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| // ---------------------------------------------- | |
| // Lutz Roeder's Mapack for .NET, September 2000 | |
| // Adapted from Mapack for COM and Jama routines. | |
| // http://www.aisto.com/roeder/dotnet | |
| // ---------------------------------------------- | |
| namespace Mapack | |
| { | |
| using System; | |
| /// <summary> | |
| /// Singular Value Decomposition for a rectangular matrix. | |
| /// </summary> | |
| /// <remarks> | |
| /// For an m-by-n matrix <c>A</c> with <c>m >= n</c>, the singular value decomposition is | |
| /// an m-by-n orthogonal matrix <c>U</c>, an n-by-n diagonal matrix <c>S</c>, and | |
| /// an n-by-n orthogonal matrix <c>V</c> so that <c>A = U * S * V'</c>. | |
| /// The singular values, <c>sigma[k] = S[k,k]</c>, are ordered so that | |
| /// <c>sigma[0] >= sigma[1] >= ... >= sigma[n-1]</c>. | |
| /// The singular value decompostion always exists, so the constructor will | |
| /// never fail. The matrix condition number and the effective numerical | |
| /// rank can be computed from this decomposition. | |
| /// </remarks> | |
| public class SingularValueDecomposition | |
| { | |
| private Matrix U; | |
| private Matrix V; | |
| private double[] s; // singular values | |
| private int m; | |
| private int n; | |
| /// <summary>Construct singular value decomposition.</summary> | |
| public SingularValueDecomposition(Matrix value) | |
| { | |
| if (value == null) | |
| { | |
| throw new ArgumentNullException("value"); | |
| } | |
| Matrix copy = (Matrix) value.Clone(); | |
| double[][] a = copy.Array; | |
| m = value.Rows; | |
| n = value.Columns; | |
| int nu = Math.Min(m,n); | |
| s = new double [Math.Min(m+1,n)]; | |
| U = new Matrix(m, nu); | |
| V = new Matrix(n, n); | |
| double[][] u = U.Array; | |
| double[][] v = V.Array; | |
| double[] e = new double [n]; | |
| double[] work = new double [m]; | |
| bool wantu = true; | |
| bool wantv = true; | |
| // Reduce A to bidiagonal form, storing the diagonal elements in s and the super-diagonal elements in e. | |
| int nct = Math.Min(m-1,n); | |
| int nrt = Math.Max(0,Math.Min(n-2,m)); | |
| for (int k = 0; k < Math.Max(nct,nrt); k++) | |
| { | |
| if (k < nct) | |
| { | |
| // Compute the transformation for the k-th column and place the k-th diagonal in s[k]. | |
| // Compute 2-norm of k-th column without under/overflow. | |
| s[k] = 0; | |
| for (int i = k; i < m; i++) | |
| { | |
| s[k] = Hypotenuse(s[k],a[i][k]); | |
| } | |
| if (s[k] != 0.0) | |
| { | |
| if (a[k][k] < 0.0) | |
| { | |
| s[k] = -s[k]; | |
| } | |
| for (int i = k; i < m; i++) | |
| { | |
| a[i][k] /= s[k]; | |
| } | |
| a[k][k] += 1.0; | |
| } | |
| s[k] = -s[k]; | |
| } | |
| for (int j = k+1; j < n; j++) | |
| { | |
| if ((k < nct) & (s[k] != 0.0)) | |
| { | |
| // Apply the transformation. | |
| double t = 0; | |
| for (int i = k; i < m; i++) | |
| t += a[i][k]*a[i][j]; | |
| t = -t/a[k][k]; | |
| for (int i = k; i < m; i++) | |
| a[i][j] += t*a[i][k]; | |
| } | |
| // Place the k-th row of A into e for the subsequent calculation of the row transformation. | |
| e[j] = a[k][j]; | |
| } | |
| if (wantu & (k < nct)) | |
| { | |
| // Place the transformation in U for subsequent back | |
| // multiplication. | |
| for (int i = k; i < m; i++) | |
| u[i][k] = a[i][k]; | |
| } | |
| if (k < nrt) | |
| { | |
| // Compute the k-th row transformation and place the k-th super-diagonal in e[k]. | |
| // Compute 2-norm without under/overflow. | |
| e[k] = 0; | |
| for (int i = k+1; i < n; i++) | |
| { | |
| e[k] = Hypotenuse(e[k],e[i]); | |
| } | |
| if (e[k] != 0.0) | |
| { | |
| if (e[k+1] < 0.0) | |
| e[k] = -e[k]; | |
| for (int i = k+1; i < n; i++) | |
| e[i] /= e[k]; | |
| e[k+1] += 1.0; | |
| } | |
| e[k] = -e[k]; | |
| if ((k+1 < m) & (e[k] != 0.0)) | |
| { | |
| // Apply the transformation. | |
| for (int i = k+1; i < m; i++) | |
| work[i] = 0.0; | |
| for (int j = k+1; j < n; j++) | |
| for (int i = k+1; i < m; i++) | |
| work[i] += e[j]*a[i][j]; | |
| for (int j = k+1; j < n; j++) | |
| { | |
| double t = -e[j]/e[k+1]; | |
| for (int i = k+1; i < m; i++) | |
| a[i][j] += t*work[i]; | |
| } | |
| } | |
| if (wantv) | |
| { | |
| // Place the transformation in V for subsequent back multiplication. | |
| for (int i = k+1; i < n; i++) | |
| v[i][k] = e[i]; | |
| } | |
| } | |
| } | |
| // Set up the final bidiagonal matrix or order p. | |
| int p = Math.Min(n,m+1); | |
| if (nct < n) s[nct] = a[nct][nct]; | |
| if (m < p) s[p-1] = 0.0; | |
| if (nrt+1 < p) e[nrt] = a[nrt][p-1]; | |
| e[p-1] = 0.0; | |
| // If required, generate U. | |
| if (wantu) | |
| { | |
| for (int j = nct; j < nu; j++) | |
| { | |
| for (int i = 0; i < m; i++) | |
| u[i][j] = 0.0; | |
| u[j][j] = 1.0; | |
| } | |
| for (int k = nct-1; k >= 0; k--) | |
| { | |
| if (s[k] != 0.0) | |
| { | |
| for (int j = k+1; j < nu; j++) | |
| { | |
| double t = 0; | |
| for (int i = k; i < m; i++) | |
| t += u[i][k]*u[i][j]; | |
| t = -t/u[k][k]; | |
| for (int i = k; i < m; i++) | |
| u[i][j] += t*u[i][k]; | |
| } | |
| for (int i = k; i < m; i++ ) | |
| u[i][k] = -u[i][k]; | |
| u[k][k] = 1.0 + u[k][k]; | |
| for (int i = 0; i < k-1; i++) | |
| u[i][k] = 0.0; | |
| } | |
| else | |
| { | |
| for (int i = 0; i < m; i++) | |
| u[i][k] = 0.0; | |
| u[k][k] = 1.0; | |
| } | |
| } | |
| } | |
| // If required, generate V. | |
| if (wantv) | |
| { | |
| for (int k = n-1; k >= 0; k--) | |
| { | |
| if ((k < nrt) & (e[k] != 0.0)) | |
| { | |
| for (int j = k+1; j < nu; j++) | |
| { | |
| double t = 0; | |
| for (int i = k+1; i < n; i++) | |
| t += v[i][k]*v[i][j]; | |
| t = -t/v[k+1][k]; | |
| for (int i = k+1; i < n; i++) | |
| v[i][j] += t*v[i][k]; | |
| } | |
| } | |
| for (int i = 0; i < n; i++) | |
| v[i][k] = 0.0; | |
| v[k][k] = 1.0; | |
| } | |
| } | |
| // Main iteration loop for the singular values. | |
| int pp = p-1; | |
| int iter = 0; | |
| double eps = Math.Pow(2.0,-52.0); | |
| while (p > 0) | |
| { | |
| int k,kase; | |
| // Here is where a test for too many iterations would go. | |
| // This section of the program inspects for | |
| // negligible elements in the s and e arrays. On | |
| // completion the variables kase and k are set as follows. | |
| // kase = 1 if s(p) and e[k-1] are negligible and k<p | |
| // kase = 2 if s(k) is negligible and k<p | |
| // kase = 3 if e[k-1] is negligible, k<p, and s(k), ..., s(p) are not negligible (qr step). | |
| // kase = 4 if e(p-1) is negligible (convergence). | |
| for (k = p-2; k >= -1; k--) | |
| { | |
| if (k == -1) | |
| break; | |
| if (Math.Abs(e[k]) <= eps*(Math.Abs(s[k]) + Math.Abs(s[k+1]))) | |
| { | |
| e[k] = 0.0; | |
| break; | |
| } | |
| } | |
| if (k == p-2) | |
| { | |
| kase = 4; | |
| } | |
| else | |
| { | |
| int ks; | |
| for (ks = p-1; ks >= k; ks--) | |
| { | |
| if (ks == k) | |
| break; | |
| double t = (ks != p ? Math.Abs(e[ks]) : 0.0) + (ks != k+1 ? Math.Abs(e[ks-1]) : 0.0); | |
| if (Math.Abs(s[ks]) <= eps*t) | |
| { | |
| s[ks] = 0.0; | |
| break; | |
| } | |
| } | |
| if (ks == k) | |
| kase = 3; | |
| else if (ks == p-1) | |
| kase = 1; | |
| else | |
| { | |
| kase = 2; | |
| k = ks; | |
| } | |
| } | |
| k++; | |
| // Perform the task indicated by kase. | |
| switch (kase) | |
| { | |
| // Deflate negligible s(p). | |
| case 1: | |
| { | |
| double f = e[p-2]; | |
| e[p-2] = 0.0; | |
| for (int j = p-2; j >= k; j--) | |
| { | |
| double t = Hypotenuse(s[j],f); | |
| double cs = s[j]/t; | |
| double sn = f/t; | |
| s[j] = t; | |
| if (j != k) | |
| { | |
| f = -sn*e[j-1]; | |
| e[j-1] = cs*e[j-1]; | |
| } | |
| if (wantv) | |
| { | |
| for (int i = 0; i < n; i++) | |
| { | |
| t = cs*v[i][j] + sn*v[i][p-1]; | |
| v[i][p-1] = -sn*v[i][j] + cs*v[i][p-1]; | |
| v[i][j] = t; | |
| } | |
| } | |
| } | |
| } | |
| break; | |
| // Split at negligible s(k). | |
| case 2: | |
| { | |
| double f = e[k-1]; | |
| e[k-1] = 0.0; | |
| for (int j = k; j < p; j++) | |
| { | |
| double t = Hypotenuse(s[j],f); | |
| double cs = s[j]/t; | |
| double sn = f/t; | |
| s[j] = t; | |
| f = -sn*e[j]; | |
| e[j] = cs*e[j]; | |
| if (wantu) | |
| { | |
| for (int i = 0; i < m; i++) | |
| { | |
| t = cs*u[i][j] + sn*u[i][k-1]; | |
| u[i][k-1] = -sn*u[i][j] + cs*u[i][k-1]; | |
| u[i][j] = t; | |
| } | |
| } | |
| } | |
| } | |
| break; | |
| // Perform one qr step. | |
| case 3: | |
| { | |
| // Calculate the shift. | |
| double scale = Math.Max(Math.Max(Math.Max(Math.Max(Math.Abs(s[p-1]),Math.Abs(s[p-2])),Math.Abs(e[p-2])), Math.Abs(s[k])),Math.Abs(e[k])); | |
| double sp = s[p-1]/scale; | |
| double spm1 = s[p-2]/scale; | |
| double epm1 = e[p-2]/scale; | |
| double sk = s[k]/scale; | |
| double ek = e[k]/scale; | |
| double b = ((spm1 + sp)*(spm1 - sp) + epm1*epm1)/2.0; | |
| double c = (sp*epm1)*(sp*epm1); | |
| double shift = 0.0; | |
| if ((b != 0.0) | (c != 0.0)) | |
| { | |
| shift = Math.Sqrt(b*b + c); | |
| if (b < 0.0) | |
| shift = -shift; | |
| shift = c/(b + shift); | |
| } | |
| double f = (sk + sp)*(sk - sp) + shift; | |
| double g = sk*ek; | |
| // Chase zeros. | |
| for (int j = k; j < p-1; j++) | |
| { | |
| double t = Hypotenuse(f,g); | |
| double cs = f/t; | |
| double sn = g/t; | |
| if (j != k) | |
| e[j-1] = t; | |
| f = cs*s[j] + sn*e[j]; | |
| e[j] = cs*e[j] - sn*s[j]; | |
| g = sn*s[j+1]; | |
| s[j+1] = cs*s[j+1]; | |
| if (wantv) | |
| { | |
| for (int i = 0; i < n; i++) | |
| { | |
| t = cs*v[i][j] + sn*v[i][j+1]; | |
| v[i][j+1] = -sn*v[i][j] + cs*v[i][j+1]; | |
| v[i][j] = t; | |
| } | |
| } | |
| t = Hypotenuse(f, g); | |
| cs = f/t; | |
| sn = g/t; | |
| s[j] = t; | |
| f = cs*e[j] + sn*s[j+1]; | |
| s[j+1] = -sn*e[j] + cs*s[j+1]; | |
| g = sn*e[j+1]; | |
| e[j+1] = cs*e[j+1]; | |
| if (wantu && (j < m-1)) | |
| { | |
| for (int i = 0; i < m; i++) | |
| { | |
| t = cs*u[i][j] + sn*u[i][j+1]; | |
| u[i][j+1] = -sn*u[i][j] + cs*u[i][j+1]; | |
| u[i][j] = t; | |
| } | |
| } | |
| } | |
| e[p-2] = f; | |
| iter = iter + 1; | |
| } | |
| break; | |
| // Convergence. | |
| case 4: | |
| { | |
| // Make the singular values positive. | |
| if (s[k] <= 0.0) | |
| { | |
| s[k] = (s[k] < 0.0 ? -s[k] : 0.0); | |
| if (wantv) | |
| for (int i = 0; i <= pp; i++) | |
| v[i][k] = -v[i][k]; | |
| } | |
| // Order the singular values. | |
| while (k < pp) | |
| { | |
| if (s[k] >= s[k+1]) | |
| break; | |
| double t = s[k]; | |
| s[k] = s[k+1]; | |
| s[k+1] = t; | |
| if (wantv && (k < n-1)) | |
| for (int i = 0; i < n; i++) | |
| { | |
| t = v[i][k+1]; | |
| v[i][k+1] = v[i][k]; | |
| v[i][k] = t; | |
| } | |
| if (wantu && (k < m-1)) | |
| for (int i = 0; i < m; i++) | |
| { | |
| t = u[i][k+1]; | |
| u[i][k+1] = u[i][k]; | |
| u[i][k] = t; | |
| } | |
| k++; | |
| } | |
| iter = 0; | |
| p--; | |
| } | |
| break; | |
| } | |
| } | |
| } | |
| /// <summary>Returns the condition number <c>max(S) / min(S)</c>.</summary> | |
| public double Condition | |
| { | |
| get | |
| { | |
| return s[0] / s[Math.Min(m, n) - 1]; | |
| } | |
| } | |
| /// <summary>Returns the Two norm.</summary> | |
| public double Norm2 | |
| { | |
| get | |
| { | |
| return s[0]; | |
| } | |
| } | |
| /// <summary>Returns the effective numerical matrix rank.</summary> | |
| /// <value>Number of non-negligible singular values.</value> | |
| public int Rank | |
| { | |
| get | |
| { | |
| double eps = Math.Pow(2.0,-52.0); | |
| double tol = Math.Max(m, n) * s[0] * eps; | |
| int r = 0; | |
| for (int i = 0; i < s.Length; i++) | |
| { | |
| if (s[i] > tol) | |
| { | |
| r++; | |
| } | |
| } | |
| return r; | |
| } | |
| } | |
| /// <summary>Return the one-dimensional array of singular values.</summary> | |
| public double[] Diagonal | |
| { | |
| get | |
| { | |
| return this.s; | |
| } | |
| } | |
| private static double Hypotenuse(double a, double b) | |
| { | |
| if (Math.Abs(a) > Math.Abs(b)) | |
| { | |
| double r = b / a; | |
| return Math.Abs(a) * Math.Sqrt(1 + r * r); | |
| } | |
| if (b != 0) | |
| { | |
| double r = a / b; | |
| return Math.Abs(b) * Math.Sqrt(1 + r * r); | |
| } | |
| return 0.0; | |
| } | |
| /// <summary>Returns the U matrix.</summary> | |
| public Matrix UMatrix | |
| { | |
| get | |
| { | |
| return this.U; | |
| } | |
| } | |
| /// <summary>Returns the U matrix.</summary> | |
| public Matrix VMatrix | |
| { | |
| get | |
| { | |
| return this.V; | |
| } | |
| } | |
| } | |
| } | |