| {"source_id": 643933, "source_row": 38, "source_revision": "356bb069eee815daa6e23e9a282eeefe1490ad44", "source_seed_sha1": "7908d4d9ee6a4ecd4c6ff2e6eafe5f2903fbfe9c", "source_url": "https://huggingface.co/datasets/bigcode/self-oss-instruct-sc2-exec-filter-50k/tree/356bb069eee815daa6e23e9a282eeefe1490ad44", "instruction": "Write a Python function that accepts a function `func` and arguments `*args`, and returns a function that calls `func` with the provided arguments and returns the result. This function should be named `call_with_args`.\n\nFor example, given `func = lambda x, y: x + y` and `*args = (5, 10)`, the returned function should return 15 and invoke `func` with `x = 5` and `y = 10`.", "original_response": "To write a function that accepts a function `func` and arguments `*args`, and returns a function that calls `func` with the provided arguments and returns the result, you can leverage Python's function closure feature.\n\nHere is how you can implement this function:\n\n```python\ndef call_with_args(func, *args):\n def wrapper():\n return func(*args)\n return wrapper\n```", "prompt": "def call_with_args(func, *args):\n 'Write a Python function that accepts a function `func` and arguments `*args`, and returns a function that calls `func` with the provided arguments and returns the result. This function should be named `call_with_args`.\\n\\nFor example, given `func = lambda x, y: x + y` and `*args = (5, 10)`, the returned function should return 15 and invoke `func` with `x = 5` and `y = 10`.'\n", "completion": " def wrapper():\n return func(*args)\n return wrapper\n", "token_count": 147, "body_sha256": "8d5012fa5883307947e1b3db2f25c0aca655e45d51959132c6e27bc8b86dbb0e", "split": "dev", "validation_status": "static_candidate_not_execution_verified", "loss_mask": "prompt=-100 |
| {"source_id": 152977, "source_row": 50, "source_revision": "356bb069eee815daa6e23e9a282eeefe1490ad44", "source_seed_sha1": "350cf868d3b087991cff88ba3c27e79d8c21b682", "source_url": "https://huggingface.co/datasets/bigcode/self-oss-instruct-sc2-exec-filter-50k/tree/356bb069eee815daa6e23e9a282eeefe1490ad44", "instruction": "Write a Python function `image_mirror` that takes in an image as a list of lists of pixel values, and returns the mirrored image as a new list of lists. The function should mirror the image along the vertical axis and return the mirrored image as a new list.\n\nYour code should pass the following test case:\n```python\n# Test that the function correctly mirrors the image\noriginal_image = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]\nmirrored_image = [[3, 2, 1], [6, 5, 4], [9, 8, 7]]\nassert image_mirror(original_image) == mirrored_image\n```", "original_response": "To write an `image_mirror` function that mirrors an image along the vertical axis, you need to:\n\n1. Define a function that takes in an image as a list of lists of pixel values.\n2. Within the function, you can reverse the order of the pixels in each row of the image to mirror them along the vertical axis.\n3. Finally, return the mirrored image as a new list of lists.\n\nHere is how you could implement such a function:\n\n```python\ndef image_mirror(image):\n mirrored_image = []\n for row in image:\n mirrored_row = list(reversed(row))\n mirrored_image.append(mirrored_row)\n return mirrored_image\n```", "prompt": "def image_mirror(image):\n 'Write a Python function `image_mirror` that takes in an image as a list of lists of pixel values, and returns the mirrored image as a new list of lists. The function should mirror the image along the vertical axis and return the mirrored image as a new list.\\n\\nYour code should pass the following test case:\\n```python\\n# Test that the function correctly mirrors the image\\noriginal_image = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]\\nmirrored_image = [[3, 2, 1], [6, 5, 4], [9, 8, 7]]\\nassert image_mirror(original_image) == mirrored_image\\n```'\n", "completion": " mirrored_image = []\n for row in image:\n mirrored_row = list(reversed(row))\n mirrored_image.append(mirrored_row)\n return mirrored_image\n", "token_count": 240, "body_sha256": "095aa151d6f0897661b6b81a83add92503df8840bbd2f6647e2a0cb27927d695", "split": "dev", "validation_status": "static_candidate_not_execution_verified", "loss_mask": "prompt=-100; completion+EOS=supervised"} |
| {"source_id": 325070, "source_row": 59, "source_revision": "356bb069eee815daa6e23e9a282eeefe1490ad44", "source_seed_sha1": "7cd633ea5eb43572df8260badf6fde86a078a0c9", "source_url": "https://huggingface.co/datasets/bigcode/self-oss-instruct-sc2-exec-filter-50k/tree/356bb069eee815daa6e23e9a282eeefe1490ad44", "instruction": "Write a Python function `curry` that takes a function `f` and a list of arguments `args` as input and returns a function that takes a list of arguments `rest` and applies them to `f` along with `args`. The returned function should support function currying.", "original_response": "Here's how you could do it:\n\n```python\ndef curry(f, *args):\n def func(*rest):\n return f(*(args + rest))\n return func\n```", "prompt": "def curry(f, *args):\n 'Write a Python function `curry` that takes a function `f` and a list of arguments `args` as input and returns a function that takes a list of arguments `rest` and applies them to `f` along with `args`. The returned function should support function currying.'\n", "completion": " def func(*rest):\n return f(*args + rest)\n return func\n", "token_count": 104, "body_sha256": "fb479d747830235d20cf2df6425b2f579a591924d29d68d67222dd05a697b088", "split": "dev", "validation_status": "static_candidate_not_execution_verified", "loss_mask": "prompt=-100 |
| {"source_id": 117700, "source_row": 86, "source_revision": "356bb069eee815daa6e23e9a282eeefe1490ad44", "source_seed_sha1": "6ae93023043af0054578f01709915e0149b78cf4", "source_url": "https://huggingface.co/datasets/bigcode/self-oss-instruct-sc2-exec-filter-50k/tree/356bb069eee815daa6e23e9a282eeefe1490ad44", "instruction": "Write a Python function to merge two dictionaries. The function should accept two dictionaries as arguments, and return a single merged dictionary. If any dictionary contains the same key, their values should be added together. If any dictionary contains a key that the other dictionary does not, the key should be added to the merged dictionary.", "original_response": "To merge two dictionaries, we can iterate through the first dictionary and add each key-value pair to the merged dictionary. For each key, we check whether the key exists in the second dictionary. If it does, we add their values together. If not, we add the key-value pair from the first dictionary to the merged dictionary.\n\nHere is the implementation:\n\n```python\ndef merge_dicts(dict1, dict2):\n merged_dict = {}\n\n for key, value in dict1.items():\n if key in dict2:\n merged_dict[key] = value + dict2[key]\n else:\n merged_dict[key] = value\n\n for key, value in dict2.items():\n if key not in merged_dict:\n merged_dict[key] = value\n\n return merged_dict\n```\n\nIn this implementation:\n- `dict1` and `dict2` are the two dictionaries to be merged.\n- `merged_dict` is the result dictionary that will be returned.\n- The first for loop iterates through each key and value pair from `dict1`. If the key is in `dict2`, the values are added together. Otherwise, the key and value from `dict1` are added to `merged_dict`.\n- The second for loop iterates through each key and value pair from `dict2`. If the key does not exist in `merged_dict`, it is added along with its value.\n- Finally, the merged dictionary is returned.", "prompt": "def merge_dicts(dict1, dict2):\n 'Write a Python function to merge two dictionaries. The function should accept two dictionaries as arguments, and return a single merged dictionary. If any dictionary contains the same key, their values should be added together. If any dictionary contains a key that the other dictionary does not, the key should be added to the merged dictionary.'\n", "completion": " merged_dict = {}\n for key, value in dict1.items():\n if key in dict2:\n merged_dict[key] = value + dict2[key]\n else:\n merged_dict[key] = value\n for key, value in dict2.items():\n if key not in merged_dict:\n merged_dict[key] = value\n return merged_dict\n", "token_count": 235, "body_sha256": "c09c261b66455f1e14053093525f6858483115793223656f239f972b142c4995", "split": "dev", "validation_status": "static_candidate_not_execution_verified", "loss_mask": "prompt=-100; completion+EOS=supervised"} |
| {"source_id": 263582, "source_row": 96, "source_revision": "356bb069eee815daa6e23e9a282eeefe1490ad44", "source_seed_sha1": "5ecf88cdfb2b95d982544cddee84e0ccd3acda0e", "source_url": "https://huggingface.co/datasets/bigcode/self-oss-instruct-sc2-exec-filter-50k/tree/356bb069eee815daa6e23e9a282eeefe1490ad44", "instruction": "Write a Python function that takes a string as input and returns the same string with a space inserted in every position. For example, given \"abc\", the function should return \"a b c\". Use string interpolation to achieve this result.", "original_response": "We can solve this problem using string interpolation (f-string) by iterating through each character in the input string and inserting a space after each character.\n\nHere's the code to implement the solution:\n\n```python\ndef space_insert(input_string):\n return ' '.join(input_string)\n```", "prompt": "def space_insert(input_string):\n 'Write a Python function that takes a string as input and returns the same string with a space inserted in every position. For example, given \"abc\", the function should return \"a b c\". Use string interpolation to achieve this result.'\n", "completion": " return ' '.join(input_string)\n", "token_count": 77, "body_sha256": "84a3c6a2d0d19e7ddd2ec97652eb0add2b766d1cea1f3fa5d2b88f06cabf8137", "split": "dev", "validation_status": "static_candidate_not_execution_verified", "loss_mask": "prompt=-100 |
| {"source_id": 307169, "source_row": 138, "source_revision": "356bb069eee815daa6e23e9a282eeefe1490ad44", "source_seed_sha1": "20196bfd81e3612d4abbb6fd8dc28ab28811d40d", "source_url": "https://huggingface.co/datasets/bigcode/self-oss-instruct-sc2-exec-filter-50k/tree/356bb069eee815daa6e23e9a282eeefe1490ad44", "instruction": "Write a Python function that takes a list of objects and returns a dictionary where each unique value is the key and its occurrences are the values. For example, given the list `['a', 'b', 'b', 'c']`, the function should return `{'a': 1, 'b': 2, 'c': 1}`. If there are no objects to count, return an empty dictionary.", "original_response": "To solve this problem, you can follow these steps:\n\n1. Check if the input list is empty. Return an empty dictionary if it is.\n2. Create an empty dictionary to store the counts of unique values.\n3. Iterate over the elements in the input list.\n4. If an element is already in the dictionary, increment its count by 1. Otherwise, add it to the dictionary with a count of 1.\n5. Return the dictionary containing the counts.\n\nHere's the implementation:\n\n```python\ndef count_unique_values(objects):\n if not objects:\n return {}\n\n counts = {}\n for obj in objects:\n if obj in counts:\n counts[obj] += 1\n else:\n counts[obj] = 1\n\n return counts\n```", "prompt": "def count_unique_values(objects):\n \"Write a Python function that takes a list of objects and returns a dictionary where each unique value is the key and its occurrences are the values. For example, given the list `['a', 'b', 'b', 'c']`, the function should return `{'a': 1, 'b': 2, 'c': 1}`. If there are no objects to count, return an empty dictionary.\"\n", "completion": " if not objects:\n return {}\n counts = {}\n for obj in objects:\n if obj in counts:\n counts[obj] += 1\n else:\n counts[obj] = 1\n return counts\n", "token_count": 198, "body_sha256": "77861f14f4883acf21674e2d2b86c88c34dc26abd29caada76c6aa7ec57793f7", "split": "dev", "validation_status": "static_candidate_not_execution_verified", "loss_mask": "prompt=-100 |
|
|
