text
stringlengths
9
16.2k
-14 - 19 a - 4 a^2 + a^3 = 0 \implies a \in \{ -2, -1, 7 \}
-50 \cdot 2 = -100
20 \cdot 14 = 280
(-2, 5, 0) \times (-5, -1, -5) = (-25, -10, 27)
\int \left(2 y\right) dy = y^2 + C
4 + c = 0 \implies c = -4
-12 w + w^2 + w^3 = 0 \implies w \in \{ -4, 0, 3 \}
f(t) = 5 + 4 t + t^2, \quad g(w) = 4 + w \implies f(g(w)) = 37 + 12 w + w^2
\lim_{c \to 2} \left(0\right) = 0
-23 + 37 = 14
14 \cdot 3 = 42
f(z) = 4 + 5 z + z^2, \quad g(a) = 3 + 2 a \implies f(g(a)) = 28 + 22 a + 4 a^2
-7 + w = 0 \implies w = 7
\lim_{w \to 5} \left(w^2\right) = 25
f(c) = 5 + 3 c + c^2, \quad g(b) = 2 + 2 b \implies f(g(b)) = 15 + 14 b + 4 b^2
-3 + t = 0 \implies t = 3
\frac{d}{dc}\left(\cos{\left(c\right)}\right) = -\sin{\left(c\right)}
2 + 3 u + u^2 = 0 \implies u \in \{ -2, -1 \}
\frac{18}{15} = \frac{6}{5}
-6 + 5 w + w^2 = 0 \implies w \in \{ -6, 1 \}
-24 + 34 y - 11 y^2 + y^3 = 0 \implies y \in \{ 1, 4, 6 \}
\lim_{u \to 3} \left(2\right) = 2
f(c) = 3 + 5 c + c^2, \quad g(b) = 2 + 3 b \implies f(g(b)) = 17 + 27 b + 9 b^2
\lim_{c \to 3} \left(\cos{\left(c\right)}\right) = \cos{\left(3\right)}
\frac{d}{dc}\left(c\right) = 1
f(u) = 1 + 4 u + u^2, \quad g(w) = 3 + 3 w \implies f(g(w)) = 22 + 30 w + 9 w^2
1 - 4 = -3
-b + b^2 = 0 \implies b \in \{ 0, 1 \}
\frac{d}{dy}\left(-4\right) = 0
\log_{5}\left(4 + 4 w\right) = 2 \implies w = \frac{21}{4}
(4, 2, -2) \times (3, -5, -4) = (-18, 10, -26)
24 - 10 c + c^2 = 0 \implies c \in \{ 4, 6 \}
\lim_{t \to 3} \left(t^2\right) = 9
(5, 3, 0) \times (4, -2, -4) = (-12, 20, -22)
-23 \cdot 16 = -368
\log_{4}\left(6 + b\right) = 3 \implies b = 58
-11 + 35 = 24
-24 + 2 c + c^2 = 0 \implies c \in \{ -6, 4 \}
\frac{d}{dy}\left(\cos{\left(y\right)}\right) = -\sin{\left(y\right)}
x = 0 \implies x = 0
\log_{3}\left(1 + 2 y\right) = 3 \implies y = 13
w \left(-1 + w\right) = -w + w^2
-35 - 2 x + x^2 = 0 \implies x \in \{ -5, 7 \}
5 + y = 0 \implies y = -5
\int \left(2 a\right) da = a^2 + C
v \left(10 + v\right) = 10 v + v^2
\frac{d}{da}\left(a^3\right) = 3 a^2
f(x) = 3 + x + x^2, \quad g(y) = 3 + 3 y \implies f(g(y)) = 15 + 21 y + 9 y^2
\frac{d}{dy}\left(y^2\right) = 2 y
\frac{d}{dv}\left(v^2 \left(-5 + v\right)\right) = 2 v \left(-5 + v\right) + v^2
\log_{3}\left(6 + 3 v\right) = 1 \implies v = -1
\log_{5}\left(6 + 3 a\right) = 2 \implies a = \frac{19}{3}
\int \left(-\sin{\left(t\right)} + \cos{\left(t\right)}\right) dt = -1 + \sin{\left(t\right)} + \cos{\left(t\right)} + C
-49 + u^2 = 0 \implies u \in \{ -7, 7 \}
8 x + 6 x^2 + x^3 = 0 \implies x \in \{ -4, -2, 0 \}
\log_{3}\left(7 + 4 a\right) = 2 \implies a = \frac{1}{2}
42 - 13 t + t^2 = 0 \implies t \in \{ 6, 7 \}
-64 + c^2 = 0 \implies c \in \{ -8, 8 \}
\log_{3}\left(2 + 2 v\right) = 1 \implies v = \frac{1}{2}
28 - 11 z + z^2 = 0 \implies z \in \{ 4, 7 \}
\log_{5}\left(2 + 4 x\right) = 3 \implies x = \frac{123}{4}
\lim_{y \to -5} \left(y^2\right) = 25
(0, 1, -1) \times (-3, -1, 0) = (-1, 3, 3)
f(a) = 2 + 4 a + a^2, \quad g(u) = 3 + u \implies f(g(u)) = 23 + 10 u + u^2
144 - 54 x - x^2 + x^3 = 0 \implies x \in \{ -8, 3, 6 \}
-49 + 43 = -6
\lim_{y \to 4} \left(y\right) = 4
49 \cdot 33 = 1617
-32 - 49 = -81
\frac{-31}{21} = \frac{-31}{21}
y^3 \left(2 + w\right) = w y^3 + 2 y^3
35 - 12 a + a^2 = 0 \implies a \in \{ 5, 7 \}
\log_{3}\left(4 + 3 u\right) = 3 \implies u = \frac{23}{3}
\frac{30}{49} = \frac{30}{49}
\frac{d}{dx}\left(1 + x^3\right) = 3 x^2
\lim_{t \to -5} \left(t^3\right) = -125
\int \left(1\right) dz = z + C
f(x) = 1 + x + x^2, \quad g(w) = 4 + 3 w \implies f(g(w)) = 21 + 27 w + 9 w^2
f(u) = 4 + 5 u + u^2, \quad g(x) = 3 + x \implies f(g(x)) = 28 + 11 x + x^2
-48 - 14 u + 7 u^2 + u^3 = 0 \implies u \in \{ -8, -2, 3 \}
\frac{49}{34} = \frac{49}{34}
\frac{-42}{40} = \frac{-21}{20}
\lim_{a \to -4} \left(6 + a\right) = 2
f(x) = 1 + 4 x + x^2, \quad g(v) = 2 + v \implies f(g(v)) = 13 + 8 v + v^2
f(c) = 1 + 3 c + c^2, \quad g(y) = 3 + 3 y \implies f(g(y)) = 19 + 27 y + 9 y^2
\frac{d}{dy}\left(\sin{\left(y\right)}\right) = \cos{\left(y\right)}
\lim_{c \to 1} \left(\cos{\left(c\right)}\right) = \cos{\left(1\right)}
7 + x = 0 \implies x = -7
\int \left(1\right) db = b + C
\frac{-40}{33} = \frac{-40}{33}
f(w) = 3 + 4 w + w^2, \quad g(u) = 3 + 3 u \implies f(g(u)) = 24 + 30 u + 9 u^2
(-5, 4, 0) \times (-1, 5, -5) = (-20, -25, -21)
24 - 29 = -5
f(z) = 5 + 2 z + z^2, \quad g(v) = 1 + v \implies f(g(v)) = 8 + 4 v + v^2
29 \cdot 2 = 58
33 \cdot 20 = 660
-7 + a = 0 \implies a = 7
\lim_{u \to 1} \left(-9 + u\right) = -8
\lim_{z \to -1} \left(z^2\right) = 1
25 \cdot 45 = 1125