Nemoriu-Research / src /core.py
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"""Exact reciprocal repair, over GF(2). Python 3.10+, standard library only.
Square matrices use one Python integer per row. Reported work is a specified
word-RAM model, NOT FLOPs or a claimed hardware-neutral speedup. n <= 64.
Every matrix traversal, word xor, set-bit scan, comparison, RNG draw and
search bookkeeping has a deterministic charge; elapsed time is also reported.
"""
from __future__ import annotations
from collections import Counter
from dataclasses import dataclass, field
import random
Mat = tuple[int, ...]
class BudgetExhausted(RuntimeError):
pass
@dataclass
class Meter:
limit: int | None = None
used: int = 0
counts: Counter = field(default_factory=Counter)
def use(self, amount: int, kind: str = "misc") -> None:
if self.limit is not None and self.used + amount > self.limit:
remaining = self.limit - self.used
self.counts[kind] += remaining
self.used = self.limit
raise BudgetExhausted
self.used += amount
self.counts[kind] += amount
@dataclass(frozen=True)
class Problem:
d: Mat
Q: Mat
P: Mat
h0: Mat
grades: tuple[int, ...]
@property
def n(self) -> int:
return len(self.d)
def zero(n: int) -> Mat:
return (0,) * n
def eye(n: int) -> Mat:
return tuple(1 << i for i in range(n))
def add(A: Mat, B: Mat, m: Meter) -> Mat:
m.use(2 * len(A), "xor")
return tuple(a ^ b for a, b in zip(A, B))
def mul(A: Mat, B: Mat, m: Meter) -> Mat:
out = []
for row in A:
m.use(2, "multiply")
value = 0
while row:
m.use(6, "multiply")
low = row & -row
value ^= B[low.bit_length() - 1]
row ^= low
out.append(value)
return tuple(out)
def nnz(A: Mat, m: Meter) -> int:
m.use(2 * len(A), "score")
return sum(row.bit_count() for row in A)
def equal(A: Mat, B: Mat, m: Meter) -> bool:
m.use(len(A), "compare")
return A == B
def differential(p: Problem, f: Mat, m: Meter) -> Mat:
# Signs coincide in characteristic two, for every degree.
return add(mul(p.d, f, m), mul(f, p.d, m), m)
def K(p: Problem, h: Mat, f: Mat, m: Meter, cross: bool = True) -> Mat:
hf = mul(h, f, m)
if not cross:
return hf
return add(hf, mul(mul(p.Q, f, m), h, m), m)
def valid(p: Problem, h: Mat, m: Meter) -> bool:
z = zero(p.n)
# Check all identities; do not short-circuit invalid candidates.
checks = [equal(differential(p, h, m), p.P, m),
equal(mul(h, h, m), z, m),
equal(mul(p.Q, h, m), z, m),
equal(mul(h, p.Q, m), z, m)]
m.use(p.n * p.n, "degree_check")
graded = all(not (row >> j & 1) or p.grades[i] == p.grades[j] - 1
for i, row in enumerate(h) for j in range(p.n))
return all(checks) and graded
def normalize(p: Problem, g: Mat, m: Meter) -> Mat:
return mul(mul(g, p.d, m), g, m)
def repaired_candidate(p: Problem, current: Mat, generator: Mat,
a: Mat, m: Meter, protect: bool = False) -> Mat:
# z = P (a - K_generator(partial a)) P; minus = plus over GF(2).
z = add(a, K(p, generator, differential(p, a, m), m), m)
if protect:
z = mul(mul(p.P, z, m), p.P, m)
return normalize(p, add(current, z, m), m)
def boundary_candidate(p: Problem, current: Mat, B: Mat, m: Meter) -> Mat:
# Strong simple reduction: any fixed-Q closed variation is partial B.
z = differential(p, B, m)
# gdg automatically removes Q mixing; explicit P sandwiches are redundant.
return normalize(p, add(current, z, m), m)
def positions(p: Problem, degree: int, m: Meter) -> tuple[tuple[int, int], ...]:
m.use(p.n * p.n, "setup")
return tuple((i, j) for i in range(p.n) for j in range(p.n)
if p.grades[i] == p.grades[j] + degree)
def proposal(p: Problem, available: tuple[tuple[int, int], ...],
rng: random.Random, m: Meter, width: int = 1) -> Mat:
m.use(p.n + 7 * width, "proposal")
rows = [0] * p.n
for _ in range(width):
i, j = available[rng.randrange(len(available))]
rows[i] ^= 1 << j
return tuple(rows)
def kernel_work(p: Problem, h: Mat, tasks: list[Mat],
charge: Meter | None = None) -> int:
"""Execute, rather than estimate, the kernel on fresh repair problems."""
local = Meter()
for task in tasks:
K(p, h, task, local)
if charge is not None:
charge.use(local.used, "kernel_evaluation")
return local.used
def semantic_certificate(p: Problem, h: Mat, f: Mat, m: Meter,
cross: bool = True) -> bool:
"""Check partial K + K partial = f - Q f Q for an arbitrary End task."""
lhs = add(differential(p, K(p, h, f, m, cross), m),
K(p, h, differential(p, f, m), m, cross), m)
rhs = add(f, mul(mul(p.Q, f, m), p.Q, m), m)
return equal(lhs, rhs, m)