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4.57 kB
| """Exact scalar contraction scheduling with at most one split request. | |
| All arithmetic uses fractions.Fraction. A fragment (i, a) applies | |
| x <- a*x + (1-a)*centers[i]. | |
| The product of the fragment retentions for request i equals retentions[i]. | |
| This is an enlarged scheduling policy: at most n+1 updates replace n updates. | |
| No claim of preserving a gradient-query count or sum of step sizes is made. | |
| """ | |
| from fractions import Fraction | |
| def execute_fragments(centers, fragments, initial=0): | |
| """Evaluate a fragment list exactly.""" | |
| x = Fraction(initial) | |
| centers = tuple(map(Fraction, centers)) | |
| for i, retention in fragments: | |
| a = Fraction(retention) | |
| x = a * x + (1 - a) * centers[i] | |
| return x | |
| def optimal_one_split_order(centers, retentions, initial=0, target=0): | |
| """Globally minimize squared terminal error over all finite fragmentations. | |
| Rational retentions must be in [0,1]. The returned policy splits at most | |
| one request into two fragments, each with the same target as its parent. | |
| The algorithm makes O(n**2) exact rational operations, apart from sorting; | |
| all rational operands have polynomial binary length in the input. | |
| It also returns the optimal squared error and the full attainable interval. | |
| """ | |
| centers = tuple(map(Fraction, centers)) | |
| retentions = tuple(map(Fraction, retentions)) | |
| initial, target = Fraction(initial), Fraction(target) | |
| n = len(centers) | |
| if len(retentions) != n: | |
| raise ValueError("centers and retentions must have equal length") | |
| if any(a < 0 or a > 1 for a in retentions): | |
| raise ValueError("retentions must lie in [0,1]") | |
| minimum_order = sorted(range(n), key=lambda i: -centers[i]) | |
| maximum_order = sorted(range(n), key=lambda i: centers[i]) | |
| def unsplit(order): | |
| return [(i, retentions[i]) for i in order] | |
| minimum = execute_fragments(centers, unsplit(minimum_order), initial) | |
| maximum = execute_fragments(centers, unsplit(maximum_order), initial) | |
| best_endpoint = min(max(target, minimum), maximum) | |
| def result(fragments, split_request, swaps): | |
| endpoint = execute_fragments(centers, fragments, initial) | |
| return { | |
| "fragments": fragments, | |
| "split_request": split_request, | |
| "endpoint": endpoint, | |
| "objective": (endpoint - target) ** 2, | |
| "optimal_endpoint": best_endpoint, | |
| "attainable_interval": (minimum, maximum), | |
| "adjacent_swaps_examined": swaps, | |
| } | |
| if target <= minimum: | |
| return result(unsplit(minimum_order), None, 0) | |
| if target >= maximum: | |
| return result(unsplit(maximum_order), None, 0) | |
| # A bubble-sort path increases the endpoint from minimum to maximum. | |
| order = minimum_order[:] | |
| suffix = [Fraction(1)] * (n + 1) | |
| for p in range(n - 1, -1, -1): | |
| suffix[p] = retentions[order[p]] * suffix[p + 1] | |
| current = minimum | |
| swaps = 0 | |
| for end in range(n - 1, 0, -1): | |
| for p in range(end): | |
| i, j = order[p], order[p + 1] | |
| if centers[i] <= centers[j]: | |
| continue | |
| ai, aj = retentions[i], retentions[j] | |
| later = suffix[p + 2] | |
| increment = later * (1 - ai) * (1 - aj) * (centers[i] - centers[j]) | |
| following = current + increment | |
| swaps += 1 | |
| if increment > 0 and current <= target <= following: | |
| lam = (target - current) / increment | |
| if lam == 0: | |
| return result(unsplit(order), None, swaps) | |
| if lam == 1: | |
| next_order = order[:] | |
| next_order[p], next_order[p + 1] = j, i | |
| return result(unsplit(next_order), None, swaps) | |
| # Final retention v interpolates the two adjacent endpoints. | |
| # The first retention ai/v keeps request i's total unchanged. | |
| v = 1 - lam * (1 - ai) | |
| first = ai / v # v>0 for an interior interpolation, even if ai=0. | |
| fragments = ( | |
| unsplit(order[:p]) | |
| + [(i, first), (j, aj), (i, v)] | |
| + unsplit(order[p + 2 :]) | |
| ) | |
| return result(fragments, i, swaps) | |
| order[p], order[p + 1] = j, i | |
| suffix[p + 1] = ai * later | |
| current = following | |
| raise ArithmeticError("attainable interval was not crossed") | |
| if __name__ == "__main__": | |
| answer = optimal_one_split_order([-1, 1], [Fraction(1, 2)] * 2) | |
| print(answer) | |