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8.88 kB
| using namespace std; | |
| const int MOD = 1000000007; | |
| int N; | |
| struct Seg { // Directions: U / R / D / L | |
| int i = -1, r, c, p, d, t = 0; | |
| long long get_time_val() { | |
| return N * ((long long)t - r - c) + i; | |
| } | |
| bool operator<(const Seg& b) const { | |
| return make_pair(r, c) < make_pair(b.r, b.c); | |
| } | |
| }; | |
| struct BIT { | |
| int N; | |
| vector<int> V; | |
| BIT() {} | |
| BIT(int _N): N(_N) { | |
| init(_N); | |
| } | |
| void init(int _N) { | |
| N = _N; | |
| V.resize(N + 1); | |
| } | |
| void clear() { | |
| fill(V.begin(), V.end(), 0); | |
| } | |
| void update(int i, int v) { | |
| for (i++; i <= N; i += (i & -i)) { | |
| V[i] += v; | |
| } | |
| } | |
| int query(int i) { | |
| int v = 0; | |
| i = min(i, N - 1); | |
| for (i++; i > 0; i -= (i & -i)) { | |
| v += V[i]; | |
| } | |
| return v; | |
| } | |
| }; | |
| struct SegTree { | |
| int N, sz; | |
| vector<vector<long long>> keys; | |
| vector<BIT> B; | |
| SegTree() {} | |
| SegTree(int _N) { | |
| init(_N); | |
| } | |
| void init(int _N) { | |
| N = _N; | |
| for (sz = 1; sz < N; sz <<= 1) | |
| ; | |
| keys.resize(sz << 1); | |
| B.resize(sz << 1); | |
| } | |
| void init_keys() { | |
| for (int i = sz; i < sz + N; i++) { | |
| auto &K = keys[i]; | |
| sort(K.begin(), K.end()); | |
| B[i].init(K.size()); | |
| } | |
| for (int i = sz - 1; i >= 1; i--) { | |
| auto &K = keys[i]; | |
| auto &c1 = keys[i << 1], &c2 = keys[(i << 1) + 1]; | |
| int a = 0, b = 0; | |
| while (a < c1.size() || b < c2.size()) { | |
| if (b == c2.size() || (a < c1.size() && c1[a] < c2[b])) { | |
| K.push_back(c1[a++]); | |
| } else { | |
| K.push_back(c2[b++]); | |
| } | |
| } | |
| B[i].init(K.size()); | |
| } | |
| } | |
| int query_larger(int a, int b, long long v, int i = 1, int r1 = 0, int r2 = -1) { | |
| if (r2 < 0) { | |
| a = max(a, 0); | |
| b = min(b, sz - 1); | |
| if (a > b) { | |
| return 0; | |
| } | |
| r2 = sz - 1; | |
| } | |
| if (a <= r1 && r2 <= b) { | |
| auto &K = keys[i]; | |
| v = lower_bound(K.begin(), K.end(), v) - K.begin(); | |
| return B[i].query(K.size() - 1) - B[i].query(v - 1); | |
| } | |
| int m = (r1 + r2) >> 1, c = i << 1; | |
| int res = 0; | |
| if (a <= m) { | |
| res += query_larger(a, b, v, c, r1, m); | |
| } | |
| if (b > m) { | |
| res += query_larger(a, b, v, c + 1, m + 1, r2); | |
| } | |
| return res; | |
| } | |
| void update_one(int i, long long v, int d) { | |
| i += sz; | |
| while (i >= 1) { | |
| auto &K = keys[i]; | |
| B[i].update(lower_bound(K.begin(), K.end(), v) - K.begin(), d); | |
| i >>= 1; | |
| } | |
| } | |
| }; | |
| vector<Seg> SS; | |
| Seg trim_seg(Seg s, int a, int b, bool hor) { | |
| if (s.d == 1 || s.d == 2) { // Forward segment. | |
| int& sv1 = hor ? s.c : s.r; // First value. | |
| int sv2 = sv1 + s.p - 1; // Last value. | |
| int t1 = max(0, a - sv1); // Truncation at start. | |
| int t2 = max(0, sv2 - b); // Truncation at end. | |
| sv1 += t1, s.t += t1; | |
| s.p -= t1 + t2; | |
| } else { // Backward segment. | |
| int& sv2 = hor ? s.c : s.r; // Last value. | |
| int sv1 = sv2 - (s.p - 1); // First value. | |
| int t1 = max(0, a - sv1); // Truncation at start. | |
| int t2 = max(0, sv2 - b); // Truncation at end. | |
| sv2 -= t2, s.t += t2; | |
| s.p -= t1 + t2; | |
| } | |
| return s; | |
| } | |
| vector<Seg> merge_opp_segs(Seg s1, Seg s2, bool hor) { | |
| int nc = (hor ? s2.c - s1.c : s2.r - s1.r) + 1; | |
| int t1 = s1.t; // Time for s1 to reach start. | |
| int t2 = s2.t + nc - 1 - (s2.i < s1.i ? 1 : 0); // Time for s2 to reach start. | |
| int m = (hor ? s1.c : s1.r) + (t2 - t1 + 2) / 2 - | |
| 1; // Last value painted over by s2. | |
| vector<Seg> S; | |
| S.push_back(trim_seg(s2, -1e9 - 1, m, hor)); | |
| S.push_back(trim_seg(s1, m + 1, 2e9 + 1, hor)); | |
| return S; | |
| } | |
| void process_linear_segs(vector<Seg> V, bool hor) { | |
| // Collect and sort forward / backward segments. | |
| int d1, d2; | |
| if (hor) { | |
| d1 = 1; | |
| d2 = 3; | |
| } else { | |
| d1 = 2; | |
| d2 = 0; | |
| } | |
| vector<tuple<int, int, Seg>> P1, P2; | |
| for (auto s : V) { | |
| if (s.d == d1) { | |
| P1.emplace_back(s.r + s.c, -s.i, s); | |
| } else { | |
| P2.emplace_back(-(s.r + s.c), -s.i, s); | |
| } | |
| } | |
| sort(P1.begin(), P1.end()); | |
| sort(P2.begin(), P2.end()); | |
| // Reduce forward / backward segments independently. | |
| vector<Seg> S1, S2; | |
| int last = -1e9 - 1; | |
| for (auto p : P1) { | |
| Seg s = trim_seg(get<2>(p), last + 1, 2e9 + 1, hor); // Trim to after last. | |
| if (s.p > 0) { // Include if not obsolete. | |
| S1.push_back(s); | |
| } | |
| last = max(last, (hor ? s.c : s.r) + (s.p - 1)); | |
| } | |
| last = 2e9 + 1; | |
| for (auto p : P2) { | |
| Seg s = trim_seg(get<2>(p), -1e9 - 1, last - 1, hor); // Trim to before last. | |
| if (s.p > 0) { // Include if not obsolete. | |
| S2.push_back(s); | |
| } | |
| last = min(last, (hor ? s.c : s.r) - (s.p - 1)); | |
| } | |
| // Merge forward / backward segments. | |
| vector<tuple<int, int, int>> E; | |
| for (int i = 0; i < S1.size(); i++) { | |
| Seg s = S1[i]; | |
| int sv = hor ? s.c : s.r; | |
| E.emplace_back(sv, 1, i); | |
| E.emplace_back(sv + s.p, 0, i); | |
| } | |
| for (int i = 0; i < S2.size(); i++) { | |
| Seg s = S2[i]; | |
| int sv = hor ? s.c : s.r; | |
| E.emplace_back(sv - (s.p - 1), 3, i); | |
| E.emplace_back(sv + 1, 2, i); | |
| } | |
| sort(E.begin(), E.end()); | |
| vector<int> inds{-1, -1}; | |
| for (int i = 0; i < E.size(); i++) { | |
| int v = get<0>(E[i]), e = get<1>(E[i]); | |
| // Update set of ongoing segments. | |
| int j = e / 2; | |
| if (e % 2) { | |
| inds[j] = get<2>(E[i]); | |
| } else { | |
| inds[j] = -1; | |
| } | |
| // Process ongoing segments? | |
| if (i + 1 < E.size() && v < get<0>(E[i + 1])) { | |
| vector<Seg> S; | |
| if (inds[0] >= 0 && inds[1] >= 0) { | |
| S = merge_opp_segs(S1[inds[0]], S2[inds[1]], hor); | |
| } else if (inds[0] >= 0) { | |
| S.push_back(S1[inds[0]]); | |
| } else if (inds[1] >= 0) { | |
| S.push_back(S2[inds[1]]); | |
| } | |
| for (auto s : S) { | |
| Seg s2 = trim_seg(s, v, get<0>(E[i + 1]) - 1, hor); | |
| if (s2.p > 0) { | |
| SS.push_back(s2); | |
| } | |
| } | |
| } | |
| } | |
| } | |
| int solve() { | |
| SS.clear(); | |
| map<int, vector<Seg>> rowS, colS; | |
| // Input. | |
| cin >> N; | |
| for (int i = 0; i < N; i++) { | |
| Seg s; | |
| s.i = i + 1; | |
| char d; | |
| cin >> s.r >> s.c >> s.p >> d; | |
| s.d = d == 'N' ? 0 : d == 'E' ? 1 : d == 'S' ? 2 : 3; | |
| if (s.d % 2) { | |
| rowS[s.r].push_back(s); | |
| } else { | |
| colS[s.c].push_back(s); | |
| } | |
| } | |
| // Reduce each relevant row / column to disjoint segments | |
| for (auto p : rowS) { | |
| process_linear_segs(p.second, true); | |
| } | |
| for (auto p : colS) { | |
| process_linear_segs(p.second, false); | |
| } | |
| // Compute base answer. | |
| int ans = 0; | |
| for (auto s : SS) { | |
| ans = (ans + (long long)s.i * s.p) % MOD; | |
| } | |
| // Consider 4 different rotations of the grid. | |
| for (int r = 0; r < 4; r++) { | |
| // Rotate everything 90 degrees clockwise. | |
| for (int i = 0; i < SS.size(); i++) { | |
| Seg &s = SS[i]; | |
| int r = s.r, c = s.c, d = s.d; | |
| s.r = c; | |
| s.c = -r; | |
| s.d = (d + 1) % 4; | |
| } | |
| // Consider 2 different vertical flips of the grid. | |
| for (int _ : {0, 1}) { | |
| // Flip everything vertically. | |
| for (int i = 0; i < SS.size(); i++) { | |
| Seg &s = SS[i]; | |
| s.r = -s.r; | |
| if (s.d % 2 == 0) { | |
| s.d = 2 - s.d; | |
| } | |
| } | |
| // Assemble list of line sweep events and distinct D segment columns. | |
| vector<tuple<int, int, Seg>> E; | |
| vector<int> cc; | |
| for (auto s : SS) { | |
| if (s.d == 1) { // R | |
| E.emplace_back(s.r, 1, s); | |
| } else if (s.d == 2) { // D | |
| E.emplace_back(s.r, 0, s); | |
| E.emplace_back(s.r + s.p - 1, 2, s); | |
| cc.push_back(s.c); | |
| } | |
| } | |
| sort(E.begin(), E.end()); | |
| sort(cc.begin(), cc.end()); | |
| cc.resize(unique(cc.begin(), cc.end()) - cc.begin()); | |
| // Initialize 2D segment tree. | |
| SegTree ST(cc.size()); | |
| for (auto s : SS) { | |
| if (s.d == 2) { // D | |
| ST.keys[ST.sz + (lower_bound(cc.begin(), cc.end(), s.c) - cc.begin())] | |
| .push_back(s.get_time_val()); | |
| } | |
| } | |
| ST.init_keys(); | |
| // Line sweep to subtract R segments covered by D ones. | |
| for (auto p : E) { | |
| int e = get<1>(p); | |
| Seg s = get<2>(p); | |
| if (e == 1) { | |
| int a = lower_bound(cc.begin(), cc.end(), s.c) - cc.begin(); | |
| int b = lower_bound(cc.begin(), cc.end(), s.c + s.p) - cc.begin() - 1; | |
| long long v = s.get_time_val(); | |
| ans = (ans + MOD - (long long)s.i * ST.query_larger(a, b, v) % MOD) % MOD; | |
| } else { | |
| ST.update_one( | |
| lower_bound(cc.begin(), cc.end(), s.c) - cc.begin(), | |
| s.get_time_val(), | |
| e == 0 ? 1 : -1 | |
| ); | |
| } | |
| } | |
| } | |
| } | |
| return ans; | |
| } | |
| int main() { | |
| int T; | |
| cin >> T; | |
| for (int t = 1; t <= T; t++) { | |
| cout << "Case #" << t << ": " << solve() << endl; | |
| } | |
| return 0; | |
| } | |