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| using namespace std; | |
| static const string CH = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; | |
| static mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); | |
| char rndCh() { | |
| return CH[rng() % CH.size()]; | |
| } | |
| struct Preset { | |
| int r, c; | |
| vector<string> mat; | |
| }; | |
| int main() { | |
| const int T = 10; | |
| const int n = 20, m = 20, k = 20; | |
| for (int tc = 1; tc <= T; ++tc) { | |
| // 1. Random target | |
| vector<string> target(n, string(m, 'A')); | |
| for (int i = 0; i < n; ++i) | |
| for (int j = 0; j < m; ++j) | |
| target[i][j] = rndCh(); | |
| // 2. Random presets | |
| vector<Preset> pres(k + 1); | |
| for (int p = 1; p <= k; ++p) { | |
| int pr = uniform_int_distribution<int>(1, n)(rng); | |
| int pc = uniform_int_distribution<int>(1, m)(rng); | |
| pres[p].r = pr; | |
| pres[p].c = pc; | |
| pres[p].mat.assign(pr, string(pc, 'A')); | |
| for (int i = 0; i < pr; ++i) | |
| for (int j = 0; j < pc; ++j) | |
| pres[p].mat[i][j] = rndCh(); | |
| } | |
| // 3. Generate random operation sequence (forward), apply in reverse | |
| // Constraints: total ops <= 4e5, preset <= 400 | |
| // For randomness, length can be random between 2e5~4e5 | |
| int maxOps = 400000; | |
| int wantOps = uniform_int_distribution<int>(200000, 400000)(rng); | |
| struct Op { int op, x, y; }; | |
| vector<Op> ops; | |
| ops.reserve(wantOps); | |
| int presetUsed = 0; | |
| // Start from target and work backwards | |
| vector<string> cur = target; | |
| auto doBackwardRotate = [&](int x, int y) { | |
| // Reverse: undo clockwise rotation, equivalent to counter-clockwise | |
| // indices: (x,y), (x,y+1), (x+1,y+1), (x+1,y) | |
| // Original clockwise: new = {d, a, b, c} | |
| // Reverse: old = {b, c, d, a} | |
| char ny = cur[x][y+1]; | |
| char nyy = cur[x+1][y+1]; | |
| char nyyy= cur[x+1][y]; | |
| char nyyyy= cur[x][y]; | |
| // Restore old | |
| cur[x][y] = ny; | |
| cur[x][y+1] = nyy; | |
| cur[x+1][y+1] = nyyy; | |
| cur[x+1][y] = nyyyy; | |
| }; | |
| for (int i = 0; i < wantOps; ++i) { | |
| // Choose a random operation for variety | |
| // 0:-4,1:-3,2:-2,3:-1,4:rotate(0),5:preset | |
| int typ = uniform_int_distribution<int>(0, 5)(rng); | |
| int op, x, y; | |
| if (typ == 5 && presetUsed >= 400) { | |
| typ = uniform_int_distribution<int>(0, 4)(rng); | |
| } | |
| if (typ == 0) { // -4: swap with up | |
| if (n <= 1) { --i; continue; } | |
| x = uniform_int_distribution<int>(2, n)(rng); | |
| y = uniform_int_distribution<int>(1, m)(rng); | |
| op = -4; | |
| // backward: same swap | |
| swap(cur[x-1][y-1], cur[x-2][y-1]); | |
| } else if (typ == 1) { // -3: swap with down | |
| if (n <= 1) { --i; continue; } | |
| x = uniform_int_distribution<int>(1, n-1)(rng); | |
| y = uniform_int_distribution<int>(1, m)(rng); | |
| op = -3; | |
| swap(cur[x-1][y-1], cur[x][y-1]); | |
| } else if (typ == 2) { // -2: swap with left | |
| if (m <= 1) { --i; continue; } | |
| x = uniform_int_distribution<int>(1, n)(rng); | |
| y = uniform_int_distribution<int>(2, m)(rng); | |
| op = -2; | |
| swap(cur[x-1][y-1], cur[x-1][y-2]); | |
| } else if (typ == 3) { // -1: swap with right | |
| if (m <= 1) { --i; continue; } | |
| x = uniform_int_distribution<int>(1, n)(rng); | |
| y = uniform_int_distribution<int>(1, m-1)(rng); | |
| op = -1; | |
| swap(cur[x-1][y-1], cur[x-1][y]); | |
| } else if (typ == 4) { // rotate | |
| if (n <= 1 || m <= 1) { --i; continue; } | |
| x = uniform_int_distribution<int>(1, n-1)(rng); | |
| y = uniform_int_distribution<int>(1, m-1)(rng); | |
| op = 0; | |
| // backward rotate | |
| doBackwardRotate(x-1, y-1); | |
| } else { | |
| // preset | |
| int pid = uniform_int_distribution<int>(1, k)(rng); | |
| int pr = pres[pid].r; | |
| int pc = pres[pid].c; | |
| x = uniform_int_distribution<int>(1, n - pr + 1)(rng); | |
| y = uniform_int_distribution<int>(1, m - pc + 1)(rng); | |
| op = pid; | |
| presetUsed++; | |
| // backward: fill this region with random chars | |
| for (int ii = 0; ii < pr; ++ii) | |
| for (int jj = 0; jj < pc; ++jj) | |
| cur[x - 1 + ii][y - 1 + jj] = rndCh(); | |
| } | |
| ops.push_back({op, x, y}); | |
| } | |
| // Now cur is the initial state | |
| vector<string> initial = cur; | |
| // 4. Write to file | |
| { | |
| string fname = to_string(tc) + ".in"; | |
| ofstream fout(fname); | |
| fout << n << " " << m << " " << k << "\n"; | |
| for (int i = 0; i < n; ++i) fout << initial[i] << "\n"; | |
| fout << "\n"; | |
| for (int i = 0; i < n; ++i) fout << target[i] << "\n"; | |
| for (int p = 1; p <= k; ++p) { | |
| fout << "\n"; | |
| fout << pres[p].r << " " << pres[p].c << "\n"; | |
| for (int i = 0; i < pres[p].r; ++i) | |
| fout << pres[p].mat[i] << "\n"; | |
| } | |
| fout.close(); | |
| } | |
| // 5. Output empty ans file | |
| { | |
| string fname = to_string(tc) + ".ans"; | |
| ofstream fout(fname); | |
| // empty | |
| fout.close(); | |
| } | |
| cerr << "generated " << tc << ".in/.out, ops=" << ops.size() | |
| << ", presetsUsed=" << presetUsed << "\n"; | |
| } | |
| return 0; | |
| } | |