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f(b) = 5 + 4 b + b^2, \quad g(u) = 4 + 2 u \implies f(g(u)) = 37 + 24 u + 4 u^2
-14 - 39 = -53
\frac{d}{dz}\left(6 + 2 z\right) = 2
\log_{5}\left(2 + y\right) = 2 \implies y = 23
48 - 12 = 36
\frac{-50}{48} = \frac{-25}{24}
4 + t = 0 \implies t = -4
\lim_{x \to 5} \left(0\right) = 0
\frac{d}{dx}\left(-x^4 + \cos{\left(x\right)}\right) = -4 x^3 - \sin{\left(x\right)}
f(w) = 1 + 2 w + w^2, \quad g(c) = 2 + c \implies f(g(c)) = 9 + 6 c + c^2
-45 - 13 = -58
-14 - 5 b + b^2 = 0 \implies b \in \{ -2, 7 \}
4 - 3 = 1
-2 - 17 = -19
\lim_{t \to -1} \left(t\right) = -1
\frac{-6}{4} = \frac{-3}{2}
\lim_{t \to 1} \left(t^3\right) = 1
(0, 5, -3) \times (1, 1, 5) = (28, -3, -5)
\log_{5}\left(8 + 2 a\right) = 1 \implies a = \frac{-3}{2}
\left(a + y\right) \left(7 + y\right) = 7 a + 7 y + a y + y^2
8 + y = 0 \implies y = -8
f(y) = 1 + y + y^2, \quad g(c) = 4 + 3 c \implies f(g(c)) = 21 + 27 c + 9 c^2
2 + 3 v + v^2 = 0 \implies v \in \{ -2, -1 \}
\log_{2}\left(5 + y\right) = 3 \implies y = 3
a^2 \left(a + c\right) = a^2 c + a^3
17 \cdot 36 = 612
(5, -5, 3) \times (-4, 5, -4) = (5, 8, 5)
(4, 0, 0) \times (3, 5, -4) = (0, 16, 20)
38 - 24 = 14
f(z) = 2 + 2 z + z^2, \quad g(v) = 1 + 2 v \implies f(g(v)) = 5 + 8 v + 4 v^2
f(c) = 3 + 5 c + c^2, \quad g(y) = 3 + 2 y \implies f(g(y)) = 27 + 22 y + 4 y^2
\log_{3}\left(3 + 3 u\right) = 3 \implies u = 8
(0, 4, 0) \times (3, -2, -5) = (-20, 0, -12)
\lim_{b \to -5} \left(3\right) = 3
\frac{d}{dt}\left(t\right) = 1
(1, -4, -3) \times (-1, 3, 2) = (1, 1, -1)
\frac{d}{dt}\left(t\right) = 1
\lim_{z \to 0} \left(2 z\right) = 0
\lim_{z \to -1} \left(0\right) = 0
\int \left(1\right) dv = v + C
\int \left(\cos{\left(t\right)}\right) dt = \sin{\left(t\right)} + C
-20 + 47 = 27
\lim_{c \to 2} \left(c^2\right) = 4
\int \left(-2 t - \sin{\left(t\right)}\right) dt = -1 - t^2 + \cos{\left(t\right)} + C
14 - 9 = 5
1 + w = 0 \implies w = -1
\int \left(3 u^2\right) du = u^3 + C
\log_{3}\left(5 + 4 u\right) = 1 \implies u = \frac{-1}{2}
6 + 7 y + y^2 = 0 \implies y \in \{ -6, -1 \}
\lim_{t \to 4} \left(\cos{\left(t\right)}\right) = \cos{\left(4\right)}
\log_{4}\left(1 + w\right) = 2 \implies w = 15
3 + z = 0 \implies z = -3
(-4, -4, 2) \times (-1, -4, -1) = (12, -6, 12)
\lim_{t \to 4} \left(-5\right) = -5
15 + 8 a + a^2 = 0 \implies a \in \{ -5, -3 \}
9 \cdot 33 = 297
\frac{d}{da}\left(-\left(3 + a\right)\right) = -1
-42 - z + z^2 = 0 \implies z \in \{ -6, 7 \}
-35 - 19 = -54
(-4, 1, 5) \times (-3, 3, -3) = (-18, -27, -9)
\log_{3}\left(2 + 4 c\right) = 2 \implies c = \frac{7}{4}
f(z) = 2 + 2 z + z^2, \quad g(w) = 4 + 2 w \implies f(g(w)) = 26 + 20 w + 4 w^2
\log_{5}\left(6 + 3 c\right) = 3 \implies c = \frac{119}{3}
\log_{4}\left(8 + z\right) = 3 \implies z = 56
(3, 0, 4) \times (4, -5, 0) = (20, 16, -15)
\int \left(-1\right) dv = -v + C
\lim_{y \to 3} \left(0\right) = 0
\log_{5}\left(1 + 2 v\right) = 1 \implies v = 2
f(t) = 2 + 2 t + t^2, \quad g(c) = 1 + 3 c \implies f(g(c)) = 5 + 12 c + 9 c^2
\lim_{c \to -2} \left(-2 + c\right) = -4
f(u) = 5 + 2 u + u^2, \quad g(z) = 1 + z \implies f(g(z)) = 8 + 4 z + z^2
\lim_{u \to 1} \left(11\right) = 11
\int \left(-1 - \sin{\left(t\right)}\right) dt = -1 - t + \cos{\left(t\right)} + C
4 + w = 0 \implies w = -4
\int \left(3 b^2 + \cos{\left(b\right)}\right) db = b^3 + \sin{\left(b\right)} + C
-24 z - 5 z^2 + z^3 = 0 \implies z \in \{ -3, 0, 8 \}
\int \left(1\right) dz = z + C
\log_{3}\left(4 + 2 y\right) = 3 \implies y = \frac{23}{2}
45 - 47 = -2
\frac{-18}{11} = \frac{-18}{11}
-21 + 11 u + 9 u^2 + u^3 = 0 \implies u \in \{ -7, -3, 1 \}
30 \cdot 13 = 390
\lim_{c \to -3} \left(-3\right) = -3
f(b) = 5 + 2 b + b^2, \quad g(w) = 1 + 3 w \implies f(g(w)) = 8 + 12 w + 9 w^2
f(u) = 1 + 5 u + u^2, \quad g(z) = 3 + 3 z \implies f(g(z)) = 25 + 33 z + 9 z^2
(-4, 0, 4) \times (0, -2, -5) = (8, -20, 8)
f(c) = 3 + 4 c + c^2, \quad g(a) = 4 + 3 a \implies f(g(a)) = 35 + 36 a + 9 a^2
39 + 12 = 51
-32 \cdot 46 = -1472
\left(c - z\right) z^4 = c z^4 - z^5
-5 + b = 0 \implies b = 5
f(b) = 1 + 3 b + b^2, \quad g(y) = 4 + y \implies f(g(y)) = 29 + 11 y + y^2
-7 + 24 = 17
\lim_{b \to -4} \left(3 + b\right) = -1
-126 + 81 a - 16 a^2 + a^3 = 0 \implies a \in \{ 3, 6, 7 \}
30 + 50 = 80
-7 + t = 0 \implies t = 7
\lim_{c \to -4} \left(\sin{\left(c\right)}\right) = -\sin{\left(4\right)}
\frac{27}{36} = \frac{3}{4}
-8 + w = 0 \implies w = 8