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idiombench

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IdiomBench (part 11)

e54eaab verified 4 days ago

136 Bytes

def fn(l, incr):
   result = l[0]
   l[0] += incr
   return result

lst = [0]
f'{fn(lst,2)} {fn(lst,3)}'
f'{fn(lst,2)} {fn(lst,3)}'
lst