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\section{Adsorption isotherm of N$_2$ in a metal-organic framework (MOF), Henry coefficients, heat of adsorptions}
\begin{figure}[H]
\centering
\subfloat[]{\includegraphics[width=7.5cm]{./Tutorial/MIL-47.jpg}}
\subfloat[]{\includegraphics[width=7.5cm]{./Tutorial/MIL-47-2x2x4.jpg}}
\caption{(left) The MIL-47 unit cell, $6.8179\times 16.1430 \times 13.9390$ \AA, $\alpha=\beta=\gamma=90^\circ$, (right) the $2\times2\times4$ supercell.}
\label{Tutorial-MIL-47.jpg}
\end{figure}
We are going to look at adsorption properties of methane in MIL-47. The MIL-47 structure is shown in Fig. \ref{Tutorial-MIL-47.jpg}.
The first step is to select the size of the system. We are going to choose a VDW cutoff of 12 \AA. This implies that all \emph{perpendicular} lengths
of the unit cell should be larger than twice the cutoff, i.e.\ 24 \AA. So, as a \emph{minimum}, we should use at least a $2\times2\times4$ unit cell.
This requirement follows from the "minimum-image convention" where the interactions are computed with only the closest periodic image.
\begin{table}[t]
\begin{tabularx}{\linewidth}{X|X|X|X|X}
type & V$^{0+}$ & V$^{2+}$ & V$^{4+}$ & DFT \\
\hline
V & 2.67677 & 1.45833 & 1.83592 & 1.68 \\
O1 & -0.986909 & -0.527963 & -0.661157 & -0.6 \\
O2 & -0.712381 & -0.439958 & -0.516643 & -0.52 \\
O3 & -0.693279 & -0.427135 & -0.501819 & -0.52 \\
C1 & 0.00680379 & -0.0146643 & -0.0110838 & -0.15 \\
H1 & 0.0434488 & 0.0574796 & 0.055858 & 0.12 \\
C2 & 0.0116383 & -0.0118276 & -0.00782077 & -0.15 \\
H2 & 0.0444475 & 0.0586772 & 0.0570134 & 0.12 \\
C3 & -0.150672 & -0.0720208 & -0.083311 & 0.0 \\
C4 & 0.605064 & 0.384265 & 0.420426 & 0.56 \\
\end{tabularx}
\caption{Obtaining charges for MIL-47: charge equilibration vs. DFT-derived charges.}
\label{Tutorial-charges}
\end{table}
The positions of the atoms are usually known from experiments, or alternatively can be obtained from QM optimizations.
Using the positions only, we can compute the frameworks-mass as 14787.6 g mol$^{-1}$, and we can already compute a few interesting properties.
The first is a measurement of how void the structures is.
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 1: go to the sub-directory '\verb+1-Helium-void-fraction+'. Compute the helium void-fraction
(look for `\verb+Rosenbluth factor new: 0.608 [-]+' in the output file).
\end{minipage}}
\end{center}
About 61\% of the structure is empty!
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 2: go to the sub-directory '\verb+1-Helium-void-fraction+'. Add a line '\verb+HeliumVoidFraction 0.61+' below '\verb+Framework 0+',
use zero cycles, and check the properties of the system.'
\end{minipage}}
\end{center}
We see that the available pore volume is 0.60977519 cm$^3$ g$^{-1}$. This density is important to know, because, using the liquid density,
it gives a first approximation of the "maximum" number of molecules in the pore.
Two other very useful properties are the accesible surface and pore-size distribution.
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 3: go to the sub-directory '\verb+3-Surface-area+'. Run and compute the surface area.
\end{minipage}}
\end{center}
The nitrogen surface area of MIL-47 is about 1650 m$^2$ g$^{-1}$.
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 4: go to the sub-directory '\verb+4-Pore-size-distribution+'. Run and compute the pore-size-distribution.
Plot the output-file in '\verb+PoreSizeDistributionHistogram+' in gnuplot using column 1 vs.\ 3
(\verb+plot 'PoreSizeDistributionHistogram' us 1:3 with lines+) to see what the typical pore sizes are.
\end{minipage}}
\end{center}
In general, the individual framework atoms are charged, but the overall framework should be charge neutral (or compensated by cations when the
framework itself has a net-charge).
For the charges there is ambiguity, since charge is not an ab-initio observable. That means that different methods to obtain charges
give different answers. For adsorption however, we are not really interested in the charges themselves but rather of their influence on the
electrostatic potential energy field \emph{inside} the cavities. The CHELPG-type methods aim to do just that: they optimize the classical
point charges on the framework work atoms to match the PES (potential energy surface) computed with ab-initio methods.
For crystals, the REPEAT method is a very nice variant taking the periodicity into account \cite{Campana2009}. However, such
computations can take several hours (or even days). A fast alternative is "charge-equilibration" \cite{Rappe1991,Wilmer2011b,Wilmer2012}.
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 5: go to the sub-directory '\verb+5-ChargeEquilibration+'. Compute the charges using charge-equilibration
for various oxidation states of vanadium (edit the '\verb+pseudo_atoms.def+'-file). The output-charges are written to
'\verb+Movies/System_0/Framework_0_final_1_1_1.cif+'.
\end{minipage}}
\end{center}
In Table \ref{Tutorial-charges} we summarize the results: charge-equilibration can give a good approximation in a matter of seconds (or minutes)
provided the charge-expansion is performed around the appropriate oxidation state \cite{Wilmer2012}.
Next we are going to choose N$_2$ as the adsorbate molecule. Since this is a small molecule, it is probably fine to use the small $2\times2\times4$.
For much larger molecules finite-size effects occur and a larger system should be used. For example, a long chain-molecule could even interacts with
\emph{itself} if the system was small, which obviously leads to erroneous results.
In order to compute an adorption isotherm we need the framework positions and charges, a force field for the adsorbate and interactions with the framework.
Here we will use a generic force field based on DREIDING and UFF \cite{MayoOlafsonGoddard1990,RappeCasewitColwellGoddardSkiff1992}.
An adsorption isotherm describes the adsorption at a fixed (chosen) temperature as a function of pressure. The first question is to examine the appropriate
pressure range for adsorption.
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 6: go to the sub-directory '\verb+6-Adsorption+'. Use a few thousand cycles and determine at what pressure
adsorption starts to occur (pressures units are Pascal). Do this for 300K and 600K.
\end{minipage}}
\end{center}
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 7: go to the sub-directory '\verb+6-Adsorption+'. Use 7500 cycles initialization, a few ten-thousand cycles for production
and compute 5 to 10 points from the starting pressure to 1000 bar.
Put the data in a file and plot the loading vs. pressure in normal scale and in log-scale.
\end{minipage}}
\end{center}
\section{NPT density of super-critical CO$_2$, RDF, diffusion}
The density of CO2 at 400 and 10 bar is about 161.53 kg m$^{-3}$, at 50 bar 745.45 kg m$^{-3}$ and at 100 bar the density is
932.81 kg m$^{-3}$ (NIST chemicaldatabase). In this example the density is
computed using Monte Carlo in the NPT-ensemble. Given the pressure $P$, the temperature $T$, and the amount of molecules $N$,
the density is computed.
\begin{verbatim}
SimulationType MonteCarlo
NumberOfCycles 50000
NumberOfInitializationCycles 10000
PrintEvery 1000
RestartFile no
Forcefield GarciaPerez2006
Box 0
BoxLengths 30 30 30
ExternalTemperature 400.0
ExternalPressure 10e5
ComputeMolecularPressure yes
VolumeChangeProbability 0.05
Component 0 MoleculeName CO2
MoleculeDefinition TraPPE
TranslationProbability 0.5
RotationProbability 0.5
RegrowProbability 0.5
CreateNumberOfMolecules 256
\end{verbatim}
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 1: go to the sub-directory '\verb+FluidCO2/MC_NPT+'. Verify the three densities listed from NIST experimental data.
\end{minipage}}
\end{center}
Next we are going to compute two important fluid properties that give inside in the structure of the fluid: the radial
distribution function (RDF) and the self-diffusion.
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 2: go to the sub-directory '\verb+FluidCO2/MC_NPT+'. Set the volume to the average of the previous step
and switch off the volume move, e.g.\ remove '\verb+VolumeChangeProbability 0.05+'.
Also replace '\verb+ComputeMolecularPressure yes+' by\\
ComputeRDF yes\\
WriteRDFEvery 1000
Plot and analyze the output rdf's that can be found in the directory '\verb+RadialDistributionFunctions+'.
\end{minipage}}
\end{center}
Next, we are going to compute a dynamic property. Therefore, we change '\verb+SimulationType MonteCarlo+' to
'\verb+SimulationType MolecularDynamics+' and we are going to use Molecular Dynamics.
\begin{verbatim}
SimulationType MolecularDynamics
NumberOfCycles 1000000
NumberOfInitializationCycles 1000
NumberOfEquilibrationCycles 10000
PrintEvery 10000
PrintPropertiesEvery 10000
Ensemble NVT
TimeStep 0.0005
Forcefield GarciaPerez2006
Box 0
BoxLengths 25 25 25
ExternalTemperature 400.0
ComputeMSD yes
PrintMSDEvery 5000
Component 0 MoleculeName CO2
MoleculeDefinition TraPPE
TranslationProbability 1.0
ReinsertionProbability 1.0
CreateNumberOfMolecules 100
\end{verbatim}
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 3: Compute teh diffusion via the mean-square displacement. Using gnuplot, plot the file
'\verb+MSDOrderN/System_0/msd_self_methane_0.dat+'. Use the slope to extract the diffusion coefficient.
\end{minipage}}
\end{center}
\section{Reaction-ensemble of ammonia}
We are going to study the ammonia synthesis reaction
\begin{equation}
N_2 + 3H_2 \leftrightarrow 2NH_3
\end{equation}
Ammonia ranks second among synthesis chemicals in amount produced, and there has been a great deal of experimental and
theoretical research into the ammonia synthesis reaction over the past 100 years. Thus there is an abundance
of experimental reference data on this reaction, allowing an accurate check of simulation models \cite{Turner2001}.
One of the most commonly used approaches in molecular simulation is to simulate
reaction equilibria in the reaction ensemble (RxMC). In this approach, the chemical reaction is
carried out by a Monte Carlo (MC) trial move. Beside thermahzation (translation, rotation, etc),
trial moves are carried out in which reactants are removed and reaction products are inserted
in the system, in such a way that an equilibrium distribution of reactants and reaction products
is obtained. The mechanism and the transition state of the reaction are not considered as
this approach is purely thermodynamic. As a result, the efficiency of this simulation technique
is not affected by the height of the activation energy barrier of the reaction as reaction kinetics
are not considered. The RxMC method
requires the ideal gas partition functions of all reactant and reaction product molecules,
a list of all possible chemical reactions in the system, and an appropriate force field
accurately describing interactions between molecules.
\begin{figure}[H]
\centering
\subfloat[]{\includegraphics[width=7.5cm]{./Tutorial/Ammonia-system.jpg}}
\subfloat[]{\includegraphics[width=7.5cm]{./Tutorial/Ammonia-fractional.jpg}}
\caption{(left) The MIL-47 unit cell, $6.8179\times 16.1430 \times 13.9390$ \AA, $\alpha=\beta=\gamma=90^\circ$, (right) the $2\times2\times4$ supercell.}
\label{Tutorial-reaction-system}
\end{figure}
Figure \ref{Tutorial-reaction-system} shows a snaphost of the N$_2$-3H$_3$-2NH$_3$ system. To efficiently
perform the reaction we use the reaction-ensemble using continuous fractional MC. The reaction is performed
along a $\lambda$-parameter from 0 to 1, where 0 denotes the full N$_2$-3H$_3$ reactant state and
1 the full product state 2NH$_3$. Using fractional molecules for each component the reaction can be
performed gradually. In addition to the usual thermalization moves we have a $\lambda$-move that attempts to
change $\lambda$ with three possible outomes:
\begin{enumerate}
\item{$\lambda$ remains between 0 and 1.}
\item{$\lambda$ goes beyond 1.}\\
We have formed real 2NH$_3$ molecules and choose new fractional molecule (randomly) with a value $\lambda-1$.
\item{$\lambda$ goes below 0.}\\
We have formed real N$_2$-3H$_3$ molecules and choose new fractional molecule (randomly) with a value $\lambda+1$.
\end{enumerate}
There moves are switched on by the '\verb+ProbabilityCFCRXMCLambdaChangeMove+' input-parameter. We
also perform volume moves to impose the pressure using '\verb+VolumeChangeProbability+' option.
The example input below defines the box, the 3 components, and the reaction using
\begin{verbatim}
Reaction 1 3 0 0 0 2
\end{verbatim}
which list the stoichiometry of the reactants and the product. So, 1 of component 0 and 3 of component 1 forms 2
molecules of component 2.
\begin{verbatim}
SimulationType MC
NumberOfCycles 15000
NumberOfInitializationCycles 10000
NumberOfEquilibrationCycles 20000
RestartFile no
PrintEvery 500
ChargeMethod Ewald
Forcefield local
CutOffVDW 9.0
CutOffCoulomb 9.0
EwaldPrecision 1e-5
Box 0
BoxLengths 38 38 38
ExternalTemperature 573.0
ExternalPressure 3e7
Reaction 1 3 0 0 0 2
ProbabilityCFCRXMCLambdaChangeMove 1.0
VolumeChangeProbability 0.1
Component 0 MoleculeName N2
MoleculeDefinition local
PartitionFunction 3.81253e4
TranslationProbability 40.0
RotationProbability 53.9
ReinsertionProbability 5.0
ExtraFrameworkMolecule no
CreateNumberOfMolecules 13
Component 1 MoleculeName H2
MoleculeDefinition local
PartitionFunction 2.48054e1
TranslationProbability 40.0
RotationProbability 53.9
ReinsertionProbability 5.0
ExtraFrameworkMolecule no
CreateNumberOfMolecules 39
Component 2 MoleculeName NH3
MoleculeDefinition local
PartitionFunction 1.498133e8
TranslationProbability 40.0
RotationProbability 53.9
ReinsertionProbability 5.0
ExtraFrameworkMolecule no
CreateNumberOfMolecules 134
\end{verbatim}
\begin{figure}[H]
\centering
\subfloat[Experiments]{
\begin{tabular}{l|l|l|l|l}
P [bar] & 573K & 673K & 773K & 873K\\
\hline
100 & 0.53 & 0.25 & 0.10 & 0.05\\
200 & 0.67 & 0.39 & 0.18 & 0.09\\
300 & 0.75 & 0.48 & 0.25 & 0.13\\
400 & 0.80 & 0.55 & 0.32 & 0.16\\
500 & 0.84 & 0.61 & 0.37 & 0.20\\
600 & 0.87 & 0.66 & 0.42 & 0.24\\
700 & 0.89 & 0.70 & 0.47 & 0.27\\
800 & 0.91 & 0.74 & 0.51 & 0.31\\
900 & 0.93 & 0.77 & 0.55 & 0.34\\
1000 & 0.94 & 0.80 & 0.58 & 0.37\\
\hline
\end{tabular}}
\hspace{2cm}
\subfloat[Simulations]{
\begin{tabular}{l|l|l|l|l}
P [bar] & 573K & 673K & 773K & 873K\\
\hline
100 & 0.56 & 0.27 & 0.12 & 0.05\\
200 & 0.69 & 0.41 & 0.20 & 0.09\\
300 & 0.78 & 0.49 & 0.26 & 0.14\\
400 & 0.82 & 0.57 & 0.32 & 0.17\\
500 & 0.86 & 0.62 & 0.37 & 0.20\\
600 & 0.88 & 0.66 & 0.42 & 0.24\\
700 & 0.90 & 0.69 & 0.45 & 0.27\\
800 & 0.91 & 0.73 & 0.50 & 0.30\\
900 & 0.93 & 0.77 & 0.53 & 0.33\\
1000 & 0.94 & 0.79 & 0.56 & 0.35\\
\hline
\end{tabular}}
\caption{Mol-fractions of the NH$_3$ in the ammonio bulk phase reaction of N$_2$ and H$_2$
computed from simulation compared to experiments over a wide range of temperatures
and pressures.}
\end{figure}
\begin{table}[H]
\centering
\begin{tabular}{l|l|l|l|l}
T [K] & N$_2$ & H$_2$ & NH$_3$ & Eq. constant K$_p$\\
\hline
573 & 3.81253E+04 & 2.48054E+01 & 1.498133E+08 & 0.006327104\\
673 & 5.72211E+04 & 3.70874E+01 & 7.741691E+07 & 0.000244159\\
773 & 8.14008E+04 & 5.24472E+01 & 5.188771E+07 & 2.06653E-05\\
873 & 1.11265E+05 & 7.11208E+01 & 4.104206E+07 & 2.97405E-06\\
\hline
\end{tabular}
\caption{Input parition function in units of \AA$^3$ and the equilibrium constant K$_p$.
The partition functions are computed based on the vibrational and rotational constants reported in the book by McQuarrie \cite{McQuarrie2000}.}
\label{Tutorial reaction-input}
\end{table}
\begin{center}
\shadowbox{%
\begin{minipage}[c]{15cm}
Exercise 1: go to the sub-directory '\verb+Tutorial/ReactionEnsembleAmmonia+'.
Using the input-parameters of Table \ref{Tutorial reaction-input} reproduce the simulation results.
\end{minipage}}
\end{center}
\newpage
\bibliographystyle{Tutorial/jpc}
\bibliography{Tutorial/biblio}
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