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French/d1512c5540a34e5ebd85520018e51b3a.jsonl CHANGED
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  {"comparison_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_10210::smith_vs_teacher", "source_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_10210", "language": "French", "seed_prompt": "Coupling in the proton NMR spectrum occurs in an AX2 system, where each proton HX is coupled to two equivalent neighbors HA. The coupling constants are given as JAX = 5 Hz for the first HX, with the coupling to the second HX also being 5 Hz. This results in the AX2 spectrum showing specific splitting patterns and multiplicities based on the number of neighbors.\n\nHow does coupling in an AX2 system occur and what is the coupling constant for the first HX?", "pair": "smith_vs_teacher", "system_left": "smith", "system_right": "teacher", "overall": "tie_both_good", "aspects": {"naturalness": "tie_both_good", "cultural_appropriateness": "tie_both_bad", "instruction_following": "tie_both_good", "coherence": "tie_both_good"}, "comment": "", "instance_feedback": "", "winner_system": null, "annotator_id": "happy_bardeen", "session_id": "d1512c5540a34e5ebd85520018e51b3a", "annotated_at": "2026-09-25T09:06:48", "duration_ms": 213156}
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  {"comparison_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_29919::smith_vs_teacher", "source_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_29919", "language": "French", "seed_prompt": "Which is the most stable arrangement of double bonds in an alkadiene—isolated, conjugated, or cumulated? As we saw in Chapter 6, the stabilities of alkenes may be assessed by comparing their heats of hydrogenation. The measured heat of hydrogenation of the two double bonds in 1,4-pentadiene is 252 kJ/mol (60.2 kcal/mol), exactly twice the heat of hydrogenation of 1-pentene. By the same reasoning, hydrogenation of the terminal double bond in the conjugated diene (E)-1,3-pentadiene releases only 111 kJ/mol (26.5 kcal/mol) when it is hydrogenated to (E)-2-pentene. Hydrogenation of the terminal double bond in the conjugated diene evolves 15 kJ/mol (3.6 kcal/mol) less heat than hydrogenation of a terminal double bond in the diene with isolated double bonds. A conjugated double bond is 15 kJ/mol (3.6 kcal/mol) more stable than a simple double bond. We call this increased stability due to conjugation the delocalization energy, resonance energy, or conjugation energy. What is the stability difference in heat evolved on hydrogenation of the terminal double bond in a conjugated diene compared to isolated double bonds?", "pair": "smith_vs_teacher", "system_left": "smith", "system_right": "teacher", "overall": "tie_both_good", "aspects": {"naturalness": "tie_both_good", "cultural_appropriateness": "tie_both_bad", "instruction_following": "tie_both_good", "coherence": "tie_both_good"}, "comment": "", "instance_feedback": "", "winner_system": null, "annotator_id": "happy_bardeen", "session_id": "d1512c5540a34e5ebd85520018e51b3a", "annotated_at": "2026-09-25T09:13:35", "duration_ms": 248821}
 
 
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  {"comparison_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_10210::smith_vs_teacher", "source_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_10210", "language": "French", "seed_prompt": "Coupling in the proton NMR spectrum occurs in an AX2 system, where each proton HX is coupled to two equivalent neighbors HA. The coupling constants are given as JAX = 5 Hz for the first HX, with the coupling to the second HX also being 5 Hz. This results in the AX2 spectrum showing specific splitting patterns and multiplicities based on the number of neighbors.\n\nHow does coupling in an AX2 system occur and what is the coupling constant for the first HX?", "pair": "smith_vs_teacher", "system_left": "smith", "system_right": "teacher", "overall": "tie_both_good", "aspects": {"naturalness": "tie_both_good", "cultural_appropriateness": "tie_both_bad", "instruction_following": "tie_both_good", "coherence": "tie_both_good"}, "comment": "", "instance_feedback": "", "winner_system": null, "annotator_id": "happy_bardeen", "session_id": "d1512c5540a34e5ebd85520018e51b3a", "annotated_at": "2026-09-25T09:06:48", "duration_ms": 213156}
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  {"comparison_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_29919::smith_vs_teacher", "source_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_29919", "language": "French", "seed_prompt": "Which is the most stable arrangement of double bonds in an alkadiene—isolated, conjugated, or cumulated? As we saw in Chapter 6, the stabilities of alkenes may be assessed by comparing their heats of hydrogenation. The measured heat of hydrogenation of the two double bonds in 1,4-pentadiene is 252 kJ/mol (60.2 kcal/mol), exactly twice the heat of hydrogenation of 1-pentene. By the same reasoning, hydrogenation of the terminal double bond in the conjugated diene (E)-1,3-pentadiene releases only 111 kJ/mol (26.5 kcal/mol) when it is hydrogenated to (E)-2-pentene. Hydrogenation of the terminal double bond in the conjugated diene evolves 15 kJ/mol (3.6 kcal/mol) less heat than hydrogenation of a terminal double bond in the diene with isolated double bonds. A conjugated double bond is 15 kJ/mol (3.6 kcal/mol) more stable than a simple double bond. We call this increased stability due to conjugation the delocalization energy, resonance energy, or conjugation energy. What is the stability difference in heat evolved on hydrogenation of the terminal double bond in a conjugated diene compared to isolated double bonds?", "pair": "smith_vs_teacher", "system_left": "smith", "system_right": "teacher", "overall": "tie_both_good", "aspects": {"naturalness": "tie_both_good", "cultural_appropriateness": "tie_both_bad", "instruction_following": "tie_both_good", "coherence": "tie_both_good"}, "comment": "", "instance_feedback": "", "winner_system": null, "annotator_id": "happy_bardeen", "session_id": "d1512c5540a34e5ebd85520018e51b3a", "annotated_at": "2026-09-25T09:13:35", "duration_ms": 248821}
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+ {"comparison_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_31008::smith_vs_teacher", "source_id": "allenai/OpenThoughts3-full-filtered-science-no-cot-decontam-v2_tmp_ids_31008", "language": "French", "seed_prompt": "5.4 (i) Consider a (polygonal) pyramid illustrated on the right. The base BCDE... is an \\(n\\)-sided regular polygon. The projection of the vertex at the top (labeled as \\(A\\)) onto the base is the center of the base (labeled as \\(A'\\)). In addition, vertex \\(A\\) forms an equilateral triangle with each edge of the base, i.e., triangles \\(ABC\\), \\(ACD\\), ... are all equilateral. Determine the dihedral angle between triangle \\(ACD\\) and the base \\(BCDEF...\\). Express this dihedral in terms of \\(n\\).\\n\\n(ii) The \\(B_4\\) skeleton of \\((BCl)_4\\), the \\(B_6\\) skeleton of \\((BCl)_6^{2-}\\), and the \\(B_{12}\\) skeleton of \\((BH)_{12}^{2-}\\) form perfect tetrahedron, octahedron, and icosahedron, respectively. Determine the dihedral angles \\(\\angle G-H-I-J\\), \\(\\angle L-M-N-O\\), and \\(\\angle R-S-T-U\\) in each of the polyhedra, as labeled as below.\\n\\n(iii) The \\(C_8\\) skeleton of \\((CH)_8\\) is a perfect cube. Determine dihedral angle \\(\\angle V-W-X-Y\\), as shown in the figure on the right.", "pair": "smith_vs_teacher", "system_left": "smith", "system_right": "teacher", "overall": "strong_a", "aspects": {"naturalness": "strong_a", "cultural_appropriateness": "tie_both_bad", "instruction_following": "tie_both_good", "coherence": "tie_both_good"}, "comment": "", "instance_feedback": "", "winner_system": "smith", "annotator_id": "happy_bardeen", "session_id": "d1512c5540a34e5ebd85520018e51b3a", "annotated_at": "2026-09-25T09:15:19", "duration_ms": 103666}