Download data/DWSIM.MathOps.Mapack/LuDecomposition.cs from introvoyz041/Dwsim: direct link, hf CLI and curl.
- Browser
- Download file 8.08 kB
-
https://huggingface.co/datasets/introvoyz041/Dwsim/resolve/main/data/DWSIM.MathOps.Mapack/LuDecomposition.cs
- Command line
-
hf download hf://datasets/introvoyz041/Dwsim/data/DWSIM.MathOps.Mapack/LuDecomposition.cs
-
curl -L -o LuDecomposition.cs https://huggingface.co/datasets/introvoyz041/Dwsim/resolve/main/data/DWSIM.MathOps.Mapack/LuDecomposition.cs
8.08 kB
| namespace Mapack | |
| { | |
| using System; | |
| /// <summary>LU decomposition of a rectangular matrix.</summary> | |
| /// <remarks> | |
| /// For an m-by-n matrix <c>A</c> with m >= n, the LU decomposition is an m-by-n | |
| /// unit lower triangular matrix <c>L</c>, an n-by-n upper triangular matrix <c>U</c>, | |
| /// and a permutation vector <c>piv</c> of length m so that <c>A(piv)=L*U</c>. | |
| /// If m < n, then <c>L</c> is m-by-m and <c>U</c> is m-by-n. | |
| /// The LU decompostion with pivoting always exists, even if the matrix is | |
| /// singular, so the constructor will never fail. The primary use of the | |
| /// LU decomposition is in the solution of square systems of simultaneous | |
| /// linear equations. This will fail if <see cref="NonSingular"/> returns <see langword="false"/>. | |
| /// </remarks> | |
| public class LuDecomposition | |
| { | |
| private Matrix LU; | |
| private int pivotSign; | |
| private int[] pivotVector; | |
| /// <summary>Construct a LU decomposition.</summary> | |
| public LuDecomposition(Matrix value) | |
| { | |
| if (value == null) | |
| { | |
| throw new ArgumentNullException("value"); | |
| } | |
| this.LU = (Matrix) value.Clone(); | |
| double[][] lu = LU.Array; | |
| int rows = value.Rows; | |
| int columns = value.Columns; | |
| pivotVector = new int[rows]; | |
| for (int i = 0; i < rows; i++) | |
| { | |
| pivotVector[i] = i; | |
| } | |
| pivotSign = 1; | |
| double[] LUrowi; | |
| double[] LUcolj = new double[rows]; | |
| // Outer loop. | |
| for (int j = 0; j < columns; j++) | |
| { | |
| // Make a copy of the j-th column to localize references. | |
| for (int i = 0; i < rows; i++) | |
| { | |
| LUcolj[i] = lu[i][j]; | |
| } | |
| // Apply previous transformations. | |
| for (int i = 0; i < rows; i++) | |
| { | |
| LUrowi = lu[i]; | |
| // Most of the time is spent in the following dot product. | |
| int kmax = Math.Min(i,j); | |
| double s = 0.0; | |
| for (int k = 0; k < kmax; k++) | |
| { | |
| s += LUrowi[k]*LUcolj[k]; | |
| } | |
| LUrowi[j] = LUcolj[i] -= s; | |
| } | |
| // Find pivot and exchange if necessary. | |
| int p = j; | |
| for (int i = j+1; i < rows; i++) | |
| { | |
| if (Math.Abs(LUcolj[i]) > Math.Abs(LUcolj[p])) | |
| { | |
| p = i; | |
| } | |
| } | |
| if (p != j) | |
| { | |
| for (int k = 0; k < columns; k++) | |
| { | |
| double t = lu[p][k]; | |
| lu[p][k] = lu[j][k]; | |
| lu[j][k] = t; | |
| } | |
| int v = pivotVector[p]; | |
| pivotVector[p] = pivotVector[j]; | |
| pivotVector[j] = v; | |
| pivotSign = - pivotSign; | |
| } | |
| // Compute multipliers. | |
| if (j < rows & lu[j][j] != 0.0) | |
| { | |
| for (int i = j+1; i < rows; i++) | |
| { | |
| lu[i][j] /= lu[j][j]; | |
| } | |
| } | |
| } | |
| } | |
| /// <summary>Returns if the matrix is non-singular.</summary> | |
| public bool NonSingular | |
| { | |
| get | |
| { | |
| for (int j = 0; j < LU.Columns; j++) | |
| if (LU[j, j] == 0) | |
| return false; | |
| return true; | |
| } | |
| } | |
| /// <summary>Returns the determinant of the matrix.</summary> | |
| public double Determinant | |
| { | |
| get | |
| { | |
| if (LU.Rows != LU.Columns) throw new ArgumentException("Matrix must be square."); | |
| double determinant = (double) pivotSign; | |
| for (int j = 0; j < LU.Columns; j++) | |
| determinant *= LU[j, j]; | |
| return determinant; | |
| } | |
| } | |
| /// <summary>Returns the lower triangular factor <c>L</c> with <c>A=LU</c>.</summary> | |
| public Matrix LowerTriangularFactor | |
| { | |
| get | |
| { | |
| int rows = LU.Rows; | |
| int columns = LU.Columns; | |
| Matrix X = new Matrix(rows, columns); | |
| for (int i = 0; i < rows; i++) | |
| for (int j = 0; j < columns; j++) | |
| if (i > j) | |
| X[i,j] = LU[i,j]; | |
| else if (i == j) | |
| X[i,j] = 1.0; | |
| else | |
| X[i,j] = 0.0; | |
| return X; | |
| } | |
| } | |
| /// <summary>Returns the lower triangular factor <c>L</c> with <c>A=LU</c>.</summary> | |
| public Matrix UpperTriangularFactor | |
| { | |
| get | |
| { | |
| int rows = LU.Rows; | |
| int columns = LU.Columns; | |
| Matrix X = new Matrix(rows, columns); | |
| for (int i = 0; i < rows; i++) | |
| for (int j = 0; j < columns; j++) | |
| if (i <= j) | |
| X[i,j] = LU[i,j]; | |
| else | |
| X[i,j] = 0.0; | |
| return X; | |
| } | |
| } | |
| /// <summary>Returns the pivot permuation vector.</summary> | |
| public double[] PivotPermutationVector | |
| { | |
| get | |
| { | |
| int rows = LU.Rows; | |
| double[] p = new double[rows]; | |
| for (int i = 0; i < rows; i++) | |
| { | |
| p[i] = (double) this.pivotVector[i]; | |
| } | |
| return p; | |
| } | |
| } | |
| /// <summary>Solves a set of equation systems of type <c>A * X = B</c>.</summary> | |
| /// <param name="value">Right hand side matrix with as many rows as <c>A</c> and any number of columns.</param> | |
| /// <returns>Matrix <c>X</c> so that <c>L * U * X = B</c>.</returns> | |
| public Matrix Solve(Matrix value) | |
| { | |
| if (value == null) | |
| { | |
| throw new ArgumentNullException("value"); | |
| } | |
| if (value.Rows != this.LU.Rows) | |
| { | |
| throw new ArgumentException("Invalid matrix dimensions.", "value"); | |
| } | |
| if (!this.NonSingular) | |
| { | |
| throw new InvalidOperationException("Matrix is singular"); | |
| } | |
| // Copy right hand side with pivoting | |
| int count = value.Columns; | |
| Matrix X = value.Submatrix(pivotVector, 0, count-1); | |
| int rows = LU.Rows; | |
| int columns = LU.Columns; | |
| double[][] lu = LU.Array; | |
| // Solve L*Y = B(piv,:) | |
| for (int k = 0; k < columns; k++) | |
| { | |
| for (int i = k + 1; i < columns; i++) | |
| { | |
| for (int j = 0; j < count; j++) | |
| { | |
| X[i,j] -= X[k,j] * lu[i][k]; | |
| } | |
| } | |
| } | |
| // Solve U*X = Y; | |
| for (int k = columns - 1; k >= 0; k--) | |
| { | |
| for (int j = 0; j < count; j++) | |
| { | |
| X[k,j] /= lu[k][k]; | |
| } | |
| for (int i = 0; i < k; i++) | |
| { | |
| for (int j = 0; j < count; j++) | |
| { | |
| X[i,j] -= X[k,j] * lu[i][k]; | |
| } | |
| } | |
| } | |
| return X; | |
| } | |
| } | |
| } | |