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find-products-of-elements-of-big-array | Detailed Explanation | Beats 82.71% of Users | 😺✨ | detailed-explanation-beats-8271-of-users-wi7q | Intuition:\n\nThe problem seems to involve determining the products of elements within specific ranges of numbers, under certain modular arithmetic constraints. | Sci-fi-vy | NORMAL | 2024-07-05T07:14:56.919438+00:00 | 2024-07-05T07:14:56.919467+00:00 | 18 | false | # Intuition:\n\nThe problem seems to involve determining the products of elements within specific ranges of numbers, under certain modular arithmetic constraints. My initial thought is to decompose the problem into smaller parts: counting occurrences of specific bits and then using those counts to compute the results f... | 0 | 0 | ['Bit Manipulation', 'Python3'] | 0 |
find-products-of-elements-of-big-array | Python | Counting | python-counting-by-aryonbe-c8yp | Code\n\n#based on https://leetcode.com/problems/find-products-of-elements-of-big-array/solutions/5145201/c-bit-count-and-binary-search-clean-code-with-a-lot-exp | aryonbe | NORMAL | 2024-06-19T07:18:05.062075+00:00 | 2024-06-19T07:18:05.062103+00:00 | 12 | false | # Code\n```\n#based on https://leetcode.com/problems/find-products-of-elements-of-big-array/solutions/5145201/c-bit-count-and-binary-search-clean-code-with-a-lot-explanitions/\nclass Solution:\n def findProductsOfElements(self, queries: List[List[int]]) -> List[int]:\n def sumAndCountBitsUpToVal(val):\n ... | 0 | 0 | ['Python3'] | 0 |
find-products-of-elements-of-big-array | Binary Search + concept of set bits | binary-search-concept-of-set-bits-by-nit-uhav | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | NitishSinghIITKGP | NORMAL | 2024-06-14T15:11:13.257781+00:00 | 2024-06-14T15:11:13.257806+00:00 | 24 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ --... | 0 | 0 | ['C++'] | 0 |
find-products-of-elements-of-big-array | Bit Manipulation + Binary Search + Cyclic Property Of Bits | 65 ms | bit-manipulation-binary-search-cyclic-pr-m2v9 | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | rohitsadhu | NORMAL | 2024-06-11T19:16:29.401149+00:00 | 2024-06-11T19:16:29.401172+00:00 | 20 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity: $$O(q * log(1e15))$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(q)$$\n<!-- Add your space com... | 0 | 0 | ['Binary Search', 'Bit Manipulation', 'C++'] | 0 |
find-products-of-elements-of-big-array | Beats 99.58% | beats-9958-by-lostsyntax-alv5 | Approach\n#### Powerful Array Generation:\n- Start by generating powerful arrays for each integer.\n- A powerful array for an integer x is the shortest sorted a | LostSyntax | NORMAL | 2024-05-23T22:15:54.948515+00:00 | 2024-07-17T03:22:34.071714+00:00 | 27 | false | # Approach\n#### **Powerful Array Generation:**\n- Start by generating powerful arrays for each integer.\n- A powerful array for an integer x is the shortest sorted array of powers of two that sum up to x. For example, the powerful array for 11 is [1, 2, 8].\n#### **Building big_nums Array:**\n- Concatenate the powerfu... | 0 | 0 | ['Binary Search', 'Dynamic Programming', 'Bit Manipulation', 'C++'] | 0 |
find-products-of-elements-of-big-array | Optimal Approach in Swift 🚦 Find Products of elements of Big Array | optimal-approach-in-swift-find-products-8xs1a | \n## Intuition\nThe problem involves calculating the product of numbers within a given range where the numbers are represented by their binary powers of 2. Each | lebon | NORMAL | 2024-05-18T00:18:08.414781+00:00 | 2024-05-18T00:32:08.541884+00:00 | 7 | false | \n## Intuition\nThe problem involves calculating the product of numbers within a given range where the numbers are represented by their binary powers of 2. Each power of 2 follows a specific pattern. To solve the problem efficiently, we can utilize these patterns to determine the counts of each power of 2 in the given ... | 0 | 0 | ['Array', 'Binary Search', 'Swift'] | 0 |
find-products-of-elements-of-big-array | 2 Solutions | Simulation, Bit Mask + Binary Search | 2-solutions-simulation-bit-mask-binary-s-0awh | Solution-1: Simualtion (TLE -- Passes 98.41% TCs)\n1. STEP-1: Identify max number from queries -- O(500)\n2. STEP-2: generate bigNums array for intergers 1 to m | shahsb | NORMAL | 2024-05-17T14:44:22.331191+00:00 | 2024-05-17T14:46:07.917560+00:00 | 23 | false | # Solution-1: Simualtion (TLE -- Passes 98.41% TCs)\n1. **STEP-1:** Identify max number from queries -- O(500)\n2. **STEP-2:** generate bigNums array for intergers 1 to maxNo. -- O(N) \n3. **STEP-3:** Iterate over each quey and generate result -- O(q * N)\n4. **STAT:** TLE -- 746 / 758 test cases passed -- 98.41%\n# So... | 0 | 0 | ['C', 'Simulation', 'Binary Tree', 'Bitmask'] | 0 |
find-products-of-elements-of-big-array | Just a runnable solution | just-a-runnable-solution-by-ssrlive-i6l6 | \n\nimpl Solution {\n pub fn find_products_of_elements(queries: Vec<Vec<i64>>) -> Vec<i32> {\n let mx = 1_000_000_000_000_006;\n let lim = 60;\ | ssrlive | NORMAL | 2024-05-13T06:06:15.566715+00:00 | 2024-05-13T06:06:15.566736+00:00 | 23 | false | \n```\nimpl Solution {\n pub fn find_products_of_elements(queries: Vec<Vec<i64>>) -> Vec<i32> {\n let mx = 1_000_000_000_000_006;\n let lim = 60;\n let mut ret = vec![];\n\n let mul = |x: i64, y: i64, m: i64| -> i64 {\n let x = x % m;\n let y = y % m;\n le... | 0 | 0 | ['Rust'] | 0 |
find-products-of-elements-of-big-array | scala | scala-by-len_master-4cj9 | scala\nobject Solution {\n def findProductsOfElements(queries: Array[Array[Long]]): Array[Int] = {\n def calc(p: Int, lim: Long): Long = {\n val len = | len_master | NORMAL | 2024-05-13T03:23:02.986330+00:00 | 2024-05-13T03:23:02.986362+00:00 | 3 | false | ```scala\nobject Solution {\n def findProductsOfElements(queries: Array[Array[Long]]): Array[Int] = {\n def calc(p: Int, lim: Long): Long = {\n val len = 1L << p\n val len2 = len * 2\n val ret = lim / len2 * len + (if (lim % len2 >= len) lim % len2 - len + 1 else 0)\n ret\n }\n\n def count... | 0 | 0 | ['Scala'] | 0 |
find-products-of-elements-of-big-array | Beats 100% in Time and Memory | Bit Manipulation | Binary Search | Java | beats-100-in-time-and-memory-bit-manipul-0okb | \n\n\n# Complexity\n- Time complexity:\nEach query will be answered in O(log(n))\n\n- Space complexity:\nO(1)\n\n# Code\n\nclass Solution {\n\n long MAAAX = | alone18 | NORMAL | 2024-05-12T16:47:21.424780+00:00 | 2024-05-12T16:47:21.424805+00:00 | 77 | false | \n\n\n# Complexity\n- Time complexity:\nEach query will be answered in $$O(log(n))$$\n\n- Space complexity:\n$$O(1)$$\n\n# Code\n```\nclass Solution {\n\n long MAAAX = 10000... | 0 | 0 | ['Binary Search', 'Bit Manipulation', 'Java'] | 0 |
find-products-of-elements-of-big-array | Bit Manipulation + Binary Search + Cyclic Property Of Bits | 65 ms | bit-manipulation-binary-search-cyclic-pr-ar3f | Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time | looneyd_noob | NORMAL | 2024-05-12T15:28:58.264301+00:00 | 2024-05-12T15:29:36.518552+00:00 | 61 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity: $$O(q * log(1e15))$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(q)$$\n<!-- Add your space com... | 0 | 0 | ['Binary Search', 'Bit Manipulation', 'C++'] | 0 |
find-products-of-elements-of-big-array | Bit manipulation, beats 100% at the time of writing | bit-manipulation-beats-100-at-the-time-o-5vog | Intuition\n\nEach number in the big_nums is a power of two. Since the answer is the product modulo some given number it is more convenient to work with exponent | vilmos_prokaj | NORMAL | 2024-05-12T03:46:11.203740+00:00 | 2024-05-12T03:46:11.203758+00:00 | 36 | false | # Intuition\n\nEach number in the `big_nums` is a power of two. Since the answer is the product modulo some given number it is more convenient to work with exponents, that is with the non-zero bit positions.\n\nThe naive solution is the following:\n```python\ndef bit_pos():\n n = 0\n while True:\n n0 = n\n... | 0 | 0 | ['Python3'] | 0 |
find-products-of-elements-of-big-array | My Solutions | my-solutions-by-hope_ma-k6fx | 1. Use the binary search\n\n/**\n * Time Complexity: O(n * log(bound) * log(bound))\n * Space Complexity: O(1)\n * where `n` is the length of the vector `querie | hope_ma | NORMAL | 2024-05-12T02:12:59.430912+00:00 | 2024-05-15T00:43:21.124065+00:00 | 11 | false | **1. Use the binary search**\n```\n/**\n * Time Complexity: O(n * log(bound) * log(bound))\n * Space Complexity: O(1)\n * where `n` is the length of the vector `queries`\n * `bound` is the maximum value of the `from`s and the `to`s of all queries `queries`\n */\nclass Solution {\n public:\n vector<int> findProdu... | 0 | 0 | [] | 0 |
find-products-of-elements-of-big-array | Short sol | short-sol-by-jwseph-obwr | Complexity\n- Time complexity: O(q\log^2 m) \n- Space complexity: O(q)\n\n# Explanation\n- Read this explanation: https://leetcode.com/problems/find-products-of | jwseph | NORMAL | 2024-05-11T21:19:30.007427+00:00 | 2024-05-11T21:23:39.536842+00:00 | 38 | false | # Complexity\n- Time complexity: $$O(q\\log^2 m)$$ \n- Space complexity: $$O(q)$$\n\n# Explanation\n- Read this explanation: https://leetcode.com/problems/find-products-of-elements-of-big-array/solutions/5143875/python-3-bisearch-count-1-s-and-accumulate-0-s/\n\n# Code\n```py\nclass Solution:\n def findProductsOfEle... | 0 | 0 | ['Binary Search', 'Python3'] | 0 |
find-products-of-elements-of-big-array | JS Solution - Binary search | js-solution-binary-search-by-cutetn-qdis | Pro tip: Big heart for lil Xie \uD83D\uDC9C\uD83D\uDC9C\uD83D\uDC9C\n\n# Complexity\n- let n = queries.length, m = max(queries[*][1])\n- Time complexity: O(nlog | CuteTN | NORMAL | 2024-05-11T19:17:56.704256+00:00 | 2024-05-11T19:17:56.704294+00:00 | 26 | false | Pro tip: Big heart for lil Xie \uD83D\uDC9C\uD83D\uDC9C\uD83D\uDC9C\n\n# Complexity\n- let `n = queries.length`, `m = max(queries[*][1])`\n- Time complexity: $$O(nlogm)$$\n- Space complexity: $$O(n + m)$$\n\n# Code\n```js\nfunction quickPow(a, b, m) {\n if (b === 0) return 1;\n let t = quickPow(a, Math.floor(b / 2), ... | 0 | 0 | ['Binary Search', 'JavaScript'] | 0 |
find-products-of-elements-of-big-array | Binary Search Solution | C++ | 200ms | binary-search-solution-c-200ms-by-shrana-rtjn | Binary search solution\n# Code\n\nclass Solution {\npublic:\n long long countOnes(long long x, long long cycle, long long pow2Is) {\n if (x < 0) {\n | shrana_ak | NORMAL | 2024-05-11T18:44:35.303834+00:00 | 2024-05-11T18:44:35.303874+00:00 | 79 | false | Binary search solution\n# Code\n```\nclass Solution {\npublic:\n long long countOnes(long long x, long long cycle, long long pow2Is) {\n if (x < 0) {\n return 0;\n }\n long long totCycle = x / cycle;\n long long ones = (totCycle * pow2Is);\n long long left = x % cycle;\n... | 0 | 0 | ['Binary Search', 'C++'] | 0 |
find-products-of-elements-of-big-array | Solution | solution-by-penrosecat-ikz2 | Intuition\n Describe your first thoughts on how to solve this problem. \nThe array only has elements corresponding to set bits in numbers. To find the index in | penrosecat | NORMAL | 2024-05-11T18:36:13.034831+00:00 | 2024-05-11T18:36:13.034858+00:00 | 22 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe array only has elements corresponding to set bits in numbers. To find the index in the big array, we need the sum of set bits upto n. \n\nTo find the final product we also need the position wise bit frequency upto (from-1) and (to) th... | 0 | 0 | ['C++'] | 0 |
first-completely-painted-row-or-column | 🔥Simple Count of coloured row/column Detailed Solution | simple-map-count-detailed-solution-by-su-qxhh | 🧠 IntuitionThe task requires finding the smallest index in arr where a row or column in the matrix mat becomes completely painted. The key idea is:
Use a hash m | Sumeet_Sharma-1 | NORMAL | 2025-01-20T01:22:28.822119+00:00 | 2025-01-20T02:33:24.565714+00:00 | 19,462 | false | # 🧠 Intuition
The task requires finding the smallest index in `arr` where a row or column in the matrix `mat` becomes completely painted. The key idea is:
- Use a hash map to quickly locate the `(row, column)` of any number in `mat`.
- Maintain counts of uncolored cells for rows and columns.
- Stop processing as soon... | 135 | 5 | ['Array', 'Hash Table', 'C++', 'Java', 'Go', 'Python3', 'JavaScript', 'C#'] | 18 |
first-completely-painted-row-or-column | Explained - using map || Very simple and easy to understand solution | explained-using-map-very-simple-and-easy-ciwc | \n# Approach\nWe will have two map for tracking the row and col of a number, so that we can get the row,col in O(1) time.\nThen we have another two map ( mprc, | kreakEmp | NORMAL | 2023-04-30T04:18:30.142507+00:00 | 2023-04-30T09:02:11.773850+00:00 | 7,368 | false | \n# Approach\nWe will have two map for tracking the row and col of a number, so that we can get the row,col in O(1) time.\nThen we have another two map ( mprc, mpcc) which basically count the no. elements seen in that row and no. of elements seen in that column.\n\n1. Map the row, col of each of elements\n2. Travesrse ... | 34 | 1 | ['C++'] | 9 |
first-completely-painted-row-or-column | 3 passes -> 2 passes||C++3ms Py3 99.05% | 3-passes-solution4ms-beats-9512-by-anwen-h592 | IntuitionUse vector in stead of a hash map.
3 passes
2nd solution is 2 passes which is much simpler. both C++ & Python are implemented.Approach
Declare vector i | anwendeng | NORMAL | 2025-01-20T00:42:25.361648+00:00 | 2025-01-20T02:42:15.696281+00:00 | 4,082 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
Use vector in stead of a hash map.
3 passes
2nd solution is 2 passes which is much simpler. both C++ & Python are implemented.
# Approach
<!-- Describe your approach to solving the problem. -->
1. Declare vector `idx(N+1)` where `N=m*n`
2. ... | 32 | 4 | ['Array', 'Matrix', 'C++', 'Python3'] | 11 |
first-completely-painted-row-or-column | Simple java solution | simple-java-solution-by-siddhant_1602-9k46 | Complexity\n- Time complexity: O(mn)\n\n- Space complexity: O(mn)\n\n# Code\n\nclass Solution {\n public int firstCompleteIndex(int[] arr, int[][] mat) {\n | Siddhant_1602 | NORMAL | 2023-04-30T04:01:22.701517+00:00 | 2023-04-30T04:11:38.847036+00:00 | 2,387 | false | # Complexity\n- Time complexity: $$O(m*n)$$\n\n- Space complexity: $$O(m*n)$$\n\n# Code\n```\nclass Solution {\n public int firstCompleteIndex(int[] arr, int[][] mat) {\n Map<Integer, int[]> nm = new HashMap<>();\n int m=mat.length;\n int n=mat[0].length;\n for (int i=0;i<m;i++)\n ... | 26 | 1 | ['Hash Table', 'Java'] | 6 |
first-completely-painted-row-or-column | Beats 80.60% | Array | HashMap | Solution for LeetCode#2661 | array-hashmap-solution-for-leetcode2661-p3bcg | IntuitionThe problem requires us to find the first index in the given array arr where a complete row or column in the matrix mat is filled. We can keep track of | samir023041 | NORMAL | 2025-01-20T00:49:26.512617+00:00 | 2025-01-20T01:02:56.044239+00:00 | 3,736 | false | 
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
The problem requires us to find the first index in the given array arr where a complete row or column in the matrix mat is ... | 25 | 6 | ['Hash Table', 'Python', 'Java', 'Python3'] | 6 |
first-completely-painted-row-or-column | ✔💯 DAY 395 | EASY | 100% 0ms | [PYTHON/JAVA/C++] | EXPLAINED | Approach 💫 | day-395-easy-100-0ms-pythonjavac-explain-vz78 | Please Upvote as it really motivates me \uD83C\uDD99\uD83C\uDD99\uD83C\uDD99\n# Intuition & Approach\n Describe your approach to solving the problem. \n##### \u | ManojKumarPatnaik | NORMAL | 2023-04-30T04:01:02.193646+00:00 | 2023-04-30T04:10:33.829332+00:00 | 1,800 | false | # Please Upvote as it really motivates me \uD83C\uDD99\uD83C\uDD99\uD83C\uDD99\n# Intuition & Approach\n<!-- Describe your approach to solving the problem. -->\n##### \u2022\tWe are given an array arr and a matrix mat.\n##### \u2022\tWe first create a HashMap called map to store the coordinates of each element in ... | 24 | 2 | ['Python', 'C++', 'Java', 'Python3'] | 4 |
first-completely-painted-row-or-column | 0ms |Beats 100% Proof | Using Hash Mapping with Simulation| Efficient & Easy C++ Solu| Full Explain | 0ms-beats-100-proof-using-hash-mapping-w-99vz | IntuitionThe task requires us to determine the smallest index i in the array arr such that either a row or a column in the matrix mat becomes completely painted | HarshitSinha | NORMAL | 2025-01-20T02:31:27.577743+00:00 | 2025-01-20T02:31:27.577743+00:00 | 2,251 | false |
---
# Intuition
The task requires us to determine the smallest index `i` in the array `arr` such that either a row or a column in the matrix `mat` becomes completely painted.
- Each element in ... | 22 | 0 | ['Array', 'Hash Table', 'Greedy', 'Matrix', 'Simulation', 'C++'] | 6 |
first-completely-painted-row-or-column | C++ 🔥 DRY RUN 🔥 single map | c-dry-run-single-map-by-tusharaherwar3-fwox | \n\n# Code\n\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n\n unordered_map<int,int>mp;\n for(int | TusharAherwar3 | NORMAL | 2023-04-30T08:28:34.435492+00:00 | 2023-05-03T16:04:57.025429+00:00 | 1,144 | false | \n\n# Code\n```\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n\n unordered_map<int,int>mp;\n for(int i = 0; i < arr.size(); i++) {\n mp[a... | 21 | 0 | ['C++'] | 4 |
first-completely-painted-row-or-column | C++ | Using Only Single Map | Explained | Easy to Understand | c-using-only-single-map-explained-easy-t-s9s0 | C++ Code\n\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n \n int n = size(mat), m = size(m | Rishabhsinghal12 | NORMAL | 2023-04-30T05:27:13.488506+00:00 | 2023-05-04T11:43:25.319984+00:00 | 2,224 | false | **C++ Code**\n```\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n \n int n = size(mat), m = size(mat[0]), res = m*n;\n \n unordered_map<int,int> map;\n \n for(int i = 0; i < m*n; i++)map[arr[i]] = i;\n \n for(... | 14 | 1 | ['Hash Table', 'C', 'C++'] | 3 |
first-completely-painted-row-or-column | Most Optimal Solution ✅Beats 100% | C++| Java | Python | JavaScript | most-optimal-solution-beats-100-c-java-p-w4lv | ⬆️Upvote if it helps ⬆️Connect with me on Linkedin [Bijoy Sing]IntuitionThe key insight is to track the painting progress of each row and column efficiently by | BijoySingh7 | NORMAL | 2025-01-20T04:17:39.090248+00:00 | 2025-01-20T04:17:39.090248+00:00 | 2,237 | false | # ⬆️Upvote if it helps ⬆️
---
## Connect with me on Linkedin [Bijoy Sing]
---
```cpp []
class Solution {
public:
int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {
int row = mat.size();
int col = mat[0].size();
unordered_map<int, pair<int, int>> pos;
fo... | 11 | 0 | ['Array', 'Hash Table', 'Matrix', 'Python', 'C++', 'Java', 'Python3', 'JavaScript'] | 5 |
first-completely-painted-row-or-column | ✅ One Line Solution | one-line-solution-by-mikposp-dzps | (Disclaimer: this is not an example to follow in a real project - it is written for fun and training mostly)Code #1.1 - One LineTime complexity: O(m∗n). Space c | MikPosp | NORMAL | 2025-01-20T10:12:10.409134+00:00 | 2025-01-20T21:17:39.308972+00:00 | 759 | false | (Disclaimer: this is not an example to follow in a real project - it is written for fun and training mostly)
# Code #1.1 - One Line
Time complexity: $$O(m*n)$$. Space complexity: $$O(m*n)$$.
```python3
class Solution:
def firstCompleteIndex(self, a: List[int], g: List[List[int]]) -> int:
return (d:=dict(zi... | 10 | 0 | ['Array', 'Hash Table', 'Matrix', 'Python', 'Python3'] | 0 |
first-completely-painted-row-or-column | C++ || don't use a hash map when a vector or an array does the trick | c-dont-use-a-hash-map-when-a-vector-or-a-fax5 | TODO(heder): Insert cute cat meme to ask for up-votes. ;)\n\n# Approach 1: vector (186ms)\n\nSeveral solutions are using an std::unordered_map for building an i | heder | NORMAL | 2023-04-30T15:20:55.106235+00:00 | 2023-05-02T20:34:04.211431+00:00 | 873 | false | **TODO(heder): Insert cute cat meme to ask for up-votes. ;)**\n\n# Approach 1: vector (186ms)\n\nSeveral solutions are using an ```std::unordered_map``` for building an index, which is a waste as we know that the elements in ```mat``` are within $$[1, n * m]$$, hence we can just directly index into a ```std::vector```.... | 10 | 1 | ['Array', 'C'] | 2 |
first-completely-painted-row-or-column | Testing the soluton | testing-the-soluton-by-datasciencebd2020-wk73 | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | datasciencebd2020 | NORMAL | 2025-01-20T22:44:51.321456+00:00 | 2025-01-20T22:44:51.321456+00:00 | 55 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 9 | 0 | ['Java'] | 0 |
first-completely-painted-row-or-column | Easy to understand code || Simple Mapping | easy-to-understand-code-simple-mapping-b-u8ke | \nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) \n {\n int m = mat.size(), n = mat[0].size();\n | mohakharjani | NORMAL | 2023-04-30T04:03:34.010958+00:00 | 2023-04-30T04:03:34.010998+00:00 | 2,285 | false | ```\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) \n {\n int m = mat.size(), n = mat[0].size();\n vector<int>rowFill(m, 0); //rowFill[i] => how much columns are filled in row = i\n vector<int>colFill(n, 0); //colFill[i] => how much rows are fi... | 8 | 2 | ['Hash Table', 'C', 'C++'] | 2 |
first-completely-painted-row-or-column | C++ | Map | Easy to Understand | c-map-easy-to-understand-by-nidhiigahlaw-051j | Approach\n\nWe first create a map that maps each element in the matrix to its row and column position. Then, for each element in the array, we look up its row a | nidhiii_ | NORMAL | 2023-04-30T04:01:44.794466+00:00 | 2023-04-30T07:12:23.387007+00:00 | 1,288 | false | # Approach\n\nWe first create a map that maps each element in the matrix to its row and column position. Then, for each element in the array, we look up its row and column position in the map and increments the count of elements in that row and column.\n\nIf the count of elements in any row or column reaches the size o... | 8 | 0 | ['C++'] | 2 |
first-completely-painted-row-or-column | Just Use A Simple Map | just-use-a-simple-map-by-saswati10-bul9 | \nclass Solution {\n public int firstCompleteIndex(int[] arr, int[][] mat) {\n \n int m = mat.length;\n int n = mat[0].length;\n | saswati10 | NORMAL | 2023-04-30T04:13:46.079986+00:00 | 2023-04-30T04:29:52.273627+00:00 | 742 | false | ```\nclass Solution {\n public int firstCompleteIndex(int[] arr, int[][] mat) {\n \n int m = mat.length;\n int n = mat[0].length;\n int r[] = new int[m];\n int c[] = new int[n];\n \n Map<Integer, int[]> map = new HashMap<>();\n \n for(int i = 0; i < m; i... | 7 | 0 | ['Array', 'Java'] | 0 |
first-completely-painted-row-or-column | First Completely Painted Row or Column - Solution Explanation and Code (Video Solution Available) | first-completely-painted-row-or-column-s-u3hw | Video SolutionIntuitionThe problem involves identifying the first index in the array arr that completes a row or a column in the matrix mat. By mapping the matr | CodeCrack7 | NORMAL | 2025-01-20T01:21:41.595932+00:00 | 2025-01-20T01:21:41.595932+00:00 | 553 | false | # Video Solution
[https://youtu.be/vejBP6zxtTY?si=kEPfeh8FK0Enzi_8]()
# Intuition
The problem involves identifying the first index in the array `arr` that completes a row or a column in the matrix `mat`. By mapping the matrix values to their coordinates, we can efficiently track the counts for rows and columns as we it... | 6 | 0 | ['Java'] | 1 |
first-completely-painted-row-or-column | 🔥C++ ✅✅ Best Solution ( 🔥 100% faster 🔥) 0(m*n) Easy to Understand + Comments 💯💯 ⬆⬆⬆ | c-best-solution-100-faster-0mn-easy-to-u-u1pc | Complexity\n- Time complexity: O(m * n)\n Add your time complexity here, e.g. O(n) \n\n- Space complexity: O(m * n)\n Add your space complexity here, e.g. O(n) | Sandipan58 | NORMAL | 2023-04-30T04:27:25.228782+00:00 | 2023-04-30T04:27:25.228806+00:00 | 406 | false | # Complexity\n- Time complexity: $$O(m * n)$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(m * n)$$\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n i... | 6 | 0 | ['Ordered Map', 'Matrix', 'C++'] | 0 |
first-completely-painted-row-or-column | 25 ms || using Hash Map || and two Arrays || Easy to UnderStand | 25-ms-using-hash-map-and-two-arrays-easy-5k26 | Code | sathish-77 | NORMAL | 2025-01-20T08:11:01.620080+00:00 | 2025-01-20T08:12:47.478378+00:00 | 278 | false |
# Code
```java []
class Solution {
public int firstCompleteIndex(int[] arr, int[][] mat) {
int[] row=new int[mat[0].length];
int[] col=new int[mat.length];
HashMap<Integer,int[]>map=new HashMap<>();
for(int i=0;i<mat.length;++i){
for(int j=0;j<mat[0].length;++j... | 5 | 0 | ['Array', 'Hash Table', 'Matrix', 'Java'] | 1 |
first-completely-painted-row-or-column | Easy solution 🚀🚀🚀🚀🚀🚀 | easy-solution-by-sharvil_karwa-wm9c | Code | Sharvil_Karwa | NORMAL | 2025-01-20T03:37:33.109615+00:00 | 2025-01-20T03:37:33.109615+00:00 | 571 | false | # Code
```cpp []
class Solution {
public:
int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {
int m = mat.size(), n = mat[0].size(), N = m * n;
vector<int> numToIndex(N + 1, -1);
for (int i = 0; i < N; ++i) {
numToIndex[arr[i]] = i;
}
vector<int... | 5 | 0 | ['Array', 'Hash Table', 'Matrix', 'Python', 'C++', 'Java'] | 1 |
first-completely-painted-row-or-column | Optimizing Space | C++, Python (3-lines), Java | reusing-input-array-c-by-not_yl3-mozz | ApproachFirst we create an array/hashmap to map each value from [1,m⋅n] to a pair containing it's row and column index (r, c). Then we create two arrays rows an | not_yl3 | NORMAL | 2025-01-20T02:03:07.859846+00:00 | 2025-01-20T15:19:38.152477+00:00 | 497 | false | # Approach
First we create an array/hashmap to map each value from $$[1, m \cdot n]$$ to a pair containing it's row and column index `(r, c)`. Then we create two arrays `rows` and `cols` of length $$m$$ and $n$ respectively. While itearting through `arr` we get the corresponding indices from our hashmap of pairs and th... | 5 | 0 | ['Array', 'Hash Table', 'C', 'Matrix', 'Python', 'C++', 'Java', 'Python3'] | 0 |
first-completely-painted-row-or-column | ✅✅Binary Search Solution || Single Set || No hash map || Unique Approach ☢ | binary-search-solution-single-set-no-has-gy0z | Intuition & Approach\n Describe your first thoughts on how to solve this problem. \nIn this problem I have used Binary search and simple unordered set to solve | 2uringTested | NORMAL | 2023-05-12T08:09:21.604822+00:00 | 2023-05-12T08:09:57.092157+00:00 | 157 | false | # Intuition & Approach\n<!-- Describe your first thoughts on how to solve this problem. -->\nIn this problem I have used Binary search and simple unordered set to solve the problem.\n\nThe problem wants us to find the minimum index such that atleast one of the row or column of the matrix is colored. \n\nIn my solution ... | 5 | 0 | ['Binary Search', 'Matrix', 'Ordered Set', 'C++'] | 1 |
first-completely-painted-row-or-column | ✅✅✅ Python3 || Easy & Understandable || Explained | python3-easy-understandable-explained-by-9x3u | Intuition\nYou only need to keep track of how many zeroes are there.\n\n# Approach\nFirst, map each item in mat to the row and column indicies so they can be ac | a-fr0stbite | NORMAL | 2023-05-02T05:58:08.866246+00:00 | 2023-05-02T05:58:08.866290+00:00 | 507 | false | # Intuition\nYou only need to keep track of how many zeroes are there.\n\n# Approach\nFirst, map each item in `mat` to the row and column indicies so they can be accessed anywhere. Next, have a list for how many zeroes are in each row and column. Then, loop over `arr` and record the painted cells. Only the 2 recently p... | 5 | 0 | ['Python3'] | 0 |
first-completely-painted-row-or-column | Store Row and Col | store-row-and-col-by-votrubac-yvqe | Go through the matrix and, for each number, remember the row and col using mn.\n\nThen, count how many elements are painted in each row and column using mc and | votrubac | NORMAL | 2023-04-30T21:17:13.764659+00:00 | 2023-04-30T21:17:13.764690+00:00 | 274 | false | Go through the matrix and, for each number, remember the row and col using `mn`.\n\nThen, count how many elements are painted in each row and column using `mc` and `nc`.\n\n**C++**\n```cpp\nint firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n int m = mat.size(), n = mat[0].size(), k = 0;\n vecto... | 5 | 0 | ['C'] | 1 |
first-completely-painted-row-or-column | Fully Explained simple Java solution | fully-explained-simple-java-solution-by-eiguu | \n# Approach\nImplement a HashMap and store row and column value for each item.\n\nNow make arrays of row and column of size column and row respectively for get | codeHunter01 | NORMAL | 2023-04-30T04:07:48.026690+00:00 | 2023-04-30T04:07:48.026729+00:00 | 709 | false | \n# Approach\nImplement a HashMap and store row and column value for each item.\n\nNow make arrays of row and column of size column and row respectively for getting the filled size of that row or that column.\n\nFor each value of arr we increase the filled size by one and check if any row or col filled size equals to c... | 5 | 0 | ['Array', 'Matrix', 'Java'] | 1 |
first-completely-painted-row-or-column | Simple || Clean || Java Solution | simple-clean-java-solution-by-himanshubh-dwmg | \njava []\nclass Solution {\n public int firstCompleteIndex(int[] arr, int[][] mat) {\n Map<Integer,Integer> map = new HashMap();\n for(int i=0 | HimanshuBhoir | NORMAL | 2023-04-30T04:01:53.432283+00:00 | 2023-04-30T04:01:53.432321+00:00 | 1,118 | false | \n``` java []\nclass Solution {\n public int firstCompleteIndex(int[] arr, int[][] mat) {\n Map<Integer,Integer> map = new HashMap();\n for(int i=0; i<arr.length; i++) map.put(arr[i],i);\n int min = arr.length;\n// Row-wise checking\n for(int i=0; i<mat.length; i++){\n int... | 5 | 0 | ['Java'] | 0 |
first-completely-painted-row-or-column | C++ || Map of each row & column | c-map-of-each-row-column-by-up1512001-dbxc | \nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n unordered_map<int,pair<int,int>> mp;\n for | up1512001 | NORMAL | 2023-04-30T04:01:16.190028+00:00 | 2023-04-30T04:01:16.190074+00:00 | 653 | false | ```\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n unordered_map<int,pair<int,int>> mp;\n for(int i=0;i<mat.size();i++){\n for(int j=0;j<mat[0].size();j++){\n mp[mat[i][j]] = {i,j};\n }\n }\n map<int... | 5 | 0 | ['C', 'C++'] | 1 |
first-completely-painted-row-or-column | Simple py,JAVA code exaplined in detail!! HASH+ARRAY | simple-pyjava-code-exaplined-in-detail-h-2xt7 | Problem understanding
They have given us a mtrix mat which has row rows and col columns.
They have also given us a array arr which tells us the grids which we s | arjunprabhakar1910 | NORMAL | 2025-01-20T11:49:01.201771+00:00 | 2025-01-20T11:49:01.201771+00:00 | 99 | false | # Problem understanding
- They have given us a mtrix `mat` which has `row` rows and `col` columns.
- They have also given us a array `arr` which tells us the grids which we should mark as painted in the matrix.
- we will traverse through the array from `0,1......arr.length`.when either of the *row* or *col* is complete... | 4 | 0 | ['Array', 'Hash Table', 'Matrix', 'Java', 'Python3'] | 0 |
first-completely-painted-row-or-column | Super Simple Solution in java/C Using Freq(track index) ( O(n*m) ) | super-simple-solution-in-javac-using-fre-a5w7 | IntuitionSince we need to check for a completed row/column we can use freq/index arr to track the last used index for each individual row/col using the freq/ind | rajnarayansharma110 | NORMAL | 2025-01-20T06:26:09.297441+00:00 | 2025-01-20T06:27:17.036131+00:00 | 179 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
Since we need to check for a completed row/column we can use freq/index arr to track the last used index for each individual row/col using the freq/index arr
# Approach
<!-- Describe your approach to solving the problem. -->
1. Store the id... | 4 | 0 | ['Hash Table', 'C', 'Java'] | 0 |
first-completely-painted-row-or-column | 🎯Easy || C++ || Python || Java ||✨Hash Table ||👌Beginner-Friendly | easy-c-python-java-hash-table-beginner-f-9rk7 | IntuitionThe idea behind this solution is to determine the first index in the array arr that completes either a row or a column in the matrix mat. Completion of | Rohithaaishu16 | NORMAL | 2025-01-20T06:24:06.869034+00:00 | 2025-01-20T06:24:06.869034+00:00 | 135 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
The idea behind this solution is to determine the first index in the array arr that completes either a row or a column in the matrix mat. Completion of a row or column means that all elements in that row or column have been seen in the sequ... | 4 | 0 | ['Array', 'Hash Table', 'Matrix', 'C++', 'Java', 'Python3'] | 0 |
first-completely-painted-row-or-column | Easy-to-understand✅✅ || Simple Hash Table Apprach 🚀🚀 || C++ 🔥🔥|| Java 🗿🗿 || Python3 💀💀 | easy-to-understand-simple-hash-table-app-a3se | IntuitionThe problem asks us to find the smallest index i such that when we paint the cell corresponding to arr[i] in the matrix mat, a row or a column becomes | Sparsh_786 | NORMAL | 2025-01-20T06:09:32.031733+00:00 | 2025-01-20T06:09:32.031733+00:00 | 304 | false | # Intuition
The problem asks us to find the smallest index $$i$$ such that when we paint the cell corresponding to $$arr[i]$$ in the matrix mat, a row or a column becomes completely painted. The matrix mat has all integers in the range $$[1, m*n]$$, and the array arr gives us the order in which these integers are paint... | 4 | 0 | ['Array', 'Hash Table', 'Matrix', 'Hash Function', 'Python', 'C++', 'Java', 'Python3'] | 0 |
first-completely-painted-row-or-column | First Completely Painted Row in RUBY! | first-completely-painted-row-in-ruby-by-8bg5r | IntuitionWhen I first saw this problem, I realized we need to efficiently track two things:
Where each number is located in the matrix
How many cells are painte | quantummaniac609 | NORMAL | 2025-01-20T05:00:26.203492+00:00 | 2025-01-20T05:00:26.203492+00:00 | 51 | false | # Intuition
When I first saw this problem, I realized we need to efficiently track two things:
1. Where each number is located in the matrix
2. How many cells are painted in each row and column
The key insight was that instead of searching the matrix each time, we could pre-compute the positions of all numbers.
# App... | 4 | 0 | ['Ruby'] | 0 |
first-completely-painted-row-or-column | Simple Logic ... Easy Approach ... Happy Coding🌞 | simple-logic-easy-approach-happy-coding-t4od4 | Intuitionstore the indexes of elements of matrix in an unordered_mapApproach1.Iterate through the array and push the row and column from the map into the row an | sourav12345singhpraval | NORMAL | 2025-01-20T02:30:45.222844+00:00 | 2025-01-20T02:30:45.222844+00:00 | 391 | false | # Intuition
store the indexes of elements of matrix in an unordered_map
# Approach
1.Iterate through the array and push the row and column from the map into the row and column vector.
2.check that if the size of the vector becomes equal to total number of rows or columns . return the i at that point
# Complexity
- Ti... | 4 | 0 | ['Array', 'Hash Table', 'Matrix', 'C++'] | 0 |
first-completely-painted-row-or-column | C++ || MATH || EASY TO UNDERSTAND | c-math-easy-to-understand-by-ganeshkumaw-3awo | Intuition\nstore index{i,j} of every element of matrix \n\n# Approach\nfor an element at index x of arr get{i,j} increment r[i] and c[j] by 1\nif r[i] came n ti | ganeshkumawat8740 | NORMAL | 2023-05-06T07:05:41.494387+00:00 | 2023-05-06T07:05:41.494414+00:00 | 663 | false | # Intuition\nstore index{i,j} of every element of matrix \n\n# Approach\nfor an element at index x of arr get{i,j} increment r[i] and c[j] by 1\nif r[i] came n time than return index x\nif c[j] came m time than return index x\n# Complexity\n- Time complexity:\nO(m*n)\n\n- Space complexity:\nO(m*n)\n\n# Code\n```\nclass... | 4 | 0 | ['Math', 'C++'] | 0 |
first-completely-painted-row-or-column | ✅🚀 || HashMap || Well explained || JAVA || Clean code | hashmap-well-explained-java-clean-code-b-cja0 | Intuition\n Describe your first thoughts on how to solve this problem. \nHere, all we need to find is the index of the element from arr[i] in the matrix.\nFor e | aeroabrar_31 | NORMAL | 2023-04-30T04:09:02.794508+00:00 | 2023-04-30T04:09:02.794541+00:00 | 539 | false | # Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nHere, all we need to find is the index of the element from arr[i] in the matrix.\nFor every element we need to find the index and to keep the count of number of elements in each row and each column, so the time complexity will be $$O(len*... | 4 | 0 | ['Hash Table', 'Java'] | 0 |
first-completely-painted-row-or-column | Unique C++ easy solution without using Pairs | unique-c-easy-solution-without-using-pai-5xe9 | ApproachA map (positionMap) stores each element's position in mat for quick lookup.Two arrays, rowCount and colCount, track how many elements have been marked i | vasanthkokkiligadda | NORMAL | 2025-01-20T17:12:43.652514+00:00 | 2025-01-20T17:16:22.231468+00:00 | 49 | false | # Approach
A map (positionMap) stores each element's position in mat for quick lookup.
Two arrays, rowCount and colCount, track how many elements have been marked in each row and column.
For each element in arr, its position is determined, and the respective row and column counts are updated.
As soon as a row or col... | 3 | 0 | ['C++'] | 1 |
first-completely-painted-row-or-column | 💢Faster✅💯 Lesser C++✅Python3🐍✅Java✅C✅Python🐍✅C#✅💥🔥💫Explained☠💥🔥 Beats 💯 | faster-lesser-cpython3javacpythoncexplai-oule | IntuitionApproach
JavaScript Code --> https://leetcode.com/problems/first-completely-painted-row-or-column/submissions/1514806461
C++ Code --> https://leetcode. | Edwards310 | NORMAL | 2025-01-20T17:04:36.410789+00:00 | 2025-01-20T17:12:58.751974+00:00 | 63 | false | 
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your first thoughts on how to solve this problem. -->
- ***JavaScript Code -->*** https:... | 3 | 0 | ['Array', 'Hash Table', 'C', 'Matrix', 'Python', 'C++', 'Java', 'Go', 'Python3', 'C#'] | 0 |
first-completely-painted-row-or-column | ✅🔥Beating 99.5% | 🔥BRUTEFORCE → OPTIMAL🔥| Detailed Expiation✅ | beating-995-bruteforce-optimal-detailed-h98i5 | Intuition
The goal is to find the first index in the array arr such that a row or column in the matrix mat is completely marked (or filled).
The problem revo | syedtahaseen123 | NORMAL | 2025-01-20T15:04:04.853594+00:00 | 2025-01-20T15:04:04.853594+00:00 | 48 | false | # Intuition
- The goal is to find the first index in the array arr such that a row or column in the matrix mat is completely marked (or filled).
- The problem revolves around efficiently marking matrix cells and checking the row/column completion condition.
# BRUTEFORCE$$ [TLE]$$
1. Iterate over the elements of arr.
... | 3 | 0 | ['Hash Table', 'Matrix', 'Java'] | 0 |
first-completely-painted-row-or-column | ✅✅Beats 100%🔥C++🔥Python|| 🚀🚀Super Simple and Efficient Solution🚀🚀||🔥Python🔥C++✅✅ | beats-100cpython-super-simple-and-effici-5y73 | Complexity
Time complexity: O(mn)
Space complexity: O(mn)
Code | shobhit_yadav | NORMAL | 2025-01-20T12:43:19.207724+00:00 | 2025-01-20T12:43:19.207724+00:00 | 53 | false | # Complexity
- Time complexity: $$O(mn)$$
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity: $$O(mn)$$
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
```cpp []
class Solution {
public:
int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {
const int m = mat.s... | 3 | 0 | ['Array', 'Hash Table', 'Matrix', 'Python3'] | 0 |
first-completely-painted-row-or-column | Simple Approach || Step by Step Explanation || Beats 100% | simple-approach-step-by-step-explanation-0ct8 | Intuition
Since the 2-d array mat contains elements from 1 to m*n, we can try thinking of a approach where we can take advantage of this constraint.
Also try th | shivamp_07 | NORMAL | 2025-01-20T11:05:07.946385+00:00 | 2025-01-20T11:05:07.946385+00:00 | 63 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
1. Since the 2-d array mat contains elements from 1 to m*n, we can try thinking of a approach where we can take advantage of this constraint.
2. Also try thinking about thinking row wise and column wise separately, this can help in building... | 3 | 0 | ['Array', 'Hash Table', 'Matrix', 'C++'] | 0 |
first-completely-painted-row-or-column | Simple solution with explanation beat 83.33% in time and space | simple-solution-with-explanation-beat-83-znvc | IntuitionThe key to solving this problem is building an index mapping, which maps each number to its corresponding row and column. This allows us to efficiently | whats2000 | NORMAL | 2025-01-20T10:34:07.146352+00:00 | 2025-01-20T10:34:07.146352+00:00 | 76 | false | # Intuition
The key to solving this problem is building an index mapping, which maps each number to its corresponding row and column. This allows us to efficiently locate the rows and columns, and keep track of their painted counts. When the count equals $m$ (for a row) or $n$ (for a column), we can determine the resul... | 3 | 0 | ['Array', 'TypeScript'] | 0 |
first-completely-painted-row-or-column | ✅ Easy to Understand | Hash Table | Java | C++ | Python | Detailed Video Explanation 🔥 | easy-to-understand-hash-table-java-c-pyt-30r8 | IntuitionThe problem involves determining the first point in an array where marking an element leads to a complete row or column being filled in a matrix. My in | sahilpcs | NORMAL | 2025-01-20T09:28:44.100083+00:00 | 2025-01-20T09:28:44.100083+00:00 | 82 | false | # Intuition
The problem involves determining the first point in an array where marking an element leads to a complete row or column being filled in a matrix. My initial thought was to map each element of the matrix to its respective coordinates, allowing quick access to the element's position. By maintaining counts of ... | 3 | 0 | ['Array', 'Hash Table', 'Matrix', 'Java'] | 1 |
first-completely-painted-row-or-column | JAVA CODE | java-code-by-ayeshakhan7-45yq | Code | ayeshakhan7 | NORMAL | 2025-01-20T09:19:39.559427+00:00 | 2025-01-20T09:19:39.559427+00:00 | 108 | false |
# Code
```java []
class Solution {
public int firstCompleteIndex(int[] arr, int[][] mat) {
int n = mat.length; //rows
int m = mat[0].length; //cols
int rowCount[] = new int[n];
int colCount[] = new int[m];
// num -> (r,c)
HashMap<Integer,int[]> map = new HashMap<>()... | 3 | 0 | ['Java'] | 1 |
first-completely-painted-row-or-column | ✅ 🔥 Faster | Greedy | Beginner friendly ✅ 🔥 | faster-greedy-beginner-friendly-by-suren-0oeq | IntuitionTwo key thing to look upon is knowing the position of each element and finding whether a particular row or column is paintedApproach
Achieve the first | Surendaar | NORMAL | 2025-01-20T08:55:36.390093+00:00 | 2025-01-20T08:55:36.390093+00:00 | 72 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
Two key thing to look upon is knowing the position of each element and finding whether a particular row or column is painted
# Approach
<!-- Describe your approach to solving the problem. -->
1. Achieve the first step by storing the index... | 3 | 0 | ['Greedy', 'Python3'] | 0 |
first-completely-painted-row-or-column | 🔥BEATS 💯 % 🎯 |✨SUPER EASY BEGINNERS 👏 | beats-super-easy-beginners-by-codewithsp-b6vg | IntuitionThe task is to find the first index in an array where marking a number in a given matrix results in a complete row or column being marked. My initial t | CodeWithSparsh | NORMAL | 2025-01-20T07:54:04.917571+00:00 | 2025-01-20T14:56:39.527721+00:00 | 293 | false | 
---
## Intuition
The task is to find the first index in an array where marking a number in a given matrix results in a complete row or column being marked. My initial thought is to track how many cells... | 3 | 0 | ['Array', 'Hash Table', 'C', 'Matrix', 'C++', 'Java', 'Python3', 'JavaScript', 'Dart'] | 3 |
first-completely-painted-row-or-column | Very intuitive solution || Double Hashing || Must Learn || Please Upvote | very-intuitive-solution-double-hashing-m-tyvv | IntuitionMaintain the live count of elements in rows and columns. At index i in arr remove the element from the live counts.If the count of row or column become | Shiv19_03 | NORMAL | 2025-01-20T07:52:25.871698+00:00 | 2025-01-20T07:52:25.871698+00:00 | 33 | false | # Intuition
Maintain the live count of elements in rows and columns. At index i in arr remove the element from the live counts.If the count of row or column becomes 0 return the index i.
# Approach
Maintain a row, column hashmap the sotres count of numbers not yet seen in arr. If any row or column turns 0 return the c... | 3 | 0 | ['Array', 'Hash Table', 'Matrix', 'Python', 'Python3'] | 0 |
first-completely-painted-row-or-column | 🚀 Optimized Bingo Solver: Fast Tracking Rows & Columns with Flattened Positions 🎯 | optimized-bingo-solver-fast-tracking-row-33zp | IntuitionThe problem can be visualized as playing bingo, where we eliminate numbers from the matrix one by one. After each elimination, we need to check whether | Bulba_Bulbasar | NORMAL | 2025-01-20T07:20:35.512589+00:00 | 2025-01-20T07:20:35.512589+00:00 | 138 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
The problem can be visualized as playing bingo, where we eliminate numbers from the matrix one by one. After each elimination, we need to check whether a complete row or column has been marked. Instead of repeatedly checking the entire row ... | 3 | 0 | ['Array', 'Hash Table', 'Java'] | 2 |
first-completely-painted-row-or-column | Beats 100% , Simple JAVA Solution without Map | beats-100-simple-java-solution-without-m-muzu | IntuitionIterate through matrix and keep track of maximum index in a row and a column. Return minimum of all maximum indexes.
In simple words, find maximum inde | parr_ot | NORMAL | 2025-01-20T06:35:36.188790+00:00 | 2025-01-20T06:35:36.188790+00:00 | 50 | false | 
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
Iterate through matrix and keep track of maximum index in a row and a column. Return minimum of all maximum indexes.
In sim... | 3 | 0 | ['Hash Table', 'Java'] | 0 |
first-completely-painted-row-or-column | Easy solution | easy-solution-by-kiran_kommanaboyina-qnne | IntuitionThe problem requires determining the first index in the array arr at which either a row or a column in the matrix mat is completely filled. The key obs | kiran_kommanaboyina | NORMAL | 2025-01-20T05:23:26.185942+00:00 | 2025-01-20T05:23:26.185942+00:00 | 34 | false | # Intuition
The problem requires determining the first index in the array arr at which either a row or a column in the matrix mat is completely filled. The key observation is that we can track the fill count of rows and columns as we iterate through arr and check if any row or column reaches its full size.
# Approac... | 3 | 0 | ['Array', 'Hash Table', 'Matrix', 'Java'] | 0 |
first-completely-painted-row-or-column | First Completely Painted Row or column | first-completely-painted-row-or-column-b-lt9k | Code | sandeepvaiml | NORMAL | 2025-01-20T04:35:06.663064+00:00 | 2025-01-20T04:35:06.663064+00:00 | 6 | false |
# Code
```python3 []
class Solution:
def firstCompleteIndex(self, arr: List[int], mat: List[List[int]]) -> int:
pos = {}
for i in range(len(mat)):
for j in range(len(mat[0])):
pos[mat[i][j]] = (i, j)
row_count=[0]*len(mat)
col_count=[0] * len(mat[0])
... | 3 | 0 | ['Python3'] | 0 |
first-completely-painted-row-or-column | Beats 100% | Very Easy solution | C++ Java Python | beats-100-very-easy-solution-c-java-pyth-2ha3 | IntuitionThe goal is to find the first index in the array arr such that marking the cells corresponding to the indices in arr completely fills either a row or a | B_I_T | NORMAL | 2025-01-20T04:16:54.278194+00:00 | 2025-01-20T04:16:54.278194+00:00 | 114 | false | 
# Intuition
The goal is to find the first index in the array arr such that marking the cells corresponding to the indices in arr completely fills either a row or a column in the matrix mat. This is done by... | 3 | 0 | ['Array', 'Hash Table', 'Math', 'Matrix', 'Python', 'C++', 'Java'] | 0 |
first-completely-painted-row-or-column | C# Solution for First Completely Painted Row or Column Problem | c-solution-for-first-completely-painted-rj4lc | IntuitionThe problem involves identifying the first step where either a row or a column in the matrix mat is completely painted, based on the order defined in t | Aman_Raj_Sinha | NORMAL | 2025-01-20T04:14:51.082886+00:00 | 2025-01-20T04:14:51.082886+00:00 | 80 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
The problem involves identifying the first step where either a row or a column in the matrix mat is completely painted, based on the order defined in the array arr.
Key observations:
1. Every integer in the matrix mat is unique and appears... | 3 | 0 | ['C#'] | 0 |
first-completely-painted-row-or-column | 0ms | Beats 100% | Efficient Java Solution | Using Hash Mapping with Simulation | Full Explanation | 0ms-beats-100-efficient-java-solution-us-2ggc | YouTubeIntuitionThe problem revolves around finding the earliest index at which a row or column in the matrix is fully painted. To do this efficiently
1. Use a | rahulvijayan2291 | NORMAL | 2025-01-20T02:58:50.794189+00:00 | 2025-01-20T06:45:52.514901+00:00 | 99 | false | 
## YouTube
https://youtu.be/jfwHLz25pfY
# Intuition
The problem revolves around finding the earliest index at which a row or column in the matrix is fully painted. To do this efficiently
1. Use a mapp... | 3 | 0 | ['Java'] | 0 |
first-completely-painted-row-or-column | C++ 🔥||Easy Solution 🎯|| Beginner Friendly⭐||Hash Table💪🏻 | c-easy-solution-beginner-friendlyhash-ta-99vi | IntuitionThe problem involves finding the first index at which either a row or column in the matrix is completely marked. Since we need to determine the earlies | pranay_20 | NORMAL | 2025-01-20T02:43:09.046849+00:00 | 2025-01-20T02:43:09.046849+00:00 | 73 | false |
# Intuition
The problem involves finding the first index at which either a row or column in the matrix is completely marked. Since we need to determine the earliest index, it makes sense to map each matrix element to its respective row and column indices. Using this mapping, we can track the count of marked elements ... | 3 | 0 | ['Array', 'Hash Table', 'Matrix', 'C++'] | 0 |
first-completely-painted-row-or-column | Map with Optimized Checking - O(N*M) | map-with-optimized-checking-onm-by-chrom-4eht | SolutionOverviewWe are given an m×n matrix mat and an array arr of length m∗n both containing every integer from [1,m∗n].Starting from index i = 0, mark the val | chromaa | NORMAL | 2024-12-24T17:32:17.877787+00:00 | 2024-12-24T17:56:33.910212+00:00 | 137 | false | # Solution
---
## Overview
We are given an $m \times n$ matrix `mat` and an array `arr` of length $m * n$ both containing every integer from $[1, m * n]$.
Starting from index `i = 0`, mark the value `arr[i]` as seen in `mat`. Return the smallest index where either a row or column is fully seen.
---
## Approach 1... | 3 | 0 | ['Array', 'Hash Table', 'Matrix', 'Python3'] | 0 |
first-completely-painted-row-or-column | Simple C++ Solution | simple-c-solution-by-imdhruba-20dw | \nclass Solution {\n \npublic:\n void put(vector<vector<int>>& mat, unordered_map<int, vector<int>> &mpp){\n \n for(int i = 0; i < mat.size( | ImDhruba | NORMAL | 2023-12-14T09:12:20.273704+00:00 | 2023-12-14T09:12:20.273723+00:00 | 9 | false | ```\nclass Solution {\n \npublic:\n void put(vector<vector<int>>& mat, unordered_map<int, vector<int>> &mpp){\n \n for(int i = 0; i < mat.size(); i++){\n for(int j = 0; j < mat[0].size(); j++){\n \n vector<int> indexes {i,j};\n mpp[mat[i][j]] =... | 3 | 0 | ['C'] | 0 |
first-completely-painted-row-or-column | Brute Force to Optimal | Easy to Understand | brute-force-to-optimal-easy-to-understan-7fnk | \n//Brute Force :- O(n^2) (will give TLE)\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n int m=m | neel200 | NORMAL | 2023-05-01T05:42:59.085041+00:00 | 2023-05-01T06:01:28.583611+00:00 | 263 | false | ```\n//Brute Force :- O(n^2) (will give TLE)\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n int m=mat.size(), n=mat[0].size(), size=arr.size(), idx=0;\n unordered_set<int>st;\n unordered_map<int, pair<int,int>>mp;\n \n for(int ... | 3 | 0 | ['C', 'C++'] | 0 |
first-completely-painted-row-or-column | 🔥🔥 Accepted || ✅✅ C++ Solution with complete explanation using map. || 100% successful 🔥🔥 | accepted-c-solution-with-complete-explan-whe0 | Approach\n Describe your approach to solving the problem. \nFirst, we store all the elements of mat in map with its elements as key and their indexes as value. | Sanjeev_PU | NORMAL | 2023-04-30T08:53:21.001510+00:00 | 2023-04-30T08:57:02.560829+00:00 | 450 | false | # Approach\n<!-- Describe your approach to solving the problem. -->\nFirst, we store all the elements of $$mat$$ in $$map$$ with its elements as key and their indexes as value. (We are storing to reduce the search complexity in matrix).\n\nWe create two more vector to store the count of the elements painted in the part... | 3 | 0 | ['Ordered Map', 'C++'] | 0 |
first-completely-painted-row-or-column | Go || My solution | go-my-solution-by-wild-boar-725o | Complexity\n- Time complexity: O(n.m) \n- Space complexity: O(n.m) \n\n# Code\n\nfunc firstCompleteIndex(arr []int, mat [][]int) int {\n\tn, m := len(mat), len( | Wild-Boar | NORMAL | 2023-04-30T07:18:24.717269+00:00 | 2023-04-30T07:36:55.367425+00:00 | 155 | false | # Complexity\n- Time complexity: $$O(n.m)$$ \n- Space complexity: $$O(n.m)$$ \n\n# Code\n```\nfunc firstCompleteIndex(arr []int, mat [][]int) int {\n\tn, m := len(mat), len(mat[0])\n\trow := make([]int, n)\n\tcol := make([]int, m)\n\thm := make(map[int][2]int)\n\n\tfor i := 0; i < n; i++ {\n\t\tfor j := 0; j < m; j++ {... | 3 | 0 | ['Go'] | 1 |
first-completely-painted-row-or-column | EASY TO UNDERSTAND || C++ || SIMPLE SOLUTION | easy-to-understand-c-simple-solution-by-2hn30 | \nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n int a = mat.size(),b = mat[0].size(),c = arr.size | yash___sharma_ | NORMAL | 2023-04-30T04:07:19.186880+00:00 | 2023-04-30T04:07:19.186947+00:00 | 434 | false | ````\nclass Solution {\npublic:\n int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {\n int a = mat.size(),b = mat[0].size(),c = arr.size();\n vector<int> r1(a,0),c1(b,0);\n vector<vector<int>> ind(a*b+1);\n for(int i = 0; i < a; i++){\n for(int j = 0; j < b; j... | 3 | 0 | ['Hash Table', 'C', 'Matrix', 'C++'] | 0 |
first-completely-painted-row-or-column | Java | Simple solution | java-simple-solution-by-judgementdey-qnxe | Complexity\n- Time complexity: O(mn)\n Add your time complexity here, e.g. O(n) \n\n- Space complexity: O(mn)\n Add your space complexity here, e.g. O(n) \n\n# | judgementdey | NORMAL | 2023-04-30T04:05:17.454007+00:00 | 2023-04-30T05:37:25.536267+00:00 | 181 | false | # Complexity\n- Time complexity: $$O(m*n)$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(m*n)$$\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\n public int firstCompleteIndex(int[] arr, int[][] mat) {\n var m = mat.length;\n var n = m... | 3 | 0 | ['Java'] | 0 |
first-completely-painted-row-or-column | Derive Intuition through Paper & Pen | derive-intuition-through-paper-pen-by-sh-y0sv | Code | shivanigam | NORMAL | 2025-01-20T22:04:46.851790+00:00 | 2025-01-20T22:04:46.851790+00:00 | 9 | false | 
# Code
```java []
class Solution {
public int firstCompleteIndex(int[] arr, int[][] mat) {
HashMap<Integer, Integer> map = new HashMap<>();
... | 2 | 0 | ['Matrix', 'Java'] | 0 |
first-completely-painted-row-or-column | 🔥 Java | Early Exit Optimization 🚀 | Beats 100% | Efficient HashMap Use | LeetCode #2661 | java-early-exit-optimization-beats-100-e-fyo9 | IntuitionThe problem involves determining the earliest point at which either a row or column in a matrix mat is fully painted, given the sequence of numbers in | yash_jain15 | NORMAL | 2025-01-20T19:07:16.352871+00:00 | 2025-01-20T19:07:16.352871+00:00 | 59 | false | # Intuition
The problem involves determining the earliest point at which either a row or column in a matrix **mat** is fully painted, given the sequence of numbers in **arr**. Since both **arr** and **mat** contain all integers from 1 to (m×n), we can efficiently track the painting process by mapping each number to its... | 2 | 0 | ['Java'] | 0 |
first-completely-painted-row-or-column | Just Simulating what the questions asks to do | C++| Easy Solution | just-simulating-what-the-questions-asks-0ke87 | IntuitionApproach
Store the location of each number in the matrix in terms of its row index and column index (can use any data structure for this eg map, array) | Lakshit_B | NORMAL | 2025-01-20T17:49:48.644982+00:00 | 2025-01-20T17:49:48.644982+00:00 | 6 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
1. Store the location of each number in the matrix in terms of its row index and column index (can use any data structure for this eg map, array)
2. Follow the directions a... | 2 | 0 | ['C++'] | 0 |
first-completely-painted-row-or-column | Easy C++ Solution | easy-c-solution-by-kartikrameshchavan200-edi7 | Code | kartikrameshchavan2003 | NORMAL | 2025-01-20T16:49:15.878094+00:00 | 2025-01-20T16:49:15.878094+00:00 | 57 | false | # Code
```cpp []
class Solution {
public:
int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {
int n = mat.size();
int m = mat[0].size();
map<int, int> mp;
for (int i = 0; i < arr.size(); i++) {
mp[arr[i]] = i;
}
int miniR = INT_MAX;
... | 2 | 0 | ['C++'] | 0 |
first-completely-painted-row-or-column | Easy Beginner Friendly C++ Sol | easy-beginner-friendly-c-sol-by-aditya13-u5sm | Please Upvote!!🥺🙏❤️Complexity
Time complexity:O(M∗N)
Space complexity:O((M∗N)+(M+N))=O(M∗N)
Code | aditya13451 | NORMAL | 2025-01-20T16:45:48.753503+00:00 | 2025-01-20T16:45:48.753503+00:00 | 39 | false | # Please Upvote!!🥺🙏❤️
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:$$O(M*N)$$
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:$$O((M*N) + (M+N)) = O(M*N)$$
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
```cpp []
class Solution {
pub... | 2 | 0 | ['Array', 'Hash Table', 'Math', 'Brainteaser', 'Matrix', 'Simulation', 'C++'] | 0 |
first-completely-painted-row-or-column | "Matrix Painting Completion" || Beats 99.09% Users . | matrix-painting-completion-beats-9909-us-u5fx | IntuitionThe problem can be approached by tracking the count of painted cells in each row and column. When either a row or a column becomes fully painted, we re | Yash-8055 | NORMAL | 2025-01-20T14:21:01.711913+00:00 | 2025-01-20T14:21:01.711913+00:00 | 29 | false | 
# Intuition
The problem can be approached by tracking the count of painted cells in each row and column. When either a row or a column becomes fully painted, we return the correspond... | 2 | 0 | ['Hash Table', 'Matrix', 'Simulation', 'C++'] | 0 |
first-completely-painted-row-or-column | EASY SOLUTION O(M*N) | easy-solution-omn-by-shyam4kb-o08f | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | shyam4KB | NORMAL | 2025-01-20T14:10:44.196757+00:00 | 2025-01-20T14:10:44.196757+00:00 | 7 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 2 | 0 | ['Java'] | 0 |
first-completely-painted-row-or-column | Simple Java Code✅|| Simple Approach🔥|| Well Explained🚀 | simple-java-code-simple-approach-well-ex-77dy | IntuitionTo find the smallest index i in arr such that a row or column in mat is completely painted:
Every integer in arr maps uniquely to a cell in mat. This a | ghumeabhi04 | NORMAL | 2025-01-20T13:44:55.973604+00:00 | 2025-01-20T13:44:55.973604+00:00 | 20 | false | # Intuition
To find the smallest index i in arr such that a row or column in mat is completely painted:
1. Every integer in arr maps uniquely to a cell in mat. This allows us to track the painting process.
2. A row is fully painted when all its cells are painted, and similarly for a column.
3. Use counters for rows an... | 2 | 0 | ['Array', 'Hash Table', 'Matrix', 'Java'] | 0 |
first-completely-painted-row-or-column | Java Solution | java-solution-by-viper_01-f0es | IntuitionApproachComplexity
Time complexity: O(m∗n)
Space complexity: O(m∗n)
Code | viper_01 | NORMAL | 2025-01-20T13:25:38.378099+00:00 | 2025-01-20T13:25:38.378099+00:00 | 11 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity: $$O(m*n)$$
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity: $$O(m*n)$$
<!-- Add your space complexity here, e.g. ... | 2 | 0 | ['Array', 'Hash Table', 'Matrix', 'Java'] | 1 |
first-completely-painted-row-or-column | Simple Java Solution - Using Brute Force (Beats 80.60%) | simple-java-solution-using-brute-force-b-hj2q | Complexity
Time complexity:
O(m∗n), where m = mat.length & n = mat[0].length
Code | ruch21 | NORMAL | 2025-01-20T12:41:48.582440+00:00 | 2025-01-20T12:41:48.582440+00:00 | 10 | false | # Complexity
- Time complexity:
$$O(m * n)$$, where m = mat.length & n = mat[0].length
# Code
```java []
class Solution {
public int firstCompleteIndex(int[] arr, int[][] mat) {
int m = mat.length;
int n = mat[0].length;
int[] rows = new int[m];
int[] cols = new int[n];
Hash... | 2 | 0 | ['Java'] | 1 |
first-completely-painted-row-or-column | Easy C++ solution✅ | Beginner friendly💯 | easy-c-solution-beginner-friendly-by-pro-izts | CodeComplexity
Time complexity: O(N*M)
Space complexity: O(N*M) | procrastinator_op | NORMAL | 2025-01-20T11:24:17.853026+00:00 | 2025-01-20T11:24:17.853026+00:00 | 15 | false |
# Code
```cpp []
class Solution {
public:
int firstCompleteIndex(vector<int>& arr, vector<vector<int>>& mat) {
int m = mat.size();
int n = mat[0].size();
map<int, int> cnt_row, cnt_col;
map<int, pair<int, int>> location;
for(int i=0; i<m; i++){
for(int j=0; j<... | 2 | 0 | ['Array', 'Hash Table', 'Matrix', 'C++'] | 0 |
first-completely-painted-row-or-column | "Simple" ahh Solution | Beats 100%. | simple-ahh-solution-beats-100-by-anaghab-9aqf | IntuitionApproach
Create a hashmap to store the positions of elements in the matrix.
Traverse the matrix and map each element to its row and column indices.
Ini | AnaghaBharadwaj | NORMAL | 2025-01-20T09:48:23.484322+00:00 | 2025-01-20T09:48:23.484322+00:00 | 28 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
1. Create a hashmap to store the positions of elements in the matrix.
2. Traverse the matrix and map each element to its row and column indices.
3. Initialize arrays to track painted counts for rows and columns.
4. Iterate throu... | 2 | 0 | ['Java'] | 1 |
first-completely-painted-row-or-column | Easy Solution Ever | easy-solution-ever-by-darshanvala-tmmc | IntuitionThe problem involves finding the first complete index in an array arr when iterating through the elements sequentially and filling rows or columns of a | DarshanVala | NORMAL | 2025-01-20T09:33:12.539566+00:00 | 2025-01-20T09:33:12.539566+00:00 | 14 | false | # Intuition
The problem involves finding the first complete index in an array arr when iterating through the elements sequentially and filling rows or columns of a matrix mat. A row or column is considered complete if all its elements have been encountered in arr at least once.
The approach is to map the positions of ... | 2 | 0 | ['Java'] | 0 |
first-completely-painted-row-or-column | 🚀 "Crack the Code: First Completely Painted Row or Column!" 🚀 | crack-the-code-first-completely-painted-lkvfw | אִינטוּאִיצִיָהכאשר פותרים בעיה זו, הרעיון המרכזי הוא לעקוב אחר התקדמות הצביעה של כל שורה ועמודה בזמן אמת. על ידי שמירה על מונים, נוכל לקבוע ביעילות מתי שורה או | HIndaCode | NORMAL | 2025-01-20T08:57:57.112031+00:00 | 2025-01-20T08:57:57.112031+00:00 | 29 | false |
# Intuition
When solving this problem, the key idea is to track the painting progress of each row and column in real time. By maintaining counters, we can efficiently determine when a row or column is fully painted.
# Approach
1. **Mapping Numbers to Positions**:
- First, map each number in the matrix to its... | 2 | 0 | ['Python'] | 1 |
first-completely-painted-row-or-column | Concise Explanation of Editorial 🤖 | concise-explanation-of-editorial-by-jagg-4xe7 | Brute Force Approach
Map the values in the matrix to their coordinates using a hash map.
Iterate through the array arr, marking the corresponding cell in the ma | _Jatin_Mehra | NORMAL | 2025-01-20T06:46:05.521477+00:00 | 2025-01-20T06:46:05.521477+00:00 | 8 | false | ### Brute Force Approach
1. Map the values in the matrix to their coordinates using a hash map.
2. Iterate through the array `arr`, marking the corresponding cell in the matrix as "visited" (by multiplying it by `-1`).
3. After each update, check if the corresponding row or column is fully visited using helper function... | 2 | 0 | ['Hash Table', 'Matrix', 'C++'] | 0 |
first-completely-painted-row-or-column | Different from other solutions maybe.. ? | different-from-other-solutions-maybe-by-xdp5p | I did not understand the other solutions so I don't know if this is the same thingIntuitionWe first map the elements in the of arr with their respective indexAf | HandleIsConstant | NORMAL | 2025-01-20T06:45:06.381344+00:00 | 2025-01-20T06:45:06.381344+00:00 | 59 | false | I did not understand the other solutions so I don't know if this is the same thing
# Intuition
We first map the elements in the of arr with their respective index
After that we traverse through the matrix row-wise and column-wise
We keep track of which element is coming in the last in the matrix with the help of va... | 2 | 0 | ['C++'] | 0 |
first-completely-painted-row-or-column | simple hashmap approach | simple-hashmap-approach-by-wokqsvnwuv-3oz9 | IntuitionApproachIterate the matrix and put in the Hashmap the iterate the array arr and then get the value from the hashmap , making a frequency array to make | woKQsvNWuV | NORMAL | 2025-01-20T06:40:12.886765+00:00 | 2025-01-20T06:40:12.886765+00:00 | 48 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
Iterate the matrix and put in the Hashmap the iterate the array arr and then get the value from the hashmap , making a frequency array to make sure of the count.
# Complexity
- Time complexity:
used O(n*m)
- Space complexity:... | 2 | 0 | ['Java'] | 2 |
first-completely-painted-row-or-column | First Completely Painted Row or Column - Easy Explanation - Unique Solution 💯 | first-completely-painted-row-or-column-e-eaxm | Intuition
Finding the maximum latest index at which all the elements in the specific row or column will be painted.
Then find the minimum of the maximum inde | RAJESWARI_P | NORMAL | 2025-01-20T06:08:40.261365+00:00 | 2025-01-20T06:08:40.261365+00:00 | 15 | false | # Intuition
1. Finding the maximum latest index at which all the elements in the specific row or column will be painted.
1. Then find the minimum of the maximum index visited so far so that we can find the smallest index at which specific row or column that can be painted.
<!-- Describe your first thoughts on how to s... | 2 | 0 | ['Array', 'Matrix', 'Java'] | 0 |
first-completely-painted-row-or-column | 🔥Beats 95.12%: Array, HashMap (Simple count the row & column) | beats-8994-array-hashmap-simple-count-th-fziz | IntuitionTo determine the first index in arr that completes a row or column in mat, we can map each value in the matrix to its (row, column) position and track | Himanshu1220 | NORMAL | 2025-01-20T05:34:51.437983+00:00 | 2025-01-20T05:37:28.827482+00:00 | 25 | false | 
# **Intuition**
To determine the first index in `arr` that completes a row or column in `mat`, we can map each value in the matrix to its `(row, column)` position and track ... | 2 | 0 | ['Array', 'Hash Table', 'Matrix', 'C++'] | 0 |
first-completely-painted-row-or-column | C++ solution!!! Easy approach | c-solution-easy-approach-by-yash3002-qnqu | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | YASH3002 | NORMAL | 2025-01-20T05:13:42.173441+00:00 | 2025-01-20T05:13:42.173441+00:00 | 7 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 2 | 0 | ['C++'] | 0 |
first-completely-painted-row-or-column | Easy to understand solution. Beats 100% 😎😎🔥🔥 | easy-to-understand-solution-beats-100-by-4zie | IntuitionFor every row number and column number when a value is encountered increment the count for it's row number and column number. Then check if any of them | nnzl48NW9N | NORMAL | 2025-01-20T04:03:38.222922+00:00 | 2025-01-20T04:03:38.222922+00:00 | 45 | false | # Intuition
For every row number and column number when a value is encountered increment the count for it's row number and column number. Then check if any of them becomes fully colored return that index as smallest value index.
# Approach
1) We need to create mapping for values till m*n so make a vector of size m*n+1... | 2 | 0 | ['Ordered Map', 'Matrix', 'Counting', 'Iterator', 'C++'] | 0 |
first-completely-painted-row-or-column | Simple solution Without using HashMap || | simple-solution-without-using-hashmap-by-gc4l | IntuitionApproachComplexity
Time complexity:
Space complexity:
Code | ritikg4360 | NORMAL | 2025-01-20T03:37:02.102940+00:00 | 2025-01-20T03:37:02.102940+00:00 | 6 | false | # Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
# Approach
<!-- Describe your approach to solving the problem. -->
# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->
- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->
# Code
`... | 2 | 0 | ['Matrix', 'Java'] | 0 |
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