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f(a) = 2 + 4 a + a^2, \quad g(y) = 3 + y \implies f(g(y)) = 23 + 10 y + y^2
\left(b - v\right) v = b v - v^2
\int \left(1\right) dw = w + C
14 - 9 c + c^2 = 0 \implies c \in \{ 2, 7 \}
-392 - 49 u + 8 u^2 + u^3 = 0 \implies u \in \{ -8, -7, 7 \}
\frac{d}{dy}\left(\sin{\left(y\right)}\right) = \cos{\left(y\right)}
\frac{d}{dw}\left(-90 \sin{\left(w\right)}\right) = -90 \cos{\left(w\right)}
\frac{d}{dy}\left(y\right) = 1
(2, 4, -4) \times (-4, -1, -2) = (-12, 20, 14)
(-4, 1, -5) \times (4, 1, 1) = (6, -16, -8)
-3 + w = 0 \implies w = 3
f(t) = 4 + 2 t + t^2, \quad g(v) = 4 + v \implies f(g(v)) = 28 + 10 v + v^2
7 \left(2 - t\right) = 14 - 7 t
4 - 5 y + y^2 = 0 \implies y \in \{ 1, 4 \}
f(a) = 1 + a + a^2, \quad g(u) = 3 + 2 u \implies f(g(u)) = 13 + 14 u + 4 u^2
v^2 \left(-3 + v\right) = -3 v^2 + v^3
(-1, -4, 5) \times (2, 1, 2) = (-13, 12, 7)
40 \cdot 30 = 1200
(-4, -3, 0) \times (3, -4, 1) = (-3, 4, 25)
-26 + 38 = 12
f(w) = 3 + 4 w + w^2, \quad g(u) = 2 + 3 u \implies f(g(u)) = 15 + 24 u + 9 u^2
f(c) = 2 + 5 c + c^2, \quad g(t) = 3 + 2 t \implies f(g(t)) = 26 + 22 t + 4 t^2
(4, -1, 2) \times (4, -5, -1) = (11, 12, -16)
\frac{-44}{42} = \frac{-22}{21}
\lim_{b \to -4} \left(b^2\right) = 16
f(c) = 4 + 3 c + c^2, \quad g(a) = 3 + 3 a \implies f(g(a)) = 22 + 27 a + 9 a^2
56 - 15 a + a^2 = 0 \implies a \in \{ 7, 8 \}
\log_{4}\left(3 + c\right) = 3 \implies c = 61
u^3 \left(u + x\right) = u^3 x + u^4
\frac{-15}{49} = \frac{-15}{49}
-3 + c = 0 \implies c = 3
\lim_{w \to 4} \left(\cos{\left(w\right)}\right) = \cos{\left(4\right)}
-10 z \left(-x + z\right) = 10 x z - 10 z^2
84 - 19 c - 6 c^2 + c^3 = 0 \implies c \in \{ -4, 3, 7 \}
f(x) = 3 + x + x^2, \quad g(w) = 1 + w \implies f(g(w)) = 5 + 3 w + w^2
2 + u = 0 \implies u = -2
f(x) = 4 + 5 x + x^2, \quad g(t) = 1 + t \implies f(g(t)) = 10 + 7 t + t^2
60 - 28 x - 3 x^2 + x^3 = 0 \implies x \in \{ -5, 2, 6 \}
-8 \left(-5 + w\right) = 40 - 8 w
\lim_{v \to 0} \left(\cos{\left(v\right)}\right) = 1
f(x) = 2 + 2 x + x^2, \quad g(v) = 3 + v \implies f(g(v)) = 17 + 8 v + v^2
\log_{4}\left(1 + 2 u\right) = 3 \implies u = \frac{63}{2}
\int \left(\cos{\left(v\right)}\right) dv = \sin{\left(v\right)} + C
5 + z = 0 \implies z = -5
\log_{5}\left(8 + 4 c\right) = 1 \implies c = \frac{-3}{4}
\frac{d}{dz}\left(z\right) = 1
\int \left(1\right) dz = z + C
41 + 37 = 78
-24 + 5 z + z^2 = 0 \implies z \in \{ -8, 3 \}
\log_{5}\left(7 + 3 z\right) = 3 \implies z = \frac{118}{3}
\log_{3}\left(5 + 4 b\right) = 2 \implies b = 1
\log_{5}\left(8 + 2 t\right) = 1 \implies t = \frac{-3}{2}
f(z) = 4 + 5 z + z^2, \quad g(w) = 1 + w \implies f(g(w)) = 10 + 7 w + w^2
\log_{5}\left(6 + 2 w\right) = 3 \implies w = \frac{119}{2}
41 + 5 = 46
\log_{2}\left(4 + 2 y\right) = 3 \implies y = 2
\log_{3}\left(7 + 2 w\right) = 2 \implies w = 1
35 + 47 x + 13 x^2 + x^3 = 0 \implies x \in \{ -7, -5, -1 \}
\lim_{u \to 0} \left(-7 u\right) = 0
v^2 \left(8 + v\right) = 8 v^2 + v^3
\frac{-40}{26} = \frac{-20}{13}
\frac{d}{db}\left(b\right) = 1
-1 + z = 0 \implies z = 1
4 v - 5 v^2 + v^3 = 0 \implies v \in \{ 0, 1, 4 \}
5 + y = 0 \implies y = -5
\frac{d}{db}\left(b^4\right) = 4 b^3
-98 - 49 y + 2 y^2 + y^3 = 0 \implies y \in \{ -7, -2, 7 \}
t \left(t + x\right) = t x + t^2
\log_{4}\left(3 + 4 b\right) = 2 \implies b = \frac{13}{4}
\lim_{x \to 5} \left(x^2\right) = 25
1 + a = 0 \implies a = -1
32 + 12 t + t^2 = 0 \implies t \in \{ -8, -4 \}
\frac{40}{33} = \frac{40}{33}
\frac{30}{44} = \frac{15}{22}
(1, -4, 1) \times (-1, 4, 4) = (-20, -5, 0)
f(u) = 5 + u + u^2, \quad g(y) = 4 + 2 y \implies f(g(y)) = 25 + 18 y + 4 y^2
\lim_{u \to 0} \left(\sin{\left(u\right)}\right) = 0
-9 \cdot 28 = -252
\lim_{u \to -4} \left(2 u\right) = -8
\frac{d}{dz}\left(z^3 \cos{\left(z\right)}\right) = 3 z^2 \cos{\left(z\right)} - z^3 \sin{\left(z\right)}
-8 + 2 x + 5 x^2 + x^3 = 0 \implies x \in \{ -4, -2, 1 \}
\int \left(1\right) dy = y + C
(3, -5, -5) \times (5, 3, 4) = (-5, -37, 34)
-12 x - 4 x^2 + x^3 = 0 \implies x \in \{ -2, 0, 6 \}
6 + y = 0 \implies y = -6
\frac{d}{da}\left(-a + a^4\right) = -1 + 4 a^3
-20 - b + b^2 = 0 \implies b \in \{ -4, 5 \}
\int \left(3 c^2 \cos{\left(c\right)} - c^3 \sin{\left(c\right)}\right) dc = c^3 \cos{\left(c\right)} + C
f(u) = 1 + 5 u + u^2, \quad g(c) = 1 + 3 c \implies f(g(c)) = 7 + 21 c + 9 c^2
-32 - 4 y + y^2 = 0 \implies y \in \{ -4, 8 \}
t = 0 \implies t = 0
\frac{d}{dy}\left(0\right) = 0
6 - 7 y + y^2 = 0 \implies y \in \{ 1, 6 \}
-56 b - b^2 + b^3 = 0 \implies b \in \{ -7, 0, 8 \}
f(t) = 2 + 4 t + t^2, \quad g(x) = 2 + 3 x \implies f(g(x)) = 14 + 24 x + 9 x^2
\log_{4}\left(5 + 2 t\right) = 3 \implies t = \frac{59}{2}
\int \left(-1 + 2 x\right) dx = -x + x^2 + C
4 + u = 0 \implies u = -4
-4 + z = 0 \implies z = 4
-2 + y = 0 \implies y = 2