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| // Ca-pasta-ty | |
| // Solution by Jacob Plachta | |
| using namespace std; | |
| template<typename T> T Abs(T x) { return(x < 0 ? -x : x); } | |
| template<typename T> T Sqr(T x) { return(x * x); } | |
| string plural(string s) { return(Sz(s) && s[Sz(s) - 1] == 'x' ? s + "en" : s + "s"); } | |
| const int INF = (int)1e9; | |
| const LD EPS = 1e-12; | |
| const LD PI = acos(-1.0); | |
| bool Read(int& x) | |
| { | |
| char c, r = 0, n = 0; | |
| x = 0; | |
| for (;;) | |
| { | |
| c = GETCHAR(); | |
| if ((c < 0) && (!r)) | |
| return(0); | |
| if ((c == '-') && (!r)) | |
| n = 1; | |
| else | |
| if ((c >= '0') && (c <= '9')) | |
| x = x * 10 + c - '0', r = 1; | |
| else | |
| if (r) | |
| break; | |
| } | |
| if (n) | |
| x = -x; | |
| return(1); | |
| } | |
| int S[LIM], X[LIM], Y[LIM]; | |
| void ReadSeq(int* V, int N, int K) | |
| { | |
| int i, A, B, C, D; | |
| Fox(i, K) | |
| Read(V[i]); | |
| Read(A), Read(B), Read(C), Read(D); | |
| FoxI(i, K, N - 1) | |
| V[i] = ((LL)A * V[i - 2] + (LL)B * V[i - 1] + C) % D; | |
| } | |
| LL ProcessCase() | |
| { | |
| int N, K, i; | |
| // input | |
| Read(N), Read(K); | |
| ReadSeq(S, N, K); | |
| ReadSeq(X, N, K); | |
| ReadSeq(Y, N, K); | |
| // aggregate requirements | |
| pair<LL, LL> P[2]; | |
| Fox(i, N) | |
| { | |
| int x = X[i] - S[i], y = X[i] + Y[i] - S[i]; | |
| P[0].x += max(0, -y); | |
| P[0].y += max(0, -x); | |
| P[1].x += max(0, x); | |
| P[1].y += max(0, y); | |
| } | |
| // check if satisfiable | |
| Fox(i, 2) | |
| if (P[i].x > P[1 - i].y) | |
| return(-1); | |
| return(max(P[0].x, P[1].x)); | |
| } | |
| int main() | |
| { | |
| int T, t; | |
| Read(T); | |
| Fox1(t, T) | |
| printf("Case #%d: %lld\n", t, ProcessCase()); | |
| return(0); | |
| } |