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4.26 kB
| // Seafood | |
| // Solution by Jacob Plachta | |
| using namespace std; | |
| template<typename T> T Abs(T x) { return(x<0 ? -x : x); } | |
| template<typename T> T Sqr(T x) { return(x*x); } | |
| string plural(string s) { return(Sz(s) && s[Sz(s)-1]=='x' ? s+"en" : s+"s"); } | |
| const int INF = (int)1e9; | |
| const LD EPS = 1e-12; | |
| const LD PI = acos(-1.0); | |
| bool Read(int &x) | |
| { | |
| char c,r=0,n=0; | |
| x=0; | |
| for(;;) | |
| { | |
| c=GETCHAR(); | |
| if ((c<0) && (!r)) | |
| return(0); | |
| if ((c=='-') && (!r)) | |
| n=1; | |
| else | |
| if ((c>='0') && (c<='9')) | |
| x=x*10+c-'0',r=1; | |
| else | |
| if (r) | |
| break; | |
| } | |
| if (n) | |
| x=-x; | |
| return(1); | |
| } | |
| int N,K; | |
| int G[2][LIM]; | |
| char O[LIM]; | |
| pair< int, pair<char,int> > P[LIM]; | |
| int C[LIM],B[LIM]; | |
| int sufCB[LIM],sufCH[LIM]; | |
| int ss,nfr; | |
| PR st[LIM],fr[LIM]; | |
| int main() | |
| { | |
| if (DEBUG) | |
| freopen("in.txt","r",stdin); | |
| // vars | |
| int T,t; | |
| int i,j,a,b,c,d,p; | |
| LL ans; | |
| // testcase loop | |
| Read(T); | |
| Fox1(t,T) | |
| { | |
| // input, and generate values | |
| Read(N); | |
| Fox(i,2) | |
| { | |
| Read(G[i][0]),Read(G[i][1]),Read(a),Read(b),Read(c),Read(d); | |
| FoxI(j,2,N-1) | |
| G[i][j]=((LL)a*G[i][j-2] + (LL)b*G[i][j-1] + c)%d+1; | |
| } | |
| scanf("%s",&O); | |
| Fox(i,N) | |
| P[i]=mp(G[0][i],mp(O[i],G[1][i])); | |
| // sort objects by position | |
| sort(P,P+N); | |
| // get list of clams | |
| K=0; | |
| Fox(i,N) | |
| if (P[i].y.x=='C') | |
| C[K++]=i; | |
| // get list of useful rocks up to final clam | |
| ss=0; | |
| FoxR(i,C[K-1]) | |
| if ((P[i].y.x=='R') && ((!ss) || (P[i].y.y>st[ss-1].x))) | |
| st[ss++]=mp(P[i].y.y,P[i].x); | |
| // get clams' backtrack positions | |
| Fill(B,-1); | |
| Fox(i,K) | |
| { | |
| j=lower_bound(st,st+ss,mp(P[C[i]].y.y+1,0))-st; | |
| if (j==ss) | |
| break; | |
| B[i]=st[j].y; | |
| } | |
| // precompute suffix mins/maxes of clams' backtrack positions/hardnesses | |
| sufCB[K]=INF,sufCH[K]=0; | |
| FoxR(i,K) | |
| { | |
| sufCB[i]=min(sufCB[i+1],B[i]); | |
| sufCH[i]=max(sufCH[i+1],P[C[i]].y.y); | |
| } | |
| // get list of useful rocks past final clam | |
| nfr=0; | |
| FoxI(i,C[K-1]+1,N-1) | |
| if ((!nfr) || (P[i].y.y>fr[nfr-1].x)) | |
| fr[nfr++]=mp(P[i].y.y,P[i].x); | |
| // DP | |
| ans=2*INF; | |
| ss=0; | |
| Fox(i,K) | |
| { | |
| // perform optional transition from an earlier clam | |
| if (!i) | |
| d=0; | |
| else | |
| { | |
| p=P[C[i-1]].x; | |
| while (ss>1) | |
| { | |
| a=st[ss-1].y; | |
| b=min(a,st[ss-2].y); | |
| if ((LL)st[ss-1].x+2*max(0,p-a)<(LL)st[ss-2].x+2*max(0,p-b)) | |
| break; | |
| st[ss-2].y=b; | |
| ss--; | |
| } | |
| d=st[ss-1].x+2*max(0,p-st[ss-1].y); | |
| } | |
| st[ss++]=mp(d,B[i]); | |
| // consider concluding with transition to final clam | |
| p=P[C[K-1]].x; | |
| if (sufCB[i]>=0) | |
| Min(ans,(LL)d+max(0,p-sufCB[i])); | |
| a=lower_bound(fr,fr+nfr,mp(sufCH[i]+1,0))-fr; | |
| if (a<nfr) | |
| Min(ans,(LL)d+(fr[a].y-p)); | |
| if (B[i]<0) | |
| break; | |
| } | |
| if (ans==2*INF) | |
| ans=-1; | |
| else | |
| ans+=P[C[K-1]].x; | |
| // output | |
| printf("Case #%d: %lld\n",t,ans); | |
| } | |
| return(0); | |
| } |