node are independent conditional on the same
	hidden target. The recursion's depth is not its computational cost.
	"""
	_validate(q, u, level, m)
	d = q - 1
	initial = u
	raw_calls = 1.0
	acceptance = []
	for _ in range(level):
	p = (1 + d * u) / q
	r = (1 - u) / q
	s = p ** m + d * r ** m
	acceptance.append(s)
	raw_calls *= m / s
	u = (p m - r m) / s
	# Use odds independently of the preceding contrast recursion to retain
	# very small errors and identify floating-point saturation explicitly.
	if initial == 1:
	log_error = None
	error = 0.0
	else:
	log_x = math.log((1 - initial) / (1 + d * initial))
	log_y = m ** level * log_x
	y = math.exp(log_y)
	log_error = math.log(d) + log_y - math.log1p(d * y)
	error = math.exp(log_error)
	contrast_from_odds = 1 - q * error / d
	return {
	"level": level,
	"m": m,
	"q": q,
	"initial_contrast": initial,
	"contrast": contrast_from_odds,
	"contrast_recursion": u,
	"accepted_signal_correct_probability": 1 - error,
	"accepted_signal_error_probability": error,
	"log_accepted_signal_error_probability": log_error,
	"contrast_rounded_to_one": contrast_from_odds == 1 and initial < 1,
	"expected_raw_signal_calls": raw_calls,
	"node_acceptance_probabilities": acceptance,
	"scope": "independent repeated signals of ONE fixed target",
	}


	def stack_chain(q: int, u: float, level: int) -> dict:
	"""Independent absorbing-chain computation for the actual binary tree.

	Each stack slot is empty (-1) or holds one pending child symbol. One raw
	signal is fed at the bottom. Agreeing pairs ripple upward; mismatches
	clear their slot and restart there. The transition matrix is constructed
	from raw symbols without using the closed purification or cost formula.
	"""
	_validate(q, u, level)
	if level == 0:
	probs = np.full(q, (1 - u) / q)
	probs[0] += u
	return {"expected_raw_signal_calls": 1.0,
	"output_probabilities_given_target_zero": probs.tolist(),
	"transient_states": 0, "linear_residual": 0.0}
	states = list(itertools.product(range(-1, q), repeat=level))
	lookup = {state: index for index, state in enumerate(states)}
	nstates = len(states)
	transition = np.zeros((nstates, nstates))
	absorb = np.zeros((nstates, q))
	raw = np.full(q, (1 - u) / q)
	raw[0] += u
	for row, state in enumerate(states):
	for symbol, probability in enumerate(raw):
	if probability == 0:
	continue
	next_state = list(state)
	absorbed = True
	for slot in range(level):
	if next_state[slot] == -1:
	next_state[slot] = symbol
	absorbed = False
	break
	if next_state[slot] == symbol:
	next_state[slot] = -1
	continue
	next_state[slot] = -1
	absorbed = False
	break
	if absorbed:
	absorb[row, symbol] += probability
	else:
	transition[row, lookup[tuple(next_state)]] += probability
	matrix = np.eye(nstates) - transition
	rhs = np.column_stack((np.ones(nstates), absorb))
	solution = np.linalg.solve(matrix, rhs)
	origin = lookup[(-1,) * level]
	return {
	"expected_raw_signal_calls": float(solution[origin, 0]),
	"output_probabilities_given_target_zero": solution[origin, 1:].tolist(),
	"transient_states": nstates,
	"linear_residual": float(np.max(np.abs(matrix @ solution - rhs))),
	"transition_row_sum_error": float(np.max(np.abs(
	transition.sum(axis=1) + absorb.sum(axis=1) - 1))),
	}


	def exported_levels(q: int, u: float, t: float, overhead: float,
	readout_cost: float = 1.0, max_level: int = 3) -> list[dict]:
	"""Same outer retention t at every level; costs include all retries.

	overhead h must cover ALL nonreadout per-primitive-trial costs. An outer
	target-independent Bernoulli(t) requests a signal only on nonerasure.
	A raw accepted signal costs (h+tE)/t in expectation. Hence unconditional
	exported cost equals (h+tE)*expected_raw_signal_calls; t cancels.
	"""
	if not 0 < t <= 1 or overhead < 0 or readout_cost <= 0:
	raise ValueError("Require 0<t<=1, h>=0, E>0")
	cg = overhead + t * readout_cost
	rows = []
	for k in range(max_level + 1):
	row = pure_level(q, u, k)
	row["outer_retention"] = t
	row["expected_logical_cost"] = cg * row["expected_raw_signal_calls"]
	row["uniform_prior_full_call_MAP_error"] = (
	(q - 1) / q * (1 - t * row["contrast"]))
	rows.append(row)
	return rows


	def upper_concave_hull(levels: list[dict]) -> list[dict]:
	"""Upper hull of (expected_cost,contrast), restricted to supplied levels."""
	points = sorted(levels, key=lambda row: row["expected_logical_cost"])
	hull = []
	for row in points:
	x, y = row["expected_logical_cost"], row["contrast"]
	if hull and x == hull[-1]["expected_logical_cost"]:
	if y <= hull[-1]["contrast"]:
	continue
	hull.pop()
	while len(hull) >= 2:
	a, b = hull[-2:]
	# Upper concavity requires nonincreasing consecutive slopes.
	cross = ((b["expected_logical_cost"] - a["expected_logical_cost"])
	* (y - b["contrast"])
	- (b["contrast"] - a["contrast"])
	* (x - b["expected_logical_cost"]))
	if cross < 0:
	break
	hull.pop()
	hull.append(row)
	return hull


	def budget_mixture(levels: list[dict], budget: float) -> dict:
	"""Optimal contrast at budget among mixtures of the supplied levels.

	This is a finite-family optimum. It is not optimal over all possible
	sequential/posterior confidence acquisition programs.
	"""
	hull = upper_concave_hull(levels)
	if not hull or budget < hull[0]["expected_logical_cost"]:
	raise ValueError("Budget cannot fund even the least costly supplied level")
	left = right = hull[-1]
	weight_right = 0.0
	for a, b in zip(hull, hull[1:]):
	if budget <= b["expected_logical_cost"]:
	left, right = a, b
	weight_right = ((budget - a["expected_logical_cost"])
	/ (b["expected_logical_cost"]
	- a["expected_logical_cost"]))
	break
	contrast = (1 - weight_right) * left["contrast"] + weight_right * right["contrast"]
	cost = ((1 - weight_right) * left["expected_logical_cost"]
	+ weight_right * right["expected_logical_cost"])
	q, t = left["q"], left["outer_retention"]
	error = (q - 1) / q * (1 - contrast)
	initial = left["initial_contrast"]
	original_error = (q - 1) / q * (1 - initial)
	return {
	"family": "finite-level recursive unanimous signal verifiers",
	"hull_levels": [row["level"] for row in hull],
	"left_level": left["level"],
	"right_level": right["level"],
	"right_probability": weight_right,
	"budget": budget,
	"expected_logical_cost": cost,
	"unused_budget": max(0.0, budget - cost),
	"contrast": contrast,
	"outer_retention": t,
	"accepted_signal_error_probability": error,
	"accepted_error_relative_reduction": (original_error - error) / original_error
	if original_error > 0 else 0.0,
	"original_uniform_prior_full_call_MAP_error": (q - 1) / q * (1 - t * initial),
	"uniform_prior_full_call_MAP_error": (q - 1) / q * (1 - t * contrast),
	"old_to_new_deficiency": (q - 1) / q * t * (contrast - initial),
	"new_to_old_deficiency": 0.0,
	"claims": "same outer retention and expected cost; not constant latency; not hardware evidence",
	}


	def _independent_checks() -> dict:
	records = []
	max_cost_relative_error = max_prob_error = max_linear_residual = 0.0
	cases = [(q, u, k) for q in (2, 3, 5) for u in (0.2, 0.6, 0.9) for k in (1, 2)]
	cases += [(q, 0.6, 3) for q in (2, 3, 5)]
	for q, u, k in cases:
	closed = pure_level(q, u, k)
	chain = stack_chain(q, u, k)
	expected = np.full(q, closed["accepted_signal_error_probability"] / (q - 1))
	expected[0] = closed["accepted_signal_correct_probability"]
	cost_error = abs(chain["expected_raw_signal_calls"]
	- closed["expected_raw_signal_calls"]) / closed["expected_raw_signal_calls"]
	probability_error = float(np.max(np.abs(np.asarray(
	chain["output_probabilities_given_target_zero"]) - expected)))
	max_cost_relative_error = max(max_cost_relative_error, cost_error)
	max_prob_error = max(max_prob_error, probability_error)
	max_linear_residual = max(max_linear_residual, chain["linear_residual"])
	records.append({"q": q, "u": u, "level": k,
	"relative_expected_cost_error": cost_error,
	"max_output_probability_error": probability_error,
	"independent_absorbing_chain": chain})
	binary_error = 0.0
	for u, k in itertools.product((.1, .2, .6, .9), range(5)):
	row = pure_level(2, u, k)
	n = 2 ** k
	v = math.tanh(n * math.atanh(u))
	expected_cost = n * v / u
	binary_error = max(binary_error, abs(row["contrast"] - v),
	abs(row["expected_raw_signal_calls"] - expected_cost) / expected_cost)
	passed = max(max_cost_relative_error, max_prob_error, max_linear_residual,
	binary_error) < 1e-9
	return {"status": "PASS" if passed else "FAIL", "cases": len(cases),
	"method": "full raw-symbol absorbing Markov chain on recursive pending stack",
	"max_relative_cost_error": max_cost_relative_error,
	"max_output_probability_error": max_prob_error,
	"max_linear_system_residual": max_linear_residual,
	"binary_SPRT_identity_checks": 20,
	"max_binary_identity_error": binary_error, "records": records}


	def _hull_lp_checks() -> dict:
	"""Independent unrestricted mixture LP, with no hull assumptions."""
	records = []
	max_error = 0.0
	for q, u, t, h in ((2, .55, .25, .1), (3, .4, 1 / 9, .1),
	(5, .6, .04, .1)):
	levels = exported_levels(q, u, t, h, max_level=3)
	costs = np.asarray([row["expected_logical_cost"] for row in levels])
	contrasts = np.asarray([row["contrast"] for row in levels])
	for budget in np.linspace(costs[0], costs[-1], 9):
	answer = budget_mixture(levels, float(budget))
	lp = linprog(-contrasts, A_ub=costs[None, :],
	b_ub=[budget], A_eq=np.ones((1, len(levels))),
	b_eq=[1.0], bounds=[(0, None)] * len(levels),
	method="highs")
	if not lp.success:
	raise RuntimeError(lp.message)
	error = abs(answer["contrast"] + lp.fun)
	max_error = max(max_error, error)
	records.append({"q": q, "u": u, "budget": float(budget),
	"hull_contrast": answer["contrast"],
	"unrestricted_mixture_LP_contrast": float(-lp.fun),
	"absolute_error": error})
	return {"status": "PASS" if max_error < 1e-9 else "FAIL",
	"cases": len(records), "max_contrast_error": max_error,
	"scope": "all mixtures of supplied finite levels, not all sequential programs",
	"records": records}


	def run() -> dict:
	checks = _independent_checks()
	hull_checks = _hull_lp_checks()
	levels = exported_levels(5, .6, .04, .1, max_level=3)
	mixture = budget_mixture(levels, 1.1)
	old_map = mixture["original_uniform_prior_full_call_MAP_error"]
	new_map = mixture["uniform_prior_full_call_MAP_error"]
	mixture["full_call_MAP_error_absolute_reduction"] = old_map - new_map
	mixture["full_call_MAP_error_relative_reduction"] = (old_map - new_map) / old_map
	return {
	"status": "PASS" if checks["status"] == hull_checks["status"] == "PASS" else "FAIL",
	"research": "Evie's Pure Form RSI",
	"scope": "mathematical verifier-strengthening component under explicit conditional-independent channels",
	"physical_measurements": False,
	"general_intelligence_gain_established": False,
	"prior_art_boundary": "binary hierarchy equals classical SPRT; neither consensus nor sequential testing is claimed as invention",
	"cost_contract": "h includes every nonreadout cost per primitive trial; E is acquisition cost; expected cost, unbounded retry tails",
	"independent_checks": checks,
	"finite_mixture_LP_checks": hull_checks,
	"q5_example": {
	"q": 5, "base_retention": .04, "base_contrast": .6,
	"overhead_h_over_E": .1, "readout_E": 1.0,
	"ungated_expected_cost": 1.1,
	"gated_primitive_expected_cost": .14,
	"gate_saving_ratio": 1.1 / .14,
	"levels": levels, "fixed_budget_mixture": mixture,
	},
	}


	if __name__ == "__main__":
	parser = argparse.ArgumentParser(description=__doc__)
	parser.add_argument("--output", default=str(Path(__file__).resolve().parent / "data" / "bootstrap.json"))
	args = parser.parse_args()
	report = run()
	path = Path(args.output)
	path.parent.mkdir(parents=True, exist_ok=True)
	path.write_text(json.dumps(report, indent=2) + "\n", encoding="utf-8")
	print(json.dumps({"status": report["status"],
	"independent_checks": {k: v for k, v in report["independent_checks"].items() if k != "records"},
	"fixed_budget_mixture": report["q5_example"]["fixed_budget_mixture"]}, indent=2))
	raise SystemExit(0 if report["status"] == "PASS" else 1)