PureOne's picture
Release VELORYN v1.0.0: boundary-kernel entropy theory
1c08905 verified
Raw History Blame Contribute Delete
3.75 kB
"""Rational logarithm and Perron-root certificates, with no floating decisions."""
from fractions import Fraction as Q
from math import isqrt
from .arithmetic import ceilq
def _series(r,tol):
t=(r-1)/(r+1)
if not t:
return Q(0),Q(0)
power,total,j=t,Q(0),0
while True:
total+=2*power/(2*j+1)
j+=1;power*=t*t
tail=2*power/((2*j+1)*(1-t*t))
if tail<=tol:
return total,total+tail
def log_bounds(x,tolerance=Q(1,10**12)):
x,tolerance=Q(x),Q(tolerance)
if x<=0 or tolerance<=0:
raise ValueError("positive log argument and tolerance required")
if x==1:
return Q(0),Q(0)
k=x.numerator.bit_length()-x.denominator.bit_length()
scale=Q(1<<k) if k>=0 else Q(1,1<<(-k))
r=x/scale
if r<1:
k-=1;r*=2
elif r>=2:
k+=1;r/=2
local=tolerance/(4*(abs(k)+1))
a,b=_series(r,local)
c,d=_series(Q(2),local)
if k>=0:
lo,hi=a+k*c,b+k*d
else:
lo,hi=a+k*d,b+k*c
bits=max(0,tolerance.denominator.bit_length()-tolerance.numerator.bit_length()+4)
while Q(1,1<<bits)>tolerance/8:
bits+=1
scale=1<<bits
return Q((lo*scale).__floor__(),scale),Q(ceilq(hi*scale),scale)
def sqrt_upper(x,bits=96):
x=Q(x)
if x<0:
raise ValueError("nonnegative radicand required")
scale=1<<bits
r=isqrt(x.numerator*scale*scale//x.denominator)
if r*r*x.denominator<x.numerator*scale*scale:
r+=1
return Q(r,scale)
def solve(a,b):
n=len(a)
work=[list(map(Q,row))+[Q(v)] for row,v in zip(a,b)]
for j in range(n):
pivot=next((i for i in range(j,n) if work[i][j]),None)
if pivot is None:
return None
work[j],work[pivot]=work[pivot],work[j]
z=work[j][j]
work[j]=[v/z for v in work[j]]
for i in range(n):
if i!=j and work[i][j]:
z=work[i][j]
work[i]=[v-z*w for v,w in zip(work[i],work[j])]
return tuple(row[-1] for row in work)
def spectral_bounds(matrix,relative_tolerance=Q(1,10**10),max_iterations=10000):
"""Enclose rho(A) for a nonnegative rational matrix with positive row sums.
t > rho(A) iff (t I - A)x=1 has an everywhere positive solution.
Exact rational bisection therefore works even for reducible/periodic A.
"""
a=tuple(tuple(map(Q,row)) for row in matrix)
n=len(a)
if not n or any(len(row)!=n or any(x<0 for x in row) for row in a):
raise ValueError("nonempty square nonnegative matrix required")
rows=tuple(map(sum,a))
if min(rows)<=0:
raise ValueError("positive row sums required")
tol=Q(relative_tolerance)
if tol<=0:
raise ValueError("positive relative tolerance required")
lo,hi=max(min(rows),max(a[i][i] for i in range(n))),max(rows)
steps=0
while hi-lo>tol*lo:
if steps>=max_iterations:
raise RuntimeError("spectral bisection budget exhausted; no certificate issued")
t=(lo+hi)/2
shifted=[[(t if i==j else 0)-a[i][j] for j in range(n)] for i in range(n)]
x=solve(shifted,[1]*n)
if x is not None and min(x)>0:
hi=t
else:
lo=t
steps+=1
return {"lower":lo,"upper":hi,"iterations":steps,
"method":"exact rational positive-resolvent bisection"}
def matmul(a,b):
return [[sum((a[i][k]*b[k][j] for k in range(len(b))),Q(0))
for j in range(len(b[0]))] for i in range(len(a))]
def serializable(x):
if isinstance(x,Q):
return str(x)
if isinstance(x,dict):
return {str(k):serializable(v) for k,v in x.items()}
if isinstance(x,(list,tuple)):
return [serializable(v) for v in x]
return x