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-9 t \left(10 + a\right) = -90 t - 9 a t
-9 + a^2 = 0 \implies a \in \{ -3, 3 \}
\int \left(3 v^2\right) dv = v^3 + C
-240 - 58 w + 3 w^2 + w^3 = 0 \implies w \in \{ -6, -5, 8 \}
\int \left(1\right) dw = w + C
4 + y = 0 \implies y = -4
f(w) = 4 + 3 w + w^2, \quad g(x) = 1 + x \implies f(g(x)) = 8 + 5 x + x^2
-7 w + w^2 = 0 \implies w \in \{ 0, 7 \}
\log_{5}\left(3 + 2 c\right) = 3 \implies c = 61
-6 - v + v^2 = 0 \implies v \in \{ -2, 3 \}
\lim_{y \to -5} \left(2 y\right) = -10
2 + 3 b + b^2 = 0 \implies b \in \{ -2, -1 \}
\log_{2}\left(5 + 3 v\right) = 3 \implies v = 1
\log_{5}\left(4 + 2 z\right) = 1 \implies z = \frac{1}{2}
-19 - 15 = -34
\int \left(2 \sin{\left(b\right)} \cos{\left(b\right)}\right) db = \sin{\left(b\right)}^2 + C
t w \left(2 + t\right) = 2 t w + t^2 w
\int \left(\cos{\left(a\right)}\right) da = \sin{\left(a\right)} + C
\int \left(-8\right) dv = -8 v + C
-41 - 37 = -78
f(b) = 2 + 3 b + b^2, \quad g(c) = 4 + c \implies f(g(c)) = 30 + 11 c + c^2
\frac{-26}{49} = \frac{-26}{49}
\int \left(3 a^2\right) da = a^3 + C
-34 + 38 = 4
-7 + w = 0 \implies w = 7
\log_{5}\left(6 + y\right) = 2 \implies y = 19
-36 - 32 = -68
f(z) = 1 + 3 z + z^2, \quad g(a) = 3 + 2 a \implies f(g(a)) = 19 + 18 a + 4 a^2
\left(t + z\right) \left(-5 + z\right) = -5 t - 5 z + t z + z^2
11 + 12 = 23
\int \left(-2 x \sin{\left(x\right)} + 2 \cos{\left(x\right)}\right) dx = 2 x \cos{\left(x\right)} + C
\log_{4}\left(6 + 4 a\right) = 3 \implies a = \frac{29}{2}
44 \cdot 25 = 1100
5 u + u^2 = 0 \implies u \in \{ -5, 0 \}
\lim_{a \to -5} \left(8 + a\right) = 3
f(y) = 4 + 5 y + y^2, \quad g(c) = 4 + c \implies f(g(c)) = 40 + 13 c + c^2
f(w) = 1 + 4 w + w^2, \quad g(t) = 3 + 2 t \implies f(g(t)) = 22 + 20 t + 4 t^2
(-5, -2, -5) \times (-2, -5, -1) = (-23, 5, 21)
-19 + 45 = 26
\frac{d}{dt}\left(-8\right) = 0
(3, -2, 4) \times (4, 2, -5) = (2, 31, 14)
-32 - 4 w + 8 w^2 + w^3 = 0 \implies w \in \{ -8, -2, 2 \}
\int \left(1\right) dx = x + C
f(w) = 5 + 2 w + w^2, \quad g(a) = 2 + a \implies f(g(a)) = 13 + 6 a + a^2
(4, -5, 1) \times (-2, -4, 2) = (-6, -10, -26)
\frac{d}{dw}\left(w\right) = 1
-37 - 19 = -56
\int \left(1 - \cos{\left(y\right)}\right) dy = y - \sin{\left(y\right)} + C
35 - 12 v + v^2 = 0 \implies v \in \{ 5, 7 \}
-23 - 45 = -68
\frac{d}{du}\left(4 u\right) = 4
30 \cdot 30 = 900
\int \left(2 b \cos{\left(b\right)} - b^2 \sin{\left(b\right)}\right) db = b^2 \cos{\left(b\right)} + C
\frac{d}{dx}\left(x^4\right) = 4 x^3
\log_{5}\left(6 + x\right) = 2 \implies x = 19
\log_{5}\left(2 + 3 w\right) = 1 \implies w = 1
\log_{3}\left(6 + 4 u\right) = 2 \implies u = \frac{3}{4}
-3 + 45 = 42
-3 \left(2 - t\right) = -6 + 3 t
8 + c = 0 \implies c = -8
\frac{d}{db}\left(b^2\right) = 2 b
\log_{5}\left(3 + t\right) = 1 \implies t = 2
3 c + c^2 = 0 \implies c \in \{ -3, 0 \}
f(x) = 3 + 2 x + x^2, \quad g(c) = 4 + c \implies f(g(c)) = 27 + 10 c + c^2
4 + 5 z + z^2 = 0 \implies z \in \{ -4, -1 \}
\log_{3}\left(7 + 2 t\right) = 2 \implies t = 1
f(t) = 1 + 4 t + t^2, \quad g(b) = 2 + 2 b \implies f(g(b)) = 13 + 16 b + 4 b^2
\left(3 + y\right) \left(2 + y\right) = 6 + 5 y + y^2
10 + 16 = 26
43 \cdot 18 = 774
\log_{2}\left(3 + y\right) = 3 \implies y = 5
f(x) = 5 + 5 x + x^2, \quad g(t) = 2 + t \implies f(g(t)) = 19 + 9 t + t^2
\frac{d}{dx}\left(2 x - \left(9 + x\right)\right) = 1
\int \left(1 - 3 w^2\right) dw = w - w^3 + C
-5 - 4 c + c^2 = 0 \implies c \in \{ -1, 5 \}
8 + 19 = 27
\lim_{t \to 4} \left(-3\right) = -3
-12 + 13 = 1
\lim_{x \to 3} \left(2 x\right) = 6
\lim_{b \to 0} \left(b^2\right) = 0
1 + z = 0 \implies z = -1
80 + 66 u + 15 u^2 + u^3 = 0 \implies u \in \{ -8, -5, -2 \}
-2 v + v^2 = 0 \implies v \in \{ 0, 2 \}
\left(c + z\right) c^2 = c^2 z + c^3
-28 - 4 w + 7 w^2 + w^3 = 0 \implies w \in \{ -7, -2, 2 \}
w = 0 \implies w = 0
-14 - 19 u - 4 u^2 + u^3 = 0 \implies u \in \{ -2, -1, 7 \}
f(b) = 3 + 5 b + b^2, \quad g(u) = 3 + u \implies f(g(u)) = 27 + 11 u + u^2
-144 + 90 t - 17 t^2 + t^3 = 0 \implies t \in \{ 3, 6, 8 \}
\frac{1}{14} = \frac{1}{14}
1 + b = 0 \implies b = -1
\left(4 + b\right) \left(1 + c\right) = 4 + b + 4 c + b c
48 - 34 u + 3 u^2 + u^3 = 0 \implies u \in \{ -8, 2, 3 \}
-6 + x = 0 \implies x = 6
60 - 17 a - 4 a^2 + a^3 = 0 \implies a \in \{ -4, 3, 5 \}
-8 - 16 = -24
\log_{4}\left(7 + 3 c\right) = 3 \implies c = 19
35 - 9 = 26
f(c) = 4 + 3 c + c^2, \quad g(a) = 1 + a \implies f(g(a)) = 8 + 5 a + a^2
u = 0 \implies u = 0